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= 1211 kJ mol-1. Therefore the molar heat of combustion of ethanol is 1211 kJ mol-1 (The molar enthalpy of combustion of ethanol is 1211 kJ mol-1). (Note that the enthalpy change for the reaction is negative because the reaction is exothermic, so the enthalpy change for the reaction is -1211 kJ mol-1, ÎH = - 1211 kJ mol-1)
(c) The heat of combustion of propane is -2,220.1 kJ/mol. Calculate the heat of formation, ï H f ï°, of propane given that ï H f ï° of H 2 O (l) = -285.3 kJ/mol and ï H f ï° of CO (g) = -393.5 kJ/mol.(d) Assuming that all of the heat evolved in burning 30.0 grams of propane is transferred to 8.00 kilograms of water (specific heat = 4.18 J/g.alculate the heat of formation, ï H f ï°, of propane given that ï H f ï° of H 2 O (l) = -285.3 kJ/mol and ï H f ï° of CO (g) = -393.5 kJ/mol. (d) Assuming that all of the heat evolved in burning 30.0 grams of propane is transferred to 8.00 kilograms of water (specific heat = 4.18 J/g.