Suppose $f$ is Lebesgue measurable on $(0,1)$, and not essentially bounded.  Can $||f||_p$ tend to $\infty$ arbitrarily slowly?    I am really lost on this problem. I assume the answer is that it can  tend to $\infty$ arbitrarlily slowly but showing that is really difficult. I have tried letting $f=\sum\limits_{k=1}^{\infty}a_k 1_{E_k}$ where $E_i$ is a disjoint collection of subset of $(0,1)$, and working from there but I am at a loss here. Any guidence?    Arbitrarilly slowly-  We say that $||f||_p$ tend to infinity arbitrarilly slowly if for every positive function $\Phi(p)$ on $(0,\infty)$ with $\lim_{p\to \infty}\Phi(p)=\infty$ there exists a function $f$ on $(0,1)$  such that $||f||_p\leq \Phi(p)$ for all large enough $p$.

This is actually an exercise in Rudin's Real and Complex Analysis, $L^p$ spaces chapter. Could anyone help me out? Thanks in advance.  Motivation: It's well known that if we have a function $f$ which belongs to $L^p(0,1)$ for all $p\ge 1$. Then $\lim_{p\rightarrow \infty}\|f\|_p=\|f\|_{\infty}$ (moreover, $\|f\|_p$ is increasing in $p$). This is true even if $\|f\|_{\infty}=\infty$.  Question: How slow (fast) can $\|f\|_p$ grow when $\|f\|_{\infty}=\infty$? More precisely, given any positive increasing function $\Phi$ with $\lim_{p\rightarrow \infty}\Phi(p)=\infty$, can we always find a function $f$ which belongs to $L^p(0,1)$ for all $p\ge 1$, and $\|f\|_{\infty}=\infty$, such that $\|f\|_p\le (\ge)\Phi(p)$ for large $p$?


What do you call a person that can't just relax, someone who always needs to be working or taking a class or working out? Someone who can sit still in one place but only if they are working on something (mentally), and if they aren't working on something mentally then they need to be physically doing something, like running errands or working out etc.. BUT the specific person I have in mind is very calm, and patient but they cannot sit around doing nothing because they feel lazy, like time is wasted.   Maybe it would help to point out that there is not a physical drive to do these things, it isn't a energy level but more of a psychological need to do these things. Often this person is somewhat tired and usually doesn't get a full nights sleep due to over them being so busy with everything they try to do.

There are some people, who always need to do something. They can't just sit and relax. If they are on the job, they constantly try to change something (e. g. propose new approaches to existing tasks). If they go on vacation, they visit all possible places.  These people are mentally healthy, even though sometimes you may suspect them having ADHD or being in a maniac phase of manic-depressive disorder.  Note that most of the time their active nature is beneficial (stuff is get done, innovation happens), but can also have negative consequences (e. g. they may bully everyone to start a project at work, which doesn't make sense economically).  Also, they are very active not because they have to, but because it seems to be part of their nature.  What do you call such people?  In Russian there is an idiom of people having an awl in the anus (шило в попе), which makes it hard for those guys and gals to sit still. I'm looking for something similar in English.


I'm new to Ubuntu. Can I use this window for upgrading but without any problems?   Does the update process delete or change other applications I'm using?

What are the different ways I can use to upgrade Ubuntu from one release to another?


I've decided to learn real analysis for the first exam about this subject at university but I'm not sure about which book to buy.  Please, can you suggest a good reference book?

During the next quarter at uni, I'll be taking a course in real analysis and since I prefer studying with an additional text I thought I'd come here to look for some book recommendations.  My background: I'm comfortable with linear algebra and single variable calculus, but shakey on multivariable calculus. I did have a slight introduction in to geometry.  For linear algebra I found the common recommendation of Hoffman & Kunze to be very helpful (although the abstractness came as a bit of a kicker at first).   For Single variable calculus I used the book Calculus by Adams and Essex, which I found frustrating to work with, because it often left me guessing at what they were trying to do or why they were doing it. I also felt that they exercised a certain lack of rigour. (Which may be due to the subject which would make it hard to derive from axioms.)  Details: Though it would be a complementary text, I'd prefer one which will still hold value as a work of reference at a later point in my studies. I've heard that Rudin's Principles of mathematical analysis is one of the better textst out there, but also read several comments discouraging Rudin's book as a first introduction to real analysis, hence my quest to gather more information and maybe get some more personalised recommendations.  The course: The mandatory course literature will consist of lecture notes, but 4 texts are suggested as recommended reading.   T.M. Apostol, Mathematical analysis. Addison-Wesley (1974) J. Dieudonné, Foundations of Modern Analysis. Academic Press (1960) A. van Rooij, Analyse voor Beginners.Epsilon Uitgaven, no. 6 (2003)   R.S. Strichartz, The way of analysis (1995)   Thanks in advance!


A while back, when first playing around with Ubuntu, I tried installing on Aspire 5517 laptop. I got the information to find out what adapter I had and how to modify Ubuntu to see it. I am now trying again to convert this laptop but have lost all that information. Any and all information will help.  Thank you.

I'm having serious problems installing the Broadcom drivers for Ubuntu. It worked perfectly on my previous version, but now, it is impossible.   What are the steps to install Broadcom wireless drivers for a BCM43xx card?  I'm a user with no advance knowledge in Linux, so I would need clear explanations on how to make, compile, etc.    lspci -vnn | grep Network showed:   Broadcom Corporation BCM4322 802.11a/b/g/n Wireless LAN Controller [14e4:432b]      iwconfig showed:  lo        no wireless extensions. eth0      no wireless extensions.   NOTE: Answer below is updated every time new information is added and confirmed working.


In the following image:   Why can't current flow across the following wire? It's a simple question, but I've kind off always wondered.  Thanks!

First of all let me just state that I do not feel confident enough to tell anyone anything about how electric circuits work or anything about the physics behind them because I simply do not know or understand it all.  But I have many times read that there has to be a closed path for current to flow in a circuit, leading to a fact that if there isn't a closed conductive loop nothing can happen.  And I have taken that to be a definitive truth, but I wonder about something(and I might just as well be terribly far of the path of reason here).  If I was to design a circuit board which contains traces through which very high frequency signals(currents) will flow then I have to consider things like signal reflections, I don't know what reflections consists of in purely physical terms(but I have to imagine that a reflected signal is a certain amount of the current(s) that was originally sent through the trace) but apparently if I send a high-frequency signal down a trace(or wire) then under certain conditions the signal can travel down the trace(wire) only to bounce off of something and then travel all the way back to where it first came from. Where it might bounce off of something again and so it can bounce back and forth travelling the length of the trace over and over again getting smaller and smaller until it dies out.  This is just stuff from the top of my head, stuff that I have never acquired a fair understanding of in the first place. But if we restrict the scenario to this very high frequency situation, if a signal or current can be reflected back towards where it came then why would it even have to be relevant whether there are a closed loop or not.  Couldn't a broken loop present paths for such currents to bounce around in?  I know that I am at a relatively very low level of insight into these complex matters but I don't now why that wouldn't be possible. I would be very happy if anyone could enlighten me.  I have one single hypothesis without anything what so ever to support it, but perhaps the very high frequency scenario alters the way that a traces copper is utilized so that it in some respect is a closed loop in it self?


I have a program which gives random files. It is simple but I'm quite new to this. Im having trouble with creating fileinfo list of files. I added a contextmenustrip which has multiple choose of file genre (e.g: video files, text files..)  I wanted to define string array with cntxtmnustrp. and want it make new array and combine with previous. But it didnt work. Should I create a arraylist and add each list to this?     public partial class Form1 : Form {     public Form1()     {         InitializeComponent();     }     Random r = new Random();     string path1;              DirectoryInfo dif;   // List<FileInfo> files;     FileInfo[] files;     FileInfo[] newfiles;       int randomchoose;     int fok;     int kok, pd;      string[] filetypes;             private void button1_Click(object sender, EventArgs e)     {          FolderBrowserDialog hoho = new FolderBrowserDialog();  // yeni dosya yeri          hoho.ShowNewFolderButton = true;          if (hoho.ShowDialog() == DialogResult.OK)          {             path1 = hoho.SelectedPath;              textBox1.Text = path1;             dif = new DirectoryInfo(path1);                            foreach (string ft in filetypes)         {            files = dif.GetFiles("*.ft", SearchOption.AllDirectories);           //files.AddRange(dif.GetFiles(string.Format("*.{0}", ft), SearchOption.AllDirectories));              newfiles = newfiles.Concat(files);         }                                                                         //pd = liste.Length;             pd = files.Length;             kok = pd;         }                       }          }            private void button1_Click_1(object sender, EventArgs e)     {         listBox1.Sorted = true;      }      private void cesit_Click(object sender, EventArgs e)     {         //contextMenuStrip1.Show();         contextMenuStrip1.Show(this.PointToScreen(cesit.Location));     }       private void videoFilesToolStripMenuItem_Click(object sender, EventArgs e)     {         filetypes = new string[2] { "txt", "png" };      }      private void musicFilesToolStripMenuItem_Click(object sender, EventArgs e)     {         //tur = ".png";         //textBox4.Text = tur;     }      private void textFilesToolStripMenuItem_Click(object sender, EventArgs e)     {      }  }

I am trying to use the Directory.GetFiles() method to retrieve a list of files of multiple types, such as mp3's and jpg's.  I have tried both of the following with no luck:  Directory.GetFiles("C:\\path", "*.mp3|*.jpg", SearchOption.AllDirectories); Directory.GetFiles("C:\\path", "*.mp3;*.jpg", SearchOption.AllDirectories);   Is there a way to do this in one call?


Let A be an invertible matrix. How to prove $\det (A^{-1}) = \frac{1}{\det A}$ without using the property that $\det (AA^{-1})=\det (A) \det(A^{-1})$? Thanks. I think $\det (A^{-1}) = \frac{1}{\det A}$ holds even without this property, given A is invertible.

I'm seeking for a proof of the following:     Let $A$ be an invertible matrix. Then the determinant of $A^{-1}$ equals:   $$\left|A^{-1}\right|=|A|^{-1} $$   I don't know where to begin the proof. Any suggestions?


Is every separable space second countable?  I know that the reverse is true. And this statement is true for metric spaces. But is it true for general topological spaces. I tried to find a counterexample but could not find one.

A toplogical space $X$ is said to be second countable   if there exists a countable basis for the topology.      $X$ is separable if there exist a countable dense subset.   Show that a second countable space always is separable.      Give an example of a space that is separable but not    second countable   The first part was easy and i managed to solve it on my own  Assume that $X$ is second countable and let $B_1, B_2, B_3...$ be a countable basis. Construct the set $A$ by taking one element $x_n$ out of every $B_n$. Then $A$ becomes dense because every open set $U$ contain a $B_n$ which in turn contain the element $x_n$ in $A$.    Again, like in the question i posted yesterday, i had trouble to come up with an example but our professor gave an example during the last lecture but i dont fully understand it:  "For an example of a separable but not second countable space let $X$ be the real line provided with the cofinite topology, i.e. where a set is open if its either empty or if its complement is finite.   Then every infinite set is dense and hence $X$ is separable.  But for an arbitrary countable family of open sets $U_1, U_2...$ write $U_i = X$\ $A_i$, where $A_i$ is finite, there is an element $x \in X$\ $(\cup_i Ai)$, because $A_i$ is countable,  such that the open set $X$\ $\{x\}$ is then not able to contain any $U_i$. Consequently $X$ is not second countable."  We asked him to explain it in more detail but his english is poor and nobody understood anything...:)       Def: A subset $A$ of a topological space $X$ is dense in $X$ if for any point $x$ in $X$, any neighborhood of $x$ contains at least one point from $A$.   $1.$ "Then every infinite set is dense"  Take $A$ to be one of these infinite sets. If $x \in A \subset X$ then it trivially fulfills the definition. But if we take a $x \not\in A$ why is it not possible to find a neighborhood in these finite sets that does not contain an element in $A$?  edit: its obvious if it is only open neighborhoods, open sets in the topology, but that is not specified in the definition.  $2.$ I am not fully understanding this either  "But for an arbitrary countable family of open sets $U_1, U_2...$ write $U_i = X$\ $A_i$, where $A_i$ is finite, there is an element $x \in X$\ $(\cup_i Ai)$, because $A_i$ is countable,  such that the open set $X$\ $\{x\}$ is then not able to contain any $U_i$. Consequently $X$ is not second countable."  Is it possible to express this in a simpler way?


I have a question regarding the absorption of light in e.g. hydrogen atoms:  I didn't quite understand how the electron knows that it can only absorb photons of the right energy.  I thought that when shining light which don't have energy equal to a transition that the electrons absorb the energy and enter transient unstable orbits and very shortly after emit the energy again. However this would mean that an emissions spectrum should be observable from all angles, which as far as I know is not correct.

This might be a stupid question, but nonetheless, it has been bothering me.  If you take a photon, make it go through some atoms in a solid, liquid or whatever, then you have the chance of this photon being absorbed by an electron, and thereby exciting the electron. This requires the photon to have enough energy to actually excite the electron to another energy level.  My question is then: How does the photon know if it has enough energy or not? Do they interact very quickly to determine if it's okay or not, or is it just something it "knows?"


If I have a registration form on a responsive website with only 3 text fields to fill and ALL of them are obligatory, should I put a star key on every label or should that star key only appear if the user left the field blank and pressed register?

If all fields in a form are required should they be marked somehow (eg. with an asterisk)?  I see this done a lot and find it redundant?  There could be a difference in big forms and small forms, but in big ones I would add a note at the top that all fields are required, but I wouldn't necessarily do that on small ones.  What do you think is the right approach?


I am am UK national ( Old British born and  bred )  , currently resident in a Gulf country .  I invited a Bangladeshi  man , a car mechanic known to me  for 6 years and also resident in the same Gulf country   ,  to visit me in the UK for a 1 week holiday  . I said that my own house in London  would be his contact  point and that I would cover any unexpected cost .  He would pay for his own travel to and within the UK.  The application visa was refused – see attached.  If he applied again  , but this time with a  Sponsorship Undertaking  SU07/12  given  by  person in the UK  , is it likely that the visa would be granted .  Note - if I were resident in the UK I would  give such an undertaking .

Many of the UK visa refusals we see here share a common pattern and the prevailing reasons refer to V 4.2 (a) and (c).    I do understand that, while the applicants may describe very different individual circumstances, there's a consistent pattern and, broadly, fall into specific categories:    Credibility (lifestyle, lack of ties, visit history, lies & omissions) Funding (insufficient funds, provenance of funds, funds parking) Sponsorship (family, friends, employer)   Question: What most commonly triggers a UK visa refusal where V 4.2 (a) and (c) are given as the grounds?  Secondarily: Given that there is a clear pattern, to what extent are these refusals predictable? Does sponsorship make a difference? Is there a set of personal circumstances, however abstract, where a refusal is all but guaranteed? For example, why do those we see here on TSE who sought entry for the PLAB or British Army appear to be refused with a common theme? Is there a uniform shortcoming or is it just discrimination?   PLAB: What is about applications for a visa, for the purpose of sitting the Professional and Linguistic Assessments Board (PLAB) exam, that seem to invite refusals. After all, the test is given so that international medical graduates can show that they qualify to practise medicine in the UK. The first part, PLAB 1, can be taken in centres outside of the UK. However, PLAB 2 can be taken only in the UK. Why can't you can't get a visa just to sit the exam, promising that you'll leave immediately after?    British Army: Since Commonwealth citizens are eligible to apply online to join, even those who don't reside in the UK, why is it so difficult to get a visa just to attend an interview to see whether you are suitable? Even with an invitation from the Army, such visa applications seem to be unsuccessful. Isn't a career in the British Army a valid reason?     Lastly:  After such a refusal, what approaches would increase the chance of a successful application?


I want to step down 230VAC so that I can have a large amount of current that I can transmit wirelessly through the transmitter coil to the receiver coil.    I want to transmit it across 5millimetres between a transmitter and receiver.    Radii of the transmitter and receiver can be at-least 4cm and 2cm respectively.    After transmitting it to the receiver coil, I'm going to rectify it so that I can have a certain amount of DC voltage.    After rectifying the amount received, I'm going to filter it. Then regulate it to 5V DC and feed it to the battery.  PROBLEM  I want 5V DC at the end of the circuit, but how can I accomplish that ?  What calculations and equipment specifications do I have to use so that I can figure this out?

I want to transfer electical power wirelessly from a transmitter to a receiver coil.   Input energy is provided by a single phase step-down transformer - 230V/12V AC, 50 Hz, 1,000 mA.   Using the 12 V AC output I want to transfer as much of the available power wirelessly from transmitter coil to the receiver coil over a distance of 5mm.  How can that be done ? What calculations should i solve so as to achieve this ?  I want to transmit across 5 millimeters. The radii of the transmitter and receiver coils I am currently using are are 5cm and 2cm respectively  After transmitting it to the receiver coil, I wish to rectify and filter it and then regulate it to 5V DC use it to charge a battery.   I want 5V DC at the end of the circuit, but how can I accomplish that ?  What calculations and equipment specifications do I have to use so that I can figure this out?


I'm using Mnsymbol package but I don't like how looks \setminus. Because that I want use the default \setminux making   \documentclass{memoir} \DeclareSymbolFont{Symbols}{OMS}{cmsy}{m}{n} \DeclareMathSymbol{\Setminus}{\mathbin}{Symbols}{}  \usepackage{Mnsymbol} \begin{document} $\setminus$ $\Setminus$ \end{document}   but, as you can see, I miss something. How I get that?

Is there a general way to change the font of a particular symbol without switching packages?  For example, suppose I'm using Computer Modern for my entire document, but I want the "subset" operator to look as it does in mathabx.  How can I redefine it to appear in this way?


I have been using Ubuntu 10.04 for a couple of years and I am new to Ubuntu terminal.  I performed my first Ubuntu OS installation a couple of weeks. 14.04  It is now my 4th installation because while I have fixed one thing, I have broken another.  First I was not able to connect to my wireless access point.  Now I cannot connect using a wired, or a wireless connection. I also managed to lose the nm-applet, and my laptop will not shut down unless I hold down the power key.   I was able to establish a connection using an wireless external USB. I also have access to a desktop to perform all checks.  I am loving the learning curve and Ubuntu, however now require some help to see what I have done as I have spent endless nights troubleshooting with no success.  My laptop is a HP dv6700 running Ubuntu 14.04.  Just to add after performing an upgrade I have also lost my cd rom. So I cant even do a re install. My start up disk creator doesn't seem to be functioning either.  I am not giving up. PLEASE HELP

Your situation   You have successfully installed Ubuntu.  You have just downloaded and booted Ubuntu live media.  The latest LTS (see also ) or latest non-LTS release are preferred. See the list of  that are currently supported.) You upgraded your Ubuntu installation to the latest release that the software updater offered you. WiFi worked before, but not now on the new release. You  to new hardware.   Your problem   The wireless of your laptop or desktop is not working. You tried switching the wireless switch off and on and you tried rebooting several times, but you don't see any WiFi access points. You can see your wireless access point, but you cannot establish a connection. You want to analyze the problem, but you don't know where to start or what information you can provide.   This question and answer was written to give people the wireless script that will provide the information needed in most cases to diagnose their wireless issue's.   Related questions


I need to create an array with the following structure:  {int, String, String, int}   I want to insert this array into another array like this:   {int, String, String, int}, {int, String, String, int}, ... and so on.   I have already tried this:  Object[] vector = new Object[100];  public void inserare(int poz, int nr, String nume, String prenume, int nota){      Object[] aux = new Object[4];     aux[0] = new Integer(nr);     aux[1] = new String(nume);     aux[2] = new String(prenume);     aux[3] = new Integer(nota);      vector[poz] = aux;  }  public void afisareLista(){      for(int i = 0; i < vector.length; i++){         System.out.println(vector[i]);     } }   Aux is inserted, but when I want to print all the elements of main array, all I get is something like this:   [Ljava.lang.Object;@15db9742   Any help for display correctly the elements is appreciated.

In Java, arrays don't override toString(), so if you try to print one directly, you get the className + '@' + the hex of the  of the array, as defined by Object.toString():  int[] intArray = new int[] {1, 2, 3, 4, 5}; System.out.println(intArray);     // prints something like '[I@3343c8b3'   But usually, we'd actually want something more like [1, 2, 3, 4, 5]. What's the simplest way of doing that? Here are some example inputs and outputs:  // Array of primitives: int[] intArray = new int[] {1, 2, 3, 4, 5}; //output: [1, 2, 3, 4, 5]  // Array of object references: String[] strArray = new String[] {"John", "Mary", "Bob"}; //output: [John, Mary, Bob]


Why do some users have an association bonus even if they are not in any other Stack Exchange sites (as shown in their profile)? P.S.- I came across many users recently (like  or ).

I found a user on Biology SE.  He has been awarded an association bonus on Biology SE, but he's not a member of any other sites.  How is that possible?  Could he have previously earned reputation on another site, joined Biology SE to earn the association bonus, and then deleted his account on the other site?  I'm just asking out of curiosity.


I want to make an event that runs every time the mouse clicks anywhere on the form.  Currently i got it set this:   this.MouseClick += new System.Windows.Forms.MouseEventHandler(this.Form_MouseClick);   But this only works when not clicking on any other element like a panel Is there any way i can override this?

I have a .NET UserControl (FFX 3.5).  This control contains several child Controls - a Panel, a couple Labels, a couple TextBoxes, and yet another custom Control.  I want to handle a right click anywhere on the base Control - so a right click on any child control (or child of a child in the case of the Panel).  I'd like to do it so that it's maintainable if someone makes changes to the Control without having to wire in handlers for new Controls for example.  First I tried overriding the WndProc, but as I suspected, I only get messages for clicks on the Form directly, not any of its children.  As a semi-hack, I added the following after InitializeComponent:    foreach (Control c in this.Controls)   {     c.MouseClick += new MouseEventHandler(       delegate(object sender, MouseEventArgs e)       {         // handle the click here       });   }   This now gets clicks for controls that support the event, but Labels, for example, still don't get anything.  Is there a simple way to do this that I'm overlooking?


Few days ago I was editing  in Spanish.SE using the mobile site. It has three tags: ,  and  and, as you can see, all of them contain accent marks.  When I was about to submit the edit, I noticed that the tags were completely broken:    I thought that I would not have any problem while submitting the revision, since the tags had not been changed. But no, even that was impossible, since the system would see those as wrong tag names.  What I had to do is to remove all the tags and start typing them from scratch, so the system would understand them.  I also reported this happening on Stack Overflow en español almost one year ago:   This is the full view:

When editing a question with tags which contain accent marks (and likely other non-ASCII characters), the display is garbled, showing HTML escape sequences to the user:    The above screen shot is taken while editing  on my Nexus 4 with Android 5.1.1 viewing the mobile web site (not the Android app).  Although I initially discovered the issue trying to edit  on the pre-private-beta ES.SO (so likely not yet visible to many people).


I was fooling around in a program (I forgot what it's called) and I had just seen a thing that made it so I could have multiple desktops at once. When I decided I didn't want it anymore, I thought that I had put it on from Compiz (since Compiz had options for the multiple desktops (called Cube I think), and so I disabled everything with the name "Cube" in it.  I closed my computer and once I went to login into my account, I saw that the bar on the side had disappeared. I went to restart and once I was back at the login screen, I decided to go see if I had the same problem in the Guest account. I went in it and the bar was still there, untouched. I decided that I should uninstall Compiz because the thing that I deactivated that caused the problem was from that.  I uninstalled it and when I restarted/came back on the login screen, I entered my password to go onto my main account and I received the message: Failed to load session "ubuntu". I then tried with my Guest account, but I had the same problem on it too.  Now I'm screwed in Windows 8 and I'm wondering what I can do to fix it. I've tried something about writing something in the command box that you access by pressing     Ctrl-Alt-F3 (the root terminal I believe). When it asks me my password I write and I have a problem where it tells me that I wrote the wrong password. I've tried it enough times to know that there's a problem with the program.

I installed CCSM to enable window previews in Unity. But when I went into extras, there was no 'window preview' option.  So I tried experimenting with other options in Compiz and now there are no borders in the dialogue boxes (close, minimize, restore buttons are not there, I had enabled some 'flat....' option in Compiz.  Later, I uninstalled Compiz and then reinstalled it. Now it says      "Failed to load session Ubuntu"   I can't even access through the guest account, I am new to Ubuntu.(please explain in detail).  All I have access to is the login screen (it still shows my custom wallpaper). Please help, I don't want to lose my stuff.


I have an old laptop with 2GB of RAM and an old Intel processor running 2 versions of Vista, one of which won't load and says it requires the repair CD and the other has a partition called Recovery (C:) I don't know much about computers, but I'm trying to install Ubuntu 13.10 on that laptop. Ubuntu launches and I can run it from a live CD. After doing a scan it says there are no bad files on the CD, but when I try to install Ubuntu it shows the loading bit after I've chosen my network (wifi), but seems to make no progress. Are the things I said at the start the problem?

I would like to see a full how-to guide on how to install Ubuntu.


A typical blender panel looks like this:    We have a layout object, and we typically add stuff to it. My add-on lets user select from many garments, and for that, I need to be able to show the garment images clearly. So I can't use a button icon, since the user won't be able to see the garment properly when it is icon-size.  So I need to show an image in the panel whose size I can set. Is there a way to add an image like that to the layout of the panel?

I'd like to show an image (png, preferably) in my panel. Does anyone know if this is supported through labels or template_XX UIPanels?


I'm working on a homework set and I need some help. I have a list that looks like this:  list = [1, 2, [3, 4], 5]   The problem is asking me to use list slicing to extract the last element of the nested list. Can someone help me with this?

I need a good explanation (references are a plus) on Python's slice notation.   To me, this notation needs a bit of picking up.   It looks extremely powerful, but I haven't quite got my head around it.


I am with difficulty to understand this prepositions "in" and "at", specifically when it refers to places.  For example, in this sentence, which is the correct and why?  I am IN the beach.  I am AT the beach.

I am really confused.  Which preposition is correct?     She is in/at the park.   They are in/at the park.   I am in/at the park.   Should I use in or at in these sentences?


The zone 'projects/exalted-skein-281903/zones/asia-south1-b' does not have enough resources available to fulfill the request. Try a different zone, or try again later. I am struggling to start VM on google cloud any help on what issue is or how to migrate the server to different India zone

This is a  about a temporary shortage of available resources in Google Cloud services.   I'm a Brazilian user of Google Cloud's Compute Engine for a while and I managed to use it fine for quite some months. Unfortunately, in the last one month or so, I've been facing difficulties starting my instances (around 9 AM) due to the problem "the zone does not have enough resources available to fulfill the request".    At the start, it happened once or twice and then I was able to start my instance. But now it's almost impossible to start it even after dozens of attempts! Following the message's suggestion, I tried to create other instances in southamerica-east1-a nd c (mine was in b) only to find out the same problem happening there. The impression I get from this is that Google has saturated their physical capacities in South America and are doing nothing to increase it.  So what can I do about it? I can't move my server to the USA or something because it's ping sensitive (stock market applications) and, as someone still using the free trial period, I certainly won't start paying for GC if Google may handle me a product I can't use and will take weeks or months to fix.


I know there are materials in the universe (both in the StarWars universe, and other plausible materials outside the StarWars universe) which cannot be penetrated by a lightsaber, but I'm not familiar with what properties of the lightsabers themselves cause them to collide on impact rather than pass through?  Aren't lightsabers just controlled beams of energy? (I'm assuming the answer here is no, considering the question).

A canon answer would be great, but not sure how likely that would be.  But what keeps lightsabers from simply going through or slicing through one another?


When I see some good question I'd like to star it and pay attention to its updates (answers, edits, comments). So it's good to see new message from the inbox messages, but it seems that I can only check these questions under my Favorites tab which I forget to do sometimes.  So, is there any way to get other people's question updates in an inbox message? If not, I think I'd like to have this new feature.

We're considering adding favorite notifications to the global inbox, and are looking for feedback on the idea (as we're not completely sold on it).  But first, some history.  Favorites are kind of like bookmarks, in that they're kept in a handy centralized place.  They also follow you across browsers.  Ok, ok... "bookmarks, on the internet" is not the most compelling feature, but Favorites also opted you into notices for those questions as if you were the owner (edits and new answers, at least).  This was probably the most confusing part (though a  feature) of the old envelope behavior judging by erroneous bug reports, so a way to opt out of this .  Now, favorite updates go nowhere.  But we could* put them into the inbox.  Here's how we envision this feature working:   Every current user has their "notify me on favorite changes" preference cleared (new users start with it cleared). The first time someone favorites a question, they're prompted to opt-in to favorite notices. Whenever a question is commented on or answered (or, possibly, edited) a new notice is pushed into the inbox of users who have favorited it, and have opted in.   Opt-in would be per-site, and it would remain possible to opt-out from your profile page.   This is not a final design, but the basic idea is correct  As I mentioned above, we're not 100% sold on this idea.  We've had a policy to date that nothing goes into the inbox that isn't specifically targeted at a user; this would be tweaking that policy.  *We could also put changes into their tab on the user page, but that reduces their visibility.


1.New employee is going to join on Sunday. 2.New employee is joining on Sunday. 3.New employee will join on Sunday. 4.New employee joins on Sunday.  Can you please let me know which sentence i should use form abou and why ?

From the grammatical point of view all are correct, just the meaning are different, please bring your clarification, thank you.        The Train will leave at 10:00 tomorrow morning.   The Train is going to leave at 10:00 tomorrow morning.   The Train leaves at 10:00 tomorrow morning.   The Train is leaving at 10:00 tomorrow morning.


I'm not sure how to actually show/explain this. I only recall learning harmonic functions being functions that satisfy Laplace's Equation.    Let $f(z)=\frac{1+z}{1-z}$ for all $z\in\mathbb{C}\backslash\{1\}$. a) Show that $f$ maps $\{z\in\mathbb{C}:|z|<1\}$ onto $\{w\in\mathbb{C}:\mathrm{Re}(w)>0\}$. b) Explain why $H\circ f$ is harmonic in $\{z\in\mathbb{C}:|z|<1\}$ if $H$ is harmonic in $\{w\in\mathbb{C}:\mathrm{Re}(w)>0\}$.    I've done $(a)$ by simply inverting $f$ and using the condition that $|z|<1$. However, I'm not sure how this is used (if it is) in part (b).

If $f:D\to D’$ is analytic and $u: D'\to R$ is harmonic then the composition of $u$ and $f$ is harmonic in $D$.  How can I show that the above statement is true/false? Can anyone help me?


Let  $\lim_{n\rightarrow \infty }\sum_{k=2}^{n}\frac{1}{k^3-k}$  I converted the above series into following form by partial fraction method:  $\sum_{k=2}^{n}\frac{1}{k^3-k} =\sum_{k=2}^{n}\frac{-1}{k}+\frac{1}{2} \sum_{k=2}^{n}\frac{1}{(k+1)(k-1)}$  The sum of the second series can be done using the following method: $\frac{1}{4}\sum_{k=2}^{n}\frac{(k+1)-(k-1)}{(k+1)(k-1)}=\frac{1}{4}\sum_{k=2}^{n}[\frac{1}{k-1}-\frac{1}{k+1}]$  Which, then can be easily solved. But the first series clearly a divergent series. How can I then be able to solve the problem? The answer is given as one fourth.

I got this question in my maths paper     Test the condition for convergence of $$\sum_{n=1}^\infty \frac{1}{n(n+1)(n+2)}$$   and find the sum if it exists.   I managed to show that the series converges but I was unable to find the sum. Any help/hint will go a long way. Thank you.


Badges are great, as well as achievements - they encourage people and make discussion, asking question and answering more fun. There are standard badges, which are cool, but from time to time I'm thinking: "Ouch, would be could if there would be an achievement for this...". Is there a way for community to propose new badges? What I can think of are:   Answering in less than 1 minute and getting your answer accepted Getting reputation to some specific number: prime number, 1337, 31415 Answering more than, say, 30 questions a day for the question with the same tag

What are badges? How do users get badges? How can users get tag badges? Can badges be lost/revoked/taken away after they are awarded? If so, how and when? How can I suggest a new badge?   For more information, see "" and the  in the .


I have a db and looking for a mysql commands to extract Extract DDL and DML and Exclude tables which are not required  could you please let me know how we can do it via command prompt?  Thanks, Kathir

Is there a way to restrict certain tables from the mysqldump command?  For example, I'd use the following syntax to dump only table1 and table2:  mysqldump -u username -p database table1 table2 > database.sql   But is there a similar way to dump all the tables except table1 and table2? I haven't found anything in the mysqldump documentation, so is brute-force (specifying all the table names) the only way to go?


Please, how to install Ubuntu Desktop 18.04 LTS on iTunes software and other Windows application software?

Can .exe and .msi files (Windows software) be installed in Ubuntu?


Let $f(x,y,z) = g(\sqrt{x^2 + y^2 +z^2})$, where $g(r)$ is twice differentiable. Calculate $f_{xx}$ + $f_{yy}$ + $f_{zz}$ in terms of the derivatives of $g$.   Prove that if $f_{xx}$ + $f_{yy}$ + $f_{zz}$ $= 0$, then $g(r) = a/r + b$, where $a$ and $b$ are constants.  I've been able to do the first part of the question and I got that $f_{xx}$ + $f_{yy}$ + $f_{zz}$ $=$ $\frac{g''(r)(x + y + z) + 3g'(r) - 1}{\sqrt{x^2 + y^2 + z^2}}$  But I cannot figure out how to prove that $g(r) = a/r + b$. I've tried everything and can't seem to be able to show it.  Can some one please give me a hand? Any assistance would be really appreciated as I have been working on this question for a few days.

If $\nabla^2 f(r) = 0$, show that $f(r) = a\log r + b$, where $a,b$ are constants and $r ^2 = x^2+y^2$.  I know $\nabla$ for cartesian coordinates. But i am not getting idea how to solve above?


Wave–particle duality is kinda bothering me... I read that electrons can act like waves, but I know that electrons are actually particles.  The theory says that if you have not observed the particle it acts like a wave and can explore all classically available particle trajectories simultaneously and when you observe it it ends up in just one place. But doesn't that just mean that this particle is a particle the whole time, but you can't know it's location without observing it and the wave just presents a range of possible locations where it might be if you do observe it?  And if so why would you call it "Wave–particle duality" if this particle is just a particle doing it's thing and a wave is just a best guess of where it is?

Apologies if this has been asked before (I did check and I believe it wasn't). I have a question about the  of photons (or other particles). Depending on what and how we measure the photon turns out to be either a wave or a particle. Recently I saw some web page (and I can't remember where) that maybe neither is true. Both the wave perception and the particle perception are just that: perceptions, strengthened by our perhaps limited ability to observe. What if the reality of the photon is something else, something "on top" of our two perceptions?? Could someone direct me to a site that could tell me more about it (or maybe debunk the whole idea?)?


How do you deal with multivariable limits? We'll use the example $f: \mathbb R ^2 \rightarrow \mathbb R$ $$\lim _{(x,y) \rightarrow (0,0)}\frac{\sqrt{|xy|}}{\sqrt{x^2 + y^2}}$$  The limit doesn't exist, if $x=y$ we have the value $1/\sqrt{2}$ and if $y = x^3$ we get $0$. How would we prove it with the $\epsilon - \delta$ proof? Do we even need to prove it through the definition, or does it suffice to show that approaching the point by different paths leads to different answers?   Given that there are an infinite amount of paths in which to approach our point, how would you prove that the limit did actually exist? Take for example $f(x,y) = xy$, where we'll take the limit $$\lim _{(x,y)\rightarrow (1,2)} f(x,y) = 2 $$ This is obvious because the function is continuous at our point of interest, but how do you prove it directly from the definition? The same tricks we used when dealing with a single variable won't apply here due to the fact that we're dealing with a point, rather than a single number.

Do we rely on certain intuition or is there an unofficial general crude checklist I should follow?  I had a friend telling me that if the sum of the powers on the numerator is smaller then the denominator, there is a higher chance that it may not exists. And if the sum of powers on the numerator is higher then the denominator, most likely, it exists. Also if there is a sin or cos or e-constant, it most likely exists.  How can I know what to do at the first glance given so little time exists for me in exam to ponder? If I spend all my time on figuring out a two-path test when the limit exists, that would be a huge disaster. Is this one of those cases where practice makes perfect? Example: $$\lim_{(x,y)\to(0,0)}\frac{(\sin^2x)(e^y-1)}{x^2+3y^2}$$ Please give me a hint and where do you get the hint. Example: $$\lim_{(x,y)\to(0,0)}\exp\left(-\frac{x^2+y^2}{4x^4+y^6}\right)$$ I need a hint for this too.  Common methods I have learnt for reference: Two-Path test, Polar Coordinates, Spherical Coordinates, Mean Value Theorem using inequalities.


I am trying to deserialise a JSON with Unity 5.4's JSON utility ().   This is what my JSON looks like: {"series":[{,"points":[{"ts":"1473850836254","value":"11.27"},{"ts":"1473851256637","value":"6.44"}]}]}  I am trying to access the values in "points" by calling something like: data.series.points[0].ts  Void Start(){ IncomingData data = IncomingData.CreateFromJSON(jsonResponse.text); // **error 1** print("Series point length" + data.series.points.Count); print("Series point 0" + data.series.points[0].ts); // **error 2** }   //----------------------------------------- classes -------------------------  [System.Serializable] public class IncomingData {     public Series series;     public static IncomingData CreateFromJSON(string json)     {            return JsonUtility.FromJson<IncomingData>(json);      } }  [System.Serializable] public class Series {     public List<Points> points = new List<Points> { }; }   [System.Serializable] public class Points {     public int ts;     public int value; }   Errors  1. keystr == NULL UnityEngine.JsonUtility:FromJson(String)  1. Unexpected node type. UnityEngine.JsonUtility:FromJson(String)  2. ArgumentOutOfRangeException: Argument is out of range. Parameter name: index  I think it has something to do with how I embed the classes within each other - I am not really good at OOP ...

This is what my JSON looks like: {"series":[{,"points":[{"ts":"1473850836254","value":"11.27"},{"ts":"1473851256637","value":"6.44"}]}]}  I am trying to access the values in "points" by calling something like: data.series.points[0].ts       Void Start(){     IncomingData data = IncomingData.CreateFromJSON(jsonResponse.text);     print("Series point length" + data.series.points.Count);     print("Series point 0" + data.series.points.get_Item[0].ts); // error     }   //----------------------------------------- classes -------------------------      [System.Serializable]     public class IncomingData     {         public Series series;         public static IncomingData CreateFromJSON(string json)         {                return JsonUtility.FromJson<IncomingData>(json);          }     }      [System.Serializable]     public class Series     {         public List<Points> points = new List<Points> { };     }       [System.Serializable]     public class Points     {         public int ts;         public int value;     }   My error:  // error CS0021: Cannot apply indexing with [] to an expression of type `method group'


Not a dup of  which barely attends to the technical reasons for or against using 90 degree routes.   As a hobbyist who's enrolling in an EE program in the fall, should I just get in the habit of avoiding right angles in PCB layout? Is this always a best practice or something that only RF or high speed scenarios require ?  Beyond mechanical or aesthetic reasons, are there reason you would want to use 90 degree angles?

I've always wondered this: every single modern PCB is routed at 45 degree angle increments. Why does the industry prefer this so much? Doesn't any-angle routing offer more flexibility?  One plausible theory would be that the existing tools only support 45 degree increments and that there isn't much pressure to move away from this.  But having just researched this topic on google, I stumbled across  - which does away with the 45 degree increments, and according to their marketing materials it does a considerably better job than the 45-degree-limited competitors.  What gives? What would it take for you personally to start routing arbitrary angles? Is it all about support in your favourite software, or are there more fundamental reasons?  Example of non-45-degree routing:   P.S. I also wondered the same about component placement, but it turns out that many pick & place machines are designed such that they can't place at arbitrary angles - which seems fair enough.


Read this book in the 80’s or 90’s. Sci-fi fantasy set aboard a generational ship, people despair because life has no meaning. Suddenly mythical creatures start appearing and some children are kidnapped into a quest with them. Parents watch via virtual reality and can help kids on the quest by sending clues.

I'm trying to track down the title/author of a novel I read some time back.  I read the novel sometime between 1998 and 2004; not sure when it was printed.  The novel itself I originally found in the YA section at my local library.  The setting of the novel is an interstellar generation ship outbound from earth, several generations into the journey.  The plot loosely runs something like this - Several students undergoing what should have been ordinary virtual reality training at school suddenly instead find themselves inside a completely unfamiliar scenario (one which resembles the stereotypical 'you all meet in a bar' RPG intro).  As time goes on, not only are the students drawn back into the 'game' simulation, but they actually begin to disappear from the ship itself - they discover that, in order for everything to go back to normal, they have to win the game.  The whole thing was revealed, in the end, to be the result of a set of embedded programs in the ship's master computer, if I recall correctly, with the programs having been placed there by a programmer who realized that the inhabitants of the ship were effectively breeding the spark of creativity and imagination out of themselves.  Said programmer had taken it on herself to leave them a legacy that would ensure that, by the time they got where they were going, that all-important spark wouldn't have died completely away.  Any suggestions?


In the recent waves of blocking websites in different countries, India also started doing it. Recently India blocked some regional websites. So I want to know is there any way to bypass the blocking and visit those websites in Firefox? Is there any firefox add on  for this?

I'm using network, where services such as Gmail or any other e-mails, Google Drive, Dropbox, all social networks are blocked. Basically my goal is to access simply GMail, but I couldn't find any way to do that so far. I understand that different proxies have different filtering rules, so please post any tricks or your-way solutions.


I was just tempted to vote to migrate a  from stackoverflow to . However it seems only possible to migrate to superuser or serverfault.  Is there a good reason why migrating to other sites is not a good idea?

When someone votes to close an off topic question, Stack Overflow shows a list of five affiliated sites that could be appropriate for that question, namely:   Meta Stack Overflow Server Fault Super User     Shouldn’t this list be more comprehensive and include all affiliated sites? For instance, (La)TeX questions on Stack Overflow should be redirected to .


How do I prove the following identity involving binomial coefficients?  $$\sum\limits_{k=1}^{n+1} \sum\limits_{m=0}^{k-1} \binom{n+1}{k}  \binom{n}{m} = 2^{2n}$$  I understand that it can be proven with induction, however I would love to see combinatorial (intuitive) or algebraic solution.

It's asked to simplify the sum  $$\displaystyle\sum_{0\le i <j\le n+1} \binom{n}{i} \times \binom{n+1}{j} $$  inspecting first values of $n$ shows the sum if apparently equal to $4^n$  I tried re-writing the sum as   $$\displaystyle\sum_{j=1}^{n+1} \binom{n+1}{j} \displaystyle\sum_{i=0}^{j-1} \binom{n}{i}  $$ but that doesn't seem to lead us to the result.  Any suggestions are welcome.  Thanks.


In the datasheet for the DAC8812, there is this diagram in Figure 33:    What is the point of drawing cascading inverting buffers when, logically, it's the same as a single non-inverting buffer? This isn't the only place I've seen it.  edit: This is different than the question  (Why two inverters cascaded in multiplexer control signal terminals?) because I'm asking about an equivalent logic diagram, not physical logical circuitry. And in the diagram in question, there is no pick-off between the buffers.

Why cascaded inverters are used in the multiplexer when it is possible to realize the circuit using a single inverter.


I know that you can't export blender models with their materials. Is there any way I may be able to turn the materials into a texture which I can export separately? Thanks, I'm quite new and I just need a solution to this problem.

I have a sphere having a planet material MADE WITH NODES, and I want to convert this material into an image texture; because this material is made with nodes and only works in Blender, but I want to use in another software. This is my sphere material :   For Example : This is Jupiter :  And this is the texture :  In this case I used a downloaded image for Jupiter to be the material but I want the opposite, I want to change the material to image texture Like The shape of Jupiter texture. Is there anyway in Blender that can achieve my goal ? This is the file with my sphere material .  Textures Needed :  Albedo / Color / Diffuse Normal Map Roughness Glossines  I am using normal nodes and I am not useing the new Principled-shader


How does an independent developer typically go about finding a group of people to playtest their iOS game in 2013?   Is it through Reddit? College campuses? Steam Forums?   For example my game is targeted at males, ages 25-33 and the initial test I want to do on an iPad.

We're a small company without enough employees to run a large scale beta in house.  The app is geo-location based so we're trying to recruits some beta testers from all over that aren't "friends and family".  Are there any sites or communities dedicated to something like this?


I am having this error for a very long time and not able to figure out the solution. Whenever i am trying to install anything using   $ sudo apt-get install <package> Setting up oracle-java8-installer (8u111+8u111arm-1~webupd8~0) ... Using wget settings from /var/cache/oracle-jdk8-installer/wgetrc Downloading Oracle Java 8... --2018-02-09 17:00:08--  http://download.oracle.com/otn-pub/java/jdk/8u111-b14/jdk-8u111-linux-x64.tar.gz Resolving download.oracle.com (download.oracle.com)... 106.51.144.109 Connecting to download.oracle.com (download.oracle.com)|106.51.144.109|:80... connected. HTTP request sent, awaiting response... 302 Moved Temporarily Location: https://edelivery.oracle.com/otn-pub/java/jdk/8u111-b14/jdk-8u111-linux-x64.tar.gz [following] --2018-02-09 17:00:08--  https://edelivery.oracle.com/otn-pub/java/jdk/8u111-b14/jdk-8u111-linux-x64.tar.gz Resolving edelivery.oracle.com (edelivery.oracle.com)... 104.122.10.148, 2600:140f:c000:189::2d3e, 2600:140f:c000:187::2d3e Connecting to edelivery.oracle.com (edelivery.oracle.com)|104.122.10.148|:443... connected. HTTP request sent, awaiting response... 302 Moved Temporarily Location: http://download.oracle.com/otn-pub/java/jdk/8u111-b14/jdk-8u111-linux-x64.tar.gz?AuthParam=1518175928_00ed0e25d1821b70eb9e792e6c25a9bf [following] --2018-02-09 17:00:08--  http://download.oracle.com/otn-pub/java/jdk/8u111-b14/jdk-8u111-linux-x64.tar.gz?AuthParam=1518175928_00ed0e25d1821b70eb9e792e6c25a9bf Connecting to download.oracle.com (download.oracle.com)|106.51.144.109|:80... connected. HTTP request sent, awaiting response... 404 Not Found 2018-02-09 17:00:08 ERROR 404: Not Found.  download failed Oracle JDK 8 is NOT installed. dpkg: error processing package oracle-java8-installer (--configure):  subprocess installed post-installation script returned error exit status 1 dpkg: dependency problems prevent configuration of oracle-java8-set-default:  oracle-java8-set-default depends on oracle-java8-installer; however:   Package oracle-java8-installer is not configured yet.      dpkg: error processing package oracle-java8-set-default (--configure): dependency problems - leaving unconfigured Errors were encountered while processing:  oracle-java8-installer  oracle-java8-set-default dpkg: error processing package oracle-java8-set-default (--configure):  dependency problems - leaving unconfigured No apport report written because the error message indicates its a followup error from a previous failure.                           Errors were encountered while processing:  oracle-java8-installer  oracle-java8-set-default E: Sub-process /usr/bin/dpkg returned an error code (1)   I tried cleaning apt using   sudo apt-get clean    tried removing everything from /var/cache regarding oracle-java8 but again whenever i tried the folder in /var/cache/oracle-java8-installer created. i tried removing every lock file from /var/cache and var/lib/dpkg.  I also tried   sudo apt-get -f install   no matter whatever i try to install using sudo apt-get, this error comes up :(.

I have Java on my Ubuntu 16.04 system, but every time I try to install a program / package I get an error:  Do you want to continue? [Y/n] y Setting up oracle-java8-installer (8u131-1~webupd8~2) ... Using wget settings from /var/cache/oracle-jdk8-installer/wgetrc Downloading Oracle Java 8... --2017-08-14 19:20:07--  http://download.oracle.com/otn-pub/java/jdk/8u131-b11/d54c1d3a095b4ff2b6607d096fa80163/jdk-8u131-linux-x64.tar.gz Resolving download.oracle.com (download.oracle.com)... 188.43.76.48, 188.43.76.74 Connecting to download.oracle.com (download.oracle.com)|188.43.76.48|:80... connected. HTTP request sent, awaiting response... 403 Forbidden 2017-08-14 19:20:08 ERROR 403: Forbidden.  download failed Oracle JDK 8 is NOT installed. dpkg: error processing package oracle-java8-installer (--configure):  subprocess installed post-installation script returned error exit status 1 Errors were encountered while processing:  oracle-java8-installer E: Sub-process /usr/bin/dpkg returned an error code (1)   How can I fix this?


I'm experiencing problems with Linguex. For some reason, weird symbols are appearing in some of my examples. The relevant part of the code is given below and the output is in the screenshot. Thank you in advance for your help!  \documentclass[11pt;a4paper]{article}  \usepackage{linguex} \usepackage{apacite} \usepackage{latexsym} %symbols \usepackage{comment} \usepackage{stmaryrd} %symbols \usepackage{amssymb} %symbols \usepackage{qtree} \usepackage{amsmath} %symbols \usepackage{url}  \usepackage[normalem]{ulem}%for \sout  \usepackage{float}%to keep tables in their place   \usepackage{color}%for changing the text colour   \usepackage{tikz} %for circles around symbols and other fancy stuff   \usepackage[T1]{fontenc}%for Scandinavian letters   \newcommand*\circled[1]{\tikz[baseline=(char.base)]{    \node[shape=circle,draw,inner sep=1pt] (char) {#1};}}%circle around symbols     \newcommand{\sem[1]}{$\llbracket$#1$\rrbracket$}%sembrackets       \usepackage{tree-dvips}%for arrows in trees  \begin{document}  \ex. $\neg$ [$\Box$ [$\exists x$ [$x$ is a merchant and Petronella marries $x$]]]\label{51220173}  \ex. \label{51220175}\a. Surface scope: what Petronella wants to do is to marry no merchant\\     $\Box > \neg \exists$     \b. Inverse scope: there is no specific merchant Petronella wants to marry\\     $\neg\exists > \Box$\label{51220175b}     \c. Split scope: Petronella does not want to marry a merchant\\     $\neg > \Box > \exists$  \end{document}

The numbering of the sentences shows as underlined dots when using      \ag. \a. \b.     of     linguex     and     tipa     .     \bg.     works fine but starts numbering from (a.)  \documentclass{article} \usepackage{linguex} \usepackage[main=english,italian,spanish,portuguese,catalan]{babel} %babel has problems with french - tried frenchle does't work either \usepackage{harvard} \bibliographystyle{agsm} \usepackage{tipa} \usepackage{hyperref} \begin{document}  \section{Catalan} text text text text text text text text text text text text text text text text text (English)  \ex. \label{cat2} \ag. en Joan t\'e m\'es vaques que en Pere. (NP-comparison)\\ D John have.3SG more cows than D Peter\\ John has more cows than Peter. \cite{Hualde2002} \bg. t' estimo m\'es que la Maria.\\ CL.2s love more that the Mary\\ I love you more than Mary. \cite{Hualde2002} \bg. en Joan \'es m\'es alt que la Maria. (AdjP-Comparison)\\ D John is more tall that D Maria\\ John is taller than Mary \cite{Hualde2002}  \section{English}  \ex. \a. This is an English example.  \b. This is an English example.  \end{document}


i am wondering if you could help me in my project. I would to ask your opinion of what algorithm is best to used in generating random numbers that ranges from 1 to 9.. Its a game like "Sphere Break" a famous mini game of FFx-2.   Please refer to the picture for   Need Opinions Please!! Need Help Badly.   My problem is that i want a certain algorithm to generate random numbers from 1 - 9 like in the picture every gameplay = another set of random coins...   P.S. i am developing an android game using unity !! thx for the response

How do I generate a random int value in a specific range? I have tried the following, but those do not work: Attempt 1: randomNum = minimum + (int)(Math.random() * maximum);  Bug: randomNum can be bigger than maximum. Attempt 2: Random rn = new Random(); int n = maximum - minimum + 1; int i = rn.nextInt() % n; randomNum =  minimum + i;  Bug: randomNum can be smaller than minimum.


So, we haven't had to type http:// since 1997 or so, but we still have to type https:// unless the website has setup a redirection.  There's macros/textexpander/bookmark for overcoming the agonizing 8 seconds this takes. Anything else? Anything builtin to the browser?

Many websites offer both, HTTP and HTTPS, e.g.,  and    Is there any way to force Chrome to try HTTPS first before HTTP when I only type stackoverflow.com in the address bar?


Can I connect the sound that was destinated to speakers from an amplifier to a PC sound card line-in? Won't my sound card burn? I don't have any other outputs on amplifier (line-out or headphones) and I don't have any other way to obtain that sound. Thanks

I would like to know whether it is possible to connect my Yamaha amplifier to my computer. I'm very scared to do this, because some say that the output from my amplifier would cause my sound card to smoke up. And I don't even have a singlue clue how I can connect my amplifier to my computer...  Can someone please help me with this?


I am planning to change from Windows to Ubuntu because Windows is hard to maintain (because of virus threats and expensive security software). But I'm  worrying whether CAD applications such as Autodesk AutoCAD, 3ds Max, CorelDraw and SketchUp, are working well with Ubuntu os?

I am planning to replace Windows, but I'm  worrying if CAD application such as Autodesk AutoCAD, 3ds Max, Corel Draw and SketchUp, are they working well with Ubuntu?


Just as for the duplicate, we should add a reason, on top of the post, as for why the feature request was declined.  Feature requests are a very important part of the site but so is the response from the team. Sometimes,  in the lot of answers and still it's just a guess by trying to find the staff in all the users that posted.  It would be way easier if something like this was done :

Could the team try to leave at least a little explanation when tagging a feature-request post with the "status-declined" tag?  On Uservoice there was usually a brief explanation.  I'm not saying it should be mandatory or anything, it would just be nice.


I've spent awhile using the extrude tool to construct a mesh, but once problem I've noticed is that if I'm creating a shape with some kind of concavity and two parts of the mesh come back together, then there are two faces pointing into each other and each one has its own set of vertices. I've been consistently entering numbers when extruding so I know that the vertices are in exactly the same position, aside from a possible small amount of floating-point error.  I found  about merging vertices to create a pyramid, but the answers on it are only applicable to creating pyramids and similar shapes, since they are about manually selecting one of the cube faces to collapse. My mesh likely has hundreds of these duplicated vertices and manually checking the entire mesh is not an option, so I either need to use a tool or get a Python script to automate the process. However, the Alt+M functionality in that question looks useful, since it seems to be able to merge arbitrary vertices.  How do I merge my vertices together? Is there some kind of Python script I can use? Is there a way I can iterate through all of the vertices, check if any two are equal in position, select them, perform the Alt+M functionality from Python, and repeat for all vertices? Since merging vertices would change the amount of vertices, the entire script would basically need run itself many times to merge all of the coinciding vertices, or somehow loop until it finds no coinciding vertices.

I'm trying to run the remove_doubles edit command on multiple selected objects. This is kinda what I got so far...  import bpy   class remDoubles(bpy.types.Operator):     """Remove Doubles on multiple objects"""     bl_label = "Remove Multiple Doubles"     bl_idname = "object.remove_doubles_multi"     bl_options = {'REGISTER', 'UNDO'}      @classmethod     def poll(cls, context):         return len(context.selected_objects) > 0      def execute(self, context):          scene = bpy.context.scene         sel = context.selected_objects          for obj in sel:             scene.objects.active = obj              #do something here             print(obj.name)             bpy.ops.mesh.remove_doubles()          return {"FINISHED"}  myobject = remDoubles()  myobject.execute()   My knowledge about classes isn't too great, please help.  My code needs some work, it just errors out giving a  'TypeError: bpy_struct.new(type): expected a single argument'  But what i intend doing is run through each object applying the remove doubles command for each.


I am planning to visit Europe in November. My initial plan was to be in Switzerland for the entire duration of the trip. I have got the visa as well. But I wish to go to Amsterdam for two nights out of 9 days and one night to Paris (travel by train). The remaining is in Switzerland only. Is it okay to travel with the visa?

In case, if I get a multiple-entry Schengen visa in one of the embassies in Ukraine, Kyiv - should my first trip be to the country which issued the visa?  Any there any requirements of this sort? Does this condition vary depending on embassy which issued the visa?  What are the possible consequences on not visiting that country first? Does it somehow depend on country where the embassy is (i.e. non-Schengen and not EU members)?


Is there a way to fit table cells to their content? (InDesign)

You know how Excel has the function "Autofit," where you select a whole row or a whole column and it resizes the entire thing to the height or depth of the largest content item? I want to do that in an InDesign table, but with one click. (I know I can drag the column out until the overflow box goes away, but I want to know if there's some automated function I'm overlooking.) Does this automatic function exist anywhere?


W: Failed to fetch http://archive.ubuntu.com/ubuntu/dists/hardy/multiverse/binary-armhf/Packages  404  Not Found [IP: 91.189.92.200 80]

Recently I have installed an older version of Ubuntu on my old machine. Whenever I try to install any software, I get an error saying it couldn't be found:  $ sudo apt-get install vlc Reading package lists... Done                Building dependency tree        Reading state information... Done     E: Couldn't find package vlc


I have a floor function proof that I need to do. The arithmetic of the actual problem isn't my problem. It is the way to do the direct proof. I don't know how to prove this. Prove that if x is a real number, then ⌊2x⌋ = ⌊x⌋ + ⌊x + 1/2⌋.  I already know for any x this is true but how do you do the proof?

I'm doing some exercises on Apostol's calculus, on the floor function. Now, he doesn't give an explicit definition of $[x]$, so I'm going with this one:     DEFINITION Given  $x\in \Bbb R$, the integer part of $x$ is the unique $z\in \Bbb Z$ such that $$z\leq x < z+1$$ and we denote it by $[x]$.   Now he asks to prove some basic things about it, such as: if $n\in \Bbb Z$, then $[x+n]=[x]+n$  So I proved it like this: Let $z=[x+n]$ and $z'=[x]$. Then we have that  $$z\leq x+n<z+1$$  $$z'\leq x<z'+1$$  Then $$z'+n\leq x+n<z'+n+1$$  But since $z'$ is an integer, so is $z'+n$. Since $z$ is unique, it must be that $z'+n=z$.  However, this doesn't seem to get me anywhere to prove that  $$\left[ {2x} \right] = \left[ x \right] + \left[ {x + \frac{1}{2}} \right]$$  in and in general that   $$\left[ {nx} \right] = \sum\limits_{k = 0}^{n - 1} {\left[ {x + \frac{k}{n}} \right]} $$  Obviously one could do an informal proof thinking about "the carries", but that's not the idea, let alone how tedious it would be. Maybe there is some easier or clearer characterization of $[x]$ in terms of $x$ to work this out.  Another property is $$[-x]=\begin{cases}-[x]\text{ ; if }x\in \Bbb Z \cr-[x]-1 \text{ ; otherwise}\end{cases}$$  I argue: if $x\in\Bbb Z$, it is clear $[x]=x$. Then $-[x]=-x$, and $-[x]\in \Bbb Z$ so $[-[x]]=-[x]=[-x]$. For the other, I guess one could say:  $$n \leqslant x < n + 1 \Rightarrow  - n - 1 < x \leqslant -n$$  and since $x$ is not an integer, this should be the same as $$ - n - 1 \leqslant -x < -n$$  $$ - n - 1 \leqslant -x < (-n-1)+1$$  So $[-x]=-[x]-1$


I am making a new animation for a company, based on their previous version that I have received. The previous version is at some arbitrary scale, but since I am updating and adding geometry (new product) it would be nice to have the scene to scale. (1 blender unit = 1m) Just resizing everything is not enough, as some objects pop back in place & size due to animation keyframes.  Is there an easy way to scale the whole scene, including camera animation, textures etc. so that I can work on it "to scale"?

I have a complex scene with physics (not baked) and I discovered a long way into the scene that I need to scale everything up for the physics to do it's thing right. I scaled everything up, pressed play and everything went to crap. My keyframes are interfering. Is there a way to set the scale of all of the objects across all of the keyframes without messing up the other keyframe settings?


I would like to know what is the order of $\mathbb{Z}_3^*/(\mathbb{Z}_3^*)^3$ as a group, where $\mathbb{Z}_3$ represents the 3-adic integers.  I know how to find the units of $\mathbb{Z}_3$, but I do not know how to compute its cube. Please help me with this.

From what I understand about the group of units of the 3-adic integers, it consists all $a$ that can be expressed as a = $\sum_{i=0}^\infty a_i 3^i$ where $a_0 \neq 0$. How can we recognize which 3-adic integers are the cubes of units? I was also told that cubes of units of 3-adic integers form a group. What does this group look like?


I am confused with the use of plural or singular with the word "performance".  My context is the following: I am running multiple experiments in order to evaluate the performance(s?) of an algorithm.  I want to say that using method A is not relevant to evaluate the algorithms in term of performance(s?).  In my native language (French), that would be plural, but I think the logic is different in English. Is it uncountable? Is it always the case?  In the sentences above, should I write performance or performances?

When I have to use information and performance I'm always confused.  However, I'm asking whether when I'm referring to more than one piece of information of performance I should use "information/performance is" or "information/performance are."


The TeX-primitive \show displays text of a command but I observed that not all, say LaTeX's commands, have been exhibited by this way. Opinions and solutions of experts please.........

I know that, whenever I want to see how some control sequence, say \mycontrolsequence, is defined, I can use \show\mycontrolsequence  then compile my code and look up the .log file. However, robust commands seem impervious to \show. For instance, if I compile the following code, \documentclass{article}  \newcommand\mycommand{foo} \show\mycommand  \DeclareRobustCommand{\myrobustcommand}{bar} \show\myrobustcommand  \begin{document} hello \end{document}  my log file contains  \mycommand=\long macro: ->foo. l.4 \show\mycommand  \myrobustcommand=macro: ->\protect \myrobustcommand  . l.7 \show\myrobustcommand   Note that, whereas the definition of \mycommand is exposed (foo), nothing transpires of \myrobustcommand's definition. Of course, in practice, I could always identify in which file a given robust command is defined and look up its definition there. However, finding the file in question may not be obvious. Hence my question: Is there an alternative way of peering into the definition of a robust command?


Studying English in school as a second language, I learned that human being would be the proper noun to describe a member of the Homo sapiens species, but it seems human is perfectly acceptable in English nowadays. It can even sometimes substitute (supposedly gender-specific) man where that was used in a gender-neutral way, e.g. in humankind, but not in *chairhuman, *firehuman etc.  The gender nouns man and (derived) woman, however, have their plurals as men and women, respectively, so why is umlauted *humen not acceptable at least as an alternative to the regular plural morphem +s which is used to form humans? The same question applies to some peoples or tribes, e.g. the Germans and Normans, not *Germen and *Normen.   The question even applies if human and man have different actual etymologies (Romance vs. Germanic), because perceived or folk etymology is often at least as important.  Also, does this effectively render these words , although they seem to contain the gender-specific morpheme man (in singular)?

What makes these two words so different that 'man' is changed to 'men', but 'German' is changed to 'Germans'?


Does anyone knows how to hide the emitting source of particles but show the particles only. I am using hair Type emitter, and particles are emmited from the vertex as reference location. I don't want to use the particle instance modifier because of the memory usage

I'm using hair on my mesh but when I comb the mesh the hair goes through it. I don't want the mesh anyways so instead of figuring out how to stop the hair from going through the mesh I'm trying to figure out how make the mesh invisible but not the hair. When I use a transparency node it effects hair and mesh  I added the particle instance modifier like it says in this question  but it didn't hide the mesh.  Thanks in advance


I want to calculate Vo by Thevenin's theorem. First I removed the RL(1k)    Now I have to calculate Vth. Can I say that Vth is 6V? or Vth=6V + voltage through 2k?  If both these options are wrong, then tell me any law or procedure to find Vth?


I would like to simulate a Brownian excursion process using a computer. I want to create sample paths of a Brownian excursion (a Brownian excursion is a Brownian bridge conditioned to be positive at all t between 0 and 1). Is there an easy was for me to do this, maybe in R or Matlab?

I would like to simulate a Brownian excursion process (a Brownian motion that is conditioned always be positive when $0 \lt t \lt 1$ to $0$ at $t=1$). Since a Brownian excursion process is a Brownian bridge that is conditioned to always be positive, I was hoping to simulate the motion of a Brownian excursion using a Brownian bridge.  In R, I am using thh 'e1017' package to simulate a Brownian bridge process. How can I use this Brownian bridge process to create a Brownian excursion?


Is there a space $X$ such that $S^1$ is homeomorphic to $X \times X$?  If there is it would need to have fundamental group $\mathbb{Z}$.  $\pi_1(X \times X)=\pi_1(X) \times \pi_1(X)$  What can I do now?

I had an exam this morning, one of the questions asked about the truth of the statement      There is a space $X$ such that $S^1$ is homeomorphic to $X\times X$.   I said that this was false and this was my reasoning... was I correct? (Note, an earlier part of the question asked me to prove $\pi_1(Y\times Z)=\pi_1(Y)\times\pi_1(Z)$, I took this as a hint.)  Suppose for the sake of contradiction that such an $X$ exists. Then $\Bbb{Z}\cong G\times G$ where $G\cong\pi_1(X)$. Let $\Phi$ be the isomorphism.  Let $\Phi(1)=(g_1,g_2)\in G\times G$. Then at least one of $g_1,g_2$ is nonzero, since $\Phi(0)=(0,0)$ (the identity on $G\times G$, and $\Phi$ is injective). Without loss of generality $g_1\ne 0$. Then which element $n\in\Bbb{Z}$ has $\Phi(n)=(kg_1,0)$? Since $$kg_1=\underbrace{g_1+\dots +g_1}_k\in G,$$ and $\Phi$ is surjective, such an $n$ should exist. But this is not possible since $\Phi(n)=(kg_1,0)$ implies (since $\Phi$ is a homomorphism) that $kg_1=ng_1$ and $ng_2=0$, and since $k$ was arbitrary and this need not hold if $k\ne 0$.


Its basically reverse baking so can you do that ? I'm not going to upload my blend file cause I believe in this case it is unnesecarie

Although I do have limited experience with 3D modeling, I'm very new (about 10 days) to using Blender 2.8  I learned how to export character models from Overwatch and import them into Blender. So far so good; I can see the mesh, the UV map, the rendering pipeline, and so-forth. I would like to export the mesh to an OBJ file or an STL file for my 3D printer's slicer to work with. However I realized that a lot of the fine details were missing. That lead me down a long dark tunnel of normal (bump) mapping, rendering, and displacement maps that left me more confused than before.  Below three images are attached. You can see that the exported OBJ is identical to the original object mesh. However the rendered image has a normal map applied that provides more detail around the muzzle of the blaster.  My question is this: Does Blender (or any other 3D editing program) have the ability to export an OBJ after applying the the normal map so that the fine details are captured for printing?   UPDATE: I attempted to apply the existing normal map as a displacement per @Duarte's suggestion below. The only effect was to completely distort the model. Fourth image below shows the result.  Object mesh:   Rendered model:   Exported OBJ file:   Normal map applied as displacement modifier:


Something weird is going with my code.  I have a small form (not designed well, but will do for now). The user type username and password, and then press submit.  I added an action listener method for the button. At first, the only thing in it was:  dispose();  and indeed, when pressed, the window closed.  Now when I add an if statement like you see in the code, it does nothing if the value is the correct, however, if it is wrong, it does what I wrote in the else part....  if I am trying to add another condition with && and the passwordfield, it give me error message: the method is deprecated, and Eclipse puts a line over the getText method for the password...  I don't get it, how can it work without an 'if', doesn't work with 'if', and give me warning with &&....thanks...  package HR;  import javax.swing.JFrame; import javax.swing.JPanel; import javax.swing.JLabel; import javax.swing.JPasswordField; import javax.swing.JFormattedTextField; import javax.swing.JButton;  import java.awt.GridLayout; import java.awt.event.ActionListener; import java.awt.event.ActionEvent;  public class SignIn extends JFrame {      /**      *       */     private static final long serialVersionUID = 1L;      public SignIn()     {         this.setTitle("HR SYSTEM LOGIN SCREEN");         this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);         this.setBounds(100, 100, 308, 179);          JPanel contentPane = new JPanel(new GridLayout(3,3,1,15));         this.getContentPane().add(contentPane);          JLabel userName = new JLabel("User Name");         contentPane.add(userName);          JLabel spaces2 = new JLabel("");         contentPane.add(spaces2);          final JFormattedTextField userText = new JFormattedTextField();         contentPane.add(userText);          JLabel password = new JLabel("Password");         contentPane.add(password);          JLabel spaces3 = new JLabel("");         contentPane.add(spaces3);          final JPasswordField passwordText = new JPasswordField();         contentPane.add(passwordText);          JLabel spaces1 = new JLabel("");         contentPane.add(spaces1);          JButton signButton = new JButton("Sign In");         contentPane.add(signButton);          JLabel spaces4 = new JLabel("");         contentPane.add(spaces4);          signButton.addActionListener(new ActionListener()          {              @Override             public void actionPerformed(ActionEvent e)              {                  if (userText.getText()=="ABC")                 {                     dispose();                 }                 else userText.setText("ABC");             }         });       }  }

I've been using the == operator in my program to compare all my strings so far. However, I ran into a bug, changed one of them into .equals() instead, and it fixed the bug.  Is == bad? When should it and should it not be used? What's the difference?


Currently when flagging posts I can either choose one of the predefined options, or the "Other" option. However, only the option "It needs moderator attention" and suboption "Other" have a way for me to actually comment on the flag. It would be good if I could add a comment to any flag, so that unusual circumstances are more clearly stated.

I'm an elected diamond moderator on one site, and a user of several others. I think it would be extremely helpful for our flagging process if users had the option to enter freeform text explaining their flag on types of flags other than the "in need of moderator attention" flag.  An example of when this is relevant: Sometimes posts have had rude/abusive flags, but the rude/abusive part might be difficult to notice, or it might be a single word or sentence buried somewhere in the middle of the post. Users have to choose between "flag it as rude with no explanation" or "flag it as misc and explain what's going on". Often they'll pick the first because of course it seems like what they should do (e.g. they know the system has special handling attached to rude/abusive flags) but it means they can't explain what's going on to us, so we have to reach out directly in private to find out.  Sometimes it also helps to be able to explain why a comment is no longer needed, because past experience tells me the "no longer needed" flag on its own might be declined on a particular site -- so I pick the custom reason instead of "no longer needed" just so I can provide explanation.  I'd prefer users be able to understand they can pick the appropriate reason and be able to attach any explanation they deem necessary to further direct moderators to the issue. If not for all kinds of flags, then at least for spam or rude/abusive flags.


Prove that   $\sum_{r=0}^n{n\choose r}^2={2n\choose n }$  I don't know how to prove such probems. Any proof by combinatorics?

I have to prove that: $$ \binom n 0 ^2  + \binom n 1 ^2  + \dots + \binom n n ^2 = \binom { 2n} n $$  I don't want a complete solution, but only a hint.


Find$\ \limsup_{n\to \infty}(\frac{2^n}{n!}) $  The following 2 facts have already been proven.   $\ 2^n < n! $ for $n \ge 4$ (Proof by induction) $\ \frac{2^{n+1}}{(n+1)!} < \frac{2^n}{n!} $ for $\ n\ge 4 $   It would be sufficient to show that $\ \lim_{n\to \infty} \frac{2^n}{n!} = 0 $  However, what are some ways to show this?   I have found a proof using the definition of convergence.   (For all $\ \epsilon > 0 $, Find N such that if n >= N, $\ |\frac{2^n}{n!} - 0| < \epsilon $)  However, I was wondering if there was a simpler proof.  Thanks!

Why is     $$\lim_{n \to \infty} \frac{2^n}{n!}=0\text{ ?}$$   Can we generalize it to any exponent $x \in \Bbb R$? This is to say, is     $$\lim_{n \to \infty} \frac{x^n}{n!}=0\text{ ?}$$     This is being repurposed in an effort to cut down on duplicates, see here: Coping with  duplicate questions.  and here: .


$x'=x^2- \frac{2}{t^2}$  Hmm I have not idea how to do it... Maybe any smart substitution could work?

Solve differential equation:  $x'=x^2- \frac{2}{t^2}$  Maybe is it sth connected with homogeneous equation? I have no idea how to solve it.


I couldnT find an answer easily, so even if this question is a dupe, the answers donT come up using  these keywords.  I want to know the difference between the different way of declaring functions in a sample app.js   var foo = function() {   //.. }  function bar() {   //.. }  var baz= function() {   //.. }  function qux() {   //.. }  // other??   I m also not clear about the scope where I can use each function. Thanks!

I've recently started maintaining someone else's JavaScript code. I'm fixing bugs, adding features and also trying to tidy up the code and make it more consistent.  The previous developer used two ways of declaring functions and I can't work out if there is a reason behind it or not.  The two ways are:  var functionOne = function() {     // Some code };     function functionTwo() {     // Some code }   What are the reasons for using these two different methods and what are the pros and cons of each? Is there anything that can be done with one method that can't be done with the other?


Is there any way of treating $\frac{1}{0}$ without breaking maths? I tried just the variable $\lambda$, thinking that it would be easy to manipulate: $$\frac{2}{0} = 2\cdot\frac{1}{0} = 2\lambda$$ But I soon realised that you couldn't divide any numbers by it because $$\frac{2}{\lambda} = \frac{2}{0}^{-1}=\frac{0}{2}=0, \text{ implying that } 2=0\lambda, \text{ or 0.}$$  Is there any system/way of making this work without destroying maths and everything it stands for?

We add negative numbers and zero to natural sequence to make it closed under subtraction, the same thing happens with division (rational numbers) and root of -1 (complex numbers).  Why this trick isn't performed with division by zero?


I've written a rest service in Salesforce.  In some cases I wish to give clients a specific return code and error payload to give them call specific information regarding the error with a JSON response.  Here's the response I'm expecting (which I wrote):  {    "message": "intermittent error please retry later" }   Here's the response I'm seeing:  [ {   "errorCode" : "INTERNAL_SERVER_ERROR",   "message" : "Invalid status code for HTTP response: 550" } ]   Where 550 is my custom return code.   My custom return payload had been replaced with the array above.   Should I be using a different error code which is not in the 5xx range?  Can I add my payload to this array somehow? Should I return 200 and have clients look for any additional information in the return payload?     Many thanks in advance, Peter

I am trying to set the status code to 429 for Too many request using the code below:  if(Limits.getQueries() < Limits.getLimitQueries()){               upsert UpdateData;               }               else if((Limits.getQueries() >= Limits.getLimitQueries()))               {                   RestContext.response.statusCode = 429;                   UpdateError[] err = new UpdateError[]{                    new UpdateReturnError(UpdateData.Id, 'Too many Requests', 'Error updating MessageID ' + msg.MessageId)                 };                 RestContext.response.responseBody = Blob.valueOf(JSON.serialize(err));                 RestContext.response.addHeader('Content-Type', 'application/json');                 break;               }             }   I am getting the following error in the raw response:    Can someone help me out with this?


We have configured SQL 2012 Server Database Transaction Replication for our client's .NET Web application to distribute SQL transaction and reporting on different SQL servers.   We had implemented transaction replication on to SQL-Node1 is working as Master DB Server, We'd configured replication of Master DB on SQL-Node2 to pull out reports in to our web application which having lots of transactions and data uploading from excel sheet entries around 10 million entries each day.   After configured replication on Two SQL 2012 server, after few weeks we facing some performance issues and found some resource get locked during uploading files on to database that's why application unable to access those tables and data. Also found that server performing too much slow during day time when users access our web application.  Now we are looking to distribute loads on different 3 Nodes of SQL 2012 Servers. Where web application will access and transact data on SQL-Node1, Reporting queries get pull data from SQL-Node2 and SQL-Node3 will be get used to upload excel sheet data on to Database which will get replicated on all other SQL Nodes.  Current Setup, All Servers having Windows Server 2008 Standard and SQL 2012 Enterprise Edition.  Database size approx : 15 GB / Replication Used : Transaction / Distributor Role configured on SQL Node1 / Subscriber role configured on SQL Node 2.    We are looking for solution to resolve above issues which can distribute different loads (reporting, data uploading, transaction) and replicate data between all SQL Nodes.  Which feature will do perform well for above scenario among SQL 2012 HA, SQL Replication or SQL Mirroring ??  Quick response will be highly appreciated....

This is a  about  Related:      I have a question regarding capacity planning. Can the Server Fault community please help with the following:   What kind of server do I need to handle some number of users? How many users can a server with some specifications handle? Will some server configuration be fast enough for my use case? I'm building a social networking site: what kind of hardware do I need? How much bandwidth do I need for some project? How much bandwidth will some number of users use in some application?


In the following code the figure number is shown as 1.1. How can I change the figure number format to 1-1?  \documentclass{book} \usepackage{graphicx} \usepackage{caption}   \begin{document} \chapter{One} test \begin{figure}[ht!] \centering  \includegraphics[scale=0.5]{10.png} \caption{} \label{handle} \end{figure}  Figure \ref{handle}. \end{document}

Some document elements (e.g., figures in the book class) are numbered per chapter (figure 1.1, 1.2, 2.1, ...). How can I achieve continuous numbering (figure 1, 2, 3, ...)?  And vice versa: Some document elements (e.g., figures in the article class) are numbered continuously. How can I achieve per-section numbering?  \documentclass{book}% for "vice versa" variant, replace `book` with `article`  \begin{document}  \chapter{foo}% for "vice versa" variant, replace `\chapter` with `\section`  \begin{figure} \centering \rule{1cm}{1cm}% placeholder for graphic \caption{A figure} \end{figure}  \end{document}   Bonus question: Is it possible to adjust the numbering of the sectioning headings themselves? Can I, e.g., switch from per-chapter to continuous numbering of sections in the book class?


So I've downloaded a program by a developer that macOS doesn't recognize, and when I want to run it I get the usual "we don't know who wrote it, would you like to trash it in one click?" warning. This is easy to bypass. Instead of coming as one executable it's actually ~120 separate executables that the main one will call, or maybe they can call each other, and my computer will interrupt and quit the program every time it wants to call a new one. I would just grind through them if I thought that the program would call every one every run and I could clean them all up at once, but my guess is it's just going to call a handful at a time so I'll never know if I've gotten them all. I ran ls -lha on the directory and they nearly all have the same output: -rwxr-xr-x@   1 <user>  staff    92M Oct 29  2019 <name_of_exe>  a few are different, but there's no difference between the ones I've already approved and the ones I haven't. After signing them with the command find . -name "*" -exec codesign --force -s - {} \;, the error message changes and it says:  Unable to open "<one_of_the_binaries>" because Apple could not check for malicious software. This software needs to be updated. Contact the software developer for more information. Firefox downloaded this file <time> from <site>.  After I go to the Privacy & Security menu to approve it, the next time I run the program I the the same warning, but now with the option to run anyway. But then when the next new executable is called, it will do the same thing with that one. Is there some way I can quickely approve all of them at once? MacOS 11.2.2.

This is a followup on this post of mine:   I'm now running MacOS High Sierra 10.13.5 and this problem is still irritating.  I use my Mac as a Standard user. When I first set it up, all applications were downloaded/installed using the Admin user.  When using my Mac as the Standard user, every time I go to run an application I get the following message:  "Whatever.app" is an application downloaded from the Internet. Are you sure you want to open it?   With the options for Cancel and Open. Of course I choose Open and everything works fine.  Now, I am used to this notice appearing the first time I try to run an app from the internet. My problem is that it appears every time.  Note that I am not asked for any Administrator credentials, and these apps have already been installed to the /Applications directory as an Administrator.  I have tried with a different Standard user and still have the same issue. I have also already used Disk Utility to repair the drive permissions, just in case.  How can I make this notice appear only on the first run?  ==========================================================  More details:  If I install an application, while logged in as the Standard user, but authenticating as the Administrator, then it only warns me about the Application on the first run, and then never again, as long as I am still logged in as that Standard user.  But all the applications I installed while logged in as Administrator give me a pop up warning every time if I try to run them while logged in as a Standard user.   There is a "solution" to this problem, but it is so incredibly inelegant. For every application I downloaded and installed, while logged in as Administrator, simply installing the application is not enough. I must actually login as the Administrator and launch the application at least once to clear the warning for all other users. This seems incredible silly. Surely there must be a better way to accomplish this?


I believe my problem is something similar to  but I am not really sure. I am not even sure my title is on topic. Using mysql. I have the following ACL design for a website:  ### tools id name  ### tasks id tool_id references tools.id name  ### roles id tool_id references tools.id name  ### access id role_id references roles.id task_id references tasks.id has_access   Website has several tools, each tool can do several tasks. Each tool has several roles (ex: admin, mod, user) and each role is allowed to perform specific set of tasks based on access table.  Problem: how do I achieve that access.task_id belongs to the correct tool and not some random tool? For example, if we have role "editor" in tool "articles" which has tasks "delete", "edit" and "publish", how do we prevent someone inserting into access table a task id belonging to "execute_shell_script" which is from a totally different tool? So roles.tool_id=tasks.tool_id for each row.  I suspect that my design is flawed in some way so feel free to point me to a better solution.  And a more general question, when db constraints get really complicated is it generally better to do them only programatically?

I have the following design. Each user has it's own contacts, it's own hosts and assign those to a domain which belongs only to him.   I want to insure that the host you assign to the domain belongs to the user that domain is assigned to.  Is it something that I have to insure in my application logic?  If I set domains.user_id foreign key to reference host.user_id and user_id.id does it eliminate my issue?    By the way can anyone suggest me a better design for my schema?