
# slower version:

s = input()
for i in range(len(s)):
  if i%2 == 0:
    print(s[i], end = '')


# optimized version of the same code:

s = input()
ans = ''
for i in range(len(s)):
  if i % 2 == 0:
    ans += s[i]
print(ans)



# slower version:

import fractions

import sys

input = sys.stdin.readline



N,M=list(map(int,input().split()))

a = list(map(int, input().split()))





lcm = a[0]

for i in range(1, N):

    g= fractions.gcd(lcm, a[i])

    lcm = lcm * a[i] // g





g=a[0]

for i in range(N):

    g=fractions.gcd(g,a[i])



for i in range(N):

    if (a[i]//g)%2==0:

        lcm=0

        break    

    

    

ans=0

l=lcm//2

if l:

    ans=(M//l)-(M//(l+l))

print(ans)




# optimized version of the same code:

import sys

input = sys.stdin.readline



def I(): return int(eval(input()))

def MI(): return list(map(int, input().split()))

def LI(): return list(map(int, input().split()))



"""

2X = ak * (2p+1)

基本的には最小公倍数/2を基本とし，これの奇数倍か．



X  = (ak//2) * (2p+1)

と書ける．第二項が奇数なので，各akが2で割り切れれう回数が同じでなければならない

a=[2,4]だと無理

"""

def main():

    from math import gcd

    N,M=MI()

    A=LI()

    

    def count(X):

        cnt=0

        while X%2==0:

            cnt+=1

            X=X//2

        return cnt

    

    C=count(A[0])

    for i in range(1,N):

        if count(A[i])!=C:

            print((0))

            exit()

            

    lca=1

    for i in range(N):

        g=gcd(lca,A[i])

        lca=(lca*A[i])//g

        

    lca2=lca//2

    ans=M//lca2 - M//lca

    

    print(ans)

    

            

    



main()

import fractions
import sys

input = sys.stdin.readline
N, M = list(map(int, input().split()))
a = list(map(int, input().split()))
lcm = a[0]
for i in range(1, N):
    g = fractions.gcd(lcm, a[i])
    lcm = lcm * a[i] // g
g = a[0]
for i in range(N):
    g = fractions.gcd(g, a[i])
for i in range(N):
    if (a[i] // g) % 2 == 0:
        lcm = 0
        break
ans = 0
l = lcm // 2
if l:
    ans = (M // l) - (M // (l + l))
print(ans)

import sys

input = sys.stdin.readline


def I():
    return int(eval(input()))


def MI():
    return list(map(int, input().split()))


def LI():
    return list(map(int, input().split()))


"""
2X = ak * (2p+1)
基本的には最小公倍数/2を基本とし，これの奇数倍か．
X  = (ak//2) * (2p+1)
と書ける．第二項が奇数なので，各akが2で割り切れれう回数が同じでなければならない
a=[2,4]だと無理
"""


def main():
    from math import gcd

    N, M = MI()
    A = LI()

    def count(X):
        cnt = 0
        while X % 2 == 0:
            cnt += 1
            X = X // 2
        return cnt

    C = count(A[0])
    for i in range(1, N):
        if count(A[i]) != C:
            print((0))
            exit()
    lca = 1
    for i in range(N):
        g = gcd(lca, A[i])
        lca = (lca * A[i]) // g
    lca2 = lca // 2
    ans = M // lca2 - M // lca
    print(ans)


main()

-import fractions -N, M = list(map(int, input().split())) -a = list(map(int, input().split())) -lcm = a[0] -for i in range(1, N): -    g = fractions.gcd(lcm, a[i]) -    lcm = lcm * a[i] // g -g = a[0] -for i in range(N): -    g = fractions.gcd(g, a[i]) -for i in range(N): -    if (a[i] // g) % 2 == 0: -        lcm = 0 -        break -ans = 0 -l = lcm // 2 -if l: -    ans = (M // l) - (M // (l + l)) -print(ans) + + +def I(): +    return int(eval(input())) + + +def MI(): +    return list(map(int, input().split())) + + +def LI(): +    return list(map(int, input().split())) + + +""" +2X = ak * (2p+1) +基本的には最小公倍数/2を基本とし，これの奇数倍か． +X  = (ak//2) * (2p+1) +と書ける．第二項が奇数なので，各akが2で割り切れれう回数が同じでなければならない +a=[2,4]だと無理 +""" + + +def main(): +    from math import gcd + +    N, M = MI() +    A = LI() + +    def count(X): +        cnt = 0 +        while X % 2 == 0: +            cnt += 1 +            X = X // 2 +        return cnt + +    C = count(A[0]) +    for i in range(1, N): +        if count(A[i]) != C: +            print((0)) +            exit() +    lca = 1 +    for i in range(N): +        g = gcd(lca, A[i]) +        lca = (lca * A[i]) // g +    lca2 = lca // 2 +    ans = M // lca2 - M // lca +    print(ans) + + +main()