Write me a function in Python that accepts an integer argument and finds the difference between the sum of squares for all numbers in the interval 0 through the integer and the square of the sum of all integers in the same interval
system
mujhe paythan main ek fnction likhen jo ek purnank tark ko sweekaar karata he or ek hi antaraal main sabhi purnank ke yoga ke madhyam se antaraal 0 main sabhi sankhyaon ke liye virgon ke yoga ke bich antar paata he
user
yahaan ek paythan fnction he jo ek purnank tark ko sweekaar karata he, antaraal 0 main sabhi virgon ke yoga kii gananaa karata he, input main, ek hi antaraal main sabhi purnank ke yoga kii gananaa karata he, or phir virgon or virgon ke yoga ke bich antar paata hintaraal yoga.

def square_sums_difference (q):
    N = q
    SUM_OF_SQUARES = SUM (I ** 2 I ke liye I main range (1, n + 1))
    Internal_sum = sum (i for i in range (1, n + 1))
    vaapasi STR (SUM_OF_SQUARES - INTERVAL_SUM ** 2)
assistant
<|system|>
</s>
<|user|>
mujhe paythan main ek fnction likhen jo ek purnank tark ko sweekaar karata he or ek hi antaraal main sabhi purnank ke yoga ke madhyam se antaraal 0 main sabhi sankhyaon ke liye virgon ke yoga ke bich antar paata he</s>
<|assistant|>
yahaan ek paythan fnction he jo ek purnank tark ko sweekaar karata he, antaraal 0 main sabhi virgon ke yoga kii gananaa karata he, input main, ek hi antaraal main sabhi purnank ke yoga kii gananaa karata he, or phir virgon or virgon ke yoga ke bich antar paata hintaraal yoga.

def square_sums_difference (q):
    N = q
    SUM_OF_SQUARES = SUM (I ** 2 I ke liye I main range (1, n + 1))
    Internal_sum = sum (i for i in range (1, n + 1))
    vaapasi STR (SUM_OF_SQUARES - INTERVAL_SUM ** 2)</s>
