from math import sqrt
def prime_numbers_in_range(a,b):
    def is_prime(x):
        if x > 1:
            for i in range(2, int(sqrt(x)+1)):
                if x % i:
                    return False
            return True
        return False
    return [i for i in range(a,b) if is_prime(i)]

I came up with the above python function to output a list of the prime numbers between a and b inclusive, but it does not work as expected. Take a look, tell me what's wrong and explain how to fix it.
system
ganit aayaat sqrt se
def prime_numbers_in_range (a, b):
    def is_prime (x):
        yadi x> 1:
            I main range (2, int (sqrt (x) +1)) ke liye:
                agar x % i:
                    vivaran jhootha he
            sahi vaapasi
        vivaran jhootha he
    lauten [i ke liye i in range (a, b) agar is_prime (i)]

main uparokt paythan fnction ke saath aayaa tha taaki e or bi samaveshi ke bich pramukh numberon kii ek suchi kaa utpaadan kiya ja sake, lekin yah ummid ke mutabik kaam nahin karata he.ek nazar daalen, mujhe bataaen ki kya galat he or samajhaayen ki ise kaise thik kiya jaae.
user
samasya nested 'is_prime' fnction main ek shabdaarth truti se he.line ke saath "agar x % i:", aap yah dekhne ke liye jaanch kar rahe hai ki kya x i dwaara vibhajya he.fnction kii vartmaan sthiti main, yadi yah check kisi bhi bindu par galat ke rup main moolyankan karata he (yani X I dwaara vibhajya he, jo yah nirdhaarit karne ke liye paryaapt he ki X prime nahin he), niyantran loop kii shuruyaat main waapas paarit ho jaataa he.is tarah se fnction keval sahi ho jaataa he yadi x i ke prayek mulya se vibhajya ho, bajaay iske anya tareeke se - fnction ko keval sach hona chahie yadi X i ke kisi bhi mulya se vibhajya nahin he.yah aasaani se vibhaajan pareekshan ko "yadi x % i == 0:" yaa "yadi x % 0:" nahin he, to ise aasaani se tay kiya ja saktaa he.iske atirikt, yah sunishchit karne ke liye ki lautaa di gai suchi vastav main di gai seemaa ke donon siron ko samaveshi he, aapako (A, B) ke bajaay (A, B+1) ke liye "Prime_numbers_in_range" fnction ke ritern statement main range maapdandon ko samyojit karnaa chahie.

yah sanshodhit code he jo sujhaaye gaye samaadhaanon ko lagu karata he:

ganit aayaat sqrt se
def prime_numbers_in_range (a, b):
    def is_prime (x):
        yadi x> 1:
            I main range (2, int (sqrt (x) +1)) ke liye:
                yadi x % i == 0:
                    vivaran jhootha he
            sahi vaapasi
        vivaran jhootha he
    range main [I ke liye I (A, B+1) yadi is_prime (i)]

is samasya ke ek saral samaadhaan ke liye, aap keval "Prime_numbers_in_range" fnction main pareekshan or parinaam suchi ko shaamil karke nested fnction kii aavashyaktaa ko samaapt kar sakate hai.
assistant
<|system|>
</s>
<|user|>
ganit aayaat sqrt se
def prime_numbers_in_range (a, b):
    def is_prime (x):
        yadi x> 1:
            I main range (2, int (sqrt (x) +1)) ke liye:
                agar x % i:
                    vivaran jhootha he
            sahi vaapasi
        vivaran jhootha he
    lauten [i ke liye i in range (a, b) agar is_prime (i)]

main uparokt paythan fnction ke saath aayaa tha taaki e or bi samaveshi ke bich pramukh numberon kii ek suchi kaa utpaadan kiya ja sake, lekin yah ummid ke mutabik kaam nahin karata he.ek nazar daalen, mujhe bataaen ki kya galat he or samajhaayen ki ise kaise thik kiya jaae.</s>
<|assistant|>
samasya nested 'is_prime' fnction main ek shabdaarth truti se he.line ke saath "agar x % i:", aap yah dekhne ke liye jaanch kar rahe hai ki kya x i dwaara vibhajya he.fnction kii vartmaan sthiti main, yadi yah check kisi bhi bindu par galat ke rup main moolyankan karata he (yani X I dwaara vibhajya he, jo yah nirdhaarit karne ke liye paryaapt he ki X prime nahin he), niyantran loop kii shuruyaat main waapas paarit ho jaataa he.is tarah se fnction keval sahi ho jaataa he yadi x i ke prayek mulya se vibhajya ho, bajaay iske anya tareeke se - fnction ko keval sach hona chahie yadi X i ke kisi bhi mulya se vibhajya nahin he.yah aasaani se vibhaajan pareekshan ko "yadi x % i == 0:" yaa "yadi x % 0:" nahin he, to ise aasaani se tay kiya ja saktaa he.iske atirikt, yah sunishchit karne ke liye ki lautaa di gai suchi vastav main di gai seemaa ke donon siron ko samaveshi he, aapako (A, B) ke bajaay (A, B+1) ke liye "Prime_numbers_in_range" fnction ke ritern statement main range maapdandon ko samyojit karnaa chahie.

yah sanshodhit code he jo sujhaaye gaye samaadhaanon ko lagu karata he:

ganit aayaat sqrt se
def prime_numbers_in_range (a, b):
    def is_prime (x):
        yadi x> 1:
            I main range (2, int (sqrt (x) +1)) ke liye:
                yadi x % i == 0:
                    vivaran jhootha he
            sahi vaapasi
        vivaran jhootha he
    range main [I ke liye I (A, B+1) yadi is_prime (i)]

is samasya ke ek saral samaadhaan ke liye, aap keval "Prime_numbers_in_range" fnction main pareekshan or parinaam suchi ko shaamil karke nested fnction kii aavashyaktaa ko samaapt kar sakate hai.</s>
