Help me figure out what's wrong with the Python code below. It's supposed to count the number of characters that overlap between the beginning of one string and the end of another. overlap('CTAAGT', 'TTCA') should return 1, but instead it returns 2.

def overlap(string1, string2):
    if len(string2) < len(string1):
        temp = string1
        string1 = string2
        string2 = temp

    print("string1: " + string1)
    print("string2: " + string2)
    
    for i in range(0, len(string1) + 1):
        print(f'{string1[i:]} == {string2[:(len(string1) - i)]}')
        if (string1[i:] == string2[:(len(string1) - i)]):
            break

    for j in range(0, len(string1) + 1):
        print(f'{string2[j:]} == {string1[:(len(string2) - j)]}')
        if (string2[j:] == string1[:(len(string2) - j)]):
            break

    return max(len(string1) - i, len(string2) - j)
system
mujhe yah pataa lagane main madad karen ki neeche die gaye paythan code main kya galat he.yah ek string kii shuruyaat or duusare ke ant ke bich overlap karne vaale varnon kii sankhya ko ginaney vaala he.overlap ('ctaagt', 'ttca') ko 1 lautnaa chahie, lekin iske bajaay yah 2 lautataa he.

DEF overlap (string 1, string 2):
    yadi len (string2) <len (string1):
        asthaayee = string1
        string1 = string2
        string2 = asthaayee

    print ("string1:" + string1)
    print ("string2:" + string2)
    
    ke liye main range main (0, len (string1) + 1):
        print (f '{string1 [i:]} == {string2 [:( len (string1) - i)]})
        if (string1 [i:] == string2 [:( len (string1) - i)]):
            todna

    J ke liye range (0, len (string 1) + 1):
        print (f '{string2 [j:]} == {string1 [:( len (string2) - j)]}')
        if (string2 [j:] == string1 [:( len (string2) - j)]):
            todna

    ritern maiks (len (string 1) - I, len (string 2) - je)
user
loop ke liye doosraa bahut jaldi samaapt ho jaataa he, isse pehle ki vah lambey samay tak string main har sthiti kii jaanch kare, yah dekhne ke liye ki kya koi overlap vahaan shuru hota he.yadi aap loop kii seemaa main len (string 1) ko len (string 2) ke saath badalte hai, to yah tab tak punrariti jari rakhega jab tak ki yah vaastavik overlap maan nahin paata he.yahan adhyatan code he:

DEF overlap (string 1, string 2):
    yadi len (string2) <len (string1):
        asthaayee = string1
        string1 = string2
        string2 = asthaayee

    print ("string1:" + string1)
    print ("string2:" + string2)
    
    ke liye main range main (0, len (string1) + 1):
        print (f '{string1 [i:]} == {string2 [:( len (string1) - i)]})
        if (string1 [i:] == string2 [:( len (string1) - i)]):
            todna

    J ke liye range (0, len (string 2) + 1): # parivartan: len (string 1) se len (string 2)
        print (f '{string2 [j:]} == {string1 [:( len (string2) - j)]}')
        if (string2 [j:] == string1 [:( len (string2) - j)]):
            todna

    ritern maiks (len (string 1) - I, len (string 2) - je)
assistant
<|system|>
</s>
<|user|>
mujhe yah pataa lagane main madad karen ki neeche die gaye paythan code main kya galat he.yah ek string kii shuruyaat or duusare ke ant ke bich overlap karne vaale varnon kii sankhya ko ginaney vaala he.overlap ('ctaagt', 'ttca') ko 1 lautnaa chahie, lekin iske bajaay yah 2 lautataa he.

DEF overlap (string 1, string 2):
    yadi len (string2) <len (string1):
        asthaayee = string1
        string1 = string2
        string2 = asthaayee

    print ("string1:" + string1)
    print ("string2:" + string2)
    
    ke liye main range main (0, len (string1) + 1):
        print (f '{string1 [i:]} == {string2 [:( len (string1) - i)]})
        if (string1 [i:] == string2 [:( len (string1) - i)]):
            todna

    J ke liye range (0, len (string 1) + 1):
        print (f '{string2 [j:]} == {string1 [:( len (string2) - j)]}')
        if (string2 [j:] == string1 [:( len (string2) - j)]):
            todna

    ritern maiks (len (string 1) - I, len (string 2) - je)</s>
<|assistant|>
loop ke liye doosraa bahut jaldi samaapt ho jaataa he, isse pehle ki vah lambey samay tak string main har sthiti kii jaanch kare, yah dekhne ke liye ki kya koi overlap vahaan shuru hota he.yadi aap loop kii seemaa main len (string 1) ko len (string 2) ke saath badalte hai, to yah tab tak punrariti jari rakhega jab tak ki yah vaastavik overlap maan nahin paata he.yahan adhyatan code he:

DEF overlap (string 1, string 2):
    yadi len (string2) <len (string1):
        asthaayee = string1
        string1 = string2
        string2 = asthaayee

    print ("string1:" + string1)
    print ("string2:" + string2)
    
    ke liye main range main (0, len (string1) + 1):
        print (f '{string1 [i:]} == {string2 [:( len (string1) - i)]})
        if (string1 [i:] == string2 [:( len (string1) - i)]):
            todna

    J ke liye range (0, len (string 2) + 1): # parivartan: len (string 1) se len (string 2)
        print (f '{string2 [j:]} == {string1 [:( len (string2) - j)]}')
        if (string2 [j:] == string1 [:( len (string2) - j)]):
            todna

    ritern maiks (len (string 1) - I, len (string 2) - je)</s>
