Trent, South Dakota  Trent is a town in Moody County, South Dakota, United States. The population was 232 at the 2010 census. Trent was laid out in 1874. Trent is located at (43.906818, -96.654698), along the Big Sioux River. According to the United States Census Bureau, the town has a total area of , all of it land. Trent has been assigned the ZIP code 57065 and the FIPS place code 63940. As of the census of 2010, there were 232 people, 102 households, and 61 families residing in the town. The population density was . There were 113 housing units at an average density of . The racial makeup of the town was 91.4% White, 0.9% African American, 3.4% Native American, 0.9% Asian, and 3.4% from two or more races. Hispanic or Latino of any race were 0.4% of the population. There were 102 households of which 19.6% had children under the age of 18 living with them, 46.1% were married couples living together, 9.8% had a female householder with no husband present, 3.9% had a male householder with no wife present, and 40.2% were non-families. 31.4% of all households were made up of individuals and 6.8% had someone living alone who was 65 years of age or older. The average household size was 2.13 and the average family size was 2.59. The median age in the town was 48.3 years. 15.1% of residents were under the age of 18; 7.7% were between the ages of 18 and 24; 23.3% were from 25 to 44; 41% were from 45 to 64; and 12.9% were 65 years of age or older. The gender makeup of the town was 49.1% male and 50.9% female. As of the census of 2000, there were 254 people, 106 households, and 64 families residing in the town. The population density was 251.9 people per square mile (97.1/km²). There were 111 housing units at an average density of 110.1 per square mile (42.4/km²). The racial makeup of the town was 98.03% White, 0.75% African American, 0.39% Native American, and 1.57% from two or more races. Hispanic or Latino of any race were 0.39% of the population.