Sheffield, Ohio  Sheffield is a village in Lorain County, Ohio, United States, along the Black River. The population was 3,982 at the 2010 census. Sheffield is located at (41.448009, -82.083397). According to the United States Census Bureau, the village has a total area of , of which is land and is water. As of the census of 2010, there were 3,982 people, 1,581 households, and 1,160 families living in the village. The population density was . There were 1,666 housing units at an average density of . The racial makeup of the village was 89.3% White, 4.0% African American, 0.3% Native American, 2.7% Asian, 1.4% from other races, and 2.2% from two or more races. Hispanic or Latino of any race were 6.1% of the population. There were 1,581 households of which 26.9% had children under the age of 18 living with them, 63.3% were married couples living together, 6.9% had a female householder with no husband present, 3.2% had a male householder with no wife present, and 26.6% were non-families. 21.9% of all households were made up of individuals and 10.7% had someone living alone who was 65 years of age or older. The average household size was 2.51 and the average family size was 2.94. The median age in the village was 45.2 years. 20.2% of residents were under the age of 18; 6.2% were between the ages of 18 and 24; 23.2% were from 25 to 44; 34.2% were from 45 to 64; and 16.2% were 65 years of age or older. The gender makeup of the village was 49.3% male and 50.7% female. As of the census of 2000, there were 2,949 people, 1,089 households, and 866 families living in the village. The population density was 272.6 people per square mile (105.2/km²). There were 1,147 housing units at an average density of 106.0 per square mile (40.9/km²). The racial makeup of the village was 90.88% White, 4.27% African American, 0.10% Native American, 0.81% Asian, 0.10% Pacific Islander, 2.61% from other races, and 1.22% from two or more races.