Hi @ptrblck, Thanks for that advice. It kind of seems to work  slightly better. But the distribution is as follows:
0 [5, 6, 9, 3, 6, 7, 5, 9, 6, 8]
1 [7, 8, 4, 7, 5, 6, 7, 6, 9, 5]
2 [6, 9, 6, 11, 4, 3, 8, 4, 6, 7]
3 [7, 10, 14, 3, 9, 6, 7, 6, 2, 0]
4 [9, 6, 7, 4, 5, 10, 0, 7, 8, 8]
5 [9, 8, 5, 9, 6, 4, 6, 7, 6, 4]