Hey @Elias_Ellison thanks for the calrification.



 Elias_Ellison:

Hmm, what do you mean exactly ? Not sure I follow.


From the discussion above I understood that when .forward is invoked it will also do the job of inferring which overloaded functions to call based on the types present… but rereading it I realise I had my understanding a bit confused. I think it is clear now.