def __init__(self, in_channels, out_channels, kernel_size, stride=1,
                 padding=0, dilation=1, groups=1,
                 bias=True, padding_mode='zeros'):
        kernel_size = _pair(kernel_size)
        stride = _pair(stride)
        padding = _pair(padding)
        dilation = _pair(dilation)
        super(Conv2d, self).__init__(
            in_channels, out_channels, kernel_size, stride, padding, dilation,
            False, _pair(0), groups, bias, padding_mode)

    def conv2d_forward(self, input, weight):
        if self.padding_mode == 'circular':
            expanded_padding = ((self.padding[1] + 1) // 2, self.padding[1] // 2,
                                (self.padding[0] + 1) // 2, self.padding[0] // 2)
            return F.conv2d(F.pad(input, expanded_padding, mode='circular'),
                            weight, self.bias, self.stride,
                            _pair(0), self.dilation, self.groups)
        return F.conv2d(input, weight, self.bias, self.stride,
                        self.padding, self.dilation, self.groups)

    def forward(self, input):
        return self.conv2d_forward(input, self.weight)

this is the official Conv2d function.
If we change the sign of “self.bias” in 4th to last line i.e
from
return F.conv2d(input, weight, self.bias, self.stride,
                        self.padding, self.dilation, self.groups)

to
return F.conv2d(input, weight, (-1*self.bias), self.stride,
                        self.padding, self.dilation, self.groups)

will this affect the backward function?