Hi
Thanks for your answer.
But there is one more question.
As you said, if I use c-function-A, then I have to calculate the gradient of c-function-A with the analytic form of c-function-A?
Is there any way to use the numerical form of c-function-A
Like for example, can I make [ c-function-A(x-delta x) / x-delta x ] as a backward part?
If I can, is it too slower than the analytic way?
Best regards,
Choi