title: Why "requests.get()" opens "url.py" in Python 3.6.4?
body: <p>Beginner having trouble with "requests.get()" in python 3.6.4</p>
  
  <p>Current setup: Visual Studio Code, Anaconda(Conda), conda env, Bash, and Git.</p>
  
  <p>Running the following in a file 'crawl.py' in debug mode:</p>
  
  <pre><code>import requests
  
  r = requests.get('https://api.github.com/events')
  text = r.text
  print(text)
  </code></pre>
  
  <p>'url.py' opens automatically, telling me there is an error:</p>
  
  <p><a href="https://i.stack.imgur.com/STwq1.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/STwq1.png" alt="enter image description here"></a></p>
  
  <p>First failed attempts(I have to use --trusted-host because SSL_certificates are messed up):</p>
  
  <p>$ pip install --trusted-host pypi.python.org -U requests</p>
  
  <p>$ pip install --trusted-host pypi.python.org -U urllib3</p>
  
  <hr>
  
  <p>I could use help to stop this error from happening and for it to simply</p>
  
  <p>continue to print the the debug console.</p>
  
  <p>I am thinking that the source of the error has to do with something like pylint</p>
  
  <p>or maybe my version of Python. Because it also fails with "parse.py" when using "urlparse".</p>
  
  <p>Feel free to recommend any free courses that might really be helpful to me as well.</p>