title: how to use awk command to cut field?
body: <p>there is a file ,which you can get by command <code>ps aux</code> in linux.  </p>
  
  <pre><code>USER       PID %CPU %MEM    VSZ   RSS TTY      STAT START   TIME COMMAND
  root         1  0.0  0.0   2280   732 ?        Ss   08:20   0:00 init [2]  
  root       327  0.0  0.1   2916  1456 ?        Ss   08:20   0:00 udevd --daemon
  root      1681  0.0  0.0   2376   800 ?        Ss   08:20   0:00 /sbin/rpcbind -w
  root      2071  0.0  0.1  27920  1708 ?        Sl   08:20   0:00 /usr/sbin/rsyslogd -c5
  </code></pre>
  
  <p>i want to get the content of last field,such as:</p>
  
  <pre><code>COMMAND
  init [2]
  udevd --daemon
  /sbin/rpcbind -w
  /usr/sbin/rsyslogd -c5
  </code></pre>
  
  <p>when i use , $ awk '{print $11}'  test,i get:</p>
  
  <pre><code>COMMAND
  init
  udevd
  /sbin/rpcbind
  /usr/sbin/rsyslogd
  </code></pre>
  
  <p>when i use ，$ awk '{print $12}' test，i get :</p>
  
  <pre><code>[2]
  --daemon
  -w
  -c5
  </code></pre>
  
  <p>how can i do?</p>