title: How can you find and replace character in a text file in Windows command-line line by line but from a specific character appear count?
body: <p>I have a text file with a semicolon separator (CSV), it has 65 columns but the last is a "comments" column that can have semicolons in his body.<br>
  I would like to know how to write a windows batch file that count the semicolons in every line and if it finds > 64 semicolons,<br>
  deletes all the semicolons that follow after 64 (or change with a comma).
  (I don´t have access to the source that builds the texts files)</p>
  
  <p>Example actual:</p>
  
  <pre><code>marshal;Stevens;Son;11223344;Dual;this person tries food; water; fruit
  </code></pre>
  
  <p>Expected output:</p>
  
  <pre><code>marshal;Stevens;Son;11223344;Dual;this person tries food, water, fruit
  </code></pre>