title: Extract xlink:href attribute from XML
body: <p>I'm trying to parse an XML but I've got problems when trying to extract a link from the response.</p>
  
  <p>My XML looks like:</p>
  
  <pre><code>&lt;properties xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xlink="http://www.w3.org/1999/xlink" lastUpdate="2016-11-23"&gt;
      &lt;property myId="3" lastUpdate="2016-11-20T01:25:17+01:00" xlink:href="http://example.com/webservice/rest/1/properties/3"/&gt;
      &lt;property myId="10" lastUpdate="2016-11-16T03:52:54+01:00" xlink:href="http://example.com/webservice/rest/1/properties/10"/&gt;
      ...
  </code></pre>
  
  <p>And my function:</p>
  
  <pre><code>    r = requests.get(url, auth=(self.usr, self.psw))
      xml = r.content
      root = ET.fromstring(xml)
      for prop in root:
          m_id= prop.attrib['myId']
          my_url = prop.attrib['xlink:href']
  </code></pre>
  
  <p>I can extract the <code>id</code> attribute, but <strong>I get an error</strong> when tries to get the URL</p>