title: Print rest of the fields in awk
body: <p>Suppose we have this data file.</p>
  
  <pre><code>john 32 maketing executive
  jack 41 chief technical officer
  jim  27 developer
  dela 33 assistant risk management officer
  </code></pre>
  
  <p>I want to print using <code>awk</code></p>
  
  <pre><code>john maketing executive
  jack chief technical officer
  jim  developer
  dela assistant risk management officer
  </code></pre>
  
  <p>I know it can be done using <code>for</code>.</p>
  
  <pre><code>awk '{printf $1;  for(i=3;i&lt;=NF;i++){printf " %s", $i} printf "\n"}' &lt; file
  </code></pre>
  
  <p>Problem is its long and looks complex.</p>
  
  <p>Is there any other short way to print <em>rest of the fields</em>.</p>