title: Send HTML file contents via python email script
body: <p>Looking for a way to send the contents of a HTML file that is generated once a day using this script below. Running into road blocks getting it to work. I can sent HTML and see it, just not sure how to print out the contents of the file and send it.</p>
  
  <p>File Format is export_MM-DD-YY.html</p>
  
  <p>Id rather have it display the contents of the HTML in the email not the HTML file. </p>
  
  <pre><code>#!/usr/bin/env python3
  
  import smtplib
  import config
  from email.mime.multipart import MIMEMultipart
  from email.mime.text import MIMEText
  
  filename = 'name_of_file'
  
      # Read a file and encode it into base64 format
      fo = open(filename, "rb")
      filecontent = fo.read()
      encodedcontent = base64.b64encode(filecontent)  # base64
      filename = os.path.basename(filename)
  
  # me == my email address
  # you == recipient's email address
  me = "From@example.com"
  you = "TO@example.com"
  subject = 'Test Subject v5'
  
  # Create message container - the correct MIME type is multipart/alternative.
  msg = MIMEMultipart('alternative')
  msg['Subject'] = subject
  msg['From'] = me
  msg['To'] = you
  
  # Create the body of the message (a plain-text and an HTML version).
  text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttps://www.python.org"
  html = """\
  
    **INSERT HTML FILE CONTENTS HERE...**
  
  """
  
  # Record the MIME types of both parts - text/plain and text/html.
  part1 = MIMEText(text, 'plain')
  part2 = MIMEText(html, 'html')
  
  # Attach parts into message container.
  # According to RFC 2046, the last part of a multipart message, in this case
  # the HTML message, is best and preferred.
  msg.attach(part1)
  msg.attach(part2)
  
  # Send the message via local SMTP server.
  server = smtplib.SMTP('smtp.gmail.com:587')
  server.starttls()
  server.login(config.EMAIL_ADDRESS, config.PASSWORD)
  
  server.sendmail(me,you,msg.as_string())
  server.quit()
  </code></pre>
  
  <p>So I think I got it working but im sure theres more code here than is needed (If anyone sees anything I can clean up?) </p>
  
  <pre><code>#!/usr/bin/env python3
  
  import smtplib
  import os
  import config
  from email.mime.multipart import MIMEMultipart
  from email.mime.text import MIMEText
  
  raport_file = open('export.html','rb')
  alert_msg = MIMEText(raport_file.read(),"html", "utf-8")
  
  # me == my email address
  # you == recipient's email address
  me = "From@example.com"
  you = "TO@example.com"
  subject = 'Test Subject v5'
  
  # Create message container - the correct MIME type is multipart/alternative.
  msg = MIMEMultipart('alternative')
  msg['Subject'] = subject
  msg['From'] = me
  msg['To'] = you
  
  # Create the body of the message (a plain-text and an HTML version).
  text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttps://www.python.org"
  html = """\
  
  """
  
  # Record the MIME types of both parts - text/plain and text/html.
  part1 = MIMEText(text, 'plain')
  part2 = MIMEText(html, 'html')
  
  # Attach parts into message container.
  # According to RFC 2046, the last part of a multipart message, in this case
  # the HTML message, is best and preferred.
  msg.attach(part1)
  msg.attach(part2)
  
  # Send the message via local SMTP server.
  server = smtplib.SMTP('smtp.gmail.com:587')
  server.starttls()
  server.login(config.EMAIL_ADDRESS, config.PASSWORD)
  
  server.sendmail(me,you,alert_msg.as_string())
  server.quit()
  </code></pre>