title: How to auto generate slug from my Album model in django 2.0.4
body: <p>I have an Album field with a list of Songs </p>
  
  <pre><code> class Album(models.Model):
      artist = models.CharField(max_length=250)
      album_title = models.CharField(max_length=250)
      genre = models.CharField(max_length=100)
      album_logo = models.CharField(max_length=1000,blank=True)
      slug = models.SlugField(unique=True)
  
      def __str__(self):
          return self.album_title               
  
  class Song(models.Model):
      album = models.ForeignKey(Album, on_delete=models.CASCADE)
      artist = models.CharField(max_length=250, blank=True)
      file_type = models.CharField(max_length=10)
      song_title = models.CharField(max_length=100)    
  
      def __str__(self):
          return self.artist
  </code></pre>
  
  <p>I would like to know how to generate slugs from the album title. I am following a tutorial which is using django 1.8 which uses regular expressions to implement this task. But from looking through the documentation they have introduced a  more simpler approach ('').
  So can you help explain how I can implement it for a beginner to understand not only in this context but if possible across board.
  Thanks in advance.</p>