title: grep word from column and remove row
body: <p>I want to <code>grep</code> a word from particular column from a file. Then remove those rows put all remaining rows into another file.
  could anyone please help me on shell command to get following output?</p>
  
  <p>I have a file with this format:</p>
  
  <pre><code>1234     8976     897561234   1234  678901234
  5678     5678     123456789   4567  123456790
  1234     1234     087664566   4567  678990000
  1223     6586     212134344   8906  123456789
  </code></pre>
  
  <p>I want to grep word "1234" in the second column alone and removed those rows alone and put remaining rows in another file. So output should be in this format:</p>
  
  <pre><code>1234     8976     897561234   1234  678901234
  5678     5678     123456789   4567  123456790
  1223     6586     212134344   8906  123456789
  </code></pre>
  
  <p>The out should be with 3 rows except 3 row out of 4 rows.</p>
  
  <pre><code>while read value ;do
    grep -v  ${value:0:10} /tmp/lakshmi.txt &gt; /tmp/output.txt
    cp /tmp/output.txt /tmp/no_post1.txt
  done &lt; /tmp/priya.txt
  </code></pre>
  
  <p>Could you please help me to modify this script?</p>