title: BeautifulSoup - which URL
body: <p>I started a little project. I am trying to scrape the URL <a href="http://pr0gramm.com/" rel="nofollow">http://pr0gramm.com/</a>
  and save the tags under a picture in a variable, but I have problems to do so.</p>
  
  <p>I am searching for this in the code</p>
  
  <pre><code>&lt;a class="tag-link" href="/top/Flaschenkind"&gt;Flaschenkind&lt;/a&gt;
  </code></pre>
  
  <p>And I actually just need the part "Flaschenkind" to be saved, but also the following tags in that line.</p>
  
  <p>This is my code so far</p>
  
  <pre><code>import requests
  from bs4 import BeautifulSoup
  
  url = "http://pr0gramm.com/"
  r = requests.get(url)
  
  soup = BeautifulSoup(r.content, "lxml")
  
  links = soup.find_all("div", {"class" : "item-tags"})
  
  print(links)
  </code></pre>
  
  <p>I sadly just get this output</p>
  
  <pre><code>[]
  </code></pre>
  
  <p>I already tried to change the URL to <a href="http://pr0gramm.com/top/" rel="nofollow">http://pr0gramm.com/top/</a>
  but I get the same output. I wonder if it happens because the site might be made with JavaScript and it can't scrape the data correctly then?</p>