title: Finding the square of a number in a sequential array of odds
body: <p>I have a sequential odd array starting at 3. So x = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13...}.
  I am wondering if there is a quick way to find at what index the square of a number n is at. So if n was 5, I am looking for where 25 is in the array. Right now I have ((n) * (n - 1)) which I add to the current i index. Is there anything faster?</p>