title: tweepy error python 2.7
body: <p>I keep getting this error:</p>
  
  <pre><code>tweepy.error.TweepError: [{u'message': u'Status is a duplicate.', u'code': 187
  </code></pre>
  
  <p>I have no clue why I am getting this error I have tried everything!</p>
  
  <p>My main code is:</p>
  
  <pre><code>import socket
  from urllib2 import urlopen, URLError, HTTPError
  
  socket.setdefaulttimeout( 23 )  # timeout in seconds
  
  url = 'http://google.co.uk'
  try :
      response = urlopen( url )
  except HTTPError, e:
      tweet_text = "Raspberry Pi Server is DOWN!"
      textfile = open('/root/Documents/server_check.txt','w')
      textfile.write("down")
      textfile.close()
  except URLError, e:
      tweet_text = "Raspberry Pi Server is DOWN!"
      textfile = open('/root/Documents/server_check.txt','w')
      textfile.write("down")
      textfile.close()
  else :
      textfile = open('/root/Documents/server_check.txt','r')
      if 'down' in open('/root/Documents/server_check.txt').read():
          tweet_text = "Raspberry Pi Server is UP!"
          textfile = open('/root/Documents/server_check.txt','w')
          textfile.write("up")
          textfile.close()
      elif 'up' in open('/root/Documents/server_check.txt').read():
          tweet_text = ""
  if len(tweet_text) &lt;= 140:
      if tweet_text == "Raspberry Pi Server is DOWN!" or tweet_text == "Raspberry Pi Server is UP!":
          api.update_status(status=tweet_text)
      else:
          pass
  else:
      print "Your message is too long!"
  </code></pre>
  
  <p>I have removed the API's for security reasons! I have also removed the link to my server.
  Any help will be appreciated!</p>
  
  <p>Thanks</p>