title: How to launch babun in a specified directory via the command line
body: <p>now I'm currently using Visual Studio Code and I wanted to make the terminal use babun instead of the default <code>cmd.exe</code><br>
  In fact, I have already managed to do that in theory - the problem is that, unlike with <code>cmd.exe</code>, the directory that I'm in upon starting the terminal is no longer the currently open project, it's just simply <code>/home/myusername</code> (i.e. a path in babun's directory tree).<br>
  This kinda sucks, since I don't really want to navigate to my directory every time.<br>
  Next, I also found out how to tell babun (in my case, <code>zsh.exe</code>) to use a default directory such as <code>C:/</code> by adding <code>cd /cygdrive/c</code> to the end of .zshrc - Unfortunately, that's not what I want either, since I don't want babun to <strong>always</strong> use the same directory.  </p>
  
  <p>Now I figured that, seeing as this would be the most comfortable option with VSC*, there might be some console argument that tells <code>zsh.exe</code> to use a specific directory. Sadly, I couldn't find anything, hence this question.
  Weirdly enough</p>
  
  <p>Anyone know how to help me out? Appreciate the help :)</p>
  
  <p>*VSC allows you to specify the path to your shell, as well as an array of arguments that will be passed.</p>