title: Launch VLC through Python
body: <p>To start vlc using python, I've done that :</p>
  
  <pre><code>import subprocess
  
  p = subprocess.Popen(["C:\Program Files(x86)\VideoLAN\VLC\vlc.exe","C:\Users\Kamilos\Desktop\TBT\Tbt_S01E17.avi"])
  </code></pre>
  
  <p>But it doesn't work, why ? :p</p>
  
  <p>(tested in python 2.7.3 and 3)</p>
  
  <p>EDIT SOLVED : like Drake said, just replace back-slash with blash</p>
  
  <pre><code>subprocess.Popen(["C:/Program Files(x86)/VideoLAN/VLC/vlc.exe","C:/Users/Kamilos/Desktop/TBT/Tbt_S01E17.avi"])‌​
  </code></pre>