title: Create new FileStream out of a byte array
body: <p>I am attempting to create a new FileStream object from a byte array. I'm sure that made no sense at all so I will try to explain in further detail below.</p>
  
  <p>Tasks I am completing:
  1) Reading the source file which was previously <em>compressed</em>
  2) Decompressing the data using GZipStream 
  3) copying the decompressed data into a byte array.</p>
  
  <p><strong>What I would like to change:</strong></p>
  
  <p>1) I would like to be able to use File.ReadAllBytes to read the decompressed data.
  2) I would then like to create a new filestream object usingg this byte array.</p>
  
  <p>In short, I want to do this entire operating using byte arrays. One of the parameters for GZipStream is a stream of some sort, so I figured I was stuck using a filestream. But, if some method exists where I can create a new instance of a FileStream from a byte array - then I should be fine.</p>
  
  <p>Here is what I have so far:</p>
  
  <pre><code>FolderBrowserDialog fbd = new FolderBrowserDialog(); // Shows a browser dialog
   fbd.ShowDialog();
  
              // Path to directory of files to compress and decompress.
              string dirpath = fbd.SelectedPath;
  
              DirectoryInfo di = new DirectoryInfo(dirpath);
  
  
   foreach (FileInfo fi in di.GetFiles())
              {
                  zip.Program.Decompress(fi);
  
              }
  
              // Get the stream of the source file.
              using (FileStream inFile = fi.OpenRead())
              {
  
                  //Create the decompressed file.
                  string outfile = @"C:\Decompressed.exe";
                  {
                      using (GZipStream Decompress = new GZipStream(inFile,
                              CompressionMode.Decompress))
                      {
                          byte[] b = new byte[blen.Length];
                          Decompress.Read(b,0,b.Length);
                          File.WriteAllBytes(outfile, b);
                      }
                  }
              }
  </code></pre>
  
  <p>Thanks for any help!
  Regards,
  Evan</p>