title: How to click on the first result on google using selenium python
body: <p>I am trying to click on the first result on the google result. Here is my code 
  where I am entering chennai craiglist which is read from csv file. So I am sure the first link that come in the organic result will be chennai.craiglist.org. But I am quiet not sure about how to do this. </p>
  
  <pre><code>from selenium import webdriver
      from selenium.webdriver.common.by import By
      from selenium.webdriver.support.ui import Select
      from selenium.common.exceptions import NoSuchElementException
      import unittest, time, re
  
      class Browse(unittest.TestCase):
      def setUp(self):
      self.driver = webdriver.Firefox()
      self.driver.implicitly_wait(30)
      self.base_url = "http://google.com/"
  
      filename = 'test.csv'
      line_number = 1
      with open(filename, 'rb') as f:
          mycsv = csv.reader(f)
          mycsv = list(mycsv)
          self.cityname=mycsv[line_number][0]
          self.username=mycsv[line_number][1]
          self.password=mycsv[line_number][2]
          self.verificationErrors = []
  
  def test_browse(self):
      driver = self.driver
      driver.get(self.base_url + "/")
      driver.find_element_by_id("gbqfq").send_keys(self.cityname)
  </code></pre>
  
  <p>I wanna know what should come after this line?</p>
  
  <p>UPDATE</p>
  
  <p>right now I am giving like </p>
  
  <pre><code>driver.find_elements_by_xpath(".//*[@id='rso']//div//h3/a")[:1].click()
  </code></pre>
  
  <p>I am not sure if it will work or not.</p>