title: How can I use a switch() statement to convert from a numeric to a letter grade?
body: <p>This IS NOT homework, but it is a practice that the teacher gave us to help study for a test. But i will not be turning this in to the teacher. (i'm hoping that is allowed)</p>
  
  <p>He wants a user to input a grade and have it assigned a letter grade. It would be easy with if statements, but i can't use ANY! I have to use the switch method.</p>
  
  <p>Here is my functional class:</p>
  
  <pre><code>public class Grade {
  
  public double getGrade(int input)
   {
    double inputGrade;
    switch(input)
    {
     case 1: inputGrade &gt;= 90;
         break;
     case 2: inputGrade &gt;= 80;
         break;
     case 3: inputGrade &gt;= 70;
         break;
     default:
         grade = 60;
    }
    return grade;
  
   }
  
  }
  </code></pre>
  
  <p>Here is my test class:</p>
  
  <pre><code>import java.util.*;
  public class TestGrade
  {
   public static void main(String[] args)
   {
    Scanner scan = new Scanner(System.in);
    int input = scan.nextInt();
    Grade lGrade = new Grade();
    double finalGrade = lGrade.getGradeSwitch(input);
    System.out.println("Your toll is $" + finalGrade);
   }
  
  }
  </code></pre>
  
  <p>I just haven't been programming enough to have this analytical mind. I HAVE tried to complete it, i just haven't found a way to covert the user input (int) into a letter grade (string) without if statements.</p>
  
  <p>I know this is incomplete, but this is as far as I could go without making errors.</p>
  
  <p>EDIT:WOW! Thanks guys, i hate to pick a single correct answer, because a lot of  you helped me!</p>
  
  <p>This is what i ended up with (that worked :D)</p>
  
  <pre><code>public String getGrade(int input)
  {
      String letterGrade;
      switch(input/10)
      {
          case 9: letterGrade = "A";
                    break;
          case 8: letterGrade = "B";
                    break;
          case 7: letterGrade = "C";
                    break;
          case 6: letterGrade = "D";
          default:
                    letterGrade = "F";
      }
      return letterGrade;
  
  }
  </code></pre>