title: Using xslt get node value at X position
body: <p>How can I get using xslt, node value at X position, without using foreach</p>
  
  <pre><code>&lt;items&gt;
  &lt;item1&gt;x&lt;/item1&gt;
  &lt;item2&gt;x&lt;/item2&gt;
  &lt;item3&gt;x&lt;/item3&gt;
  &lt;/items&gt;
  </code></pre>
  
  <p>This is explained in programming sense:</p>
  
  <pre><code>&lt;xsl:value-of select="Items/Item[2]"/&gt;
  </code></pre>
  
  <p>==================================================</p>
  
  <p>Just to little expand question, in the following xml:</p>
  
  <pre><code>&lt;items&gt;
      &lt;about&gt;xyz&lt;/about&gt;
      &lt;item1&gt;
         &lt;title&gt;t1&lt;/title&gt;
         &lt;body&gt;b1&lt;/body&gt;
      &lt;/item1&gt;
      &lt;item2&gt;
         &lt;title&gt;t2&lt;/title&gt;
         &lt;body&gt;b2&lt;/body&gt;
      &lt;/item2&gt;
      &lt;item3&gt;
         &lt;title&gt;3&lt;/title&gt;
         &lt;body&gt;3&lt;/body&gt;
     &lt;/item3&gt;
  &lt;/items&gt;
  </code></pre>
  
  <p><strong>How can I select second's item title.</strong></p>