Then for the second eye the magnification would become 
  
    
      
        
          
            Magnification
          
        
        =
        
          
            1
            
              (
              1
              −
              (
              0.005
              
                /
              
              1.6
              )
              ×
              14.5
              )
            
          
        
        ⋅
        
          
            1
            
              (
              1
              −
              0.015
              ×
              −
              4
              )
            
          
        
        =
        1.0475
        ×
        0.9434
        =
        0.9882
        =
        98.82
        
        %
      
    
    {\displaystyle {\textrm {Magnification}}={\frac {1}{(1-(0.005/1.6)\times 14.5)}}\cdot {\frac {1}{(1-0.015\times -4)}}=1.0475\times 0.9434=0.9882=98.82\,\%}
  ,
which is much closer to that of the first eye.
The formula for iseikonic lenses (without cylinder) is:

  
    
      
        
          
            Magnification
          
        
        =
        
          
            1
            
              (
              1
              −
              (
              
                
                  t
                  n
                
              
              )
              P
              )
            
          
        
        ⋅
        
          
            1
            
              (
              1
              −
              h
              F
              )
            
          
        
      
    
    {\displaystyle {\textrm {Magnification}}={\frac {1}{(1-({\frac {t}{n}})P)}}\cdot {\frac {1}{(1-hF)}}}
  where:  t = center thickness (in metres);n = refractive index;P = front base curve (in 1/metres);h = vertex distance (in metres);F = back vertex power (in 1/metres), (essentially, the prescription for the lens, quoted in diopters).