user
Task

This is admittedly a trivial task but I thought it would be interesting to see how succinctly (or otherwise) different languages can handle it.

Given the string: "abracadabra", replace programatically:

* the first 'a' with 'A'
* the second 'a' with 'B'
* the fourth 'a' with 'C'
* the fifth 'a' with 'D'
* the first 'b' with 'E'
* the second 'r' with 'F'

Note that there is no replacement for the third 'a', second 'b' or first 'r'.

The answer should, of course, be : "AErBcadCbFD".

Other tasks related to string operations:

Metrics

* Array length
* String length
* Copy a string
* Empty string  (assignment)

Counting

* Word frequency
* Letter frequency
* Jewels and stones
* I before E except after C
* Bioinformatics/base count
* Count occurrences of a substring
* Count how many vowels and consonants occur in a string

Remove/replace

* XXXX redacted
* Conjugate a Latin verb
* Remove vowels from a string
* String interpolation (included)
* Strip block comments
* Strip comments from a string
* Strip a set of characters from a string
* Strip whitespace from a string -- top and tail
* Strip control codes and extended characters from a string

Anagrams/Derangements/shuffling

* Word wheel
* ABC problem
* Sattolo cycle
* Knuth shuffle
* Ordered words
* Superpermutation minimisation
* Textonyms (using a phone text pad)
* Anagrams
* Anagrams/Deranged anagrams
* Permutations/Derangements

Find/Search/Determine

* ABC words
* Odd words
* Word ladder
* Semordnilap
* Word search
* Wordiff  (game)
* String matching
* Tea cup rim text
* Alternade words
* Changeable words
* State name puzzle
* String comparison
* Unique characters
* Unique characters in each string
* Extract file extension
* Levenshtein distance
* Palindrome detection
* Common list elements
* Longest common suffix
* Longest common prefix
* Compare a list of strings
* Longest common substring
* Find common directory path
* Words from neighbour ones
* Change e letters to i in words
* Non-continuous subsequences
* Longest common subsequence
* Longest palindromic substrings
* Longest increasing subsequence
* Words containing "the" substring
* Sum of the digits of n is substring of n
* Determine if a string is numeric
* Determine if a string is collapsible
* Determine if a string is squeezable
* Determine if a string has all unique characters
* Determine if a string has all the same characters
* Longest substrings without repeating characters
* Find words which contains all the vowels
* Find words which contain the most consonants
* Find words which contains more than 3 vowels
* Find words whose first and last three letters are equal
* Find words with alternating vowels and consonants

Formatting

* Substring
* Rep-string
* Word wrap
* String case
* Align columns
* Literals/String
* Repeat a string
* Brace expansion
* Brace expansion using ranges
* Reverse a string
* Phrase reversals
* Comma quibbling
* Special characters
* String concatenation
* Substring/Top and tail
* Commatizing numbers
* Reverse words in a string
* Suffixation of decimal numbers
* Long literals, with continuations
* Numerical and alphabetical suffixes
* Abbreviations, easy
* Abbreviations, simple
* Abbreviations, automatic

Song lyrics/poems/Mad Libs/phrases

* Mad Libs
* Magic 8-ball
* 99 bottles of beer
* The Name Game (a song)
* The Old lady swallowed a fly
* The Twelve Days of Christmas

Tokenize

* Text between
* Tokenize a string
* Word break problem
* Tokenize a string with escaping
* Split a character string based on change of character

Sequences

* Show ASCII table
* De Bruijn sequences
* Summarize and say sequence
* Generate lower case ASCII alphabet
assistant
Set up to not particularly rely on absolute structure of the word. Demonstrate with both the original 'abracadabra' and with a random shuffled instance.

```
sub mangle ($str is copy) {
    $str.match(:ex, 'a')».from.map: { $str.substr-rw($_, 1) = 'ABaCD'.comb[$++] };
    $str.=subst('b', 'E');
    $str.substr-rw($_, 1) = 'F' given $str.match(:ex, 'r')».from[1];
    $str
}

say $_, ' -> ', .&mangle given 'abracadabra';

say $_, ' -> ', .&mangle given 'abracadabra'.comb.pick(*).join;

```

Output:

```
abracadabra -> AErBcadCbFD
caarabadrab -> cABraECdFDb
```