user
Task

Show here (on this page) the decimal numbers formed by:

:   :   (**n**   **1'**s   appended by the digit   **3**)   and then square the result,     where    **0   <=   n   <   8**

See also

* oeis:A151997
assistant
In an attempt to stave of terminal ennui, Find the first 8 where a(n) is semiprime.

```
say "$_, {.²}" for (^∞).map({ ( 1 x $_ ~ 3)} ).grep({ .is-prime })[^8]

```

Output:

```
3, 9
13, 169
113, 12769
11113, 123498769
111111113, 12345679432098769
11111111113, 123456790165432098769
111111111111111111111113, 12345679012345679012346098765432098765432098769
111111111111111111111111111111111111111111111111111111111111111111111111111111111113, 12345679012345679012345679012345679012345679012345679012345679012345679012345679012765432098765432098765432098765432098765432098765432098765432098765432098765432098769
```