The operation $\Theta$ is defined by $a \ominus b=a^{b}-b^{a}$. What is the value of $2 \Theta(2 \odot 5)$ ?
Using the definition,

$$
2 \odot(2 \odot 5)=2 \odot\left(2^{5}-5^{2}\right)=2 \odot(32-25)=2 \odot 7=2^{7}-7^{2}=128-49=79
$$

ANSWER: 79