7.3. In the 7th grade, there are 25 people, and each attends a dance club or a drama club (some attend both clubs). Everyone took a math test, and the teacher calculated the percentage of students who received a failing grade (2) separately among the "dancers" and among the "actors." It turned out that the percentage is the same and equals $30 \%$. Can the percentage of failing grades in the entire class be more than $35 \%$?
Answer. It can. Solution. Consider the following example. Suppose there are 10 "dancers" and 20 "actors" in the class, then the number of "dancing actors" will be $10+20-25=5$ people, and the number of "pure dancers" will be $10-5=5$ and the number of "pure actors" will be $20-5=15$. Suppose that three "dancers" and six "actors" received twos, and the "dancing actors" did not receive any twos. Then the percentage of twos among "dancers" and among "actors" is $\frac{3}{10}=\frac{6}{20}=30 \%$, while the percentage of twos in the entire class is $\frac{9}{25}=36 \%$. Comment. A complete solution to the problem is considered any example that meets the conditions. In the given example, the "round" numbers of dancers and actors (10 and 20) are "suggested" by the round percentage ( $=30 \%$ ).