2. (8 points) The height of the larger cylinder is twice that of the smaller cylinder, the lateral surface area of the larger cylinder is 12 times that of the smaller cylinder, the volume of the larger cylinder is $\qquad$ times that of the smaller cylinder.
【Solution】Solution: The lateral area of a cylinder $=2 \pi r h$, let the lateral area of the larger cylinder be $S_{\text {large }}$, and the lateral area of the smaller cylinder be $S_{\text {small }}$. From the problem, we have $S_{\text {large }}=12 S_{\text {small; }} h_{\text {large }}=2 h_{\text {small }}$
$$
\therefore r_{\text {large }}=6 r \text { small; }
$$
Therefore, the answer is: 72.