6. Divide 2004 into the sum of $n(n>1)$ consecutive natural numbers, the number of ways to do this is ( )
A. $\theta$
B. 1
C. 2
1). 3
6. I)
$2004=2^{2} \times 3 \times 167, 2004$ has 3 odd factors greater than 1: 3, 167, 501. It is not difficult to prove that the number of ways to express a natural number as the sum of $n$ consecutive natural numbers is consistent with the number of odd factors of this natural number greater than 1.
$$
2004=667+668+669=72+73+\cdots+95=247+248+\cdots+254
$$