Find the degree measure of an angle whose complement is 25% of its supplement.
$\mathrm{(A) \ 48 } \qquad \mathrm{(B) \ 60 } \qquad \mathrm{(C) \ 75 } \qquad \mathrm{(D) \ 120 } \qquad \mathrm{(E) \ 150 }$
Solution 1
We can create an equation for the question, $4(90-x)=(180-x)$
$360-4x=180-x$
$3x=180$
After simplifying, we get $x=60 \Rightarrow \mathrm {(B)}$


Solution 2
Given that the complementary angle is $\frac{1}{4}$ of the supplementary angle. Subtracting the complementary angle from the supplementary angle, we have $90^{\circ}$ as $\frac{3}{4}$ of the supplementary angle.
Thus the degree measure of the supplementary angle is $120^{\circ}$, and the degree measure of the desired angle is $180^{\circ} - 120^{\circ} = 60^{\circ}$. $\mathrm {(B)}$
~ Nafer