1. For $-4<x<1$, for the expression $\frac{x^{2}-2 x+2}{2 x-2}$
A. No maximum or minimum value
B. Has a minimum value of 1
C. Has a maximum value of 1
D. Has a minimum value of -1
1. E Let $f(x)=\frac{x^{2}-2 x+2}{2 x-2}$, then $f^{\prime}(x)=\frac{x(x-2)}{2(x-1)^{2}}, f^{\prime}(x)=0, x=0,2 . f^{\prime \prime}(x)=\frac{1}{(x-1)^{3}}$. $f^{\prime \prime}(0)=-1, f^{\prime \prime}(2)=1, f(0)=-1, f(2)=1$, but $-4<x<1$. Therefore, the answer is E.