$\frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\frac{1}{3}$ equals
(A) $3 \frac{1}{3}$
(B) $7+\frac{1}{3}$
(C) $\frac{3}{7}$
(D) $7+3$
(E) $7 \times \frac{1}{3}$
Since we are adding $\frac{1}{3}$ seven times, then the result is equal to $7 \times \frac{1}{3}$.

ANswer: (E)