Adam and Mada are playing a game of one-on-one basketball, in which participants may take $2$-point shots (worth $2$ points) or $3$-point shots (worth $3$ points). Adam makes $10$ shots of either value while Mada makes $11$ shots of either value. Furthermore, Adam made the same number of $2$-point shots as Mada made $3$-point shots. At the end of the game, the two basketball players realize that they have the exact same number of points! How many total points were scored in the game?

[i]2017 CCA Math Bonanza Lightning Round #2.1[/i]
1. Let \( x \) be the number of 2-point shots Adam made. Since Adam made a total of 10 shots, the number of 3-point shots Adam made is \( 10 - x \).

2. Let \( y \) be the number of 3-point shots Mada made. Since Mada made a total of 11 shots, the number of 2-point shots Mada made is \( 11 - y \).

3. According to the problem, Adam made the same number of 2-point shots as Mada made 3-point shots. Therefore, we have:
   \[
   x = y
   \]

4. The total points scored by Adam can be expressed as:
   \[
   2x + 3(10 - x) = 2x + 30 - 3x = 30 - x
   \]

5. The total points scored by Mada can be expressed as:
   \[
   3y + 2(11 - y) = 3y + 22 - 2y = y + 22
   \]

6. Since Adam and Mada scored the same number of points, we set their point totals equal to each other:
   \[
   30 - x = y + 22
   \]

7. Substituting \( y = x \) into the equation, we get:
   \[
   30 - x = x + 22
   \]

8. Solving for \( x \):
   \[
   30 - x = x + 22 \\
   30 - 22 = 2x \\
   8 = 2x \\
   x = 4
   \]

9. Therefore, Adam made 4 two-point shots and \( 10 - 4 = 6 \) three-point shots. Mada made 4 three-point shots and \( 11 - 4 = 7 \) two-point shots.

10. The total points scored by Adam is:
    \[
    2(4) + 3(6) = 8 + 18 = 26
    \]

11. The total points scored by Mada is:
    \[
    3(4) + 2(7) = 12 + 14 = 26
    \]

12. The total points scored in the game is:
    \[
    26 + 26 = 52
    \]

The final answer is \(\boxed{52}\).