11. (12 points) $0 \sim 9$ can form two five-digit numbers $A$ and $B$. If the sum $A+B$ is a six-digit number with the last five digits being the same, then the number of different values of $A \times B$ is $\qquad$.


【Solution】Solution: According to the problem, we know:
The first digit of the six-digit number must be 1. According to the rule of casting out nines, the following five digits are all 7. Therefore, the sum of the first digits of these two five-digit numbers is
17. The sum of the last four digits, which is 7, can be paired in pairs.

Pairing the digits that sum to 7, the five-digit number starting with 9 has $8 \times 6 \times 4 \times 2=384$ (ways). Depending on the different cases, the difference between the two five-digit numbers varies, and the smaller the difference, the larger the product. Therefore, these 384 products are all different. Hence, the answer is: 384.