Find the law that forms the sequence 425, 470, 535, 594, 716, $802, \ldots$ and give its next two terms.
Each term of the sequence is the sum of the previous term and the squares of each of its digits. Indeed,

$$
470=425+4^{2}+2^{2}+5^{2}, 535=470+4^{2}+7^{2}+0^{2}, \ldots
$$

Thus, after 802, the next terms will be 870 and 983.