1) If the numbers 0.3; 0.3̅; (0.3̅)²; 1/0.3; 1/0.3̅ are arranged in ascending order, the third number is
(A) 0.3
(B) 0.3̅
(C) (0.3̅)²
(D) 1/0.3
(E) 1/0.3̅.
1) The answer is $(\mathrm{B})$.

Since $0, \overline{3}=\frac{1}{3}$, we have $(0, \overline{3})^{2}<0.3<0, \overline{3}$, on the other hand $0, \overline{3}<1<\frac{1}{0, \overline{3}}<\frac{1}{0.3}$.