9. (7 points) As shown in the figure, the area of the rectangular card is 40, the area of the square card is 25, and the area of the triangular card is 12. The overlapping area between the rectangular card and the square card is 6, the overlapping area between the rectangular card and the triangular card is 4, the overlapping area between the triangular card and the square card is 3, and the overlapping area of the three cards is 2. Then, the total area covered by the three cards is $\qquad$
【Solution】Solution: As shown in the figure, let the area of hexagon $A B C D E F$ be $x$, the area of quadrilateral $F G H L$ be $y$, and the area of triangle $L D I$ be $z$.
By the problem, $\left\{\begin{array}{l}x+2=6 \\ y+2=4, \\ z+2=3\end{array}\right.$
$$
\therefore x=4, y=2, z=1 \text {, }
$$
$\therefore$ The total area covered by the three cards $=40+25+12-(x+y+z+2 \times 2)=66$.
Therefore, the answer is 66