Consider a triangle and 2 lines that each go through a corner and intersects the opposing segment, such that the areas are as on the attachment.

Find the "?"
1. **Identify the given elements and apply Van Aubel's theorem:**
   Let $ABC$ be a triangle and let $P$ be a point inside the triangle. Let $E = BP \cap CA$, $F = CP \cap AB$, and $D = AP \cap BC$. According to Van Aubel's theorem, we have:
   \[
   \frac{EA}{EC} + \frac{FA}{FB} = \frac{PA}{PD}
   \]

2. **Apply the theorem to the specific triangle and point:**
   In the problem, the notations of $A$ and $P$ are interchanged. We apply the theorem to triangle $PBC$ and point $A$. This means we need to consider the segments and points accordingly.

3. **Express the areas in terms of the segments:**
   Let the areas of the sub-triangles be denoted as follows:
   - Area of $\triangle PBC = S$
   - Area of $\triangle PAB = S_1$
   - Area of $\triangle PAC = S_2$
   - Area of $\triangle PAB = S_3$

   According to the problem, we need to find the unknown area denoted by "?".

4. **Use the area ratios to find the unknown area:**
   By Van Aubel's theorem, we have:
   \[
   \frac{EA}{EC} + \frac{FA}{FB} = \frac{PA}{PD}
   \]
   Since the areas are proportional to the segments, we can write:
   \[
   \frac{S_1}{S_2} + \frac{S_3}{S_4} = \frac{S_5}{S_6}
   \]
   where $S_1, S_2, S_3, S_4, S_5, S_6$ are the areas of the respective sub-triangles.

5. **Solve for the unknown area:**
   Given the areas of the sub-triangles, we can set up the equation and solve for the unknown area. For example, if we know the areas of $\triangle PAB$, $\triangle PAC$, and $\triangle PBC$, we can find the unknown area by solving the equation derived from Van Aubel's theorem.

The final answer is $\boxed{?}$ (the unknown area).