[ Pascal's Triangle and Newton's Binomial ]

How many times greater is the sum of the numbers in the 101st row of Pascal's Triangle compared to the sum of the numbers in the 100th row?

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Let in the 100th row stand the numbers $c_{0}, c_{1}, \ldots, c_{100}$. Then in the 101st row stand the numbers $c_{0}, c_{0}+c_{1}, c_{1}+c_{2}, \ldots, c_{99}+$ $c_{100}, c_{100}$

their sum is $2 c_{0}+2 c_{1}+\ldots+2 c_{100}$.

## Otvet

Twice.