Someone leaves 46800 frts to their children in such a way that this amount would be divided equally among them. However, before the inheritance is divided, two children die, which results in each of the remaining children receiving 1950 frts more than they would have otherwise. Question: How many children were there?
If the number of children is $x$, then each receives $\frac{46800}{x}$ frt; if two children die, each receives $\frac{46800}{x-2}$ frt, which is 1950 frt more than before; $x$ is thus obtained from the following equation:

$$
\frac{46800}{x}+1950=\frac{46800}{x-2}
$$

Rearranging the equation, we get:

$$
x^{2}-2 x-48=0
$$

from which $x_{1}=8$ and $x_{2}=-6$. Therefore, there were 8 children.

(Mór Feuer, Gymnasium VII. class, Nyíregyháza.)

The problem was also solved by: Béla Bálint, Jenő Fekete, Antal Freund, Bernát Friedmann, Gyula Friedman, Emil Geist, Zsigmond Goldstein, Béla Grünhut, Tivadar Hönigsfeld, Ervin Hofbauer, Dániel Jakobovits, Nándor Kántor, Béla Kiss, Mór Klein, Ödön Kornis, Viktor Mohr, Jenő Piovarcsy, Frigyes Riesz, Miksa Roth, Béla Schneider, Elek Simon, Károly Szabó, István Szita, Aladár Tauszig, Ármin Weisz.