282. Given the system of equations:

$$
\begin{gathered}
x^{3}-y^{5}=2882 \\
x-y=2
\end{gathered}
$$

if it is known that $x_{1}=5, y_{1}=3 ; x_{3}=1+3 \sqrt{-2}$, then how to write $x_{2}, y_{2} ; y_{3} ; x_{4}, y_{4}$ without calculations?
282. Reasoning as in the previous question, we have:

$$
x_{4}=1-3 \sqrt{2}
$$

the left sides of the equations will not change if we substitute $-y$ for $x$ and $-x$ for $y$; therefore:

$$
x_{2}=-3, y_{2}=-5 ; y_{3}=-1+3 \sqrt{2} ; y_{4}=-1-3 \sqrt{2}
$$