G4.2 Amongst the seven numbers $3624,36024,360924,3609924,36099924,360999924$ and 3609999924 , there are $n$ of them that are divisible by 38 . Find the value of $n$.
$\begin{array}{l}38=2 \times 19, \text { we need to investigate which number is divisible by } 19 . \\ 19^{2}=361 \\ 3624=3610+13 \\ 36024=36100-76=100\left(19^{2}\right)-19 \times 4 \\ 360924=361000-76 \\ 3609924=3610000-76 \\ 36099924=36100000-76 \\ 360999924=361000000-76 \\ 3609999924=3610000000-76 \\ n=6\end{array}$