The value of $3^{2}-(4 \times 2)$ is
(A) 4
(B) 17
(C) 1
(D) -2
(E) 0
The value of $3^{2}-(4 ¥ 2)$ is
(A) 4
(B) 17
(C) 1
(D) -2
(E) 0

## Solution

By order of operations,

$3^{2}-(4 ¥ 2)=9-(4 ¥ 2)=9-8=1$.

ANSWER: (C)