7. (10 points) As shown in the figure, the beads on the bracelet are numbered from 1 to 22 in a counterclockwise direction starting from the pendant. Xiao Ming plays a bead-counting game with the rule: starting from bead 1, count natural numbers clockwise one by one, but skip any number that contains the digit 7 or is a multiple of 7, and directly count the next number. For example: after counting to 6, the next number is 8; after counting to 13, the next number is 15, etc. When counting to 100, it should land on the 4th bead.
【Analysis】Numbers containing the digit 7 or multiples of 7 are: units place: $7, 17, 27, \cdots, 97$, tens place: $70, 71, 72, \cdots, 79$, multiples of 7: $100 \div 7=14 \cdots 2$, among which $7, 70, 77$ are both multiples of 7 and contain the digit 7, according to this, solve it.
【Solution】Solution: Numbers containing the digit 7 or multiples of 7 are: units place: $7, 17, 27, \cdots, 97$, tens place: 70, 71, $72, \cdots, 79$, multiples of 7: $100 \div 7=14 \cdots 2$, among which $7, 70, 77$ are both multiples of 7 and contain the digit 7,
Therefore, there are $10+10+14-4=30, 100-30=70, 70 \div 22=3 \cdots 4$
Answer: When counting to 100, it should land on the 4th bead.
The answer is: 4.