24. L. N. Tolstoy's Problem. Five brothers divided their father's inheritance equally. The inheritance included three houses. Since the three houses could not be divided into 5 parts, the three older brothers took them, and in return, the younger brothers were given money. Each of the three brothers paid 800 rubles, and the younger brothers divided this money among themselves, so that everyone ended up with an equal share. How much is one house worth?
24. Two younger brothers received 2400 rubles, and each received 1200 rubles. $(2400: 2=$ $=1200)$. Therefore, the total value of the inheritance, i.e., three houses, is 6000 rubles. $(1200 \times$ $\times 5=6000)$. Then one house costs 2000 rubles. $(6000: 3=2000)$.