The polynomial $(x+y)^9$ is expanded in decreasing powers of $x$. The second and third terms have equal values 
when evaluated at $x=p$ and $y=q$, where $p$ and $q$ are positive numbers whose sum is one. What is the value of $p$? 
$\textbf{(A)}\ 1/5 \qquad  \textbf{(B)}\ 4/5 \qquad  \textbf{(C)}\ 1/4 \qquad  \textbf{(D)}\ 3/4 \qquad  \textbf{(E)}\ 8/9$
Solution by e_power_pi_times_i

The second and third term of $(x+y)^9$ is $9x^8y$ and $36x^7y^2$, respectively. For them to be equal when $x = p$, $\dfrac{p}{4} = y$. For them to be equal when $y = q$, $x = 4q$. Then $p+\dfrac{p}{4} = q+4q$, so $\dfrac{5p}{4} = 5q$, which simplifies to $p = 4q$. Since $p+q = 1$, $p = \boxed{\textbf{(B) } 4/5}$.