A6. Let $x<-2$. Simplify the fraction $\frac{x^{2}-1+|x+1|}{x^{2}-2 x}$. The result is
(A) $-\frac{x+1}{x-2}$
(B) $\frac{x+1}{x}$
(C) $-\frac{x+1}{x}$
(D) 1
(E) -1

## II. PART
A6. If $x<-2$, then $x+1<-1<0$, so $|x+1|=-(x+1)$ and the fraction is equal to

$$
\frac{x^{2}-1-(x+1)}{x^{2}-2 x}=\frac{(x+1)(x-1)-(x-1)}{x(x-2)}=\frac{(x+1)(x-2)}{x(x-2)}=\frac{x+1}{x}
$$

II. PART