What is the value of $\frac{24+12}{4^{2}-4}$ ?
Solution 1

The numerator is equal to $24+12=36$. The denominator is equal to $4^{2}-4=16-4=12$, so

$$
\frac{24+12}{4^{2}-4}=\frac{36}{12}=3
$$

## Solution 2

By factoring 4 out of both the numerator and denominator, we get

$$
\frac{24+12}{4^{2}-4}=\frac{4(6+3)}{4(4-1)}=\frac{6+3}{4-1}=\frac{9}{3}=3 .
$$

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