8. (10 points) Player A and Player B are having a table tennis match, with a best-of-three format. In each game, the first to score 11 points and the opponent scoring less than 10 points wins; if the score is tied at 10, the first to score 2 more points wins. The total points scored by both A and B are 30 points. Without considering the order of the scores, the number of possible score combinations for the three games is $\qquad$ kinds.
【Analysis】Through analysis, we can know: the total scores of A and B are both 30 points, $30<3 \times 11$, in the three rounds, one of them won two rounds, so at least two scores are not less than 11, the total score of A is $30: 30=11+9+10$, the corresponding score of B is: $30=7+11+12:$ the corresponding scores are $\left\{\begin{array}{l}11: 7 \\ 9: 11 \\ 10: 12\end{array}\right.$, then 7, 9 are reduced by 1 in sequence, 10 and 12 are increased by 1 in sequence: $\left\{\begin{array}{l}11: 6 \\ 8 ; 11 \\ 11: 13\end{array}\left\{\begin{array}{l}11: 5 \\ 7: 11 \\ 12: 14\end{array},\left\{\begin{array}{l}11: 4 \\ 6: 11 \\ 13: 15\end{array} 、\left\{\begin{array}{l}11: 3 \\ 5: 11 \\ 14: 16\end{array} 、\left\{\begin{array}{l}11: 2 \\ 4: 11 \\ 15: 17\end{array} 、\left\{\begin{array}{l}11: 1 \\ 3: 11 \\ 16: 18\end{array} 、\left\{\begin{array}{l}11: 0 \\ 2: 11, \\ 17: 19\end{array}\right.\right.\right.\right.\right.\right.\right.$, the above 8 are all B's victories, the corresponding 8 cases where A wins, but considering the order of the scores does not matter, there are 8 cases, according to this, the answer can be given.

【Solution】Solution: The total scores of A and B are both 30 points
$$
30<3 \times 11
$$

In the three rounds, one of them won two rounds, so at least two scores are not less than 11, the total score of A is:
$$
30: 30=11+9+10
$$

The corresponding score of B is:
$$
30=7+11+12:
$$

The corresponding scores are $\left\{\begin{array}{l}11: 7 \\ 9: 11 \\ 10: 12\end{array}\right.$,
then 7, 9 are reduced by 1 in sequence, 10 and 12 are increased by 1 in sequence:
$$
\left\{\begin{array}{l}
11: 6 \\
8 ; 11 \\
11: 13
\end{array} 、 \left\{\begin{array}{l}
11: 5 \\
7: 11 \\
12: 14
\end{array} 、 \left\{\begin{array}{l}
11: 4 \\
6: 11 \\
13: 15
\end{array} 、 \left\{\begin{array}{l}
11: 3 \\
5: 11 \\
14: 16
\end{array} 、 \left\{\begin{array}{l}
11: 2 \\
4: 11 \\
15: 17
\end{array} 、 \left\{\begin{array}{l}
11: 1 \\
3: 11 \\
16: 18
\end{array} 、 \left\{\begin{array}{l}
11: 0 \\
2: 11 \\
17: 19
\end{array}\right.\right.\right.\right.\right.\right.\right.
$$

The above 8 are all B's victories, the corresponding 8 cases where A wins, but considering the order of the scores does not matter, there are 8 cases,

Answer: There are 8 possible score combinations for the three rounds.
The answer is: 8.