35. In triangle $ABC$, points $M, N$, and $P$ are taken: $M$ and $N$ are on sides $AC$ and $BC$, and $P$ is on segment $MN$, such that

$$
\frac{|AM|}{|MC|}=\frac{|CN|}{|NB|}=\frac{|MP|}{|PN|}
$$

Find the area of triangle $ABC$, if the areas of triangles $AMP$ and $BNP$ are $T$ and $Q$.
35. Denoting the ratio $\frac{|A M|}{|M C|}=\lambda$, we will have $S_{M C P}=\frac{T}{\lambda}$, $S_{C P N}=\lambda Q, \frac{S_{M C P}}{S_{C P N}}=\lambda$, i.e., $\frac{T}{Q}=\lambda^{3}$,

$$
\begin{aligned}
S_{A B C} & =\frac{|A C|}{|M C|} \cdot \frac{|B C|}{|C N|} S_{C M N}=\frac{(\lambda+1)^{2}}{\lambda}\left(\frac{T}{\lambda}+\lambda Q\right)= \\
& =\frac{(\lambda+1)^{2}}{\lambda^{2}}\left(T+\lambda^{2} Q\right)=(\lambda+1)^{3} Q=\left(T^{1 / 3}+Q^{1 / 3}\right)^{3}
\end{aligned}
$$