136 The relationship between the graph of the function $y=\arcsin (-x)$ and the graph of $y=\operatorname{arc} \sin x$ is $(\quad)$
A. Symmetric with respect to the $x$-axis, not symmetric with respect to the $y$-axis
B. Symmetric with respect to the $y$-axis, not symmetric with respect to the $x$-axis
C. Symmetric with respect to the origin, not symmetric with respect to the $x$-axis
D. Symmetric with respect to the $x$-axis and $y$-axis
136 D. Since $\arcsin (-x)=-\arcsin x(x \in[-1,1])$, the graph of $y=\arcsin (-x)$ is symmetric to the graph of $y=\operatorname{arc} \sin x$ with respect to the $x$-axis. Additionally, $\operatorname{arc} \sin (-x)=f_{1}(x)$ and $\operatorname{arc} \sin x=f_{2}(x)$ have the relationship $f_{1}(-x)=f_{2}(x)$, so the graphs of the two are also symmetric with respect to the $y$-axis. (Of course, "symmetric with respect to the $x$ and $y$ axes" implies "symmetric with respect to the origin").