11. Given 5 points on a plane, it is known that the lines connecting these points are neither parallel nor perpendicular to each other, and do not coincide. Through each point, perpendiculars are drawn to the lines connecting it to the other four points. What is the maximum number of intersection points of these perpendiculars? (excluding the original five points)

 untranslated text remains unchanged:
(不包括原来的五个点)
11. Given 5 points, they can form $C_{5}^{2}=10$ lines by connecting each pair of points. Among these, every 4 points can form $C_{4}^{2}=6$ lines by connecting each pair, so from each point, 6 perpendicular lines can be drawn to the other 4 points, resulting in a total of $5 \times 6=30$ lines. If all these perpendicular lines intersect each other, there will be $C_{30}^{2}=455$ intersection points, but some of these do not meet the conditions:
（1）Each line has 3 perpendicular lines that are parallel to each other, and they do not intersect. Since these perpendicular lines are drawn from 10 lines, there are 30 intersection points that do not exist.
（2）The 5 given points can form $C_{5}^{3}=10$ triangles, each with 3 concurrent lines. The 30 perpendicular lines mentioned in (1) are exactly the altitudes of these 10 triangles, leading to an overcount of 20 points.
（3）The perpendicular lines passing through the original points each have 6 lines, and since the original 5 points are not included, these perpendicular lines have $5 \times C_{6}^{2}=75$ intersection points that do not meet the conditions.
Therefore, the maximum number of intersection points of these perpendicular lines is 310.