## Task B-1.1.

If $\frac{a+b}{b}=\frac{3}{2}$ and $\frac{c}{b-c}=\frac{4}{5}$, what is $\frac{c-a}{c}$?
## First solution.

From $\frac{a+b}{b}=\frac{a}{b}+1=\frac{3}{2}$ it follows that $\frac{a}{b}=\frac{1}{2}$.

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2 points

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Now, $\frac{c-a}{c}=1-\frac{a}{c}=1-\frac{9}{8}=-\frac{1}{8}$.

2 points