1. A class of students learned at the award ceremony that the number of students (a student can submit multiple papers in one subject) who won awards in the subject paper competition is shown in Table 1.
Table 1
\begin{tabular}{|c|c|c|c|}
\hline & Mathematics & Physics & Chemistry \\
\hline Provincial & 3 & 2 & 3 \\
\hline Municipal & 18 & 6 & 12 \\
\hline
\end{tabular}

It is known that a total of 28 students in the class received awards, among which, 13 students received exactly two awards. Then, the maximum number of awards that the student who received the most awards in the class might have received is ( ) items.
(A) 3
(B) 4
(C) 5
(D) 6
- 1. B.

The class won a total of
$$
18+12+6+3+3+2=44 \text { (awards), }
$$

Those who won only two awards won a total of $13 \times 2=26$ awards.
Thus, the number of people who did not win two awards is 28 -
$$
13=15 \text { people. }
$$

Since everyone won at least one award, there are 44 $26-15=3$ awards left.

Therefore, the person who won the most awards could have won $3+1=4$ awards.