1. Since a syllable consists of two different letters, identical letters can only appear at the junction of syllables.

First, let's find the number of combinations of two syllables with a matching letter at the junction. Such syllables (in terms of the arrangement of vowels and consonants) are either AMMO $(3 \cdot 8 \cdot 3$ variants) or MAAN $(8 \cdot 3 \cdot 8$ variants), totaling 264 variants.

From each such combination, a funny word can be formed in two ways - by adding an arbitrary syllable either at the beginning or at the end. Since the language has 48 syllables $(8 \ldots 3=24$ syllables of the form MA and another 24 syllables of the form AM), each of these methods yields $264 \cdot 48$ words.

However, some words are counted twice. These are words where the letters at the junction of the first syllable with the second and the letters at the junction of the second with the third syllable match. Clearly, all such words have the form AMMOON or MAANNO, and their number is $3 \cdot 8 \cdot 3 \cdot 8 + 8 \cdot 3 \cdot 8 \cdot 3 = 2 \cdot 24^{2}$.
Answer: $2 \cdot 264 \cdot 48-2 \cdot 24^{2}=24192$ funny words.