8. It is known that 99 wise men are seated around a large round table, each wearing a hat of one of two different colors. Among them, 50 people's hats are of the same color, and the remaining 49 people's hats are of the other color. However, they do not know in advance which 50 people have the same color and which 49 people have the other color. They can only see the colors of the hats on others' heads, but not their own. Now they are required to simultaneously write down the color of their own hat on the paper in front of them. Question: Can they pre-arrange a strategy to ensure that at least 74 of them write the correct color?
8. Sure.

Suppose there are 50 white hats and 49 black hats. Those who see 50 white hats and 48 black hats are all wearing black hats. Thus, they can all write down the correct color, and there are 49 such people.

Next, let those who see 49 white hats and 49 black hats follow this strategy:

Observe which color of hat is more prevalent among the next 49 people in the clockwise direction, and write down that color.

Assume $A$ is such a person. And $B$ is the 25th person wearing a white hat after $A$ in the clockwise direction. If there are no more than 48 people between them, $A$ will write “white” on his paper. Otherwise, $B$ will write “white” on his paper.

Since the 50 people wearing white hats can be divided into 25 such $(A, B)$ pairs, in each pair, one person will write the correct color. Therefore, adding the 49 people wearing black hats, a total of $25 + 49 = 74$ people can write the correct color.