【Question 15】  
In the figure, there are 9 circles connected by 9 straight lines, each line passing through 3 circles. Player A and Player B take turns coloring the 9 circles; the first player to color all 3 circles on a single line with their own color wins; a draw counts as a win for Player B. Now, Player A has chosen “$A$” first, and Player B has chosen “$B$” next. For Player A to win, the next move should be in the square labeled $\qquad$ (list all possible options).
【Analysis and Solution】
(1) If Player A chooses 1, then Player B must choose 4, Player A must choose 7, Player B must choose 3, Player A must choose 6, Player B must choose 5, Player A must choose 2; the game ends in a draw, with Player B winning.
(2) If Player A chooses 2, then Player B must choose 3,

If Player A chooses 1, regardless of what Player B chooses, Player A can then choose either 4 or 5; Player A wins. (3) If Player A chooses 3, then Player B must choose 2, Player A must choose 6, Player B must choose 4, Player A must choose 7; regardless of what Player B chooses, Player A can then choose either 1 or 5; Player A wins.
(4) If Player A chooses 4, then Player B must choose 1,

If Player A chooses 3; regardless of what Player B chooses, Player A can then choose either 2 or 6; Player A wins.
(5) If Player A chooses 5, and Player B chooses 4, then Player A must choose 7,

If Player B chooses 6, regardless of what Player A chooses, Player B can then choose either 2 or 3; Player B wins.
(6) If Player A chooses 6, it is found through trials that Player B can only choose 3;
(1) If Player A chooses 6, Player B chooses 3, Player A chooses 1,

Then Player B must choose 4, Player A must choose 7, Player B must choose 5, Player A must choose 2; the game ends in a draw, with Player B winning.
(2) If Player A chooses 6, Player B chooses 3, Player A chooses 2,

Player B chooses 7, regardless of what Player A chooses, Player B can then choose either 1 or 4; Player B wins.
(3) If Player A chooses 6, Player B chooses 3, Player A chooses 4,

Then Player B must choose 1, Player A must choose 7, Player B must choose 5, Player A must choose 2; the game ends in a draw, with Player B winning.
(4) If Player A chooses 6, Player B chooses 3, Player A chooses 5,

Then Player B must choose 7, regardless of what Player A chooses, Player B can then choose either 1 or 4; Player B wins.
(5) If Player A chooses 6, Player B chooses 3, Player A chooses 7, then Player B must choose 5,

Regardless of what Player A chooses, Player B can then choose either 1 or 4; Player B wins or the game ends in a draw, with Player B winning.
(7) If Player A chooses 7, Player B chooses 6, Player A must choose 2, Player B must choose 3, Player A must choose 4, Player B must choose 1, Player A must choose 5; the game ends in a draw, with Player B winning.
In summary, for Player A to win, the next move should be in the squares labeled $2$, $3$, or $4$.