8. (5 points) According to the rules, Xiaoming's comprehensive evaluation score in mathematics for this semester is equal to the sum of half the average score of 4 tests and half the final exam score. It is known that the scores of the 4 tests are 90, 85, 77, and 96. If Xiaoming wants his comprehensive evaluation score to be no less than 90, then he must score at least $\qquad$ points in the final exam.
【Analysis】First, find the average score of the 4 tests. It is known that the comprehensive evaluation score of mathematics this semester is equal to the sum of half the average score of the 4 tests and half the final exam score. Subtract half the average score of the tests from the comprehensive evaluation score, and then divide by $\frac{1}{2}$.

【Solution】Solution: The average score of the tests:
$$
\begin{array}{l} 
\text { (90+85+77+96) } \div 4 \\
= 384 \div 4 \\
= 87 \text { (points); } \\
87 \times \frac{1}{2}=43.5 \text { (points); } \\
(90-43.5) \div \frac{1}{2} \\
= 46.5 \times 2 \\
= 93 \text { (points); }
\end{array}
$$

Answer: He needs to score at least 93 points in the final exam.
Therefore, the answer is: 93.
【Comment】This problem examines the method of calculating weighted averages. The key is to find the average score of the 4 tests, and then determine the score in the final exam.