14. The set of real numbers $x$ that satisfy $\frac{1}{x+1}>\frac{1}{x-2}$ is ( ).
(A) $x>2$
(B) $x<-1$
(C) $x<2$ or $x<-1$
(D) $-1<x<2$
(E) $*$
14. (D).

When $x0>x-2$, the inequality holds: When $x>2$, we have $x+1>x-2>0$, thus, $\frac{1}{x-2}>$ $\frac{1}{x+1}$. Then $\frac{1}{x+1}>\frac{1}{x-2} \Leftrightarrow-1<x<2$.