2. Calculate the value of the expression $\sqrt{(\sqrt{3}-3)^{2}}-(\sqrt{3}-3)$.
2. Since $\sqrt{3}<3$ and thus $\sqrt{3}-3<0$, it follows that $\sqrt{(\sqrt{3}-3)^{2}}=-(\sqrt{3}-3)$. $\quad 2$ POINTS Therefore, $\sqrt{(\sqrt{3}-3)^{2}}-(\sqrt{3}-3)=-(\sqrt{3}-3)-(\sqrt{3}-3)=6-2 \sqrt{3}$.