1. If $2012^{2}+2010 \times 2011 \times 2013 \times 2014=k^{2}(k>0)$, then $k=$
```
\begin{aligned}
k^{2} & =2012^{2}+2010 \times 2011 \times 2013 \times 2014 \\
& =2012^{2}+(2012-1) \times(2012+1) \times(2012-2) \times(2012+2) \\
& =2012^{2}+\left(2012^{2}-1\right) \times\left(2012^{2}-4\right) \\
& =\left(2012^{2}-2\right)^{2}
\end{aligned}
```

Therefore, \( k=2012^{2}-2=4048142 \).