trapezoid has side lengths $10, 10, 10$, and $22$. Each side of the trapezoid is the diameter of a semicircle with the two semicircles on the two parallel sides of the trapezoid facing outside the trapezoid and the other two semicircles facing inside the trapezoid as shown. The region bounded by these four semicircles has area $m + n\pi$, where m and n are positive integers. Find $m + n$.
[img]https://3.bp.blogspot.com/-s8BoUPKVUQk/XoEaIYvaz4I/AAAAAAAALl0/ML0klwHogGYWkNhY6maDdI93_GkfL_eyQCK4BGAYYCw/s200/2018%2Bps%2Bhs9.png[/img]
1. **Identify the semicircles and their diameters:**
   - The trapezoid has side lengths \(10, 10, 10, 22\).
   - Each side of the trapezoid is the diameter of a semicircle.
   - The semicircles on the parallel sides (lengths 10 and 22) face outside the trapezoid.
   - The semicircles on the non-parallel sides (both lengths 10) face inside the trapezoid.

2. **Calculate the area of each semicircle:**
   - The area of a semicircle with diameter \(d\) is given by \(\frac{1}{2} \pi \left(\frac{d}{2}\right)^2 = \frac{\pi d^2}{8}\).

   - For the semicircle with diameter 10:
     \[
     \text{Area} = \frac{\pi \cdot 10^2}{8} = \frac{100\pi}{8} = 12.5\pi
     \]
     There are two such semicircles, so their combined area is:
     \[
     2 \times 12.5\pi = 25\pi
     \]

   - For the semicircle with diameter 22:
     \[
     \text{Area} = \frac{\pi \cdot 22^2}{8} = \frac{484\pi}{8} = 60.5\pi
     \]

3. **Calculate the total area of the semicircles:**
   - The total area of the semicircles is the sum of the areas of the semicircles facing outside and inside:
     \[
     25\pi + 60.5\pi = 85.5\pi
     \]

4. **Calculate the area of the trapezoid:**
   - The height \(h\) of the trapezoid can be found using the Pythagorean theorem in one of the right triangles formed by dropping a perpendicular from one of the vertices of the shorter parallel side to the longer parallel side.
   - Let the height be \(h\) and the distance from the foot of the perpendicular to the nearest endpoint of the longer parallel side be \(x\). Then:
     \[
     x^2 + h^2 = 10^2 \quad \text{and} \quad (22 - x)^2 + h^2 = 10^2
     \]
     Solving these equations, we find:
     \[
     x = 6 \quad \text{and} \quad h = 8
     \]
   - The area of the trapezoid is:
     \[
     \text{Area} = \frac{1}{2} \times (10 + 22) \times 8 = \frac{1}{2} \times 32 \times 8 = 128
     \]

5. **Calculate the area of the region bounded by the semicircles:**
   - The total area of the semicircles is \(85.5\pi\).
   - The area of the semicircles facing inside the trapezoid is \(25\pi\).
   - The area of the region bounded by the semicircles is:
     \[
     128 + 85.5\pi - 25\pi = 128 + 60.5\pi
     \]

6. **Identify \(m\) and \(n\):**
   - From the expression \(128 + 60.5\pi\), we have \(m = 128\) and \(n = 60.5\).

7. **Sum \(m\) and \(n\):**
   \[
   m + n = 128 + 60.5 = 188.5
   \]

The final answer is \(\boxed{188.5}\)