3. (5 points) 190 is expressed as the sum of 10 consecutive even numbers, the largest of which is

Express the above text in English, keeping the original text's line breaks and format, and output the translation result directly.
28
【Analysis】According to the problem, let the smallest even number be $2 N$, since they are 10 consecutive even numbers, arranged from smallest to largest, each subsequent number is 2 more than the previous one, and then solve according to the problem.

【Solution】Solution: Let the smallest even number be $2 N$, according to the problem, we have:
$$
\begin{array}{c}
2 \mathbf{N}+2(\mathbf{N}+1)+2(\mathbf{N}+2)+\cdots+2(\mathbf{N}+7)+2(\mathbf{N}+8)+2(\mathbf{N}+9)=190 \\
10 \times 2 \mathbf{N}+0+2+4+\cdots+14+16+18=190 \\
20 \mathbf{N}+(0+18) \times 10 \div 2=190 \\
20 \mathbf{N}+18 \times 5=190 \\
20 \mathbf{N}+90=190 \\
20 N=100 \\
N=5
\end{array}
$$

Then the largest even number is: $2(\mathbf{N}+9)=2 \times(5+9)=2 \times 14=28$.
Answer: The largest of these even numbers is 28.
Therefore, the answer is: 28.