2. To get to the Solovyov family's cottage, you first need to walk 3 km along the highway and then 2 km along a path. Upon arriving at the station, Mom called her son Vasya at the cottage and asked him to meet her on a bicycle. They started moving towards each other at the same time. Mom walks at a constant speed of 4 km/h the entire time, while Vasya rides along the path at a speed of 20 km/h and along the highway at a speed of 22 km/h. At what distance from the station did Vasya meet Mom? Give your answer in meters.

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# Solution:

Vasya rode 2 kilometers along the path in $2: 20=0.1$ hours. During this time, his mother walked $4 \cdot 0.1=0.4$ km. After this, Vasya and his mother started moving towards each other on the road at constant speeds. $3-0.4=2.6$ km. We can set up the equation $(22+4) \cdot t=2.6$; from which $t=0.1$ hours. That is, the time it took for Vasya and his mother to meet is $0.1+0.1=0.2$ hours. In this time, his mother walked $4 \cdot 0.2=0.8$ km or 800 meters.

Answer: 800 m.