1. If $\frac{100}{x}>\sqrt{1994}-25>\frac{125}{x+2}$, then the positive integer $x$ is ( ).
(A) 4
(B) 5
(C) 6
(D) 7
$-1 . B$
From $44^{2}=193620$, when $x=6,7$, the left side $=\frac{100}{x}<19$, it is easy to verify that the inequality holds when $x=5$.