88. Among the balls that differ only in color, there are 6 white, 4 black, and 8 red. In how many ways can two boys divide these balls (not necessarily equally) between themselves so that each of them gets at least two balls of each color?
88. When the boys take two balls of each color, they will have left to divide 2 white and 4 red balls. This can be done in $(2+1)(4+1)=15$ ways. (Compare with problem 87.$)$