4. As shown in Figure 2, the perimeter of rhombus $A B C D$ is 52, and the diagonal $A C=24$. Then the area of rhombus $A B C D$ is ( ).
(A) 60
(B) 90
(C) 105
(D) 120
(E) 144
4. D.

From the given, we have $A B=\frac{52}{4}=13$.
In $\triangle A B C$, $A B=B C=13, A C=24$, by Heron's formula we get
$$
\begin{array}{l}
S_{\triangle A B C}=\sqrt{25 \times 12 \times 12}=60 \\
\Rightarrow S_{\text {Lobachevsky } A B C D}=60 \times 2=120 .
\end{array}
$$