Jim wrote the sequence of symbols $\triangle \wedge \backsim \diamond \odot \odot \diamond \triangleleft$ a total of 50 times. How many more $\odot$ symbols than symbols did he write?
(A) 50
(B) 150
(C) 200
(D) 250
(E) 275
Solution 1

The sequence of symbols includes 5 O's and 2 's.

This means that, each time the sequence is written, there are $5-2=3$ more $\bigcirc^{\prime}$ s written than $\mathbf{n}$ 's.

When the sequence is written 50 times, in total there are $50 \cdot 3=150$ more $\odot$ 's written than 's.

## Solution 2

The sequence of symbols includes 5 O's and 2 's.

When the sequence is written 50 times, there will be a total of $50 \cdot 5=250 \bigcirc$ 's written and a total of $50 \cdot 2=100$ 's written.

This means that there are $250-100=150$ more ''s written than 's.

ANsWER: (B)