The mean (average) of the three integers $p, q$ and $r$ is 9 .

The mean of the two integers $s$ and $t$ is 14 .

The mean of the five integers $p, q, r, s$, and $t$ is
(A) 11
(B) 11.5
(C) 12
(D) 10
(E) 13
Since the mean of $p, q$ and $r$ is 9 , then $\frac{p+q+r}{3}=9$ and so $p+q+r=27$.

Since the mean of $s$ and $t$ is 14 , then $\frac{s+t}{2}=14$ or $s+t=28$.

Therefore, the mean of the five integers is $\frac{p+q+r+s+t}{5}=\frac{(p+q+r)+(s+t)}{5}=\frac{27+28}{5}$, which equals 11.

ANSWER: (A)