1. Choose several numbers from $1,2, \cdots, 7$, such that the sum of the even numbers equals the sum of the odd numbers. Then the number of ways to choose the numbers that meet the condition is ( ) kinds.
(A) 6
(B) 7
(C) 8
(D) 9
-1. B.
Notice that, $2+4+6=12$, so the sum of the numbers taken out is no more than 24.
$$
\begin{array}{l}
\text { Also } 12=2+4+6=5+7, \\
10=4+6=3+7, \\
8=2+6=1+7=3+5, \\
6=6=2+4=1+5, \\
4=4=1+3,
\end{array}
$$

Therefore, there are 7 ways to choose the numbers.