Problems 7, 8 and 9 are about these kites.
To promote her school's annual Kite Olympics, Genevieve makes a small kite and a large kite for a bulletin board display. The kites look like the one in the diagram. For her small kite Genevieve draws the kite on a one-inch grid. For the large kite she triples both the height and width of the entire grid.

[asy]
for (int a = 0; a < 7; ++a)
{
for (int b = 0; b < 8; ++b)
{
dot((a,b));
}
}
draw((3,0)--(0,5)--(3,7)--(6,5)--cycle);[/asy]


What is the number of square inches in the area of the small kite? 

$ \text{(A)}\ 21\qquad\text{(B)}\ 22\qquad\text{(C)}\ 23\qquad\text{(D)}\ 24\qquad\text{(E)}\ 25 $
To find the area of the small kite, we can use the Shoelace Theorem or divide the kite into simpler geometric shapes. Here, we will use the method of dividing the kite into triangles and rearranging them into a rectangle.

1. **Identify the vertices of the kite:**
   The vertices of the kite are given as \((3,0)\), \((0,5)\), \((3,7)\), and \((6,5)\).

2. **Divide the kite into triangles:**
   We can divide the kite into four triangles by drawing lines from the center of the kite to each vertex. The center of the kite is at the intersection of the diagonals. The diagonals intersect at the midpoint of each diagonal.

3. **Calculate the area of each triangle:**
   The kite can be divided into two pairs of congruent triangles. Each pair of triangles can be rearranged to form a rectangle.

   - The first pair of triangles are \(\triangle (3,0), (0,5), (3,5)\) and \(\triangle (3,0), (3,5), (6,5)\).
   - The second pair of triangles are \(\triangle (3,5), (0,5), (3,7)\) and \(\triangle (3,5), (3,7), (6,5)\).

4. **Calculate the area of the rectangle formed by rearranging the triangles:**
   - The base of the rectangle is the length of the horizontal diagonal, which is 6 units (from \((0,5)\) to \((6,5)\)).
   - The height of the rectangle is the length of the vertical diagonal, which is 7 units (from \((3,0)\) to \((3,7)\)).

   Therefore, the area of the rectangle is:
   \[
   \text{Area} = \text{base} \times \text{height} = 6 \times 7 = 42 \text{ square units}
   \]

5. **Divide the area by 2 to get the area of the kite:**
   Since the kite is formed by two congruent triangles, the area of the kite is half the area of the rectangle:
   \[
   \text{Area of the kite} = \frac{42}{2} = 21 \text{ square units}
   \]

Conclusion:
The number of square inches in the area of the small kite is \(\boxed{21}\).