15. A conductor must select some people from 6 tenors and 8 baritones to form a chorus. The difference in the number of tenors and baritones must be a multiple of 4, and the chorus must have at least one person. Let $N$ be the number of different combinations that can be selected, then the remainder when $N$ is divided by 100 is ( ).
(A) 47
(B) 48
(C) 83
(D) 95
(E) 96
15. D.

As shown in Table 2.
Table 2
\begin{tabular}{|c|c|c|}
\hline \begin{tabular}{c} 
Tenor \\
(Number)
\end{tabular} & \begin{tabular}{c} 
Bass \\
(Number)
\end{tabular} & Combination Number \\
\hline 0 & 4,8 & $\mathrm{C}_{6}^{0}\left(\mathrm{C}_{8}^{4}+\mathrm{C}_{8}^{8}\right)=71$ \\
1 & 1,5 & $\mathrm{C}_{6}^{1}\left(\mathrm{C}_{8}^{1}+\mathrm{C}_{8}^{5}\right)=384$ \\
2 & 2,6 & $\mathrm{C}_{6}^{2}\left(\mathrm{C}_{8}^{2}+\mathrm{C}_{8}^{6}\right)=1556$ \\
3 & 3,7 & $\mathrm{C}_{6}^{3}\left(\mathrm{C}_{8}^{3}+\mathrm{C}_{8}^{7}\right)=1280$ \\
4 & $0,4,8$ & $\mathrm{C}_{6}^{4}\left(\mathrm{C}_{8}^{0}+\mathrm{C}_{8}^{4}+\mathrm{C}_{8}^{8}\right)=1080$ \\
5 & 1,5 & $\mathrm{C}_{6}^{5}\left(\mathrm{C}_{8}^{1}+\mathrm{C}_{8}^{5}\right)=384$ \\
6 & 2,6 & $\mathrm{C}_{6}^{6}\left(\mathrm{C}_{8}^{2}+\mathrm{C}_{8}^{6}\right)=56$ \\
\hline \multicolumn{3}{|c|}{ Total } \\
\hline
\end{tabular}

Therefore, the required result is $4095 \equiv 95(\bmod 100)$.