2. (2 points) It is known about the numbers $x_{1}$ and $x_{2}$ that $x_{1}+x_{2}=2 \sqrt{1703}$ and $\left|x_{1}-x_{2}\right|=90$. Find $x_{1} \cdot x_{2}$.
Solution: Let $A=x_{1}+x_{2}, B=x_{1} \cdot x_{2}, C=\left|x_{1}-x_{2}\right|$. Since $C^{2}=A^{2}-4 \cdot B$, we find $B=-322$.

Answer: -322 .