2. (3 points) There are five gifts priced at 2 yuan, 5 yuan, 8 yuan, 11 yuan, and 14 yuan, and five gift boxes priced at 3 yuan, 6 yuan, 9 yuan, 12 yuan, and 15 yuan. One gift is paired with one gift box, resulting in $\qquad$ different prices.
【Analysis】According to the known prices, the "list method" can be used to solve it.
【Solution】Solution:
\begin{tabular}{|l|c|c|c|c|c|c|c|}
\hline Packaging \\
\hline & 3 \\
\hline
\end{tabular}

There are 25 possible combinations, among which there are cases of repeated prices. A total of 5 yuan, 8 yuan, 11 yuan, 14 yuan, 17 yuan, 20 yuan, 23 yuan, 26 yuan, and 29 yuan can be formed,

There are 9 different prices in total.

Therefore, the answer is: 9.