(1) Given the set $M=\{2,0,11\}$, if $A \varsubsetneqq M$, and $A$ contains at least one even number. Then the number of sets $A$ that satisfy the condition is $\qquad$ .
(1) 5 Hint: Method 1 The sets $A$ that satisfy the condition are: $\{2\},\{0\},\{2,0\}$, $\{2,11\},\{0,11\}$, a total of 5.

Method 2 The proper subsets of set $M$ are $2^{3}-1=7$ in number, among which the subsets that do not contain even numbers are $\phi$ and $\{11\}$, 2 in number. Therefore, the sets $A$ that satisfy the condition are $7-2=5$ in number.