235. The surface area of a spherical segment is $S$ (the spherical part of the segment is considered). Find the maximum value of the volume of this segment.
235. If $h$ is the height of the segment, then its volume is $\frac{1}{2} S h - \frac{1}{3} \pi h^{3}$. The maximum volume will be at $h = \sqrt{\frac{S}{2 \pi}}$; it will be equal to $\frac{S}{3} \sqrt{\frac{S}{2 \pi}}$