The value of $\frac{1}{2}+\frac{1}{4}$ is
(A) 1
(B) $\frac{1}{8}$
(C) $\frac{1}{6}$
(D) $\frac{2}{6}$
(E) $\frac{3}{4}$
The value of $\frac{1}{2}+\frac{1}{4}$ is
(A) 1
(B) $\frac{1}{8}$
(C) $\frac{1}{6}$
(D) $\frac{2}{6}$
(E) $\frac{3}{4}$

## Solution

Using a common denominator,

$\frac{1}{2}+\frac{1}{4}=\frac{2}{4}+\frac{1}{4}=\frac{3}{4}$.

ANSWER: (E)