6. If real numbers $x, y$ satisfy $(x+5)^{2}+(y-12)^{2}=14^{2}$, then the minimum value of $x^{2}+y^{2}$ is
A. 2
B. 1
C. $\sqrt{3}$
D. $\sqrt{2}$
6. $\mathrm{B}(x+5)^{2}+(y-12)^{2}=14^{2}$ represents a circle with center $C(-5,12)$ and radius 14. Let $P$ be any point on the circle, then $|O P| \geqslant|C P|-|O C|=1$. The equality holds when $C$, $O$, and $P$ are collinear, and $P$ and $C$ are on opposite sides of $O$.