(1) If the solution set of the inequality $\frac{1}{2} x^{2}-2 x+m x<0$ with respect to $x$ is $\{x \mid 0<x<$ $2\}$, then $m=$ $\qquad$ .
(1) 1 Hint: According to the problem, 2 is a real root of the equation $\frac{1}{2} x^{2}-2 x+m x=0$. Substituting and calculating, we get $m=1$.