The sum of four numbers is $T$. Suppose that each of the four numbers is now increased by 1 . These four new numbers are added together and then the sum is tripled. What is the value of this final result?
(A) $3 T+3$
(B) $3 T+4$
(C) $3 T+12$
(D) $T+12$
(E) $12 T$
If each of the four numbers is increased by 1 , then the increase in their sum is 4 .

That is, these four new numbers when added together have a sum that is 4 more than their previous sum $T$, or $T+4$.

This new sum $T+4$ is now tripled.

The result is $3 \times(T+4)=(T+4)+(T+4)+(T+4)$ or $3 T+12$.

ANswer: $(\mathrm{C})$