14. Let the four idioms "一家之言", "言扬行举", "举世皆知", "知行合一" each character represent one of 11 consecutive non-zero natural numbers, with the same character representing the same number and different characters representing different numbers. If the sum of the numbers represented by the four characters in each idiom is 21, what is the largest number that "行" can represent?

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【Answer】 8
【Solution】 It is not difficult to observe that the characters “一, “言”, “举”, “知”, “行” each appear twice, while the other Chinese characters appear only once. Let the numbers represented by these five characters be $a, b, c, d, e$ (all positive integers),

Assume the 11 consecutive natural numbers are $(x+1),(x+2), \cdots,(x+11)$,
then $(x+1)+(x+2)+\cdots+(x+11)+a+b+c+d+e=21 \times 4$,
which simplifies to $11 x+a+b+c+d+e=18$, so $x=0$, and when $a+b+c+d=1+2+3+4=10$, $e$ is maximized at 8, and the 11 numbers are 1 to 11. We can construct “一家之言”、“言扬行举”、“举世皆知”、“知行合一” as “ $3,5,11,2 $”, “ $2$, $10,8,1$ ", "1, 9, 7, 4", “ $4,8,6,3$ ".
In summary, the number that “行” can represent is maximized at 8.