5.1. For the celebration of the Name Day in the 5th grade parallel, several pizzas were ordered. 14 pizzas were ordered for all the boys, with each boy getting an equal share. Each girl also received an equal share, but half as much as each boy. How many pizzas were ordered if it is known that there are 13 girls in this parallel, and there are more boys than girls? Pizzas can be divided into parts.
# Answer: 15

Solution. Let the number of boys be $m$, and the number of pizzas that the girls received be $x$. If each boy had eaten as much as each girl, the boys would have eaten 7 pizzas. Then $m: 13=7: x$, from which $m x=91$. The number 91 has only one divisor greater than 13, which is 91. Therefore, $m=91, x=1$, the answer is $14+1=15$ pizzas (unfortunately, only one pizza was ordered for 13 girls, but this was by their choice).