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Try to find two consecutive numbers; the sum of the digits of the first one is 8, and the second one is divisible by 8.

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Think about what can be said about the sum of the digits of a number if the sum of the digits of the previous number is 8.

## Solution

The sum of the digits of the second number will be 9 (there cannot be a transition over 9, as the first number does not have the digit 9). The smallest number that is a multiple of both 9 (the sum of the digits is 9) and 8 (by the condition) is 72. The sum of the digits of the previous number 71 is 8.

## Answer

71 and 72.