7. In the Cartesian coordinate system, the figure determined by
$$
|x|+|y|+|x+y| \leqslant 2
$$

has an area of $\qquad$
II. 7.3.
From the problem, we know that the determined figure is an isosceles right triangle with a side length of 1 in the first and third quadrants, and a square with a side length of 1 in the second and fourth quadrants, with a total area of 3.