Tina writes four letters to her friends Silas, Jessica, Katie, and Lekan. She prepares an envelope for Silas, an envelope for Jessica, an envelope for Katie, and an envelope for Lekan. However, she puts each letter into a random envelope. What is the probability that no one receives the letter they are supposed to receive?
1. **Identify the total number of ways to distribute the letters:**
   - Tina has 4 letters and 4 envelopes. The total number of ways to distribute the letters into the envelopes is given by the factorial of 4:
   \[
   4! = 24
   \]

2. **Identify the number of derangements (permutations where no element appears in its original position):**
   - A derangement is a permutation of a set where none of the elements appear in their original positions. The number of derangements of 4 items, denoted as \( !4 \), can be calculated using the formula:
   \[
   !n = n! \sum_{k=0}^{n} \frac{(-1)^k}{k!}
   \]
   For \( n = 4 \):
   \[
   !4 = 4! \left( \frac{(-1)^0}{0!} + \frac{(-1)^1}{1!} + \frac{(-1)^2}{2!} + \frac{(-1)^3}{3!} + \frac{(-1)^4}{4!} \right)
   \]
   \[
   !4 = 24 \left( 1 - 1 + \frac{1}{2} - \frac{1}{6} + \frac{1}{24} \right)
   \]
   \[
   !4 = 24 \left( 1 - 1 + 0.5 - 0.1667 + 0.0417 \right)
   \]
   \[
   !4 = 24 \left( 0.375 \right)
   \]
   \[
   !4 = 9
   \]

3. **Calculate the probability:**
   - The probability that no one receives the letter they are supposed to receive is the ratio of the number of derangements to the total number of permutations:
   \[
   P(\text{no one receives their own letter}) = \frac{!4}{4!} = \frac{9}{24} = \frac{3}{8}
   \]

The final answer is \(\boxed{\frac{3}{8}}\).