1.  Given $A, B$ are two interior angles of an acute $\triangle ABC$, then the point corresponding to the complex number $z=(\cos B-\sin A)+i(\sin B-\cos A)$ in the complex plane is located in
(A) the first quadrant
(B) the second quadrant
(C) the third quadrant
(D) the fourth quadrant
(B)
1.【Analysis and Solution】Since $A+B\sin \left(\frac{\pi}{2}-A\right)=\cos A \\
\cos B-\sin A0 .
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It indicates that $z$ is located in the second quadrant.