What is the area, in $\mathrm{m}^{2}$, of the shaded part of the rectangle?
(A) 14
(D) 56
(B) 28
(E) 42
(C) 33.6

![](https://cdn.mathpix.com/cropped/2024_04_20_46ead6524a8d61e21c51g-101.jpg?height=184&width=504&top_left_y=2101&top_left_x=1277)
What is the area, in $\mathrm{m}^{2}$, of the shaded part of the rectangle?
(A) 14
(B) 28
(C) 33.6
(D) 56
(E) 42

![](https://cdn.mathpix.com/cropped/2024_04_20_748fdafcde2a47412608g-443.jpg?height=223&width=580&top_left_y=1119&top_left_x=1401)

## Solution

The two unshaded triangles each have a base of $7 \mathrm{~m}$ and a height of $4 \mathrm{~m}$. This means that each of the triangles has an area of $\frac{7 \times 4}{2}=14 \mathrm{~m}^{2}$. The two triangles thus have a total area of $28 \mathrm{~m}^{2}$.

The shaded triangles have an area of $56-28=28 \mathrm{~m}^{2}$.

ANSWER: (B)