141. $5,2^{(x+2)(x+3)}=1$.

141. $5,2^{(x+2)(x+3)}=1$.
Solution. Any non-zero number to the power of zero equals one; therefore, we can write $1=5.2^{0}$. Thus, $5.2^{(x-2)(x+3)}=5.2^{0}$, from which $(x-2)(x+3)=0$. According to the property of multiplication, $x-2=0$ or $x+3=0$, i.e., $x=2, x=-3$.