$3+$ [ Examples and counterexamples. Constructions]

In the product of seven natural numbers, each factor was decreased by 3. Could the product have increased exactly 13 times as a result?

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The product $1 \cdot 1 \cdot 1 \cdot 1 \cdot 1 \cdot 2 \cdot 16=32$ after the specified operation turns into $(-2)^{5} \cdot(-1) \cdot 13=13 \cdot 32$.

## Answer

It could.