3. (5 points) In the figure, $ABCD$ and $DEFG$ are both squares. Given that $CE=14, AG=2$, the sum of the areas of the two squares is $\qquad$ .


【Solution】Solution: Let the side length of the larger square be $a$, and the side length of the smaller square be $b$, then $a+b=14$ (1), $a-b=2$ (2),
(1)+(2) gives: $2 a=16$,
$$
\begin{array}{l}
a=8, \\
b=14-8=6,
\end{array}
$$

Therefore: $8 \times 8+6 \times 6$,
$$
\begin{array}{l}
=64+36, \\
=100 ;
\end{array}
$$

Answer: The sum of the areas of the two squares is 100.
So the answer is: 100.