610. A natural number is written using 10 sixes and several zeros. Can it be an exact power?

Can it be an exact power?
$\triangle$ The sum of the digits of this number is 60. Based on the divisibility rules for 3 and 9, the number is divisible by 3, but not by $3^{2}=9$. Therefore, it cannot be a perfect square, a perfect cube, or any perfect power with a natural exponent greater than 1.

Answer: cannot.