$1^{2} / 3 \%$ of the country's students are engaged with math magazines, specifically $2^{1} / 3 \%$ of the boys and $2 / 3 \%$ of the girls. How many boys and how many girls are engaged with the magazines among 75000 students?
Let the number of male students be $u$, and the number of female students be $v$. Then the number of male students interested in mathematics is $7 u / 300$, and the number of female students interested in mathematics is $2 v / 300$. Thus, the following system of equations holds for $u$ and $v$:

$$
\begin{gathered}
u+v=75000 \\
\frac{7}{300} u+\frac{2}{300} v=\frac{5}{300} 75000
\end{gathered}
$$

The solution to this system is: $\quad u=45000, \quad v=30000$.

Thus, the number of male students interested in mathematics is 1050; the number of female students is 200.