20. (3 points) Xiao Qiang and Xiao Lin have more than 400 stamps in total. If Xiao Qiang gives some stamps to Xiao Lin, Xiao Qiang's stamps will be $\frac{6}{19}$ fewer than Xiao Lin's; if Xiao Lin gives the same number of stamps to Xiao Qiang, then Xiao Lin's stamps will be $\frac{6}{17}$ fewer than Xiao Qiang's. Therefore, Xiao Qiang originally had $\qquad$ stamps, and Xiao Lin originally had $\qquad$ stamps.
【Solution】Solution: $\left(1-\frac{6}{19}\right): 1=13: 19,13+19=32$;
$1:\left(1-\frac{6}{17}\right)=17: 11,17+11=28$,
The least common multiple of 32 and 28 is 224, Xiao Qiang and Xiao Lin have more than 400 stamps in total, so they have $224 \times 2=448$ stamps, $448 \div 32 \times 13=182,448 \div 28 \times 17=272$.

Xiao Qiang: $(182+272) \div 2=227$ stamps
Xiao Lin: $448-227=221$.
Therefore, the answers are: 227,221.