Jane and Josh wish to buy a candy. However Jane needs seven more cents to buy the candy, while John needs one more cent. They decide to buy only one candy together, but discover that they do not have enough money. How much does the candy cost?
1. Let \( C \) be the cost of the candy in cents.
2. Let \( J \) be the amount of money Jane has in cents.
3. Let \( H \) be the amount of money John has in cents.

From the problem, we know:
- Jane needs 7 more cents to buy the candy, so \( J + 7 = C \).
- John needs 1 more cent to buy the candy, so \( H + 1 = C \).

4. They decide to combine their money but still do not have enough to buy the candy. This means:
\[ J + H < C \]

5. Substitute \( C \) from the equations above:
\[ J + H < J + 7 \]
\[ H < 7 \]

6. Substitute \( C \) from the equations above:
\[ J + H < H + 1 \]
\[ J < 1 \]

7. Since Jane needs 7 more cents, we have:
\[ J + 7 = C \]
\[ J < 1 \]

8. Since \( J \) is less than 1 cent and \( J + 7 = C \), the only possible value for \( J \) is 0 cents (as Jane cannot have negative money):
\[ J = 0 \]

9. Substitute \( J = 0 \) into \( J + 7 = C \):
\[ 0 + 7 = C \]
\[ C = 7 \]

Therefore, the cost of the candy is \( \boxed{7} \) cents.