7. Let $A>B>0$, and $A$ is $x \%$ larger than $B$. Then $x=(\quad)$.
(A) $100\left(\frac{A-B}{B}\right)$
(B) $100\left(\frac{A+B}{B}\right)$
(C) $100\left(\frac{A+B}{A}\right)$
(D) $100\left(\frac{A-B}{A}\right)$
(E) $100 \frac{A}{B}$
7. A. From $A=B(1+x \%) \Rightarrow x=100\left(\frac{A}{B}-1\right)$.