(2 $[x]$ represents the greatest integer not exceeding the real number $x$. Then, in the Cartesian coordinate system $x O y$, the area of the figure formed by all points $(x, y)$ satisfying $[x] \cdot [y]=2013$ is $\qquad$ .
(2) 16 Hint: Let $[x]=a,[y]=b$, that is, the figure formed by all such points $(x, y)$ is the region enclosed by the inequalities $a \leqslant x<a+1, b \leqslant y<b+1$, with an area of 1.

Since $2013=1 \times 2013=3 \times 671=11 \times 183=33 \times 61$, the points $(x, y)$ that satisfy $[x] \cdot[y]=2013$ form 16 regions each with an area of 1, thus the total area is 16.