2) A two-digit number is added to the number obtained by reversing its digits. The sum obtained is then divided by the sum of the digits of the given number, and the result is squared. What number is obtained?
(A) 36
(B) 49
(C) 100
(D) 121
(E) it depends on the digits of the given number.
2) The answer is (D). Indicating with $a$ and $b$ the two digits of the number, the sequence of operations can be expressed in the following way:

$$
\left(\frac{(10 a+b)+(10 b+a)}{a+b}\right)^{2}=\left(\frac{11 a+11 b}{a+b}\right)^{2}=\left(\frac{11(a+b)}{a+b}\right)^{2}=11^{2}=121
$$