3. If the complex number $z$ satisfies $z+|z|=2+8 \mathrm{i}$, then $|z|^{2}$ equals
A. 68
B. 169
C. 208
D. 289
3. $\mathrm{D}|z| \in \mathbf{R}$ can be set as $z=a+8 \mathrm{i}(a \in \mathbf{R}), a+\sqrt{a^{2}+64}=2, a=-15$, so $|z|^{2}=15^{2}+8^{2}=$ $17^{2}=289$.