3. Let $x \in(-1,1), f(x)$ be an even function, $g(x)$ be an odd function, and $f(x)+$ $g(x)=-2 \log (1+x)$, then $10^{f(x)}=$ $\qquad$ , $10^{g(x)}=$ $\qquad$ .
$10^{f(x)}=\frac{1}{1-x^{2}}, 10^{g(x)}=\frac{1-x}{1+x} ;$