1. Among the positive integers not greater than 2017, there are $\qquad$ numbers that are divisible by 12 but not by 20.
$$
\left[\frac{2017}{12}\right]-\left[\frac{2017}{60}\right]=168-33=135 .
$$

Solve
$$
\left[\frac{2017}{12}\right]-\left[\frac{2017}{60}\right]=168-33=135 .
$$