The roots of $(x^{2}-3x+2)(x)(x-4)=0$ are:
$\textbf{(A)}\ 4\qquad\textbf{(B)}\ 0\text{ and }4\qquad\textbf{(C)}\ 1\text{ and }2\qquad\textbf{(D)}\ 0,1,2\text{ and }4\qquad\textbf{(E)}\ 1,2\text{ and }4$
Factor $x^2-3x+2$ to get $(x-2)(x-1).$ The roots are $\boxed{\mathrm{(D)}\ 0,1,2\text{ and }4.}$