5. The number of real roots of the equation $x|=i-3| x \mid+2=0$ is:
(A) 1; (B) 2; (C) 3; (D) 4.
Answer: (C).
When $x>0$, the equation $x^{2}-3 x+2=0$ yields $x=1$ or 2;
When $x<0$, the equation is $-x^{2}+3 x+2=0$, yielding $x=\frac{3 \pm \sqrt{17}}{2}$. Since $x<0$, we should discard $x=\frac{3+\sqrt{17}}{2}$.
Therefore, there are three real roots.