The average of $10,4,8,7$, and 6 is
(A) 33
(B) 13
(C) 35
(D) 10
(E) 7
The average of $10,4,8,7$, and 6 is
(A) 33
(B) 13
(C) 35
(D) 10
(E) 7

Solution

$\frac{10+4+8+7+6}{5}=\frac{35}{5}=7$

ANSWER: (E)