In a tennis tournament there are participants from $n$ different countries. Each team consists of a coach and a player whom should settle in a hotel. The rooms considered for the settlement of coaches are different from players' ones. Each player wants to be in a room whose roommates are [b][u]all[/u][/b] from countries which have a defense agreement with the player's country. Conversely, each coach wants to be in a room whose roommates are [b][u]all[/u][/b] from countries which don't have a defense agreement with the coach's country. Find the minimum number of the rooms such that we can [u][b]always[/b][/u] grant everyone's desire.

[i]proposed by Seyed Reza Hosseini and Mohammad Amin Ghiasi[/i]
1. **Define the problem and notation:**
   - Let there be \( n \) countries.
   - Each team consists of a coach and a player.
   - Players and coaches are to be settled in separate rooms.
   - Players want to be in rooms with players from countries that have a defense agreement (friends).
   - Coaches want to be in rooms with coaches from countries that do not have a defense agreement (enemies).

2. **Room allocation for players:**
   - Suppose players are allocated into \( k \) rooms, denoted as \( a_1, a_2, \ldots, a_k \).
   - Clearly, \( k \leq n \) because each room can have players from different countries.

3. **Claim: \( n+1 \) rooms are sufficient to satisfy everyone's wishes.**
   - Assume the player from a specific country (say Fire country) is in room \( a_j \).
   - Without loss of generality, assume that in every room \( a_i \) with \( i < j \), the player from Fire country has at least one enemy. If not, we can move the player to room \( a_i \).

4. **Room allocation for coaches:**
   - For room \( a_1 \), since all players are friends, their coaches must be placed in separate rooms, denoted as \( b(1,1), b(1,2), \ldots, b(1,a_1) \).
   - For room \( a_2 \), each player has an enemy in room \( a_1 \). Thus, their coaches can be placed in one of the previous rooms. Allocate separate rooms for the remaining coaches of players in room \( a_2 \), denoted as \( b(2,1), \ldots, b(2,a_2-1) \).

5. **Inductive step for room allocation:**
   - For a player \( A \) from room \( a_i \) (where \( i > 2 \)), place their coach in the first room that fits, starting from the last room \( b(i-1,a_{i-1}-1) \).
   - If \( A \) has an enemy country player \( B_j \) in room \( a_j \) (where \( j < i \)), and the coach of \( B_{i-1} \) is in one of the rooms \( b(i-1,1), \ldots, b(i-1,a_{i-1}-1) \), place \( A \)'s coach in the same room.
   - If \( B_{i-1} \)'s coach is not in these rooms, it means they are in one of the previous rooms. Due to the special room allotting system, from room \( a_{i-1} \), only one player’s coach is in previous rooms.

6. **Conclusion:**
   - If \( A \)'s coach cannot be placed in any of the rooms \( b(i-1,1), \ldots, b(i-1,a_{i-1}-1) \), then any coach of a player from room \( a_{i-1} \) who is in any of the rooms \( b(1,1), \ldots, b(i-2,a_{i-2}-1) \) must be from an enemy country of \( A \).
   - Inductively, if \( B_j \)'s coach is in any of the rooms \( b(i-j,1), \ldots, b(i-j,a_{i-j}-1) \), place \( A \)'s coach with them.
   - If not, it means they are in one of the previous rooms, \( b(1,1), \ldots, b(j-1,a_{j-1}-1) \). Due to the special room allotting system, from room \( a_j \), only one player’s coach is in previous rooms.
   - Finally, place \( A \)'s coach with \( B_1 \)'s coach in one of the rooms \( b(1,1), \ldots, b(1,a_1) \).

7. **Calculation of total rooms:**
   - The number of rooms needed for coaches is \( a_1 + \sum_{k \ge i \ge 2} a_i - 1 = n - k + 1 \).
   - Total number of rooms is \( k + n - k + 1 = n + 1 \).

8. **Special case:**
   - If all countries are friends, \( k = 1 \), and all coaches need separate rooms. Thus, \( n + 1 \) rooms are necessary.

The final answer is \( \boxed{ n + 1 } \).