In the diagram $\triangle PQR$ is isosceles. The value of $x$ is 
(A) 40
(B) 70
(C) 60
(D) 30
(E) 110

![](https://cdn.mathpix.com/cropped/2024_04_20_46ead6524a8d61e21c51g-065.jpg?height=412&width=439&top_left_y=813&top_left_x=1296)
Since $P Q=P R$, then $\angle P Q R=\angle P R Q$.

Since the angles in a triangle add up to $180^{\circ}$, then $40^{\circ}+\angle P Q R+\angle P R Q=180^{\circ}$,

so $\angle P Q R+\angle P R Q=140^{\circ}$.

Since $\angle P Q R=\angle P R Q$, then $\angle P Q R=\angle P R Q=70^{\circ}$.

Since the angle labelled as $x^{\circ}$ is opposite $\angle P R Q$, then $x^{\circ}=\angle P R Q=70^{\circ}$, so $x=70$.

ANSWER: (B)