17. Fill in $2013 \times 1, 2013 \times 2, 2013 \times 3, 2013 \times 4, 2013 \times 5, 2013 \times 6, 2013 \times 7, 2013 \times 8, 2013 \times 9, 2013 \times 10, 2013 \times 11$ into the table below, so that the numbers filled in can be divided by the position number of their respective columns. Then there are $\qquad$ different ways to fill in the table.
【Analysis】Since $2013=3 \times 11 \times 61$
Therefore, among 1 to 11, the divisors of 3 are $1, 3, 11$ these three
So, apart from $2013 \times 1, 2013 \times 2, 2013 \times 3, 2013 \times 6, 2013 \times 9, 2013 \times 11$ these six numbers which can
exchange positions with each other,
the rest $2013 \times 4, 2013 \times 5, 2013 \times 7, 2013 \times 8, 2013 \times 10$ must be filled under $4, 5, 7, 8, 10$
$2013 \times 2, 2013 \times 6$ can be filled under 2, 6, with 2 ways to fill
9 can be filled with $2013 \times 3, 2013 \times 9$, with 2 ways to fill
The remaining 3 numbers can be filled under $1, 3, 11$ arbitrarily, with 6 ways to fill
In total, there are $2 \times 2 \times 6=24$ ways to fill