## Task 1 - 190611

From a bus station, four buses depart simultaneously at 12:00. The time until each bus returns and departs again from the same bus station is $\frac{3}{4} \mathrm{~h}$ for the first bus, $\frac{1}{2} \mathrm{~h}$ for the second bus, 36 minutes for the third bus, and 1 hour for the fourth bus.

At what time will all four buses depart from the bus station simultaneously for the first time after this?

How many trips has each of the four buses completed by then?
The departure times are

for the first bus: $12.00, 12.45, 13.30, 14.15, 15.00, \ldots$,

for the second bus: 12.00, 12.30, 13.00, 13.30, 14.00, 14.30, 15.00, ...,

for the third bus: 12.00, 12.36, 13.12, 13.48, 14.24, 15.00, ...,

for the fourth bus: 12.00, 13.00, 14.00, 15.00, ...,

From this, it can be seen: The four buses depart simultaneously again at 15.00. By then, the first bus has made 4 trips, the second bus 6 trips, the third bus 5 trips, and the fourth bus 3 trips.