What is the height of the tower that appears twice as large at an angle from 18 meters compared to 48 meters?
$\beta=2 \alpha-\alpha=\alpha$, therefore $D C=30$.

$m=\sqrt{30^{2}-18^{2}}=24 \mathrm{~m}$.

![](https://cdn.mathpix.com/cropped/2024_05_02_064e2e1818a53beb1ae6g-1.jpg?height=504&width=705&top_left_y=236&top_left_x=691)