1. Mrs. Pekmezac loves fruit. In her garden, she harvested $5 \frac{3}{4} \mathrm{~kg}$ of blueberries, $4 \frac{1}{2} \mathrm{~kg}$ of cherries, $2 \frac{19}{20} \mathrm{~kg}$ of raspberries, and $1 \frac{4}{5} \mathrm{~kg}$ of blackberries. She decided to store the fruit in the refrigerator, in bags of 75 dag. Fruit of different types can be stored in the same bag. How many bags does she need to prepare at a minimum?
First method: The total amount of fruit harvested is

$5 \frac{3}{4}+4 \frac{1}{2}+2 \frac{19}{20}+1 \frac{4}{5}=\frac{23}{4}+\frac{9}{2}+\frac{59}{20}+\frac{9}{5}=$

2 POINTS

$=\frac{115+90+59+36}{20}=\frac{300}{20}=15 \text{ kg}$

2 POINTS

75 dag $=0.75 \text{ kg}$

1 POINT

She needs to prepare $15: 0.75=1500: 75=20$ bags.

NOTE 1: The correct determination of the total mass of the fruit, regardless of the method of calculation and the unit of measurement, is awarded 4 points, and the number of bags needed is awarded an additional 2 points.