A5. What is the value of the expression $2 \cdot \frac{0, \overline{6}-1,2^{-1}}{\frac{1}{3}-1}+(4-3)^{2}$ ?
(A) 0.5
(B) 1
(C) $1, \overline{3}$
(D) $\frac{3}{2}$
(E) $\frac{5}{4}$
A5. We write $0, \overline{6}$ as a fraction with the simplified fraction $\frac{2}{3}$. Similarly, we write 1.2 as a simplified fraction and consider the negative exponent. We simplify the double fraction and get $\frac{1}{4}$. Then we multiply this by 2 and add the result of the expression in parentheses, which is 1. The value of the expression is $\frac{3}{2}$.