If $\frac{n+1999}{2}=-1$, then the value of $n$ is
(A) -2001
(B) -2000
(C) -1999
(D) -1997
(E) 1999
If $\frac{n+1999}{2}=-1$, then the value of $n$ is
(A) -2001
(B) -2000
(C) -1999
(D) -1997
(E) 1999

## Solution

By inspection or by multiplying each side by 2 , we arrive at $n+1999=-2$ or $n=-2001$.

ANSWER: (A)