(11) There are 6 different books, including one math book, two English books, and three music books. Arrange them in a row so that the English books are not adjacent, and the music books are also not adjacent. The number of different arrangements is $\qquad$ .
11 Divide into two steps, first arrange the music books, there are $\mathrm{A}_{3}^{3}=6$ ways; then arrange the English and math books, if the math book is placed at the ends of the music books, then the English books must be placed separately in the middle of the music books, at this time there are $2 \times \mathrm{A}_{2}^{2}=4$ (ways) to arrange, if the math book is placed between the music books, then one English book must be placed between the other two music books, and the other English book is placed in one of the other 4 spaces, at this time there are $2 \times 2 \times 4=16$ (ways) to arrange.
By the principle of step-by-step, there are $6 \times(4+16)=120$ (ways) to arrange.