## Task 4 - 040814

The number $62^{* *} 427$ is divisible by 99.

Determine the missing digits, and explain how you found them! How many solutions are there?
The sum of the existing digits of the number $62 * * 427$ is 21. Since it is divisible by 9, its sum of digits must also be divisible by 9, so the following sums of digits are possible: 27 and 36.

The following numbers result in one of these sums of digits:

$6215427,6251427,6224427,6242427,6233427,6269427,6296427,6278427,6287427$

Now it must be checked which of these numbers are also divisible by the number 11. Thus, one obtains exactly one number that is divisible by 99, and that is: 6224427.