23. In a basketball game at a certain middle school, A scored $\frac{1}{4}$ of the total points, B scored $\frac{2}{7}$ of the total points, C scored 15 points, and the remaining seven players each scored no more than 2 points. Then the total score of the remaining seven players is ( ).
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
23. B.

Let the total score of all players be $S$. Then
$$
\frac{S}{4}, \frac{2 S}{7} \in \mathbf{Z}_{+} \Rightarrow 28 \text{ divides } S.
$$

Given that the total score of the remaining seven players is $x$, we know
$$
\begin{array}{l}
x \leqslant 14 . \\
\text { Hence } \frac{S}{4}+\frac{2 S}{7}+15+x=S \\
\Rightarrow 0 \leqslant \frac{13 S}{28}-15=x \leqslant 14 \\
\Rightarrow 15 \leqslant \frac{13 S}{28} \leqslant 29 .
\end{array}
$$

Upon inspection, the only $S$ that satisfies 28 divides $S$ is 56. Therefore, $x=11$.