3. A company was manufacturing toys. They received an order that 20 workers could complete in 90 days. Due to summer vacations and leaves, only 10 workers worked for the first 40 days. At that point, they realized they were falling behind schedule, so they immediately hired 40 more workers. How many days did it take them to fulfill the order? By how many days did they fall behind or exceed the 90-day deadline?
3. Using the rule of three, we calculate how long it would take 10 workers to complete the work: $x=\frac{20 \cdot 90}{10}=180$ days. The remaining work is for 140 days $(180-40=140)$. The remaining work will be completed by 50 workers $(10+40)$. Using the rule of three, we calculate that they will complete the work in 28 days. Thus, the entire work was completed in 68 days $(40+28=68)$, and they finished 22 days ahead of schedule.

Using the rule of three: $x=\frac{20 \cdot 90}{10}=180$ days. ................................................................................... Calculation of the remaining work: $180-40=140$ days ................................................................................................

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Using the rule of three: $x=\frac{10 \cdot 140}{50}=28$ days.......................................................... Calculation of the days for completed work: $40+28=68$ days .............................................................. Answer: They finished 22 days ahead of schedule. ...............................................................................)