Evaluate $\frac{2^{5}-2^{3}}{2^{2}}$.
(A) 6
(B) 1
(C) $\frac{1}{4}$
(D) 0
(E) 30
Evaluate $\frac{2^{5}-2^{3}}{2^{2}}$.
(A) 6
(B) 1
(C) $\frac{1}{4}$
(D) 0
(E) 30

## Solution

Evaluating the given expression we would have

$$
\frac{2^{5}-2^{3}}{2^{2}}=\frac{32-8}{4}=\frac{24}{4}=6
$$

ANSWER: (A)