1. Let $A=[-2,4), B=\left\{x \mid x^{2}-a x-4 \leq 0\right\}$, if $B \subseteq A$, then the range of the real number $a$ is ( ).

A . $[-3,0)$
B . $[-2,0)$
C. $[0,2)$
D. $[0,3)$
【Answer】D

【Analysis】【Detailed】

Since $f(x)=x^{2}-a x-4$ opens upwards, and $\left\{x \mid x^{2}-a x-4 \leq 0\right\} \subseteq[-1,4)$, it follows that $\left\{\begin{array}{l}f(-2) \geq 0, \\ f(4)>0 \text {. Solving, we get } a \in[0,3) \text {. }\end{array}\right.$

Therefore, the answer is: D