35. Given that $a, b$ are opposite numbers, then $a^{2015} b^{2016}+a^{2016} b^{2017}+a^{2017} b^{2016}+a^{2016} b^{2015}=$
Answer: 0.
Solution: Since $a, b$ are opposite numbers,

we have
$$
a+b=0,
$$

the original expression $=a^{2015} b^{2015}(b+a)+a^{2016} b^{2016}(b+a)=0$.