3.43 When multiplying two numbers, one of which is 10 more than the other, a student made a mistake by reducing the tens digit of the product by 4. When dividing the resulting product by the smaller multiplier to check the answer, he got a quotient of 39 and a remainder of 22. Find the multipliers.
3.43 According to the condition, $x(x+10)-40-22=39 x$, where $x-$ is the sought smaller factor. From this, we find $x=31$ and $x+10=41$.

Answer: 31 and 41.