In the square shown, the numbers in each row, column, and diagonal multiply to give the same result. The sum of the two missing numbers is
(A) 28
(D) 38
(B) 15
(E) 72
(C) 30

| 12 | 1 | 18 |
| :---: | :---: | :---: |
| 9 | 6 | 4 |
|  |  | 3 |
In the square shown, the numbers in each row, column, and diagonal multiply to give the same result. The sum of the two missing numbers is
(A) 28
(D) 38
(B) 15
(C) 30
(E) 72

| 12 | 1 | 18 |
| :---: | :---: | :---: |
| 9 | 6 | 4 |
|  |  | 3 |

## Solution

The numbers in each row, column and diagonal multiply to give a product of (12)(1)(18) or 216. We are now looking for two numbers such that $(12)(9)(\quad)=216$ and $(1)(6)(\quad)=216$. The required numbers are 2 and 36 which have a sum of 38 .

ANSWER: (D)