5. (6 points) As shown in the figure, there are 3 rectangles. The length of rectangle (1) is 16 cm, and the width is 8 cm; the length and width of rectangle (2) are half of the length and width of rectangle (1); the length and width of rectangle (3) are half of the length and width of rectangle (2). Then the perimeter of this figure is $\qquad$ cm.
【Solution】Solve: $[16+(8+8 \div 2+8 \div 2 \div 2)] \times 2$
$$
\begin{array}{l}
=(16+14) \times 2 \\
=60 \text { (cm) }
\end{array}
$$

Answer: The perimeter of this figure is 60 cm.
Therefore, the answer is: 60.