There are 2 red, 5 yellow and 4 blue balls in a bag. If a ball is chosen at random from the bag, without looking, the probability of choosing a yellow ball is
(A) $\frac{2}{11}$
(B) $\frac{5}{11}$
(C) $\frac{4}{11}$
(D) $\frac{6}{11}$
(E) $\frac{7}{11}$
In total, there are $2+5+4=11$ balls in the bag.

Since there are 5 yellow balls, then the probability of choosing a yellow ball is $\frac{5}{11}$.

ANswer: (B)