3.3. Find the sum of all two-digit numbers for each of which the sum of the squares of the digits is 73 more than the product of the same digits.
Solution. Such two-digit numbers are $19, 89, 91, 98$. Their sum is 297.

Answer: 297. ( ( )

![](https://cdn.mathpix.com/cropped/2024_05_06_a8c31eb257d724803ce6g-04.jpg?height=61&width=813&top_left_y=635&top_left_x=673)