2. If one root of the equation $2 x^{2}-3 x+m=0$ is greater than -2 and less than -1, and the other root is greater than 2 and less than 3, then the range of values for $m$ is ( ).
(A) $m<\frac{9}{8}$
(B) $-14<m<\frac{9}{8}$
(C) $-9<m<-5$
(D) $-14<m<-2$
2. C.

Let $f(x)=2 x^{2}-3 x+m$.
From the given information, we can roughly sketch the graph of $y=f(x)$, knowing that $f(-2)>0, f(-1)>0$. Solving these inequalities simultaneously yields $-9<m<-5$.