5. Find four consecutive even numbers whose sum is 3924.
5. Since each even number differs from the previous even number by two, the second number differs from the first by two, the third by four, and the fourth by six. Together, they exceed the first number by $12(2+4+6=12)$.

Let's determine their sum if all were equal to the first number: $3924-12$ = 3912. Since in this case all four numbers are the same, we can determine the first number: $3912: 4=978$.

The next even number will be $980(978+2=980)$. Similarly, we determine the third $(980+2=982)$ and fourth numbers $(982+2=984)$.

Answer: $978,980,982,984$.