Each day, Jenny ate $ 20\%$ of the jellybeans that were in her jar at the beginning of the day. At the end of the second day, $ 32$ remained. How many jellybeans were in the jar originally?

$ \textbf{(A)}\  40\qquad \textbf{(B)}\  50 \qquad \textbf{(C)}\ 55 \qquad \textbf{(D)}\  60\qquad \textbf{(E)}\ 75$
1. Let \( x \) be the number of jellybeans in the jar originally.
2. Each day, Jenny eats \( 20\% \) of the jellybeans, which means \( 80\% \) of the jellybeans remain. Mathematically, this can be expressed as:
   \[
   \text{Remaining jellybeans at the end of the day} = 0.8 \times \text{jellybeans at the beginning of the day}
   \]
3. At the end of the first day, the number of jellybeans remaining is:
   \[
   0.8x
   \]
4. At the end of the second day, the number of jellybeans remaining is:
   \[
   0.8 \times 0.8x = 0.64x
   \]
5. We are given that at the end of the second day, 32 jellybeans remain. Therefore, we set up the equation:
   \[
   0.64x = 32
   \]
6. Solving for \( x \), we divide both sides by 0.64:
   \[
   x = \frac{32}{0.64}
   \]
7. Simplifying the division:
   \[
   x = \frac{32}{0.64} = 50
   \]

The final answer is \(\boxed{50}\).