【Question 15】  
The sum of two numbers, A and B, is 1149. When A is divided by B, the quotient is 8 and the remainder is 24. Therefore, A is $\qquad$
【Analysis and Solution】The problem of multiple times.
(Method One)
Let the number $y$ be $x$, then the number $x$ is $8x + 24$; according to the problem, we get $(8x + 24) + x = 1149$;

Solving for $x$ gives $x = 125$;
The number $x$ is $8 \times 125 + 24 = 1024$ or $1149 - 125 = 1024$.
(Method Two)
The number $y$ is $(1149 - 24) \div (1 + 8) = 125$;
The number $x$ is $8 \times 125 + 24 = 1024$ or $1149 - 125 = 1024$.