22. As shown in the figure, extend the sides $A B, B C, C D, D A$ of quadrilateral $A B C D$ to $E, F, G, H$, respectively, such that $\frac{B E}{A B}=\frac{C F}{B C}=\frac{D G}{C D}=\frac{A H}{D A}=\frac{4}{5}$. If the area of quadrilateral $A B C D$ is 100, then the area of quadrilateral $E F G H$ is $\qquad$
$388$