3. The sum of two natural numbers is 17402, one of which is a multiple of 10. Removing the unit digit of this number results in the other number. Then the difference between these two numbers is ( ).
(A) 10272
(B) 11700
(C) 13362
(D) 14238
(E) 15426
3. D.

Let one of the numbers be $\overline{A B C D 0}(0<A \leqslant 9,0 \leqslant$ $B, C, D \leqslant 9)$. Then the other number is $\overline{A B C D}$.
From the problem, we know
$$
\begin{array}{l}
\overline{A B C D 0}+\overline{A B C D}=17402 \\
\Rightarrow D=2, C=8, B=5, A=1 .
\end{array}
$$

Therefore, the answer is $15820-1582=14238$.