7.1 The number 100 was divided by some number less than 50, with a remainder of 6. By what number could the division have occurred?
Let $x$ be the number by which they divided, $m$ be the quotient: $100 = m \cdot x + 6$ (since 6 is the remainder, then $x > 6$, and $m \geq 2$, since $x < 50$) $m \cdot x = 94 = 2 \cdot 47$. From this, it is clear that the numbers $m$ and $x$ are exactly the numbers 2 and 47, i.e., $m = 2$, $x = 47$. (since the number 94 can only be represented as a product of two natural numbers in four ways: $1 \cdot 94, 94 \cdot 1, 2 \cdot 47, 47 \cdot 2$, then all ways except $2 \cdot 47$ are eliminated).

## Answer: 47.