Let $t$ be TNYWR.

Suppose that $O$ is the origin. Points $P(a, b)$ and $Q(c, 1)$ are in the first quadrant with $a=2 c$. If the slope of $O P$ is $t$ and the slope of $O Q$ is 1 , what is the slope of $P Q$ ?
$O$ has coordinates $(0,0)$ and $Q$ has coordinates $(c, 1)$.

Since the slope of $O Q$ is 1 , then $c=1$.

Since $a=2 c$, then $a=2$ which means that the coordinates of $P$ are $(2, b)$.

Since the slope of $O P$ is $t$, then $t=\frac{b-0}{2-0}$, which means that $b=2 t$.

$P$ has coordinates $(2,2 t)$ and $Q$ has coordinates $(1,1)$.

The slope of $P Q$ is thus $\frac{2 t-1}{2-1}$ which equals $2 t-1$.

Since the answer to (b) is 11 , then $t=11$.

This means that the slope of $P Q$ is $2 \cdot 11-1$ which equals 21 .

ANSWER: $132,11,21$