7. The edge length of a cube is 2, and it has a total of 20 points, including all vertices and midpoints of all edges. If any 3 of these points are taken as the vertices of a triangle, the number of triangles with an area equal to $\frac{3}{2}$ is $\qquad$ .
7. 96

As shown in the figure, the areas of $\triangle A M N, \triangle C M, \triangle C_{1} M N$, and $\triangle D_{1} M N$ are all $\frac{2}{3}$. Each face of the cube has 4 midlines connecting the midpoints of adjacent edges (such as $M N$), and there are 6 faces in total, so the number of triangles with an area of $\frac{2}{3}$ is $4 \times 4 \times 6=96$.