2. The solution set of the inequality $(x+1)(x+2)(x+3)>26 x-2$ is
2. $\{x \mid x>-8, x \neq 1\}$.

The original inequality is equivalent to
$$
x^{3}+6 x^{2}-15 x+8>0,
$$

which is
$$
(x-1)^{2}(x+8)>0.
$$

Therefore, the solution set of the original inequality is $\{x \mid x>-8, x \neq 1\}$.