9. (6 points) The sum of the first 2015 digits in the decimal part of the repeating decimal 0.0142857 . is $\qquad$

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【Answer】Solution: The repeating decimal $0.01^{4285} 7$ has a cycle of 6 digits, the first digit of the decimal part is 0, and the 2014th digit after the decimal point is $2014 \div 6=335$ (groups) $\cdots 4$,

The remainder is 4, so the 4th digit in the 336th cycle is 8,
Thus, the sum of the first 2015 digits of the decimal part is:
$$
\begin{aligned}
& (1+4+2+8+5+7) \times 335+1+4+2+8 \\
= & 27 \times 335+15 \\
= & 9045+15 \\
= & 9060 ;
\end{aligned}
$$

Answer: The sum is 9060.
Therefore, the answer is: 9060.