1. What is the smallest number that is greater than 2015 and divisible by both 6 and 35 ?
Answer: 2100
Solution: The desired number is divisible by $2,3,5$ and 7 . Hence, it is the least multiple of $2 \times 3 \times 5 \times 7=210$ that is greater than 2015. The desired number is 2100 .