1. Given that $AB$ is a diameter of $\odot C$ with radius 2, $\odot D$ is internally tangent to $\odot C$ at point $A$, $\odot E$ is internally tangent to $\odot C$, externally tangent to $\odot D$, and tangent to $AB$ at point $F$. If the radius of $\odot D$ is 3 times the radius of $\odot E$, then the radius of $\odot D$ is $\qquad$ and the chord value is $\qquad$.
$-1.4 \sqrt{15}-14$.
As shown in Figure 3.
Let the radius of $\odot E$ be $r$. According to the problem, we have
$$
D E=4 r, C D=2-3 r, C E=2-r, E F=r \text {. }
$$

By the Pythagorean theorem, we get
$$
\left(\sqrt{E C^{2}-E F^{2}}+C D\right)^{2}+E F^{2}=E D^{2} \text {. }
$$

Solving this, we get $r=\frac{4 \sqrt{15}-14}{3}$.
Therefore, the radius of $\odot D$ is $4 \sqrt{15}-14$.