Given $12$ points in a plane no three of which are collinear, the number of lines they determine is: 
$\textbf{(A)}\ 24 \qquad \textbf{(B)}\ 54 \qquad \textbf{(C)}\ 120 \qquad \textbf{(D)}\ 66 \qquad \textbf{(E)}\ \text{none of these}$
Since no three points are collinear, every two points must determine a distinct line. Thus, there are  $\dbinom{12}{2} = \frac{12\cdot11}{2} = 66$ lines. 
Therefore, the answer is $\fbox{(D) 66}$