7. Regardless of the value of $t$, the line $(t+1) x-(2 t+5) y-6=0$ always passes through a fixed point $A$, then the coordinates of point $A$ are $\qquad$ .
7. $(-4,-2)$. Hint: The equation is transformed into $x-5 y-6+(x-2 y) t=0$, by $\left\{\begin{array}{l}x-2 y=0 \\ x-5 y-6=0\end{array}\right.$, solving yields $\left\{\begin{array}{l}x=-4, \\ y=-2 .\end{array}\right.$