2. In $\triangle A B C$, it is known that $\angle A C B$ is an obtuse angle, $C F$ is the median on side $A B$, and $B E$ is the altitude on side $A C$. If $C F=B E$, then $\angle A C F=(\quad)$.
(A) $15^{\circ}$
(B) $30^{\circ}$
(C) $45^{\circ}$
(D) $60^{\circ}$
2. B.

As shown in Figure 3, draw $F D \perp A C$ at point $D$. Then $F D=\frac{1}{2} B E=\frac{1}{2} C F$.
Thus, $\angle A C F=30^{\circ}$.