The integer 287 is exactly divisible by
(A) 3
(B) 4
(C) 5
(D) 7
(E) 6
The integer 287 is exactly divisible by
(A) 3
(B) 4
(C) 5
(D) 7
(E) 6

## Solution 1

$\frac{287}{7}=41$

## Solution 2

If we think in terms of divisibility tests we see that:

287 is not divisible by 3 because $2+8+7=17$ is not a multiple of 3 ;

287 is not divisible by 4 because 87 is not divisible by 4 ;

287 is not divisible by 5 because it doesn't end in 0 or 5 ;

287 is divisible by 7 because $287=7 \times 41$;

287 is not divisible by 6 because it is not even and is not divisible by 3 .

ANSWER: (D)