The following example is taken from Pethe Ferentz's work entitled "Mathesis" (Béts, 1812), and we provide it in its original wording and spelling: Four Gamblers together won 280 forints: the second, 16 forints less, won as much as the first; the third, 24 forints less, won as much as the two first; the fourth won as much as the first and third together: - how much did each win?
Let $x$ be the first "santzolo's" earnings, then according to the problem, the second, third, and fourth earnings are $x-16$, $2x-40$, and $3x-40$ respectively.

Thus,

$$
\begin{aligned}
x+(x-16)+(2x-40)+(3x-40) & =280 \\
7x & =376 \\
x & =53 \frac{5}{7} \text{ forints. }
\end{aligned}
$$

and thus

Therefore, the earnings of the four "santzolos" are $53 \frac{5}{7}$, $37 \frac{5}{7}$, $67 \frac{3}{7}$, and $121 \frac{1}{7}$ forints. Gyöngyi (Miskolc, Electric Railway Engineering I. o. t.)