【Question 15】  
Zhao, Qian, Sun, and Li, four children, all like playing chess. Among them, someone likes playing Chinese chess, someone likes playing Go, and someone likes both types of chess. Therefore, the different ways these four people can like these two types of chess are $\qquad$ kinds.
【Analysis and Solution】Counting.
4 people, some like playing Chinese chess, some like playing Go, and some like both; then exactly 2 people have the same hobbies;

Considering the types where exactly 2 people have the same hobbies, there are $C_{3}^{2}=3$ cases.
Case (1): 2 people like playing Chinese chess, 1 person likes playing Go, and 1 person likes both;

Case (2): 1 person likes playing Chinese chess, 2 people like playing Go, and 1 person likes both;
Case (3): 1 person likes playing Chinese chess, 1 person likes playing Go, and 2 people like both.

Considering 4 different people, there are $C_{4}^{2} \times C_{2}^{1} \times C_{1}^{1}=6 \times 2 \times 1=12$ ways;
Therefore, the different ways these four people can like these two types of chess are $3 \times 12=36$ ways.