2. A fruit store is conducting a promotional sale, with the following combinations: Combination A: 2 kg of fruit $A$, 4 kg of fruit $B$; Combination B: 3 kg of fruit $A$, 8 kg of fruit $B$, 1 kg of fruit $C$; Combination C: 2 kg of fruit $A$, 6 kg of fruit $B$, 1 kg of fruit $C$. It is known that fruit $A$ costs 2 yuan per kg, fruit $B$ costs 1.2 yuan per kg, and fruit $C$ costs 10 yuan per kg. One day, the store earned a total of 441.2 yuan from selling these three combinations, with the sales of fruit $A$ amounting to 116 yuan. What is the sales amount for fruit $C$? $\qquad$ yuan.
2.150.

Let the number of sets of fruit A, B, and C sold on that day be $x$, $y$, and $z$ respectively. According to the problem, we have
$$
\begin{array}{l}
\left\{\begin{array}{l}
2(2 x+3 y+2 z)=116, \\
8.8 x+25.6 y+21.2 z=441.2,
\end{array}\right. \\
\therefore\left\{\begin{array}{l}
2 x+3 y+2 z=58, \\
22 x+64 y+53 z=1103 .
\end{array}\right.
\end{array}
$$
(2) - (1) $\times 11$, eliminating $x$, we get
$$
31(y+z)=465 \text {, }
$$

Thus, $y+z=15$.
Therefore, a total of 15 kg of fruit C was sold, and the sales revenue from fruit C is $15 \times 10=150$ (yuan).