2. Carlson has a runny nose. He uses square handkerchiefs measuring 25 cm $\times 25 \mathrm{~cm}$. Over eight days, Carlson used $3 \mathrm{~m}^{2}$ of fabric. How many handkerchiefs did Carlson use per day?
2. First method of solving.
1) $25 \times 25=625\left(\mathrm{~cm}^{2}\right)-$ area of one handkerchief;
2) $3 \times 10000=30000\left(\mathrm{~cm}^{2}\right)$ - contained in $3 \mathrm{~m}^{2}$;
3) $30000: 625=48$ (handkerchiefs) - Carlson used over 8 days
4) $48: 8=6$ (handkerchiefs) - Carlson used per day.

Second method of solving (Setov Mikhail, student of School No. 15).

From 1 m², 16 handkerchiefs can be obtained (see diagram). Carlson used $3 \mathrm{~m}^{2}$, which means $3 \times 16=48$ handkerchiefs over 8 days. Therefore, he used 6 handkerchiefs per day $(48: 8=6)$.

![](https://cdn.mathpix.com/cropped/2024_05_21_e53d4ff4f2278a1c0d12g-070.jpg?height=588&width=663&top_left_y=1048&top_left_x=705)

Third method of solving (Babenko Dima, student of School No. 28).

1) $300 \cdot 100=30000\left(\mathrm{~cm}^{2}\right)-$ was in $3 \mathrm{~m}^{2}$;
2) $300: 25=12$ (h.) - on one side
3) $100: 25=4$ (h.) - on the other side.
4) $12 \times 4=48$ (h.) — in total.
5) $48: 8=6$ (h.) — Carlson used per day.

Fourth method of solving (Selemin Alexei, student of School No. 9)

1) $25 \times 25=625\left(\mathrm{~cm}^{2}\right)$ - area of one handkerchief;
2) $3 \times 10000=30000\left(\mathrm{~cm}^{2}\right)$ - contained in 3 square meters;
3) $30000: 8=3750\left(\mathrm{~cm}^{2}\right)$ — fabric Carlson used per day;
4) $3750: 625=6$ (h.) — Carlson used per day.

Answer: 6 handkerchiefs.