## Task 2 - 100622

The Soviet spacecraft Soyuz 6, Soyuz 7, and Soyuz 8 orbited the Earth in a group flight. The group of three spacecraft took an average of 88 minutes for each orbit and covered a distance of approximately $41000 \mathrm{~km}$ during this time.

Calculate the length of the path that the spacecraft group traveled on average

a) in each hour,

b) in each second during their flight!

For task a), the answer should be given in kilometers and rounded to the nearest thousand kilometers, and for task b), the answer should be given in meters and rounded to the nearest hundred meters.
a) Since the spacecraft group covered an average of $41000 \mathrm{~km}$ in 88 minutes, it covered in each minute due to 41000 : $88 \approx 466$ approximately $466 \mathrm{~km}$, in 60 minutes thus approximately $60 \cdot 466 \mathrm{~km}$, which is about 28000 $\mathrm{km}$.

b) Since the spacecraft group covered $466 \mathrm{~km}=466000 \mathrm{~m}$ in each minute, it covered in each second the 60th part of it, thus due to $466000: 60=7767$ approximately $7800 \mathrm{~m}$.