Which of the numbers $-5, \frac{3}{2}, 2, \frac{3}{5}, 8$ is larger than its square?
(A) -5
(B) $\frac{3}{2}$
(C) 2
(D) $\frac{3}{5}$
(E) 8
We calculate the square of each number: $(-5)^{2}=25,\left(\frac{3}{2}\right)^{2}=\frac{9}{4}, 2^{2}=4,\left(\frac{3}{5}\right)^{2}=\frac{9}{25}$, and $8^{2}=64$. We can quickly tell that each of $-5,2$ and 8 is less than its square.

Since $\frac{3}{2}=1 \frac{1}{2}$ and $\frac{9}{4}=2 \frac{1}{4}$, then $\frac{3}{2}$ is also less than its square.

However, $\frac{3}{5}=\frac{15}{25}$ is larger than its square $\frac{9}{25}$.

ANSWER: (D)

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