8.3. Find the integer solutions of the system:

$$
\left\{\begin{array}{l}
a b+c=94 \\
a+b c=95
\end{array}\right.
$$
Answer: $a=95, b=0, c=94$ or $a=31, b=2, c=32$.

Solution. Subtracting the first equation from the second, we get:

$$
(a-c)(1-b)=1
$$

Since $a, b, c$ are integers, there are two possible cases:

1) $a-c=1, 1-b=1$, i.e., $b=0$. Substituting into the system, we get $c=94, a=95$.
2) $a-c=-1, 1-b=-1$, i.e., $c=a+1, b=2$. Substituting $b$ and $c$ into the first equation, we get $a=31$, from which $c=32$.