On Fridays, the price of a ticket to a museum is $\$ 9$. On one particular Saturday, there were 200 visitors to the museum, which was twice as many visitors as there were the day before. The total money collected from ticket sales on that particular Saturday was $\frac{4}{3}$ as much as the day before. The price of tickets on Saturdays is $\$ k$. Determine the value of $k$.
There were 200 visitors on Saturday, so there were 100 visitors the day before. Since tickets cost $\$ 9$ on Fridays, the total money collected on Friday was $\$ 900$.

Therefore, the amount of money collected from ticket sales on the Saturday was $\$ 900 \times \frac{4}{3}=\$ 1200$.

Since there were 200 visitors on Saturday, the price of tickets on that particular Saturday was $\frac{\$ 1200}{200}=\$ 6$.

In fact, if all conditions are kept the same in this problem but the number of ticket sales on Saturday changes, the answer will still be 6 . Can you see why this is true?

ANSWER: 6

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