7. (10 points) Please fill in the blanks in the following equation with the numbers $1-9$, using each number exactly once, to make the equation true. It is known that the two-digit number $\overrightarrow{\mathrm{DE}}$ is not a multiple of 3, so the five-digit number $\overrightarrow{\mathrm{ABCDE}}$ is $\qquad$.



Fill in the blanks in the above text, maintaining the original text's line breaks and format, and output the translation result directly.
【Solution】Solution: $2016=2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 3 \times 3$,
Since the two-digit number $\overrightarrow{\mathrm{DE}}$ is not a multiple of 3, then $\overline{\mathrm{DE}}$ must be multiplied by at least one single-digit number that can be divided by 3, at this time, $2016=32 \times 7 \times 9=56 \times 6 \times 6$; obviously $56 \times 6 \times 6$ does not meet the requirements, so it is discarded, hence $2016=\overline{\mathrm{DE}} \times \square \times \square=$ $32 \times 7 \times 9, \overline{\mathrm{DE}}=32 ; 1 \sim 9$ the digits have already used $2,3,7,9$; then look at $\square \times \square \times(\overline{\overline{\mathrm{AB}}}-C)$ can only be $1,4,5,6,8$. Only $2016=4 \times 8 \times 63=6 \times 8 \times 42=4 \times 6 \times 84$ might fit,
(1) If $2016=4 \times 8 \times 63$, then $63=70-7=71-8=72-9=64-1=65-2=66-3=67-4=$ $68-5=69-6$ (digits are repeated, so discard);
(2) If $2016=6 \times 8 \times 42$, then $42=50-8=51-9=43-1=44-2=45-3=46-4=47-5=$ $48-6=49-7$ (digits are repeated, so discard),
(3) If $2016=4 \times 6 \times 84$, then $84=90-6=91-7=92-8=93-9=85-1=86-2=87-3=$ $88-4=89-5$,

The only one that fits is $84=85-1$, so $2016=4 \times 6 \times(85-1)$, that is: $\overline{\mathrm{AB}}=85, C=1$. This five-digit number $\overrightarrow{\mathrm{ABCDE}}$ is: 85132. Therefore, the answer is: 85132.