309. 26 persons together spent 88 coins, with each man spending 6, each woman 4, and each girl 2 coins. How many were men, women, and girls?
309. 10 solutions; from $x+y+z=26$

and

$$
6 x+4 y+2 z=88
$$

we get:

$$
2 x+y=18
$$

from which

$$
y=18-2 x
$$

therefore,

$$
2 x \leqslant 18
$$

H

$$
x \leqslant 9
$$

T. e

$$
\begin{aligned}
& x=0, \quad 1, \quad 2, \quad 3, \quad 4, \quad 5, \quad 6, \quad 7, \quad 8, \quad 9 \\
& y=18,16,14,12,10, \quad 8, \quad 6, \quad 4, \quad 2, \quad 0 \\
& z=8, \quad 9,10,11,12,13,14,15,16,17
\end{aligned}
$$

If we exclude the cases $x=0, y=0$, then 8 solutions.