2. In an airplane with 62 rows, each having 6 seats, passengers have seated themselves in such a way that in no 2 rows are seats occupied in the same positions. What is the maximum number of passengers that can be in the airplane?
IV/2. Since there are 6 seats in each row, we have $2^{6}=64$ different seating possibilities for passengers in each row. Since for each of the 64 seating methods, we can find its complementary one (i.e., one that has exactly the seats occupied that are unoccupied in the given row), we can form 32 fully occupied rows from 32 complementary pairs. Therefore, in an airplane with 64 rows, there would be $6 \cdot 32=192$ passengers. However, since our airplane has only 62 rows, we omit the least occupied rows: the empty row and the row with 1 passenger. In an airplane with 62 rows, there can be a maximum of $192-1=191$ passengers.