1A. Determine the largest term of the sequence $a_{n}=\frac{2016^{n}}{n!}, n \in \mathbb{N}$.
Solution. Od

$$
\frac{a_{n+1}}{a_{n}}=\frac{2016}{n+1}
$$

it follows that the sequence grows up to the 2015th term which is equal to the 2016th, and then decreases. Therefore, the largest terms of the sequence are $a_{2015}$ and $a_{2016}$.