1.2.9 * The odd function $f(x)$ is increasing within its domain $(-1,1)$. Given that $f(1-m)+f\left(m^{2}-1\right)<0$, find the range of real numbers for $m$.
From the condition, we know that $f(1-m)<-f\left(m^{2}-1\right)=f\left(1-m^{2}\right)$. Therefore, $m$ must simultaneously satisfy the conditions $\left\{\begin{array}{l}-1<1-m<1, \\ -1<1-m^{2}<1, \\ 1-m<1-m^{2},\end{array}\right.$ Solving these, we get $0<m<1$.