Three identical squares form rectangle $W X Y Z$, as shown. The perimeter of $W X Y Z$ is $56 \mathrm{~m}$. The area of $W X Y Z$ is
(A) $66 \mathrm{~m}^{2}$
(B) $147 \mathrm{~m}^{2}$
(D) $196 \mathrm{~m}^{2}$
(E) $348 \mathrm{~m}^{2}$

![](https://cdn.mathpix.com/cropped/2024_04_20_46ead6524a8d61e21c51g-009.jpg?height=204&width=441&top_left_y=207&top_left_x=1292)
The side lengths of each of the three identical squares are equal.

The perimeter of $W X Y Z$ is $56 \mathrm{~m}$ and is comprised of 8 such side lengths.

Thus, the length of each side of the three identical squares is $56 \mathrm{~m} \div 8=7 \mathrm{~m}$.

The area of each of the three identical squares is $7 \mathrm{~m} \times 7 \mathrm{~m}=49 \mathrm{~m}^{2}$.

Therefore, the area of $W X Y Z$ is $3 \times 49 \mathrm{~m}^{2}=147 \mathrm{~m}^{2}$.

ANSWER: (B)