1. Calculate $\frac{22223^{3}+11112^{3}}{22223^{3}+11111^{3}}$ The result is
二、1.1 $\frac{1}{33334}$ Let $a=22223, b=11112$. Then the original expression $=\frac{a^{3}+b^{3}}{a^{3}+(a-b)^{3}}=\frac{a+b}{2 a-b}$.