A1. In 2023, a natural number $n$ has all digits equal to 1. What is the sum of the digits of the natural number $n \cdot 1111$?
(A) 8080
(B) 8083
(C) 8086
(D) 8092
(E) 8101
A1. When we multiply $n \cdot 1111$ in writing, we first write the number $n$ four times under each other and then add the digits in columns. There is never a carry-over when calculating the sum of the digits. Therefore, the sum of the digits of the product $n \cdot 1111$ is equal to four times the sum of the digits of the number $n$, which is $4 \cdot 2023=8092$.