1. Vinko has a field in the shape of a rectangle with a length of 63 m. From Mark, he bought an adjacent field of the same length, which is 4 m wider than Vinko's. Both fields together have an area of $2016 \mathrm{~m}^{2}$. How much did Vinko pay his neighbor Mark if the price of $1 \mathrm{~m}^{2}$ is $150 \mathrm{kn}$?
1. Let $x$ be the width of Vinko's field. Then the width of the purchased field is $x+4 \mathrm{~m}$.

![](https://cdn.mathpix.com/cropped/2024_05_30_8091e4f2781742023a76g-01.jpg?height=576&width=679&top_left_y=777&top_left_x=697)

Therefore, we have:

$63 \cdot(x+x+4)=2016$

$2 \cdot x+4=2016: 63$

$2 \cdot x+4=32$

$2 \cdot x=32-4$

$2 \cdot x=28$

$x=14$

The width of Marko's field is $14+4=18 \mathrm{~m}$.

The area of Marko's field is $63 \cdot 18=1134 \mathrm{~m}^{2}$.

The amount Vinko paid is $1134 \cdot 150=170100 \mathrm{kn}$.