468. Find the corrected sample variance for the given sample distribution of size $n=10$:

$$
\begin{array}{cccc}
x_{i} & 0.01 & 0.05 & 0.09 \\
n_{i} & 2 & 3 & 5
\end{array}
$$
The problem is solved. To avoid operations with fractions, we will switch to conditional variants $u_{i}=100 x_{i}$. As a result, we get the distribution

$$
\begin{array}{llll}
u_{i} & 1 & 5 & 9 \\
n_{i} & 2 & 3 & 5
\end{array}
$$

We will find the corrected sample variance of the conditional variants

$$
s_{u}^{2}=\frac{\sum n_{i} u_{i}^{2}-\left[\sum n_{i} u_{i}\right]^{2} / n}{n-1} .
$$

Substituting the data from the problem into this formula, we get

$$
s_{u}^{2}=10,844
$$

We will find the corrected variance of the original variants:

$$
s_{X}^{2}=s_{u}^{2} / 100^{2}=10,844 / 10000 \simeq 0,0085
$$