26. $a, b, c$ are the sides opposite to the internal angles $A$, $B$, $C$ of $\triangle ABC$, respectively. Given $a=2, b=\sqrt{2}$, and $\frac{\sin C}{\sin B}=\frac{\sqrt{6}+\sqrt{2}}{2}$.
Try to find: (1) the side $c$ and the supplementary angle of angle $A$;
(2) Calculate:
i)
$$
\begin{array}{l}
\sin \left(180^{\circ}-A\right) \cdot \cos \left(180^{\circ}-A\right) \\
-\operatorname{tg}\left(90^{\circ}-A\right) \cdot \operatorname{ctg}\left(180^{\circ}-A\right),
\end{array}
$$
$$
-1
$$
ii) $\frac{-1}{\cos (B+C)+\operatorname{tg}}(B+C)$.
(Given: $\left.=\sqrt{3}+1,135^{\circ}\right)$ (Answer: $\frac{1}{2}$ )
(Answer: $2-\sqrt{2}$ )