10. Determine the volume of a truncated square pyramid if its height is 6, the side of the lower base is 4, and the upper base is 2.
10. Using the formula for the volume of a truncated pyramid

$$
V=\frac{H}{3}(B+b+\sqrt{B b})
$$

we get:

$$
V=\frac{6}{3}(16+4+\sqrt{16 \cdot 4})=2(16+4+8)=56
$$

It is interesting to see the solution of the Egyptian mathematician. We will translate the text from the papyrus verbatim:

"Problem to solve the pyramid (a drawing is attached on the side) as if it were said: 4 at the bottom, 2 at the top. Do as it is done: the square of 4 gives 16. Double 4 gives 8. Do as it is done: the square of 2 gives 4. Add 16, add 8, add 4, which gives 28. Do as it is done: take one third of 6, which makes 2. Do as it is done: take 28 twice, which makes 56. This is 56. You will find it correct."