7、In parallelogram $A B C D$, points $P, Q, R, S$ are the midpoints of sides $A B, B C, C D, D A$ respectively, and point $T$ is the midpoint of segment $\mathrm{SR}$. Given that the area of parallelogram $\mathrm{ABCD}$ is 120 square centimeters, what is the area of $\triangle P Q T$ in square centimeters?
【Analysis】Obviously, since $\mathrm{SR}$ is parallel to $\mathrm{PQ}$, we have $S_{\triangle P Q T}=S_{\triangle P Q S}=\frac{1}{4} S_{A B C D}=30$.