10. (5 points) For $n$ consecutive natural numbers starting from 1, if one of the numbers is removed, the average of the remaining numbers is $\frac{152}{7}$, then the removed number is $\qquad$
【Solution】Solution: Let the removed number be $x$, then the sum after removing one number is:
$$
(1+n) n \div 2 - x = \frac{152}{7} \times (n-1) \text{; }
$$

Clearly, $n-1$ is a multiple of 7;
When $n=8, 15, 22, 29, 36$, $x$ is negative, which does not meet the requirements.
When $n=43$, the sum is $946, 42 \times \frac{152}{7} = 912, 946 - 912 = 34$.
When $n=50$, the sum is $1225, 49 \times \frac{152}{7} = 1064, 1225 - 1064 = 161 > 50$, which does not meet the requirements.
Answer: The removed number is 34.
Therefore, the answer is: 34.