2. Let $\alpha, \beta$ be the two real roots of the equation $2 x^{2}-3|x|-2=0$. Then the value of $\frac{\alpha \beta}{|\alpha|+|\beta|}$ is ( ).
(A) -1
(B) 1
(C) $-\frac{2}{3}$
(D) $\frac{2}{3}$
2. A.

The original equation is $(2|x|+1)(|x|-2)=0$.
Since $2|x|+1>0,|x|-2=0$, therefore, $x= \pm 2$. Hence, $\frac{a \beta}{|\alpha|+|\beta|}=\frac{2 \times(-2)}{|2|+|-2|}=-1$.