Sofia went to bring some sweets to her grandmother: seven blackberry sweets, six coconut sweets, and three chocolate sweets. On the way, the greedy Sofia ate two sweets. Which of the following situations is possible?

(a) Her grandmother did not receive any chocolate sweets.

(b) Her grandmother received fewer coconut sweets than chocolate sweets.

(c) Her grandmother received the same number of sweets of each of the three varieties.

(d) There are two varieties of sweets of which her grandmother received the same number.

(e) The number of blackberry sweets her grandmother received is greater than the number of the other two varieties combined.
The correct option is (d).

Let's examine each of the proposed situations. Remember that, in the end, grandma received $7+6+3-2=14$ sweets.

(a) Impossible, because she received, at a minimum, $3-2=1$ chocolate sweet.

(b) Impossible, because she received, at a minimum, $6-2=4$ coconut sweets.

(c) Impossible, because $7-2=5>3$.

(d) Possible, because Sofia could have eaten one blackberry sweet and one chocolate sweet, leaving 6 blackberry, 6 coconut, and 2 chocolate sweets for grandma.

(e) Impossible, because 7 is not greater than $6+3-2=7$.