4. As shown in Figure 1, in $\triangle A B C$, $D E / / A B / /$ $F G$, and the ratio of the distances from $F G$ to $D E$ and $A B$ is $1: 2$. If the area of $\triangle A B C$ is 32, and the area of $\triangle C D E$ is 2, then the area of $\triangle C F G$ is ( ).
(A) 6
(B) 8
(C) 10
(D) 12
4.B.

From $D E / / A B / / F G$, we know,
$$
\frac{C D}{C A}=\sqrt{\frac{S_{\triangle C D E}}{S_{\triangle C B B}}}=\sqrt{\frac{2}{32}}=\frac{1}{4} \text {. }
$$

Also, $\frac{F D}{F A}=\frac{1}{2}$, so, $F D=D C$. Therefore,
$$
\frac{S_{\triangle C D E}}{S_{\triangle C F C}}=\left(\frac{1}{2}\right)^{2}=\frac{1}{4}, S_{\triangle C F C}=8 .
$$