13. (8 points) Six football teams are playing a round-robin tournament, where each team plays against every other team. If a match ends in a draw, each team gets 1 point; otherwise, the winning team gets 3 points and the losing team gets 0 points. Now, after four rounds (each team has played 4 matches), the total points of each team are all different. It is known that the team in third place has a total of 7 points, and there have been 4 matches that ended in a draw. Therefore, the team in fifth place can have a maximum of $\qquad$ points and a minimum of $\qquad$ points.
【Solution】Solution: The total number of matches played, $4 \times 6 \div 2=12$ (matches), among which 4 matches were draws, the number of matches with a winner is: $12-4=8$ (matches), the total points scored by the six teams: $3 \times 8+2 \times 4=32$ (points), because, the top three teams scored at least: $7+8+9=24$ (points), so, the bottom three teams scored at most: $32-24=8$ (points), also, because, the fourth team scored more points than the fifth team, so, the fifth team scored at most 3 points, because, the sixth team might score 0 points, so, the fifth team scored at least 1 point, hence the answer is: 3,1.