1. What is the value of $\frac{2018+2018+2018}{2018+2018+2018+2018}$ ?
A $\frac{1}{2018}$
B 1
C 0.2018
D -2018
E $\frac{3}{4}$
1. E When we simplify the calculation, we obtain $\frac{3 \times 2018}{4 \times 2018}$ which can then be cancelled down to give $\frac{3}{4}$.