296. On the table lie three piles of pebbles, with 30 pebbles in each pile. Two players take turns taking any number of pebbles from the table, but in one move, only from one pile. The winner is the one who takes the last pebbles from the table. Who and how will win with the correct play?
$\triangle$ Let's compare the conditions of this problem with those of the previous one. There were two piles, not three, and as proven earlier, it was disadvantageous to start the game. This consideration leads to the following idea for the beginning player: he should take all 30 stones from one pile, for example, the third one, on his first move. This will reduce the problem to problem 295, but with the players' positions swapped. From then on, he should follow the same strategy that the second player used there. Since the second player won in problem 295, the beginning player wins here.

Answer: the beginning player.

In solving this problem, another key idea used in game problems was revealed: one should strive to pass the turn of a disadvantageous move to the other player.