Of the following sets, the one that includes all values of $x$ which will satisfy $2x - 3 > 7 - x$ is: 
$\textbf{(A)}\ x > 4 \qquad \textbf{(B)}\ x \frac{10}{3}\qquad\textbf{(E)}\ x < 0$
$2x-3>7-x\implies 3x>10\implies \boxed{x>\frac{10}{3} (\textbf{D})}$.