5. There were 5 times more strawberry bushes on the first bed than on the second. When 22 bushes were transplanted from the first bed to the second, the number of strawberry bushes on each bed became the same. How many bushes were there on each bed?
## 5. First method of solving.

Let's build a graphical model of the problem's condition

![](https://cdn.mathpix.com/cropped/2024_05_21_e53d4ff4f2278a1c0d12g-031.jpg?height=331&width=1128&top_left_y=1905&top_left_x=470)

1) $22: 2=11$ (bushes) - this is $1/5$ of all the bushes (that were on the second bed);
2) $11 \times 5=55$ (bushes) - this was on the first bed.

Second method of solving (Nikolai Zherebtsov - student of School No. 46).

1) $5+1=6$ (parts) - in total;
2) $6: 2=3$ (parts) - this is how many parts each bed has;
3) $5-3=2$ (parts) - this is how many parts were transplanted from the first bed to the second;
4) $22: 2=11$ (bushes) - this is how many bushes are in one part (there were on the second bed)
5) $11 \times 5=55$ (bushes) - this was on the first bed.

Third method of solving (Vitaliy Semikin - student of School No. 48).

1) $22+22=44$ (bushes) - this is how many fewer bushes there are on the second bed compared to the first;
2) $44: 4=11$ (bushes) - this is how many bushes are in one part (there were on the second bed)
3) $11 \times 5=55$ (bushes) - this was on the first bed.

Answer: 11 bushes were on the second bed, 55 bushes were on the first.