Real numbers $w$, $x$, $y$, and $z$ satisfy $w+x+y = 3$, $x+y+z = 4,$ and $w+x+y+z = 5$. What is the value of $x+y$?
    
$\textbf{(A) }-\frac{1}{2}\qquad\textbf{(B) }1\qquad\textbf{(C) }\frac{3}{2}\qquad\textbf{(D) }2\qquad\textbf{(E) }3$

1. We start with the given equations:
   \[
   w + x + y = 3
   \]
   \[
   x + y + z = 4
   \]
   \[
   w + x + y + z = 5
   \]

2. Subtract the first equation from the third equation:
   \[
   (w + x + y + z) - (w + x + y) = 5 - 3
   \]
   Simplifying, we get:
   \[
   z = 2
   \]

3. Substitute \(z = 2\) into the second equation:
   \[
   x + y + 2 = 4
   \]
   Simplifying, we get:
   \[
   x + y = 2
   \]

Thus, the value of \(x + y\) is \(\boxed{2}\).