7. How many different products that are divisible by 10 (order does not matter) can be formed from the numbers $2,3,5,7,9$? Numbers in the product do not repeat!
7. For a number to be divisible by 10, it must be divisible by 2 and 5.

Thus, the product must necessarily include 2 and 5. We get the first product $-2 \times 5$.

Now, let's add one more factor to this product:

$$
2 \times 5 \times 3, 2 \times 5 \times 7, 2 \times 5 \times 9
$$

Add one more factor to the obtained products:

$$
2 \times 5 \times 3 \times 7, 2 \times 5 \times 3 \times 9, 2 \times 5 \times 7 \times 9
$$

Add one more factor:

$$
2 \times 5 \times 3 \times 7 \times 9
$$

In total, we have eight products $1+3+3+1=8$.

Answer: eight products.

## TWENTY-THIRD