At the SUPER-SUPER store clearance, all products are $50\%$ cheaper, and on Saturdays, there is an additional $20\%$ discount. Carla bought a pair of pants before the clearance, and now she laments: On Saturday, I would have saved $R \$ 50.40$ on the pants. What was the price of the pants before the clearance?
During the sale, except on Saturdays, products are $50\%$ cheaper. On Saturdays, with an additional $20\%$ discount, the products are costing $80\%$ of the prices outside of Saturdays, that is

$$
80 \% \text { of } 50 \%=\frac{80}{100} \times \frac{50}{100}=\frac{40}{100}=40 \% \text { of the original price. }
$$

Therefore, Roberta missed out on saving $60\%$, which corresponds to R\$ 50.40. Since

$$
\begin{aligned}
& 60 \% \leadsto 50.40 \\
& 10 \% \leadsto 50.40 \div 6=8.4 \text{ and} \\
& 100 \% \leadsto 8.4 \times 10=84.00
\end{aligned}
$$

the price of the pants before the sale was R\$ 84.00.