4. (3 points) If the natural numbers $a, b, c, d$ when divided by 6 all leave a remainder of 4, then the remainder when $a+b+c+d$ is divided by 3 is
【Solution】Solution: Since the natural numbers $a, b, c, d$ when divided by 6 all leave a remainder of 4, $a, b, c, d$ can all be expressed as: 6 $\times$ integer +4,

The sum of four such numbers is: $6 \times$ integer +16, when divided by 3 leaves a remainder of 1, the resulting remainder is 1.
The answer is 1.