Problems 14, 15 and 16 involve Mrs. Reed's English assignment. 

A Novel Assignment 

The students in Mrs. Reed's English class are reading the same 760-page novel. Three friends, Alice, Bob and Chandra, are in the class. Alice reads a page in 20 seconds, Bob reads a page in 45 seconds and Chandra reads a page in 30 seconds.

Before Chandra and Bob start reading, Alice says she would like to team read with them. If they divide the book into three sections so that each reads for the same length of time, how many seconds will each have to read?

$ \textbf{(A)}\ 6400 \qquad 
\textbf{(B)}\ 6600 \qquad 
\textbf{(C)}\ 6800 \qquad 
\textbf{(D)}\ 7000 \qquad 
\textbf{(E)}\ 7200$
1. First, we need to determine the reading rates of Alice, Bob, and Chandra in pages per second:
   - Alice reads a page in 20 seconds, so her rate is \( \frac{1}{20} \) pages per second.
   - Bob reads a page in 45 seconds, so his rate is \( \frac{1}{45} \) pages per second.
   - Chandra reads a page in 30 seconds, so her rate is \( \frac{1}{30} \) pages per second.

2. Next, we need to find a common time \( t \) in seconds that each person will read for, such that the total number of pages read by all three equals 760 pages.

3. Let \( t \) be the time in seconds each person reads. The number of pages read by each person is:
   - Alice: \( \frac{t}{20} \) pages
   - Bob: \( \frac{t}{45} \) pages
   - Chandra: \( \frac{t}{30} \) pages

4. The total number of pages read by all three is:
   \[
   \frac{t}{20} + \frac{t}{45} + \frac{t}{30} = 760
   \]

5. To solve for \( t \), we first find a common denominator for the fractions. The least common multiple of 20, 45, and 30 is 180. Rewriting the fractions with a common denominator:
   \[
   \frac{t}{20} = \frac{9t}{180}, \quad \frac{t}{45} = \frac{4t}{180}, \quad \frac{t}{30} = \frac{6t}{180}
   \]

6. Adding these fractions:
   \[
   \frac{9t}{180} + \frac{4t}{180} + \frac{6t}{180} = \frac{19t}{180}
   \]

7. Setting the sum equal to 760:
   \[
   \frac{19t}{180} = 760
   \]

8. Solving for \( t \):
   \[
   19t = 760 \times 180
   \]
   \[
   19t = 136800
   \]
   \[
   t = \frac{136800}{19}
   \]
   \[
   t = 7200
   \]

9. Therefore, each person will read for 7200 seconds.

The final answer is \( \boxed{7200} \).