9. Given the equation $a^{2} x^{2}-\left(3 a^{2}-8 a\right) x+2 a^{2}$ $-13 a+15=0$ (where $a$ is a non-negative integer) has at least one integer root. Then $a=$ $\qquad$
$9.1,3,5$
Since $a \neq 0$, we get
$$
x_{1}=\frac{2 a-3}{a}=2-\frac{3}{a}, x_{2}=\frac{a-5}{a}=1-\frac{5}{a} \text {. }
$$

Therefore, $a$ can take 1.3 or 5.