7 Given complex numbers $Z_{1}$ and $Z_{2}$ satisfy $\left|Z_{1}\right|=2,\left|Z_{2}\right|=3$. If the angle between the vectors they correspond to is $60^{\circ}$, then $\left|\frac{Z_{1}+Z_{2}}{Z_{1}-Z_{2}}\right|=$ $\qquad$ .
Solving by the cosine rule, we get
$$
\begin{array}{l}
\left|Z_{1}+Z_{2}\right|=\sqrt{\left|Z_{1}\right|^{2}+\left|Z_{2}\right|^{2}-2\left|Z_{1}\right|\left|Z_{2}\right| \cos 120^{\circ}}=\sqrt{19}, \\
\left|Z_{1}-Z_{2}\right|=\sqrt{\left|Z_{1}\right|^{2}+\left|Z_{2}\right|^{2}-2\left|Z_{1}\right|\left|Z_{2}\right| \cos 60^{\circ}}=\sqrt{7},
\end{array}
$$

Therefore,
$$
\frac{\left|Z_{1}+Z_{2}\right|}{\left|Z_{1}-Z_{2}\right|}=\frac{\sqrt{19}}{\sqrt{7}}=\frac{\sqrt{133}}{7} .
$$