Example 11. Find the number of consecutive zeros at the end of 1987!. 

 untranslated text:
将上面的文本翻译成英文，请保留源文本的换行和格式，直接输出翻译结果。 

 translated text:
Example 11. Find the number of consecutive zeros at the end of 1987!. 

Note: The note at the end is not part of the original text and is provided for context.
To solve this problem, it is equivalent to finding the exponent of $1 \mathrm{C}$ in 1987!, which is the same as finding the exponent of 5 in 1987!, since
$$
\begin{array}{l}
{\left[\frac{1987}{5}\right]+\left[\frac{1987}{5^{2}}\right]+\left[\begin{array}{c}
1987 \\
5^{3}
\end{array}\right]} \\
+\left[\frac{1987}{5^{4}}\right]=494,
\end{array}
$$

thus 1987! ends with exactly 494 zeros.