14. A basket of apples, the first time sold one quarter of the total number of apples in the basket plus 6 (if there are 36 apples, one quarter of it is 9, one third of it is 12), the second time sold one third of the remaining plus 4, the third time sold half of the remaining plus 3, and finally 4 were left, how many apples were there in the basket originally?
【Solution】: $\left[\left(3 \div \frac{1}{2}+4\right) \div\left(1-\frac{1}{3}\right)+6\right] \div\left(1-\frac{1}{4}\right)$,
$$
\begin{aligned}
= & {\left[(6+4) \div \frac{2}{3}+6\right] \div \frac{3}{4}, } \\
= & {\left[10 \times \frac{3}{2}+6\right] \times \frac{4}{3}, } \\
= & {[15+6] \times \frac{4}{3}, } \\
= & 21 \times \frac{4}{3}, \\
= & 28 \text { (apples); }
\end{aligned}
$$

Answer: The basket originally had 28 apples.