16. (15 points) As shown in the figure, Xiaohong and Xiaoli's homes are located directly west and east of the cinema, respectively. One day, they both set out from their homes at the same time. Xiaohong walks at a speed of 52 meters per minute, and Xiaoli walks at a speed of 70 meters per minute, and they both arrive at the cinema at the same time. After the movie, Xiaohong heads home first, maintaining her speed, and 4 minutes later, Xiaoli also starts walking home at a speed of 90 meters per minute, and they both arrive home at the same time. Find

the distance between their homes in meters.
【Analysis】According to the problem: the time used by Xiaoli for the first time $\times$ the speed of the first time $=$ (the time used for the first time - 4) $\times$ the speed of the second time. Let's assume the time used for the first time is $x$ hours. According to this, we can find the time used, and then based on the distance $=$ speed $\times$ time, we can find the distance between the two houses. According to this, solve the problem.

【Solution】Let the time used for the first meeting be $x$ minutes.
$$
\begin{array}{l}
70 x=90 \times(x-4) \\
70 x=90 x-360 \\
90 x-70 x=360 \\
20 x=360 \\
x=360 \div 20 \\
x=18 \\
\text { (52+70) }
\end{array}
$$

Answer: The distance between the two houses is 2196 meters.