G1.4 When 491 is divided by a two-digit integer, the remainder is 59 . Find this two-digit integer. Let the number be $10 x+y$, where $0<x \leq 9,0 \leq y \leq 9$.
$\begin{array}{l}491=(10 x+y) \cdot Q+59 ; 59<10 x+y \\ 491-59=432=(10 x+y) \cdot Q ; 432=72 \times 6 \text {; the number is } 72 .\end{array}$