As shown in the figure, points $C$, $E$, and $B$ are collinear, $CB \perp AB$, $AE \parallel DC$, $AB=8$, $CE=5$. Then the area of $\triangle AED$ is
Geometry, Equal Area Transformation
Connect $A C$
Since $A E / / D C$
Therefore $S_{\triangle A E D}=S_{\triangle A E C}$
Since $C B \perp A B$
Therefore $S_{\triangle A E C}=C E \times A B \div 2=5 \times 8 \div 2=20$
Therefore $S_{\triangle A E D}=20$