Three dice with faces numbered 1 through 6 are stacked as shown. Seven of the eighteen faces are visible, leaving eleven faces hidden (back, bottom, between). The total number of dots NOT visible in this view is
The numbers on one die total $1+2+3+4+5+6 = 21$, so the numbers
on the three dice total $63$. Numbers $1, 1, 2, 3, 4, 5, 6$ are visible, and these total $22$.
This leaves $63 - 22 = \boxed{\text{(D) 41}}$ not seen.