7. Design a computer operation program: (1) Initial value $x=3, y=0$. (2) $x=x+2$. (3) $y=y+x$. (4) If $y \geqslant 10000$, then proceed to (5); otherwise continue from (2).
(5) Print $x$. (6) Stop running. What is the result printed by this program?
$\qquad$
7. 201 Explanation:
\begin{tabular}{|c|c|c|c|c|c|}
\hline$n$ & 1 & 2 & 3 & $\cdots$ & $n$ \\
\hline$x$ & $3+2$ & $3+2 \times 2$ & $3+3 \times 2$ & $\cdots$ & $3+n \times 2$ \\
\hline$y$ & $3+2$ & $2 \times 3+3 \times 2$ & $3 \times 3+6 \times 2$ & $\cdots$ & $3 n+\frac{n(n+1)}{2} \times 2$ \\
\hline
\end{tabular}

Therefore, $3 n+\frac{n(n+1)}{2} \times 2 \geqslant 10000$, the smallest $n=99$, at this time $x=3+99 \times 2=201$.