I2.4 In Figure $1, \alpha=c, \beta=43, \gamma=59$ and $\omega=d$, find the value of $d$.
$\begin{array}{l}\angle B A C=\omega^{\circ}(\angle \mathrm{s} \text { in the same seg. }) \\ \angle A C D=\beta^{\circ}(\angle \mathrm{s} \text { in the same seg. }) \\ \left.\angle B A D+\angle B C D=180^{\circ} \text { (opp. } \angle \text { s cyclic quad. }\right) \\ c+d+43+59=180 \\ d=180-43-59-36=42(\because c=36)\end{array}$