19. If the sum of 25 consecutive even numbers is 10000, then the largest number among these 25 consecutive even numbers is ( ).
(A) 360
(B) 388
(C) 412
(D) 416
(E) 424
19. E.

Let the largest number among these 25 consecutive even numbers be $n$.
Then 10000
$$
\begin{array}{l}
=n+(n-2)+(n-4)+\cdots+(n-48) \\
=25 n-(2+4+\cdots+48) \\
=25 n-600 \\
\Rightarrow n=\frac{10000+600}{25}=424 .
\end{array}
$$