3.28 One of the three barrels is filled with water, while the others are empty. If the second barrel is filled with water from the first barrel, then $\frac{1}{4}$ of the water that was in the first barrel will remain. If the third barrel is then filled from the second, $\frac{2}{9}$ of the water that was in the second barrel will remain.

If, finally, the water from the third barrel is poured into the empty first barrel, it will require an additional 50 buckets to fill it. Determine the capacity of each barrel.
3.28 Let $x$ be the capacity of the first barrel; then the capacity of the second is $\frac{3}{4} x$, and the third is $\frac{3}{4} \cdot \frac{7}{9} x=\frac{7}{12} x$. According to the condition, $\frac{7}{12} x + 50 = x$, from which $x = 120$. Thus, the capacities of the barrels are 120, 90, and 70 buckets.

Answer: 120, 90, and 70 buckets.