6. Today is March 20, 2005, Sunday. Then, the day after today by $2005^{3}$ days is ( ).
(A) Wednesday
(B) Thursday
(C) Friday
(D) Saturday
6.D.

Since $2005^{3}=(7 \times 286+3)^{3}=7 k+27=7 k_{1}+6$ $\left(k 、 k_{1} \in \mathbf{N}\right)$, therefore, it is Saturday.