[Text problems (other)]

Pilyulkin, Guslya, and Toropyzhka are decorating a New Year's tree. It is known that Guslya hung twice as many ornaments on the tree as Pilyulkin, Pilyulkin hung 15 fewer ornaments than Toropyzhka, and Toropyzhka hung twice as many as Guslya and Pilyulkin combined. How many ornaments are decorating the tree?

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The first method. Suppose Pilulkin hung one part of all the toys, then Guslya hung two such parts, and together they hung three parts of the toys (see the figure). Therefore, Toropyzhka hung 6 parts, which is 5 parts more than what Pilulkin hung. Since these 5 parts consist of 15 toys, one part is three toys. Thus, the tree is decorated with $3+6+18=27$ toys.

![](https://cdn.mathpix.com/cropped/2024_05_06_79aa1f75de69bad6c7b2g-28.jpg?height=257&width=854&top_left_y=0&top_left_x=602)

The second method. Suppose Pilulkin hung $x$ toys, then Guslya hung $2x$ toys, and together they hung $3x$ toys. Toropyzhka hung $2 \cdot 3x = 6x$ toys. Knowing that he hung 15 more toys than Pilulkin, we can set up the equation: $6x - x = 15$, from which $x = 3$. Thus, there are 27 toys on the tree.

## Answer

27 toys.