1. The wolf saw a roe deer several meters away from him and chased after her along a straight forest path. The wolf's jump is $22\%$ shorter than the roe deer's jump. Both animals jump at a constant speed. All the roe deer's jumps are of the same length, and the wolf's jumps are also equal to each other. There is a period of time during which both the wolf and the roe deer make a certain whole number of jumps. Each time, it turns out that the wolf has made $t\%$ more jumps than the roe deer. Find the greatest integer value of $\mathrm{t}$, for which the wolf will not be able to catch the roe deer.
Solution: Let x be the length of the roe deer's jump, then $0.78x$ is the length of the wolf's jump; y - the number of jumps the roe deer makes in a unit of time specified in the condition, $y\left(1+\frac{t}{100}\right)$ - the number of jumps the wolf makes in the same unit of time. The wolf will not be able to catch up with the roe deer if the distance covered by the roe deer in a unit of time - xy - is always greater than the distance covered by the wolf in the same unit of time $0.78xy\left(1+\frac{t}{100}\right)$. We will form the inequality: $0.78xy\left(1+\frac{t}{100}\right)<xy ; 1+\frac{t}{100}<\frac{50}{39} ; t<\frac{1100}{39}$. The maximum value of $t$ that satisfies this inequality, $t=28\%$.

Answer: 28.