9.192. $\sqrt{x^{3}+3 x+4}>-2$,
## Solution.

The solutions to this inequality are the values of the unknown that belong to the domain of definition: $x^{3}+3 x+4 \geq 0,(x+1)\left(x^{2}-x+4\right) \geq 0$. Here $x^{2}-x+4>0$ for $x \in R$. Then $x+1 \geq 0, x \geq-1$.

Answer: $x \in[-1 ; \infty)$.