7.2. Petya and Borya each made five shots at one target, hitting "5" once, "7" twice, "8" once, "9" twice, "10" twice, "11" once, and "12" once. With his last four shots, Petya scored seven times more points than with his first shot. It is known that both Petya and Borya hit "10". Who hit "12"? Justify your answer.
Solution: We have that with the last four shots, Petya scored no more than $12+11+10+9=42$, which means his first shot was no more than $42: 7=6$. Therefore, his first shot hit the "five," and the last four shots in total scored 35. During this, there was exactly one "ten," so the remaining three shots scored 25. This can be done in two ways: $7+9+9$ and $7+7+11$. In both cases, Borya hit the 12.

Note: The reasoning provided is not the only possible one.

Answer: Borya.

| in progress | points |
| :--- | :--- |
| Correct and fully justified answer | 7 points |
| An example is provided showing how the shooting could have gone, but it is not justified that Petya could not hit the "12" | 2 points |
| Answer without justification and/or incorrect answer | 0 points |