Problem 5. Four identical rectangles are glued together to form a larger rectangle (drawing on the right). Calculate the perimeter of the larger rectangle if each of the four smaller rectangles has a perimeter of 4

![](https://cdn.mathpix.com/cropped/2024_06_05_e235c78af50361de0ec1g-03.jpg?height=186&width=238&top_left_y=1743&top_left_x=1246)
$d m$.
Solution. According to the diagram, the length of the smaller rectangle is 3 times its width. Therefore, let its sides be $a$ and $3a$. Then, for the smaller rectangles, $L=2(a+3a)=8a$ and $L=4 dm=40 \text{~cm}$, so $8a=40 \text{~cm}$, i.e., $a=5 \text{~cm}$. The sides of the larger rectangle are $4a$ and $3a$, 
i.e., $20 \text{~cm}$ and $15 \text{~cm}$. Therefore, the perimeter of the larger rectangle is $L_{g}=2(20+15)=70 \text{~cm}$

## VI section