When $x=3$, the value of $x(x-1)(x-2)(x-3)(x-4)$ is
(A) 6
(B) -6
(C) 0
(D) 24
(E) -24
When we substitute $x=3$, the product becomes $3(2)(1)(0)(-1)$.

Since one of the factors is 0 , the entire product is equal to 0 .

ANSWER: $(\mathrm{C})$