22. Eight people sit around a round table, each with an identical coin in front of them, and everyone flips their coin simultaneously. If the coin lands heads up, the person stands up; if the coin lands tails up, the person remains seated. What is the probability that no two adjacent people stand up? ( ).
(A) $\frac{47}{256}$
(B) $\frac{3}{16}$
(C) $\frac{49}{256}$
(D) $\frac{25}{128}$
(E) $\frac{51}{256}$
22. A.

Eight people each stand or sit, with a total of $2^{8}=256$ different arrangements.
We will discuss the scenarios below.
(1) No one is standing, there is 1 arrangement;
(2) One person is standing, there are $\mathrm{C}_{8}^{1}=8$ different arrangements;
(3) Two people are standing, but not adjacent, there are $\mathrm{C}_{8}^{2}-8=20$ different arrangements;
(4) Four people are standing, but no two are adjacent, there are 2 different arrangements;
(5) Three people are standing, but no two are adjacent, there are $\frac{8(3+2+1)}{3}=16$ different arrangements;
(6) There are no more than four people standing, otherwise, there must be two adjacent people standing.
Thus, $P=\frac{1+8+20+2+16}{2^{8}}=\frac{47}{256}$.