10. (10 points) From $1,2,3, \cdots, 2014$, select 315 different numbers (order does not matter) to form an arithmetic sequence. Among the formed arithmetic sequences, those that include 1 have $\qquad$ ways of selection; in total, there are $\qquad$ ways of selection.
【Analysis】It is known that to form an arithmetic sequence, among the 315 numbers, there are 314 common differences, the smallest common difference is 1; the largest common difference is 6. Next, we can solve the problem by categorizing and discussing.

【Solution】Solution: To form an arithmetic sequence, among the 315 numbers, there are 314 common differences, the smallest common difference is 1; the largest common difference is 6,

Reason: $314 \times 6=1884<2014<314 \times 7<2205$;
The ones containing 1 are only 6 kinds;
For a common difference of 1, there are: $2014-(315-1)=1700$ kinds;
For a common difference of 2, there are: $2014-(2 \times 314-1)+1=1386$ kinds;
For a common difference of 3, there are: $2014-(3 \times 314-1)+1=1072$ kinds;
For a common difference of 4, there are: $2014-(4 \times 314+1)+1=758$ kinds;
For a common difference of 5, there are: $2014-(5 \times 314+1)+1=444$ kinds;
For a common difference of 6, there are: $2014-(6 \times 314+1)+1=130$ kinds;
In total, there are $1700+1386+1072+758+444+130=5490$ kinds.
Therefore, the answers are 6, 5490.