6. (5 points) 2015 minus its $\frac{1}{2}$, then minus the remaining $\frac{1}{3}$, then minus the remaining $\frac{1}{4}, \cdots$, and finally minus the remaining $\frac{1}{2015}$, the final number obtained is $\qquad$ .
6. (5 points) 2015 minus its $\frac{1}{2}$, then minus the remaining $\frac{1}{3}$, then minus the remaining $\frac{1}{4}, \cdots$, and finally minus the remaining $\frac{1}{2015}$, the final number obtained is $\qquad$ .

【Solution】Solution: $2015 \times\left(1-\frac{1}{2}\right) \times\left(1-\frac{1}{3}\right) \times\left(1-\frac{1}{4}\right) \times \cdots \times\left(1-\frac{1}{2015}\right)$
$$
\begin{array}{l}
=2015 \times \frac{1}{2} \times \frac{2}{3} \times \frac{3}{4} \times \cdots \times \frac{2014}{2015} \\
=1
\end{array}
$$

Therefore, the answer is: 1 .