7. (10 points) There are 37 people standing in a line to count off. The first person reports 1, and each subsequent person reports a number that is 3 more than the previous person's number. During the counting, one person made a mistake and reported a number that was 3 less than the previous person's number. The sum of the numbers reported by these 37 people is exactly 2011. Then, the person who made the mistake is the $\qquad$th person to report a number.
【Solution】Solution: The 37 people report numbers forming an arithmetic sequence with the first term 1 and a common difference of 3. The 37th term is $1+(37-1) \times 3=109$. The sum of these 37 numbers is $(1+109) \times 37 \div 2=2035$, $2035-2011=24$,

Since the person who made the mistake reported a number 6 less, $24 \div 6=4$

This means the 37th, 36th, 35th, and 34th people reported incorrectly, so the 34th person who reported the number made the mistake. The answer is: 34.