Folklore

At the market, fish are sold, both large and small. Today, three large and one small fish together cost as much as five large fish did yesterday. And two large and one small fish today cost as much as three large and one small fish did yesterday. Can we determine from this information which is more expensive: one large and two small fish today, or five small fish yesterday?
Let's denote "fish prices": today, a large fish costs $b_{c}$, and a small one costs $m_{c}$. Yesterday, a large fish cost $b_{v}$, and a small one cost $-m_{v}$. Then, $3 b_{c} + m_{c} = 5 b_{v}$,

$2 b_{c} + m_{c} = 3 b_{v} + m_{v}$. From this, we get: $5 m_{v} = 5(2 b_{c} + m_{c} - 3 b_{v}) = 10 b_{c} + 5 m_{c} - 3(3 b_{c} + m_{c}) = b_{c} + 2 m_{c}$. That is, five small fish yesterday cost as much as one large and two small fish today.

## Answer

It is possible.