Sofia went to deliver some sweets to her grandmother; there are 7 blackberry sweets, 6 coconut sweets, and 3 chocolate sweets. On the way, the greedy Sofia ate 2 sweets. Which of the following situations is possible?

(A) Grandma did not receive any chocolate sweets.

(B) Grandma received fewer coconut sweets than chocolate sweets.

(C) Grandma received the same number of sweets of each of the 3 varieties.

(D) There are 2 varieties of sweets of which Grandma received the same number.

(E) The number of blackberry sweets Grandma received is greater than the other 2 combined.
Let's examine each of the proposed situations. Remember that at the end, grandma received $7+6+3-2=14$ candies.

(A) Impossible because she received at least $3-2=1$ chocolate candy.

(B) Impossible because she received at least $6-2=4$ coconut candies.

(C) Impossible because $7-2=5>3$.

(D) Possible because Sofia could have eaten 1 blackberry candy and 1 chocolate candy, leaving for grandma: 6 blackberry, 6 coconut, and 2 chocolate candies.

(E) Impossible because 7 is not greater than $6+2-3$.

Therefore, the only possible situation is (D).