3. Polynomial
$$
\begin{array}{l}
|x+1|+|x+2|+\cdots+|x+2008|+ \\
|x-1|+|x-2|+\cdots+|x-2008|
\end{array}
$$
The minimum value of the above expression is ( ).
(A) 4034072
(B) 4030056
(C) 2008
(D) 0
3. A.

From the problem, we know that within $-1 \leqslant x \leqslant 1$, the polynomial has the
$$
\begin{array}{l}
\text { minimum value } \\
2(1+2+\cdots+2008) \\
=2008 \times 2009=4034072 .
\end{array}
$$