$\triangle A B C$ is constructed from nine small, equilateral triangles, as shown. If the perimeter of each of the nine small triangles is $6 \mathrm{~cm}$, then the perimeter of $\triangle A B C$, in $\mathrm{cm}$, is
(A) 18
(D) 36
(B) 24
(C) 27
(E) 54

![](https://cdn.mathpix.com/cropped/2024_04_20_6027bc27089ed4fc493cg-079.jpg?height=358&width=343&top_left_y=1491&top_left_x=1399)
Since the perimeter of each of the small equilateral triangles is $6 \mathrm{~cm}$, then the side length of each of these triangles is $2 \mathrm{~cm}$. Since there are three of the small triangles along each side of triangle of $A B C$, then the side length of triangle $A B C$ is $6 \mathrm{~cm}$, and so its perimeter is $18 \mathrm{~cm}$.

Answer: (A)