Three people played. $A$ had $10 \mathrm{~K}$, $B$ had $57 \mathrm{~K}$, and $C$ had $29 \mathrm{~K}$. At the end of the game, $B$ had three times as much money as $A$, and $C$ had three times as much money as what $A$ won. How much did $C$ win or lose?
If $A x K$ won, then according to the problem,

$$
10+x+3(x+10)+3 x=96
$$

from which

$$
x=8
$$

so $C$ had $24 \mathrm{~K}$ at the end of the game, and thus lost $5 \mathrm{~K}$.

(Koffler Béla, Budapest, V. district, fóreál.)

The problem was also solved by: Babocsai Gy., Bendl K., Chambré M., Czukor G., Dénes M., Erdős V., Fried E., Füstös P., Grossberger Z., Kirchknopf E., Kiss J., Kovács Gy., Kuffler P., Lázár B., Lengyel K., Miklóssy K., Neumann L., Paunz A., Petrik S., Rajz E., Rosenthal M., Sárközy P., Schlesinger J., Schnabel L., Steiger J., Steiner L., Stolczer I., Szilárd V., Szőke D, Tandlich E., Tóth B, Viola R., Wáhl V., Weisz J.