How many of the four integers $222,2222,22222$, and 222222 are multiples of 3 ?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
We could use a calculator to divide each of the four given numbers by 3 to see which calculations give an integer answer.

Alternatively, we could use the fact that a positive integer is divisible by 3 if and only if the sum of its digits is divisible by 3 .

The sums of the digits of $222,2222,22222$, and 222222 are $6,8,10$, and 12 , respectively.

Two of these sums are divisible by 3 (namely, 6 and 12) so two of the four integers (namely, 222 and 222 222) are divisible by 3 .

ANSWER: (C)