2. (8 points) Two cars, A and B, start driving towards each other from points $A$ and $B$ simultaneously. After 6 hours, the distance they have traveled is 3/5 of the distance between $A$ and $B$. Car A travels at 42 kilometers per hour, which is $1 / 7$ less than the speed of Car B. Therefore, the distance between $A$ and $B$ is $\qquad$ meters.
【Solution】Solution: $42 \div\left(1-\frac{1}{7}\right)=49$ (km);
$$
\begin{aligned}
& (42+49) \times 6 \div \frac{3}{5}, \\
= & 91 \times 6 \times \frac{5}{3}, \\
= & 910 \text { (km); }
\end{aligned}
$$

Answer: Therefore, the distance between $A$ and $B$ is 910 km.
The answer is: 910.