The decimal expansion of $\frac{2}{13}$ is the repeating decimal $0 . \overline{153846}$. What digit occurs in the 2008th place after the decimal point?
(A) 8
(B) 6
(C) 5
(D) 4
(E) 3
The digits after the decimal point occur in repeating blocks of 6 digits.

Since $2008 \div 6=334.666 \ldots$, then the 2008th digit after the decimal point occurs after 334 blocks of digits have been used.

In 334 blocks of 6 digits, there are $334 \times 6=2004$ digits in total. Therefore, the 2008th digit is 4 digits into the 335 th block, so must be 8 .

ANswer: (A)