69*. Solve the puzzle:

$$
\begin{array}{r}
\text { MOUNTAIN } \\
+\begin{array}{c}
\text { FIRE }
\end{array} \\
\hline \text { VOLCANO. }
\end{array}
$$
$\triangle$ Three digits can be found immediately:

$$
\mathrm{B}=1, \quad \mathrm{y}=0, \quad \mathrm{O}=9
$$

Let's find the digit K. Since it results from adding 9 to 9 and is certainly different from 9, then $\mathrm{K}=8$.

Further solution reduces to restoring the record:

$$
\begin{array}{r}
\Gamma 9 \mathrm{PA} \\
+\begin{array}{r}
9 \Gamma 9 \mathrm{Hb}
\end{array} \\
\hline 10 \mathrm{L} 8 \mathrm{AH} .
\end{array}
$$

From here, PA + Hb $=\mathrm{AH}, \quad \Gamma+\Gamma+1=\mathrm{L}+10, \quad 2 \Gamma=\mathrm{L}+9$.

From the last equality, it follows that the digit L is odd. Moreover, it is different from 1 and 9. Then it can take the values 3, 5, and 7.

1) Let $\mathrm{L}=3$.

Then $\Gamma=6$.

Now let's look at the equality

$$
\begin{array}{r}
\mathrm{PA} \\
+\begin{array}{c}
\mathrm{Hb}
\end{array} \\
\hline \mathrm{AH} .
\end{array}
$$

We have already used the digits $0,1,3,6,8,9$. Therefore, the digits P, A, H, and b can take the values $2,4,5$, and 7.

From the last equality, it is clear that the value 7 can only be taken by the digit A. Then $\mathrm{P}=2, \mathrm{H}=4$ or $\mathrm{P}=4, \mathrm{H}=2$, and thus $\mathrm{b}=5$. But since from the last column $\mathrm{H}=2$, only the second possibility is valid: $\mathrm{P}=4, \mathrm{H}=2$. We get:

$$
6947+96925=103872
$$

2) Let $\mathrm{L}=5$.

In this case, $\Gamma=7$.

Then the digits P, A, H, and b in the last puzzle take the values $2,3,5$, and 6. In this case, $\mathrm{A}=6$. But if $\mathrm{b}$ takes the value 2, 3, or 4, then the sum $\mathrm{A}+\mathrm{b}$ in the second column is 8, 9, or 10, respectively, which is impossible.

3) Let $\mathrm{L}=7$.

Then $\Gamma=8$. It turned out that $\mathrm{K}=\Gamma$. Therefore, this case is also impossible.

Answer: $6947+96925=103872$.