We want to paint some identically-sized cubes so that each face of each cube is painted a solid color and each cube is painted with six different colors. If we have seven different colors to choose from, how many distinguishable cubes can we produce?
1. **Determine the number of ways to choose 6 colors out of 7:**
   Since we need to paint each cube with 6 different colors out of 7 available colors, we first need to choose which 6 colors to use. The number of ways to choose 6 colors out of 7 is given by the binomial coefficient:
   \[
   \binom{7}{6} = 7
   \]

2. **Calculate the number of permutations of the 6 chosen colors:**
   Once we have chosen 6 colors, we need to arrange them on the 6 faces of the cube. The number of permutations of 6 colors is:
   \[
   6! = 720
   \]

3. **Account for the symmetries of the cube:**
   A cube has 24 rotational symmetries (including rotations around its faces, edges, and vertices). Therefore, each unique coloring can be rotated in 24 different ways that would make it look the same. To find the number of distinguishable colorings, we need to divide the total number of colorings by the number of symmetries:
   \[
   \frac{7 \times 720}{24} = \frac{5040}{24} = 210
   \]

Conclusion:
\[
\boxed{210}
\]