10. (12 points) 36 students numbered $1, 2, 3, \cdots, 36$ stand in a circle facing inward in numerical order. The first time, the student numbered 1 turns around. The second time, the students numbered $2, 3$ turn around. The third time, the students numbered $4, 5, 6$ turn around, ..., the 36th time, all students turn around. At this point, the students still facing inward are . $\qquad$
【Solution】Solution: The first time, 1 student turns around, the second time, 2 students turn around, the third time, 3 students turn around, $\cdots$, the eighth time, 8 students turn around,
$$
\begin{array}{l}
1+2+3+4+5+6+7+8=36 \text { (people) } \\
36 \div 8=4 \cdots 4
\end{array}
$$

So after the 32nd time, all 36 students face inward;
4 more times will result in $1+2+3+4=10$ people facing outward, then $36-10=26$ people face inward.
The answer is: 26 .