When a positive integer $N$ is divided by $60$, the remainder is $49$. When $N$ is divided by $15$, the remainder is

$ \mathrm{(A) \ } 0 \qquad \mathrm{(B) \ } 3 \qquad \mathrm {(C) \ } 4 \qquad \mathrm{(D) \ } 5 \qquad \mathrm{(E) \ } 8$
1. Given that when a positive integer \( N \) is divided by \( 60 \), the remainder is \( 49 \). This can be expressed as:
   \[
   N = 60k + 49
   \]
   for some integer \( k \).

2. We need to find the remainder when \( N \) is divided by \( 15 \). Substitute \( N = 60k + 49 \) into the expression and consider the modulo \( 15 \):
   \[
   N \equiv 60k + 49 \pmod{15}
   \]

3. Simplify \( 60k + 49 \) modulo \( 15 \):
   \[
   60k \equiv 0 \pmod{15} \quad \text{(since \( 60 \) is a multiple of \( 15 \))}
   \]
   \[
   49 \equiv 49 \pmod{15}
   \]

4. Now, reduce \( 49 \) modulo \( 15 \):
   \[
   49 \div 15 = 3 \quad \text{with a remainder of } 4
   \]
   \[
   49 \equiv 4 \pmod{15}
   \]

5. Therefore, the remainder when \( N \) is divided by \( 15 \) is \( 4 \).

The final answer is \(\boxed{4}\).