Julia and James pick a random integer between $1$ and $10$, inclusive. The probability they pick the same number can be written in the form $m/n$ , where $m$ and $n$ are relatively prime positive integers. Compute $m + n$.
1. Let's denote the set of integers from 1 to 10 as \( S = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\} \).
2. Julia and James each pick a number from this set independently.
3. The total number of possible outcomes when both pick a number is \( 10 \times 10 = 100 \).
4. We are interested in the event where Julia and James pick the same number. There are 10 such favorable outcomes: (1,1), (2,2), ..., (10,10).
5. The probability of this event is given by the ratio of the number of favorable outcomes to the total number of outcomes:
   \[
   P(\text{same number}) = \frac{\text{number of favorable outcomes}}{\text{total number of outcomes}} = \frac{10}{100} = \frac{1}{10}
   \]
6. The fraction \(\frac{1}{10}\) is already in its simplest form, where \(m = 1\) and \(n = 10\).
7. Therefore, \(m + n = 1 + 10 = 11\).

The final answer is \( \boxed{ 11 } \)