5. What is the least number greater than 1992 that gives a remainder of $7$ when divided by $9$?
5. Divide 1992 by 9 with a remainder

| $-1992\llcorner 9$ |
| :--- |
| $\frac{18}{-19}$ |
| $\frac{-18}{221}$ |
| $\frac{-12}{9}$ |
| 3 |

We obtained a remainder of 3. To make the remainder equal to 7, the divisor needs to be increased by four:

$$
1992+4=1996 \text {. }
$$

Answer: 1996.