8. (3 points) The digits of a non-zero unit integer, when rearranged from right to left, form a new integer called the reverse number of the original integer. For example, the reverse number of 325 is 523, and the reverse number of 1376 is 6731. There are two three-digit numbers whose sum is 1372. The maximum sum of their reverse numbers is $\qquad$
【Analysis】Let the original two three-digit numbers be $\mathrm{a}_{1} b_{1} c_{1}, a_{2} b_{2} c_{2}$. According to the problem, we have: $100 \times\left(\mathrm{a}_{1}+a 2\right)$ $+10 \times\left(b_{1}+b_{2}\right)+\left(c_{1}+c_{2}\right)=1372$ (Equation 1), where $\mathrm{a}_{1} 、 b_{1} 、 c_{1} 、 a_{2} 、 b_{2} 、 c_{2}$ are all single digits. We need to find the maximum value of $100 \times\left(c_{1}+c_{2}\right)+10 \times\left(b_{1}+b_{2}\right)+\left(\mathrm{a}_{1}+a 2\right)$ (Equation 2). First, consider $c_{1}+c_{2}$. From 1372, we know that $c_{1}+c_{2}=12$ or 2. To maximize Equation 2, $c_{1}+c_{2}=12$. At this point, we know: $1 b_{1}+b_{2}=6$ or 16. When $b_{1}+b_{2}=6, \mathrm{a}_{1}+a 2=13$, at this time Equation 2 = 1273. When $b_{1}+b_{2}=16, \mathrm{a}_{1}+a 2=12$, at this time Equation 2 = 1372. Based on this, solve.

【Solution】Solution: Let the original two three-digit numbers be $\mathrm{a}_{1} b_{1} c_{1}, a_{2} b_{2} c_{2}$. According to the problem, we have: $100 \times\left(\mathbf{a}_{1}+a 2\right)+10 \times\left(b_{1}+b_{2}\right)+\left(c_{1}+c_{2}\right)=1372$ (Equation 1), where $\mathbf{a}_{1} 、 b_{1} 、 c_{1} 、 a_{2} 、 b_{2}$, and $c_{2}$ are all single digits. We need to find the maximum value of $100 \times\left(c_{1}+c_{2}\right)+10 \times\left(b_{1}+b_{2}\right)+\left(\mathrm{a}_{1}+a 2\right)$ (Equation 2). First, consider $c_{1}+c_{2}$. From 1372, we know that $c_{1}+c_{2}=12$ or 2. To maximize Equation 2, $c_{1}+c_{2}=12$. At this point, we know: $1 b_{1}+b_{2}=6$ or 16. When $b_{1}+b_{2}=6, \mathrm{a}_{1}+a 2=13$, at this time Equation 2 = 1273. When $b_{1}+b_{2}=16, \mathrm{a}_{1}+a 2=12$, at this time Equation 2 = 1372. Therefore, the answer is: 1372.