8. A triangle with side lengths $24,70,74$ is inscribed in a circle. Find the difference between the numerical values of the area and the circumference of the circle in terms of $\pi$.
Answer: $1295 \pi$
Solution: Notice that the given triangle is a right triangle with hypotenuse equal to 74 because $12^{2}+$ $35^{2}=37^{2}$ which implies that $24^{2}+70^{2}=74^{2}$. From this, we know that the area and circumference of the circle are $37^{2}(\pi)$ or $1369 \pi$ and $74 \pi$, respectively. Thus, the difference is equal to $1295 \pi$.