【Question 11】There is a natural number that when divided by 7 leaves a remainder of 3, and when divided by 9 leaves a remainder of 4. Please write down the first two natural numbers that satisfy the conditions in ascending order here $\qquad$ _.
Analysis:
Numbers that leave a remainder of 3 when divided by 7 are: $3,10,17,24,31 \cdots$;
Numbers that leave a remainder of 4 when divided by 9 are: $4,13,22,31 \cdots$;
Therefore, the form of numbers that satisfy "leaving a remainder of 3 when divided by 7, and a remainder of 4 when divided by 9" is $[7,9] n+31=63 n+31$ ( $n$ is a natural number). In ascending order, the first two natural numbers that meet the condition are 31,94