9.4. Under the Christmas tree, there are 2012 cones. Winnie-the-Pooh and donkey Eeyore are playing a game: they take cones for themselves in turns. On his turn, Winnie-the-Pooh takes 1 or 4 cones, and Eeyore takes 1 or 3. Pooh goes first. The player who cannot make a move loses. Who among the players can guarantee a win, no matter how the opponent plays?
Answer: Winnie-the-Pooh

Winnie's first move should be to take 4 cones, and subsequently, after any of Eeyore's moves, take one cone each time. In this case, after each of Eeyore's moves, an odd number of cones will remain under the tree. As the number of cones under the tree gradually decreases, inevitably, there will come a moment when only one cone remains. By taking it, Pooh will win.

There are other strategies as well.

+ a complete and justified solution

$\pm$ the correct answer and the correct strategy are provided, but it is not explained why this strategy leads to success

- the correct answer and mention of parity are provided, but the game strategy is missing
- only the answer is provided