13.037. One mill can grind 19 centners of wheat in 3 hours, another - 32 centners in 5 hours, and a third - 10 centners in 2 hours. How should 133 tons of wheat be distributed among these mills so that, starting work simultaneously, they also finish it simultaneously?
## Solution.

Let $x$ hours be the time the mills work. The first mill will grind $\frac{19}{3} x$ tons of wheat in this time; the second $-\frac{32}{5} x$ tons; the third $-\frac{10}{2} x$ tons. According to the condition, $\frac{19}{3} x+\frac{32}{5} x+\frac{10}{2} x=1330$, from which $x=75$ hours. Therefore, the first mill will grind $\frac{19}{3} \cdot 75=475$ tons; the second - $\frac{32}{5} \cdot 75=480$; the third $\frac{10}{2} \cdot 75=375$ tons.

Answer: 475, 480, and 375 tons.