7、In the arithmetic expression

, the Chinese characters “第、十、一、届、华、杯、赛” represent 7 digits from 1, 2, 3, 4, 5, 6, 7, 8, 9, with different characters representing different digits, such that the addition expression is correct. Then the sum of the 7 digits represented by “第、十、一、届、华、杯、赛” is $\qquad$.


$7 、 35$
Solution: According to the addition rule, “第” =1. “届+赛” =6 or “届+赛” =16. If “届+赛” =6, “届” and “赛” can only be 2 or 4 respectively, at this time “一十杯” =10 can only be “一” and “杯” being 3 or 7 respectively. At this time, “十+华” $=9$, “十” and “华” can only take $(1,8), (2, 7)$, (3, 6), (4, 5), but 1, 2, 3, 4 have already been taken and cannot be taken again. Therefore, “届+赛” =6 cannot be filled, it can only be “届+赛” $=16, \quad "十+$ 华” $+1=10$, which means “二 + 杯” $=9$ and “十 + 华” =9 at the same time. So they can take values from $(3,6)$, (4, 5) respectively.

Therefore, the sum of the 7 numbers represented by “第、十、一、届、华、杯、赛” is
$$
1+9+9+16=35 \text { . }
$$