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An engineer arrives at the train station at 8 o'clock in the morning every day. At exactly 8 o'clock, a car arrives at the station and takes the engineer to the factory. One day, the engineer arrived at the station at 7 o'clock and started walking towards the car. Meeting the car, he got in and arrived at the factory 20 minutes earlier than usual. How long did the engineer walk? The speeds of the car and the engineer are constant.

#
In 20 minutes, the car would have traveled the distance the engineer walked twice. Therefore, the car met the engineer at $7:50$.

## Answer

50 minutes.