In the diagram, $A B C D$ and $D E F G$ are squares with equal side lengths, and $\angle D C E=70^{\circ}$. The value of $y$ is
(A) 120
(B) 160
(C) 130
(D) 110
(E) 140

![](https://cdn.mathpix.com/cropped/2024_04_20_e85ef69091c57cb633f3g-129.jpg?height=274&width=431&top_left_y=199&top_left_x=1324)
Since squares $A B C D$ and $D E F G$ have equal side lengths, then $D C=D E$, ie. $\triangle C D E$ is isosceles. Therefore, $\angle D E C=\angle D C E=70^{\circ}$ and so

and

$$
\angle C D E=180^{\circ}-70^{\circ}-70^{\circ}=40^{\circ}
$$

$y^{\circ}=360^{\circ}-\angle A D C-\angle C D E-\angle G D E$

![](https://cdn.mathpix.com/cropped/2024_04_20_688a3b42f69739f2e244g-231.jpg?height=331&width=507&top_left_y=534&top_left_x=1302)

$y^{\circ}=360^{\circ}-90^{\circ}-40^{\circ}-90^{\circ}$

$y^{\circ}=140^{\circ}$

$y=140$

ANSWER: (E)