$A B C D$ is a square with $A B=x+16$ and $B C=3 x$, as shown. The perimeter of $A B C D$ is
(A) 16
(B) 32
(C) 96
(D) 48
(E) 24

![](https://cdn.mathpix.com/cropped/2024_04_20_ac36362783317e0251fdg-129.jpg?height=344&width=336&top_left_y=782&top_left_x=1361)

## Part B: Each correct answer is worth 6.
Since $A B C D$ is a square, then $A B=B C$, or

$$
\begin{aligned}
x+16 & =3 x \\
16 & =2 x \\
x & =8
\end{aligned}
$$

Thus the side length of the square is $x+16=3 x=24$, and the perimeter is $4(24)=96$.

ANSWER: (C)