In the above equation, different Chinese characters represent different digits from $0-9$. If it is known that “Tong Xin $=10$”, what is: Zhen + Xing + Zhong + Hua =?



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In the above equation, different Chinese characters represent different numbers from $0-9$. If it is known that “Tong Xin (同心) $=10$”, what is: Zhen + Xing + Zhong + Hua $=$ ?

【Analysis】 $0 \sim 9$ includes 10 numbers in total. Tong Xin $=10$, which means only the numbers $2 \sim 9$ remain, a total of 8 numbers. The sum of these 8 numbers is fixed, which is 44. We can consider “Zhen + Xing + Zhong + Hua” as a whole $x$, and “Liang + An + Si + Di” as another whole $y$, and then calculate the value of $x$.

【Solution】Solution: According to the analysis, let Zhen + Xing + Zhong + Hua $=x$, Liang + An + Si + Di $=y$
Then $\frac{x}{y+10}=1 \cdots$
Also, $\because x+y=2+3+4+5+6+7+8+9=44 \cdots$ (2)
From (1) and (2), we get $\left\{\begin{array}{l}x=27 \\ y=17\end{array}\right.$
That is: Zhen + Xing + Zhong + Hua $=27$
Therefore, the answer is: 27