16. Given that a sphere is tangent to the three sides and two bases of a regular triangular prism. If the volume of the sphere is $\frac{32 \pi}{3}$, then the volume of the triangular prism is $\qquad$
$16.48 \sqrt{3}$.
From the volume, the radius of the sphere $R=2$, the height of the triangular prism is 4, and the side length of the base is $4 \sqrt{3}$.
Thus, $V=\frac{\sqrt{3}}{4}(4 \sqrt{3})^{2} \times 4=48 \sqrt{3}$.