10. (15 points) The wolves in the Wolf Castle have been bullying the sheep too much, finally leading to a rebellion of the sheep. After receiving the notification to attack the Wolf Castle, the little sheep set out one after another. At 7 o'clock, Little Gray looked up and found that the distances of 5 sheep to the Wolf Castle formed an arithmetic sequence with a common difference of 20 (unit: meters). From front to back, these 5 sheep were $A, B, C, D, E$; at 8 o'clock, Little Gray looked up again and found that the distances of these 5 sheep to the Wolf Castle still formed an arithmetic sequence, but with a common difference of 30 (unit: meters), and the order from front to back became $B, E, C, A, D$. Among these 5 sheep, the fastest sheep runs $\qquad$ meters more per hour than the slowest sheep.
10. (15 points) The wolves in the Wolf Castle have been bullying the sheep too much, finally leading to a rebellion. After receiving the notification to attack the Wolf Castle, the little sheep started to set out one after another. At 7 o'clock, Little Gray looked from a high place and found that the distances of 5 sheep to the Wolf Castle formed an arithmetic sequence with a common difference of 20 (unit: meters). From front to back, these 5 sheep were $A, B, C, D, E$; at 8 o'clock, Little Gray looked from a high place again and found that the distances of these 5 sheep to the Wolf Castle still formed an arithmetic sequence with a common difference of 30 (unit: meters), but the order from front to back became $B, E, C, A, D$. Among these 5 sheep, the fastest sheep runs $\qquad$ meters more per hour than the slowest sheep.

【Solution】
Solution: Let the common part length be $L$
$A$ ran $L+30$
$B$ ran $20+L+120=140+L$
$C$ ran $40+L+60=100+L$
$D$ ran $60+L$
$E$ ran $80+L+90=170+L$;
The fastest is $E$, and the slowest is $A$, the difference is:
$170+L-(30+L)=140$.
$140 \div 1=140$ meters/hour
Answer: The difference between the fastest and the slowest is 140 meters/hour.