2. Solve the inequality $\log _{x}\left(36-60 x+25 x^{2}\right)<0$.
Solution: $\log _{x}\left(36-60 x+25 x^{2}\right)0, \quad x \neq 1, \quad x \neq 6 / 5$.

1) $01 \Leftrightarrow 5 x^{2}-12 x+7>0 ;\left\{\begin{array}{l}{\left[\begin{array}{c}x7 / 5\end{array} \Leftrightarrow 01, \quad x \neq 6 / 5 ; 36-60 x+25 x^{2}<1 \Leftrightarrow 5 x^{2}-12 x+7<0 \Leftrightarrow 1<x<7 / 5, x \neq 6 / 5$.

Answer: $x \in(0 ; 1) \cup(1 ; 6 / 5) \cup(6 / 5 ; 7 / 5)$.