4. If a positive integer $x$ satisfies $x-[\sqrt{x}]^{2}=9$, then $x$ is called a "good number". Among the 2014 positive integers from $1 \sim 2014$, the number of good numbers is ( ) .
(A) 36
(B) 40
(C) 44
(D) 48
Let $[\sqrt{x}]=n$.
Then $x=n^{2}+9 \Rightarrow n \leqslant \sqrt{n^{2}+9}<n+1$ $\Rightarrow n \geqslant 5$.
Also, $n^{2}+9 \leqslant 2014 \Rightarrow n \leqslant 44$.
Therefore, there are 40 good numbers that meet the conditions.