9.160. $0.008^{x}+5^{1-3 x}+0.04^{\frac{3}{2}(x+1)}<30.04$.
## Solution.

From the condition, we have $0.2^{3 x}+\frac{5}{5^{3 x}}+0.08 \cdot 0.2^{3 x}5^{-1} \Leftrightarrow 3 x>-1, x>-\frac{1}{3}$.

Answer: $x \in\left(-\frac{1}{3} ; \infty\right)$.