In Maria Ivanovna's class, the annual English test has been held. It turned out that the average score in both groups A and B decreased compared to last year (see the table).

| Group A |  |  | Group $\mathrm{B}$ |  |  |
| :---: | :---: | :---: | :---: | :---: | :---: |
| 1 | AntonoV | 31 | 1 | Averyanov | 36 |
| 2 | Belousova | 46 | 2 | Voronova | 49 |
| 3 | Grigoryev | 52 | 3 | Danilov | 31 |
| 4 | Demin | 51 | 4 | Zlydneva | 35 |
| 5 | Isaev | 32 | 5 | Larionov | 48 |
| 6 | Kalinina | 41 | 6 | Melnikova | 32 |
| 7 | Morozikh | 59 | 7 | Ozerova | 35 |
| 8 | Popov | 32 | 8 | Rassudova | 47 |
| 9 | Sidorov | 44 | 9 | Uvarova | 35 |
| 10 | Filippovskaya | 54 | 10 | Yakhontov | 40 |
| Average |  | 44.2 | Average |  | 38.8 |
| Last year |  | 44.4 | Last year |  | 39.2 |

Maria Ivanovna needs to write a report, but she knows that the school principal will be displeased because he believes that the average score should increase every year. The scores cannot be changed, but Maria Ivanovna can transfer students from one group to another. Can she make it so that the average score in each group is higher than last year?
To increase the average score in both groups, it is necessary to transfer students from Group A to Group B whose average scores are higher than the average in Group B but lower than the average in Group A. The scores higher than the average in B but lower than the average in A are those of Kalinina and Sidorov. If both are transferred, then the average score in Group A will become $(44.2 \cdot 10 - 44 - 41) : 8 = 44.5 / 8 > 44.4$, and in Group B - $(38.8 \cdot 10 + 44 + 41) : 12 = 39 \frac{5}{12} > 39.2$.

## Answer

It is possible.