【Question 9】As shown in the figure, in rectangle $A B C D$, the area of $\triangle F D C$ is 4, and the area of $\triangle F D E$ is 2. Then the area of the shaded quadrilateral $A E F B$ is $\qquad$ .
Parse: Connect BE, by the trapezoid butterfly theorem, we know that $S_{\triangle B E F}=S_{\triangle C D F}=4$, so $S_{\triangle B C F}=4 \times 4 \div 2=8$ therefore $S_{\triangle B C D}=4+8=12, S_{A B C D}=12 \times 2=24$ so $S_{A E F B}=24-2-4-8=10$