9. $|x-2|-|x|>0$.

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9. $|x-2|-|x|>0$.
9. Roots of submodular expressions 2 and 0.

If $x \leqslant 0$, then $-x+2+x>0$, $x$ is any from the interval $x \leqslant 0$.

If $0 \leqslant x \leqslant 2$, then $-x+2-x>0$, $x0$, no solution.

Answer: $x<1$