The set of $x$-values satisfying the inequality $2 \leq |x-1| \leq 5$ is: 
$\textbf{(A)}\ -4\leq x\leq-1\text{ or }3\leq x\leq 6\qquad$
$\textbf{(B)}\ 3\leq x\leq 6\text{ or }-6\leq x\leq-3\qquad\textbf{(C)}\ x\leq-1\text{ or }x\geq 3\qquad$
$\textbf{(D)}\ -1\leq x\leq 3\qquad\textbf{(E)}\ -4\leq x\leq 6$
This inequality can be split into two inequalities:
$2\le x-1\le5$ or $2\le1-x\le5$. Solving for x gives
$3\le x\le6$ or $-4\le x\le-1$. $\boxed{\textbf{(A)}}$