4. (6 points) A number when divided by 3 leaves a remainder of 2, when divided by 4 leaves a remainder of 3, and when divided by 5 leaves a remainder of 4. This number is $\qquad$
【Analysis】Interpreting "divided by 3 leaves a remainder of 2, divided by 4 leaves a remainder of 3, divided by 5 leaves a remainder of 4" as being 1 less than when divided by 3, 1 less than when divided by 4, and 1 less than when divided by 5, means this number is at least 1 less than the least common multiple (LCM) of 3, 4, and 5. Since 3, 4, and 5 are pairwise coprime, the LCM of these three numbers is their product. Find the LCM of 3, 4, and 5, then subtract 1.

【Solution】Solution: $3 \times 4 \times 5-1$,
$$
\begin{array}{l}
=60-1, \\
=59 ;
\end{array}
$$

Answer: The number is 59.
Therefore, the answer is: 59.
【Comment】This problem mainly examines the method of finding the least common multiple (LCM) when three numbers are pairwise coprime: If three numbers are pairwise coprime, their LCM is the product of these three numbers.