Let 
$S_1=\{(x,y)|\log_{10}(1+x^2+y^2)\le 1+\log_{10}(x+y)\}$
and 
$S_2=\{(x,y)|\log_{10}(2+x^2+y^2)\le 2+\log_{10}(x+y)\}$.
What is the ratio of the area of $S_2$ to the area of $S_1$?
$\mathrm{(A) \ } 98\qquad \mathrm{(B) \ } 99\qquad \mathrm{(C) \ } 100\qquad \mathrm{(D) \ } 101\qquad \mathrm{(E) \ }  102$
Looking at the constraints of $S_1$:
$x+y > 0$
$\log_{10}(1+x^2+y^2)\le 1+\log_{10}(x+y)$
$\log_{10}(1+x^2+y^2)\le \log_{10} 10 +\log_{10}(x+y)$
$\log_{10}(1+x^2+y^2)\le \log_{10}(10x+10y)$
$1+x^2+y^2 \le 10x+10y$
$x^2-10x+y^2-10y \le -1$
$x^2-10x+25+y^2-10y+25 \le 49$
$(x-5)^2 + (y-5)^2 \le (7)^2$
$S_1$ is a circle with a radius of $7$. So, the area of $S_1$ is $49\pi$.
Looking at the constraints of $S_2$:
$x+y > 0$
$\log_{10}(2+x^2+y^2)\le 2+\log_{10}(x+y)$
$\log_{10}(2+x^2+y^2)\le \log_{10} 100 +\log_{10}(x+y)$
$\log_{10}(2+x^2+y^2)\le \log_{10}(100x+100y)$
$2+x^2+y^2 \le 100x+100y$
$x^2-100x+y^2-100y \le -2$
$x^2-100x+2500+y^2-100y+2500 \le 4998$
$(x-50)^2 + (y-50)^2 \le (7\sqrt{102})^2$
$S_2$ is a circle with a radius of $7\sqrt{102}$. So, the area of $S_2$ is $4998\pi$.
So the desired ratio is $\frac{4998\pi}{49\pi} = 102 \Rightarrow \boxed{E}$.