$A B C D$ is a square with $A B=x+16$ and $B C=3 x$, as shown. The perimeter of $A B C D$ is
(A) 16
(D) 48
(B) 32
(E) 24
(C) 96

![](https://cdn.mathpix.com/cropped/2024_04_20_6ed09463f225f8ba1f07g-129.jpg?height=333&width=334&top_left_y=744&top_left_x=1367)
Since $A B C D$ is a square, then $A B=B C$, or $x+16=3 x$

$16=2 x$

$x=8$

Thus the side length of the square is $x+16=3 x=24$, and the perimeter is $4(24)=96$.

ANSWER: (C)