A [i]quadratic[/i] number is a real root of the equations $ax^2 + bx + c = 0$ where $|a|,|b|,|c|\in\{1,2,\ldots,10\}$. Find the smallest positive integer $n$ for which at least one of the intervals$$\left(n-\dfrac{1}{3}, n\right)\quad \text{and}\quad\left(n, n+\dfrac{1}{3}\right)$$does not contain any quadratic number.
1. **Understanding the problem**: We need to find the smallest positive integer \( n \) such that at least one of the intervals \( \left(n-\dfrac{1}{3}, n\right) \) and \( \left(n, n+\dfrac{1}{3}\right) \) does not contain any quadratic number. A quadratic number is a real root of the equation \( ax^2 + bx + c = 0 \) where \( |a|, |b|, |c| \in \{1, 2, \ldots, 10\} \).

2. **Roots of quadratic equations**: The roots of the quadratic equation \( ax^2 + bx + c = 0 \) are given by:
   \[
   x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
   \]
   We need to check if these roots fall within the specified intervals for different values of \( n \).

3. **Checking for \( n = 1 \)**:
   - For \( x^2 + x - 3 = 0 \), the root is:
     \[
     x = \frac{-1 + \sqrt{13}}{2} \approx 1.302 \in \left(1, 1 + \frac{1}{3}\right)
     \]
   - For \( x^2 + 3x - 3 = 0 \), the root is:
     \[
     x = \frac{-3 + \sqrt{21}}{2} \approx 0.791 \in \left(1 - \frac{1}{3}, 1\right)
     \]
   Thus, \( n = 1 \) fits.

4. **Checking for \( n = 2 \)**:
   - For \( x^2 + x - 7 = 0 \), the root is:
     \[
     x = \frac{-1 + \sqrt{29}}{2} \approx 2.192 \in \left(2, 2 + \frac{1}{3}\right)
     \]
   - For \( x^2 + x - 5 = 0 \), the root is:
     \[
     x = \frac{-1 + \sqrt{21}}{2} \approx 1.791 \in \left(2 - \frac{1}{3}, 2\right)
     \]
   Thus, \( n = 2 \) fits.

5. **Checking for \( n = 3 \)**:
   - For \( x^2 - 3x - 1 = 0 \), the root is:
     \[
     x = \frac{3 + \sqrt{13}}{2} \approx 3.302 \in \left(3, 3 + \frac{1}{3}\right)
     \]
   - For \( x^2 - x - 5 = 0 \), the root is:
     \[
     x = \frac{1 + \sqrt{21}}{2} \approx 2.791 \in \left(3 - \frac{1}{3}, 3\right)
     \]
   Thus, \( n = 3 \) fits.

6. **Checking for \( n = 4 \) to \( n = 10 \)**:
   - For \( x^2 - nx - 1 = 0 \), the root is:
     \[
     x = \frac{n + \sqrt{n^2 + 4}}{2} \in \left(n, n + \frac{1}{3}\right)
     \]
   - For \( x^2 - nx + 1 = 0 \), the root is:
     \[
     x = \frac{n + \sqrt{n^2 - 4}}{2} \in \left(n - \frac{1}{3}, n\right)
     \]
   Thus, \( n = 4 \) to \( n = 10 \) fit.

7. **Checking for \( n = 11 \)**:
   - The greatest possible quadratic number is given by:
     \[
     x = \frac{|b| + \sqrt{b^2 + 4|a||c|}}{2|a|}
     \]
     For \( |a| = 1 \), \( |b| = 10 \), and \( |c| = 10 \), the maximum root is:
     \[
     x = \frac{10 + \sqrt{140}}{2} \approx 10.92
     \]
     This value is less than 11, so there is no quadratic number in \( \left(11, 11 + \frac{1}{3}\right) \).

Hence, the smallest positive integer \( n \) for which at least one of the intervals does not contain any quadratic number is \( \boxed{11} \).