7.1 Rays OA and OB form a right angle. Seventh-grader Petya drew rays OC and OD inside this angle, forming an angle of $10^{\circ}$, and then calculated all the acute angles between any pairs of the drawn rays (not only adjacent ones). It turned out that the sum of the largest and the smallest of the found angles is $85^{\circ}$. Find the measures of the three angles into which the right angle is divided by rays OC and OD.
Solution: See fig.

If the smallest angle turned out to be $\alpha$ or $\beta$, for example $\alpha$, then the largest angle would be the angle $\beta+10^{\circ}$, and their sum would be $90^{\circ}$, which contradicts the condition of the problem. Therefore, the smallest angle is the angle $10^{\circ}$, and the largest angle is one of these angles $\alpha+10^{\circ}$ or $\beta+10^{\circ}$, for example, $\beta+10^{\circ}$. Then $\left(\beta+10^{\circ}\right)+10^{\circ}=85^{\circ}, \beta=65^{\circ}$. Therefore,

$$
\alpha=90^{\circ}-\left(\beta+10^{\circ}\right)=90^{\circ}-75^{\circ}=15^{\circ}
$$

Thus, the answer is: $65^{\circ}, 15^{\circ}, 10^{\circ}$.