7. (5 points) In the equation “Hope Cup is Good $\times 8=\overline{\text { Good Hope Cup }} \times 5$”, different Chinese characters represent different digits. Therefore, the six-digit even number represented by “Hope Cup is Good” is $\qquad$ .
【Solution】Solution: According to the problem, we have:
$(\overline{\text { HopeCup }} \times 1000+$ JustGood $) \times 8=(\overline{\text { JustGood }} \times 1000+\overline{\text { HopeCup }}) \times 5$
Rearranging gives: HopeCup $\times 7995=$ JustGood $\times 4992$;
7995 and 4992 have a common factor of 39, which can be simplified.
$\overline{\text { HopeCup }} \times 205=$ JustGood $\times 128$; At this point, 205 and 128 are coprime, indicating that JustGood is a multiple of 205, and HopeCup is a multiple of 128. According to the problem, JustGood itself must be even, and these six numbers cannot be repeated. When JustGood is 2 times 205, it satisfies the condition.

HopeCupJustGood $=256410$
Therefore, the answer is: 256410