The number of faces $(F)$, vertices $(V)$ and edges $(E)$ of a polyhedron are related by the equation $F+V-E=2$. If a polyhedron has 6 faces and 8 vertices, how many edges does it have?
(A) 12
(B) 14
(C) 16
(D) 18
(E) 10
The polyhedron has 6 faces and 8 vertices.

The equation $F+V-E=2$ becomes $6+8-E=2$ or $14-E=2$ or $E=14-2=12$.

Therefore, the polyhedron has 12 edges.

ANSWER: (A)