3. Real numbers $a, b, c$ satisfy $a+b+c=0$, and $abc>0$. Then the value of $\frac{1}{a}+\frac{1}{b}+\frac{1}{c}$ is ( ).
(A) Positive
(B) Negative
(C) Zero
(D) Cannot be determined
3. B.

From the problem, we know that $a, b, c$ must be two negative and one positive (let's assume $a<0, b<0, c>0$).
Then $c>-a>0 \Rightarrow -\frac{1}{a}>\frac{1}{c}$.
And $\frac{1}{b}<0$, so $\frac{1}{a}+\frac{1}{b}+\frac{1}{c}<0$.