The arithmetic mean (ordinary average) of the fifty-two successive positive integers beginning at 2 is:
$\text{(A) } 27\quad \text{(B) } 27\tfrac{1}{4}\quad \text{(C) } 27\tfrac{1}{2}\quad \text{(D) } 28\quad \text{(E) } 27\tfrac{1}{2}$
To solve the problem, find the sum of the first $52$ terms of an [arithmetic sequence](https://artofproblemsolving.com/wiki/index.php/Arithmetic_sequence) with first term $2$ and common difference $1$ and divide that by $52$.  The $52^\text{nd}$ term of the sequence is $2+51=53$, so the sum of the first $52$ terms of the sequence is $\frac{52(2+53)}{2} = 1430$.  Thus, the [arithmetic mean](https://artofproblemsolving.com/wiki/index.php/Arithmetic_mean) is $\frac{1430}{52} = \frac{55}{2} = \boxed{\textbf{(C) } 27\frac{1}{2}}$.