1. How many times is number $A$ greater or smaller than number $B$, if

$$
\begin{gathered}
A=\underbrace{1+\ldots+1}_{2022 \text { times }}+\underbrace{2+\ldots+2}_{2021 \text { times }}+\ldots+2021+2021+2022, \\
B=\underbrace{2023+\ldots+2023}_{2022 \text { times }}+\underbrace{2022+\ldots+2022}_{2021 \text { times }}+\ldots+3+3+2
\end{gathered}
$$
# Solution

The number $B$ will be calculated according to its representation as

$$
B=\sum_{m=1}^{2022} Q_{m}, \quad \text { where } \quad Q_{m}=(m+1) m
$$

The number $A$ can be rewritten as the sum of arithmetic progressions

$$
A=1+(1+2)+\ldots+(1+2+\ldots+2021)+(1+2+\ldots+2022)
$$

Then

$$
A=\sum_{m=1}^{2022} S_{m}, \quad \text { where } \quad S_{m}=(m+1) m / 2
$$

Now it is clear that $A$ and $B$ represent sums with an equal number of terms, but each term in $A$ is half the corresponding term in $B$.

Answer: half as much $\left(A=\frac{1}{2} B\right)$.