2. Let set $A=\left\{x \mid x^{2}-[x]=2\right\}$ and $B=\{x|| x \mid<2\}$, where the symbol $[x]$ denotes the greatest integer less than or equal to $x$, then $A \cap B=$
$\qquad$ .
Rong's matter $\{-1, \sqrt{3}\}$.
Analysis: Since $|x|<2,[x]$ can take the values $-2,-1,0,1$.
When $[x]=-2$, then $x^{2}=0$ has no solution; when $[x]=-1$, then $x^{2}=1$, so $x=-1$; when $[x]=0$, then $x^{2}=2$ has no solution; when $[x]=1$, then $x^{2}=3$, so $x=\sqrt{3}$, therefore $x=-1$ or $\sqrt{3}$.