3.54 Three pumps, pumping water for irrigation, started working simultaneously. The first and third pumps finished working simultaneously, while the second one finished 2 hours after the start. As a result, the first pump pumped out $9 \mathrm{~m}^{3}$ of water, and the second and third together pumped out $28 \mathrm{~m}^{3}$. How much water does each pump pump out per hour, given that the third pump pumps out $3 \mathrm{~m}^{3}$ more per hour than the first, and that the three pumps, working together, pump out $14 \mathrm{~m}^{3}$ per hour?
3.54 Let the first and second pumps extract $x$ and $y$ m$^{3}$ per hour, respectively, then the third pump extracts $(x+3)$ m$^{3}$ per hour. The second and third pumps extracted $2 y$ and $(28-2 y)$ m$^{3}$ of water, respectively. The first pump worked for $\frac{9}{x}$ hours, and the third pump for $\frac{28-2 y}{x+3}$ hours. According to the condition,

$\frac{9}{x}=\frac{28-2 y}{x+3}$ and $2 x+y+3=14$.

Solving the system of equations, we find $x=3, y=5$.

Answer: 3.5 and $6 \mathrm{~m}^{3}$.