$32 \cdot 22$ satisfies the inequality $10^{4} \leqslant A \leqslant 10^{5}$ for the number of integers $A$ is $x \cdot 10^{4}+$ 1, then the value of $x$ is
(A) 9 .
(B) 8 .
(C) 7 .
(D) 6 .
(China Shanghai Junior High School Mathematics Competition, 1986)
[Solution] Since $10^{5}-10^{4}=9 \cdot 10^{4}$, the number of integers $A$ such that $10^{4} \leqslant A \leqslant 10^{5}$ is $9 \cdot 10^{4}+1$, which means $x=9$. Therefore, the correct choice is $(A)$.