G10.1
$$
\begin{array}{l}
1^{2}-1=0 \times 2 \\
2^{2}-1=1 \times 3 \\
3^{2}-1=2 \times 4 \\
4^{2}-1=3 \times 5
\end{array}
$$
$$
A^{2}-1=3577 \times 3579
$$

If $A>0$, find $A$.
$\begin{array}{l}A^{2}-1=(3578-1) \times(3578+1) \\ A=3578\end{array}$