1. Seven friends entered a cafe and ordered 3 small cups of coffee, 8 medium cups, and 10 large cups. The volume of a small cup is half the volume of a medium cup, and the volume of a large cup is three times the volume of a small cup. How should the friends divide the cups of coffee among themselves so that everyone drinks an equal amount of coffee? Pouring coffee from one cup to another is not allowed.
Solution: Let's call the amount of coffee in a small cup a "norm". Then, in total, we have $3+8 \times 2+10 \times 3=49$ norms. Since there are seven friends, each should get 7 norms.

We divide as follows: 1 small + 2 large - 3 people; 2 medium + 1 large - 4 people.

Criteria. A correct example - 7 points. No additional reasoning is required. If the result is obtained that each person needs 7 "norms", but the example is not shown (or the example is incorrect) - $\mathbf{1}$ point.

Incorrect example, lack of example - 0 points.