let $n=x-y^{x-y}$. Find $n$ when $x=2$ and $y=-2$.
$\textbf{(A)}\ -14 \qquad \textbf{(B)}\ 0 \qquad \textbf{(C)}\ 1 \qquad \textbf{(D)}\ 18 \qquad \textbf{(E)}\ 256$
Substitute the variables to determine the value of $n$.
\[n = 2 - (-2)^{2-(-2)}\]
\[n = 2 - (-2)^4\]
\[n = 2 - 16\]
\[n = -14\]
The answer is $\boxed{\textbf{(A)}}$.