6. (10 points) Choose four different digits from 0 to 9 to fill in the four parentheses in the box, there are ( ) ways to make the statement in the box correct.
This sentence contains ( ) numbers greater than 1, ( ) numbers greater than 2, ( ) numbers greater than 3, and ( ) numbers greater than 4.
A. 1
B. 2
C. 3
D. 4
【Analysis】First, consider that the 4 empty slots for numbers are all different, and there are a total of 8 numbers, including $1,2,3,4$. If there are 0 and 1, then there are at least 5 numbers greater than 1, and the numbers greater than 4 are at most 4 and at least 1. Enumerate and select based on these conditions.

【Solution】Solution: According to the problem:
Let there be $a$ numbers greater than 1, $b$ numbers greater than 2, $c$ numbers greater than 3, and $d$ numbers greater than 4.

Since $1,2,3,4$ each appear once, and there are 4 empty slots, then $a>b>c>d$. And $a \geqslant 5,1 \leqslant d \leqslant 4$
(1) If $d=4$, then among these 8 numbers, there need to be 4 numbers greater than 4, but currently only $a, b, c$ are greater than 4, which does not meet the condition.
(2) If $d=3$, then among these 8 numbers, there need to be 3 numbers greater than 4, $a, b, c$ are all greater than 4, which meets the condition. Then the numbers greater than 3 total 4. This contradicts $c>4$
(3) If $d=2$, then $a, b$ are greater than 4, $c$ is not greater than 4, $c$ is then 3 or 4, analyzing $a, b, c, d$ are sequentially $7,5,3,2$ or $7,5,4,2$
(4) If $d=1$, then $a$ is greater than 4, $b, c$ are not greater than 4, by $3,4, a$ all being greater than 2, so $b$ $\geqslant 3$, then the numbers greater than 2 total 4, so $b=4$, at this time the numbers greater than 3 are $a, b, 4$ at this time $c \geqslant 3$, then the numbers greater than 2 total 5, which is a contradiction. Therefore, the answer is: B.