(7) Arrange the positive integers whose sum of digits is 5 in ascending order to form a sequence, then 2012 is the $\qquad$th term.
(7) 38 Hint: Express 5 as the sum of no more than four positive integers, there are 6 methods:
$$
5=1+4=2+3=1+1+3=1+2+2=1+1+1+2 \text {, }
$$

Fill them into a $1 \times 4$ grid (as shown in the figure), and supplement any missing digits with 0, to form positive integers no greater than 2012. Then $\{5\}$ has 3 ways; $\{1,4\}$ has 9 ways; $\{2,3\}$ has 7 ways;
(Problem 7) $\{1,1,3\}$ has 9 ways; $\{1,2,2\}$ has 7 ways; $\{1,1,1,2\}$ has 3 ways; in total, there are 38 numbers, with 2012 being the largest, so 2012 is the 38th term.