The table shows population information for two towns for the years 2003 and 2004.

| Town | 2003 Population | Percentage Change From 2003 to 2004 |
| :---: | :---: | :---: |
| Cayleyville | 10000 | $4 \%$ |
| Pascalberg | 25000 | $-12 \%$ |

What is the difference between the populations of the two towns in 2004 ?
(A) 12400
(B) 11600
(C) 17600
(D) 13800
(E) 17400
$4 \%$ of 10000 is $\frac{4}{100} \times 10000=400$, so the population of Cayleyville in 2004 is 10400 .

$12 \%$ of 25000 is $\frac{12}{100} \times 25000=3000$, so the population of Pascalberg in 2004 is 22000 . So the population difference in 2004 is $22000-10400=11600$.