2. Using the six digits $0,1,2,3,4,5$ to form a four-digit even number without repeating digits, and arrange these even numbers in ascending order, then the 99th number is $\qquad$ .
2. The even numbers (with 0, 2, 4 as the unit digit) starting with 1 in the thousands place are $P_{3}^{1} P_{4}^{2}=36$; the even numbers (with 0, 4 as the unit digit) starting with 2 in the thousands place are $P_{2}^{1} P_{4}^{2}=$ 24; the even numbers (with 0, 2, 4 as the unit digit) starting with 3 in the thousands place are $P_{3}^{1} P_{4}^{2}=36$; the even numbers starting with 4 in the thousands place and 0 in the hundreds place (with 2 as the unit digit) are $P_{3}^{1}=3$; the total number of these numbers is $36+24+36+3=99$, and the last one is the 99th even number, which is 4052.