9. (10 points) In a square with a side length of 300 cm, two right-angled sectors and a semicircle are placed as shown in the figure. The area difference between the two shaded regions is $\qquad$ square centimeters, and the perimeter difference between the two shaded regions is $\qquad$ centimeters. ( $\pi$ is taken as 3.14)
9. (10 points) In a square with a side length of 300 cm, as shown in the figure, two right-angled sectors and a semicircle are placed. The difference in the areas of the two shaded regions is $\qquad$ square centimeters. $(\pi$ is taken as 3.14)
The area of sector $ABC$ = (1)+(2)+(3), the area of sector $BCD$ = (2)+(3)+(4), the area of square $ABCD$ = (1)+(2)+(3)+(4)+(5), so the area of sector $ABC$ + the area of sector $BCD$ - the area of square $ABCD$ = (2)+(3) - (5), from which the difference in the areas of the two shaded regions can be calculated;
(2) Connect $BE$, $CE$, since $BC=BE=CE$, triangle $BCE$ is an equilateral triangle, so the central angle of sector $BCE$ is $60^{\circ}$, and the central angle of sector $CED$ is $30^{\circ}$. The perimeter of the shaded regions can be calculated accordingly, and then the difference can be found.

【Solution】Solution: (1) $S_{\text {sector } ABC}=$ (1)+(2)+(3)
$S_{\text {sector } BCD}=(2)+(3)+(4)$
$S_{\text {square } ABCD}=(1)+(2)+(3)+(4)+(5)$,
(3) - (5) $=S_{\text {sector } ABC} + S_{\text {sector } BCD} - S_{\text {square } ABCD}$ - (2)
$$
\begin{array}{l}
=3.14 \times 300^{2} \div 4 + 3.14 \times 300^{2} \div 4 - 300 \times 300 - 3.14 \times (300 \div 2)^{2} \div 2 \\
=3.14 \times 90000 \div 4 + 3.14 \times 90000 \div 4 - 300 \times 300 - 3.14 \times 22500 \div 2 \\
=70650 + 70650 - 90000 - 35325 \\
=15975 \text { (square centimeters) }
\end{array}
$$
(2) Connect $BE$, $CE$

The perimeter of the shaded region (3) is
$$
\begin{array}{l}
\frac{1}{3} \times 3.14 \times 300 \times 2 + 3.14 \times 300 \div 2 \\
=628 + 471 \\
=1099 \text { (centimeters) }
\end{array}
$$

The perimeter of the shaded region (5) is
$$
\begin{array}{l}
\frac{1}{6} \times 3.14 \times 300 \times 2 + 300 \\
=314 + 300 \\
=614 \text { (centimeters) }
\end{array}
$$
$1099 - 614 = 485$ (centimeters)
Answer: The difference in the areas of the two shaded regions is 15975 square centimeters, and the difference in the perimeters of the two shaded regions is 485 centimeters. Therefore, the answers are: 15975, 485.