If $x=11, y=-8$, and $2 x-3 z=5 y$, what is the value of $z$ ?
(A) -6
(B) 13
(C) 54
(D) $\frac{62}{3}$
(E) $-\frac{71}{3}$
Since $x=11, y=-8$ and $2 x-3 z=5 y$, then $2 \times 11-3 z=5 \times(-8)$ or $22-3 z=-40$.

Therefore, $3 z=22+40=62$ and so $z=\frac{62}{3}$.

ANSWER: (D)