10. The three views of a geometric solid are shown in the figure, where the front view is an equilateral triangle, then the geometric solid
A. The radius of the circumscribed sphere is $\frac{\sqrt{3}}{3}$
B. The volume is $\sqrt{3}$
C. The surface area is $\sqrt{6}+\sqrt{3}+1$
D. The surface area of the circumscribed sphere is $\frac{16 \pi}{3}$
Draw the intuitive diagram of the geometric body, then the plane $P A B \perp$ plane $A B C$, $\triangle A B C$ is an isosceles right triangle, $P A=P B=P C=2$, thus $R=O P=O C=\frac{2 \sqrt{3}}{3}, S=4 \pi R^{2}=\frac{16 \pi}{3}$. Therefore, the answer is $D$.
Note: The volume of the geometric body is $\frac{\sqrt{3}}{3}$, and the surface area is $\sqrt{7}+\sqrt{3}+1$.