When playing preference, each of the three players is dealt 10 cards, and two cards are placed in the pot. How many different deals are possible in this game? (Consider possible deals without regard to which specific player receives each set of 10 cards.)

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See problems $\underline{30692}, \underline{30702}$.

## Answer

$\frac{C_{32}^{10} C_{22}^{10} C_{12}^{10}}{3!}=\frac{32!}{(10!)^{3} \cdot 2!\cdot 3!}$ arrangements.