【Question 1】
If $10+9+8 \times 7 \div \square+6-5 \times 4-3 \times 2=1$, then $\square=$ $\qquad$.
【Analysis and Solution】
$$
\begin{aligned}
10+9+8 \times 7 \div \square+6-5 \times 4-3 \times 2 & =1 \\
8 \times 7 \div \square & =1+3 \times 2+5 \times 4-6-9-10 \\
56 \div \square & =2 \\
\square & =28
\end{aligned}
$$