(3) If the function $y=\log _{a}\left(x^{2}-a x+1\right)$ has a minimum value, then the range of values for $a$ is ( ),
(A) $0<a<1$
(B) $0<a<2, a \neq 1$
(C) $1<a<2$
(D) $a \geqslant 2$
(3) When $01$, $y=\log _{a}\left(x^{2}-\right.$ $a x+1)$ has a minimum value if and only if $t=x^{2}-a x+1$ has a minimum value greater than 0. This is equivalent to $\Delta=a^{2}-4<0$, so $1<a<2$. Therefore, the correct choice is C.