14. (3 points) The unit digit of $1^{8}+2^{8}+3^{8}+4^{8}+5^{8}+6^{8}+7^{8}+8^{8}+9^{8}+10^{8}+11^{8}$ is
14. (3 points) The unit digit of $1^{8}+2^{8}+3^{8}+4^{8}+5^{8}+6^{8}+7^{8}+8^{8}+9^{8}+10^{8}+11^{8}$ is $\qquad$ 4.

【Solution】Solution: Since any power of 1 is 1, the unit digit of $1^{8}$ is 1, $2^{8}=(2 \times 2 \times 2 \times 2) \times(2 \times 2 \times 2 \times 2)=16^{2}$, the unit digit is 6, $3^{8}=(3 \times 3 \times 3 \times 3) \times(3 \times 3 \times 3 \times 3)=81^{2}$, the unit digit is 1.

Similarly: The unit digit of $4^{8}$ is 6, the unit digit of $5^{8}$ is 5, the unit digit of $6^{8}$ is 6, the unit digit of $7^{8}$ is 1, the unit digit of $8^{8}$ is 6, the unit digit of $9^{8}$ is 1, the unit digit of $10^{8}$ is 0, and the unit digit of $11^{8}$ is 1,
$$
1+6+1+6+5+6+1+6+1+0+1=34 \text {, }
$$

Therefore, the unit digit of $1^{8}+2^{8}+3^{8}+4^{8}+5^{8}+6^{8}+7^{8}+8^{8}+9^{8}+10^{8}+11^{8}$ is 4;
Hence the answer is: 4