4. A large bag contains coins of 1 cent, 10 cents, and 25 cents. The number of 10 cent coins is twice the number of 1 cent coins, and the number of 25 cent coins is three times the number of 10 cent coins. The total amount of money (in cents) in the bag could be
(A) 306 ;
(B) 333 ;
(C) 342 ;
(D) 348 ; (E) 360 .
4. Suppose there are $p$ pennies, $d$ dimes, and $q$ quarters in the bag. Given that $d=2 p, q=3 d$, thus $q=6 p$. Let $A$ be the value of the coins in the bag (in cents), then $A=p+10(2 p)+25(6 p)=171 p$. Among the given options, only $(C)$ is a multiple of 171.
(C) True.