2. The distance from the top of the can on the floor to the top of the bottle on the table is $150 \mathrm{~cm}$. The distance from the top of the bottle on the floor to the top of the can on the table is $110 \mathrm{~cm}$. What is the height of the table?

A $110 \mathrm{~cm}$
B $120 \mathrm{~cm}$
C $130 \mathrm{~cm}$
D $140 \mathrm{~cm}$
E $150 \mathrm{~cm}$
2. C Let $t$ be the height of the table, $b$ the height of the bottle and $c$ the height of the can (all measured in $\mathrm{cm}$ ). The first diagram shows $t+b=c+150$; the second diagram shows $t+c=b+110$. Adding these equations gives $2 t+b+c=260+b+c$ so $2 t=260$. So the table has height $130 \mathrm{~cm}$.