3. Use the method proposed in question 2 to solve:
(i) question 1 (vi) and (vii);
(ii) $256 x \equiv 179(\bmod 337)$;
(iii) $1215 x \equiv 560(\bmod 2755)$;
(iv) $1296 x \equiv 1105(\bmod 2413)$.
3. (i) As an example from Question 1 (vi). $2^{6} x \equiv 83(\bmod 105) . x \equiv 52^{6} \cdot 83 \equiv 1+52^{6} \cdot 19 \equiv$ $1+13 \cdot 13 \cdot 19 \equiv 1+64 \cdot 19 \equiv 62(\bmod 105)$.
(ii) $x \equiv 179 \cdot 168^{8} \equiv 179 \cdot 21 \cdot 21 \equiv 179 \cdot 104 \equiv 81(\bmod 337)$.
(iii) $243 x \equiv 112(\bmod 551), x \equiv 112 \cdot 184^{5} \equiv 200(\bmod 551)$, $x \equiv 200+551 \cdot t(\bmod 2755), t=0,1,2,3,4$.
(iv) $2^{4} \cdot 3^{4} x \equiv 1105(\bmod 2413), \quad x \equiv 1105 \cdot 402^{4} \equiv 1105 \cdot 67 \cdot 67 \equiv$ $-783(\bmod 2413)$, here using $2413=6 \cdot 402+1$.