## Problem 3

i) In the exercise $8+10 \times 2+2 \times 8: 4$ place a pair of round brackets so that you obtain:

a) the smallest possible number (3 points)

b) the largest possible number (2 points)

ii) Calculate $3 m+5 n+4 p$, given that $m+n=25$ and $n+2 p=65$. (2 points)
## Problem 3

i) a) $(8+10 \times 2+2 \cdot 8): 4=11$. $3 p$

$$
\text { b) } 8+10 \times(2+2) \times 8: 4=88 \quad \text {................................................................ 2p }
$$

ii) $3 m+3 n+2 n+4 p=3 \times(m+n)+2 \times(n+2 p)=$ $\qquad$ $1 p$

$3 \times 25+2 \times 65=75+130=205$ $1 p$