Shaovalov A.v.

For which $n>2$ can the integers from 1 to $n$ be arranged in a circle so that the sum of any two adjacent numbers is divisible by the next number in the clockwise direction?
Just like in solving the problem $\underline{98454}$, we prove that there is no more than one even number. Therefore, there are no more than three numbers in total. The numbers 1, 2, 3 can be placed in any order.

## Answer

Only when $n=3$