Consider a square of side length $12$ centimeters. Irina draws another square that has $8$ centimeters more of perimeter than the original square. What is the area of the square drawn by Irina?
1. Calculate the perimeter of the original square:
   \[
   \text{Perimeter of original square} = 4 \times 12 = 48 \text{ cm}
   \]

2. Determine the perimeter of Irina's square:
   \[
   \text{Perimeter of Irina's square} = 48 \text{ cm} + 8 \text{ cm} = 56 \text{ cm}
   \]

3. Calculate the side length of Irina's square:
   \[
   \text{Side length of Irina's square} = \frac{56 \text{ cm}}{4} = 14 \text{ cm}
   \]

4. Compute the area of Irina's square:
   \[
   \text{Area of Irina's square} = 14 \text{ cm} \times 14 \text{ cm} = 196 \text{ cm}^2
   \]

The final answer is \(\boxed{196}\) cm\(^2\).