$14, from 23, 65, 35, 96, 18, 82, 70$ these seven numbers, if any number of them are taken out and added together, the number of ways in which their sum is a multiple of 11 is $\qquad$ kinds.
【Analysis】If the sum of some numbers is a multiple of 11, then the sum of their remainders when divided by 11 should also be a multiple of 11.
The remainders of these 7 numbers when divided by 11 are $1, 10, 2, 8, 7, 5, 4$.
Therefore, the problem is essentially to find how many ways there are to add some of the numbers $1, 2, 4, 5, 7, 8, 10$ so that the sum is a multiple of 11.
1. Taking 2 numbers, there are $(1, 10)(4, 7)$, a total of 2 ways.
2. Taking 3 numbers, there are $(1, 2, 8)(2, 4, 5)(4, 8, 10)(5, 7, 10)$, a total of 4 ways.
3. Taking 4 numbers, there are $(1, 4, 7, 10)(2, 5, 7, 8)$, a total of 2 ways.
4. Taking 5 numbers, there are $(1, 2, 4, 5, 10)(1, 2, 4, 7, 8)$, a total of 2 ways.
5. Taking 6 numbers, there is $(1, 2, 5, 7, 8, 10)$, a total of 1 way.
6. Taking 7 numbers, there are 0 ways.
In summary, there are $2+4+2+2+1=11$ ways.