4. (8 points) Fill in each box with a digit so that the multiplication problem is correct. Then, the sum of the two multipliers is . $\qquad$

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4. (8 points) Fill in a digit in each box so that the multiplication vertical equation holds. Then, the sum of the two multipliers is $\underline{118}$.

【Solution】Solution: According to the problem, we know:
The first digit of the result is 2, so the first digit in the second result is also 2.
Based on the 1 in the first result, there must be a carry of 1 from multiplying by the digit 5, and the tens digit must be even to meet the condition. The unit digit of the first multiplier can only be 2 or 3 to satisfy the carry of 1.

When the unit digit of the first multiplier is 2, no even number in the tens place can produce a result in the 200s. This does not meet the problem's requirements.

When the unit digit of the first multiplier is 3, let's examine the even number cases.
$23 \times 9=207.43,63,83$; no matter what number they are multiplied by, they cannot form a result with the hundreds and tens digits being 20.
Therefore, it must be $23 \times 95=2185$, so $23+95=118$.
Thus, the answer is: 118