9. (5 points) A cylindrical container with a depth of 30 cm, an outer diameter of 22 cm, and a wall thickness of 1 cm, is already filled with water to a depth of 27.5 cm. Now, a conical iron block with a base diameter of 10 cm and a height of 30 cm is placed inside. Then, $\qquad$ cubic centimeters of water will overflow.
【Solution】Solution: The original volume of water is: $3.14 \times\left(\frac{20}{2}\right)^{2} \times 27.5=8635$ (cubic centimeters), after placing the conical iron block, the volume of water in the cylindrical container is:
$$
\begin{array}{l}
3.14 \times\left(\frac{20}{2}\right)^{2} \times 30-\frac{1}{3} \times 3.14 \times\left(\frac{10}{2}\right)^{2} \times 30, \\
=9420-785, \\
=8635 \text { (cubic centimeters), }
\end{array}
$$

Therefore, the volume of water that overflowed is: $8635-8635=0$ (cubic centimeters), answer: 0 cubic centimeters of water overflowed. The answer is: 0.