8. As shown in the figure, in the right-angled $\triangle A B C$, $A B=3, A C=4$, points $D 、 E 、 F 、 G 、 H 、 I$ are all on the rectangle $K L M J$, and $A B E D 、 A C H I 、 B C G F$ are all squares. Then the area of $K L M J$ is $\qquad$ ـ
【Answer】 110

【Solution】As shown in the figure, after cutting, we get the cyclic quadrilateral $A N L O$, thus obtaining four identical triangles: $\triangle A B C$, $\triangle N F B$, $\triangle L G F$, $\triangle O C G$, each with an area of $\frac{1}{2} \times 3 \times 4=6$. Then, the sum of the areas of the three squares is $9+16+25=50$, and the area of each of the three rectangles is $3 \times 4=12$. Therefore, the total area is
$$
4 \times 6+50+12 \times 3=24+50+36=110
$$