10.160. In a trapezoid with an area of $594 \mathrm{~m}^{2}$, the height is 22 m, and the difference between the parallel sides is $6 \mathrm{~m}$. Find the length of each of the parallel sides.
## Solution.

Since $S=\frac{1}{2}(a+b) h$, then $\frac{1}{2}(a+b) \cdot 22=594$, from which $a+b=54$. From the system of equations $\left\{\begin{array}{l}a+b=54, \\ a-b=6\end{array}\right.$ we find $a=30$ (m), $b=24$ (m).

Answer: $\quad 30$ m and 24 m.