14. One of the longest-living animals in the world is the Arctic quahog, and generally, Arctic quahogs can live for hundreds of years. Now there is a large Arctic quahog, 70 years old, and 4 smaller Arctic quahogs whose ages are 3 years, 4 years, 5 years, and 6 years, respectively. In $\qquad$ years, the sum of the ages of the 4 smaller Arctic quahogs will first exceed the age of the large Arctic quahog.
【Analysis】The current age difference is $70-3-4-5-6=52$ (years), every year the 4 younger ones grow $4-1=3$ (years) more than the older one, $52 \div 3=17 \ldots \ldots .1$, so it will take $17+1=18$ (years).