33. Dima and Gosha are playing "noughts-noughts" on a $14 \times 441$ board. In one move, a player can place one nought in any empty cell. They take turns, with Gosha going first. The player who, after their move, forms 7 consecutive noughts either vertically or horizontally wins. Who among the players can win, regardless of how their opponent plays?
33. Dima will win. In each column, we will divide the cells into pairs of the form $(a, a+7)$. Dima should complete Gosha's move to a pair, except in the case when he sees 7 zeros in a row. It is clear that Gosha will not be able to win in a row. Suppose that Gosha wins by placing seven zeros in a row vertically. Note that any arrangement of seven zeros in a row in a column of 14 cells touches one cell from each pair. Therefore, before Gosha's winning move, each player made 6 moves in this column. Then, after Gosha's sixth move in this column, there were already 11 zeros in it. Consequently, in one of its seven-cell halves, there were 6 zeros, and Dima could win on the next move by placing the seventh zero in this half (as required by his strategy).