1. The minimum value of the function $f(x)=\frac{5-4 x+x^{2}}{2-x}$ on $(-\infty, 2)$ is ( ).
(A) 0
(B) 1
(C) 2
(D) 3
- 1. C.

When $x<2$. Therefore,
$$
f(x)=\frac{1}{2-x}+(2-x) \geqslant 2,
$$

with equality holding if and only if $\frac{1}{2-x}=2-x$. This equation has a solution $x=1 \in(-\infty, 2)$. Therefore, the minimum value of $f(x)$ on $(-\infty, 2)$ is 2.