A2. The painter drew a picture with a building and a bush in front of it on an advertising panel. In the picture, the bush is $1.5 \mathrm{~cm}$ tall, and the building is $7.5 \mathrm{dm}$ tall. In nature, the bush is $\frac{3}{4} \mathrm{~m}$ tall. How tall is the building if the painter drew it in the same ratio as in nature?
(A) $1.5 \mathrm{~m}$
(B) $150 \mathrm{dm}$
(C) $3.75 \mathrm{~m}$
(D) $37500 \mathrm{~cm}$
(E) $375 \mathrm{dm}$
A2. In the picture, the sizes of the plant and the building are in a ratio of 1:50. If the plant is $0.75 \mathrm{~m}$ tall in nature, the building is 50 times as tall, which is $37.5 \mathrm{~m}=375 \mathrm{~dm}$.