1. The sum of the x-coordinates of the x-axis intercepts of the graph of the function $y=x^{2}-2006|x|+2008$ is $\qquad$
$=.1 .0$.
The original problem is transformed into solving the equation
$$
x^{2}-2006|x|+2008=0
$$

We are to find the sum of all real roots.
If a number $x_{0}$ is a root of equation (1), then its opposite number $-x_{0}$ is also a root of equation (1). Therefore, the sum of all real roots of the equation is 0, i.e., the sum of the x-coordinates of the points where it intersects the x-axis is 0.