A single elimination tournament is held with $2016$ participants. In each round, players pair up to play games with each other. There are no ties, and if there are an odd number of players remaining before a round then one person will get a bye for the round. Find the minimum number of rounds needed to determine a winner.

[i]Proposed by Nathan Ramesh
1. In a single elimination tournament, each round halves the number of participants (or nearly halves if there is an odd number of participants, in which case one participant gets a bye).
2. We start with 2016 participants. After each round, the number of participants is approximately halved.

Let's calculate the number of participants after each round:
- After 1st round: $\left\lceil \frac{2016}{2} \right\rceil = 1008$
- After 2nd round: $\left\lceil \frac{1008}{2} \right\rceil = 504$
- After 3rd round: $\left\lceil \frac{504}{2} \right\rceil = 252$
- After 4th round: $\left\lceil \frac{252}{2} \right\rceil = 126$
- After 5th round: $\left\lceil \frac{126}{2} \right\rceil = 63$

At this point, we have 63 participants, which is an odd number. One participant will get a bye in the next round:
- After 6th round: $\left\lceil \frac{63 + 1}{2} \right\rceil = 32$

Continuing with the halving process:
- After 7th round: $\left\lceil \frac{32}{2} \right\rceil = 16$
- After 8th round: $\left\lceil \frac{16}{2} \right\rceil = 8$
- After 9th round: $\left\lceil \frac{8}{2} \right\rceil = 4$
- After 10th round: $\left\lceil \frac{4}{2} \right\rceil = 2$
- After 11th round: $\left\lceil \frac{2}{2} \right\rceil = 1$

Thus, it takes 11 rounds to determine a winner.

The final answer is $\boxed{11}$