If $a=2^{3}$ and $b=3^{2}$ evaluate $\frac{(a-b)^{2015}+1^{2015}}{(a-b)^{2015}-1^{2015}}$.
Since $a=2^{3}$ and $b=3^{2}$, then $a-b=8-9=-1$.

Therefore,

$$
\frac{(a-b)^{2015}+1^{2015}}{(a-b)^{2015}-1^{2015}}=\frac{(-1)^{2015}+1}{(-1)^{2015}-1}=\frac{-1+1}{-1-1}=0
$$

ANSWER: 0