80. In $\triangle A B C$, $C P=\frac{1}{3} B C, C Q=\frac{1}{4} A C, B Q$ intersects $A P$ at point $N$. If the area of $\triangle A B C$ is $12$, the area of $\triangle A B N$ is $\qquad$
Reference answer: $72 / 11$