8. Finding the minimum force acting on the buoy from the current, knowing the horizontal component of the tension force, is not difficult.

Consider the forces acting on the buoy along the horizontal axis: on one side, there is the force from the current, and on the other side, the horizontal component of the tension force,

$M_{5} * a_{\sigma_{-} x}=T^{*} \sin (a)-F_{\text {current_rop }}$

where $M_{5}$ is the mass of the buoy, $a_x$ is its acceleration along the horizontal axis, and $F_{\text {current_rop }}$ is the force acting on the buoy from the current in the horizontal direction.

Therefore, at the moment the anchor detaches, the equality holds

$F_{\text {current_rop }}=T^{*} \sin (a)$

which means the minimum value of the force acting on the buoy from the current is equal to its horizontal projection and is

$$
F_{\text {current }}=F_{\text {current_hor }}=400[\mathrm{H}]
$$
Answer: The minimum value of the force acting on the buoy from the current, capable of moving the buoy from its position, is $400 \mathrm{H}$.

## Grading. Maximum 12 points.