(Column 11 Arrange the three numbers $1.5^{-0.2}, 1.5^{0.7},\left(\frac{2}{3}\right)^{\frac{1}{3}}$ in ascending order.
Solve $\left(\frac{2}{3}\right)^{\frac{1}{3}}=\left(\frac{3}{2}\right)^{-\frac{1}{3}}=1.5^{-\frac{1}{3}}$, the exponential function $y=1.5^{x}$, is increasing on $(-\infty,+\infty)$.
Since $-\frac{1}{3}<-0.2<0.7$, it follows that $1.5^{-\frac{1}{3}}<1.5^{-0.2}<1.5^{0.7}$, that is
$$
\left(\frac{2}{3}\right)^{\frac{1}{3}}<1.5^{-0.2}<1.5^{0.7} .
$$