[Cubic Polynomials]

One of the roots of the equation $x^{3}-6 x^{2}+a x-6=0$ is 3. Solve the equation.

#
According to Vieta's theorem, the sum of the two remaining roots is 3, and their product is 2. From this, it is clear that $x_{1}=1$, $x_{2}=2$.

## Answer

$x_{1}=1, x_{2}=2, x_{3}=3$