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In the numbers МИХАЙЛО and ЛОМОНОСОВ, each letter represents a digit (different letters correspond to different digits). It is known that the products of the digits of these numbers are equal. Can both numbers be odd?
Note that 10 different letters are used, so each digit is denoted by some letter, in particular, among these digits there is a zero. Thus, the product of the digits of one (and therefore the second) number is zero. Consequently, there is a zero in the notation of both numbers. In the words MIKHAILO and LOMONOSOV, the common letters are M, L, and O, so zero is denoted by one of them. It cannot be L and M, since numbers cannot start with zero. Therefore, zero is denoted by the letter O. In the number MIKHAILO, the zero is at the end, so it is even.

## Answer

No. $\quad 2$