A list of 5 integers repeats to form the pattern:

$$
4,-3,2,-1,0,4,-3,2,-1,0, \ldots
$$

What is the sum of the first 23 integers?
(A) 3
(B) 8
(C) 10
(D) 11
(E) 13
The sum of each block of 5 repeating integers is $4-3+2-1+0=2$.

In the first 23 integers, there are 4 such blocks of 5 integers, plus 3 additional integers (since $23=4 \times 5+3$ ).

The sum of the 4 blocks of 5 repeating integers is $4 \times 2=8$, and the next three integers in the list following these 4 blocks are $4,-3,2$.

Thus, the sum of the first 23 integers is $8+4-3+2=11$.

ANSWER: (D)