An [i]exterior [/i] angle is the supplementary angle to an interior angle in a polygon. What is the sum of the exterior angles of a triangle and dodecagon ($12$-gon), in degrees?
1. **Understanding the problem**: We need to find the sum of the exterior angles of a triangle and a dodecagon (12-gon).

2. **Sum of exterior angles of any polygon**: The sum of the exterior angles of any polygon is always $360^\circ$. This is a well-known property of polygons.

3. **Sum of exterior angles of a triangle**: For a triangle, the sum of the exterior angles is $360^\circ$.

4. **Sum of exterior angles of a dodecagon**: For a dodecagon (12-gon), the sum of the exterior angles is also $360^\circ$.

5. **Adding the sums**: To find the total sum of the exterior angles of both the triangle and the dodecagon, we add the two sums together:
   \[
   360^\circ + 360^\circ = 720^\circ
   \]

The final answer is $\boxed{720^\circ}$.