1. $\frac{\text { Hua Cup }}{\text { Shao } \times \text { Jun }+ \text { Jin Tan }+ \text { Lun } \times \text { Shu }}=15$
In the equation above, different Chinese characters represent different digits from $1-9$. When the three-digit number “Hua Cup Sai” reaches its maximum value, please write down one way to make the equation true.
1. $\frac{\text { HuaCup }}{\text { Shao } \times \text { Jun }+ \text { JinTan }+ \text { Lun } \times \text { Shu }}=15$
In the equation above, different Chinese characters represent different digits from $1-9$. When the three-digit number “HuaCup” reaches its maximum value, please write down one way to fill in the numbers that makes the equation true.
【Analysis】First, analyze that since the value of the fraction is 15, the numerator must be a multiple of 15, and the three-digit number must be the largest possible, so this three-digit number is 975. Continue reasoning to find the solution.
【Solution】Solution: According to the problem:
(1) Since the value of the fraction is 15, the numerator must be a multiple of 15, and the three-digit number must be the largest possible, so this three-digit number is 975.
(2) Therefore, $975 \div 15=65$, so the denominator value is 65, and the remaining digits are $1,2,3,4,6,8$.
(3) If $6 \times 8=48$, the sum of the other digits is 17, which does not work. If $4 \times 8=32$, the sum of the other digits is 33, which does not work. If $3 \times 8=24$, the sum of the other digits is 41, which also does not work.
$2 \times 8+43+1 \times 6=65$ satisfies the condition.
Therefore, the answer is: 975