When the polynomial $x^3-2$ is divided by the polynomial $x^2-2$, the remainder is 
$\text{(A)} \ 2 \qquad  \text{(B)} \ -2 \qquad  \text{(C)} \ -2x-2 \qquad  \text{(D)} \ 2x+2 \qquad  \text{(E)} \ 2x-2$
Working out $\frac{x^3-2}{x^2-2}$ using polynomial long division, we get $x + \frac{2x-2}{x^2-2}$. 
Thus the answer is $2x -2$, for choice $\boxed{(E)}$.