14. (1994 American High School Mathematics Examination) A bag of popping corn, of which $\frac{2}{3}$ are white kernels and $\frac{1}{3}$ are yellow kernels. It is known that $\frac{1}{2}$ of the white kernels will pop, and $\frac{2}{3}$ of the yellow kernels will pop. If a kernel is randomly selected from the bag and placed in the pan and it pops, what is the probability that it is a white kernel?
A. $\frac{1}{2}$
B. $\frac{5}{9}$
C. $\frac{4}{7}$
D. $\frac{3}{5}$
E. $\frac{2}{3}$
14. D. Reason: According to the problem, the proportion of white corn that will pop is $\frac{2}{3} \cdot \frac{1}{2}=\frac{1}{3}$, and the proportion of yellow corn that will pop is $\frac{1}{3} \cdot \frac{2}{3}=\frac{2}{9}$. Therefore, the probability that a popped kernel is white is
$$
\frac{\frac{1}{3}}{\frac{1}{3}+\frac{2}{9}}=\frac{3}{5}
$$