In the diagram, $P Q R, Q S T$ and $P S U$ are straight lines. The value of $x$ is
(A) 75
(B) 85
(C) 95
(D) 125
(E) 155

![](https://cdn.mathpix.com/cropped/2024_04_20_ac36362783317e0251fdg-086.jpg?height=260&width=458&top_left_y=800&top_left_x=1300)
Since $\angle T Q R=125^{\circ}$, then $\angle T Q P=180^{\circ}-\angle T Q R=180^{\circ}-125^{\circ}=55^{\circ}$.

Since the sum of the angles in a triangle is $180^{\circ}$, then

$$
\angle P S Q=180^{\circ}-\angle S P Q-\angle S Q P=180^{\circ}-30^{\circ}-55^{\circ}=95^{\circ}
$$

Since $\angle T S U$ and $\angle P S Q$ are opposite, then $\angle T S U=\angle P S Q=95^{\circ}$, so $x=95$.

ANSWER: (C)