The height of a ramp is $1.2 \mathrm{~m}$, its length is $4.8 \mathrm{~m}$. At the center of the ramp, there is a $14.6 \mathrm{~kg}$ mass, to which a rope is attached. This rope passes over a pulley at the top of the ramp, so that its direction is parallel to the direction of the ramp. On the other end of the rope, a $2.2 \mathrm{~kg}$ mass is hanging. In which direction will the motion occur and what will be its acceleration:1[^0]


[^0]:    ${ }^{1}$ The acceleration due to free fall: $g=980.8 \frac{\mathrm{cm}}{\mathrm{sec}^{2}}$ (according to Gruber's determination, in Budapest $g=980.837 \frac{\mathrm{cm}}{\mathrm{sec}^{2}}$).
To balance a body resting on an incline, a counterweight of $14.6 \cdot \frac{1.2}{4.8} = 3.65 \text{ kg}$ is required. Since only a $2.2 \text{ kg}$ weight is available, the entire system will move downward along the incline.

$$
\text{Acceleration} = \frac{\text{driving force}}{\text{moving mass}} = \frac{1.45 \cdot g}{16.8} = 84.7 \frac{\text{cm}}{\text{sec}^2}.
$$

(Schwarz Oszkár, Budapest.)

The problem was also solved by: Dömény I., Jánosy Gy.