The value of $\frac{3}{a+b}$ when $a=4$ and $b=-4$ is: 
$\textbf{(A)}\ 3\qquad\textbf{(B)}\ \frac{3}{8}\qquad\textbf{(C)}\ 0\qquad\textbf{(D)}\ \text{any finite number}\qquad\textbf{(E)}\ \text{meaningless}$
As the denominator is $4 - (-4) = 0$, the value of the fraction $\frac{3}{4 - (-4)}$ is $\textbf{(E)}\ \text{meaningless}$