5、A, B, and C each have some apples, with the total being less than 100. If A gives $\frac{1}{6}$ and $\frac{1}{4}$ of his apples to B and C respectively, the three will have the same number of apples. Therefore, A originally had the most $\qquad$ apples, and originally B had  more apples than C. apples.
【Analysis】Suppose A originally had 12 shares, then gave 2 shares to B, and 3 shares to C, leaving A with 7 shares. The three together have 21 shares, and the total number is less than 100, so each share can be at most 4. Therefore, A can have at most 48 apples. B originally had 5 shares, and C had 4 shares, so B has 1 more share than C, which means 4 more apples.