2. Friends Miha and Blaž are renting motorbikes for a weekend trip from different providers. Miha has to pay 100 euros at the beginning, and when he returns the motorbike, he has to pay an additional 4 euros for each kilometer driven. Blaž pays 200 euros at the beginning, and then 3 euros for each kilometer driven. How many kilometers at least must the friends drive for Miha to pay more than Blaž?
2. Let $x$ be the number of kilometers traveled, and $m(x)$ and $b(x)$ be the amounts that depend on $x$. The amount for Miha's bike is $m(x)=4x+100$, and the amount for Blaž's bike is $b(x)=3x+200$. Miha will pay more than Blaž when $4x+100 > 3x+200$. Solving the inequality, we get the solution $x > 100$. They must travel at least 101 kilometers.

![](https://cdn.mathpix.com/cropped/2024_06_07_6d1b766ff5bddd57ba61g-06.jpg?height=60&width=1642&top_left_y=2300&top_left_x=207)

![](https://cdn.mathpix.com/cropped/2024_06_07_6d1b766ff5bddd57ba61g-06.jpg?height=51&width=1639&top_left_y=2353&top_left_x=206)

![](https://cdn.mathpix.com/cropped/2024_06_07_6d1b766ff5bddd57ba61g-06.jpg?height=54&width=1636&top_left_y=2400&top_left_x=207)

Solving the inequality . .............................................................................................................................

![](https://cdn.mathpix.com/cropped/2024_06_07_6d1b766ff5bddd57ba61g-06.jpg?height=48&width=1636&top_left_y=2506&top_left_x=210)

Answer: They must travel at least 101 kilometers..................................... 1 point