1. A job was started by 33 workers and according to the plan, it was supposed to be completed in 80 days. However, after 16 days of work, 9 workers were assigned to another job. How many days will it take to complete the work?
Solution. Let, starting from the 16th day, 33-9 workers complete the work in $x$ days. Then it holds: $80 \cdot 33=16 \cdot 33+x(33-9)$ from which
$x=88$. Therefore, the entire work will be completed in 88+16 days, so the delay will be $8+16=24$ days.