11. (5 points) Arrange the natural numbers $1,2,3,4$, in ascending order without any gaps, to get: 1234567891011121314. In this sequence of digits, when the first set of 5 consecutive even digits appears, the position of the first (even) digit from the left is the how many-th digit?
【Analysis】First, analyze according to the number of digits. It is known that 2-digit numbers do not meet the requirements. Among the 3-digit numbers, $100-199$ also do not meet the requirements. Continue reasoning accordingly.

【Solution】Solution: According to the problem:
First, if it is a 2-digit number, then 5 consecutive even numbers cannot appear. Considering 3-digit numbers, if they are between $100-200$, every 3 digits must include 1, which does not meet the requirements.
200201 is exactly 5 even numbers connected, which meets the requirements.
$1-9$ have a total of 9 digits;
10 - 99 have a total of 90 numbers, which is 180 digits.
100 - 199 have a total of 100 numbers, which is 300 digits.
Adding one more is the number required by the problem.
In total, $9+180+300+1=490$.
Answer: When even digits first appear 5 times consecutively, the position of the first (even) digit from the left is the 490th.