[ Decimal numeral system ]

Can you find two consecutive numbers, where the sum of the digits of the first one is 8, and the second one is divisible by 8?

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Think about what can be said about the sum of the digits of a number if the sum of the digits of the previous number is 8.

## Solution

The sum of the digits of the second number is likely to be 9 (since the previous one is 8). Let's try to find numbers that are simultaneously multiples of 9 (sum of digits 9) and 8 (by the condition), i.e., numbers that are multiples of 72. The first such number that comes to mind - 72 - works, since it is divisible by 8, and the previous number - 71 - has a sum of digits equal to 8. Thus, these numbers are 71 and 72.

## Answer

71 and 72.