Consider the set $A=\{1,2,3, \ldots, 2011\}$. How many subsets of $A$ exist such that the sum of their elements is 2023060?
Observe that the sum $1+2+\cdots+2011=\frac{2011 \times 2012}{2}=$ 2023066. Therefore, to obtain a subset of $A$ that has a sum of its elements equal to 2023060, it suffices to remove from $A$ the elements whose sum is 6. The possible cases are:

- Subsets with one element: $\{6\}$.
- Subsets with two elements: $\{2,4\}$ and $\{1,5\}$.
- Subsets with three elements: $\{1,2,3\}$.

Therefore, there are four subsets of $A$ whose sum of elements is 6, and consequently, there are also four subsets of $A$ whose sum of elements is 2023060.

Suggestion: Observe that the ant is always at 1 in the odd seconds.