IS. 2 Let $Q=\log _{128} 2^{3}+\log _{128} 2^{5}+\log _{128} 2^{7}+\ldots+\log _{128} 2^{P}$. Find the value of $Q$.
$\begin{aligned} Q & =3 \log _{128} 2+5 \log _{128} 2+7 \log _{128} 2+\ldots+95 \log _{128} 2 \\ & =(3+5+\ldots+95) \log _{128} 2=\frac{3+95}{2} \times 47 \times \log _{128} 2=\log _{128} 2^{2303}=\log _{128}\left(2^{7}\right)^{329}=329\end{aligned}$