7. Given that the real number $x$ satisfies
$$
|2 x+1|+|2 x-5|=6 \text {. }
$$

Then the range of values for $x$ is $\qquad$
$$
\text { II.7. }\left[-\frac{1}{2}, \frac{5}{2}\right] \text {. }
$$

Notice that,
$$
\begin{array}{l}
|2 x+1|+|2 x-5| \\
\geqslant|(2 x+1)+(5-2 x)|=6 .
\end{array}
$$

The equality holds if and only if $(2 x+1)(2 x-5) \leqslant 0$, that is,
$$
-\frac{1}{2} \leqslant x \leqslant \frac{5}{2}
$$