7.2. The sum of three positive integers (not necessarily distinct) is 100. By subtracting them pairwise (the larger minus the smaller), three difference numbers can be obtained. What is the maximum possible value of the sum of these three difference numbers?
7.2. The maximum possible value of the sum of these three differences is 194.

Let the three positive integers be $a$, $b$, and $c$, and assume without loss of generality that $a \geqslant b \geqslant c$. The sum of their pairwise differences is
$$
(a-b)+(a-c)+(b-c)=2(a-c).
$$

Since $b \geqslant 1$ and $c \geqslant 1$, and $a+b+c=100$, it follows that $a \leqslant 98$. Therefore,
$$
2(a-c) \leqslant 2(98-1)=194.
$$

The equality holds when $a=98$, $b=c=1$.