7. Given complex numbers $z_{1}$ and $z_{2}$ satisfy $\left|z_{1}\right|=2,\left|z_{2}\right|=3$. If the angle between the vectors they correspond to is $60^{\circ}$, then $\left|\frac{z_{1}+z_{2}}{z_{1}-z_{2}}\right|=$ $\qquad$ .
$=.7 . \frac{\sqrt{133}}{7}$.
As shown in Figure 8, by the cosine rule we get
$$
\begin{array}{l}
\left|z_{1}+z_{2}\right|=\sqrt{19}, \\
\left|z_{1}-z_{2}\right|=\sqrt{7} .
\end{array}
$$

Therefore, $\left|\frac{z_{1}+z_{2}}{z_{1}-z_{2}}\right|=\frac{\sqrt{133}}{7}$.