6. (3 points) A deck of playing cards has 54 cards, with the jokers considered as 0 points, $A$ as 1 point, $J$ as 11 points, $Q$ as 12 points, and $K$ as 13 points. If you draw several cards at random, disregarding the suits, and if it is required that each draw must include 2 cards whose points add up to 14, then at least ( ) cards must be drawn.
A. 26
B. 27
C. 28
D. 29
【Analysis】54 cards are divided into four parts as follows: the Big Joker and the Small Joker, $1-6$, $7$, $8-13$. Considering the worst-case scenario: how can you get the most cards without any two cards adding up to 14? In these four parts, when you take cards from the $1-6$ range, you cannot take cards from the $8-13$ range, and vice versa; and you can only take one 7, and the Big and Small Jokers must be taken. Thus, you can take the cards as follows: the Big and Small Jokers, all from $1-6$, and one 7 (or the Big and Small Jokers, one 7, and all from $8-13$), totaling 27 cards. Taking one more card will definitely result in two cards adding up to 14. Therefore, to meet the requirement of the question, you need to take at least $27+1=28$ cards.

【Solution】According to the analysis of the problem, you can take the cards as follows: the Big and Small Jokers, all from $1-6$, and one 7 (or the Big and Small Jokers, one 7, and all from $8-13$), totaling 27 cards,

Taking one more card will definitely result in two cards adding up to 14.
Therefore, to meet the requirement of the question, you need to take at least $27+1=28$ cards.
So the answer is: $C$.