【Example 1】 8 pairs of brothers stand in a circle, requiring each pair of brothers to be adjacent. How many different ways are there to arrange them?
Since there is no explicit absolute position when standing in a circle, we should only consider the relative order. First, let the 4 elder brothers stand in a circle, which has $\frac{1}{4} A_{4}^{4}$ $=3!=6$ different circular arrangements; then let the 4 younger brothers insert themselves in between, each can stand on the left or the right of their elder brother, with 2 ways for each, so there are a total of $6 \cdot 2^{4}=96$ different ways to stand.