Madam Mim has a deck of $52$ cards, stacked in a pile with their backs facing up. Mim separates the small pile consisting of the seven cards on the top of the deck, turns it upside down, and places it at the bottom of the deck. All cards are again in one pile, but not all of them face down; the seven cards at the bottom do, in fact, face up. Mim repeats this move until all cards have their backs facing up again. In total, how many moves did Mim make $?$
To solve this problem, we need to understand the effect of each move on the deck of cards. Each move consists of taking the top 7 cards, reversing their order, and placing them at the bottom of the deck. We need to determine how many such moves are required until all cards are facing down again.

1. **Initial Setup**:
   - We start with a deck of 52 cards, all facing down.
   - After the first move, the top 7 cards are reversed and placed at the bottom, so the bottom 7 cards are now facing up.

2. **Effect of Each Move**:
   - Each move affects the position of the cards in the deck. Specifically, the top 7 cards are moved to the bottom in reversed order.
   - We need to track the position of the cards and their orientation (facing up or down).

3. **Mathematical Representation**:
   - Let’s denote the position of the cards by their indices from 0 to 51 (0 being the top card and 51 being the bottom card).
   - After each move, the position of each card changes. We can represent this as a permutation of the indices.

4. **Cycle Detection**:
   - To find the number of moves required to return to the original configuration, we need to determine the cycle length of the permutation induced by the moves.
   - Specifically, we need to find the smallest positive integer \( k \) such that after \( k \) moves, the deck returns to its original state.

5. **Permutation Analysis**:
   - Each move can be seen as a permutation of the indices. Let’s denote the permutation by \( \sigma \).
   - The permutation \( \sigma \) can be described as follows: \( \sigma(i) = (i + 7) \mod 52 \) for \( i \) in the range 0 to 51.

6. **Finding the Order of the Permutation**:
   - The order of the permutation \( \sigma \) is the smallest positive integer \( k \) such that \( \sigma^k \) is the identity permutation.
   - This means we need to find the smallest \( k \) such that \( 7k \equiv 0 \pmod{52} \).

7. **Solving the Congruence**:
   - We need to solve \( 7k \equiv 0 \pmod{52} \).
   - This is equivalent to finding the smallest \( k \) such that \( 7k \) is a multiple of 52.
   - Since 7 and 52 are coprime (their greatest common divisor is 1), the smallest \( k \) is \( 52 \).

8. **Conclusion**:
   - Therefore, the number of moves required for all cards to return to their original state (all facing down) is \( 52 \).

The final answer is \( \boxed{52} \).