A3. In the country of Dragon Hill, the inhabitants have decided to use a new way of measuring daily time. Each day is divided into two equal halves at noon and midnight. Instead of dividing each half into 12 hours of 60 minutes each, they divided it into 10 dragon hours of 100 dragon minutes each. The mayor of Dragon Hill has a clock that was made to measure time in dragon hours and dragon minutes. At noon, the mayor's clock shows 10:00, while a regular clock shows 12:00. What time does the regular clock show when the mayor's clock shows 8:25?
(A) 7:54
(B) 8:15
(C) 8:25
(D) 9:15
(E) 9:54
A3. Time $8.25 \mathrm{v}$ in dragon hours and dragon minutes corresponds to $8 \frac{25}{100}=8 \frac{1}{4}=\frac{33}{4}$ dragon hours. Since 10 dragon hours equal 12 regular hours, 1 dragon hour equals $\frac{12}{10}$ regular hours. Therefore, $\frac{33}{4}$ dragon hours correspond to $\frac{33}{4} \cdot \frac{12}{10}=\frac{99}{10}=9 \frac{9}{10}=9 \frac{54}{60}$ regular hours. Thus, the regular clock would show 9.54.