9. (12 points) Three people, A, B, and C, depart from location $A$ to location $B$. A departs at 8:00, B at 8:20, and C at 8:30. They all travel at the same speed. 10 minutes after C departs, the distance from A to $B$ is exactly half the distance from B to $B$. At this moment, C is 2015 meters away from $B$. What is the distance between $A$ and $B$ in meters? $\qquad$
【Solution】Solution: According to the problem, we have:
Let the distance between Yi and Bing, which is 10 minutes of travel, be 1 unit;
The distance between Yi and Jia, which is 20 minutes of travel, is 2 units;
The distance from Jia to $B$ is equal to the distance between Jia and Yi, which is also 2 units.
Therefore, the distance from Bing to $B$ is 5 units corresponding to 2015, so 1 unit is $2015 \div 5=403$ meters.
The distance between Yi and Bing is also the distance Bing travels in 10 minutes, which is 1 unit, so the total distance is 6 units, which is: $403 \times 6=2418$ meters.

Therefore, the answer is: 2418.