9. On each of three pieces of paper a five-digit number is written as shown. Three of the digits are covered. The sum of the three numbers is 57263 . What are the covered digits?
A 0,2 and 2
B 1,2 and 9
C 2,4 and 9
D 2, 7 and 8
E 5,7 and 8
9. B Let the missing digits be $P, Q, R$. Placing the numbers in a column addition, we get:

There is nothing to carry from the sum of the tens digits, so the sum of the middle digits is $7+P+3$ and this must end in 2 . Hence $P=2$. The sum of the digits in the next column is $5+2+R+1$ (where the 1 is carried from the middle digits). This must end in a 7 , giving $R=9$. The first digits have sum $1+2+Q+1$ and must end in 5 so $Q=1$. Therefore the missing digits are $1,2,9$.