2. In tetrahedron $ABCD$, if $AB=CD=5$, $AC=BD=4$, $AD=BC=x$, then the range of values for $x$ is ( ).
(A) $1<x<9$
(B) $1<x<\sqrt{41}$
(C) $3<x<9$
(D) $3<x<\sqrt{41}$
2.D.

Completing the shape to make the edges of tetrahedron $ABCD$ the face diagonals of a rectangular prism. It is easy to see that $\triangle ABC$ is an acute triangle, hence, $x^{2}+4^{2}>5^{2}$ and $x^{2}<4^{2}+5^{2}$, i.e., $3<x<\sqrt{41}$.