2. Compute
$$
\sum_{n_{60}=0}^{2} \sum_{n_{59}=0}^{n_{60}} \cdots \sum_{n_{2}=0}^{n_{3}} \sum_{n_{1}=0}^{n_{2}} \sum_{n_{0}=0}^{n_{1}} 1 .
$$
Answer: 1953
Solution: The given sum counts the number of non-decreasing 61-tuples of integers $\left(n_{0}, \ldots, n_{60}\right)$ from the set $\{0,1,2\}$. Such 61-tuples are in one-to-one correspondence with strictly increasing 61 -tuples of integers $\left(m_{0}, \ldots, m_{60}\right)$ from the set $\{0,1,2, \ldots, 62\}$ : simply let $m_{k}=n_{k}+k$. But the number of such $\left(m_{0}, \ldots, m_{60}\right)$ is almost by definition $\binom{63}{61}=\binom{63}{2}=1953$.