The sum of four consecutive odd integers is 200 . What is the largest of these four integers?
Since the four integers are consecutive odd integers, then they differ by 2 .

Let the four integers be $x-6, x-4, x-2, x$.

Since the sum of these integers is 200 , then $(x-6)+(x-4)+(x-2)+x=200$.

Simplifying and solving, we obtain $4 x-12=200$ and $4 x=212$ and $x=53$.

Therefore, the largest of the four integers is 53 .

ANSWER: 53