11. (10 points) There are three consecutive even numbers, the product of which is a five-digit number. The unit digit of this five-digit number is 0, the ten-thousand digit is 2, and the tens, hundreds, and thousands digits are three different digits. What is the sum of these three consecutive even numbers?

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【Analysis】 $26 \times 26 \times 26=17576,31 \times 31 \times 31=29791$, so the three consecutive even numbers are between 24, 26, 28, 30, 32, considering the unit digit is 0, it should have factors 2,5.

【Solution】Solution: $26 \times 26 \times 26=17576,31 \times 31 \times 31=29791$, so the three consecutive even numbers are between 24, 26, $28,30,32$, considering the unit digit is 0, it should have factors 2,5, $26 \times 28 \times 30=21840$, which meets the requirement. $28 \times 30 \times 32=26880$, does not meet the requirement, $30 \times 32 \times 34=32640$, does not meet the requirement.

Therefore, the sum of these three consecutive even numbers is $26+28+30=84$. The answer is: 84.