A cube having the digits $1,2,3,4,5,6$ on its six faces is tossed. What is the probability that the number on the top face is 5 or 6 ?
(A) $\frac{5}{6}$
(B) $\frac{1}{5}$
(C) $\frac{1}{3}$
(D) $\frac{11}{36}$
(E) $\frac{2}{5}$
When the cube is tossed, the total number of possibilities is 6 and the number of desired outcomes is 2 .

So the probability of tossing a 5 or 6 is $\frac{2}{6}$ or $\frac{1}{3}$.

ANsWER: (C)