106. Prime factorization. Find the prime divisors of the number 1000027.
106. $1000027=(100)^{3}+(3)^{3}=(100+3) \cdot(10000-300+9)=$ $103 \cdot 9709=103 \cdot 7 \cdot 1387=103 \cdot 7 \cdot(1460-73)=103 \cdot 7 \cdot 73 \cdot 19$.