35 The curve $x^{2}+y^{2}-2 y=0$ has any point $(x, y)$ that satisfies the inequality $x+y+c \geqslant 0$. Then the range of the real number $c$ is
A. $[-\sqrt{2}-1,+\infty)$
B. $[\sqrt{2}-1,+\infty)$
C. $(-\infty, \sqrt{2}+1]$
D. $(-\infty,-\sqrt{2}+1]$
35 B. When the circle is tangent to the line, $c= \pm \sqrt{2}-1$. Therefore, the y-intercept of the line $x+y+c=0$ on the y-axis $-c \leqslant-\sqrt{2}+1$, which means $c \geqslant \sqrt{2}-1$.