【Question 11】A natural number has 10 different divisors (i.e., factors, which are natural numbers that can divide it), but its prime factors (i.e., factors that are prime numbers) are only 2 and 3. Therefore, this natural number is $\qquad$ ـ.
Let's analyze: Suppose this number is $2^{a} \times 3^{b}$ (where $a$ and $b$ are positive integers). According to the problem, $(a+1) \times (b+1)=10=2 \times 5$, so $a=1, b=4$ or $a=4, b=1$.

Therefore, this natural number is $2^{1} \times 3^{4}=162$ or $2^{4} \times 3^{1}=48$