2. Given $a, b, c \in \mathbf{R}$, and satisfy $a>b>c$, $a+b+c=0$. Then, the range of $\frac{c}{a}$ is $\qquad$
2. $\left(-2,-\frac{1}{2}\right)$.

From $a>b>c$ and $a+b+c=0$, we know $a>0, c-2 ; \\
0=a+b+c>a+2 c \Rightarrow-\frac{a}{2}>c \Rightarrow \frac{c}{a}<-\frac{1}{2} .
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