A certain concrete mixture is made of cement, sand, and soil in the ratio $1: 3: 5$ per kilogram. How many kilograms of this mixture can be made with 5 kilograms of cement?
(a) $13 \frac{1}{3}$
(b) 15
(c) 25
(d) 40
(e) 45
According to the data of the problem, we have:

$$
\begin{array}{cccc}
\text { cement } & \text { sand } & & \text { soil } \\
1 \mathrm{~kg} & \longleftrightarrow 3 \mathrm{~kg} & \longleftrightarrow & 5 \mathrm{~kg}
\end{array}
$$

Therefore, with $5 \mathrm{~kg}$ of cement, we have:

$$
\begin{aligned}
& \text { cement } \quad \text { sand } \quad \text { soil } \\
& 1 \mathrm{~kg} \times 5 \longleftrightarrow 3 \mathrm{~kg} \times 5 \longleftrightarrow 5 \mathrm{~kg} \times 5
\end{aligned}
$$

Thus, with 5 kilograms of cement, this mixture totals $5+15+25=45 \mathrm{~kg}$.