The value of $\frac{4^{3}}{10^{2}-6^{2}}$ is
(A) 1
(B) 0.5
(C) -35.36
(D) 1.5
(E) 4
Calculating each of the numerator and denominator first, $\frac{4^{3}}{10^{2}-6^{2}}=\frac{64}{100-36}=\frac{64}{64}=1$.