7.1. Karlson counts 200 buns baked by Fräulein Bock: «one, two, three, ..., one hundred and nine, one hundred and ten, ..., one hundred and ninety-eight, one hundred and ninety-nine, two hundred». How many words will he say in total? (Each word is counted as many times as it was said.)
Answer: 443 words.

Solution. One word will be required to pronounce 29 numbers: $1,2,3,4,5,6,7$, $8,9,10,11,12,13,14,15,16,17,18,19,20,30,40,50,60,70,80,90,100,200$.

Among the first 99 numbers, the number of those pronounced in two words: $99-27=72$, thus, the number of words required for their pronunciation is $2 \cdot 72=144$.

In the next hundred (from 101 to 199), each number that is pronounced in one word in the first hundred will be pronounced in two, and the number of words is: $2 \cdot 27=54$. The rest are pronounced in three words: $3 \cdot(99-27)=216$.

Thus, to count all the pastries, $29+144+54+216=443$ words will be needed.

## Criteria.

1 point. The number of numbers pronounced in one word is found reasonably.

2 points. The number of words required to pronounce numbers from 1 to 99 is found correctly and reasonably.

2 points. The number of words required to pronounce numbers from 100 to 199 or 200 is found correctly and reasonably.

Comment. Points for the criteria above are cumulative.

3 points. The correct answer without reasoning.