33.22 $[x],[y],[z]$ represent the greatest integers not exceeding $x, y, z$ respectively. If $[x]=5,[y]=-3,[z]=-1$, then the number of possible values for $[x-y-z]$ is
(A) 3.
(B) 4.
(C) 5.
(D) 6.
(China Shanxi Province Taiyuan City Junior High School Mathematics Competition, 1993)
[Solution] $\because 5 \leqslant x<6,-3 \leqslant y<-2,-1 \leqslant z<0$, we have $\quad 2<-y \leqslant 3,0<-z \leqslant 1$.
$$
\therefore 7<x-y-z<10 \text {. }
$$

Thus, $[x-y-z]$ can take the values $7,8,9$. Therefore, the answer is $(A)$.