The sum of $29+12+23$ is
(A) $32^{2}$
(B) $2^{6}$
(C) $3^{4}$
(D) $1^{64}$
(E) $64^{0}$
The sum of $29+12+23$ is
(A) $32^{2}$
(B) $2^{6}$
(C) $3^{4}$
(D) $1^{64}$
(E) $64^{0}$

## Solution

Evaluating each of the given choices gives the following: $32^{2}=1024,2^{6}=64,3^{4}=81,1^{64}=1$, and $64^{0}=1$. Since $29+12+23=64$, the correct choice is B.

ANSWER: (B)