4. (10 points) As shown in the figure, quadrilateral $ABCD$ is a square with a side length of 11 cm, $G$ is on $CD$, quadrilateral $CEFG$ is a square with a side length of 9 cm, $H$ is on $AB$, $\angle EDH$ is a right angle, the area of triangle $EDH$ is $\qquad$ square centimeters.
【Analysis】1、Extend $E F$ and $A D$ to intersect at point $K$; 2、The areas of $\triangle D E K$ and $\triangle A D H$ are equal, so, $H B=2$;
3、 $S_{\text {shaded }}=S_{A B E K}-S_{D E K}-S_{A D H}-S_{B H E}$
【Solution】

According to the above analysis
$$
0.5 \times 2 \times(11+9)=101
$$