$11 、$ Satisfy all 7 conditions below, the five different natural numbers $\mathrm{A} 、 \mathrm{~B} 、 \mathrm{C} 、 \mathrm{D} 、 \mathrm{E}$ are $\mathrm{A}=(\quad), \mathrm{B}=(\quad)$, $\mathrm{C}=(\quad), \mathrm{D}=(\quad), \mathrm{E}=(\quad)$ respectively. What are they?
（1）These numbers are all less than 10;
(2) A is greater than 5;
(3) $\mathrm{A}$ is a multiple of $\mathrm{B}$;
(4) $\mathrm{C}$ plus $\mathrm{A}$ equals $\mathrm{D}$;
(5) The sum of $B 、 C 、 E$ equals $A$;
(6) The sum of B and $\mathrm{C}$ is less than $\mathrm{E}$;
(7) The sum of $\mathrm{C}$ and $\mathrm{E}$ is less than $\mathrm{B}+5$.
【Analysis】Logical reasoning. From (4) we get $\mathrm{A}\mathrm{A}>\mathrm{E}$.
From (4), $\mathrm{C}$ is not 0; from (3) we get, $\mathrm{B}$ is not 0, so there is no 0 among these numbers,

Therefore, $B+C$ is at least 3. If $B+C=4$, then, $E$ is at least 5, $A$ is at least 9, but $\mathrm{D}$ is greater than $\mathrm{A}$, so it does not meet the conditions.
So $B+C=3, E$ is at least 4, if $E=4$, then $C=1, B=2$,
From (5) $\mathrm{A}=7$, at this point (3) is not satisfied, so $\mathrm{E}$ is not 4. If $\mathrm{E}=6$, from (5) we get $\mathrm{A}=9$ which also does not meet the conditions. Therefore, $\mathrm{E}=5$, from (7) $\mathrm{C}=1, \mathrm{D}=9$, satisfying all conditions. In summary, $\mathrm{A}=8, \mathrm{~B}=2, \mathrm{C}=1, \mathrm{D}=9, \mathrm{E}=5$.