A pot weighs $645 \mathrm{~g}$ and another one $237 \mathrm{~g}$. José divides $1 \mathrm{~kg}$ of meat between the two pots, so that both, with their contents, have the same weight. How much meat did he put in each pot?
Converting $1 \mathrm{~kg}$ to $1000 \mathrm{~g}$, we have that the two pots together, plus the meat, weigh $645+237+1000=1882 \mathrm{~g}$. Therefore, each pot, plus its meat content, should weigh $1882 \div 2=941 \mathrm{~g}$. Thus, José placed:

$$
941-645=296 \mathrm{~g} \quad \text { and } \quad 941-237=704 \mathrm{~g}
$$

in these two pots.