B2. Peter decides to buy a new car. He has gathered some data on the model with a gasoline engine and the model with a diesel engine in a table.

|  | car price | fuel costs | consumption |
| :--- | :---: | :---: | :---: |
| gasoline engine | 13300 EUR | 0.940 EUR / liter | 7.4 liters / 100 km |
| diesel engine | 14970 EUR | 0.892 EUR / liter | 5.2 liters / 100 km |

A By what percentage is the price of the model with a diesel engine higher than that of the model with a gasoline engine? Round the result to one decimal place.

B How much fuel would the car with a gasoline engine and how much would the car with a diesel engine consume if it were to travel 15000 km?

C After how many months would the savings due to fuel costs cover the price difference between the more expensive and the cheaper model, if he were to drive 15000 km annually?
B2. The price of the Z model with a diesel engine is $\frac{14970-13300}{13300} \cdot 100=12.6 \%$ higher than the price of the Z model with a gasoline engine.

B A gasoline engine car would consume in one year $15000 \mathrm{~km} \cdot \frac{7.4 \mathrm{l}}{100 \mathrm{~km}}=1110 \mathrm{l}$, while the model with a diesel engine would consume $15000 \mathrm{~km} \cdot \frac{5.2 \mathrm{l}}{100 \mathrm{~km}}=780 \mathrm{l}$.

C If Peter buys the car with a diesel engine, he would spend $1110 \mathrm{l} \cdot \frac{0.940}{\mathrm{l}}-$ $780 \mathrm{l} \cdot \frac{0.892}{\mathrm{l}}=347.64$ euros less on fuel annually. The higher costs of purchasing the diesel car would be recovered by Peter in $\frac{14970-13300}{347.64}=4.804$ years or 58 months.

Scoring: Total: 7 points
A The price is higher by $12.6 \%$. ..... $2 \mathrm{t}$
B Annual consumption of the gasoline engine: 11101. ..... $1 \mathbf{t}$
Annual consumption of the diesel engine: 7801. ..... $1 \mathrm{t}$
C Calculation: $1110 \cdot 0.940-780 \cdot 0.892=347.64$ euros less on fuel ..... $1 \mathrm{t}$
Calculation: $\frac{14970-13300}{347.64}=\frac{1670}{347.64}=4.804$ years $=58$ months. ..... 1 t
Answer: The costs would be recovered by Peter in 58 months. ..... 1 t