2. (8 points) Dad's birthday is on May 1st, and Chunchun's birthday is on July 1st. Starting from December 26, 2012 (Day 1), until Day 2013, Dad and Chunchun have had $\qquad$ birthdays in total.
2. (8 points) Dad's birthday is on May 1st, and Chunchun's birthday is on July 1st. Starting from December 26, 2012 (Day 1), until the 2013th day, Dad and Chunchun have had a total of 11 birthdays.
【Solution】Solution: According to the analysis,
$$
(2013-6) \div 365=5 \cdots 182
$$

The quotient is 5, indicating that both Dad and Chunchun have had 5 birthdays.
Considering there must be a leap year within 5 years,
the remaining 181 days fall in the first half of the year, so within these 181 days, Dad can have 1 birthday, while Chunchun cannot have a birthday. Therefore, Dad has $5+1=6$ birthdays, and Chunchun has 5 birthdays,

So, the total number of birthdays: $6+5=11$ (birthdays);
Answer: Dad and Chunchun have had a total of 11 birthdays.
The answer is: 11.