8. One of these options gives the value of $17^{2}+19^{2}+23^{2}+29^{2}$. Which is it?
A 2004
B 2008
C 2012
D 2016
E 2020
8. E Since the units digits of all the options are different, it is sufficient to add the units digits of the four squares in the sum. As $7^{2}=49,17^{2}$ has a units digit of 9 . In a similar way, we calculate that $19^{2}$ has a units digit of $1,23^{2}$ has a units digit of 9 and $29^{2}$ has a units digit of 1 . Therefore the units digit of the given sum is the units digit of $9+1+9+1$, that is 0 . As we are told that the correct answer is one of the options, we may deduc that it is 2020 .