8. (5 points) If a natural number has an even number of even digits, it is called a "Hope Number", for example: 26, 201, 533 are Hope Numbers, while 8, 36, 208 are not Hope Numbers. Therefore, if all Hope Numbers are arranged in ascending order, the 2010th Hope Number is $\qquad$
【Solution】Solution: By summarizing the pattern, we can see that except for the numbers $0, 1, 3, 5, 7, 9$, in every ten numbers, there are five hopeful numbers,

for example: 11, 13, 15, 17, 19; 100, 102, 104, 106, 108; .
Therefore, $2010-1=2009$
$$
\begin{array}{l}
2009 \div 5=401 \cdots 4 \\
401 \times 10=4010,
\end{array}
$$

So, the "401st ten" group, which is 4011, 4013, 4015, 4017, 4019, because the remainder is 4, so counting four more from 4011, it is 4019. Answer: The 2010th hopeful number is 4019, so the answer is: 4019.