35.1. How many natural numbers $n$ exist such that

$$
100<\sqrt{n}<101 ?
$$

$$
\text { (8-9 grades) }
$$
35.1. If $100<\sqrt{ } \bar{n}<101$, then $10000<n<10201$. The last inequality is satisfied by 200 natural numbers: 10001, 10002, ..., 10200. These and only these numbers satisfy the given inequality. Answer. 200.