Laila writes a list of numbers. Her first number is 4 . Each number after the first is 7 more than the previous number. Which of the following numbers appears in Laila's list?
(A) 45
(B) 46
(C) 47
(D) 48
(E) 49
Solution 1

Writing the numbers that appear in the list, we get

$$
4,11,18,25,32,39,46,53, \ldots
$$

Of the given answers, the number that appears in Laila's list is 46 .

Solution 2

Laila begins her list at 4 and each new number is 7 more than the previous number.

Therefore, each of the numbers in her list will be 4 more than a multiple of 7 .

Since 42 is a multiple of $7(6 \times 7=42)$, then $42+4=46$ will appear in Laila's list.

ANswer: (B)