8. (6 points) Given that the product of 9 numbers is 800, if one of the numbers is changed to 4, the product of these 9 numbers becomes 200. If another number is then changed to 30, the product of these 9 numbers becomes 1200, then the product of the 7 numbers that were not changed is . $\qquad$
【Analysis】As long as we find out what the two altered numbers are, we can determine the product of the other 7 numbers. It is known that the product of the 9 numbers is 800. When one of the numbers is changed to 4, the product of these 9 numbers becomes 200. The product has decreased by $800 \div 200=4$ (times), so the altered number has also been reduced by 4 times. Therefore, the altered number is: $4 \times 4=16$; Similarly, $1200 \div 200=6$, the product has increased by 6 times, so the second altered number has also been increased by 6 times, and its original value should be: $30 \div 6=5$. Therefore, the product of the other 7 numbers, excluding these two altered numbers, is: $800 \div(16 \times 5) = 10$.

【Solution】The first number originally was: $(800 \div 200) \times 4=16$;
The second number originally was: $30 \div (1200 \div 200)=5$;
Therefore, the product of the other 7 numbers is:
$$
800 \div (16 \times 5) = 10
$$

The answer is: 10.