219. Without solving the quadratic equation $x^{2} + p x + q = 0$, form a new equation, one of whose roots is equal to the sum of the cubes of the roots of the given equation, and the other is the cube of their sum.
Instruction. The solution is similar to the solution of the previous problem.

Answer. $x^{2}+p\left(2 p^{2}-3 q\right) x+\left(p^{2}-3 q\right) p^{4}=0$.