A positive integer is a [i]palindrome [/i] if it is written identically forwards and backwards. For example, $285582$ is a palindrome. A six digit number $ABCDEF$, where $A, B, C, D, E, F$ are digits, is called [i]cozy [/i] if $AB$ divides $CD$ and $CD$ divides $EF$. For example, $164896$ is cozy. Determine all cozy palindromes.

1. **Identify the structure of the palindrome:**
   Since $ABCDEF$ is a palindrome, it must be written identically forwards and backwards. Therefore, $D = C$, $E = B$, and $F = A$. This means the number can be written as $ABCCBA$.

2. **Check the cozy condition:**
   For the number $ABCCBA$ to be cozy, the following conditions must be satisfied:
   - $AB$ divides $CD$
   - $CD$ divides $EF$

3. **Simplify the conditions:**
   Since $D = C$, $E = B$, and $F = A$, the number $ABCCBA$ simplifies to $ABCCBA = ABCCBA$. Therefore, we need to check:
   - $CC$ divides $BA$
   - $BA$ divides $CC$

4. **Analyze the divisibility:**
   - $CC$ is a two-digit number where both digits are the same, i.e., $CC = 11c$ (since $CC$ can be written as $10c + c = 11c$).
   - $BA$ is a two-digit number, i.e., $BA = 10b + a$.

   For $CC$ to divide $BA$, we need $11c$ to divide $10b + a$. Since $11c$ is a multiple of 11, $10b + a$ must also be a multiple of 11. This implies that $10b + a \equiv 0 \pmod{11}$.

5. **Check the divisibility of $BA$ by 11:**
   Since $10b + a \equiv 0 \pmod{11}$, $BA$ must be a multiple of 11. Therefore, $BA$ can be written as $11k$ for some integer $k$.

6. **Check the divisibility of $CC$ by $BA$:**
   Since $CC = 11c$ and $BA = 11k$, for $11c$ to divide $11k$, $c$ must divide $k$. Therefore, $c = k$.

7. **Determine the digits:**
   Since $A = B$ and $C = A$, the number $ABCCBA$ simplifies to $AAAAAA$. Therefore, the number must be of the form $AAAAAA$ where $A$ is any digit from 1 to 9.

8. **List all possible cozy palindromes:**
   The possible values for $A$ are 1 through 9. Therefore, the cozy palindromes are:
   - $111111$
   - $222222$
   - $333333$
   - $444444$
   - $555555$
   - $666666$
   - $777777$
   - $888888$
   - $999999$

The final answer is $\boxed{111111, 222222, 333333, 444444, 555555, 666666, 777777, 888888, 999999}$.