What is the sum of the roots of the equation $10^{x}+10^{1-x}=10$?
Using the identity of exponentiation, our equation can be rewritten as

$$
10^{2 x}-10 \cdot 10^{x}+10=0
$$

in terms of \(10^{x}\), it can be transformed into a quadratic equation. Based on the relationship between the roots and coefficients,

$$
10^{x_{1}} \cdot 10^{x_{2}}=10
$$

thus

$$
10^{x_{1}+x_{2}}=10, \text{ i.e., } x_{1}+x_{2}=1
$$

The sum of the two roots is 1.