2. If $a, b, c, d$ are integers, and
$$
a \lg 2+b \lg 3+c \lg 5+d \lg 7=2013 \text {, }
$$

then the ordered tuple $(a, b, c, d)=$ $\qquad$
2. $(2013,0,2013,0)$.

From the problem, we have
$$
2^{a} \times 3^{b} \times 5^{c} \times 7^{d}=10^{2013}=2^{2013} \times 5^{2013} \text {. }
$$

By the Fundamental Theorem of Arithmetic, we know
$$
(a, b, c, d)=(2013,0,2013,0) .
$$