Find the minimum positive value of $ 1*2*3*4*...*2020*2021*2022$ where you can replace $*$ as $+$ or $-$
To find the minimum positive value of the expression \(1 * 2 * 3 * \ldots * 2020 * 2021 * 2022\) where each \( * \) can be replaced by \( + \) or \( - \), we need to consider the sum of the sequence with different combinations of \( + \) and \( - \) signs.

1. **Pairing Terms:**
   We can pair the terms in the sequence to simplify the calculation. Consider the pairs \((1, 2), (3, 4), \ldots, (2021, 2022)\). Each pair can be written as:
   \[
   (1 - 2) + (3 - 4) + \cdots + (2021 - 2022)
   \]
   Each pair sums to \(-1\):
   \[
   1 - 2 = -1, \quad 3 - 4 = -1, \quad \ldots, \quad 2021 - 2022 = -1
   \]

2. **Summing the Pairs:**
   There are \(1011\) pairs in total (since \(2022/2 = 1011\)). Therefore, the sum of all pairs is:
   \[
   -1 - 1 - 1 - \cdots - 1 \quad (\text{1011 times})
   \]
   This results in:
   \[
   -1011
   \]

3. **Adjusting the Sum:**
   To find the minimum positive value, we need to adjust the sum by changing the sign of one of the terms. For example, if we change the sign of the last term \(2022\) from \( -2022 \) to \( +2022 \), the sum becomes:
   \[
   -1011 + 2022 = 1011
   \]

4. **Ensuring Minimum Positive Value:**
   We need to ensure that the sum is the minimum positive value. By changing the sign of one term, we can achieve the smallest positive value. Changing the sign of any other term will result in a larger positive value.

Therefore, the minimum positive value of the expression is \(1\).

The final answer is \(\boxed{1}\).