## Task A-2.1. (4 points)

Determine the sum of all positive divisors of the number 2010.
## First solution.

The number 2010 can be factored as $2 \cdot 3 \cdot 5 \cdot 67$, so all positive divisors of 2010 are:

$1,2,3,5,6,10,15,30,67,134,201,335,402,670,1005,2010$.

(3 points)

Their sum is 4896.