1. There is a quadratic equation, whose two roots are two-digit numbers formed by the digits 1, 9, 8, and 4. Let the difference between these two roots be $\mathrm{x}$, which makes $\sqrt{1984 \mathrm{x}}$ an integer. Try to find this equation and its two roots.
1. The required equation is $\mathrm{y}^{2}-(18+49) \mathrm{y}+18 \times 49$ $=0$. The two roots are $\mathrm{y}_{1}=49, \mathrm{y}_{2}=18$.