Canadian currency has coins with values $\$ 2.00, \$ 1.00, \$ 0.25, \$ 0.10$, and $\$ 0.05$. Barry has 12 coins including at least one of each of these coins. What is the smallest total amount of money that Barry could have?
(A) $\$ 3.75$
(B) $\$ 3.90$
(C) $\$ 3.70$
(D) $\$ 3.40$
(E) $\$ 3.95$

Part B: Each correct answer is worth 6.
Barry's 12 coins include at least one of each of the 5 coins of different values.

The total value of these 5 coins is $\$ 2.00+\$ 1.00+\$ 0.25+\$ 0.10+\$ 0.05=\$ 3.40$.

Barry has the smallest total amount of money that he could have if each of his remaining $12-5=7$ coins has value $\$ 0.05$ (the smallest possible value of a coin).

Thus, the smallest total amount of money that Barry could have is

$$
\$ 3.40+7 \times \$ 0.05=\$ 3.40+\$ 0.35=\$ 3.75
$$

ANSWER: (A)