1. Calculate
\begin{tabular}{lll}
$78 \times 4+488=$ & $350 \times(12+342 \div 9)=$ & $(3600-18 \times 200) \div 253=$ \\
$1903-475 \times 4=$ & $480 \div(125-117)=$ & $(243-162) \div 27 \times 380=$
\end{tabular}
【Answer】Solution:
$$
\begin{array}{l}
78 \times 4+488=312+488=800 \\
350 \times(12+342 \div 9)=350 \times(12+38)=350 \times 50=17500 \\
(3600-18 \times 200) \div 253=(3600-3600) \div 253=0 \\
1903-475 \times 4=1903-1900=3 \\
480 \div(125-117)=480 \div 8=60 \\
(243-162) \div 27 \times 380=81 \div 27 \times 380=3 \times 380=1140
\end{array}
$$