Task 1 - 120521
\(4 * * \cdot 3 * *\)
    \(* * * 5\)
        \(3 * * *\)
            \(8 * *\)
                            In the following task, each asterisk \(\left({ }^{*}\right)\) is to be replaced by one of the digits
    \(* * * * 3 *\)
                            \(0,1,2,3,4,5,6,7,8,9\) so that a correctly solved multiplication
                            problem is formed.
Each line must begin with a non-zero digit.
As a result, only a correctly completed problem is required without any justification.
$4 * * .3$ can only end in 5 if the first factor is $4 * 5$. The factor $3 * *$ must end in 2, as only then is the third partial result a three-digit number starting with 8. The first intermediate product starts with 1. The second product ends in 0. If it ended in 5, the third product would have to be 880, which is not possible. Therefore, for now:

```
4*5 - 3*2
    1**5
        3**0
            8*0
```

****30

The third product is equal to 830 by the final sum. Thus, the first factor is 415 and the first intermediate product is 1245. This makes the tens digit in the second factor even. This is only possible with 8. The solution is therefore unique.

## $415 \cdot 382$

1245

3320

830

158530