7.6. A rectangular chocolate bar is divided by grooves into $1995 \times 1995$ squares. Two players, A and B, play a game according to the following rules: Each player, on their turn, divides one rectangular piece of chocolate into two smaller rectangles (only along the grooves) and can immediately eat one of the resulting rectangular pieces (or choose not to eat it). The player who cannot make a move loses. Player A starts. Who will win under the correct strategy?
7.6. Under the correct strategy, B will win.

If A does not eat the chocolate after the first move, or even if A does eat it but leaves 1 piece of chocolate with one side of even length, then B will turn them into 2 identical pieces of chocolate. Then, B will consistently adopt a symmetric strategy: whatever A does to one piece, B will do the same to the other. This will ultimately lead to B's victory.

If A leaves 1 piece of chocolate with both sides of odd length after the first move, then B will leave 1 piece of chocolate that is a square with odd side length. Thus, it returns to the initial situation. As long as B maintains the above response measures, B will always have the assurance to continue, thereby winning the game.