17. Person A walks from home to Person B's home. At the same time, Person B rides a bicycle from home towards Person A's home. Each maintains a constant speed, and Person B's cycling speed is 5 times Person A's walking speed. It is known that the distance between the two homes is 10560 feet, and Person A's stride length is 2.5 feet. When Person A meets Person B, Person A has walked ( ) steps.
(A) 704
(B) 845
(C) 1056
(D) 1760
(E) 3520
17. A.

Since Yi's cycling speed is 5 times that of Jia's walking speed, in the time it takes Jia to take one step, Yi cycles a distance of $\frac{25}{2}$ feet. Together, they cover 15 feet. Therefore, the total number of steps Jia and Yi take when they meet is $\frac{10560}{15}=704$.