9. On each of the six faces of a cube, there are some numbers written, and the sum of the numbers on opposite faces equals 50. If we first flip the cube 97 times from left to right, and then 98 times from front to back, the number on the bottom face of the cube at this time is $\qquad$ the number on the front face is
, and the number on the right face is
. (One flip means flipping one face)
【Answer】The number on the bottom face is 37, the number on the front face is 35, and the number on the right face is 11.
【Key Point】Periodic Problem
【Analysis】
According to the problem, the initial number on the left face is $50-13=37$, the number on the back face is $50-15=35$, and the number on the bottom face is $50-11=39$; for a cube, if it is continuously flipped in the same direction 4 times, it will return to its initial orientation;
Since $97 \div 4=24 \ldots \ldots .1,98 \div 4=24 \ldots \ldots .2$,
the operations in the original problem can be simplified to first flipping from left to right 1 time, then flipping from front to back 2 times;
After flipping from left to right 1 time, the six faces of the cube are:
The number on the left face is 39, the number on the right face is 11, the number on the front face is 15, the number on the back face is 35, the number on the top face is 37, and the number on the bottom face is 13; after flipping from front to back 2 times, the six faces of the cube are:
The number on the left face is 39, the number on the right face is 11, the number on the front face is 35, the number on the back face is 15, the number on the top face is 13, and the number on the bottom face is 37; therefore, after the required operations, the number on the bottom face of the cube is 37, the number on the front face is 35, and the number on the right face is 11.