1061. There are candies in three boxes. In the first box, there are 8 candies less than in the other two together, and in the second box, there are 12 less than in the first and third together. How many candies are in the third box?
$\triangle$ Let the number of candies in the first, second, and third boxes be denoted by $a, b$, and $c$ respectively. We obtain the system of equations:

$$
\left\{\begin{array}{l}
a=b+c-8 \\
b=a+c-12
\end{array}\right.
$$

Adding these equations term by term:

$$
a+b=(a+b)+2 c-20
$$

Then

$$
2 c-20=0, \quad c=10
$$

Answer: 10.