The average of $-5,-2,0,4$, and 8 is
(A) 1
(B) 0
(C) $\frac{19}{5}$
(D) $\frac{5}{4}$
(E) $\frac{9}{4}$
The average of $-5,-2,0,4$, and 8 is
(A) 1
(B) 0
(C) $\frac{19}{5}$
(D) $\frac{5}{4}$
(E) $\frac{9}{4}$

## Solution

The average is, $\frac{(-5)+(-2)+(0)+(4)+(8)}{5}=1$.

ANSWER: (A)