The equation $y=a x^{2}+b x+c$ was used to create the table of values below:

$$
\begin{array}{l|l|l|}
x & 0 & 1 \\
\hline y & 8 & 9
\end{array}
$$

What is the value of $a+b$ ?
(A) -2
(B) 1
(C) 3
(D) 5
(E) -5
From the table of values, when $x=0, y=8$, and so $8=a \cdot 0^{2}+b \cdot 0+c$ or $c=8$.

From the table of values, when $x=1, y=9$, and so $9=a \cdot 1^{2}+b \cdot 1+c$ or $a+b+c=9$.

Since $a+b+c=9$ and $c=8$, then $a+b+8=9$ or $a+b=1$.

ANswer: (B)