1. Write in the form of a power of 2 the value of the expression

$2^{3} \cdot[-2022:(2+0+2+2)-2023:(-2-0-2-3)]:(-3)$.
1. Write in the form of a power of 2 the value of the expression

$$
2^{3} \cdot[-2022:(2+0+2+2)-2023:(-2-0-2-3)]:(-3)
$$

## Solution.

$$
\begin{aligned}
& 2^{3} \cdot[-2022:(2+0+2+2)-2023:(-2-0-2-3)]:(-3) \\
& =8 \cdot[-2022: 6-2023:(-7)]:(-3) \\
& =8 \cdot[-337+289]:(-3) \\
& =8 \cdot(-48):(-3) \\
& =-384:(-3) \\
& =128 \quad 1 \text { POINT } \\
& =2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2=2^{7} \quad 1 \text { POINT } \\
& \text { TOTAL } 6 \text { POINTS }
\end{aligned}
$$

## Remark.

If the student does not write the values of the powers and does not write the product of identical factors, scoring is done analogously:

$$
\begin{aligned}
& 2^{3} \cdot[-2022:(2+0+2+2)-2023:(-2-0-2-3)]:(-3) \\
= & 2^{3} \cdot[-2022: 6-2023:(-7)]:(-3) \\
= & 2^{3} \cdot[-337+289]:(-3) \\
= & 2^{3} \cdot(-48):(-3)
\end{aligned}
$$

$$
\begin{aligned}
& =2^{3} \cdot 16 \quad 1 \text { POINT } \\
& =2^{3} \cdot 2^{4} \quad 1 \text { POINT } \\
& =2^{7} \quad 1 \text { POINT } \\
& \text { TOTAL } 6 \text { POINTS }
\end{aligned}
$$