1. On the right

side, in a column of squares, each square except for 9.7 represents a number. It is known that the sum of any 3 consecutive squares is 19. Then $A+H+M+O$ equals ( ).
(A) 21
(B) 23
(C) 25
(D) 26
-1. D.
From the given, we easily know that $A+H=10$.
$$
\begin{array}{l}
\because M+O+X=O+X+7, \\
\therefore M=7 .
\end{array}
$$

Similarly, $O=9$.
$$
\therefore A+H+M+O:=26 \text {. }
$$