2. Given in rectangle $A B C D$, $A B=2, B C=3$. Then the modulus of $\boldsymbol{A B}+\boldsymbol{B} \boldsymbol{C}+\boldsymbol{A} \boldsymbol{C}$ equals ( ).
(A) 0
(B) 5
(C) $\sqrt{13}$
(D) $2 \sqrt{13}$
2.D.

Since $A B+B C+A C=2 A C$, and
$$
|A C|=\sqrt{A B^{2}+B C^{2}}=\sqrt{13} \text {, }
$$

Therefore, $|A B+B C+A C|=2 \sqrt{13}$.