112 A tetrahedron with vertices from the vertices of a cube has
A. 70
B. 64
C. 58
D. 52
112 C. There are $C_{8}^{4}=70$ ways to choose any four points from the eight vertices of a cube, but to form a tetrahedron, we must subtract the six faces of the cube, and also remove the six diagonal planes that do not meet the requirements, so there are $70-6-6=58$ tetrahedrons.