1. Solve the equation: $\frac{8 x+13}{3}=\frac{19-12 x}{2}-\left(16 x-\frac{7-4 x}{6}\right)$.
1. $\frac{8 x+13}{3}=\frac{19-12 x}{2}-\left(16 x-\frac{7-4 x}{6}\right)$

$\frac{8 x+13}{3}=\frac{19-12 x}{2}-16 x+\frac{7-4 x}{6} / \cdot 6$

1 BOD

$2 \cdot(8 x+13)=3 \cdot(19-12 x)-96 x+7-4 x \quad 1$ BOD

$16 x+26=57-36 x-96 x+7-4 x \quad 1$ BOD

$16 x+36 x+96 x+4 x=57+7-26$

$152 x=38 \quad /: 152$

1 BOD

$x=\frac{38}{152}$

1 BOD

$x=\frac{1}{4}$

1 BOD

TOTAL 6 POINTS

Note: If the student has not fully simplified the fraction, the solution should be evaluated with 5, not 6 points.