16. (15 points) As shown in the figure, the area of $\triangle A B C$ is 5 square centimeters, $A E=E D$, $B D=2 D C$. The total area of the shaded parts is $\qquad$ square centimeters.
【Solution】Solution: The area of $S \triangle D C F = 5 \div 5 = 1$ (square centimeter).
The area of the shaded part equals the area of $\triangle B D F = \triangle D C F$'s area $\times 2 = 1 \times 2 = 2$ (square centimeters); Answer: . The total area of the shaded part is 2 square centimeters.

Therefore, the answer is: 2.