In the diagram, the object is made up of seven $1 \times 1 \times 2$ solids. What is the total surface area of the object?
(A) 42
(B) 40
(C) 38
(D) 48
(E) 70

![](https://cdn.mathpix.com/cropped/2024_04_20_6027bc27089ed4fc493cg-065.jpg?height=309&width=246&top_left_y=859&top_left_x=1292)
The object has 7 "front" faces, each of which is $1 \times 1$. Therefore, the surface area of the front is $7 \times 1 \times 1=7$.

Similarly, the surface area of the "back" is 7 .

Now consider the faces on the left, top, right and bottom. Each of these faces is $1 \times 2$, so each has an area of 2 .

How many of these faces are there?

If we start at the bottom left and travel clockwise around the figure, we have 2 left faces, 2 top faces, 2 left faces, 1 top face, 3 right faces, 1 bottom face, 1 right face, and 2 bottom faces, or 14 faces in total.

Therefore, the surface area accounted for by these faces is $14 \times 2=28$.

Therefore, the total surface area of the object is $7+7+28=42$.

ANsWER: (A)