The weight of a lioness is six times the weight of her female cub and four times the weight of her male cub. If the difference between the weights of the male and female cub is $14 \mathrm{~kg}$, the weight of the lioness, in $\mathrm{kg}$, is
(A) 84
(B) 252
(C) 168
(D) 140
(E) 112
Solution 1

Let the weight of the lioness be $L$.

Then the weight of the female cub is $\frac{1}{6} L$ and the weight of the male cub is $\frac{1}{4} L$.

Thus, $\frac{1}{4} L-\frac{1}{6} L=14$ or $\frac{3}{12} L-\frac{2}{12} L=14$ or $\frac{1}{12} L=14$ or $L=168$.

Therefore, the weight of the lioness is $168 \mathrm{~kg}$.

## Solution 2

Let the weight of the female cub be $F$.

Then the weight of the male cub is $F+14$.

Also, the weight of the lioness is equal to both of $6 F$ and $4(F+14)$.

Therefore, $6 F=4 F+56$ or $2 F=56$ or $F=28$.

Thus, the weight of the lioness is $6(28)=168 \mathrm{~kg}$.

ANSWER: (C)