In the sequence shown, Figure 1 is formed using 7 squares.

Each figure after Figure 1 has 5 more squares than the previous figure. What figure has 2022 squares?
(A) Figure 400
(B) Figure 402
(C) Figure 404
(D) Figure 406
(E) Figure 408

![](https://cdn.mathpix.com/cropped/2024_04_20_6027bc27089ed4fc493cg-008.jpg?height=130&width=108&top_left_y=954&top_left_x=1171)

Figure 1

![](https://cdn.mathpix.com/cropped/2024_04_20_6027bc27089ed4fc493cg-008.jpg?height=133&width=174&top_left_y=947&top_left_x=1298)

Figure 2

![](https://cdn.mathpix.com/cropped/2024_04_20_6027bc27089ed4fc493cg-008.jpg?height=174&width=239&top_left_y=913&top_left_x=1493)

Figure 3
Figure 1 is formed with 7 squares.

Figure 2 is formed with $5+7$ squares.

Figure 3 is formed with $5+5+7=2 \times 5+7$ squares.

Figure 4 will be formed with $5+5+5+7=3 \times 5+7$ squares.

Figure 5 will be formed with $5+5+5+5+7=4 \times 5+7$ squares.

Thus, the number of groups of 5 squares needed to help form each figure is increasing by 1 .

Also, in each case the number of groups of 5 squares needed is one less than the Figure number. For example, Figure 6 will be formed with 5 groups of 5 squares plus 7 additional squares. In general, we can say that Figure $N$ will be formed with $N-1$ groups of 5 squares, plus 7 additional squares.

Since $2022=403 \times 5+7$, the figure with 2022 squares has 403 groups of 5 squares, plus 7 additional squares.

Thus, $N-1=403$ and so $N=404$. The number of the figure that has 2022 squares is 404 .

ANsWer: (C)