A3. The quotient of the geometric sequence $\sqrt{2}+1, \frac{3}{\sqrt{6}-\sqrt{3}}, 3 \sqrt{2}+3$ is:
(A) $-\sqrt{3}$
(B) 1
(C) $\frac{\sqrt{3}}{3}$
(D) $\sqrt{3}$
(E) 3
A3. Let's calculate the quotient $q=\frac{3}{(\sqrt{2}+1)(\sqrt{6}-\sqrt{3})}=$

$$
\frac{3}{(2 \sqrt{3}-\sqrt{3}+\sqrt{6}-\sqrt{6})}=\frac{3}{\sqrt{3}}=\sqrt{3}
$$