One side of a rectangle has length 18. The area plus the perimeter of the rectangle is 2016. Find the perimeter of the rectangle.

1. Let the length of one side of the rectangle be \(18\) and the other side be \(a\).
2. The perimeter \(P\) of the rectangle is given by:
   \[
   P = 2 \times (18 + a) = 2a + 36
   \]
3. The area \(A\) of the rectangle is given by:
   \[
   A = 18 \times a = 18a
   \]
4. According to the problem, the sum of the area and the perimeter is \(2016\):
   \[
   A + P = 2016
   \]
5. Substituting the expressions for \(A\) and \(P\) into the equation:
   \[
   18a + (2a + 36) = 2016
   \]
6. Simplify the equation:
   \[
   20a + 36 = 2016
   \]
7. Solve for \(a\):
   \[
   20a = 2016 - 36
   \]
   \[
   20a = 1980
   \]
   \[
   a = \frac{1980}{20}
   \]
   \[
   a = 99
   \]
8. Now, calculate the perimeter using \(a = 99\):
   \[
   P = 2 \times (18 + 99) = 2 \times 117 = 234
   \]

The final answer is \(\boxed{234}\).