44.2. The sum of the first $n$ terms of an arithmetic progression is equal to $n^{2}+5 n$. Find the tenth term of the progression.

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44.2. The tenth term of the given progression can be found as the difference between the sums of its first ten and first nine terms. These sums can be found from the expression $n^{2}+5 n$, by substituting $n=10$ and $n=9$ respectively. Thus, the desired tenth term is

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\left(10^{2}+5 \cdot 10\right)-\left(9^{2}+5 \cdot 9\right)=150-126=24 .
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