9. In a triangle with side lengths of $50, 120, 130$, take all points inside and outside the triangle that are at least 2 units away from at least one point on the triangle's sides. Then the area of the region formed by all the taken points is $\qquad$ (take $\left.\pi=\frac{22}{7}\right)$.
9. $1182 \frac{4}{7}$.

The region is shown in Figure 8.

The initial triangle divides it into inner and outer parts. The part outside the triangle includes three sectors near the vertices, which can be combined to form a circle with a radius of 2; the remaining three rectangles are $2 \times 50, 2 \times 120, 2 \times 130$. Therefore, the area outside the triangle is $600 + \frac{88}{7}$.

The part inside the triangle includes three quadrilaterals near the vertices, which can be combined to form a triangle with side lengths of $5, 12, 13$; the remaining three rectangles have a width of 2, and the sum of their lengths is 270. Therefore, the area inside the triangle is $30 + 540$.
Thus, the total area of the region is $1182 \frac{4}{7}$.