Find the maximum number of planes in the space, such there are $ 6$ points, that satisfy to the following conditions:
[b]1.[/b]Each plane contains at least $ 4$ of them
[b]2.[/b]No four points are collinear.
1. **Understanding the problem**: We need to find the maximum number of planes in space such that there are 6 points, each plane contains at least 4 of these points, and no four points are collinear.

2. **Initial setup**: Let's denote the 6 points as \( P_1, P_2, P_3, P_4, P_5, P_6 \). We need to ensure that each plane contains at least 4 of these points and no four points are collinear.

3. **Analyzing the conditions**:
   - Each plane must contain at least 4 points.
   - No four points are collinear, which means any set of 4 points forms a plane.

4. **Counting the planes**:
   - Consider the combination of choosing 4 points out of 6. The number of ways to choose 4 points from 6 is given by the binomial coefficient:
     \[
     \binom{6}{4} = \frac{6!}{4!(6-4)!} = 15
     \]
   - However, not all combinations of 4 points will necessarily form distinct planes because some sets of 4 points might lie on the same plane.

5. **Constructing the planes**:
   - Let's consider a specific configuration. Place points \( A_1, A_2, A_3 \) on one line \( l_1 \) and points \( B_1, B_2, B_3 \) on another skew line \( l_2 \).
   - Any plane containing \( l_1 \) will contain \( A_1, A_2, A_3 \) and at least one of \( B_1, B_2, B_3 \). There are 3 such planes.
   - Similarly, any plane containing \( l_2 \) will contain \( B_1, B_2, B_3 \) and at least one of \( A_1, A_2, A_3 \). There are 3 such planes.

6. **Verifying the maximum number of planes**:
   - We have 3 planes containing \( l_1 \) and 3 planes containing \( l_2 \). These planes are distinct because \( l_1 \) and \( l_2 \) are skew lines.
   - Therefore, the total number of distinct planes is \( 3 + 3 = 6 \).

7. **Conclusion**:
   - Given the constraints, the maximum number of planes that can be formed is 6. This configuration ensures that each plane contains at least 4 points and no four points are collinear.

\[
\boxed{6}
\]