7. Alexey plans to buy one of two car brands: "A" for 900 thousand rubles or "B" for 600 thousand rubles. On average, Alexey drives 15 thousand km per year. The cost of gasoline is 40 rubles per liter. The cars consume the same type of gasoline. The car is planned to be used for 5 years, after which Alexey will be able to sell the car of brand "A" for 500 thousand rubles, and the car of brand "B" for 350 thousand rubles.

| Car Brand | Fuel Consumption (l/100km) | Annual Insurance Cost (rubles) | Average Annual Maintenance Cost (rubles) |
| :--- | :--- | :--- | :--- |
| "A" | 9 | 35000 | 25000 |
| "B" | 10 | 32000 | 20000 |

Using the data in the table, answer the question: how much more expensive will the purchase and ownership of the more expensive car be for Alexey?
Answer: 160000.

Use of car brand "A":

$900000+(15000 / 100) * 9 * 5 * 40+35000 * 5+25000 * 5-500000=970000$

Use of car brand "B":

$600000+(15000 / 100) * 10 * 5 * 40+32000 * 5+20000 * 5-350000=810000$

Difference: $970000-810000=160000$