5.3. Solve the inequality

$$
12 \cdot \frac{|x+10|-|x-20|}{|4 x-25|-|4 x-15|}-\frac{|x+10|+|x-20|}{|4 x-25|+|4 x-15|} \geqslant-6
$$

In the answer, write the sum of its integer solutions that satisfy the condition $|x|<100$.
Answer: 10 (solution of the inequality: $\left.\left[\frac{15}{4} ; 5\right) \cup\left(5 ; \frac{25}{4}\right]\right)$.)