4. At a large conference, four people need to be selected from five volunteers—Xiao Zhang, Xiao Zhao, Xiao Li, Xiao Luo, and Xiao Wang—to undertake four different tasks: translation, tour guiding, etiquette, and driving. If Xiao Zhang and Xiao Zhao can only perform the first two tasks, and the other three can perform all four tasks, then the number of different selection schemes is $\qquad$ kinds.
Analysis:
Case one: Both Xiao Zhao and Xiao Zhang participate in the work: There are 2 choices for them, and selecting 2 out of the remaining 3 people to participate in the work, there are $A_{2}^{2} \times A_{3}^{2}=12$ ways; Case two: Either Xiao Zhao or Xiao Zhang participates in the work: There are 2 ways to choose one out of the two people, and each person can choose one of the two jobs, which also has 2 ways, making a total of $2 \times 2=4$ ways, and selecting 3 out of the remaining 3 people to participate in the work, there are $A_{3}^{3}=6$ ways, making a total of $4 \times A_{3}^{3}=24$ ways, the total number is $12+24=36$ ways.