Given a right triangle $A B C$. From the vertex $B$ of the right angle, a median $B D$ is drawn. Let $K$ be the point of tangency of side $A D$ of triangle $A B D$ with the inscribed circle of this triangle. Find the acute angles of triangle $A B C$, if $K$ bisects $A D$.
Point $K$ bisects $A D$, so $A B=B D$. Therefore, $\angle A=60^{\circ}$.

## Answer

$30^{\circ}, 60^{\circ}$.

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