$(1+11+21+31+41)+(9+19+29+39+49)=$
$\text{(A)}\ 150 \qquad \text{(B)}\ 199 \qquad \text{(C)}\ 200 \qquad \text{(D)}\ 249 \qquad \text{(E)}\ 250$
We make use of the [associative](https://artofproblemsolving.com/wiki/index.php/Associative) and [commutative](https://artofproblemsolving.com/wiki/index.php/Commutative) properties of [addition](https://artofproblemsolving.com/wiki/index.php/Addition) to rearrange the [sum](https://artofproblemsolving.com/wiki/index.php/Sum) as
\begin{align*} (1+49)+(11+39)+(21+29)+(31+19)+(41+9) &= 50+50+50+50+50 \\ &= 250 \Longrightarrow \boxed{\text{E}} \end{align*}