8 . The positive integer solutions $(x, y)$ of the equation $1!+2!+\cdots+x!=y^{2}$ are $\qquad$ .
8. $(1,1),(3,3)$.

When $x=1$, $y=1$, the equation is satisfied;
When $x=2$, $1!+2!=3$, the equation has no solution;
When $x=3$, $1!+2!+3!=9, y=3$, the equation is satisfied;

When $x=4$, $1!+2!+3!+4!=33$, the equation has no solution;

When $x \geqslant 5$, $1!+2!+\cdots+x!$ ends in 3, while the last digit of a square number is $0,1,4,5,6,9$, the equation has no solution.