14. In the workshop, five clocks were checked. It turned out that clock No. 3 is 3 minutes behind clock No. 2 per day. Clock No. 1 is 1 minute behind clock No. 2 per day, clock No. 4 is behind clock No. 3, and clock No. 5 is behind clock No. 1. If the readings of all five clocks are added together and the sum is divided by 5, the exact time is obtained. It is also known that one of these clocks is accurate. Which one exactly?
14. Let clock No. 1 show $x$ min, then clock No. $2-(x+1)$, clock No. $3-(x-2)$, clock No. $4-(x-3)$ and clock No. $5-(x-1)$. The sum of the readings of all clocks $x+(x+1)+(x-2)+(x-3)+(x-1)=5 x-5$. Since $(5 x-5): 5=$ $=x-1$, and this is the reading of clock No. 5, then these clocks show the exact time.