8. At a little past 8 o'clock in the morning, two cars left the fertilizer plant one after another heading for Happiness Village. Both cars were traveling at a speed of 60 kilometers per hour. At 8:32, the distance the first car had traveled from the fertilizer plant was three times that of the second car. By 8:39, the distance the first car had traveled from the fertilizer plant was twice that of the second car. Then, at what time, in minutes past 8 o'clock, did the first car leave the fertilizer plant?
8.【Solution】$39-32=7$. In these 7 minutes, the distance each car travels is exactly equal to 1(=3-2) times the distance the second car had traveled by 8:32. Therefore, by 8:32, the first car had traveled $7 \times 3$ $=21$ (minutes), meaning it left the fertilizer factory at 8:11 $(32-21=11)$.

【Note】The conclusion of this problem is independent of the speed of the two cars, as long as their speeds are the same. The answer is always 8:11.