The rectangle shown has side lengths of 8 and 4 . The area of the shaded region is
(A) 32
(B) 16
(C) 64
(D) 12
(E) 4

![](https://cdn.mathpix.com/cropped/2024_04_20_6027bc27089ed4fc493cg-047.jpg?height=204&width=352&top_left_y=2294&top_left_x=1320)

Part B: Each correct answer is worth 6.
The area of the rectangle is $8 \times 4$, or 32 .

The unshaded portion of the rectangle is a triangle with base of length 8 and height $h$, as shown.

Since the dotted line (the height) with length $h$ is parallel to the vertical side of the rectangle, then $h=4$.

Thus, the area of the unshaded triangle is $\frac{1}{2} \times 8 \times 4=4 \times 4=16$.

![](https://cdn.mathpix.com/cropped/2024_04_20_748fdafcde2a47412608g-231.jpg?height=204&width=352&top_left_y=169&top_left_x=1540)

The area of the shaded region is the area of the rectangle minus the area of the unshaded triangle.

Thus, the area of the shaded region is $32-16=16$.

Answer: (B)