A rectangle is inscribed in a circle of area $32\pi$ and the area of the rectangle is $34$. Find its perimeter.

[i]2017 CCA Math Bonanza Individual Round #2[/i]
1. **Determine the radius of the circle:**
   The area of the circle is given as \(32\pi\). The formula for the area of a circle is:
   \[
   \pi r^2 = 32\pi
   \]
   Solving for \(r\):
   \[
   r^2 = 32 \implies r = \sqrt{32} = 4\sqrt{2}
   \]

2. **Relate the radius to the rectangle:**
   The rectangle is inscribed in the circle, so the diagonal of the rectangle is the diameter of the circle. Therefore, the diameter \(d\) is:
   \[
   d = 2r = 2 \times 4\sqrt{2} = 8\sqrt{2}
   \]

3. **Express the diagonal in terms of the rectangle's side lengths:**
   Let the side lengths of the rectangle be \(a\) and \(b\). The diagonal of the rectangle can be expressed using the Pythagorean theorem:
   \[
   \sqrt{a^2 + b^2} = 8\sqrt{2}
   \]
   Squaring both sides:
   \[
   a^2 + b^2 = (8\sqrt{2})^2 = 128
   \]

4. **Use the area of the rectangle:**
   The area of the rectangle is given as 34:
   \[
   ab = 34
   \]

5. **Find the sum of the sides:**
   We need to find \(a + b\). We use the identity \((a + b)^2 = a^2 + b^2 + 2ab\):
   \[
   (a + b)^2 = 128 + 2 \times 34 = 128 + 68 = 196
   \]
   Taking the square root of both sides:
   \[
   a + b = \sqrt{196} = 14
   \]

6. **Calculate the perimeter:**
   The perimeter \(P\) of the rectangle is given by:
   \[
   P = 2(a + b) = 2 \times 14 = 28
   \]

The final answer is \(\boxed{28}\).