6. $\left(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}+\frac{1}{384}\right) \times 128=$ .
$\begin{array}{l}\text { [Analysis] Original expression }=\left(\frac{1}{3 \times 1}+\frac{1}{3 \times 2}+\frac{1}{3 \times 4}+\frac{1}{3 \times 8}+\frac{1}{3 \times 16}+\frac{1}{3 \times 32}+\frac{1}{3 \times 64}+\frac{1}{3 \times 128}\right) \times 128 \\ =\frac{1}{3} \times(128+64+32+16+8+4+2+1)=\frac{1}{3} \times 255=85 \\\end{array}$