8. (7 points) Arrange even numbers as shown in the figure below. Ask: 2008 is in the $\qquad$ column.
\begin{tabular}{lllc}
2 & 4 & 6 & 8 \\
16 & 14 & 12 & 10 \\
18 & 20 & 22 & 24 \\
32 & 30 & 28 & 26 \\
$\ldots$ & & &
\end{tabular}
【Analysis】First, we find that the even numbers in the sequence repeat every 8 numbers, with odd rows increasing from left to right and even rows decreasing from right to left, in reverse order to the previous row; then we determine that 2008 is the $2008 \div 2=1004$th number, and then divide 1004 by 8 to find the remainder, and further determine based on the remainder.

【Solution】Solution: 2008 is the $2008 \div 2=1004$th number,
$$
1004 \div 8=125 \cdots 4,
$$

indicating that 2008 has gone through 125 cycles and is in the same column as the fourth number in the first row, which is in the 4th column. Therefore, the answer is: 4.