1.24. $l=224, m=2001, n=2014$. Answer: $839\left(x=\frac{180}{4015}=\frac{36}{803}\right)$.

II. Compute the value of the expression

$$
((\ldots((2018 \oplus 2017) \oplus 2016) \oplus \ldots \oplus 2) \oplus 1)
$$

if $x \oplus y=\frac{3(x+y)}{x y+9}$.
Solution. Since $x \oplus 3=\frac{3(x+3)}{3 x+9}=1$, regardless of the value of $x$, the desired expression is $(((x \oplus 3) \oplus 2) \oplus 1)=((1 \oplus 2) \oplus 1)=\left(\left(\frac{3(1+2)}{1 \cdot 2+9}\right) \oplus 1\right)=\left(\frac{9}{11} \oplus 1\right)=\frac{3\left(\frac{9}{11}+1\right)}{\frac{9}{11} \cdot 1+9}=\frac{5}{9}=0.555 \ldots \approx 0.56$.

Answer: 0.56 .