2. In the Cartesian coordinate system $x O y$, the area of the figure enclosed by the curve
$$
2|x|+3|y|=5
$$

is ( ).
(A) $\frac{5}{3}$
(B) 5
(C) $\frac{20}{3}$
(D) $\frac{25}{3}$
2. D.

As shown in Figure 1, it is clear that the figure enclosed by the curve $2|x|+3|y|=5$ is symmetric about the $x$-axis and $y$-axis. Therefore, we only need to consider the part of the graph in the first quadrant. In this case, $x>0, y>0$, so the curve is $2 x+3 y=5$.

Thus, the figure enclosed by the curve $2|x|+3|y|=5$ is a rhombus, and its area is
$$
2 \times \frac{5}{2} \times \frac{5}{3}=\frac{25}{3} \text {. }
$$