Kanel-Belov A.Y.
The sum of the digits of a natural number $n$ is 100. Can the sum of the digits of the number $n^{3}$ be 1000000?
It is enough to take a number with ones standing at the $1-\mathrm{m}, 10-\mathrm{m}, 100-\mathrm{m}, \ldots, 10^{99}$-th place (counting from the right).
Answer
It can.
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