3. (10 points) Each lead type is engraved with a digit. If printing twelve pages of a book, the lead types for page numbers used are the following 15: $1,2,3,4,5,6,7,8,9,1,0,1,1,1,2$.
Now, a new book is to be printed, and 2011 lead types for page numbers are taken from the warehouse, with some left over after typesetting. Then, this book can have at most $\qquad$ pages. The minimum number of leftover lead types is $\qquad$.
【Analysis】Calculate the number of lead characters used for the first 9 pages, the number of lead characters used per page from page 10 to page 99, and the number of lead characters used per page from page 100 to page 999, then solve accordingly.

【Solution】Solution: The first 9 pages use 9 lead characters,
From page 10 to page 99, each page uses 2 lead characters, for a total of 99 pages,
$$
9+(100-10) \times 2=189 \text { (characters) }
$$

From page 100 to page 999, each page uses 3 lead characters,
100 pages use $189+3$ lead characters,
Let the total number of pages be $k$, according to the problem we have
$$
\begin{array}{l}
189+3(k-99)<2011, \\
3 k<2011+297-189=2119=3 \times 706+1 .
\end{array}
$$

Answer: This book has at most 706 pages. At least 1 lead character remains.