Through an internal point $P$ of an equilateral triangle $ABC$, perpendiculars are drawn to the three sides, with the feet of the perpendiculars being $D, E, F$ in sequence. Connect $AP, BP, CP$. If the area of the equilateral triangle $ABC$ is 2028 square centimeters, and the areas of triangles $PAD$ and $PBE$ are both 192 square centimeters, then the area of triangle $PCF$ is $\qquad$ square centimeters.

【Answer】 630
【Problem Type】Geometry: Half Model
【Solution】
Draw lines through point $P$ parallel to $AB$, $AC$, and $BC$, then $S_{1}=S_{2}$, $S_{3}=S_{4}$, $S_{5}=S_{6}$, $S_{7}=S_{8}$, $S_{9}=S_{10}$, $S_{11}=S_{12}$; so $S_{\text {shaded }}=S_{\text {white }}=\frac{1}{2} S_{\triangle A B C}=\frac{1}{2} \times 2028=1014 \mathrm{~cm}^{2}$, then $S_{\triangle P C F}=1014-192 \times 2=630 \mathrm{~cm}^{2}$