5. Find all natural numbers ending in ...196, which, after erasing these digits, decrease by an integer factor.

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5. The desired number $N=1000 x+196$. Erasing the digits 196 in the number $N$ reduces it by 196 and also by 1000 times, so after erasing we get $x$. According to the condition, $1000 x+196=k x$, where $k$ is an integer. From this, $x=\frac{196}{k-1000}$. $k-1000=196 ; 98 ; 49 ; 28 ; 14 ; 4 ; 2 . \quad x=1,2,4,7,14,49,98$.

The desired numbers: $1196,2196,4196,7196,14196,49196,98196$.