7. (15 points) Insert 2 " $\div$ " and 2 "+" between the 9 "1"s below to make the calculation result an integer. The smallest integer is $\qquad$
\begin{tabular}{|lllllllllll|}
\hline 1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 & $=$ & $?$ \\
\hline
\end{tabular}
【Answer】Solution: According to the analysis, we have
$$
\begin{array}{l}
111 \div 111+1 \div 1+1 \\
=1+1+1 \\
=3
\end{array}
$$

Answer: The smallest integer is 3.
Therefore, the answer is: 1.