24. Given a word arithmetic puzzle:
Where different Chinese characters represent different digits from $0-9$, and the same Chinese characters represent the same digit, making the equation true. Please write one way to fill in the numbers to make the equation true.


24. Given the word arithmetic problem:
$$
(\overline{\text { HuaLao }}+\overline{\text { BaiNian }}+\overline{\text { HuaDan }}) \times(\overline{\text { SanNian }}-（ \text { Jin+Tan+Fan+Fan }))=2010
$$

where different Chinese characters represent different digits from $0-9$, and the same characters represent the same digit, making the equation valid. Please provide one way to fill in the numbers to make the equation true.

【Analysis】First, factorize 2010 into prime factors, then substitute the numbers one by one to verify.
【Solution】Solution: According to the analysis, factorize 2010 into prime factors: $2010=2 \times 3 \times 5 \times 67$
$$
=134 \times 15=201 \times 10=335 \times 6=67 \times 30
$$
$67=14+36+17,30=46-(9+2+0+5)$ fits the problem
(3) $\overline{\text { HuaLao }}+\overline{\text { BaiNian }}+\overline{\text { HuaDan }}=134=23+91+20$

Then, $\overline{\text { SanNian }}-($ Jin + Tan + Fan + Fan $)=15=41-(6+7+8+5)$ fits the problem
$\overline{\text { HuaLao }}=23, \overline{\text { BaiNian }}=91, \overline{\text { HuaDan }}=20, \overline{\text { SanNian }}=41$, Jin $=6$, Tan $=7$, Fan $=8$, Fan $=5$
(4) $\overline{\text { HuaLao }}+\overline{\text { BaiNian }}+\overline{\text { HuaDan }}=201$, then $\overline{\text { HuaLao }}=58, \overline{\text { BaiNian }}=90, \overline{\text { HuaDan }}=53$,

SanNian- $($ Jin + Tan + Fan + Fan $)=28-(7+6+4+1)=10$
Therefore, the answers are: $(23+91+20) \times(41-(6+7+8+5))=2010$;
$(14+36+17) \times(46-(9+2+0+5))=2010 ;$
$(58+90+53) \times(28-(6+7+4+1))=2010$