Three. (Full marks 25 points) Six cassette tapes are packed in a "regular way", which means that every two boxes in a row must form a cuboid. The given dimensions of the cassette tape box are $a=11 \mathrm{~cm}, b=7 \mathrm{~cm}, c=2 \mathrm{~cm}$.
(1) Please provide a way to pack them that minimizes the surface area, and draw a diagram to illustrate it;
(2) If the specific dimensions of $a, b, c$ are not given, but it is assumed that $a \geqslant b \geqslant c$, can the known packing method be used to minimize the surface area? Please explain your reasoning.
Three, as shown in the figure, for a cassette tape, the areas of the three faces sharing a vertex can be denoted as \( C = ab, B = ca, A = bc \).
6 cassette tapes, noting that 6 \( = 1 \times 6 = 2 \times 3 \), thus there are two types of "regular square" packaging: "1 \times 6" and "2 \times 3".
(1) Given \( a \geqslant b \geqslant c \), then in the "1 \times 6" method, the packaging form with the smallest surface area should be as shown in the left figure below.
At this time, the surface area is \( S_{1} = 2C + 12B + 12A \).
In the "2 \times 3" method, the packaging form with the smallest surface area should be as shown in the right figure above.
At this time, the surface area is \( S_{2} = 4C + 6B + 12A \).
Substituting \( a = 11 \, \text{cm}, b = 7 \, \text{cm}, c = 2 \, \text{cm} \), through calculation, we find that \( S_{1} = 586 \, \text{cm}^2, S_{2} = 578 \, \text{cm}^2 \). Therefore, the packaging form with the smallest surface area is the "1 \times 6" method.
(2) We only need to compare \( S_{1} \) and \( S_{2} \).
\[
\begin{aligned}
\because & S_{1} - S_{2} \\
& = (2C + 12B + 12A) - (4C + 6B + 12A) \\
& = 6B - 2C = 6ca - 2ab \\
& = 2a(3c - b),
\end{aligned}
\]
\(\therefore\) When \( a \geqslant b, b < 3c \), the packaging form with the smallest surface area is the "2 \times 3" method;
When \( a \geqslant b = 3c \), either packaging form can be used.
(710043, Xiguang Middle School, Xi'an City, Liu Kangning, compiled)