6. When 2007 bars of soap are packed into $N$ boxes, where $N$ is a positive integer, there is a remainder of 5 . How many possible values of $N$ are there?
(A) 14
(B) 16
(C) 18
(D) 20
(E) 13
6. (A)
$2007-5=2002 . N$ is a factor of 2002 and $2002=2 \times 7 \times 11 \times 13$.

There are altogether $2 \times 2 \times 2 \times 2=16$ factors of $N$. However, $N$ must exceed 5 . So, $N$ cannot be 1 or 2 . Hence there are 14 possible choices of $N$.