A1 The solution to the inequality $x^{2}+2 x-3>x-1$ are those real numbers $x$ for which:
(A) $x1$
(B) $x \geq 1$
(C) $x \geq-3$
(D) $x \in(-2,1)$
(E) $x \in[-2,1]$
A1. We solve the inequality $x^{2}+x-2>0$. We factorize the left side of the inequality $(x+2)(x-1)>0$. The zeros of the quadratic function on the left side of the inequality are $x_{1}=-2$ and $x_{2}=1$. From the sketch, we read off $x1$.