2. (10 points) Tongtong and Linlin each have several cards: If Tongtong gives 6 cards to Linlin, Linlin becomes 3 times as many as Tongtong; if Linlin gives 2 cards to Tongtong, then Linlin becomes 2 times as many as Tongtong. Therefore, Linlin originally had $\qquad$ .


【Solution】Solution: Tongtong gives Linlin 6 cards, Linlin has $\frac{3}{4}$ of the total; Linlin gives Tongtong 2 cards, Linlin has $\frac{2}{3}$ of the total; so the total: $(6+2) \div\left(\frac{3}{4}-\frac{2}{3}\right)=96$, Linlin originally had: $96 \times \frac{3}{4}-6=66$, therefore the answer is: 66.