If $a=\frac{2}{3} b$ and $b \neq 0$, then $\frac{9 a+8 b}{6 a}$ is equal to
(A) $\frac{7}{2}$
(B) 9
(C) $\frac{3}{2}$
(D) $\frac{11}{2}$
(E) $\frac{17}{6}$
Since $a=\frac{2}{3} b$, then $3 a=2 b$. Since $b \neq 0$, then $a \neq 0$.

Thus, $\frac{9 a+8 b}{6 a}=\frac{9 a+4(2 b)}{6 a}=\frac{9 a+4(3 a)}{6 a}=\frac{21 a}{6 a}=\frac{7}{2}($ since $a \neq 0)$.

Alternatively, $\frac{9 a+8 b}{6 a}=\frac{3(3 a)+8 b}{2(3 a)}=\frac{3(2 b)+8 b}{2(2 b)}=\frac{14 b}{4 b}=\frac{7}{2}($ since $b \neq 0)$.

ANSwer: (A)