1. Given two circles $\odot O_{1}$ and $\odot O_{2}$ whose centers are both on the line $y=1-x$, intersecting at points $A$ and $B$, and $A(-7,9)$. Then the coordinates of point $B$ are $\qquad$.
-,1. $(-8,8)$.
After translating the line $y=1-x$, points $A$ and $B$ downward by one unit, we get the line $y=-x$, $A'(-7,8)$, and $B'$.

It is easy to see that points $A$ and $B$ are symmetric with respect to the line $y=1-x$. Therefore, points $A'$ and $B'$ are symmetric with respect to the line $y=-x$. Thus, point $B'(-8,7)$. Translating point $B'(-8,7)$ upward by one unit, we get point $B(-8,8)$.