9. (10 points) Four black $1 \times 1 \times 1$ cubes and four white $1 \times 1 \times 1$ cubes can form $\qquad$ different $2 \times 2 \times 2$ cubes (considering the same cube after rotation as one situation).
【Analysis】First, analyze the case where a color is on the same face. Then, enumerate the cases where the white on the same face becomes 3 and then 2.

【Solution】Solution: According to the problem:
(1) White at the bottom positions 5, 6, 7, 8 is 1 case (same face).
(2) White at the bottom positions 5, 6, 7, the fourth block can be at positions $1,2,4$, a total of 3 cases.
(3) White at the bottom positions 5, 6, the top can be at positions 1,4 or 1,3, a total of 2 cases.
(4) White at the bottom positions 5, 7, the top can be at position 1,3, a total of 1 case.
$1+3+2+1=7$ (cases).
Therefore, the answer is: 7