18 Given real numbers $x_{1}, x_{2}, \cdots, x_{10}$ satisfy
$$
\sum_{i=1}^{10}\left|x_{i}-1\right| \leqslant 4, \sum_{i=1}^{10}\left|x_{i}-2\right| \leqslant 6,
$$

find the average $\bar{x}$ of $x_{1}, x_{2}, \cdots, x_{10}$.
\[
\begin{array}{l}
1810=\left|\sum_{i=1}^{10}\left[\left(x_{i}-1\right)-\left(x_{i}-2\right)\right]\right| \leqslant \\
\sum_{i=1}^{10}\left|x_{i}-1\right|+\sum_{i=1}^{10}\left|x_{i}-2\right| \leqslant 10, \text{ so we have } \\
\qquad \begin{array}{c}
\sum_{i=1}^{10}\left|x_{i}-1\right|=4, \sum_{i=1}^{10}\left|x_{i}-2\right|=6 \Rightarrow 1 \leqslant x_{i} \leqslant 2 \\
\Rightarrow \bar{x}=1+\frac{1}{10} \sum_{i=1}^{10}\left(x_{i}-1\right)=1.4 .
\end{array}
\end{array}
\]