2. If $2^{x}=3^{y}=5^{z}>1$, then the order of $2 x, 3 y, 5 z$ from smallest to largest is ( ).
(A) $3 y<2 x<5 z$
(B) $5 z<2 x<3 y$
(C) $2 x<3 y<5 z$
(D) $5 z<3 y<\hat{i} x$
2. A.

Let $2^{x}=3^{y}=5^{z}=k$, then $k>1$, and
$$
2 x=\frac{2}{\lg 2} \lg k, 3 y=\frac{3}{\lg 3} \lg k, 5 z=\frac{5}{\lg 5} \lg k \text {. }
$$

Since $2^{3}1, \lg k>0$, therefore, $3 y<2 x<5 z$.