## Task 1 - 050711

Two boys are comparing their savings. They find out: $\frac{2}{3}$ of Peter's savings is exactly as much as $\frac{3}{4}$ of Rainer's savings.

Who has saved more money?
Let Peter's amount of money be $p$, Rainer's $r$. Then $\frac{2}{3} p = \frac{3}{4} r$ and consequently $p = \frac{8}{9} r > r$, so Peter has saved more money than Rainer.