The value of $\left(\frac{11}{12}\right)^{2}$ is
(A) between $1 \frac{1}{2}$ and 2
(D) between 0 and $\frac{1}{2}$
(B) between $\frac{1}{2}$ and 1
(E) between 1 and $1 \frac{1}{2}$
(C) greater than 2
Evaluating, $\left(\frac{11}{12}\right)^{2}=\left(\frac{11}{12}\right) \times\left(\frac{11}{12}\right)=\frac{11 \times 11}{12 \times 12}=\frac{121}{144}$.

Since $\frac{121}{144}>\frac{72}{144}=\frac{1}{2}$ and $\frac{121}{144}<\frac{144}{144}=1$, the value of $\left(\frac{11}{12}\right)^{2}$ is between $\frac{1}{2}$ and 1 .

ANSWER: (B)