A pan weighs $645 \mathrm{~g}$ and another $237 \mathrm{~g}$. José divides $1 \mathrm{~kg}$ of meat between the two pans, so that both with their contents have the same weight. How much meat did he put in each pan?
Converting kilograms to grams, we have $1 \mathrm{~kg}=1000 \mathrm{~g}$. The two pots together with the meat weigh

$$
645+237+1000=1882 \mathrm{~g}
$$

Therefore, each pot with its content of meat should weigh $1882 \div 2=941 \mathrm{~g}$. Thus, José placed in each pot, respectively,

$$
941-645=296 \mathrm{~g} \text{ and } 941-237=704 \mathrm{~g}
$$