For every $ 0 \le i \le 17$, $ a_i \equal{} \{ \minus{} 1, 0, 1\}$. 
How many $ (a_0,a_1, \dots , a_{17})$ $ 18 \minus{}$tuples are there satisfying :
$ a_0 \plus{} 2a_1 \plus{} 2^2a_2 \plus{} \cdots \plus{} 2^{17}a_{17} \equal{} 2^{10}$

$\textbf{(A)}\ 9  \qquad\textbf{(B)}\ 8  \qquad\textbf{(C)}\ 7  \qquad\textbf{(D)}\ 4  \qquad\textbf{(E)}\ 1$
1. We need to find the number of 18-tuples \((a_0, a_1, \dots, a_{17})\) where each \(a_i \in \{-1, 0, 1\}\) and they satisfy the equation:
   \[
   a_0 + 2a_1 + 2^2a_2 + \cdots + 2^{17}a_{17} = 2^{10}
   \]

2. Notice that \(2^{10}\) is a power of 2, and we need to express it as a sum of terms of the form \(2^i a_i\) where \(a_i \in \{-1, 0, 1\}\).

3. We can write \(2^{10}\) as a sum of distinct powers of 2, considering the constraints on \(a_i\). The possible ways to write \(2^{10}\) using the terms \(2^i a_i\) are:
   \[
   2^{10}, \quad 2^{11} - 2^{10}, \quad 2^{12} - 2^{11} - 2^{10}, \quad \ldots, \quad 2^{17} - 2^{16} - \cdots - 2^{11} - 2^{10}
   \]

4. Each of these expressions represents a unique way to form \(2^{10}\) using the terms \(2^i a_i\) with \(a_i \in \{-1, 0, 1\}\). 

5. To count the number of such sets, we observe that each expression corresponds to a unique combination of \(a_i\) values. Specifically, each expression involves a different set of indices \(i\) where \(a_i = 1\) and the rest are 0 or -1.

6. The number of such distinct sets is equal to the number of terms in the sequence from \(2^{10}\) to \(2^{17} - 2^{16} - \cdots - 2^{11} - 2^{10}\). This sequence has 8 terms.

Conclusion:
\[
\boxed{8}
\]