3. The difference of two natural numbers is 5 times less than their sum and 24 times less than their product. Find these numbers.
Solution. Let $x$ be the larger of the two numbers, and $y$ be the smaller. The condition of the problem is $\left\{\begin{array}{c}x+y=5(x-y) \\ x y=24(x-y)\end{array} \rightarrow\left\{\begin{array}{c}2 x=3 y \\ \frac{3}{2} y^{2}=12 y\end{array}\right.\right.$.

$y=0$ is not a natural number, the second solution is $y=8 \rightarrow x=12$.

Answer: $12,8$.