Problem 1. Tanya photographed four kittens eating sausages (Fig. 1). Soon she took another shot (Fig. 2). Each kitten eats its sausages continuously and at a constant speed, and does not touch others' sausages. Who will finish first and who will finish last? Explain your answer.

Fig. 1

![](https://cdn.mathpix.com/cropped/2024_05_06_a681d444f3973745158cg-1.jpg?height=1025&width=1086&top_left_y=507&top_left_x=178)

[5 points]

(T. I. Goleneva-Kutuzova, T. V. Kazitsina, A. A. Trunin)
Answer. Tigrasha will finish first, and Snezhok will finish last.

Solution. During the time that passed between the two photos, Chernysh ate 2 sausages, Tigrasha 5, Snezhok 3, and Pushok 4. Let's wait the same amount of time and look at the cats again. Chernysh will eat another 2 sausages, leaving him with one, which will take him half the time. The same goes for Pushok: he will eat 4, and he will have two sausages left to eat, which will also take half the time. Tigrasha will eat 5 sausages, and he will have two left, which is less than half of five. Snezhok will eat 3 sausages, and he will have two left, which is more than half of three. Therefore, Tigrasha will finish his sausages the fastest, and Snezhok will finish the slowest.