9. Martha multiplied two 2-digit numbers correctly on a piece of paper. Then she scribbled out three digits as shown.
What is the sum of the three digits she scribbled out?

A 5
B 6
C 9
D 12
E 14
9. B Let the three missing digits from left to right be $a, b$ and $c$. Consider the final digit ' 2 ' of the answer. This is the last digit of $3 \times b$ and hence $b=4$. Also, note that if $a$ were 2 or more, then the answer would be more than 400. Therefore $a=1$. Hence the multiplication is $13 \times 24=312$, giving $c=1$. Therefore the sum of the digits scribbled out is $a+b+c=1+4+1=6$.