1.100 people share 1000 RMB, and the money of any 10 people does not exceed 190 RMB. Then, the most one person can have is ( ) RMB.
(A) 109
(B) 109
(C) 118
(D) 119
-1 . (B).
Let the person with the most money have $x$ yuan, and the rest are divided into 11 groups, each with 9 people, and this person together with each group of 9 people does not exceed 190 yuan. Therefore,
$$
190 \times 11 \geqslant 1000-x+11 x .
$$

This gives $x \leqslant 109$.
So, one person can have at most 109 yuan, and the rest each have 9 yuan, which meets the requirements.