7. From $1,2, \cdots, 1995$, what is the maximum number of numbers that can be selected such that none of the selected numbers is 19 times another?
7. If the number of chosen numbers is more than $1995-100=1895$, then there must be two numbers belonging to one of the following 100 pairs: $(6,6 \times 19),(7,7 \times 19), \cdots,(105,105 \times 19)$. One number must be 19 times the other, so $n \leqslant 1895$. Taking $1,2,3,4,5,106,107$, $\cdots, 1995$, these 1895 numbers satisfy the problem's requirements.