4. What is the 2012th digit in the sequence 012343210012343210012...?
4. In the sequence 012343210012343210012....the "subsequence" 012343210 which has 9 digits repeats.

1 point

$2012: 9=223$

21

32

5

Up to the 2012th digit, the "subsequence" 012343210 repeats 223 times, and there are still five digits remaining.

2 points

This means that the 2012th digit in the given sequence is the 5th digit of the "subsequence" 012343210.

Therefore, the 2012th digit in the given sequence is 4.

1 point

.TOTAL 4 POINTS