## Task 1 - 010621

During a test flight on the route Moscow-Mirny (a Soviet Antarctic station), two Soviet aircraft of the types "AN-10" and "IL-18" crossed Europe, Asia, Australia, Antarctica, the Indian Ocean, and the Pacific Ocean.

The AN-10 covered the enormous distance of $25300 \mathrm{~km}$ in $48 \mathrm{~h}$ and $7 \mathrm{~min}$, while the IL-18 took $44 \mathrm{~h}$ and $36 \mathrm{~min}$.

What distance did the two aircraft cover on average in 1 hour?
The average speed is obtained as the quotient of the distance and the flight time. For the AN-10, it is:

$$
\frac{25300 \mathrm{~km}}{48 \frac{7}{60} \mathrm{~h}}=525.8 \frac{\mathrm{km}}{\mathrm{h}}
$$

and for the IL-18:

$$
\frac{25300 \mathrm{~km}}{44 \frac{36}{60} \mathrm{~h}}=567.3 \frac{\mathrm{km}}{\mathrm{h}}
$$

The aircraft flew on average approximately $526 \mathrm{~km}$ and $567 \mathrm{~km}$ per hour, respectively.