10. (3 points) Cars A and B both depart from point A, pass through point B, and head to point C. The distance between A and B is equal to the distance between B and C. Car B's speed is 80% of Car A's speed. It is known that Car B departs 11 minutes earlier than Car A, but stops for 7 minutes at point B, while Car A continues non-stop to point C. In the end, Car B arrives at point C 4 minutes later than Car A. Then, Car A surpasses Car B $\qquad$ minutes after Car B departs.
10. (3 points) Two cars, A and B, both depart from point A, pass through point B, and head to point C. The distance between A and B is equal to the distance between B and C. Car B's speed is 80% of Car A's speed. It is known that Car B departs 11 minutes earlier than Car A, but stops for 7 minutes at point B, while Car A continues non-stop to point C. In the end, Car B arrives at point C 4 minutes later than Car A. Therefore, 27 minutes after Car B departs, Car A overtakes Car B.
【Solution】: $11-7=4$ (minutes)
$4 \div(1-80 \%)=20$ (minutes);
$20+7=27$ (minutes);
At this point, Car B is at point B;
Car A needs: $40 \times 80 \% \div 2=16$ (minutes) to reach point B;
That is, 16 + 11 = 27 (minutes) after Car B departs;
That is, 27 minutes after Car B departs, both Car A and Car B are at point B, at which point Car A begins to overtake Car B.
Answer: 27 minutes after Car B departs, Car A overtakes Car B.
The answer is: 27.