2. $V, W, X, Y, Z$ are 5 digits in base 5. The three three-digit numbers $(V Y Z)_{5},(V Y X)_{5},(V V W)_{5}$ in base 5 increase sequentially with a common difference of 1. What is the three-digit number $(X Y Z)_{5}$ in base 10?
2. From $(V Y Z)_{5}+1=(V Y X)_{5}=(V V W)_{5}-1$ we get $5(V-Y)=X-W+1$. Clearly, $V-Y \geqslant 1, X-W \leqslant 4$, so, only $V-Y=1, X-W=4$. Therefore, we deduce that $X=4, W=$ $0, Z=3, V=2, Y=1$, thus $(X Y Z)_{5}=(413)_{5}=108$