13) What is the probability that the sum of the values obtained by rolling a die three times is less than or equal to 5?
$\begin{array}{ll}\text { (A) Less than } 3 \% & \text { (B) between } 3 \% \text { and } 5 \%\end{array}$
(E) more than $9 \%$.
(C) between $5 \%$ and $7 \%$
(D) between $7 \%$ and $9 \%$
13) The answer is $(\mathrm{B})$.

A score $\leq 5$ can only be achieved with $1,1,1$ or $1,1,2$ or $1, 1, 3$ or $1,2, 2$.

While the first result can be obtained in a unique way, each of the others can be obtained in three different ways (for example, for the result $1,1,2$, it can be obtained with 2 on the first or second and 0 on the third roll).

Since the possible outcomes (ordered!) when rolling three dice are $6^{3}=216$, the sought probability is equal to

$$
\frac{1+3+3+3}{216}=\frac{10}{216} \approx 0.046 \text{. }
$$