The sum of nine consecutive positive integers is 99 . The largest of these integers is
(A) 9
(B) 11
(C) 19
(D) 7
(E) 15

## Part B: Each question is worth 6 credits.
Solution

Since the sum of the nine integers is 99 , their average is $\frac{99}{9}$ or 11 .

Because there is an odd number of consecutive integers, 11 is the middle integer and 15 is the largest.

ANSWER: (E)

PART B:

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