The sides of a parallelogram are 8 and 3; the bisectors of two angles of the parallelogram, adjacent to the longer side, divide the opposite side into three parts. Find each of them.
Each of the specified bisectors cuts off an isosceles triangle from the parallelogram.

## Solution

Let $B K$ and $C M$ be the bisectors of angles $B$ and $C$ of parallelogram $A B C D$, where $A D=B C=8, A B=C D=3$.

Since $\angle A B K=\angle C B K=\angle A K B$, triangle $A B K$ is isosceles. Therefore, $A K=A B=3$.

Similarly, $M D=D C=3$.

## Answer

$3,2,3$.