60. Let the number of positive divisors of 3600 be $m$, and the number of positive divisors of 36 be $n$, then $\frac{m}{n}=$
Answer: 5.
Solution: Since
$$
3600=2^{4} \times 3^{2} \times 5^{2},
$$

Therefore, the number of positive divisors of 3600
$$
m=(4+1)(2+1)(2+1)=5 \times 3 \times 3=45.
$$

Also, since
$$
\begin{array}{c}
36=2^{2} \times 3^{2}, \\
27
\end{array}
$$

Therefore, the number of positive divisors of 36
$$
\begin{array}{c}
n=(2+1)(2+1)=3 \times 3=9. \\
\frac{m}{n}=\frac{45}{9}=5.
\end{array}
$$

Hence