The sum of the three smallest distinct divisors of some number $A$ is 8. How many zeros can the number $A$ end with?

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The number 8 can be represented as the sum of three different natural numbers in two ways: $8=1+2+5=$ $1+3+4$. The numbers 1, 3, and 4 cannot be the three smallest divisors of the number $A$: if $A$ is divisible by 4, then it is also divisible by 2. Therefore, the three smallest divisors of $A$ are 1, 2, and 5. Thus, $A$ is divisible by 10, but not by 4. Consequently, the number $A$ ends with exactly one zero.

## Answer

One zero.