2. The graph of the quadratic function $y=a x^{2}+$ $b x+c$ is shown in Figure 1. Which of the following conclusions is correct? ( ).
(A) $3|a|+|c|>2|b|$
(B) $3|a|+|c|=2|b|$
(C) $3|a|+|c|<2|b|$
(D) $3|a|+|c| \leqslant 2|b|$
2. C.

From the graph, we know $a0, c0$, i.e.,
$$
a+b+c>0 \text {. }
$$

Since $-\frac{b}{2 a}>1$, we have,
$$
2 a+b>0 \text {. }
$$

From equations (1) and (2), we get $3 a+2 b+c>0$.
Then $3|a|+|c|-2|b|=-3 a-c-2 b$
$$
=-(3 a+2 b+c)<0 \text {. }
$$

Therefore, $3|a|+|c|<2|b|$.