1. Given $a+b+c=0, a>b>c$. Then the range of $\frac{c}{a}$ is $\qquad$ .
$$
\text{2.1. }-2b>c, \text{ get } a>0, cb>c, \text{ get}
$$
$$
1>\frac{b}{a}>\frac{c}{a} \text{. }
$$

Substitute equation (1) into equation (2) to get
$$
1>-1-\frac{c}{a}>\frac{c}{a} \text{. }
$$

Solving, we get $-2<\frac{c}{a}<-\frac{1}{2}$.