A nickel is placed on a table. The number of nickels which can be placed around it, each tangent to it and to two others is:
$\textbf{(A)}\ 4 \qquad\textbf{(B)}\ 5 \qquad\textbf{(C)}\ 6 \qquad\textbf{(D)}\ 8 \qquad\textbf{(E)}\ 12$
Arranging the nickels in a hexagonal fashion, we see that only $\boxed{\textbf{(C) }6}$ nickels can be placed around the central nickel.