11. (10 points) On Qingming Festival, students take a bus to the martyrs' cemetery to pay respects. If the bus increases its speed by one-fifth after driving for 1 hour, it can arrive 10 minutes earlier than the scheduled time; if the bus first drives 60 kilometers at the original speed and then increases its speed by one-third, it can arrive 20 minutes earlier than the scheduled time. How many kilometers is it from the school to the martyrs' cemetery?
【Analysis】First, find the scheduled time after driving for 1 hour, the time used is the scheduled time's $1 \div\left(1+\frac{1}{5}\right)=$ $\frac{5}{6}$, so the scheduled time is $10 \div\left(1-\frac{5}{6}\right)=60$ minutes, thus the total scheduled time for the entire journey is 1 hour + 60 minutes $=$ 120 minutes; then find the time used, the time used is the scheduled time's $1 \div\left(1+\frac{1}{3}\right)=\frac{3}{4}$, which means it is ahead by $120 \times$ $\left(1-\frac{3}{4}\right)=30$ minutes, finally find the ratio corresponding to 60 kilometers, which is $1-\frac{20}{30}$, and solve accordingly.
【Solution】Solution: If the speed is increased by one-fifth after driving for 1 hour, then the time used after driving for 1 hour is the scheduled time's $1 \div\left(1+\frac{1}{5}\right)=\frac{5}{6}$,
so the scheduled time is $10 \div\left(1-\frac{5}{6}\right)=60$ minutes, thus the total scheduled time for the entire journey is 1 hour + 60 minutes $=120$ minutes;

If the car first travels 60 kilometers at the original speed, then increases the speed by one-third, the time used is the scheduled time's $1 \div\left(1+\frac{1}{3}\right)=\frac{3}{4}$, which means it is ahead by $120 \times\left(1-\frac{3}{4}\right)=30$ minutes,
but it actually arrived 20 minutes ahead, indicating that $\frac{2}{3}$ of the journey had the speed increased,
$$
\begin{array}{l}
60 \div\left(1-\frac{2}{3}\right) \\
=60 \div \frac{1}{3} \\
=180 \text { (kilometers), }
\end{array}
$$

Answer: The distance from the school to the Martyrs' Cemetery is 180 kilometers.