1. As shown in Figure 1, it is known that rectangle $A B C D$ can be exactly divided into seven small rectangles of the same shape and size. If the area of the small rectangle is 3, then the perimeter of rectangle $A B C D$ is
$-1.19$.
Let the length of the small rectangle be $a$ and the width be $b$. Then $3a = 4b \Rightarrow a = \frac{4}{3}b \Rightarrow ab = \frac{4}{3}b^2 = 3$. Solving this, we get $b = \frac{3}{2}, a = 2$.
Therefore, the perimeter of rectangle $ABCD$ is $2(4a + b) = 8a + 2b = 16 + 3 = 19$.