2. Given the following two propositions:
(1) Let $a, b, c$ be complex numbers. If $a^{2}+b^{2}>c^{2}$, then $a^{2}+b^{2}-c^{2}>0$.
(2) Let $a, b, c$ be complex numbers. If $a^{2}+b^{2}-c^{2}>0$, then $a^{2}+b^{2}>c^{2}$.; then the correct statement is
(A) Proposition (1) is correct, and Proposition (2) is also correct;
(B) Proposition (1) is correct, and Proposition (2) is incorrect;
(C) Proposition (1) is incorrect, and Proposition (2) is also incorrect;
(D) Proposition (1) is incorrect, and Proposition (2) is correct.
2. (B)

Statement (1) is correct. $a^{2}+b^{2}>c^{2}$ indicates that $a^{2}+b^{2}$ and $c^{2}$ are real numbers, therefore, according to the rule of transposition, we have $a^{2}+b^{2}-c^{2}>0$.

Statement (2) is incorrect. $a^{2}+b^{2}-c^{2}>0$ only indicates that $a^{2}+b^{2}-c^{2}$ is a real number, but it does not guarantee that $a^{2}+b^{2}$ and $c^{2}$ are both real numbers, hence $a^{2}+b^{2}>c^{2}$ may not hold.
For example, take $a=2+\mathrm{i}, b=\mathrm{i}, c=\sqrt{2}+\sqrt{2} \mathrm{i}$, then we have
$a^{2}+b^{2}-c^{2}=(3+4 \mathrm{i})+(-1)-4 \mathrm{i}=2>0$, but it is not true that $a^{2}+b^{2}=2+4 \mathrm{i}>4 \mathrm{i}=c^{2}$.