## Task 1 - 130611

A distance of $7 \mathrm{~m}$ in length is to be divided into four parts such that the second segment is $40 \mathrm{~cm}$ longer than the first, the third is $40 \mathrm{~cm}$ longer than the second, and the fourth is $40 \mathrm{~cm}$ longer than the third.

Determine whether such a division is possible, and if so, give the lengths of each of the four segments!
The lengths of the four segments are $x, x+40, x+80$, and $x+120$ (all in $\mathrm{cm}$), so the sum is:

$$
x+x+40+x+80+x+120=4 x+240=700 \mathrm{~cm} \quad \Rightarrow \quad x=115 \mathrm{~cm}
$$

The first segment is thus $115 \mathrm{~cm}$ long, the second $155 \mathrm{~cm}$, the third $195 \mathrm{~cm}$, and the fourth $235 \mathrm{~cm}$.