A game with three piles of stones. There are three piles of stones: the first has 10, the second has 15, and the third has 20. On a turn, it is allowed to split any pile into two smaller parts; the player who cannot make a move loses.

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There are 45 stones in total. In the end, we will get 45 piles of one stone each. To break down the first pile into single stones, it takes 9 moves; for the second pile, it will take 14 moves; for the third pile, it will take 19 moves (the number of moves does not depend on whether we separate the stones one by one or in groups). Thus, the number of moves is $9+14+19=42$, and this number does not depend on the moves made by the partners. The last, even move is made by the second player, and he wins.