Kevin is in first grade, so his teacher asks him to calculate $20+1\cdot 6+k$, where $k$ is a real number revealed to Kevin. However, since Kevin is rude to his Aunt Sally, he instead calculates $(20+1)\cdot (6+k)$. Surprisingly, Kevin gets the correct answer! Assuming Kevin did his computations correctly, what was his answer?

[i]Proposed by James Lin[/i]
1. First, let's write down the two expressions given in the problem:
   - The correct expression according to the order of operations (PEMDAS/BODMAS): \( 20 + 1 \cdot 6 + k \)
   - Kevin's incorrect expression: \( (20 + 1) \cdot (6 + k) \)

2. Simplify the correct expression:
   \[
   20 + 1 \cdot 6 + k = 20 + 6 + k = 26 + k
   \]

3. Simplify Kevin's incorrect expression:
   \[
   (20 + 1) \cdot (6 + k) = 21 \cdot (6 + k) = 21 \cdot 6 + 21 \cdot k = 126 + 21k
   \]

4. According to the problem, Kevin's incorrect expression gives the correct answer. Therefore, we set the two expressions equal to each other:
   \[
   26 + k = 126 + 21k
   \]

5. Solve for \( k \):
   \[
   26 + k = 126 + 21k
   \]
   \[
   26 - 126 = 21k - k
   \]
   \[
   -100 = 20k
   \]
   \[
   k = \frac{-100}{20} = -5
   \]

6. Substitute \( k = -5 \) back into the correct expression to find the answer:
   \[
   26 + k = 26 + (-5) = 21
   \]

The final answer is \(\boxed{21}\).