4. (8 points) In a $4 \times 4$ grid paper, place candies according to the following requirements: (1) Each cell must contain candies; (2) In adjacent cells, the left cell contains 1 fewer candy than the right cell, and the top cell contains 2 fewer candies than the bottom cell; (3) The bottom-right cell contains 20 candies. Therefore, the total number of candies on the grid paper is $\qquad$. (Adjacent cells refer to cells that share a common edge)
【Answer】Solution: According to the problem, the number of candies in the grid cells is as shown in the figure, and it is found that a pair of cells that are centrally symmetric
contain a total of 31 candies,
$\therefore$ there are $\frac{31 \times 16}{2}=248$ candies in total.
or $11+12+13+14+13+14+15+16+15+16+17+18+17+18+19+20=248$
Therefore, the answer is 248.