32. Suppose that $a, b, c$ are distinct numbers such that
$$
(b-a)^{2}-4(b-c)(c-a)=0 \text {, }
$$
find the value of $\frac{b-c}{c-a}$.
32 Ans: 1.
Observe that $((b-c)+(c-a))^{2}-4(b-c)(c-a)=0$. Hence $((b-c)-(c-a))^{2}=0$. Thus $b-c=c-a$.