12. A magazine prints six photos, which are of three 

famous people and their baby photos, but the three baby photos are not labeled as to which three people they belong to, and readers have to choose themselves. Assuming each photo is equally likely. Then the probability that a reader randomly selects three photos, making the baby photos correspond to the names of the three celebrities is ( ).
(A) $\frac{1}{9}$
(B) $\frac{1}{6}$
(C) $\frac{1}{4}$
(D) $\frac{1}{3}$
(E) $\frac{1}{2}$
12. B.

Let event $A$ be the event of correctly selecting three baby photos. Then $P(A)=\frac{1}{3!}=\frac{1}{6}$.