1. $2019^{\ln \ln 2019}-(\ln 2019)^{\ln 2019}$ $=$ . $\qquad$

Fill in the blank (8 points per question, total 64 points)
1. $2019^{\ln \ln 2019}-(\ln 2019)^{\ln 2019}$ $=$ . $\qquad$
\begin{array}{l}\text {1.0. } \\ 2019^{\ln \ln 2019}=\left(e^{\ln 2019}\right)^{\ln \ln 2019} \\ =\left(e^{\ln \ln 2019}\right)^{\ln 2019}=(\ln 2019)^{\ln 2019} .\end{array}