25. Person A distributes 24 apples to Person B and Person C, and each of the three people has at least two apples. Then there are ( ) ways to distribute the apples.
(A) 105
(B) 114
(C) 190
(D) 210
(E) 380
25. C.

Let the three people have $x$, $y$, and $z$ apples respectively.
Since each person has at least two apples, let $a=x-2$, $b=y-2$, $c=z-2$.
From $x+y+z=24 \Rightarrow a+b+c=18$.
By the stars and bars method, the total number of ways is $\mathrm{C}_{18+2}^{2}=\mathrm{C}_{20}^{2}=190$.