1. (10 points) The little rabbit and the little turtle travel from location $A$ to the forest amusement park. The little rabbit starts at 9:00 AM, jumping 40 meters per minute, and after every 3 minutes of jumping, it plays on the spot for 2 minutes. The little turtle starts at 6:40 AM, crawling 10 meters per minute without any breaks or playtime. It is known that the little turtle arrives at the forest amusement park 15 seconds earlier than the little rabbit. How far is it from $A$ to the forest amusement park in meters?
【Analysis】As shown in the line segment diagram:
In the first stage, which is 5 minutes, the rabbit walks $40 \times 3=120$ meters, the turtle walks 50 meters in 5 minutes, the rabbit is faster than the turtle by: 120 - 50 $=70$ (meters), in the first stage (i.e., the playing stage in the middle) the turtle's distance traveled should be greater than or equal to the rabbit's distance, 15 seconds is $\frac{1}{4}$ minute, the rabbit walks $40 \times \frac{1}{4}=10$ meters; from 6:40 to 9:00, there are 140 minutes, $140 \times 10=1400$ (meters), $1400-$ $10=1390$ (meters), $1390 \div 70 \approx 19$ (groups), i.e., 19 groups of 5 minutes $19 \times 5=95$ (minutes), then the rabbit's distance in the first stage: $19 \times 120=2280$ (meters), the turtle's distance in the first stage: $1390+95 \times 10=2340$ (meters) In the second stage: $2340-2280=60$ (meters), the rabbit is faster than the turtle by: $40-10=30$ (meters) every 5 minutes, $60 \div 30=2$ (minutes) $95+2=97$ (minutes) Total distance: $1400+97 \times 10=2370$ (meters).

【Solution】Solution: As shown in the line segment diagram:
Every 5 minutes, the rabbit is faster than the turtle by: $40 \times 3-50=70$ (meters)
15 seconds is $\frac{1}{4}$ minute, the rabbit walks $40 \times \frac{1}{4}=10$ meters
From 6:40 to 9:00, there are 140 minutes
$$
\begin{array}{l}
140 \times 10=1400 \text { (meters) } \\
1400-10=1390 \text { (meters) } \\
1390 \div 70 \approx 19 \text { (groups) }
\end{array}
$$

i.e., 19 groups of 5 minutes $19 \times 5=95$ (minutes)
Then the rabbit's distance in the first stage: $19 \times 120=2280$ (meters)
The turtle's distance in the first stage: $1390+95 \times 10=2340$ (meters)
In the second stage: $2340-2280=60$ (meters)
$60 \div(40-10)=2$ (minutes)
$95+2=97$ (minutes)
Total distance: $1400+97 \times 10=2370$ (meters).