Each of the sides of five congruent rectangles is labeled with an integer. In rectangle A, $w = 4, x = 1, y = 6, z = 9$. In rectangle B, $w = 1, x = 0, y = 3, z = 6$. In rectangle C, $w = 3, x = 8, y = 5, z = 2$. In rectangle D, $w = 7, x = 5, y = 4, z = 8$. In rectangle E, $w = 9, x = 2, y = 7, z = 0$. These five rectangles are placed, without rotating or reflecting, in position as below. Which of the rectangle is the top leftmost one?


$\mathrm{(A)\ } A \qquad \mathrm{(B) \ }B \qquad \mathrm{(C) \  } C \qquad \mathrm{(D) \  } D \qquad \mathrm{(E) \  }E$
Looking at the list of $w$ and $y$ values that must match up left-to-right, we have $(w,y) = A(4,6), B(1,3), C(3,5), D(7,4), E(9,7)$.  Looking for digits that only appear once, we see that $9$, $6$, $1$, and $5$ cannot match up to other digits, and thus must appear on the ends.  $1$ and $9$ only appear on the left, and thus their respective blocks $B$ and $E$ must appear on the left.  Similarly, $6$ and $5$ only appear on the right, and thus their blocks $A$ and $C$ must appear on the right-most block of their row.  Therefore, $D$, the only block without a unique digit, must be the top-center block.
Now that we have placed one block, $D$, we can only place block $E$ to the left of $D$, and block $A$ to the right of $D$.  Thus, $\boxed{E}$ is the right answer.
Completing the puzzle, the top boxes read $EDA$, while the bottom two boxes read $BC$.