2. The graph of the quadratic function $f(x)=a x^{2}+b x+c$ is shown in the figure. Let
$$
N=|a+b+c|+|2 a-b|, M=|a-b+c|+|2 a+b| \text {, }
$$

then ( ).
A. $M>N$
B. $M=N$
C. $M<N$
D. The relationship between $M$ and $N$ cannot be determined
2. C. Hint: $f(1)=a+b+c0, a>0,-\frac{b}{2 a}>1$.

Thus $b0$. Also $f(0)=c0$, hence
$$
\begin{array}{l}
\quad M-N=|a-b+c|+|2 a+b|-|a+b+c|-|2 a-b|=(a-b+c)+(a+b+c)-(2 a+b)- \\
(2 a-b)=-2(a-c)<0, \\
\therefore M<N .
\end{array}
$$