8. (6 points) On a quadrilateral piece of paper, there are 10 points. If the vertices of the quadrilateral are included, there are a total of 14 points. It is known that no three of these points are collinear. According to the following rules, cut this piece of paper into some triangles:
(1) Each triangle's vertices are 3 of these 14 points;
(2) Inside each triangle, there are no other points from these 14 points.
Then, the maximum number of triangles that can be cut from this quadrilateral piece of paper is $\qquad$.
【Answer】Solution: Through the above analysis, we get: the maximum number of triangles that can be cut out is $4+2 \times 9=22$ (pieces). Answer: This piece of quadrilateral paper can cut out a maximum of 22 triangles. Therefore, the answer is: 22.