8. How many different products divisible by ten can be formed from the numbers $2,3,5,7,9 ?$
8. For the product of numbers to be divisible by 10, the factors must include the numbers 2 and 5. Taking this into account, the following products satisfy the condition of the problem:
1) $2 \cdot 5$
2) $2 \cdot 5 \cdot 3$
3) $2 \cdot 5 \cdot 7$
4) $2 \cdot 5 \cdot 9$;
5) $2 \cdot 5 \cdot 3 \cdot 7$
6) $2 \cdot 5 \cdot 3 \cdot 9$
7) $2 \cdot 5 \cdot 7 \cdot 9$
8) $2 \cdot 5 \cdot 3 \cdot 7 \cdot 9$.

In total, there are 8 products.