Let $A=\{1,2,\ldots, 2006\}$. Find the maximal number of subsets of $A$ that can be chosen such that the intersection of any 2 such distinct subsets has 2004 elements.
To solve this problem, we need to find the maximal number of subsets of \( A = \{1, 2, \ldots, 2006\} \) such that the intersection of any two distinct subsets has exactly 2004 elements.

1. **Understanding the Problem:**
   - Each subset must have at least 2004 elements.
   - The intersection of any two distinct subsets must have exactly 2004 elements.

2. **Considering Subsets with 2006 Elements:**
   - If a subset has 2006 elements, it is the entire set \( A \).
   - There can be at most one such subset because any other subset would have to intersect with it in all 2006 elements, which contradicts the requirement of having exactly 2004 elements in the intersection.

3. **Considering Subsets with 2005 Elements:**
   - Let’s denote a subset with 2005 elements as \( S \).
   - If \( S \) is missing one element from \( A \), say \( a \), then \( S = A \setminus \{a\} \).
   - Any other subset \( T \) with 2005 elements must miss a different element, say \( b \), so \( T = A \setminus \{b\} \).
   - The intersection \( S \cap T \) will be \( A \setminus \{a, b\} \), which has exactly 2004 elements.
   - There are 2006 such subsets, each missing a different element from \( A \).

4. **Considering Subsets with 2004 Elements:**
   - Let’s denote a subset with 2004 elements as \( U \).
   - If \( U \) is missing two elements from \( A \), say \( a \) and \( b \), then \( U = A \setminus \{a, b\} \).
   - Any other subset \( V \) with 2004 elements must miss a different pair of elements, say \( c \) and \( d \), so \( V = A \setminus \{c, d\} \).
   - The intersection \( U \cap V \) will be \( A \setminus \{a, b, c, d\} \), which has 2002 elements, not 2004.
   - Therefore, subsets with 2004 elements cannot be used.

5. **Conclusion:**
   - The maximal number of subsets of \( A \) such that the intersection of any two distinct subsets has exactly 2004 elements is achieved by considering subsets with 2005 elements.
   - There are 2006 such subsets, each missing a different element from \( A \).

The final answer is \(\boxed{2006}\).