25.2 The graphs of the algebraic expressions $2 x+3 y-6=0, 4 x-3 y-6=0, x=2$ and $y=$ $\frac{2}{3}$ intersect at
(A) 6 points.
(B) 1 point.
(C) 2 points.
(D) no points.
(E) an unlimited number of points.
(6th American High School Mathematics Examination, 1955)
[Solution] From the first two equations, we can solve for $x=2, y=\frac{2}{3}$. Therefore, the four lines intersect at one point. Hence, the answer is $(B)$.