## Task B-3.5.

There are tokens on three piles: one pile has 5 tokens, another has 10 tokens, and the third has 15 tokens. Two players are playing a game. In one move, it is allowed to divide one pile of tokens into two smaller piles, not necessarily equal. The player who cannot make a move loses. Which player will win, the one who plays first or the one who plays second?
## Solution.

After each move, the number of piles increases by one.

At the beginning, there are 3 piles, and at the end, $5+10+15=30$.

This means that 27 moves will be played.

The first player wins because they will play the last move.

Note: If a student arrives at the possible 27 moves and the first player's victory by listing some of the pile distribution variants, but does not conclude that the number of piles increases by 1 with each move, they can receive a maximum of 4 points.