A5 Dano je zaporedje

$a_{1}=\sqrt{5}$

$a_{2}=\sqrt{5 \sqrt{5}}$

$a_{3}=\sqrt{5 \sqrt{5 \sqrt{5}}}$

$a_{4}=\sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5}}}}$

The fifth term of this sequence is equal to:
(A) $5 \frac{1}{32}$
(B) $\sqrt[32]{5^{31}}$
(C) $5 \cdot \sqrt[32]{5}$
(D) $5^{5} \sqrt{5}$
(E) $5^{\frac{32}{31}}$
A5. The fifth term has the expression $a_{5}=\sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5}}}}}$, which can be written as $\sqrt[32]{5^{16} \cdot 5^{8} \cdot 5^{4} \cdot 5^{2} \cdot 5}$. Simplify the powers of 5 under the root $\sqrt[32]{5^{31}}$ and express it as a power of 5 5 .