In rectangle $P Q R S, P Q=12$ and $P R=13$. The area of rectangle $P Q R S$ is
(A) 30
(B) 60
(C) 36
(D) 78
(E) 72

![](https://cdn.mathpix.com/cropped/2024_04_20_6027bc27089ed4fc493cg-060.jpg?height=271&width=458&top_left_y=1255&top_left_x=1278)
Triangle $P Q R$ is a right-angled triangle since $\angle P Q R=90^{\circ}$ (because $P Q R S$ is a rectangle). In $\triangle P Q R$, the Pythagorean Theorem gives,

$$
\begin{aligned}
P R^{2} & =P Q^{2}+Q R^{2} \\
13^{2} & =12^{2}+Q R^{2} \\
169 & =144+Q R^{2} \\
169-144 & =Q R^{2} \\
Q R^{2} & =25
\end{aligned}
$$

So $Q R=5$ since $Q R>0$. The area of $P Q R S$ is thus $12 \times 5=60$.

ANSwER: (B)