Example: 58 girls and 25 boys stand in a circle, with at least two boys standing between any two girls. How many different arrangements are there (arrangements that coincide by rotating the circle are considered the same)?
Let $G, B$ represent a girl and a boy respectively. First, select 16 boys from 25 boys to form 8 groups of “$BGB$” structure with 8 girls; then consider the remaining 9 boys and the 8 groups of “$BGB$” as 17 elements for a circular arrangement.

First, the number of ways to choose 16 boys from 25 boys is $C_{25}^{16}$. Second, the number of circular arrangements of the 17 elements is $A_{16}^{16}$. Third, the number of arrangements of the 16 boys in the 8 groups on 16 positions is $A_{16}^{16}$.
Therefore, the total number of arrangements is $C_{25}^{16} \cdot A_{16}^{16} \cdot A_{16}^{16}=\frac{25!16!}{9!}$