144. Form the equation of a parabola with its vertex at the origin, symmetric about the $O x$ axis, and passing through the point $A(-3; -6)$.
Solution. From the condition, we conclude that the equation of the parabola should be sought in the form $y^{2}=-2 p x$. Since point $A$ belongs to the parabola, its coordinates satisfy this equation:

$$
36=-2 p(-3) ; 36=3 \cdot 2 p ; 2 p=12
$$

Thus, the equation of the parabola has the form $y^{2}=-12 x$.