1. Set $A=\{2,0,1,4\}$,
$$
B=\left\{k \mid k \in \mathbf{R}, k^{2}-2 \in A, k-2 \notin A\right\} \text {. }
$$

Then the product of all elements in set $B$ is $\qquad$ .
$-、 1.72$
From $k^{2}-2 \in A$, we get $k^{2}=4,2,3,6$, that is, $k= \pm 2, \pm \sqrt{2}, \pm \sqrt{3}, \pm \sqrt{6}$.
Since $k-2 \notin A$, thus, $k \neq 2$.
Therefore, $k=-2, \pm \sqrt{2}, \pm \sqrt{3}, \pm \sqrt{6}$.
Hence, the set $B=\{-2, \pm \sqrt{2}, \pm \sqrt{3}, \pm \sqrt{6}\}$.
Thus, the product of all elements in set $B$ is 72.