7. How many numbers less than 2011 are divisible by 117 and 2?
7. When solving this problem, one can reason as follows. First, list the numbers less than 2011 and divisible by 117 (2), then among them, select those that are divisible by 2 (117), and determine how many there are.

Since the number is divisible by both 2 and 117, it will also be divisible by their product $2 \times 117=234$. By dividing 2011 by 234, we can determine the number of such numbers (2011:234 $=8$ (remainder 128).

Answer: eight numbers.

## TWENTY-SECOND