Hull Street is nine miles long. The first two miles of Hull Street are in Richmond, and the last two miles of the street are in Midlothian. If Kathy starts driving along Hull Street from a random point in Richmond and stops on the street at a random point in Midlothian, what is the probability that Kathy drove less than six miles?

$\text{(A) }\frac{1}{16}\qquad\text{(B) }\frac{1}{9}\qquad\text{(C) }\frac{1}{8}\qquad\text{(D) }\frac{1}{6}\qquad\text{(E) }\frac{1}{4}$
1. **Restate the problem in terms of coordinates:**
   - Let \( p \) be the starting point in Richmond, which is in the interval \([0, 2]\).
   - Let \( q \) be the stopping point in Midlothian, which is in the interval \([7, 9]\).
   - We need to find the probability that the distance \( q - p \) is less than 6 miles.

2. **Set up the inequality:**
   - We need \( q - p < 6 \).
   - Rearrange to get \( q < p + 6 \).

3. **Define the sample space:**
   - The sample space for \( (p, q) \) is the Cartesian product of the intervals \([0, 2]\) and \([7, 9]\).
   - This forms a rectangle in the \( pq \)-plane with vertices at \((0, 7)\), \((2, 7)\), \((0, 9)\), and \((2, 9)\).

4. **Graph the inequality:**
   - The line \( q = p + 6 \) intersects the sample space.
   - For \( p = 0 \), \( q = 6 \) (which is outside the interval \([7, 9]\)).
   - For \( p = 2 \), \( q = 8 \) (which is within the interval \([7, 9]\)).

5. **Determine the region of interest:**
   - The inequality \( q < p + 6 \) will be satisfied in the region below the line \( q = p + 6 \) within the sample space.
   - The line \( q = p + 6 \) intersects the sample space at \((2, 8)\).

6. **Calculate the area of the region of interest:**
   - The region of interest is a right triangle with vertices at \((0, 7)\), \((2, 7)\), and \((2, 8)\).
   - The base of the triangle is 2 units (from \( p = 0 \) to \( p = 2 \)).
   - The height of the triangle is 1 unit (from \( q = 7 \) to \( q = 8 \)).
   - The area of the triangle is \(\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 2 \times 1 = 1\).

7. **Calculate the total area of the sample space:**
   - The total area of the sample space is the area of the rectangle, which is \(2 \times 2 = 4\).

8. **Calculate the probability:**
   - The probability is the ratio of the area of the region of interest to the total area of the sample space.
   - Thus, the probability is \(\frac{1}{4}\).

The final answer is \(\boxed{\frac{1}{4}}\).