34. In the book of records, a whole number expressing the number of meters of fabric sold was blotted out with ink. The total revenue could not be read either, but the end of this entry was visible: 7 r. 28 k. - and it is known that this amount does not exceed 500 r. The price of 1 m of fabric is 4 r. 36 k. Help the inspector restore this entry.
34. Since one factor ends with the digit 6 (436), and the product ends with the digit 8 (...728), the second factor must end with the digit 8 or 3. If it ends with the digit 8, then \(436 \cdot 8 = 3488\). We have

![](https://cdn.mathpix.com/cropped/2024_05_21_00604dc020e3721fc1f4g-125.jpg?height=245&width=177&top_left_y=1748&top_left_x=951)

Since \((8 + x)\) ends with the digit 2, then \(x = 4\). Therefore, \(6 \cdot y\) must end with the digit 4, so \(y = 4\) or \(y = 9\). If \(y = 4\), then the amount of sold material is 48 meters or 148 meters, but neither of these numbers satisfies the condition, as we get 208 rubles 28 kopecks and 1081 rubles 28 kopecks. The only remaining option is \(y = 9\). Then, 4 rubles 36 kopecks \(\cdot 98 = 427\) rubles 28 kopecks. If we assume that the second factor (the number of meters) ends with the digit 3, then a similar analysis shows that none of the possible numbers \(23, 123, 223, 73, 173\) satisfy the condition of the problem. Therefore, 98 meters were sold at 4 rubles 36 kopecks per meter for a total of 427 rubles 28 kopecks.