7. (10 points) Convert the product $0.243 \times 0.325233$ to a decimal, the digit at the 2013th position after the decimal point is $\qquad$


【Analysis】Since $0.2^{4} 3=\frac{243}{999}=\frac{9}{37}, 0.32^{523} 3=\frac{325233-3}{999990}=\frac{10841}{33333}$, converting the product
$0.243 \times 0.325233$ to a fraction, we get the result, and then solve it based on the repeating decimal.
【Solution】Solution: $0.2^{4} \dot{3}=\frac{243}{999}=\frac{9}{37}, 0.32_{2}^{523} \dot{3}=\frac{325233-3}{999990}=\frac{10841}{33333}$,
$$
\begin{array}{l}
0.243 \times 0.325233 \\
=\frac{9}{37} \times \frac{10841}{33333}, \\
=\frac{879}{11111}, \\
=0.0^{791}, \\
2013 \div 5=402 \cdots 3,
\end{array}
$$

Therefore, the 2013th digit is 9.
The answer is: 9.