Three, write 10 different
natural numbers, such that each of them is a divisor of the sum of these 10 numbers (explain the reason why the 10 natural numbers written meet the conditions of the problem).
Three natural numbers $1,2,3$, each of them is a divisor of the sum of these 3 numbers. If there are already $k(=3)$ natural numbers $a_{1}$, $a_{2}, \cdots, a_{i}$, each of which is a divisor of the sum (denoted as $p$) of these $k$ numbers, then $k+1$ natural numbers $a_{1}, a_{2}, \cdots, a_{k}, p$, each of them is also a divisor of the sum of these $k+1$ numbers.

Following this idea, the numbers $1,2,3$ can be extended to the following 10 natural numbers:
$$
1,2,3,6,12,24,48,96,192,384 \text {. }
$$

Each of them is a divisor of their sum.