# 2. Solution:

According to the condition, the center of the second blot is at a distance of no less than 2 cm from the edge of the sheet, i.e., inside a rectangle of 11 cm by 16 cm. Consider the event A "The blots intersect." For this to happen, the center of the second blot must fall within a circle of radius 4 cm with the same center as the first blot.

The probability of this event is $P(A)=\frac{S_{\mathrm{kp}}}{S_{\text {mp }}}=\frac{16 \pi}{11 \cdot 16}=\frac{\pi}{11}$.
Answer. $\frac{\pi}{11}$.