17. If the sum of six consecutive positive integers is 2013, then the largest number among these six consecutive positive integers is ( ).
(A) 335
(B) 338
(C) 340
(D) 345
(E) 350
17. B.

Let the largest number among these six numbers be $n$. Then $n+(n-1)+\cdots+(n-5)=2013$.
Solving this, we get $n=338$.