A rectangular picture of Pierre de Fermat, measuring $20 \mathrm{~cm}$ by $40 \mathrm{~cm}$, is positioned as shown on a rectangular poster measuring $50 \mathrm{~cm}$ by $100 \mathrm{~cm}$. What percentage of the area of the poster is covered by the picture?
(A) $24 \%$
(D) $25 \%$
(B) $16 \%$
(C) $20 \%$
(E) $40 \%$

![](https://cdn.mathpix.com/cropped/2024_04_20_ac36362783317e0251fdg-128.jpg?height=309&width=280&top_left_y=1447&top_left_x=1432)
The area of the entire poster is $(50 \mathrm{~cm})(100 \mathrm{~cm})=5000 \mathrm{~cm}^{2}$.

The area of the picture of Pierre de Fermat is $(20 \mathrm{~cm})(40 \mathrm{~cm})=800 \mathrm{~cm}^{2}$.

Thus, the percentage of the poster covered by the picture is

$\frac{800 \mathrm{~cm}^{2}}{5000 \mathrm{~cm}^{2}} \times 100 \%=\frac{8}{50} \times 100 \%=16 \%$

ANSWER: (B)