10. (10 points) As shown in the figure, the area of pentagon $A B C E F$ is 2014 square centimeters, $B C$ is perpendicular to $C E$ at point $C$, $E F$ is perpendicular to $C E$ at point $E$, quadrilateral $A B D F$ is a square, and $C D: E D=3: 2$. Therefore, the area of triangle $A C E$ is ( ) square centimeters.
A. 1325
B. 1400
C. 1475
D. 1500
【Solution】Solution: Draw the "chord diagram" of the square $ABCD$ as shown in the figure on the right, assuming the length of $CD$ is $3a$, and the length of $DE$ is $2a$,

Then $BG=3a, DG=2a$. According to the Pythagorean theorem, we have $BD^2=BG^2+DG^2=9a^2+4a^2=13a^2$, so the area of the square $ABDF$ is $13a^2$;

Since $CD=EF, BC=DE$, the areas of triangles $BCD$ and $DEF$ are equal, which is $3a^2$;
Also, because the area of the pentagon $ABCDE$ is 2014 square centimeters, we have $13a^2+6a^2=2014$, solving for $a^2=106$, the area of triangle $ACE$ is: $5a \times 5a \div \frac{1}{2}=\frac{25}{2}a^2$, which is $\frac{25}{2} \times 106=1325$.