1. If $y=\log _{2016}\left(x^{2}-a x+65\right)$ has a range of $R^{+}$, then the range of values for $a$ is $\qquad$
$$
-161, \Rightarrow x^{2}-a x+64>0$
$$
\therefore \Delta=a^{2}-4 \cdot 64<0, \quad \therefore-16<a<16 .
$$