1. For the quadratic equation in $x$, $2 a x^{2}-2 x-3 a-2=$ 0, one root is greater than 1, and the other root is less than 1. Then the value of $a$ is ( ).
(A) $a>0$ or $a0$
(D) $-4<a<0$
(Hint: Utilize the characteristic of the parabola $a f(1)<0$, solving this inequality will yield the result. Or let $y=x-1$, then find $a$ by the roots of the equation in $y$ having opposite signs. Answer: $(\mathrm{A})$ )