Nick is taking a $10$ question test where each answer is either true or false with equal probability. Nick forgot to study, so he guesses randomly on each of the $10$ problems. What is the probability that Nick answers exactly half of the questions correctly?
1. We need to determine the probability that Nick answers exactly half of the questions correctly on a 10-question true/false test. Each question has an equal probability of being answered correctly or incorrectly, which is \( \frac{1}{2} \).

2. Let \( X \) be the number of questions Nick answers correctly. Since each question is answered correctly with probability \( \frac{1}{2} \) and incorrectly with probability \( \frac{1}{2} \), \( X \) follows a binomial distribution with parameters \( n = 10 \) and \( p = \frac{1}{2} \). The probability mass function of a binomial random variable is given by:
   \[
   P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}
   \]
   where \( \binom{n}{k} \) is the binomial coefficient.

3. We are interested in the probability that Nick answers exactly 5 questions correctly, i.e., \( P(X = 5) \). Substituting \( n = 10 \), \( k = 5 \), and \( p = \frac{1}{2} \) into the binomial probability formula, we get:
   \[
   P(X = 5) = \binom{10}{5} \left( \frac{1}{2} \right)^5 \left( \frac{1}{2} \right)^5
   \]

4. Simplify the expression:
   \[
   P(X = 5) = \binom{10}{5} \left( \frac{1}{2} \right)^{10}
   \]

5. Calculate the binomial coefficient \( \binom{10}{5} \):
   \[
   \binom{10}{5} = \frac{10!}{5! \cdot 5!} = \frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1} = 252
   \]

6. Substitute \( \binom{10}{5} = 252 \) into the probability expression:
   \[
   P(X = 5) = 252 \left( \frac{1}{2} \right)^{10} = 252 \cdot \frac{1}{1024}
   \]

7. Simplify the final expression:
   \[
   P(X = 5) = \frac{252}{1024} = \frac{63}{256}
   \]

The final answer is \( \boxed{\frac{63}{256}} \).