9. Xiao Ming set off from home to school at exactly 7:00 AM at a speed of 52 meters per minute. When he arrived at school, the hour and minute hands on his watch were on either side of the number 7 and equidistant from it. Given that Xiao Ming walked for less than an hour, the distance from Xiao Ming's home to the school is $\qquad$ meters.

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The distance from Xiao Ming's home to the school is $\qquad$ meters.
【Analysis】At 7 o'clock, the distance between the hour hand and the minute hand is $210^{\circ}$ clockwise. When the hour hand and the minute hand are exactly on both sides of 7 and equidistant from it, the hour hand and the minute hand have traveled a total of $210^{\circ}$. Therefore, the time Xiao Ming spent walking is $210^{\circ} \div (6^{\circ} + 0.5^{\circ}) = \frac{420}{13}$ minutes. The distance from Xiao Ming's home to the school is $\frac{420}{13} \times 52 = 1680$ meters.