# Problem 1. (2 points)

Do there exist two natural numbers $x$ and $y$, having the same number of natural divisors, such that $x<y$, and the sum of all divisors of $x$ (including 1 and the number itself) is greater than the sum of natural divisors of $y$ (including 1 and the number itself)?
Answer: Yes

Solution:

For example, the numbers 38 and $39: 1+2+19+38=60>56=1+3+13+39$.