9. The figure below shows a glass in the shape of a right circular cylinder. A straight, thin straw (neglecting its thickness) of length 12 cm is placed inside the glass. When one end of the straw touches the bottom of the cylinder, the other end can protrude from the top edge of the cylinder by a minimum of 2 cm and a maximum of 4 cm. The volume of this glass is $\qquad$ cubic centimeters. (Take $\pi=314$) (Hint: In a right triangle, “leg 6, leg 8, hypotenuse 10”)


9、 226.08.
Solution: As shown in the figure, a straight, thin straw of length 12 cm is placed inside a glass, with one end protruding by a maximum of 4 cm, indicating that the height of the right circular cylinder $\mathrm{CB}=12-4=8$ (cm); the other end can protrude by a minimum of 2 cm, indicating that the diagonal of the rectangular cross-section of the right circular cylinder is $\mathrm{AC}=12-2=10$ (cm). From the common knowledge of right triangles, where the "leg 6, leg 8, hypotenuse 10," we know that the diameter of the base circle of the cylinder is 6 cm, and the radius is 3 cm. Therefore, the volume of this glass is (cubic centimeters).