9. A number $x$ is greater than 2022 . Which is the smallest of the following?
A $\frac{x}{2022}$
B $\frac{2022}{x-1}$
C $\frac{x+1}{2022}$
D $\frac{2022}{x}$
$\mathrm{E} \frac{2022}{x+1}$
9. E As $x$ is greater than 2022 , then $\frac{x}{2022}$ and $\frac{x+1}{2022}$ are greater than 1 , whereas $\frac{2022}{x}$ and $\frac{2022}{x+1}$ are less than 1 .
So we can eliminate A and C. As the remaining three fractions all have the same numerator and positive denominators, the smallest fraction is that with the largest denominator, namely $\frac{2022}{x+1}$.