5. (10 points) “Xiong Da” $\times$ “Xiong Er” $=$ “Xiong Xiong Di”. If the same Chinese character represents the same digit from 0 to 9, different characters represent different digits, and “Da” > “Er”, then the sum of all three-digit numbers represented by “Xiong Xiong Di” that satisfy the condition is $\qquad$
【Analysis】According to the problem, “Bear” $=1$, if “Big” $\times$ “Two” $9$, then “Big” + “Two” $9$, then “Big” + “Two” $<9$;

Enumerate: “Bear Two” $=10$, the younger brother is 0, “Bear Big” has no value to take. Because different Chinese characters represent different numbers; “Bear Two” $=12$, “Bear Big” can be $13,14,15,16$ (discard, repeated numbers);
“Bear Two” $=13$, “Bear Big” can be 14,15 (discard, repeated numbers);
“Bear Two” $=14$, “Bear Big” has no value to take.
Therefore, the sum of the three-digit numbers represented by “Bear Brothers” is: $12 \times(13+14+15)+13 \times 14=686$.
So the answer is: 686.