3. The sum of two numbers is 13,5927. If in the larger of these numbers, the decimal point is moved one digit to the left, the result is the smaller number. Find these numbers.
3. One of the sought numbers is 10 times larger than the other. Let the smaller number be $x$, then the larger one is $10 x$. We have $10 x + x = 13.5927$, which means $11 x = 13.5927$, from which $x = 13.5927 : 11 = 1.2357$. Therefore, the smaller number is 1.2357, and the larger one is 12.357.