1. Given that $a$, $b$, and $c$ are all positive integers, and $a b c=$ 2010. Then the minimum value of $a+b+c$ is ( ).
(A) 84
(B) 82
(C) 78
(D) 76
$$
\begin{array}{l}
\text { I.1.C. } \\
\text { From } 2010=2 \times 3 \times 5 \times 67=6 \times 5 \times 67 \\
=1 \times 30 \times 67=\cdots,
\end{array}
$$

we know that the minimum value of $a+b+c$ is 78.