36. $\log _{2 x+3} x^{2}<1$.

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36. $\log _{2 x+3} x^{2}<1$.
36. If $0<2 x+3$, i.e. $x>-\frac{3}{2}$.

The inequality is satisfied when $-\frac{3}{2}<x<1$, i.e. $2 x>-2$, then $x^{2}<2 x+3$, i.e. $-1<x<3$.

Answer: $-\frac{3}{2}<x<3, x \neq 0, x \neq-1$.