1. Let set $A=\left\{x^{2}, x+1,-3\right\}, B=\{x-5,2 x$ $\left.-1, x^{2}+1\right\}$, satisfying $A \cap B=\{-3\}$. Then the value of $x$ is ( ).
(A) 2
(B) 1
(C) 0
(D) -1
- 1.(D).

Substitute $x=2,1,0,-1$ into sets $A$ and $B$, considering the uniqueness of set elements and check if $A \cap B=\{-3\}$, we find $x=-1$.