B1. Five years ago, the ratio of the number of years of Clara, Jerca, and Tina was 9:10:13. In ten years, the ratio of their ages will be $14: 15: 18$. How old are Clara, Jerca, and Tina today?
B1. Let $x$ be Clare's age, $y$ Jere's age, and $z$ Tine's age. Five years ago, their ages were $x-5$, $y-5$, and $z-5$. For them, the following holds:

$$
x-5=9 t, \quad y-5=10 t, \quad z-5=13 t
$$

In ten years, their ages will be $x+10, y+10$, and $z+10$, and the following will hold:

$$
x+10=14 s, \quad y+10=15 s, \quad z+10=18 s
$$

Thus, $x=9 t+5=14 s-10$, from which it follows that $t=\frac{14 s-15}{9}$. Similarly, $y=10 t+5=15 s-10$, so $t=\frac{15 s-15}{10}$. If we compare, we get $\frac{14 s-15}{9}=\frac{15 s-15}{10}$ or $s=3$. Their ages are $x=14 \cdot 3-10=32, y=15 \cdot 3-10=35$ and $z=18 \cdot 3-10=44$.