6.8 times of shooting, hitting 3 times, among which there are exactly 2 consecutive hits. The number of such scenarios is ( .
(A) 15
(B) 30
(C) 48
(D) 60
6. (B).

Considering the two consecutive hits and the single hit as two elements to be inserted into 6 spaces created by the five positions, we find that the number of qualified scenarios is $P_{6}^{2}=6 \times 5=30$.