14. Person A departs from location A to location B, while persons B and C depart from location B to location A. After person A has traveled 50 kilometers, persons B and C start from B simultaneously. As a result, person A meets person B at location C, and person A meets person C at location D. It is known that person A's speed is three times that of person C, and person A's speed is 1.5 times that of person B. The distance between locations C and D is 12 kilometers. Therefore, the distance between A and B is $\qquad$ kilometers.
【Analysis】The speed ratio of A, B, and C is $3: 2: 1$. Excluding the 50 kilometers A travels first, when A and B meet, the distance ratio of the three is $3: 2: 1=12: 8: 4$. Suppose at this point A, B, and C have traveled 12 parts, 8 parts, and 4 parts, respectively. At this point, the distance between A and C is 4 parts. When they meet, the distance ratio between A and C is $3: 1$, and at this point, A has traveled 3 parts of the distance, from C to D, which is 12 kilometers. Thus, 1 part of the distance is 4 kilometers. The distance between A and B is $4 \times (12+8)+50=130$ kilometers.