8. Andrew divided some apples into six equal piles. Boris divided the same number of apples into five equal piles. Boris noticed that each of his piles contained two more apples than each of Andrew's piles. How many apples did Andrew have?
A 30
B 55
C 60
D 75
E 90
8. C Let the number of apples Andrew had be $6 n$. When Boris divided the same number of apples into five piles, each pile contained two more apples than each of Andrew's piles. Therefore $6 n=5(n+2)$ and hence $6 n=5 n+10$. This has solution $n=10$. Therefore the number of apples Andrew had was $6 \times 10=60$.