14. The archery target consists of 10 concentric circles, the difference in radius between two adjacent concentric circles is equal to the radius of the smallest inner circle. The smallest inner circle is called the 10-ring (as shown in the right figure), and the outermost ring is called the 1-ring. Question: What fraction of the 1-ring area is the 10-ring area?
14. 10 ring area is $\frac{1}{19}$ of 1 ring area.
14.【Solution】Let the radius of the small circle of 10 ring be 1, then the outer radius of 1 ring is 10, and the inner radius is 9.
$$
10 \text { ring area }=\pi, 1 \text { ring area }=\pi \times 10^{2}-\pi \times 9^{2}=19 \pi 。 \frac{\pi}{19 \pi}=\frac{1}{19} \text {, }
$$

Therefore, the 10 ring area is $\frac{1}{19}$ of the 1 ring area.