Example 2 The scoring rules for a certain football tournament are: 3 points for a win, 1 point for a draw, and 0 points for a loss. A team participated in 15 matches and accumulated 33 points. If the order of the matches is not considered, then the number of scenarios for the team's wins, draws, and losses is ( ).
(A) 15
(B) 11
(C) 5
(D) 3
Let the team win $x$ games, draw $y$ games, and lose $z$ games, where $x, y, z \in \mathbf{N}$, and $0 \leqslant x, y, z \leqslant 15$.
According to the problem, we set up the system of equations
$$
\left\{\begin{array}{l}
x+y+z=15, \\
3 x+y=33 .
\end{array}\right.
$$

From equation (2), we get
$$
x=11-\frac{y}{3} \text{. }
$$

Combining with equation (1), the solutions that satisfy the system of equations are
$$
\left\{\begin{array}{l}
x=11, \\
y=0, \\
z=4;
\end{array} \left\{\begin{array}{l}
x=10, \\
y=3, \\
z=2;
\end{array} \left\{\begin{array}{l}
x=9, \\
y=6, \\
z=0.
\end{array}\right.\right.\right.
$$

Therefore, there are 3 scenarios for the team's wins, draws, and losses. Hence, the answer is D.