363. The velocity of a material point is given by the formula $v=\left(4 t^{3}-2 t+1\right)$ m/s. Find the distance traveled by the point in the first 4 s from the start of the motion.
Solution. According to formula (1), we have

$$
s=\int_{0}^{4}\left(4 t^{3}-2 t+1\right) d t=\left.\left(t^{4}-t^{2}+t\right)\right|_{0} ^{4}=256-16+4=244(\text { m })
$$

Thus, in 4 s, the point has traveled 244 m.