G2.4 Given that $\cos 16^{\circ}=\sin 14^{\circ}+\sin d^{\circ}$ and $0<d<90$, find the value of $d$.
$\begin{array}{l}\sin d^{\circ}=\cos 16^{\circ}-\sin 14^{\circ} \\ \sin d^{\circ}=\sin 74^{\circ}-\sin 14^{\circ} \\ \sin d^{\circ}=2 \cos 88^{\circ} \sin 30^{\circ} \\ \sin d^{\circ}=\cos 44^{\circ}=\sin 46^{\circ} \\ d=46\end{array}$