25. Arrange the numbers $0,0,1,1,2,2,4,4$ in a row (0 can be placed first), so that no four consecutive numbers form 2014. There are $\qquad$ ways.
【Analysis】There are $C_{8}^{2} \times C_{6}^{2} \times C_{4}^{2} \times C_{2}^{2}=2520$ ways to arrange.
If 2014 appears, then 2014 has 5 possible positions.
The remaining digits can be arranged arbitrarily, resulting in $5 \times P_{4}^{4}=120$ ways.
Among these, 20142014 is counted once in the first position and once in the fifth position, which is a repetition.
Therefore, there are 119 ways in which 2014 appears.
Thus, the number of arrangements that meet the requirements is $2520-119=2401$.