1. Given $y=f(x)+x^{3}$ is an even function, and $f(10)=10$. If the function $g(x)=f(x)+5$, then the value of $g(-10)$ is $\qquad$ .
1. 2015.

From the given, $f(-10)+(-10)^{3}=f(10)+10^{3}$, which means $f(-10)=f(10)+2000=2010$, thus, $g(-10)=f(-10)+5=2015$.