$14 \cdot 1$ As shown in the figure, when the two wheels rotate once, the two arrows point to two numbers. What is the probability that the sum of the two numbers pointed to by the arrows is even?
(A) $\frac{1}{6}$.
(B) $\frac{3}{7}$.
(C) $\frac{1}{2}$.
(D) $\frac{2}{3}$.
(E) $\frac{5}{7}$.
[Solution] Consider the parity of the sum of the numbers in the two wheels below:
\begin{tabular}{c|c|c}
\hline Numbers in wheel $B$ & Numbers in wheel $A$ & Number of even sums \\
\hline 6 & $3,4,5,8$ & 2 \\
7 & $3,4,5,8$ & 2 \\
9 & $3,4,5,8$ & 2 \\
\hline
\end{tabular}

The probability that the sum is even is
$$
\frac{2+2+2}{4+4+4}=\frac{1}{2} \text {. }
$$

Therefore, the answer is $(C)$.