Let's calculate (using logarithms) the area of a triangle whose sides are: $a=35.463 \mathrm{~m}, \quad b=45.963 \mathrm{~m}, \quad c=$ $67.349 \mathrm{~m}$. Furthermore, what is the length of one side of a square whose area is equal to the area of the triangle?

(The area of the triangle $t=\sqrt{s(s-a)(s-b)(s-c)}$, where $s=\frac{1}{2}(a+b+c)$.)
The area of the triangle $t=761.1 \mathrm{~m}^{2}$, so the side of the square

$$
x=\sqrt{t}=27.58 \mathrm{~m} .
$$

Number of solutions: 17.