4. Solve the equation $6(x-1)(x+2)-4(x-3)(x+4)=2(x-5)(x-6)$.
4. $6\left(x^{2}+2 x-x-2\right)-4\left(x^{2}+4 x-3 x-12\right)=2\left(x^{2}-6 x-5 x+30\right) \quad 1$ BOD

$6\left(x^{2}+x-2\right)-4\left(x^{2}+x-12\right)=2\left(x^{2}-11 x+30\right) \quad 1$ BOD

$6 x^{2}+6 x-12-4 x^{2}-4 x+48=2 x^{2}-22 x+60 \quad$ 1 BOD

$6 x^{2}-4 x^{2}-2 x^{2}+6 x-4 x+22 x=60-48+12 \quad 1$ BOD

$24 x=24 \quad 1$ BOD

$x=1 \quad 1$ BOD

TOTAL 6 POINTS