The fraction $\frac {5x - 11}{2x^2 + x - 6}$ was obtained by adding the two fractions $\frac {A}{x + 2}$ and 
$\frac {B}{2x - 3}$. The values of $A$ and $B$ must be, respectively: 
$\textbf{(A)}\ 5x,-11\qquad\textbf{(B)}\ -11,5x\qquad\textbf{(C)}\ -1,3\qquad\textbf{(D)}\ 3,-1\qquad\textbf{(E)}\ 5,-11$
This is essentially asking for the partial fraction decomposition of \[\frac{5x-11}{2x^2 + x - 6}\]
Looking at $A$ and $B$, we can write
\[A(2x-3) + B(x+2) = 5x-11\].
Substituting $x= -2$, we get
\[A(-4-3) + B(0) = -21 \Rrightarrow A = 3\]
Substituting $x = \frac{3}{2}$, we get
\[A(0) + B(\frac{7}{2}) = \frac{15}{2} - \frac{22}{2} \Rrightarrow B = -1\]
Thus, our answer is $\boxed{D}$
~JustinLee2017