5. Arrange the 5 numbers $2,0,1,9,2019$ in any order in a row, to form an 8-digit number (the first digit cannot be 0), then the number of different 8-digit numbers that can be produced is $\qquad$ .
Answer: 95.
Solution: It is easy to know that all non-zero-leading permutations of $2,0,1,9,2019$ total $4 \times 4!=96$. Among them, except for the permutations $(2,0,1,9,2019)$ and $(2019,2,0,1,9)$ which correspond to the same number 20192019, the rest of the numbers are distinct. Therefore, the number of 8-digit numbers that meet the condition is $96-1=95$.