1. The range of the function $y=\sin x\left(\frac{\pi}{6} \leqslant x \leqslant \frac{2 \pi}{3}\right)$ is
1. $\left[\frac{1}{2}, 1\right]$. According to the graph of $y=\sin x$, the range can be obtained as $\left[\frac{1}{2}, 1\right]$.