A man has $2.73 in pennies, nickels, dimes, quarters and half dollars. If he has an equal number of coins of each kind, then the total number of coins he has is 
$\text{(A)}\ 3 \qquad  \text{(B)}\ 5 \qquad  \text{(C)}\ 9 \qquad  \text{(D)}\ 10 \qquad  \text{(E)}\ 15$
Solution by e_power_pi_times_i
Denote the number of pennies, nickels, dimes, quarters, and half-dollars by $x$. Then $x+5x+10x+25x+50x = 273$, and $x = 3$. The total amount of coins is $5x$, which is $\textbf{\text{(E)}}\ 15$.