8 Given three points $A, B, C$ in a plane satisfying $|\overrightarrow{A B}|=3,|\overrightarrow{B C}|=4,|\overrightarrow{C A}|=$ 5, then $\overrightarrow{A B} \cdot \overrightarrow{B C}+\overrightarrow{B C} \cdot \overrightarrow{C A}+\overrightarrow{C A} \cdot \overrightarrow{A B}$ is $\qquad$.
(8) -25 Hint: From the condition, we know $\overrightarrow{A B} \perp \overrightarrow{B C}$, so
$$
\overrightarrow{A B} \cdot \overrightarrow{B C}+\overrightarrow{B C} \cdot \overrightarrow{C A}+\overrightarrow{C A} \cdot \overrightarrow{A B}=\overrightarrow{C A} \cdot(\overrightarrow{A B}+\overrightarrow{B C})=-\overrightarrow{C A}^{2}=-25 \text {. }
$$