A2. Rectangle $A B C D$ is divided into five equal rectangles. The perimeter of each of these rectangles is 20.

What is the area of rectangle $A B C D$?
A) 72
B) 112
C) 120
D) 140
E) 150

![](https://cdn.mathpix.com/cropped/2024_04_17_8b40d2c2e9518068878ag-1.jpg?height=288&width=334&top_left_y=1692&top_left_x=1518)
A2. C) 120 Twice the length of a rectangle is equal to three times its width. The ratio of length : width is therefore $3: 2$. With a perimeter of 20, the length and width must be equal to 6 and 4. The area of a rectangle is then $6 \times 4=24$ and the area of rectangle $A B C D$ is five times as large, so $5 \times 24=120$.