1. Which two-digit numbers are more numerous: those with both digits of the same parity, or those with digits of different parity?

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# Answer: There are an equal number of numbers.

Solution. All two-digit numbers are divided into nine tens. In each ten, with the same tens digit, there are five numbers of each type. Therefore, in the end, there are an equal number of these types of numbers. Criteria. Only answer: 0 points.