2. Let $a>0>b>c, a+b+c=1, M=$ $\frac{b+c}{a}, N=\frac{a+c}{b}, P=\frac{a+b}{c}$. Then the size relationship between $M, N, P$ is ( ).
(A) $M>N>P$
(B) $N>P>M$
(C) $P>M>N$
(D) $M>P>N$
2. (D).

Since $M=\frac{1}{a}-1, N=\frac{1}{b}-1$,
$$
P=\frac{1}{c}-1, N-P=\frac{c-b}{b c}<0, M>P$. Therefore, $M>P>N$.