The degree measures of the angles of a convex 18-sided polygon form an increasing arithmetic sequence with integer values. Find the degree measure of the smallest angle.
1. **Identify the sum of the interior angles of the polygon:**
   For an \( n \)-sided polygon, the sum of the interior angles is given by:
   \[
   \text{Sum of interior angles} = (n-2) \times 180^\circ
   \]
   For an 18-sided polygon:
   \[
   \text{Sum of interior angles} = (18-2) \times 180^\circ = 16 \times 180^\circ = 2880^\circ
   \]

2. **Set up the arithmetic sequence:**
   Let the angles be \( a, a+d, a+2d, \ldots, a+17d \), where \( a \) is the smallest angle and \( d \) is the common difference.

3. **Sum of the angles in the arithmetic sequence:**
   The sum of the angles in an arithmetic sequence is given by:
   \[
   \text{Sum} = \frac{n}{2} \times (\text{first term} + \text{last term})
   \]
   For our sequence:
   \[
   \text{Sum} = \frac{18}{2} \times (a + (a + 17d)) = 9 \times (2a + 17d) = 18a + 153d
   \]
   Given that the sum of the angles is 2880 degrees:
   \[
   18a + 153d = 2880
   \]

4. **Determine the middle angle:**
   Since the sequence has 18 terms, the middle angles are the 9th and 10th terms. The 9th term is \( a + 8d \) and the 10th term is \( a + 9d \). The average of these two terms is:
   \[
   \frac{(a + 8d) + (a + 9d)}{2} = \frac{2a + 17d}{2} = a + \frac{17d}{2}
   \]
   Given that the average of the middle angles is the average of all angles:
   \[
   \frac{2880}{18} = 160^\circ
   \]
   Therefore:
   \[
   a + \frac{17d}{2} = 160
   \]

5. **Set up the system of equations:**
   We now have two equations:
   \[
   18a + 153d = 2880
   \]
   \[
   a + \frac{17d}{2} = 160
   \]

6. **Solve the system of equations:**
   First, solve the second equation for \( a \):
   \[
   a + \frac{17d}{2} = 160
   \]
   Multiply through by 2 to clear the fraction:
   \[
   2a + 17d = 320
   \]
   Now we have:
   \[
   2a + 17d = 320
   \]
   \[
   18a + 153d = 2880
   \]

7. **Eliminate \( a \) by solving the system:**
   Multiply the first equation by 9:
   \[
   9(2a + 17d) = 9 \times 320
   \]
   \[
   18a + 153d = 2880
   \]
   Both equations are identical, so we can solve for \( a \) and \( d \):
   \[
   2a + 17d = 320
   \]
   \[
   a = 160 - \frac{17d}{2}
   \]

8. **Substitute \( a \) back into the first equation:**
   \[
   18(160 - \frac{17d}{2}) + 153d = 2880
   \]
   Simplify:
   \[
   2880 - 153d + 153d = 2880
   \]
   This confirms that the equations are consistent.

9. **Find the smallest angle:**
   The smallest angle is \( a \):
   \[
   a = 160 - \frac{17d}{2}
   \]
   Since \( a \) must be an integer, \( \frac{17d}{2} \) must be an integer. Let \( d = 2k \) for some integer \( k \):
   \[
   a = 160 - 17k
   \]
   To ensure \( a \) is positive and an integer, \( k \) must be such that \( 160 - 17k \) is an integer and positive.

10. **Determine the value of \( k \):**
    Since \( a \) must be positive:
    \[
    160 - 17k > 0
    \]
    \[
    k < \frac{160}{17} \approx 9.41
    \]
    Therefore, \( k \) can be any integer from 0 to 9. The smallest angle occurs when \( k = 1 \):
    \[
    a = 160 - 17 \times 1 = 143
    \]

The final answer is \( \boxed{143} \).