Task 1. On the board, in a row, the digits are written as follows:

$$
\begin{array}{lllllllll}
1 & 1 & 1 & 2 & 2 & 2 & 5 & 5 & 5 .
\end{array}
$$

Between them, several plus signs can be placed so that the resulting sum ends in the digit one:

$$
1+1+12+2+25+5+5=51
$$

How can several plus signs be placed so that the resulting sum ends in zero? An example is sufficient.
Answer: $111+22+2+555=690$.

Note. There are many other correct examples.

## Criteria

## 4 p. A correct example is provided.

(Examples with only one plus sign are also accepted.)