Problem 3. The length of the side of one square is three times the length of the side of another square. Their perimeters differ by $32 \mathrm{~cm}$. Determine the lengths of the sides of the two squares.
Solution. Let $L_1$ be the perimeter of the first square, and $L$ be the perimeter of the second square. If $L_{1}=4 a$, then $L=4 \cdot 3 a$. Since $32=L-L_{1}=12 a-4 a=8 a$, it follows that the length of the side of the first square is $4 \mathrm{~cm}$, and the side of the second square is $12 \mathrm{~cm}$.

Problem 4 If 23 is subtracted from a given number, and the resulting difference is divided by 11, and the quotient obtained is multiplied by 5, the result will be a number that is 5 greater than the smallest two-digit number. What is that number?