What is the maximum number of rectangular wooden blocks with dimensions $20 \mathrm{~cm} \times 30 \mathrm{~cm} \times 40 \mathrm{~cm}$ that could fit into a rectangular box with inner dimensions $40 \mathrm{~cm} \times 60 \mathrm{~cm} \times 80 \mathrm{~cm}$ ?
(A) 2
(B) 4
(C) 10
(D) 8
(E) 6

![](https://cdn.mathpix.com/cropped/2024_04_20_46ead6524a8d61e21c51g-081.jpg?height=314&width=507&top_left_y=1453&top_left_x=1205)
The volume of the box of $40 \times 60 \times 80=192000 \mathrm{~cm}^{3}$. The volume of each of the blocks is $20 \times 30 \times 40=24000 \mathrm{~cm}^{3}$. Therefore, the maximum number of blocks that can fit inside the box is $\frac{192000 \mathrm{~cm}^{3}}{24000 \mathrm{~cm}^{3}}=8.8$ blocks can indeed be fit inside this box. Can you see how?

Answer: (D)