## Task 2 - 090612

During the holidays, Klaus was in the countryside. From his observations, the following joke problem emerged:

$$
1 \frac{1}{2} \text { chickens lay in } 1 \frac{1}{2} \text { days } 1 \frac{1}{2} \text { eggs }
$$

Determine the total number of eggs that 7 chickens would lay in 6 days at the same laying rate!
If $1 \frac{1}{2}$ chickens lay $1 \frac{1}{2}$ eggs in $1 \frac{1}{2}$ days, then in 6 days they lay four times as much $\left(1 \frac{1}{2} \cdot 4=6\right)$, i.e., 6 eggs.

7 chickens are $\frac{14}{3}$ times $1 \frac{1}{2}$ chickens, since $\frac{14}{3} \cdot 1 \frac{1}{2}=7$. Therefore, the 7 chickens lay $\frac{14}{3} \cdot 6=28$ eggs in 6 days.