7. A rectangular sheet of iron was divided into 2 parts such that the first part was 4 times larger than the second. What is the area of the entire sheet if the first part is $2208 \mathrm{~cm}^{2}$ larger than the second?
7. Let's make a brief record of the problem:

![](https://cdn.mathpix.com/cropped/2024_05_21_e53d4ff4f2278a1c0d12g-051.jpg?height=483&width=1200&top_left_y=1523&top_left_x=408)

1) $2208: 3=736\left(\mathrm{~cm}^{2}\right)$ - corresponds to one part;
2) $736 \times 4=2944\left(\mathrm{~cm}^{2}\right)$ - area of the first part of the sheet;
3) $2944+736=3680\left(\mathrm{~cm}^{2}\right)$ - total area.

Instead of the second and third steps, we can immediately get the answer based on the brief record:

$$
736 \times 5=3680\left(\mathrm{~cm}^{2}\right)
$$

Answer: the area of the rectangle is $3680 \mathrm{~cm}^{2}$.

## SEVENTH