5. Find all integer pairs $(x, y)$ such that $x^{3}=y^{3}+2 y^{2}+1$.

Translate the above text into English, please keep the original text's line breaks and format, and output the translation result directly.
5. Notice that, when $y>0$ or $y<-3$, we always have $y^{3}<y^{3}+2 y^{2}+1<(y+$ $1)^{3}$, at this time $y^{3}+2 y^{2}+1$ is not a cube number, so the original equation has no solution. Therefore, we only need to consider the cases $y=$ $-3,-2,-1,0$. Substituting them respectively, we get the integer solutions of the equation as $(x, y)=(-2$, $-3),(1,-2)$ or $(1,0)$.