$\diamondsuit$ and $\Delta$ are [whole numbers](https://artofproblemsolving.com/wiki/index.php/Whole_number) and $\diamondsuit \times \Delta =36$.  The largest possible value of $\diamondsuit + \Delta$ is 
$\text{(A)}\ 12 \qquad \text{(B)}\ 13 \qquad \text{(C)}\ 15 \qquad \text{(D)}\ 20\ \qquad \text{(E)}\ 37$
Since it doesn't take too long, we can just make a table with all the possible values of the [sum](https://artofproblemsolving.com/wiki/index.php/Sum): 
\[\begin{array}{|c|c|c|} \multicolumn{3}{}{} \\ \hline \diamondsuit & \Delta & \diamondsuit + \Delta \\ \hline 36 & 1 & 37 \\ \hline 18 & 2 & 20 \\ \hline 12 & 3 & 15 \\ \hline 9 & 4 & 13 \\ \hline 6 & 6 & 12 \\ \hline \end{array}\]
Clearly $37\rightarrow \boxed{\text{E}}$ is the largest.