2. A. If the graph of the direct proportion function $y=a x(a \neq 0)$ and the graph of the inverse proportion function $y=\frac{b}{x}(b \neq 0)$ intersect at two points, and one of the intersection points has coordinates $(-3,-2)$, then the coordinates of the other intersection point are ( ).
(A) $(2,3)$
(B) $(3,-2)$
(C) $(-2,3)$
(D) $(3,2)$
2. A. D.

From $-2=a(-3),(-3)(-2)=b$, we get $a=\frac{2}{3}, b=6$.

Solving the system of equations $\left\{\begin{array}{l}y=\frac{2}{3} x, \\ y=\frac{6}{x},\end{array}\right.$ we get
$$
\left\{\begin{array} { l } 
{ x = - 3 , } \\
{ y = - 2 ; }
\end{array} \quad \left\{\begin{array}{l}
x=3 \\
y=2
\end{array}\right.\right.
$$

Therefore, the coordinates of the other intersection point are $(3,2)$.