8.2. Replace the two asterisks with two different numbers so that the identity equality is obtained:

$$
(3 x-*)(2 x+5)-x=6 x^{2}+2(5 x-*)
$$
Answer: 2 and 5. Solution. Let $A$ and $B$ be the numbers corresponding to the first and second asterisks. Then, multiplying the brackets according to algebraic rules and equating the coefficients of $x$ and the constant terms, we get: $14-2 A=10, -5 A=-2 B$. From this, $A=2, B=5$.