Let's simplify the following fraction:

$$
\frac{6 x^{3}+13 x^{2}+15 x-25}{2 x^{3}+4 x^{2}+4 x-10}
$$
$$
\begin{gathered}
\frac{6 x^{3}+13 x^{2}+15 x-25}{2 x^{3}+4 x^{2}+4 x-10}=\frac{6 x\left(x^{2}+3 x+5\right)-5 x^{2}-15 x-25}{2 x\left(x^{2}+3 x+5\right)-2 x^{2}-6 x-10}= \\
=\frac{6 x\left(x^{2}+3 x+5\right)-5\left(x^{2}+3 x+5\right)}{2 x\left(x^{2}+3 x+5\right)-2\left(x^{2}+3 x+5\right)}=\frac{6 x-5}{2 x-2}
\end{gathered}
$$

(Géza Klein, Budapest, VI. district, real.)

Number of solutions: 33.