3. (8 points) Jia, Yi, and Bing are sawing wooden sticks of the same thickness. They are given 8 meters, 10 meters, and 6 meters of wooden sticks respectively, and are required to saw them into 2-meter segments. After the work is done, Jia, Yi, and Bing have sawn 24, 25, and 27 segments respectively. The fastest sawing speed is $\qquad$ times faster than the slowest.
【Solution】Solution: For A: $8 \div 2=4$ (segments)
$$
\begin{array}{l}
4-1=3 \text { (times) } \\
3 \times(24 \div 4) \\
=3 \times 6 \\
=18 \text { (times) } \\
\text { For B: } 10 \div 2=5 \text { (segments) } \\
5-1=4 \text { (times) } \\
4 \times(25 \div 5) \\
=4 \times 5 \\
=20 \text { (times) } \\
\end{array}
$$

For C: $6 \div 2=3$ (segments)
$$
\begin{array}{l}
3-1=2 \text { (times) } \\
2 \times(27 \div 3) \\
=2 \times 9 \\
=18 \text { (times) } \\
18=18<20 \\
20-18=2 \text { (times) }
\end{array}
$$

Answer: The fastest sawing speed is 2 times more than the slowest. Therefore, the answer is: 2.