## problem statement

Calculate the limit of the function:

$\lim _{x \rightarrow 0}\left(\frac{11 x+8}{12 x+1}\right)^{\cos ^{2} x}$
## Solution

$\lim _{x \rightarrow 0}\left(\frac{11 x+8}{12 x+1}\right)^{\cos ^{2} x}=\left(\frac{11 \cdot 0+8}{12 \cdot 0+1}\right)^{\cos ^{2} 0}=$

$=(8)^{\left(1^{2}\right)}=8^{1}=8$

## Problem Kuznetsov Limits 18-19