1. Choose 3 numbers from $0,1,2,3,4,5,6,7,8,9$ such that their sum is an even number not less than 10, then the number of different ways to choose is $\qquad$.
(1998 National High School League Question)
Exercise A
1.3 The sum of 3 numbers is even, there are only 2 possibilities: when all 3 numbers are even, there are $C_{5}^{3}$ ways to choose; when 1 of the 3 numbers is even and the other 2 are odd, there are $C_{5}^{1} C_{5}^{2}$ ways to choose. The sum of the 3 numbers taken out is an even number less than 10 in the following 9 cases: $(0,1,3),(0,1,5),(0,1,7),(0,2,4),(0,2,6),(0,3,5),(1,2,3),(1,2,5),(1,3,4)$, so the number of different ways that meet the conditions is $C_{5}^{3}+$ $C_{5}^{1} C_{5}^{2}-9=51$.