## Task 1 - 090521

Six equally sized dice are stacked on a table as shown in the image. The number on the top face is 1.

Determine the sum of the numbers on the hidden faces of these dice!

Note that the sum of the numbers on opposite faces of each die is always 7.

![](https://cdn.mathpix.com/cropped/2024_06_06_b85a894aa8dbf722a7b3g-0046.jpg?height=329&width=97&top_left_y=378&top_left_x=1619)
When exactly 5 dice are rolled, two opposite faces of each die are hidden. The sum of their numbers is therefore $5 \cdot 7=35$.

For the top die, only the face opposite to the one with the number 1 is hidden. According to the problem, this face has the number 6.

Thus, the sum of the numbers on all hidden faces is $35+6=41$.