2. (10 points) Among all natural numbers that are multiples of 20, the sum of those not exceeding 3000 and are also multiples of 14 is $\qquad$
【Analysis】Among all multiples of 20 not exceeding 2014 and are multiples of 14, the smallest is 140, the largest is 2940, there are 21 in total, then solve using the "Gauss summation" method.

【Solution】Solution: $20=2 \times 2 \times 5$
$$
14=2 \times 7
$$
The least common multiple of 20 and 14 is: $2 \times 2 \times 5 \times 7=140$
$$
\begin{array}{l}
3000 \div 140 \approx 21.4 \\
140 \times 21=2940
\end{array}
$$

So, among all multiples of 20 not exceeding 3000 and are multiples of 14, the smallest is 140, the largest is 2940, there are 21 in total,
$$
\begin{aligned}
& (140+2940) \times 21 \div 2 \\
= & 3080 \times 21 \div 2 \\
= & 32340 .
\end{aligned}
$$

Answer: Among all natural numbers that are multiples of 20, not exceeding 3000 and are multiples of 14, the sum of these numbers is 32340. Therefore, the answer is: 32340.