1. Let set $A=\{-1,0,2\}$, set $B=\{-x \mid x \in A$, and $2-x \notin A\}$. Then $B=(\quad)$.
(A) $\{1\}$
(B) $\{-2\}$
(C) $\{-1,-2\}$
(D) $\{-1,0\}$
-,1. A.
Notice that, only when $x=-1$, $-1 \in A, 2-(-1) \notin A$. Therefore, $B=\{1\}$.