A6 The solution to the equation $\frac{5 y}{6}+\frac{11-3 y}{4}=\frac{2 y-5}{3}-\frac{1}{4}$ is:
(A) $y=\frac{41}{7}$
(B) $y=-\frac{56}{11}$
(C) $y=8$
(D) $y=-41$
(E) the equation has no solution

## II. PART
A6. In the equation, we eliminate the fractions by multiplying by 12. We get $10 y + 66 - 18 y = 16 y - 40 - 6$. We rearrange the equation to $-24 y = -112$ and calculate $y = 8$.

## Group B