Seven dwarfs stood around the perimeter of their garden, one in each corner, and stretched a rope around the entire garden. Snow White came out from Smudla and walked along the rope. First, she walked four meters to the east, where she met Prof. From there, she continued two meters to the north until she reached Rejpal. From Rejpal, she walked west and after two meters, she met Stydlín. She then continued three meters to the north, until she reached Štístko. She set off to the west and after four meters, she met Kejchal, from where she had three meters to the south to Dřímal. Finally, she followed the rope to the shortest path back to Smudla, thus completing her walk around the garden.

How many square meters does the entire garden have?

(M. Mach)

Hint. Draw the shape of the garden, preferably on graph paper.
Let's draw the entire garden on a square grid, where one square represents one square meter.

![](https://cdn.mathpix.com/cropped/2024_04_17_617ae705de5106651eccg-5.jpg?height=639&width=746&top_left_y=1488&top_left_x=655)

Now we can easily determine the area of the shape. First, we count all the whole squares, which are 21 in the marked area. We still need to add two triangles, which together form one more whole square. We have counted 22 squares, so the garden has an area of $22 \mathrm{~m}^{2}$.

Another solution. If we don't have squared paper, we can divide the garden drawing as shown in the following image; we will mark the common point of the auxiliary segments as $B$ and according to the task, we will add the sizes of the necessary sides (all in meters).

![](https://cdn.mathpix.com/cropped/2024_04_17_617ae705de5106651eccg-6.jpg?height=525&width=759&top_left_y=240&top_left_x=654)

From this, we can easily determine the areas of the individual parts:

- The rectangle "Stydlín-Štístko-Kejchal-Dřímal" has an area of $3 \cdot 4=12\left(\mathrm{~m}^{2}\right)$.
- The rectangle "Smudla-Prófa-Rejpal-B" has an area of $4 \cdot 2=8\left(\mathrm{~m}^{2}\right)$.
- The triangle "Šmudla-Dřímal-B" can be seen as half of a square with a side of $2 \mathrm{~m}$ divided by a diagonal; its area is therefore half of the original square, i.e., $(2 \cdot 2): 2=2\left(\mathrm{~m}^{2}\right)$.

The garden of the dwarfs has an area of $12+8+2=22\left(\mathrm{~m}^{2}\right)$.