When evaluated, the sum of the digits of the integer equal to $10^{2021}-2021$ is
(A) 18194
(B) 18176
(C) 18167
(D) 18153
(E) 18185
If $n$ is a positive integer, $10^{n}$ is equal to 1 followed by $n$ zeros, when evaluated.

For example, $10^{4}=10000$ and $10^{2021}$ is equal to $1 \underbrace{00 \ldots 0}_{20210 \text { s }}$.

The result of adding 1 to the positive integer consisting of only $n$ 9s is $10^{n}$.

For example, $1+9999=10000=10^{4}$ and $1+\underbrace{99 \ldots 9}_{20219_{\mathrm{s}}}=1 \underbrace{00 \ldots 0}_{20210 \mathrm{~s}}=10^{2021}$.

Let $S$ be the integer equal to $10^{2021}-2021$.

Since $10^{2021}=1+\underbrace{99 \ldots 9}_{20219 \mathrm{~s}}$, then $S=1+\underbrace{99 \ldots 9}_{20219 \mathrm{~s}}-2021=\underbrace{99 \ldots 9}_{20219 \mathrm{~s}}-2020=\underbrace{99 \ldots 9}_{20179 \mathrm{~s}} 7979$.

The sum of the digits of the integer equal to $10^{2021}-2021$ is $2019 \times 9+2 \times 7=18185$.

ANSWER: (E)