8,9

Find the equation of the plane passing through the point $M(-2 ; 0 ; 3)$ and parallel to the plane $2 x-y-3 z+5=0$.
The vector perpendicular to the desired plane has coordinates (2; -1; -3). Since the plane passes through the point $M(-2; 0; 3)$, its equation is

$$
2(x+2)-y-3(z-3)=0, \text { or } 2 x-y-3 z+13=0 \text {. }
$$

## Answer

$2 x-y-3 z+13=0$.