Evaluate
$$\frac{(2 + 2)^2}{2^2} \cdot \frac{(3 + 3 + 3 + 3)^3}{(3 + 3 + 3)^3} \cdot \frac{(6 + 6 + 6 + 6 + 6 + 6)^6}{(6 + 6 + 6 + 6)^6}$$
1. Start by simplifying each term in the given expression:
   \[
   \frac{(2 + 2)^2}{2^2} \cdot \frac{(3 + 3 + 3 + 3)^3}{(3 + 3 + 3)^3} \cdot \frac{(6 + 6 + 6 + 6 + 6 + 6)^6}{(6 + 6 + 6 + 6)^6}
   \]

2. Simplify the first fraction:
   \[
   \frac{(2 + 2)^2}{2^2} = \frac{4^2}{2^2} = \frac{16}{4} = 4
   \]

3. Simplify the second fraction:
   \[
   \frac{(3 + 3 + 3 + 3)^3}{(3 + 3 + 3)^3} = \frac{(4 \cdot 3)^3}{(3 \cdot 3)^3} = \frac{12^3}{9^3} = \left(\frac{12}{9}\right)^3 = \left(\frac{4}{3}\right)^3 = \frac{4^3}{3^3} = \frac{64}{27}
   \]

4. Simplify the third fraction:
   \[
   \frac{(6 + 6 + 6 + 6 + 6 + 6)^6}{(6 + 6 + 6 + 6)^6} = \frac{(6 \cdot 6)^6}{(4 \cdot 6)^6} = \frac{36^6}{24^6} = \left(\frac{36}{24}\right)^6 = \left(\frac{3}{2}\right)^6 = \frac{3^6}{2^6}
   \]

5. Combine all the simplified terms:
   \[
   4 \cdot \frac{64}{27} \cdot \frac{3^6}{2^6}
   \]

6. Simplify the combined expression:
   \[
   4 \cdot \frac{64}{27} \cdot \frac{3^6}{2^6} = 4 \cdot \frac{2^6}{3^3} \cdot \frac{3^6}{2^6}
   \]

7. Notice that \( \frac{2^6}{2^6} = 1 \) and \( \frac{3^6}{3^3} = 3^3 \):
   \[
   4 \cdot 1 \cdot 3^3 = 4 \cdot 27 = 108
   \]

The final answer is \( \boxed{108} \).