10.1. New smartwatches cost 2019 rubles. Namzil has $\left(500^{2}+4 \cdot 500+3\right) \cdot 498^{2}-500^{2}$. $503 \cdot 497$ rubles. Will he have enough money to buy the smartwatches?
Answer: No.

Solution: Let $a=500$. Then the original expression is $\left(a^{2}+4 \cdot a+3\right) \cdot(a-2)^{2}-a^{2}$. $(a+3) \cdot(a-3)=\left(a^{2}+4 \cdot a+3\right) \cdot\left(a^{2}-4 a+4\right)-a^{2} \cdot\left(a^{2}-9\right)=a^{4}-4 a^{3}+4 a^{2}+4 a^{3}-16 a^{2}+$ $16 a+3 a^{2}-12 a+12-a^{4}+9 a^{2}=4 a+12$. Substitute $a: 4 a+12=4 \cdot 500+12=2012<2019$. Therefore, Nazzhimil does not have enough money to buy the smartwatch.

Criteria: Only the answer - 0 points. The idea to substitute $a=500$, but the solution is not completed or has an error - 3 points. If the expression is simplified directly through arithmetic calculations and the solution is not completed or an error is made - 2 points. 7 points for a complete and correct solution (including, possibly, direct calculations).