What is the value of $\frac{3^{5}-3^{4}}{3^{3}}$ ?
By factoring $3^{3}$ out of the numerator, we have

$$
\frac{3^{5}-3^{4}}{3^{3}}=\frac{3^{3}\left(3^{2}-3\right)}{3^{3}}=3^{2}-3=9-3=6 .
$$

ANSWER: 6