The expression $\left(2 \times \frac{1}{3}\right) \times\left(3 \times \frac{1}{2}\right)$ equals
(A) $\frac{1}{6}$
(B) $\frac{1}{5}$
(C) 1
(D) 5
(E) 6
Re-arranging the order of the numbers being multiplied,

$$
\left(2 \times \frac{1}{3}\right) \times\left(3 \times \frac{1}{2}\right)=2 \times \frac{1}{2} \times 3 \times \frac{1}{3}=\left(2 \times \frac{1}{2}\right) \times\left(3 \times \frac{1}{3}\right)=1 \times 1=1
$$

ANSWer: $(\mathrm{C})$