## Task 2 - 330732

In a department store, $\frac{4}{5}$ of all employees were women. At the beginning of a month, 12.5% of these women were unmarried. Of the men employed in this department store, 18.75% were unmarried.

During the month, four couples got married, where both the man and the woman in each couple belonged to the aforementioned unmarried employees of the department store. There were no other changes.

Afterward, there were exactly 36 employees of the department store who were still unmarried.

How many employees did the department store have in total?
If the department store had a total of $x$ employees, then among them were $\frac{4}{5} x$ women and $\frac{1}{5} x$ men.

At the beginning of the month, $\frac{12.5}{100} \cdot \frac{4}{5} x=\frac{1}{10} x$ women and $\frac{18.75}{100} \cdot \frac{1}{5} x=\frac{3}{80} x$ men were unmarried, which together made $\frac{1}{10} x+\frac{3}{80} x=\frac{11}{80} x$ unmarried employees.

After the marriage of the 4 couples, there were still $\frac{11}{80} x-8$ employees who were unmarried. Therefore,

$$
\frac{11}{80} x-8=36 \quad \Rightarrow \quad x=320
$$

The department store had a total of 320 employees.