(3) For a positive integer $n$, if $n=p \cdot q\left(p \geqslant q, p, q \in \mathbf{N}^{*}\right)$, when $p-q$ is the smallest, we call $p \cdot q$ the "best factorization" of $n$, and define $f(n)=\frac{q}{p}$. For example, the factorizations of 12 are $12 \times 1, 6 \times 2, 4 \times 3$, where $4 \times 3$ is the best factorization of 12, so $f(12)=$ $\frac{3}{4}$. Regarding $f(n)$, there are the following four judgments:
(1) $f(4)=0$;
(2) $f(7)=\frac{1}{7}$;
(3) $f(24)=\frac{3}{8}$;
(4) $f(2012)=$ $\frac{4}{503}$.
Among them, the sequence numbers of all correct judgments are $\qquad$
(3) (2), (4) Hint: Since $4=2 \times 2, 7=7 \times 1, 24=6 \times 4, 2012=$ $503 \times 4$, then
$$
f(4)=1, f(7)=\frac{1}{7}, f(24)=\frac{2}{3}, f(2012)=\frac{4}{503} \text {. }
$$

Therefore, (1) and (3) are incorrect, (2) and (4) are correct.