145. Find two numbers if their sum is 432, and their greatest common divisor is 36.
145. Given $x=36 x_{1}$ and $y=36 y_{1}$, and $\left(x_{1}, y_{1}\right)=$ $=1$. We find $x_{1}+y_{1}=12$, hence $x_{1}=1, y_{1}=11 ; x_{2}=$ $=5, y_{2}=7$.

Answer. $x_{1}=36, y_{1}=396 ; x_{2}=180, y_{2}=252$.