10. The solution set of the inequality $\log _{a}\left(a-\frac{x^{2}}{2}\right)>\log _{a}(a-x)$ is $A$, and $A \cap \mathbf{Z}=\{1\}$, then the range of values for $a$ is $\qquad$
10. $a \in(1,+\infty)$ When $a \geqslant 2$, $a-\frac{x^{2}}{2}>a-x>0.0<x<2$; When $1<a<2$, $0<x<a$. Both of these are suitable; It is easy to verify that when $0<a<1$, $-\sqrt{2 a}<x<0$, which is not suitable.