736. Find $z^{\prime}$, if

$$
z=\frac{4 x^{2}}{\sqrt[5]{(2-x)^{3}}}
$$
Solution. $\ln z=\ln 4+2 \ln x-\frac{3}{5} \ln (2-x)$;

$$
\frac{z^{\prime}}{z}=\frac{2}{x}-\frac{3(2-x)^{\prime}}{5(2-x)}=\frac{2}{x}+\frac{3}{5(2-x)}=\frac{20-7 x}{5 x(2-x)}
$$

from this

$$
z^{\prime}=\frac{20-7 x}{5 x(2-x)} \cdot \frac{4 x^{2}}{\sqrt{(2-x)^{3}}}=\frac{4 x(20-7 x)}{5(2-x)^{5}(2-x)^{3}}
$$

Using the logarithmic derivative, find the derivatives of the following functions: