$36 \cdot 65$ On the table, there are 32 chess pieces, and two people, A and B, take turns to take some of the pieces. The rule is: A takes first, and each person must take at least 1 piece and at most 6 pieces each time, and the one who takes the last piece wins. To ensure victory, at the beginning, the number of pieces A should take first is 
(A) 6 pieces.
(B) 5 pieces.
(C) 4 pieces.
(D) 3 pieces.
(Chinese Jiangsu Province Suzhou City High School Mathematics Competition, 1990)
［Solution］If the first player leaves a situation with 7 pieces left for the opponent at the end, he can win;
By reverse reasoning, in the previous move, he should leave a situation with 14 pieces for the opponent (no matter how many pieces the opponent takes, he only needs to take the number of pieces that adds up to 7 with the opponent's);

Similarly, Player A only needs to leave situations of $7-14-21-28-35-\cdots$ for the opponent.
In the given scenario, after he takes 4 pieces, leaving 28 pieces for the opponent, he can win.
Therefore, the answer is $(C)$.