Let $a<b<c$ be the solutions of the equation $2016 x^{3}-4 x+\frac{3}{\sqrt{2016}}=0$. Determine the value of $-1 /\left(a b^{2} c\right)$.
Answer: 1354752. Let $y=\sqrt{2016} x$. The equation becomes $0=y^{3}-$ $4 y+3=(y-1)\left(y^{2}+y-3\right)$ whose solutions are 1 and $\frac{-1 \pm \sqrt{13}}{R \text{ Response2 }}$, so $b=1 / \sqrt{2016}, a=$ $-\frac{1+\sqrt{13}}{\text{ Response } 2 \sqrt{2016}}$ and $a=\frac{-1+\sqrt{13}}{\text{ Response2 } \sqrt{2016}}$. We then calculate that $-1 /\left(a b^{2} c\right)=2016^{2} / 3$.