2. Find the smallest natural number that ends in 56, is divisible by 56, and has the sum of its digits equal to 56.
2. Answer: 29899856.

The number has the form $100 A+56$, where $A$ is divisible by 7 and is even. The sum of the digits of $A$ is 45. It is sufficient to indicate the smallest number with these properties. Clearly, it must be at least six digits. The smallest even number with a digit sum of 45 is 199998, but it is not divisible by 7. The next larger such numbers start with the digit 2, and end with 8, as otherwise the sum of the digits would be less. Then the other digits are one more 8 and the rest are nines. The next two largest options are 289998 and 298998. It is easy to see that the first of these is not divisible by 7, but the second is, so we append 56 to it.