[ Problems on percentages and ratios ]

Two traders bought the same amount of goods at the same price in the city and each took the goods to their own village to sell. The first sold the goods at twice the purchase price. The second first increased the price by $60 \%$ and sold a quarter of the goods, then increased the price by another $40 \%$ and sold the remaining goods. Who made more revenue?
Let each merchant pay $x$ rubles for the goods. Then the profit of the first merchant is also $x$ rubles.

The second merchant first increased the price by $60\%$ and sold a quarter of the goods at this price. For this, he received $1 / 4 \cdot 1.6 x = 0.4 x$.

Then he increased the price by another $40\%$, that is, to $1.4 \cdot 1.6 x = 2.24 x$, and sold $3 / 4$ of the goods at this price, for which he received

$2.24 x \cdot 3 / 4 = 1.68 x$. In total, he sold the goods for

$0.4 x + 1.68 x = 2.08 x$ rubles, and the profit amounted to $1.08 x$ rubles.

## Answer

The second merchant.