3a

Given 100 numbers $a_{1}, a_{2}$,
$a_{1}-4 a_{2}+3 a_{3} \geq 0$,
$a_{2}-4 a_{3}+3 a_{4} \geq 0$,
$a_{3}-4 a_{4}+3 a_{5} \geq 0$,
$\ldots$,
$a_{99}-4 a_{100}+3 a_{1} \geq 0$,

Given 100 numbers $a_{1}, a_{2}, a_{3}, \ldots, a_{100}$, satisfying the conditions:
$a_{100}-4 a_{1}+3 a_{2} \geq 0$

It is known that $a_{1}=1$, determine $a_{2}, a_{3}, \ldots, a_{100}$.
See the solution of problem $\underline{78005}$.

## Answer

$a_{1}=a_{2}=\ldots=a_{100}=1$.