14. (15 points) Teacher Wang distributed 200 candies to three children, Jia, Yi, and Bing. Jia has more than twice as many candies as Yi, and Yi has more than three times as many candies as Bing. Therefore, Jia has at least $\qquad$ candies, and Bing has at most $\qquad$ candies.
【Solution】Solution: A is 2 times 3 = 6 times more than C, so the total is 6 + 3 + 1 = 10 times more than C plus 200 ÷ (2 × 3 + 3 + 1) = 20 (pieces),

C at most: 20 - 1 = 19 (pieces),
At this point, A and B have at least: 200 - 19 = 181 (pieces),
181 ÷ (2 + 1) = 60 (pieces) ... 1 (piece),
B at most 60 pieces,
A at least: 60 × 2 + 1 = 121 (pieces).
Therefore, the answers are: 121, 19.