The grid below contains six rows with six points in each row. Points that are adjacent either horizontally or vertically are a distance two apart. Find the area of the irregularly shaped ten sided figure shown.
[asy]
import graph; size(5cm); 
pen dps = linewidth(0.7) + fontsize(10); defaultpen(dps);
pen dotstyle = black;
draw((-2,5)--(-3,4), linewidth(1.6)); 
draw((-3,4)--(-2,1), linewidth(1.6)); 
draw((-2,1)--(1,0), linewidth(1.6)); 
draw((1,0)--(2,1), linewidth(1.6)); 
draw((2,1)--(1,3), linewidth(1.6)); 
draw((1,3)--(1,4), linewidth(1.6)); 
draw((1,4)--(2,5), linewidth(1.6)); 
draw((2,5)--(0,5), linewidth(1.6)); 
draw((-2,5)--(-1,4), linewidth(1.6)); 
draw((-1,4)--(0,5), linewidth(1.6)); 
dot((-3,5),linewidth(6pt) + dotstyle); 
dot((-2,5),linewidth(6pt) + dotstyle); 
dot((-1,5),linewidth(6pt) + dotstyle); 
dot((0,5),linewidth(6pt) + dotstyle); 
dot((1,5),linewidth(6pt) + dotstyle); 
dot((2,5),linewidth(6pt) + dotstyle); 
dot((2,4),linewidth(6pt) + dotstyle); 
dot((2,3),linewidth(6pt) + dotstyle); 
dot((2,2),linewidth(6pt) + dotstyle); 
dot((2,1),linewidth(6pt) + dotstyle); 
dot((2,0),linewidth(6pt) + dotstyle); 
dot((-3,4),linewidth(6pt) + dotstyle); 
dot((-3,3),linewidth(6pt) + dotstyle); 
dot((-3,2),linewidth(6pt) + dotstyle); 
dot((-3,1),linewidth(6pt) + dotstyle); 
dot((-3,0),linewidth(6pt) + dotstyle); 
dot((-2,0),linewidth(6pt) + dotstyle); 
dot((-2,1),linewidth(6pt) + dotstyle); 
dot((-2,2),linewidth(6pt) + dotstyle); 
dot((-2,3),linewidth(6pt) + dotstyle); 
dot((-2,4),linewidth(6pt) + dotstyle); 
dot((-1,4),linewidth(6pt) + dotstyle); 
dot((0,4),linewidth(6pt) + dotstyle); 
dot((1,4),linewidth(6pt) + dotstyle); 
dot((1,3),linewidth(6pt) + dotstyle); 
dot((0,3),linewidth(6pt) + dotstyle); 
dot((-1,3),linewidth(6pt) + dotstyle); 
dot((-1,2),linewidth(6pt) + dotstyle); 
dot((-1,1),linewidth(6pt) + dotstyle); 
dot((-1,0),linewidth(6pt) + dotstyle); 
dot((0,0),linewidth(6pt) + dotstyle); 
dot((1,0),linewidth(6pt) + dotstyle); 
dot((1,1),linewidth(6pt) + dotstyle); 
dot((1,2),linewidth(6pt) + dotstyle); 
dot((0,2),linewidth(6pt) + dotstyle); 
dot((0,1),linewidth(6pt) + dotstyle); [/asy]
To find the area of the irregularly shaped ten-sided figure, we will use Pick's Theorem. Pick's Theorem states that for a simple polygon whose vertices are points on a lattice, the area \(A\) of the polygon can be determined by the formula:

\[
A = I + \frac{B}{2} - 1
\]

where:
- \(I\) is the number of interior lattice points.
- \(B\) is the number of boundary lattice points.

1. **Identify the boundary points \(B\):**
   - Count the number of lattice points that lie on the boundary of the polygon.
   - From the diagram, we can see the boundary points are: 
     \[
     (-2,5), (-3,4), (-2,1), (1,0), (2,1), (1,3), (1,4), (2,5), (0,5), (-1,4)
     \]
   - There are 10 unique boundary points.

2. **Identify the interior points \(I\):**
   - Count the number of lattice points that lie strictly inside the polygon.
   - From the diagram, we can see the interior points are:
     \[
     (-2,4), (-2,3), (-2,2), (-1,3), (-1,2), (0,4), (0,3), (0,2), (1,2), (1,1), (1,0)
     \]
   - There are 12 interior points.

3. **Apply Pick's Theorem:**
   - Substitute \(I = 12\) and \(B = 10\) into Pick's formula:
     \[
     A = I + \frac{B}{2} - 1
     \]
     \[
     A = 12 + \frac{10}{2} - 1
     \]
     \[
     A = 12 + 5 - 1
     \]
     \[
     A = 16
     \]

The final answer is \(\boxed{16}\).