2. Divide the 100 natural numbers $1, 2, \cdots, 100$ into 50 groups, each containing two numbers. Now, substitute the two numbers in each group (denoted as $a$ and $b$) into $\frac{1}{2}(|a-b|+a+b)$ for calculation, and obtain 50 values. Find the maximum value of the sum of these 50 values.
Since the 100 numbers from $1 \sim 100$ are all different, in each pair of numbers, there must be a larger number. Therefore, the result of the calculation is the larger of the two numbers. Hence, the maximum sum of these 50 values is
$$
51+52+\cdots+100=3775
$$