330. In a triangle, from vertex $A$ there are a median, a bisector, and an altitude. Which angle is larger: between the median and the bisector or between the bisector and the altitude, if angle $A$ is given?
330. Let $A D$ be the altitude, $A L$ the angle bisector, and $A M$ the median. Extend the angle bisector to intersect the circumcircle of the triangle at point $A_{1}$. Since $M A_{1} \| A D$, then $\angle M A_{1} A=\angle L A D$. Answer: if $\angle A=90^{\circ}$, the angles are equal; if $\angle A \neq 90^{\circ}$, then it is the opposite.