17. (6 points) The shaded part in the figure consists of two circular arcs with centers at points $A$ and $C$, $A E=4 m$, point $B$ is the midpoint of $A E$, then the perimeter of the shaded part is $\qquad$ $m$, and the area is $\qquad$ $m^{2}$
(Circle ratio $\pi$ is taken as 3 ).
17. (6 points) The shaded part in the figure consists of two circular arcs with centers at points $A$ and $C$, respectively. $A E=4 m$, and point $B$ is the midpoint of $A E$. The perimeter of the shaded part is $13 m$, and the area is $\quad 7 m^{2}$ (take $\pi$ as 3).

【Solution】Solution: The perimeter of the shaded part: $4+3 \times 4 \times 2 \div 4+3 \times 2 \times 2 \div 4$,
$$
\begin{aligned}
=4 & +6+3, \\
= & 13 \text { (meters); }
\end{aligned}
$$

The area of the shaded part: $3 \times 4^{2} \div 4+3 \times 2^{2} \div 4-2 \times 4$,
$$
\begin{array}{l}
=12+3-8, \\
=7 \text { (square meters); }
\end{array}
$$

Answer: The perimeter of the shaded part is 13 meters, and the area is 7 square meters.
Therefore, the answers are: $13, 7$.