8. A person has a total of 23 coins of 5 cents, 10 cents, and 25 cents. Among them, the number of 10 cent coins is three more than the number of 5 cent coins. If the total value of the coins is 320 cents, then the number of 25 cent coins is ( ) more than the number of 5 cent coins.
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
8. C.

Let there be $x$ coins of 5 cents. Then there are $x+3$ coins of 10 cents, and $23-(x+3)-x$ coins of 25 cents.
According to the problem,
$$
\begin{array}{l}
5 x+10(x+3)+25(23-x-(x+3))=320 \\
\Rightarrow x=6 .
\end{array}
$$

Therefore, the required number is $23-(x+3)-x-x=2$.