10. In the figure, the area of each small equilateral triangle is 12 square centimeters, so the area of the large equilateral triangle is $\qquad$ square centimeters.
【Solution】Solution: As shown in the figure, by adding some small equilateral triangles on the right, $\triangle A B C$ is divided into three obtuse triangles of equal area, $\triangle A M B, \triangle B N C, \triangle A P C$, and a small equilateral triangle $\triangle P M N$. The area of $\triangle A M B$ is half of the parallelogram $A D B M$ it is in, which is $12 \times 4 \div 2=24$ square centimeters. Therefore, the area of $\triangle A B C$ is $3 \times 24+12=84$ square centimeters. The answer is 84.