Kalob's window measures $50 \mathrm{~cm} \times 80 \mathrm{~cm}$. Which of the following measurements would give an area that is exactly double the area of his window?
(A) $25 \mathrm{~cm} \times 160 \mathrm{~cm}$
(D) $100 \mathrm{~cm} \times 160 \mathrm{~cm}$
(B) $40 \mathrm{~cm} \times 100 \mathrm{~cm}$
(C) $50 \mathrm{~cm} \times 160 \mathrm{~cm}$
Measured in $\mathrm{cm}^{2}$, the area of Kalob's window is $50 \times 80$.

Measured in $\mathrm{cm}^{2}$, twice the area of Kalob's window is $50 \times 80 \times 2$ which is equal to $50 \times 160$. Thus, a window with dimensions $50 \mathrm{~cm} \times 160 \mathrm{~cm}$ is a window with area double the area of Kalob's window.

ANswer: (C)