3. $[x],[y],[z]$ respectively represent the greatest integers not exceeding $x, y, z$. If $[x]=5,\left[y^{\prime}\right]=-3,[z]=-1$, then the number of possible values for $[x-y-z]$ is ( ).
(A) 3
(B) 4
(C) 5
(D) 6
3. $\because 5 \leqslant x<6,-3 \leqslant y<-2,-1 \leqslant z<0$, there is $2<$ $-y \leqslant 3,0<-z \leqslant 1, \therefore 7<x-y-z<10$. Therefore, the values that $\{x-y$ $-z]$ can take are $7,8,9$. Hence, the answer is (A).