2. The sum of five consecutive integers is 2015 . What is the smallest of these integers?
A 401
B 403
C 405
D 407
E 409
2. A Let the five consecutive integers be $n-2, n-1, n, n+1$ and $n+2$. These have a sum of $5 n$. Hence $5 n=2015$ and therefore $n=403$. Therefore, the smallest integer is $403-2=401$