A round table has a diameter of $1.40 \, \text{m}$. For a party, the table is expanded by adding three planks, each $40 \, \text{cm}$ wide, as shown in the figure. If each person at the table should have a space of $60 \, \text{cm}$, how many guests can sit at the table?
![](https://cdn.mathpix.com/cropped/2024_05_01_bd5219fde2a4a59a7005g-2.jpg?height=506&width=724&top_left_y=618&top_left_x=996)
![](https://cdn.mathpix.com/cropped/2024_05_01_bd5219fde2a4a59a7005g-5.jpg?height=510&width=750&top_left_y=470&top_left_x=752)

The perimeter of the enlarged table is

$$
140 \times \pi + 40 \times 6 \simeq 140 \times 3.14 + 240 = 679.60 \mathrm{~cm}
$$

If each guest needs $60 \mathrm{~cm}$ to sit around the table and

$$
\frac{679.60}{60} \simeq 11.3
$$

Then, 11 guests can be accommodated.