6. The graph of the linear function $y=k(x-1)$ passes through the point $M(-1,-2)$. Then its intersection with the $y$-axis is ( ).
(A) $(0,-1)$
(B) $(1,0)$
(C) $(0,0)$
(D) $(0,1)$
6. A.

From the problem, we know that $k(-1-1)=-2$, which means $k=1$. Therefore, the function expression is $y=x-1$. Substituting $x=0$ into it, we get $y=-1$. Hence, the intersection point of its graph with the $y$-axis is $(0,-1)$.