The value of $2^{4}-2^{3}$ is
(A) $0^{1}$
(B) $2^{1}$
(C) $2^{2}$
(D) $2^{3}$
(E) $1^{1}$
We note that $2^{2}=2 \times 2=4,2^{3}=2^{2} \times 2=4 \times 2=8$, and $2^{4}=2^{2} \times 2^{2}=4 \times 4=16$. Therefore, $2^{4}-2^{3}=16-8=8=2^{3}$.