$33 \cdot 10$ number $2^{1984}$ has the following properties:
(A) It is a 597-digit number.
(B) It is divisible by 1984.
(C) The last digit is 4.
(D) The last digit is 6.
(E) It is less than $3^{1200}$.
(Chongqing, Sichuan Province, China Junior High School Mathematics Competition, 1984)
[Solution] From $\lg 2^{1984}=1984 \lg 2=1984 \cdot 0.3010=597.184$, we know that $2^{1984}$ is a 598-digit number, so (A) is not true.
Also, $1984=2^{6} \cdot 31$, but $2^{1984}$ does not have 31 as a factor, so (B) is not true. Notice that $2^{1984}=2^{496 \cdot 4}=16^{496}$, and its unit digit is 6.
Therefore, the correct choice is $(D)$.