9.2. Little kids were eating candies. Each one ate 11 candies less than all the others together, but still more than one candy. How many candies were eaten in total?
Answer: 33 candies.

Solution: Let $S$ be the total number of candies eaten by the children. If one of the children ate $a$ candies, then according to the condition, all the others ate $a+11$ candies, and thus all together ate $S=a+(a+11)=2a+11$ candies. This reasoning is valid for each child, so all the children ate the same number of candies: $a=(S-11)/2$ each.

Now let $N$ be the number of children. Then the condition can be written as $a=a \cdot (N-1)-11$, from which $11=a \cdot (N-2)$. The number 11 is prime, so one of the factors is 1, and the other is 11. But by the condition $a>1$, so $a=11, N-2=1$. Thus, $N=3$, and a total of $S=a \cdot N=33$ candies were eaten.