7. If $x=\sqrt{3}-2$, then
$$
\frac{-x^{2}-2 x}{x^{2}-1} \div\left(\frac{1}{|x|+1}+\frac{1}{|x|-1}\right)
$$

the value is
$$
\text { II.7. } \frac{\sqrt{3}}{2} \text {. }
$$

Since $x=\sqrt{3}-2<0$, then $|x|=-x$.
Thus the original expression $=\frac{-x(x+2)}{x^{2}-1} \div \frac{2|x|}{|x|^{2}-1}=\frac{x+2}{2}=\frac{\sqrt{3}}{2}$.