【Question 7】 80 students stand in a row facing the teacher, and report numbers in sequence from left to right according to the teacher's command: $1, 2, 3 \cdots \cdots$. After reporting, the teacher asks the students who reported numbers that are multiples of 2 to turn around, then asks the students who reported numbers that are multiples of 4 to turn around, followed by those who reported multiples of 8, ... up to those who reported multiples of 64. Now, the number of students facing away from the teacher is $\qquad$.
Analysis:
At the beginning, students face the teacher, and the requirement is for students to turn their backs to the teacher, which means finding the number of students who have turned an odd number of times.
$$
\left[\frac{80}{2}\right]=40 \text { people, }\left[\frac{80}{4}\right]=20 \text { people, }\left[\frac{80}{8}\right]=10 \text { people, }\left[\frac{80}{16}\right]=5 \text { people, }\left[\frac{80}{32}\right]=2 \text { people, }\left[\frac{80}{64}\right]=1 \text { person. }
$$
(64, 32, 16, 8, 4, 2 are the 6th, 5th, 4th, 3rd, 2nd, and 1st powers of 2, respectively) Then, the number of students who have turned 6 times is 1, the number of students who have turned 5 times is $2-1=1$ person, the number of students who have turned 4 times is $5-2=3$ people, the number of students who have turned 3 times is $10-5=5$ people, the number of students who have turned 2 times is $20-10=10$ people, and the number of students who have turned 1 time is $40-20=20$ people. Therefore, the number of students who have turned an odd number of times is $1+5+20=26$ people.