By default, iPhone passcodes consist of four base-$10$ digits. However, Freya decided to be unconventional and use hexadecimal (base-$16$) digits instead of base-$10$ digits! (Recall that $10_{16} = 16_{10}$.) She sets her passcode such that exactly two of the hexadecimal digits are prime. How many possible passcodes could she have set?
1. **Identify the hexadecimal digits and the prime digits among them:**
   - Hexadecimal digits: \(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F\)
   - Prime digits in hexadecimal: \(2, 3, 5, 7, B, D\) (since \(B = 11_{10}\) and \(D = 13_{10}\) are prime in base-10)

2. **Count the number of prime and non-prime digits:**
   - Number of prime digits: \(6\)
   - Number of non-prime digits: \(16 - 6 = 10\)

3. **Determine the number of ways to choose 2 prime digits and 2 non-prime digits:**
   - Number of ways to choose 2 prime digits from 6: \(\binom{6}{2} = \frac{6!}{2!(6-2)!} = 15\)
   - Number of ways to choose 2 non-prime digits from 10: \(\binom{10}{2} = \frac{10!}{2!(10-2)!} = 45\)

4. **Calculate the total number of ways to choose the digits:**
   - Total ways to choose 2 prime and 2 non-prime digits: \(15 \times 45 = 675\)

5. **Determine the number of ways to arrange the chosen digits:**
   - Number of ways to arrange 2 prime and 2 non-prime digits in a 4-digit passcode: \(\binom{4}{2} = 6\)

6. **Calculate the total number of possible passcodes:**
   - Total number of possible passcodes: \(675 \times 6 = 4050\)

The final answer is \(\boxed{4050}\).