5. Point $P$ is located on side $AB$ of square $ABCD$ such that $AP: PB=1: 2$. Point $Q$ lies on side $BC$ of the square and divides it in the ratio $BQ: QC=2$. Lines $DP$ and $AQ$ intersect at point $E$. Find the ratio of the lengths $PE: ED$.
Answer: $P E: E D=2: 9$.

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