If two numbers differ by 2 and their sum is 20 , the larger number is
(A) 11
(B) 10
(C) 9
(D) 12
(E) 8

Part B: Each correct answer is worth 6.
Solution 1

Since the two numbers differ by 2 but add to 20, the smaller number must be 1 less than half of 20 while the larger number is 1 greater than half of twenty.

The smaller number is 9 and the larger is 11 .

## Solution 2

Since the numbers differ by 2 , let the smaller number be represented by $x$ and the larger number be represented by $x+2$.

Since their sum is 20 , then $x+x+2=20$ or $2 x=18$ or $x=9$.

The smaller number is 9 and the larger is 11 .

ANSWER: (A)