Problem 1. The lengths of the sides of triangle $ABC$ are $54 \mathrm{~mm}$, $39 \mathrm{~mm}$, and $47 \mathrm{~mm}$, and the lengths of the sides of triangle $KLM$ are $8 \mathrm{~cm}$, $4 \mathrm{~cm}$, and $5 \mathrm{~cm}$. Which one has the larger perimeter?
The perimeter of triangle $ABC$ is

$$
54+39+47=140 \text{~mm}=14 \text{~cm}
$$

and the perimeter of triangle $KLM$ is

$$
8+4+5=17 \text{~cm}
$$

Thus, triangle $KLM$ has a larger perimeter.