60. Winnie-the-Pooh and Piglet set off to visit each other at the same time. But since Winnie-the-Pooh was composing another "hum" all the way, and Piglet was counting the crows flying by, they did not notice each other when they met. After the meeting, Piglet reached Winnie-the-Pooh's house in 4 min, and Winnie-the-Pooh reached Piglet's house in 1 min. How many minutes was each of them on the way?
60. Let's illustrate schematically:

![](https://cdn.mathpix.com/cropped/2024_05_21_00604dc020e3721fc1f4g-132.jpg?height=242&width=1128&top_left_y=273&top_left_x=470)

After meeting, Winnie-the-Pooh traveled the distance $C B$, which is the same distance Piglet traveled before the meeting, 4 times faster than Piglet traveled the distance $C A$ after the meeting. Therefore, Winnie-the-Pooh's speed is greater than Piglet's. The distance $A C$ is greater than $B C$ by the same factor as Winnie-the-Pooh's speed is greater than Piglet's. Therefore, Winnie-the-Pooh traveled the distance $B C$ faster than Piglet traveled the distance $A C$ by the same factor as his speed is greater than Piglet's.

From this,

$$
A C: B C = 2 \text{ and } v_{\text{Winnie-the-Pooh}}: v_{\text{Piglet}} = 2; (2+2=4)
$$

Winnie-the-Pooh was on the way for $4: 2 + 1 = 3$ (min), and Piglet for $3 \cdot 2 = 6$ (min).