Carolyn has a $\$ 5$ bill, a $\$ 10$ bill, a $\$ 20$ bill, and a $\$ 50$ bill in her wallet. She closes her eyes and removes one of the four bills from her wallet. What is the probability that the total value of the three bills left in her wallet is greater than $\$ 70$ ?
(A) 0.5
(B) 0.25
(C) 0.75
(D) 1
(E) 0
In the table below, we determine the total value of the three bills that remain in Carolyn's wallet when each of the four bills is removed.

| Bill Removed | Sum of the Bills Remaining |
| :---: | :---: |
| $\$ 5$ | $\$ 10+\$ 20+\$ 50=\$ 80$ |
| $\$ 10$ | $\$ 5+\$ 20+\$ 50=\$ 75$ |
| $\$ 20$ | $\$ 5+\$ 10+\$ 50=\$ 65$ |
| $\$ 50$ | $\$ 5+\$ 10+\$ 20=\$ 35$ |

It is equally likely that any one of the four bills is removed from the wallet and therefore any of the four sums of the bills remaining in the wallet is equally likely.

Of the four possible sums, $\$ 80, \$ 75, \$ 65$, and $\$ 35$, two are greater than $\$ 70$.

Therefore, the probability that the total value of the three bills left in Carolyn's wallet is greater than $\$ 70$, is $\frac{2}{4}$ or 0.5 .