## Problem Statement

Calculate the indefinite integral:

$$
\int \frac{1-\cos x}{(x-\sin x)^{2}} d x
$$
## Solution

$$
\int \frac{1-\cos x}{(x-\sin x)^{2}} d x=\int \frac{d(x-\sin x)}{(x-\sin x)^{2}}=-\frac{1}{x-\sin x}+C
$$

Source — "http://pluspi.org/wiki/index.php/?%?%?%?%?%?%?%?%?%?%?%? %D0%9A%D1%83%D0%B7%D0%BD%D0%B5%D1%86%D0%BE%D0%B2_%D0%98%D0%BD %D1%82%D0%B5%D0%B3%D1%80%D0%B0%D0%BB%D1%8B_3-10" Categories: Kuznetsov Problem Book Integrals Problem 3 | Integrals

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## Problem Kuznetsov Integrals 3-11

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