Robyn has 4 tasks to do and Sasha has 14 tasks to do. In order for Robyn and Sasha to do the same number of tasks, how many of Sasha's tasks should Robyn do?
(A) 6
(B) 4
(C) 5
(D) 7
(E) 2
Between them, Robyn and Sasha have $4+14=18$ tasks to do.

If each does the same number of tasks, each must do $18 \div 2=9$ tasks. This means that Robyn must do $9-4=5$ of Sasha's tasks.

ANSWER: $(\mathrm{C})$