My frisbee group often calls "best of five" to finish our games when it's getting dark, since we don't keep score. The game ends after one of the two teams scores three points (total, not necessarily consecutive). If every possible sequence of scores is equally likely, what is the expected score of the losing team?

$\textbf{(A) }2/3\hspace{14em}\textbf{(B) }1\hspace{14.8em}\textbf{(C) }3/2$

$\textbf{(D) }8/5\hspace{14em}\textbf{(E) }5/8\hspace{14em}\textbf{(F) }2$

$\textbf{(G) }0\hspace{14.9em}\textbf{(H) }5/2\hspace{14em}\textbf{(I) }2/5$

$\textbf{(J) }3/4\hspace{14em}\,\textbf{(K) }4/3\hspace{13.9em}\textbf{(L) }2007$
1. **Define the problem and notation:**
   - Let team \( A \) be the winning team and team \( B \) be the losing team.
   - The game ends when one team scores 3 points.
   - We need to find the expected score of the losing team \( B \).

2. **List all possible sequences of scores:**
   - If \( B \) scores 0 points, the only sequence is \( AAA \).
   - If \( B \) scores 1 point, the possible sequences are \( BAAA \), \( ABAA \), and \( AABA \).
   - If \( B \) scores 2 points, the possible sequences are \( BBAAA \), \( BABAA \), \( BAABA \), \( ABBAA \), \( ABABA \), and \( AABBA \).

3. **Count the number of sequences for each score of \( B \):**
   - For \( B = 0 \): 1 sequence (\( AAA \)).
   - For \( B = 1 \): 3 sequences (\( BAAA \), \( ABAA \), \( AABA \)).
   - For \( B = 2 \): 6 sequences (\( BBAAA \), \( BABAA \), \( BAABA \), \( ABBAA \), \( ABABA \), \( AABBA \)).

4. **Calculate the total number of sequences:**
   \[
   1 + 3 + 6 = 10
   \]

5. **Determine the probabilities for each score of \( B \):**
   - Probability that \( B \) scores 0 points: \(\frac{1}{10}\)
   - Probability that \( B \) scores 1 point: \(\frac{3}{10}\)
   - Probability that \( B \) scores 2 points: \(\frac{6}{10}\)

6. **Calculate the expected score of \( B \):**
   \[
   \text{Expected score} = \left(\frac{1}{10} \cdot 0\right) + \left(\frac{3}{10} \cdot 1\right) + \left(\frac{6}{10} \cdot 2\right)
   \]
   \[
   = 0 + \frac{3}{10} + \frac{12}{10}
   \]
   \[
   = \frac{15}{10}
   \]
   \[
   = \frac{3}{2}
   \]

The final answer is \(\boxed{\frac{3}{2}}\)