3. If $x^{3}+x^{2}+x+1=0$, then the value of $y=x^{97}+x^{96}+\cdots$ $+x^{103}$ is ( ).
(A) -1
(B) 0
(C) 1
(Dic
3. A.

From the given, we have $x^{4}=1$. Therefore, $y=x^{97}+x^{98}+\cdots+x^{103}$
$$
\begin{array}{l}
=x^{97}\left(1+x+x^{2}+x^{3}\right)+x^{100}\left(x+x^{2}+x^{3}\right)=x^{97} \times 0+ \\
\left(x^{4}\right)^{25}(-1)=-1
\end{array}
$$