## Task 4 - 320614

A cyclist rides from Schnellhausen to Sausedorf, covering 36 kilometers each day. At the same time, another cyclist, who covers 34 kilometers each day, rides from Sausedorf towards him. The distance between Schnellhausen and Sausedorf is 350 km.

In how many days will the two cyclists meet? Also, perform a check.
The distance between the two cyclists was initially 350 kilometers. It decreased by $36 \mathrm{~km} + 34 \mathrm{~km} = 70 \mathrm{~km}$ daily. Consequently, the two cyclists will meet in $350 \mathrm{~km} : 70 \mathrm{~km} = 5$ days.

To verify, we can calculate the distance covered by the cyclists in five days:

Since $5 \cdot 36 \mathrm{~km} = 180 \mathrm{~km}$, the meeting point of the two cyclists is 180 kilometers from Schnellhausen, and since $5 \cdot 34 \mathrm{~km} = 170 \mathrm{~km}$, the distance to Sausedorf is $170 \mathrm{~km}$. The two distances together make up the distance from Schnellhausen to Sausedorf: $180 \mathrm{~km} + 170 \mathrm{~km} = 350 \mathrm{~km}$.

Solutions from the 1st Round 1992 adopted from $[5]$

### 3.33.2 2nd Round 1992, Class 6