10. Li Yun is sitting by the window in a train traveling at a speed of 60 kilometers per hour, and he sees a freight train with 30 carriages coming towards him. When the front of the freight train passes his window, he starts timing, and when the last carriage passes his window, the recorded time is 18 seconds. It is known that the length of each freight carriage is 15.8 meters, the spacing between carriages is 1.2 meters, and the length of the freight train's front is 10 meters. What is the speed of the freight train?
10. Solution: The speed of the bus is 60 km/h, the distance it travels in 18 seconds is: $\frac{60 \times 1000}{3600} \times 18=300$ (meters)
The length of the truck is $(15.8+1.2) \times 30+10=520$ (meters)
The distance the truck travels in 18 seconds is $520-300=220$ (meters)
$$
\frac{220 \times 3600}{1000 \times 18}=44 \text { (km/h) }
$$