Three fair six-sided dice are rolled. The expected value of the median of the numbers rolled can be written as $\frac{m}{n}$, where $m$ and $n$ are relatively prime integers. Find $m+n$. 

[i]Proposed by [b]AOPS12142015[/b][/i]
To find the expected value of the median of three fair six-sided dice, we can use symmetry and properties of expected values.

1. **Symmetry Argument**:
   Consider a roll of the dice resulting in values \(a, b, c\) such that \(a \leq b \leq c\). By symmetry, for each roll \((a, b, c)\), there is a corresponding roll \((7-a, 7-b, 7-c)\). The median of the roll \((a, b, c)\) is \(b\), and the median of the roll \((7-a, 7-b, 7-c)\) is \(7-b\).

2. **Expected Value Calculation**:
   Since each roll \((a, b, c)\) has a corresponding roll \((7-a, 7-b, 7-c)\), the expected value of the median \(b\) can be calculated as follows:
   \[
   \text{Expected value of the median} = \frac{b + (7-b)}{2} = \frac{7}{2}
   \]

3. **Verification by Expected Value of Each Die**:
   The expected value of a single fair six-sided die is:
   \[
   E(X) = \frac{1 + 2 + 3 + 4 + 5 + 6}{6} = \frac{21}{6} = \frac{7}{2}
   \]
   Since the dice are fair and independent, the expected value of the median of three dice should also be \(\frac{7}{2}\).

Thus, the expected value of the median of the numbers rolled is \(\frac{7}{2}\). This can be written as \(\frac{m}{n}\) where \(m = 7\) and \(n = 2\). Since \(m\) and \(n\) are relatively prime, we have \(m+n = 7+2 = 9\).

The final answer is \(\boxed{9}\).