16. (15 points) There are four rectangles, each 7 cm long and 5 cm wide, that can be arranged to form a larger rectangle (without overlapping). How many different ways can they be arranged (illustrate with diagrams and list all answers)? What is the maximum and minimum perimeter of the larger rectangle in centimeters?

Draw the diagrams and list all the answers, and calculate the maximum and minimum perimeter.
【Answer】Solution: (1) The length is $5 \times 4=20$ cm, and the width is 7 cm,
so the perimeter is $(20+7) \times 2=54$ (cm),
(2) The length is $7 \times 4=28$ cm, and the width is 5 cm,
so the perimeter is: $(28+5) \times 2=66$ (cm),
(3) The length is $7+7=14$ cm, and the width is $5+5=10$ cm,

so the perimeter is $(14+10) \times 2=48$ (cm),
Answer: The perimeter of the combined rectangle is maximally 66 cm, and minimally 48 cm.