10. (3 points) On a highway, there are three points $A$, $O$, and $B$. $O$ is between $A$ and $B$, and the distance between $A$ and $O$ is 1360 meters. Two people, Jia and Yi, start from points $A$ and $O$ respectively at the same time and head towards point $B$. After 10 minutes, Jia and Yi are at the same distance from point $O$: After 40 minutes, Jia and Yi meet at point $B$. What is the distance between points $O$ and $B$ in meters?
【Analysis】At the 40th minute, person A and person B meet at point $B$, meaning that at this time, person A has walked 1360 meters, so A's speed is $1360 \div 40$ meters per minute. Therefore, in 10 minutes, person A walks $1360 \div 40 \times 10=340$ meters, which is $1360-340=1020$ meters away from point 0. Since at the 10th minute after departure, the distances of person A and person B from point $O$ are equal, then person B walks $1020 \div 10=102$ meters per minute. Since at the 40th minute, person A and person B meet at point $B$, at this time, person B has walked 2 $OB$s, then the distance between $O$ and $B$ is $102 \times 40 \div 2$ meters.

【Solution】Solution: $(1360-1360 \div 40 \times 10) \div 10 \times 40 \div 2$
$$
\begin{array}{l}
=(1360-340) \div 10 \times 40 \div 2, \\
=1020 \times 40 \div 2, \\
=2040 \text { (meters). }
\end{array}
$$

Answer: The distance between $O$ and $B$ is 2040 meters.
The answer is: 2040.