## Task 2 - 170522

On three trees, there are a total of 56 birds.

After 7 birds flew from the first tree to the second, and 5 birds flew from the second tree to the third, there were now twice as many birds on the second tree as on the first, and three times as many birds on the third tree as on the second.

Calculate how many birds originally sat on each of the trees!
If the number of birds sitting on the first tree at the end is denoted by $x$, then there are $2x$ birds on the second tree, and $4x$ birds on the third tree. Together, this makes $7x$ birds.

Since $56 \div 7 = 8$, there must be 8 birds on the first tree, 16 birds on the second tree, and 32 birds on the third tree at the end.

Therefore, at the beginning, there were 7 more birds on the first tree than the 8 birds, which makes 15 birds.

On the second tree, there were not yet the 7 birds that flew over from the first tree, but there were the 5 birds that later flew to the third tree; thus, there were 2 fewer birds than 16 birds at the beginning, which makes 14 birds.

On the third tree, there were 5 fewer birds than 32 birds at the beginning, which makes 27 birds.