46. Write the system of equations of the line passing through the point $(3, -2, 1)$ and perpendicular to the lines given by the systems:

$$
\frac{x-1}{2}=\frac{y+2}{3}=\frac{z-3}{-1} \quad \text{and} \quad \frac{x+3}{4}=\frac{y+1}{-1}=\frac{z+3}{3}
$$
46. Let $m, n, p$ be the coefficients of the desired line. The condition of perpendicularity gives two equations:

$$
\begin{aligned}
& 2 m+3 n-p=0 \\
& 4 m-n+3 p=0
\end{aligned}
$$

Solving them, we get: $m: n: p=4:(-5):(-7)$. From this, we obtain the equations of the line:

$$
\frac{x-3}{4}=\frac{y+2}{-5}=\frac{z-1}{-7}
$$