3. Each of the three boys was bought candies by their parents. Vitya was given 35 candies, Maria was given fewer than Vitya, and Sasha was given as many candies as Vitya and Maria together, and the number of candies he has is even. What is the maximum number of candies the boys could have been bought?
3. According to the condition, Maria has fewer candies than Petya. Therefore, she can have 34, 33... 1 candies. Since Sasha has an even number of candies, Maria must have an odd number $(33,31,29 \ldots 3,1)$. We need to find the greatest number of candies, so Maria will have 33 candies. Sasha will have 68 candies $(35+33=68)$, and all the children together will have $136(35+33+68=136)$.

Answer: the greatest number of candies is 136.