East and West towns are 45 kilometers apart. Person A and Person B start from the two towns at the same time and walk towards each other. A walks 1 kilometer more per hour than B. After 5 hours, the two meet, so A walks $\qquad$ kilometers per hour.


【Analysis and Solution】
Journey, Meeting Problem.
$v_{\text {甲 }}+v_{\text {乙 }}=45 \div 5=9$ km/h
$v_{\text {甲 }}-v_{\text {乙 }}=1$ km/h;
$v_{\text {甲 }}=(9+1) \div 2=5$ km/h.