11. (10 points) On Qingming Festival, the students take a bus to the martyrs' cemetery for recruitment. If the bus increases its speed by one-fifth after driving for 1 hour, it can arrive 20 minutes earlier than the scheduled time; if the bus first travels $72 \mathrm{~km}$ at the original speed, and then increases its speed by one-third, it can arrive 30 minutes earlier than the scheduled time. How many $km$ is it from the school to the martyrs' cemetery?
【Analysis】First, find the scheduled time after driving for 1 hour, the time used is the scheduled time's $1 \div\left(1+\frac{1}{5}\right)=$ $\frac{5}{6}$, so the scheduled time is $20 \div\left(1-\frac{5}{6}\right)=120$ minutes, thus the total scheduled time for the entire journey is 1 hour + 120 minutes $=180$ minutes; then find the time used, the time used is the scheduled time's $1 \div\left(1+\frac{1}{3}\right)=\frac{3}{4}$, which means arriving 180 $\times\left(1-\frac{3}{4}\right)=45$ minutes early, finally find the fraction corresponding to 72 kilometers, which is $1-\frac{30}{45}$, and solve accordingly.
【Solution】Solution: If the speed is increased by one-fifth after driving for 1 hour, then the time used after driving for 1 hour is the scheduled time's $1 \div\left(1+\frac{1}{5}\right)=\frac{5}{6}$, so the scheduled time is $20 \div\left(1-\frac{5}{6}\right)=120$ minutes, thus the total scheduled time for the entire journey is 1 hour + 120 minutes $=180$ minutes;

If the original speed is maintained for the first 72 kilometers, and then the speed is increased by one-third, the time used is the scheduled time's $1 \div$ $\left(1+\frac{1}{3}\right)=\frac{3}{4}$, which means arriving $180 \times\left(1-\frac{3}{4}\right)=45$ minutes early,

but actually arrived 30 minutes early, indicating that $\frac{2}{3}$ of the journey had the speed increased;
$$
72 \div\left(1-\frac{2}{3}\right)=216 \text { (kilometers). }
$$

Answer: The distance from the school to the martyrs' cemetery is 216 kilometers.