2. Let $A_{n}$ denote the product of multiples of $n$ not exceeding 100, where $n$ is a positive integer. For example, $A_{3}=3 \times 6 \times 9 \times \cdots \times 99$. Then the greatest common divisor of $A_{2}, A_{3}, A_{4}, \cdots, A_{17}$ is ( ).
(A)I
(B) 6
(C) 30
(D) 120
2. D.
$$
\begin{array}{l} 
A_{2}=2 \times 4 \times 6 \times \cdots \times 100=2^{50}(1 \times 2 \times 3 \times \cdots \times 50), \\
A_{3}=3 \times 6 \times 9 \times \cdots \times 99=3^{33}(1 \times 2 \times 3 \times \cdots \times 33), \\
\cdots \cdots \\
A_{16}=16 \times 32 \times 48 \times 64 \times 80 \times 96 \\
=16^{6}(1 \times 2 \times 3 \times 4 \times 5 \times 6), \\
A_{17}=17 \times 34 \times 51 \times 68 \times 85=17^{5}(1 \times 2 \times 3 \times 4 \times 5),
\end{array}
$$

Therefore, the greatest common divisor of $A_{2}, A_{3}, A_{4}, \cdots, A_{17}$ is
$$
1 \times 2 \times 3 \times 4 \times 5=120 \text {. }
$$