1. Condition $p:|x+1|>2$, Condition $q: \frac{1}{3-x}>1$. Then $\neg p$ is $\neg q$'s ( ).
(A) sufficient but not necessary condition
(B) necessary but not sufficient condition
(C) sufficient and necessary condition
(D) neither sufficient nor necessary condition
- 1.A.

From condition $p$, we get $\neg:-3 \leqslant x \leqslant 1$;
From condition $q$, we get ᄀ $q: x \leqslant 2$ or $x \geqslant 3$.