3. Let the function be
$$
f(x)=x^{2}+x+m\left(m \in \mathbf{R}_{+}\right) \text {. }
$$

If $f(t)<0$, then your judgment on the existence of zeros of the function $y=f(x)$ in the interval $(t, t+1)$ is $\qquad$ .
3. There exists a zero point.

Because 
$$
\begin{array}{l}
f(t)<0, \\
f(t+1)>0 .
\end{array}
$$
Hence,
$$
\begin{array}{l}
-10 \\
\Rightarrow f(t+1)>0 .
\end{array}
$$

Thus, the function $y=f(x)$ has a zero point in the interval $(t, t+1)$.