【Question 11】
Two trains depart from two cities at the same time heading towards each other, and they meet after 3.3 hours. If Train A departs 24 minutes earlier, then 3 hours after Train B departs, the two trains still need to travel 14 kilometers to meet; if Train B departs 36 minutes earlier, then 3 hours after Train A departs, the two trains still need to travel 9 kilometers to meet. The distance between the two cities is $\qquad$ kilometers.
【Analysis and Solution】
Travel problem.
Let the speed of car A be $x$ km/h, and the speed of car B be $y$ km/h;
The distance between the two cities $=3.3(x+y)=\frac{24}{60} x+3(x+y)+14=\frac{36}{60} y+3(x+y)+9$;
That is, $\left\{\begin{array}{l}\frac{24}{60} x+3(x+y)+14=3.3(x+y) \\ \frac{36}{60} y+3(x+y)+9=3.3(x+y)\end{array}\right.$;
Solving, we get $\left\{\begin{array}{l}x=115 \\ y=85\end{array}\right.$;

The distance between the two cities is $(115+85) \times 3.3=660$ km.