Let $m,n\geq 2$. One needs to cover the table $m \times n$ using only the following tiles:
Tile 1 - A square $2 \times 2$.
Tile 2 - A L-shaped tile with five cells, in other words, the square $3 \times 3$ [b]without[/b] the upper right square $2 \times 2$.
Each tile 1 covers exactly $4$ cells and each tile 2 covers exactly $5$ cells. Rotation is allowed.
Determine all pairs $(m,n)$, such that the covering is possible.




To determine all pairs \((m, n)\) such that the covering is possible using the given tiles, we need to analyze the constraints imposed by the tiles and the dimensions of the board.

1. **Tile Coverage Analysis**:
   - Tile 1 (a \(2 \times 2\) square) covers exactly 4 cells.
   - Tile 2 (an L-shaped tile with five cells) covers exactly 5 cells.

2. **Coloring the Board**:
   Let's color the board in an alternating fashion with 3 colors and let \(A_i\) be the set of cells with color \(i\):
   \[
   \begin{array}{|c|c|c|c|c|c|c|c|c|} \hline
   1 & 2 & 3 & 1 & 2 & 3 & 1 & 2 & 3 \\ \hline
   1 & 2 & 3 & 1 & 2 & 3 & 1 & 2 & 3 \\ \hline
   1 & 2 & 3 & 1 & 2 & 3 & 1 & 2 & 3 \\ \hline
   1 & 2 & 3 & 1 & 2 & 3 & 1 & 2 & 3 \\ \hline
   1 & 2 & 3 & 1 & 2 & 3 & 1 & 2 & 3 \\ \hline
   1 & 2 & 3 & 1 & 2 & 3 & 1 & 2 & 3 \\ \hline
   1 & 2 & 3 & 1 & 2 & 3 & 1 & 2 & 3 \\ \hline
   1 & 2 & 3 & 1 & 2 & 3 & 1 & 2 & 3 \\ \hline
   1 & 2 & 3 & 1 & 2 & 3 & 1 & 2 & 3 \\ \hline
   \end{array}
   \]

3. **Parity Consideration**:
   From this coloring, we observe that placing either of the two tiles changes the parity of the number of cells covered from each color or keeps it the same. Therefore, the number of cells of each color on the board must have the same parity.

4. **Divisibility by 3**:
   Suppose \(3 \nmid m\). Then, \(A_1\) has \(n\) more cells than \(A_3\), but \(A_1 \equiv A_3 \pmod{2}\). This implies \(2 \mid n\). Similarly, by coloring the rows, if \(3 \nmid n\), then \(2 \mid m\).

5. **Divisibility by 2**:
   If \(2 \mid m\) and \(2 \mid n\), then both dimensions must be even.

6. **Combining Conditions**:
   For the board to be coverable:
   - \(3 \mid m\) or \(3 \mid n\)
   - \(2 \mid m\) and \(2 \mid n\)

   Therefore, \(6 \mid m\) or \(6 \mid n\).

Conclusion:
The pairs \((m, n)\) such that the covering is possible are those where either \(6 \mid m\) or \(6 \mid n\).

The final answer is \( \boxed{ (m, n) } \) such that \(6 \mid m\) or \(6 \mid n\).