A square has a perimeter of $28 \mathrm{~cm}$. The area of the square, in $\mathrm{cm}^{2}$, is
(A) 196
(B) 784
(C) 64
(D) 49
(E) 56
Since the four sides of a square are equal in length and the perimeter is 28 , then each side has length $\frac{28}{4}=7$.

The area of the square is the product of the length and width, which are each equal to 7.

Therefore, the area of the square in $\mathrm{cm}^{2}$ is $7 \times 7=49$.

ANSWER: (D)