$9.275 \frac{x^{2}-7|x|+10}{x^{2}-6 x+9}<0$.

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$9.275 \frac{x^{2}-7|x|+10}{x^{2}-6 x+9}<0$.
## Solution.

$$
\begin{aligned}
& \frac{x^{2}-7|x|+10}{(x-3)^{2}}<0 \Leftrightarrow\left\{\begin{array} { l } 
{ x ^ { 2 } - 7 | x | + 1 0 < 0 , } \\
{ x \neq 3 }
\end{array} \Leftrightarrow \left\{\begin{array}{l}
(|x|-2)(|x|-5)<0, \\
x \neq 3
\end{array} \Leftrightarrow\right.\right. \\
& \Leftrightarrow\left\{\begin{array} { l } 
{ 2 < | x | < 5 , } \\
{ x \neq 3 }
\end{array} \Leftrightarrow \left\{\left\{\begin{array}{l}
2<x<5 \\
-5<x<-2 \\
x \neq 3
\end{array}\right.\right.\right.
\end{aligned}
$$

Answer: $\quad x \in(-5 ;-2) \cup(2 ; 3) \cup(3 ; 5)$.