8. (15 points) Fengfeng, Leilei, and Feifei have different eating habits. The table below shows today's lunch menu at the school cafeteria. A “ $\checkmark$ ” indicates that they like the food, and a “ $\times$ ” indicates that they refuse the food. If each of the three people orders 1 dish they like today, and no two people can order the same dish, how many different ordering schemes are there? $\qquad$ kinds.
\begin{tabular}{|c|c|c|c|c|c|c|c|c|}
\hline & Papaya Chicken & Scallion Beef & Lotus Root Lamb & Sea-Caught Shrimp & & Fresh White Sprouts & Garlic Monteng & Braised Eggplant \\
\hline Fengfeng & $\times$ & $x$ & $\times$ & $\times$ & $\times$ & $\checkmark$ & $\checkmark$ & $\checkmark$ \\
\hline Leilei & $\checkmark$ & $\sqrt{ }$ & $\checkmark$ & $x$ & $\times$ & $\checkmark$ & $\checkmark$ & $\times$ \\
\hline Feifei & $\checkmark$ & $x$ & $x$ & V & V & V & $\times$ & $\checkmark$ \\
\hline
\end{tabular}
【Answer】Solution: According to the problem, for three people to order randomly - two people order the same, there are $3 \times 5 \times 5-(2 \times 5+2 \times 3+2 \times 5)$ ways,

one person orders randomly $+2 \times$ all three order the same, there are 2 ways,
thus, the number of different ordering schemes is $3 \times 5 \times 5-(2 \times 5+2 \times 3+2 \times 5)+2=51$ ways,