2. Given $f(x)=\frac{1}{x^{2}}+\frac{1}{x^{4}}$, if $f(a-2)<f(2 a+1)$ holds, then the range of values for $a$ is
$f(x)$ is an even function and is decreasing on $(0,+\infty)$, then $|a-2|>|2 a+1| \Rightarrow 3 a^{2}+8 a-3<0$ $\Rightarrow-3<a<\frac{1}{3}$ and $a \neq-\frac{1}{2}$, so the range of $a$ is $\left(-3,-\frac{1}{2}\right) \cup\left(-\frac{1}{2}, \frac{1}{3}\right)$.