The equations $ 2x \plus{} 7 \equal{} 3$ and $ bx\minus{}10 \equal{} \minus{}\!2$ have the same solution for $ x$. What is the value of $ b$?

$ \textbf{(A)}\minus{}\!8 \qquad
\textbf{(B)}\minus{}\!4 \qquad
\textbf{(C)}\minus{}\!2 \qquad
\textbf{(D)}\ 4 \qquad
\textbf{(E)}\ 8$
1. First, solve the equation \(2x + 7 = 3\) for \(x\):
   \[
   2x + 7 = 3
   \]
   Subtract 7 from both sides:
   \[
   2x = 3 - 7
   \]
   Simplify the right-hand side:
   \[
   2x = -4
   \]
   Divide both sides by 2:
   \[
   x = \frac{-4}{2} = -2
   \]

2. Now, substitute \(x = -2\) into the second equation \(bx - 10 = -2\):
   \[
   b(-2) - 10 = -2
   \]
   Simplify the left-hand side:
   \[
   -2b - 10 = -2
   \]
   Add 10 to both sides:
   \[
   -2b = -2 + 10
   \]
   Simplify the right-hand side:
   \[
   -2b = 8
   \]
   Divide both sides by -2:
   \[
   b = \frac{8}{-2} = -4
   \]

The final answer is \(\boxed{-4}\).