## Task B-1.6.

A bus departs from the initial station with a constant number of passengers. At the first station, $20 \%$ of the passengers get off, and 24 passengers get on. At the next station, $\frac{2}{3}$ of the passengers get off, and no one gets on. At the last station, the remaining 16 passengers get off. How many passengers boarded the bus at the initial station?
## Solution.

Let the number of passengers who entered the bus at the initial station be denoted by $x$. After $20 \%$ of the passengers get off at the first station, there are $x-20 \% x=0.8 x$ passengers left in the bus.

(2 points)

When we add the 24 passengers who enter, after the first station there are $0.8 x+24$ passengers in the bus.

Of that number, $\frac{2}{3}$ of the passengers get off at the next station, which means $\frac{1}{3}$ of that number remains, i.e., $\frac{1}{3}(0.8 x+24)$,

and since that number is 16, we have $\frac{1}{3}(0.8 x+24)=16$, which means $x=30$.

At the initial station, 30 passengers entered the bus.