11、The sum of two numbers, A and B, is 888888. The digits in the ten-thousands place and the tens place of A are both 2, and the digits in the ten-thousands place and the tens place of B are both 6. If the digits in the ten-thousands place and the tens place of both A and B are replaced with zero, then A is three times B. What is A? What is B? (20 points)
11. 626626,262262

Solution: After replacing the digits in the ten-thousands place and the tens place with zeros, the sum of the two numbers, A and B, is 808808. Since A is three times B, B is $808808 \div (3+1) = 202202$, and A is $3 \times 202202 = 606606$. Therefore, the original number A is 626626, and the original number B is 262262.

Scoring Reference: (1) Correctly providing the answer, 5 points; (2) For each digit, being able to explain the reasoning, 10 points; (3) Even if the final answer is incorrect, for correctly reasoned digits, appropriate points should be given.