[ Coordinate method on the plane $]$

Find the equation of the line passing through the intersection point of the lines $3 x+2 y-5=0$ and $x-3 y+2=0$ and parallel to the y-axis.
Solving the system of equations

$$
\left\{\begin{array}{l}
3 x+2 y-5=0 \\
x-3 y+2=0
\end{array}\right.
$$

we find the coordinates of the point $B\left(x_{0} ; y_{0}\right)$ of intersection of these lines: $x_{0}=1, y_{0}=1$.

Since the desired line is parallel to the y-axis and passes through the point $B\left(x_{0} ; y_{0}\right)$, its equation is of the form $x=$ $x_{0}$, i.e., $x=1$.

## Answer

$x=1$.