8. Given that the three sides and the area of a triangle are all integers, and the perimeter is a perfect square, then the minimum value of such a triangle's perimeter is $\qquad$

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8.16

Analysis: Solution one: Since $a+b+c$ is a perfect square, $a+b+c=1,4,9,16$, ..., and $a, b, c \in Z$, hence $a+b+c \geq 4$;

If $a+b+c=4$, then the side lengths are $1,1,2$, which cannot form a triangle;
If $a+b+c=9$, then the side lengths could be $3,3,3$ and $2,3,4$ and $1,4,4$, in these cases, the areas are not integers,
which does not meet the requirements;
If $a+b+c=16$, then the side lengths can be $5,5,6$, in this case, the area is 12, which satisfies the condition.
Solution two: Since $2 p=a+b+c$ is a perfect square, hence $2 \mid p$, i.e., the perimeter is a multiple of 4;
If $a+b+c=4$, it is obviously not valid; if $a+b+c=16$, then the side lengths can be 5,5,6, in this case, the area is 12, which satisfies the condition.