A street has parallel curbs $40$ feet apart. A crosswalk bounded by two parallel stripes crosses the street at an angle. The length of the curb between the stripes is $15$ feet and each stripe is $50$ feet long. Find the distance, in feet, between the stripes.
$\textbf{(A)}\ 9 \qquad \textbf{(B)}\ 10 \qquad \textbf{(C)}\ 12 \qquad \textbf{(D)}\ 15 \qquad \textbf{(E)}\ 25$
Drawing the problem out, we see we get a parallelogram with a height of $40$ and a base of $15$, giving an area of $600$.


If we look at it the other way, we see the distance between the stripes is the height and the base is $50$.
[asy] draw((0,0)--(5,0)); draw((2.5,5)--(7.5,5)); draw((0,0)--(2.5,5)); draw((5,0)--(7.5,5),linewidth(2)); draw((2,4)--(6,2),dashed);[/asy]
The area is still the same, so the distance between the stripes is $600/50 = \boxed{\textbf{(C)}\ 12}$.