7. (3 points) Distribute 50 chocolates to 4 children, with each child receiving a different number of chocolates. The child who gets the most chocolates can get at least $\qquad$ chocolates.
7. (3 points) Distribute 50 chocolates to 4 children, with each child receiving a different number of chocolates. The child who gets the most chocolates can get at least $\qquad$ chocolates.

【Solution】Solution: Since each child must receive a different number of chocolates, the first distribution of chocolates to the 4 children can be: $1, 2, 3, 4$. From this, we can see that the last person is the one who gets the most chocolates;

Then, there are $50-(1+2+3+4)=40$ chocolates left; If all 40 chocolates are given to the last person, he can get a maximum of $4+40=44$ chocolates,

To make the number of chocolates he gets less, the remaining 40 chocolates can be distributed by giving each person 10 more, thus the number of chocolates each person gets would be: 11, 12, 13, 14,

Answer: The child who gets the most chocolates can get at least 14 chocolates; Therefore, the answer is: 14.