In the diagram, $\angle P Q R=\angle P R Q$. If $Q R=5$ and $P R=7$, then the perimeter of $\triangle P Q R$ is
(A) 12
(B) 14
(C) 17
(D) 18
(E) 19

![](https://cdn.mathpix.com/cropped/2024_04_20_6027bc27089ed4fc493cg-051.jpg?height=372&width=314&top_left_y=1836&top_left_x=1339)
Since $\angle P Q R=\angle P R Q$, then $\triangle P Q R$ is an isosceles triangle and $P Q=P R=7$. Therefore, the perimeter of $\triangle P Q R$ is $P Q+Q R+P R=7+5+7=19$.

ANsWer: (E)