The number of integers between $-\sqrt{8}$ and $\sqrt{32}$ is
(A) 5
(B) 6
(C) 7
(D) 8
(E) 19

## Part B: Each correct answer is worth 6.
The number of integers between $-\sqrt{8}$ and $\sqrt{32}$ is
(A) 5
(B) 6
(C) 7
(D) 8
(E) 19

## Solution

Since $-\sqrt{8} \doteq-2.8$ and $\sqrt{32} \doteq 5.7$, the integers between -2.8 and 5.7 would be $-2,-1,0,1,2,3,4$, and 5. There are eight integers.

ANSWER: (D)

## Part B: