16. Observe $7=5 \times 1+2, 12=5 \times 2+2, 17=5 \times 3+2$, here 7, 12, and 17 are called "3 consecutive numbers that leave a remainder of 2 when divided by 5". If the sum of 3 consecutive numbers that leave a remainder of 2 when divided by 5 is 336, then the smallest of these numbers is $\qquad$
【Analysis】This problem mainly examines the smallest term in an arithmetic sequence.

【Solution】Solution: Since these three numbers all leave a remainder of 2 when divided by 5, these three consecutive numbers form an arithmetic sequence, with the middle number being $336 \div 3=112$,

so the smallest one is $112-5=107$.
【Comment】This problem can be solved by identifying that each pair of consecutive numbers differs by 5.