37. In two boxes, there are 70 coins. It is known that in the first box, $\frac{5}{9}$ of the total number of coins are gold, and the rest are silver, in the second box, $\frac{7}{17}$ of the number of coins are silver, and the rest are gold. How many coins are in each box
37.Let $9 x$ be the number of coins in the first box, and $17 y$ be the number in the second, then $9 x + 17 y = 70$, where $x$ and $y$ are natural numbers, and $1 \leq y \leq 4$. By enumeration, we find that $y=2$, and $x=4$. Answer: in the first -36 coins, in the second -34.