8. The function $f(x)$ provides the following information:

When $x \in[-3,3]$, the solution to the inequality $x^{3} \cdot f(x)<0$ is $\qquad$ .
8. $(-3,-1) \cup(0,1)$ From the information provided by the function $f(x)$, it can be obtained that: when $x \in(-3,-1)$ or $x \in(1,3)$, $f(x)>0$; when $x \in(-1,1)$, $f(x) < 0$.

$$
\left\{\begin{array}{l}
{ f ( x ) > 0 , \text{ if } x \in (-3, -1) \text{ or } x \in (1, 3), } \\
{ f ( x ) < 0 , \text{ if } x \in (-1, 1). }
\end{array}\right.
$$

Therefore, the solution set of the inequality $x^{3} \cdot f(x)<0$ is $(-3,-1) \cup(0,1)$.