In the figure, $A D \perp B C, B A \perp C A, A B=7, B C=25, A D=h$ and $\angle C A D=\theta$.

G10.3 If $100 \sin \theta=t$, find $t$.
G10.4 Find $h$.
$$
\begin{array}{l}
A C^{2}+7^{2}=25^{2}(\text { Pythagoras' theorem }) \\
A C=24 \\
\angle A C D=90^{\circ}-\theta(\angle \mathrm{s} \mathrm{sum} \text { of } \triangle) \\
\angle A B C=\theta(\angle \mathrm{s} \mathrm{sum} \text { of } \triangle) \\
t=100 \sin \theta=100 \times \frac{24}{25}=96 \\
\text { Area of } \triangle A B C=\frac{1}{2} \cdot 7 \times 24=\frac{1}{2} \cdot 25 h \\
h=\frac{168}{25}
\end{array}
$$

Method 2
$$
\begin{array}{l}
\text { In } \triangle A B D, \\
h=A B \sin \theta \\
\quad=7 \times \frac{24}{25}=\frac{168}{25}
\end{array}
$$