Task 1 - 180621 a) The multispectral camera MKF-6 of Soyuz-22 photographed a rectangular area of $115 \mathrm{~km}$ width and $165 \mathrm{~km}$ length with each shot.

Calculate the area of such a region!

b) During the 83rd orbit around the Earth on September 20, 1976, Soyuz 22 flew over the GDR from Eisenach to Pasewalk. On a map with a scale of 1 : 700000, the distance flown over has a length of $65 \mathrm{~cm}$.

How long is this distance in reality? (Give the answer in km) (Calculation without considering the curvature of the Earth)
a) Since $115 \cdot 165=18975$, the area of such a region is $18975 \mathrm{~km}^{2}$.

b) Since $700000 \cdot 65=45500000$, the distance in reality is $45500000 \mathrm{~cm}=455 \mathrm{~km}$ long.