The 26 letters of the English alphabet are listed in an infinite, repeating loop:

ABCDEFGHIJKLMNOPQRSTUVWXYZABC ...

What is the $258^{\text {th }}$ letter in this sequence?
(A) $V$
(B) $W$
(C) $X$
(D) $Y$
(E) $Z$
In the sequence, the letters of the alphabet repeat in blocks of 26 letters.

Thus, 10 of these blocks gives a sequence that contains $10 \times 26=260$ letters.

Each block of 26 letters ends with the letter $Z$, and so the $260^{\text {th }}$ letter is a $Z$.

Moving backward in the sequence from this $Z$, we get that the $259^{\text {th }}$ letter is a $Y$, and the $258^{\text {th }}$ letter is an $X$.

ANswer: (C)