(2) Given the set of points on the plane $M=\left\{(x, y) \mid y=\sqrt{2 x-x^{2}}\right\}, N=\{(x, y) \mid y=k(x+1)\}$. When $M \cap N \neq \varnothing$, the range of values for $k$ is ( ).
(A) $\left[-\frac{\sqrt{3}}{3}, \frac{\sqrt{3}}{3}\right]$
(B) $\left[0, \frac{\sqrt{3}}{3}\right]$
(C) $\left[-\frac{\sqrt{3}}{3}, 0\right]$
(D) $\left[\frac{\sqrt{3}}{3},+\infty\right)$
(2) The graph of set $M$ is the upper half of a circle with center at $(1,0)$ and radius 1, and the graph of set $N$ is a line passing through $(-1,0)$. If the line intersects the circle, it is easy to see that its angle of inclination lies within $\left[0, \frac{\pi}{6}\right]$, i.e., $k \in\left[0, \frac{\sqrt{3}}{3}\right]$. Therefore, the answer is B.