If $(x-4)(5 x+2)=0$, then the two possible values of $5 x+2$ are
(A) -4 and $\frac{2}{5}$
(B) 0 and -18
(C) 0 and 22
(D) 0 and 4
(E) 4 and 22
Since $(x-4)(5 x+2)=0$, then $x-4=0$ or $5 x+2=0$.

If $x-4=0$, then $x=4$, and so $5 x+2=22$.

If $5 x+2=0$, then $5 x+2=0$. (Here, we don't have to actually figure out $x$, which is $x=-\frac{2}{5}$.) Therefore, the two possible values of $5 x+2$ are 0 and 22 .

ANswer: (C)