10. Given a sequence $\left\{a_{n}\right\}$ with 100 terms, satisfying $a_{1}=0, a_{100}=475$, and $\left|a_{k+1}-a_{k}\right|=5(k=1,2, \cdots, 99)$, then the number of different sequences that meet the conditions is $\qquad$.
The sequence $\left\{a_{n}\right\}$ has a difference of 5 between any two adjacent terms. Since $475 \div 5=95$, then $x_{1}+x_{2}+\cdots+x_{99}=95$, where $x_{i} \in\{-1,1\}$. Thus, there are 97 1s and 2 -1s in $x_{i}$, so the number of different sequences that meet the condition is $C_{99}^{2}=4851$.