298. Solve the equation:

$$
x^{3}-2 x^{2}-\left(a^{2}-a-1\right) x+a^{2}-a=0
$$
$\triangle$ One root of the equation can be guessed here: $x_{1}=1$ (check it!). We get:

$$
(x-1)\left(x^{2}-x+a-a^{2}\right)=0
$$

The roots of the quadratic equation

$$
x^{2}-x+a-a^{2}=0
$$

can also be guessed: $x_{2}=a, x_{3}=1-a$.

Answer: $1, a, 1-a$.