5. (5 points) From the 100 natural numbers $1 \sim 100$, remove two consecutive even numbers. The average of the remaining numbers is 50. Then the product of the two removed numbers is $\qquad$.


【Solution】Solution: $(1+2+\cdots+99+100)-50 \times(100-2)$
$$
\begin{array}{l}
=(1+100) \times 100 \div 2-4900 \\
=5050-4900 \\
=150
\end{array}
$$

Since the two numbers removed are consecutive even numbers,
the two numbers removed are: $74, 76$,
so the product of the two numbers removed is:
$$
74 \times 76=5624
$$

Therefore, the answer is: 5624.