$二 、$ (16 points) $1,2,3,4,5,6$ each is used once to form a six-digit number $\overline{a b c d e f}$, such that the three-digit numbers $\overline{a b c}$, $\tilde{b} c \bar{d}, \bar{c} d e, \overline{d e f}$ can be successively divisible by $4,5,3,11$. Find this six-digit number.
II. Since $5 \mid \overline{b c d}$, therefore, $d=5$.
Also, since $11 \mid \overline{d e f}$, therefore, $d+f-e$ is a multiple of 11.
But $3 \leqslant d+f \leqslant 5+6=11, 1 \leqslant e \leqslant 6$,
so $-3 \leqslant d+f-e \leqslant 10$.
Therefore, it can only be that $d+f-e=0$, i.e., $5+f=e$.
Also, since $e \leqslant 6, f \geqslant 1$, it can only be that $f=1, e=6$.
Furthermore, since $3 \mid \overline{c d e}$, i.e., $3 \mid \overline{c 56}$, therefore, $c+5$ is divisible by 3.
And since $4 \mid \bar{a} \bar{a} c$, it follows that $c$ is even, so $c=4$. Further deducing, $b=2, a=3$.
Thus, $\overline{a b c d e f}=324561$.