Your friend sitting to your left (or right?) is unable to solve any of the eight problems on his or her Combinatorics $B$ test, and decides to guess random answers to each of them. To your astonishment, your friend manages to get two of the answers correct. Assuming your friend has equal probability of guessing each of the questions correctly, what is the average possible value of your friend’s score? Recall that each question is worth the point value shown at the beginning of each question.
1. Let's denote the total number of questions as \( n = 8 \).
2. Each question has an equal probability of being guessed correctly, which is \( p = \frac{1}{2} \).
3. The number of correct answers is given as \( k = 2 \).

We need to find the expected score of your friend. Each question has a different point value, and we need to consider the distribution of these point values.

4. Let's denote the point values of the questions as \( a_1, a_2, \ldots, a_8 \). The minimum score your friend can get by answering two questions correctly is \( a_1 + a_2 \) (assuming \( a_1 \) and \( a_2 \) are the smallest point values), and the maximum score is \( a_7 + a_8 \) (assuming \( a_7 \) and \( a_8 \) are the largest point values).

5. To find the expected score, we need to consider all possible pairs of questions that your friend can answer correctly. There are \( \binom{8}{2} = 28 \) such pairs.

6. The expected score \( E \) can be calculated as the average of the sums of all possible pairs of point values:
\[
E = \frac{1}{\binom{8}{2}} \sum_{1 \leq i < j \leq 8} (a_i + a_j)
\]

7. Since the point values are symmetrical and the problem suggests that the average score is around the middle value, we can simplify the calculation by noting that the average score is the average of the minimum and maximum possible scores:
\[
\text{Minimum score} = a_1 + a_2
\]
\[
\text{Maximum score} = a_7 + a_8
\]
\[
\text{Average score} = \frac{a_1 + a_2 + a_7 + a_8}{2}
\]

8. Given the point values are \( 1, 2, 3, 4, 5, 6, 7, 8 \), the minimum score is \( 1 + 2 = 3 \) and the maximum score is \( 7 + 8 = 15 \).

9. Therefore, the average score is:
\[
\text{Average score} = \frac{3 + 15}{2} = 9
\]

Conclusion:
\[
\boxed{9}
\]