101. A special number. What number is formed from five consecutive digits (not necessarily in order) such that the number formed by the first two digits, multiplied by the middle digit, gives the number formed by the last two digits. (For example, if we take the number 12896, then 12, multiplied by 8, gives 96. However, unfortunately, $1,2,6,8,9$ are not consecutive digits, so this example is not a valid solution.)
101. The desired number is 13452. The consecutive digits are \(1,2,3,4,5 ; 13 \times 4=52\).

[For a six-digit number, V. Milli proposed the following solution: \(947658.94 \times 7=658 .-M . G\).