1. Let $x_{1}, x_{2}, \cdots, x_{n}$ be numbers that can take one of the values $-3, 0, 1$, and
$$
\begin{array}{l}
x_{1}^{2}+x_{2}^{2}+\cdots+x_{n}^{2}=279, \\
x_{1}^{3}+x_{2}^{3}+\cdots+x_{n}^{3}=-585 .
\end{array}
$$

Then the value of $x_{1}^{4}+x_{2}^{4}+\cdots+x_{n}^{4}$ is ( ).
(A) 2005
(B) 2006
(C) 2007
(D) 2008
- 1.C.

Let $x_{1}, x_{2}, \cdots, x_{n}$ be $n$ numbers, where $-3$ appears $b$ times, $1$ appears $b$ times, and $0$ appears $c$ times. Then
$$
\left\{\begin{array} { l } 
{ 9 a + b = 2 7 9 , } \\
{ - 2 7 a + b = - 5 8 5 }
\end{array} \Rightarrow \left\{\begin{array}{l}
a=24, \\
b=63 .
\end{array}\right.\right.
$$

Thus, the original expression $=24 \times(-3)^{4}+63 \times 1=2007$.