What is the integer equal to $\sqrt{\frac{119^{2}-17^{2}}{119-17}-10^{2}}$ ?
Factoring $119^{2}-17^{2}$ as a difference of squares, we have $119^{2}-17^{2}=(119-17)(119+17)$.

Then

$$
\sqrt{\frac{119^{2}-17^{2}}{119-17}-10^{2}}=\sqrt{\frac{(119-17)(119+17)}{119-17}-10^{2}}=\sqrt{119+17-100}=\sqrt{36}=6
$$

ANSWER: 6

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