Squirrels prepare supplies of hazelnuts, beech nuts, and spruce cones for the winter. Zrzečka, Pizizubka, and Křivoouško have the same number of supplies. Zrzečka has twice as many hazelnuts as Pizizubka. Křivoouško has 20 more hazelnuts than Pizizubka. All three have the same number of beech nuts, which is 48 pieces. Together, they have 180 cones and 180 hazelnuts. How many hazelnuts, cones, and beech nuts does each squirrel have?

(Dillingerová)
First, we determine the number of hazelnuts: as stated in the problem, each squirrel has exactly 48 hazelnuts.

Number of walnuts: Let's imagine that Pizizubka has one part of the total number of walnuts. Then Zrzečka has two of these parts. Křivoouško has 20 more walnuts than Pizizubka. This means that if we set aside these 20 walnuts from the total pile, Křivoouško will have the same number of walnuts as Pizizubka. So the total amount of $180-20=160$ walnuts represents 4 Pizizubka's parts. Pizizubka therefore has $160: 4=40$ walnuts, Zrzečka has $2 \cdot 40=80$ walnuts, and Křivoouško has $40+20=60$ walnuts.

Now we calculate how many items each squirrel has in total:

$$
(3 \cdot 48+180+180): 3=504: 3=168
$$

items of hazelnuts, walnuts, and pine cones in total.

The number of pine cones in their supplies is therefore calculated to complete 168.

$$
\begin{array}{ll}
\text { Zrzečka: } & 168-48-80=40 \text { pine cones. } \\
\text { Pizizubka: } & 168-48-40=80 \text { pine cones. } \\
\text { Křivoouško: } & 168-48-60=60 \text { pine cones. }
\end{array}
$$

The squirrels have prepared the following supplies for the winter:

| Zrzečka: | 48 hazelnuts, | 80 walnuts, | 40 pine cones |
| :--- | :--- | :--- | :--- |
| Pizizubka: | 48 hazelnuts, | 40 walnuts, | 80 pine cones |
| Křivoouško: | 48 hazelnuts, | 60 walnuts, | 60 pine cones |