The reciprocal of $\left( \frac{1}{2}+\frac{1}{3}\right)$ is 
$\text{(A)}\ \frac{1}{6} \qquad \text{(B)}\ \frac{2}{5} \qquad \text{(C)}\ \frac{6}{5} \qquad \text{(D)}\ \frac{5}{2} \qquad \text{(E)}\ 5$
The [reciprocal](https://artofproblemsolving.com/wiki/index.php/Reciprocal) for a [fraction](https://artofproblemsolving.com/wiki/index.php/Fraction) $\frac{a}{b}$ turns out to be $\frac{b}{a}$, so if we can express the [expression](https://artofproblemsolving.com/wiki/index.php/Expression) as a single fraction, we're basically done.
The expression is equal to $\frac{3}{6}+\frac{2}{6}=\frac{5}{6}$, so the reciprocal is $\frac{6}{5}\rightarrow \boxed{\text{C}}$.