6. Let $a$, $b$, $c$ be three prime numbers, and satisfy $a b c=5(a+b+c)$.
Then these three numbers in ascending order are $\qquad$
6. $2,5,7$.

From $a b c=5(a+b+c)$ and $a, b, c$ are all prime numbers, we know that one of these three numbers must be equal to 5.
Without loss of generality, let $a=5$, and $b>c$. Then $b c=5+b+c$,

which simplifies to $(b-1)(c-1)=6$.
Thus, $(b, c)=(4,3)$ (discard), $(7,2)$.
Therefore, these three numbers in ascending order are $2,5,7$.