A pentagon is divided into 5 equal sections, as shown. An arrow is attached to the centre of the pentagon. The arrow is spun once. What is the probability that the arrow stops in the section numbered 4 ?
(A) $\frac{3}{5}$
(D) $\frac{1}{4}$
(B) $\frac{1}{2}$
(E) $\frac{1}{5}$
(C) $\frac{4}{5}$

![](https://cdn.mathpix.com/cropped/2024_04_20_6027bc27089ed4fc493cg-027.jpg?height=228&width=236&top_left_y=691&top_left_x=1346)
Exactly 1 of the 5 equal sections contains the number 4 .

Therefore, the probability that the spinner lands on 4 is $\frac{1}{5}$.

ANsWER: (E)