In the $4 \times 4$ grid shown, each of the four symbols has a different value. The sum of the values of the symbols in each row is given to the right of that row. What is the value of
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9

| $\odot$ | $\triangle$ | $\triangle$ | $\odot$ | 26 |
| :---: | :---: | :---: | :---: | :---: |
| $\triangle$ | $\triangle$ | $\triangle$ | $\triangle$ | 24 |
| $\square$ | $\bullet$ | $\odot$ | $\bullet$ | 27 |
| $\square$ | $\odot$ | $\square$ | $\triangle$ | 33 |
From the second row, $\triangle+\Delta+\triangle+\triangle=24$ or $4 \triangle=24$, and so $\triangle=6$.

From the first row, $\odot+\triangle+\Delta+\odot=26$ or $2 \odot+2 \triangle=26$.

Since $\triangle=6$, then $2 \odot=26-12=14$, and so $\odot=7$.

From the fourth row, $\square+\odot+\square+\triangle=33$.

Since $\triangle=6$ and $\odot=7$, then $2 \square+7+6=33$, and so $2 \square=20$ or $\square=10$.

Finally, from the third row, $\square+\bullet+\odot+=27$.

Since $\square=10$ and $\odot=7$, then $2=27-10-7=10$.

Thus, $=5$.

ANswer: (A)