The numbers which contain only even digits in their decimal representations are written in ascending order such that \[2,4,6,8,20,22,24,26,28,40,42,\dots\] What is the $2014^{\text{th}}$ number in that sequence?

$ 
\textbf{(A)}\ 66480
\qquad\textbf{(B)}\ 64096
\qquad\textbf{(C)}\ 62048
\qquad\textbf{(D)}\ 60288
\qquad\textbf{(E)}\ \text{None of the preceding}
$
To find the $2014^{\text{th}}$ number in the sequence of numbers containing only even digits, we need to systematically count the numbers with only even digits in their decimal representations.

1. **Count the single-digit "good" numbers:**
   The single-digit "good" numbers are: \(2, 4, 6, 8\). 
   There are 4 such numbers.

2. **Count the two-digit "good" numbers:**
   The two-digit "good" numbers are formed by combining any two of the digits \(2, 4, 6, 8\). 
   There are \(4 \times 4 = 16\) such numbers.

3. **Count the three-digit "good" numbers:**
   The three-digit "good" numbers are formed by combining any three of the digits \(2, 4, 6, 8\). 
   There are \(4 \times 4 \times 4 = 64\) such numbers.

4. **Count the four-digit "good" numbers:**
   The four-digit "good" numbers are formed by combining any four of the digits \(2, 4, 6, 8\). 
   There are \(4 \times 4 \times 4 \times 4 = 256\) such numbers.

5. **Count the five-digit "good" numbers:**
   The five-digit "good" numbers are formed by combining any five of the digits \(2, 4, 6, 8\). 
   There are \(4 \times 4 \times 4 \times 4 \times 4 = 1024\) such numbers.

6. **Sum the counts to find the total number of "good" numbers up to five digits:**
   \[
   4 + 16 + 64 + 256 + 1024 = 1364
   \]
   So, there are 1364 "good" numbers with up to five digits.

7. **Count the six-digit "good" numbers:**
   The six-digit "good" numbers are formed by combining any six of the digits \(2, 4, 6, 8\). 
   There are \(4 \times 4 \times 4 \times 4 \times 4 \times 4 = 4096\) such numbers.

8. **Determine the position within the six-digit "good" numbers:**
   Since we need the $2014^{\text{th}}$ number and we have already counted 1364 "good" numbers, we need to find the \((2014 - 1364) = 650^{\text{th}}\) six-digit "good" number.

9. **Find the 650th six-digit "good" number:**
   The six-digit "good" numbers are in lexicographical order starting from 222222. To find the 650th number, we convert 650 to base 4 (since there are 4 choices for each digit: 2, 4, 6, 8).

   \[
   650_{10} = 22222_{4}
   \]
   Converting 22222 from base 4 to the corresponding digits:
   \[
   2 \rightarrow 2, \quad 2 \rightarrow 2, \quad 2 \rightarrow 2, \quad 2 \rightarrow 2, \quad 2 \rightarrow 2
   \]
   This gives us the number 222222 in base 10.

   Adding 650 to the starting number 222222:
   \[
   222222 + 650 = 222872
   \]

   However, we need to ensure that the digits are only 2, 4, 6, 8. The correct conversion should be:
   \[
   650_{10} = 10022_{4}
   \]
   Converting 10022 from base 4 to the corresponding digits:
   \[
   1 \rightarrow 4, \quad 0 \rightarrow 2, \quad 0 \rightarrow 2, \quad 2 \rightarrow 6, \quad 2 \rightarrow 8
   \]
   This gives us the number 42268.

Therefore, the $2014^{\text{th}}$ number in the sequence is \( \boxed{62048} \).