【Question 2】  
$a, b, c$ are all prime numbers, and $a+b=49, b+c=60$, then $c=$ $\qquad$ .
【Analysis and Solution】
If the sum of two prime numbers equals 49, and 49 is an odd number;
then the two prime numbers must be one odd and one even;
so the even number must be 2, and the other odd number is $49-2=47$.
(1) When $\left\{\begin{array}{l}a=2 \\ b=47\end{array}\right.$, $c=60-b=60-47=13$ is a prime number, which meets the condition;
(2) When $\left\{\begin{array}{l}a=47 \\ b=2\end{array}\right.$, $c=60-b=60-2=48$ is a composite number, which does not meet the condition; In conclusion, $a=2, b=47, c=13$.