The value of $\frac{2^{8}}{8^{2}}$ is
(A) $\frac{1}{16}$
(B) 8
(C) 4
(D) $\frac{1}{4}$
(E) 2
Solution 1

Using exponent laws,

$$
\frac{2^{8}}{8^{2}}=\frac{2^{8}}{\left(2^{3}\right)^{2}}=\frac{2^{8}}{2^{6}}=2^{2}=4
$$

## Solution 2

Calculating directly,

$$
\frac{2^{8}}{8^{2}}=\frac{256}{64}=4
$$

ANSWER: (C)