2. The numbers 1059, 1417, and 2312 leave the same remainder when divided by $d$, and $d>1$, find $d$.


2. Since $1059 \equiv 1417 \equiv 2312(\bmod d), d \mid(895,358)$, and $(895,358)=179$, which is a prime number, and $d>1$, therefore $d=179$.