If $x=-2$, the value of $(x)\left(x^{2}\right)\left(\frac{1}{x}\right)$ is
(A) 4
(B) $-8 \frac{1}{2}$
(C) -4
(D) -8
(E) 16
Solution

First, simplify the expression.

$$
(x)\left(x^{2}\right)\left(\frac{1}{x}\right)=x^{2}
$$

If $x=-2$, the value of the expression is $(-2)^{2}=4$.

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