460. The amount of heat $Q$, received by a certain substance when heated from 0 to $T$, is determined by the formula $Q=$ $=0.1054 t+0.000002 t^{2}$ ( $Q$ - in joules, $t$ - in kelvins). Find the heat capacity of this substance at $100 \mathrm{~K}$.
Solution. We find the heat capacity:

$$
C=Q_{T}^{\prime}=0.1054+0.000004 \dot{T}
$$

At $T=100 \mathrm{~K}$ we get

$$
C_{T=100}=0.1054+0.000004 \cdot 100=0.1058(\text{J/K). }
$$