The two tables below were formed according to the same rule, but in the second one, we indicate only three numbers. What number should be placed in the cell with $\star$?

| 5  | 8  | 11 | 14 | 17 |
| :---: | :---: | :---: | :---: | :---: |
| 12 | 15 | 18 | 21 | 24 |
| 19 | 22 | 25 | 28 | 31 |
| 26 | 29 | 32 | 35 | 38 |
| 33 | 36 | 39 | 42 | 45 |

![](https://cdn.mathpix.com/cropped/2024_05_01_bd5219fde2a4a59a7005g-1.jpg?height=403&width=434&top_left_y=1215&top_left_x=1188)
| 5 | 8 | 11 | 14 | 17 |
| :---: | :---: | :---: | :---: | :---: |
| 12 | 15 | 18 | 21 | 24 |
| 19 | 22 | 25 | 28 | 31 |
| 26 | 29 | 32 | 35 | 38 |
| 33 | 36 | 39 | 42 | 45 |

![](https://cdn.mathpix.com/cropped/2024_05_01_bd5219fde2a4a59a7005g-3.jpg?height=397&width=440&top_left_y=1138&top_left_x=1185)

Let's observe that in the first table, each row is an arithmetic progression with a common difference of 3, and each column is an arithmetic progression with a common difference of 7. Suppose in the second table, each row is an arithmetic progression with a common difference of \(a\) and each column is an arithmetic progression with a common difference of \(b\). Thus, we have:

| \(39-2a\) | \(39-a\) | 39 | \(39+a\) | \(39+2a\) |
| :---: | :---: | :---: | :---: | :---: |
| \(39-2a+b\) |  |  |  | \(39+2a+b\) |
| \(39-2a+2b\) |  |  |  | 87 |
| 56 |  |  |  |  |
|  |  |  | \(\star\) |  |

Therefore: \(\left\{\begin{array}{l}39+2a+2b=87 \\ 39-2a+3b=56 .\end{array}\right.\) Adding these two equations, we get \(78 + 5b = 143\), hence \(b=13\) and \(a=\frac{48-2b}{2}=11\). Therefore, the number in the position of \(\star\) is: \(39+a+4b=39+11+4 \times 13=102\).