Sure, here is the translated text:

```
II. In the following table, two of the logarithmic values are incorrect. Please correct them.
\begin{tabular}{|c|c|c|c|c|c|c|}
\hline$x$ & 0.021 & 0.27 & 1.5 & 2.8 & 3 & 5 \\
\hline $\lg x$ & $2 a+b+c-3$ & $6 a-3 b-2$ & $3 a-b+c$ & $1-2 a+2 b-c$ & $2 a-b$ & $a+c$ \\
\hline$x$ & 6 & 7 & 8 & 9 & 14 & \\
\hline $\lg x$ & $1+a-b-c$ & $2(b+c)$ & $3-3 a-3 c$ & $4 a-2 b$ & $1-c+2 b$ & \\
\hline
\end{tabular}
```
$\lg 7=2 b+c$,
$\lg 1.5=3 a-b+c-1$
II. [Analysis and Solution] $\lg 1.5$ and $\lg 7$ are incorrect, $\lg 1.5$ should be corrected to $3 a-b+c-1$, and $\lg 7$ should be corrected to $2 b+c$, for the following reasons:
We start the analysis from the logarithms of $3, 5, 7$:
(1) If $\lg 3 \neq 2 a-b$, then $\lg 9=2 \lg 3 \neq 4 a-2 b$.
$\lg 0.27=3 \lg 3-2 \neq 6 a-3 b-2$.
Thus, there are three incorrect logarithmic values in the table, which contradicts the problem statement, therefore:
$\lg 3=2 a-b$
(2) If $\lg 5 \neq a+c$, then
$\lg 2=1-\lg 5 \neq 1-a-c$
and $\lg 8=3 \lg 2 \neq 3-3 a-3 c$,
$$
\lg 6=\lg 3+\lg 2 \neq 1+a-b-c .
$$

There are also three incorrect logarithmic values in the table, which contradicts the problem statement, therefore:
$\lg 5=a+c$
From (1) and (2), it can be seen that the value of $\lg 1.5$ in the table is incorrect and should be corrected to
$\lg 1.5=\lg 3+\lg 5-1=3 a-b+c-1$.
(3) Now we examine the values in the table related to $\lg 7$, namely $\lg 0.021, \lg 2.8, \lg 14$.
$\lg 0.021=\lg 3+\lg 7-3$,
$\lg 2.8=2 \lg 2+\lg 7-1$,
$\lg 14=\lg 2+\lg 7$.
If $\lg 7=2 b+c$, then we have
$\lg 0.021=(2 a-b)+2(b+c)-3=2 a+b+2 c-3$.
$\lg 2.8=2(1-a-c)+2(b+c)-1=1-2 a+2 b$.
$\lg 14=(1-a-c)+2(b+c)=1-a+2 b+c$.
These three values are different from those given in the table, meaning there are three more incorrect logarithmic values in the table, which contradicts the problem statement. Therefore, the value of $\lg 7$ in the table is incorrect and should be corrected to
$\lg 7=\lg 14-\lg 2=(1-a+2 b)-(1-a-c)=2 b+c$.
When $\lg 7=2 b+c$, the calculated values of $\lg 0.021, \lg 2.8$, and $\lg 14$ are consistent with those given in the table.
In summary, the only incorrect values in the table are $\lg 1.5$ and $\lg 7$, which should be corrected to
$$
\lg 7=2 b+c, \lg 1.5=3 a-b+c-1 .
$$