Problem 5. The sum of the lengths of the sides of a rectangle is $40 \mathrm{~cm}$. One side of the rectangle is 4 times longer than the other.

a) Determine the lengths of the sides of the rectangle.

b) Can the given rectangle be divided into 4 equal squares with 3 parallel lines?

![](https://cdn.mathpix.com/cropped/2024_06_05_9d1696c7fd1a2cbf5bb5g-02.jpg?height=238&width=541&top_left_y=1232&top_left_x=883)

c) By how many centimeters does the sum of the lengths of the sides of the divided square differ from the sum of the lengths of the sides of the rectangle?
Solution. a) We have $x+x+4x+4x=40, 10x=40, x=4 \text{ cm}$. One side is $16 \text{ cm}$ long and the other is $4 \text{ cm}$.

b) It is possible, the side of each square is 4 cm long.

c) The sum of the sides of the square is

$$
4+4+4+4=16 \text{ cm}, 40-16=24 \text{ cm}
$$

## IV section