1. Given the directed line segment $P Q$ with the coordinates of the starting point $P$ and the end point $Q$ being $(-1,1)$ and $(2,2)$ respectively, if the line $l: x+m y+m=0$ intersects the extension of $P Q$, then the range of values for $m$ is $\qquad$ .
1. The equation of line $l$ is $x + m y + m = 0$, which can be rewritten as $x + m(y + 1) = 0$. This is clearly the equation of a line passing through point $M(0, -1)$. Draw a line $l_{1} \parallel PQ$ through point $M$. Clearly, the slope of $l_{1}$ is $k_{1} = \frac{2 - 1}{2 + 1} = \frac{1}{3}$. Draw a line $l_{2}$ through points $M$ and $Q$, then the slope of $l_{2}$ is $k_{2} = \frac{3}{2}$. As shown in the figure, the line $l$ that intersects the extension of $PQ$ should be between $l_{1}$ and $l_{2}$, i.e., $k_{1} - m > \frac{2}{3}, -3 < m < -\frac{2}{3}$.