Someone in 1893 is as old as the sum of the digits of their birth year; so how old are they?
In the context of the task

$$
1800+10 x+y=1893-(1+8+x+y)
$$

or

$$
11 x+2 y=84
$$

from which

$$
y=42-5 x-\frac{x}{2}
$$

if

$$
x=2 u
$$

then

$$
y=42-11 u
$$

It is necessary that $x$ and $y$ be positive integers less than 10, so it is necessary that:

$$
42>11 u
$$

thus

$$
u<\frac{42}{11}
$$

We see that $u$ can only be 3, and thus $y=9$ and $x=6$. Therefore, the person in question was born in 1869 and was 24 years old in 1893.

(Dezső Brandt, Székesfehérvár.)

The problem was also solved by: Bojedain F., Devecis M., Fekete J., Frankl I., Freibauer E., Friedmann B., Goldziher K., Gross N., Kántor N., Kárf I., Kármán T., Kornis Ö., Krátky Gy., Manheim E., Petrogalli G., Pollák S., Porkoláb J., Roth M., Schwartz E., Spitzer Ö., Szabó I., Szabó K., Weisz J.