G3.2 There are $R$ zeros at the end of $\underbrace{99 \ldots 9}_{2009 \text { of }} \times \underbrace{99 \ldots 9}_{2009 \text { of } 9^{\prime} s}+1 \underbrace{99 \ldots 9}_{2009 \text { of } 9^{\prime} s}$, find the value of $R$.
$\begin{array}{l}\underbrace{99 \ldots 9}_{2009 \text { of } 9^{\prime} s} \times \underbrace{99 \ldots 9}_{2009 \text { of } 9^{\prime} s}+1 \underbrace{99 \ldots 9}_{\text {2009 of }}=(1 \underbrace{0 \ldots 0}_{\text {2009 of o } 0^{\prime} s}-1) \times(\underbrace{0 \ldots .0}_{\text {2009 of } 0^{\prime} s}-1)+(2 \underbrace{0 \ldots 0}_{\text {2009 of } 0^{\prime} s}-1) \\ =\left(10^{2009}-1\right)\left(10^{2009}-1\right)+2 \times 10^{2009}-1 \\ =10^{4018}-2 \times 10^{2009}+1+2 \times 10^{2009}-1=10^{4018} \\ R=4018 \\\end{array}$