Let's calculate the dimensions of a cylindrical container with a volume of $1 \mathrm{hl}$, if the height of the cylinder is equal to the diameter of its base (to the nearest $1 \mathrm{~mm}$).
Let the radius of the base of the cylinder be $r$, then according to the problem, the height is $2r$ and the volume is $100 \mathrm{dm}^{3}$, so

$$
2 r \cdot r^{2} \pi=100
$$

or

$$
r=\sqrt[3]{\frac{50}{\pi}}
$$

By performing the calculation, we obtain $r=2.515 \mathrm{dm}, \mathrm{s}$, thus the height of the cylinder is

$$
h=5.03 \mathrm{dm}
$$

(Csada Imre, Pápa.)

Number of solutions: 27.