A circular spinner is divided into 8 equal sections, as shown. An arrow is attached to the centre of the spinner. The arrow is spun once. What is the probability that the arrow stops in a section containing a prime number that is odd?
(A) $\frac{1}{8}$
(D) $\frac{4}{8}$
(B) $\frac{2}{8}$
(C) $\frac{3}{8}$
(E) $\frac{7}{8}$

![](https://cdn.mathpix.com/cropped/2024_04_20_46ead6524a8d61e21c51g-021.jpg?height=344&width=350&top_left_y=1080&top_left_x=1321)
On the spinner given, the prime numbers that are odd are 3,5 and 7 .

Since the spinner is divided into 8 equal sections, the probability that the arrow stops in a section containing a prime number that is odd is $\frac{3}{8}$.

ANSWER: (C)