7. If $\log _{a} \sqrt{2}<1$, then the range of values for $a$ is
When solving $\log _{a} \sqrt{2}1$, if $a>\sqrt{2}$; when $0<a<1$, $\log _{a} \sqrt{2}<0$. Therefore, the range of $a$ is $(0,1) \cup(\sqrt{2},+\infty)$.