9. Let $E(n)$ denote the greatest integer $k$ that is a divisor of the product $1^{1}, 2^{2}, 3^{3} \cdots n^{n}$. Then $E(150)=$
$9.1,2, \cdots, 150$ contains 30 multiples of 5, each having one factor of 5 removed, along with their respective exponents, the exponent of 5 is
$$
\begin{array}{l}
5+5 \cdot 2+5 \cdot 3+\cdots+5 \cdot 30=5(1+2+3 \\
+\cdots+30)=2325 .
\end{array}
$$
1. $2, \cdots, 150$ contains 6 multiples of $5^{2}$, each having one factor of 5 removed, and then another factor of 5 removed, along with their respective exponents, the exponent of 5 is $5^{2}+5^{2} \cdot 2+\cdots+5^{2} \cdot 6=5^{2}(1+2+\cdots+6)$ $=525$.
$1, 2, \cdots, 150$ contains only one multiple of $5^{3}$, which has had two factors of 5 removed, and can have one more factor of 5 removed, along with its respective exponent, the exponent of 5 is $5^{3}$ $=125$.
$1,2, \cdots, 150$ contains no multiples of $5^{4}$.
$\therefore E(150)=2325+525+125=2975$