8. (10 points) A and B are playing a table tennis match, with a best-of-three format. In each game, the first to score 11 points and the opponent less than 10 points wins; if the score is tied at 10, the first to score 2 more points wins. The total points scored by A and B are both 30 points. Without considering the order of the scores, the number of possible score combinations for the three games is $\qquad$ kinds.
【Analysis】Through analysis, we can know: The total scores of A and B are both 30 points, $30<3 \times 11$, in the three rounds, one of them won two rounds, so at least two scores are not less than 11, the total score of A is $30: 30=11+9+10$, the corresponding score of B is: $30=7+11+12$ : The corresponding scores are $\left\{\begin{array}{l}11: 7 \\ 9: 11 \\ 10: 12\end{array}\right.$, then 7, 9 are reduced by 1, 10 and 12 are increased by $1:\left\{\begin{array}{l}11: 6 \\ 8 ; 11 \\ 11: 13\end{array} 、\left\{\begin{array}{l}11: 5 \\ 7: 11 \\ 12: 14\end{array}\left\{\begin{array}{l}11: 4 \\ 6: 11 \\ 13: 15\end{array} 、\left\{\begin{array}{l}11: 3 \\ 5: 11 \\ 14: 16\end{array} 、\left\{\begin{array}{l}11: 2 \\ 4: 11 \\ 15: 17\end{array} 、\left\{\begin{array}{l}11: 1 \\ 3: 11 \\ 16: 18\end{array} 、\left\{\begin{array}{l}11: 0 \\ 2: 11, \\ 17: 19\end{array}\right.\right.\right.\right.\right.\right.\right.$, the above 8 are all B's victories, the 8 corresponding to A's victory are also 8, but considering the order of the scores is not counted, there are 8 situations, according to this to solve.

【Solution】Solution: The total scores of A and B are both 30 points
$$
30<3 \times 11
$$

In the three rounds, one of them won two rounds, so at least two scores are not less than 11, the total score of A is:
$$
30: 30=11+9+10
$$

The corresponding score of B is:
$$
30=7+11+12 \text { : }
$$

Then 7, 9 are reduced by 1, 10 and 12 are increased by 1:
$$
\left\{\begin{array} { l } 
{ 1 1 : 6 } \\
{ 8 ; 1 1 } \\
{ 1 1 : 1 3 }
\end{array} 、 \left\{\begin{array} { l } 
{ 1 1 : 5 } \\
{ 7 : 1 1 } \\
{ 1 2 : 1 4 }
\end{array} 、 \left\{\begin{array} { l } 
{ 1 1 : 4 } \\
{ 6 : 1 1 } \\
{ 1 3 : 1 5 }
\end{array} 、 \left\{\begin{array} { l } 
{ 1 1 : 3 } \\
{ 5 : 1 1 } \\
{ 1 4 : 1 6 }
\end{array} 、 \left\{\begin{array} { l } 
{ 1 1 : 2 } \\
{ 4 : 1 1 } \\
{ 1 5 : 1 7 }
\end{array} 、 \left\{\begin{array} { l } 
{ 1 1 : 1 } \\
{ 3 : 1 1 } \\
{ 1 6 : 1 8 }
\end{array} 、 \left\{\begin{array}{l}
11: 0 \\
2: 11 \\
17: 19
\end{array}\right.\right.\right.\right.\right.\right.\right.
$$

The above 8 are all B's victories, the 8 corresponding to A's victory are also 8, but considering the order of the scores is not counted, there are 8 situations,

Answer: There are 8 situations for the scores of the three rounds.
The answer is: 8 .