(2) (2006 - Shanghai) Three students proposed their own ideas to solve the problem: "For the inequality $x^{2}+25+\left|x^{3}-5 x^{2}\right| \geqslant a x$ to hold for all $x$ in $[1,12]$, find the range of real number $a$."
Student A says: "We only need the minimum value of the left side of the inequality to be no less than the maximum value of the right side."
Student B says: "Transform the inequality into a function of variable $x$ on the left side and a constant on the right side, then find the maximum and minimum values of the function."
Student C says: "Consider both sides of the inequality as functions of $x$, and plot the function graphs."
Referring to the above problem-solving ideas, what do you think is the correct conclusion they are discussing, i.e., the range of $a$?
The function $y=x+\frac{25}{x}$ is monotonically decreasing on $(0,5)$ and monotonically increasing on $(5,+\infty)$, while $\mid x^{2}-$ $5 x \mid \geqslant 0$, with equality holding when $x=5$ or $x=0$. Therefore, $x+\frac{25}{x}+\left|x^{2}-5 x\right| \geqslant 10$, where equality holds if and only if $x=5$. Thus, for the inequality concerning $x$
$$
x^{2}+25+\left|x^{3}-5 x^{2}\right| \geqslant a x
$$

to hold for all $x$ in $[1,12]$, the range of values for $a$ is $a \leqslant 10$.