1. The trousers are cheaper than the jacket, the jacket is cheaper than the coat, the coat is cheaper than the fur, and the fur is cheaper than the diamond necklace by the same percentage. By what percentage is the fur more expensive than the trousers, if the diamond necklace is 6.25 times more expensive than the coat?
Answer: by $1462.5\%$.

Solution. According to the condition $\frac{B K}{Sh}=\frac{\Pi}{\Pi}=\frac{\Pi}{K}=\frac{K}{B}=\alpha$. In this case, the cost of the diamond necklace $(B K)$ is related to the cost of the coat (P) by the ratio $B K=\Pi \cdot \alpha^{2}$. Then $\alpha=\sqrt{6.25}=\sqrt{\frac{25}{4}}=\frac{5}{2}$. The relationship between the cost of the fur coat (Sh) and the trousers (B) is determined by the ratio $Sh=B \cdot \alpha^{3}=B \cdot \frac{125}{8}$. From this, $\frac{Sh}{B}=\frac{125}{8}$, and the desired value is determined as $\left(\frac{125}{8}-1\right) \cdot 100=1462.5$.

Answer to variant 172: by $78.4\%$.

Answer to variant 173: by $93.6\%$.

Answer to variant 174: by $309.6\%$.