10. (12 points) In the table below, $A, B, C, D, E, F, G, H, M$ each represent a different non-zero digit, where $A+B=14, M \div G=M-F=H-C, D \times F=24, B+E=16$, then $H$ represents $\qquad$ .
【Solution】Solution: Since the digits represented are non-zero, they can only be the 9 digits from $1-9$. Given $B+E=16=9+7$, $A+B=14=9+5$, so $B=9, A=5, E=7$.

The remaining digits are $1,2,3,4,6,8$, a total of 6 digits.
Since $D \times F=24, M \div G=M-F=H-C$, $F$ can only be one of $3,4,6,8$. Clearly, $F$ cannot be 8.

When $F=6, D=4$, then $M=8$ does not meet the requirements.
When $F=4, D=6$, $M=8$ does not meet the requirements.
When $F=3, D=8$, then $M=6, G=2, H-C=3, H=4, C=1$.
Therefore, the answer is: 4