9. Divisible by 11 with a remainder of 7, divisible by 7 with a remainder of 5, and not greater than 200, the sum of all such natural numbers is $\qquad$
【Answer】Solution: All natural numbers not greater than 200 that leave a remainder of 7 when divided by 11 are: $18,29,40,62,73,84$, $95,106,117,128,139,150,161,172,183,194 ;$ the smallest number that leaves a remainder of 7 when divided by 11 and a remainder of 5 when divided by 7 is $40,[11,7]=77$, and they are 117, 194 in sequence; the sum of all natural numbers not greater than 200 that satisfy the conditions is: $40+117+194=351$. Therefore, the answer is: 351.