## Task 1 - 180611

In a district of Leipzig, 260 large apartments were renovated.

For one tenth of these apartments, each apartment has $55 \mathrm{~m}^{2}$ of living space; for one quarter of the 260 apartments, each apartment has $67 \mathrm{~m}^{2}$ of living space; each of the other 260 apartments has $80 \mathrm{~m}^{2}$ of living space.

Calculate the total living space of these 260 renovated apartments!
A tenth of the 260 apartments are 26 apartments; because $260: 10=26$.

A quarter of the 260 apartments are 65 apartments; because $260: 4=65$.

The remaining apartments are 169 apartments; because $260-26-65=169$.

The living area of the first 26 apartments is $1430 \mathrm{~m}^{2}$; because $26 \cdot 55=1430$.

The living area of the next 65 apartments is $4355 \mathrm{~m}^{2}$; because $65 \cdot 67=4355$. The living area of the remaining 169 apartments is $13520 \mathrm{~m}^{2}$; because $169 \cdot 80=13520$.

The total living area of the 260 apartments is $19305 \mathrm{~m}^{2}$; because $1430+4355+13520=19305$.