The average of 19 consecutive integers is 99 . The largest of these integers is
(A) 118
(B) 108
(C) 109
(D) 117
(E) 107
The average of 19 consecutive integers is 99 . The largest of these integers is
(A) 118
(B) 108
(C) 109
(D) 117
(E) 107

## Solution

If the average of the 19 consecutive numbers is 99 the middle number is 99 which is the tenth number. If the tenth number is 99 , the nineteenth number will be 108 .

ANSWER: (B)