The gure below shows a large square divided into $9$ congruent smaller squares. A shaded square bounded by some of the diagonals of those smaller squares has area $14$. Find the area of the large square.
[img]https://cdn.artofproblemsolving.com/attachments/5/e/bad21be1b3993586c3860efa82ab27d340dbcb.png[/img]
1. Let's denote the side length of each of the 9 congruent smaller squares as \( s \). Therefore, the side length of the large square is \( 3s \) since it is composed of a \( 3 \times 3 \) grid of smaller squares.

2. The shaded square is bounded by the diagonals of the smaller squares. Each side of the shaded square is the diagonal of one of the smaller squares. The diagonal of a smaller square with side length \( s \) is given by \( s\sqrt{2} \) (using the Pythagorean theorem).

3. The area of the shaded square is given as 14. The area of a square is given by the side length squared. Therefore, if the side length of the shaded square is \( s\sqrt{2} \), its area is:
   \[
   (s\sqrt{2})^2 = 2s^2
   \]
   Given that this area is 14, we have:
   \[
   2s^2 = 14 \implies s^2 = 7
   \]

4. The area of the large square is the side length squared. The side length of the large square is \( 3s \), so its area is:
   \[
   (3s)^2 = 9s^2
   \]
   Substituting \( s^2 = 7 \) into the equation, we get:
   \[
   9s^2 = 9 \times 7 = 63
   \]

Conclusion:
\[
\boxed{63}
\]