3. On the bus route, there are only four stops - "Initial", "First", "Final", and "Last". At the first two stops, passengers only got on, and at the remaining stops, they only got off. It turned out that 30 passengers got on at the "Initial" stop, and 14 passengers got off at the "Last" stop. At the "First" stop, three times fewer passengers got on than got off at the "Final" stop. Which passengers are more - those traveling from "Initial" to "Last", or those traveling from "First" to "Final", and by how many?

Solution:
Answer: Those traveling from "First" to "Final" are six more.

Let $x$ be the number of people who got on at "First". Then, $3x$ people got off at "Final". Since the number of people getting on equals the number of people getting off, we have $30 + x = 3x + 14$, from which $x = 8$. Let $y$ be the number of people traveling from "Initial" to "Final". Then, the number of people traveling from "Initial" to "Final" is $8 - y$. Together with those traveling from "First" to "Final", they make up 14 people. Therefore, the number of people traveling from "First" to "Final" is $14 - 8 + y = 6 + y$. That is, six more people are traveling from "First" to "Final" than from "Initial" to "Final".