6.22 The sum of three numbers is $\frac{11}{18}$, and the sum of their reciprocals, which form an arithmetic progression, is 18. Find these numbers.
6.22 Let $x, y, z$ be the required numbers. Then, using the conditions, we get the system

$$
\left\{\begin{array}{l}
x+y+z=\frac{11}{18} \\
\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=18 \\
\frac{2}{y}=\frac{1}{x}+\frac{1}{z}
\end{array}\right.
$$

Solving it, we find $x=\frac{1}{9}, y=\frac{1}{6}, z=\frac{1}{3}$.

Answer: $\frac{1}{9} ; \frac{1}{6} ; \frac{1}{3}$