1. Given the function $y=x^{2}+\frac{1}{\sqrt{-x}}$, point $P(x, y)$ lies on the graph of this function. Then, point $P(\ddot{x}, y)$ should be in the ( ) of the Cartesian plane.
(A) first quadrant
(B) second quadrant
(C) third quadrant
(D) fourth quadrant
-.1.B.
Since $-x>0$, then, $x<0$, thus, we know that point $P(x, y)$ should be in the second quadrant.