## Subject 3.

The sum of four numbers is 2014. Find the four numbers knowing that if we add 16 to the first number, subtract 16 from the second number, divide the third number by 16, we get the fourth number in each case.
## Subject 3.

$$
\begin{array}{ll}
a+b+c+d=2014, a+16=d, b-16=d, c: 16=d & \ldots .2 p \\
a=d-16, b=d+16, c=d \cdot 16 & \ldots .2 p . \\
a+b+c+d=2014 \Rightarrow d-16+d+16+d \cdot 16+d=2014 \Rightarrow 19 \cdot d=2014 \Rightarrow d=106 & \mathbf{. . 2 p} . \\
a=90, b=122, c=1696, d=106 & \ldots . .1 p .
\end{array}
$$