7、Xiaoming and Xiaohong are running on a 600-meter circular track. The two start from the same point at the same time and run in opposite directions. The time interval between the first and second meeting is $\mathbf{50}$ seconds. It is known that Xiaohong's speed is $\mathbf{2}$ meters/second slower than Xiaoming's. Then Xiaoming's speed is $\qquad$ meters/second
【Answer】 7
Analysis:
Method one: Let Xiaohong's speed be $\mathrm{x}$ meters/second, and Xiaoming's speed be $\mathrm{x}+2$ meters/second. The two meet after covering the entire distance together, so $50(x+x+2)=600, x=5$, then Xiaoming's speed is $5+2=7$ meters/second. Method two: The two meet after covering the entire distance together, so the sum of their speeds is $600 \div 50=12$, the difference in their speeds is 2 meters/second, then the speed of Xiaoming (the faster one) is $(12+2) \div 2=7$ meters/second.