Solve the system of equations:

$$
\begin{aligned}
& x^{3}-y^{3}=26 \\
& x^{2} y-x y^{2}=6
\end{aligned}
$$
$(x-y)^{3}=x^{3}-y^{3}-3\left(x^{2} y-x y^{2}\right)=8$, that is, $x-y=2$. From the second equation, we find $x y=3$. By Vieta's formulas, we get the answer.

## Answer

$(3,1),(-1,-3)$.