1. In a plane, there are 5 given points. The lines connecting these points are neither parallel nor perpendicular to each other, and they do not coincide. Through each point, draw perpendiculars to the lines connecting the other 4 points. What is the maximum number of intersection points of these perpendiculars (excluding the 5 given points)?
1. Every 2 points form a straight line, making a total of $C_{5}^{2}=10$ lines. Every 3 points determine a triangle, forming a total of $C_{5}^{3}=10$ triangles. Each point can generate $C_{4}^{2}=6$ perpendicular lines, making a total of $5 C_{4}^{2}=30$ perpendicular lines, which can have at most $C_{30}^{2}$ intersection points (including repeated counts and known points). However, each line has 3 perpendicular lines that are parallel to each other, and they do not intersect, so we should subtract $10 C_{3}^{2}$. Additionally, the 3 altitudes of each triangle intersect at the same point, leading to repeated counts, so we should also subtract $10\left(C_{3}^{2}-1\right)$ points. Finally, each known point is the common intersection of 6 perpendicular lines and should not be counted, so we need to subtract $5 C_{6}^{2}$. Therefore, the maximum number of intersection points is $C_{30}^{2}-10 C_{3}^{2}-10\left(C_{3}^{2}-1\right)-5 C_{6}^{2}=310$.