2.48. In an oblique triangular prism, the distances between the lateral edges are equal to $a, b$ and $c$. The lateral edge is equal to $l$, and the height of the prism is $h$. Determine the total surface area of the prism.
2.48. The total surface area of the prism $S_{\text {full }}=2 S_{\text {base }}+S_{\text {lateral }}$. Since $a$, $b, c$ are the distances between the lateral edges of the prism, $a+b+c$ is the perimeter of the section perpendicular to the edge. Therefore, $S_{\text {lateral }}=$ $=(a+b+c) l=2 p l$, where $p=\frac{1}{2}(a+b+c)$. Using Heron's formula, we find $S_{\text {section }}=\sqrt{p(p-a)(p-b)(p-c)}$. Next, considering that $V=S_{\text {section }}^{-} l=$ $=S_{\text {base }} h$, we have $S_{\text {base }}=S_{\text {section }} \frac{l}{h}$. Finally, we get

$$
S_{\text {full }}=\frac{2 l}{h} \sqrt{p(p-a)(p-b)(p-c)}+2 p l
$$

Answer: $\frac{2 l}{h}(\sqrt{p(p-a)(p-b)(p-c)}+p h)$.