G1.2 Find the integral part of $16 \div(0.40+0.41+0.42+\ldots+0.59)$.
$\begin{array}{l}0.40+0.41+0.42+\ldots+0.59=\frac{20}{2} \cdot(0.40+0.59)=9.9 \\ 1=9.9 \div 9.9<16 \div 9.9<18 \div 9=2 \\ \text { Integral part }=1\end{array}$