14. Given $n$ numbers $x_{1}, x_{2}, \cdots, x_{n}$, each number is one of $0,1,-1$. If $x_{1}+x_{2}+\cdots+x_{n}=1000$, then the value of $x_{1}^{2017}+x_{2}^{2017}+\cdots+x_{n}^{2017}$ is ( ).
(A) 1
(B) 10
(C) 100
(D) 1000
Answer: D.
Solution: Regardless of $x_{i}=0,-1,1(i=1,2, \cdots, n)$, we always have $x_{i}^{2017}=x_{i}$. Therefore, $x_{1}^{2017}+x_{2}^{2017}+\cdots+x_{n}^{2017}=x_{1}+x_{2}+\cdots+x_{n}=1000$. Hence, the correct choice is D.