2) $\sqrt{12^{12}}$ is equal to:
(A) $6^{6}, \quad$ (B) $12^{2 \sqrt{3}}$
(C) $2^{12} 3^{6}$,
(D) $6^{12}$,
(E) none of the above numbers
2. The answer is $(\mathbf{C}) \cdot \sqrt{12^{12}}=12^{\frac{12}{2}}=12^{6}=\left(2^{2} \cdot 3\right)^{6}=2^{12} \cdot 3^{6}$.