7. The 3 roots of the equation $x^{3}-\sqrt{3} x^{2}-(2 \sqrt{3}+1) x+3+\sqrt{3}=0$ are $\qquad$ .
$7.1+\sqrt{3}, \frac{-1 \pm \sqrt{1+4 \sqrt{3}}}{2}$.
The left side of the original equation is transformed as follows:
$$
\begin{array}{l}
x^{3}-(\sqrt{3}+1) x^{2}+x^{2}-(2 \sqrt{3}+1) x+3+\sqrt{3}=0, \\
x^{2}[x-(\sqrt{3}+1)]+[x-(\sqrt{3}+1)](x-\sqrt{3})=0, \\
{[x-(\sqrt{3}+1)]\left[x^{2}+x-\sqrt{3}\right]=0,}
\end{array}
$$
$$
x-(\sqrt{3}+1)=0 \text { or } x^{2}+x-\sqrt{3}=0 \text {. }
$$