A group of tourists was supposed to arrive at the train station at 5 o'clock. By this time, a bus was supposed to come from the tourist base to pick them up. However, arriving at the train station at 3:10, the tourists started walking to the tourist base. Meeting the bus on the road, they got on and arrived at the tourist base 20 minutes earlier than the scheduled time. At what speed did the tourists walk before meeting the bus, if the bus's speed was 60 km/h?
Tourists saved 20 minutes, during which the bus would have traveled the distance they walked twice.

Therefore, on the way to the station, the bus saved 10 minutes, meaning it met the tourists at 4:50. This means the tourists walked the distance from the station to the meeting point in 100 minutes, which is 10 times slower than the bus.

## Answer

6 km/h.