In the  Mathematical  Competition  of  HMS (Hellenic  Mathematical  Society)  take part  boys and  girls  who are divided  into  two  groups : [i]Juniors[/i]  and  [i]seniors.[/i]The number of the  boys  taking  part  of this year  competition  is  55%  of the  number  of all participants. The  ratio  of the number  of juniors  boys  to  the number of senior  boys  is equal  to the  ratio of the  number of juniors  to the number of seniors. Find  the ratio  of the number of junior  boys  to the number  of  junior  girls.
1. Let \( b \) be the number of boys and \( g \) be the number of girls participating in the competition. According to the problem, the number of boys is 55% of the total number of participants. Therefore, we have:
   \[
   b = \frac{55}{100}(b + g)
   \]
   Simplifying this equation:
   \[
   b = 0.55(b + g)
   \]
   \[
   b = 0.55b + 0.55g
   \]
   \[
   b - 0.55b = 0.55g
   \]
   \[
   0.45b = 0.55g
   \]
   \[
   \frac{b}{g} = \frac{0.55}{0.45} = \frac{11}{9}
   \]

2. Let \( jb \) be the number of junior boys, \( sb \) be the number of senior boys, \( jg \) be the number of junior girls, and \( sg \) be the number of senior girls. According to the problem, the ratio of the number of junior boys to senior boys is equal to the ratio of the number of juniors to seniors. Therefore, we have:
   \[
   \frac{jb}{sb} = \frac{j}{s}
   \]
   This implies:
   \[
   jb = \frac{j}{s} sb
   \]

3. We need to find the ratio of the number of junior boys to the number of junior girls. From the previous step, we know:
   \[
   \frac{jb}{jg} = \frac{b}{g} = \frac{11}{9}
   \]

The final answer is \( \boxed{ \frac{11}{9} } \).