IS. 1 Given that $a=\sqrt{(19.19)^{2}+(39.19)^{2}-(38.38)(39.19)}$. Find the value of $m$.
Let $x=19.19, y=39.19$ then $x<y$ and $38.38=2 x$ $a=\sqrt{x^{2}+y^{2}-2 x y}=\sqrt{(y-x)^{2}}=y-x=39.19-19.19=20$