7. The solution set of the inequality $\sqrt{2 x+5}>x+1$ is
7. $\left[-\frac{5}{2}, 2\right) \cdot\left\{\begin{array}{l}x+10 \\ 2 x+5>(x+1)^{2},\end{array}\right.$ Solving, we get $-\frac{5}{2} \leqslant x<2$.