The numerical value of $2^{-2} \times 2^{-1} \times 2^{0} \times 2^{1} \times 2^{2}$ is
(A) 4
(B) 1
(C) 0
(D) $\frac{1}{4}$
(E) $\frac{1}{2}$
Using exponent laws,

$$
2^{-2} \times 2^{-1} \times 2^{0} \times 2^{1} \times 2^{2}=2^{-2-1+0+1+2}=2^{0}=1
$$

Alternatively,

$$
2^{-2} \times 2^{-1} \times 2^{0} \times 2^{1} \times 2^{2}=\frac{1}{4} \times \frac{1}{2} \times 1 \times 2 \times 4=1
$$

ANSWER: (B)