There is a tunnel between locations $A$ and $B$. A car departs from $B$ towards $A$ at 08:16, and a truck departs from $A$ towards $B$ at 09:00. It is known that the truck and the car arrive at the two ends of the tunnel simultaneously, but the truck leaves the tunnel 2 minutes later than the car. If the car arrives at $A$ at 10:56, and the truck arrives at $B$ at 12:20, then the time they simultaneously arrive at the two ends of the tunnel is $\qquad$.
【Analysis and Solution】
Travel problem, proportional travel.
The car departs from $B$ at 08:16 and arrives at $A$ at 10:56, requiring 2 hours and 40 minutes $=160$ minutes to travel the entire $A B$ route; the truck departs from $A$ at 09:00 and arrives at $B$ at 12:20, requiring 3 hours and 20 minutes $=200$ minutes to travel the entire $A B$ route; the time ratio for the car and truck passing through the tunnel is $160: 200=4: 5$; the truck and car arrive at the two ends of the tunnel simultaneously, but the truck leaves the tunnel 2 minutes later than the car; $2 \div(5-4)=2$; the car takes $2 \times 4=8$ minutes to pass through the tunnel, and the truck takes $2 \times 5=10$ minutes; when the distance is the same, the speed ratio is inversely proportional to the time ratio;
$$
v_{\text {car }}: v_{\text {truck }}=5: 4 \text {; }
$$

Assume the truck takes $t$ minutes from departure to reaching the tunnel, and the truck takes $200-10-t=190-t$ minutes from exiting the tunnel to arriving at $B$; the car takes $(t+44)$ minutes from departure to reaching the tunnel;
$$
(t+44):(190-t)=4: 5
$$

Solving for $t$ gives $t=60$;
That is, the truck takes 60 minutes from departure to reaching the tunnel;
09:00 plus 60 minutes is 10:00;
That is, the time they simultaneously reach the two ends of the tunnel is 10:00.