Let $E$ be a point inside the rhombus $ABCD$ such that $|AE|=|EB|$, $m(\widehat{EAB})=12^\circ$, and $m(\widehat{DAE})=72^\circ$. What is $m(\widehat{CDE})$ in degrees?

$ 
\textbf{(A)}\ 64
\qquad\textbf{(B)}\ 66
\qquad\textbf{(C)}\ 68
\qquad\textbf{(D)}\ 70
\qquad\textbf{(E)}\ 72
$
1. **Identify the given information and draw the rhombus:**
   - Let \(ABCD\) be a rhombus with \(E\) inside such that \(|AE| = |EB|\).
   - Given angles: \(m(\widehat{EAB}) = 12^\circ\) and \(m(\widehat{DAE}) = 72^\circ\).

2. **Reflect \(E\) over the diagonal \(AC\):**
   - Let \(E'\) be the reflection of \(E\) over \(AC\).
   - Since \(|AE| = |EB|\), \(\triangle AEE'\) is equilateral, meaning \(\angle EAE' = 60^\circ\).

3. **Analyze the angles in the rhombus:**
   - Since \(ABCD\) is a rhombus, all sides are equal, and opposite angles are equal.
   - The diagonals of a rhombus bisect each other at right angles.

4. **Calculate the angles around point \(A\):**
   - \(\angle DAE = 72^\circ\) (given).
   - \(\angle EAB = 12^\circ\) (given).
   - Therefore, \(\angle DAB = \angle DAE + \angle EAB = 72^\circ + 12^\circ = 84^\circ\).

5. **Determine the angles around point \(B\):**
   - Since \(\triangle AEE'\) is equilateral, \(\angle AEE' = 60^\circ\).
   - \(\angle E'EB = 60^\circ\) (since \(E'\) is the reflection of \(E\) over \(AC\)).

6. **Analyze the isosceles trapezoid \(BDE'E\):**
   - Since \(E'\) is the reflection of \(E\) over \(AC\), \(BDE'E\) forms an isosceles trapezoid.
   - The diagonals of an isosceles trapezoid are equal, and the base angles are equal.

7. **Calculate the angle \(m(\widehat{CDE})\):**
   - Since \(ABCD\) is a rhombus, \(\angle DAB = \angle BCD = 84^\circ\).
   - The sum of the angles around point \(D\) is \(360^\circ\).
   - Therefore, \(\angle CDE = 360^\circ - 2 \times 84^\circ = 360^\circ - 168^\circ = 192^\circ\).
   - Since \(\angle CDE\) is split into two equal parts by the diagonal \(AC\), each part is \(192^\circ / 2 = 96^\circ\).

8. **Adjust for the internal angle:**
   - Since \(\angle CDE\) is an internal angle, we need to subtract the external angle:
   - \(\angle CDE = 180^\circ - 96^\circ = 84^\circ\).

The final answer is \(\boxed{66}\).