14. The radius of the clock face is 20 cm, and it is externally tangent to another smaller disk with a radius of 10 cm at the 12 o'clock position. The smaller disk has a fixed pointer, which initially points vertically upward. When the smaller disk rolls clockwise along the outer edge of the larger clock face, always remaining tangent, until the pointer on the smaller disk points vertically upward again, the point of tangency between the two disks is located at the ( ) o'clock position on the larger clock face.
(A) 2
(B) 3
(C) 4
(D) 6
(E) 8
14. C.

As shown in Figure 3.
Let the angular displacement of the large circle be $\theta$. Then the angular displacement of the small circle is $360^{\circ}-\theta$.
Thus, $20 \theta=10\left(360^{\circ}-\theta\right) \Rightarrow \theta=120^{\circ}$.
Therefore, the two disks are externally tangent at the 4 o'clock position on the large dial.