Now, 4 different colors of flowers are to be planted. Each section will plant one color of flower, and adjacent sections cannot plant the same color of flower. The number of different planting methods is $\qquad$ (answer with a number).

Translate the above text into English, please keep the original text's line breaks and format, and output the translation result directly.
9. 120 Solution 1 As shown in the figure, number the 6 parts of the flower bed.

According to the different planting schemes for zones $1, 2, 3, 4$, consider two cases.
(1) If zones $1, 2, 3, 4$ are planted with 4 different colors of flowers, there are $A_{4}^{4}$ methods. Then arrange zone 5: if zone 5 is the same color as zone 3, there is 1 method for zone 6; if zone 5 is the same color as zone 2, there are 2 methods for zone 6.
Therefore, there are $A_{4}^{4} \times (1+2) = 4 \times 3 \times 2 \times 3 = 72$ (methods) in this case.
(2) If zones $1, 2, 3, 4$ are planted with 3 different colors of flowers, then zones 2 and 4 must be the same color, with $A_{4}^{3}$ methods; then arrange zone 5, with 2 methods; finally, arrange zone 6, with 1 method. Therefore, there are $A_{4}^{3} \times 2 \times 1 = 48$ (methods) in this case.
Thus, there are a total of $72 + 48 = 120$ (methods).