14. A wooden block floating in a cylindrical vessel with a base area $\mathrm{S}=25$ cm², partially filled with water, had a small stone placed on it. As a result, the block remained afloat, and the water level in the vessel rose by $h_{1}=1.5$ cm. Then the stone was removed from the block and dropped into the water. The stone sank, and the water level in the vessel rose by $h_{2}=0.5$ cm. Find the average density of the stone material, given that the density of water $\rho=1 \mathrm{g} / \mathrm{cm}^3$
14. When the stone was placed on the block, the pressure on the bottom of the vessel increased by the amount

$$
p_{1}=\rho g h_{1}
$$

and the force of pressure on the bottom of the vessel increased, on one side by the weight of the stone $m g$, where $m$ is the mass of the stone, and on the other by the amount $p_{1} S$. From the equality

$$
m g=p_{1} S
$$

we find

$m=\rho h_{1} S$.

The submerged stone will displace a volume $h_{2} S$ of water, equal to its own volume, that is, the volume of the stone

$$
V=h_{2} S
$$

$$
\rho_{\mathrm{K}}=\frac{m}{V}=\rho \frac{h_{1}}{h_{2}}=3 \rho=3 \frac{\tau}{\mathrm{cm}^{3}}
$$