10. (5 points) As shown in the figure, $AB=24$ (cm), in rectangle $BDEF$, $EF=15$ (cm), the area of the shaded $\triangle BCE$ is 60 square cm, then the area of $\triangle DCE$ is $\qquad$ square cm.
【Analysis】The lengths of $AB$ and $EF$ are known, so the area of triangle $ABE$ can be calculated. Given that the area of triangle $BCE$ is 60 square centimeters, the area of triangle $ABC$ can be determined, which allows us to find the length of $BC$. With $BC$ known, the length of $DE$ can be calculated, and thus the area of triangle $DCE$ can be found.

【Solution】Solution: The area of triangle $ABC$: $24 \times 15 \div 2 - 60$,
$$
\begin{array}{l}
=180-60, \\
=120 \text { (square centimeters); }
\end{array}
$$
The length of $BC$: $120 \times 2 \div 24$,
$$
\begin{array}{l}
=240 \div 24, \\
=10 \text { (centimeters); }
\end{array}
$$

So the length of $DC$ is: $15-10=5$ (centimeters);
The length of $DE$: $60 \times 2 \div 10=12$ (centimeters);
Therefore, the area of triangle $DCE$ is: $5 \times 12 \div 2=30$ (square centimeters);
Answer: The area of $\triangle DCE$ is 30 square centimeters.
The answer is: 30.