Lori makes a list of all the numbers between $1$ and $999$ inclusive. She first colors all the multiples of $5$ red. Then she colors blue every number which is adjacent to a red number. How many numbers in her list are left uncolored?

$\mathrm{(A) \ } 400 \qquad \mathrm{(B) \ } 402 \qquad \mathrm {(C) \ } 597 \qquad \mathrm{(D) \ } 600 \qquad \mathrm{(E) \ } 602$
1. **Identify the multiples of 5 between 1 and 999:**
   - The multiples of 5 are given by the sequence \(5, 10, 15, \ldots, 995\).
   - This is an arithmetic sequence where the first term \(a = 5\) and the common difference \(d = 5\).
   - To find the number of terms in this sequence, we use the formula for the \(n\)-th term of an arithmetic sequence:
     \[
     a_n = a + (n-1)d
     \]
     Setting \(a_n = 995\), we get:
     \[
     995 = 5 + (n-1) \cdot 5
     \]
     \[
     995 = 5 + 5n - 5
     \]
     \[
     995 = 5n
     \]
     \[
     n = \frac{995}{5} = 199
     \]
     So, there are 199 multiples of 5 between 1 and 999.

2. **Determine the numbers adjacent to the multiples of 5:**
   - Each multiple of 5 has two adjacent numbers, one before and one after, except for the boundary cases.
   - For example, the number 5 has 4 and 6 as adjacent numbers, and the number 10 has 9 and 11 as adjacent numbers.
   - However, the first multiple of 5 (which is 5) does not have a number before it in the range, and the last multiple of 5 (which is 995) does not have a number after it in the range.
   - Therefore, the total number of blue numbers is \(2 \times 199 - 2 = 396\).

3. **Calculate the total number of colored numbers:**
   - The total number of red numbers is 199.
   - The total number of blue numbers is 396.
   - Therefore, the total number of colored numbers is:
     \[
     199 + 396 = 595
     \]

4. **Calculate the number of uncolored numbers:**
   - The total number of numbers between 1 and 999 is 999.
   - The number of uncolored numbers is:
     \[
     999 - 595 = 404
     \]

The final answer is \(\boxed{404}\)