4. Fill in each box in the figure with the appropriate number so that the multiplication problem is correct. Then the product is ( ).
(A) 2986
(B) 2858
(C) 2672
(D) 2754
Analysis: Multiple Choice Analysis One: Clearly, the product of a three-digit number and a two-digit number is less than three thousand, so $\mathrm{D}$ is less than $3, \overline{\mathrm{d} 7}=17$ or 27. According to the four options, only $2754 \div 17=162,2754 \div 27=102$. Checking $27 \times 102$ meets the requirements. The answer is D.

Multiple Choice Analysis Two: Factorize the numbers in the four options and write them in the form of a three-digit number multiplied by a two-digit number, to see if the unit digit of the two-digit number is 7 and if the vertical multiplication fits the problem.
$$
2986=2 \times 1493,2858=2 \times 1429,2672=2^{4} \times 167,2754=2 \times 3^{4} \times 17
$$

Only $102 \times 27$ meets the requirements.
The answer is D.
If this question is a fill-in-the-blank, the fill-in-the-blank analysis: For easier explanation, label the blanks with letters, as shown in the figure:
(1) $\overline{A B C} \times 7=\overline{E 1 F}$, so $\mathrm{A}=1$, and at the same time $\mathrm{F}=\mathrm{K}$.
(2) According to the product $\overline{2 I J K}, H=1$ or $2, \mathrm{D}$ equals 1 or 2;
(3) When $H=D$ equals 1, then $E=G=9$, then the unit digit of $C \times D$ is 9, only $1 \times 9,3 \times 3$, and $7 \times 7$, so only $1 \times 9$ meets the requirements, at this time, $\mathrm{D}=1, \overline{A B C} \times \mathrm{D}=109, \overline{A B C}=109$, and $109 \times 7$ is less than 900, exclude this case.
(4) When $\mathrm{H}$ equals 2, then $\mathrm{D}=2, \overline{A B C} \times 2=\overline{20 G}$, so $\overline{A B C}=\overline{10 C}, \overline{10 C} \times 7=\overline{E 1 F}, \mathrm{C}=2$.

So the answer is $102 \times 27=2754$.
The answer is D.