The slope of the line $\frac{x}{3} + \frac{y}{2} = 1$ is
$\textbf{(A)}\ -\frac{3}{2}\qquad \textbf{(B)}\ -\frac{2}{3}\qquad \textbf{(C)}\ \frac{1}{3}\qquad \textbf{(D)}\ \frac{2}{3}\qquad \textbf{(E)}\ \frac{3}{2}$
To find the slope, all we have to do is put the equation into slope-intercept form. We subtract $\frac{x}{3}$ from both sides and then multiple all 
terms by $2$. This yields $y=-\frac{2}{3}x+1$, so the slope is $-\frac{2}{3} \implies \boxed{\text{B}}$.