2. What is the probability that two cards randomly selected (without replacement) from a standard 52-card deck are neither of the same value nor the same suit?
Answer: $\frac{12}{17}$
Solution: After choosing a first card, the second needs to be in one of the other three suits and of a different value. Hence, the answer is $\frac{3 \cdot 12}{52-1}=\frac{12}{17}$.