Let $n$ be a fixed positive integer and consider an $n\times n$ grid of real numbers. Determine the greatest possible number of cells $c$ in the grid such that the entry in $c$ is both strictly greater than the average of $c$'s column and strictly less than the average of $c$'s row.

[i]Proposed by Holden Mui[/i]
1. **Define the problem and notation:**
   Let \( n \) be a fixed positive integer and consider an \( n \times n \) grid of real numbers. We need to determine the greatest possible number of cells \( c \) in the grid such that the entry in \( c \) is both strictly greater than the average of \( c \)'s column and strictly less than the average of \( c \)'s row.

2. **Introduce the concept of a "cool" cell:**
   A cell \( c \) is called "cool" if the entry in \( c \) is strictly greater than the average of \( c \)'s column and strictly less than the average of \( c \)'s row.

3. **Construct an example for \( n = 4 \):**
   Consider the following \( 4 \times 4 \) grid:
   \[
   \begin{array}{cccc}
   1 & 1 & 1 & 0 \\
   1 & 1 & 1 & 0 \\
   1 & 1 & 1 & 0 \\
   0 & 0 & 0 & 2 \\
   \end{array}
   \]
   This example can be generalized for any \( n \).

4. **Count the number of cells that cannot be cool:**
   Every row and column must have at least one cell that is less than the average of that row or column. This is because all the numbers in a set cannot be greater than the average. Thus, we can count \( 2n \) cells that cannot be cool.

5. **Consider the possibility of double-counting:**
   We claim that at most one cell is counted twice, i.e., there is at most one cell that is the smallest in its row and largest in its column. Assume there exist two such cells with numbers \( x \) and \( y \). Consider the intersection of the column of \( x \) and the row of \( y \). This implies that \( x > y \). Similarly, \( y < x \), which is a contradiction.

6. **Calculate the maximum number of cool cells:**
   The maximum number of cool cells is given by:
   \[
   n^2 - (2n - 1) = n^2 - 2n + 1 = (n-1)^2
   \]

The final answer is \(\boxed{(n-1)^2}\).