*1. A set $M=\{19,93,-1,0,25, -78,-94,1,17,-2\}$ consists of ten elements. All non-empty subsets of $M$ are denoted as $M_{i}(i=1,2, \cdots, 1023)$, and the product of all elements in each non-empty subset is denoted as $m_{i}(i=1,2, \cdots, 1023)$. Then $\sum_{i=1}^{1023} m_{i}=(\quad)$.
(A) 0
(B) 1
(C) -1
(D) None of the above
1. C. Let the ten elements be $a_{1}, a_{2}, \cdots, a_{10}$. Then
$$
\begin{aligned}
\sum_{i=1}^{1023} m_{i}= & a_{1}+a_{2}+\cdots+a_{10}+a_{1} a_{2}+a_{1} a_{3}+\cdots \\
& +a_{8} a_{10}+a_{1} a_{2} a_{3}+\cdots+a_{9} a_{10} a_{1}+\cdots \\
& +a_{1} a_{2} \cdots a_{10} \\
= & \prod_{i=1}^{10}\left(1+a_{i}\right)-1
\end{aligned}
$$

Since one of the $a_{i}$ is -1, then $\prod_{i=1}^{10}\left(1+a_{i}\right)=0$. Therefore, $\sum_{i=1}^{1023} m_{i}=-1$.