2. Given the line $l: 2 x+y=10$, draw a line $l^{\prime} \perp l$ through the point $(-10,0)$, then the coordinates of the intersection point of $l^{\prime}$ and $l$ are $\qquad$
$(2,6)$
2.【Analysis and Solution】It is known that the slope of $l^{\prime}$ is $\frac{1}{2}$, so the equation of $l^{\prime}$ is $l^{\prime}: y=\frac{1}{2}(x+10)$. Solving the system of equations $\left\{\begin{array}{l}2 x+l y=10 \\ x-2 y=-10\end{array}\right.$ yields the intersection point coordinates as $(2,6)$.