1. Given $\frac{a}{b}=\frac{c}{d}=\frac{e}{f}=\frac{2}{3}$. Then
$$
\frac{a^{-2}+2^{-2} \cdot c^{-2}+3^{-3} \cdot e^{-2}+4^{-4} \cdot 2^{-2}}{b^{-2}+2^{-2} \cdot d^{-2}+3^{-3} \cdot f^{-2}+4^{-4} \cdot 3^{-2}}=
$$
$$
\text { II. } 1 . \frac{9}{4} \text {. }
$$

First, raise to the power of -2, then according to the basic properties of fractions, we get
$$
\frac{a^{-2}}{b^{-2}}=\frac{2^{-2} \cdot c^{-2}}{2^{-2} \cdot d^{-2}}=\frac{3^{-2} \cdot e^{-2}}{3^{-2} \cdot f^{-2}}=\frac{4^{-4} \cdot 2^{-2}}{4^{-4} \cdot 3^{-2}}=\frac{9}{4} \text {. }
$$

Using the properties of proportions, the result can be found.