(2) In a match between A and B consisting of 7 games (no ties per game), the probability of the match result being A to B as $4: 3$ is ( ).
(A) $\frac{35}{128}$
(B) $\frac{5}{16}$
(C) $\frac{4}{7}$
(D) $\frac{5}{8}$
(2) A Hint: The probability that meets the condition is $\frac{\mathrm{C}_{7}^{4}}{2^{7}}=\frac{35}{128}$.