Terence Tao is playing rock-paper-scissors. Because his mental energy is focused on solving the twin primes conjecture, he uses the following very simple strategy: 

   ·He plays rock first. 
   ·On each subsequent turn, he plays a different move than the previous one, each with probability ½. 

What is the probability that his 5th move will be rock?
1. **First Move:**
   Terence's first move is rock. This is given and has a probability of 1.

2. **Second Move:**
   On the second move, Terence will play either paper or scissors, each with a probability of \( \frac{1}{2} \).

3. **Third Move:**
   We now consider two cases for the third move:
   - **Case 1:** The second move is paper.
     - The third move will be either rock or scissors, each with a probability of \( \frac{1}{2} \).
   - **Case 2:** The second move is scissors.
     - The third move will be either rock or paper, each with a probability of \( \frac{1}{2} \).

4. **Fourth Move:**
   We now consider the fourth move for each sub-case of the third move:
   - **Case 1.1:** The second move is paper, and the third move is rock.
     - The fourth move will be either paper or scissors, each with a probability of \( \frac{1}{2} \).
   - **Case 1.2:** The second move is paper, and the third move is scissors.
     - The fourth move will be either rock or paper, each with a probability of \( \frac{1}{2} \).
   - **Case 2.1:** The second move is scissors, and the third move is rock.
     - The fourth move will be either paper or scissors, each with a probability of \( \frac{1}{2} \).
   - **Case 2.2:** The second move is scissors, and the third move is paper.
     - The fourth move will be either rock or scissors, each with a probability of \( \frac{1}{2} \).

5. **Fifth Move:**
   We now consider the fifth move for each sub-case of the fourth move:
   - **Case 1.1.1:** The second move is paper, the third move is rock, and the fourth move is paper.
     - The fifth move will be rock with a probability of \( \frac{1}{2} \).
   - **Case 1.1.2:** The second move is paper, the third move is rock, and the fourth move is scissors.
     - The fifth move will be rock with a probability of \( \frac{1}{2} \).
   - **Case 1.2.1:** The second move is paper, the third move is scissors, and the fourth move is rock.
     - The fifth move cannot be rock.
   - **Case 1.2.2:** The second move is paper, the third move is scissors, and the fourth move is paper.
     - The fifth move will be rock with a probability of \( \frac{1}{2} \).
   - **Case 2.1.1:** The second move is scissors, the third move is rock, and the fourth move is paper.
     - The fifth move will be rock with a probability of \( \frac{1}{2} \).
   - **Case 2.1.2:** The second move is scissors, the third move is rock, and the fourth move is scissors.
     - The fifth move will be rock with a probability of \( \frac{1}{2} \).
   - **Case 2.2.1:** The second move is scissors, the third move is paper, and the fourth move is rock.
     - The fifth move cannot be rock.
   - **Case 2.2.2:** The second move is scissors, the third move is paper, and the fourth move is scissors.
     - The fifth move will be rock with a probability of \( \frac{1}{2} \).

6. **Combining Probabilities:**
   - For Case 1.1: \( \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \)
     - Probability of fifth move being rock: \( \frac{1}{4} \times \frac{1}{2} = \frac{1}{8} \)
   - For Case 1.2: \( \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \)
     - Probability of fifth move being rock: \( \frac{1}{4} \times \frac{1}{2} = \frac{1}{8} \)
   - For Case 2.1: \( \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \)
     - Probability of fifth move being rock: \( \frac{1}{4} \times \frac{1}{2} = \frac{1}{8} \)
   - For Case 2.2: \( \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \)
     - Probability of fifth move being rock: \( \frac{1}{4} \times \frac{1}{2} = \frac{1}{8} \)

7. **Total Probability:**
   \[
   \frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8} = \frac{4}{8} = \frac{1}{2}
   \]

The final answer is \( \boxed{\frac{1}{2}} \).