938*. Two motor transport companies sent out cars to transport agricultural products in a total number of less than 18. The number of cars sent by the second company is less than twice the number of cars sent by the first company. If the first company had sent out 4 more cars, the number of cars sent by the first company would have been less than the number of cars sent by the second company. How many cars did each company send out?
Let $x$ and $y$ be the number of cars sent by the first and second auto enterprises, respectively. We obtain the system of inequalities:

$$
\left\{\begin{array}{l}
x+y<18 \\
y<12 \\
x+4<y
\end{array}\right.
$$

Since $x+4<y$ and $y<18-x$ (from the first inequality of the system), we have

$$
x+4<18-x, \quad 2 x<14, \quad x<7
$$

Then $4<x<7$. Therefore, $x=5$ or $x=6$. Let's consider both cases.

1) Suppose $x=5$. The system of inequalities becomes:

$$
\left\{\begin{array}{l}
5+y<18 \\
y<10 \\
5+4<y
\end{array}\right.
$$

From this, $9<y<10$, which is impossible.

2) Suppose $x=6$. We get:

$$
\left\{\begin{array}{l}
6+y<18 \\
y<12 \\
6+4<y
\end{array}\right.
$$

Then $10<y<12$. Therefore, $y=11$.

Answer: 6 and 11.