2) In the adjacent figure, the radius of the outer circle is double that of the inner circle. What is the ratio between the area of the shaded region and that of the white region inside?

$\begin{array}{lll}\text { (A) } 2 & \text { (B) } 3 & \text { (C) } 4\end{array}$

(D) it depends on the position of the circle

(E) none of the above.

![](https://cdn.mathpix.com/cropped/2024_04_17_548b825896d130d6fc47g-1.jpg?height=250&width=250&top_left_y=1397&top_left_x=1180)
2) The answer is (B)

Let $r$ be the radius of the inner circle, its area is $\pi r^{2}$. The area of the shaded region will be $\pi(2 r)^{2}-\pi r^{2}=3 \pi r^{2}$ and the ratio of the two areas required will therefore be $\frac{3 \pi r^{2}}{\pi r^{2}}=3$.