285. Solve the equation:

$$
2 x^{5}+5 x^{4}-13 x^{3}-13 x^{2}+5 x+2=0
$$
$\triangle$ This is a reciprocal equation of odd degree. Based on the statement of the reference problem 285, it has a root $x=-1$. Let's factorize the left-hand side of the equation:

$$
(x+1)\left(2 x^{4}+3 x^{3}-16 x^{2}+3 x+2\right)=0
$$

The equation

$$
2 x^{4}+3 x^{3}-16 x^{2}+3 x+2=0
$$

is also a reciprocal equation. Solve it using the known method. Complete the solution on your own.

Answer: $-1,2,1 / 2,-2 \pm \sqrt{3}$.