$2 \cdot 39$ makes the real-coefficient quadratic equation $2 k x^{2}+(8 k+1) x+8 k=0$ have two distinct real roots. The range of $k$ is
(A) $k-\frac{1}{16}$.
(C) $k \geqslant-\frac{1}{16}$.
(D) None of the above results is correct.
(Tianjin, China Junior High School Mathematics Competition, 1983)
[Solution] If the equation has two distinct real roots, then
$$
\left\{\begin{array}{l}
k \neq 0, \\
\Delta=(8 k+1)^{2}-4 \cdot 2 k \cdot 8 k>0 .
\end{array}\right.
$$

Solving this gives $k>-\frac{1}{16}$, and $k \neq 0$.
Therefore, the correct choice is $(D)$.