The value of $(\sqrt{\sqrt{9}+\sqrt{1}})^{4}$ is
(A) $\sqrt{10}$
(B) 10
(C) 16
(D) 82
(E) 100
Calculating from the inside out, $(\sqrt{\sqrt{9}+\sqrt{1}})^{4}=(\sqrt{3+1})^{4}=(\sqrt{4})^{4}=2^{4}=16$.

Answer: (C)