1. Nезнayka jumped from his house to Znayka's house. For the first three-quarters of the path, he jumped with jumps the length of two of his usual steps, and for the remaining quarter of the path, he jumped with jumps the length of three of his usual steps. It turned out that the number of jumps of two steps was 350 more than the number of jumps of three steps. How many usual steps is it from Znayka's house to Nезнayka's house? Assume that all steps of Nезнayka are the same.

Solution. Let the desired distance be $S$ steps, then the number of jumps of two and three steps is $\frac{3 S}{4 \cdot 2}$ and $\frac{S}{4 \cdot 3}$, respectively. We obtain the relationship $\frac{3 S}{8}-\frac{S}{12}=350 \Leftrightarrow \frac{7 S}{24}=350 \varnothing$ $S=1200$ (steps).
Answer variant l: 1200.

Answer variant 2: 1800.

Answer variant $3: 2040$.

Answer variant 4: 900.

Scoring evaluation: 15 баллов - correct solution and correct answer; 10 баллов - arithmetic error in otherwise correct solution