Fifty numbers have an average of 76 . Forty of these numbers have an average of 80. The average of the other ten numbers is
(A) 60
(B) 4
(C) 72
(D) 40
(E) 78
If 50 numbers have an average of 76 , then the sum of these 50 numbers is $50(76)=3800$.

If 40 numbers have an average of 80 , then the sum of these 40 numbers is $40(80)=3200$.

Therefore, the sum of the 10 remaining numbers is $3800-3200=600$, and so the average of the 10 remaining numbers is $\frac{600}{10}=60$.

ANswer: (A)