【Question 8】
A cultural and artistic team is practicing gymnastics to celebrate New Year's Day. If 1000 team members are arranged in several rows, the total number of rows is greater than 16, and from the second row onwards, each row has 1 more person than the previous row. The formation should be arranged in $\qquad$ rows to meet the requirements, and at this time, the first row should have $\qquad$ members.
【Analysis and Solution】
If a positive integer $n$ can be expressed as the sum of $k$ consecutive positive integers starting from $m$;
$$
\text { i.e., } n=m+(m+1)+\cdots+(m+k-1)=[m+(m+k-1)] \times k \div 2=\frac{k(2 m+k-1)}{2} \text {; }
$$

If $k$ is odd, then $2 m+k-1$ is even, $\frac{2 m+k-1}{2}$ is an integer; $n=k \times \frac{2 m+k-1}{2}$, i.e., $n=$ odd number $\times$ integer;
If an arithmetic sequence has an odd number of terms, then the sum of this arithmetic sequence $=$ middle term (integer) $\times$ number of terms (odd number);
If $k$ is even, then $2 m+k-1$ is odd, $\frac{k}{2}$ is an integer; $n=(2 m+k-1) \times \frac{k}{2}$, i.e., $n=$ odd number $\times$ integer;
If an arithmetic sequence has an even number of terms, then the sum of this arithmetic sequence $=$ sum of the two middle terms (odd number) $\times$ half the number of terms (integer); hence, a positive integer can be expressed as the sum of consecutive positive integers, then this number can definitely be expressed in the form of "odd number $\times$ integer"; but when $k=1$, this integer can only be expressed as "1 consecutive positive integer", this case is excluded;
The number of ways a positive integer can be expressed as the sum of consecutive positive integers is equal to the number of odd divisors of this positive integer - 1.
$1000=2^{3} \times 5^{3}$, has $3+1=4$ odd divisors;
Therefore, 1000 can be decomposed into the sum of several consecutive positive integers in $4-1=3$ ways;
$1000=5 \times 200$, decompose 1000 into 5 numbers, the center number is $200,1000=198+199+200+201+202$;
$1000=25 \times 40$, decompose 1000 into 25 numbers, the center number is $40,1000=28+29+\cdots 52$;
$1000=125 \times 8$, decompose 1000 into 16 numbers, the two middle numbers are 62 and $63,1000=55+56+\cdots+70$;
Since the total number of rows is greater than 16;
Therefore, the formation should be arranged in 25 rows to meet the requirements, at this time the first row should have 28 members.