1. Given that the graph of the function $y=f^{-1}(x)$ passes through the point $(1, 0)$. Then the inverse function of $f\left(\frac{1}{3} x-2\right)$ must pass through the point ( ).
(A) $(1,6)$
(B) $(6,1)$
(C) $(0,6)$
(D) $(6,0)$
-1.A.
Since the graph of $y=f(x)$ passes through the point $(0,1)$, therefore, the graph of $y=f\left(\frac{1}{3} x-2\right)$ passes through the point $(6,1)$, and its inverse function's graph passes through the point $(1,6)$.