Let $a_0, a_1, \ldots, a_9$ and $b_1 , b_2, \ldots,b_9$ be positive integers such that $a_9<b_9$ and $a_k \neq b_k, 1 \leq k \leq 8.$ In a cash dispenser/automated teller machine/ATM there are $n\geq a_9$ levs (Bulgarian national currency) and for each $1 \leq i \leq 9$ we can take $a_i$ levs from the ATM  (if in the bank there are at least $a_i$ levs).  Immediately after that action the bank puts $b_i$ levs in the ATM or we take $a_0$ levs. If we take $a_0$ levs from the ATM the bank doesn’t put any money in the ATM. Find all possible positive integer values of $n$ such that after finite number of takings money from the ATM there will be no money in it.
To solve this problem, we need to find all possible positive integer values of \( n \) such that after a finite number of transactions, the ATM will be empty. Let's analyze the problem step by step.

1. **Understanding the Problem:**
   - We have an initial amount \( n \) in the ATM.
   - We can take \( a_i \) levs from the ATM, where \( 1 \leq i \leq 9 \) and \( a_9 < b_9 \).
   - After taking \( a_i \) levs, the bank puts \( b_i \) levs back into the ATM.
   - Alternatively, we can take \( a_0 \) levs, and the bank does not put any money back.

2. **Key Observations:**
   - If we take \( a_0 \) levs, the amount in the ATM decreases by \( a_0 \).
   - If we take \( a_i \) levs (for \( 1 \leq i \leq 9 \)), the net change in the ATM is \( b_i - a_i \).
   - We need to ensure that after a finite number of transactions, the ATM will be empty.

3. **Special Case Analysis:**
   - Consider \( n = 1 \). If we take \( a_0 = 1 \), the ATM will be empty immediately.
   - For \( n > 1 \), we need to ensure that the net change in the ATM can eventually lead to zero.

4. **General Case Analysis:**
   - Suppose \( n > 1 \) and let \( p \) be the smallest prime not dividing \( n \).
   - Set \( a_0 = a_1 = \ldots = a_9 = p \) and \( b_1 = \ldots = b_9 = 2p \).
   - The net change in the ATM for each transaction is either \( -p \) (if we take \( a_0 \)) or \( p \) (if we take \( a_i \) for \( 1 \leq i \leq 9 \)).
   - Since \( n \) is not divisible by \( p \), \( n - kp \neq 0 \) for any integer \( k \).

5. **Conclusion:**
   - If \( n \) is not divisible by any prime \( p \), then the ATM can never be depleted because the number of levs changes by \( p \) or \( 2p \) each time.
   - Therefore, the only possible value of \( n \) that allows the ATM to be depleted is \( n = 1 \).

The final answer is \( \boxed{ n = 1 } \).