5. If a number can be expressed as the sum of the digits of some multiple of 91, then this number is called a "harmonious number". Then, among $1,2, \cdots, 2008$, the number of harmonious numbers is $\qquad$
5.2007 .

Notice that $91=7 \times 13$.
Numbers with a digit sum of 1 are not multiples of 91.
$1001, 10101, 10011001, 101011001$,
$100110011001, 1010110011001, \cdots$
are all multiples of 91, and their digit sums are 2, 3, $4, 5, 6, 7, \cdots$ respectively. Therefore, among $1, 2, \cdots, 2008$, the number of numbers that can be expressed as the digit sum of some multiple of 91 is 2007.