10. In the complex plane, take any three different roots of the equation $z^{100}-1=0$ as vertices to form a triangle, then the number of different acute triangles is $\qquad$ .
As shown in the figure, select $z_{1}$ and draw the diameter $z_{1} z_{51}$. Then select $z_{j}$ and draw the diameter. At this point, since the center is inside the acute triangle, the third point can only be chosen on the minor arc $\overparen{z_{1} z_{j}}$ opposite to it, and there are $j-2$ ways to do so.
Thus, for $z_{1}$, the number of ways to form an acute triangle is $0+1+2+\cdots+48=49 \times 24$. The same applies to the other points.
Note that each acute triangle is counted 3 times, so the number of different acute triangles is $\frac{49 \times 24 \times 100}{3}=39200$.