2. If real numbers $x, y$ satisfy $(x+5)^{2}+(y-12)^{2}=14^{2}$, then the minimum value of $x^{2}+y^{2}$ is ( ).
(A) 2
(B) 1
(C) $\sqrt{3}$
(D) $\sqrt{2}$
2. (B).

As shown in Figure 6, $(x+5)^{2}+(y-12)^{2}=14^{2}$ is a circle with center at point $C(-5, 12)$ and radius 14. Let $P$ be any point on the circle, then $|O P| \geqslant |C P|-|O C|=14-13=1$. 
When points $C$, $O$, and $P$ are collinear, the equality holds. Therefore, the minimum value of $P$ to point $O$ is 1.