Júlio and Denise had lunch at a restaurant that offers three types of dishes and three types of vitamins, whose prices are in the table below. Each chose a dish and a vitamin. Júlio spent 6 reais more than Denise. How much did Denise spend?

|  | $R \$$ |
| :--- | :---: |
| simple dish | 7 |
| dish with meat | 11 |
| dish with fish | 14 |
| milk vitamin | 6 |
| fruit vitamin | 7 |
| special vitamin | 9 |
The prices of a dish plus a vitamin are:

![](https://cdn.mathpix.com/cropped/2024_05_01_31838da74537f7019fc7g-3.jpg?height=109&width=891&top_left_y=1393&top_left_x=591)

Among these, those that differ from 6 are: 14 and 20 or 17 and 23. Therefore, we have two solutions: Denise can spend $7+7=14$ and Júlio $14+6=11+9=20$ or Denise spends $11+6=17$ and Júlio $14+9=23$.