7.108. $0,1 \log _{2}^{4}(x-4)-1,3 \log _{2}^{2}(x-4)+3,6=0$.

7.108. $0.1 \log _{2}^{4}(x-4)-1.3 \log _{2}^{2}(x-4)+3.6=0$.
## Solution.

Domain of definition: $x-4>0, x>4$.

Solving this equation as a biquadratic equation in terms of $\log _{2}(x-4)$, we have $\left(\log _{2}(x-4)\right)_{1}=-2 ;\left(\log _{2}(x-4)\right)_{2}=2 ;\left(\log _{2}(x-4)\right)_{3}=-3 ;\left(\log _{2}(x-4)\right)_{4}=3$, from which $x_{1}=\frac{17}{4}, x_{2}=8, x_{3}=\frac{33}{8}, x_{4}=12$.

Answer: $\frac{17}{4} ; \frac{33}{8} ; 8 ; 12$.