[u]Round 1[/u]

[b]1.1.[/b] What is the area of a circle with diameter $2$?

[b]1.2.[/b] What is the slope of the line through $(2, 1)$ and $(3, 4)$?

[b]1.3.[/b] What is the units digit of $2^2 \cdot 4^4 \cdot 6^6$ ?


[u]Round 2[/u]

[b]2.1.[/b] Find the sum of the roots of $x^2 - 5x + 6$.

[b]2. 2.[/b] Find the sum of the solutions to $|2 - x| = 1$.

[b]2.3.[/b] On April $1$, $2018$, Mr. Dospinescu, Mr. Phaovibul and Mr. Pohoata all go swimming at the same pool. From then on, Mr. Dospinescu returns to the pool every 4th day, Mr. Phaovibul returns every $7$th day and Mr. Pohoata returns every $13$th day. What day will all three meet each other at the pool again? Give both the month and the day.


[u]Round 3[/u]

[b]3. 1.[/b] Kendall and Kylie are each selling t-shirts separately. Initially, they both sell t-shirts for $\$ 33$ each. A week later, Kendall marks up her t-shirt price by $30 \%$, but after seeing a drop in sales, she discounts her price by $30\%$ the following week. If Kim wants to buy $360$ t-shirts, how much money would she save by buying from Kendall instead of Kylie? Write your answer in dollars and cents.

[b]3.2.[/b] Richard has English, Math, Science, Spanish, History, and Lunch. Each class is to be scheduled into one distinct block during the day. There are six blocks in a day. How many ways could he schedule his classes such that his lunch block is either the $3$rd or $4$th block of the day?

[b]3.3.[/b] How many lattice points does $y = 1 + \frac{13}{17}x$ pass through for $x \in [-100, 100]$ ? (A lattice point is a point where both coordinates are integers.)


[u]Round 4[/u]

[b]4. 1.[/b] Unsurprisingly, Aaron is having trouble getting a girlfriend. Whenever he asks a girl out, there is an eighty percent chance she bursts out laughing in his face and walks away, and a twenty percent chance that she feels bad enough for him to go with him. However, Aaron is also a player, and continues asking girls out regardless of whether or not previous ones said yes. What is the minimum number of girls Aaron must ask out for there to be at least a fifty percent chance he gets at least one girl to say yes?

[b]4.2.[/b] Nithin and Aaron are two waiters who are working at the local restaurant. On any given day, they may be fired for poor service. Since Aaron is a veteran who has learned his profession well, the chance of him being fired is only $\frac{2}{25}$ every day. On the other hand, Nithin (who never paid attention during job training) is very lazy and finds himself constantly making mistakes, and therefore the chance of him being fired is $\frac{2}{5}$. Given that after 1 day at least one of the waiters was fired, find the probability Nithin was fired.

[b]4.3.[/b] In a right triangle, with both legs $4$, what is the sum of the areas of the smallest and largest squares that can be inscribed? An inscribed square is one whose four vertices are all on the sides of the triangle.


PS. You should  use hide for answers. Rounds 5-8 have been posted [url=https://artofproblemsolving.com/community/c3h2784569p24468582]here[/url]. Collected [url=https://artofproblemsolving.com/community/c5h2760506p24143309]here[/url].
<details><summary>Round 1</summary>
<details><summary>S1.1</summary>
1. The radius of the circle is half of the diameter. Given the diameter is \(2\), the radius \(r\) is:
   \[
   r = \frac{2}{2} = 1
   \]
   The area \(A\) of a circle is given by the formula:
   \[
   A = \pi r^2
   \]
   Substituting \(r = 1\):
   \[
   A = \pi \cdot 1^2 = \pi
   \]
   Therefore, the area of the circle is \(\boxed{\pi}\).
</details>
<details><summary>S1.2</summary>
2. The slope \(m\) of the line through points \((2, 1)\) and \((3, 4)\) is calculated using the formula:
   \[
   m = \frac{y_2 - y_1}{x_2 - x_1}
   \]
   Substituting the given points:
   \[
   m = \frac{4 - 1}{3 - 2} = \frac{3}{1} = 3
   \]
   Therefore, the slope of the line is \(\boxed{3}\).
</details>
<details><summary>S1.3</summary>
3. To find the units digit of \(2^2 \cdot 4^4 \cdot 6^6\), we first find the units digit of each factor:
   \[
   2^2 = 4 \quad \text{(units digit is 4)}
   \]
   \[
   4^4 = 256 \quad \text{(units digit is 6)}
   \]
   \[
   6^6 = 46656 \quad \text{(units digit is 6)}
   \]
   Now, we multiply the units digits:
   \[
   4 \cdot 6 = 24 \quad \text{(units digit is 4)}
   \]
   \[
   4 \cdot 6 = 24 \quad \text{(units digit is 4)}
   \]
   Therefore, the units digit of \(2^2 \cdot 4^4 \cdot 6^6\) is \(\boxed{4}\).
</details>
</details>

<details><summary>Round 2</summary>
<details><summary>S2.1</summary>
1. By Vieta's formulas, the sum of the roots of the quadratic equation \(ax^2 + bx + c = 0\) is given by \(-\frac{b}{a}\). For the equation \(x^2 - 5x + 6\):
   \[
   a = 1, \quad b = -5, \quad c = 6
   \]
   The sum of the roots is:
   \[
   -\frac{-5}{1} = 5
   \]
   Therefore, the sum of the roots is \(\boxed{5}\).
</details>
<details><summary>S2.2</summary>
2. To solve \(|2 - x| = 1\), we consider the two cases:
   \[
   2 - x = 1 \quad \text{or} \quad 2 - x = -1
   \]
   Solving each case:
   \[
   2 - x = 1 \implies x = 1
   \]
   \[
   2 - x = -1 \implies x = 3
   \]
   The solutions are \(x = 1\) and \(x = 3\). Their sum is:
   \[
   1 + 3 = 4
   \]
   Therefore, the sum of the solutions is \(\boxed{4}\).
</details>
<details><summary>S2.3</summary>
3. We need to find the least common multiple (LCM) of 4, 7, and 13. Since these numbers are pairwise relatively prime, their LCM is their product:
   \[
   \text{LCM}(4, 7, 13) = 4 \cdot 7 \cdot 13 = 364
   \]
   Therefore, they will all meet again 364 days after April 1, 2018. Calculating the date:
   \[
   \text{April 1, 2018} + 364 \text{ days} = \text{March 31, 2019}
   \]
   Therefore, they will meet again on \(\boxed{\text{March 31, 2019}}\).
</details>
</details>