10. The number of triangles with integer sides and the longest side being 11 is $\qquad$.

The total number of such triangles is $\qquad$.
Let's assume $a \leqslant b \leqslant c=11$. When $a=1$, $b=11$, there is 1 triangle; when $a=2$, $b=11,10$, there are 2 triangles; $\cdots$; when $a=5$, $b=11,10,9,8,7$, there are 5 triangles; when $a=6$, $b=11,10,9,8,7,6$, there are 6 triangles; when $a=7$, $b=11,10,9,8,7$, there are 5 triangles; $\cdots$; when $a=11$, $b=11$, there is 1 triangle. Therefore, there are a total of 36 triangles.