Problems 14, 15 and 16 involve Mrs. Reed's English assignment. 

A Novel Assignment 

The students in Mrs. Reed's English class are reading the same 760-page novel. Three friends, Alice, Bob and Chandra, are in the class. Alice reads a page in 20 seconds, Bob reads a page in 45 seconds and Chandra reads a page in 30 seconds.

Chandra and Bob, who each have a copy of the book, decide that they can save time by "team reading" the novel. In this scheme, Chandra will read from page 1 to a certain page and Bob will read from the next page through page 760, finishing the book. When they are through they will tell each other about the part they read. What is the last page that Chandra should read so that she and Bob spend the same amount of time reading the novel?

$ \textbf{(A)}\ 425 \qquad 
\textbf{(B)}\ 444 \qquad 
\textbf{(C)}\ 456 \qquad 
\textbf{(D)}\ 484 \qquad 
\textbf{(E)}\ 506$
1. Let \( x \) be the number of pages Chandra reads, and \( y \) be the number of pages Bob reads. We know that the total number of pages is 760, so we have:
   \[
   x + y = 760
   \]

2. Chandra reads a page in 30 seconds, so the time she spends reading \( x \) pages is \( 30x \) seconds. Bob reads a page in 45 seconds, so the time he spends reading \( y \) pages is \( 45y \) seconds. We want Chandra and Bob to spend the same amount of time reading, so:
   \[
   30x = 45y
   \]

3. Simplify the equation \( 30x = 45y \) by dividing both sides by 15:
   \[
   2x = 3y
   \]

4. Now we have a system of linear equations:
   \[
   \begin{cases}
   x + y = 760 \\
   2x = 3y
   \end{cases}
   \]

5. Solve the second equation for \( y \):
   \[
   y = \frac{2x}{3}
   \]

6. Substitute \( y = \frac{2x}{3} \) into the first equation:
   \[
   x + \frac{2x}{3} = 760
   \]

7. Combine the terms on the left-hand side:
   \[
   \frac{3x + 2x}{3} = 760
   \]
   \[
   \frac{5x}{3} = 760
   \]

8. Multiply both sides by 3 to clear the fraction:
   \[
   5x = 2280
   \]

9. Divide both sides by 5 to solve for \( x \):
   \[
   x = \frac{2280}{5} = 456
   \]

10. Therefore, the last page that Chandra should read is page 456.

The final answer is \( \boxed{456} \).