What is the minimum number of times you have to take your pencil off the paper to draw the following figure (the dots are for decoration)? You must lift your pencil off the paper after you're done, and this is included in the number of times you take your pencil off the paper. You're not allowed to draw over an edge twice. 

[center][img]http://i.imgur.com/CBGmPmv.png[/img][/center]
To solve this problem, we need to determine the minimum number of times we have to lift the pencil to draw the given figure. This involves understanding the properties of the graph formed by the figure.

1. **Identify the vertices and their degrees**:
   - First, we need to identify all the vertices in the figure and count the degree (number of edges connected) of each vertex.
   - Let's denote the vertices as \( V_1, V_2, \ldots, V_n \).

2. **Count the vertices with odd degrees**:
   - According to graph theory, a vertex with an odd degree must be either a starting or an ending point of a path.
   - We count the number of vertices with odd degrees in the figure.

3. **Apply the Handshaking Lemma**:
   - The Handshaking Lemma states that the sum of the degrees of all vertices in a graph is even. Therefore, the number of vertices with odd degrees must be even.
   - Let’s denote the number of vertices with odd degrees as \( k \).

4. **Determine the number of paths**:
   - Each path in the graph will start and end at vertices with odd degrees.
   - Therefore, the minimum number of paths required to cover all edges without retracing any edge is \( \frac{k}{2} \).

5. **Include the final lift of the pencil**:
   - After drawing all the paths, we need to lift the pencil one final time.

6. **Construct the paths**:
   - We need to find a construction that uses the minimum number of paths. This involves finding a way to draw the figure such that the number of times we lift the pencil is minimized.

Given the solution provided, we know there are 10 vertices with odd degrees, so:

\[ k = 10 \]

Thus, the minimum number of paths required is:

\[ \frac{k}{2} = \frac{10}{2} = 5 \]

Including the final lift of the pencil, the total number of times we lift the pencil is:

\[ 5 + 1 = 6 \]

Therefore, the minimum number of times you have to take your pencil off the paper is 6.

The final answer is \( \boxed{6} \).