## Task 2 - 060512

A distance of $168 \mathrm{~m}$ in length was divided into three parts. The second part was three times as large as the first, while the third part was four times the length of the first part.

Calculate the lengths of the individual sections!
If the length of the first section is $a$, then the second section is $3 a$ long and the third is $4 a$ long. In total, this is $a+3 a+4 a=168 \mathrm{~m}$, which means the first section has a length of $a=21 \mathrm{~m}$.

The second section thus has a length of $3 \cdot 21 \mathrm{~m}=63 \mathrm{~m}$ and the third section $4 \cdot 21 \mathrm{~m}=84 \mathrm{~m}$.