$2.9 \quad \frac{x^{2}+x-5}{x}+\frac{3 x}{x^{2}+x-5}+4=0$.

Solve the equation:

$2.9 \quad \frac{x^{2}+x-5}{x}+\frac{3 x}{x^{2}+x-5}+4=0$.
2.9 Task. Use the substitution $\frac{x^{2}+x-5}{x}=z$.

Solution: $x_{1}=-5, x_{2}=1, x_{3,4}=-1 \pm \sqrt{6}$.