1. Set $A=\{2,0,1,7\}, B=\left\{x \mid x^{2}-2 \in A, x-2 \notin A\right\}$, then the product of all elements in set $B$ is
A. 36
B. 54
C. 72
D. 108
$$
\begin{array}{l}
x^{2}-2=2 \Rightarrow x= \pm 2 \Rightarrow x=-2 ; x^{2}-2=0 \Rightarrow x= \pm \sqrt{2} ; \\
x^{2}-2=1 \Rightarrow x= \pm \sqrt{3} ; x^{2}-2=7 \Rightarrow x= \pm 3 \Rightarrow x=-3,
\end{array}
$$

Then $B=\{-2,-3, \pm \sqrt{2}, \pm \sqrt{3}\}$, so the answer is $A$.