14. The sum of the digits of some natural number $A$ is $B$, the sum of the digits of number $B$ is $C$. It is known that the sum of the numbers $A$, $B$, and $C$ is 60. What is the number $A$? Are you sure you have found all solutions?
14. If the number $A$ is a two-digit number, and $B$ and $C$ are one-digit numbers, then: $A=\overline{x y}=10 x+y ; B=C=x+y$. From this: $A+B+C=12 x+3 y=60$ and $4 x+y=20$. Considering that $x$ and $y$ are digits, we find that $x=y=4$, or $x=5, y=0$. If the numbers $A$ and $B$ are two-digit numbers, and the number $C$ is a one-digit number, then $C=x+y-9$ and $A+B+C=12 x+3 y=69$, from which: $4 x+y=23$ and $x=4, y=7$. Answer: $44,47,50$.