An integer minus 77, then multiplied by 8, and divided by 7, the quotient is 37, and there is a remainder. This integer is $\qquad$
I analyze and solve the problem of inversion.
$$
37 \times 7+1=260,37 \times 7+2=261,37 \times 7+3=262,37 \times 7+4=263,37 \times 7+5=264,37 \times 7+6=265 \text {, among which } 8
$$

is a multiple of only $264$; $264 \div 8+77=110$; this integer is 110.