2. Determine the fraction that is equal to the fraction $\frac{73}{95}$, and the sum of the numerator and denominator is the smallest possible square of a natural number.
2. Let $\frac{73 k}{95 k}, k \in \mathbb{N}$ be the desired fraction.

Then it holds that $73 k + 95 k = n^{2}, n \in \mathbb{N}$, or $168 k = n^{2}$.

Further, $2 \cdot 2 \cdot 2 \cdot 3 \cdot 7 \cdot k = n^{2}$, so $k = 2 \cdot 3 \cdot 7$ or $k = 42$.

The desired fraction is $\frac{73 k}{95 k} = \frac{73 \cdot 42}{95 \cdot 42} = \frac{3066}{3990}$.