8. Player A and Player B are having a table tennis match, with a best-of-three format. In each game, the first to score 11 points and have the opponent with fewer than 10 points wins; after a 10-all tie, the first to score 2 more points wins. The total points scored by both A and B are 30 points. Without considering the order of the scores, the number of possible score combinations for the three games is.
【Answer】16
【Analysis】 $30<3 \times 11$, in three games, one person won two games, so at least two scores are no less than 11. The total score of player A is $30: 30=11+9+10$, and the corresponding scores of player B are: $30=7+10+12$; the corresponding scores are:
$\left\{\begin{array}{l}11: 6 \\ 8: 11 \\ 11: 13\end{array} 、\left\{\begin{array}{l}11: 5 \\ 7: 11 \\ 12: 14\end{array} 、\left\{\begin{array}{l}11: 4 \\ 7: 11 \\ 13: 15\end{array} 、\left\{\begin{array}{l}11: 3 \\ 6: 11 \\ 14: 16\end{array} 、\left\{\begin{array}{l}11: 2 \\ 5: 11 \\ 15: 17\end{array} 、\left\{\begin{array}{l}11: 1 \\ 4: 11 \\ 16: 18\end{array} 、\left\{\begin{array}{l}11: 0 \\ 3: 11 \\ 17: 19\end{array} 、\right.\right.\right.\right.\right.\right.\right.$
The above 8 cases are all where player B won, and there are also 8 cases where player A won, totaling $8 \times 2=16$ cases.