2. 8 girls and 25 boys stand in a circle, with at least two boys standing between any two girls. How many different arrangements are there (arrangements that can be made to coincide by rotating the circle are considered the same)?
2. Fix one of the girls as $A$, for any circular arrangement that meets the requirements, transform it into a linear arrangement starting from $A$ in a clockwise direction. Since each girl is followed by at least two boys, we can correspond each girl along with the two boys immediately following her to a black ball, and the remaining 9 boys each to a white ball. When only the differences between boys and girls are considered, and not the differences between girls and girls, or boys and boys, this correspondence is a one-to-one mapping, and the correspondence between the resulting arrangements is also a one-to-one mapping. Thus, the problem is reduced to calculating the number of all arrangements of 8 black balls and 9 white balls where the first ball is a black ball. Clearly, there are $C_{16}^{7}$ different arrangements in this case.

For each arrangement of black and white balls, each black ball corresponds to a group of three people, where the first is a girl and the next two are boys. Arranging the 7 girls other than $A$ into the last 7 groups of three, there are 7! ways to do this; arranging the 25 boys into 25 positions, there are 25! different ways. By the multiplication principle, the total number of arrangements sought is $16!25!/ 9!$ kinds.