2、Define new operations: $A \oplus B=A^{2}+B^{2}, A \otimes B=A$ divided by $\mathbf{B}$'s remainder, then $(2013 \oplus 2014) \otimes 10=$
【Answer】5
Analysis: $\left(2013^{2}+2014^{2}\right)$ modulo 10, 2013 $\div$ 10 has a remainder of $3$, 2014 $\div$ 10 has a remainder of 4, which means the remainder of $\left(2013^{2}+2014^{2}\right)$ modulo 10 is the same as the remainder of $\left(3^{2}+4^{2}\right)$ modulo 10, which is 5