1. There are 4 propositions:
(1) For any two skew lines in space, there exist infinitely many planes that form equal angles with these two lines.
(2) For any 3 pairwise skew lines in space, there exist infinitely many lines that intersect all three lines.
(3) For any 4 pairwise skew lines in space, there does not exist a line that intersects all four lines.
(4) If 3 planes intersect pairwise, producing 3 distinct intersection lines, then these 3 lines are concurrent. Among these, the false propositions are ( ).
A. 1
B. 2
C. 3
D. 4
1. B
(1) Through a point in space, it is evident that two parallel lines to the given two lines can be constructed, thus the described plane can be formed, correct.
(2) Let the three pairwise skew lines be $a, b, c$. Among all planes passing through $a$, there is only one that is parallel to $b$ and only one that is parallel to $c$. Therefore, there are infinitely many planes passing through $a$ and intersecting $b, c$, with intersection points $B, C$. Line $BC$ is either parallel or intersects with $a$, but there is at most one plane such that $BC \parallel a$. Thus, there are infinitely many planes where $BC$ intersects with $a$, meaning there are infinitely many lines $BC$ that intersect with $a, b, c$, correct.
(3) In a plane, construct 4 concurrent lines, with the common point being $K$. Draw a perpendicular line $l$ through $K$ to the plane. Take 4 different points on $l$, and through each point, draw a parallel line to one of the 4 lines, ensuring that parallel lines to all 4 lines are drawn. The 4 lines thus constructed serve as a counterexample, incorrect.
(4) These 3 intersection lines may be mutually parallel, incorrect.