2. Given that the sum of five distinct positive integers is 10,001. Then the minimum value of the least common multiple of these five positive integers is ( ).
(A) 2016
(B) 4032
(C) 2130
(D) 4380
2. D.

Let the least common multiple of five numbers be $M$. Then these five numbers can be represented as $\frac{M}{a}, \frac{M}{b}, \frac{M}{c}, \frac{M}{d}, \frac{M}{e}$, where $a, b, c, d, e$ are all positive integers.
$$
\begin{array}{l}
\text { Hence } \frac{1}{a}+\frac{1}{b}+\frac{1}{c}+\frac{1}{d}+\frac{1}{e}=\frac{10001}{M} \\
\leqslant \frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}=\frac{137}{60}=\frac{10001}{4380} \\
\Rightarrow M \geqslant 4380 .
\end{array}
$$

When the five numbers are $4380, 2190, 1460, 1095, 876$, the least common multiple takes the minimum value of 4380.