1. If the system of inequalities about $x$ $\left\{\begin{array}{l}11-2 x \geqslant 1, \\ x-t>0\end{array}\right.$, the sum of all integer solutions is 12, then the range of values for $t$ is
二、1. $2 \leqslant t<3$ or $-3 \leqslant t<-2$.
Solving the system of inequalities gives $t<x \leqslant 5$.
From the given information, the integer $x=5,4,3$ or $5,4, \cdots,-2$.
Therefore, $2 \leqslant t<3$ or $-3 \leqslant t<-2$.