2. In the summer, Ponchik eats honey cakes four times a day: instead of morning exercise, instead of a daytime walk, instead of an evening run, and instead of a nighttime swim. The quantities of cakes eaten instead of exercise and instead of a walk are in the ratio of $3: 2$; instead of a walk and instead of a run - as $5: 3$; and instead of a run and instead of a swim - as $6: 5$. By how many more or fewer cakes did Ponchik eat instead of exercise compared to instead of swimming on the day when a total of 216 cakes were eaten?
# Solution

According to the problem, we can establish the following ratios for the number of doughnuts eaten instead of engaging in a particular useful activity:

$$
\frac{\text { Morning Exercise }}{\text { Walk }}=\frac{3}{2} \quad \frac{\text { Walk }}{\text { Jog }}=\frac{5}{3} \quad \frac{\text { Jog }}{\text { Swim }}=\frac{6}{5}
$$

or equivalently,

$$
\frac{\text { Morning Exercise }}{\text { Walk }}=\frac{15}{10} \quad \frac{\text { Walk }}{\text { Jog }}=\frac{10}{6} \quad \frac{\text { Jog }}{\text { Swim }}=\frac{6}{5}
$$

From this, we can denote: Morning Exercise $=15 x$, Walk $=10 x$, Jog $=$ $6 x$, Swim $=5 x$. It is known that a total of 216 doughnuts were eaten, so

$$
15 x+10 x+6 x+5 x=216 \Rightarrow x=6
$$

Therefore, instead of morning exercise, Donut ate 90 doughnuts, and instead of swimming, he ate 30. Answering the question of the problem, Donut ate 60 more doughnuts instead of morning exercise than instead of swimming.

Answer: 60 more doughnuts.