6. A wire 104 centimeters long was bent into a rectangular frame. The length and width of this frame are whole numbers of centimeters. In how many ways can the frame be obtained?
6. First, let's determine what the sum of the length and width is, that is, we will calculate the semi-perimeter. For this, we divide 104 by 2 and get 52. Let's represent the number 52 as the sum of two addends:

$$
52=1+51=2+50=3+49=\ldots=25+27=26+26 \text {. }
$$

We get 26 ways.

Answer: 26 ways.