10.2. Each face of a rectangular parallelepiped $3 \times 4 \times 5$ is divided into unit squares. Is it possible to inscribe a number in each square so that the sum of the numbers in each cellular ring of width 1, encircling the parallelepiped, is equal to 120?
Answer: Yes, it is possible.

Example. In all the squares (two) of the $3 \times 4$ faces, we write the number 5, in all the squares (two) of the $3 \times 5$ faces, we write the number 8, and in all the squares (two) of the $4 \times 5$ faces, we write the number 9.

Verification: The sum of the numbers in each cell ring passing through edges of length 3 is $(4 \times 5 + 5 \times 8) \times 2 = 120$, the sum of the numbers in each cell ring passing through edges of length 4 is $(3 \times 5 + 5 \times 9) \times 2 = 120$, and the sum of the numbers in each cell ring passing through edges of length 5 is $(3 \times 8 + 4 \times 9) \times 2 = 120$.

Note. The example provided is not the only one. An answer without an example is 0 points, an answer with a correct example but without verification is 5 points. A system of equations (from which the correct example follows) is formulated but not solved, 3 points.