Daniel's age is one-ninth of his father's age. One year from now, Daniel's father's age will be seven times Daniel's age. The difference between their ages is
(A) 24
(B) 25
(C) 26
(D) 27
(E) 28
Daniel's age is one-ninth of his father's age. One year from now, Daniel's father's age will be seven times Daniel's age. The difference between their ages is
(A) 24
(B) 25
(C) 26
(D) 27
(E) 28

## Solution

Let Daniel's age be $d$. Then Daniel's father's age is $9 d$.

In one year, Daniel's age will be $d+1$ and Daniel's father's will be $9 d+1$.

![](https://cdn.mathpix.com/cropped/2024_04_20_748fdafcde2a47412608g-413.jpg?height=221&width=323&top_left_y=911&top_left_x=310)

Therefore, now Daniel's age is 3 and Daniel's father's age is 27, so the difference between their ages is 24 .

ANswer: (A)