In the diagram, $A B=25 \mathrm{~cm}, A C=20 \mathrm{~cm}$ and $\angle A=90^{\circ}$. What is the area of triangle $A B C$ ?
(A) $500 \mathrm{~cm}^{2}$
(B) $300 \mathrm{~cm}^{2}$
(C) $60 \mathrm{~cm}^{2}$
(D) $150 \mathrm{~cm}^{2}$
(E) $250 \mathrm{~cm}^{2}$

![](https://cdn.mathpix.com/cropped/2024_04_20_6027bc27089ed4fc493cg-076.jpg?height=297&width=334&top_left_y=274&top_left_x=1275)
Triangle $A B C$ has base $A B$ of length $25 \mathrm{~cm}$ and height $A C$ of length $20 \mathrm{~cm}$. Therefore, the area of triangle $A B C$ is $\frac{1}{2} b h=\frac{1}{2}(25 \mathrm{~cm})(20 \mathrm{~cm})=\frac{1}{2}\left(500 \mathrm{~cm}^{2}\right)=250 \mathrm{~cm}^{2}$.