A box of strawberries, containing $12$ strawberries total, costs $\$ 2$. A box of blueberries, containing $48$ blueberries total, costs $ \$ 3$. Suppose that for $\$ 12$, Sareen can either buy $m$ strawberries total or $n$ blueberries total. Find $n - m$.

[i]Proposed by Andrew Wu[/i]
1. First, determine how many boxes of strawberries Sareen can buy with $12. Each box of strawberries costs $2, so the number of boxes of strawberries is:
   \[
   \frac{12}{2} = 6 \text{ boxes}
   \]

2. Each box of strawberries contains 12 strawberries. Therefore, the total number of strawberries Sareen can buy is:
   \[
   6 \times 12 = 72 \text{ strawberries}
   \]

3. Next, determine how many boxes of blueberries Sareen can buy with $12. Each box of blueberries costs $3, so the number of boxes of blueberries is:
   \[
   \frac{12}{3} = 4 \text{ boxes}
   \]

4. Each box of blueberries contains 48 blueberries. Therefore, the total number of blueberries Sareen can buy is:
   \[
   4 \times 48 = 192 \text{ blueberries}
   \]

5. Now, we have \( m = 72 \) (strawberries) and \( n = 192 \) (blueberries). We need to find \( n - m \):
   \[
   n - m = 192 - 72 = 120
   \]

The final answer is \( \boxed{120} \).