8. Five points $A, B, C, D, E$ on a plane satisfy: $A B=8$ cm, $B C=4$ cm, $A D=5$ cm, $D E=1$ cm, $A C=12$ cm, $A E=6$ cm. If the area of triangle $E A B$ is 24 square cm, then the distance from point $A$ to $C D$ is $\qquad$ meters
【Key Point】Pythagorean Theorem
【Answer】 $\frac{60}{13}$
【Analysis】(1) Given $A B=8$ cm, $B C=4$ cm, $A C=12$ cm, it can be known that points $A, B, C$ are on the same straight line;
(3) The area of triangle $E A B$ is 24 square cm, $A B \times A E \times \frac{1}{2}=24$, which means $A B$ is perpendicular to $A E$. Draw the following diagram
(4) The problem is converted to finding the height of the hypotenuse $C D$ in right triangle $A C D$, i.e., the length of $A F$
$A B^{2}+A C^{2}=C D^{2}$, resulting in $C D=13$
$A C \times A D \times \frac{1}{2}=C D \times A F \times \frac{1}{2}$, solving for $A F=\frac{60}{13}$.