6. Person A draws five lines on a plane, with no three lines intersecting at the same point. If two lines determine an intersection point in the figure, A can get one piece of candy; if there is a set of parallel lines, A can also get one piece of candy. For example, in Figure 11, there are seven intersection points and one set of parallel lines, so A can get 8 pieces of candy. Question: What are the possible numbers of candies A can get?
6. $1,5 、 8 、 10$.

Consider the following scenarios:
(1) If no two lines are parallel, there are $C_{5}^{2}=10$ intersection points, and Jia can obtain 10 candies;
(2) If exactly two lines are parallel, there are $10-C_{2}^{2}=9$ intersection points and one set of parallel lines, and Jia can also obtain 10 candies;
(3) If exactly three lines are parallel, there are $10-C_{3}^{2}=7$ intersection points and one set of parallel lines, and Jia can obtain 8 candies;
(4) If exactly four lines are parallel, there are $10-C_{4}^{2}=4$ intersection points and one set of parallel lines, and Jia can obtain 5 candies;
(5) If there are exactly two sets of parallel lines, each with two lines, there are $10-\mathrm{C}_{2}^{2}-\mathrm{C}_{2}^{2}=8$ intersection points and two sets of parallel lines, and Jia can obtain 10 candies;
(6) If all five lines are parallel, there are 0 intersection points and one set of parallel lines, and Jia can obtain 1 candy;
(7) If there are exactly two sets of parallel lines, one with two lines and the other with three lines, there are $10-C_{2}^{2}-C_{3}^{2}=6$ intersection points and two sets of parallel lines, and Jia can obtain 8 candies.
In summary, the number of candies Jia can obtain is $1,5,8,10$.