8. (10 points) The pattern shown consists of 1 circle and 2 identical squares (the common part of the 2 squares is an octagon). If the radius of the circle is 60 cm, then the area of the shaded part is $\qquad$ square cm. ( $\pi$ is taken as 3.14)
【Solution】Solution:
As shown in the figure below: Connect $A B, A D$. Since $A D$ is the diameter of the circle, $\angle A B D=90^{\circ}$;

Let, $A B=a, B D=b$, that is: the small leg of the small right triangle $A B C$ is $a$ (the other 7 small right triangles are also $a$), and the side length of the 2 large squares is $b$;

By the Pythagorean theorem: $a^{2}+b^{2}=A D^{2}=(2 R)^{2}=120^{2}=14400$ (square centimeters);
The area of the small right triangle $A B C$ $=\frac{1}{2} \times A C \times B C=\frac{1}{4} a^{2}$, that is, the area of 4 right triangles equals $a^{2}$,
and $b^{2}$ represents the area of the large square;
Then: The area of 4 right triangles + the area of the large square $=14400$ (square centimeters);
From the figure, it can be seen that:
The total area of the figure $=$ the area of the regular octagon + the area of 8 small squares $;$ and the area of the large square $=$ the area of the regular octagon + the area of 4 small squares;

That is: The total area of the figure $=$ the area of the regular octagon + the area of 8 small squares $=$ the area of the regular octagon + the area of 4 small squares + the area of 4
small squares $=$ the area of the large square + the area of 4 small squares $=a^{2}+b^{2}=14400$ (square centimeters);
The area of the shaded part $=$ the total area of the figure - the area of the circle $=14400-\pi \gamma^{2}=14400-3.14 \times 60^{2}=3096$ (square centimeters).

Therefore, the answer is: 3096.