11. (15 points) Four people, A, B, C, and D, share 2013 candies. A gets 10 more than twice what B gets, 18 more than three times what C gets, and 55 less than five times what D gets. How many candies does A get?

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【Analysis】Let Jia get $x$ pieces of candy. According to the problem, we can get: Yi gets $\frac{1}{2} \times(x-10)$ pieces of candy, Bing gets $\frac{1}{3} \times(x$
- 18) pieces of candy, and Ding gets $\frac{1}{5} \times(x+55)$ pieces of candy. Based on the total of 2013 pieces of candy, we can set up the equation: $x+\frac{1}{2} \times(x$
- 10) $+\frac{1}{3} \times(x-18)+\frac{1}{5} \times(x+55)=2013$. We can solve this equation using the properties of equations.

【Solution】Solution: Let Jia get $x$ pieces of candy
$$
\begin{aligned}
x+\frac{1}{2} \times(x-10)+\frac{1}{3} \times(x-18)+\frac{1}{5} \times(x+55) & =2013 \\
2 \frac{1}{30} x & =2013 \\
2 \frac{1}{30} x \div 2 \frac{1}{30} & =2013 \div 2 \frac{1}{30} \\
x & =990
\end{aligned}
$$

Answer: Jia gets 990 pieces of candy.