1. Given non-zero real numbers $x, y$ satisfy
$$
\begin{array}{l}
(5 x+y)^{2019}+x^{2019}+30 x+5 y=0 . \\
\text { Then } \frac{x}{y}=
\end{array}
$$
- 1. $-\frac{1}{6}$.

The given equation can be transformed into
$$
(5 x+y)^{2019}+5(5 x+y)=-\left(x^{2019}+5 x\right) \text {. }
$$

Let $f(t)=t^{2019}+5 t$. Then $f(t)$ is a monotonic odd function on $\mathbf{R}$. Therefore,
$$
\begin{aligned}
f(5 x+y)=-f(x)=f(-x) \\
\Rightarrow 5 x+y=-x \Rightarrow \frac{x}{y}=-\frac{1}{6} .
\end{aligned}
$$