If $b \neq 0$, we define $a \oslash b=a b-\frac{a}{b}$. For example, $3 \oslash 1=3(1)-\frac{3}{1}=0$.

If $x=4 \triangleright 2$ and $y=2 \oslash 2$, what is the value of $x^{y}$ ?
Using the definition, $x=4 \odot 2=4(2)-\frac{4}{2}=6$ and $y=2 \odot 2=2(2)-\frac{2}{2}=3$.

Therfore, $x^{y}=6^{3}=216$.

ANSWER: 216