2. (10 points) YY's family of 3, plus YY's cousin, have a total age of 95 years this year. Dad is 4 years older than Mom, and YY is 3 years older than the cousin. 8 years ago, the sum of their ages was 65 years. Then Dad is $\qquad$ years old this year.
【Analysis】Since the sum of ages this year is 95 years. Then the sum of ages of the four people 8 years ago should be $95-8 \times 4=63$ years, while the actual sum of ages is 65 years, which means 2 years were over-subtracted, indicating that the cousin was not born 8 years ago, so the cousin's age this year is $8-2=6$ years, then YY's age is $6+3=9$ years, so the sum of the parents' ages is 95 - 6 - 9 = 80 years, and since the father is 4 years older than the mother, adding 4 to their age sum and then dividing by 2 will give the father's age.

【Solution】Solution: Since the sum of ages this year is 95 years. Then the sum of ages of the four people 8 years ago should be $95-8 \times 4$ $=63$ (years)

While the actual sum of ages is 65 years, which means 2 years were over-subtracted, indicating that the cousin was not born 8 years ago, so the cousin's age this year is $8-2=6$ (years)

Then YY's age is $6+3=9$ (years)
Then the father's age is $(95-9-6+4) \div 2$
$=84 \div 2$
$=42$ (years)
Answer: The father is 42 years old this year.
So the answer is: 42.