73. An electronic computer can quickly calculate the sum

$$
\frac{2}{1 \cdot 3}+\frac{2}{3 \cdot 5}+\frac{2}{5 \cdot 7}+\ldots+\frac{2}{99 \cdot 101}
$$

However, you can compete with it if you uncover the secret and rewrite the terms differently. How can this be done?
73. Since $\frac{2}{1 \cdot 3}=1-\frac{1}{3} ; \frac{2}{3 \cdot 5}=\frac{1}{3}-\frac{1}{5} ; \cdots \frac{2}{99 \cdot 101}=\frac{1}{99}-\frac{1}{101}$, we will have $1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\ldots+\frac{1}{99}-\frac{1}{101}=1-\frac{1}{101}=\frac{100}{101}$.