$2^{3} \times 2^{2} \times 3^{3} \times 3^{2}$ is equal to
(A) $6^{5}$
(B) $6^{6}$
(C) $6^{10}$
(D) $36^{10}$
(E) $36^{36}$
Using exponent rules, $2^{3} \times 2^{2} \times 3^{3} \times 3^{2}=2^{3+2} \times 3^{3+2}=2^{5} \times 3^{5}=(2 \times 3)^{5}=6^{5}$.

ANSWER: (A)