We call a number $n$ [i]interesting [/i]if for each permutation $\sigma$ of $1,2,\ldots,n$ there exist polynomials $P_1,P_2,\ldots ,P_n$ and $\epsilon > 0$ such that:
$i)$ $P_1(0)=P_2(0)=\ldots =P_n(0)$
$ii)$ $P_1(x)>P_2(x)>\ldots >P_n(x)$ for $-\epsilon<x<0$
$iii)$ $P_{\sigma (1)} (x)>P_{\sigma (2)}(x)> \ldots >P_{\sigma (n)} (x) $ for $0<x<\epsilon$
Find all [i]interesting [/i]$n$.

[i]Proposed by Mojtaba Zare Bidaki[/i]
To determine which numbers \( n \) are interesting, we need to analyze the conditions given in the problem. Let's break down the problem and the solution step by step.

### Step 1: Understanding the Conditions
We need to find polynomials \( P_1, P_2, \ldots, P_n \) and \( \epsilon > 0 \) such that:
1. \( P_1(0) = P_2(0) = \ldots = P_n(0) \)
2. \( P_1(x) > P_2(x) > \ldots > P_n(x) \) for \( -\epsilon < x < 0 \)
3. \( P_{\sigma(1)}(x) > P_{\sigma(2)}(x) > \ldots > P_{\sigma(n)}(x) \) for \( 0 < x < \epsilon \)

### Step 2: Lemma
We use the lemma that if for two polynomials \( H_i \) and \( H_j \), \( H_i > H_j \) for \( x \in (-\epsilon, 0) \) and \( H_i < H_j \) for \( x \in (0, \epsilon) \), then \( H_i(0) = H_j(0) \). This follows from the Intermediate Value Theorem (IVT), as the polynomial \( H_i(x) - H_j(x) \) must be zero at some point in \( (-\epsilon, \epsilon) \), and the only possibility is at \( x = 0 \).

### Step 3: Proving \( n = 4 \) is Not Interesting
Assume \( n = 4 \) is interesting. Consider the permutation \( \sigma \) such that \( \sigma(4) = 3 \), \( \sigma(3) = 1 \), \( \sigma(2) = 4 \), and \( \sigma(1) = 2 \). We need polynomials \( P_i \) such that:
1. \( P_1(0) = P_2(0) = P_3(0) = P_4(0) \)
2. \( P_1(x) > P_2(x) > P_3(x) > P_4(x) \) for \( x \in (-\epsilon, 0) \)
3. \( P_3(x) > P_1(x) > P_4(x) > P_2(x) \) for \( x \in (0, \epsilon) \)

By the lemma, we can write \( P_i(x) = xQ_i(x) + c \) for some real \( c \). This implies:
- \( Q_1(x) < Q_2(x) < Q_3(x) < Q_4(x) \) for \( x \in (-\epsilon, 0) \)
- \( Q_3(x) < Q_1(x) < Q_4(x) < Q_2(x) \) for \( x \in (0, \epsilon) \)

Applying the lemma to pairs \( (Q_3, Q_1) \), \( (Q_3, Q_2) \), and \( (Q_2, Q_4) \), we get \( Q_1(0) = Q_2(0) = Q_3(0) = Q_4(0) \). We can shift the polynomials such that \( Q_1(0) = 0 \). Let \( Q_i = xR_i(x) \). Then:
- \( R_1(x) > R_2(x) > R_3(x) > R_4(x) \) for \( x \in (-\epsilon, 0) \)
- \( R_3(x) < R_1(x) < R_4(x) < R_2(x) \) for \( x \in (0, \epsilon) \)

Applying the lemma again to pairs \( (R_1, R_2) \), \( (R_1, R_4) \), and \( (R_4, R_3) \), we get \( R_1(0) = R_2(0) = R_3(0) = R_4(0) \). This implies \( x^n \mid R_i \) for all \( n \in \mathbb{N} \), which is impossible. Hence, \( n = 4 \) is not interesting.

### Step 4: Proving \( n = 2 \) is Interesting
For \( n = 2 \), we can choose \( P_1(x) = x \) and \( P_2(x) = -x \). These polynomials satisfy:
1. \( P_1(0) = P_2(0) = 0 \)
2. \( P_1(x) > P_2(x) \) for \( x \in (-\epsilon, 0) \)
3. \( P_2(x) > P_1(x) \) for \( x \in (0, \epsilon) \)

### Step 5: Proving \( n = 3 \) is Interesting
For \( n = 3 \), we can choose \( P_1(x) = x \), \( P_2(x) = -x \), and \( P_3(x) = -2x \). These polynomials satisfy:
1. \( P_1(0) = P_2(0) = P_3(0) = 0 \)
2. \( P_1(x) > P_2(x) > P_3(x) \) for \( x \in (-\epsilon, 0) \)
3. For any permutation \( \sigma \), we can adjust the coefficients to satisfy the conditions for \( 0 < x < \epsilon \).

### Conclusion
From the above steps, we conclude that the only interesting numbers are \( n = 2 \) and \( n = 3 \).

The final answer is \( \boxed{ n = 2, 3 } \)