In the sum shown, $P, Q$ and $R$ represent three different single digits. The value of $P+Q+R$ is
(A) 13
(D) 3
(B) 12
(C) 14
(E) 4

| $P 7 R$ |
| ---: |
| $+\quad 39 R$ |
| $R Q 0$ |
Since the second number being added is greater than 300 and the sum has hundreds digit $R$, then $R$ cannot be 0 .

From the ones column, we see that the ones digit of $R+R$ is 0 . Since $R \neq 0$, then $R=5$.

This makes the sum

$$
\begin{array}{r}
P \quad 15 \\
+\quad 3 \quad 95 \\
\hline 5 Q 0
\end{array}
$$

Since $1+7+9=17$, we get $Q=7$ and then $1+P+3=5$ and so $P=1$, giving the final sum

$$
\begin{array}{r}
1175 \\
1395 \\
\hline 570
\end{array}
$$

Therefore, $P+Q+R=1+7+5=13$.

ANSWER: (A)