## 3. Spheres

In a red and blue box, there are a total of 105 spheres. After transferring as many spheres from the red box to the blue box as there were in the blue box initially, the red box had 13 more spheres than the blue box. Determine five times the difference between the initial number of spheres in the red and blue boxes.

## Result: $\quad 295$
## Solution:

Let's graphically represent the given conditions.
![](https://cdn.mathpix.com/cropped/2024_05_30_adbfbded7af8db94c594g-2.jpg?height=982&width=1632&top_left_y=747&top_left_x=204)

In the blue box, there are 23 balls, and in the red box, there are $105-23=82$ balls.

Five times the difference is $5 \cdot(82-23)=5 \cdot 59=295$.