1.6 Using 6 straight lines, a regular 12-sided polygon is divided into 12 congruent shapes, there are ( ) ways.
(A) 1 way
(B) 2 ways
(C) more than 2 ways
(D) infinitely many ways
-1. (D).
Obviously, $A_{1} A_{7}$, $A_{2} A_{8}$, $A_{3} A_{9}$, $A_{4} A_{10}$, $A_{5} A_{11}$, and $A_{6} A_{12}$ divide the regular dodecagon $A_{1} A_{2} A_{3} \cdots A_{10} A_{11} A_{12}$ into 12 congruent triangles. With the center $O$ of the regular dodecagon as the center, rotate $A_{1} A_{7}$, $A_{2} A_{8}$, $A_{3} A_{9}$, $A_{4} A_{10}$, $A_{5} A_{11}$, and $A_{6} A_{12}$ in the same direction by an angle $\alpha$ $\left(0^{\circ}<\alpha<30^{\circ}\right)$ to reach $A_{1}^{\prime} A_{7}^{\prime}$, $A_{2}^{\prime} A_{8}^{\prime}$, $A_{3}^{\prime} A_{9}^{\prime}$, $A_{4}^{\prime} A_{10}^{\prime}$, $A_{5}^{\prime} A_{11}^{\prime}$, and $A_{6}^{\prime} A_{12}^{\prime}$, respectively. According to the properties of central symmetry and the criteria for congruent figures, it is easy to know: $A_{1}^{\prime} A_{7}^{\prime}$, $A_{2}^{\prime} A_{8}^{\prime}$, $A_{3}^{\prime} A_{9}^{\prime}$, $A_{1}^{\prime} A_{10}^{\prime}$, $A_{5}^{\prime} A_{11}^{\prime}$, and $A_{6}^{\prime} A_{12}^{\prime}$ divide the regular dodecagon $A_{1} A_{2} \cdots A_{11} A_{12}$ into 12 congruent figures.