2. (6 points) If the side length of a large regular hexagon is equal to the perimeter of a small equilateral triangle, then the area of the large regular hexagon is $\qquad$ times the area of the small equilateral triangle.
【Solution】Solution: According to the analysis,
Since each large equilateral triangle is similar to the small equilateral triangle,
And since the side length of the large equilateral triangle: the side length of the small equilateral triangle $=1: 3$,
Therefore, the area of each large equilateral triangle is $3^{2}=9$ times the area of the small equilateral triangle,
Therefore, the area of this large regular hexagon is the area of the small equilateral triangle: $6 \times 9=54$ times.
Answer: The area of this large regular hexagon is 54 times the area of the small equilateral triangle.
So the answer is: 54.