If $\sqrt{4+9+x^{2}}=7$, then a possible value for $x$ is
(A) 6
(B) 2
(C) 4
(D) 36
(E) 0
Since $\sqrt{4+9+x^{2}}=7$, then $4+9+x^{2}=7^{2}$ or $13+x^{2}=49$ or $x^{2}=36$.

Therefore, the possible values for $x$ are $x= \pm 6$. Therefore, the answer is (A).

ANSwer: (A)