2. (10 points) As shown in the figure, there is a row of trees with equal spacing but different heights. The roots of the trees form a straight line, and the tops of the trees also form a straight line, with these two lines forming a 45-degree angle. The tallest tree is 2.8 meters high, and the shortest tree is 1.4 meters high. The height of the 4th tree from left to right is ( ) meters.
A. 2.6
B. 2.4
C. 2.2
D. 2.0
2. (10 points) As shown in the figure, there is a row of trees with equal spacing but different heights. The roots of the trees form a straight line, and the tops of the trees also form a straight line. These two lines form a 45-degree angle. The tallest tree is 2.8 meters high, and the shortest tree is 1.4 meters high. What is the height of the 4th tree from left to right? ( )
A. 2.6
B. 2.4
C. 2.2
D. 2.0
【Analysis】Since $\angle A=45^{\circ}$, the tallest tree is 2.8 meters high, so $A C=2.8$ meters. Also, because the roots of the trees form a straight line and the tops of the trees form a straight line, all the trees are parallel to each other, so $A B=1.4$ meters, $B C=A C-A B=1.4$ meters. Since the spacing between the trees is the same, each spacing is $1.4 \div 7=0.2$ meters. Therefore, the height of the 4th tree from left to right is: $0.2 \times 4+1.4$. Solve accordingly.
【Solution】Solution: Because:

The roots of the trees form a straight line, and the tops of the trees form a straight line, $\angle A=45^{\circ}$, the tallest tree is 2.8 meters high, and the shortest tree is 1.4 meters high,

So $A C=2.8$ meters, $A B=1.4$ meters, $B C=A C-A B=1.4$ meters,
Also, because: the spacing between the trees is the same,
So:
$1.4 \div 7=0.2$ (meters)
$0.2 \times 4+1.4$
$=0.8+1.4$
$=2.2$ (meters)
Answer: The height of the 4th tree from left to right is 2.2 meters.
Therefore, the correct choice is: $C$.