9.044. $\frac{\sqrt{17-15 x-2 x^{2}}}{x+3}>0$.

9.044. $\frac{\sqrt{17-15 x-2 x^{2}}}{x+3}>0$.
## Solution.

The given inequality is equivalent to a system of two inequalities

$$
\left\{\begin{array} { l } 
{ 17 - 15 x - 2 x ^ { 2 } > 0 , } \\
{ x + 3 > 0 }
\end{array} \Leftrightarrow \left\{\begin{array} { l } 
{ 2 x ^ { 2 } + 15 x - 17 < 0 , } \\
{ x > -3 }
\end{array} \Leftrightarrow \left\{\begin{array}{l}
-\frac{17}{2} < x < 1
\end{array}\right.\right.\right.
$$

Answer: $\quad x \in(-3 ; 1)$.