3. From the numbers $1,2,3,4,5$, randomly draw 3 numbers (repetition allowed) to form a three-digit number, the probability that the sum of its digits equals 9 is
A. $\frac{13}{125}$
B. $\frac{16}{125}$
C. $\frac{18}{125}$
D. $\frac{19}{125}$
3. $\mathrm{D} \quad 9=1+3+5=1+4+4=2+2+5=2+3+4=3+3+3$, there are $6+3+3+6+1=$ 19 ways, so the probability is $\frac{19}{125}$.