8. (10 points) As shown in the figure, the six vertices of the hexagon are marked as $A, B, C, D, E, F$. Initially, the six Chinese characters “华罗庚金杯赛” are located at the vertices $A, B, C, D, E, F$ respectively. If the six characters are arbitrarily rearranged at the vertices, such that each vertex still has one character, and each character is at a vertex adjacent to its initial position, then the number of different arrangements is $\qquad$ kinds.
【Analysis】Obviously, there are only two cases, which need to be discussed separately: swapping two adjacent characters, and moving one position clockwise or counterclockwise. Finally, the total number of different arrangements can be obtained.

【Solution】According to the analysis, there are two types of situations:
(1) Moving one position in sequence, moving one position clockwise, there are 1 different arrangement method, moving one position counterclockwise, there are 1 different arrangement method;
(2) Swapping two adjacent positions, there are: 2 different arrangement methods in total.

In summary, there are: $1+1+2=4$ different arrangement methods.
Therefore, the answer is: 4.