9.179. $|x-6|>\left|x^{2}-5 x+9\right|$.
## Solution.

Since $x^{2}-5 x+9>0$ for $x \in R$, the given inequality has the form $|x-6|>x^{2}-5 x+9$. It is equivalent to two inequalities

1) $x-6>x^{2}-5 x+9 \Leftrightarrow x^{2}-6 x+15<0, \varnothing$;
2) $x-6<-x^{2}+5 x-9 \Leftrightarrow x^{2}-4 x+3<0 \Leftrightarrow 1<x<3$.

Answer: $x \in(1 ; 3)$.