One side of a rectangle has length 18. The area plus the perimeter of the rectangle is 2016. Find the
perimeter of the rectangle.
1. Let \( l = 18 \) be the length of one side of the rectangle, and let \( w \) be the width of the rectangle.
2. The area \( A \) of the rectangle is given by:
   \[
   A = l \cdot w = 18w
   \]
3. The perimeter \( P \) of the rectangle is given by:
   \[
   P = 2l + 2w = 2(18) + 2w = 36 + 2w
   \]
4. According to the problem, the sum of the area and the perimeter is 2016:
   \[
   A + P = 2016
   \]
   Substituting the expressions for \( A \) and \( P \):
   \[
   18w + (36 + 2w) = 2016
   \]
5. Simplify and solve for \( w \):
   \[
   18w + 36 + 2w = 2016
   \]
   \[
   20w + 36 = 2016
   \]
   \[
   20w = 2016 - 36
   \]
   \[
   20w = 1980
   \]
   \[
   w = \frac{1980}{20}
   \]
   \[
   w = 99
   \]
6. Now, substitute \( w = 99 \) back into the expression for the perimeter:
   \[
   P = 36 + 2w
   \]
   \[
   P = 36 + 2(99)
   \]
   \[
   P = 36 + 198
   \]
   \[
   P = 234
   \]

The final answer is \(\boxed{234}\)