1. If the cube root of $\sqrt{125}$ is $A$, and the square root of $\sqrt{25}$ is $B$. Then $A+B=(\quad)$.
(A) $2 \sqrt{5}$ or 0
(B) 10 or 0
(C) $2 \sqrt{5}$
(D) 10
-1. A.
Since the cube root of $\sqrt{125}$ is $\sqrt{5}$, and the square root of $\sqrt{25}$ is $\pm \sqrt{5}$, therefore, $A+B=2 \sqrt{5}$ or 0.