11. Given point $A(3,1)$, $F$ is the focus of the parabola $y^{2}=5 x$, and $M$ is a moving point on the parabola. When $|M A|+|M F|$ takes the minimum value, the coordinates of point $M$ are $\qquad$
11. $\left(\frac{1}{5}, 1\right)$.

Let the directrix of the parabola be $l: x=-\frac{5}{4}$.
Draw a perpendicular from point $M$ to $l$, with the foot of the perpendicular being $H$. Then $|A M|+|M F|=|A M|+|M H| \geqslant|A H|$.
When points $A$, $M$, and $H$ are collinear, the equality holds, at which point, the point $M\left(\frac{1}{5}, 1\right)$.