It is known that the remainder of dividing a certain prime number by 60 is a composite number. Which one?
Since $60=2^{2} \cdot 3 \cdot 5$, the remainder cannot be a multiple of the numbers 2, 3, or 5 (otherwise, the original number would have the same property and could not be prime). Since the remainder is less than 60 and is the product of at least two prime factors, it is equal to 7$\cdot$7. Other options are not possible, as the next product of two prime numbers ( $7 \cdot 11$ ) is greater than 60.

## Answer

49. 

## Problem