2. A string 60 dm long was cut into three pieces. The length of one of them is 1 cm more than another and 1 cm less than the third. Find the length of each piece.
2. First method of solving. Let's make a drawing according to the problem statement.

![](https://cdn.mathpix.com/cropped/2024_05_21_e53d4ff4f2278a1c0d12g-170.jpg?height=360&width=1111&top_left_y=1396&top_left_x=470)

1) $600-3=597$ cm - the length of the string if all parts were as small as the smallest one
2) $597: 3=199$ cm - the length of the first part;
3) $199+1=200$ cm - the length of the second part;
4) $200+1=201$ cm - the length of the third part.

Second method of solving. Let's denote one part of the rope as $a$, then the other is $a-1$, and the third is $a+1$. Since the length of the rope is 600 cm (60 dm $=600$ cm), we can form the equation: $a + a - 1 + a + 1 = 600, 3a = 600, a = 200$ cm. Now let's find the lengths of the other two parts: $200 - 1 = 199, 200 + 1 = 201$.

Answer: the length of the first part is 199 cm, the second is $200$ cm, and the third is $201$ cm.