3. The sum and the quotient of two numbers are both 6, then the product of these two numbers minus the difference of these two numbers (larger minus smaller) equals ( ).
(A) $26 \frac{4}{7}$
( B ) $5 \frac{1}{7}$
( C ) $\frac{6}{7}$
(D) $\frac{4}{49}$
Analysis: This is a simple multiple problem. It is easy to get the larger number as $\frac{36}{7}$, and the smaller number as $\frac{6}{7}$. The product of the two numbers is $\frac{36}{7} \times \frac{6}{7}=\frac{216}{49}$, and the difference between the two numbers is $\frac{36}{7}-\frac{6}{7}=\frac{30}{7}$. The product of these two numbers minus the difference between these two numbers (larger minus smaller) equals $\frac{216}{49}-\frac{30}{7}=\frac{6}{49}$, so the answer is D.