5. (7 points) There is a sequence of numbers: $1,1,2,3,5,8,13,21, \cdots$, starting from the third number, each number is the sum of the two preceding ones. How many of the first 2007 numbers are even?
【Analysis】Since the sum of the first two numbers is even, i.e., odd + odd = even; similarly, the fourth number is: odd + even = odd, and so on, always odd, odd, even, odd, odd, even $\cdots$; every three numbers form a cycle, then determine how many cycle periods are in 2007 numbers, and then combine the remainder to find the number of even numbers.
【Solution】Solution: $2007 \div 3=669$,
Also, because each cycle period contains 2 odd numbers and 1 even number,
Therefore, the number of even numbers in the first 2007 numbers is: $1 \times 669=669$;
Answer: In the first 2007 numbers, 699 are even numbers.
So the answer is: 699.