3-5. Determine the maximum value of the ratio of a three-digit number to the number equal to the sum of the digits of this number.
Solve 5. Answer: 100. The sum of the digits of a three-digit number \(100a + 10b + c\) is \(a + b + c\). It is clear that \(\frac{100a + 10b + c}{a + b + c} \leqslant 100\). Moreover, for the number 100, the given ratio is 100.

\section*{8th Grade}