2. As shown in Figure 1, $A C=B C, D C=E C, \angle A C B=$ $\angle E C D=90^{\circ}$, and
$\angle E B D=42^{\circ}$. Then the degree measure of $\angle A E B$ is ( ).
(A) $128^{\circ}$
(B) $130^{\circ}$
(C) $132^{\circ}$
(D) $134^{\circ}$
$$
\begin{array}{l}
\text { It is easy to see that } \triangle A C E \cong \triangle B C D . \\
\text { Therefore, } \angle C A E = \angle C B D . \\
\text { Then, } \angle A E B = \angle C A E + \angle E B C + 90^{\circ} \\
= \angle C B D + \angle E B C + 90^{\circ} \\
= \angle E B D + 90^{\circ} = 132^{\circ} .
\end{array}
$$