5. (10 points) A school organizes a hiking activity, planning to depart from location A at 10:10 AM and arrive at location B at 13:10 PM. However, they departed 5 minutes late and arrived 4 minutes early. They arrived at location C, which is exactly on schedule. What is the arrival time at location C? ( )
A. 11:40 AM
B. 11:50 AM
C. 12:00 PM
D. 12:10 PM
【Analysis】First, analyze the plan: departing from location A at 10:10, arriving at location B at 13:10, the time is 3 hours. Departing 5 minutes late, but arriving 4 minutes early, the time difference is 9 minutes. According to the proportional relationship, the solution can be found.

【Solution】Solution: According to the problem:
The plan is to depart from location A at 10:10 and arrive at location B at 13:10, which is 3 hours.
Departing 5 minutes late, but arriving 4 minutes early, the time difference is 9 minutes.
Every hour, 3 minutes are caught up, meaning every 20 minutes, 1 minute is caught up.
100 minutes catch up 5 minutes.
100 minutes after 10:10 is 11:50.
Therefore, the answer is: $B$.