7.1. Form three irreducible (not necessarily proper) fractions, the product of which is 1, using six numbers from the set $\{1,2,3,4,5,6,7,8,9\}$ as numerators and denominators. (Each number can be used once or not at all).
Answer: for example, $3 / 8, 4 / 9, 6 / 1$ or $3 / 4, 6 / 1, 2 / 9$.

Path to solution: Obviously, 5 and 7 cannot be used because there would be nothing to cancel them with, the remaining numbers consist of twos and threes in their factorization, by distributing them, we construct the example.

Criterion: Any correct set of fractions - 7 points. It is understood that 5 and 7 cannot be used, but the example is not constructed - 1 point.