## 43. Calves, Cows, Pigs, Chickens

The dowry of a young peasant girl consists of a cow, a calf, a pig, and a chicken. Her fiancé knew that five cows, seven calves, nine pigs, and one chicken together cost 108210 francs, and also that a cow is 4000 francs more expensive than a calf, that three calves cost as much as ten pigs, and that 3000 chickens cost as much as five calves. Based on all this information, he tried to calculate the value of his bride's dowry - but he failed. Could you help him?
43. Let $c$ be the price of a pig. Then the price of a calf is $(10 / 3) c$, and therefore, the price of a cow is $(10/3)c+4000$ and the price of a chicken is $(5 / 3000) \cdot(10 / 3) \cdot c$.

Considering the first piece of information the suitor had, we get

$$
(50 / 3) c+20000+(70 / 3) c+9 c+c / 180=108210
$$

from which it follows that

$$
c=1800 \text {. }
$$

The dowry of the bride, therefore, amounts to

$$
6000+10000+1800+10=17810 \text { francs. }
$$