Points $P(15,55), Q(26,55)$ and $R(26,35)$ are three vertices of rectangle $P Q R S$. The area of this rectangle is
(A) 360
(B) 800
(C) 220
(D) 580
(E) 330

![](https://cdn.mathpix.com/cropped/2024_04_20_46ead6524a8d61e21c51g-017.jpg?height=252&width=442&top_left_y=657&top_left_x=1294)
The $y$-coordinates of points $P(15,55)$ and $Q(26,55)$ are equal.

Therefore, the distance between $P$ and $Q$ is equal to the positive difference between their $x$-coordinates, or $26-15=11$.

Similary, the $x$-coordinates of points $R(26,35)$ and $Q(26,55)$ are equal.

Therefore, the distance between $R$ and $Q$ is equal to the positive difference between their $y$-coordinates, or $55-35=20$.

Since $P Q=11$ and $R Q=20$, the area of rectangle $P Q R S$ is $11 \times 20=220$.

ANSwer: (C)