14. (12 points) The letters in the figure below represent different numbers within $1-9$. Adjacent cells can form 24 two-digit numbers (such as $\overline{\mathrm{AB}}, \overrightarrow{\mathrm{BA}}, \overline{\mathrm{GD}}$). Three numbers in the same row or column can form 12 three-digit numbers (such as $\overline{\mathrm{ABC}}, \overrightarrow{\mathrm{BEH}}$, $\overrightarrow{\mathrm{HEB}}$). Among these 36 numbers, the maximum number of composite numbers is $\qquad$.
【Solution】Solution: According to the problem, the only two-digit prime numbers related to 5 are 53 and 59, so $E$ is 5. Also, 3, 6, and 9, no matter how they are combined, always form two-digit or three-digit composite numbers, so we consider $C=3, F=6, I=9$. At this point, $H=4, 49$, and 94 are all composite numbers. The remaining four numbers are $1, 2, 7, 8$. If the unit digit is even, the number must be a composite number, so we consider $A=8$, $G=2$, and thus $D=1, B=7$. At this point, among the 36 numbers, only $13, 31, 457$ are not composite numbers, so among the 36 numbers, the maximum number of composite numbers is 33. Therefore, the answer is 33.