94. How many six-digit numbers are there in which three digits are even and three are odd?
94. The places for odd digits can be chosen in $C_{6}^{3}=20$ ways. On each of the remaining three places, there will be an even digit. Thus, after choosing places for the odd digits, each digit of the required six-digit number can be chosen in five ways (either even or odd). In total, we get $20 \cdot 5^{6}$ numbers. However, among them will be those that start with zero. There are $C_{5}^{3} \cdot 5^{5}=10 \cdot 5^{5}$ such numbers. Finally, we get $20 \cdot 5^{6}-10 \cdot 5^{6}=281250$ required six-digit numbers.