8. Line $l$ :
$$
m(2 x-y-5)+(3 x-8 y-14)=0
$$

is intercepted by circle $\odot A$ with center $A(1,0)$ and radius 2, the length of the shortest chord is ( ).
(A) $\sqrt{2}$
(B) $\sqrt{3}$
(C) $2 \sqrt{2}$
(D) $2 \sqrt{3}$
8. C.

Given that the line $l$ passes through the fixed point $B(2,-1)$, and $A B=\sqrt{2}$ $<2$, we know that point $B$ is inside $\odot A$.

When the line $l$ is perpendicular to $A B$, the chord intercepted by the line $l$ on $\odot A$ is the shortest, and the length of the shortest chord is $2 \sqrt{2}$.