4. (8 points) In the following horizontal equation, the same Chinese characters represent the same digits, different Chinese characters represent different digits, and no Chinese character represents 7. "迎", "春", and "杯" are not equal to 1. Therefore, the sum of the three digits represented by "迎", "春", and "杯" is $\qquad$
Learn math $\times 7 \times$ Welcome $\times$ Spring $\times$ Cup $=$ Cheer up cheer up $\times$ Bar.
【Answer】Solution: If it contains 5, then it must be "add", at this time $\overline{\text { add }}=56,3$ and 9 each remain one, which cannot be satisfied, so it does not contain 5, add is a multiple of 7, and is not 49, consider the distribution of $3,6,9$.

First case, if $=9$, then 3,6 are on the left, and add is not a multiple of 3, then add $=14$ or 28, no solution; second case, 9 is on the left, then 3,6 are on the right, we can get $1 \times 2 \times 4 \times 9 \times 7=63 \times 8$, so the sum of the three digits represented by “welcome”, “spring”, “cup” is 15. Therefore, the answer is 15.