A1. The equation $0, \overline{3}-\frac{1}{\frac{1}{x}-\frac{1}{3}}=3$ has the solution:
(A) $x=-24$
(B) $x=3$
(C) $x=-3$
(D) $x=24$
(E) $x=0$
A1. The number $0, \overline{3}$ can be written as the fraction $\frac{1}{3}$. We then rearrange the equation to $\mathrm{v} \frac{1}{3}-\frac{3 x}{3-x}=3$ and $\mathrm{v} 3-x-9 x=$ $27-9 x$, from which we express $x=-24$.