149 The size order of the four real numbers $\sin 1, \sin 2, \sin 3, \sin 4$ is
A. $\sin 4<\sin 3<\sin 1<\sin 2$
B. $\sin 4<\sin 3<\sin 2<\sin 1$
C. $\sin 4<\sin 2<\sin 3<\sin 1$
D. None of the above answers is correct
149 A. Since $\sin 1>0, \sin 2=\sin (\pi-2)>0, \sin 3=\sin (\pi-3)>0, \sin 4=$ $\sin (4-\pi)<0$, and $0<\pi-3<1<\pi-2<\frac{\pi}{2}$, we have
$$
\sin 4<\sin 3<\sin 1<\sin 2
$$