1. If real numbers $x, y$ satisfy $(x+5)^{2}+(y-12)^{2}=14^{2}$, then the minimum value of $x^{2}+y^{2}$ is
A. 2
B. 1
C. $\sqrt{3}$
D. $\sqrt{2}$
1. B Hint: Combine geometric and algebraic thinking, notice that $(x+5)^{2}+(y-12)^{2}=14^{2}$ is a circle with center $C(-5,12)$ and radius 14. Let $P$ be any point on the circle, then $|O P| \geqslant|C P|-|O C|=14-13=1$.