14. There is a large square containing two smaller squares. These two smaller squares can move freely within the large square (no part of the smaller squares can move outside the large square, and the sides of the smaller squares must be parallel to the sides of the large square). If the minimum overlapping area of the two smaller squares is 9, and the maximum overlapping area is 25, and the sum of the side lengths of the three squares (one large square and two smaller squares) is 23, then the sum of the areas of the three squares is ( ).


【Analysis】The maximum overlapping area is the area of the smallest square, which is 25. Let the side length of the middle square be $\mathrm{x}$, then the side length of the large square is $x+5-3=x+2$. Therefore, according to the sum of the three side lengths, we can set up the following equation: $5+x+x+2=23$, solving for $x$ gives $x=8$, so the sum of the areas of the three squares is: $5^{2}+8^{2}+10^{2}=189$.