8. (10 points) It is known that the speed of the EMU (Electric Multiple Unit) train is twice that of the ordinary fast train. The speed of the EMU train increases by $25 \%$ to reach the speed of the high-speed train. The average speed of the high-speed train and the ordinary fast train is 15 kilometers/hour faster than the express train, and the average speed of the EMU train and the ordinary fast train is 10 kilometers/hour slower than the express train. Therefore, the speeds of the high-speed train and the ordinary fast train are $\qquad$ kilometers/hour and $\qquad$ kilometers/hour.
【Analysis】Let the speed of the ordinary express train be $x$ km/h, then the speed of the EMU (Electric Multiple Unit) train is $2 x$ km/h, and the speed of the high-speed train is $(1+25 \%) \times 2 x=2.5 x$ km/h. According to the given conditions: the average speed of the high-speed train and the ordinary express train is 15 km/h faster than the special express train, and the average speed of the EMU train and the ordinary express train is 10 km/h slower than the special express train, which means the average speed of the high-speed train and the ordinary express train is 25 km/h faster than the average speed of the EMU train and the ordinary express train. We can set up an equation to solve for $x$.

【Solution】Solution: Let the speed of the ordinary express train be $x$ km/h, then the speed of the EMU train is $2 x$ km/h, and the speed of the high-speed train is $(1+25 \%) \times 2 x=2.5 x$ km/h, then
$$
\begin{array}{c}
\frac{\mathrm{x}+2.5 \mathrm{x}}{2}-\frac{\mathrm{x}+2 \mathrm{x}}{2}=15+10, \\
1.75 x-1.5 x=25 \\
0.25 x=25 \\
0.25 x \div 0.25=25 \div 0.25 \\
2.5 x=2.5 \times 100=250 \quad x=100
\end{array}
$$

Answer: The speeds of the high-speed train and the ordinary express train are 250 km/h and 100 km/h, respectively. Therefore, the answer is: 250, 100.