In the number $74982.1035$ the value of the place occupied by the digit 9 is how many times as great as the value of the place occupied by the digit 3?
$\text{(A)}\ 1,000 \qquad \text{(B)}\ 10,000 \qquad \text{(C)}\ 100,000 \qquad \text{(D)}\ 1,000,000 \qquad \text{(E)}\ 10,000,000$
The digit $9$ is $5$ places to the left of the digit $3$. Thus, it has a place value that is $10^5 = 100,000$ times greater.
$\boxed{\textbf{(C)}}$