[Text problems (other)]

Forty gold and forty silver coins were distributed among three empty chests, with both types of coins in each chest. In the first chest, there were 7 more gold coins than silver ones, and in the second chest, there were 15 fewer silver coins than gold ones. Which type of coin is more in the third chest and by how many?

#
In the first two chests, the total number of gold coins is $7+15=22$ more than the total number of silver coins. Since initially, the number of gold and silver coins was equal, in the third chest, there are 22 fewer gold coins than silver.

## Answer

There are 22 more silver coins.