6. Given four points in the Cartesian plane $A(1,0)$, $B(3,0)$, $C(0,1)$, $D(6,1)$. Then the coordinates of the point in the Cartesian plane that minimizes the sum of the squares of the distances to these four points are $\qquad$ -
$6 .\left(\frac{5}{2}, \frac{1}{2}\right)$