14. (6 points) A bucket contains some water. If the water is increased to 4 times its original amount, the total weight of the bucket and water is 16 kilograms; if the water is increased to 6 times its original amount, the total weight of the bucket and water is 22 kilograms. Then the bucket originally contained \qquad kilograms of water, and the bucket weighs \qquad kilograms.
【Analysis】According to the problem, the weight of the bucket remains unchanged. The (22-16) kilograms of water is (6-4) times the original amount of water. From this, we can find the original weight of the water, and thus the weight of the bucket.

【Solution】Solution: The original amount of water in the bucket:
$$
\begin{aligned}
& (22-16) \div(6-4), \\
= & 6 \div 2, \\
= & 3 \text { (kg), }
\end{aligned}
$$

Weight of the bucket: $16-4 \times 3$,
$$
\begin{array}{l}
=16-12, \\
=4 \text { (kg); }
\end{array}
$$

Answer: The bucket originally contained 3 kg of water, and the bucket weighs 4 kg.
Therefore, the answers are: 3,4.