10. There are 70 points on a circle, choose one of them and label it 1, then label the point two points clockwise from it as 2, the point three points clockwise from the last as 3, then the point four points clockwise from the last as 4, and continue this operation until $1,2,3, \cdots, 2014$ are all marked on the points. Each point may be labeled with more than one number. What is the smallest integer marked on the point that is labeled 2014? $\qquad$
【Answer】5
【Explanation】Find the pattern, the pattern between the number of points and the marked numbers
\begin{tabular}{|l|l|l|l|l|l|l|l|}
\hline Number & 1 & 2 & 3 & 4 & 5 & $\cdots \cdots$ & $\mathrm{n}$ \\
\hline Points & 1 & 3 & 6 & 10 & 15 & $\cdots \cdots \cdot$ & $\frac{n(n+1)}{2}$ \\
\hline
\end{tabular}

So $\frac{2014 \times(2014+1)}{2}=2029105, 2029105 \div 70$ has a remainder of 15, so the smallest integer is 5.