Júlio and Denise had lunch at a restaurant that offers three types of dishes and three types of vitamins, whose prices are in the table below. Each chose a dish and a vitamin. Júlio spent 6 reais more than Denise. How much did Denise spend?

|  | $\mathrm{R} \$$ |
| :--- | :---: |
| simple dish | 7 |
| dish with meat | 11 |
| dish with fish | 14 |
| milk vitamin | 6 |
| fruit vitamin | 7 |
| special vitamin | 9 |
The prices of a dish plus a vitamin are

![](https://cdn.mathpix.com/cropped/2024_05_01_666a1aec7e447b0a6cbeg-062.jpg?height=108&width=908&top_left_y=2036&top_left_x=654)

Among these, the ones that differ by 6 are 14 and 20, or 17 and 23. Therefore, we have two solutions: either Denise spends $7+7=14$ and Júlio $14+6=11+9=20$, or Denise spends $11+6=17$ and Júlio $14+9=23$.