B. For any real numbers $x, y, z$, the operation “*” is defined as
$$
x * y=\frac{3 x^{3} y+3 x^{2} y^{2}+x y^{3}+45}{(x+1)^{3}+(y+1)^{3}-60} \text {, }
$$

and $x * y * z=(x * y) * z$.
Then $2013 * 2012 * \cdots * 2=$ ( ).
(A) $\frac{607}{967}$
(B) $\frac{1821}{967}$
(C) $\frac{5463}{967}$
(D) $\frac{16389}{967}$
B. C.
$$
\begin{array}{l}
\text { Let } 2013 * 2012 * \cdots * 4 = m \text {. Then } \\
(2013 * 2012 * \cdots * 4) * 3 = m * 3 \\
=\frac{3 m^{3} \times 3 + 3 m^{2} \times 9 + m \times 27 + 45}{m^{3} + 3 m^{2} + 3 m + 1 + 64 - 60} = 9 \text {. } \\
\text { Therefore, } (2013 * 2012 * \cdots * 3) * 2 \doteq 9 * 2 \\
=\frac{3 \times 9^{3} \times 2 + 3 \times 9^{2} \times 2^{2} + 9 \times 2^{3} + 45}{10^{3} + 3^{3} - 60} = \frac{5463}{967} . \\
\end{array}
$$