3. (8 points) The advertising slogan for battery $A$ is “One is stronger than six”, which means that battery $A$ is more efficient than other batteries. We assume that the power of one $A$ battery is 6 times that of a $B$ battery. There are two clocks with the same power consumption rate. Now, 4 $A$ batteries are installed in clock A, and 3 $B$ batteries are installed in clock B. As a result, clock B operates normally for 2 months before the batteries are depleted. How many more months can clock A operate normally compared to clock B? $\qquad$ months.
【Solution】Solution: According to the analysis, the power ratio of each battery of $A$ and $B$ is $6: 1$, the ratio of the number of batteries of Jia and Yi is $4: 3$, then the total power ratio is $(6 \times 4):(1 \times 3)=8: 1, \because$ the power consumption rate of the two clocks is the same,
$\therefore$ the working time is proportional to the total power, clock Yi has worked for 2 months, the normal working time of clock Jia is: $8 \times 2=$ 16 months,

more than clock Yi by: $16-2=14$ months.
Therefore, the answer is: 14.