7. If the three interior angles $A, B, C$ of $\triangle A B C$ satisfy $\cos A=\sin B=2 \tan \frac{C}{2}$, then the value of $\sin A+\cos A+2 \tan A$ is $\qquad$.
Obviously, $B$ is an obtuse angle, then $\cos A=\cos \left(B-90^{\circ}\right) \Rightarrow B-A=90^{\circ} \Rightarrow 2 A+C=90^{\circ}$, thus $\cos A=2 \tan \left(45^{\circ}-A\right)=\frac{2(1-\tan A)}{1+\tan A} \Rightarrow 2-2 \tan A=\cos A+\sin A$ $\Rightarrow \sin A+\cos A+2 \tan A=2$.