1. As shown in Figure 3, it is known that
$$
\begin{array}{l}
A B=2, B C=A E=6, \\
C E=C F=7, B F=8 .
\end{array}
$$

Then the ratio of the area of quadrilateral $A B D E$ to the area of $\triangle C D F$ is $\qquad$ .
$=1.1$.
Since $A C=B F=8, C E=C F=7, B C=A E=6$, therefore, $\triangle A E C \cong \triangle B C F$. $=S_{\triangle A C F}-S_{\triangle B D C}=S_{\triangle C D F}$.