If $x=11, y=8$, and $2 x+3 z=5 y$, what is the value of $z$ ?
(A) 6
(B) $\frac{62}{3}$
(C) 13
(D) 15
(E) $\frac{46}{5}$
Since $x=11, y=8$ and $2 x+3 z=5 y$, then $2 \times 11+3 z=5 \times 8$ or $3 z=40-22$.

Therefore, $3 z=18$ and so $z=6$.

ANsWer: (A)

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