7. A mowing team had to mow two meadows, one twice as large as the other. For half a day, the team mowed the larger meadow. After that, they split in half: one half stayed on the large meadow and finished it by evening, while the other half mowed the smaller meadow but did not finish it. How many mowers were in the team, if it is known that the remaining work was completed by one mower on the following day?
7. If the whole brigade mowed a large meadow for half a day and half of the brigade mowed for another half a day, it is clear that the brigade mowed $\frac{2}{3}$ of the meadow in half a day, and half of the brigade mowed $\frac{1}{3}$ of the meadow in half a day. Since the second meadow is half the size of the first, after working on it with half of the brigade for half a day, the uncut area is $\frac{1}{2}-\frac{1}{3}=\frac{1}{6}$. This area was mowed by one mower in one day. Therefore, one mower mows $\frac{1}{6}$ of the meadow in one day, and the whole brigade mows $\frac{4}{3}$. Answer: there were 8 mowers in the brigade.