Anna thinks of an integer.

- It is not a multiple of three.
- It is not a perfect square.
- The sum of its digits is a prime number.

The integer that Anna is thinking of could be
(A) 12
(B) 14
(C) 16
(D) 21
(E) 26
12 and 21 are multiples of $3(12=4 \times 3$ and $21=7 \times 3)$ so the answer is not (A) or (D).

16 is a perfect square $(16=4 \times 4)$ so the answer is not $(\mathrm{C})$.

The sum of the digits of 26 is 8 , which is not a prime number, so the answer is not (E).

Since 14 is not a multiple of a three, 14 is not a perfect square, and the sum of the digits of 14 is $1+4=5$ which is prime, then the answer is 14 , which is choice (B).

ANSWER: (B)