Find all positive integers $N$ such that an $N\times N$ board can be tiled using tiles of size $5\times 5$ or $1\times 3$. 

Note: The tiles must completely cover all the board, with no overlappings.
1. **Define the problem and initial observations:**
   We need to find all positive integers \( N \) such that an \( N \times N \) board can be completely tiled using tiles of size \( 5 \times 5 \) or \( 1 \times 3 \). The tiles must cover the board completely without any overlaps.

2. **Identify non-good integers:**
   - For \( N = 1 \), \( N = 2 \), and \( N = 4 \), the total number of cells in the board is \( N^2 \), which are 1, 4, and 16 respectively. None of these numbers are divisible by 3, and since we cannot use \( 5 \times 5 \) tiles (as they are too large), these boards cannot be tiled using \( 1 \times 3 \) tiles alone. Hence, \( N = 1, 2, 4 \) are not good.

3. **Identify good integers:**
   - For \( N = 3 \), the board has \( 3^2 = 9 \) cells, which can be tiled using three \( 1 \times 3 \) tiles.
   - For \( N = 5 \), the board has \( 5^2 = 25 \) cells, which can be tiled using one \( 5 \times 5 \) tile.
   - For \( N = 7 \), the board has \( 7^2 = 49 \) cells. We can tile this board using one \( 5 \times 5 \) tile and four \( 1 \times 3 \) tiles to cover the remaining 24 cells (as shown in the attachment).

4. **Generalize the solution:**
   - If \( n \) is a good integer, then \( n + 3 \) is also a good integer. This is because we can add a row and a column of \( 1 \times 3 \) tiles to the \( n \times n \) board to cover the additional cells. This implies that if \( n \) is good, then \( n + 3k \) for any integer \( k \geq 0 \) is also good.

5. **List all good integers:**
   - Starting from \( N = 3 \), we have \( 3, 6, 9, 12, \ldots \).
   - Starting from \( N = 5 \), we have \( 5, 8, 11, 14, \ldots \).
   - Starting from \( N = 7 \), we have \( 7, 10, 13, 16, \ldots \).

6. **Conclusion:**
   - The integers \( N \) that are not good are \( N = 1, 2, 4 \).
   - All other positive integers \( N \) are good.

The final answer is \( \boxed{ N \ne 1, 2, 4 } \).