8. $y=\tan 1935 x-\tan 2021 x+\tan 2107 x$ has $\qquad$ zeros in the interval $[0, \pi]$.

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8. $y=\tan 1935 x-\tan 2021 x+\tan 2107 x$ has $\qquad$ zeros in the interval $[0, \pi]$.
8.2022 .

Notice,
$$
\begin{array}{l}
\tan 1935 x + \tan 2107 x \\
= \frac{2 \tan 2021 x}{1 - \tan ^{2} 2021 x}(1 - \tan 1935 x \cdot \tan 2107 x) .
\end{array}
$$

Then $\tan 1935 x + \tan 2107 x = \tan 2021 x$
$$
\begin{array}{l} 
\Leftrightarrow \frac{2 \tan 2021 x}{1 - \tan ^{2} 2021 x}(1 - \tan 1935 x \cdot \tan 2107 x) \\
= \tan 2021 x \\
\Leftrightarrow \tan 2021 x = 0 \text{ or } \\
1 + \tan ^{2} 2021 x = 2 \tan 1935 x \cdot \tan 2107 x . \\
\text{ Also } 1 + \tan ^{2} 2021 x - 2 \tan 1935 x \cdot \tan 2107 x \\
= 1 + (\tan 1935 x + \tan 2107 x)^{2} - \\
2 \tan 1935 x \cdot \tan 2107 x \\
= 1 + \tan ^{2} 1935 x + \tan ^{2} 2107 x \\
> 0,
\end{array}
$$

Therefore, only $\tan 2021 x = 0 \Rightarrow x = \frac{k \pi}{2021}$.
Since $x \in [0, \pi]$, then $k = 0, 1, \cdots, 2021$. Thus, there are 2022 zeros.