(Column 1 Use the monotonicity of logarithmic functions to arrange the following four numbers in ascending order: $\log _{\frac{1}{2}} 0.3$, $\log _{3} 0.2,0,1$.)
The function $f(x)=\log _{\frac{1}{2}} x$ is a decreasing function, $\log _{\frac{1}{2}} 0.3>\log _{\frac{1}{2}} 0.5=1$; the function $f(x)=\log _{3} x$ is an increasing function, $\log _{3} 0.2<\log _{3} 1=0$. Therefore, $\log _{3} 0.2<0<1<\log _{\frac{1}{2}} 0.3$.
Explanation In comparing sizes, 1 is often regarded as $\log _{a} a$, and 0 is regarded as $\log _{a} 1$.