G2.1 By removing certain terms from the sum, $\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+\frac{1}{8}+\frac{1}{10}+\frac{1}{12}$, we can get 1 . What is the product of the removed term(s)?
$$
\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+\frac{1}{12}=\frac{3}{4}+\frac{1}{4}=1
$$

The removed terms are $\frac{1}{8} ; \frac{1}{10}$.
$$
\text { Product }=\frac{1}{80}
$$