11. Define $a \oplus b=(a+2)(b+2)-2$. The calculation result of $1 \times 3 \times 5 \times 7 \times 9 \times 11 \times 13-(1 \bigcirc 30507 \sim 9011)$ is $\qquad$
【Analysis】 $a \oplus b \bullet c=[(a+2)(b+2)-2+2](c+2)-2=(a+2)(b+2)(c+2)-2$, thus 1 - 3 - $911=(1+2)(3+2) \cdots(11+2)-2=3 \times 5 \times 7 \times 9 \times 11 \times 13-2$ so the result of the original expression is 2