13. (15 points) Person A and Person B start from points A and B simultaneously, walking towards each other. Person A walks 70 meters per minute, and Person B walks 60 meters per minute. They meet at a point 80 meters away from the midpoint. Find the distance between points A and B.
【Analysis】Jia and Yi meet 80 meters away from the midpoint, which means Jia has traveled $80 \times 2=160$ (meters) more than Yi. The speed difference between the two is $70-60=10$ (meters/minute). By dividing the distance difference by the speed difference, we can find the meeting time, then calculate the speed sum, and multiply the meeting time by the speed sum to find the distance between $A$ and $B$.
$$
\begin{array}{l} 
\text { 【Solution】Solution: }(80 \times 2) \div(70-60) \\
= 160 \div 10 \\
= 16 \text { (minutes) } \\
(70+60) \times 16 \\
= 130 \times 16 \\
= 2080 \text { (meters) }
\end{array}
$$

Answer: The distance between $A$ and $B$ is 2080 meters.