1. The product of three natural numbers is 240. The product of the first and second number is 60, and the product of the first and third number is 24. What are these numbers?
Solution. From the condition of the problem, it follows that $a \cdot b \cdot c=240, a \cdot b=60, a \cdot c=24$. Then from (a.b) $\mathrm{c}=240$ and $\mathrm{a} \cdot \mathrm{b}=60$ we have $60 \cdot \mathrm{c}=240$ which means $c=4$. Due to $\mathrm{a} \cdot \mathrm{c}=24$ we get that $a=6$. Then from $a \cdot b=60$ we get that $b=10$.