244. One median of a triangle is twice as long as another. Find its sides if they are expressed as integers.
244. Denoting the sides corresponding to the given medians by $x$ and $y(y>x)$, and the third side by $z$, we obtain the equation:

$$
2 z^{2}=2 y^{2}-3 x^{2} \quad(1)
$$

We can represent it as $\frac{2 y+2 z}{x}=\frac{3 x}{y-z}=\frac{m}{n}$, which gives us $x=4 m n, y=m^{2}+6 n^{2}, z=m^{2}-6 n^{2}$.

From the conditions $x>0, y>0, z>0, zy-x$ we find $\frac{m}{n}>3$.

Example. $m=4, n=1, x=16, y=22, z=10$.