6. (10 points) From the 11 integers $1 \sim 11$, any 6 numbers are taken. Then the number of correct conclusions below is ( ).
(1) There must be two numbers that are coprime;
(2) There must be one number that is a multiple of another number;
(3) There must be one number whose double is a multiple of another number.
A. 3
B. 2
C. 1
D. 0
【Analysis】(1) According to the definition of coprime numbers, two numbers whose only common factor is 1 are called coprime numbers. Among these 11 numbers, the prime numbers are $2, 3, 5, 7, 11$. Any two prime numbers are definitely coprime. Also, among these 11 numbers, there are five even numbers: $2, 4, 6, 8, 10$, and six odd numbers. Therefore, when any 6 numbers are taken, there must be two numbers that are coprime.
(2) For example, taking five even numbers and one odd number, among these five even numbers, $4, 6, 8, 10$ are all multiples of 2. If taking $1, 3, 5, 7, 9, 11$, 9 is a multiple of 3; if taking $6, 7, 8, 9, 10, 11$, there is no multiple relationship.
(3) For example, 2 is the 2 times of 1, and 2 is a multiple of 2; 4 is the 2 times of 2, and 4 is a multiple of 4. According to this, the answer is as follows.

【Solution】According to the above analysis: From the 11 integers from 1 to 11, any 6 numbers taken, (1) there must be two numbers that are coprime; this statement is correct.
(3) there must be one number whose 2 times is a multiple of another number. This statement is correct. Therefore, the answer is: $B$.