7, 10 consecutive four-digit numbers whose sum is a multiple of 37, the smallest sum of these 10 numbers is
【Analysis】Let the smallest number be $a$, then the sum of the 10 numbers is $(a+a+9) \times 10 \div 2=5(2 a+9)$, so $2 a+9$ is a multiple of 37, and $a$ is a four-digit number, so $2 a+9$ is at least 2009, and it must be a multiple of 37, and an odd number, so the smallest value is 2035, the minimum sum of the 10 numbers is $5 \times 2035=10175$