12. (5 points) Three people, A, B, and C, compare the number of candies they each have.
A says: “I have 13, 3 less than B, and 1 more than C.”
B says: “I am not the one with the least, C and I differ by 4, and A has 11.”
C says: “I have fewer than A, A has 10, and B has 2 more than A.”
If each person has one false statement among the three they made, then the person with the least candies has $\qquad$ candies.
【Answer】Solution: Jia says "I have 13, 3 less than Yi" is in contradiction with Bing saying "Jia has 10, Yi has 2 more than Jia", Jia's statements are one right and one wrong, so Yi saying Jia has 11 must be wrong, the first two statements are correct; assuming Jia has 13, then Yi has 2 more than Jia, Yi would have 15, Jia has 1 more than Bing, Bing would have 12, but Bing and Yi do not differ by 4, contradiction, the assumption does not hold;

Therefore, Jia has 10, Bing has 9, Yi has 13,
$13>10>9$, the least is 9.
Answer: The person with the least candies has 9 candies.
So the answer is: 9.