1. Given the sequences $\left\{a_{n}\right\} 、\left\{b_{n}\right\} 、\left\{c_{n}\right\}$ are all arithmetic sequences, and
$$
a_{1}+b_{1}+c_{1}=0, a_{2}+b_{2}+c_{2}=1 .
$$

Then $a_{2015}+b_{2015}+c_{2015}=$ $\qquad$
$-, 1.2014$.
Notice, $\left\{a_{n}+b_{n}+c_{n}\right\}$ is an arithmetic sequence with the first term 0 and common difference 1.
Therefore, $a_{2015}+b_{2015}+c_{2015}=2014$.