5. (10 points) Adding the digits of a number to get a new number is called one operation. A number that can become 6 after several such operations is called a "good number". The number of "good numbers" not exceeding 2012 is $\qquad$, and the greatest common divisor of these "good numbers" is $\qquad$.
5. (10 points) Adding the digits of a number to get a new number is called one operation. A number that can become 6 after several such operations is called a "good number". The number of "good numbers" not exceeding 2012 is $\qquad$ 223, and the greatest common divisor of these "good numbers" is $\qquad$.

【Analysis】The "good numbers" in the problem actually refer to the numbers less than or equal to 2012 that leave a remainder of 6 when divided by 9, i.e., the sequence 6, 15, 24, etc. The greatest common divisor of 6 and 15 is the greatest common divisor of this sequence.

【Solution】Solution: $(2014-6) \div 9+1$
$$
\begin{array}{l}
=1998 \div 9+1 \\
=222+1 \\
=223 \text { (numbers); }
\end{array}
$$
The greatest common divisor of 6 and 15 is 3, so the greatest common divisor of all "good numbers" is 3.
Answer: The number of "good numbers" not exceeding 2012 is 223, and the greatest common divisor of these "good numbers" is 3.
Therefore, the answers are: 223, 3.