Xavier, Yolanda, and Zixuan have a total of $\$ 50$. The ratio of the amount Xavier has to the total amount Yolanda and Zixuan have is $3: 2$. Yolanda has $\$ 4$ more than Zixuan. How much does Zixuan have?
(A) $\$ 16$
(B) $\$ 8$
(C) $\$ 14$
(D) $\$ 13$
(E) $\$ 30$
Since Xavier, Yolanda and Zixuan have $\$ 50$ in total, and the ratio of the amount that Xavier has to the amount that the other two have is $3: 2$, then Xavier has $\frac{3}{5}$ of the total, or $\frac{3}{5} \times \$ 50=\$ 30$. Therefore, Yolanda and Zixuan together have $\$ 50-\$ 30=\$ 20$.

We know that Yolanda has $\$ 4$ more than Zixuan, so we must break $\$ 20$ into two parts, one of which is $\$ 4$ larger than the other.

If Yolanda has $\$ 12$ and Zixuan has $\$ 8$, this satisfies the requirements.

Therefore, Zixuan has $\$ 8$.

ANswer: (B)