9.027. $(x+1)(3-x)(x-2)^{2}>0$.
Solution.

We have

$$
(x+1)(x-3)(x-2)^{2}<0,\left\{\begin{array} { l } 
{ ( x + 1 ) ( x - 3 ) < 0 , } \\
{ x - 2 \neq 0 }
\end{array} \Leftrightarrow \left\{\begin{array}{l}
-1<x<3 \\
x \neq 2
\end{array}\right.\right.
$$

Answer: $\quad x \in(-1 ; 2) \cup(2 ; 3)$.