A cube has a volume of $125 \mathrm{~cm}^{3}$. What is the area of one face of the cube?
(A) $20 \mathrm{~cm}^{2}$
(B) $25 \mathrm{~cm}^{2}$
(C) $41 \frac{2}{3} \mathrm{~cm}^{2}$
(D) $5 \mathrm{~cm}^{2}$
(E) $75 \mathrm{~cm}^{2}$
A cube has a volume of $125 \mathrm{~cm}^{3}$. What is the area of one face of the cube?
(A) $20 \mathrm{~cm}^{2}$
(B) $25 \mathrm{~cm}^{2}$
(C) $41 \frac{2}{3} \mathrm{~cm}^{2}$
(D) $5 \mathrm{~cm}^{2}$
(E) $75 \mathrm{~cm}^{2}$

## Solution

If the volume of the cube is $125 \mathrm{~cm}^{3}$, then the length, width and height are each $5 \mathrm{~cm}$.

The area of one face is $5 \times 5$ or $25 \mathrm{~cm}^{2}$.

ANSWER: (B)