The natural numbers from 1 to 2100 are entered sequentially in 7 columns, with the first 3 rows as shown. The number 2002 occurs in column $m$ and row $n$. The value of $m+n$ is

|  | Column 1 | Column 2 | Column 3 | Column 4 | Column 5 | Column 6 | Column 7 |
| :---: | :---: | :---: | :---: | :---: | :---: | :---: | :---: |
| Row 1 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Row 2 | 8 | 9 | 10 | 11 | 12 | 13 | 14 |
| Row 3 | 15 | 16 | 17 | 18 | 19 | 20 | 21 |
| $\vdots$ | $\vdots$ | $\vdots$ | $\vdots$ | $\vdots$ | $\vdots$ | $\vdots$ | $\vdots$ |

(A) 290
(B) 291
(C) 292
(D) 293
(E) 294
If we divide 2002 by 7 , we see that $2002=7(286)$. Since there are 7 natural numbers in each row, and the last entry in each row is the multiple of 7 corresponding to the row number, then 2002 must lie in the $7^{\text {th }}$ column of the $286^{\text {th }}$ row. So $m=7, n=286$, and $m+n=293$.