## Problem Statement

Calculate the limit of the function:

$\lim _{x \rightarrow-3} \frac{x^{2}+2 x-3}{x^{3}+4 x^{2}+3 x}$
## Solution

$$
\begin{aligned}
& \lim _{x \rightarrow-3} \frac{x^{2}+2 x-3}{x^{3}+4 x^{2}+3 x}=\left\{\frac{0}{0}\right\}=\lim _{x \rightarrow-3} \frac{(x+3)(x-1)}{(x+3)\left(x^{2}+x\right)}= \\
& =\lim _{x \rightarrow-3} \frac{x-1}{x^{2}+x}=\frac{-3-1}{(-3)^{2}-3}=\frac{-4}{9-3}=-\frac{4}{6}=-\frac{2}{3}
\end{aligned}
$$

## Problem Kuznetsov Limits 10-26