## Task 6 - 040516

The sum of two natural numbers is 968. One of the addends ends with a zero. If you remove this zero, you get the other number.

Determine these two numbers!
The last digit of the smaller number must be 8. Then 8 is also the middle digit of the larger number.

From the given sum, it is easy to see that the two addends must be 88 and 880. As a formula:

$$
a+b=968 \quad ; \quad a=10 \cdot b
$$

Substitution yields $10 \cdot b+b=968$ with $b=88$ and consequently $a=880$.