105. All integers are written in a row, starting from one. Determine which digit stands at the $206788-\mathrm{th}$ place.

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105. There are nine single-digit numbers, $99-9=90$ two-digit numbers, $999-99=900$ three-digit numbers, and generally $9 \cdot 10^{n-1}$ $n$-digit numbers.

Single-digit numbers will occupy nine places in the sequence we have written, two-digit numbers $90 \cdot 2=180$ places, three-digit numbers $900 \cdot 3=2700$ places, four-digit numbers $9000 \cdot 4=36000$ places, and five-digit numbers $90000 \cdot 5=$ $\Leftarrow 450000$ places. From this, it is clear that the digit we are interested in will belong to a five-digit number.

Digits belonging to numbers with no more than four digits will have numbers from 1 to $9+180+2700+36000=38889$. To find out how many five-digit numbers will fit in the interval from the 38889th place to the 206788th, we need to divide the difference $206788-38889=167899$ by 5 (division with remainder):

$$
206788-38889=5 \cdot 33579+4
$$

Thus, the digit we are looking for will belong to the 33579th five-digit number, i.e., the number 43579 (since the first five-digit number is 10000). In this number, the digit we are interested in is in the 4th place. Therefore, the digit we are looking for is 7.