7. In the expansion of $\left(x+\frac{4}{x}-4\right)^{5}$, the coefficient of $x^{3}$ is $\qquad$ .(answer with a specific number)
$$
\left(x+\frac{4}{x}-4\right)^{5}=\left(\sqrt{x}-\frac{2}{\sqrt{x}}\right)^{10}, T_{r+1}=C_{10}^{r}(\sqrt{x})^{10-r}\left(-\frac{2}{\sqrt{x}}\right)^{r}=(-2)^{r} C_{10}^{r} x^{5-r} \text {, }
$$

Take $r=2 \Rightarrow T_{3}=4 \cdot 45 x^{3}=180 x^{3}$.