Four boys bought a boat for $\textdollar 60$. The first boy paid one half of the sum of the amounts paid by the other boys; 
the second boy paid one third of the sum of the amounts paid by the other boys; 
and the third boy paid one fourth of the sum of the amounts paid by the other boys. How much did the fourth boy pay? 
$\textbf{(A) }\textdollar 10\qquad \textbf{(B) }\textdollar 12\qquad \textbf{(C) }\textdollar 13\qquad \textbf{(D) }\textdollar 14\qquad \textbf{(E) }\textdollar 15$
If the first boy paid one half of the sum of the amounts paid by the other boys, that means that he paid $\frac{1}{3}$ of the total.
If the second boy paid one third of the sum of the amounts paid by the other boys, that means that he paid $\frac{1}{4}$ of the total.
If the third boy paid one fourth of the sum of the  amounts paid by the other boys, that means that he paid $\frac{1}{5}$ of the total. 
Summing it up, we get $\textdollar 20 + \textdollar 15 + \textdollar 12 = \textdollar 47$.
Therefore, our answer is $\textdollar 60 - \textdollar 47 = \boxed{\textbf{(C) }\textdollar 13}$
~awin