41. In a triangle, two altitudes are not less than the sides to which they are dropped. Find the angles of the triangle.
41. Answer: angles of the triangle $-90^{\circ}, 45^{\circ}, 45^{\circ}$.

Let $h_{a}$ and $h_{b}$ be the heights dropped to sides $a$ and $b$. By the condition, $a \leqslant h_{a}, b \leqslant h_{b}$, but in any triangle $h_{a} \leqslant b_{2} h_{b} \leqslant$ $\leqslant a$, so $a \leqslant h_{a} \leqslant b \leqslant h_{b} \leqslant a$.

Thus, $a=b=h_{a}=h_{b}$, i.e., the triangle is isosceles and right-angled.