11. (3 points) The Yirong ferry has a speed of 40 kilometers per hour. On odd days, it sails downstream from $A$ to $B$, and on even days, it sails upstream from $B$ to $A$. (The water speed is 24 kilometers per hour.) On one odd day, the ferry lost power while sailing to the midpoint $C$ and could only drift to $B$. The captain noted that the time used that day was $\frac{43}{18}$ times the original time on odd days. On another even day, the ferry lost power while sailing to the midpoint $C$, and during the drift, the repair crew worked for 1 hour to fix it, after which the ferry proceeded to $A$ at twice its speed. The captain found that the time used that day was exactly the same as the original time on even days. What is the distance between $A$ and $B$ in kilometers?
【Analysis】Two equal relationships are: the time required to travel downstream from $A$ to $C$ + the time required to drift downstream from $B$ to $C$ = the time required to travel downstream from $A$ to $B$ $\times \frac{43}{18} ;$ the time required to travel upstream from $B$ to $C$ + the repair time + the time required to travel upstream from $(A, C$ distance + 24 kilometers $)$ = the time required to travel upstream from $A$ to $B$. Substituting the relevant values will solve the problem.

【Solution】Let the distance between $A$ and $B$ be $x$ kilometers, and the distance between $A$ and $C$ be $y$ kilometers, then
$$
\begin{array}{l}
\text { we have }\left\{\begin{array}{l}
\frac{x}{40+24} \times \frac{43}{18}=\frac{y}{40+24}+\frac{x-y}{24} \\
\frac{x}{40-24}=\frac{x-y}{40-24}+1+\frac{y+24}{2 \times 40-24}
\end{array}\right. \\
\left\{\begin{array}{l}
\frac{x}{64} \times \frac{43}{18}=\frac{y}{64}+\frac{x-y}{24} \\
\frac{x}{16}=\frac{x-y}{16}+1+\frac{y+24}{56}
\end{array}\right. \\
\text { Solving, we get }\left\{\begin{array}{l}
x=192 \\
y=32
\end{array}\right.
\end{array}
$$

Answer: The distance between $A$ and $B$ is 192 kilometers.