## Task B-1.3.

The father is 33 years older than his daughter, and 11 years ago, the daughter was 4 times younger than him. How old is the father?
## Solution.

If we denote the father's age by $x$, the daughter's age is $x-33$. Then:

$$
\begin{aligned}
x-11 & =4 \cdot(x-33-11) \\
x-11 & =4 x-176 \\
x & =55
\end{aligned}
$$

The father is 55 years old.

(1 point)