The first three terms of an arithmetic progression are $x - 1, x + 1, 2x + 3$, in the order shown. The value of $x$ is: 
$\textbf{(A)}\ -2\qquad\textbf{(B)}\ 0\qquad\textbf{(C)}\ 2\qquad\textbf{(D)}\ 4\qquad\textbf{(E)}\ \text{undetermined}$
Let $y$ represent the common difference between the terms. We have $(x+1)-y=(x-1)\implies y=2$.
Substituting gives us $(2x+3)-2=(x+1)\implies 2x+1=x+1\implies x=0$.
Therefore, our answer is $\boxed{\textbf{(B)}\ 0}$;