7. The inverse function of $y=f(x)$ is $y=f^{-1}(x), y=f(x-1)$ passes through the point $(3,3)$. Then the graph of the function $y=f^{-1}(x+2)$ must pass through the point
$$
=.7 .(1,2) \text {. }
$$

From the problem, we have $f^{-1}(3)=2$, which means $f^{-1}(1+2)=2$. Therefore, it passes through the point $(1,2)$.