Three players agree that the loser will owe the winners as much as each winner has. After three games, each player has lost once. How much did they start with, if at the end of the game each had 8 crowns?
At the beginning of the game, $A$, $B$, and $C$ had $x$, $y$, and $24-x-y$ K each. After the first game, $A$ had $2$ K left, because in the next two games he quadrupled it. Therefore,

$$
x-y-(24-x-y)=2 x-24=2, \text{ so } x=13 \text{ K}.
$$

After the second game, $B$ had $4$ K left, so

$$
2 y-2-2(24-x-y)=4 y-24=4, y=7 \text{ K}.
$$

Thus, at the beginning of the game, $C$ had $24-x-y=4 \text{ K}$.