G3.4 Given that $5^{\log 30} \times\left(\frac{1}{3}\right)^{\log 0.5}=d$, find the value of $d$.
$\begin{array}{l}\log 30 \log 5+\log 0.5 \log \frac{1}{3}=\log d \\ \log (3 \times 10) \log \frac{10}{2}+(-\log 2)(-\log 3)=\log d \\ (\log 3+1)(1-\log 2)+\log 2 \log 3=\log d \\ \log 3+1-\log 3 \log 2-\log 2+\log 2 \log 3=\log d \\ \log d=\log 3+1-\log 2=\log \frac{3 \times 10}{2} \\ d=15\end{array}$