2. Two parks with a total area of 110 hectares are divided into the same number of plots, and in each park, the plots have the same area, but differ from those in the other park. If the first park were divided into plots of the same area as the second, it would result in 75 plots. If the second park were divided into plots of the same area as the first, it would result in 108 plots. Determine the area of each park.
2. Answer. 50 and 60 hectares. Solution. Let x be the area of the first park. According to the condition, we will construct a table (for the new division):

| Park | In the new division |  |  |
| :---: | :---: | :---: | :---: |
|  | Area of the park | Number of plots | Area of the plot |
| First | x | 75 | x/75 |
| Second | $110-\mathrm{x}$ | 108 | $(110-\mathrm{x}) / 108$ |

Then for the original division, the following applies:

| Park | In the original division |  |  |
| :---: | :---: | :---: | :---: |
|  | Area of the park | Number of plots | Area of the plot |
| First | $\mathrm{x}$ | $108 \mathrm{x} /(110-\mathrm{x})$ | $(110-\mathrm{x}) / 108$ |
| Second | $110-\mathrm{x}$ | $75(110-\mathrm{x}) / \mathrm{x}$ | $\mathrm{x} / 75$ |

According to the condition, $108 \mathrm{x} /(110-\mathrm{x})=75(110-\mathrm{x}) /$ x. From this, we find x=50.

Evaluation criteria. Correct solution - 7 points, correct solution but incorrect answer due to a calculation error - 5 points, correct model and equation - $\mathbf{3}$ points, in all other cases - $\mathbf{0}$ points.