If the product of four consecutive positive integers is 358800 , then the sum of these four integers is
(A) 102
(B) 98
(C) 94
(D) 90
(E) 106
Let the four consecutive positive integers be $n, n+1, n+2, n+3$.

So we need to solve the equation $n(n+1)(n+2)(n+3)=358800$.

Now $n(n+1)(n+2)(n+3)$ is approximately equal to $n^{4}$, so $n^{4}$ is close to 358800 , and so $n$ is close to $\sqrt[4]{358800} \approx 24.5$.

So we try $24(25)(26)(27)=421200$ which is too big, and so we try $23(24)(25)(26)=358800$, which is the value we want.

So the sum is $23+24+25+26=98$.

ANSWER: (B)