2. (3 points) There is a division equation, the sum of the dividend and divisor is 136, and the quotient is 7, then the divisor is
2. (3 points) There is a division equation, the sum of the dividend and divisor is 136, the quotient is 7, then the divisor is $\qquad$ 17.

【Analysis】Method one: The sum of the dividend and divisor is 136, the quotient is 7, which means the dividend is 7 times the divisor. The sum of the dividend and divisor is (7+1) times the divisor. Dividing 136 by (7+1) will give the divisor, thus solving the problem; Method two: According to the dividend = quotient $\times$ divisor, let the divisor be $x$, then the dividend is $7x$. Based on "the sum of the dividend and divisor is 136", set up an equation and solve it.

【Solution】Solution: Method one:
$$
\begin{array}{l}
136 \div(7+1) \\
=136 \div 8 \\
=17
\end{array}
$$

Answer: The divisor is 17.

Method two:
Let the divisor be $x$, the dividend is $7x$, according to the problem:
$$
\begin{aligned}
7 x+x & =136 \\
8 x & =136 \\
x & =17
\end{aligned}
$$

Answer: The divisor is 17.
Therefore, the answer is: 17.
【Comment】To solve this problem, it can be treated as a sum-multiples problem: the sum of two numbers $\div$ the sum of multiples $=1$ times the number; or set an unknown, find the equal relationship based on the relationship between the dividend, divisor, and quotient, and solve the equation.