13.3. Find the number if it is known that the product of the number and the number written in reverse order is 78445.

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\text { (6-7 grades) }
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13.3. It is clear that the sought multipliers are three-digit numbers. If the product of two three-digit numbers is 78445, then one of them ends in 5. Therefore, the second number starts with the digit 5. Then the first digit of the first number and the last digit of the second number must be one, otherwise the product of the sought numbers will be greater than 78445. Thus, we need to find the middle digit instead of the asterisk so that the equality $1 * 5 \cdot 5 * 1=78445$ holds. It is not difficult to verify that such a digit is 4. Answer: $145 \cdot 541=78445$.