8. (3 points) In the figure, there are 10 beads on each of the three rods. By dividing the beads on each rod into upper and lower parts, two three-digit numbers are obtained. The upper part must be a three-digit number with all different digits, and it must be a multiple of the lower three-digit number. What is the three-digit number in the upper part? $\qquad$
【Analysis】Since the three-digit number above is a multiple of the three-digit number below, assuming the three-digit number below is $a b c$, then the three-digit number above can be expressed as $k \cdot a b c$. Each of the three sections of the abacus has 10 beads, so the sum of the two numbers is $(k \mid 1) a b c=|00 \times 10| 10 \times 10 \mid 1 \times 10=1110$, decomposing 1110 into prime factors: $1110=2 \times 3 \times 5 \times 37$, since the digits of the number above are all different, the number below can be $5 \times 37-185$, and the number above is $185 \times(2 \times 3-1)=925$.

【Solution】Let the three-digit number below be $a b c$, then the three-digit number above can be expressed as $k \cdot a b c$.
The sum of the two numbers is $(k \mid 1) a b c=|00 \times 10| 10 \times 10 \mid 1 \times 10=1110$,
$$
1110=2 \times 3 \times 5 \times 37 \text {, }
$$

Since the digits of the number above are all different, the number below can be $5 \times 37-185$,
The number above is $185 \times(2 \times 3-1)=925$.
Therefore, the answer is: 925.