29.2. Find the smallest natural number that ends in 56, is divisible by 56, and has the sum of its digits equal to 56.

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(7-10 \text { cl.) }
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29.2. The desired number can be represented as $100k + 56$. Since $100k$ must be divisible by 56, the number $k$ must be divisible by 14, i.e., it is even, divisible by 7, and has a sum of digits equal to $56 - 5 - 6 = 45$. The smallest even number with a sum of digits 45 is 199998, but it is not divisible by 7. The next largest even numbers with the same sum of digits will be: 289998, 298998, etc. The first of these is also not divisible by 7, whereas the second one is. Thus, the answer to the problem is the number $298998 \cdot 100 + 56 = 29899856$.