22. In the Cartesian coordinate system, the number of triangles with positive area whose vertices are points $(i, j)$ $(i, j=1,2, \cdots, 5)$ is ( ).
(A) 2128
(B) 2148
(C) 2160
(D) 2200
(E) 2300
22. B.

Notice that, by the problem's setup, the points form $\mathrm{C}_{25}^{3}=2300$ groups of three points, among which there are degenerate triangles (i.e., with an area of 0), when the three points are collinear.

Also, the grid of points in the problem contains 12 lines passing through five points (including 5 horizontal lines, 5 vertical lines, and 2 diagonal lines), forming $12 \mathrm{C}_{5}^{3}=120$ degenerate triangles; 4 lines passing through exactly four points, forming $4 \mathrm{C}_{4}^{3}=16$ degenerate triangles; and 16 lines passing through exactly three points, forming $16 \mathrm{C}_{3}^{3}=16$ degenerate triangles.
Excluding these degenerate triangles, the desired result is
$$
2300-120-16-16=2148 \text {. }
$$