8. (10 points) As shown in the figure, the six vertices of the hexagon are marked as $A, B, C, D, E, F$. Initially, the six Chinese characters “华罗庚金杯赛” are located at the vertices $A, B, C, D, E, F$ respectively. If the six characters are arbitrarily rearranged at the vertices, such that the final result is that each vertex still has one character, and each character is at a vertex adjacent to its initial position, then the number of different arrangements is $\qquad$ kinds.
【Analysis】Obviously, there are only two cases, which need to be discussed separately: swapping two adjacent characters, and moving one position clockwise or counterclockwise. Finally, the total number of different arrangements can be obtained.

【Solution】Solution: According to the analysis, there are two types of situations:
(1) Moving one position in sequence, moving one position clockwise, there are 1 different arrangement method, moving one position counterclockwise, there are 1 different arrangement method;
(2) Swapping two adjacent positions, there are: 2 different arrangement methods in total.

In summary, there are: $1+1+2=4$ different arrangement methods.
Therefore, the answer is: 4.