If $\sqrt{y-5}=5$ and $2^{x}=8$, then $x+y$ equals
(A) 13
(B) 28
(C) 33
(D) 35
(E) 38
If $\sqrt{y-5}=5$ and $2^{x}=8$, then $x+y$ equals
(A) 13
(B) 28
(C) 33
(D) 35
(E) 38

## Solution

Since $\sqrt{y-5}=5$, then

$$
\begin{aligned}
(\sqrt{\mathrm{y}-5})^{2} & =5^{2} \\
y-5 & =25 \\
y & =30
\end{aligned}
$$

Also, since $2^{x}=8$, then

$$
\begin{aligned}
2^{x} & =2^{3} \\
x & =3
\end{aligned}
$$

Thus, $x+y=33$.

ANSWER: (C)