35. To multiply a two-digit number by 9, you need to subtract from the given number the number of tens increased by one, and append to the result the complement of the number of units to 10.
Instruction. Multiplying a two-digit number $10 A+B$ by $9=10-1$, we will have

$$
100 A+10 B-10 A-B
$$

or

$$
[(10 A+B)-(A+1)] \cdot 10+(10-B)
$$