【Example 4】Given 5 points on a plane. It is known that the lines connecting these points are neither parallel, perpendicular, nor coincident. Through each point, draw perpendiculars to the lines connecting it to the other 4 points. What is the maximum number of intersection points of these perpendiculars (excluding the original 5 points)?
Given 5 points, they can form $C_{5}^{2}=10$ lines by connecting each pair of points. Each set of 4 points can form $C_{4}^{2}=6$ lines. Therefore, 6 perpendicular lines should be drawn from each point, making a total of $5 \times 6=30$ lines. If every two of these perpendicular lines intersect, there would be $C_{30}^{2}=455$ intersection points. However, these perpendicular lines are drawn to 10 lines, and each line has 3 perpendicular lines, which are parallel and do not intersect, so we need to subtract $10 C_{3}^{2}=30$. Additionally, the 5 given points can form $C_{5}^{3}=10$ triangles, and the 30 perpendicular lines are exactly the altitudes of these triangles. The 3 altitudes of each triangle intersect at the same point, so we need to subtract $10 C_{3}^{2}-10=20$. Finally, since 6 perpendicular lines are drawn from each original point, we need to subtract $5 C_{6}^{2}=75$. Therefore, the maximum number of intersection points of these perpendicular lines is $455-30-20-75=330$.