8 . Write $1,2, 3, 4, 5, 6,7,8,9, 10, 11, 12, 13, 14, 15, 16$ in a $4 \times 4$ table, one number per cell. Add up the four numbers in each (row) and each (column), requiring each sum to be the same. Try to write the numbers in each cell:
8. The sum of four rows $=1+2+\cdots+16$
$=136$, so the sum of each row $=\frac{136}{4}=34$. Each row of 4 numbers can be divided into two pairs, making the sum of each pair equal to 17, and ensuring that the sum of each column of 4 numbers also equals 34, then we have $17=16+1=15+2$
$$
\begin{array}{l}
=14+3=13+4=12+5=11+6 \\
=10+7=9+8 .
\end{array}
$$

By trying, we can get the table on the right.
The solution is not unique.