26. In five baskets A, B, V, G, and D, there are apples of five different varieties. In each of the baskets A and B, there are apples of the 3rd and 4th varieties, in basket V - 2nd and 3rd, in basket G - 4th and 5th, in basket D - 1st and 5th. Number the baskets so that basket No. 1 contains apples of the 1st variety (at least one), basket No. 2 contains apples of the 2nd variety, and so on.
$\triangle$ Let's represent two sets - the set of baskets and the set of their numbers. Each of these sets has five elements; let's denote them with points (Fig. 1).

![](https://cdn.mathpix.com/cropped/2024_05_21_0aa0e6ac168e80891953g-016.jpg?height=352&width=449&top_left_y=1957&top_left_x=1249)

Fig. 1

We will establish a correspondence between these two sets so that the conditions of the problem are met. We will connect the corresponding elements of the two sets with solid lines, and the non-corresponding elements with dashed lines or not connect them at all.

Since apples of the first variety are only in basket D, we need to assign number 1 to this basket; draw a solid line between points D and 1. Next, number 2 can only be assigned to basket B, and after that, number 5 can only be assigned to basket G. Finally, numbers 3 and 4 will be given to baskets A and B (in any order).

Answer: The baskets are arranged, starting from number 1, in the order D, B, A, B, G or in the order D, B, B, A, G.