The sum of the digits of an even ten digit integer is 89 . The last digit is
(A) 0
(B) 2
(C) 4
(D) 6
(E) 8
The sum of the digits of an even ten digit integer is 89 . The last digit is
(A) 0
(B) 2
(C) 4
(D) 6
(E) 8

## Solution

89 is a large number to be the sum of the digits of a ten digit number. In fact, the largest possible digital sum is $10 \times 9$ or 90 . Since 89 is only 1 less than 90 , the number in question must be composed of nine 9's and one 8 . In order that the number be divisible by 2 , the last digit must be 8 .

ANSWER: (E)