13. As shown in the figure, Jia, Yi, and Bing are three stations, with the distance from Yi station to Jia and Bing stations being equal. Xiaoming and Xiaoqiang start from Jia and Bing stations respectively at the same time and walk towards each other. Xiaoming meets Xiaoqiang 100 meters past Yi station, then they continue walking. Xiaoming reaches Bing station and immediately turns back, and 300 meters past Yi station, he catches up with Xiaoqiang again. What is the distance between Jia and Bing stations?
13. The distance between Station A and Station C is 600 meters.
13.【Solution】When Xiao Ming first meets Xiao Qiang, he has walked half the total distance plus 100 meters; he starts his second journey 100 meters past Station B, and catches up with Xiao Qiang 300 meters from Station B, $300-100=200$ (meters), which means he has walked the total distance plus 200 meters. This can be used to determine that the distance he walked the second time is twice the distance he walked the first time. Therefore, the distance Xiao Qiang walked the second time is also twice the distance he walked the first time. Xiao Qiang's second distance is $300+100=400$ (meters), so his first distance was 200 meters. The distance between Station B and Station C is $200+100=300$ (meters), and the distance between Station A and Station C is $300 \times 2=$ 600 (meters).