Daniel can hack a finite cylindrical log into $3$ pieces in $6$ minutes. How long would it take him to cut it into $9$ pieces, assuming each cut takes Daniel the same amount of time?

[i]2015 CCA Math Bonanza Lightning Round #1.3[/i]
1. **Understanding the problem**: Daniel can hack a finite cylindrical log into 3 pieces in 6 minutes. We need to determine how long it would take him to cut the log into 9 pieces, assuming each cut takes the same amount of time.

2. **Identifying the number of cuts**: To cut a log into \( n \) pieces, you need \( n-1 \) cuts. For example:
   - To cut a log into 3 pieces, you need \( 3-1 = 2 \) cuts.
   - To cut a log into 9 pieces, you need \( 9-1 = 8 \) cuts.

3. **Calculating the time per cut**: Given that 2 cuts take 6 minutes, we can find the time per cut:
   \[
   \text{Time per cut} = \frac{6 \text{ minutes}}{2 \text{ cuts}} = 3 \text{ minutes per cut}
   \]

4. **Calculating the total time for 8 cuts**: Since each cut takes 3 minutes, the total time for 8 cuts is:
   \[
   \text{Total time} = 8 \text{ cuts} \times 3 \text{ minutes per cut} = 24 \text{ minutes}
   \]

Conclusion:
\[
\boxed{24 \text{ minutes}}
\]