(3) Find the range of real numbers $m$ such that the equation $x^{2}-m x+2 m-2=0$:
(1) has a solution in the interval $\left[0, \frac{3}{2}\right]$;
(2) has a solution in the interval $\left(0, \frac{3}{2}\right)$;
(3) has exactly one solution in the interval $\left(0, \frac{3}{2}\right)$;
(4) has two solutions in the interval $\left[0, \frac{3}{2}\right]$.
(3) Analysis: First, discuss (1) in four cases, (1) 0 is a solution; (2) $\frac{3}{2}$ is a solution; (3) there is exactly one solution in $\left(0, \frac{3}{2}\right)$, and $0, \frac{3}{2}$ are not solutions; (4) there are two solutions (including repeated roots) in $\left(0, \frac{3}{2}\right)$. (1) $\left[-\frac{1}{2}, 4-2 \sqrt{2}\right]$
(2) $\left(-\frac{1}{2}, 4-2 \sqrt{2}\right]$
(3) $\left(-\frac{1}{2}, 1\right]$
(4) $[1,4-2 \sqrt{2}]$