$36 \cdot 67$ The 2nd "Chinese Youth" Cup Junior High School Mathematics Competition, if there are 148 students whose scores are between 100 and 120 points (scores are recorded as positive integers), and students with the same score are listed as the same rank, assuming the maximum number of students in the same rank is $x$, then the minimum value of $x$ is
(A) 7.
(B) 8.
(C) 20.
(D) 100.
(2nd China Tianjin "Chinese Youth Cup" Mathematics Invitational Competition, 1988)
[Solution] There are 21 positive integers between 100 and 120, noting that
$$
148=21 \cdot 7+1,
$$

thus the minimum value of $x$ is $7+1=8$. Therefore, the answer is (B).