69. Let $f(x)=(x-1)(x-3)(x-5)(x-7)(x-9)$, then $f(0)+f(1)+f(2)+\ldots+f(10)=$
Answer: 0.
Solution: From the given conditions, we get $f(1)=f(3)=f(5)=f(7)=f(9)=0$,

and since
$$
f(0)+f(10)=0, \quad f(2)+f(8)=0, \quad f(4)+f(6)=0,
$$

thus
$$
f(0)+f(1)+f(2)+\ldots+f(10)=0 .
$$