In a group of 200 people, only $1 \%$ are women. Determine the number of men who must leave the group so that $98 \%$ of the remaining people are male.

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Solution

The number of women is $200 \cdot \frac{1}{100}=2$. For this number to represent $2\% = 100\% - 98\%$ of the new total number of people $x$, we must have $2 = x \cdot \frac{2}{100}$, that is, $x = 100$. Therefore, $198 - 98 = 100$ men must leave the group.