103. Find the limit of the relative error of the number $a=$ $=142.5$, if $\Delta a=0.05$.
Solution. $\quad \mathbf{\varepsilon}_{a}=\frac{0.05}{142.5} \cdot 100 \% =0.00034 \cdot 100 \% =0.03 \%$.

104-111. Determine the limits of the relative errors of the following numbers:

$\begin{array}{ll}\text { 104. } a=6.93 ; \Delta a=0.02 . & \text { 105. } a=12.79 ; \Delta a=2 .\end{array}$

$\begin{array}{ll}\text { 106. } a=648.5 ; \Delta a=0.05 . & \text { 107. } a=792.3 ; \Delta a=0.05 \text {. }\end{array}$