25. Given that the sum of 3 distinct natural numbers is 55, and the sum of any two of these numbers is a perfect square, then these three natural numbers are $\qquad$ _.
Let's analyze: Suppose these three numbers are $a$, $b$, and $c$, then $a+b+c=55$,
so $a+b+b+c+a+c=2(a+b+c)=110$, and $110=25+36+49$, thus $a$, $b$, and $c$ are $55-25=30, 55-36=19, 55-49=6$.