118. Let the order of the sides of the triangle be $a>b>\boldsymbol{c}$; indicate the order of the corresponding heights $\boldsymbol{h}_{a}$, $h_{b}, h_{c}$.
118. The doubled area of the triangle $a h_{a}=b h_{b}=c h_{c}$, and therefore from the inequality $a>b>c$ it follows that $h_{a}<h_{b}<h_{c}$.