Three bags of jelly beans contain 26, 28, and 30 beans.  The ratios of yellow beans to all beans in each of these bags are $50\%$, $25\%$, and $20\%$, respectively.  All three bags of candy are dumped into one bowl.  Which of the following is closest to the ratio of yellow jelly beans to all beans in the bowl?
$\text{(A)}\ 31\% \qquad \text{(B)}\ 32\% \qquad \text{(C)}\ 33\% \qquad \text{(D)}\ 35\% \qquad \text{(E)}\ 95\%$
In bag $A$, there are $26$ jellybeans, and $50\%$ are yellow.  That means there are $26\times 50\% = 26\times 0.50 = 13$ yellow jelly beans in this bag.
In bag $B$, there are $28$ jellybeans, and $25\%$ are yellow.  That means there are $28\times 25\% = 28\times 0.25 = 7$ yellow jelly beans in this bag.
In bag $C$, there are $30$ jellybeans, and $20\%$ are yellow.  That means there are $30\times 20\% = 30\times 0.20 = 6$ yellow jelly beans in this bag.
In all three bags, there are $13 + 7 + 6 = 26$ yellow jelly beans in total , and $26 + 28 + 30 = 84$ jelly beans of all types in total.
Thus, $\frac{26}{84} = \frac{26}{84}\cdot 100\% = \frac{13 }{ 42} \cdot 100\% = 30.9\%$ of all jellybeans are yellow.  Thus, the correct answer is $\boxed{A}$