5. The figure $\mathrm{a}$ below is a cross-sectional view of a sealed water bottle, with the upper part being conical and the lower part cylindrical, both with a base diameter of 10 centimeters. The total height of the water bottle is 26 centimeters, and the height of the liquid surface inside is 12 centimeters. When the water bottle is inverted, as shown in figure $\mathrm{b}$, the height of the liquid surface is 16 centimeters. The volume of the water bottle is $\qquad$ cubic centimeters. $(\pi=3.14$, the thickness of the water bottle walls is negligible).
5. Solution: If part of the liquid in the bottle is removed, making the height 11 cm when upright, then the height is 15 cm when inverted. At this point, the liquid in the bottle is exactly half of the bottle's capacity. Therefore, the bottle's capacity is equivalent to the volume of a cylinder with a height of 22 cm (with the same base area), i.e., the bottle's capacity is:
$$
3.14 \times\left(\frac{10}{2}\right)^{2} \times 22=1727 \text { (cubic centimeters) }
$$