79. Three geologists had to reach a station located 60 km from their base in 3 hours. Can they do this if they have a motorcycle at their disposal, on which no more than two can ride with a maximum speed of $50 \mathrm{km} / h$, while a pedestrian walks at a speed of 5 km/h?
79. Two people get on a motorcycle and drive for 1 hour, while the third walks this hour behind them. After driving 50 km in 1 hour, one of the geologists walks the remaining 10 km on foot and arrives at the station on time $(10: 5=2,1+2=3)$. The second person drives the motorcycle to meet the third when they are 45 km apart $(50-5=$ $=45)$, and meets him after $\frac{9}{11}$ hours $\left(45:(50+5)=\frac{45}{55}=\frac{9}{11}\right)$. During this time, the motorcycle will travel $\frac{450}{11}$ km $\left(50 \cdot \frac{9}{11}=\frac{450}{11}\right)$. This means that from the meeting point to the station, they have $\frac{560}{11}$ km left to travel $\left(\frac{450}{11}+10=\frac{560}{11}\right)$. They will cover this distance in $\frac{56}{55}$ hours $\left(\frac{560}{11}: 50=\frac{56}{55}\right)$. Thus, for the entire distance from the base to the station, these two geologists will spend $2 \frac{46}{55}$ hours $\left(1+\frac{56}{55}+\frac{45}{55}=2 \frac{46}{55}\right)$, i.e., less than 3 hours.