9. (12 points) Two people, A and B, stand facing each other 30 meters apart, playing "Rock, Paper, Scissors". The winner moves forward 3 meters, the loser moves back 2 meters, and in the case of a tie, both move forward 1 meter. After 15 rounds, A is 17 meters from the starting point, and B is 2 meters from the starting point. How many times did A win? $\qquad$
【Solution】Solution: According to the problem, we have:
If there is a win or loss, advance 1 meter; if it's a draw, advance 2 meters.
They advanced 19 meters in 15 attempts.
If all 15 rounds were win or loss rounds, there would be a distance of 15 meters. Therefore, there were 4 draws and 11 win or loss rounds.
$$
17-4=13 \text { (meters). }
$$

Based on 11 win or loss rounds, they advanced 13 meters. If all were wins, they would need to advance 33 meters.
The difference in quantity is $33-13=20$ (meters).
Each round has a difference of 5 points, so 4 rounds have a difference of 20 points.
Therefore, Player A has 7 wins and 4 losses. $7 \times 3-4 \times 2=13$ (meters).
The answer is: 7