A5. The solution to the equation $\sqrt[3]{x}+\sqrt{16}=\sqrt[3]{8}$ is:
(A) $x=-8$
(B) $x=-\frac{\sqrt{2}}{2}$
(C) $x=2$
(D) $x=8$
(E) none of the above
A5. We simplify the equation: $\sqrt[3]{x}+4=2$, then rearrange to get $\sqrt[3]{x}=-2$. Finally, we cube it and obtain the solution $x=-8$.