9. Three pairwise coprime positive integers, all greater than 1, have a product of 27000. Then their sum is ( ).
(A) 100
(B) 137
(C) 156
(D) 160
(E) 165
9. D.

Notice that, $27000=2^{3} \times 3^{3} \times 5^{3}$. Therefore, the three numbers are $2^{3} 、 3^{3} 、 5^{3}$, and their sum is 160.