1. If $f(x)$ is an odd function on the interval $\left[t, t^{2}-3 t-3\right]$, then $t=$
1. -1 Explanation: The domain of an odd function is symmetric about the origin, and the right endpoint of the interval does not need to be smaller. Therefore, $-t=t^{2}-3 t-3$ $\geqslant 0 \Leftrightarrow t=-1$.