14. There are 2006 balls lined up in a row. They are coloured to be red, white, blue and black in the following order: 5 red, 4 white, 1 blue, 3 black, 5 red, 4 white, 1 blue, 3 black, $\cdots$. Then the last ball is coloured to be $\qquad$
14.red.

The problem states: There are 2006 balls arranged in a row, each dyed one of four colors: red, white, blue, and black, and they are arranged in the following order: 5 red balls, 4 white balls, 1 blue ball, 3 black balls, 5 red balls, 4 white balls, 1 blue ball, 3 black balls, $\cdots \cdots$. The color of the last ball is 
Given $2006=13 \times 154+4$, the last ball is red.