30.14 If $n$ is the smallest non-prime number greater than 1 and it has no prime factors less than 10, then
(A) $100<n \leqslant 110$.
(B) $110<n \leqslant 120$.
(C) $120<n \leqslant 130$.
(D) $130<n \leqslant 140$.
(E) $140<n \leqslant 150$.
(35th American High School Mathematics Examination, 1984)
[Solution] The number $n$ must be the product of two or more prime numbers greater than 10 (they do not have to be distinct), the smallest prime number satisfying this condition is 11.
So their smallest product is $11 \cdot 11=121$.
Therefore, the answer is $(C)$.