## Task A-1.1.

Determine the natural number $n$ such that the sum of its two smallest divisors is 6, and the sum of its two largest divisors is 1122.
## Solution.

The smallest divisor of the number $n$ is 1.

From the condition of the problem, it follows that the second smallest divisor of the number $n$ is the number 5. 1 point

The two largest divisors of the number $n$ are $\frac{n}{5}$ and $n$.

Therefore,

$$
1122=n+\frac{n}{5}=\frac{6 n}{5}
$$

from which it follows that $n=935$.