It is known that on the surface of the Earth, a freely falling object travels a distance of $s \approx 4.903 t^{2}$ meters in $t$ seconds. How does the formula change if the distance is measured in feet and the time in minutes?
We know that 1 minute is 60 seconds and 1 English foot $\approx 0.3048 \mathrm{~m}$.

Therefore, $s=\frac{4.903 \cdot(60 t)^{2}}{0.3048} \approx 57909 t^{2}$, if we measure distance in feet and time in minutes.

Remark. Many of the solvers noted that different results can be obtained because the foot-meter conversion is not uniform.

Agnes Sándor (Pápa, Reformed College Gym., 9th grade) even listed some of the different measurements. These are:
1 foot $=0.3048 \mathrm{~m}$
(English, US, Russian)
$=0.316 \mathrm{~m} \quad$ (Hungarian, Austrian)
$=0.325 \mathrm{~m}$
(French), respectively

From this, it is clear that we do not live on the same size feet.