B1. What is the smallest positive integer consisting of the digits 2, 4, and 8, where each of these digits appears at least twice and the number is not divisible by 4?
B1. 244882 We only consider numbers with the even digits 2, 4, and 8. If such a number ends in the digit 4 or 8, then the number is a multiple of 20 plus 4 or 8 and thus divisible by 4. If such a number ends in the digit 2, then it is a multiple of 20 plus 2 and thus not divisible by 4. The last digit must therefore be a 2. The remaining digits can be sorted from low to high. We then find 244882.