Example 10: There are 100 points on a circle, and each pair of points is connected by a chord. If no three chords intersect at the same point inside the circle (except at the endpoints), how many intersection points are there inside the circle?
Solution: Every 4 points on the circle form a convex quadrilateral, whose two diagonals (chords) intersect at one point, so each set of 4 points corresponds to one intersection point. Since no three chords intersect at the same point, different sets of four points correspond to different intersection points.

Conversely, let point $P$ be the intersection of chords $A C$ and $B D$, then $P$ is the intersection point corresponding to the set of four points $\{A, B, C, D\}$. Therefore, the number of intersection points is the total number of ways to choose 4 points from these 100 points, which is $C_{100}^{4}$.