6. Two companies collected 300 tons of olives in the first year, and in the second year, they collected $1 / 3$ more olives than in the first year. How many tons of olives did each of these companies collect in the first year, if in the second year the first company collected twice as many olives as in the first year, and the second company collected a fifth more olives than in the first year?
6. Let $x$ be the quantity of olives in tons that the first company collected in the first year.

Then the second company collected $300-x$ tons of olives in the first year.

In the second year, they collected $\frac{1}{3}$ more olives, i.e., $300+\frac{1}{3} \cdot 300=400$ tons of olives.

The second company collected $\frac{1}{5}$ more olives in the second year than in the first year, i.e.,

$300-x+\frac{1}{5} \cdot(300-x)=\frac{6}{5} \cdot(300-x)=360-\frac{6}{5} x$ tons of olives.

Both companies collected in the second year:

$2 x+360-\frac{6}{5} x=400$

$2 x-\frac{6}{5} x=40 / \cdot 5$

$10 x-6 x=200$

$4 x=200 /: 4$

$x=50$

2 POINTS

The first company collected 50 tons of olives in the first year, and the second company collected $300-x=300-50=250$ tons of olives.