1.1. Weights with 1, 2, 3, 4, 8, 16 grams were divided into two piles of equal weight. $B$ in the first one there are two weights, in the second - four weights. Which two weights are in the first pile?
Answer: 1.16 (All answers)

Solution. The total weight of the weights is 34 grams, i.e., each pile weighs 17 grams. Two weights can add up to 17 grams in only one way $-16+1$: if we do not take the 16-gram weight, then with two weights we will not exceed $8+4=12$ grams.