6. Given two lines $l_{1}: 2 x+y=3, l_{2}: x+4 y=2$. Line $l$ passes through the intersection point $P$ of $l_{1}$ and $l_{2}$ and the origin, then the equation of line $l$ is $\qquad$ .
6. $x-10 y=0$. Hint: We can set the equation of $l$ as: $(2 x+y-3)+\lambda(x+4 y-2)=0$, substitute $(0,0)$, and solve to get $\lambda=-\frac{3}{2}$.