1. Let set $A=\left\{x^{2}, x+1,-3\right\}, B=\left\{x-5,2 x-1, x^{2}+1\right\}$, satisfying $A \cap B=\{-3\}$, then the value of $x$ is ( ).
A. 2
B. 1
C. 0
D. -1
1. Substitute $x=2,1,0,-1$ into sets $A, B$, considering the uniqueness of set elements and check if $A \cap B=$ $\{-3\}$, we find $x=-1$, so the answer is D.