3. As shown in Figure 1, $A$ and $B$ are two points on the inverse proportion function $y=\frac{k}{x}(k>0)$, $A C \perp x$-axis at point $C$, $B D \perp y$-axis at point $D$, and $A C$ and $B D$ intersect at point $E$. The relationship between the areas of $\triangle A D E$ and $\triangle B C E$ is ().
(A) $S_{\triangle A D E}>S_{\triangle B C E}$
(B) $S_{\triangle D E E}=S_{\triangle B C E}$
(C) $S_{\triangle A D E}<S_{\triangle B C E}$
(D) Uncertain
3. B.
$$
\begin{array}{l}
S_{\text {AASE }}=\frac{1}{2}(O C \cdot A C-O C \cdot E C)=\frac{1}{2}(k-D E \cdot O D) \\
=\frac{1}{2}(D B \cdot O D-D E \cdot O D)=S_{\triangle B C E} .
\end{array}
$$