16. (3 points) Use the ten different digits $0-9$ to form a ten-digit number that can be divided by 11, the largest number is
16. (3 points) Use the ten different digits from $0-9$ to form a ten-digit number that can be divided by 11, the largest number is $\underline{976524130}$.
【Solution】Let the sum of the digits in the odd positions of the number be $x$, and the sum of the digits in the even positions be $y$. Then, $x+y=0+1+2+\cdots+9=45$, and $x-y$ or $y-x=0,11,22$ (the maximum absolute value does not exceed 22). Since $x+y=45$ is odd, according to the parity of numbers, $x-y$ is also odd, so $x-y=11$ or -11. Solving the equations $x+y=45$ and $x-y=11$ or -11, we get $x=28$ or $17, y=17$ or 28. To form the largest ten-digit number, the first few digits should be as large as possible, such as $9,8,7,6$. Therefore, we should take $x=28, y=17$. At this point, the sum of the other three digits in the odd positions is: $28-(9+7)=12$, and the sum of the other three digits in the even positions is: $17 - (8+6)=3$.
Thus, the other three digits in the even positions can only be $2,1,0$; and the other three digits in the odd positions are $5,4,3$. Therefore, the largest ten-digit number is: 9876524130.
Hence, the answer is: 9876524130.