8. Generate a random integer $x \in\{1,2, \cdots, 2016\}$ with equal probability, then the probability that the sum of the digits of $x$ in binary is no more than 8 is . $\qquad$
Since $2016=11111100000_{(2)}$, in binary, the number of $x$ whose sum of digits exceeds 8 is $C_{6}^{4} \cdot C_{5}^{5}+C_{6}^{5}\left(C_{5}^{5}+C_{5}^{4}\right)=15+6 \cdot 6=51$. Let $A=$ “the sum of digits of $x$ in binary does not exceed 8”, then $P(A)=1-\frac{51}{2016}=1-\frac{17}{672}=\frac{655}{672}$.