1. Let $a$ be a real number, and $a^{3}+a^{2}-a+2=0$. Then
$$
\begin{array}{l}
(a+1)^{2011}+(a+1)^{2012}+(a+1)^{2013} \\
=(\quad) .
\end{array}
$$
(A) 3
(B) -3
(C) 1
(D) -1
$\begin{array}{l}\text { I. 1. D. } \\ \text { Given } 0=a^{3}+a^{2}-a+2=(a+2)\left(a^{2}-a+1\right) \\ \Rightarrow a+2=0 \Rightarrow a+1=-1 \text {. } \\ \text { Therefore, }(a+1)^{2011}+(a+1)^{2012}+(a+1)^{2013} \\ =(-1)^{2011}+(-1)^{2012}+(-1)^{2013}=-1 \text {. }\end{array}$