There are some positive integers, when divided by 5, the remainder plus the quotient when divided by 6 equals 11. Find the sum of all numbers that satisfy this condition.

Find the sum of all such numbers.
Number Theory, Remainders.
(1) If this number $\div 5$ has a remainder of 0, then the quotient of this number $\div 6$ is $11-0=11$; $6 \times 11=66, 6 \times 11+5=71$, from $66 \sim 71$, the number that $\div 5$ has a remainder of 0 is 70; (2) If this number $\div 5$ has a remainder of 1, then the quotient of this number $\div 6$ is $11-1=10$; $6 \times 10=60, 6 \times 10+5=65$, from $60 \sim 65$, the number that $\div 5$ has a remainder of 1 is 61; (3) If this number $\div 5$ has a remainder of 2, then the quotient of this number $\div 6$ is $11-2=9$; $6 \times 9=54, 6 \times 9+5=59$, from $54 \sim 59$, the number that $\div 5$ has a remainder of 2 is 57; (4) If this number $\div 5$ has a remainder of 3, then the quotient of this number $\div 6$ is $11-3=8$; $6 \times 8=48, 6 \times 8+5=53$, from $48 \sim 53$, the numbers that $\div 5$ have a remainder of 3 are 48 and 53; (5) If this number $\div 5$ has a remainder of 4, then the quotient of this number $\div 6$ is $11-4=7$; $6 \times 7=42, 6 \times 7+5=47$, from $42 \sim 47$, the number that $\div 5$ has a remainder of 4 is 44; Therefore, the sum of all numbers that satisfy these conditions is $70+61+57+48+53+44=333$.