A car with a weight of $P=1800 \mathrm{~kg}$ starts on a road where $\rho=\frac{1}{50}, e=\frac{1}{40} ; 1 \frac{1}{12}$ minutes after, while covering $900 \mathrm{~m}$, it reaches its maximum speed: $v=12 \frac{\mathrm{m}}{\mathrm{sec}}$. How many horsepower is its power? What is the traction force?[^0]


[^0]:    ${ }^{1}$ In this problem, $\rho$ is the coefficient of friction, and $e$ is the sine of the incline angle.
With similar considerations as in problem 1133, $1 \frac{1}{2}$ minutes of work $L=161700 \mathrm{mkg}$.

$$
H=\frac{L}{90 \cdot 75} \text { horsepower }=24 \text { horsepower. }
$$

Traction force $=\frac{L}{s}=1797 \mathrm{~kg}$ weight.

(Rézó Földes, Budapest.)

The problem was also solved by: Bánó L., Csada I., Frank A., Gráf V., Grünhut H., Haar A., Jánosy Gy., Koritsánszky I., Schwarz O., Székely J.