Each point is at least an endpoint of one line segment, then the number of different connection methods is
(A) 120 kinds
(B) 125 kinds
(C) 130 kinds
(D) 135 kinds
5. (D).

Since 3 points can connect at most 3 line segments, the number of ways to connect the lines in the question is $C_{10}^{7}-5 C_{6}^{4}=135$.