[ Volume of a parallelepiped $]$ [Volume of a tetrahedron and pyramid]

The volume of the parallelepiped $A B C D A 1 B 1 C 1 D 1$ is $V$. Find the volume of the pyramid $A B C C 1$.

#
Let $S$ be the area of the base $ABCD$ of the parallelepiped $ABCD A1 B1 C1 D1$, and $h$ be the height of the parallelepiped. Then

$$
V_{ABCC^{1}}=\frac{1}{3} S_{\triangle ABC} \cdot h=\frac{1}{3 \cdot} \cdot \frac{1}{2} S \cdot h=\frac{1}{6} S h=\frac{1}{6} V .
$$

## Answer

$\frac{1}{6} V$.