5,6,7,8 |  |

A four-digit number starts with the digit 6. This digit was moved to the end of the number. The resulting number turned out to be 1152 less than the original. Find the original number.
Let's write the condition of the problem in the form of a rebus, for example:

## $-6 A B C$  $\frac{1.52}{1152}$

Then C $=8$ and the example takes the form:

Therefore, $B=3$ and the example has the following form:

## $-6 \mathrm{~A}^{438}$  $-{ }_{A 38}^{10}$

Since a carry-over has occurred, then $A=5$ :

$-6538$

$\begin{array}{r}-5386 \\ \hline 152\end{array}$

## Answer

6538.00