Problem 7.1. Inside a large square, there is a small square, the corresponding sides of which are parallel. The distances between some sides of the squares are marked on the diagram. By how much is the perimeter of the large square greater than the perimeter of the small square?

![](https://cdn.mathpix.com/cropped/2024_05_06_2763d6d141aaad15ef08g-01.jpg?height=307&width=299&top_left_y=351&top_left_x=577)
Answer: 32.

Solution. Let the side of the small square be $x$, then the side of the large square, if measured horizontally, is $2+x+6=x+8$. The perimeter of a square is four times its side, so it is not difficult to calculate the difference in perimeters:

$$
4(x+8)-4x=32
$$