The number of integer values of $x$ for which $\frac{3}{x+1}$ is an integer is
(A) 4
(B) 3
(C) 5
(D) 1
(E) 6
The problem is equivalent to determining all values of $x$ for which $x+1$ is a divisor of 3 .

The divisors of 3 are $3,-3,1,-1$.

If $x+1=3,-3,1,-1$, then $x=2,-4,0,-2$, respectively. There are 4 such values.

ANSWER: (A)

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