Points $P, Q$ and $R$ are on a number line. $Q$ is halfway between $P$ and $R$. If $P$ is at -6 and $Q$ is at -1 , then $R$ is at
(A) 4
(B) -11
(C) 3
(D) -7
(E) 5

## Part B: Each correct answer is worth 6.
Since $Q$ is halfway between $P$ and $R$, then the distance between $P$ and $Q$ is equal to the distance between $Q$ and $R$.

The distance between $P$ and $Q$ is $-1-(-6)=-1+6=5$.

![](https://cdn.mathpix.com/cropped/2024_04_20_748fdafcde2a47412608g-153.jpg?height=108&width=450&top_left_y=1366&top_left_x=1518)

Since $P$ is 5 units to the left of $Q$, then $R$ is 5 units to the $\operatorname{right}$ of $Q$.

That is, $R$ is located at $-1+5=4$ on the number line.

ANSWER: (A)