$35 \cdot 10$ A $11 \times 11 \times 11$ cube is made up of $11^{3}$ unit cubes, how many unit cubes can be seen at most from one point?
(A) 328.
(B) 329.
(C) 330.
(D) 331.
(E) 332.
(41st American High School Mathematics Examination, 1990)
[Solution] From one point, the maximum number of faces of a cube that can be seen is 3 (as shown in the figure, the figure is a $4 \times 4 \times 4$ cube).
The front face has $11 \cdot 11$ unit cubes visible;
The side face, excluding the unit cubes along the common edge with the front face which have already been counted, has $11 \cdot 10$ unit cubes visible;

The top face of the cube, excluding the already counted unit cubes, has $10 \cdot 10$ unit cubes visible.
In total, there are $11 \cdot 11 + 11 \cdot 10 + 10 \cdot 10 = 331$ (unit cubes).
Therefore, the answer is $(D)$.