165. On a straight line, there are 6 points, and on a parallel line, there are 8 points. How many triangles exist with vertices at these points?
$\triangle$ First, let's calculate the number of triangles where two vertices lie on the first line, and one vertex lies on the second line:

$$
C_{6}^{2} \cdot C_{8}^{1}=15 \cdot 8=120
$$

Similarly, let's calculate the number of triangles where one vertex lies on the first line, and two vertices lie on the second line:

$$
C_{6}^{1} \cdot C_{8}^{2}=6 \cdot 28=168
$$

This gives us $120+168=288$ triangles.

Answer: 288.