12.52. In triangle $A B C$, the height $A H$ is equal to the median $B M$. Find the angle $M B C$.

![](https://cdn.mathpix.com/cropped/2024_05_21_22b0ba5e8c5a1f49bd81g-276.jpg?height=266&width=439&top_left_y=984&top_left_x=539)

Fig. 12.2
12.52. Drop a perpendicular $M D$ from point $M$ to line $B C$. Then $M D = A H / 2 = B M / 2$. In the right triangle $B D M$, the leg $M D$ is equal to half of the hypotenuse $B M$. Therefore, $\angle M B C = \angle M B D = 30^{\circ}$.