$30 、 \mathrm{~A}, \mathrm{~B}$ There is a tunnel between the two places. A car left from $\mathrm{B}$ heading towards $\mathrm{A}$ at 08:16, and a truck left from $\mathrm{A}$ heading towards $\mathrm{B}$ at 09:00. It is known that the truck and the car arrived at the two ends of the tunnel simultaneously, but the truck left the tunnel 2 minutes later than the car. If the car arrived at $\mathrm{A}$ at 10:56, and the truck arrived at $\mathrm{B}$ at 12:20, then the time they arrived at the two ends of the tunnel simultaneously is $\qquad$
Analysis: The truck takes 200 minutes to complete the entire journey, while the car takes 160 minutes. The time ratio for the truck to the car to complete the entire journey $\mathrm{AB}$ is 5:4. Since both vehicles pass through the tunnel (with equal distance), the time ratio for passing through the tunnel is also 5:4. The truck takes 2 minutes longer than the car to pass through the tunnel, and since the truck's time is 1 part more than the car's, 1 part is 2 minutes. Therefore, the truck takes 10 minutes to pass through the tunnel, and the car takes 8 minutes.

As shown in the figure, segment CD represents the tunnel. Let the time the truck takes from $\mathrm{A}$ to C be $x$ minutes. Since the car starts 44 minutes earlier than the truck and both vehicles arrive at C and D simultaneously, the time the car takes from B to D is $x+44$. Therefore, the time the truck takes to travel segment BD is $\frac{5}{4}(x+44)$. According to the problem, $x+10+\frac{5}{4}(x+44)=200$, solving for $x$ gives $x=60$. The truck departs from $\mathrm{A}$ at 9:00, and after 60 minutes, it reaches point $\mathrm{C}$, so they arrive at the two ends of the tunnel simultaneously at 10:00.