7. (10 points) The school organizes 482 people to go on an outing, renting 42-seat buses and 20-seat minibuses. If it is required that each person has one seat and each seat is occupied by one person, then there are several rental schemes.

将上面的文本翻译成英文，请保留源文本的换行和格式，直接输出翻译结果。
Note: The last sentence is a repetition of the instruction and should not be part of the translated text. Here is the corrected output:

7. (10 points) The school organizes 482 people to go on an outing, renting 42-seat buses and 20-seat minibuses. If it is required that each person has one seat and each seat is occupied by one person, then there are several rental schemes.
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【Analysis】Let there be $x$ 42-seat buses and $y$ 20-seat minibuses. According to the problem, we have: $42 x + 20 y = 482$, we need to find the integer solutions of the equation, which will give us the answer.

【Solution】Let there be $x$ 42-seat buses and $y$ 20-seat minibuses. According to the problem, we have: $42 x + 20 y = 482$. Dividing both sides by 2 gives: $21 x + 10 y = 241$. The last digit of $10 y$ is 0, so the last digit of $21 x$ must be 1. Therefore, $x$ can only be 1 or 11. When $x = 1$, $y = 22$; when $x = 11$, $y = 1$.

Therefore, there are 2 rental schemes.
Answer: There are 2 rental schemes.