Describe a construction of quadrilateral $ABCD$ given:

(i) the lengths of all four sides;

(ii) that $AB$ and $CD$ are parallel;

(iii) that $BC$ and $DA$ do not intersect.
1. **Assign coordinates to points:**
   Let \( A(-a, 0) \), \( B(0, 0) \), \( C(x_C, y_C) \), and \( D(x_D, y_D) \). Since \( AB \parallel CD \), we have \( y_C = y_D \).

2. **Use the given side lengths:**
   - For \( BC = b \):
     \[
     b^2 = x_C^2 + y_C^2 \quad \text{(1)}
     \]
   - For \( AD = d \):
     \[
     d^2 = (x_D + a)^2 + y_C^2 \quad \text{(2)}
     \]
   - For \( CD = c \):
     \[
     c^2 = (x_C - x_D)^2 \quad \text{(3)}
     \]

3. **Condition for non-intersecting \( BC \) and \( DA \):**
   Since \( BC \) and \( DA \) do not intersect, we have:
   \[
   c = x_C - x_D \quad \text{(4)}
   \]

4. **Substitute equation (4) into equation (1):**
   \[
   b^2 = (x_D + c)^2 + y_C^2 \quad \text{(5)}
   \]

5. **Subtract equation (5) from equation (2):**
   \[
   d^2 - b^2 = (x_D + a)^2 + y_C^2 - (x_D + c)^2 - y_C^2
   \]
   Simplify the equation:
   \[
   d^2 - b^2 = (x_D + a)^2 - (x_D + c)^2
   \]
   \[
   d^2 - b^2 = (x_D^2 + 2ax_D + a^2) - (x_D^2 + 2cx_D + c^2)
   \]
   \[
   d^2 - b^2 = 2ax_D + a^2 - 2cx_D - c^2
   \]
   \[
   d^2 - b^2 = 2x_D(a - c) + a^2 - c^2
   \]

6. **Solve for \( x_D \):**
   \[
   2x_D(a - c) = d^2 - b^2 - a^2 + c^2
   \]
   \[
   x_D = \frac{d^2 - b^2 - a^2 + c^2}{2(a - c)}
   \]

7. **Calculate \( x_C \) and \( y_C \):**
   From equation (4):
   \[
   x_C = x_D + c
   \]
   Substitute \( x_D \) into the equation:
   \[
   x_C = \frac{d^2 - b^2 - a^2 + c^2}{2(a - c)} + c
   \]
   From equation (1):
   \[
   y_C^2 = b^2 - x_C^2
   \]
   Substitute \( x_C \) into the equation to find \( y_C \).

The problem is solved.

The final answer is \( \boxed{ x_D = \frac{d^2 - b^2 - a^2 + c^2}{2(a - c)} } \) and \( x_C = \frac{d^2 - b^2 - a^2 + c^2}{2(a - c)} + c \).