2. In $\triangle A B C$, $A B \leqslant A C \leqslant B C$, and the smallest interior angle is not less than $59^{\circ}$. Then the maximum value of the largest interior angle is $\qquad$ degrees.
2. According to the problem, we have $\angle C \leqslant \angle B \leqslant \angle A$. From $59^{\circ} \leqslant \angle C \Rightarrow$ $59^{\circ} \leqslant \angle B$, then $\angle B+\angle C \geqslant 118^{\circ}$. Therefore, $\angle A \leqslant 62^{\circ}$.