A4. The quadratic equation is $3 x^{2}+6 x-m=0$. If one solution of the equation is $x=-3$, then $m$ is equal to:
(A) -13
(B) -9
(C) 3
(D) 6
(E) 9
A4. Considering $x=-3$ we get: $3 \cdot(-3)^{2}+6 \cdot(-3)-m=0$, from which the solution $m=9$ follows.