$\underline{\text { Folkpor }}$  It is known that $5(a-1)=b+a^{2}$. Compare the numbers $a$ and $b$.

#
$a-b=a+a^{2}-5 a+5=(a-2)^{2}+1>0$.

## Answer

$a>b$.

## Translation

$a-b=a+a^{2}-5 a+5=(a-2)^{2}+1>0$.

## Answer

$a>b$.