12. For a positive integer $n, n!=1 \times 2 \times \cdots \times n$. If a positive integer $N$ satisfies $5! \times 9! = 12 \times N!$, then the value of $N$ is ( ).
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
12. A.

Notice that, $5!=120$.
Then $120 \times 9!=12 \times N$ !
$$
\begin{array}{l}
\Rightarrow N!=10 \times 9!=10! \\
\Rightarrow N=10 .
\end{array}
$$