5. (D) Solution 1 - Using the data from the question we have: $0.1333 \ldots=\frac{1.333 \ldots}{10}=\frac{1+0.333 \ldots}{10}=\frac{1}{10}\left(1+\frac{1}{3}\right)=\frac{1}{10} \times \frac{4}{3}=\frac{2}{15}$.
2 - Using the rule that provides the generating fraction of a repeating decimal, we have: $0,1333 \ldots=\frac{13-1}{90}=\frac{12}{90}=\frac{2}{15}$.