Fomin S.B.

Two people toss a coin: one tossed it 10 times, the other - 11 times.

What is the probability that the second one got heads more times than the first one?
The events "the second one got more heads than the first" and "the second one got more tails than the first" are obviously equally probable. But they also complement each other (since the second one tossed the coin exactly one more time than the first, either heads or tails must be more, but not both at the same time). Therefore, the probability of each event is $1 / 2$.

## Answer

$1 / 2$.