The positive divisors of 6 are 1, 2, 3, 6. The sum of the positive divisors of 1184 is
(A) 2394
(B) 2396
(C) 2398
(D) 2400
(E) 2402
We start by finding the prime factors of 1184 :

$$
1184=2 \cdot 592=2^{2} \cdot 296=2^{3} \cdot 148=2^{4} \cdot 74=2^{5} \cdot 37
$$

The positive divisors of 1184 cannot contain prime factors other than 2 and 37, and cannot contain more than 5 factors of 2 or 1 factor of 37 .

Thus, the positive divisors are

$$
1,2,4,8,16,32,37,74,148,296,592,1184
$$

(The first five of these divisors have 0 factors of 37 and 0 through 5 factors of 2 , while the last five have 1 factor 37 and 0 through 5 factors of 2.)

The sum, $S$, of these divisors is

$$
\begin{aligned}
S & =1+2+4+8+16+32+37+74+148+296+592+1184 \\
& =(1+2+4+8+16+32)+37 \cdot(1+2+4+8+16+32) \\
& =(1+2+4+8+16+32) \cdot(1+37) \\
& =63 \cdot 38 \\
& =2394
\end{aligned}
$$

ANSWER: (A)