11. There are 6 numbers: 1, 3, 3, 27, 81, 243. Each time, you can either take one of them, or take several different numbers to find their sum (each number can only be taken once, which can result in a new number). This way, a total of 63 new numbers can be obtained. If they are arranged in ascending order, they are 1, 3, 4, 9, ... What is the 58th number? $\qquad$ -
【Analysis】The question tells us there are a total of 63 numbers, and it requires the 58th; therefore, we need to use a reverse approach.
Since they are arranged from smallest to largest:
The 63rd is the largest: $1+3+9+27+81+243=364$
The 62nd is by subtracting the smallest 1;
The 61st is by subtracting the second smallest 3;
The 60th is not by subtracting 9, but by subtracting $(1+3)$, which is smaller than 9;
The 59th is by subtracting 9;
The 58th is by subtracting $(1+9), 364-10=354$