1. Determine the sum and product of 20 consecutive integers among which there are 8 positive ones.
1. Since it involves consecutive numbers and there are 8 positive ones, then among the remaining numbers are 0 and 11 negative ones.

Thus, these numbers are $-11, -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8$ 1 POINT

Since there is the number 0 among them, then their product is 0. 1 POINT

For the sum, it holds that $-11 + (-10) + (-9) + \ldots + 6 + 7 + 8 =$

$$
\begin{aligned}
& = -11 + (-10) + (-9) + (-8 + 8) + (-7 + 7) + \ldots + (-1 + 1) + 0 = \\
& = -11 + (-10) + (-9) = -30
\end{aligned}
$$