A store had $376$ chocolate bars. Min bought some of the bars, and Max bought $41$ more of the bars than Min bought. After that, the store still had three times as many chocolate bars as Min bought. Find the number of chocolate bars that Min bought.
1. Let \( a \) be the number of chocolate bars that Min bought.
2. Let \( b \) be the number of chocolate bars that Max bought.
3. According to the problem, Max bought 41 more bars than Min, so we can write the equation:
   \[
   b = a + 41
   \]
4. The total number of chocolate bars initially was 376. After Min and Max bought their bars, the store still had three times as many bars as Min bought. Therefore, the remaining bars in the store can be expressed as:
   \[
   376 - a - b = 3a
   \]
5. Substitute \( b = a + 41 \) into the equation:
   \[
   376 - a - (a + 41) = 3a
   \]
6. Simplify the equation:
   \[
   376 - a - a - 41 = 3a
   \]
   \[
   376 - 2a - 41 = 3a
   \]
   \[
   335 - 2a = 3a
   \]
7. Combine like terms:
   \[
   335 = 5a
   \]
8. Solve for \( a \):
   \[
   a = \frac{335}{5} = 67
   \]

The final answer is \( \boxed{67} \)