9.140. $\frac{4}{\sqrt{2-x}}-\sqrt{2-x}<2$.
## Solution.

Domain of definition: $x<2$, then we have $(\sqrt{2-x})^{2}+2(\sqrt{2-x})-4>0$. Solving this inequality as a quadratic equation in terms of $\sqrt{2-x}$, we get $\sqrt{2-x}-1+\sqrt{5} \Leftrightarrow 2-x>(\sqrt{5}-1)^{2}, x<-4+2 \sqrt{5}$.

Answer: $x \in(-\infty ;-4+2 \sqrt{5})$.