9. (15 points) A rectangular plot of land $ABCD$ is divided into two rectangles as shown in the figure, which are contracted to households A and B, respectively. The area of household A's vegetable greenhouse is equal to the area of household B's chicken farm, and the remaining part of household A's area is 96 acres more than that of household B. Given that $BF$ $=3 CF$, what is the total area of the rectangle $ABCD$ in acres?
【Analysis】According to the problem, we know that $B F=3 C F$, so the area of the rectangle belonging to household A is 3 times the area of the rectangle belonging to household B. The vegetable greenhouse area of household A is equal to the chicken farm area of household B, and the remaining part of household A is 96 acres more than that of household B. This means the area of the rectangle of household A is 96 acres more than that of household B. According to the difference-multiple problem, the area of the rectangle of household B is 96 $\div(3-1)=48$ acres, so the total area of rectangle $A B C D$ is $48 \times(1+3)=192$ acres.

【Solution】Solution: Since $B F=3 C F$, the area of rectangle $A B E F$ = the area of rectangle $E F C D$ $\times 3$, the vegetable greenhouse area of household A is equal to the chicken farm area of household B, and the remaining part of household A is 96 acres more than that of household B.

The area of the rectangle of household B is: $96 \div(3-1)=48$ (acres),
So the total area of rectangle $A B C D$ is: $48 \times(1+3)=192$ (acres).