36. The number $n \cdot(n+2)$ ends with the digit 4. Name the second to last digit of this number.
36. The numbers $n$ and $(n+2)$ have the same parity, but since their product is even (ends in the digit 4), these numbers are even. Therefore, the product $n(n+2)$ is divisible by 4. However, numbers divisible by 4 are those where the last two digits form a number divisible by 4. Such numbers are $24, 44, 64, 84$. Therefore, the second last digit can be $2, 4, 6$ or 8.