13. From the numbers $1,2, \cdots, 10$, if 3 numbers are randomly drawn, the probability that at least two of the numbers are consecutive integers is $\qquad$
13. $\frac{8}{15}$.

Suppose the 3 numbers drawn are such that no two are adjacent, denoted as $i, j, k(1 \leqslant i<j<k \leqslant 10)$. Then $i, j-1, k-2$ are distinct and can only take values from the set $\{1,2, \cdots, 8\}$, yielding a total of $C_{8}^{3}$ different combinations.

Additionally, the total number of ways to draw any 3 numbers is $\mathrm{C}_{10}^{3}$.
Thus, the required probability $P=1-\frac{\mathrm{C}_{8}^{3}}{\mathrm{C}_{10}^{3}}=\frac{8}{15}$.