8. During the middle school math club activities, 11 guests were invited to give specialized lectures. The club paid each guest the same amount, with the total amount being $\overline{1 A 2}$ dollars. Then the digit $A$ in the tens place of the three-digit number is $(\quad$.
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
8. D.

From the problem, we know $111 \overline{1 A 2}$.
Thus, $1+2-A=3-A \equiv 0(\bmod 11)$.
Note that, $0 \leqslant A \leqslant 9$.
Then $-6 \leqslant 3-A \leqslant 0 \Rightarrow 3-A=0$
$\Rightarrow A=3$.