20. (6 points) Person A and Person B start from points $A$ and $B$ respectively at the same time, heading towards each other, and meet at point $C$. If, at the start, Person A increases their speed by $\frac{1}{4}$, and Person B increases their speed by 10 kilometers per hour, they still meet at point $C$. Then, Person B originally traveled at $\qquad$ kilometers per hour.
【Solution】Solution: According to the problem, we know:
Based on the fact that the meeting point of A and B is the same, the ratio of their speeds remains constant. When A increases his speed by $\frac{1}{4}$, B also needs to increase his speed by $\frac{1}{4}$. Since B's increase is 10 kilometers per hour, we have $10 \div \frac{1}{4}=40$ kilometers/hour.

Therefore, the answer is: 40