14. If $x, y \in \mathbf{R}$ satisfy
$$
2 x-2 x^{2} y^{2}-2 y\left(x+x^{2}\right)-x^{2}=5 \text {, }
$$

then $(x, y)=$ $\qquad$
14. $\left(3,-\frac{2}{3}\right)$.

If we consider the equation in the problem as a quadratic equation in $x$, then
$$
\begin{array}{l}
\Delta=4(y-1)^{2}-20\left(2 y^{2}+2 y+1\right) \geqslant 0 \\
\Rightarrow(3 y+2)^{2} \leqslant 0 \\
\Rightarrow y=-\frac{2}{3}, x=3 .
\end{array}
$$