Suppose that

$$
\begin{aligned}
M & =1^{5}+2^{4} \times 3^{3}-4^{2} \div 5^{1} \\
N & =1^{5}-2^{4} \times 3^{3}+4^{2} \div 5^{1}
\end{aligned}
$$

What is the value of $M+N$ ?
Since $M=1^{5}+\left(2^{4} \times 3^{3}\right)-\left(4^{2} \div 5^{1}\right)$ and $N=1^{5}-\left(2^{4} \times 3^{3}\right)+\left(4^{2} \div 5^{1}\right)$, then when $M$ and $N$ are added the terms $\left(2^{4} \times 3^{3}\right)$ and $\left(4^{2} \div 5^{1}\right)$ "cancel" out.

Thus, $M+N=1^{5}+1^{5}=2$.

ANSWER: 2