6.015. $\frac{7(x-2)(x-3)(x-4)}{(2 x-7)(x+2)(x-6)}=-2$.
## Solution.

Domain of definition: $x \neq \frac{7}{2}, x \neq-2, x \neq 6$.

From the condition, we get $\frac{11 x^{3}-93 x^{2}+190 x}{(2 x-7)(x+2)(x-6)}=0$. Considering the domain of definition, this equation is equivalent to

$$
\begin{aligned}
& 11 x^{3}-93 x^{2}+190 x=0 \Leftrightarrow x\left(11 x^{2}-93 x+190\right)=0 \Rightarrow \\
& \Rightarrow x_{1}=0 \text { or } 11 x^{2}-93 x+190=0, x_{2}=5, x_{3}=\frac{38}{11}
\end{aligned}
$$

Answer: $x_{1}=0, x_{2}=5, x_{3}=\frac{38}{11}$.