7. Given the point sets $A=\left\{(x, y) \left\lvert\,(x-3)^{2}+(y-4)^{2} \leqslant\left(\frac{5}{2}\right)^{2}\right.\right\}, B=\left\{(x, y) \mid(x-4)^{2}+(y-\right.$ $\left.5)^{2}>\left(\frac{5}{2}\right)^{2}\right\}$, then the number of integer points in $A \cap B$ is $\qquad$.
7. 7 Given, $A$ represents the circle and its interior with center at point $(3,4)$ and radius $\frac{5}{2}$, while $B$ represents the exterior of the circle with center at $(4,5)$ and radius $\frac{5}{2}$. There are 7 points: $(1,3),(1,4),(1,5),(2,3),(2,2),(3,2),(4,2)$.