Teacher Kadrnozkova was buying tickets at the cash register of the zoo for her students and for herself. The ticket for an adult was more expensive than for a schoolchild, but not more than twice as much. Teacher Kadrnozkova paid a total of 994 CZK. Teacher Hnizdo had three more students with him than his colleague, so he paid 1120 CZK for his students and for himself.

1. How many students did Teacher Hnizdo have with him?
2. How much did the ticket for an adult cost?
From the given information, it directly follows that the entrance fee for three students cost $1120 - 994 = 126$ (CZK), so for one student it was $126 : 3 = 42$ (CZK). For 1120 CZK, Teacher Hnízdo could buy tickets for a maximum of 26 students (and 28 CZK would remain), because $1120 : 42 = 26$ (remainder 28). When we add the remainder to the price of a student ticket, we get the price of an adult ticket (this ticket should be more expensive than a student ticket, but not more than twice as much). The teacher's ticket therefore cost $42 + 28 = 70$ (CZK) and there were $26 - 1 = 25$ students.

(For verification: $25 \cdot 42 + 70 = 1120$ and $22 \cdot 42 + 70 = 994$, so everything is in perfect order.)