Kim earned scores of 87,83, and 88 on her first three mathematics examinations. If Kim receives a score of 90 on the fourth exam, then her average will 

$\mathrm{(A) \ \text{remain the same} } \qquad \mathrm{(B) \ \text{increase by 1} } \qquad \mathrm{(C) \ \text{increase by 2} } \qquad \mathrm{(D) \ \text{increase by 3} } \qquad \mathrm{(E) \ \text{increase by 4} }$
The average of the first three test scores is $\frac{88+83+87}{3}=86$. The average of all four exams is $\frac{87+83+88+90}{4}=87$. It increased by one point. $\mathrm{(B)}$