Jose, Thuy, and Kareem each start with the number 10.  Jose subtracts 1 from the number 10, doubles his answer, and then adds 2.  Thuy doubles the number 10, subtracts 1 from her answer, and then adds 2.  Kareem subtracts 1 from the number 10, adds 2 to his number, and then doubles the result.  Who gets the largest final answer?
$\text{(A)}\ \text{Jose} \qquad \text{(B)}\ \text{Thuy} \qquad \text{(C)}\ \text{Kareem} \qquad \text{(D)}\ \text{Jose and Thuy} \qquad \text{(E)}\ \text{Thuy and Kareem}$
Jose gets $10 - 1 = 9$, then $9 \cdot 2 = 18$, then $18 + 2 = 20$.
Thuy gets $10 \cdot 2 = 20$, then $20 - 1 = 19$, and then $19 + 2 = 21$.
Kareem gets $10 - 1 = 9$, then $9 + 2 = 11$, and then $11\cdot 2 = 22$.
Thus, Kareem gets the highest number, and the answer is $\boxed{C}$.