7. (3 points) Five children $A, B, C, D, E$ are sitting in a circle (as shown in the right figure). The teacher gives $A, B, C, D, E$ 2, 4, 6, 8, 10 balls respectively. Then, starting from $A$, they play a game in a clockwise direction: if the number of balls the left neighbor has is less than their own, they give 2 balls to the left neighbor; if the left neighbor has more or the same number of balls, they do not give any. This continues until the fourth round. The number of balls each of them has at the end is
7. (3 points) Five children $A, B, C, D, E$ sit in a circle (as shown in the right figure). The teacher gives $A, B, C, D, E$ 2, 4, 6, 8, 10 balls respectively. Then, starting from $A$, they play a game in a clockwise direction: if the number of balls the left neighbor has is less than their own, they give 2 balls to the left neighbor; if the left neighbor has more or the same number of balls, they do not give any. This continues until the fourth round, and the number of balls each of them has is $6, 6, 6, 6, 6$.
【Solution】Solution: After the teacher distributes the balls, the game begins:
After the first round, the number of balls $A, B, C, D, E$ have is $4, 4, 6, 8, 8$;
After the second round, the number of balls $A, B, C, D, E$ have is $4, 6, 6, 8, 6$;
After the third round, the number of balls $A, B, C, D, E$ have is $6, 6, 6, 6, 6$;
After the fourth round, the number of balls $A, B, C, D, E$ have is still $6, 6, 6, 6, 6$.
Therefore, the answer is: $6, 6, 6, 6, 6$.