B2. Let $p$ be Peter's, $r$ Rok's, and $s$ Simon's age in years, where their ages are the solutions to the equations $3^{p}+3^{4}=90, 2^{r}+44=76$, and $5^{3}+6^{s}=1421$.

A. How old are Peter, Rok, and Simon?

B. In how many years will Rok be twice as old as Peter?

C. Connect the numbers $p, r$, and $s$ with arithmetic operations to get the largest possible result. Write down the calculations.
B2. The solution to the equation $3^{p}+3^{4}=90 \Leftrightarrow 3^{p}=90-3^{4} \Leftrightarrow 3^{p}=9$ is $p=2$. The solution to the equation $2^{r}+44=76 \Leftrightarrow 2^{r}=76-44 \Leftrightarrow 2^{r}=32$ is $r=5$. The solution to the equation $5^{3}+6^{s}=1421 \Leftrightarrow 6^{s}=$ $1421-5^{3} \Leftrightarrow 6^{s}=1296$ is $s=4$.

The year when Rok will be twice as old as Peter, denoted by $x$. Write and solve the equation: $5+x=2 \cdot(2+x)$. Rok will be twice as old as Peter in $x=1$ year.

The maximum possible result is obtained by exponentiation: $\left(2^{5}\right)^{4}=1048576$ or $\left(4^{2}\right)^{5}=1048576$.

A. Calculating the age of Peter $(p=2)$, Rok $(r=5)$, and Simon $(s=4)$.... 3 times 1 t

B. Writing and solving the equation $5+x=2 \cdot(2+x)$. .1 t

Rok will be twice as old as Peter in one year. .
C. $\left(2^{5}\right)^{4}=1048576$ or $\left(4^{2}\right)^{5}=1048576$