2. Connecting the intersection points of the hyperbola $x y=20$ and the circle $x^{2}+y^{2}=41$ in sequence forms a convex quadrilateral. The area of this quadrilateral is ( ).
(A) 18
(B) 20
(C) 22
(D) 30
2.A.

Let $A\left(x_{0}, y_{0}\right)\left(x_{0}>0, y_{0}>0\right)$.
From the fact that the two curves are symmetric with respect to the origin and the line $y=x$, the coordinates of the other three intersection points are $B\left(y_{0}, x_{0}\right)$,
$$
C\left(-x_{0},-y_{0}\right) 、 D\left(-y_{0},-x_{0}\right) \text {. }
$$

From this, we know that quadrilateral $A B C D$ is a rectangle, and its area is
$$
\begin{array}{l}
|A B| \cdot|A D| \\
=\sqrt{2\left(x_{0}-y_{0}\right)^{2}} \cdot \sqrt{2\left(x_{0}+y_{0}\right)^{2}} \\
=2 \sqrt{x_{0}^{2}+y_{0}^{2}-2 x_{0} y_{0}} \cdot \sqrt{x_{0}^{2}+y_{0}^{2}+2 x_{0} y_{0}} \\
=2 \sqrt{41-2 \times 20} \cdot \sqrt{41+2 \times 20}=18 .
\end{array}
$$