$29, 2025$ has a 0 in the hundreds place, removing the 0 results in 225 (only the 0 in the hundreds place is removed), $225 \times 9=2025$, such a 4-digit number is called a "zero-clever number". Therefore, please list all the "zero-clever numbers" are $\qquad$
Solution: Zero cannot be in the first position. Therefore, it can only be in the units, tens, or hundreds place at most.
(1) When 0 is in the units place, the original number is 10 times the new number after removing 0, so it is impossible for 0 to be in the units place.
(2) When 0 is in the tens place, at this time, $\overline{a b 0 c}=\overline{a b c} \times 9$
Simplifying $\overline{a b} \times 100+c=\overline{a b} \times 90+9 c$, we get $\overline{a b} \times 5=4 c$
So $5 \mid c, c$ cannot be 0 (the units digit cannot be 0),
So $c=5$, when $c=5$, $\overline{a b}=4$ (not valid, $\overline{a b}$ is a two-digit number)
(3) When 0 is in the tens place, at this time, $\overline{a 0 b c}=\overline{a b c} \times 9$
$1000 a+\overline{b c}=900 a+\overline{b c} \times 9 \quad$ Simplifying gives $25 a=\overline{b c} \times 2$
So $25 \mid \overline{b c}$, so the possible values of $\overline{b c}$ are $25, 50, 75$, corresponding to $a$ being $2, 4, 6$ respectively
Therefore, all "zero-clever numbers" are $2025, 4050, 6075$.