69. As shown in the figure, in $\triangle A B C$, $B C>A C, \angle A=60^{\circ}, D$ and $E$ are the midpoints of $A B$ and $A C$ respectively. If $P C$ bisects $\angle A C B$ and $P D$ bisects $\angle A D E$, then $\angle D P C=$ $\qquad$ ـ.
Reference answer: $120^{\circ}$