9.3. In the product of three natural numbers, each factor was decreased by 3. Could the product have increased by exactly 2022 in this case?
Answer. Yes, it could.

Solution. The product $1 \cdot 1 \cdot 678$ serves as an example. After the specified operation, it becomes $(-2) \cdot(-2) \cdot 675=2700=678+2022$.

Remark. The given example is the only one. Here is how to come up with it. Suppose two of the factors were 1, and the third was $a$. Their product was $a$, and after the reduction, it became $(-2)^{2}(a-3)=4 a-12$. Therefore, for $4 a-12=a+2022$, the condition is satisfied. Solving this equation, we get $a=678$.

Comment. Only the correct answer - 0 points.

A set of numbers satisfying the condition is presented - 7 points.

In an otherwise correct solution, due to an arithmetic error, the set $1,1, a$ is obtained, where the value of $a$ is incorrect - 5 points.