10. (7 points) In the repeating decimal 0.2017, if the sum of all digits from the $m$-th digit to the $n$-th digit after the decimal point is 2017, when $m$ takes the minimum value, $n=$ $\qquad$


【Solution】Solution: $2+0+1+7=10$,
$$
\begin{array}{l}
2020 \div 10=202, \\
202 \times 4=808,
\end{array}
$$

It can be known that the sum of all digits after the 808th decimal place is 2020.
$$
2020-(2+0+1)=2017 \text{. }
$$

Therefore, the answer to this problem is 808.