How many different sentences with two words can be written using all letters of the word $\text{YARI\c{S}MA}$? 
(The Turkish word $\text{YARI\c{S}MA}$ means $\text{CONTEST}$. It will produce same result.)

$ 
\textbf{(A)}\ 2520
\qquad\textbf{(B)}\ 5040
\qquad\textbf{(C)}\ 15120
\qquad\textbf{(D)}\ 20160
\qquad\textbf{(E)}\ \text{None of the above}
$
1. **Identify the total number of characters:**
   The word "YARIŞMA" consists of 7 letters: Y, A, R, I, Ş, M, A. Note that the letter 'A' appears twice.

2. **Calculate the number of permutations of the letters:**
   Since there are 7 letters with one letter repeating twice, the number of distinct permutations of these letters is given by:
   \[
   \frac{7!}{2!}
   \]
   where \(7!\) is the factorial of 7, and \(2!\) accounts for the repetition of the letter 'A'.

3. **Calculate the factorials:**
   \[
   7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 5040
   \]
   \[
   2! = 2 \times 1 = 2
   \]
   Therefore,
   \[
   \frac{7!}{2!} = \frac{5040}{2} = 2520
   \]

4. **Consider the placement of the space:**
   To form a sentence with two words, we need to place a space among the letters. There are 7 letters, so there are 8 possible positions for the space (before the first letter, between each pair of letters, and after the last letter).

5. **Calculate the total number of different sentences:**
   Each of the 2520 permutations can have the space placed in any of the 8 positions. Therefore, the total number of different sentences is:
   \[
   2520 \times 8 = 20160
   \]

Conclusion:
\[
\boxed{20160}
\]