1. Can the number 8 be represented as the sum of eight integers such that the product of these numbers is also equal to 8?
1. For example, $4+2+1+1+1+1+(-1)+(-1)=8$

and $4 \cdot 2 \cdot 1 \cdot 1 \cdot 1 \cdot 1 \cdot(-1) \cdot(-1)=8$.

Answer: Yes.