9.205. $\left(x^{2}+4 x+10\right)^{2}-7\left(x^{2}+4 x+11\right)+7<0$.
## Solution.

Rewrite the given inequality as

$$
\begin{aligned}
& \left(x^{2}+4 x+10\right)^{2}-7\left(x^{2}+4 x+10\right)0 \text { for } x \in R,
\end{aligned}
$$

then the obtained inequality is equivalent to the inequality $x^{2}+4 x+3<0$. Hence, $-3<x<-1$.

Answer: $x \in(-3 ;-1)$.