The sum of the first 100 positive integers (that is, $1+2+3+\cdots+99+100)$ equals 5050 . The sum of the first 100 positive multiples of 10 (that is, $10+20+30+\cdots+990+1000$ ) equals
(A) 10100
(B) 5950
(C) 50500
(D) 6050
(E) 45450
Each term of the sum $10+20+30+\cdots+990+1000$ is 10 times larger than its corresponding term in the sum $1+2+3+\cdots+99+100$, and so the required sum is 10 times larger than the given sum.

Since $1+2+3+\cdots+99+100=5050$, then $10+20+30+\cdots+990+1000=5050 \times 10=50500$.

ANSWER: (C)