In the addition shown, a digit, either the same or different, can be placed in each of the two boxes. What is the sum of the two missing digits?
(A) 9
(D) 3
(B) 11
(C) 13
$7 \square 8$
$\overline{2182}$

863

$\square 91$
In the addition shown, a digit, either the same or different, can

863

be placed in each of the two boxes. What is the sum of the two missing digits?
(A) 9
(B) 11
(C) 13
(D) 3
(E) 7
2182

## Solution

Adding in the units column gives us, $3+1+8=12$. This means a carry over of 1 into the tens column since $12=1 \times 10+2$. In the tens column, we have 1 (carried over) $+6+9+\square=18$. The digit that is placed in this box is 2 with a carry over of 1 unit into the hundreds column. Moving to the hundreds column we have, 1 (carried over) $+8+\square+7=21$. The missing digit here is 5 . The two missing digits are 2 and 5 giving a sum of 7 .

ANSWER: (E)