1. If $-3<x<-1$, then simplifying $|2-| 1+x||$ yields ().
(A) $1-x$
(B) $-3+x$
(C) $3-x$
(D) $3+x$
$\begin{array}{l}\text { i.1. D. } \\ \text { Original expression }=|2+(1+x)|=|3+x|=3+x \text {. }\end{array}$