Example 11. Factorize:
$$
3 x^{2}-7 x y-6 y^{2}-10 x+8 y+8 \text{. }
$$
Solve $3 x^{2}-7 x y-6 y^{2}$
$$
\begin{array}{l}
=(x-3 y)(3 x+2 y), \\
3 x^{2}-10 x+8=(x-2)(3 x-4), \\
-6 y^{2}+8 y+8=(-3 y-2)(2 y-4) .
\end{array}
$$

The factorization of the above three quadratic trinomials can be expressed in the following form:
$$
\begin{array}{l}
\text { Therefore } 3 x^{2}-7 x y-6 y^{2}-10 x+8 y+8 \\
=(x-3 y-2)(3 x+2 y-4) .
\end{array}
$$