A6. The area of square $A B C D$ is $36 \mathrm{~m}^{2}$. Let $|B E|=2|E C|$. What fraction of the area of square $A B C D$ is occupied by triangle $B E D$?
(A) $\frac{3}{4}$
(B) $\frac{2}{3}$
(C) $\frac{1}{4}$
(D) $\frac{2}{5}$
(E) $\frac{1}{3}$

![](https://cdn.mathpix.com/cropped/2024_06_07_ec35f4a613e63419eaedg-06.jpg?height=360&width=372&top_left_y=1916&top_left_x=1550)
A6. The area of triangle $B E C$ is $S=6 \mathrm{~m}^{2}$, and that of triangle $B A D$ is $S=18 \mathrm{~m}^{2}$. The area of triangle $B E D$ to be found is $36-18-6=12 \mathrm{~m}^{2}$. The corresponding ratio of areas is $\frac{12}{36}=\frac{1}{3}$.

## Sklop B