8. (10 points) There are 60 colored balls in a bag, with 6 balls of each color. If you draw balls while blindfolded, to ensure that you have three balls of the same color, you need to draw at least 21 balls.
【Analysis】 $60 \div 6=10$, there are 10 types of colored balls. Considering the worst-case scenario, if 2 balls of each color are taken, taking one more ball will ensure that there are three balls of the same color among the balls taken. Therefore, the answer is $2 \times 10+1=21$.

【Solution】Solution: $60 \div 6=10$ (types), $2 \times 10+1=21$ (balls);

Answer: At least 21 balls need to be taken; hence the answer is: 21.