For some real number $r$, the polynomial $8x^3-4x^2-42x+45$ is divisible by $(x-r)^2$. Which of the following numbers is closest to $r$?

$\text{(A)} \ 1.22 \qquad \text{(B)} \ 1.32 \qquad \text{(C)} \ 1.42 \qquad \text{(D)} \ 1.52 \qquad \text{(E)} \ 1.62$
To determine the value of \( r \) such that the polynomial \( 8x^3 - 4x^2 - 42x + 45 \) is divisible by \( (x - r)^2 \), we need to ensure that both \( P(r) = 0 \) and \( P'(r) = 0 \). 

1. **Define the polynomial and its derivative:**
   \[
   P(x) = 8x^3 - 4x^2 - 42x + 45
   \]
   \[
   P'(x) = \frac{d}{dx}(8x^3 - 4x^2 - 42x + 45) = 24x^2 - 8x - 42
   \]

2. **Substitute \( y = 2x \) to simplify the polynomial:**
   \[
   P(x) = 8x^3 - 4x^2 - 42x + 45
   \]
   \[
   \text{Let } y = 2x \Rightarrow x = \frac{y}{2}
   \]
   \[
   P\left(\frac{y}{2}\right) = 8\left(\frac{y}{2}\right)^3 - 4\left(\frac{y}{2}\right)^2 - 42\left(\frac{y}{2}\right) + 45
   \]
   \[
   = 8 \cdot \frac{y^3}{8} - 4 \cdot \frac{y^2}{4} - 42 \cdot \frac{y}{2} + 45
   \]
   \[
   = y^3 - y^2 - 21y + 45
   \]

3. **Find the roots of the simplified polynomial using the Rational Root Theorem:**
   The Rational Root Theorem suggests that the possible rational roots of \( y^3 - y^2 - 21y + 45 \) are the factors of 45 divided by the factors of 1, i.e., \( \pm 1, \pm 3, \pm 5, \pm 9, \pm 15, \pm 45 \).

4. **Test the possible roots:**
   \[
   P(3) = 3^3 - 3^2 - 21 \cdot 3 + 45 = 27 - 9 - 63 + 45 = 0
   \]
   Thus, \( y = 3 \) is a root.

5. **Factor the polynomial:**
   Since \( y = 3 \) is a root, we can factor \( y^3 - y^2 - 21y + 45 \) as:
   \[
   (y - 3)(y^2 + 2y - 15)
   \]
   We can verify this by expanding:
   \[
   (y - 3)(y^2 + 2y - 15) = y^3 + 2y^2 - 15y - 3y^2 - 6y + 45 = y^3 - y^2 - 21y + 45
   \]

6. **Find the repeated root:**
   For \( (x - r)^2 \) to divide the polynomial, \( y = 3 \) must be a repeated root. Thus, \( r = \frac{3}{2} = 1.5 \).

The final answer is \( \boxed{1.52} \).