Condition of the problem

Find the derivative.

$y=\ln \ln ^{2} \ln ^{3} x$
## Solution

$y^{\prime}=\left(\ln \ln ^{2} \ln ^{3} x\right)^{\prime}=\frac{1}{\ln ^{2} \ln ^{3} x} \cdot 2 \ln ^{3} \ln ^{3} x \cdot \frac{1}{\ln ^{3} x} \cdot 3 \ln ^{2} x \cdot \frac{1}{x}=$ $=\frac{2}{\ln ^{3} \ln ^{3} x} \cdot \frac{3}{\ln x} \cdot \frac{1}{x}=\frac{6}{x \cdot \ln x \cdot \ln \ln ^{3} x}$

Problem Kuznetsov Differentiation 8-31