11. Given the function
$$
f(x)=\left\{\begin{array}{ll}
-x-1, & -1 \leqslant x < 1 \\
x+1, & x \geqslant 1
\end{array}\right.
$$
the solution set of $f(x) > -1$ is
$\qquad$
$$
=.11 \cdot\left[-1,-\frac{1}{2}\right) \cup(0,1] \text {. }
$$
(1) When $-1 \leqslant x-1$.
Solving for $x-1$.
Solving for $x<\frac{3}{2}$. Then $0<x \leqslant 1$.
In summary, the solution set is $\left[-1,-\frac{1}{2}\right) \cup(0,1]$.