## Task 2 - 010612

In the Soviet rocket tests conducted in October 1961, at a target distance of about $12500 \mathrm{~km}$, all hits were within a circle whose radius was less than $1 \mathrm{~km}$. How large would the radius of the hit circle be for a student who, with the same accuracy, throws a softball at a target $25 \mathrm{~m}$ away?
The ratio of the radius of the hit circle to the distance of the target corresponds to the accuracy of the hit. That is, according to the problem statement, the unknown ratio $x: 25 \mathrm{~m}$ should be equal to the ratio $1 \mathrm{~km}$ : 12500 $\mathrm{km}$.

$$
x=25 \mathrm{~m} \cdot \frac{1 \mathrm{~km}}{12500 \mathrm{~km}}=0.002 \mathrm{~m}=2 \mathrm{~mm}
$$

The hit circle of the student would have a radius of $2 \mathrm{~mm}$.