16. Calculate $(\sqrt{1300}]+[\sqrt{1901}]+\cdots$ $+[\sqrt{1993}]=(\quad)$.
(1993, Hope Cup Mathematics Competition)
$$
\begin{array}{l}
\text { Analysis } \because 43<\sqrt{1900}, \sqrt{1901}, \cdots, \\
\sqrt{1935}<44,44 \leqslant \sqrt{1936}, \sqrt{1937}, \cdots, \\
\sqrt{1993}<45, \\
\therefore[\sqrt{1900}],[\sqrt{1901}], \cdots,[\sqrt{1935}] \text { are all } 43, \text { a total of 36, } [\sqrt{1936}],[\sqrt{1937}], \cdots, [\sqrt{1993}] \text { are all } 44, \text { a total of 58. } \\
\text { Therefore, the required value is } 43 \times 36+44 \times 58=4100.
\end{array}
$$