4. The incident took place in 1968. A high school graduate returned from a written university entrance exam and told his family that he couldn't solve the following problem:

Several identical books and identical albums were bought. The books cost 10 rubles 56 kopecks, and the albums cost 56 kopecks. The number of books bought was 6 more than the number of albums. How many books were bought if the price of a book, which is more than one ruble, exceeds the price of an album?

The adults delved into calculations. But the little brother, a fifth-grader, suddenly blurted out:

- There's nothing to solve here. 8 books!

How did he solve the problem?

If solving this problem caused you difficulty, then think it over again and again, delve into the conditions so that they are clearly imprinted in your memory. Look for and seek new approaches to solving the problem. Try to "guess" the answer, find it by making a rough estimate. How many solutions does the problem have? Write down the solution and check your answer.
4. S o l u t i o n. Since the book is more expensive than a ruble, no more than 10 books were bought. Moreover, it is clear that no fewer than 7 books were bought. By checking, we find that the number 1056 is divisible by 8 and not divisible by $7,9,10$. A n s w e r: 8 books.