B1. Write the expression that corresponds to the given diagram.

Then calculate the value of the expression if:

A is the least common multiple of the numbers 3 and 5,

$B$ is the length of the leg in a right triangle with a hypotenuse of 5 units and another leg of 4 units,

$C$ is the smallest prime number.

![](https://cdn.mathpix.com/cropped/2024_06_07_c432f7ef362881c6ef9bg-3.jpg?height=676&width=1065&top_left_y=690&top_left_x=538)
B1. The expression that corresponds to the diagram is

$$
(95-A: B):((107-98) \cdot C)
$$

Since $A=15, B=3$ and $C=2$, its value is $(95-15: 3):((107-98) \cdot 2)=5$.

![](https://cdn.mathpix.com/cropped/2024_06_07_c432f7ef362881c6ef9bg-6.jpg?height=662&width=1062&top_left_y=540&top_left_x=520)

Scoring: Total: 7 points

The expression written with symbols $\underbrace{(95-A: B)}_{1 \mathrm{t}}: \underbrace{((107-98) \cdot C)}_{\mathbf{1 t}}$, one point for each part. ...... $\mathbf{2} \mathbf{t}$

One point for each correctly determined number $A, B, C$: $A=15, B=3, C=2 \ldots \ldots .3 \mathbf{t}$

![](https://cdn.mathpix.com/cropped/2024_06_07_c432f7ef362881c6ef9bg-6.jpg?height=52&width=1651&top_left_y=1516&top_left_x=228)