Ali chooses one of the stones from a group of $2005$ stones, marks this stone in a way that Betül cannot see the mark, and shuffles the stones. At each move, Betül divides stones into three non-empty groups. Ali removes the group with more stones from the two groups that do not contain the marked stone (if these two groups have equal number of stones, Ali removes one of them). Then Ali shuffles the remaining stones. Then it's again Betül's turn. And the game continues until two stones remain. When two stones remain, Ali confesses the marked stone. At least in how many moves can Betül guarantee to find out the marked stone?

$ 
\textbf{(A)}\ 11
\qquad\textbf{(B)}\ 13
\qquad\textbf{(C)}\ 17
\qquad\textbf{(D)}\ 18
\qquad\textbf{(E)}\ 19
$
1. **Understanding the Problem:**
   - Ali marks one stone out of 2005 stones.
   - Betül divides the stones into three non-empty groups.
   - Ali removes the group with more stones from the two groups that do not contain the marked stone.
   - The game continues until two stones remain, and Ali reveals the marked stone.

2. **Objective:**
   - Determine the minimum number of moves Betül needs to guarantee finding the marked stone.

3. **Strategy Analysis:**
   - Betül can shrink the pile by almost one-half each time.
   - For a pile of \(2n + 1\) stones, Betül can split it into a pile of 1 stone and two piles of \(n\) stones.
   - For a pile of \(2n + 2\) stones, Betül can split it into a pile of 2 stones and two piles of \(n\) stones.

4. **Mathematical Justification:**
   - Each move effectively reduces the number of stones by approximately half.
   - The number of moves required to reduce the pile to 2 stones can be estimated using the logarithm base 2.

5. **Calculation:**
   - The number of moves required is given by \(\lceil \log_2 2005 \rceil\).
   - Calculate \(\log_2 2005\):
     \[
     \log_2 2005 \approx 10.97
     \]
   - Taking the ceiling of 10.97:
     \[
     \lceil 10.97 \rceil = 11
     \]

6. **Conclusion:**
   - Betül can guarantee finding the marked stone in at least 11 moves.

The final answer is \(\boxed{11}\)