2. Six numbers are given, the arithmetic mean of which is equal to some number A. Petrov calculated the arithmetic mean of the first four numbers - it turned out to be A+10. Vasechkin calculated the arithmetic mean of the last four numbers - it is A - 7. In which direction and by how much does the arithmetic mean of the first, second, fifth, and sixth of these numbers differ from A?
Answer: 3 less.

Solution - similar to option v3a.