In the diagram, squares of side length 1 meet each other at their vertices. The perimeter of the figure is
(A) 14
(B) 20
(C) 24
(D) 28
(E) 32

![](https://cdn.mathpix.com/cropped/2024_04_20_6ed09463f225f8ba1f07g-014.jpg?height=382&width=228&top_left_y=1148&top_left_x=1312)
The perimeter of each of the squares of side length 1 is $4 \times 1=4$.

The perimeters of the 7 squares in the diagram do not overlap, and so the perimeter of the entire figure is $7 \times 4=28$.

ANSWER: (D)