7. Let $[x]$ denote the greatest integer not exceeding the real number $x$, and $\{x\}=x-[x]$. Then
$$
\left\{\frac{2015!}{2017}\right\}=
$$
$\qquad$
$\begin{array}{l}\text { 7. } \frac{1}{2017} \cdot \\ \text { From } 2016! \equiv -1 \equiv 2016(\bmod 2017) \\ \Rightarrow 2017!2016(2015!-1) \\ \Rightarrow 2017 \text { ! } 2015!-1) \\ \Rightarrow\left\{\frac{2015!}{2017}\right\}=\frac{1}{2017} .\end{array}$