9. Arrange all positive integers that are coprime with 143 in ascending order to form a sequence. The 2022nd term of this sequence is $\qquad$
Since $143=11 \times 13$, in the range $[1,143]$, there are $143-13-11+1=120$ positive integers that are coprime with 143. Since $2022=$ $120 \times 16+102$, the 102nd number in the sequence of positive integers in $[1,143]$ that are coprime with 143 (arranged from largest to smallest) is $142,141,140,139,138,137,136$, $135,134,133,131,129,128,127,126,125,124,123,122$, and the 102nd number is 122.
Therefore, the 2022nd term of this sequence is $143 \times 16+122=2410$.