8,9 |

In a right triangle $ABC$ with equal legs $AC$ and $BC$, a circle is constructed on side $AC$ as a diameter, intersecting side $AB$ at point $M$. Find the distance from vertex $B$ to the center of this circle, if $BM = \sqrt{2}$.
$C M$ - height of the triangle.

## Solution

Answer

$\sqrt{5}$.