7、Xiaoming and Xiaohong are running on a 600-meter circular track. The two start from the same starting point at the same time and run in opposite directions. The time interval between the first and second meeting is 50 seconds. It is known that Xiaohong's speed is 2 meters/second slower than Xiaoming's, so Xiaoming's speed is $\qquad$ meters/second
【Answer】7
Analysis:
Method one: Let Xiaohong's speed be $\mathrm{x}$ meters/second, and Xiaoming's speed be $\mathrm{x}+2$ meters/second. The two meet after covering the entire distance once, so $50(x+x+2)=600, x=5$, then Xiaoming's speed is $5+2=7$ meters/second.
Method two: The two meet after covering the entire distance once, so the combined speed of the two is $600 \div 50=12$, the speed difference between the two is 2 meters/second, then the speed of Xiaoming (the faster one) is $(12+2) \div 2=7$ meters/second.