560. How many zeros are at the end of the product of all natural numbers from 1 to 60?
$\triangle$ Since zeros in the product of natural numbers are formed by multiplying twos by fives, it is desirable to know how many twos and fives are in the prime factorization of the given product. However, since there are more twos than fives in this factorization, it is sufficient to count the number of fives.

First of all, fives are present in the prime factorizations of the numbers

$$
5,10,15,20,25,30,35,40,45,50,55,60 .
$$

There are 12 such numbers.

In addition, there is one extra five in the numbers 25 and 50. In total, this results in 14 fives. Therefore, the given product ends with 14 zeros. Answer: 14