5. In the "6 out of 45" lottery, a participant makes a bet by selecting any 6 numbers from 1 to 45 (the order of selection does not matter, but all numbers must be different). During the draw, a random winning combination of 6 numbers is determined. A "jackpot" is the event where a participant, by making a bet, guesses all 6 numbers correctly.

A player bought 100 tickets and in each, selected 6 numbers such that there were no repeating combinations in two different tickets. Estimate the probability p of the "jackpot."
Answer:

1) from 0.01 to 0.1
2) from 0.001 to 0.01
3) from 0.0001 to 0.001
4) from 0.00001 to 0.0001

Answer: 4. In the lottery, there are $C_{45}^{6}=\frac{45 \cdot 44 \cdot 43 \cdot 42 \cdot 41 \cdot 40}{1 \cdot 2 \cdot 3 \cdot 4 \cdot 5 \cdot 6}=8145060$ possible combinations of numbers. The probability of a "jackpot" for a player with a hundred tickets with different combinations is $\frac{100}{8145060} \approx 0.0000123$.