10. The sum of the ages of four people, A, B, C, and D, is 100 years. A is 32 years old, and the sum of his age and B's age is three times the sum of the ages of the other two people. C is 3 years older than D. Therefore, among these four people, the sum of the ages of the oldest and the youngest is $\qquad$.
【Answer】 54
【Solution】 Sum and multiple problem + sum and difference problem. The sum of the ages of A and B is 3 times the sum of the ages of C and D, and the total sum of the ages of A, B, C, and D is 100 years. According to the sum and multiple formula, C and D: 100 $\div(3+1)=25$ (years), A and B: $100-25=75$ (years). A is 32 years old, so B $75-32=43$ (years). C and D are 25 years old, C is 3 years older than D, $43+11=54$ (years).