5. Person A and Person B simultaneously solve the same math competition problem. If they solve it correctly, the teacher will give a reward of 190 yuan, with the rule that the reward goes to whoever solves it correctly. If both solve it correctly, the reward is split equally. It is known that the probability of A solving it correctly is $\frac{3}{4}$, and the probability of B solving it correctly is $\frac{4}{5}$. What is the most reasonable distribution of the reward? $\qquad$
5. 100 Detailed Explanation: A gets 90 yuan, B gets 100 yuan; Hint: The probability of A answering correctly alone is $\frac{\frac{3}{4} \times \frac{1}{5}}{\frac{3}{4} \times \frac{1}{5}+\frac{1}{4} \times \frac{4}{5}+\frac{3}{4} \times \frac{4}{5}}=\frac{3}{19}$, the probability of B answering correctly alone is $\frac{\frac{1}{4} \times \frac{4}{5}}{\frac{3}{4} \times \frac{1}{5}+\frac{1}{4} \times \frac{4}{5}+\frac{3}{4} \times \frac{4}{5}}=\frac{4}{19}$, the probability of A and B answering correctly simultaneously is $\frac{\frac{3}{4} \times \frac{4}{5}}{\frac{3}{4} \times \frac{1}{5}+\frac{1}{4} \times \frac{4}{5}+\frac{3}{4} \times \frac{4}{5}}=\frac{12}{19}$, therefore, the prize money A should receive is $\frac{3}{19} \times 190+\frac{12}{19} \times \frac{190}{2}=90$; the prize money B should receive is $\frac{4}{19} \times 190+\frac{12}{19} \times \frac{190}{2}=100$