8. The shape of a workpiece is shown in Figure 4, the degree of arc $\overparen{B C}$ is $60^{\circ}, A B=$ $6 \text{ cm}$, the distance between points $B$ and $C$ equals $A B$, $\angle B A C=30^{\circ}$. Then the area of this workpiece is $\qquad$.
$8.6 \pi \mathrm{cm}^{2}$.
From the condition, points $A$, $B$, and $C$ lie on a circle with a radius of $6 \mathrm{~cm}$, so the area of the workpiece is
$$
\frac{60}{360} \times \pi \times 6^{2}=6 \pi\left(\mathrm{cm}^{2}\right) \text {. }
$$