4. A. As shown in Figure 2, the area of $\triangle A B C$ is 24, point $D$ is on line segment $A C$, and point $F$ is on the extension of line segment $B C$, with $B C=4 C F$. If quadrilateral $D C F E$ is a parallelogram, then the area of the shaded part in the figure is ( ).
(A) 3
(B) 4
(C) 6
(D) 8
4. A. C.

As shown in Figure 7, in quadrilateral DCFE, $DE // CF, EF // DC$:
Connect $CE$ and $AF$.
Since $DE // CF$, which means $DE // BF$, therefore,
$S_{\triangle DEB} = S_{\triangle DEC}$.
Thus, the area of the shaded part is equal to the area of $\triangle ACE$.
Similarly, $S_{\triangle CEF} = S_{\triangle MCF}$.
Also, since $BC = 4CF$, then $S_{\triangle MBC} = 4S_{\triangle MCF}$.
Therefore, the area of the shaded part is 6.