10.1. Propose a word problem that reduces to solving the inequality

$$
\frac{11}{x+1.5}+\frac{8}{x} \geqslant \frac{12}{x+2}+2
$$

Write the problem statement, its solution, and the answer.

Example of the required problem. Points A and B are connected by two roads: one is 19 km long, and the other is 12 km long. At 12:00, a pedestrian left point A on the longer road and walked the first 11 km at a constant speed, and then, getting tired, walked the remaining distance to point B at an average speed 1.5 km/h slower. At 14:00, a second pedestrian left point A on the shorter road and walked the entire distance at an average speed 0.5 km/h faster than the first pedestrian initially walked. What was the average speed at which the first pedestrian walked the last 8 km of the journey, if it is known that he arrived at point B no earlier than the second pedestrian?

Brief solution. If \( x \) is the required average speed of the first pedestrian (in km/h) on the second part of the journey, then \( x+1.5 \) is his speed on the first part, and \( (x+1.5)+0.5=x+2 \) is the average speed of the second pedestrian. Then, by calculating the time each pedestrian spent on the journey, we obtain the required inequality. Since by the problem's condition \( x > 0 \), both sides of the inequality can be multiplied by the quantity \( x(x+1.5)(x+2) > 0 \), then we get \( 11x(x+2) + 8(x+1.5)(x+2) \geqslant 12x(x+1.5) + 2x(x+1.5)(x+2) \), or, after transformations, \( (x-4)(x+1)(x+3) \leqslant 0 \). Therefore, \( 0 < x \leqslant 4 \), and all found values of \( x \) satisfy the problem's condition.
Answer: no more than 4 km/h.