If $3(x-5)=3(18-5)$, then $x$ is
(A) $\frac{44}{3}$
(B) $\frac{32}{3}$
(C) 9
(D) 18
(E) 81
If $3(x-5)=3(18-5)$, then $x$ is
(A) $\frac{44}{3}$
(B) $\frac{32}{3}$
(C) 9
(D) 18
(E) 81

Solution

Since $3(x-5)=3(18-5)$, divide both sides by 3 to get $(x-5)=(18-5)$.

Therefore, $x=18$.

ANSWER: (D)