The height of a right triangle, dropped to the hypotenuse, is 1, and one of the acute angles is $15^{\circ}$.

Find the hypotenuse.
Draw the median from the vertex of the right angle.

## Solution

Let $C H$ be the height of the right triangle $A B C$, drawn from the vertex of the right angle $C, \angle A=15^{\circ}$. Draw the median $C M$. The angle $C M H$ as the external angle of the isosceles triangle $A M C$ is $30^{\circ}$. From the right triangle $C M H$, we find that $C M=2 C H=2$. Therefore, $A B=2 C M=4$.

## Answer

4.