4. Professor Wang arrived at the station at 8:00 AM. When he boarded the train, the hour and minute hands of the clock on the platform were exactly symmetrical to each other. The train departed at 8:35 AM and arrived at the final station at 2:15 PM. When Professor Wang got off the train, the hour and minute hands of the clock on the platform were exactly vertically symmetrical. He walked out of the station at exactly 3:00 PM. Therefore, the total time Professor Wang spent on the train is $\qquad$ minutes.
【Answer】 360
【Analysis】When boarding the train, the hour and minute hands of the clock are exactly symmetrical. At 8 o'clock, the angle between the hour and minute hands is 120 degrees. $120 \div(6+0.5)=\frac{240}{13}$ (minutes), at this time it is 8 o'clock $\frac{240}{13}$ minutes.

At 2:15 PM, the angle between the hour and minute hands is $15 \times 6-(60+0.5 \times 15)=22.5$ (degrees).
When walking to the platform, it is exactly vertically symmetrical: $22.5 \div(6+0.5)=\frac{45}{13}$ (minutes), at this time it is 2:15 PM $\frac{240}{13}$ minutes.
Professor Wang spent 6 hours on the train, totaling 360 minutes.