12. Person A and Person B start from points A and B respectively at the same time and travel towards each other at a constant speed, meeting after 8 hours. If both increase their speed by 2 kilometers per hour, they will meet 6 hours later at a point 3 kilometers away from the midpoint of AB. Given that A travels faster than B, how many kilometers does A originally travel per hour? $\qquad$ kilometers.
【Analysis】If both individuals walk 2 kilometers more per hour, then their combined speed increases by 4 kilometers per hour, reducing the meeting time from 8 hours to 6 hours. The time ratio is $4: 3$, so the speed ratio is $3: 4 = 12: 16$, meaning the combined speed increases from 12 kilometers/hour to 16 kilometers/hour.
In the second scenario, the two individuals meet 3 kilometers away from the midpoint, resulting in a distance difference of 6 kilometers over 6 hours. Therefore, the speed difference between the two individuals is 1 kilometer/hour. Using the sum and difference method, we can determine that after the speed increase, their speeds are 8.5 kilometers/hour and 7.5 kilometers/hour, respectively. Thus, originally, person A walked 6.5 kilometers per hour.