17. Two squares with side lengths of 4 and 10 are placed as shown in the figure. Then the area of the shaded part in the figure is $\qquad$

 untranslated part: 

(If there was a figure, it would be mentioned here, but since the original text does not include a figure, this part remains unchanged.)
【Analysis】Both shaded parts are trapezoids with equal bases (the upper base is 4, the lower base is 10). When combined, the height can be considered as 10 $-4=6$. Then, using the formula for the area of a trapezoid $S=(a+b) h \div 2$, substitute the data to solve.

【Solution】Solution: According to the analysis,
$$
\begin{aligned}
& (4+10) \times(10-4) \div 2 \\
= & 14 \times 6 \div 2 \\
= & 42
\end{aligned}
$$

Answer: The area of the shaded part in the figure is 42.
Therefore, the answer is: 42.