Given a regular hexagon, a circle is drawn circumscribing it and another circle is drawn inscribing it. The ratio of the area of the larger circle to the area of the smaller circle can be written in the form $\frac{m}{n}$ , where m and n are relatively prime positive integers. Compute $m + n$.
1. **Determine the radius of the circumscribed circle:**
   - A regular hexagon can be divided into 6 equilateral triangles.
   - The radius of the circumscribed circle is equal to the side length \( s \) of the hexagon.
   - Therefore, the area of the circumscribed circle is:
     \[
     \text{Area}_{\text{circumscribed}} = \pi s^2
     \]

2. **Determine the radius of the inscribed circle:**
   - The inscribed circle touches the midpoint of each side of the hexagon.
   - The distance from the center of the hexagon to the midpoint of a side is the height of one of the equilateral triangles formed by dividing the hexagon.
   - The height \( h \) of an equilateral triangle with side length \( s \) is given by:
     \[
     h = \frac{\sqrt{3}}{2} s
     \]
   - Therefore, the radius of the inscribed circle is:
     \[
     r_{\text{inscribed}} = \frac{\sqrt{3}}{2} s
     \]
   - The area of the inscribed circle is:
     \[
     \text{Area}_{\text{inscribed}} = \pi \left( \frac{\sqrt{3}}{2} s \right)^2 = \pi \left( \frac{3}{4} s^2 \right) = \frac{3 \pi}{4} s^2
     \]

3. **Calculate the ratio of the areas:**
   - The ratio of the area of the larger circle to the area of the smaller circle is:
     \[
     \frac{\text{Area}_{\text{circumscribed}}}{\text{Area}_{\text{inscribed}}} = \frac{\pi s^2}{\frac{3 \pi}{4} s^2} = \frac{\pi s^2 \cdot 4}{3 \pi s^2} = \frac{4}{3}
     \]

4. **Simplify the ratio and find \( m + n \):**
   - The ratio \(\frac{4}{3}\) is already in its simplest form, where \( m = 4 \) and \( n = 3 \).
   - Therefore, \( m + n = 4 + 3 = 7 \).

The final answer is \( \boxed{ 7 } \).