9. (3 points) The following is a 3x3 grid, where the characters 【Hua, Luo, Geng, Bei, Shu, Xue, Jing, Ying, Sai】 represent nine different digits from 1 to 9, and these nine numbers meet the following three conditions:
(1) The sum of the four numbers in each "square" is equal.
(2) Hua $\times$ Hua $=$ Ying $\times$ Ying + Sai $\times$ Sai.
(3) Shu > Xue
According to the above conditions, the product of the three numbers represented by 【Hua, Bei, Sai】 is $\qquad$
【Analysis】According to the 3 conditions in the question, classify and discuss each one to determine the values of the numbers represented by 华, 杯, and 赛, and thus find the product of the three numbers.

【Solution】Solution: According to the text in the figure, 华, 罗, 庚, 杯, 数, 学, 精, 英, and 赛 represent nine different numbers from 1 to 9, respectively. Since $5^{2}=3^{2}+4^{2}$, according to condition (2), 华 is 5, and 英 and 赛 are 3 and 4 or 4 and 3;
(1) When 英 is 3 and 赛 is 4, from condition (1) 罗 + 庚 = 7, and 5 + 罗 = 3 + 精, it can be deduced that 罗 can only be 6, 庚 is 1, and 精 is 8,

So 8 + 杯 = 4 + 学, there is no solution, which does not meet the requirements,
Therefore, 英 is 4, and 赛 is 3;
(2) Since from condition (1) 罗 + 庚 = 7, at this point, 罗 and 庚 can only be 1 and 6 or 6 and 1,
(1) When 罗 is 6 and 庚 is 1, from condition (1) 5 + 6 = 4 + 精, 杯 + 精 = 3 + 学, at this time 精 is 7, 杯 is larger than 学 by
4, which does not meet the requirements.
(2) When 罗 is 1 and 庚 is 6, from condition (1) 5 + 杯 = 6 + 学, 杯 + 精 = 学 + 3, it can be deduced: 精 = 2, 杯 is larger than 学 by
1,
Also, from condition (3) 数 > 学, it can be deduced that 学 is 7, 杯 is 8, and 数 is 9, which meets the requirements.
Therefore, 华 is 5, 杯 is 8, and 赛 is 3,
Thus, the product of the three numbers represented by 华, 杯, and 赛 is: $5 \times 8 \times 3 = 120$.
The answer is: 120.