Let $t$ be TNYWR.

The lines with equations $y=13$ and $y=3 x+t$ intersect at the point $(a, b)$. What is the value of $a$ ?
Since the two lines intersect at $(a, b)$, then these coordinates satisfy the equation of each line.

Therefore, $b=13$ and $b=3 a+t$.

Since $b=13$, then $13=3 a+t$ or $3 a=13-t$, and so $a=\frac{13}{3}-\frac{1}{3} t$.

Since the answer to (b) is 1 , then $t=1$, and so $a=\frac{13}{3}-\frac{1}{3}=4$.

ANSWER: $8,1,4$