## Task 6 - V00606

What is the fraction with a single-digit denominator that is greater than $\frac{7}{9}$ and less than $\frac{8}{9}$?
A possible fraction is the arithmetic mean of $\frac{7}{9}$ and $\frac{8}{9}$:

$$
\frac{\frac{7}{9}+\frac{8}{9}}{2}=\frac{\frac{15}{9}}{2}=\frac{15}{30}=\frac{5}{6}
$$

The problem is not uniquely solvable, as for example, $\frac{6}{7}$ is also such a fraction.