A tourist group rented a car for 220 koronas. At the moment of departure, one more passenger joined them, so that each passenger had to pay 2 koronas less. How many passengers were there originally?
Let the number of tourists be $x$; then each one gets $220: x$ korona. If one more passenger joins them, then each one gets $220 : (x+1)$ korona, which is 2 less than the previous amount. The equation, whose roots include $x$, is as follows:

$$
\frac{220}{x}=\frac{220}{x+1}+2
$$

After appropriate rearrangement, this equation takes the following form:

$$
x^{2}+x-110=0
$$

and its roots are $x^{\prime}=10, \quad x^{\prime \prime}=-11$.

Since we are dealing with people, $x$ can only have a positive value, which is 10 passengers originally.

(Suták Sándor, 8th grade student of the Grammar School, Nyíregyháza).

The problem was also solved by: Berzenczey Domokos, 8th grade student of the Real School, Déva; Weisz Lipót, 6th grade student of the Real School, Pécs; Rosenberg József, 8th grade student of the Real School, Györ; Imre János, 8th grade student of the Grammar School, Nyíregyháza.