2. If the focal distance of the conic section $\frac{x^{2}}{k-2}+\frac{y^{2}}{k+5}=1$ is independent of the real number $k$, then its foci coordinates are $\qquad$
2. $(0, \pm \sqrt{7})$.

Since $(k+5)-(k-2)=7$ is a constant, it represents an ellipse with foci on the $y$-axis, and $c=\sqrt{7}$.
Therefore, the coordinates of its foci should be $(0, \pm \sqrt{7})$.