$J K L M$ is a square and $P Q R S$ is a rectangle. If $J K$ is parallel to $P Q, J K=8$ and $P S=2$, then the total area of the shaded regions is
(A) 32
(B) 16
(C) 56
(D) 48
(E) 62

![](https://cdn.mathpix.com/cropped/2024_04_20_46ead6524a8d61e21c51g-045.jpg?height=174&width=464&top_left_y=1515&top_left_x=1275)
The total area of the shaded regions is the difference between the area of square $J K L M$ and the area of the portion of rectangle $P Q R S$ that overlaps $J K L M$.

Since $J K=8$, then the area of square $J K L M$ is $8 \times 8$ or 64 .

Since $J K$ is parallel to $P Q$, then the portion of $P Q R S$ that overlaps $J K L M$ is a rectangle, and has length equal to $J K$ or 8 , and width equal to $P S$ or 2 .

So the area of the portion of $P Q R S$ that overlaps $J K L M$ is $8 \times 2=16$.

Therefore the total area of the shaded regions is $64-16=48$.

ANSWER: (D)