5. (16th "Hope Cup" Grade 1 High School 2nd Test) The even function $f(x) (x \in \mathbf{R})$ satisfies: $f(-4)=$ $f(1)=0$, and is decreasing on the intervals $[0,3]$ and increasing on $[3,+\infty)$, then the solution set of the inequality $x^{3} f(x)<0$ is ( )
A. $(-\infty,-4) \cup(4,+\infty)$
B. $(-4,-1) \cup(1,4)$
C. $(-\infty,-4) \cup(-1,0)$
D. $(-\infty,-4) \cup(-1,0) \cup(1,4)$
5. D From the problem, $f(4)=f(-4)=0$, draw a schematic diagram, see the right figure. When $x>0$, $x^{3} f(x)0$, i.e., $f(-x)>0$. $-x \in(0,1) \cup(4,+\infty), x \in(-\infty,-4) \cup(-1,0)$. Therefore, choose D.