How many sides does that polygon have, in which the number of diagonals is 33 more than the number of sides?
If the number of pages is $n$, then

$$
\frac{n(n-3)}{2}=n+33
$$

or

$$
n^{2}-5 n-66=0
$$

from which the positive value of $n$ is 11.

The problem was also solved by: Bauer E., Breuer P., Dénes M., Döri V., Engler J., Erdős V., Fried E., Grün E., Grünwald M., Klein G., Köhler I., Koffer B., Lendvai D., Lengyel K., Neumann L., Schnabel L., Sichermann F., Spitzer L., Steiner L., Stolzer I., Szilárd V., Vilcsek A., Viola R., Wellis E.