1. If $\frac{20122012 \cdots 201215}{n \uparrow}$ is divisible by 15, then the minimum value of $n$ is ( ).
(A) 3
(B) 4
(C) 5
(D) 6
-1.A.
Obviously, 5। $\underset{n \uparrow}{20122012 \cdots 201215}$.
And the sum of the digits of the permutation of $n$ 2012s is $5n$, so the minimum value of $n$ is 3.