7. (10 points) 6 small circles of equal radius and 1 large circle are arranged as shown in the figure. The area of the large circle is 120. Therefore, the area of one 

small circle is $\qquad$ .
【Solution】Solution: According to the analysis, as shown in Figure 1, by symmetry, the areas of $\triangle A D E$ and $\triangle O B E$ are equal. Therefore, it can be known that the area of $\triangle A O D$ is equal to the area of $\triangle A O B$, both of which are one-third of the area of $\triangle A B C$. Since $\triangle A O D$ and $\triangle A B C$ are both inscribed equilateral triangles in the circle, it can be concluded that the area of the smaller circle is one-third of the area of the larger circle,

According to this, the area of the smaller circle is 40

Therefore, the answer is: 40.