The points $(6,12)$ and $(0,-6)$ are connected by a straight line. Another point on this line is:
$\textbf{(A) \ }(3,3)  \qquad \textbf{(B) \ }(2,1) \qquad \textbf{(C) \ }(7,16) \qquad \textbf{(D) \ }(-1,-4) \qquad \textbf{(E) \ }(-3,-8)$
The slope of this line is $\frac{y_2-y_1}{x_2-x_1}=\frac{12+6}{6-0}=3$. Hence, its equation is $y=3x-6$. The only given point which satisfies these conditions is $\boxed{\textbf{(A)}\ (3,3)}$.