2. If real numbers $x, y$ satisfy $(x+5)^{2}+(y-12)^{2}=14^{2}$, then the minimum value of $x^{2}+y^{2}$ is
A. 2
B. 1
C. $\sqrt{3}$
D. $\sqrt{2}$
Solve for
$x^{2}+y^{2}$ which represents the square of the distance $d$ from point $M(x, y)$ on the circle $(x+5)^{2}+(y-12)^{2}=14^{2}$ to the origin $O$. Let the center of the circle be $C(-5,12)$, then $d_{\min }=R-|O C|=1$, where the equality holds when $O, M, C$ are collinear. Therefore, the minimum value of $x^{2}+y^{2}$ is $d_{\min }^{2}=1$, so the answer is $B$.