What is $\frac{2^3 + 2^3}{2^{-3} + 2^{-3}}$?
$\textbf {(A) } 16 \qquad \textbf {(B) } 24 \qquad \textbf {(C) } 32 \qquad \textbf {(D) } 48 \qquad \textbf {(E) } 64$
We can synchronously multiply ${2^3}$ to the expresions both above and below the fraction bar. Thus, 
\[\frac{2^3+2^3}{2^{-3}+2^{-3}}\\=\frac{2^6+2^6}{1+1}\\={2^6}.\]
Hence, the fraction equals to $\boxed{{\textbf{(E) }64}}$.