133. Digits and Prime Numbers. Using each of the nine digits once and only once, form prime numbers (numbers that do not divide evenly by any integer except 1 and themselves) whose sum is the smallest.

For example, four prime numbers

61

+283

47

59

450

contain all nine digits once and only once, and their sum is 450, but it can be significantly reduced. This is a very simple puzzle.
133. The digits 4, 6, and 8 must be in the second place, since no prime number can end in these digits. The digits 2 and 5 can appear in the units place only if the prime number is a single digit, meaning there are no other digits. After this, the solution can be completed without much difficulty:

\[
\begin{array}{r}
47 \\
61 \\
+\quad 89 \\
2 \\
3 \\
5 \\
\hline 207
\end{array}
\]