37. Convert $\frac{1}{7}$ to a decimal, then find the sum of the digit in the 2017th position after the decimal point and the digit in the 7102nd position after the decimal point.
Answer: 9.
Solution: $\frac{1}{7}=0.142857142857 \cdots=0.142857$. Each 6 digits form a repeating cycle.
Since
$$
2017=6 \times 336+1 \text{. }
$$

Therefore, converting $\frac{1}{7}$ to a decimal, the 2017th digit after the decimal point is 1.
Also, since
$$
7102=6 \times 1183+4,
$$

converting $\frac{1}{7}$ to a decimal, the 7102nd digit after the decimal point is 8.

Thus, the sum of the 2017th digit and the 7102nd digit after the decimal point is
$$
1+8=9 \text{. }
$$