469. Solve the equation:

$$
x^{4}+5 x^{3}-3 x^{2}-35 x-28=0
$$

(solved by elementary means).
469. $x^{4}+x^{3}+4 x^{3}+4 x^{2}-7 x^{2}-7 x-28 x-28=0$;

$$
\begin{gathered}
x^{3}(x+1)+4 x^{2}(x+1)-7 x(x+1)-28(x+1)=0 ; x_{1}=-1 \\
x^{3}+4 x^{2}-7 x-28=0 \\
x^{2}(x+4)-7(x+4)=0 \\
x_{2}=-4 ; \quad x^{2}-7=0 ; \quad x_{3,4}= \pm \sqrt{7}
\end{gathered}
$$