Example 4 (Question from the 7th "Hope Cup" Invitational Competition) The angle between two rays drawn from a point outside plane $M$ to $M$ is $\alpha(0\beta$
D. Cannot be determined



Translate the above text into English, please keep the original text's line breaks and format, and output the translation result directly.
Solution: Choose D. Reason: As shown in Figure 7-4, point $P$ is outside plane $M$, $PB$ and $PD$ are two rays, $PA \perp$ plane $M$ at $A$, $AB$ and $AD$ are the projections of $PB$ and $PD$ on plane $M$, $\angle BPD=\alpha, \angle BAD=\beta, \angle APD=\gamma$, making $\gamma=2\beta$ (which is possible). Then, fix the positions of points $P, A, B$ and the direction of $AD$. As point $D$ approaches point $A$, the size of $\alpha$ can infinitely approach $\beta$, during which $\alpha$ can equal $\beta$ or be greater than $\beta$. Similarly, in the initial figure, if $\gamma=\frac{1}{2}\beta$, then as point $D$ approaches point $A$, $\alpha<\beta$.