We have a deck containing 52 cards. Each card has a value among "1, 2, 3, $4,5,6,7,8,9,10$, jack, queen, king" and a suit among "hearts, diamonds, spades, clubs", such that, for each value and each suit, the deck contains a unique card with this value and this suit. A hand of 5 cards is a selection of 5 cards from this deck, without regard to the order in which the cards are chosen. How many 5-card hands contain four cards of the same value?

Only a numerical answer is expected here.
To choose a 5-card hand where 4 cards have the same value, you first need to choose the value in question. There are 13 choices for this since there are 13 values. There are then 48 choices for the fifth card. Therefore, there are a total of $13 \times 48 = 624$ possible hands.

Comment: The exercise was handled very well overall. However, there are a few recurring mistakes to note. Several students forgot to take into account the choice of the suit of the fifth card. Others unfortunately made mistakes in counting the values present in the deck.