What is the remainder when $2^{202} +202$ is divided by $2^{101}+2^{51}+1$?
$\textbf{(A) } 100 \qquad\textbf{(B) } 101 \qquad\textbf{(C) } 200 \qquad\textbf{(D) } 201 \qquad\textbf{(E) } 202$
\begin{align*} 2^{202} + 202 &= (2^{101})^2 + 2\cdot 2^{101} + 1 - 2\cdot 2^{101} + 201\\ &= (2^{101} + 1)^2 - 2^{102} + 201\\ &= (2^{101} - 2^{51} + 1)(2^{101} + 2^{51} + 1) + 201. \end{align*}
Thus, we see that the remainder is surely $\boxed{\textbf{(D) } 201}$
(Source: [https://artofproblemsolving.com/community/c5h2001950p14000817](https://artofproblemsolving.comhttps://artofproblemsolving.com/community/c5h2001950p14000817))