## Task 1 - 060831

The edge of one cube has a length of $a_{1}=2 \mathrm{~cm}$, and that of another cube has a length of $a_{2}=6 \mathrm{~cm}$.

Calculate the ratio of the edge lengths of these two cubes, the ratio of their surface areas, and the ratio of their volumes!
Let the surface areas of the two cubes be $O_{1}$ and $O_{2}$, and the volumes be $V_{1}$ and $V_{2}$. Then we have:

$$
\begin{aligned}
a_{1}: a_{2} & =2: 6=1: 3 \\
O_{1}: O_{2} & =6 a_{1}^{2}: 6 a_{2}^{2}=24: 216=1: 9 \\
V_{1}: V_{2} & =a_{1}^{3}: a_{2}^{3}=8: 216=1: 27
\end{aligned}
$$