4. The equation of the line passing through point $A(1,-4)$ and parallel to the line $2 x+3 y+5=0$ is $\qquad$
4. $2 x+3 y+10=0$, Hint: We can set the equation as $2 x+3 y+c=0$, substitute $(1,-4)$, and solve for $c$.

Substitute the point $(1, -4)$ into the equation $2 x+3 y+c=0$ to find the value of $c$.