G6.4 A group of 5 people is to be selected from 6 men and 4 women. Find $d$, the number of ways that there are always more men than women.
3 men and 2 women, number of combinations $=C_{3}^{6} \cdot C_{2}^{4}=120$
4 men and 1 woman, number of combinations $=C_{4}^{6} \cdot C_{1}^{4}=60$
5 men, number of combinations $=C_{5}^{6}=6$
Total number of ways $=120+60+6=186$