# Task 1.

Since the pedestrian covers 1 km in 10 minutes, his speed is 6 km/h. There are more oncoming trams than overtaking ones because, relative to the pedestrian, the speed of the former is greater than that of the latter. If we assume the pedestrian is standing still, the speed of the oncoming trams is the sum of the tram's own speed $V$ and the pedestrian's speed. Therefore, the relative speed of the oncoming trams is $V+6$, and the relative speed of the overtaking trams is $V-6$. It is clear that the number of trams passing a given point in a certain time is proportional to their speed, from which we have:

$$
\frac{V+6}{V-6}=\frac{700}{300} \rightarrow 3 V+18=7 V-42 \text {, i.e. } V=15 \text {. }
$$
Answer: 15 km $/$ hour.

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