Each lottery ticket has a 9-digit numbers, which uses only the digits $1$, $2$, $3$. Each ticket is colored [color=red]red[/color],[color=blue] blue [/color]or [color=green]green[/color]. If two tickets have numbers which differ in all nine places, then the tickets have different colors. Ticket $122222222$ is red, and ticket $222222222$ is [color=green]green.[/color] What color is ticket $123123123$ ?
1. We are given that ticket $122222222$ is red and ticket $222222222$ is green. We need to determine the color of ticket $123123123$.
2. According to the problem, if two tickets differ in all nine places, they must have different colors.
3. Let's consider ticket $331331331$. This ticket differs in all nine places from both $122222222$ and $222222222$. Therefore, $331331331$ must be blue.
4. Next, consider ticket $311311311$. This ticket also differs in all nine places from both $122222222$ and $222222222$. Therefore, $311311311$ must be blue.
5. Now, consider ticket $133133133$. This ticket differs in all nine places from $311311311$ (which is blue) and $222222222$ (which is green). Therefore, $133133133$ must be red.
6. Next, consider ticket $212212212$. This ticket differs in all nine places from $331331331$ (which is blue) and $133133133$ (which is red). Therefore, $212212212$ must be green.
7. Finally, ticket $212212212$ also differs in all nine places from $123123123$. Therefore, $123123123$ cannot be green.
8. Since $123123123$ cannot be blue (as it differs in all places from $331331331$ and $311311311$) and cannot be green (as it differs in all places from $212212212$), it must be red.

\(\boxed{\text{red}}\)