Chris and Pat are playing catch. Standing $1 \mathrm{~m}$ apart, Pat first throws the ball to Chris and then Chris throws the ball back to Pat. Next, standing $2 \mathrm{~m}$ apart, Pat throws to Chris and Chris throws back to Pat. After each pair of throws, Chris moves $1 \mathrm{~m}$ farther away from Pat. They stop playing when one of them misses the ball. If the game ends when the 29th throw is missed, how far apart are they standing and who misses catching the ball?
(A) $15 \mathrm{~m}$, Chris
(B) $15 \mathrm{~m}$, Pat
(C) $14 \mathrm{~m}$, Chris
(D) $14 \mathrm{~m}$, Pat
(E) $16 \mathrm{~m}$, Pat
At each distance, two throws are made: the 1 st and 2 nd throws are made at $1 \mathrm{~m}$, the $3 \mathrm{rd}$ and 4 th are made at $2 \mathrm{~m}$, and so on, with the 27 th and 28 th throws being made at $14 \mathrm{~m}$. Therefore, the 29th throw is the first throw made at $15 \mathrm{~m}$.

At each distance, the first throw is made by Pat to Chris, so Chris misses catching the 29th throw at a distance of $15 \mathrm{~m}$.

ANSWER: (A)