3. In $5, 8, 15, 18, 25, 28, \cdots, 2008, 2015$, there are $\qquad$ numbers whose digit sum is even (the digit sum of 138 is $1+3+8=12$)
【Answer】 The sum of the digits of 202 is even, there are a total of $(2008-8) \div 10+1=201$ pairs, and the sum of the digits of the last number is $2+0+1+5=8$, which is even, so the answer is $201+1=202$