3. From the 10 numbers $0,1,2,3,4,5,6,7,8,9$, choose 3 numbers such that their sum is an even number not less than 10. 
The number of different ways to choose them is $\qquad$ .
$3.5 i$
From these 10 numbers, the number of ways to choose 3 different even numbers is $C_{5}^{3}$; the number of ways to choose 1 even number and 2 different odd numbers is $C_{5}^{1} C_{5}^{2}$.

From these 10 numbers, the number of ways to choose 3 numbers such that their sum is an even number less than 10, there are the following 9 different ways:
$$
\begin{array}{l}
(0,1,3) ;(0,1,5),(0,2,4),(1,2,3) ;(0,1,7) ; \\
(0,2,6),(0,3,5),(1,2,5),(1,3,4) .
\end{array}
$$

Therefore, the number of different ways that meet the requirements of the problem is
$$
C_{5}^{3}+C_{5}^{1} C_{5}^{2}-9=51 \text { ways. }
$$