3. Using "Kepler's Third Law: the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit," we can calculate the time it takes for a planet in the solar system to complete one orbit around the Sun (i.e., its orbital period). If the average distance of Earth from the Sun is $\alpha_{1}=1$ astronomical unit, and the orbital period of Earth around the Sun is $T_{1}=365.26$ days, and the average distance of Mars from the Sun is $\alpha_{2}=1.524$ astronomical units, then the orbital period of Mars $T_{2}=$ $\qquad$ days (to 0.01 days), which is equivalent to $\qquad$ years (to 0.001 years).
3.
$$
687.19 ; 1.881
$$