3. As shown in the figure, there are two cubes of different sizes, the edge length of the larger cube is 6 times that of the smaller cube. The 6 faces of the larger cube are painted red, and the 6 faces of the smaller cube are painted yellow, then the two cubes are glued together. The red area on the surface of this solid figure is $\qquad$ times the yellow area.
【Answer】Solution: Assume the edge length of the small cube is 1, then the edge length of the large cube is 6. The exposed surface area of the large cube is $6 \times 6 \times 6-1=215$, and the exposed surface area of the small cube is 5. Therefore, $215 \div 5=43$ times. The answer is 43.