1. If $\frac{1}{t}-|t|=1$, then the value of $\frac{1}{t}+|t|$ is ( ).
(A) $\sqrt{5}$
(B) $\pm \sqrt{5}$
(C) $\sqrt{3}$
(D) $\pm \sqrt{3}$
- 1. A.

Given that $t>0$, then $\frac{1}{t}+|t|>0$.
Therefore, $\frac{1}{t}+|t|=\sqrt{\left(\frac{1}{t}-|t|\right)^{2}+4}=\sqrt{5}$