2. In the arithmetic sequence $\left\{a_{n}\right\}$,
$$
a_{2}+a_{11}+a_{14}=-6 \text {. }
$$

Then the sum of the first 17 terms $\sum_{i=1}^{17} a_{i}$ is ( ).
(A) 0
(B) -34
(C) 17
(D) 34
2. B.

Let the common difference be $d$. Then
$$
a_{2}+a_{11}+a_{14}=3 a_{1}+24 d=3 a_{9} \text {. }
$$

Combining with the given condition, we get $a_{9}=-2$.
Thus, the sum of the first 17 terms is $17 a_{9}=-34$.