3. If a parallelogram can be divided into 92 equilateral triangles with a side length of 1, then all possible values of the perimeter of such a parallelogram are $\qquad$ .
3. 94 and 50.

Let the lengths of two sides of a parallelogram be $a$ and $b$, where $a, b \in \mathbf{N}_{+}$, and $a \leqslant b$. Then
$$
\begin{array}{l}
a b \sin 60^{\circ}=92 \times \frac{\sqrt{3}}{4} \\
\Rightarrow a b=46 \\
\Rightarrow(a, b)=(1,46) \text { or }(2,23) .
\end{array}
$$

Therefore, all possible values of the perimeter of the parallelogram $2(a+b)$ are 94 and 50.