9.32 Let $-1<a<0, \quad \theta=\arcsin a$, then the solution set of the inequality $\sin x<a$ is
(A) $\{x \mid 2 n \pi+\theta<x<(2 n+1) \pi-\theta, n \in Z\}$.
(B) $\{x \mid 2 n \pi-\theta<x<(2 n+1) \pi+\theta, n \in Z\}$.
(C) $\{x \mid(2 n-1) \pi+\theta<x<2 n \pi-\theta, n \in Z\}$.
(D) $\{x \mid(2 n-1) \pi-\theta<x<2 n \pi+\theta, n \in Z\}$.
[Solution] As shown in the right figure, using the image of the sine line, which is a trigonometric function line, we know that the solution set of $\sin x < a$ is
$$
\{x \mid(2 n-1) \pi-\theta<x<2 n \pi+\theta, n \in Z\} \text{. }
$$

Therefore, the correct choice is $(D)$.