11. Given the real-coefficient equations $x^{2}-2 x+2=0$ and $x^{2}+2 m x+1=0$, if the 4 different roots corresponding to points on the complex plane are concyclic, then the range of values for $m$ is $\qquad$
11. When $-10$, i.e., $m1$, the equation $\pi^{2}+2 m x+1=0$ has two distinct real roots $x_{3}, x_{4}$. Then the points corresponding to $x_{1}, x_{2}$ lie on the circle L with $x_{3}, x_{4}$ as the endpoints of its diameter. The equation of the circle is $\left(x-x_{3}\right)\left(x-x_{4}\right)+y^{2}=0$, which simplifies to $x^{2}+y^{2}-\left(x_{3}+x_{4}\right) x + r_{3} x_{1}=0$.

Substituting $x_{3}+x_{4}=-2 m, x_{3} x_{4}=1$ and the coordinates of the points corresponding to $x_{1}, x_{2}$, which are $(1, \pm 1)$, into the equation, we get $m=-\frac{3}{2}$.
Therefore, the values of $m$ are $\left\{m \mid-1<1 m<1\right.$ or $\left.m=-\frac{3}{2}\right\}$.