9. (5 points) As shown in the figure, the shaded part is a square with a side length of 6 cm. Around it are four rectangles. If the sum of the perimeters of the four rectangles is 92 cm, then the sum of the areas of the four rectangles is $\qquad$ square centimeters.
【Analysis】According to the problem, the rectangles in the figure can be cut and reassembled. As shown in the figure, it is easy to know that the perimeter and area of the original four rectangles remain unchanged after cutting and reassembling. Then, using the known side length of the square and the sum of the perimeters of the four rectangles, the sum of the areas of the four rectangles can be calculated.

【Solution】According to the analysis, the rectangles in the figure can be cut and reassembled as shown in the figure. The sum of the perimeters of the four rectangles $=6 \times 4 \times 2+2 \times$ side length 1 $+2 \times$ side length 2; side length 1 $+$ side length 2 $=\frac{1}{2} \times(92-24-24)=22$; then the sum of the areas of the four rectangles is: $6 \times$ side length 1 $+6 \times$ side length 2 $=6 \times 22=132$ (square centimeters). Therefore, the answer is: 132 square centimeters.