The number of values of $x$ satisfying the [equation](https://artofproblemsolving.com/wiki/index.php/Equation)
\[\frac {2x^2 - 10x}{x^2 - 5x} = x - 3\]
is:
$\text{(A)} \ \text{zero} \qquad \text{(B)} \ \text{one} \qquad \text{(C)} \ \text{two} \qquad \text{(D)} \ \text{three} \qquad \text{(E)} \ \text{an integer greater than 3}$
Since $x^2 - 5x$ is in the denominator, $x \neq 0,5$. Simplifying,
\[2\left(\frac{x^2 - 5}{x^2 - 5}\right) = 2 = x-3\]
Thus $x = 5$, which isn't in the [domain](https://artofproblemsolving.com/wiki/index.php/Domain) of the equation. Thus there are no values of $x \Rightarrow \mathrm{(A)}$.