97. The number $A$ is written in the decimal system using 666 threes, and the number $B$ is written using 666 sixes. From which digits does the product $A \cdot B$ consist?
97. The desired number will be equal to the product $A_{1} \cdot B_{1}$, where $A_{1}$ consists of 666 digits 9, and $B_{1}$ consists of 666 digits 2. But $A_{1}$ is one less than the number $10^{6666}$, which is expressed by a one followed by 666 zeros. Therefore, multiplying the number $B_{1}$ by this number is the same as multiplying $B_{1}$ by $10^{655}$ (resulting in a number consisting of 666 twos and 666 zeros) and subtracting the number $B_{1}$ from the result. It is easy to see that the resulting difference will have the form $\underbrace{22 \ldots 2177}_{665 \text { times }} \underbrace{\ldots 78}_{665 \text { times }}$