In the picture there are six coins, each with radius 1cm. Each coin is tangent to exactly two other coins next to it (as in the picture). Between the coins, there is an empty area whose boundary is a star-like shape. What is the perimeter of this shape?
[img]https://i.imgur.com/aguQRVd.png[/img]
1. **Identify the Geometry**: The problem involves six coins, each with a radius of 1 cm, arranged such that each coin is tangent to exactly two other coins. The centers of these coins form a regular hexagon.

2. **Hexagon Properties**: In a regular hexagon, each internal angle is \(120^\circ\) or \(\frac{2\pi}{3}\) radians. The sum of the internal angles of a hexagon is \(720^\circ\) or \(4\pi\) radians.

3. **Perimeter Calculation**: The boundary of the empty area between the coins is a star-like shape. This boundary is formed by the arcs of the circles. Each arc is part of the circumference of a circle with radius 1 cm.

4. **Arc Length Calculation**: Each angle at the center of the hexagon corresponds to an arc on the boundary. Since the total angle around the hexagon is \(4\pi\) radians, and each arc corresponds to an angle of \(\frac{2\pi}{3}\) radians, the total length of the arcs is the sum of these angles.

5. **Summing the Arcs**: The total perimeter of the star-like shape is the sum of the lengths of these arcs. Since the radius of each circle is 1 cm, the length of an arc corresponding to an angle \(\theta\) is given by \(r\theta\). Here, \(r = 1\) cm and \(\theta = 4\pi\) radians.

\[
\text{Total Perimeter} = 1 \times 4\pi = 4\pi \text{ cm}
\]

The final answer is \(\boxed{4\pi \text{ cm}}\).