5. Given $n!=n \times(n-1) \times(n-2) \times \cdots \times 2 \times 1$, then $10!\div(5!\times 2!)=$
【Analysis】15120
$$
10!\div(5!\times 2!)=10!\div 5!\div 2!=(10 \times 9 \times \cdots \times 2 \times 1) \div(5 \times 4 \times 3 \times 2 \times 1) \div(2 \times 1)=(10 \times 9 \times 8 \times 7 \times 6) \div 2=15120 .
$$