$2, \mathrm{n}$ is the smallest integer with the following property: it is a multiple of 15, and each of its digits is 0 or 8. Find
$$
\frac{\mathrm{n}}{15}
$$
Solve $n$ should be a common multiple of 5 and 3. The last digit of a multiple of 5 can only be 0 or 5, and since $n$ consists only of the digits 0 and 8, the last digit of $n$ must be 0. As a multiple of 3, the number of 8s in $n$ must be a multiple of 3. Given the requirement for $n$ to be the smallest, we should have $n=8880$, thus $\frac{n}{15}=592$.