8. The sequence $\{2 n+1\}$ is cyclically divided into (3), $(5,7),(9,11,13),(15,17,19,21),(23),(25,27),(29,31,33),(35,37,39,41),(43), \cdots$, the sum of the numbers in the 100th parenthesis is . $\qquad$
8. 1992.

Each loop is recorded as a group, then the 100th parenthesis is the fourth parenthesis in the 25th group. The sum of the numbers in the fourth parenthesis of each group forms an arithmetic sequence with the first term being 72 and the common difference being 80, so $72+24 \cdot 80=1992$.