2. (8 points) 2010 consecutive natural numbers are arranged in ascending order. The average of the numbers in the odd positions is 2345. Then the average of the numbers in the even positions is $\qquad$ .
【Solution】Solution: $2010 \div 2=505$;
Therefore, there are 505 odd numbers and 505 even numbers,
the average of the sum of odd numbers is the one right in the middle, the average of the sum of even numbers is also the one right in the middle;
Therefore, their averages differ by 1;
That is, $2345+1=2346$.
So the answer is: 2346.