1.93 Given that 99 lines divide the plane into $n$ parts, try to find all possible values of $n$ within the range less than 199.

 untranslated text remains the same as requested. However, the provided text is already translated into English, maintaining the original format and line breaks.
[Solution] When 99 lines are all parallel, they divide the plane into 100 parts; when 98 lines are parallel and the other one is not parallel to them, they divide the plane into 198 parts. Of course, when the 99 lines intersect at a single point, they also divide the plane into 198 parts. Below, we prove that within the range less than 199, there are no other solutions for $n$.
(1) Suppose among the known lines, $k$ lines are parallel $(2 \leqslant k \leqslant 97)$, and the rest do not parallel to them. In this case, the $k$ parallel lines divide the plane into $k+1$ parts, and each additional line increases the number of regions by at least $k+1$. Therefore, the number of parts is no less than $(k+1)(99-k+1) \geqslant 3 \times 98 > 200$. Thus, there is no solution for $n$ in this scenario.
(2) Suppose no two lines are parallel, but $k$ lines intersect at a point $O (2 \leqslant k \leqslant 98)$, and the remaining lines do not pass through point $O$. In this case, the $k$ lines passing through point $O$ divide the plane into $2k$ parts. Each additional line increases the number of regions by at least $k+1$. Therefore, the number of parts is no less than $2k + (99-k)(k+1) \geqslant 196 + 99 > 200$, so there is no solution for $n$.

In summary, within the range less than 199, the only possible values for $n$ are 100 and 198.