Aliens from Lumix have one head and four legs, while those from Obscra have two heads and only one leg. If 60 aliens attend a joint Lumix and Obscra interworld conference, and there are 129 legs present, how many heads are there?
1. Let \( l \) represent the number of Lumix aliens and \( o \) represent the number of Obscra aliens.
2. We are given two pieces of information:
   - The total number of aliens is 60.
   - The total number of legs is 129.
   
   These can be written as the following system of equations:
   \[
   l + o = 60 \quad \text{(1)}
   \]
   \[
   4l + o = 129 \quad \text{(2)}
   \]

3. To eliminate \( o \), we subtract equation (1) from equation (2):
   \[
   (4l + o) - (l + o) = 129 - 60
   \]
   Simplifying this, we get:
   \[
   3l = 69
   \]
   Solving for \( l \):
   \[
   l = \frac{69}{3} = 23
   \]

4. Substitute \( l = 23 \) back into equation (1) to find \( o \):
   \[
   23 + o = 60
   \]
   Solving for \( o \):
   \[
   o = 60 - 23 = 37
   \]

5. Now, we need to find the total number of heads. Lumix aliens have 1 head each and Obscra aliens have 2 heads each. Therefore, the total number of heads is:
   \[
   l + 2o = 23 + 2 \times 37 = 23 + 74 = 97
   \]

The final answer is \(\boxed{97}\)