In a recent basketball game, Shenille attempted only three-point shots and two-point shots. She was successful on $20\%$ of her three-point shots and $30\%$ of her two-point shots. Shenille attempted $30$ shots. How many points did she score?

$ \textbf{(A)}\ 12\qquad\textbf{(B)}\ 18\qquad\textbf{(C)}\ 24\qquad\textbf{(D)}\ 30\qquad\textbf{(E)}\ 36 $
1. Let the number of attempted three-point shots be \( x \) and the number of attempted two-point shots be \( y \). We know that:
   \[
   x + y = 30
   \]
2. Shenille was successful on \( 20\% \) of her three-point shots. Therefore, the number of successful three-point shots is:
   \[
   0.2x
   \]
3. Each successful three-point shot is worth 3 points. Thus, the total points from successful three-point shots is:
   \[
   3 \times 0.2x = 0.6x
   \]
4. Shenille was successful on \( 30\% \) of her two-point shots. Therefore, the number of successful two-point shots is:
   \[
   0.3y
   \]
5. Each successful two-point shot is worth 2 points. Thus, the total points from successful two-point shots is:
   \[
   2 \times 0.3y = 0.6y
   \]
6. The total points scored by Shenille is the sum of the points from successful three-point shots and successful two-point shots:
   \[
   0.6x + 0.6y
   \]
7. Using the equation \( x + y = 30 \), we substitute \( x + y \) into the total points equation:
   \[
   0.6x + 0.6y = 0.6(x + y) = 0.6 \times 30 = 18
   \]

The final answer is \(\boxed{18}\).