Thee tiles are marked $ X$ and two other tiles are marked $ O$. The five tiles are randomly arranged in a row. What is the probability that the arrangement reads $ XOXOX$?

$ \textbf{(A)}\ \frac{1}{12}\qquad 
\textbf{(B)}\ \frac{1}{10}\qquad 
\textbf{(C)}\ \frac{1}{6}\qquad 
\textbf{(D)}\ \frac{1}{4}\qquad 
\textbf{(E)}\ \frac{1}{3}$
1. **Determine the total number of ways to arrange the tiles:**
   - We have 3 tiles marked \( X \) and 2 tiles marked \( O \).
   - The total number of ways to arrange these tiles can be calculated using the formula for permutations of a multiset:
     \[
     \frac{n!}{n_1! \cdot n_2! \cdot \ldots \cdot n_k!}
     \]
     where \( n \) is the total number of items, and \( n_1, n_2, \ldots, n_k \) are the frequencies of the distinct items.
   - Here, \( n = 5 \), \( n_1 = 3 \) (for \( X \)), and \( n_2 = 2 \) (for \( O \)):
     \[
     \frac{5!}{3!2!} = \frac{120}{6 \cdot 2} = \frac{120}{12} = 10
     \]

2. **Determine the number of favorable outcomes:**
   - We are looking for the specific arrangement \( XOXOX \).
   - There is only one way to arrange the tiles in this specific order.

3. **Calculate the probability:**
   - The probability \( P \) of the arrangement \( XOXOX \) is the ratio of the number of favorable outcomes to the total number of possible arrangements:
     \[
     P = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible arrangements}} = \frac{1}{10}
     \]

Conclusion:
\[
\boxed{\frac{1}{10}}
\]