What number should be removed from the list
\[1,2,3,4,5,6,7,8,9,10,11\]
so that the average of the remaining numbers is $6.1$?
$\text{(A)}\ 4 \qquad \text{(B)}\ 5 \qquad \text{(C)}\ 6 \qquad \text{(D)}\ 7 \qquad \text{(E)}\ 8$
Adding all of the numbers gives us $\frac{11\cdot12}{2}=66$ as the current total. Since there are $11$ numbers, the current average is $\frac{66}{11}=6$. We need to take away a number from the total and then divide the result by $10$ because there will only be $10$ numbers left to give an average of $6.1$. Setting up the equation:
$\frac{66-x}{10}=6.1$
$66 - x = 61$
$x = 5$
Thus, the answer is $\boxed{B}$