1.2014 Arrange chairs in a circle, with $n$ people sitting on the chairs, such that when one more person sits down, they will always sit next to one of the original $n$ people. Then the minimum value of $n$ is $\qquad$
-、1. 672 .
From the problem, we know that after $n$ people sit down, there are at most two empty chairs between any two people.
If we can arrange for there to be exactly two empty chairs between any two people, then $n$ is minimized.
Thus, if we number the chairs where people are sitting, we easily get the arithmetic sequence: $1,4,7, \cdots, 2014$.
Therefore, $2014=1+3(n-1) \Rightarrow n=672$.