Each of the following four large congruent squares is subdivided into combinations of congruent triangles or rectangles and is partially [b]bolded[/b]. What percent of the total area is partially bolded?


[asy]
import graph; size(7.01cm); real lsf=0.5; pen dps=linewidth(0.7)+fontsize(10); defaultpen(dps); pen ds=black; real xmin=-0.42,xmax=14.59,ymin=-10.08,ymax=5.26; 
pair A=(0,0), B=(4,0), C=(0,4), D=(4,4), F=(2,0), G=(3,0), H=(1,4), I=(2,4), J=(3,4), K=(0,-2), L=(4,-2), M=(0,-6), O=(0,-4), P=(4,-4), Q=(2,-2), R=(2,-6), T=(6,4), U=(10,0), V=(10,4), Z=(10,2), A_1=(8,4), B_1=(8,0), C_1=(6,-2), D_1=(10,-2), E_1=(6,-6), F_1=(10,-6), G_1=(6,-4), H_1=(10,-4), I_1=(8,-2), J_1=(8,-6), K_1=(8,-4); 
draw(C--H--(1,0)--A--cycle,linewidth(1.6)); draw(M--O--Q--R--cycle,linewidth(1.6)); draw(A_1--V--Z--cycle,linewidth(1.6)); draw(G_1--K_1--J_1--E_1--cycle,linewidth(1.6)); 
draw(C--D); draw(D--B); draw(B--A); draw(A--C); draw(H--(1,0)); draw(I--F); draw(J--G); draw(C--H,linewidth(1.6)); draw(H--(1,0),linewidth(1.6)); draw((1,0)--A,linewidth(1.6)); draw(A--C,linewidth(1.6)); draw(K--L); draw((4,-6)--L); draw((4,-6)--M); draw(M--K); draw(O--P); draw(Q--R); draw(O--Q); draw(M--O,linewidth(1.6)); draw(O--Q,linewidth(1.6)); draw(Q--R,linewidth(1.6)); draw(R--M,linewidth(1.6)); draw(T--V); draw(V--U); draw(U--(6,0)); draw((6,0)--T); draw((6,2)--Z); draw(A_1--B_1); draw(A_1--Z); draw(A_1--V,linewidth(1.6)); draw(V--Z,linewidth(1.6)); draw(Z--A_1,linewidth(1.6)); draw(C_1--D_1); draw(D_1--F_1); draw(F_1--E_1); draw(E_1--C_1); draw(G_1--H_1); draw(I_1--J_1); draw(G_1--K_1,linewidth(1.6)); draw(K_1--J_1,linewidth(1.6)); draw(J_1--E_1,linewidth(1.6)); draw(E_1--G_1,linewidth(1.6)); 
dot(A,linewidth(1pt)+ds); dot(B,linewidth(1pt)+ds); dot(C,linewidth(1pt)+ds); dot(D,linewidth(1pt)+ds); dot((1,0),linewidth(1pt)+ds); dot(F,linewidth(1pt)+ds); dot(G,linewidth(1pt)+ds); dot(H,linewidth(1pt)+ds); dot(I,linewidth(1pt)+ds); dot(J,linewidth(1pt)+ds); dot(K,linewidth(1pt)+ds); dot(L,linewidth(1pt)+ds); dot(M,linewidth(1pt)+ds); dot((4,-6),linewidth(1pt)+ds); dot(O,linewidth(1pt)+ds); dot(P,linewidth(1pt)+ds); dot(Q,linewidth(1pt)+ds); dot(R,linewidth(1pt)+ds); dot((6,0),linewidth(1pt)+ds); dot(T,linewidth(1pt)+ds); dot(U,linewidth(1pt)+ds); dot(V,linewidth(1pt)+ds); dot((6,2),linewidth(1pt)+ds); dot(Z,linewidth(1pt)+ds); dot(A_1,linewidth(1pt)+ds); dot(B_1,linewidth(1pt)+ds); dot(C_1,linewidth(1pt)+ds); dot(D_1,linewidth(1pt)+ds); dot(E_1,linewidth(1pt)+ds); dot(F_1,linewidth(1pt)+ds); dot(G_1,linewidth(1pt)+ds); dot(H_1,linewidth(1pt)+ds); dot(I_1,linewidth(1pt)+ds); dot(J_1,linewidth(1pt)+ds); dot(K_1,linewidth(1pt)+ds); 
clip((xmin,ymin)--(xmin,ymax)--(xmax,ymax)--(xmax,ymin)--cycle); 
[/asy]

$ \textbf{(A)}12\frac 12\qquad\textbf{(B)}20\qquad\textbf{(C)}25\qquad\textbf{(D)}33 \frac 13\qquad\textbf{(E)}37\frac 12 $
1. **Identify the area of each bolded region in the four squares:**

   - **First Square:**
     The bolded region is a right triangle with legs equal to the side of the square. The area of this triangle is:
     \[
     \text{Area} = \frac{1}{2} \times \text{side} \times \text{side} = \frac{1}{2} \times s^2
     \]
     Since the square's area is \(s^2\), the fraction of the bolded area is:
     \[
     \frac{\frac{1}{2} s^2}{s^2} = \frac{1}{2}
     \]

   - **Second Square:**
     The bolded region is a quadrilateral that can be divided into two right triangles, each with an area of \(\frac{1}{4} s^2\). Therefore, the total bolded area is:
     \[
     \frac{1}{4} s^2 + \frac{1}{4} s^2 = \frac{1}{2} s^2
     \]
     The fraction of the bolded area is:
     \[
     \frac{\frac{1}{2} s^2}{s^2} = \frac{1}{2}
     \]

   - **Third Square:**
     The bolded region is a right triangle with legs equal to half the side of the square. The area of this triangle is:
     \[
     \text{Area} = \frac{1}{2} \times \left(\frac{s}{2}\right) \times \left(\frac{s}{2}\right) = \frac{1}{8} s^2
     \]
     The fraction of the bolded area is:
     \[
     \frac{\frac{1}{8} s^2}{s^2} = \frac{1}{8}
     \]

   - **Fourth Square:**
     The bolded region is a quadrilateral that can be divided into two right triangles, each with an area of \(\frac{1}{8} s^2\). Therefore, the total bolded area is:
     \[
     \frac{1}{8} s^2 + \frac{1}{8} s^2 = \frac{1}{4} s^2
     \]
     The fraction of the bolded area is:
     \[
     \frac{\frac{1}{4} s^2}{s^2} = \frac{1}{4}
     \]

2. **Sum the fractions of the bolded areas:**
   \[
   \frac{1}{2} + \frac{1}{2} + \frac{1}{8} + \frac{1}{4}
   \]

3. **Convert all fractions to a common denominator (8):**
   \[
   \frac{1}{2} = \frac{4}{8}, \quad \frac{1}{2} = \frac{4}{8}, \quad \frac{1}{8} = \frac{1}{8}, \quad \frac{1}{4} = \frac{2}{8}
   \]

4. **Add the fractions:**
   \[
   \frac{4}{8} + \frac{4}{8} + \frac{1}{8} + \frac{2}{8} = \frac{11}{8}
   \]

5. **Convert the fraction to a percentage:**
   \[
   \frac{11}{8} = 1.375 \quad \text{or} \quad 137.5\%
   \]

6. **Since the problem asks for the percentage of the total area of the four squares, we need to divide by 4:**
   \[
   \frac{137.5\%}{4} = 34.375\%
   \]

The final answer is \( \boxed{25\%} \)