If $3 k=10$, what is the value of $\frac{6}{5} k-2$ ?
Solution 1

By factoring and substituting, we get

$$
\frac{6}{5} k-2=\frac{2}{5}(3 k)-2=\frac{2}{5}(10)-2=4-2=2 .
$$

## Solution 2

Solving for $k$, we have $k=\frac{10}{3}$, so

$$
\frac{6}{5} k-2=\frac{6}{5} \times \frac{10}{3}-2=\frac{60}{15}-2=4-2=2 .
$$

ANSWER: 2

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