$2 \cdot 88$ Using each digit from $0,1,2,3, \cdots, 9$ once, find the largest possible multiple of 12 that can be formed.
[Solution] A multiple of 12 can be divided by both 3 and 4. Since $9+8+7+6+5+4$ $+3+2+1=45$, which is divisible by 3, to make the number a multiple of 12, we only need its last two digits to be divisible by 4. Since placing larger digits at the front forms a larger number, the answer to this problem is 9876543120.