4. (10 points) Xiaohua needs to arrive at the Youth Palace for an activity at 2 PM, but his watch is 4 minutes fast every hour. He deliberately set his watch correctly at 10 AM. When Xiaohua arrives at the Youth Palace at 2 PM according to his watch, he actually arrives ( ) minutes early.
A. 14
B. 15
C. 16
D. 17
【Analysis】First, analyze the problem of fast and slow clocks. According to the proportional relationship between distances, the solution can be found.
【Solution】Solution: According to the problem, we know:
At 10:00 AM, the standard clock moves 60 units per hour, while Xiaohua's clock is 4 minutes fast, which is 64 units. The distance ratio is 15:16. When Xiaohua's clock shows 2:00 PM, Xiaohua's clock has moved 4 rounds, totaling 240 units.

According to the proportional relationship, let the distance the standard clock has moved be $x$, then we have: $15:16 = x:240$, solving for $x=225$.
$$
240-225=15 \text{ (minutes) }
$$

Therefore, the answer is: $B$.