8. (5 points) When drawing 2 circles on paper, you can get a maximum of 2 intersection points. When drawing 3 circles, you can get a maximum of 6 intersection points. So, if you draw 10 circles on paper, you can get $\qquad$ intersection points.
【Analysis】When there are already $n$ circles, when drawing another circle, the maximum number of intersection points with the other $n$ circles is: this circle intersects with each of the other $n$ circles at two points.

【Solution】Solution: Recursive analysis:
Drawing the 1st circle, the number of intersection points is 0,
Drawing the 2nd circle, it intersects with the 1st circle at two points, the number of intersection points is $0+2=2$,
Drawing the 3rd circle, it intersects with the first two circles at two points each, the number of intersection points is $0+2+4=6$,

Drawing the 10th circle, it intersects with the previous 9 circles at two points each, the number of intersection points: $0+2+4+6+\cdots+18=90$; hence the answer to this problem is: 90.