In a sequence of numbers, each number, except the first, equals twice the previous number. If the sum of the second and third numbers in the list is 24 , then the sixth number is
(A) 112
(B) 192
(C) 64
(D) 40
(E) 128
Let the first number in the list be $a$. Then the second and third numbers are $2 a$ and $4 a$, respectively. So $2 a+4 a=24$, or $a=4$. Now the fourth, fifth and sixth numbers will be $8 a$, $16 a$ and $32 a$, respectively. So the sixth number is $32(4)=128$.

ANSWER: (E)