14. If the solution interval of the inequality $x^{2}-a x-6 a<0$ with respect to $x$ does not exceed 5 in length, find the range of values for $a$.
14. If the solution to the inequality is $\left(x_{1}, x_{2}\right)$, then $\left|x_{1}-x_{2}\right|=\sqrt{\left(x_{1}+x_{2}\right)^{2}-4 x_{1} x_{2}}=\sqrt{a^{2}+24 a} \leqslant 5$, i.e., $\left\{\begin{array}{l}\Delta=a^{2}+24 a>0 \\ \sqrt{a^{2}+24 a} \leqslant 5,\end{array}\right.$ which gives $-25 \leqslant a<-24$ or $0<a \leqslant 1$.