If $x+y+z=25$ and $y+z=14$, then $x$ is
(A) 8
(B) 11
(C) 6
(D) -6
(E) 31

Part B: Each question is worth 6 credits.
If $x+y+z=25$ and $y+z=14$, then $x$ is
(A) 8
(B) 11
(C) 6
(D) -6
(E) 31

## Solution

We are given that $x+y+z=25$

$$
\text { and } \quad y+z=14
$$

Subtract equation (2) from equation (1) to get $x=11$.

ANSWER: (B)

## PART B: