15. In the division equation with a remainder $A \div B=C \cdots 8$, $A+B+C=2994$, then $A=$
【Answer】 8 or 2864
【Analysis】Integer number theory + factorization
From $A \div B=C \cdots 8$ we get $A=B C+8$, so, $A+B+C=B C+B+C+8=2994$, i.e., $B C+B+C+1=2987 \Rightarrow B(C+1)+C+1=(B+1)(C+1)=2987$, $2987=29 \times 103$, and $B>8$,

Possible values are $\left\{\begin{array}{l}B+1=2987 \\ C+1=1\end{array}\right.$ or $\left\{\begin{array}{l}B+1=29 \\ C+1=103\end{array}\right.$ or $\left\{\begin{array}{l}B+1=103 \\ C+1=29\end{array}\right.$,
Solving gives: $\left\{\begin{array}{l}B=2986 \\ C=0\end{array}\right.$ or $\left\{\begin{array}{l}B=28 \\ C=102\end{array}\right.$ or $\left\{\begin{array}{l}B=102 \\ C=28\end{array}\right.$,
Therefore, the possible values of $\mathrm{A}$ are: 8 or 2864.