2. From the numbers $1,2,3, \cdots, 10$, if 3 numbers are randomly drawn, the probability that at least two of the numbers are consecutive positive integers is $\qquad$ .
2. $\frac{8}{15}$ Detailed Explanation: The number of ways to draw three consecutive positive numbers is 8; only two numbers are consecutive: corresponding to 1,2

and 9,10, there are 7 ways each; corresponding to $2,3,3,4, \cdots, 8,9$, there are 6 ways each, so there are a total of $2 \times 7+7 \times 6=56$ ways. Therefore, the required probability is $p=\frac{8+56}{C_{10}^{3}}=\frac{8}{15}$.