265. In a triangle, from vertex $A$ come out the median, bisector, and altitude. Which angle is larger: between the median and the bisector or between the bisector and the altitude, if angle $\hat{A}$ equals $\alpha$?
265. Let $A D$ be the altitude, $A L$ the angle bisector, and $A M$ the median. Extend the angle bisector to intersect the circumcircle of the triangle at point $A_{1}$. Since $M A_{1} \| A D$, then $\widehat{M A_{1} A}=L \widehat{A D}$

Answer: if $\alpha$ $>90^{\circ}$ - the opposite; if $\alpha=90^{\circ}$, the angles are equal.