A8. Triangle $A B C$ is right-angled at $C$. Point $P$ lies on side $B C$, point $Q$ lies on side $A C$, and point $R$ lies on side $A B$ such that

$B P=B R$ and $A Q=A R$.

Angle $P R Q$ is:
(A) $30^{\circ}$
(B) $45^{\circ}$
(C) $50^{\circ}$
(D) $55^{\circ}$
(E) $60^{\circ}$
A8. $\begin{aligned} & P R B=90^{\circ}-\frac{1}{2} \quad B \\ & Q R A=90^{\circ}-\frac{1}{2} \quad A \\ & P R Q=180^{\circ}-\quad P R B-\quad Q R A= \\ & \frac{1}{2} \quad B+\frac{1}{2} \quad A=\frac{1}{2} \times 90^{\circ}=45^{\circ}\end{aligned}$

![](https://cdn.mathpix.com/cropped/2024_04_17_a2053d8a9f115fa3d794g-1.jpg?height=366&width=599&top_left_y=2190&top_left_x=1111)

The correct answer is (B).