2. Arrange the positive even numbers in 5 columns as shown in Table 1.
Table 1
\begin{tabular}{|l|c|c|c|c|c|}
\hline & Column 1 & Column 2 & Column 3 & Column 4 & Column 5 \\
\hline Row 1 & & 2 & 4 & 6 & 8 \\
\hline Row 2 & 16 & 14 & 12 & 10 & \\
\hline Row 3 & & 18 & 20 & 22 & 24 \\
\hline Row 4 & 32 & 30 & 28 & 26 & \\
\hline$\ldots .$. & & & & & \\
\hline
\end{tabular}

According to the arrangement pattern above, 2006 should be in ).
(A) Row 250, Column 2
(B) Row 250, Column 4
(C) Row 251, Column 2
(D) Row 251, Column 4
2. D.

From Table 1, we know that the numbers in the 1st column are of the form $16 k$ (where $k$ is an integer), the numbers in the 2nd column are of the form $16 k \pm 2$, the numbers in the 3rd column are of the form $16 k \pm 4$, the numbers in the 4th column are of the form $16 k \pm 6$, and the numbers in the 5th column are of the form $16 k+8$.
Since $2006=125 \times 16+6$, therefore, 2006 is in the 4th column.
Also, according to the largest number in the $n$th row being $8 n$, we know that 2008 (which is in the same row as 2006) is in the 251st row.