Aviov N.i.
Petya added 100 consecutive powers of two, starting from a certain one, while Vasya added a certain number of
consecutive natural numbers, starting from 1. Could they have obtained the same result?
$2^{99}+\ldots+2^{198}=2^{99}\left(2^{100}-1\right)=1+2+3+\ldots+\left(2^{100}-1\right)$

## Answer

It can be done.