IS. 3 Consider the line $12 x-4 y+(Q-305)=0$. If the area of the triangle formed by the $x$-axis, the $y$-axis and this line is $R$ square units, what is the value of $R$ ?
$$
12 x-4 y+24=0 \Rightarrow \text { Height }=6, \text { base }=2 ; \text { area } R=\frac{1}{2} \cdot 6 \cdot 2=6
$$

Remark: the original question is $\ldots 12 x-4 y+Q=0 \ldots$. The answer is very difficult to carry forward to next question.