Zé Roberto and Humberto are playing the Millenium Game!
There are 30 empty boxes in a queue, and each box have a capacity of one blue stome.
Each player takes a blue stone and places it in a box (and it is a [i]move[/i]).
The winner is who, in its move, obtain three full consecutive boxes. 

If Zé Roberto is the first player, who has the winner strategy?
1. **Define the sequence \(a_n\)**:
   Let \(a_n\) be a sequence where \(a_n = 1\) if the first player (Zé Roberto) has a winning strategy with \(n\) stones, and \(a_n = 0\) otherwise.

2. **Base cases**:
   - For \(n = 1\), \(a_1 = 0\) because with only one stone, the first player cannot achieve three consecutive full boxes.
   - For \(n = 2\), \(a_2 = 0\) for the same reason as above.
   - For \(n = 3\), \(a_3 = 1\) because the first player can place all three stones in the first three boxes and win.

3. **Recurrence relation**:
   To determine \(a_n\) for \(n > 3\), we need to consider the possible moves of the first player. If there exists a position \(k\) such that placing a stone in position \(k+2\) results in two separate subgames where both subgames are losing positions for the second player, then \(a_n = 1\).

   Formally, if there exists a \(k\) such that:
   \[
   a_k = 0 \quad \text{and} \quad a_{n-k-5} = 0,
   \]
   then \(a_n = 1\).

4. **Calculate \(a_n\) for \(n = 4\) to \(n = 30\)**:
   We need to compute \(a_n\) for each \(n\) from 4 to 30 using the recurrence relation. This involves checking all possible positions \(k\) for each \(n\) and verifying if the conditions \(a_k = 0\) and \(a_{n-k-5} = 0\) hold.

   - For \(n = 4\), we check:
     \[
     a_4 = 1 \quad \text{if there exists a } k \text{ such that } a_k = 0 \text{ and } a_{4-k-5} = 0.
     \]
     Since \(4 - k - 5\) is negative for all \(k\), \(a_4 = 0\).

   - For \(n = 5\), similarly, \(a_5 = 0\).

   - For \(n = 6\), we check:
     \[
     a_6 = 1 \quad \text{if there exists a } k \text{ such that } a_k = 0 \text{ and } a_{6-k-5} = 0.
     \]
     Since \(6 - k - 5\) is non-negative only for \(k = 0\), and \(a_0 = 0\), \(a_6 = 1\).

   Continue this process up to \(n = 30\).

5. **Determine the winner**:
   After computing \(a_{30}\), we can determine if Zé Roberto has a winning strategy. If \(a_{30} = 1\), Zé Roberto has a winning strategy. If \(a_{30} = 0\), Humberto has a winning strategy.

The final answer is \( \boxed{ a_{30} } \).