$1.24 \frac{\sqrt{\frac{a b c+4}{a}+4 \sqrt{\frac{b c}{a}}}}{\sqrt{a b c}+2} ; a=0.04$.
1.24 Assuming $a b c \neq 0$, we have:

$$
\begin{aligned}
& \frac{a b c+4}{a}+4 \sqrt{\frac{b c}{a}}=b c+\frac{4}{a}+4 \sqrt{\frac{b c}{a}}= \\
& =(\sqrt{b c})^{2}+4 \sqrt{\frac{b c}{a}}+\left(\frac{2}{\sqrt{a}}\right)^{2}=\left(\sqrt{b c}+\frac{2}{\sqrt{a}}\right)^{2} \\
& \frac{\sqrt{\left(\sqrt{b c}+\frac{2}{\sqrt{a}}\right)^{2}}}{\sqrt{a b c}+2}=\frac{\sqrt{a b c}+2}{\sqrt{a}(\sqrt{a b c}+2)}=\frac{1}{\sqrt{a}}
\end{aligned}
$$

For $a=0.04$, we find $\frac{1}{\sqrt{0.04}}=5$.

Answer: 5.