Laura drew 5 circles inside which she wants to place numbers. She arranges the circles to form a fraction and its integer value.

In how many ways did Laura place the numbers 2, 3, 5, 6, and 11 inside the circles so that the equality is true?
As the fraction is equal to an integer, its numerator must be a multiple of its denominator. Let's test all possibilities and choose the ones that satisfy the conditions of the problem:

$$
\begin{aligned}
& \frac{3+5+6}{2}=7 ; \frac{3+11+6}{2}=10 ; \frac{5+11+6}{2}=11 \longrightarrow \text { do not satisfy } \\
& \frac{2+5+11}{3}=6 \quad \longrightarrow \quad \text { satisfies } \\
& \frac{3+6+11}{5}=4 \quad \longrightarrow \quad \text { does not satisfy } \\
& \frac{2+5+11}{6}=3 \quad \longrightarrow \quad \text { satisfies } \\
& \frac{2+3+6}{11}=1 \quad \longrightarrow \quad \text { does not satisfy. }
\end{aligned}
$$

Thus, we have two answers:

$$
\frac{(2)+(5)+(11)}{(3)}=6 \quad \frac{(2)+(5)+(11)}{6}=(3)
$$