5. (10 points) In the following two equations, the same Chinese characters represent the same digits, and different Chinese characters represent different digits:
$$
\text { 数字花园 }+ \text { 探秘 }=2015, \overline{\text { 探秘 }}+1+2+3+\cdots+10=\overline{\text { 花园 }}
$$

Then the four-digit number 数字花园 = . $\qquad$

---

Translation:
5. (10 points) In the following two equations, the same Chinese characters represent the same digits, and different Chinese characters represent different digits:
$$
\text { 数字花园 }+ \text { 探秘 }=2015, \overline{\text { 探秘 }}+1+2+3+\cdots+10=\overline{\text { 花园 }}
$$

Then the four-digit number 数字花园 = . $\qquad$

Note: The Chinese characters in the equations are kept as they are, as they represent specific digits in the problem.
5. (10 points) In the following two equations, the same Chinese characters represent the same digits, and different Chinese characters represent different digits:
数字花园 + 探秘 $=2015, \overline{\text { 探秘 }}+1+2+3+\cdots+10=\overline{\text { 花园 }}$
Then the four-digit number 数学花园 $=$ $\qquad$ .

【Solution】Solution: According to the analysis, let $x=\overline{\text { 数学 }}, y=\overline{\text { 花园 }} \quad \mathrm{z}=\overline{\text { 探秘 }}$
Then: 数字花园 $+\overline{\text { 探秘 }}=100 x+y+z=2015 \cdots$ (1)
$\overline{\text { 探秘 }}+1+2+3+\cdots+10=z+1+2+3+\cdots+10=y$
$z+\frac{(1+10) \times 10}{2}=y$
$z+55=y \cdots(2)$
Solving (1) and (2) together:
$$
\left\{\begin{array}{l}
100 x+y+z=2015 \\
z+55=y
\end{array}\right.
$$

We get: $50 x+y=1035$
$$
\begin{array}{l}
\because 100>z=y-55 \geqslant 10 \therefore 65 \leqslant y<100 \quad 65 \leqslant 1035-50 x<100 \\
935<50 x \leqslant 970
\end{array}
$$
$18.7<x \leqslant 19.4$ and $\because x$ is an integer
$$
\begin{array}{l}
\therefore x=19 \\
y=1035-50 \times 19=85
\end{array}
$$

Therefore, the answer is: 1985