The hunter has two dogs. Once, getting lost in the forest, he came to a fork in the road. The hunter knows that each dog will choose the way home with a probability of $p$. He decided to release the dogs one after the other. If both choose the same road, he will follow them; if they split, the hunter will choose a road by flipping a coin. Will this method increase the hunter's chances of choosing the road home, compared to if he had only one dog?

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The probability of choosing the correct path with one dog is $p$. The probability of choosing the correct road, if acting in the specified manner, with two dogs is $p^{2}+1 / 2 \cdot 2 p(1-p)=p$, which is the same.

## Answer

It will not increase.