8. Arrange 27 numbers in a row, where there are 3 of the number 1, 3 of the number 2, ..., and 3 of the number 9. The requirement is that there is one number between the first 1 and the second 1, and one number between the second 1 and the third 1; there are two numbers between the first 2 and the second 2, and two numbers between the second 2 and the third 2; ...; there are nine numbers between the first 9 and the second 9, and nine numbers between the second 9 and the third 9. The following table shows a partial arrangement of the numbers. Please complete the entire row of data.
\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|}
\hline & & & & & & & & & 5 & 7 & 4 & 6 & 9 & 2 & 5 & 8 & & & & & & & & & & \\
\hline
\end{tabular}
【Analysis】Logical Reasoning
\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|}
\hline 3 & 4 & 7 & 9 & 3 & 6 & 4 & 8 & 3 & 5 & 7 & 4 & 6 & 9 & 2 & 5 & 8 & 2 & 7 & 6 & 2 & 5 & 1 & 9 & 1 & 8 & 1 \\
\hline
\end{tabular}

According to the given numbers, after 8 comes 4 or 2. We find that 2 has only one possible placement, so both 2s are placed at the back. This leaves the two 4s to be placed at the front.
With 2 and 4 determined, we can sequentially determine $9, 6, 5, 7, 3, 8, 1$.