(1) Given the set $A=\{x \in \mathbf{R}|| x-2 \mid \leqslant 1\}$, set $B=\left\{x \in \mathbf{R} \left\lvert\, \frac{x-5}{2-x}>0\right.\right\}$, then $A \cap B=$ $\qquad$
(1) $\{x \mid 2<x \leqslant 3\}$ Hint: It is easy to know that $A=\{x \mid 2 \leqslant x \leqslant 3\}, B=$ $\{x \mid 2<x<5\}$, so $A \cap B=\{x \mid 2<x \leqslant 3\}$.