2. (5 points) There are three natural numbers, their sum is 2015, the sums of each pair are $m+1, m+2011$ and $m+2012$, then $m=$ $\qquad$
2. (5 points) There are three natural numbers, their sum is 2015, the sums of each pair are $m+1, m+2011$ and $m+2012$, then $m=$ $\qquad$ .

【Solution】Solution: According to the problem, we have:
$$
\begin{array}{r}
m+1+m+2011+m+2012=2015 \times 2 \\
3 m+4024=4030 \\
3 m=6 \\
m=2
\end{array}
$$

Therefore, the answer is: 2.