2. How many consecutive terms of the arithmetic progression $32,28,24, \ldots$, starting from the first, must be summed to get a sum equal to 132?

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# Solution:

$\frac{32+32-4(n-1)}{2} \cdot n=132, n^{2}-17 n+66=0, n=\frac{17 \pm 5}{2}=\left[\begin{array}{c}6, \\ 11 .\end{array}\right.$ Answer: 6 or 11.