When three consecutive integers are added, the total is 27 . When the same three integers are multiplied, the result is
(A) 504
(B) 81
(C) 720
(D) 729
(E) 990
If the sum of three consecutive integers is 27 , then the numbers must be 8,9 and 10 . (We could see this algebraically by calling the integers $x, x+1$ and $x+2$ and solving the equation $x+(x+1)+(x+2)=27$.

Their product is $8 \times 9 \times 10=720$.

ANSWER: $(\mathrm{C})$