15. Three rectangular pieces of paper (Jia, Bing, Ding) and one square piece (Yi) can be combined to form a large rectangle with an area of 480 square centimeters. It is known that the areas of Yi, Bing, and Ding are all three times that of Jia. The total perimeter of the four rectangles Jia, Yi, Bing, and Ding is $\qquad$ centimeters.
Analysis: The key point is to skillfully find the perimeter and area.
This type of question requires students to master the methods of skillfully finding the perimeter and area.

According to the basic method of sum, difference, and multiple problems, if we assume that the area of A is 1 unit, then the other 3 pieces have an area of 3 units each. Therefore, the area of A is 48, so the area of B is $48 \times 3=144$ square centimeters, and the side length is 12 centimeters. Since A and B share one side, the other side has a 3 times relationship, so the width of the rectangle is $12+12 \div 3=16$ centimeters, and the length is 30 centimeters. Therefore, the perimeter of the original rectangle is $(16+30) \times 2=92$ centimeters. Clearly, the length and width of each rectangle in the figure cannot be determined, but the large rectangle is cut into four smaller rectangles, and the sum of the perimeters of A, B, C, and D is twice that of the original rectangle, $92 \times 2=184$ centimeters.