\section*{Problem 4 - 111044}

Determine all triples \((m, x, y)\) consisting of a real number \(m\), a negative integer \(x\), and a positive integer \(y\) that satisfy the following system of equations (1), (2)!

\[
-2 x+3 y=2 m \quad(1) \quad ; \quad x-5 y=-11
\]
}

From (2) follows \(5 y-11=x0}\) directly \(y=1\) or \(y=2\). In the first case, \(x=-6\) and \(m=\frac{15}{2}\), in the second \(x=-1\) and \(m=4\).

Thus, the two solution triples \((4,-1,2)\) and \(\left(\frac{15}{2},-6,1\right)\) are obtained. The verification confirms that both specified triples are solutions of the system of equations.