In a chess tournament, there were 12 participants (each played against each other once). By the end of the tournament, it turned out that there were 9 participants, each of whom scored no more than 4 points. It is known that Petya scored exactly 9 points. How did he play against each of the two remaining chess players? (Win - 1 point, draw - 0.5 points, loss - 0 points.)

#
Consider the nine participants mentioned in the problem. They played $9 \cdot 8: 2=36$ games, which means they distributed exactly 36 points. Therefore, each of them scored exactly 4 points in this "sub-tournament." Consequently, all the games they played with the other three chess players, they lost. In particular, they all lost to Pete. Since Pete scored 9 points, he lost the other two games.

## Answer

Pete lost to both.