If a number $N,N \ne 0$, diminished by four times its reciprocal, equals a given real constant $R$, then, for this given $R$, the sum of all such possible values of $N$ is
$\text{(A) } \frac{1}{R}\quad \text{(B) } R\quad \text{(C) } 4\quad \text{(D) } \frac{1}{4}\quad \text{(E) } -R$
Write an equation from the given information.
\[N - \frac{4}{N} = R\]
\[N^2 - 4 = RN\]
\[N^2 - RN - 4 = 0\]
By [Vieta's Formulas](https://artofproblemsolving.com/wiki/index.php/Vieta%27s_Formulas), the sum of all possible values of $N$ for a given $R$ is $R$, so the answer is $\boxed{\textbf{(B)}}$.