14. A group of monkeys is divided into three teams to pick peaches in an orchard, with each team having an equal number of monkeys. After finishing the picking, they combine the peaches and divide them equally. If each monkey gets 5 peaches, there will be 27 left; if each monkey gets 7 peaches, one of the monkeys will get fewer than 7 peaches (at least 1). The total number of peaches picked by the group of monkeys is $\qquad$ peaches.
Analysis: The test point is the profit and loss problem.
This type of question requires students to master the basic method of solving application problems by setting up equations or the problem-solving approach for profit and loss.

In the distribution process, we find that the second distribution plan is short of 7, but there are several situations where it is short of 7. Which one is it? By observing the first distribution plan, we can find that the total number of peaches must be a multiple of 3. Since the second plan is to distribute 7 peaches to each monkey, the distributed quantity must also be a multiple of 3, so the missing part must also be a multiple of 3, which means it is short of 3 or 6.
If it is short of 6, $(27+6) \div(7-5)$ cannot be divided evenly, which does not meet the requirement, so it is excluded;

If it is short of 3, $(27+3) \div(7-5)=15$ (monkeys), the total number of peaches is: $15 \times 5+27=102$ (peaches)