Carl, James, Saif, and Ted play several games of two-player For The Win on the Art of Problem Solving website. If, among these games, Carl wins $5$ and loses $0,$ James wins $4$ and loses $2,$ Saif wins $1$ and loses $6,$ and Ted wins $4,$ how many games does Ted lose?
1. We start by noting that each game has exactly one winner and one loser. Therefore, the total number of wins must equal the total number of losses.

2. We are given the number of wins for each player:
   - Carl wins 5 games.
   - James wins 4 games.
   - Saif wins 1 game.
   - Ted wins 4 games.

3. Summing these, the total number of wins is:
   \[
   5 + 4 + 1 + 4 = 14
   \]

4. We are also given the number of losses for some players:
   - Carl loses 0 games.
   - James loses 2 games.
   - Saif loses 6 games.
   - Ted's losses are unknown and need to be determined.

5. Let \( L \) represent the number of games Ted loses. Since the total number of losses must equal the total number of wins, we set up the equation:
   \[
   0 + 2 + 6 + L = 14
   \]

6. Simplifying the left-hand side, we get:
   \[
   8 + L = 14
   \]

7. Solving for \( L \), we subtract 8 from both sides:
   \[
   L = 14 - 8 = 6
   \]

Thus, Ted loses 6 games.

The final answer is \(\boxed{6}\).