1. Given $y z \neq 0$, and the set $\{2 x, 3 z, x y\}$ can also be represented as $\left\{y, 2 x^{2}, 3 x z\right\}$, then $x=$
If $2 x=y \Rightarrow\left\{\begin{array}{l}2 x^{2}=x y, \\ 3 x z=3 z\end{array} \Rightarrow\left\{\begin{array}{l}x=1, \\ y=2,\end{array}\right.\right.$ satisfies the conditions;
If $2 x=2 x^{2} \Rightarrow x=1 \Rightarrow\left\{\begin{array}{l}x y=y, \\ 3 z=3 x z,\end{array}\right.$ satisfies the conditions;
If $2 x=3 x z \Rightarrow 3 z=2$, if $y=2 \Rightarrow x y=2 x=2 x^{2} \Rightarrow x=1$, contradiction;
if $2 x^{2}=2 \Rightarrow x=-1 \Rightarrow x y=-y=y \Rightarrow y=0$, contradiction. In summary, $x=1$.