8. (10 points) Given $n!=1 \times 2 \times 3 \times \cdots \times n$, what is the result of the expression $\frac{(2014!-1)!\times 2015!}{(2014!)!}$? $\qquad$ .
$$
\begin{array}{l}
\text { [Solution] Solution: Original expression }=\frac{(2014!-1)!\times 2015 \times 2014!}{(2014!)!} \\
=\frac{(2014!)!\times 2015}{(2014!)!} \\
=2015
\end{array}
$$

Therefore, the answer is: 2015
$$