854. Solve the equation in natural numbers

$$
x y^{2}-x y-y^{2}+y=94
$$
$\triangle$ Let's factorize the left side of the equation:

$$
x y^{2}-x y-y^{2}+y=y(x y-x-y+1)=y(y-1)(x-1) .
$$

Moreover, the number 94 can be factored into prime factors: $94=2 \cdot 47$.

Let's think about which divisors of the number 94 differ by 1? This is only possible when $y-1=1, y=2$.

It remains to find $x$:

$$
2(x-1)=94, \quad x-1=47, \quad x=48
$$

Answer: $(48,2)$.