5. There were 2 minutes left before the electric train departed when the motorist was 2 km from the station. For the first minute, he drove at a speed of 30 km/h. At what speed should he drive during the second minute to catch the train?
5. The first method of solving.
1) $2 \times 1000=2000$ (m) - need to travel;
2) $30 \times 1000=30000(\mathrm{m} / \mathrm{h})$ - speed of the car;
3) $30000: 60=500$ (m/s) - speed in the first minute;
4) $2000-500=1500$ (m) - left to travel in 1 minute;
5) $1500 \times 60=90000(\mathrm{m} / \mathbf{h})=90(\mathrm{km} / \mathbf{h})$.

The second method of solving (Alexei Petrov, student of School No. 14).

If the speed is 30 km/h, then in 1 minute the motorist will travel $1 / 2$ km. He has 1.5 km left. 1.5 km is exactly 3 times $1 / 2$. Therefore, the speed should be three times greater $30 \times 3=90$ (km/h).

The third method of solving (Denis Skrynnikov, student of School No. 14).

To travel the entire distance in 1 minute, the motorist needs to travel at a speed of 120 km/h, and to travel in 2 minutes, he needs to travel at a speed of 60 km/h. But he traveled at a speed of 30 km/h for one minute, so he needs to travel the second minute at a speed of $120-30=90$ (km/h).

Answer: the motorist should travel at a speed of 90 km/h.