14. Put the numbers $1, 2, 3, \ldots \ldots, 10$ into the 10 spaces below, each space filled with one of A, B, C, D, E, F, G, H, I, J, and the sum of any three consecutive numbers does not exceed 16.
Then A - B - C + D - E - F + G - H - I + J = ( ).


【Analysis】Extremum, reasoning problem. A+B+C is less than or equal to 16, D+E+F is less than or equal to 16, G+H+I is less than or equal to 16, so J is greater than or equal to 55-48=7. Therefore, G is greater than or equal to 7, similarly, D is greater than or equal to 7, A is greater than or equal to 7, so A, D, G, J are 7, 8, 9, 10 respectively.

Therefore, the required result is 7+8+9+10-(1+2+3+4+5+6)=13.