The Rimaszombat telegraph station's line consists of 60 Meidinger elements. If the current from this station is directly fed into the telegraph machine at the Miskolc station, what will be the intensity of the current in Amperes? The distance to Miskolc is $79 \mathrm{~km}$, the diameter of the iron wire conductor is $5 \mathrm{~mm}$; the resistance of a $1 \mathrm{~mm}$ long and $1 \mathrm{~mm}$ diameter iron wire is $0.2 \mathrm{Ohm}$, (the problem incorrectly states that the resistance of a $1 \mathrm{~mm}$ long and $1 \mathrm{~mm}$ diameter iron wire is $0.024 \mathrm{Ohm}$), the electromotive force of the Meidinger element is $1.079 \mathrm{Volt}$, its internal resistance is $0.62 \mathrm{Ohm}$, and the resistance of the Morse machine is equivalent to the resistance of $16 \mathrm{~km}$ of iron wire.
If the elements are connected in series, then according to Ohm's law, the intensity of the current is

$$
I=\frac{n E}{n R_{b}+R_{k}}
$$

where $n$ is the number of elements, $E$ is the electromotive force of one element, $R_{b}$ is the internal, and $R_{k}$ is the external resistance. Here, the external resistance $R_{k}$ represents the sum of the resistances of the conducting iron wire and the telegraph, which together are equivalent to the resistance of a $95 \mathrm{~km}$ long, $5 \mathrm{~mm}$ diameter iron wire. Since the resistance is directly proportional to the length and inversely proportional to the square of the diameter, therefore

$$
R_{k}=\frac{95 \times 10^{3}}{5^{2}} \times 0.2 \mathrm{Ohm}=760 \mathrm{Ohm}
$$

Thus,

$$
I=\frac{60 \times 1.079}{60 \times 0.62+760} \frac{\text { Volt }}{\text { Ohm }}=0.0812 \text { Ampère }
$$

(Bernát Friedmann.)