3. The graph of the function $y=-x^{2}+p x+q$ intersects the $x$-axis at points $(a, 0),(b, 0)$. If $a>1>b$, then ( ).
(A) $p+q>1$
(B) $p-r q=1$
(C) $p+q<1$
(D) $f q$ ) $=0$
3. $\mathrm{A}$ (Hint: From the problem, $a, b$ 

are the roots of the equation $x^{2}-p x-q=0$. By Vieta's formulas $p+q=$ $(a+b)-a b=(a-1)(1-b)+1$.