11.24 What is greater: $\operatorname{tg} 1$ or $\operatorname{arctg} 1 ?$
11.24 Since $\operatorname{arctg} 1=\frac{\pi}{4}\operatorname{tg} \frac{\pi}{4}=1$, then $\operatorname{tg} 1>\operatorname{arctg} 1$.