6. Two square building blocks of different sizes are glued together to form the solid figure shown on the right, where the four vertices of the bottom face of the smaller block are exactly the midpoints of the edges of the top face of the larger block. If the edge length of the larger block is 2, then the surface area of this solid figure is $\qquad$ .


Analysis: As shown in the right figure, because the four vertices of the bottom face of the small building block are precisely the midpoints of the edges of the top face of the large building block. The area of one face of the large cube is twice the area of one face of the small cube. The surface area of this solid figure is the surface area of the large cube plus the area of one face of the four small cubes. Therefore, the answer is: $6 \times 2 \times 2 + 4 \times (2 \times 2 \div 2) = 32$.