4. (10 points) The average score of six students in a math exam is 92.5 points. Their scores are distinct integers, with the highest score being 99 points and the lowest score being 76 points. Therefore, the score of the student ranking 3rd from the top is at least ( )
A. 94
B. 95
C. 96
D. 97
4. (10 points) The average score of six students in a math exam is 92.5 points. Their scores are different integers, with the highest being 99 points and the lowest being 76 points. Therefore, the score of the student ranking 3rd from the top is at least ( )
A. 94
B. 95
C. 96
D. 97
【Analysis】To find the minimum score of the 3rd student, we know the average score of the six students, which allows us to calculate the total score. Subtracting the highest and lowest scores from the total score gives the total score of the other four students. To minimize the 3rd student's score, the 2nd student's score should be the maximum possible, which is 98. This allows us to find the total score of the remaining three students, and then using "total score ÷ number of students = average score," we can determine the average score of the other three students, and subsequently analyze and deduce the answer to the problem.
【Solution】Solution: $92.5 \times 6 - 99 - 76 = 380$ (points),
Since the highest score is 99 points, the best score for the second student is: 98
The total score of the remaining three students is: $380 - 98 = 282$ (points),
To minimize the 3rd student's score, the 4th and 5th students' scores should be as close as possible to the 3rd student's score, so these three numbers differ by 1,
$$
282 \div 3 = 94 \text { (points) }
$$

Therefore, the 3rd student's score is at least: $94 + 1 = 95$ (points).
Answer: The 3rd place student must score at least 95 points.
Hence, the correct choice is: B.