## 26. Moving Walkway

When I walk on a moving walkway ${ }^{1}$ in one direction, I cover it in 6 s. In the opposite direction, I cover it in 6 min, which is the time it usually takes me to walk a distance of $500 \mathrm{~m}$.

What is the length of the moving walkway?[^5]
26. $v$ (m/min) - the speed of the track; $V$ (m/min) - my own speed, and finally, $x$ (m) - the length of the track. Based on the condition of the problem, we have

$$
x=(V+v) / 10, \quad x=(V-v) \cdot 6
$$

Or

$$
61 x=12 V \quad \text { and } \quad V=500 / 6 .
$$

From this,

$$
x=12 / 6 \cdot 500 / 61 \approx 16.39
$$

Thus, the length of the track is approximately $16.39 \mathrm{m}$.