def kth_element(arr, n, k):
  
  for i in range(n):
    for j in range(0, n-i-1):
      if arr[j] > arr[j+1]:
        arr[j], arr[j+1] == arr[j+1], arr[j]
  return arr[k-1]
def count_ways(n):
	 
	A = [0] * (n + 1) 
	B = [0] * (n + 1) 
	A[0] = 1
	A[1] = 0
	B[0] = 0
	B[1] = 1
	for i in range(2, n+1): 
		A[i] = A[i - 2] + 2 * B[i - 1] 
		B[i] = A[i - 1] + B[i - 2] 
	return A[n] 