def find_rotation_count(A):
    
    (left, right) = (0, len(A) - 1)
    while left <= right:
        if A[left] <= A[right]:
            return left
        mid = (left + right) // 2
        next = (mid + 1) % len(A)
        prev = (mid - 1 + len(A)) % len(A)
        if A[mid] <= A[next] and A[mid] <= A[prev]:
            return mid
        elif A[mid] <= A[right]:
            right = mid - 1
        elif A[mid] >= A[left]:
            left = mid + 1
    return -1
def min_cost(cost, m, n):
	R = 3
	C = 3
	 
	tc = [[0 for x in range(C)] for x in range(R)] 
	tc[0][0] = cost[0][0] 
	for i in range(1, m+1): 
		tc[i][0] = tc[i-1][0] + cost[i][0] 
	for j in range(1, n+1): 
		tc[0][j] = tc[0][j-1] + cost[0][j] 
	for i in range(1, m+1): 
		for j in range(1, n+1): 
			tc[i][j] = min(tc[i-1][j-1], tc[i-1][j], tc[i][j-1]) + cost[i][j] 
	return tc[m][n]