def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
    
    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])
def truncate_number(number: float) -> float:
    """ Given a positive floating point number, it can be decomposed into
    and integer part (largest integer smaller than given number) and decimals
    (leftover part always smaller than 1).
    Return the decimal part of the number.
    >>> truncate_number(3.5)
    0.5
    """
    return number % 1.0