def get_median(arr1, arr2, n):
  
  i = 0
  j = 0
  m1 = -1
  m2 = -1
  count = 0
  while count < n + 1:
    count += 1
    if i == n:
      m1 = m2
      m2 = arr2[0]
      break
    elif j == n:
      m1 = m2
      m2 = arr1[0]
      break
    if arr1[i] <= arr2[j]:
      m1 = m2
      m2 = arr1[i]
      i += 1
    else:
      m1 = m2
      m2 = arr2[j]
      j += 1
  return (m1 + m2)/2
def min_cost(cost, m, n):
	R = 3
	C = 3
	 
	tc = [[0 for x in range(C)] for x in range(R)] 
	tc[0][0] = cost[0][0] 
	for i in range(1, m+1): 
		tc[i][0] = tc[i-1][0] + cost[i][0] 
	for j in range(1, n+1): 
		tc[0][j] = tc[0][j-1] + cost[0][j] 
	for i in range(1, m+1): 
		for j in range(1, n+1): 
			tc[i][j] = min(tc[i-1][j-1], tc[i-1][j], tc[i][j-1]) + cost[i][j] 
	return tc[m][n]