def get_odd_collatz(n):
    if n%2==0:
        odd_collatz = [] 
    else:
        odd_collatz = [n]
    while n > 1:
        if n % 2 == 0:
            n = n/2
        else:
            n = n*3 + 1
            
        if n%2 == 1:
            odd_collatz.append(int(n))
    return sorted(odd_collatz)
from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
    for idx, elem in enumerate(numbers):
        for idx2, elem2 in enumerate(numbers):
            if idx != idx2:
                distance = abs(elem - elem2)
                if distance < threshold:
                    return True
    return False