// matrix_mul_serial.c | |
// 串行矩阵乘法,测量纯计算时间(不含矩阵生成/初始化) | |
static double get_time() { | |
struct timeval tv; | |
gettimeofday(&tv, NULL); | |
return tv.tv_sec + tv.tv_usec * 1e-6; | |
} | |
int main(int argc, char *argv[]) { | |
int N = 8000; | |
if (argc >= 2) { | |
N = atoi(argv[1]); | |
} | |
// 分配并初始化矩阵 | |
double *A = malloc((size_t)N * N * sizeof(double)); | |
double *B = malloc((size_t)N * N * sizeof(double)); | |
double *C = calloc((size_t)N * N, sizeof(double)); | |
if (!A || !B || !C) { | |
fprintf(stderr, "内存分配失败\n"); | |
return EXIT_FAILURE; | |
} | |
srand(0); | |
for (long long i = 0; i < (long long)N * N; i++) { | |
A[i] = rand() / (double)RAND_MAX; | |
B[i] = rand() / (double)RAND_MAX; | |
} | |
// 纯计算部分计时 | |
double t0 = get_time(); | |
for (int i = 0; i < N; i++) { | |
for (int j = 0; j < N; j++) { | |
double sum = 0.0; | |
for (int k = 0; k < N; k++) { | |
sum += A[(long long)i * N + k] * B[(long long)k * N + j]; | |
} | |
C[(long long)i * N + j] = sum; | |
} | |
} | |
double t1 = get_time(); | |
printf("Serial multiplication time: %.6f seconds\n", t1 - t0); | |
free(A); | |
free(B); | |
free(C); | |
return 0; | |
} | |