text: since SO4- ions are not oxidized at the anode:\n\n\nCu2+(aq) + 2e- --> Cu(s)\n\n2H2O(l) --> 4H+(aq) + O2(g) + 4e-\n\n4H+(aq) + 4e- --> 2H2(g) \n\nthe overall equation:\n\n2Cu2+(aq) + 2H2O(l)  ->  2Cu(s) + 2H2(g) + 02(g)\n\n\nthe products are Cu(s), H2(g)and O2(g)