text: 4x^2-10x+6=2(2x^2-5x+3)=2(2x-3)(x-1)\n\nso the function becomes:\n(2(2x-3)(x-1))/(3-2x)\n\nthe top part can be multiplied by -1 to flip one of the roots\nwe will choose to flip the (2x-3) into (3-2x)\njust remember to put a - out in front to cancel out multiplying by -1\n\n-2(3-2x)(x-1)/(3-2x)=\n-2(x-1)      \n\nx cannot be equal to 3/2\nthis makes a hole(not an asymptote) at x=3/2\n\nthere are no horizontal or oblique or vertical asymptotes