text: The beam is at 48 degrees to the horizontal.. Its weight of 588N acts at its middle (0.5L) vertically downwards. There is a load of 1770N at its end (1L). The tension due to the cable acts perpendicular to the beam and at a distance of 0.66L. Now, the basic equation in physics tells that the clockwise moment is balanced by the counter-clockwise moment in a stationary object. So, if 'T' is the tension in the cable;\n\nT*0.66L = 588*0.5L*cos48 + 1770*1L*cos48\n\nsolve this to get the answer to A).\n\nThe answer to B) is got by equating the horizontal forces to zero as the beam is stationary. The equation is:\n\nHR - T*cos(90-48) = 0.\n\nhere HR is the horizontal component of the reaction force by the floor. T is as above\n\nC) The vertical component is got by equating the vertical forces to zero.\n\nVR - 588 - 1770 + T*sin(90-48) = 0