text: Sure the F value should be 100+200+100+300=700N\nTo find the point of affect, let's suppose the distance of point from A be x, then from the torques equilibrium at x:\n100*x+200*(x-2)+100*(x-4)+\n300*(x-6)=0    so    700x-2600=0\nx=26/7 almost 3.71 means 'x point' resides somewhere between B & C, much closer to C.