text: That's easy\nThe key to projectile motion is resolving motion horizontally and vertically(or downwards).The vertical motion is accelerated motion,acceleration being g while horizontal motion is not accelerated and is at constant speed.\nSuppose at time t=0 the ball leaves the table.\nVh(0)=3m/s          Horizontal Velocity\nVd(0)=0m/s          Downwards velocity\nNow time taken to hit floor is same as  time taken by downwards velocity component to cover 1.25 m\nUse s=ut+1/2 gt^2      here u=Vd(0)\n1.25=0+0.5*9.8*t^2\nt=sqrt(1.25/(.5*9.8))\nt= 0.50507 sec\nTo calculate how far it travels just multiply this time by Vh(0)  \n3*.50507=1.515m