text: You can split up the (x^2-4)^(4/3) into ((x^2-4)^(1/3))*(x^2-4), because you are adding the exponents when you multiply(1/3+1=4/3).  Then you can factor out the (x^2-4)^(1/3) and come up with:\n((x^2-4)^(1/3))*(8x^2+(x^2-4))\nWhich simplifies to:\n((x^2-4)^(1/3))*(9x^2-4)=0\n\nThat means two things:\n9x^2-4=0\nand\n(x^2-4)^(1/3)=0\n\nTake the first one, and you get the answer +-2/3\nTake the second one, cube both sides, and get x^2-4=0, which yields +-2.\n\nPlug all four of those answers into x to check for extraneous roots.  All four work, so there are no extraneous answers.\n\nHope that helps!  Tell me if something doesn't make sense.\n\nEDIT:\nTo the poster below me, ^ means "raised to the power of", and you have to hold your mouse over the equation in his post to get the whole thing.