text: Think of the die as containing one 1, one 2, two 3s, two 4s, six 5s, and six 6s.\n\nThis way, the probability of rolling a 3 is 2/18 = 1/9 and the probability of rolling a 5 is 6/18 = 1/3, which is three times as likely as 1/9.\n\nNow, since there is only one 2 present on the die, the chance of rolling a two is 1/18. Since there are two 4s on the die, the chance of rolling a 4 is 2/18. Add these two probabilities together to get:\n1/18 + 2/18 = 3/18 = 1/6\n\nThe answer is (a) 1/6\n\nGood luck, I hope this helps!