text: 1. The father is heterozygous.  Use these in the punnet square:\n    Aa x aa.  (The father is the heterozygous one, the mother is the homozygous)\n\n2. You're right.  It is a dominant inheritence.  To prove that just use these in a punnet square:  Ff x Ff    Those show that both parents have freckles because it is dominant.  But if you do the punnet square on that, you will see that there is a 25% chance that the offspring will not be freckled. (there is a "ff" in one of the squares)  That is where the unfreckled kids came from.\n\n3. Okay, this one is kind of tricky to explain through words over the computer.  But, you take your BbCc x BbCc and it kind of like "foiling it."  I don't know if you are familiar with the term "foil" but it is used in math.  First you set up a dihybrid cross.  (i assume you know what that is, 16 squares total.)  Take your first term:  BbCc.  Along the top of the punnet square do this:\n\n        1st block:  BC\n        2nd block:  Bc\n         3rd block:  bC\n         4th blcok:  bc\n\nNow take your second term and do the exact same thing since both terms are the same.  Now all you have to do is cross them.  I don't know what to tell you about what color their offspring can be because you didn't tell me what the "Cc" trait is for.  But to find out the percent is easy.  Just take how ever many blacks you get and divide it by 16 since there are a total of 16 blocks.\n\nI hope this helped you.  I  took Genetics last year.  E-mail me back at bhuff89@yahoo.com and let me know how everything went.