text: By Euler's Identity:\n\ne ^ (i * pi) = -1\n\nTaking the square root of both sides:\n\ne ^ (i * pi / 2) = i\n\nTaking the i'th root of both sides:\n\ne ^ (pi/2) = i ^ (1/i)\n\nI fear that one or more of the steps isn't valid, but my answer is:\n\ne ^ (pi/2)