text: Use the formula: \n\ndistance = vt + 0.5 * at^2\n\nThe distance of the van from the entrance of the tunnel is Dv = 5t + 155.\n\nThe distance of the car from the entrance of the tunnel is Dc = 30t + 0.5 * 2(t^2).\n\nThe two collide when Dv = Dc\n\n5t + 155 = 30t - t^2\nt^2 - 25t + 155 = 0\n\nUse quadratic formula and you get \n\nt = 11.4 and 13.6\n\nThere would be therefore be a collision at 11.4 seconds.\n\nThen use same formula to work out distance\n\nDc = 30 * 11.4 - 1 * 11.4 * 11.4\nDc = 212m\n\n**Phew.. I'm a bit rusty this morning**