text: First, Plot all the points on a graph.\nThe Focus is (11, 2).\nNow, Plot the 2 asymptotes.\nThis can be done by substituting, x=0 to find y then y=0 to find x.\nThe first one is a line crossing (0,-6) and (4.5,0)\nThe second one is a line crossing (0,10) and (7.5,0).\n\nNow with these lines and the focus, you will see that the hyperbola opens to the right.\n\n---\n\nThe equation is:\n{[(x-h)^2]/(a^2)} - {[(y-k)^2]/(b^2)} = 1\n\nwith the equations of the asymptotic lines as:\ny - k = +/- (b/a)(x - h)\n\n-----\nSo the 2 asymptotes equation will give,\ny = 4x/3 - 6 and y = -4x/3 + 10\n\nHence, b=4, a=3\nSolving for h, k\n\nk - 4h/3 = -6\nk + 4h/3 = 10\nNow, 2k = 4, this k = 2.  Giving h = 6\n\n--- The equation is \n{[(x-6)^2]/(3^2)} - {[(y-2)^2]/(4^2)} = 1