text: let me try it:\n\na) Area of triangle:\n\n\na/1) plot a graph. draw a perpendicular from C to AB. area = 1/2 * AB * perpendicular distance.\n\na.2) area = 1/2 [x1 (y1-y2) + x2 (y2-y3) + x3 (y3-y1)]\n\nwhere x1, x2, x3 are x - cordinates and y1, y2, y3 are y-cordinates. \n\na.3) distance between any two points = sqrt |(x^2 - y^2)|\nusing this find AB, BC and CA.\narea= SQRT (s* (s-AB) * (s-BC) * (s-CA))\nwhere s = (AB+BC+CA) * 0.5\n\n(b) AB is the diameter of circle F.\narea = pi * (AB^2) * 0.25 \n\n(c) this needs to be plotted probably to know their intersection. this can also be done using integral calculus. i am not sure what is your level of proficeincy in calculus.