text: Use the quadratic formula\na = 1, b = -2 and c = 5\n[-b +/- sqrt(b^2-4ac)]/(2a)\n= [2 +/- sqrt(4-4*1*5)]/(2*1)\n= [2 +/- sqrt(4-20)]/2\n= [2 +/- sqrt(-16)]/2\n= [2 +/- 4i]/2\n= (2+4i)/2 or (2-4i)/2\n= 1+2i or 1-2i