text: Well, 9 letter word. If all of the were different, then there would be 9! permutations.\n\nBut there are 3 N's, 2 K's, and 2 E's, 1 B, and 1 U. So, we must divide 11! by (3! * 2! * 2! * 1! * 1!).\n\nANSWER : 11! / (6 * 2 * 2 * 1 * 1) = 1,663,200