text: x + y = 14 ...so ...x = 14 - y\n\nx^2 +y^2 = 130 ...plugging in x from above...\n\n(14-y)^2 + y^2 = 130   ...multiply out your products...\n\n196 -28y +y^2 + y^2 = 130  ...combining your y^2\n\n2y^2 -28y +196 -130 = 0  ....moving over the 130 \n2y^2 -28y + 66 = 0  ...dividing equation by 2\ny^2 -14y + 33 = 0  ...performing FOIL method and finding roots...\n\ny = (y-11)(y-3) = 0 ...y can be 11 or 3\n\nIf y is 11, then plugging back into x = 14 - y...x is 3\nIf y is 3, then plugging back into x = 14 - y...x is 11\n\nSo your two number can be 11 and 3 \n\nActually, if you don't want to do the algebra...\n4x4 + 10x10 = 116 NOT 130\n5x5 + 9x9 = 106 NOT 130 \nand 2x2 + 12x12 = 148 NOT 130 \nso 3 and 11 can be your only solutions