text: anything.  but if you want it to be perfectly factorable...\n\nit can be several numbers.\n\n(8z +7 )(z+5 ) c would equal 47\n(4z + 7)(2z + 5) c would equal 34\n(8z + 5)(z + 7) c would equal 61\n(2z + 7)(4z + 5) c would equal 38\n(8z + 35)(z + 1) c would equal 43\n(z + 35)(8z + 1) c would equal 281\n(2z + 35)(4z + 1) c would equal 142\n(4z + 35)(2z +1) c would equal 74\n\nand so on...