text: since the base of one triangle is 9/5 of the other, the height of this triangle is also 9/5 of the other. \narea1 = (base)(height)/2\ntherefore area2 = ((9/5)base)((9/5)height)/2\n                          = (9/5)^2 [(base)(height)/2]\ntherefore the area of the larger triangle will be (9/5)^2 = 81/25 times that of the smaller triangle