text: Is it supposed to say it is thrown from an initial height of 5 feet?  The path of the ball will be in the form of a parabola y=ax^2 + bx + c where\n\na = 1/2 the force of gravity (gravity is -32 feet/second^2, so -16 feet/second^2)\nx = time, so in this case 2\nb = the velocity\nc = the initial starting height\n\nSo just plug in your numbers and solve\n\n= -16*(2^2) + 35*2 + 5\n= -64 + 70 + 5\n= 11 feet\n\nOh, and the function would be h(t) = -16t^2 + 35t + 5