text: That works, but you need to add the latent heat of fusion required to make the ice into water.  You can do the e=smt where e is the energy required (in J), s is the specific heat of ice(2100 J/kg per degree C), m is the mass of ice (kg), and t is the change in temp (C).\n\ne=(2100)(.1)(20)\ne=4200 J\n\nThen to make it into water, you need to do e=ml, there e is the energy required (J), m is the mass (kg), and l is the laternt heat of fusion (about 3.3 x 10^5 J/kg for water).\n\ne=(.1)(3.3 x 10^5)\ne=33000 J\n\nThen add the two e's together to ge a total\n\ne=37200 J