text: First figure out how many moles of H+ come from the HCl.\nSince the HCl-H+ ratio is 1:1 use the volume and molarity of the HCl and the answer will be moles of H+.\n\nUse Molarity = moles/liters to get that answer.  Don't forget the change mL to liters.\n\nThen figure out how many moles of OH- come from the NaOH using the same formula.  The NaOH - OH- ratio is also 1:1.\n\nOne of the two numbers, H+ or OH-, is bigger than the other; subtract to find out which one is in excess.  If it is the H+, get the pH by taking the -log.  If it is the OH-, get the pOH by taking the \n-log and then subtract from 14 to get the pH \n(since pH + pOH = 14).\n\nSecond problem:  take the antilog of -1.84 to get the H+.\nFor the OH- subtract the pH from 14 to get the pOH and then take the antilog of that number to get the OH- (remember to change the number to a negative before you take the antilog).\n\nYou now have your H+ and OH-, proceed as in the first problem