text: Use the trig identity sin2a = 2sinacosa, and the fact that cos(arcsinx) = √(1-x²) to answer this.\n\nsin(2arcsin3/5) =\n\n2sin(arcsin3/5)(cos(arcsin3/5) = \n\n2 * 3/5 * √(1-(3/5)² = \n\n2 * 3/5 * √(16/25) = \n\n2 * 3/5 * 4/5 = 24/25\n\nHope that helped!