text: Acceleration in a circular path=V^2/r\nV=tangential velocity of the mass\nr=radius of circle.\nHere the mass is moving in circular \npath in a vertical circle. Hence the \ngravity will come in to play. At the \ntop it will act against while at the \nbottom it will add.\nAcceleration on top \n=V^2/r-g\n=[4^2/.72]-9.81\n=22.22-9.81\n=12.41m/sec^2\nAcceleration at bottom\n=V^2+g\n=[4^2/.72]+9.81\n=22.22+9.81\n=32.03 m/sec^2