text: 3(4^3+2*4^2-3*4*7+7^2-5*7+1)\n\ndo exponents first\n\n4^3=64\n4^2=16\n7^2=49\n\nnow put back into the equation\n3(64+2*16-3*4*7+49-35+1)\n\nnow do multiplication\n\n2*16=32\n3*4=12\n12*7=84\n5*7=35\n\nso now you have 3(64+32-84+49-35+1)\n\nnow read left to right\n\n64+32=96\n96-84=12\n12+49=61\n61-35=26\n26+1=27\n\n3*27=81\n\nbut i could be wrong because you didn't close parentheses "()" but assuming they closed them that's what a got...it was simple because you just plug in the values for x and y  and then solve using order of operations\n\ncheck ya later ♥