text: I think you mean 100.102 g of water. If not, substitute your original value into the equation below.\n\nQ = m deltaT c = (100.102 g) (0.996 degC) (4.184J/g degC)\n    = 417.15 J\n\n417.15 J/ 2.50 g= 166.86 J/g KBr