text: You can combine the right side terms using the\n property log(a/b) = log a - log b in reverse.\n\nIt is log(3/(2x-1))\n\nSo now you have log(x+1) = log(3/(2x-1)\n\nSince the logs are equal, so must be the things you took the log of.\nSo x+1 = 3/(2x-1)\n\nCross multiply: (x+1)(2x-1) = 3 \n\n2x^2 + x - 1 = 3\n\n2x^2 + x - 4 = 0\n\nSolve for x.  Check that when you plug it in, you don't end up with the log of a negative number.