text: The same procedure as used in acidic medium can be applied, for example, to balance the complete combustion of propane:
  :Unbalanced reaction: CH + O → CO + HO
  :Reduction: 4 H + O + 4 e → 2 HO
  :Oxidation: 6 HO + CH → 3 CO + 20 e + 20 H
  By multiplying the stoichiometric coefficients so the numbers of electrons in both half reaction match:
  :20 H + 5 O + 20 e → 10 HO
  :6 HO + CH → 3 CO + 20 e + 20 H
  the balanced equation is obtained:
  :CH + 5 O → 3 CO + 4 HO