text: When treated with sodium borohydride, molybdate is reduced to molybdenum(IV) oxide:
  :NaMoO + NaBH + 2HO → NaBO + MoO + 2NaOH + 3H
  Sodium molybdate reacts with the acids of dithiophosphates:
  :NaMoO +   → [MoO(SP(OR))]
  which further reacts to form [MoO(SP(OR))].