# Write a python function to count the number of digits in factorial of a given number.
import math


def find_Digits(n):
    if n < 0:
        return 0
    if n <= 1:
        return 1
    x = n * math.log10(n / math.e) + math.log10(2 * math.pi * n) / 2.0
    return math.floor(x) + 1
