Programming, Tech, Discrete Maths.
miss the other two throws. Considering this, P(Kevin making exactly two out of four throws) = Possible outcomes * P(making throws twice) * P(missing throws twice). Let's rewrite it as P(2/4) = 6 * 0.63^2 * 0.37^2 = 0.326 P(making 3rd throw in fifth attempt) = P(making exactly 2 throws of 4