Cryptography, Python, Math, Mathematics, Diffie Hellman.
12,322,846,688,760,936,252,042,622,733. Solving for the unique integers m and k such that x-1 = m(2^k), we find that m = 3,080,711,672,190,234,063,010,655,683 and k = 2. Let a = 4,658,103,515,624,502,847,038,292,640. Therefore, b = a^m (mod x) = 1. Since 1 modulo x = b modulo x, we can say that b ≡