Probability, Statistics, Distributed Systems, Software Engineering, Interview Questions.
cache[i-1][j-1] return cache def maximum_keys(m, n, h): # Computes the nCr values using dynamic programming cache = ncr(m) p = recursion(m, n, h, cache, {})/(n**m) return p def recursion(m, n, h, cache, dp): # base case if n == 1: return 0 if m > h else 1 s = 0 for k in range(h+1): if m >= k: # Use