Laser, Optics, Physics, STEM, Light.
considering D >> d, l. For the fringes to disappear, the path difference between the light waves that arrive from S’ at the two slits must equal half the wavelength of the source, i.e., λ/2. Thus, we have S’S₂ — S’S₁ = ld/D = λ/2. — (3) In other words, if instead of two point-sources, we had a