Programming, Tech, Discrete Maths.
missing 2 shots 4C2 = 4!/2!(4–2)! = 6 possible outcomes If Kevin has 63% chance of making a throw then he has 37% (100-63) of missing a throw P(of making a throw) = 63/100 = 0.63 P(of not making a throw) = 1 - 0.63 = 0.37 To make 2 throws out of four throws, it means Kevin has to make 2 throws and