Woodworking, Statistical Mechanics, Science, Philisophy, Experimental Philosophy.
(n1+n2)Rln2 n1 = moles (quantity) of gas A n2 = moles (quantity) of gas B Meaning that at room temperature, the minimum work needed to unmix two gases: ΔST = (n1+n2)Rln2 * 298 Assuming 0.5 moles of gas A from 0.5 moles of gas B it would be: 298*R*ln(2) = 1717.5 Joules to unmix a mole of 50/50 ideal