Cryptography, Cybersecurity, Number Theory, Information Security, Rsa.
this public key available for all to see. Steve selects a random ephemeral key k = 197 to be used only once. Using this ephemeral key and Anthony’s public key, he computes c1 = g^k (mod p) = 2¹⁹⁷(mod 467) = 87 and c2 = m(A^k) (mod p) = 123(224¹⁹⁷) (mod 467)= 309. These two numbers c1 = 87 and c2 =