Cybersecurity, Cryptography.
can then checks that log_g(g^x)==log_h(h^x). Peggy first creates her secret (x), and then calculates: Next Peggy creates a non-interactive challenge (c) and which is a hash of g,xG,h,xH,vG,vH and N: and computes: z=cx+r The proof this then (z,c). Overall, Eve cannot construct a valid pair of z,c