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over F11 for the above equation, namely (0, 5), (0, 6), (3, 3), (3, 8), (5, 4), (5, 7), (6, 1), (6, 10), (7, 0), (9, 3), (9, 8), (10, 3) and (10, 8), as shown in the figure below. All of these 13 solutions and a special point O (so-called point at infinity) form a group of 14 elements, i.e., E(F11)