Programming, The Assignment Problem, Minimum Matrix Sum, Python, Software Development.
i['row'] == j['row'] and j['modified'] > 0: i['modified_value'] = i['modified_value'] - j['minVal'] Voila! Now, if we print newlist, we can see that the four values with 0’s are at the top of our list, and we can easily select the ones that don’t occur in duplicate rows or columns. Our output