Python, Numerical Methods, Mathematics, Newtons Method.
is much closer to the solution. Let’s call this new point as x1 (which is our new approximation). Now we know the coordinate of the new approximation. i.e., (x1, 0). We substitute this value in our original equation and evaluate x1 as follows: 0 = f(x0) + f′(x0) (x1−x0) x1−x0 = − f(x0) / f′(x0) x1