Cryptography, Cybersecurity.
(13–1101b), and for multiplication we get x³+x²+x (14–1110b). Add=(x³)+(x²+1)=x³+x²+1 Mult=(x³)×(x²+1)=x⁵+x³ Now we divide x⁵+x³ by the primitive (x⁴+x+1) and get the remainder: __x______ x^4 + x+1 | x^5+x^3 x^5 +x^2+x -------- x^3+x^2+x Thus the result of the multiplication is the remainder of