Physics, Elasticity, Maharashtra Hsc Result, Tension.
modulus of the material. Solution : L = 20 m A = 1.25 ×10⁻⁴ m² F = mg = 2.5 × 9.8N l = 10⁻⁴ m . . . . . Eg2: A brass wire of length 4.5m with cross sectional area of 3×10⁻⁵ m² and a copper wire of length 5.0 m with cross sectional area 4×10⁻⁵ m² are stretched by the same load. The same elongation