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(N/2)*(N/2) = N²/4 operations for both the even and odd terms. Doing this and applying some simple symmetric logic will allow us to calculate the value of F(k) for all integral values of k between 0 and N — 1, effectively reducing the number of operations from N² to 2 × (N/2) × (N/2) = N²/2 i.e, a