Probability, Statistics, Distributed Systems, Software Engineering, Interview Questions.
and mu = 100 and c = 1 rho = lambda/(c*mu) = 8/10 = 0.8 Expected number of messages in the queue P = rho²/(1-rho) = 0.64/0.2 = 3.2 Expected waiting time in the queue = P/lambda = 3.2/80 = 40ms. In the above problem, what if the number of queues are 3? rho = lambda/(c*mu) = 8/30 = 0.267 Expected