Math, Linear Algebra, Eigenvectors, Ml So Good, Information Technology.
Matrix for a Matrix with a diagonal of Lambda. The result is: Operation calculus Next, we proceed to multiplicate the primary diagonal and the secondary diagonal: = (1-λ)(2-λ) = 0 We simplify: λ² — 3λ + 2 = 0 It cames: λ1 = 1 λ2 = -2 Those two are the Eigenvalues! Eigenvectors We have to subtract