Cryptography, Cybersecurity.
and can then easily find the other factor as 79: a=2 M=2*3*5*7 n=553 g=math.gcd(a**M-1,n) print (g) print (n//g) Coding The basic algorithm is then [taken from [here][2][here]: # Code derived from https://github.com/google/paranoid_crypto from typing import Optional import gmpy2 from gmpy2 import