Telecommunication.
Example 1. We calculate the capacity of a non-noisy channel having a band of 2.7 kHz and an alphabet consisting of 4 and 8 levels. From the formula [2] we obtain, with L=4 and B=2,7 kHz: C=10.8 kbps From the formula [2] we obtain, with L=8 and B=2,7 kHz: C=16 kbps The capacity of the channel