Probability, Statistics, Distributed Systems, Software Engineering, Interview Questions.
Base case if n <= 0: return 0 s = 0 for k in range(1, n+1): # If already computed, then don't call recursion a = recursion(n-k, p, cache, dp) if n-k not in dp else dp[n-k] s += cache[n][k]*((1-p)**k)*(p**(n-k))*a dp[n] = (1+s) return dp[n] def retry_attempts(n, p): cache = ncr(n) return