Cryptography, Cybersecurity, Tls, Rsa.
which will then produce an incorrect signature (s). If we do it on s2, then: e=65537 dP = 1 * pow(e,-1,p-1) dQ= 1 * pow(e,-1,q-1) qInv= 1 * pow(q,-1,p) s1 = pow(m,dP,p) s2 = pow(m,dQ,q)+1 h = (qInv*(s1 - s2)) % p s= s2 + h*q Notice that s2 has one added to it. We can first recover p with: and where