Dynamic Programming, Recursion, Python, Coding Tutorial, Python Programming.
optimal one using max memo[(capacity, index)] = max(prices[index]+solveKnapsack(weights, prices, capacity - weights[index], index+1, memo), solveKnapsack(weights, prices, capacity, index + 1, memo)) return memo[(capacity, index)] def knapsack(weights, prices, capacity): # create a memo dictionary