Probability, Statistics, Distributed Systems, Software Engineering, Interview Questions.
[[0]*(n+1) for i in range(n+1)] for i in range(n+1): for j in range(i+1): if j == 0 or i == j: cache[i][j] = 1 else: cache[i][j] = cache[i-1][j] + cache[i-1][j-1] return cache def prob(n, p, cache): # Calculate probability f (above) with n and p s = 0 for k in range(int((n+1)/2), n+1): s +=