Cryptography, Cybersecurity.
Multiply: 1x^3 + 1 Divide: 1x^3 + 1x^2 For the division, we determine the inverse of b and then multiply by a. In this case we have a×b^{−1} = (x²+x+1)×(x³+x²+x)=x⁵+x⁴+x³+x⁴+x³+x²+x³+x²+x=x⁵+x³+x. As we have a higher power that the field, we now need to divide by the primitive (x⁴+x+1) and get the