Calculus, Optimization, Mathematics.
0.001x² − 50. We now take the derivative of P(x): P’(x) = 5 − 0.002x. Setting this equal to 0, we can see that x = 5/0.002 = 2500. So, x = 2500 is a point of interest. Using the candidates’ test, we can evaluate if this is a minimum or a maximum (or neither, as you will see in some cases). P’’(x) =