Probability, Statistics, Distributed Systems, Software Engineering, Interview Questions.
cache[n][k]*((1-p)**k)*(p**(n-k)) return s def binary_search(p, m=1000): # Maximum 1000 servers cache = ncr(m) # We want only odd number of servers odd_numbers = [x for x in range(1, m+1) if x % 2 == 1] left, right = 0, len(odd_numbers)-1 q = -1 while left <= right: mid = int((left+right)/2) n =