Math, Mathematics, Geometry, Path, 2d.
Figure 5 Using the same method from the previous case, we know that a<e, b<f, c<g, d<h. Therefore, we have a+b+c+d < e+f+g+h. In other words, AB < AC+CD+DB. As seen in the proof of figure 1 and 2, we can utilize the same method to prove that every other path is always larger than the direct and