We need to find the greatest possible product when two integers whose sum is 246 are multiplied. 

Let the two integers be x and (246-x). So, their product is (x)(246-x) = 246x - x^2.

To maximize this expression, we can complete the square: 

- (x^2 - 246x) = -[(x-123)^2 - 15129] 
= -(x-123)^2 + 15129 

Since the square of a real number is always non-negative, the expression is maximized when (x-123) is equal to zero, which means that x = 123. 

So, the greatest product obtainable is -(123-123)^2 + 15129 = 15129.
Qual è il massimo prodotto ottenibile da due interi la cui somma è 246?