is P(notB|A) same as not(P(B|A)) is P(notB|A) same as not(P(B|A))  if not then what is the difference  between them? this is taken from bayes question.

The negation operator applies to logical propositions or events, not numbers.  Consequently, the operator cannot be applied to a probability.  This means that there is no such thing as $\text{not } \mathbb{P}(B|A)$.  The rule you are looking for might be the following:
$$\mathbb{P}(\text{not } B|A) = 1-\mathbb{P}(B|A).$$
