How to determine the no of multiplication operations in convolution operation? Let's say We have an input of size 28×28×192. We apply 32,  5×5 convolution filters with padding "same". How many multiplication operations will be there in total?
I know there will be 282832 * 55192 multiplications, But I cannot understand how. Your help will be appreciated.

With no dilation, stride equal to $1$ and padding equal to same, the output and input size are the same. For each output pixel, we have a complete element-wise multiplication between the filter and the input, i.e. $5\times 5$ multiplications. Since there are $32$ filters, for each output pixel (with channels accounted), we have $32\times 5\times 5$ multiplications. Because the output size is $28\times28\times192$, the total number of multiplications equates to $28\times28\times192\times5\times5\times32=120422400$.
