Power series help please! $$ \frac{2}{3-x}  $$
I need to find a power series representation for this. I figured i'd pull the two out, but I can't figure out what to do with the three.

We know that $1 + r + r^2 + r^3......= \dfrac{1}{1-r}$. So we can write $\dfrac{2}{3-x} = \frac{2}{3}\dfrac{1}{1-\frac{x}{3}} = \frac{2}{3}(1+\frac{x}{3}+\frac{x^2}{9} + \frac{x^3}{27} + \frac{x^4}{81}.......)= \frac{2}{3}\sum_{n=0}^\infty(\frac{x}{3})^n$
