Need help with logarithmic differentitation I have the expression
$$y = \sqrt{x^2(x+1)(x+2)}.$$
I have tried looking at videos but I still cannot arrive at the correct answer and don't know how to get there.
By the way, the correct answer is
$$y' = \frac{4x^2+9x+4}{2\sqrt{(x+1)(x+2)}}.$$
Please, help.

Alternatively, write $$y^2=x^2(x+1)(x+2)$$
Then $$2yy'=2x(x+1)(x+2)+x^2(x+1)+x^2(x+2)$$ whence 
$$y'=\frac{2x(x+1)(x+2)+x^2(x+1)+x^2(x+2)}{2x\sqrt{(x+1)(x+2)}}$$
$$y'=\frac{2(x+1)(x+2)+x(x+1)+x(x+2)}{2\sqrt{(x+1)(x+2)}}\\=\frac{4x^2+9x+4}{2\sqrt{(x+1)(x+2)}}$$
assuming you wanted $x\sqrt{(x+1)(x+2)}$ since $\sqrt{x^2}=|x|$ and we get something not that nice with that.
