Solve a Linear Equation Please help to solve this problem.what is the answer of this equation. Is it any famous problem?
If $a,b,c\in\mathbb{C}$ such that
$$a+b\neq0,\quad b+c\neq0,\quad a+c\neq0\\a+b+c=-23,\quad ab+ac+bc=-324$$
Then what is the value of $x$ in the following equation?
$$\frac{x^2+2b^2+c^2}{a+b}+\frac{x^2+2c^2+a^2}{b+c}+\frac{x^2+2a^2+b^2}{a+c}=0$$

HINT:
$$\frac{x+2b^2+c^2}{a+b}=\frac{x+a^2+b^2+c^2+b^2-a^2}{a+b}=\frac{x+a^2+b^2+c^2}{a+b}+b-a$$
and  $$a^2+b^2+c^2=(a+b+c)^2-2(ab+bc+ca)$$
