Fraction issue, I don't know why I'm having this result. I don't know how to get this result: $\frac{38}{17}$
This is the equation, can anyone explain why?

$(\frac{x}{4}) - (x - \frac{5}{6}) = (1 + \frac{2(x-5)}{3})$

I did this : LCM $= 12$.
Then: $$3(x) - 2(x-5) = 4(1 + 2(x-5)$$
$$3x - 2x + 10 = 4(1 + 2x - 10)$$
$$3x - 2x + 10 = 4 + 8x - 40$$
$$-7x = -46$$
$$\frac{(-46)}{-7}$$

$$ \frac{x}{4} - \left(x - \frac{5}{6}\right) = 1 + \frac{2(x-5)}{3} $$
First add the $x/4$ and $-x$ on the LHS and distribute the $2/3$ on the RHS,
$$ \frac{-3}{4}x + \frac{5}{6} = 1 + \frac{2}{3}x - \frac{10}{3} $$
Move all the constants to the LHS and $x$'s to the RHS,
$$ \frac{5}{6}  - \frac{6}{6} + \frac{20}{6} = \frac{8}{12}x + \frac{9}{12}x$$
Simplify,
$$ \frac{19}{6} = \frac{17}{12} x $$
Multiply both sides by $\frac{12}{17}$,
$$ \frac{38}{17} = x $$
