Factoring out the expression I'm sorry, it must pretty basic, but...
How to factor out this expression $x^2 + 5x - 5 = 0$  ? 
(The method I normally use to factor expressions doesn't work there because when we factor expression above so that format will be $(ax + b)(qx + c)$ $b$ and $c$ definitely won't be integers, and method that I use only works when $b$ and $c$ are integers)

Since $x^2+5x-5$ is a monic polynomial whose roots are $\frac{1}{2} \left(-5+3\sqrt{5}\right)$ and $\frac{1}{2} \left(-5-3\sqrt{5}\right)$,$$x^2+5x-5=\left(x-\frac{1}{2} \left(-5+3\sqrt{5}\right)\right)\left(x-\frac{1}{2} \left(-5-3\sqrt{5}\right)\right).$$
