Sketching a graph using completing the square For the question $f(X) = X^2 + 4KX + (3+11K)$, where $K$ is a constant.
given that $K = 1$,
Sketch the graph $y=f(X)$, showing the coordinates of any point at which the graph crosses a coordinate axis.
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I get 
... $(x+2)^2 - 4^2 + (3 + 11)$ which is equivalent to $(x+2)^2 + 10$
and i get $(-2, 10)$ for the minimum coordinates, however i do not get how the $-2$ value was achieved for the first coordinate value.

The reason why we perform the completing square trick is to change the original to the form $y = (x+h)^2 + k$ so that we can deduce the minimum of y.
Since the squared term is always positive, the minimum value of it is 0. This occurs when x = -h. In your case, h = 2.
Answering part
Performing completing square, we have $y = x^2 + 4x + \4 - \4 +(3+11) = (x+2)^2 - 4 + (3+11)= (x+2)^2 + 10$. 
The -2 comes directly from setting $x + 2 = 0$. 
