Find table values of this $y=(x-4)(x-2)(x+1)(x+4)$ how to find this $$y=(x-4)(x-2)(x+1)(x+4)$$
I know that x - intercept is $$4,2,-1,-4$$
and y- intercept is $$32$$
In table values 
$$ x = -5,-3,-1,2,3$$
now What is the values of $y$ ?
Thanks in advance

Let the function be $f(x)$ for convenience.
Plug in each value:
$f(-5)=(-5-4)(-5-2)(-5+1)(-5+4)=(-9)(-7)(-4)(-1)=252$
$f(-3)=(-3-4)(-3-2)(-3+1)(-3+4)=(-7)(-5)(-2)(1)=-70$
$f(-1)=(-1-4)(-1-2)(-1+1)(-1+4)=(-5)(-3)(0)(3)=0$
$f(2)=(2-4)(2-2)(2+1)(2+4)=(-2)(0)(3)(6)=0$
$f(3)=(3-4)(3-2)(3+1)(3+4)=(-1)(1)(4)(7)=-28$
