Get variable value from Logarithm? I have below equation.
$$ x =  \left(\frac{1}{-2 \log_{10}\left(9 + \frac{46}{x}\right)}\right)^2 $$
I am not very familiar with Logarithm.
How can I grab value of $x$ from this equation?

For $x>0$ write the equation
$$x = \left(\frac{1}{-2 \log_{10}\left(9 + \frac{46}{x}\right)}\right)^2$$
as
$$\dfrac{1}{-2\sqrt{x}}=\log_{10}\left(9 + \frac{46}{x}\right)=\dfrac{1}{\ln10}\ln\left(9 + \frac{46}{x}\right)$$
or
$$\dfrac{\ln10}{-2\sqrt{x}}=\ln\left(9 + \frac{46}{x}\right)=\ln9+\ln\left(1 + \frac{46}{9x}\right)$$
An approximation could be find with the series
$$\ln(1+z)=z-\dfrac{1}{2}z^2+\dfrac{1}{3}z^3-\dfrac{1}{4}z^4+\dfrac{1}{5}z^5+\cdots$$
by getting some terms!
