Algebraic Fractions grade 7 I am a student and I am having difficulty with answering this question. I keep getting the answer wrong. Please may I have a step by step solution to this question so that I won't have difficulties with answering these type of questions in the future.
Write as a single fraction in its simplest Form. 
$$\frac{3}{2x+1}+\frac{8}{2x^2-7x-4}$$
I factorised both fractions:
$$\frac{3}{(2x+1)} \qquad \frac{8}{(2x+1)(x+4)}$$
And got rid of $(2x+1)$. I don't know what to do next.
Kind Regards

The standard approach as I understand it is:
$$\begin{align}
\frac{3}{2x+1}&+\frac{8}{2x^2-7x-4} \\
&=\frac{3}{2x+1}+\frac{8}{(2x+1)(x-4)} \tag{factorise denom.}\\
&= \frac{3(x-4)}{(2x+1)(x-4)}+\frac{8}{(2x+1)(x-4)} \tag{common denom.}\\
&= \frac{3(x-4)+8}{(2x+1)(x-4)} \tag{common frac.}\\
&= \frac{3x-12+8}{(2x+1)(x-4)} \tag{multiply out}\\
&= \frac{3x-4}{(2x+1)(x-4)} \tag{result}\\
\end{align}$$
