Solve for a and b? $a = \frac 1{20}(b^2 + 2b + 25)$ and $-a-1=-b$ Solve for a and b using two equations:
$$\begin{align} a & = \frac 1{20}(b^2 + 2b + 25)\\ \\ -a-1&=-b\end{align}$$
Thank you!

$-a - 1 = -b \iff a + 1 = b\iff a = b-1$. 
Now substitute $a$ into the first equation 
$$\begin{align} b-1  = \dfrac 1{20}(b^2 +2b + 25)  & \iff 20 b - 20  = b^2 + 2b + 25 \\ \\ &\iff b^2 -18b +45 = 0\end{align}$$
and solve for $b$.
Then back substitute to solve for $a$.
