Solve $\frac{4^{2x}+4^x+1}{2^{2x}+2^x+1}=13$ for $x$ 
Solve $$\frac{4^{2x}+4^x+1}{2^{2x}+2^x+1}=13$$ for $x$ 

Any help is appreciated. I'm entering a challenge and can't reach the solution.

Alternative approach: notice that
$$t^4+t^2+1 = (t^2+1)^2-t^2 = (t^2+t+1)(t^2-t+1)$$
so
$$\frac{t^4+t^2+1}{t^2+t+1} = t^2-t+1$$
so either
$$t^2+t+1=0$$
or
$$t^2-t+1=13$$
