Finding the values that $x$ can take $\left|\frac{-10}{x-3}\right|>\:5$ $$\left|\frac{-10}{x-3}\right|>\:5$$


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*Find the values that $x$ can take. 


I know that
$$\left|\frac{-10}{x-3}\right|>\:5$$
and
$$\left|\frac{-10}{x-3}\right|<\:-5$$

$$\left| \frac { -10 }{ x-3 }  \right| >\: 5\\ \frac { 10 }{ \left| x-3 \right|  } >5\\ \left| x-3 \right| <2\\ -2<x-3<2\\ 1<x<5\\ \left( 1;5 \right) -\left\{ 3 \right\} \\ \\ $$
