Rationalizing the denominator 3 It is a very difficult question. How can we Rationalizing the denominator?
$$\frac{2^{1/2}}{5+3*(4^{1/3})-7*(2^{1/3})}$$

$\frac1{A+B\sqrt[3]{n}+C\sqrt[3]{n^2}}=
\frac{ \begin{vmatrix}
1&\sqrt[3]n&\sqrt[3]{n^2}\\ 
B&A&Cn\\ 
C&B&A
\end{vmatrix} }{\begin{vmatrix}
A&Cn&Bn\\ 
B&A&Cn\\ 
C&B&A
\end{vmatrix}}=
\frac{A^2-BCn+(C^2n-AB)\sqrt[3]{n}+(B^2-AC)\sqrt[3]{n^2}}
{A^3+B^3n+C^3n^2-3ABCn}$  
