How do you solve for θ in the equation $\tan \frac{\theta}{5} + \sqrt{3} = 0$ $$\tan \frac{\theta}{5}  + \sqrt{3}   = 0$$
Alright so the $\frac{\theta}{5}$ is confusing me.
Would it be wrong to do 
\begin{eqnarray}
\tan \frac{\theta}{5}&=&-\sqrt{3}\\
\frac{\theta}{5}&=&\tan^{-1}(-\sqrt{3})\\
\theta&=& 5\tan^{-1}(-\sqrt{3})\\
\theta&=& -\frac{5\pi}{3} + 5\pi n
\end{eqnarray}

hint: Add $n\pi$ to your answer !
