Permutation question. $qpq^{-1}$, $q,p,r,s \in S_{8}$. Let $p,r,s,q \in S_{8}$ be the permutation given by the following products of cycles:
$$p=(1,4,3,8,2)(1,2)(1,5)$$
$$q=(1,2,3)(4,5,6,8)$$
$$r=(1,2,3,8,7,4,3)(5,6)$$
$$s=(1,3,4)(2,3,5,7)(1,8,4,6)$$
Compute $qpq^{-1}$ and $r^{-2}sr^{2}.$
thanks for your help. 
I want to write the following permutations like : 
$p=\begin{pmatrix}
1 & 2&3&4&5&6&7&8\\4&1&8&3&?&?&?&2\end{pmatrix}$
$q=\begin{pmatrix}
1 & 2&3&4&5&6&7&8\\2&3&1&5&6&8&7&4\end{pmatrix}$
$r=\begin{pmatrix}
1 & 2&3&4&5&6&7&8\\ 2&3&8&3&6&5&4&7\end{pmatrix}$
$s=\begin{pmatrix}
1 & 2&3&4&5&6&7&8\\ 3&?&4&1&?&?&?&?\end{pmatrix}$
can you help me plese to fill the $?$ mark. Is there another method to compute $qpq^{-1}$? 
thanks:) 

If you write all right then
$$
p= \begin{pmatrix}
1 & 2&3&4&5&6&7&8\\4&1&8&3&5&6&7&2
\end{pmatrix}
\begin{pmatrix}
1 & 2&3&4&5&6&7&8\\2&1&3&4&5&6&7&8
\end{pmatrix}
\begin{pmatrix}
1 & 2&3&4&5&6&7&8\\5&2&3&4&1&6&7&8
\end{pmatrix}
$$
and so on (sorry, I write badly the formula). So you have first to calculate $p,q,r,s$.
