Prove expression is not prime $$
(n + 4)^4 + 4
$$
If n is natural number, how to prove that above expression is not prime? 
I am stuck here
$$
(n+4)^2 \cdot (n+4)^2 + 2 . 2
$$
$$
\left(\left(n^2+4^2\right) \cdot 2\right)\left(\left(n^2+4^2\right) \cdot 2\right)
$$

Hint: $(x+4)^4+4=0$ has roots $x = -4 \pm \sqrt{\pm 2i}=-4 \pm (1 \pm i)\,$, so the expression factors as: $$(x+4)^4+4=(x^2 + 6 x + 10) (x^2 + 10 x + 26)$$
