Solve $\frac{5}{x+3}+\frac{2}{2x+6}=4$ I want to solve $\frac{5}{x+3}+\frac{2}{2x+6}=4$ for $x$
I try this;
$5(2x+6)+2(x+3)=4(x+3)(2x+6)$
$12x+36 = 4(2x^2+12x+18)$
$8x^2+36x+36=0$
Where I would then go to the formula, however the answer says -1.5, what am I doing wrong.

We have $5\over{x+3}$ + $2\over{2x+6}$ = 4.
This can be rewritten as $10\over{2x+6}$ + $2\over{2x+6}$ = 4.
Multiplying by 2x + 6 on each side, we get: 10 + 2 = 4(2x + 6)
Dividing by 4 on each side: 3 = 2x + 6
$\Rightarrow$ -3 = 2x $\Rightarrow$ x = $-3\over{2}$
