Find a permutation $X \in S_6$ which satisfies the equation $\begin{pmatrix}1&2&3&4&5&6\\ 4&3&1&5&2&6\end{pmatrix} \circ X = \begin{pmatrix}1&2&3&4&5&6\\ 3&2&4&5&1&6\end{pmatrix}$
I've tried this solution and checked this website, but none of them were helpful or my problem is little bit different and may require more steps to get the solution. Could anybody help me sort this out?

Hint:
$$X=\begin{pmatrix}1&2&3&4&5&6\\ 4&3&1&5&2&6\end{pmatrix}^{-1}\circ \begin{pmatrix}1&2&3&4&5&6\\ 3&2&4&5&1&6\end{pmatrix}.$$
