How to solve the cubic equation $x^3-12x+16=0$ Please help me for solving this equation $x^3-12x+16=0$

Hint: $x=2$ is a solution of the polynomial.
So $x^3-12x+16$ is divisible by $(x-2)$.
And $x^3-12x+16= (x-2)(x^2+2x-8)$.
The roots of $x^3-12x+16=0$ are $x=2$ and the roots of $x^2+2x-8=0$.
