Conversion to base $9$ Where am I going wrong in converting $397$ into a number with base $9$?
$397$ with base $10$ $$= 3 \cdot 10^2 + 9 \cdot 10^1 + 7 \cdot 10^0$$  To convert it into a number with base $9$ 
$$3 \cdot 9^2 + 9 \cdot 9^1 + 7 \cdot 9^0 = 243 + 81 + 7  = 331$$
But answer is $481$?????  

Here is a layout of the conversion algorithm (successive Euclidean divisions)
$$\begin{array}{ccrcrc*{10}{c}}
&&44&&4 \\
9&\Bigl)&397&\Bigl)&44&\Bigl)& \color{red}{\mathbf 4}\\
&&\underline{36}\phantom{7}&&\underline{36}\\
&&37&&\color{red}{\mathbf 8} \\
&&\underline{36} \\
&&\color{red}{\mathbf 1}
\end{array}$$
This is based on Horner's scheme:
\begin{align}
[397]_{10}&=9\cdot 44+ \color{red}1=9(9\cdot 4+\color{red}8)+\color{red}1=9^2\cdot\color{red}4+9\cdot\color{red}8+1\cdot \color{red}1.
\end{align}
