Finding $k$ such that $\frac{3x^2+kx-44}{x^2-121}$ simplifies to $\frac{3x-4}{x-11}$ 
If the rational expression $\frac{3x^2+kx-44}{x^2-121}$, where $k$ is an element of $\mathbb{W}$, simplifies to $\frac{3x-4}{x-11}$, then the value of $k$ must be?

my work:
$$\frac{3x^2+kx-44}{x^2-121}= \frac{3x-4}{x-11}$$
so the answer = value of $k$ is $11$.

Hint:
It simply means that $x+11$ divides the numerator, i.e. $-11$  is a root of the numerator, the other root being $4/3$.  Use Vieta's relations to determine $k$.
