Probability of getting 4 Aces What is the probability of drawing 4 aces from a standard deck of 52 cards. Is it:
$$
\frac{1}{52} \times \frac{1}{51} \times \frac{1}{50} \times \frac{1}{49} \times 4!
$$
or do I simply say it is:
$$
\frac{4}{52} = \frac{1}{13}
$$

The first answer you provided ($\frac{1}{52}\times \frac{1}{51}\times \frac{1}{50}\times \frac{1}{49}\times 4!$) is correct.
If we draw four cards from 52 cards, then the total possible outcomes are $C_4^{52} 4!$.
The number of outcomes that have four aces in a row is $4!$ 
Thus the probability of drawing 4 aces from a standard deck of 52 cards is 
$$
\frac{4!}{C_4^{52} 4!} = \frac{1}{C_4^{52}} = \frac{4!}{52\times  51\times  50\times  49}
$$
