Simplifying Square Roots Frustration Okay, I'm really frustrated with this.
So, when you have $3 \sqrt 5 + 5 \sqrt 5$,
you get $8\sqrt5$, right?
Okay, so what do I do for here:
$\sqrt{11} - 3 \sqrt{11}$
Is it just $-3  \sqrt{11}$ ?
What about for $6 \sqrt 2 + 4  \sqrt{50}$ ?
Do I multiply the $6 \sqrt{2}$ so that I can make what's inside of the square root equal to $50$?

Compare:
\begin{align}
  x - 3 x
  &= 1x - 3 x \\
  &= (1 - 3)x \\
  &= -2 x
\end{align}
to
\begin{align}
  \sqrt{11} - 3 \sqrt{11}
  &= 1\sqrt{11} - 3 \sqrt{11} \\
  &= (1 - 3)\sqrt{11} \\
  &= -2 \sqrt{11}
\end{align}
