Can someone show me HOW to do this, I don't just want the answer $4n$ to the power of $3$ over $2 = 8$ to the power of negative $1$ over $3$
Written Differently for Clarity:
$$(4n)^\frac{3}{2} = (8)^{-\frac{1}{3}}$$


EDIT
Actually, the problem should be solving $4n^{\frac{3}{2}} = 8^{-\frac{1}{3}}$.  Another user edited this question for clarity, but they edited it incorrectly to add parentheses around the right hand side, as can be seen above.


$${ \left( 4n \right)  }^{ \frac { 3 }{ 2 }  }={ \left( 8 \right)  }^{ -\frac { 1 }{ 3 }  }\\ \left( { \left( 4n \right)  }^{ \frac { 3 }{ 2 }  } \right) ^{ 2/3 }=\left( { \left( { 2 }^{ 3 } \right)  }^{ -\frac { 1 }{ 3 }  } \right) ^{ 2/3 }\\ 4n=2^{ -\frac { 2 }{ 3 }  }\\ n=\frac { 2^{ -\frac { 2 }{ 3 }  } }{ 4 } =\frac { 1 }{ 4\sqrt [ 3 ]{ 4 }  } $$
