Simplifying $\frac{\sqrt{3}}{2\sqrt{3}+1} + \frac{\sqrt{3}}{11}$ I realize that is a basic math problem, but I am still having problems with it. 
The expression $$\frac{\sqrt{3}}{2\sqrt{3}+1} + \frac{\sqrt{3}}{11}$$ equals one of the following:


*

*$2\sqrt{3}-1$

*$\dfrac{6}{11}$

*$4\sqrt{3}$

*$12$


How do I simplify this?

$$\begin{align}\frac{\sqrt3}{2\sqrt3+1}+\frac{\sqrt3}{11}&=\frac{\sqrt3(2\sqrt3-1)}{(2\sqrt3+1)(2\sqrt3-1)}+\frac{\sqrt3}{11}\\&=\frac{6-\sqrt3}{11}+\frac{\sqrt3}{11}\\&=\frac{6}{11}\end{align}$$
