Antiderivative of $\sqrt{(x^2-a^2)(x^2-b^2)(x^2-c^2)}$ Is it possible to explicitly find the antiderivative of $\sqrt{(x^2-a^2)(x^2-b^2)(x^2-c^2)}$? It is rather straight-forward to find it when $a=0$, or $b=0$ or $c=0$. This is also easy in the case where $a=b$, or $b=c$, or $a=c$. But I have been struggling to do this in the general case. Any help is appreciated. Thanks!

Hint:
$\sqrt{(x^2-a^2)(x^2-b^2)(x^2-c^2)}=\sqrt{(x+a)(x-a)(x+b)(x-b)(x+c)(x-c)}$
consult with Lauricella function
