How to integrate $\frac{4x+4}{x^4+x^3+2x^2}$? Please could anyone help me to integrate
$\quad\displaystyle{4x + 4 \over x^4 + x^3 + 2x^2}.\quad$
I know how to use partial fraction and I did this: 
$$
x^{4} + x^{3} + 2x^{2} = x^{2}\left(x^{2} + x + 2\right)
$$
And then ?.$\quad$ Thanks all.

Hint:
$$
\begin{align}
\frac{4x+4}{x^4+x^3+2x}
&=\frac{4x+4}{x^2(x^2+x+2)}\\
&=\frac1x+\frac2{x^2}-\frac{x+1/2}{x^2+x+2}-\frac{5/2}{x^2+x+2}
\end{align}
$$
