Algebraic Fractions grade 7 I am a student and I am having difficulty with answering this question. I keep getting the answer wrong. Please may I have a step by step solution to this question so that I won't have difficulties with answering these type of questions in the future.
Write as a single fraction in its simplest Form. 
$$\frac{3}{2x+1}+\frac{8}{2x^2-7x-4}$$
I factorised both fractions:
$$\frac{3}{(2x+1)} \qquad \frac{8}{(2x+1)(x+4)}$$
And got rid of $(2x+1)$. I don't know what to do next.
Kind Regards

Getting $\frac{1}{2x+1}$ common, we have
$\frac{1}{2x+1} \left[3 + \frac{8}{x-4} \right]$
$\frac{1}{2x+1} \left[\frac{3(x-4) + 8}{x-4}\right]$
$\frac{1}{2x+1} \left[\frac{3x - 12 + 8}{x-4}\right]$
$\frac{1}{2x+1} . \frac{3x - 4}{x-4}$
