Sum of square patterns Can anyone give the name of this pattern
$$136^2+137^2+138^2+139^2+140^2+141^2+142^2+143^2+144^2 =\\ 
145^2+146^2+147^2+148^2+149^2+150^2+151^2+152^2$$

If we consider the equation of a certain type.
$$(n-4)^2+(n-3)^2+(n-2)^2+(n-1)^2+n^2+(n+1)^2+(n+2)^2+(n+3)^2+$$
$$+(n+4)^2=(k-3)^2+(k-2)^2+(k-1)^2+k^2+$$
$$+(k+1)^2+(k+2)^2+(k+3)^2+(k+4)^2$$
The solutions can be written simply using the sequence.  The next element which is obtained from the previous one.
$$p_2=3p_1+4s_1$$
$$s_2=2p_1+3s_1$$
If we use the first element of the sequence.  $( p ; s) - (2 ; 1)$
Then the formula will look like.
$$n=2p^2\pm6ps+4s^2$$
$$k=2p^2\pm6ps+5s^2$$
If we use the first element of the sequence.  $(p ; s ) - ( 3 ; 2 )$
Then the formula will look like.
$$n=2(2p^2\pm6ps+4s^2)$$
$$k=2(2p^2\pm6ps+5s^2)$$
