How to use the Law of Sines to Find an Angle I am trying to figure out how to find an angle with the law of sines. 
I have a triangle where:
A = $120^\circ$
B = unmarked
C = $\theta$
a = 45
b = unmarked
c = 36
How can I find the angle for C?
I have tried:
$$\frac{sin120^\circ}{45} = \frac{sinB}{b} =\frac{sin\theta}{36} $$
$$36(\frac{sin\theta}{36}) = 36(\frac{sin120^\circ}{45})$$
$$sin\theta = \frac{36sin120^\circ}{45}$$
$$ \theta = \frac{36(120^\circ)}{45} = 95^\circ$$
But, the answer is supposed to be $44^\circ$.

The following step is completely wrong 
$$\sin\theta = \frac{36 \sin120^\circ}{45} \iff \color{red}{\theta = \frac{36(120^\circ)}{45} = 95^\circ}$$
we have that $\sin120^\circ=\sqrt 3/2$ and then
$$\sin\theta = \frac{36\sin120^\circ}{45} \iff \sin \theta = \frac{36\sqrt 3}{2\cdot 45} \iff \theta = \arcsin \left(\frac{2\sqrt 3}{9}\right)$$
