Evaluating $\sum_{n = 1}^{\infty} \frac{2}{2^{n}}$ 
Evaluate $$\sum_{n = 1}^{\infty} \frac{2}{2^{n}}$$

This is a geometric series and since $a = \dfrac{1}{2}$ Then the infinite sum is jsut $S = \dfrac{1}{1-\frac{1}{2}} = 2$ Then I multiply by $2$ to get $4$ right? But the actual answer should just be $2$. Am I missing something?

$$\sum\limits_{n = 1}^\infty  {\frac{2}{{{2^n}}}}  = 2\sum\limits_{n = 1}^\infty  {{{\left( {\frac{1}
{2}} \right)}^n}}  = 2.\frac{{1/2}}
{{1 - 1/2}} = 2.1 = 2$$
