Real Solutions of the expression $\sqrt[2]{x+3-4\sqrt[2]{x-1}}+\sqrt[2]{x+8-6\sqrt[2]{x-1}}-1=0$ I recently stumbled across the following question:

Find all the real solutions $x$ of the expression $\sqrt[2]{x+3-4\sqrt[2]{x-1}}+\sqrt[2]{x+8-6\sqrt[2]{x-1}}-1=0$

It was given by one of my teachers (he was teaching us a few problems involving real and rational numbers).
Although I used a few typical algebraic manipulations (such as shifting terms from LHS to RHS and squaring both sides) all of them repeatedly led me towards wrong results. When I plugged the expression $\sqrt[2]{x+3-4\sqrt[2]{x-1}}+\sqrt[2]{x+8-6\sqrt[2]{x-1}}-1$ into Desmos, I came to see that all real numbers from 5 to 10 gave the value of zero when plugged into the expression. Could anyone show (through algebraic manipulations) why this is the case?

$\sqrt[2]{x+3-4\sqrt[2]{x-1}}+\sqrt[2]{x+8-6\sqrt[2]{x-1}}=1$
Let $x=1+t^2$, then we re-write the eq. as
$$\sqrt{(t-2)^2}+\sqrt{(t-3)^2}=1$$
$$\implies |t-2|+|t-3|=1$$
When $2\le t \le 3$. then the equation becomes
$$ (t-2)+(3-t)=1\implies 1=1$$
So all roots are $2\le  t\le 3$ \implies $5 \le x \le 10.$
Hence this equation has all numbers in $[5,10]$ as infinitely many roots.
Similarly one can check no roots in $(-\infty,5)$ and no root in $(10,\infty)$.
