square root of $\frac{2+\sqrt{3}}{4}$ 
Find the square root of $\frac{2+\sqrt{3}}{4}$.

Attempt:
I'm thinking of equating it to $a + bi$. And then finding the root. Is that right?

To add to the other answers, notice that:
$$\frac{\sqrt{2 + \sqrt{3}}}{2} = \frac{\sqrt{3} + 1}{2\sqrt{2}} = \frac{\sqrt{6} + \sqrt{2}}{4},$$
where I've used zezanjee's hint
$$2 + \sqrt{3} = \frac{(\sqrt{3} + 1)^2}{2}$$
in the comments.
