Find the derivative respect to $x$? Question
$\sqrt{2x+1}$ 
$=\sqrt{2x+1}$ 
$=\sqrt{2x} + \sqrt{1}$ 
$=\dfrac{1}{2x^{1/2}}$
however the right answer is $\dfrac{1}{\sqrt{2x+1}}$
Can you please help me out? 
this chapter name is (differentiationg rational power
$x^{p/q}$)

$\sqrt{2x+1} \neq \sqrt{2x}+\sqrt{1}$: Witness $3 = \sqrt{9} = \sqrt{2 \cdot 4 + 1} \neq \sqrt{2 \cdot 4} + \sqrt{1} = 2 \sqrt{2} + 1$.
The right way to solve this is to apply the chain rule.
