Solve $\sqrt{3}^n=3^3$ I got answer but i could not understand, can anyone explain me ?
$\sqrt{3}^n=3^3$
$\implies{3}^{n/2}=3^3$
$\implies \frac{n}{2}=3\implies n=6$
How we get ${3}^{n/2}$ in the second line and how we get $\frac{n}{2}$ in third line.

$ {\sqrt{3}}^{n} = 3^3$
$\Rightarrow$ $({\sqrt{3}}) ^{n} = 3^3$
$\Rightarrow$ $({3}^{1/2}) ^{n} = 3^3$
$\Rightarrow$ $({3}) ^{{(1/2)}.{n}} = 3^3$
$\Rightarrow$ $({3}) ^{n/2} = 3^3$
$\Rightarrow$ $n/2 = 3$
$\Rightarrow$ $n = 6$
