Simplifying some square numbers expressions I need help to fix theese out. Thank you.
$ \frac { \frac {1} {\sqrt {3} } - \sqrt {12} } { \sqrt {3} } $

$ \frac { \sqrt {x} } {\sqrt[3] {3} } + \frac {\sqrt[4] {x}} {\sqrt {x} } $

$ \sqrt {5} - \sqrt {3} = n \Rightarrow \sqrt {5} + \sqrt {3} = ? $ 

$$ \frac { \frac {1} {\sqrt {3} } - \sqrt {12} } { \sqrt {3} } = \frac { -\frac{5}{\sqrt{3}} } { \sqrt {3} } = \frac { -5 } { \sqrt{3}\sqrt {3} } = \frac { -5 } { (\sqrt{3})^2 } =  \frac { -5 } { 3 } = -\frac { 5 } { 3 }  $$

$$ \frac { \sqrt {x} } {\sqrt[3] {3} } + \frac {\sqrt[4] {x}} {\sqrt {x} } =$$
$$ \frac { \sqrt {x} } {\sqrt[3] {3} } + x^{\frac{1}{4}-\frac{1}{2}} =$$
$$ \frac { \sqrt {x} } {\sqrt[3] {3} } + x^{-\frac{1}{4}} =$$
$$ \frac { \sqrt {x} } {\sqrt[3] {3} } + \frac{1}{\sqrt[4]{x}}$$

$$ \sqrt {5} - \sqrt {3} = n \Longleftrightarrow$$ 
$$\left(\sqrt{5}-\sqrt{3}\right)\cdot \left(\sqrt{5}+\sqrt{3}\right)= n\cdot \left(\sqrt{5}+\sqrt{3}\right)\Longleftrightarrow$$
$$\sqrt{5}+\sqrt{3} = \frac{2}{n}$$
