Finding values of $t$ I have this equation - 
$3t^{\frac{1}{2}} - \frac{2}{5} t^{\frac{-3}{2}} = 0 $ 
I'm struggling on how to find the values of $t$ 
First, I power both sides by $2$ to make the power be a whole number . 
I get 
$3t - \frac{2}{5} t^{-3} = 0 $ 
From here I'm stunned and stuck . Can I get a hint ! Thanks ! 

The equation
$$
3t^{\frac{1}{2}} - \frac{2}{5} t^{\frac{-3}{2}} = 0
$$
is equivalent to
$$
t^{\frac{1}{2}} = \frac{2}{15} t^{\frac{-3}{2}} \;.
$$
Since $t$ cannot be zero$\color{green}{^*}$, you are allowed to multiply both sides by $t^{\frac{3}{2}}$:
$$
t^{2} = \frac{2}{15} \;.
$$
So, the solution is
$$
t = \pm\sqrt{\frac{2}{15}} \;.
$$
$\small\color{green}{^*\text{: If $t$ were zero, we would have $0^{\frac{-3}{2}} = \dfrac{1}{0}$.}}$
