A tricky math problem about the difference of 2 squares Jose is given two 2-digit numbers AB and CD where (A, B, C,
and D represent unique digits) and is told to find the
difference between the squares of these numbers.
However, Jose has dyslexia and reverses the digits of each
number before finding the difference between the squares.
Miraculously, Jose gets the correct answer nonetheless.
Find the answer Jose obtained.

Hint: AB is a number that can be expressed as 10A + B.


Even if $A,B,C,D$ must be distinct and non-zero, I seem to have four sets of solutions (or perhaps two pairs of sets) to $A^2-B^2=C^2-D^2$, such as 
$$8^2-7^2 = 15 =4^2-1^2 \text{ so } 87^2-41^2 = 5888 = 78^2-14^2$$ 
$$8^2-4^2 = 48 = 7^2-1^2 \text{ so }84^2-71^2 = 2015 = 48^2-17^2$$
$$9^2-7^2 = 32 =6^2-2^2 \text{ so }97^2-62^2 = 5565 = 79^2-26^2$$
$$9^2-6^2 = 45 =7^2-2^2 \text{ so } 96^2-72^2 = 4032 = 69^2-27^2$$ 
