Resolving a Limit I'm studying for college exams and I don't know how to solve this type of limit:
$$\begin{align}
\lim_{x\to -3} \sqrt{\frac{x^2-9}{2x^2+7x+3}}
\end{align}$$
Any help?
Update: I know that the solution is:
$$\begin{align}
\frac{1}{5} \sqrt{30}
\end{align}$$

If a polynomial has $-3$ as a root, then $x+3$ can always be factored out:
$$\lim_{x\to-3}\sqrt{\frac{x^2-9}{2x^2+7x+3}}=\lim_{x\to-3}\sqrt{\frac{(x+3)(x-3)}{(x+3)(2 x+1)}}=\lim_{x\to-3}\sqrt{\frac{x-3}{2x+1}}=\sqrt\frac{-6}{-5}=\sqrt\frac65$$
