Line $11x+3y-48 = 0$ tangent a graph $f(x) = \frac{4x + 3}{3x - 6}$ at $(a,b)$ Line $11x+3y-48 = 0$ tangent a graph $f(x) = \frac{4x + 3}{3x - 6}$ at (a,b) when $a<b$
$a-b = ...$
Find gradient of the line, df(x) / dx
$\frac{(4x+3)3 - (3x-6)(4)} {(3x-6)^2}$
Which the same as $ -11/3$
$(12x+9 - 12x + 24 ) 3= -11(3x-6)^2$
If i solve x, literally i solve $a $ right?
Is there less complicated way to solve it?

The equation $$-\frac{11}{3}x+16=\frac{4x+3}{3x-6}$$ must have only on e solution.
Compute the discriminant! It is $x=3$
