Integral of a rational expression involving quadratics. I want to solve this integral but I have some problems...

$$\int_2^3 \frac{(x^2-2x+1)}{(x^2+2x+1)}$$

I transformed both in $(x-1)^2$ and $(x+1)^2$ respectively but didn't find any answer. I tried as well to transform the rational expression into $1 -\frac{4x}{(x^2+2x+1)}$, but I wasn't capable of finding any antiderivative.
Thanks for responding!

$$ \frac{x^2-2x+1}{x^2+2x+1}=1-\frac {4x+4-4}{(x+1)^2}=1-4\frac {x+1}{(x+1)^2}+\frac 4{(x+1)^2}$$
