Complex number fraction Find the real and imaginary number:
$$\frac{1}{z}=\frac{2}{2+j3}+\frac{1}{3-j2}$$
How do I invert $\frac{1}{z}$ to $z$ so that I can start solving it?

The denominators of the right hand side are closely related.

We obtain
  \begin{align*}
\frac{1}{z}&=\frac{2}{2+j3}+\frac{1}{3-j2}=\frac{2}{2+j3}+\frac{j}{2+j3}
\end{align*}
  It follows
  \begin{align*}
z=\frac{2+j3}{2+j}=\frac{1}{5}(2+j3)(2-j)=\frac{1}{5}(7+j4)
\end{align*}

