integral ordered pair $(x,y)$ in $x^2+y^2=2x+2y+xy$ 
Find all possible integral ordered pair $(x,y)$ in $x^2+y^2=2x+2y+xy$

what i try $y^2-(x+2)y+x^2-2x=0$
$$y=\frac{x+2\pm\sqrt{(x+2)^2-4(x^2-2x)}}{2}$$
$$y=\frac{x+2\pm \sqrt{-3x^2+12x+4}}{2}$$
How do i solve it Help me please 

Hint:
If $x\le-1$ or $x\ge5$ then $-3x^2+12+4<0$, so its square root is not real;
that limits the possibilities to a few you could check.
