What is the general solution to $2 \cos^2 x-\cos x=0$? What is the general solution to this trig equation?
$$2 \cos^2 x-\cos x=0$$
Thanks.

$2\cos^2 x-\cos x=0$
$\implies \cos x(2\cos x-1)=0$
Either
$\cos x=0$
$\implies x=\dfrac{\pi}{2}\pm 2n\pi$
Or
$2\cos x-1=0$
$\implies \cos x=\dfrac{1}{2}$
$\implies x=\dfrac{\pi}{3}\pm 2n\pi$
where
 $n \in Z$
