Approximate Trigonometric Integral Let the function $I(x)$ be defined as
$$I(x) = \int_{-\pi/2}^{\pi/2}{\rm d} \theta \ \frac{\cos^2{\theta}}{\sqrt{\cos^2\theta+x^2\sin^2\theta}} \ , $$
Then we have for instance $I(0)=2$. Is there a nice answer for $I(x)$ for $x$ small? The most obvious thing to do would be to binomially expand
$$I(x) \approx \int_{-\pi/2}^{\pi/2}{\rm d} \theta \ \left( \cos \theta - \frac{x^2}{2}\frac{\sin^2\theta}{\cos\theta}\right) \ , $$
but this doesn't seem promising since the $\cos \theta$ in the denominator of the second term renders it no longer small near $\pm \pi/2$. For what it's worth, Mathematica gives an answer in terms of elliptic functions for $I(x)$ so I'm expecting $I(x)$ to  be smooth enough that some approximation should exist.

There is something interesting : starting from the result given by Wofram Alpha
$$I(x)=\frac{2 \left(x^2 K\left(1-x^2\right)-E\left(1-x^2\right)\right)}{x^2-1}$$  Expanding  as a series around $x=0$
$$I(x)=2 +\sum_{n=1}^\infty \Big[a_n-b_n \log(2)+c_n \log(x^2)\Big]\, x^{2n}$$ and the coefficients are
$$\left(
\begin{array}{cccc}
 n & a_n & b_n & c_n \\
 1 & \frac{3}{2} & 2 & \frac{1}{2} \\
 2 & \frac{51}{32} & \frac{9}{4} & \frac{9}{16} \\
 3 & \frac{105}{64} & \frac{75}{32} & \frac{75}{128} \\
 4 & \frac{40985}{24576} & \frac{1225}{512} & \frac{1225}{2048} \\
 5 & \frac{110439}{65536} & \frac{19845}{8192} & \frac{19845}{32768} \\
 6 & \frac{2224761}{1310720} & \frac{160083}{65536} & \frac{160083}{262144}
\end{array}
\right)$$ where interesting patterns seem to appear.
Using the terms in the table, there is a good fit for $0 \leq x \leq \frac 34$ (the maximum error being $0.014$ at the right bound; it is only $6.92 \times 10^{-5}$ for $x=\frac 12$.
