Find the function and domain for $ (f\circ f)$ when $ f(x) = x+ \frac {1} {x} \ $ Find the function and domain for $ (f\circ f)$ 
My answer is $ \frac {x^4+3x^2+1x} {(x^2+1)(x)}?$
However, the program I am using states I am wrong. What have I done incorrectly? 

$$\ (f\circ f)=x+\frac{1}{x}+\frac{1}{x+\frac{1}{x}}=\frac{x^2+1}{x}+\frac{x}{x^2+1}=\frac{x^4+x^2+x^2+1+x^2}{x(x^2+1)}=\frac{x^4+3x^2+1}{x(x^2+1)}$$
The domain is right, it's $\ x≠0$, but in the numerator you have 1 and not $\ 1x$
