How i get the $x$ of the equation I have this:
$\frac{32}{20 - \frac{16}{5-\frac{5}{x}}}$ = 1
My main problem is that I want to multiply by something on both sides.
I will move $(5-\frac{5}{x})$ to side of 1, then:
$\frac{32}{20-16} = 1(5-\frac{5}{x}$)
$8 = 5 -\frac{5}{x}$ , now multiply by $x$
$8x = 5x - 5 $
$3x = 5$
$x = 5/3$
But according to symbolab it's $x = 15/19$, could you help me what I'm wrong about? I have done a lot of exercises, but I have a hard time clearing the $ x $ when it is very low.

This step is uncorrect
$$\frac{32}{20 - \frac{16}{5-\frac{5}{x}}}=1\implies \color{red}{\frac{32}{20-16} = 1(5-\frac{5}{x})}$$
following this way it should be indeed (for $x\neq 1$)
$$\frac{32}{20 - \frac{16}{5-\frac{5}{x}}}=1\implies \frac{1}{(5-\frac{5}{x})}\cdot\frac{32}{20 - \frac{16}{5-\frac{5}{x}}}=\frac{1}{(5-\frac{5}{x})}\cdot 1\implies \frac{32}{20(5-\frac{5}{x})-16} = \frac{1}{(5-\frac{5}{x})}$$
and then
$$\implies 32(5-\frac{5}{x})={20(5-\frac{5}{x})-16}\\\implies160x-160=100x-100 -16x\implies76x=60\implies x=\frac{15}{19}$$
