Solving $\sqrt{x^2 +2x + 1}-\sqrt{x^2-4x+4}=3$ My question is: Solve  $\sqrt{x^2 +2x + 1}-\sqrt{x^2-4x+4}=3$
I deduced that:$LHS= x+1-(x-2)$
I am unable to solve this equation.  I would like to get some hints to solve it.

$$\sqrt {x^2 +2x + 1}-\sqrt { x^2-4x+4}= \sqrt{(x+1)^2} - \sqrt{(x-2)^2}=|x+1|-|x-2|$$
You have to consider three cases:


*

*$x \geq 2$

*$-1<x<2$

*$x \leq -1$

