Solve $\frac{5}{x+3}+\frac{2}{2x+6}=4$ I want to solve $\frac{5}{x+3}+\frac{2}{2x+6}=4$ for $x$
I try this;
$5(2x+6)+2(x+3)=4(x+3)(2x+6)$
$12x+36 = 4(2x^2+12x+18)$
$8x^2+36x+36=0$
Where I would then go to the formula, however the answer says -1.5, what am I doing wrong.

$\frac{5}{x+3}$+$\frac{2}{2(x+3)}$=4
$\frac{(5*2+2)}{2(x+3)}$=4
12=8(x+3)
x=$\frac{-12}{8}$
x=$\frac{-3}{2}$
