What is area of circle given areas of $4$ squares 
I can't find a way to solve this, I know that by using power of the point the other square area is 64cm^2 and that its side length is 8, but for the area of the circle I'm not too sure where to start, can someone help?


The area of the triangle $ABC$ is 
$$Area_{ABC} = \frac 12 BX\cdot AC = \frac12 \cdot 5\cdot (4+10) = 35$$
Then, the circumradius of $ABC$ is,
$$R = \frac{AB\cdot BC\cdot CA}{4Area_{ABC}}
=\frac{\sqrt{4^2+5^2}\cdot \sqrt{10^2+5^2}\cdot 14}{4\cdot35}
=\frac{\sqrt{205}}{2}$$
Thus, the area of the circle is
$$Area_{circle} = \pi R^2= \frac{205\pi}4$$
