If $f(x) = -3x^3 + 2x^2$, find $f(-1)$ and $f(1/2)$. I hope you can help me out
For number 8 and 9 find each value if $f(x) = -3x^3 + 2x^2$
8) $f(-1)$ 
9) $f(1/2)$

For x=-1 we write $f(-1)=-3*(-1)^3+2*(-1)^2=3+2=5$
For x=1/2 we write $f\left(\frac{1}{2}\right)=-3\left(\frac{1}{2}\right)^3+2\left(\frac{1}{2}\right)^2=\frac{1}{8}$ 
