Find solution set $\sqrt{x-5} + 5 =0$ Find solution set :
$\sqrt{x-5} + 5 =0$
Is there a solution to a set of complex numbers ?

No.  There is no solution because $\sqrt{}$ is by definition non-negative.
However $\pm\sqrt{x-5} + 5 = 0$ does have a solution.
$\pm\sqrt{x-5} + 5 = 0$
$\pm\sqrt{x-5} = -5$
$(\pm\sqrt{x-5})^2 = (-5)^2$
$x-5 = 25$
$x = 30$.
But seriously.  You are NOT allowed to say $\sqrt{x-5} = -5$.  You just can't.  It's against the rules.
