Is it possible to find the sum of all integer values that $x$ can take? Is it possible to find the sum of all integer values that $x$ can take? In:
$$\sqrt{x+3-4\sqrt{x-1}}+\sqrt{x+8-6\sqrt{x-1}}=1$$

hint: $x+3-4\sqrt{x-1}=(\sqrt{x-1}-2)^2, x+8-6\sqrt{x-1}=(\sqrt{x-1}-3)^2$
