$\left(\sqrt{8}+\sqrt{2}\right)^2$ = 18 why?? I would like to now why 
$$\left(\sqrt{8}+\sqrt{2}\right)^2$$
is equal to $18$? Please provide me
the proccess. Thank you.

It does look counter-intuitive, doesn't it? But if you step through the multiplication, I think it will become crystal clear to you. First of all, $$(\sqrt{8} + \sqrt{2})^2 = (\sqrt{8} + \sqrt{2})(\sqrt{8} + \sqrt{2})$$, right? Applying FOIL (First, Outer, Inner, Last), we get $$\sqrt{8} \sqrt{8} = 8$$ $$\sqrt{8} \sqrt{2} = 4$$ $$\sqrt{2} \sqrt{8} = 4$$ $$\sqrt{2} \sqrt{2} = 2$$ And then $8 + 4 + 4 + 2 = 18$.
