Evaluate the values of $x$ in $\sqrt{2x-5} = \sqrt[3]{6x-15}$ 
$$\sqrt{2x-5} = \sqrt[3]{6x-15}$$
  
  
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*Evaluate the values of $x$

I believe that there would be an easier approach to this problem because I will have to expand 3th degree binomial as shown below
$$(2x-5)^3 = (6x-15)^2$$
What am I missing?
Regards

$$(2x-5)^3 = (6x-15)^2$$
$$(2x-5)^3 = (3(2x-5))^2$$
$$(2x-5)^3 = 9(2x-5)^2$$
This may help :)
Then: $(2x-5)=0\lor (2x-5)=9$
Thus: $x=2\frac{1}{2}\lor x=7$
