Find the indicated derivative Find the indicated derivative
$\frac {d}{dt}$ $\frac {(6t-5)^6}{t+9}$ 
I'm stuck after getting to this part
$\frac {(6t-5)^6-36(6t-5)^5(t+9)}{(t+9)^2}$
How do they get to the answer
$\frac {(6t-5)^5(30t+329)}{(t+9)^2}$

Can also use product and chain rules: $$6(6t-5)^5\cdot 6\cdot (t+9)^{-1}+(6t-5)^6\cdot -1\cdot (t+9)^{-2}\cdot 1$$
$$\frac{(t+9)\cdot 36\cdot (6t-5)^5}{t+9} -\frac{(6t-5)^6}{(t+9)^2}$$ 
$$\frac{(6t-5)^5[(36t+324)-(6t-5)]}{(t+9)^2}$$
$$\frac{(6t-5)^5(30t+329)}{(t+9)^2}$$
