factorise the expression $x^3 - 3x^2 -4x + 12$ 
Factorize the expression $$x^3-3x^2-4x+12$$ Hence calculate the ranges of values of $x$ for which $x^3-3x^2>4x-12$.

I factorised it to obtain $(x-2)(x-3)(x+2)$ but I don't how how to get to the next step.

$$
{x}^{3}-3\,{x}^{2}-4\,x+12={x}^{3}-4\,x-3\,{x}^{2}+12=x(x^2-4)-(3x^2-12)=
$$
$$
=x(x^2-4)-3(x^2-4)=(x-3)(x^2-4)=(x-3)(x-2)(x+2).
$$
