How to find Ratio And proportion If $\frac{4x+3y}{4x-3y}=\frac{7}{5}$.Find the Value of the $\frac{2x^2-11y^2}{2x^2+11y^2}$.
Okay I just want hint how to solve this problem.

In your first equation $\frac{4x+3y}{4x-3y}=\frac{7}{5}$, try solving x in terms of y or vice versa. 
Then you will find that $x=\frac{9}{2}y$ or $y=\frac{2}{9}x$,
so now substitute one of these to $\frac{2x^2-11y^2}{2x^2+11y^2}$
if you choose $x=\frac{9}{2}y$ you'll have,
$$\frac{2x^2-11y^2}{2x^2+11y^2}=\frac{\frac{81}{2}y^2-11y^2}{\frac{81}{2}y^2+11y^2}$$
cancelled all y^2, finally you have $\frac{81-22}{81+22}=\frac{59}{103}$
also if you choose $y=\frac{2}{9}x$, same process and you'll have $\frac{59}{103}$ as an answer.
