Compute $(1 - \omega + \omega^2)(1 + \omega - \omega^2)$ where $\omega^3 = 1$ If $\omega^3 = 1$ and $\omega \neq 1$, then compute $(1 - \omega + \omega^2)(1 + \omega - \omega^2)$
I'm pretty lost, I don't really know where to start.
Thanks

$$(1 - \omega + \omega^2)(1 + \omega - \omega^2)$$
$$=((1 + \omega^2) - \omega)(1 + \omega - \omega^2)$$
$$=(-\omega - \omega)(-\omega^2 - \omega^2)$$
$$=(-2\omega)(-2\omega^2)$$
$$=4\omega^3=4$$
Where $1+\omega+\omega^2=0$ and $\omega^3=1$
