Evaluating an expression given values of symmetric polynomials Evaluate $\dfrac x{yz} + \dfrac y {xz} + \dfrac z y$
Given, $z+y+x=4, \qquad xyz=-60, \qquad xy+xz+yz=-17$
How do we do this? I found a common denominator, and substituted it for $-60$, but I am unaware of how to proceed. 
Someone already asked the question but there is no useful answer. These are the possible answers:
A.   $4/17$
B.   $−5/6$
C.   $17/60$
D.   $−33/60$
E.   $33/60$

Assuming there is a typo.
We have to find -
\begin{align}
& \frac{x}{yz} + \frac{y}{xz} + \frac{z}{xy} \\[10pt]
= {} & \frac{x^2 + y^2 + z^2}{xyz} \tag 1
\end{align}
Also $x + y + z = 4$.
Squaring both sides,
$$x^2 + y^2 + z^2 + 2(xy + yz + zx) = 16$$
$$x^2 + y^2 + z^2 + 2(-17) = 16$$
$$x^2 + y^2 + z^2 = 16 + 34$$
$$x^2 + y^2 + z^2 = 50$$
Put this in equation $(1)$
$$= \frac{50}{-60}$$
$$= \frac{-5}6$$
