Calculate $ \lim_{x \to 4} \frac{3 -\sqrt{5 -x}}{1 -\sqrt{5 -x}} $ How evaluate the following limit?
$$ \lim_{x \to 4} \frac{3 -\sqrt{5 -x}}{1 -\sqrt{5 -x}} $$
I cannot apply L'Hopital because $ f(x) =  3 -\sqrt{5 -x} \neq 0 $ at $x = 5$

I think the problem is $$\lim_{x\to4}\frac{3-\sqrt{5+x}}{1-\sqrt{5-x}}$$
HINT:
$$\frac{3-\sqrt{5+x}}{1-\sqrt{5-x}}=\frac{3^2-(5+x)}{1^2-(5-x)}\cdot\frac{1+\sqrt{5-x}}{3+\sqrt{5+x}}=-\frac{1+\sqrt{5-x}}{3+\sqrt{5+x}}$$ if $x\ne4$
Now here $x\to4\implies x\ne4$
