Calculate the derivative using limit definition. This is the function $f(x)$$=\frac{1}{\sqrt{3x-2}}$ .
I wrote that $$\lim_{h\to 0}\frac{\frac{\sqrt{3x+3h-2}}{3x+3h-2}-\frac{\sqrt{3x-2}}{3x-2}}{h}.$$
I am not able to continue further.

HINT:
Note that 
$$\begin{align}
\frac{1}{\sqrt{3(x+h)-2}}-\frac{1}{\sqrt{3x-2}}&=\frac{\frac{1}{3(x+h)-2}-\frac{1}{3x-2}}{\frac{1}{\sqrt{3(x+h)-2}}+\frac{1}{\sqrt{3x-2}}}\\\\
&=\frac{\frac{-3h}{(3(x+h)-2)(3x-2)}}{\frac{1}{\sqrt{3(x+h)-2}}+\frac{1}{\sqrt{3x-2}}}
\end{align}$$
Divide by $h$ and let $h\to 0$.
