Solving basic system of equations $x, y$ are positive reals such that $y\sqrt{x^2 - y^2} = 48$ and $x + y + \sqrt{x^2 - y^2} = 24$. How to find $x$ and $y$? Squaring equations leads to complicated equations with polynomials of high degrees. Is there any way to omit it and solve it smarter?

Call $x^2-y^2=z^2 \quad (1)$ then:
$yz=48 \quad(2)$ and $x+y+z=24 \quad(3)$
From $(1)$ we have:
$$x^2=y^2+z^2=(y+z)^2-2yz$$
and using $(2)$ and $(3)$ we get:
$$x^2=(24-x)^2-2.48 \Rightarrow x=10$$
and then $y=8$ or $y=6$
