Solve for $x: 2/\sqrt{2-x^2} = 4- 2x^2?$ How do you expand and solve for $x$?
It is $2 = 4\sqrt{2-x^2} - 2x^2\sqrt{2-x^2}$
Thank you!
How would I solve for x?

\begin{align*}
\frac{2}{\sqrt{2-x^2}} &= 4 - 2x^2\\
2 &= 2(2-x^2)^{3/2}\\
1 &= (2-x^2)^{3/2}\\
1 &= 2-x^2\\
1 &= x^2\\
\pm1 &= x
\end{align*}
