If $3(4^h)=4(2^k)$ and $9(8^h)=20(4^k)$,show that $2^h = \frac{4}{5}$ If $3(4^h)=4(2^k)$ and $9(8^h)=20(4^k)$,show that $2^h = \frac{4}{5}$.
I tried to substitute the equation 1 into equation 2 so that I can find the value of $k$ or $h$, but it did not work as the base is not the same (I cannot compare to find the answer)
How can I find the answer?

${\left( {3({4^h}) = 4({2^k})} \right)^2 \rightarrow 9({16^h}) = 16({4^k}) 
\choose 9({8^h}) = 20({4^k})}$$\Rightarrow$ $\frac{{9({{16}^h})}}{{9({8^h})}} = \frac{{16({4^k})}}{{20({4^k})}} \Rightarrow {2^h} = \frac{4}{5}$
