Making sure I'm not doing something wrong I'm solving a matrix equation: $$2(A-B+X) = 3(X-A)$$
Where $A = \left( \begin{matrix} 1&2 \\ 3&4 \end{matrix} \right)$ and $B = \left( \begin{matrix} -1&0 \\ 1&1 \end{matrix} \right) $
So far I've done: $$2(A-B+x) = 3(X - A)$$ $$\Rightarrow 2 \left( \begin{matrix} 1&2 \\ 3&4 \end{matrix} - \begin{matrix} -1&0 \\ 1&1 \end{matrix} + X \right) = 3 \left( X - \begin{matrix} 1&2 \\ 3&4 \end{matrix} \right)$$
$$ \Rightarrow 2 \left( \begin{matrix} 2&2 \\ 2&3 \end{matrix} + X \right) = 3X - \begin{matrix} 3&6 \\ 9&12 \end{matrix}$$
$$\Rightarrow \begin{matrix} 4&4 \\ 4&6 \end{matrix} + 2X = 3X - \begin{matrix} 3&6 \\ 9&12 \end{matrix}$$
But I'm not sure if I can put it on this form, asssuming the 2 matrices form the matrix $C$ when added:
$$C + 2X = 3X$$ 
Because I remember something about watching out for positioning when subtracting two matrices..
Some help needed with the next step.

It might be more clear if you don't write out the elements until necessary.
$$2(A-B+X) = 3(X-A) \\
2A-2B+2X = 3X-3A \\
5A-2B = X$$
Matrices add and subtract normally; that is, $A+A = 2A, 10Q-8Q = 2Q, 3X-2X = X,$ etc.
