prove this by binomial theorem Prove that by binomial theorem :
$\dbinom{6}{0}+\dbinom{6}{2}+\dbinom{6}{4}+\dbinom{6}{6}=\dbinom{6}{1}+\dbinom{6}{3}+\dbinom{6}{5}$
I started to prove it by moving the right side to the left :
$\dbinom{6}{0}+\dbinom{6}{2}+\dbinom{6}{4}+\dbinom{6}{6}-\dbinom{6}{1}-\dbinom{6}{3}-\dbinom{6}{5}=0$ 
it should be done by the binomial coefficient ...?....
how ?? 
thanks in advance

Hint: The number of subsets of even cardinality= The number of subsets with odd cardinality.
