How can I determine the value of this limit? $\lim\limits_{t \to -\sqrt{8}} \frac{t + 2\sqrt{2}}{3t^2 - 24}.$ Evaluate the following limit:
$$\lim_{t \to -\sqrt{8}} \frac{t + 2\sqrt{2}}{3t^2 - 24}.$$

$$\lim_{t \to -2\sqrt{2}} \frac{t + 2\sqrt{2}}{3t^2 - 24} = \lim_{t \to -2\sqrt{2}} \frac{t + 2\sqrt{2}}{3(t^2 - 8)} =\lim_{t\to -2\sqrt 2} \frac{t + 2\sqrt 2}{3(t+ 2\sqrt 2)(t-2\sqrt 2)}$$
Cancel, and evaluate.
