Quadratic equation $4x^2+4x=7$ using quadratic formula Solve using quadratic formula. $4x^2+4x=7$
So $4x^2+4x-7=0$
$A=4$ $b=4$ $c=-7$
$$x=\frac{-4\pm\sqrt{(4)^2-4(4)(-7)}}{2(4)}=\frac{-4\pm\sqrt{16+112}}{8}=\frac{-4\pm\sqrt{128}}{8}$$
What's next?

Next is simplifying:
$$x=\frac{-4\pm\sqrt{4^2-4\cdot4\cdot-7}}{2\cdot4}=\frac{-4\pm\sqrt{16+112}}{8}=-\frac12\pm\frac18\cdot8\sqrt{2}=-\frac12\pm\sqrt2$$
