Solve equations $\sqrt{t +9} - \sqrt{t} = 1$ Solve equation:  $\sqrt{t +9} - \sqrt{t} = 1$
I moved - √t to the left side of the equation $\sqrt{t +9} = 1 -\sqrt{t}$
I squared both sides $(\sqrt{t+9})^2  = (1)^2 (\sqrt{t})^2$
Then I got $t + 9 = 1+ t$
Can't figure it out after that point.
The answer is $16$

$$\sqrt{t +9} - \sqrt{t} = 1$$
Multiplying by $\sqrt{t +9} + \sqrt{t}$ you get
$$9=\sqrt{t +9} +\sqrt{t} $$
Now adding
$$\sqrt{t +9} + \sqrt{t} =9$$
$$\sqrt{t +9} - \sqrt{t} = 1$$
you get 
$$\sqrt{t+9}=5 \Rightarrow t=25-9 $$
