Simplifying Square Roots Frustration Okay, I'm really frustrated with this.
So, when you have $3 \sqrt 5 + 5 \sqrt 5$,
you get $8\sqrt5$, right?
Okay, so what do I do for here:
$\sqrt{11} - 3 \sqrt{11}$
Is it just $-3  \sqrt{11}$ ?
What about for $6 \sqrt 2 + 4  \sqrt{50}$ ?
Do I multiply the $6 \sqrt{2}$ so that I can make what's inside of the square root equal to $50$?

*

*$\sqrt{11}-3\sqrt{11}=\color{red}{1}\cdot\sqrt{11}-3\sqrt{11}=-2\sqrt{11}.$

*$6\sqrt 2+4\sqrt{50}=6\sqrt 2+4\color{blue}{\sqrt{2\cdot 5^2}}=6\sqrt{2}+4\cdot \color{blue}{5\sqrt 2}=6\sqrt 2+20\sqrt 2=26\sqrt 2$.
