Simultaneous equation with fractional solutions. How do you get to find $x$ when $y$ is a fraction ? Anyone mind to explain it step by step for the clearest explanation.=)
$$-7x +2y = 2$$
$$14x + 3y = -5$$
Answer: $x=?, y=-1/7$ 

Inserting $y=-\frac{1}{7}$ in the first equation
$-7x-2\cdot \frac{1}{7}=2$
Transforming 2 into $\frac{14}{7}$ to have a common denominator with $2\cdot \frac{1}{7}$
$-7x-\frac{2}{7}=\frac{14}{7} \quad \quad |+\frac{2}{7}$ 
Adding $\frac{2}{7}$ on both sides.
$-7x\underbrace{-\frac{2}{7}+\color{blue}{\frac{2}{7}}}_{=0}=\frac{14}{7} +\color{blue}{\frac{2}{7}}$ 
$-7x+0=\frac{14}{7} +\color{blue}{\frac{2}{7}}$ 
$-7x=\frac{14}{7}+\frac{2}{7}$
$-7x=\frac{16}{7}$
$-x=\frac{16}{7\cdot 7}$
$x=-\frac{16}{49}$
