How to simplify $42\sqrt{45} \over 7\sqrt{35}$? The problem is $$42\sqrt{45} \over 7\sqrt{35}$$ HELP! My daughter's math sheet shows how to reduce the squareroots, but the examples all use the same square-root; the problems show two different numbers square-rooted. Can you please help work this problem so I know how to help her with this assignment?
Thanks!

$$\frac{42 \sqrt{45}}{7 \sqrt{35}} \;\; = \;\; \frac{42}{7} \cdot \frac{\sqrt{45}}{\sqrt{35}} \;\; = \;\; \frac{42}{7} \cdot \sqrt{\frac{45}{35}} \;\; = \;\; \frac{6}{1} \cdot \sqrt{\frac{9}{7}}$$
$$ = \;\; \frac{6}{1} \cdot \frac{\sqrt{9}}{\sqrt{7}} \;\; = \;\; \frac{6}{1} \cdot \frac{3}{\sqrt{7}} \;\; = \;\; \frac{6}{1} \cdot \frac{3}{\sqrt{7}} \cdot \frac{\sqrt{7}}{\sqrt{7}}$$
$$= \;\; \frac{6 \cdot 3 \cdot \sqrt{7}}{1 \cdot \sqrt{7} \cdot \sqrt{7}} \;\; =\;\; \frac{18\sqrt{7}}{7}$$
