How to solve $\int\frac{2+3x}{3x^2+4x-6}\,dx$? I am trying to solve
$$\int\frac{2+3x}{3x^2+4x-6}\,dx$$ using partial fraction decomposition but it fails, how to solve it?

$\int\frac{2+3x}{3x^2+4x-6}=\frac{1}{2}\int\frac{6x+4}{3x^2+4x-6}=\frac{\ln(|3x^2+4x-6|)}{2}+K$
Since $6x+4$ is the derivative of $3x^2+4x-6$
