A 10 digit positive number and ordered triplets A 10 digit positive number is said to be a “LearnHub”number if its digits are all distinct and it is a multiple of 11111. How many “LearnHub” numbers are there?
Find the number of ordered triplets (a, b, c) of positive integers for which LCM (a, b) =1000, LCM (b, c) = 2000 and LCM (c, a) = 2000.
How do i do this ? I have worked a lot on them.

$1000 = 2^3 * 5^3$
$2000 = 2^4 * 5^3$
Since LCM of $a$ and $b$ is $1000$, they at the most contain $2$ three times and $5$ three times.
Also the LCM of terms containing $C$ is $2000$, the term $c$ should contain $2$ four times, as $a$ and $b$ can contain $2$ only three times.
so $c$ should either be
$2^4 = 16$
$2^4 * 5^1 = 80$
$2^4 * 5^2 = 400$
or $2^4 * 5^3 = 2000$. 
Either $a$ or $b$ should have $2^3$. Hence fixing one as $2^3$ other can take values from $2^0$ to $2^3$.
Hence total combination= $2*4 - 1$ (the one combination is $2^3,2^3$ which we took twice)$= 7$
2 of the three should have power of $5$ as $5^3$, whereas the third can take 4 values in terms of powers of $5$ $(5^0$ to $5^3)$. Hence total no of such arrangement = $(3!/2! *4) -2$(this is for $5^3,5^3,5^3$ which we took thrice) = $12 -2 =10$
Hence ordered triplets will be $10*7 = 70$
