How to factor $4x^2 + 2x + 1$? I want to know how to factor $4x^2 + 2x + 1$? I found the roots using quadratic equation and got $-1 + \sqrt{-3}$ and $-1 - \sqrt{-3}$, so I thought the factors would be $(x - (-1 + \sqrt{-3}))$ and $(x - (-1 - \sqrt{-3}))$
However, according to MIT's course notes, the factors are $(1 - (-1 + \sqrt{-3})x)$ and $(1 - (-1 - \sqrt{-3})x)$  
Course Notes (pg. 30) 
Are these two expressions equivalent, or am I simply not factoring correctly? Thanks.

$$4x^2+2x+1$$
Finding roots by quadratic rule as follows 
$$x=\frac{-2\pm\sqrt{2^2-4(4)(1)}}{2(4)}$$ $$=\frac{-2\pm2i\sqrt{3}}{8}$$
$$=-\frac{1}{4}\pm\frac{i\sqrt 3}{4}$$
$$x=-\frac{1}{4}+\frac{i\sqrt 3}{4}\ \vee\ x=-\frac{1}{4}-\frac{i\sqrt 3}{4}$$
Edit:

Now, we have the factors as follows $$4x^2+2x+1=4\left(x+\frac{1}{4}-\frac{i\sqrt 3}{4}\right)\left(x+\frac{1}{4}+\frac{i\sqrt 3}{4}\right)$$

