indefinite integral of $\cos(x) / x$? How can I evaluate ;
$$\int \frac{\cos(x)}{x} \, dx $$
I tried to do partial integration but it became to an infinite loop of partial integrations

Recall the Taylor series expansion for $\cos x$
\begin{align*}\cos x &= 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \cdots \\
\implies \frac{\cos x}{x} &= \frac{1}{x} - \frac{x}{2!} - \frac{x^3}{4!} - \frac{x^5}{6!} + \cdots \\
\therefore \int \frac{\cos x}{x} &= ln\ x - \frac{x^2}{2 \times 2!} + \frac{x^4}{4 \times 4!} - \frac{x^6}{6 \times 6!} + \cdots + \frac{x^{2k}}{(-1)^{k}\times2k \times (2k)!} + \cdots
\end{align*}
This sum approaches zero so that the indefinite integral is $ln(x)$ up to an integration constant.  Moreover, if the terminals of integration are say $a$ and $b$ (not zero or infinity), the definite integral would be $ln(a)-ln(b)$.  Where the terminals include zero or infinity, the Trigonometric Integral $Ci(x)$ or $Cin(x)$ need to be used.
