Find five consecutive odd integers such that their sum is $55$. So my professor asked us to do an Olympiad exercise which says that the sum of five consecutive odd integers is $55$, find those integers. But I've never seen such an exercise so it is quite new and if I learn how then I will be able to solve similar exercises.
I tried to think of it in terms of geometry but that didn't help me.

Hint: Choose one of those equations and solve it:
$$\begin{align}
& \text{The first integer:} & \qquad x+\color{blue}{x+2+x+4+x+6+x+8}=55 \\\,\\
& \text{The second integer:} & \qquad \color{red}{x-2}+x+\color{blue}{x+2+x+4+x+6}=55 \\\,\\
& \text{The third integer:} & \qquad \color{red}{x-4+x-2}+x+\color{blue}{x+2+x+4}=55 \\\,\\
& \text{The fourth integer:} & \qquad \color{red}{x-6+x-4+x-2}+x+\color{blue}{x+2}=55 \\\,\\
& \text{The fifth integer:} & \qquad \color{red}{x-8+x-6+x-4+x-2}+x=55
\end{align}$$
Obviously the simplest choice is to solve for the third integer, since the $2$s and $4$s cancel out, and you're left with the simple equation, $5x=55$.
