Resolving a Limit I'm studying for college exams and I don't know how to solve this type of limit:
$$\begin{align}
\lim_{x\to -3} \sqrt{\frac{x^2-9}{2x^2+7x+3}}
\end{align}$$
Any help?
Update: I know that the solution is:
$$\begin{align}
\frac{1}{5} \sqrt{30}
\end{align}$$

We have by the L'Hôpital theorem:
$$\begin{align}
\lim_{x\to -3} \frac{x^2-9}{2x^2+7x+3}=\lim_{x\to -3}\frac{2x}{4x+7}=\frac{6}{5}\end{align}$$
Notice that
$$\lim_{x\to -3}{\sqrt{\frac{x^2-9}{2x^2+7x+3}}}=\sqrt{\lim_{x\to -3}\frac{x^2-9}{2x^2+7x+3}}\quad\text{Why?}$$
