Indices: $\left(2^\left(n+3\right) - 2^n\right)/14$ The questions im working on is..
$ \left(2^\left(n+3\right) - 2^n\right)/14 
$
My thought process behind solving it was to spilt the first 2 term into two separate terms then cancelling the 2^n leaving 2^3 over 14

$ (2^n \cdot 2^3-2^n)/14
$ 

$ (2^3)/14 = 8/14
$

however this is incorrect, how am i supposed to correctly simplify this equation?
Sorry about messing up the formatting so much

Steps:
$2^{n+3}= 2^n2^3= 2^n×8.$
$(2^{n+3} -2^n) = 2^n(8-1)=7×2^n.$
$14=2×7$.
$\dfrac{7×2^n}{14}= 2^n/2^1= 2^{n-1}.$
