Integral $\int \frac{x+2}{x^3-x} dx$ I need to solve this integral but I get stuck, let me show what I did:
$$\int \frac{x+2}{x^3-x} dx$$
then:
$$\int \frac{x}{x^3-x} + \int \frac{2}{x^3-x}$$  
$$\int \frac{x}{x(x^2-1)} + 2\int \frac{1}{x^3-x}$$
$$\int \frac{1}{x^2-1} + 2\int \frac{1}{x^3-x}$$
now I need to resolve one integral at the time so:
$$\int \frac{1}{x^2-1}$$ with x = t I have:
$$\int \frac{1}{t^2-1}$$ 
Now I have no idea about how to procede with this...any help?

HINT:
$$\int\frac{x+2}{x^3-x}=\int\frac{-2}{x}+\int\frac{\frac{3}{2}}{x-1}+\int\frac{\frac{1}{2}}{x+1}$$
Can u do it from here?
