Simultaneous equation that turns into quadratic Solve for $x$ and $y$:
\begin{cases}
y &= 4x^2 - x - 6 \\
y &= 2 - x.
\end{cases}
I have tried rearranging to get $x + y = 2$ and then substituting $y$ into it but hit a dead end. I'm pretty sure it turns into a quadratic equation. Any help would be appreciated thanks.

You can substitute $y$ into the first equation to get: 
$4x^2-x-6=2-x$ 
$4x^2-8=0$ 
Plus this into the quadratic formula where $a=4$, $b=0$, and $c=-8$
$x = \dfrac{-(0)\pm \sqrt{(0)^{2} - 4 (4)(-8)}}{2(4)}$ 
$x=\pm \sqrt {2}$
$y=2\pm \sqrt 2$
