Algebraic Expressions with Fractions can someone review this and see if i've done it correctly please.
$$\frac{\frac {3x} {y}}{\frac {2x}{7}}
$$
$$= \frac{3x}{y} . \frac{7}{2x}$$
$$= \frac{21x}{2xy}
$$
$$= \frac {21}{2y}
$$
Thank you for your time.

Your answer and method look correct (but as pointed out in the comments, you need to add the restriction $x\ne 0$). I would have liked to have seen more steps though to demonstrate understanding.
$$\frac{\frac{3x}{y}}{\frac{2x}{7}}$$
$$= \color{red}{\frac{\frac{3x}{y}}{\frac{2x}{7}}\cdot\frac{\frac{7}{2x}}{\frac{7}{2x}}}$$
$$= \color{red}{\frac{\frac{3x}{y}\cdot\frac{7}{2x}}{\frac{2x}{7}\cdot\frac{7}{2x}}}$$
$$= \color{red}{\frac{\frac{3x}{y}\cdot\frac{7}{2x}}{\frac{14x}{14x}}}$$
$$= \color{red}{\frac{\frac{3x}{y}\cdot\frac{7}{2x}}{1}}$$
$$= \frac{3x}{y}\cdot\frac{7}{2x}$$
$$= \frac{21x}{2xy}$$
$$= \frac{21}{2y}$$
