If the value of $xy$ , If $ x^2 + y^2 = 34$ and $x + y =8$ If $ x^2 + y^2 = 34$ and $x + y =8$ find the value of xy
So what should I be considering here the sum of two squares or..
I'm struggling here & any help to figure this out will be kindly appreciated

Use:
$$x+y=8\Longleftrightarrow x=8-y\Longleftrightarrow x^2=\left(8-y\right)^2$$
So:
$$x^2+y^2=34\Longleftrightarrow\left(8-y\right)^2+y^2=34$$
So, for $y$ we find $y=3$ or $y=5$
