What am I doing wrong finding the limit of $\left(\frac{3x^2-x+1}{2x^2+x+1}\right)^\left(\frac{x^3}{1-x}\right)$? $$\lim_{x\to\infty}\left(\frac{3x^2-x+1}{2x^2+x+1}\right)^\left(\frac{x^3}{1-x}\right)$$
Divide by $x^2$, get
$$\lim_{x\to\infty}(1,5)^\infty=\infty$$
The answer in the book is $0$.
I've also tried substituting $x$ for $\frac{1}{h}$ where $h$ tends to zero and using some form of $(1+\frac{1}{n})^n$, and using the exponent rule, but everything lands me at infinity.
Do I misunderstand something fundamentally?

Note that
$$\frac{3x^2-x+1}{2x^2+x+1} \to \frac32$$
but
$$\frac{x^3}{1-x}=-\frac{x^3}{x-1}\to -\infty$$
