solve for $x$: $(x^4-13x^2+36)^4+|x^2+x-6|+\sqrt{x^3-7x+6}=0$ There is an equation that I think it is complicated ,a little!
$$(x^4-13x^2+36)^4+|x^2+x-6|+\sqrt{x^3-7x+6}=0$$
Actually we must solve for $x$ here.
I want you to hint me how can I simplify the equation and solve it.

Hint:
Observe that for real $x$
each of the summands must be $=0$
Now $x^2+x-6=(x+3)(x-2)$
$$x^4-13x^2+36=(x^2-4)(x^2-9)$$
$$x^3-7x+6=x^3-2^3-7(x-2)$$ or try divide $x^3-7x+6$ by $x-2$ 
