Differentiation help (lots of square roots) help finding the first derivative of this question:
$y=\sqrt{ 1 + \sqrt{ 1+\sqrt{1+8x}}}$
I get confused, is it meant to be done implicitly or is it just a really long chain rule?

It seems like it is a long chain rule indeed:
\begin{align}
\frac{dy}{dx}&=\frac{1}{2\sqrt{1+\sqrt{1+\sqrt{1+8x}}}} \cdot \frac d{dx} \left(1+\sqrt{1+\sqrt{1+8x}} \right) \\
&=\frac{1}{2\sqrt{1+\sqrt{1+\sqrt{1+8x}}}}\cdot \frac 1{2\sqrt{1+\sqrt{1+8x}}} \cdot \frac d{dx} \left(1+\sqrt{1+8x} \right) \\
&= \cdots
\end{align}
Perhaps you can finish the rest?
