Find the type of triangle from equation. In triangle $ABC$, the angle($BAC$) is a root of the equation 
$$\sqrt{3}\cos x + \sin x = \frac{1}{2}.$$ 
Then the triangle $ABC$ is
a) obtuse angled  
b) right angled
c) acute angled but not equilateral
d) equilateral.
Thanks in advance.

$\frac{\sqrt{3}}{2}\cdot \cos x + \frac{1}{2}\sin x = \frac{1}{4}$
$\sin ({x + \frac{\pi}{3}}) = \frac{1}{4}$
