Solve the inequality $2\left|x+\frac{1}{4}\right| < 9$
I keep trying to figure this out and I can't.
I tried to split up the absolute value first.
$2 (x+\frac{1}{4}) < 9$
$2+x+\frac{1}{4} < 9$ 
subtract $2$ from both sides? $x+\frac{1}{4} < 7$
and
$2 -(x+\frac{1}{4}) < 9$ 
$2-x-\frac{1}{4} < 9$
subtract $2$ from both sides? $-x-\frac{1}{4} < 7$
well that's not right. I suck at this. :c
Thanks for any helpers.

$2|x+0,25| < 9 \rightarrow |x+0,25| < 4,5 \rightarrow |x| < 4,25 \rightarrow -4,25 < x <4,25$
You can negate $0,25$ from each side, since it is positive, and the absolute value won't effect it.
