Using the distributive property to factor $(5^{-1}\cdot 5^x - 5^x - 5\cdot 5^x + 5^2\cdot 5^x)$ I can't seem to understand the distributive property.
Take this:
$$ 5^{-1}\cdot 5^x - 5^x - 5\cdot 5^x  + 5^2\cdot 5^x$$ 
becoming this:
$$ 5^x\left(\frac 15 - 1 - 5 +25\right) $$
Help? :D

Every term has a factor of $5^x$ which is factored out.
Also, note that:
$$5^{-1} = \frac 1{5^1} = \frac 15,\quad 5^2 = 25$$

$$\begin{align}  5^{-1}\cdot \color{blue}{5^x} -  (1)\cdot \color{blue}{5^x} - 5\cdot \color{blue}{5^x} + 5^2\cdot \color{blue}{5^x} &= \frac 15\cdot \color{blue}{5^x} -(1)\cdot \color{blue}{5^x} - 5\cdot \color{blue}{5^x}+ 25\cdot \color{blue}{5^x}\\ \\ &  =\color{blue}{5^x}\left(\frac 15 -1-5 + 25\right)\\ \\ & = \frac{96}5\end{align}$$
