Boolean Algebra simplify minterms I have this equation 
$$\bar{A}\cdot\bar{B}\cdot\bar{C} + A\cdot\bar{B}\cdot C + A\cdot B\cdot \bar{C} + A \cdot B\cdot C$$
and need to simplify it. I have got as far as I can and spent a good 2 hours at it. I've realized I now need to use De Morgan's law to continue however I am baffled as to which rule to use. If someone could send me in the right direction that would be great!
$$\bar{A}\cdot\bar{B}\cdot\bar{C} + A\cdot\bar{B}\cdot C + A\cdot B\cdot \bar{C} + A \cdot B\cdot C$$
$$\bar{A}\cdot\bar{B}\cdot\bar{C} + A(\bar{B}\cdot\bar{C} + B\cdot\bar{C} + B\cdot C$$
$$\bar{A}\cdot\bar{B}\cdot\bar{C} + A(\bar{B}\cdot C + B(\bar{C} + C)) $$
$$\bar{A}\cdot\bar{B}\cdot\bar{C} + A(\bar{B}\cdot C + B) $$ 
$$\bar{A}\cdot\bar{B}\cdot\bar{C} + A(C + B) $$ 
Thanks

The $\mathrm{ExOR}$ function can be denoted by: $\oplus$ ; $X \oplus Y=\overline {X}\cdot Y +X \cdot \overline{Y} $. 
Also $\overline{X \oplus Y}=\overline {X}\cdot \overline{Y} +X \cdot {Y} $
Hence $$\begin{align}
\bar{A}\cdot\bar{B}\cdot\bar{C} + A\cdot\bar{B}\cdot C + A\cdot B\cdot \bar{C} + A \cdot B\cdot C &=\left(\bar{A}\cdot\bar{B}\cdot\bar{C} + A\cdot\bar{B}\cdot C \right)+ \left(A\cdot B\cdot \bar{C} + A \cdot B\cdot C \right) \\
&=\bar{B}\left(\bar{A}\cdot\bar{C} + A\cdot C \right)+A\cdot B\left(\bar{C} + C \right)\\
&=\bar{B}\left(\overline{A \oplus C}\right)+A\cdot B\\
\end{align}$$
