Need help with basic factoring equation I'm just trying to brush up on my factoring of quadratic equations.
$$\frac1{x+3} + \frac1{x^2 + 5x +6}$$
$$\frac1{x+3} + \frac1{(x+2)(x+3)}$$
$$\frac{(x+2)(x+3) + (x+3)}{(x+2)(x+2)(x+3)}$$
Then I'm stuck. I think you can factor out the $(x+2)(x+3)$ from top and bottom?

Between your second and third step it can be improved: since you have 
$
\frac1{x+3} + \frac1{(x+2)(x+3)}
$
in the second step, you want to give all fractions a common denominator - the least common denominator. Since both terms have a $x+3$ in the denom. already, multiply the first term by $\frac{x+2}{x+2}$, and add the fractions to get 
$$
\frac{x+2}{(x+2)(x+3)} + \frac 1{(x+2)(x+3)} = \frac{x+3}{(x+2)(x+3)} = \frac{1}{x+2}.
$$
