Is it possible to simplify $\frac{2^{2x-1} - 2^{x-1}}{2^{2x-1}}$? Is it possible to simplify this expression? 
$\frac{2^{2x-1} - 2^{x-1}}{2^{2x-1}}$ 

$$\begin{align}\frac{2^{2x-1} - 2^{x-1}}{2^{2x-1}}
&=\frac{2^{2x-1}}{2^{2x-1}}-\frac{2^{x-1}}{2^{2x-1}}
\\
&=1-2^{(x-1)-(2x-1)}
\\
&=1-2^{-x}
\end{align}$$
