Can someone help me with this question of finding x as exponent? The equation is:
$$6^{x+1} - 6^x = 3^{x+4} - 3^x$$
I need to find x. I forgot how to use logarithm laws. Help would be appreciated. Thanks.

This means
$$
6^x(6-1) = 3^x(3^4 - 1) \iff \\
5 \cdot 6^x = 80 \cdot 3^x \iff \\
5 \cdot 2^x \cdot 3^x = 80 \cdot 3^x \iff \\
5 \cdot 2^x = 80 \iff \\
2^x = 16 \Rightarrow \\
x = 4
$$
