Equation $2n^2=m^2+1$ Given the equation
$$2n^2=m^2+1$$
Is there a general solution? 

since $m$ is odd for example  $$2\cdot5^2=7^2+1$$ $$2\cdot29^2=41^2+1$$
Any hint would be appreciation.

If
$2n^2=m^2+1$
then
$2(3n+2m)^2 = 18n^2 + 14nm +8m^2$
$=9(m^2 + 1) + 14nm + 8m^2$
$=9(m^2+1) + 14nm + 8(2n^2-1)$
$=16n^2 + 14nm + 9m^2 + 1$
$=(4n+3m)^2 + 1$
so we have (1,1) -> (5,7) -> (29,41) etc.
