If $p =\frac{4\sin\theta \cos\theta}{\sin\theta +\cos\theta}$ Find the value of $\frac{p+2\sin\theta}{p-2\sin\theta}$ Problem : 

If $\displaystyle p =\frac{4\sin\theta\cos\theta}{\sin\theta +\cos\theta}$, find the value of $\displaystyle \frac{p+2\sin\theta}{p-2\sin\theta} + \frac{p+2\cos\theta}{p-2\cos\theta}$.

Please help how to proceed in such problem..Thanks..

You can directly substitute the value P in the given term
We get:  
$\large \large \frac {3\sinθ  +  \cosθ}{\sinθ  -  \cosθ}    +         \frac {3\cosθ  +  \sinθ}{\cosθ -  \sinθ}$
which simplifies to $2$
