text: # In the given figure, a || gm ABCD and a rectangle ABEF are of equal area. Then,
  
  Question:
  
  In the given figure, a || gm ABCD and a rectangle ABEF are of equal area. Then,
  
  (a) perimeter of ABCD = perimeter of ABEF
  (b) perimeter of ABCD < perimeter of ABEF
  (c) perimeter of ABCD > perimeter of ABEF
  
  (d) perimeter of $A B C D=\frac{1}{2}$ (perimeter of $A B E F$ )
  
  Solution:
  
  (c) perimeter of ABCD > perimeter of ABEF
  
  Parallelogram ABCD and rectangle ABEF lie on the same base AB, i.e., one side is common in both the figures.
  In ||gm ABCD, we have:
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