text: ## Nick2019 3 years ago I need help!!!
  
  1. Nick2019
  
  2. cherio12
  
  okay well the theorem is $z^2=x^2+y^2$ and you know everything has to be an integer (whole number)
  
  3. cherio12
  
  you can just try different values. For instance for the first one i might try z=51 and x=24. so 51^2=24^2+y^2. Solving i get y=45. So this works
  
  4. Nick2019
  
  can you try 19?
  
  5. Nick2019
  
  @cherio12 can you try #19 plz
  
  6. cherio12
  
  you just have to play with the numbers. I first tried $z^2=25^2+20^$ but i got z= 32.0156..so this didn't work next i tried $25^2=20^2+y^2$ y=15 (this is an integer) so it checks out
  
  7. cherio12
  
  does this make sense?
  
  8. Nick2019
  
  thats the answer in the book so i should be able to learn off your 2 answers
  
  9. Nick2019
  
  wait so on 18# i got 2601=576+y2 then do i get y by itself? @cherio12
  
  10. cherio12
  
  yes. you should go 2601-576=y^2. then take the squareroot of both sides to just get y
  
  11. Nick2019
  
  ok how do you know were to put the numbers on the equation?
  
  12. cherio12
  
  what do you mean?
  
  13. Nick2019
  
  wait oh i see you said move them around and it has to be a whole number
  
  14. cherio12
  
  yup, its always (leg)^2+(leg)^2=(hypotenuse)^2
  
  15. Nick2019
  
  thanks man! helped alot
  
  16. cherio12
  
  its commonly written as x^2+y^2=z^2
  
  17. cherio12
  
  no problem =D
  
  18. Nick2019
  
  k
  
  19. Nick2019
  
  wait so on # 20 i got 91.82592222ect
  
  20. cherio12
  
  okay so that means you picked the wrong combo of hypotenuse and legs. try another combo (by the way the hypotenuse will always be the largest of the 3 numbers)
  
  21. Nick2019
  
  so set it up as x2= 96 + 28?
  
  22. cherio12
  
  i would try $96^2=x^2+28^2$
  
  23. Nick2019
  
  do get x by its self?
  
  24. cherio12
  
  yes
  
  25. cherio12
  
  |dw:1359577137858:dw|
  
  26. Nick2019
  
  but i still will get that 91.etc right?
  
  27. cherio12
  
  i was just showing you the triangle to help show what i meant by x, y and z
  
  28. Nick2019
  
  i know im saying when i get x by its self and take 9216 and square it i get that 91.00202 number
  
  29. cherio12
  
  o you mean for the 96, 28 problem?
  
  30. Nick2019
  
  yes
  
  31. cherio12
  
  $96^2=x^2+28^2$ $9216=x^2+784$ $9216-784=x^2$ $x=\sqrt{8432}$ x=91.8259 so this way didn't work.
  
  32. cherio12
  
  i would then try $z^2=96^2+28^2$
  
  33. Nick2019
  
  but you would still get 91.8259 right?
  
  34. cherio12
  
  no i got 100
  
  35. cherio12
  
  you add 96^2 and 28^2 in this example instead of subtracting them (like we tried before)
  
  36. Nick2019
  
  ohhh
  
  37. Nick2019
  
  now i see thakns agian lol
  
  38. Nick2019
  
  hey can you help @cherio12 with # 23
  
  39. cherio12
  
  sure
  
  40. cherio12
  
  okay so i first tried z^2=72^2+75^2 But i got z=103.966 so that's not right then i tried 75^2=x^2+72^2
  
  41. Nick2019
  
  ok i did the first but didnt try that one what did you get?
  
  42. cherio12
  
  21
  
  43. Nick2019
  
  can you show how you did that?
  
  44. cherio12
  
  75^2=x^2+72^2 solve for x
  
  45. Nick2019
  
  ok thanks i got 21
  
  46. cherio12
  
  no problem
  
  47. Nick2019
  
  hey @cherio12 for #24 you you do the same?
  
  48. cherio12
  
  yes, your two legs are 6 and 3
  
  49. Nick2019
  
  so would it be 6(2)=3(2)+x2
  
  50. Nick2019
  
  @cherio12
  
  51. cherio12
  
  by(2) do you mean you are squaring it?
  
  52. Nick2019
  
  no 6 to the power 2 like 6*6
  
  53. cherio12
  
  that means squaring, but yes that is correct
  
  54. Nick2019
  
  wait that doesnt work
  
  55. Nick2019
  
  i tried both ways and got not a whole number
  
  56. cherio12
  
  I don't believe you are supossed to get an integer for this problem
  
  57. Nick2019
  
  so would 5.19 work?
  
  58. Nick2019
  
  @cherio12
  
  59. cherio12
  
  i got 7.937
  
  60. cherio12
  
  6^2+3^2=x^2
  
  61. Nick2019
  
  ya that was my second way
  
  62. Nick2019
  
  so would you set up # 25 and # 26 the same way?
  
  63. cherio12
  
  yes for 25, but for 26 you will use a ratio
  
  64. cherio12
  
  i gotta go eat..be back later
  
  65. Nick2019
  
  ok when you get back can you explain ratio?
  
  66. Nick2019
  
  @cherio12 you back?
  
  67. cherio12
  
  yes
  
  68. cherio12
  
  okay well for starters find the other leg on the 5,3 triangle
  
  69. Nick2019
  
  wait on the # 25 its just 11 and x so is it 121 then sqare root answer is 11?
  
  70. cherio12
  
  no, there are two 11 sides
  
  71. Nick2019
  
  oh i see cuase of that line thingy
  
  72. Nick2019
  
  73. cherio12
  
  no for 25, it is 11^1+11^2=x^2
  
  74. Nick2019
  
  so its 15.49
  
  75. cherio12
  
  yes
  
  76. cherio12
  
  does that make sense why?
  
  77. Nick2019
  
  yes i just didnt try that way and remember there not whole numbers
  
  78. Nick2019
  
  so how do you do #26 is it 2 problems in 1
  
  79. Nick2019
  
  @cherio12
  
  80. cherio12
  
  find the other leg in the 5,3 triangle first
  
  81. Nick2019
  
  5.83
  
  82. Nick2019
  
  wait no its 4
  
  83. cherio12
  
  yes 4
  
  84. Nick2019
  
  now do the other triangel?
  
  85. cherio12
  
  now we can use like triangle ratios 4/5=7/x
  
  86. Nick2019
  
  so 4 sqare + 5 square = 7sqare?
  
  87. cherio12
  
  no, no square
  
  88. cherio12
  
  just ratio, just division
  
  89. Nick2019
  
  so 0.8=7
  
  90. cherio12
  
  4/5=7/x .8=7/x .8x=7
  
  91. Nick2019
  
  oh ok wow being sick for one day of notes can rweally heart you
  
  92. cherio12
  
  haha, no problem
  
  93. Nick2019
  
  wait # 28 its 2x and 2x+4 and the length of the hypot is 4x-4
  
  94. Nick2019
  
  @cherio12
  
  95. cherio12
  
  yes, just apply the Pythagorean theorem
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