text: # JavaScript: Find the armstrong numbers of 3 digits
  
  ## JavaScript Conditional Statement and loops: Exercise-9 with Solution
  
  Write a JavaScript program to find the armstrong numbers of 3 digits.
  
  Note : An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 371 is an Armstrong number since 3**3 + 7**3 + 1**3 = 371.
  
  Pictorial Presentation:
  
  Sample Solution:-
  
  HTML Code:
  
  ``````<!DOCTYPE html>
  <html>
  <meta charset=utf-8 />
  <title>Three digit armstrong numbers</title>
  <body>
  
  </body>
  </html>
  ```
  ```
  
  JavaScript Code:
  
  ``````function three_digit_armstrong_number()
  {
  for (var i = 1; i < 10; ++i)
  {
  for (var j = 0; j < 10; ++j)
  {
  for (var k = 0; k < 10; ++k)
  {
  var pow = (Math.pow(i,3) + Math.pow(j,3) + Math.pow(k,3));
  var plus = (i * 100 + j * 10 +  k);
  if (pow == plus)
  {
  console.log(pow);
  }
  }
  }
  }
  }
  three_digit_armstrong_number();
  ```
  ```
  
  Sample Output:
  
  ```153
  370
  371
  407
  ```
  
  Flowchart:
  
  Live Demo:
  
  See the Pen javascript-conditional-statements-and-loops-exercise-9 by w3resource (@w3resource) on CodePen.
  
  Improve this sample solution and post your code through Disqus
  
  What is the difficulty level of this exercise?
  
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  ﻿
  
  ## JavaScript: Tips of the Day
  
  Creates an array of elements, ungrouping the elements in an array produced by zip and applying the provided function
  
  Example:
  
  ```const tips_unzip = (arr, fn) =>
  arr
  .reduce(
  (acc, val) => (val.forEach((v, i) => acc[i].push(v)), acc),
  Array.from({
  length: Math.max(...arr.map(x => x.length))
  }).map(x => [])
  )
  .map(val => fn(...val));
  
  console.log(tips_unzip([[2, 15, 200], [3, 25, 300]], (...args) => args.reduce((acc, v) => acc + v, 0)));
  ```
  
  Output:
  
  ```[5, 40, 500]
  ```
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