text: # F frequency of small diameter organ pipe
  
  1. Dec 17, 2005
  
  ### msimard8
  
  This is a multiple choice question
  
  The fundamental frequency of a small diameter organ pipe is
  
  a) directly proportional to its length
  b) inversely proportional to its length
  c) independent of its length
  d) inversely proportional to its diameter
  e) directly proportional to its diameter
  
  well this is what i know (assume)
  
  the organ pipe is closed at one end
  
  what formulas should i consider solving this problem
  
  2. Dec 17, 2005
  
  ### mukundpa
  
  go to text
  
  3. Dec 17, 2005
  
  ### msimard8
  
  whats that suppose to mean
  
  4. Dec 17, 2005
  
  ### mukundpa
  
  in your text book i think they have derived formulae for fundamental frequency and their overtones for open and cloced organ pipes, with the diagrams.
  
  5. Dec 17, 2005
  
  ### msimard8
  
  the only formula i see is
  
  Ln=(2n=1) wavlength/4
  
  which doesnt describe the question
  
  Right now I am thinking that the diameter has no effect because, all diameter does is increase or decrease the amplitude of the wavelength which effects the loudness or intensity of the sound.
  
  So therefore d and e are eliminated
  
  The length of the pipe determines how many waves can fit in the pipe.
  
  umm so confused
  
  6. Dec 18, 2005
  
  ### mukundpa
  
  dont get confused,
  The formula is about the of a closed tube rasonating with nth harmonic of a given frequency f, and is
  Ln=(2n-1) wavlength/4
  ( if it is + it is for nth overtone)
  (n = 1) gives first hormonic or fundamentalfrequency,length is wavlength/4
  (n = 2) gives first overtone frequency, length is 3*wavlength/4
  (n = 3) gives second overtone frequency, length of tube is 5*wavlength/4 and so on
  forget this here
  Now on to the question
  The frequency is given by
  f = c/lembda = wave velocity / wavelength
  in a colsed organ pipe standing waves will be produces with wavelength
  4L(fundamental)= f0
  4L/3(first overtone) = f1 = 3f0
  5L/4(second overtone) =f2 =5f0 and so on
  so the fundamental frequency of a close orgon pipe is
  f0 = c/(4*L)
  
  Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook
metadata: {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}