text: Mathematics
  
  An angle is $14^{o}$ more than its complementary angle. What is the measure?
  
  SOLUTION
  
  Let first angle is $={{x}^{o}}$
  
  Then, IInd angle is $=x+{{14}^{o}}$
  
  According to given question,
  
  $x+x+14={{90}^{o}}$
  
  $2x={{90}^{o}}-{{14}^{o}}$
  
  $2x={{76}^{o}}$
  
  $x={{38}^{o}}$
  
  Then, IInd angle is $x+{{14}^{o}}={{38}^{o}}+{{14}^{o}}={{52}^{o}}$
  
  You're just one step away
  
  Subjective Medium Published on 09th 09, 2020
  Questions 120418
  Subjects 10
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