text: # How do you find the derivative of x^2 lnx?
  
  $y ' = 2 x \cdot \ln \left(x\right) + {x}^{2} \cdot \frac{1}{x} = 2 x \ln \left(x\right) + x = x \left[2 \ln \left(x\right) + 1\right]$
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