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  # Algebra 2
  
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  Given V = 2πr2h, solve for h
  
  A)h = V/2r2
  
  B)h = V2πr2
  
  C)h = V - 2πr2
  
  D)h = V/2πr2
  
  f(x) = x2 - 5
  
  For the function shown, what is the range of the function when the domain is {2, 4, 7}?
  
  A){-1, 44}
  
  B){-1, -5}
  
  C){6, 21, 54}
  
  D){-1, 11, 44}
  
  Guest Aug 15, 2017
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  1)
  
  When the question asks to solve for in the equation of $$V=2\pi r^2h$$, it means get h, alone, on one side of the equation.  This only requires one step, in this case:
  
   $$V=2\pi r^2h$$ Divide by $$2\pi r^2$$ on both sides of the equation. $$h=\frac{V}{2\pi r^2}$$ We're done! h is by itself.
  
  The appropriate answer choice, therefore, is D
  
  2) If the domain is only {2, 4, 7}, just plug them in the original equation of $$f(x)=x^2-5$$.
  
   $$f(2)=2^2-5=-1$$ $$f(4)=4^2-5=11$$ $$f(7)=7^2-5=44$$
  
  Now, find the answer choice that has all three of these in its domain. That would be D again.
  
  TheXSquaredFactor  Aug 15, 2017
  
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