text: ## Elementary Algebra
  
  $14x^2-10x-8$
  We use the rules of exponents to obtain: $\frac{56x^4-40x^3-32x^2}{4x^2}=\frac{56x^4}{4x^2}-\frac{40x^3}{4x^2}-\frac{32x^2}{4x^2}=14x^2-10x-8$
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