text: # If y is inversely proportional to the square of x and y =1/9 when x =4, find y when x = 12?
  
  When y is inversely proportional to the square of x, it satisfies the equation
  
  y = k/x^2
  
  for some constant k. Using the given information, we can find k to be
  
  k = y*x^2 = (1/9)*4^2 = 16/9
  
  Then when x=12, we have
  
  y = (16/9)/12^2 = 16/(9*16*9) = 1/81
  
  thanked the writer.
  
  When y is inversely proportional to the square of x, it satisfies the equation
  
  y = k/x^2
  
  for some constant k. Using the given information, we can find k to be
  
  k = y*x^2 = (1/9)*4^2 = 16/9
  
  Then when x=12, we have
  
  y = (16/9)/12^2 = 16/(9*16*9) = 1/81
  
  thanked the writer.
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