text: 75 views
  q.1) find number of 5 digit number in which digit are in ascending order.
  +5
  for ascending, we need to avoid $0$, we cannot place it anywhere, so we're left with $9$ options,
  
  So, we'll be choosing $5$ digits out of $9$,i.e. $^9C_5$
  
  and after choosing there is only $1$ way to arrange them.
  
  ∴ Answer will be $^9C_5 \times 1 = ^{9}C_5 = 126$
  0
  0
  repetition not allowed
  0
  in question it is mention that we have to arrange in ascending order ,have you any such number in which digit is repeated but it's still in ascending order???
  +1
  @BASANT
  
  then it is non-decreasing order...
  
  @srestha mam
  
  i didn't ask for this particular question, i asked for generally, due to it's look more tough.. May anyone have any simple method?
  0
  @Shaik
  
  in that case ans also be same
  
  because , take any example
  
  like 2235
  
  arrangement done in 1 way only
  0
  
  no mam,
  
  check this question https://gateoverflow.in/8399/gate2015-3-5
  
  and should check the first link provided on the comment on the question
  
  +1 vote
  out of 1,2,3,4,5,6,7,8,9 pick any 5 digits. only one way to arrange them(ascending order). So, 9C5.
  
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