text: # Suppose ABCD is a parallelogram in which angle A = 108'. Calculate angles B, C and D.
  
  2
  by AishwaryaRangan
  
  2014-05-30T15:35:46+05:30
  If ABCD is a parallelogram
  In parallelogram ABCD
  m/_A=108·
  m/_C=m/_A=108·                                           (opposite angle of a parallelogram are                                                                                       congruent)
  m/_A+m/_B=180                                            (adjacent angle of a parallelogram are                                                                                       congruent)
  108+m/_B=180
  m/_B=180-108
  m/_B=72
  m/_B=m/_D=72                                              (opposite angle of a parallelogram are                                                                                       congruent)
  • Brainly User
  2014-05-30T15:46:26+05:30
  
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  Consider a,b,c,d to be the vertices of the parallelogram taken in cyclic order.
  A = 108 degree
  opposite sides are equal
  C = 108 degree
  base angles are supplementary
  A+B = 180
  B =180-108=72
  B and D are opposite . Hence D = 72 degree
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