text: # Algebra I
  
  posted by Cale
  
  Scott wants to make 6 gal of a 50% sugar solution by mixing together a 60% sugar solution and pure water. How much of each solution must he use?
  
  mixture 1 @ 60% = x gallons
  pure water = 100% - x (??? that's my question...is that correct? or is it 0?)
  mixture @ 50% = 6 gallons
  
  60x + 100(6-x)= 50 * 6
  60x + 600-100x = 300
  600 - 40x = 300
  -40x = -300
  x = 7.5
  
  1. Reiny
  
  I would do it this way:
  Amount of pure water needed --- x gal
  Amount of the 60% stuff ------ 6-x
  
  .6(6-x) + 0x= .5(6)
  3.6 - .6x = 3
  -.6x = -.6
  x = 1
  
  so use 5 gal of the 60% plus 1 gal of pure water
  
  your answer of 7.5 gal should have made no sense to you. You want to end up with only 6 gal, so how could you add 7.5 ????
  
  2. Cale
  
  Thank you. My answer of 7.5 didn't make sense. i was obviously overthinking...thinking pure would = 100%.
  
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