text: Question
  
  # A transformer has 840 loops in its secondary winding and is designed to accept an input...
  
   A transformer has 840 loops in its secondary winding and is designed to accept an input AC potential difference of 760 V and produce an output of 380 V. How many loops does the transformer’s primary winding contain?
  
  Here we are given that ,
  
  Number of loops in secondary winding N2 = 840
  
  Number of loops in primary winding N1 = to be find
  
  Input AC potential difference Vi = 760 V
  
  Output AC potential difference Vo = 380 V
  
  So for the loops that the transformer’s primary winding contain will be given by the transformation ratio of transformer that is given as
  
  Vi/Vo = N1/N2
  
  So that on plugging the value we will get,
  
  N1 = Vi/Vo × N2 = 760/380 × 840 = 1680
  
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