text: # Absolutely no idea how to do this
  
  • May 6th 2005, 03:34 PM
  Philmac
  Absolutely no idea how to do this
  How many natural numbers less than 200 leave a remainder of 3 when divided by 7 and a remainder of 4 when divided by 5?
  • May 6th 2005, 04:15 PM
  beepnoodle
  For the remainder of 3 when divided by 7, look at numbers of the form 7n+3,
  the first few are 3,10,17,... get the idea now? You can do the same thing for the ones that leave a remainder of 4 when divided by 5. Then what you can do is compare the two lists and see what numbers are the same.
  • May 6th 2005, 04:22 PM
  Philmac
  Thanks, but my teacher doesn't like it when we do trial and error (I mean just comparing two lists) it has to be "clean."
  
  But I like the 7n+3. Would this work?
  
  x=7n+3
  x=5n+4
  
  0=2n-1
  -2n=-1
  2n=1
  n=1/2
  
  Well that didn't work :) is there something kind of like that I could do though?
metadata: {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}