text: # algebra
  
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  The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 50 amps when the resistances is 20 ohms. What is the current when the resistance is 60 ohms?
  
  • algebra -
  
  I = k/R
  50 = k/20, so k = 1000, making
  
  I = 1000/R
  I(60) = 1000/60 = 16.67
  
  • algebra -
  
  if y varies directly as x and y = 9 when x =2 find when x =10
  
  • algebra -
  
  E = I*R = 50 * 20 = 1000 Volts = Supply
  voltage.
  
  I = E/R = 1000/60 = 16.67 Amps.
  
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