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  # Hwk5B-2 - PHYS 153 Term 2 2008-09 Homework 5B Feb 23 27...
  
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  + + R = 8 . 0 Ω r 1 = 1 . 0 Ω r 2 = 1 . 0 Ω E 2 = 8 . 0 V E 1 = 12 . 0 V + + + 10 . 0 Ω 20 . 0 Ω 60 . 0 Ω 60 . 0 Ω 30 . 0 Ω 20 . 0 Ω 5 . 0 Ω 5 . 0 Ω 10 . 0 V 5 . 0 V E 15 . 0 Ω PHYS 153 Term 2, 2008-09 Homework 5B Feb. 23 - 27 Problem 1 Copper has 8 . 5 × 10 28 free electrons per cubic meter. A 71 . 0 cm length of 12-gauge copper wire that is 2 . 05 mm in diameter carries 4 . 85 A of current. (a) How much time does it take for an electron to travel the length of the wire? (b) Repeat part (a) for 6-gauge copper wire (diameter 4 . 12 mm) of the same length that carries the same current. (c) Generally speaking, how does changing the diameter of a wire that carries a given amount of current a ff ect the drift velocity of the electrons in the wire? Problem 2 In the circuit of the figure below, find (a) the current through the 8 . 0 Ω resistor and (b) the total rate of dissipation of electrical energy in the 8 . 0 Ω resistor and in the internal resistance of the batteries. (c) In one of the batteries, chemical energy is being converted
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