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   2006-10-19, 14:19 #1 Mini-Geek Account Deleted     "Tim Sorbera" Aug 2006 San Antonio, TX USA 426710 Posts Easy How do you calculate (and what is) 1+2+3+4...97+98+99+100 in under 10 seconds?
   2006-10-19, 14:39 #2 retina Undefined     "The unspeakable one" Jun 2006 My evil lair 5,879 Posts Divide into 2 sets, 1-50 & 51-100 Reverse the order of the second set Imagine the second set written below the first set Add each vertical pair (the pattern emerges), all pairs add to 101 Clearly there are 50 such pairs Answer is 101*50 This is the arithmetic progression Last fiddled with by retina on 2006-10-19 at 14:45 Reason: spoiler tags added
  2006-10-19, 16:22   #3
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  "Tim Sorbera"
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  Quote:
   Originally Posted by retina Divide into 2 sets, 1-50 & 51-100 Reverse the order of the second set Imagine the second set written below the first set Add each vertical pair (the pattern emerges), all pairs add to 101 Clearly there are 50 such pairs Answer is 101*50
  The way I found was the same, except you added 1+99, 2+98...49+51 to get 49 100s (4900) then added the 50 and the 100 that were left over (because neither of them could be added to something different to make 100), to get 5050.
  
   2006-10-19, 17:14 #4 mfgoode Bronze Medalist     Jan 2004 Mumbai,India 22×33×19 Posts Arithmetic progression. Sorry to correct you but Retina is right, tho' you are also right tho' your method is not orthodox. This problem was solved in a jiffy by Gauss, when he was 6 yrs. old , one of the three greatest mathematicians, who ever lived,[ Archimedes, Newton and Gauss] I'm glad you mentioned it as it has refreshed my aging memory. Mally Last fiddled with by mfgoode on 2006-10-19 at 17:16 Reason: Add on
  
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