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  # John traveled 80% of the way from Yellow-town to
  
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  Senior Manager
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  John traveled 80% of the way from Yellow-town to [#permalink]  05 Apr 2006, 00:49
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  Question Stats:
  
  100% (02:55) correct 0% (00:00) wrong based on 1 sessions
  John traveled 80% of the way from Yellow-town to Green-fields by train at an average speed of 80 miles per hour. The rest of the way John traveled by car at an average speed of v miles per hour. If the average speed for the entire trip was 60 miles per hour, what is v in miles per hour?
  
  (a) 30
  (b) 40
  (c) 50
  (d) 55
  (e) 70
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  The average speed for the entire trip= Total distance/Total time
  
  60/60=D/T
  
  D/T=1
  
  Pick 100 km for D...
  This would yield T=100 minutes
  
  Using the question stem we calculate 80 km were traveled in 1h (or 60 minutes)....
  
  This leaves us with 40 minutes (2/3 of an hour) to travel 20km.....
  
  R*T=D
  
  R*2/3=20
  
  R=30
  
  Manager
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  A.
  
  Let "100" be the total distance travel (D). Thus, D1 = 80 and D2 = 20.
  V1 = 80 mph, V2 is the unknown, and total velocity (V) = 60 mph.
  
  D1/V1 + D2/V2 = D/V
  
  80/80 + 20/V2 = 100/60
  
  20/V2 = 2/3
  
  20 (3/2) = V2
  
  30 = V2
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  let total distance be d
  
  First part by train took 0.8d/80 = 0.01 hour
  Last part of journey took 0.2d/v hours
  
  average speed = 80dv/(0.8vd + 16d) = 60
  80vd = 48vd + 960d
  32vd = 960
  vd = 30d
  v = 30
  Senior Manager
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  A 30 m/hr
  
  if we consider total distance to be x and time taken as t.
  
  (0.8x/80)+(0.2x)/v = (x/60)
  => v = 30
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