text: # 0.5 Discrete structures recursion  (Page 4/8)
  
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  Algorithm 1:   Even(positive integer k)
  
  Input: k , a positive integer
  
  Output: k-th even natural number (the first even being 0)
  
  Algorithm:
  
  if k = 1, then return 0;
  
  else return Even(k-1) + 2 .
  
  Here the computation of Even(k) is reduced to that of Even for a smaller input value, that is Even(k-1). Even(k) eventually becomes Even(1) which is 0 by the first line. For example, to compute Even(3), Algorithm Even(k) is called with k = 2. In the computation of Even(2), Algorithm Even(k) is called with k = 1. Since Even(1) = 0, 0 is returned for the computation of Even(2), and Even(2) = Even(1) + 2 = 2 is obtained. This value 2 for Even(2) is now returned to the computation of Even(3), and Even(3) = Even(2) + 2 = 4 is obtained.
  
  As can be seen by comparing this algorithm with the recursive definition of the set of nonnegative even numbers, the first line of the algorithm corresponds to the basis clause of the definition, and the second line corresponds to the inductive clause.
  
  By way of comparison, let us see how the same problem can be solved by an iterative algorithm.
  
  Algorithm 1-a:   Even(positive integer k)
  
  Input: k, a positive integer
  
  Output: k-th even natural number (the first even being 0)
  
  Algorithm:
  
  int   i, even;
  
  i := 1;
  
  even := 0;
  
  while( i<k ) {
  
  even := even + 2;
  
  i := i + 1;
  
  }
  
  return even .
  
  Example 2: Algorithm for computing the k-th power of 2
  
  Algorithm 2   Power_of_2(natural number k)
  
  Input: k , a natural number
  
  Output: k-th power of 2
  
  Algorithm:
  
  if k = 0, then return 1;
  
  else return 2*Power_of_2(k - 1) .
  
  By way of comparison, let us see how the same problem can be solved by an iterative algorithm.
  
  Algorithm 2-a   Power_of_2(natural number k)
  
  Input: k , a natural number
  
  Output: k-th power of 2
  
  Algorithm:
  
  int   i, power;
  
  i := 0;
  
  power := 1;
  
  while( i<k ) {
  
  power := power * 2;
  
  i := i + 1;
  
  }
  
  return power .
  
  The next example does not have any corresponding recursive definition. It shows a recursive way of solving a problem.
  
  Example 3: Recursive Algorithm for Sequential Search
  
  Algorithm 3   SeqSearch(L, i, j, x)
  
  Input: L is an array, i and j are positive integers, i ≤j, and x is the key to be searched for in L.
  
  Output: If x is in L between indexes i and j, then output its index, else output 0.
  
  Algorithm:
  
  if i ≤j , then
  
  {
  
  if L(i) = x, then return i ;
  
  else return SeqSearch(L, i+1, j, x)
  
  }
  
  else return 0.
  
  Recursive algorithms can also be used to test objects for membership in a set.
  
  Example 4: Algorithm for testing whether or not a number x is a natural number
  
  Algorithm 4   Natural(a number x)
  
  Input: A number x
  
  Output: "Yes" if x is a natural number, else "No"
  
  Algorithm:
  
  if x<0,   then return "No"
  
  else
  
  if x = 0,   then return "Yes"
  
  else return Natural( x - 1 )
  
  Example 5: Algorithm for testing whether or not an expression w is a proposition (propositional form)
  
  Algorithm 5   Proposition( a string w )
  
  Input: A string w
  
  Output: "Yes" if w is a proposition, else "No"
  
  Algorithm:
  
  if w is 1(true), 0(false), or a propositional variable, then return "Yes"
  
  else if w = ~w1, then return Proposition(w1)
  
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