text: Coding Interview questions set 6
  
  Let's begin with set 6,
  
  13)Given an array of integer nums and an integer target, return indices of the two numbers such that they add up to the target.
  
  Assumptions: Each input would have exactly one solution, and you may not use the same element twice.
  
  Example 1:
  
  Input: nums = [2,7,11,15], target = 9
  
  Output: [0,1]
  
  Output: Because nums[0] + nums[1] == 9, we return [0, 1].
  
  Example 2:
  
  Input: nums = [3,2,4], target = 6
  
  Output: [1,2]
  
  Solution:
  
  `const twoSum = (nums, target) => {  const map = {};  for (let i = 0; i < nums.length; i++) {    const another = target - nums[i];    if (another in map) {      return [map[another], i];    }    map[nums[i]] = i;  }  return null;};`
  
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  14)Given an array of numbers containing n distinct numbers in the range [0, n], return the only number in the range that is missing from the array.
  
  Could you implement a solution using only O(1) extra space complexity and O(n) runtime complexity?
  
  Example 1:
  
  Input: nums = [3,0,1]
  
  Output: 2
  Explanation: n = 3 since there are 3 numbers, so all numbers are in the range [0,3].
  2 is the missing number in the range since it does not appear in nums.
  
  Solution:
  `var missingNumber = function (nums) {    var sum = 0;    for (let i = 0; i < nums.length; i++) {      sum += i + 1 - nums[i];    }`
  
  return sum;
  };
  
  Written By:
  
  Saurabh Joshi
  
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