text: # . A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD
  
  A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD and DC into which BC is divided by the point of contact D are of lengths 8 cm and 6 cm respectively (see Fig. 10.14). Find the sides AB and AC.
  
  Solution:
  
  Let the given circle touch the sides AB and AC of the triangle at point E and F respectively and the length of the line segment AF be x.
  
  In ∆ABC,
  
  CF = CD = 6cm (Tangents on the circle from point C)
  
  BE = BD = 8cm (Tangents on the circle from point B)
  
  AE = AF = x (Tangents on the circle from point A)
  
  AB = AE + EB = x + 8
  
  BC = BD + DC = 8 + 6 = 14
  
  CA = CF + FA = 6 + x
  
  2S = AB + BC + CA
  
  = x + 8 + 14 + 6 + x
  
  = 28 + 2x
  
  = 42x+3x2 = 196+x2+28x
  
  = 2x2+14x-196 = 0
  
  = x2 +7x-98 = 0
  
  = x2 14x-7x-98 =0
  
  = x(x+14)-7(x+14) = 0
  
  =(x+14)(x-7) = 0
  
  Either x+14 = 0 or x - 7 =0
  
  Therefore, x = - 14 and 7
  
  However, x = - 14 is not possible as the length of the sides will be negative.
  
  Therefore, x = 7
  
  Hence, AB = x + 8 = 7 + 8 = 15 cm
  
  CA = 6 + x = 6 + 7 = 13 cm
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