text: +0
  
  +1
  1
  178
  4
  
  how do you solve 2(1/x+3) -3
  
  Sep 13, 2018
  
  #1
  +701
  +2
  
  Using the Distributive property  for 2(1/x+3)
  
  6x+2/x
  
  then subtracting 3
  
  3x+2/x
  
  Sep 13, 2018
  #2
  +1
  
  2(1/x+3) -3 =
  
  2/x + 6 - 3 =
  
  2/x + 3 Or: (3x + 2) / x
  
  Sep 13, 2018
  #3
  +101050
  0
  
  The second answer is the correct one.
  
  Sep 13, 2018
  #4
  0
  
  (3x+2) / x I think
  
  Sep 14, 2018
  edited by Guest  Sep 14, 2018
metadata: {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}