text: ## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
  
  $16a^4-5.6a^3-a+0.35$
  Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $(2a-0.7)(8a^3-0.5)$, is equivalent to \begin{array}{l}\require{cancel} 2a(8a^3)+2a(-0.5)-0.7(8a^3)-0.7(-0.5) \\\\= 16a^4-a-5.6a^3+0.35 \\\\= 16a^4-5.6a^3-a+0.35 .\end{array}
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