text: # How do you solve  |x| > 12?
  
  Apr 10, 2018
  
  $x > 12 \mathmr{and} x < - 12$
  
  #### Explanation:
  
  This equation requires an understanding of absolute value. This is how to solve this equation:
  
  $| x | > 12$
  
  Case 1: $x > 12$
  
  Case 2: $- x > 12$
  
  Now don't be fooled, when you divide both sides of an inequalities by a negative number, you have to flip the sign, so:
  
  $x < - 12$ is the second answer
  
  Answers are: $x > 12 \mathmr{and} x < - 12$
metadata: {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 6, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 1, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}