text: ## Trigonometry 7th Edition
  
  Published by Cengage Learning
  
  # Chapter 2 - Section 2.1 - Definition II: Right Triangle Trigonometry - 2.1 Problem Set - Page 63: 55
  
  #### Answer
  
  $\frac{2}{\sqrt 3}$
  
  #### Work Step by Step
  
  To find out exact value of $\csc 60^{\circ}$, considering special triangle- $30^{\circ} - 60^{\circ} - 90^{\circ}$ $\csc 60^{\circ}$ = $\frac{hypotenuse}{side - opposite - 60^{\circ}}$ $\csc 60^{\circ}$ = $\frac{2}{\sqrt 3}$ = $\frac{2}{\sqrt 3}$
  
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