Rationale: O and P should serve on A
The answer: (D)
Question: In case N is the only individual sewing on committee B, which among the following shouldserve on committee A?
Options:
(A) V and U
(B) V and T
(C) U and S
(D) O and P
(E) T and U


Rationale: T = 52/24 * 18/5 = 8 se
The answer: (C)
Question: In what time will a railway train 52 m long moving at the rate of 24 kmph pass a telegraph post on its way?
Options:
(A) 3 sec
(B) 4 sec
(C) 8 sec
(D) 6 sec
(E) 7 sec


Rationale: In 1 kg mixture quantity of iron = 200 gm
Let x gm sand should be added, then
10% of (1000 + x) = 200
\ x = 1000 gm = 1 kg
The answer: (A)

Question: In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%?
Options:
(A) 1 kg
(B) 200 gms
(C) 800 gms
(D) 1.8 kg
(E) None of these
Rationale: O and P should serve on A
The answer: (D)
Question: In case N is the only individual sewing on committee B, which among the following shouldserve on committee A?
Options:
(A) V and U
(B) V and T
(C) U and S
(D) O and P
(E) T and U


Rationale: T = 52/24 * 18/5 = 8 se
The answer: (C)
Question: In what time will a railway train 52 m long moving at the rate of 24 kmph pass a telegraph post on its way?
Options:
(A) 3 sec
(B) 4 sec
(C) 8 sec
(D) 6 sec
(E) 7 sec


Rationale: In 1 kg mixture quantity of iron = 200 gm
Let x gm sand should be added, then
10% of (1000 + x) = 200
\ x = 1000 gm = 1 kg
The answer: (A)

user
Question: In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%?
Options:
(A) 1 kg
(B) 200 gms
(C) 800 gms
(D) 1.8 kg
(E) None of these
assistant
Rationale: O and P should serve on A
The answer: (D)
Question: In case N is the only individual sewing on committee B, which among the following shouldserve on committee A?
Options:
(A) V and U
(B) V and T
(C) U and S
(D) O and P
(E) T and U


Rationale: T = 52/24 * 18/5 = 8 se
The answer: (C)
Question: In what time will a railway train 52 m long moving at the rate of 24 kmph pass a telegraph post on its way?
Options:
(A) 3 sec
(B) 4 sec
(C) 8 sec
(D) 6 sec
(E) 7 sec


Rationale: In 1 kg mixture quantity of iron = 200 gm
Let x gm sand should be added, then
10% of (1000 + x) = 200
\ x = 1000 gm = 1 kg
The answer: (A)

Question: In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%?
Options:
(A) 1 kg
(B) 200 gms
(C) 800 gms
(D) 1.8 kg
(E) None of these