Thermodynamics derivatives: Does $(\partial A/\partial B) = (\partial B/\partial A)^{-1}$?

If I need to find, for instance:
$$\mathcal{T} := \left(\frac{\partial U}{\partial S}\right)\_{V, N}$$
knowing:
$$\left(\frac{\partial S}{\partial U}\right)\_{V, N} = \frac{1}{T}$$
Can I say that $\mathcal{T} = (1/T)^{-1} = T$ ? In general terms, let $A$ and $B$ are two thermodynamics values, is it true that
$(\partial A/\partial B) = (\partial B/\partial A)^{-1}$ ?


