A student is provided with 500 mL of 600 ppm solutions of fructose. What volume of this solution in millilitres contains 0.15 fructose? [closed]








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> 
> A student is provided with 500 mL of 600 ppm solutions of fructose. What volume of this solution in millilitres contains 0.15 fructose?
> 
> 
> 


Does this mean that I just have to use 600 ppm as the concentration and the 0.15 as the weight? Like this: 


\begin{align\*}
{600 \space ppm}
&=\frac {0.15 g}{x}\cdot 10^{6} \\
x&=\frac {0.15 }{600}\cdot 10^{6} \\ 
x&=250 \space mL\\
&
\end{align\*}


And when can 500 mL be used?




Assuming it's $0.15gm$ of fructose,$$ppm=\frac{Weight\;of\;solute\_{(in\;gm)}}{Weight\;of\;solution\_{(in\;gm)}}10^6$$
Since density of water is $1gm/ml$, $500ml$ of water would weigh $500gm$
$$\therefore600=\frac{W\_b}{500}10^6$$
$$\therefore W\_b=0.3gm$$


Thus, $500ml$ of water contains $0.3gm$ of fructose. You can find out what volume will contain $0.15gm$ of it.


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