Synthesis of tin(II) nitrate

I tried to prepare $\ce{Sn(NO3)2}$ using tin(II) chloride and nitric acid according to the reaction


$$\ce{SnCl2 + 2 HNO3 -> Sn(NO3)2 + 2 HCl},$$


but stannous chloride appears to be poorly soluble (turbid solution). What is the correct method to prepare $\ce{Sn(NO3)2}$?





> 
> Stannous Nitrate is obtained in white leaflets having the
> composition $\ce{Sn(NO3)2.20H2O}$ by cooling to $\pu{-20 °C}$. a solution of
> stannous oxide in nitric acid of density 1.2. It is also formed by the
> action of highly diluted nitric acid on the metal, some of the acid
> thus suffering maximum reduction to ammonia: 
> 
> 
> $$\ce{4Sn + 10HNO3 -> 4Sn(NO3)2 + NH4NO3 + 3H2O}$$
> 
> 
> According to C. H. H. Walker, tin dissolves in nitric acid forming
> stannous and stannic nitrates, the relative proportion of these two
> salts produced depending on the temperature and the strength of the
> acid; moreover, the yellowish white precipitate which separates when
> the somewhat concentrated acid is employed is said to be a hydrated,
> ill-defined, stannic nitrate.
> 
> 
> 


**Ref.**: <http://tin.atomistry.com/stannous_nitrate.html>


You can also check the post linked by Ivan.


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