In an Electrotlytic cell using MgSO4 electrolyte, Cu(OH)2 and Mg(OH)2 are visible products, Where Does SO4 go?

[![enter image description here](https://i.stack.imgur.com/n7CFH.jpg)](https://i.stack.imgur.com/n7CFH.jpg)I have an electrolytic cell with $\ce{MgSO4}$in an aqueous solution at full saturation, running at a potential of $3.6v$ with a copper anode because I need some $\ce{Cu(OH)2}$.


Production of $\ce{Cu(OH)2}$, $\ce{CuOH}$ and $\ce{Mg(OH)2}$ are all visible.


There's no gas production at the anode but I expect that the oxygen is remaining in solution due to $\ce{OH}$ production.


There's no sign of $\ce{SO2}$ or $\ce{SO3}$, so
what Happens to $\ce{SO4-}$?


**EDIT**  

$\ce{SO4-}$ eventually rejoins $\ce{Mg}$ because the more reactive base will always oxidize a less reactive neutral or acidic salt, not to mention that $\ce{H2SO4}$ is a species that will form under these conditions as $\ce{Mg}$ and $\ce{Cu}$ both become insoluble (which should actually yield $\ce{H2SO5}$ because $$\ce{Cu + MgSO4 + H2O -> Cu(OH)2 + Mg(OH)2}$$ @cathode, $$\ce{H2O + SO4- -> H2SO5}$$ @anode, which doesn't hang around too long $$\ce{H2SO5 -> 2H2SO4 + O2(g)}$$ and the obvious reformation of $\ce{MgSO4}$ via $\ce{H2SO4}$ + $\ce{Mg(OH)2}$ and $\ce{CuSO4}$ + $\ce{Mg(OH)2}$ so I was eventually left with $\ce{Cu(OH)2}$ as the only insoluble product.


I have since been able to produce $\ce{Mg(OH)2}$, omitting $\ce{Cu}$ entirely of course, but coming up with a process wasn't easy with my 3 months of experience. I however have been able to completely separate $\ce{Mg+}$ from $\ce{SO4-}$, yielding $\ce{H2SO4}$and $\ce{Mg(OH)2}$using perlite.




It forms $CuSO\_4$, which is soluble in water. $Cu(OH)\_2, CuOH$ and $Mg(OH)\_2$ prefer to precipitate, while $CuSO\_4$ just floating there, completely invisible. Actually, even when ppl try to obtain $CuSO\_4$ in such electrolytic cells, they simply collect $Cu(OH)\_2$, add $H\_2SO\_4$ and crystallize sulfate. So it is there, but there is no way you can obtain it directly. 


[remark] You can also try to crystallize it from solution, since it's there. But maybe you won't succeed. 


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