How to compare the stability of 3,4-Dimethylcyclopentene and Cyclopentane, 1-methyl-2-methylene

Two alkenes are given as follows:


[![3,4-Dimethylcyclopentene](https://i.stack.imgur.com/DPwEX.png)](https://i.stack.imgur.com/DPwEX.png),
[![enter image description here](https://i.stack.imgur.com/EsACy.png)](https://i.stack.imgur.com/EsACy.png)


How do I compare their stability?


Denoting the first compound as (A) and the second as (B).
Both the alkenes have same number of $\alpha$ hydrogens, which is $3$. Hence in terms of stability by hyperconjugation they should be similar. However the structure (A) contains $2$ carbons in $sp^2$ hybridisation "inside" the ring, whereas the compound (B) contains only one such ring carbon. Now since the typical bond angle of $sp^2$ is given as $120^\circ$, it is was intuitive for me to think that structure (A) would suffer a higher angle strain since the angles of a pentagon are $108^\circ$, however it seems incorrect since the solution of my paper did not consider this. Please help me to figure out what is that I am doing wrong and what the correct order should be, or whether they have equal stabilities.


