Electrophilic addition to alkenes

Consider the addition of HBr (in absence of any radical initiators or environment that promotes radical mechanistic pathway), to 3-bromocyclopentene.


[![(R)-3-bromocyclopentene](https://i.stack.imgur.com/ritMft.jpg)](https://i.stack.imgur.com/ritMft.jpg)


The first step is the attack of $\ce{H^+}$
On the exposed π electron cloud. But my query is whether it forms a classical carbocation like this one to oppose the negative inductive effects of the halogen atom:


[![(R)-bromocyclopentane-1-ylium cation](https://i.stack.imgur.com/O0G07t.jpg)](https://i.stack.imgur.com/O0G07t.jpg)


Or does it proceed with the formation of bromonium ion like this one to partially complete its octet using lone pairs on Br. 


[![cyclopentene-bromonium ion](https://i.stack.imgur.com/U8dj5t.jpg)](https://i.stack.imgur.com/U8dj5t.jpg)


These two would lead to different products but I'm interested in the major one.
The first one would lead to 1,3-dibromocyclohexane, while the second one would lead to 1,2-dibromocyclohexane.




Since it is electrophilic addition, it can go via 2 ways. Either by forming classical carbocation or cyclic carbocation. Since the electrophile will be H+ it will go with classical carbocation. Therefore product will be 1,3 dibromo cyclopentane. Also taken in account the mesomeric effect of bromine atom


 -1