Calculate the partial pressure of NO2

Calculate the partial pressure of $\ce{NO2}$.


$$p\_{\ce{N2}}/p\_{\ce{O2}}=5$$


$$\ce{N2(g) + O2(g) <=> 2NO(g)}$$


Let’s assume $K=0.1$


$$K= \frac{p\_{\ce{NO}}^2}{p\_{\ce{O2}}\cdot p\_{\ce{N2}}}$$


$$K= \frac{p\_{\ce{NO}}^2}{p\_{\ce{O2}}\cdot p\_{\ce{O2}}\cdot5}$$


But how do I proceed?




Ok.
Now you have 3 variables and 2 equations.
To solve the problem you need 3 equations.


Third equation you'll get from the partial pressure law: 



> 
> The total pressure of an ideal gas mixture is the sum of the partial pressures of each individual gas in the mixture.
> 
> 
> 


Tip: suppose total pressure is 1.


 2

When applying partial pressures please do not forget the partial pressure that the product itself exerts (NO)


So we have: p(O2)+ p(N2) + p(NO) = total pressure of the system. 


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