Calculating equilibrium constant given Ka value? [closed]








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> 
> $\ce{NH\_3(aq) + H\_3O^+(aq) <-> NH\_4^+(aq) + H\_2O(l)}$
> 
> 
> $\ce{K\_a}$ for $\ce{NH\_4^+}$ is $5.6\times10^{-10}$.
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> 


I am completely lost and I have no idea how to approach this question.




Never mind, I figured it out. All I had to do is reciprocate the value since Ka is the reciprocal of the equilibrium constant for that reaction. 


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