What is the volume of the produced SO2 gas at STP? [closed]








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> 
> In a electricity producing plant $3.1\times10^7\ \mathrm{kg}$ coal with $2.4\ \%$ rhombic sulfur is burnt every year. What is the volume of the produced $\ce{SO2}$ gas at STP?
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My effort for solving this answer :


In one day how much sulfur is burnt. Then I wrote the equation 


$$\ce{S + O2 -> SO2}$$ 


With the unitary method I tried but I am confused from where to start, how to start? Please give me a hint how to start the answer.




You have an excess of oxygen, right...?


So the limiting reactant is the sulfur, which is $2.4$% of the coal. 


Spoiler:
Step 1:



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>  So calculate the sulfur content, which is $3.1 \times 10^7$ kilograms multiplied by $2.4 \times 10^{-2}$ which is $7.44 \times 10^5$ kilograms of sulfur. 
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Step 2:



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>  The $\ce{SO\_2}$ is $50$% sulfur by mass (32 amu of sulfur vs. 64 amu total) so there is $1.488 \times 10^6$ kilograms of $\ce{SO\_2}$ produced. 
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Step 3 (for moles, optional):



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>  If you want moles, divide by $64$, which is $2.325 \times 10^4$ moles (someone check my math)
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Then again, you emphasized STP, so proceed with caution (sulfur doesn't react at $20$ degrees Celsius).


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