Will adding up protons and electrons (without neutrons) create a new element?

If protons have a positive charge and electrons have a negative charge,
can we add up several protons and electrons together to create a new element, *without adding neutrons to hold the nuclei together*?




Yes and no.


Elements are defined by the number of protons only. It does not matter if (say) a carbon nucleus has six or seven (or eight) neutrons, they will all react the same.\*


With that, to create *new* elements, you would need to get up to some 115 or so protons fused together. **But** there is a reason for neutrons: all the positively charged protons in the nucleus repel each other electrostatically so neutrons are there to stabilise the nucleus — you can think of it as cushioning protons apart. For each element there is a set number of neutrons that will create a *stable* nucleus. E.g. for hydrogen (one proton) it is zero or one, for oxygen it is eight, for carbon six or seven, for tin it can be $62, 64, 65, 66, 67, 68, 69, 70, 72$ or $74$.


Nuclei with other neutron numbers decay radioactively on half-life scales from femtoseconds to millions of years. I would expect no-neutron nuclei (non-hydrogen) to be on the very short edge of that spectrum (although I’m no radiochemist).




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\*: There are reactions in certain systems that depend a lot on hydrogen being $\ce{^1H}$ rather than $\ce{^2H}$ or $\ce{D}$ because they rely on the tunneling effect whose probability decreases with mass (I think by the factor $m^2$). That’s also why one shouldn’t drink $\ce{D2O}$


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Jan's answer is correct. I will try to fill in a few details about why neutrons are essential to creating stable nuclei.


All stable isotopes excepting Hydrogen-1 have neutrons in their nuclei. Hydrogen, for example has two stable isotopes: The first simply has a proton with no neutrons in the nucleus, while the second, often called Deuterium has a proton and one neutron.


Oxygen has three stable isotopes (O-16, O-17 and O-18), and by stable, I mean that they NEVER decay. The reason they never decay is that they cannot transmute (decay) to any other configuration of protons and neutrons without existing in a higher energy state. Since they don't have the energy, the protons and neutrons that make up those nuclei are stuck in that configuration (until something gives them the necessary energy to go to a higher energy state).


Now, as to your question: Neutrons play an important role in stabilizing the nucleus. Protons and neutrons respond to the Strong Nuclear Force (SNF) and are attracted to each other by that force. Protons, with charge, ALSO respond to the electrostatic force. Since all protons are positively charged, the more of them present in a nucleus, the larger the force that is trying to rip the nucleus apart.


Neutrons, in a nucleus bring added SNF to the nucleus without adding any repulsive electrostatic force. Thus they play an important role in creating stable nuclei. They increase the tendency of a nucleus to stick together. Thus all elements beyond Hydrogen have some neutrons in their nuclei.


And that explains why we don't find atoms with large numbers of protons and very few neutrons. By the time we get to Uranium, we find that nature needed more than one neutron for each new proton in order to create stable nuclei. U-238 is the most abundant form of Uranium and it has 92 protons and 146 neutrons.


But that leaves us with one other important dilemma. If neutrons attract each other, and there is NO electrostatic repulsive force between them, one could reason that we should find atoms with large numbers of neutrons and very few protons. Why not Hydrogen 99? 1 proton and 98 neutrons would seem to be extremely stable, yet it is not found in nature. In fact, if you add even one more neutron to Deuterium, you find that it (Tritium) decays with about a 12.32 year half-life.


The answer, is that there exists yet another force besides the SNF and the electrostatic force. It is called the Weak Nuclear Force because it is weaker than the SNF.


For an introduction to the Weak Nuclear Force I would go here:


<https://en.wikipedia.org/wiki/Weak_interaction>


So, we need neutrons to make atoms stable. Electrons cannot exist inside the nucleus due to the Uncertainty principle, but that's another issue entirely.


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I'll focus on the nucleus only. As far as I'm aware, there is little to no variation in radioactive decay lifetimes as a function of ion charge state; that is to say that the number of electrons surrounding a nucleus has little to no impact on whether the nucleus will decay. I'm open to corrections from measurements at, say, the Hollifield facility at Oak Ridge.


The 1-hydrogen nucleus is stable - one proton, no neutrons.


The 4-lithium nucleus is listed as having a decay time of 8E-23 seconds per the Chart of the Nucleides. So, three protons and one neutron is really, really unstable. A 3-lithium nucleus has never been observed. So, three protons with no neutrons is not stable.


The 2-He nucleus has been put forth as the mechanism for the observed 'exotic 2-proton decay' of even-Z nuclei. However, a recent paper [on 2-proton 19-Mg decay](http://journals.aps.org/prc/abstract/10.1103/PhysRevC.90.014301) says 'modeling the decay as the tunneling of a diproton ($^{2}$He nucleus) typically yielded lifetimes several orders of magnitude too short.' Thus, it would appear that the 2-He nucleus, two protons and no neutrons, which has never been observed alone, is not the object leading to observed 2-proton decays. Thus, while it has been postulated, it does not seem to occur. 


A no-neutron universe would then consist of hydrogen, and hydrogen alone.


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Without getting into the specifics of nuclear forces, there is a simple way to think about this.


What matter for *chemistry* is the number of protons in the *nucleus* of the atom as this determines the nature of the electron orbitals the atom will have which is what chemistry is about.


So, if you could persuade electrons to joint the nucleus *and that led to a proton turning into an neutron* then you would indeed have a new element. Whether that would be a stable element depends on all sorts of complicated stuff involving nuclear stability (and the strong and weak nuclear forces I'm trying to avoid dealing with). Besides, we already mostly know what nuclei are stable or not as nuclear physics has explored the possibilities extensively. 


Moreover, this process actually happens, though it isn't common. There is a rare form of radioactive decay for proton rich nuclei where the nucleus "captures" and electron transforming a proton to a neutron and thereby creating a different element. An example would be rubidium-83 (37 protons, 46 neutrons) decaying to krypton-83 (36 protons, 47 neutrons). [Wikipedia lists more examples.](http://www.wikiwand.com/en/Electron_capture)


So the answer is: yes you can add electrons to a nucleus to create a new element. But the fact that it isn't common suggests it is hard. And this reflects both the instability of most of the products you *could* get (even if it could happen the products would be too unstable to see in most cases) and the difficulty of the reaction mechanism (there is a big energy barrier preventing it happening for most nuclei).


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