Oxidation of 2-Methyl, 2-Phenyl Propane

Considering oxidation mechanism of side-chains in arenes, it is known that side-chains get oxidized to carboxylic group ($-COOH$).


Below is a picture of 2-Methyl, 2-Phenyl Propane. When it gets refluxed with acidified $KMnO\_4$ or acidified $K\_2Cr\_2O\_7$, it should be oxidized to give benzoic acid.


But according to the provided source, it seems 2-Methyl, 2-Phenyl Propane doesn't react with the above oxidizing agents.


My question is,


**Why does this compound disobey the general oxidation of benzyl derivatives?**


Note, the source has a OH on position 4 of the ring, that makes it difficult for me to name it.


*Source:* <https://papers.gceguide.com/A%20Levels/Chemistry%20(9701)/9701_s13_qp_41.pdf>
**Qno:5 c) i)**


Or is the OH that makes the difference in this question?


**2-Methyl,2-Phenyl Propane:**


[![enter image description here](https://i.stack.imgur.com/ITbNn.png)](https://i.stack.imgur.com/ITbNn.png)




For oxidation of aromatic side chains, you must have at least one Benzylic hydrogen. tert-butyl Benzene (which is actually 2-methyl,2-phenyl propane) doesn't have any benzylic hydrogen.


**-By @Soumik Das**


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