How does xenon react with O₂F₂?

This reaction was asked in my college entrance exam. I searched through the entire Internet, but I couldn't find any papers/sources.


I suspect since O₂F₂ is a strong fluorinating agent, one of the xenon fluorides (XeF₂, XeF₄, or XeF6) will form, but I am not sure. Reaction conditions were not given in the question.




From my research, it really depends on the experimental conditions and procedure. One paper in 1965 found that primarily $\ce{XeF2}$ was formed when xenon reacted with $\ce{O2F2}$ at low temperatures$^1$. In contrast, another paper found a mixture of $\ce{XeF2}$ and $\ce{XeF4}$ was formed, and prolonged exposure to $\ce{O2F2}$ generated mostly $\ce{XeF4}$ but no $\ce{XeF6}$ was observed$^2$.


**Sources:**


1. <https://pubs.acs.org/doi/10.1021/ic50027a038>
2. <https://pubs.acs.org/doi/10.1021/ic00334a037>


 12