Finding Enthalpy [closed]








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Given Information
$\ce{CH\_4 + 2 O\_2 -> CO\_2 + 2 H\_2O}$


"The Heat of reaction is $-802000\, \frac{J}{mol}$ of $\ce{CH\_4}$ at $25\, ^\circ C$.
Rate of Moles of $\ce{CH\_4}$ used is $0.625\, \frac{kmol}{h}$.
What is the enthalpy of reaction?"


Someone told me that the answer is $0.625 \cdot (-802000)$
But I dont get the logic behind it.


Thank you.


