Can't nobelium form compounds like other lanthanides/actinides do?

Over the past week I've been browsing through [WebElements](https://www.webelements.com/nobelium/compounds.html) just to find out some interesting facts/properties about certain elements in the Periodic Table. 


I've just come across the uncommon element [nobelium](https://www.webelements.com/nobelium/compounds.html) and it looks like it doesn't form compounds with anything despite being an actinide. For example, actinium can form Actinium Trichloride and promethium can form Promethium(III) Fluoride.


Is there a reason why nobelium is so 'special'?




[Wikipedia](https://en.m.wikipedia.org/wiki/Nobelium) reports that nobelium does form compounds, but unlike other later actinides it could adopt a +2 oxidation state as well as +3, which complicates identifying specific compounds (e.g. nobelium reacts with chlorine but the specific product is not known). The +2 state is stabilized by the full shell configuration $[\ce{Rn}]5f^{14}$. Experiments in aqueous solution seem to show a preference for the +2 oxidation state, and $\ce{No}^{2+}$ has been coprecipitated into solids. But we have yet to definitively identify a neat nobelium compound in either specific oxidation state.


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