What i the reaction of an alkene with cold, dilute, neutral potassium permanganate? [closed]








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How will an alkene react with *dilute, cold, neutral* $\ce{KMnO4}$?




The behaviour of $\ce{KMnO4}$ in a neutral medium is nearly the same as its behaviour in slightly alkaline medium.


In alkaline medium:


$\ce{3R-CH=CH-R + 2MnO4- + 2OH- -> R-CH(OH)-CH(OH)-R + MnO4^2-}$


In neutral medium:


$\ce{3R-CH=CH-R + 2MnO4- + 4H2O -> R-CH(OH)-CH(OH)-R + MnO2 + 2OH-}$


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