Name of an unsaturated cyclic compound

[![enter image description here](https://i.stack.imgur.com/siySo.png)](https://i.stack.imgur.com/siySo.png)


I deduced the name as cyclodeca-1,6-dien-3-yne. Is it correct?




You have the right name unless you need to specify the geometric isomer. 


If I may stretch you a little, consider whether to specify the relative positions of the atoms at the double-bonds, e.g. (1​*Z*,6​*Z*)-cyclodeca-1,6-dien-3-yne. It's not possible to tell which geometric isomer it is from your drawing, because you would need a clear depiction of the bond angles around the double-bonds. If this drawing is all you have to go on, you can't specify the isomer and your answer is spot on.


The below image is a model of your molecule showing the (1​*Z*,6​*E*)-cyclodeca-1,6-dien-3-yne form. You can see the difference between *E* ("opposite" or in this case "trans"), on the left, and *Z* ("together" or in this case "cis"), on the right, by looking at the shape of the chain of the four carbons nearest each double-bond. Of course, there is more to geometric isomerism than this but I hope this is a useful introduction if you've not encountered it before.


[![(1Z,6E)-cyclodeca-1,6-dien-3-yne](https://i.stack.imgur.com/AZ6nH.png)](https://i.stack.imgur.com/AZ6nH.png)


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Your answer is correct. In case of cyclic unsaturated hydrocarbon organic compound with no side group attached, then numbering of multiple bonds should be done in such a way that there will be minimum number to multiple bonds.


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