How to get the condensed electron configuration for Zinc ion

The question said "Write the condensed electron configuration for $\ce{Zn^{2+}}$I got [Ar] 4s$^2+$ 3d$^8$. Why was this the incorrect answer? Zinc lost 2 electrons and surely those electrons should go from the d orbitals?




By the time the $\ce{3d}$ orbitals are filled with electrons, the $\ce{4s}$ orbitals have become higher in energy, making it easier to remove them. Here are energy level curves for both the neutral and +1 forms of the $\ce{3d}$ atoms, with electron energy on the $y$-axis:


[![enter image description here](https://i.stack.imgur.com/Rl02F.png)](https://i.stack.imgur.com/Rl02F.png)


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you have done only wrong thing and that is sufficient to make your answer wrong .
Electron will not be removed from 3d subshell but it will be removed from 4s subshell. The reason is whenever we fill electrons we see the value of (n+l){Principal quantum number + azimuthal quantum number}, the subshell having smaller value of (n+l) gets the electroon first, butt when we have to remove an electron,it is removed froom the subshell having greatest value of n(Principal quantum number).


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