Reaction of HBr + 2,4-dimethylpent-1,3-diene yields 3 products?

My understanding is that either pi bond can react with HBr but that you still have to follow Marovnikov's rule or whatever.


I end up with 2 allylic carbocations that are actually the same molecule along with 1 unformed non allylic carbonation. From there there is only one product...


