How long does it take to saturate H2O with O3 [closed]








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Let’s assume I have one liter of distilled $\ce{H2O}$ in an stainless steel container – from the bottom side of the container I do bubble ozone trough the $\ce{H2O}$.


Of cause it is not pure O3, so let’s assume that the gas consists of:


7% $\ce{O3}$


83% $\ce{ O2}$


10%. $\ce{ N2 / NO2 / NO}$


The gas flow is about 5 liters per minute and the corona discharge consumes about 500W.


How long will it approximately take, till full saturation of the
 $\ce{H2O}$ with $\ce{O3}$ will take place?




The solubility of ozone in water as per one website is:


[![enter image description here](https://i.stack.imgur.com/h4AgR.jpg)](https://i.stack.imgur.com/h4AgR.jpg)


First thing is to establish which curve you need. In 1 m$^3$ gas you have 70 L ozone:


$\frac{70\ L\ \ce{O3}}{1\ m^3}\frac{1\ mol}{0.082\cdot 298\ L}\frac{16\cdot 3\ g\ \ce{O3}}{1\ mol}= 138\ g\ \ce{O3}/m^3$


Let us take the curve of 150 g/m$^3$ which has an ozone solubility of 30 mg/L water. 
Then:


$\frac{30\cdot 10^{-3}\ g\ \ce{O3}}{1\ L\ \ce{H2O}}\frac{1\ mol}{16\cdot 3\ g\ \ce{O3}}\frac{0.082\cdot 298\ L}{1\ mol}\frac{1\ min}{5\cdot 0.07\ L\ \ce{O3}}= 0.044\ min$


Which is about 3 seconds. 


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