Bromination of Phenylacetone

Looking at the following reaction, I understand how the product forms, however, can somebody help me understand why two products are formed? Would the identical mechanism produce the two products?


[![enter image description here](https://i.stack.imgur.com/ZUHgw.png)](https://i.stack.imgur.com/ZUHgw.png)




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Edit: This is how I understand the mechanism.


[![enter image description here](https://i.stack.imgur.com/PygK1.jpg)](https://i.stack.imgur.com/PygK1.jpg)




The mechanism that I have submitted in the edit of my post is **correct**. The reason both products are formed, is due to the the enol intermediate being planar with respect to the oxygen, allowing it to be attacked from either plane. This allows for the formation of a the so-called *racemic mixture.*


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The first step involves the formation of enol by protonation of the carbonyl oxygen. Then the electrophile adds to the enolate, and it may approach in either direction, from the top or the bottom of the plane of the enol.And so, a racemic mixture is obtained.


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