What will the correct value of spin quantum number for last electron of Na+ ion?

Electronic configuration of $Na^+$ ion is $1s^2,2s^2,2p^6,3s^0$.


I have noticed usually , we take spin quantum number as +1/2 first & then -1/2.


So , like for the above Q:It is for first 3e=+1/2 & last 3 = -1/2.


But , according to Hunds rule in my textbook. There are 2 ways spin quantum number is given I.e for N atom as example:


[![enter image description here](https://i.stack.imgur.com/wrX2o.jpg)](https://i.stack.imgur.com/wrX2o.jpg)


Electronic configuration of N = $1s^2,2s^2,2p^3$


For the last 3 electrons , either it is +1/2 or -1/2 as starting for the first 3 electrons.


So , I am having difficulty in understanding whether also for Na+ ions , we can start the order of spin in any way I.e it could be +1/2 or -1/2 for starting ?


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