Themochemistry-unknown metal [closed]








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> 
> Pellets of an unknown metal were heated to 95.0 °C and then transferred to a calorimeter containing 175 g of water at 20.0 °C. The highest temperature recorded was 23.6 °C and 96.0 g of the metal were used.
> 
> 
> a) Calculate the specific heat capacity of the unknown metal.
> 
> 
> 


(Metal)Hg=Hl(Water)


$$95\ \mathrm g\times c\times \Delta T=175\ \mathrm g\times4.19\ \mathrm{J/(g\ ^\circ C)}\times(23.6\ \mathrm{^\circ C}-20\ \mathrm{^\circ C})$$


I just wanna know how to get the change in temperature for the metal.




I think you are right so far ;


heat given by metal = heat take by water


so neglecting losses of energy ; 


$\delta T\_{metal} = 95- 23.6$ 
$\delta T\_{water} = 23.6-20 $


and by substituting values with correct units in : 
$ m\_{metal} c' \delta T\_{metal} = m\_{water} c \delta T\_{water} $ 


you should get the desired result.


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