How to draw protonated benzene (horseshoe) carbocation structure with ChemDraw?

Is there a way to draw the aromatic "horseshoe" (forgot the official name) structure of a protonated benzene cation (arenium) with ChemDraw, and not the cation with double bonds?


[![benzenium](https://i.stack.imgur.com/2uwSr.png)](https://i.stack.imgur.com/2uwSr.png)




Draw cyclohexane. Open Drawing Elements. Select 270o circle. Orient with lasso and adjust size. Insert in cyclohexane. Add H's and +.  
  
[![enter image description here](https://i.stack.imgur.com/pRwey.jpg)](https://i.stack.imgur.com/pRwey.jpg)  
  

**ADDENDUM**: For a centered structure. Draw cyclohexane, arc and + inside each other. Select them. Go to Object>align. Select L/R centered then T/B centered. Add hydrogens. See also Comments. PS: Clearly, ChemDraw does not recognize the structure as protonated benzene. Can't have everything ;).  
  
[![enter image description here](https://i.stack.imgur.com/6hwol.jpg)](https://i.stack.imgur.com/6hwol.jpg)


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That is a terrible way of drawing that intermediate. You should draw a cyclohexane, then right-click on the four bonds where the delocalization takes place and choose double -> tautomeric.[![benzenium](https://i.stack.imgur.com/6KUks.png)](https://i.stack.imgur.com/6KUks.png)


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