How does the splitting in this molecule take place?


> 
> Consider the following molecule and data:
> 
> 
> [![alkane](https://i.stack.imgur.com/hSKLu.png)](https://i.stack.imgur.com/hSKLu.png)
> 
> 
> $$
> \begin{align}
> \mathrm{H\_a} &= \pu{1.0 ppm} &\quad J\_\mathrm{ab} &= \pu{5.0 Hz}\\
> \mathrm{H\_b} &= \pu{3.0 ppm} &\quad J\_\mathrm{bc} &= \pu{8.0 Hz}\\
> \mathrm{H\_c} &= \pu{6.0 ppm} &\quad J\_\mathrm{ac} &= \pu{1.0 Hz}\\
> \end{align}
> $$
> 
> 
> Draw a splitting diagram for $\mathrm{H\_b}.$ $(\pu{1 box} = \pu{1 Hz})$
> 
> 
> 


Tried to draw the splitting diagram and ended up with this diagram:


[![My splitting diagram](https://i.stack.imgur.com/sMtjH.png)](https://i.stack.imgur.com/sMtjH.png)


I am also stuck as to how to draw the spectrum of the whole molecule as I feel $\mathrm{H\_a}$ would be triplet of triplet. Am I on the right track and how to draw the sketch of the spectrum?




According to given data, you may consider expected peak patterns are not complicated such as $\mathrm{ABX}$ or $\mathrm{A\_2B}$ patterns (more reading [look here](https://www.chem.wisc.edu/areas/reich/nmr/notes-5-hmr-12-ABX.pdf). This is simply a $\mathrm{A\_2X}$ pattern ($\delta\_X = \pu{6 ppm}$ and $\delta\_A = \pu{1 ppm}$ without geminal coupling of two $\ce{H\_b}$ protons), and hence, peak is a $dt$ for $\ce{H\_b}$ as depicted below with relative heights of the peaks:


[![Hb peak](https://i.stack.imgur.com/d6vSz.jpg)](https://i.stack.imgur.com/d6vSz.jpg)


Similarly, $\ce{H\_c}$ is also a $dt$ resonance with $J = 1 \text{ & } \pu{8 Hz}$ and $\ce{H\_a}$ is a $tt$ with $J = 1 \text{ & } \pu{5 Hz}$. OP should able to figure out the intensities of relevant peaks. 


**A valuable reference:**


Roy H. Bible, Jr., Ph.D., In *Interpretation of NMR Spectra: An Empirical Approach*; Springer Science: New York, NY, 1965 (<https://doi.org/10.1007/978-1-4684-8288-1>) (Note: Most relavent to this question is chapter 4 of the book titled "Higher-Order Spin Patterns and Multiple Resonance").


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