What factors influence the resultant oxidation state of Fe in 3Ca(OH)2+2FeCL3?


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> $\ce{3Ca(OH)2 + 2FeCl3 -> 2Fe(OH)3 + 3CaCl2}$
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What factors influence the resulting oxidation state in the iron hydroxide molecule in this reaction? Since iron's oxidation state ranges from +2 to +6, and there exists iron hydroxide (II), how do we know what the oxidation state will be in this reaction? 


Would this equation yield $\ce{Fe(OH)2}$ under some conditions? 


I [googled and found](https://sites.google.com/site/himulacom/zvonok-na-urok/9-klass---vtoroj-god-obucenia/urok-no52-oksidy-gidroksidy-i-soli-zeleza-ii-i-zeleza-iii) that in order to obtain $\ce{Fe(OH)2}$ we react $\ce{FeCl2}$ and $\ce{KOH}$ with no air present:



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> $\ce{FeCl2 + 2KOH -> 2KCl + Fe(OH)2}$ 
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Would my initial equation yield $\ce{Fe(OH)2}$ in the absence of air? If yes, why? 




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The oxidation state of $\ce{Fe}$ before the reaction is +3. 


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