What is the hybridization state of the carbon atoms in [10]annulene?

I know that one of the more stable structures of [10]annulene or cyclodecapentaene is planar boat-shaped. But that means the hybridization state of the carbons must have changed to suit the geometry. What does it change to? And how are the hybridized orbitals distributed such that the double bonds remain intact? 


Edit: I have encountered this molecule only once and am not familiar with the naming convention. For much the same reason, I don't know the exact structure of the most stable isomer of the compound. So even though I was more interested in the boat-shaped isomer of the compound, I think to do away with the ambiguity of the question, I should mainly ask for the most stable isomer of the molecule, viz., trans,cis,cis,cis,cis-isomer. 


