Does restriction on spin in orbits exist?

For a valence electron in Antimony (Sb) with the electron configuration:


$Kr(5s)^2(4d)^{10}(5p)^3$


The 3 valence electrons have the quantum numbers $n=5,l=1,m=1$, resulting in the following possibilities for $(n,l,m\_l,m\_s)$:


$(5,1,−1,−\frac{1}{2});(5,1,−1,\frac{1}{2});(5,1,1,−\frac{1}{2});(5,1,1,\frac{1}{2});(5,1,0,−\frac{1}{2});(5,1,0,\frac{1}{2})(5,1,−1,−\frac{1}{2})$


$(5,0,0,−\frac{1}{2});(5,0,0,\frac{1}{2})$


Then looking at the actual quantum numbers of Sb (from a former exam) it is given as:


$(5,1,−1,-\frac{1}{2});(5,1,1,-\frac{1}{2});(5,1,0,-\frac{1}{2})$


$(5,0,0,−\frac{1}{2});(5,0,0,\frac{1}{2})$


Where did the quantum sets with $l=1$ and $m\_s=−\frac{1}{2}$ go? When I look at the valence electrons in Kr the set is **with** $l=1$ and $m\_s=−\frac{1}{2}$:


$(4,1,−1,−\frac{1}{2});(4,1,−1,\frac{1}{2});(4,1,1,−\frac{1}{2});(4,1,1,\frac{1}{2});(4,1,0,−\frac{1}{2});(4,1,0,\frac{1}{2})
(4,0,0,−\frac{1}{2});(4,0,0,\frac{1}{2})$


Summing up the question: Why can the valence electrons in Kr have $l=1$ and $m\_s=−\frac{1}{2}$ and the ones in Sb not? Perhaps it is a mistake in the exam?


