Can NaH open the epoxide ring to form alcohol? If so, how?

I was looking at the organic chemistry 8th Ed textbook by Paula Yurknais Brucie. On page 509, I found this:


[![enter image description here](https://i.stack.imgur.com/v35BU.png)](https://i.stack.imgur.com/v35BU.png)


I think about it for a while and I am doubting that it is wrong. I believe the hydride ion itself cannot act as a nucleophile for SN2. (not really sure but I guess it is too small and too basic to work as a nucleophile, it should be much easier to attack hydrogen rather than carbon for hydride ion)


Is this reaction is possible with $\ce{NaH}$ in solvents other than water and alcohol? If so, how does the hydride ion open the epoxide ring? (hoping for an answer with mechanism)


And I am specifically talking about hydride ion (or hydrogen anion). Not sodium borohydride $\ce{NaBH4}$, lithium aluminum hydride $\ce{LiAlH4}$, or other metal hydrides.




Further to my comments above, I am going to offer my opinion that the book is wrong and the epoxide is not opened by sodium hydride as depicted. I have failed to find any literature examples of such a reaction and, in 40+ years as a synthetic chemist, I can recall no reactions in which $\ce{NaH}$, unmodified by other reagents, acts as a source of nucleophilic $\ce{H-}$.


Can anyone produce a literature example?


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