Organometallic Synthesis: Cp2Ti(I)Me from TiCl4

I've been working on this synthesis question for a couple days but I'm a little stuck. The question is:



> 
> Using only $\ce{TiCl\_{4}}$, $\ce{NaCp}$, $\ce{PhLi}$, $\ce{MeI}$, and $\ce{EtMgBr}$, synthesize $\ce{Cp\_{2}Ti(I)Me}$. (should take 4 to 6 steps)
> 
> 
> 


But it seems to me the synthesis can be done in 2 steps like so:


$\ce{TiCl\_{4} + 2NaCp -> Cp\_{2}TiCl\_{2}}$


$\ce{Cp\_{2}TiCl\_{2} + MeI -> Cp\_{2}Ti(I)Me}$


Which doesn't match the question's "4-6 steps" note, so I'm not sure what I'm missing.


