Reduction of carbamate with LAH

The products of the reduction of esters with $\ce {LiAlH4}$ and the products of the reduction of amides with $\ce {LiAlH4}$ are vastly different. The former reduction cleaves the ester and produces two alcohols while the latter reduction produces an amine with the carbonyl group of the original amide replaced with $\ce {CH2}$. A [carbamate](https://en.wikipedia.org/wiki/Carbamate) seems to display both chemical behaviour of esters and amides. I am curious to know what would be the mechanism by which reduction of carbamate with $\ce {LiAlH4}$ takes place and what would be the products of such a reduction. 




Carbamates are usually reduced to *N*-methyl groups. There are numerous examples:


[![Reduction of methyl carbamate](https://i.stack.imgur.com/zw65I.png)](https://i.stack.imgur.com/zw65I.png)


[*J. Am. Chem. Soc.* **2012,** *134* (16), 6936–6939](https://doi.org/10.1021/ja301387k)


[![Reduction of t-butyl carbamate / Boc](https://i.stack.imgur.com/ukrbt.png)](https://i.stack.imgur.com/ukrbt.png)


[*Org. Lett.* **2012,** *14* (18), 4834–4837](https://doi.org/10.1021/ol302165d)


But it is not always a given. In this next example, the nitrogen is part of a three-membered ring (aziridine). These nitrogens are better leaving groups than usual, cf. [Ketone/aldehyde synthesis from N-acylazetidines or aziridines](https://chemistry.stackexchange.com/q/78953/16683) where the same kind of reactivity is observed:


[![Reduction of aziridine carbamate](https://i.stack.imgur.com/uUtdC.png)](https://i.stack.imgur.com/uUtdC.png)


[*Angew. Chem. Int. Ed.* **2002,** *41* (24), 4683–4685](https://doi.org/10.1002/anie.200290015)


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