Diazo Coupling reaction with para-substituted phenol?

Usually Diazo coupling occurs at *para*-position unless the *para*-position is occupied, in which case coupling occurs at *ortho*-position. 


While solving questions I found in both the cases as shown, the coupling occurred at *ortho*-position of the $\ce{-OH}$ group:


[![enter image description here](https://i.stack.imgur.com/klYyY.jpeg)](https://i.stack.imgur.com/klYyY.jpeg)


So in case of phenol, is it possible that in all cases the coupling will occur at *ortho*-position with respect to the $\ce{-OH}$ group in phenol, irrespective of whether the other group has stronger +M Effect than $\ce{-OH}$?


I am not sure but I think this is happening because of Hydrogen bonding as shown below. But in that case it should also happen with the $\ce{-NH2}$ group. Is this the reason or there is some other?


[![enter image description here](https://i.stack.imgur.com/HImMw.jpg)](https://i.stack.imgur.com/HImMw.jpg)


