explain the reaction mechanism [duplicate]








**This question already has an answer here**:
 
 




[Preparation of alkyl halide from alcohols](/questions/2676/preparation-of-alkyl-halide-from-alcohols)

 (1 answer)
 

Closed 9 years ago.



$\ce{ROH + NaBr + H2SO4 -> RBr + NaHSO4 + H2O}$


What is exactly the reaction mechanism.


Is it $\ce{NaBr + H2SO4 -> NaHSO4 + HBr}$ and then 


$\ce{HBr}$ reacts with $\ce{ROH}$?


If yes the why in the reaction of $\ce{NaBr}$ and $\ce{H2SO4}$ does $\ce{H2SO4}$ oxidise $\ce{NaBr}$?





> 
> HBr reacts with ROH?
> 
> 
> 


Exactly. It's just a nucleophilic substitution.


 3