Confusion in finding Effective Atomic Number of a complex

In finding EAN (Effective Atomic Number) of metal in complexes, I came over one compound:
$\ce{[(CO)2RhH2Rh(CO)3 Cl]^+}$


Here the hydrogen are shown as bridging atoms and we are supposed to calculate EAN of individual rhodium atoms
The main problem is that hydrogen has a single electron, then how can it form a bridging bond?


I thought, maybe hydrogen is giving electron to one of the rhodium atoms and other rhodium is giving lone pair to hydrogen, but this doesn't seem like a good argument.


