Explanation of metallic crystal structures using orbitals and electron configuration

There has to be a direct relation between metallic crystal structure formation and electrons in orbitals. For instance, we know that **Fe2+** forms *body centered cubic* or *bcc* structure with the coordination number of 8, which means each Fe atom bonds with 8 others after getting rid of the two electrons in the 4S orbital.


The electron configuration of one Fe2+ would look as follows:


1s2 2s22p6 3s23p63d6


The problem is, that I do not see how Fe2+ would react with 8 others, based on the electron configuration and the octet rule, to form bcc structure.


