Reaction of silicon dioxide with sodium hydroxide

I recently learnt about this equation but I would like to know how NaOH reacts with the 3d structure of SiO2 and gives Na2SiO3 and H2O.


[![enter image description here](https://i.stack.imgur.com/blaIA.png)](https://i.stack.imgur.com/blaIA.png)


Can anyone explain with simple diagram how NaOH forms new bond in SiO2 to give the above mentioned products?Like how they replace, displace etc in the 3d structure.




To use simple terms, $\ce{NaOH}$ breaks the "vertical" bonds $\ce{Si−O}$ without touching the "horizontal" bonds of your picture. As a consequence, sodium silicate is not $\ce{Na2SiO3}$. It has the structure of a long polymer $\ce{Na\_{2n}(SiO3)\_n}$. The polymeric ion $\ce{(SiO3^{2−})\_n}$ is
made of long chains of atoms $\ce{-O-Si-O-Si-O-Si-O -}$etc., where each $\ce{Si}$ atom is still attached to two negatively charged oxygen atoms $\ce{O^−}$, one "above" and one "under" the main $\ce{-O-Si-O-Si-O -}$chain. And a positive ion $\ce{Na+}$ is placed near each such oxygen atom.


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