Cobalt Oxalate / Potassium Permanganate Titration

My class just did a lab today where we mixed cobalt oxalate with $40~\mathrm{mL}$ of $\ce{H2SO4}$ and then titrated it with $\ce{KMnO4}$ (potassium permanganate). I need the mole ratio of cobalt oxalate and $\ce{KMnO4}$ and am not sure how to set up the equation. She provided us with this formula with 3 variables A,B,C - 
`Co(a)(C2O4)(b) * (c)H2O` 
but I am not sure what to do with it. I am also confused as cobalt oxalate appears as $\ce{CoC2O4}$ in her equation yet Google says it's $\ce{H2C2CoO6}$. 


My table in my lab book is asking me for "Moles Oxalate Present" , "Mass of Oxalate in Sample" , and "Percent Mass of Oxalate in Sample (%)". It is also referring to the "Mass of transition metal oxalate used" which we took during the actual lab. (I guess this lets me know that it solely wants oxalate and to calculate these values aside from cobalt oxalate?)


I am very confused and if any part of this question needs to be cleared up I can certainly do so.


I can provide any/all data that I took during the lab, but explaining conceptually will still do me some good here. I really just don't know where to start with all this data.


My book also gave me this formula for the reaction of oxalate ions with permanganate ions:


$$\ce{5C2O4^{2-} + 2MnO4- + 16H+ -> 10CO2 + 2Mn^{2+} + 8H2O}$$


Will this factor at all into my calculations?


