What happens to the Lithium halide salt when reacting Lithium metal with alkyl halides?

In organic chemistry, I learned a lot of useful reactions but unfortunately I didn't get to try many of them first hand (what's sad is I am a Chemistry major too). I've searched the internet back and forth for the answer to this question which I am fairly sure I know the answer to, but I thought I would just double check.


When reacting lithium with an alkyl halide (the reaction requires 2 mol Li metal per 1 mol of the alkyl halide), one mol of lithium forms the organometallic compound while the other forms the lithium halide salt. The reaction takes place in diethyl ether, so my question is does the halide salt fall out of solution or not? I would assume so considering diethyl ethers low dielectric constant in combination with the ionic character of Lithium salts, but I thought I would ask in hopes someone on here has performed this reaction first hand. Thanks!


Edit: So I read LiCl has minimal solubility in diethyl ether, but LiBr is moderately to highly soluble which makes absolutely no sense to me. I guess perhaps the lone pairs on oxygen might play a role in this but then again why wouldn't this have the same affect on LiCl? 


