Kinetic energy of an ideal gas

I've heard that the kinetic energy of any different gases are the same



> 
> All gases at a given temperature have the same average kinetic energy.
> 
> 
> 


But if we have 2 moles of hydrogen and 4 moles of helium in a container at a specific temperature will the kinetic energies become the same?
I think it cannot be as the **n** is different..


As the kinetic energy is ![](https://i.stack.imgur.com/1ARp9.jpg)
3nrt/2


This might be a small question but this has been a conflict between my friends..
![enter image description here](https://i.stack.imgur.com/fnIgy.jpg)




The answer is in front of you. $E\_v$ is the **Total translational** kinetic energy not the **Average** kinetic energy. If you want **average translational** kinetic energy per mol this is given by: $E\_v/n$ or $3/2RT$.


 1