Trichloroacetic acid aqueous solution

I have bought some ~~anhydride of~~ trichloroacetic acid ([TCA](https://en.wikipedia.org/wiki/Trichloroacetic_acid)) and would like to prepare an acidic solution. My problem is, that I don't know how much "powder" to mix with how much water to produce an x% acidic solution of TCA. I am aiming for as close to 100% as possible. From what I know, I need to measure pH to derive the concentration (I only have some litmus paper to do that)? Does there exist formulas or tables, that I can follow? Sources of these?


EDIT: Based on a comment, I obtained these values:


I have bought 1 kg of TCA powder of



```
1000 g / 163.38 gmol^-1 = 6.1207 mol
18.01528 gmol^-1 * 6.1207 mol = 110.27 g of water

```

somehow I need to dissolve 1 kg of powder into 110.27 mL of water. How can that work? I doubt 1 kg of powder can be dissolved in such a tiny amount of water.


EDIT2: Wikipedia says `Solubility in water: Soluble in 0.1 parts`. Does this mean I need `0.1 * TCA amount` for a 100% solution? That would mean I need to dissolve 1 kg of TCA in 100 mL of water.


EDIT3: If you have any idea about the true solubility of TCA, please help, there seems to be a lot of misinformation out there. 1000 g / 100 mL seems very strange to me! You can see the strange data [here](https://pubchem.ncbi.nlm.nih.gov/compound/trichloroacetic_acid#section=Solubility), from multiple sources.


EDIT4: I have asked my Chinese supplier about how they prepare their TCA solution and he said they use 120g - 154.1g / 100 mL recipe for a "standard" solution. The concentration can then be calculated by mole or by mass, but naturally is never 100%. The only way a 100% liquid TCA could exist would be to melt it down into liquid form.


