Structure of OSF4

Recently I had given a test where I was asked to specify the hybridisation of $\ce{OSF4}$ and its structure.
I guessed that the structure would be trigonal bipyramidal, but I was unsure since I hadn't dealt with molecules with double bonds.


So my first question is: Should having double bonds in the structure affect my geometry considerations of the structures or will it be the same as in structures only containing single bonds (say $\ce{PCl5}$) ?


Also, if I am supposed to draw its structure then where would I place the double bonded oxygen? Axial or equatorial position? Why? 
I know that when lone pairs are considered they are placed at the equatorial position (after considering repulsions). Is there anything common in this case?





> 
> So my first question is: Should having double bonds in the structure affect my geometry considerations of the structures or will it be the same as in structures only containing single bonds (say ) ?
> 
> 
> Also, if I am supposed to draw its structure then where would I place the double bonded oxygen? Axial or equatorial position? Why? I know that when lone pairs are considered they are placed at the equatorial position (after considering repulsions). Is there anything common in this case?
> 
> 
> 


The answer to your question is NO. A double bond shouldn't make any difference. It would be a **Trigonal Bipyramidal** where the 2 F's will occupy the axial positions according to ***Bent's Rule*** and the remaining two F's along with the Oxygen atom will occupy the equatorial position.


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