Would a hypothetical Og2 +235 form a chemical bond?

In a hypothetical (?) Og2+235 we would have a simple sigma bonding orbital occupied by one electron (leading to a bond order of 1/2). But how to take into account the giant repulsion of the two nuclei? Generally how are nucleis taken into account for energy calculations from molecular orbitals in MO theory? So far I've always read about the electrons but very few about the nuclei in the system.


Same in He23+, half bond order but very large repulsion. My intuition says that He21+ should be more stable, even if both have the **same bond order**.


Where in the framework of MO theory is exactly that taken into account? How does nuclei repulsion change the MO energy scheme?




I would not bet on it. We apparently can't even get $\ce{He2^{3+}}$, let alone higher single-electron diatomic ions. From [Wikipedia](https://en.wikipedia.org/wiki/Helium_compounds):



> 
> $\ce{He2^+}$ was predicted to exist by Linus Pauling in 1933. It was discovered when doing mass spectroscopy on ionised helium. The dihelium cation is formed by an ionised helium atom combining with a helium atom: $\ce{He^+ + He -> He2^+}$.[[1](https://doi.org/10.1016/j.ijms.2004.07.012)]
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> The diionised dihelium $\ce{He2^{2+}} (1Σ\_g^+)$ is in a singlet state. It breaks up $\ce{He2^{2+}->2 He^+}$ releasing 200 kcal/mol of energy. It has a barrier to decomposition of 35 kcal/mol and a bond length of 0.70 Å.[1]
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Thus even with only two positive charges the helium dimer is prone to breaking up due to electrostatic repulsion. Although the dication above is metastable, we should expect the stability to only become worse with an additional positive charge and only one bonding electron instead of two.


A simple classical electrostatic calculation is instructive. Suppose you have a negative charge and two positive charges, the latter equidistant from the negative charge on opposite sides. The net force is attractive if all charges are one unit, but this net attraction is lost if we give two or more (and certainly 118!) units to both positive charges. The true quantum mechanical calculation is of course much more complicated, but can give only less favorable results because as the positive nuclear charges approach the electron cloud cannot stay fully between them. Thereby $\ce{H2^+}$ is predicted to be the only single-electron homonuclear diatomic ion that remains bound.


**Cited Reference**


1. Grandinetti, Felice (October 2004). "Helium chemistry: a survey of the role of the ionic species". *International Journal of Mass Spectrometry*. **237** (2–3): 243–267. Bibcode:2004IJMSp.237..243G. <https://doi.org/10.1016/j.ijms.2004.07.012>.


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