The overall Gibbs free energy in Gluconeogenesis

Gluconeogenesis is an exergonic process but I wonder what is the overall Gibbs free energy in step 3 and step 10?


I know there’s about $\pu{2\times ( -31.4 ) kJ/mol}$ for 2 pyruvates convert to 2 phosphoenolpyruvates (PEP). The reverse reaction path would vary in gluconeogenesis, but there’s no information on the web on this reverse energy.


Gluconeogenesis step 10:


$\ce{2 Pyruvate + 4 ATP + 2 GTP ->[Acetyl CoA、Biotin Pyruvate carboxylase][Mg^{2+}] 2PEP + 4ADP + 2GDP + 6Pi}$


Step 3:


$\ce{\mathrm{F1,6BP} + H2O ->[Fructo-1,6-bisphosphatase] \mathrm{F6P} + Pi}$


