How to get (2R,3R)-2,3-dibromobutane from but-2-yne?

What I had in mind was to form but-2-ene with $\ce{H2}$ and Lindlar's catalyst and then simply add bromine ($\ce{Br2}$). But this addition, if I'm not mistaken, is a trans-addition. So I would end up with (2*R*,3*S*)-2,3-dibromobutane instead of (2*R*,3*R*).


Note that this is (2*R*,3*S*)-2,3-dibromobutane: 


[![(2R,3S)-2,3-dibromobutane](https://i.stack.imgur.com/dz5RF.png)](https://i.stack.imgur.com/dz5RF.png)


Have I made a mistake, or is there something wrong in my way of thinking? If my solution is wrong, how could I get (2*R*,3*R*)?




I think I figured it out. Lindlar is a cis-addition so one would not obtain a (2*R*,3*S*), but rather (2*S*,3*S*) and (2*R*,3*R*) which happen to be enantiomers. 


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