Why does free-radical chlorination of isopropyl bromide give 1-bromo-2-chloropropane? [closed]








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**Source:** Morrison and Boyd - Chapter Alkanes - exercise no. 15



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> Free-radical chlorination of either n-propyl or isopropyl bromide gives 1-bromo-2-chloropropane, and free-radical chlorination of either isobutyl or tert-butyl bromide gives 1-bromo-2-chloro-2-methylpropane. What appears to be happening? Is there any pattern?
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I have really no idea how this can be happening.


