Question on chemical equilibrium [closed]








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8 moles of so2 and 4 moles of O2 are mixed in a closed vessel.the reaction proceeds at constant temperature. By the moment when equilibrium sets in,80% of the initial amount of so2 enters into the reaction. The equilibrium pressure would be? My attempt: reaction will be 2so2+O2---->2so3. There will be 1.6mole of so2,0.8 mole of O2 remaining and 6.4 mole of so3 will be formed. Now how to find the equilibrium pressure? 


