Why is more than one product formed in Swarts Reaction?

I have got a very clear idea about Swarts reaction for monohalo compound. But I found the following reaction in Chrome
[![Swarts reaction](https://i.stack.imgur.com/3GBGH.png)](https://i.stack.imgur.com/3GBGH.png)


Now, my question is why are 2 products formed? Secondly why is there no trifluoro compound? What is the possible mechanism for this reaction?


Source: <https://protonstalk.com/wp-content/uploads/2021/02/image1-e1612596758363.png>
[Source of the image](https://www.frontiersin.org/articles/10.3389/fchem.2018.00114/full)




Since $\ce{SbCl5}$ is a Lewis acid, we can consider a carbocation mechanism.


In the first stage, a chlorine atom is preferentially taken off the $\ce{CCl2}$ carbon because then the carbocation is stabilized by pi back-donation from the other chlorine. The antimony in $\ce{SbF3}$, being in a lower oxidation state and less acidic than its counterpart in $\ce{SbCl5}$, gives off a fluoride ion to restore neutrality to the organic compound.


In the second stage, the carbocation is stabilized by pi back-donaation from the fluorine, which is very electronegative but has available electrons and good overlap with the carbon. The $\ce{R}$ group lacks lone pairs and is less effective at stabilizing the carbocation, so difluorination at what was originally the $\ce{CCl2}$ carbon is a likely end point.


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