Surface-dependency of kinetic in speed law?

we can comprehend the quantitative dependency of the kinetic of a chemical reaction through the speed law: $v(t) = k \cdot c(...)^k \cdot c(...)^n$ 


Here I used the concentration $c$ for that take place in aqueous phases. For the gas phase, I can use $v(t) = k \cdot p(...)^k \cdot p(...)^n $ All is fine, moreover I can convert $p$ into $c$ through $pV=nRT$


But what is with solid-solid reaction? Here the "reaction surface" is the crucial key word. But how can I express this in the speed law which I written above for aqueous and gas reaction? Or is this impossible for solid-solid reaction in this way?


Thank for your answers!


