How did you convert primary alcohol using HCl (with ZnCl2)?

I kinda feel weird for this type of question. When primary OH (alcohol) is converted with HCl (with ZnCl2), how did the free Cl-ion come from? If, it is came from HCl, since when we get rid of the H from HCl?
[![enter image description here](https://i.stack.imgur.com/mLvff.png)](https://i.stack.imgur.com/mLvff.png)
[![enter image description here](https://i.stack.imgur.com/I9Ub5.png)](https://i.stack.imgur.com/I9Ub5.png)




Though the [Lucas' reagent](https://en.wikipedia.org/wiki/Lucas%27_reagent) is a solution of *concentrated* $\ce{HCl}$ and $\ce{ZnCl2}$, it still is an aqueous solution containing $\ce{Cl^-}$, because


* as a strong acid, practically all $\ce{HCl}$ in the aqueous phase dissociated \*
* $\ce{ZnCl2}$ is well water soluble


\* One can purchase solutions of HCl in organic solvents which (depending of the solvent) may prohibit the dissociation. An example of such a "dry solution" is $\ce{HCl}$ in diethyl ether ([entry at Sigma](https://www.sigmaaldrich.com/US/en/product/sigald/455180)).


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