VT graph thermodynamics

If we have one mole monoatomic ideal gas was taken through process AB as shown in the figure then ∆ S is positive and work is also positive but how can we find the value of work and heat absorbed as pressure is changing .k![enter image description here](https://i.stack.imgur.com/iNtAL.jpg)




Since you know the number of moles of ideal gas, you can find the inital and final pressures with the ideal gas law: $PV = nRT$. For entropy you may first take that $U = \frac{3}{2} nRT$, and that $dU = \delta Q + \delta W$. $ $ $\delta Q $ and $ \delta W$ may be substituted by $\delta Q = T \mathrm{d}S$, and $\delta W = -p\mathrm{d}V$. This should be enough for you to solvew the problem.


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