Peak at m/z = 39 in mass spectrum of 3-chloropropene

I've noticed that in the mass spectrum of 3-chloropropene, there is a peak at m/z = 39, which to me, indicates the formation of the C3H3 ion. 


However, given that 3 bonds would have to be broken to form this ion, how can the frequency of this cleavage be explained?


[![enter image description here](https://i.stack.imgur.com/A9QsW.png)](https://i.stack.imgur.com/A9QsW.png)




It would indeed be $\ce{C3H3^+}$ assuming predominant isotopic species. Although there can be other isomers, the cyclic isomer, the [cyclopropenyl cation](https://en.wikipedia.org/wiki/Cyclopropenium_ion) is strongly stabilized by aromaticity.


As PLD comments, there are really only two steps, not three, to forming this cation. The allyl cation ($\ce{C3H5^+},m/z=41)$ is first obtained by loss of the chlorine atom plus an electron. The aromatic cyclopropenyl cation noted above is then obtained by loss of $\ce{H2}$.


 6