Finding out the final product

The question is to find out the final product $T$ in the following series of reactions.


[![enter image description here](https://i.stack.imgur.com/QAJqs.jpg)](https://i.stack.imgur.com/QAJqs.jpg)


I am provided the following options to choose from


[![enter image description here](https://i.stack.imgur.com/K28Jz.jpg)](https://i.stack.imgur.com/K28Jz.jpg)


With alcoholic $\ce{KOH}$ elimination will occur and with $\ce{KOH}$ syn diol will be formed in place of double bonds.I am unable to see what will $\ce{CaO}$ do to the syn diol.I had an idea that it is used for decarboxylation hence the final product should have 1 carbon less but I am unable to get the right answer.Any ideas?Thanks.




Lets see this step-by-step. 


Bromocyclohexane is reacted with alcoholic KOH. This, as you would know, results in the formation of an *alkene* by elimination reaction. Product P would be **Cyclohexene**. 


Cyclohexene is heated with KMnO4. You might think a cis-1,2-cyclohexanediol would form, and indeed it does. But vigorous oxidation provided by the heat cleaves the C-C bond between the two hydroxy groups and essentially converts into **1,6-hexanedioic acid** (product Q, a.k.a adipic acid). 


Calcium Oxide, being a pretty strong base, reacts with the dicarboxylic acid and forms a salt**calcium adipate** (product R)


Heating a calcium salt of any carboxylic acid results in the *elimination of a* $\ce{CaCO3}$ *molecule*, and forms a ketone. If you take calcium adipate, upon heating would give **cyclopentanone**(product S). 


Now, cyclopentanone, just like any other carbonyl compound with α-hydrogens, undergoes an aldol reaction, heating which would result in the formation of the compound given in option (B). 


Here is the complete reaction mechanisms:
![enter image description here](https://i.stack.imgur.com/p8hct.jpg)


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