Why am I getting a triplet instead of a singlet on NMR for aryl HH2-group?

I am trying to interpret an $\ce{^1H}$-$\mathrm{NMR}$ spectrum on the molecule 4-amino-*N*-(2-chlorophenyl)benzenesulfonamide that I produced in a lab session. I have managed to assign all the hydrogen atoms to their peaks with reasoning but one, the 4-amino-group. The only peak left is a triplet, which has to be signal due to the 4-amino but this should be a singlet as there are no neighbouring hydrogen atoms. I have used software to generate a $\ce{^1H}$-$\mathrm{NMR}$ spectrum and it is coming up with the peak at the same position as my lab generated $\ce{^1H}$-$\mathrm{NMR}$, but as a singlet. Why is this triplet present in my lab $\mathrm{NMR}$ spectrum?


Is this to do with possible hydrogen bonding between the $\ce{NH2}$ and water? I do have a slight broad peak at $\pu{4.1 ppm}$.




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Edit (02/04/22)


ChemDraw predictive NMR:


[![ChemDraw predictive NMR](https://i.stack.imgur.com/k4Vzc.jpg)](https://i.stack.imgur.com/k4Vzc.jpg)


Lab generated NMR:


[![Lab generated NMR](https://i.stack.imgur.com/8ldHp.jpg)




To understanding the OP's problem of corresponding $\ce{^1H}$-$\mathrm{NMR}$, it was nice exchange of comments between OP and orthocresol. I agreed of all advices given by orthocresol. Yet I'm bothered by the large and significant signal at about $\pu{2.0 ppm}$, which was assigned as $\mathrm{DMSO}$-$d\_5$ signal by OP. However, it is known fact that $\mathrm{DMSO}$-$d\_5$ signal appeares around $\pu{2.5 ppm}$, which is exactly in the spectrum but errouniously assigned as signal of $\ce{CH3}$-group of intermediate with a question mark by OP. I donn't agree with these assignment of OP and my thoughts are given as follows:


I think OP's deacetylation experiment didn't work at all (only a trace of product appears). My reasoning is due to the appearence of two-proton doublet at around $\pu{7.7 ppm}$ due to the $\ce{H}$-7 and $\ce{H}$-7'. If acetamide group is removed, the lone pair of free $\ce{NH2}$-group is available and mesomeric effect would sheilded $\ce{H}$-7 and $\ce{H}$-7' positions (increasing electron density) more than that in phenyl nucleus. I'd expect that signal to be more at around $6.5$-$\pu{7.0 ppm}$. Therefore, I think the $\ce{^1H}$-$\mathrm{NMR}$ spectrum provided by OP is simply the unreacted starting material (acetamide intermediate) as I assigned the peak as follows:


[![Suggested peak of NMR](https://i.stack.imgur.com/yd6H7.jpg)](https://i.stack.imgur.com/yd6H7.jpg)


I think the $\mathrm{NMR}$ signal due to acetamide proton $(\ce{CH3CONH}-)$ should be burried in $7.0$-$\pu{7.5 ppm}$ reagion. It is probably the sharp singlet around $\pu{7.25 ppm}$ to my best guess (comparision of integrations at $7.0$-$\pu{7.5 ppm}$ reagion and $7.5$-$\pu{8.0 ppm}$ reagion would give the confirmation).


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