
### Instruction: help me answer this question The base of an equilateral triangle with side 2a lies along the y-axis, such that the mid-point of the base is at the origin. Find the vertices of the triangle., think step by step
### Assistant:  , The answer is Let the triangle be ABC with base BC lying along the y-axis. O (0, 0) is the mid-point of the base BC. Let the third vertex be A (x, y). Side of the triangle is 2a units. Applying distance formula, we get x^2 + (y-a)^2 = a^2. Therefore, the coordinates of A are (a, 0) and the coordinates of B and C are (0, a) and (0, -a) respectively.
