
### Instruction: help me answer this question The 6-digit number is to be formed out of which unit place is fixed as 0. The remaining 5 places can be filled by 1, 3, 5, 7 and 9. Here, n = 5 and the numbers of choice available are 5. So, the total ways in which the rest of the places can be filled are 5P5, think step by step
### Assistant: We have 5 places and 5 numbers to fill them. This is a permutation problem because the order matters. The number of ways to arrange n objects is nPn. So, the total ways to fill 5 places with 5 numbers is 5P5 = 120. , The answer is The total ways in which the rest of the places can be filled are 120
