
### Instruction: help me answer this question The relation f is defined by f = {(x, y): y = x^2, 0 ≤ x < 3} and g is defined by g = {(x, y): y = x, 1 ≤ x ≤ 4}. Show that f is a function and g is not a function., think step by step
### Assistant: A relation is a function if for every value of x in its domain, there is only one value of y. In this case, f satisfies this property and hence is a function, while g does not and hence is not a function. , The answer is The relation f is a function as for every value of x in the given domain (0 ≤ x < 3), there is only one value of y such that (x, y) belongs to f. However, the relation g is not a function as for x = 2, there are two values of y (2 and 3) such that (x, y) belongs to g.
