
                ### Instruction: help me answer this question A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. Find the probability that the sum of numbers that turn up is
(i) 3.
(ii) 12., think step by step
                ### Assistant:  , The answer is The sample space S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
n(S) = 12

(i) Let 'P' be the event having the sum of numbers as 3.
n(P) = 1
P(P) = n(P)/n(S) = 1/12

(ii) Let 'Q' be the event having the sum of the number as 12.
n(Q) = 1
P(Q) = n(Q)/n(S) = 1/12
