
### Instruction: help me answer this question Foci (0, ±13), the conjugate axis is of length 24., think step by step
### Assistant: Given foci (0, ±13) are on the y-axis, and the conjugate axis is of length 24, so the equation of the hyperbola is of the form y2/a2 – x2/b2 = 1. Here, a = 12 and c = 13. We know that a2 + b2 = c2, so b2 = 25. , The answer is The equation of the hyperbola is y2/25 – x2/144 = 1.
