
### Instruction: help me answer this question Draw a quadrilateral in the Cartesian plane whose vertices are (– 4, 5), (0, 7), (5, – 5) and (– 4, –2). Also, find its area., think step by step
### Assistant:  , The answer is Let ABCD be the given quadrilateral with vertices A (-4,5) , B (0,7), C (5,-5) and D (-4,-2). To find the area, draw the diagonal AC. Area (ABCD) = area (∆ABC) + area (∆ADC). Area of ∆ ABC = ½ [x1 (y2 – y3) + x2 (y3 – y1) + x3 (y1 – y2)] = 29 square units. Area of ∆ ACD = ½ [x1 (y2 – y3) + x2 (y3 – y1) + x3 (y1 – y2)] = 63/2 square units. Area (ABCD) = 121/2 square units.
