content_image/301416.jpg content_image/301417.jpg content_image/301418.jpg
<img src='content_image/301416.jpg'>

The process is identical to that in section 3.2.1 once we have made the following ans¨ atz for the holographic gauge field: 

<img src='content_image/301417.jpg'>

ϵ µ is the polarization vector, defined only in the Minkowski directions. g ( ρ ) is determined from the equations of motion, just as f ( ρ ) was for the scalars. In this geometry, the mass spectrum of the vector mesons is exactly the same as that for the scalars: 

<img src='content_image/301418.jpg'>

This is to be expected since they both form part of an N = 2 hypermultiplet. In the more complicated geometries that we will study later the N = 2 hypermultiplet will be broken, and then the masses will differ. 

