content_image/353719.jpg content_image/353716.jpg content_image/353717.jpg content_image/353718.jpg
<img src='content_image/353719.jpg'>

for p = 1 + y$_{1}$/n + · · · and q = 1 + z/n as before. Note that a = − 2 corresponds to a binomial distribution, so we are usually interested in the case − 2 < a < 0. After expanding the equation we receive as before, from the first term of the left and right hand side, the equation 

which has the solution y$_{1}$ = 2 w − a where 

The second equation, which is slightly longer, has the solution 

<img src='content_image/353716.jpg'>

<img src='content_image/353717.jpg'>

<img src='content_image/353718.jpg'>

