content_image/355857.jpg
where (1 − x ) comes from I 3 L = 0 , I 3 R = − 1 , Q = 0. For Z ′ → ξ + $_{R}$ξ − $_{R}$, the factor is x , coming from I 3 L = 0 , I 3 R = 0 , Q = 1. For Z ′ → Δ ++ R Δ −− R , the factor is (1 − 3 x ), coming from I 3 L = 0 , I 3 R = 1 , Q = 2. 

The decay of Z ′ to the physical Higgs bosons of the effective two-doublet electroweak sector should also be considered. They are ( φ + $_{2}$, φ 0 $_{2}$) and ( φ + $_{L}$, φ 0 $_{L}$). The physical linear combination is ( v 3 Φ 2 − v 2 Φ$_{L}$) / √ v 2 2 + v 2 $_{3}$. Since v 2 $_{2}$/v 2 3 = x/ (1 − 2 x ), the Z ′ couplings are completely determined. The resulting factor for both Z ′ → H + $_{L}$H − L and Z ′ → A 0 $_{L}$H 0 L is (1 − 3 x ) / 2. 

Let Γ 0 = ( g $^{′}$) $^{2}$M$_{Z}$ ′ / 48 π , then the partial decay widths in units of Γ 0 and their respective branching fractions (%) are given in Table II. In the special case where m$_{A}$$_{R}$ > 2 m$_{Δ}$ ++ R , which 

## TABLE II: Z ′ decay widths and branching fractions. 

<img src='content_image/355857.jpg'>

is allowed in part of the parameter space shown in Fig. 1, and assuming that m$_{H}$ 0 R 1 > 2 m$_{Δ}$ ++ R as well, we will have the spectacular decay chain Z ′ → A 0 $_{R}$H 0 R 1 → Δ ++ R Δ −− R + Δ ++ R Δ −− R , resulting in 8 charged muons as shown in Fig. 2. This branching fraction is of order 20 percent, given the fact that both A 0 R and H 0 R 1 decay predominantly into Δ ++ R Δ −− R , and the 

