You are an AI assistant, who knows every language and how to translate one language to another. Given a task, you explain in simple steps what the task is asking, any guidelines that it provides. You solve the task and show how you used the guidelines to solve the task.
system
Detailed Instructions: In this task, you are given inputs k, i, and A, where k and i are integers and A is a list. You need to find every ith element of A starting from the kth element. The process stops when the position of the next ith element exceeds the length of the list.
Q: 1, 1, ['P', '9909', '1199', 'M', 'I', 't', 'v', '7191']
A:
user
Task: Find every ith element of list A starting from the kth element and stopping when the position of the next ith element exceeds the length of the list.

Given:
- k = 1
- i = 1
- A = ['P', '9909', '1199', 'M', 'I', 't', 'v', '7191']

Steps:

1. Initialize a variable, called result, to store the final list of elements.
2. Calculate the first element's index: first_index = k - 1.
3. Iterate through the elements of A using a loop. For each iteration:
    a. Get the element at index first_index and add it to the result list.
    b. Update the first_index by adding i (first_index = first_index + i).
    c. Check if the new first_index is greater than or equal to the length of A. If it is, break the loop.
4. Return the result list.

Solution:

1. result = []
2. first_index = 1 - 1 = 0
3. Loop:
   a. result = ['P']
   b. first_index = 0 + 1 = 1
   c. first_index < len(A), continue loop
   
   a. result = ['P', '9909']
   b. first_index = 1 + 1 = 2
   c. first_index < len(A), continue loop

   a. result = ['P', '9909', '1199']
   b. first_index = 2 + 1 = 3
   c. first_index < len(A), continue loop

   a. result = ['P', '9909', '1199', 'M']
   b. first_index = 3 + 1 = 4
   c. first_index < len(A), continue loop

   a. result = ['P', '9909', '1199', 'M', 'I']
   b. first_index = 4 + 1 = 5
   c. first_index < len(A), continue loop

   a. result = ['P', '9909', '1199', 'M', 'I', 't']
   b. first_index = 5 + 1 = 6
   c. first_index < len(A), continue loop

   a. result = ['P', '9909', '1199', 'M', 'I', 't', 'v']
   b. first_index = 6 + 1 = 7
   c. first_index < len(A), continue loop

   a. result = ['P', '9909', '1199', 'M', 'I', 't', 'v', '7191']
   b. first_index = 7 + 1 = 8
   c. first_index >= len(A), break loop

4. Result: ['P', '9909', '1199', 'M', 'I', 't', 'v', '7191']
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