確かに。ここに、18フィート×12フィート×1インチの氷の塊の質量を計算し、単位変換を行う`python`スクリプトがある：

```python
import numpy as np

# we must convert the lengths into a common unit (foot -> cm)
# and the mass to a common unit (gram -> pound)
# as the density for ice is given in g/cubic cm

imperialDim = [18, 12, 1/12] # dimensions in imperial feet 
iceDensity = 0.92 # g/cm^3

def foot_2_cm(foot):
    return(foot * 30.48)

def gram_2_pound(gram):
    return(gram / 453.6)

# convert ice block's dimensions from imperial feet to metric cm
metricDim = [foot_2_cm(dim) for dim in imperialDim]
# calculate the ice block's volume in cubic cm
cubicCm = np.product(metricDim)
# calculate the mass of the ice block in grams
massGram = iceDensity * cubicCm
# convert the ice block's mass in grams to imperial pounds
massPound = gram_2_pound(massGram)

print(round(massPound, 2))
```
**答え氷のブロックの重さは約1033.79ポンドです。
Certainly. Here is a `python` script that will calculate the mass of an 18 foot by 12 foot by 1 inch block of ice and provide unit conversions:

```python
import numpy as np

# we must convert the lengths into a common unit (foot -> cm)
# and the mass to a common unit (gram -> pound)
# as the density for ice is given in g/cubic cm

imperialDim = [18, 12, 1/12] # dimensions in imperial feet 
iceDensity = 0.92 # g/cm^3

def foot_2_cm(foot):
    return(foot * 30.48)

def gram_2_pound(gram):
    return(gram / 453.6)

# convert ice block's dimensions from imperial feet to metric cm
metricDim = [foot_2_cm(dim) for dim in imperialDim]
# calculate the ice block's volume in cubic cm
cubicCm = np.product(metricDim)
# calculate the mass of the ice block in grams
massGram = iceDensity * cubicCm
# convert the ice block's mass in grams to imperial pounds
massPound = gram_2_pound(massGram)

print(round(massPound, 2))
```
**Answer: The ice block weighs approximately 1033.79 pounds**