もちろん！PythonによるFizzBuzz問題の実装です：

```python
def fizz_buzz(n):
    for i in range(1, n + 1):
        if i % 15 == 0:
            print("FizzBuzz")
        elif i % 3 == 0:
            print("Fizz")
        elif i % 5 == 0:
            print("Buzz")
        else:
            print(i)

fizz_buzz(100)
```

このプログラムは1からnまでの数（この場合は100）を表示し、3で割り切れる数を "Fizz"、5で割り切れる数を "Buzz"、3と5の両方で割り切れる数を "FizzBuzz "と置き換えます。
Sure! Here's an implementation of the FizzBuzz problem in Python:

```python
def fizz_buzz(n):
    for i in range(1, n + 1):
        if i % 15 == 0:
            print("FizzBuzz")
        elif i % 3 == 0:
            print("Fizz")
        elif i % 5 == 0:
            print("Buzz")
        else:
            print(i)

fizz_buzz(100)
```

This program will print the numbers from 1 to n (in this case, 100), and replace numbers that are divisible by 3 with "Fizz", numbers divisible by 5 with "Buzz", and numbers divisible by both 3 and 5 with "FizzBuzz".