IrPbBr is half-Heusler structured and crystallizes in the cubic F-43m space group. Ir(1) is bonded to four equivalent Pb(1) atoms to form IrPb4 tetrahedra that share corners with four equivalent Br(1)Pb4 tetrahedra, corners with twelve equivalent Ir(1)Pb4 tetrahedra, and edges with six equivalent Br(1)Pb4 tetrahedra. Pb(1) is bonded in a body-centered cubic geometry to four equivalent Ir(1) and four equivalent Br(1) atoms. Br(1) is bonded to four equivalent Pb(1) atoms to form BrPb4 tetrahedra that share corners with four equivalent Ir(1)Pb4 tetrahedra, corners with twelve equivalent Br(1)Pb4 tetrahedra, and edges with six equivalent Ir(1)Pb4 tetrahedra.
IrPbBr is half-Heusler structured and crystallizes in the cubic F-43m space group. Ir(1) is bonded to four equivalent Pb(1) atoms to form IrPb4 tetrahedra that share corners with four equivalent Br(1)Pb4 tetrahedra, corners with twelve equivalent Ir(1)Pb4 tetrahedra, and edges with six equivalent Br(1)Pb4 tetrahedra. All Ir(1)-Pb(1) bond lengths are 2.97 Å. Pb(1) is bonded in a body-centered cubic geometry to four equivalent Ir(1) and four equivalent Br(1) atoms. All Pb(1)-Br(1) bond lengths are 2.97 Å. Br(1) is bonded to four equivalent Pb(1) atoms to form BrPb4 tetrahedra that share corners with four equivalent Ir(1)Pb4 tetrahedra, corners with twelve equivalent Br(1)Pb4 tetrahedra, and edges with six equivalent Ir(1)Pb4 tetrahedra.