Ho2TeO2 crystallizes in the hexagonal P6_3/mmc space group. Ho(1) is bonded in a 4-coordinate geometry to three equivalent Te(1) and four equivalent O(1) atoms. Te(1) is bonded to six equivalent Ho(1) atoms to form distorted TeHo6 pentagonal pyramids that share corners with twelve equivalent O(1)Ho4 tetrahedra, edges with six equivalent Te(1)Ho6 pentagonal pyramids, and edges with six equivalent O(1)Ho4 tetrahedra. O(1) is bonded to four equivalent Ho(1) atoms to form OHo4 tetrahedra that share corners with six equivalent Te(1)Ho6 pentagonal pyramids, corners with six equivalent O(1)Ho4 tetrahedra, edges with three equivalent Te(1)Ho6 pentagonal pyramids, and edges with three equivalent O(1)Ho4 tetrahedra.
Ho2TeO2 crystallizes in the hexagonal P6_3/mmc space group. Ho(1) is bonded in a 4-coordinate geometry to three equivalent Te(1) and four equivalent O(1) atoms. All Ho(1)-Te(1) bond lengths are 3.14 Å. There is one shorter (2.27 Å) and three longer (2.31 Å) Ho(1)-O(1) bond lengths. Te(1) is bonded to six equivalent Ho(1) atoms to form distorted TeHo6 pentagonal pyramids that share corners with twelve equivalent O(1)Ho4 tetrahedra, edges with six equivalent Te(1)Ho6 pentagonal pyramids, and edges with six equivalent O(1)Ho4 tetrahedra. O(1) is bonded to four equivalent Ho(1) atoms to form OHo4 tetrahedra that share corners with six equivalent Te(1)Ho6 pentagonal pyramids, corners with six equivalent O(1)Ho4 tetrahedra, edges with three equivalent Te(1)Ho6 pentagonal pyramids, and edges with three equivalent O(1)Ho4 tetrahedra.