HoAu4 crystallizes in the tetragonal I4/m space group. Ho(1) is bonded to twelve equivalent Au(1) atoms to form a mixture of edge and face-sharing HoAu12 cuboctahedra. Au(1) is bonded to three equivalent Ho(1) atoms to form a mixture of distorted edge and corner-sharing AuHo3 cuboctahedra.
HoAu4 crystallizes in the tetragonal I4/m space group. Ho(1) is bonded to twelve equivalent Au(1) atoms to form a mixture of edge and face-sharing HoAu12 cuboctahedra. There are eight shorter (2.99 Å) and four longer (3.01 Å) Ho(1)-Au(1) bond lengths. Au(1) is bonded to three equivalent Ho(1) atoms to form a mixture of distorted edge and corner-sharing AuHo3 cuboctahedra.