  Let $p\geq 1$, $\eps >0$, $r\geq (1+\eps) p$, and $X$ be a $(-1/r)$-concave
random vector in $\R^n$ with Euclidean norm $|X|$. We prove that $(\E
|X|^{p})^{1/{p}}\leq c (C(\eps) \E|X|+\sigma_{p}(X))$, where
$\sigma_{p}(X)=\sup_{|z|\leq 1}(\E|<z,X>|^{p})^{1/p}$, $C(\eps)$ depends only
on $\eps$ and $c$ is a universal constant. Moreover, if in addition $X$ is
centered then $(\E |X|^{-p})^{-1/{p}}\geq c(\eps) (\E|X| - C \sigma_{p}(X))$.

Probability;Metric Geometry