The problem is asking us to divide fractions. Recall that dividing by a number is the same as multiplying by its reciprocal. Thus $$\frac{64}{7}\div\frac{8}{3}=\frac{64}{7}\cdot\frac{3}{8}.$$Then we can cancel out the common factor of 64 and 8 which is 8 and we arrive at $$\frac{64}{7}\cdot\frac{3}{8}=\frac{\cancel{8}\cdot8}{7}\cdot\frac{3}{\cancel{8}}.$$Finally, we multiply the remaining terms (make sure to multiply numerators by numerators and denominators by denominators) and we get $$\frac{\cancel{8}\cdot8}{7}\cdot\frac{3}{\cancel{8}}=\frac{3\cdot8}{7}=\boxed{\frac{24}{7}}.$$Note: 24 and 7 have no common denominators so we cannot simplify the fraction further.
Simplify $\frac{64}{7}\div\frac{8}{3}$.
{'answer': '\\frac{24}{7}', 'subject': 'Prealgebra', 'level': 2, 'unique_id': 'test/prealgebra/1803.json'}