A quadratic has exactly one distinct solution when its discriminant is 0.  The discriminant of $4x^2 + nx + 25$ is $n^2 - 4(4)(25)$.  Setting this equal to 0 gives $n^2 - 400 = 0$, so $n^2 = 400$.  The positive solution of this equation is $n = \boxed{20}$.
For two real values of $n$, the equation $4x^2+nx+25=0$ has exactly one solution in $x$. What is the positive value of $n$?
{'answer': '20', 'subject': 'Algebra', 'level': 3, 'unique_id': 'train/algebra/479.json'}