Infrared Spectroscopy Primary and secondary amines can be identified by a characteristic N–H stretching absorption in the 3300 to 3500 cm –1 range of the IR spectrum. Alcohols also absorb in this range (Section 17.11), but amine absorption bands are generally sharper and less intense than hydroxyl bands. Primary amines show a pair of bands at about 3350 and 3450 cm –1 from the symmetric and asymmetric stretching modes, and secondary amines show a single band at 3350 cm –1 . Tertiary amines have no absorption in this region because they have no N–H bonds. Figure 24.9 recalls the IR spectrum of cyclohexylamine from Section 12.8. Nuclear Magnetic Resonance Spectroscopy Amines are difficult to identify solely by 1 H NMR spectroscopy because N–H hydrogens tend to appear as broad signals without clear-cut coupling to neighboring C–H hydrogens. As with O–H absorptions (Section 17.11), amine N–H absorptions can appear over a wide range and are best identified by adding a small amount of D 2 O to the sample. Exchange of N–D for N–H occurs, and the N–H signal disappears from the NMR spectrum. Hydrogens on the carbon next to nitrogen are deshielded because of the electron-withdrawing effect of the nitrogen, and they therefore absorb further downfield than alkane hydrogens. N -Methyl groups are particularly distinctive because they absorb as a sharp three-proton singlet at 2.2 to 2.6 δ . This N -methyl resonance at 2.42 δ is easily seen in the 1 H NMR spectrum of N -methylcyclohexylamine (Figure \(\PageIndex{1}\)). Carbons next to amine nitrogens are slightly deshielded in the 13 C NMR spectrum and absorb about 20 ppm downfield from where they would absorb in an alkane of similar structure. In N -methylcyclohexylamine, for example, the ring carbon to which nitrogen is attached absorbs at a position 24 ppm downfield from any other ring carbon. Exercise \(\PageIndex{1}\) Compound A , C 6 H 12 O, has an IR absorption at 1715 cm –1 and gives compound B , C 6 H 15 N, when treated with ammonia and NaBH 4 . The IR and 1 H NMR spectra of B are shown. What are the structures of A and B ? Answer \(\ce{(CH3)3CCOCH3 ​→ ​(CH3)3CCH(NH2)CH3}\) Mass Spectrometry The nitrogen rule of mass spectrometry says that a compound with an odd number of nitrogen atoms has an odd-numbered molecular weight. Thus, the presence of nitrogen in a molecule is detected simply by observing its mass spectrum. An odd-numbered molecular ion usually means that the unknown compound has one or three nitrogen atoms, and an even-numbered molecular ion usually means that a compound has either zero or two nitrogen atoms. The logic behind the rule derives from the fact that nitrogen is trivalent, thus requiring an odd number of hydrogen atoms. For example, morphine has the formula C 17 H 19 NO 3 and a molecular weight of 285 amu. Alkylamines undergo a characteristic α cleavage in the mass spectrometer, similar to the cleavage observed for alcohols (Section 17.11). C–C bond nearest the nitrogen atom is broken, yielding an alkyl radical and a resonance-stabilized, nitrogen-containing cation. As an example, the mass spectrum of N -ethylpropylamine shown in Figure \(\PageIndex{2}\) has peaks at m / z = 58 and m / z = 72, corresponding to the two possible modes of α cleavage.