How to find size of an array in C without sizeof
Whether you use this method of getting the number of elements in an array or the more traditional sizeof method, please encapsulate the logic in a macro.Instead of writing either of these:  size_t length = sizeof array / sizeof array[0];

  size_t length = (&array)[1] - array;

Define this macro instead:  #define countof( array )  ( sizeof(array) / sizeof((array)[0]) )

Or if you must:  #define countof( array )  ( (&(array))[1] - (array) )

And then you can just say:  size_t length = countof(array);

Edit: I used to call this macro 'elementsof', but it seems that 'countof' is a more common name for it and is a bit more clear too - so I'm going to run with that name in the future.