{"event_info":{"picture":"https://img.loigiaihay.com/picture/event/2018/0417/bai-14-sgk-li-12-cb-0.jpg","title":"Bài 14. Mạch có R, L, C mắc nối tiếp","display_type":1,"cat_id":63,"cat_title":"SGK Vật lí lớp 12","alias":"bai-14-mach-co-r-l-c-mac-noi-tiep","introtext":"","ad_popup_m":"","content_box_above":"","type":"event","page_builder":"","item_id":804,"item_type":2},"list_articles":[{"article_id":81657,"cat_id":63,"publish_time":1595408220,"type_ex":1,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2020/0722/resize_mon-li5-0_1.jpg","title":"Phương pháp giải một số dạng bài tập về Mạch xoay chiều có R,L,C mắc nối tiếp","label":"Phương pháp giải một số dạng bài tập về Mạch xoay chiều có R,L,C mắc nối tiếp","alias":"phuong-phap-giai-mot-so-dang-bai-tap-ve-mach-xoay-chieu-co-rlc-mac-noi-tiep","introtext":"Tổng hợp cách giải một số dạng bài tập về mạch xoay chiều có R,L,C mắc nối  tiếp","display_type":0,"article_type":1},{"article_id":105054,"cat_id":63,"publish_time":1642125720,"type_ex":3,"is_hot":0,"is_link":0,"thumbnail":"","title":"Bài toán cực trị của mạch RLC mắc nối tiếp","label":"Bài toán cực trị của mạch RLC mắc nối tiếp","alias":"bai-toan-cuc-tri-cua-mach-rlc-mac-noi-tiep","introtext":"Bài toán cực trị của mạch RLC mắc nối tiếp","display_type":0,"article_type":1},{"article_id":55153,"cat_id":63,"publish_time":1557480180,"type_ex":1,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2019/0510/resize_ly-thuyet-mach-co-r-l-c-mac-noi-tiep-0.jpg","title":"Lý thuyết mạch có R, L, C mắc nối tiếp","label":"Lý thuyết mạch có R, L, C mắc nối tiếp","alias":"ly-thuyet-mach-co-r-l-c-mac-noi-tiep","introtext":"Lý thuyết mạch có R, L, C mắc nối tiếp. Điện áp và tổng trở của mạch, ...","display_type":0,"article_type":1},{"article_id":45107,"cat_id":63,"publish_time":1539674400,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/1016/resize_12-0_1.png","title":"Câu C1 trang 75 SGK Vật lý 12","label":"","alias":"cau-c1-trang-75-sgk-vat-ly-12","introtext":"Giải Câu C1 trang 75 SGK Vật lý 12","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p>Hiệu điện thế của mạch điện một chiều gồm nhiều điện trở ghép nối tiếp bằng tổng hiệu điện thế của từng đoạn U = U<sub>1</sub> + U<sub>2</sub> + …</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":45108,"cat_id":63,"publish_time":1539674520,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/1016/resize_13-0_1.png","title":"Câu C2 trang 76 SGK Vật lý 12","label":"","alias":"cau-c2-trang-76-sgk-vat-ly-12","introtext":"Giải Câu C2 trang 76 SGK Vật lý 12","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p>Đoạn mạch chỉ có \\(\\overrightarrow R \\)</p>\r\n<p>\\(\\overrightarrow {{U_R}} \\) hợp với \\(\\overrightarrow I \\) một góc 0<sup>o</sup></p>\r\n<p>\\(\\overrightarrow {{U_R}} \\) song song với \\(\\overrightarrow I \\)</p>\r\n<p>Đoạn mạch có C</p>\r\n<p>\\(\\overrightarrow {{U_C}} \\) hợp với \\(\\overrightarrow I \\) một góc -90<sup>o</sup></p>\r\n<p>\\(\\overrightarrow {{U_C}} \\) vuông góc với \\(\\overrightarrow I \\) hướng xuống</p>\r\n<p>Đoạn mạch chỉ có \\(\\overrightarrow L \\)</p>\r\n<p>\\(\\overrightarrow {{U_L}} \\) hợp với \\(\\overrightarrow I \\) một góc 90<sup>o</sup></p>\r\n<p>\\(\\overrightarrow {{U_L}} \\) vuông góc với \\(\\overrightarrow I \\) hướng lên</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":45109,"cat_id":63,"publish_time":1539674700,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/1016/resize_14-0_1.png","title":"Câu C3 trang 77 SGK Vật lý 12","label":"","alias":"cau-c3-trang-77-sgk-vat-ly-12","introtext":"Giải Câu C3 trang 77 SGK Vật lý 12","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p>Với \\({U_L} &gt; {U_C}\\)</p>\r\n<p><img style=\"max-width: 100%;\" src=\"https://img.loigiaihay.com/picture/2019/0510/h142-sgk-vat-li-12.PNG\" alt=\"\" width=\"200\" height=\"212\" /></p>\r\n<p>Từ hình vẽ ta có:</p>\r\n<p>\\(\\eqalign{&amp; {U^2} = {U_{{R^2}}} + U_{LC}^2 = {U_{{R^2}}}{\\left( {{U_L} - {U_C}} \\right)^2}  \\cr &amp; Hay\\,\\,{U^2} = \\left[ {{R^2} + {{\\left( {{Z_L} - {Z_C}} \\right)}^2}} \\right]{I^2}  \\cr &amp;  \\Rightarrow I = {U \\over {\\sqrt {{R^2} + {{\\left( {{Z_L} - {Z_C}} \\right)}^2}} }} \\cr} \\)</p>\r\n<p>Đặt \\(Z = \\sqrt {{R^2} + {{\\left( {{Z_L} - {Z_C}} \\right)}^2}} \\)</p>\r\n<p>\\(I = \\displaystyle{U \\over Z}\\)</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":6792,"cat_id":63,"publish_time":1405157640,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0419/resize_bai-1-trang-79-sgk-li-12-cb-0.jpg","title":"Bài 1 trang 79 SGK Vật lí 12","label":"Bài 1 trang 79 sgk vật lý 12","alias":"bai-1-trang-79-sgk-vat-ly-12","introtext":"Giải bài 1 trang 79 SGK Vật lí 12. Phát biểu định luật Ôm đối","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p><span>Định luật Ôm của dòng điện xoay chiều của đoạn mạch R, L, C mắc nối tiếp: “Cường độ hiệu dụng trong mạch R, L, C mắc nối tiếp có giá trị bằng thương số của điện áp hiệu dụng giữa hai đầu mạch và tổng trở của mạch.”</span></p>\r\n<p> </p>\r\n<p>Biểu thức: \\(I = \\frac{U}{Z} = \\frac{U}{{\\sqrt {{R^2} + {{({Z_L} - {Z_C})}^2}} }}\\)</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":6793,"cat_id":63,"publish_time":1405157820,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0419/resize_bai-2-trang-79-sgk-li-12-cb.jpg","title":"Bài 2 trang 79 SGK Vật lí 12","label":"Bài 2 trang 79 sgk vật lý 12","alias":"bai-2-trang-79-sgk-vat-ly-12","introtext":"Dòng nào ở cột A tương ứng với dòng nào ở cột B ?","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p><span>1 - e;              2 - c;            3 - a;         </span></p>\r\n<p><span>4 - a;              5 - c;             6 - f.</span></p>\r\n<p style=\"text-align: right;\"><strong><span>Loigiaihay.com</span></strong></p>"},{"article_id":6794,"cat_id":63,"publish_time":1405158360,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0419/resize_bai-3-trang-79-sgk-li-12-cb-0.jpg","title":"Bài 3 trang 79 SGK Vật lí 12","label":"Bài 3 trang 79 sgk vật lý 12","alias":"bai-3-trang-79-sgk-vat-ly-12","introtext":"Giải bài 3 trang 79 SGK Vật lí 12. Trong mạch điện xoay chiều nối tiếp","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p><span>Trong mạch điện xoay chiều nối tiếp, cộng hưởng  là hiện tượng cường độ dòng điện trong mạch đạt giá trị lớn nhất khi cảm kháng bằng dung kháng (Z<sub>L </sub>= Zc).</span></p>\r\n<p><span>Đặc trưng của cộng hưởng: </span></p>\r\n<p><span>- Dòng điện cùng pha với điện áp.</span></p>\r\n<p><span>- Tổng trở mạch đạt giá trị nhỏ nhất là \\(Z_{min} = R\\).</span></p>\r\n<p>- Cường độ dòng điện có giá trị lớn nhất:  \\(I_{max}=\\dfrac{U}{R}\\)</p>\r\n<p><span>- Công suất của mạch cực đại: \\(P_{max}=\\dfrac{U^2}{R}\\)</span></p>\r\n<p style=\"text-align: right;\"><strong><span>Loigiaihay.com</span></strong></p>\r\n<p> </p>"},{"article_id":6795,"cat_id":63,"publish_time":1405158480,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2020/1207/resize_mon-li7-0.jpg","title":"Bài 4 trang 79 SGK Vật lí 12","label":"Bài 4 trang 79 sgk vật lý 12","alias":"bai-4-trang-79-sgk-vat-ly-12","introtext":"Mạch điện xoay chiều gồm có","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p style=\"text-align: justify;\">Dung kháng: </p>\r\n<p style=\"text-align: justify;\">\\({Z_C} = \\dfrac{1}{{\\omega C}} = \\dfrac{1}{{100\\pi  \\cdot \\dfrac{1}{{2000\\pi }}}} = 20\\Omega \\)</p>\r\n<p style=\"text-align: justify;\">Tổng trở của mạch là</p>\r\n<p style=\"text-align: justify;\"> \\(Z = \\sqrt {{R^2} + Z_C^2}  = \\sqrt {{{20}^2} + {{20}^2}}\\)\\(\\,  = {\\rm{ }}20\\sqrt 2 \\Omega \\)</p>\r\n<p style=\"text-align: justify;\">Cường độ dòng điện hiệu dụng: \\(I = \\dfrac{U}{Z} = \\dfrac{{60}}{{20\\sqrt 2 }} = \\dfrac{3}{{\\sqrt 2 }}A\\)</p>\r\n<p style=\"text-align: justify;\">=&gt; \\({I_0} = I\\sqrt 2  = \\frac{3}{{\\sqrt 2 }}.\\sqrt 2  = 3(A)\\)</p>\r\n<p style=\"text-align: justify;\">Độ lệch pha:</p>\r\n<p style=\"text-align: justify;\">\\(\\tan \\varphi  = \\dfrac{{ - {Z_C}}}{R} =  - 1 \\Rightarrow \\varphi  = \\dfrac{{ - \\pi }}{4}\\).</p>\r\n<p style=\"text-align: justify;\">Ta có: </p>\r\n<p>\\(\\varphi  = {\\varphi _u} - {\\varphi _i} \\to {\\varphi _i} = {\\varphi _u} - \\varphi  = 0 - ( - \\frac{\\pi }{4}) = \\frac{\\pi }{4}\\)</p>\r\n<p style=\"text-align: justify;\">Tức là i sớm pha hơn u một góc \\(\\dfrac{\\pi }{4}\\)</p>\r\n<p style=\"text-align: justify;\">Vậy biểu thức tức thời của cường độ dòng điện là: \\(i = 3\\cos \\left( {100\\pi t + \\dfrac{\\pi }{4}} \\right)\\,\\,(A)\\). </p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":6796,"cat_id":63,"publish_time":1405296300,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-5-trang-79-sgk-li-12-cb-0.jpg","title":"Bài 5 trang 79 SGK Vật lí 12","label":"Bài 5 trang 79 sgk vật lý 12","alias":"bai-5-trang-79-sgk-vat-ly-12","introtext":"Giải bài 5 trang 79 SGK Vật lí 12. Mạch điện xoay chiều gồm","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p>+ Từ phương trình điện áp: \\(u = 120\\sqrt 2 cos100\\pi t\\left( V \\right)\\), ta có:</p>\r\n<p>- Hiệu điện thế cực đại \\({U_0} = 120\\sqrt 2 \\left( V \\right)\\)</p>\r\n<p>- Tần số góc \\(\\omega  = 100\\pi \\left( {rad/s} \\right)\\)</p>\r\n<p>- Pha ban đầu của điện áp: \\({\\varphi _u} = 0\\left( {rad} \\right)\\)</p>\r\n<p>+ Cảm kháng: \\({Z_L} = \\omega L = 100\\pi .\\dfrac{{0,3}}{\\pi } = 30\\Omega \\)</p>\r\n<p>+ Mạch gồm điện trở mắc nối tiếp với cuộn cảm thuần</p>\r\n<p>=&gt; Tổng trở của mạch: \\(Z = \\sqrt {{R^2} + Z_L^2}  = \\sqrt {{{30}^2} + {{30}^2}}  = 30\\sqrt 2 \\Omega \\)</p>\r\n<p>+ Cường độ dòng điện cực đại trong mạch: \\({I_0} = \\dfrac{{{U_0}}}{Z} = \\dfrac{{120\\sqrt 2 }}{{30\\sqrt 2 }} = 4A\\)</p>\r\n<p>+ Độ lệch pha của u so với i:</p>\r\n<p>\\(\\begin{array}{l}\\tan \\varphi  = \\dfrac{{{Z_L}}}{R} = \\dfrac{{30}}{{30}} = 1\\\\ \\Rightarrow \\varphi  = \\dfrac{\\pi }{4}\\left( {rad} \\right)\\end{array}\\)</p>\r\n<p>Ta có, \\(\\varphi  = \\dfrac{\\pi }{4} &gt; 0\\) tức là u nhanh pha hơn i một góc \\(\\dfrac{\\pi }{4}\\)</p>\r\n<p>Ta suy ra:</p>\r\n<p>\\(\\begin{array}{l}{\\varphi _u} - {\\varphi _i} = \\dfrac{\\pi }{4}\\\\ \\Rightarrow {\\varphi _i} = {\\varphi _u} - \\dfrac{\\pi }{4} = 0 - \\dfrac{\\pi }{4} =  - \\dfrac{\\pi }{4}\\left( {rad} \\right)\\end{array}\\)</p>\r\n<p style=\"text-align: justify;\">=&gt; Biểu thức cường độ dòng điện trong mạch: \\(i = 4cos\\left( {100\\pi t - \\dfrac{\\pi }{4}} \\right)A\\).</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":6797,"cat_id":63,"publish_time":1405297440,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-6-trang-79-sgk-li-12-cb-0.jpg","title":"Bài 6 trang 79 SGK Vật lí 12","label":"Bài 6 trang 79 sgk vật lý 12","alias":"bai-6-trang-79-sgk-vat-ly-12","introtext":"Giải bài 6 trang 79 SGK Vật lí 12. Mạch điện xoay chiều gồm điện","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p style=\"text-align: justify;\"><span>Mạch R nối tiếp với C nên <span>U</span><sub>R</sub></span><span> và <span>U</span><sub>C</sub><span> </span></span><span>vuông góc với nhau.</span></p>\r\n<p style=\"text-align: justify;\">Ta có:</p>\r\n<p style=\"text-align: justify;\">U<sup>2</sup> = U<sup>2</sup><sub>R</sub> + U<sup>2</sup><sub>C</sub> =&gt;U<sub>R</sub> = \\(\\sqrt{U^{2} - U_{C}^{2}}\\) = \\(\\sqrt{100^{2} - 80^{2}}\\) = 60 V.</p>\r\n<p style=\"text-align: justify;\">Cường độ dòng điện hiệu dụng: I = \\(\\frac{U_{R}}{R}\\) = \\(\\frac{60}{30}\\) = 2 A.</p>\r\n<p style=\"text-align: justify;\">Dung kháng: Z<sub>C</sub> = \\(\\frac{U_{C}}{I}\\) = \\(\\frac{80}{2}\\) = 40 Ω</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":6798,"cat_id":63,"publish_time":1405297980,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-7-trang-80-sgk-li-12-cb-0.jpg","title":"Bài 7 trang 80 SGK Vật lí 12","label":"Bài 7 trang 80 sgk vật lý 12","alias":"bai-7-trang-80-sgk-vat-ly-12","introtext":"Giải bài 7 trang 80 SGK Vật lí 12. Mạch điện xoay chiều gồm","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p>+ Từ phương trình điện áp, \\(u = 80cos100\\pi t\\left( V \\right)\\) ta có:</p>\r\n<p>- Hiệu điện thế hiệu dụng: \\(U = \\dfrac{{{U_0}}}{{\\sqrt 2 }} = \\dfrac{{80}}{{\\sqrt 2 }} = 40\\sqrt 2 V\\)</p>\r\n<p>- Tần số góc: \\(\\omega  = 100\\pi \\left( {rad/s} \\right)\\), \\({\\varphi _u} = 0\\left( {rad} \\right)\\)</p>\r\n<p>+ Mặt khác, hiệu điện thế hiệu dụng giữa hai đầu mạch: \\(U = \\sqrt {U_R^2 + U_L^2} \\)</p>\r\n<p>Ta suy ra: \\({U_R} = \\sqrt {{U^2} - U_L^2}  = \\sqrt {{{\\left( {40\\sqrt 2 } \\right)}^2} - {{40}^2}}  = 40V\\)</p>\r\n<p>+ Cường độ dòng điện hiệu dụng trong mạch: \\(I = \\dfrac{{{U_R}}}{R} = \\dfrac{{40}}{{40}} = 1A\\)</p>\r\n<p>=&gt; Cường độ dòng điện cực đại trong mạch: \\({I_0} = I\\sqrt 2  = 1.\\sqrt 2  = \\sqrt 2 A\\)</p>\r\n<p>a) Cảm kháng: \\({Z_L} = \\dfrac{{{U_L}}}{I} = \\dfrac{{40}}{1} = 40\\Omega \\)</p>\r\n<p>b) Độ lệch pha của u so với i:</p>\r\n<p>\\(\\begin{array}{l}\\tan \\varphi  = \\dfrac{{{Z_L}}}{R} = \\dfrac{{{U_L}}}{{{U_R}}} = \\dfrac{{40}}{{40}} = 1\\\\ \\Rightarrow \\varphi  = \\dfrac{\\pi }{4}\\left( {rad} \\right)\\end{array}\\)</p>\r\n<p>Ta suy ra: \\({\\varphi _u} - {\\varphi _i} = \\dfrac{\\pi }{4} \\Rightarrow {\\varphi _i} = {\\varphi _u} - \\dfrac{\\pi }{4} = 0 - \\dfrac{\\pi }{4} =  - \\dfrac{\\pi }{4}\\left( {rad} \\right)\\)</p>\r\n<p>=&gt; Biểu thức cường độ dòng điện trong mạch: \\(i = \\sqrt 2 cos\\left( {100\\pi t - \\dfrac{\\pi }{4}} \\right)A\\)</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":6799,"cat_id":63,"publish_time":1405298640,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-8-trang-80-sgk-li-12-cb-0.jpg","title":"Bài 8 trang 80 SGK Vật lí 12","label":"Bài 8 trang 80 sgk vật lý 12","alias":"bai-8-trang-80-sgk-vat-ly-12","introtext":"Giải bài 8 trang 80 SGK Vật lí 12. Mạch điện xoay chiều gồm có","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p>+ Từ phương trình điện áp: \\(u = 120\\sqrt 2 cos100\\pi t\\left( V \\right)\\) , ta có:</p>\r\n<p>- Hiệu điện thế cực đại: \\({U_0} = 120\\sqrt 2 \\left( V \\right)\\)</p>\r\n<p>- Tần số góc: \\(\\omega  = 100\\pi \\left( {rad/s} \\right)\\)</p>\r\n<p>- Pha ban đầu của điện áp: \\({\\varphi _u} = 0\\left( {rad} \\right)\\)</p>\r\n<p>+ Cảm kháng: \\({Z_L} = \\omega L = 100\\pi .\\dfrac{{0,2}}{\\pi } = 20\\Omega \\)</p>\r\n<p>+ Dung kháng: \\({Z_C} = \\dfrac{1}{{\\omega C}} = \\dfrac{1}{{100\\pi .\\dfrac{1}{{5000\\pi }}}} = 50\\Omega \\)</p>\r\n<p>+ Tổng trở của mạch: \\(Z = \\sqrt {{R^2} + {{\\left( {{Z_L} - {Z_C}} \\right)}^2}}  = \\sqrt {{{30}^2} + {{\\left( {20 - 50} \\right)}^2}}  = 30\\sqrt 2 \\Omega \\)</p>\r\n<p>+ Cường độ dòng điện cực đại trong mạch: \\({I_0} = \\dfrac{{{U_0}}}{Z} = \\dfrac{{120\\sqrt 2 }}{{30\\sqrt 2 }} = 4A\\)</p>\r\n<p>+ Độ lệch pha của u so với i:</p>\r\n<p>\\(\\begin{array}{l}\\tan \\varphi  = \\dfrac{{{Z_L} - {Z_C}}}{R} = \\dfrac{{20 - 50}}{{30}} =  - 1\\\\ \\Rightarrow \\varphi  =  - \\dfrac{\\pi }{4}\\left( {rad} \\right)\\end{array}\\)</p>\r\n<p>Ta suy ra:</p>\r\n<p>\\({\\varphi _u} - {\\varphi _i} =  - \\dfrac{\\pi }{4} \\Rightarrow {\\varphi _i} = {\\varphi _u} + \\dfrac{\\pi }{4} = 0 + \\dfrac{\\pi }{4} = \\dfrac{\\pi }{4}\\left( {rad} \\right)\\)</p>\r\n<p>=&gt; Biểu thức cường độ dòng điện trong mạch: \\(i = 4cos\\left( {100\\pi t + \\dfrac{\\pi }{4}} \\right)A\\)</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":6800,"cat_id":63,"publish_time":1405299420,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2020/1207/resize_mon-li7-0_1.jpg","title":"Bài 9 trang 80 SGK Vật lí 12","label":"Bài 9 trang 80 sgk vật lý 12","alias":"bai-9-trang-80-sgk-vat-ly-12","introtext":"Giải bài 9 trang 80 SGK Vật lí 12. Mạch điện xoay chiều gồm có:","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p style=\"text-align: justify;\">a) Áp dụng các công thức: Z<sub>C</sub> = \\(\\frac{1}{\\omega C}\\) = 40 Ω; Z<sub>L</sub> = ωL = 10 Ω</p>\r\n<p style=\"text-align: justify;\">=&gt; Z = \\(\\sqrt{R^{2} + (Z_{L} - Z_{C})^{2}}\\) = 50 Ω</p>\r\n<p style=\"text-align: justify;\">Cường độ dòng điện hiệu dụng: I = \\(\\frac{U}{Z}\\) = \\(\\frac{120}{50}\\) = 2,4A.</p>\r\n<p style=\"text-align: justify;\">Độ lệch pha: tanφ = \\(\\frac{Z_{L}- Z_{C}}{R}\\) = \\(\\frac{-3}{4}\\) =&gt; φ ≈ -37<sup>0</sup> ≈ -0,645 rad. Tức là i sớm pha hơn u một góc 0,645 rad.</p>\r\n<p style=\"text-align: justify;\">Vậy biểu thức tức thời của cường độ dòng điện là: i = 2,4\\(\\sqrt2\\)cos(100πt + 0,645 ) (A)</p>\r\n<p style=\"text-align: justify;\">b) Tổng trở trên đoạn AM là: \\({Z_{RC}} = \\sqrt {{R^2} + Z_C^2}  = \\sqrt {{{40}^2} + {{40}^2}}  = 40\\sqrt 2 \\Omega \\)</p>\r\n<p style=\"text-align: justify;\">    U<sub>AM </sub>có giá trị là  U<sub>AM </sub>=  I. Z<sub>AM</sub>,= 2,4.\\(40\\sqrt 2\\)= \\(96\\sqrt 2\\) V</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":6804,"cat_id":63,"publish_time":1405300080,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-10-trang-80-sgk-li-12-cb-0_5.jpg","title":"Bài 10 trang 80 SGK Vật lí 12","label":"Bài 10 trang 80 sgk vật lý 12","alias":"bai-10-trang-80-sgk-vat-ly-12","introtext":"Giải bài 10 trang 80 SGK Vật lí 12. Cho mạch điện xoay chiều","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p style=\"text-align: justify;\">Hiện tượng cộng hưởng khi:</p>\r\n<p style=\"text-align: justify;\"><!--[if gte mso 9]><xml>\r\n <o:OfficeDocumentSettings>\r\n  <o:RelyOnVML/>\r\n  <o:AllowPNG/>\r\n </o:OfficeDocumentSettings>\r\n</xml><![endif]--></p>\r\n<p style=\"text-align: justify;\"><!--[if gte mso 9]><xml>\r\n <w:WordDocument>\r\n  <w:View>Normal</w:View>\r\n  <w:Zoom>0</w:Zoom>\r\n  <w:TrackMoves/>\r\n  <w:TrackFormatting/>\r\n  <w:PunctuationKerning/>\r\n  <w:ValidateAgainstSchemas/>\r\n  <w:SaveIfXMLInvalid>false</w:SaveIfXMLInvalid>\r\n  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<w:LsdException Locked=\"false\" Priority=\"29\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Quote\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"30\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Intense Quote\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"66\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 2 Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"67\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 1 Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"68\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 2 Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"69\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 3 Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"70\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Dark List Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"71\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Shading Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"72\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful List Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"73\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Grid Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"60\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Shading Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"61\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light List Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"62\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Grid Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"63\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 1 Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"64\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 2 Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"65\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 1 Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"66\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 2 Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"67\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 1 Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"68\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 2 Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"69\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 3 Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"70\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Dark List Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"71\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Shading Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"72\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful List Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"73\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Grid Accent 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"60\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Shading Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"61\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light List Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"62\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Grid Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"63\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 1 Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"64\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 2 Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"65\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 1 Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"66\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 2 Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"67\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 1 Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"68\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 2 Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"69\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 3 Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"70\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Dark List Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"71\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Shading Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"72\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful List Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"73\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Grid Accent 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"60\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Shading Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"61\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light List Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"62\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Grid Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"63\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 1 Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"64\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 2 Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"65\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 1 Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"66\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 2 Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"67\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 1 Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"68\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 2 Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"69\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 3 Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"70\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Dark List Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"71\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Shading Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"72\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful List Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"73\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Grid Accent 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"60\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Shading Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"61\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light List Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"62\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Grid Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"63\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 1 Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"64\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 2 Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"65\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 1 Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"66\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 2 Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"67\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 1 Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"68\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 2 Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"69\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 3 Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"70\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Dark List Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"71\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Shading Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"72\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful List Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"73\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Grid Accent 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"60\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Shading Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"61\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light List Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"62\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Grid Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"63\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 1 Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"64\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 2 Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"65\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 1 Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"66\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 2 Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"67\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 1 Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"68\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 2 Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"69\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 3 Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"70\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Dark List Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"71\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Shading Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"72\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful List Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"73\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Grid Accent 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"19\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Subtle Emphasis\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"21\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Intense Emphasis\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"31\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Subtle Reference\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"32\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Intense Reference\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"33\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Book Title\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"37\" Name=\"Bibliography\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"39\" QFormat=\"true\" Name=\"TOC Heading\"/>\r\n </w:LatentStyles>\r\n</xml><![endif]--><!--[if gte mso 10]>\r\n<style>\r\n /* Style Definitions */\r\n table.MsoNormalTable\r\n\t{mso-style-name:\"Table Normal\";\r\n\tmso-tstyle-rowband-size:0;\r\n\tmso-tstyle-colband-size:0;\r\n\tmso-style-noshow:yes;\r\n\tmso-style-priority:99;\r\n\tmso-style-parent:\"\";\r\n\tmso-padding-alt:0cm 5.4pt 0cm 5.4pt;\r\n\tmso-para-margin-top:0cm;\r\n\tmso-para-margin-right:0cm;\r\n\tmso-para-margin-bottom:10.0pt;\r\n\tmso-para-margin-left:0cm;\r\n\tline-height:115%;\r\n\tmso-pagination:widow-orphan;\r\n\tfont-size:11.0pt;\r\n\tfont-family:\"Arial\",\"sans-serif\";\r\n\tmso-ascii-font-family:Arial;\r\n\tmso-ascii-theme-font:minor-latin;\r\n\tmso-hansi-font-family:Arial;\r\n\tmso-hansi-theme-font:minor-latin;\r\n\tmso-bidi-font-family:\"Times New Roman\";\r\n\tmso-bidi-theme-font:minor-bidi;\r\n\tmso-fareast-language:EN-US;}\r\n</style>\r\n<![endif]--><!--[if gte mso 9]><xml>\r\n <o:OfficeDocumentSettings>\r\n  <o:RelyOnVML/>\r\n  <o:AllowPNG/>\r\n </o:OfficeDocumentSettings>\r\n</xml><![endif]--></p>\r\n<p style=\"text-align: justify;\"><!--[if gte mso 9]><xml>\r\n <w:WordDocument>\r\n  <w:View>Normal</w:View>\r\n  <w:Zoom>0</w:Zoom>\r\n  <w:TrackMoves/>\r\n  <w:TrackFormatting/>\r\n  <w:PunctuationKerning/>\r\n  <w:ValidateAgainstSchemas/>\r\n  <w:SaveIfXMLInvalid>false</w:SaveIfXMLInvalid>\r\n  <w:IgnoreMixedContent>false</w:IgnoreMixedContent>\r\n  <w:AlwaysShowPlaceholderText>false</w:AlwaysShowPlaceholderText>\r\n  <w:DoNotPromoteQF/>\r\n  <w:LidThemeOther>VI</w:LidThemeOther>\r\n  <w:LidThemeAsian>X-NONE</w:LidThemeAsian>\r\n  <w:LidThemeComplexScript>X-NONE</w:LidThemeComplexScript>\r\n  <w:Compatibility>\r\n   <w:BreakWrappedTables/>\r\n   <w:SnapToGridInCell/>\r\n   <w:WrapTextWithPunct/>\r\n   <w:UseAsianBreakRules/>\r\n   <w:DontGrowAutofit/>\r\n   <w:SplitPgBreakAndParaMark/>\r\n   <w:EnableOpenTypeKerning/>\r\n   <w:DontFlipMirrorIndents/>\r\n   <w:OverrideTableStyleHps/>\r\n  </w:Compatibility>\r\n  <m:mathPr>\r\n   <m:mathFont m:val=\"Cambria Math\"/>\r\n   <m:brkBin m:val=\"before\"/>\r\n   <m:brkBinSub m:val=\"--\"/>\r\n   <m:smallFrac m:val=\"off\"/>\r\n   <m:dispDef/>\r\n   <m:lMargin m:val=\"0\"/>\r\n   <m:rMargin m:val=\"0\"/>\r\n   <m:defJc m:val=\"centerGroup\"/>\r\n   <m:wrapIndent m:val=\"1440\"/>\r\n   <m:intLim m:val=\"subSup\"/>\r\n   <m:naryLim m:val=\"undOvr\"/>\r\n  </m:mathPr></w:WordDocument>\r\n</xml><![endif]--><!--[if gte mso 9]><xml>\r\n <w:LatentStyles DefLockedState=\"false\" DefUnhideWhenUsed=\"true\"\r\n  DefSemiHidden=\"true\" DefQFormat=\"false\" DefPriority=\"99\"\r\n  LatentStyleCount=\"267\">\r\n  <w:LsdException Locked=\"false\" Priority=\"0\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Normal\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"9\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"heading 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"9\" QFormat=\"true\" Name=\"heading 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"9\" QFormat=\"true\" Name=\"heading 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"9\" QFormat=\"true\" Name=\"heading 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"9\" QFormat=\"true\" Name=\"heading 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"9\" QFormat=\"true\" Name=\"heading 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"9\" QFormat=\"true\" Name=\"heading 7\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"9\" QFormat=\"true\" Name=\"heading 8\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"9\" QFormat=\"true\" Name=\"heading 9\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"39\" Name=\"toc 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"39\" Name=\"toc 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"39\" Name=\"toc 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"39\" Name=\"toc 4\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"39\" Name=\"toc 5\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"39\" Name=\"toc 6\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"39\" Name=\"toc 7\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"39\" Name=\"toc 8\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"39\" Name=\"toc 9\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"35\" QFormat=\"true\" Name=\"caption\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"10\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Title\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"1\" Name=\"Default Paragraph Font\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"11\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Subtitle\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"22\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Strong\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"20\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"Emphasis\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"59\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Table Grid\"/>\r\n  <w:LsdException Locked=\"false\" UnhideWhenUsed=\"false\" Name=\"Placeholder Text\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"1\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" Name=\"No Spacing\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"60\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Shading\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"61\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light List\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"62\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Grid\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"63\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"64\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"65\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"66\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"67\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"68\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 2\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"69\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Grid 3\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"70\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Dark List\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"71\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Shading\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"72\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful List\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"73\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Colorful Grid\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"60\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Shading Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"61\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light List Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"62\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Light Grid Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"63\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 1 Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"64\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium Shading 2 Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"65\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" Name=\"Medium List 1 Accent 1\"/>\r\n  <w:LsdException Locked=\"false\" UnhideWhenUsed=\"false\" Name=\"Revision\"/>\r\n  <w:LsdException Locked=\"false\" Priority=\"34\" SemiHidden=\"false\"\r\n   UnhideWhenUsed=\"false\" QFormat=\"true\" 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line-height: 115%; font-family: 'Cambria Math','serif'; mso-bidi-font-family: 'Cambria Math'; mso-ansi-language: EN-US;\" lang=\"EN-US\">ω = </span>\\(\\sqrt{\\frac{1}{LC}}\\) = 100π (rad/s)</p>\r\n<p style=\"text-align: justify;\">Khi đó cường độ dòng điện hiệu dụng đạt giá trị cực đại và dòng điện cùng pha với điện áp:</p>\r\n<p style=\"text-align: justify;\">I<span style=\"mso-bidi-font-size: 11.0pt; line-height: 115%; font-family: 'Cambria Math','serif'; mso-fareast-font-family: Arial; mso-fareast-theme-font: minor-latin; mso-bidi-font-family: 'Cambria Math'; mso-ansi-language: EN-US; mso-fareast-language: EN-US; mso-bidi-language: AR-SA;\" lang=\"EN-US\"> = </span>\\(\\frac{U}{R}\\) = \\(\\frac{40\\sqrt{2}}{20}\\) = 2\\(\\sqrt2\\) A =&gt; I<sub>max</sub> = 4 và φ = 0.</p>\r\n<p style=\"text-align: justify;\">Biểu thức của dòng điện: i = 4cos(100πt) (A).</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>\r\n<p><!--[if gte mso 9]><xml>\r\n 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<m:smallFrac m:val=\"off\"/>\r\n   <m:dispDef/>\r\n   <m:lMargin m:val=\"0\"/>\r\n   <m:rMargin m:val=\"0\"/>\r\n   <m:defJc m:val=\"centerGroup\"/>\r\n   <m:wrapIndent m:val=\"1440\"/>\r\n   <m:intLim m:val=\"subSup\"/>\r\n   <m:naryLim m:val=\"undOvr\"/>\r\n  </m:mathPr></w:WordDocument>\r\n</xml><![endif]--></p>"},{"article_id":6816,"cat_id":63,"publish_time":1405301340,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-11-trang-80-sgk-li-12-cb-0.jpg","title":"Bài 11 trang 80 SGK Vật lí 12","label":"Bài 11 trang 80 sgk vật lý 12","alias":"bai-11-trang-80-sgk-vat-ly-12","introtext":"Giải bài 11 trang 80 SGK Vật lí 12. Chọn câu đúng:","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p style=\"text-align: justify;\">Tổng trở của đoạn mạch là  \\(Z=\\sqrt{R^{2} + (Z_{L} - Z_{C})^{2}}=40 \\sqrt2\\Omega\\)</p>\r\n<p style=\"text-align: justify;\">Cường độ dòng điện hiệu dụng:  \\(I=\\dfrac{U}{Z}=\\dfrac{240}{40\\sqrt{2}}=\\dfrac{6}{\\sqrt{2}}A\\).</p>\r\n<p style=\"text-align: justify;\">=&gt; Cường độ dòng điện cực đại: \\(I_0=I\\sqrt{2}=6A\\)</p>\r\n<p style=\"text-align: justify;\">Độ lệch pha: \\(tan\\varphi=\\dfrac{Z_{L}- Z_{C}}{R}=1=&gt; \\varphi = \\dfrac{\\pi }{4}\\).</p>\r\n<p style=\"text-align: justify;\">Tức là i trễ pha hơn u một góc \\(\\dfrac{\\pi }{4}\\).</p>\r\n<p style=\"text-align: justify;\">Vậy biểu thức tức thời của cường độ dòng điện là: \\(i = 6cos(100\\pi t - \\dfrac{\\pi }{4})A\\)</p>\r\n<p style=\"text-align: justify;\"><strong>Chọn đáp án D</strong></p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"},{"article_id":6830,"cat_id":63,"publish_time":1405303080,"type_ex":2,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-12-trang-80-sgk-li-12-cb-0.jpg","title":"Bài 12 trang 80 SGK Vật lí 12","label":"Bài 12 trang 80 sgk vật lý 12","alias":"bai-12-trang-80-sgk-vat-ly-12","introtext":"Chọn câu đúng:","display_type":1,"article_type":1,"content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p style=\"text-align: justify;\">Tổng trở của đoạn mạch là  Z = \\(\\sqrt{R^{2} + (Z_{L} - Z_{C})^{2}}\\) = 40 Ω</p>\r\n<p style=\"text-align: justify;\">Cường độ dòng điện hiệu dụng: I = \\(\\frac{U}{Z}\\) = \\(\\frac{120}{40}\\) = 3A.</p>\r\n<p style=\"text-align: justify;\">Độ lệch pha: tanφ = \\(\\frac{Z_{L}- Z_{C}}{R}\\) = 0 =&gt; φ =0. Tức là i và u một góc cùng pha</p>\r\n<p style=\"text-align: justify;\">Vậy biểu thức tức thời của cường độ dòng điện là: i = 3\\(\\sqrt2\\)cos(100πt) (A)</p>\r\n<p style=\"text-align: justify;\">Chọn đáp án D.</p>\r\n<p style=\"text-align: right;\"><strong>Loigiaihay.com</strong></p>"}],"most_views":[{"article_id":6797,"cat_id":63,"publish_time":1405297440,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-6-trang-79-sgk-li-12-cb-0.jpg","title":"Bài 6 trang 79 SGK Vật lí 12","alias":"bai-6-trang-79-sgk-vat-ly-12","introtext":"Giải bài 6 trang 79 SGK Vật lí 12. Mạch điện xoay chiều gồm điện","display_type":1},{"article_id":6800,"cat_id":63,"publish_time":1405299420,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2020/1207/resize_mon-li7-0_1.jpg","title":"Bài 9 trang 80 SGK Vật lí 12","alias":"bai-9-trang-80-sgk-vat-ly-12","introtext":"Giải bài 9 trang 80 SGK Vật lí 12. Mạch điện xoay chiều gồm có:","display_type":1},{"article_id":6796,"cat_id":63,"publish_time":1405296300,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-5-trang-79-sgk-li-12-cb-0.jpg","title":"Bài 5 trang 79 SGK Vật lí 12","alias":"bai-5-trang-79-sgk-vat-ly-12","introtext":"Giải bài 5 trang 79 SGK Vật lí 12. Mạch điện xoay chiều gồm","display_type":1},{"article_id":6798,"cat_id":63,"publish_time":1405297980,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-7-trang-80-sgk-li-12-cb-0.jpg","title":"Bài 7 trang 80 SGK Vật lí 12","alias":"bai-7-trang-80-sgk-vat-ly-12","introtext":"Giải bài 7 trang 80 SGK Vật lí 12. Mạch điện xoay chiều gồm","display_type":1},{"article_id":6799,"cat_id":63,"publish_time":1405298640,"is_hot":0,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2018/0417/resize_bai-8-trang-80-sgk-li-12-cb-0.jpg","title":"Bài 8 trang 80 SGK Vật lí 12","alias":"bai-8-trang-80-sgk-vat-ly-12","introtext":"Giải bài 8 trang 80 SGK Vật lí 12. Mạch điện xoay chiều gồm có","display_type":1}],"list_sub_event":[],"top_banner":"","cfg_info":{"last_cfg_time":"1521866679","ad.popup_frequency":"0","ad.adsense.detail_bottom.unit_id":"ca-app-pub-8529835372050931/9927553003","ad.adsense.popup.unit_id":"ca-app-pub-8529835372050931/2161779402","current.force.update.version":"181","support.email":"loigiaihay.com@gmail.com","support.fanpage":"https://www.facebook.com/Loigiaihay/","popup_rating_after":"86400","admob.app_id":"ca-app-pub-8529835372050931~4358271409","admob.unit.article_detail_bottom":"ca-app-pub-8529835372050931/1883637630","admob.unit.article_detail_top":"ca-app-pub-8529835372050931/8604898230","admob.unit.event_article_top":"ca-app-pub-8529835372050931/7406887709","admob.unit.interestial":"ca-app-pub-8529835372050931/2741937409","ios_appstore_link":"https://itunes.apple.com/us/app/loigiaihay/id1209891610?mt=8","android_appstore_link":"https://play.google.com/store/apps/details?id=com.tp.loigiaihay","min_version":"2.1.3","latest_version":"1.3.9","force_update":false},"popup_ads":[]}