{"article_info":{"article_id":148148,"cat_id":1541,"cat_title":"SBT Toán 8 - Chân trời sáng tạo","publish_time":1693296900,"cat_id2":1541,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2023/0829/resize_1-0_51.png","title":"Giải bài 5 trang 22 sách bài tập toán 8 - Chân trời sáng tạo","label":"Bài 5 trang 22 sách bài tập toán 8 - Chân trời sáng tạo","alias":"giai-bai-5-trang-22-sach-bai-tap-toan-8-chan-troi-sang-tao","introtext":"Tính:\r\na) \\(x - \\frac{{2x - y}}{4} + \\frac{{x + 4y}}{{12}}\\);\r\n","content":"<style>\r\n.method-close-icon{position: relative;float: right;top: 6px;transform: rotate(270deg);-ms-transform:rotate(270deg);-moz-transform:rotate(270deg);-webkit-transform:rotate(270deg);-o-transform:rotate(270deg);}\r\n.method-open-icon{position: relative;float: right;top: 6px;}\r\n</style>\r\n<p><strong style=\"font-size: 16px;\">Đề bài</strong></p><p>Tính:</p>\r\n<p>a) \\(x - \\frac{{2x - y}}{4} + \\frac{{x + 4y}}{{12}}\\);</p>\r\n<p>b) \\(\\frac{y}{x} - \\frac{x}{y} - \\frac{{{x^2} + {y^2}}}{{xy}}\\);</p>\r\n<p>c) \\(\\frac{4}{{x + 2}} - \\frac{3}{{x - 2}} + \\frac{{12}}{{{x^2} - 4}}\\);</p>\r\n<p>d) \\(\\frac{{x + y}}{{{x^2} - xy}} - \\frac{{4x}}{{{x^2} - {y^2}}} - \\frac{{x - y}}{{{x^2} + xy}}\\).</p><div id=\"pos_end_question\"></div><div style=\"padding-top: 10px;padding-bottom: 2px;margin-bottom: 10px;\"><p class=\"show-detail-method\" style=\"background: #654bc2;text-align: center;border-radius:5px;padding: 10px;margin-bottom: 0px;\" onclick=\"showDetailMethod();\"><strong style=\"font-size: 16px;\">Phương pháp giải - Xem chi tiết</strong><img class=\"method-open-icon\" id=\"method_colapse_icon\" src=\"data:image/png;base64,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\"></p>  <div class=\"content_method_content\" style=\"padding: 10px 10px 5px 10px;border: dashed 1px #654bc2;border-top:none;\"><p>Tính:</p>\r\n<p>a) \\(x - \\frac{{2x - y}}{4} + \\frac{{x + 4y}}{{12}}\\);</p>\r\n<p>b) \\(\\frac{y}{x} - \\frac{x}{y} - \\frac{{{x^2} + {y^2}}}{{xy}}\\);</p>\r\n<p>c) \\(\\frac{4}{{x + 2}} - \\frac{3}{{x - 2}} + \\frac{{12}}{{{x^2} - 4}}\\);</p>\r\n<p>d) \\(\\frac{{x + y}}{{{x^2} - xy}} - \\frac{{4x}}{{{x^2} - {y^2}}} - \\frac{{x - y}}{{{x^2} + xy}}\\).</p>  </div>\r\n<script type=\"text/javascript\">\r\n    var is_open =true;\r\n    function showDetailMethod(){\r\n        if(is_open){\r\n            document.querySelector(\".content_method_content\").style.display='none';\r\n            document.getElementById(\"method_colapse_icon\").classList.remove(\"method-open-icon\");\r\n            document.getElementById(\"method_colapse_icon\").classList.add(\"method-close-icon\");\r\n        }else{\r\n            document.querySelector(\".content_method_content\").style.display='block';\r\n            document.getElementById(\"method_colapse_icon\").classList.remove(\"method-close-icon\");\r\n            document.getElementById(\"method_colapse_icon\").classList.add(\"method-open-icon\");\r\n        }\r\n        is_open = !is_open;\r\n    }\r\n</script>\r\n</div><p><strong style=\"font-size: 16px;\">Lời giải chi tiết</strong></p><p>a) \\(x - \\frac{{2x - y}}{4} + \\frac{{x + 4y}}{{12}} = \\frac{{12x}}{{12}} - \\frac{{3\\left( {2x - y} \\right)}}{{12}} + \\frac{{x + 4y}}{{12}} = \\frac{{12x - 6x + 3y + x + 4y}}{{12}} = \\frac{{7x + 7y}}{{12}}\\)</p>\r\n<p>b) \\(\\frac{y}{x} - \\frac{x}{y} - \\frac{{{x^2} + {y^2}}}{{xy}} = \\frac{{{y^2}}}{{xy}} - \\frac{{{x^2}}}{{xy}} - \\frac{{{x^2} + {y^2}}}{{xy}} = \\frac{{{y^2} - {x^2} - {x^2} - {y^2}}}{{xy}} = \\frac{{ - 2{x^2}}}{{xy}} = \\frac{{ - 2x}}{y}\\)</p>\r\n<p>c) \\(\\frac{4}{{x + 2}} - \\frac{3}{{x - 2}} + \\frac{{12}}{{{x^2} - 4}} = \\frac{{4\\left( {x - 2} \\right)}}{{\\left( {x + 2} \\right)\\left( {x - 2} \\right)}} - \\frac{{3\\left( {x + 2} \\right)}}{{\\left( {x + 2} \\right)\\left( {x - 2} \\right)}} + \\frac{{12}}{{\\left( {x + 2} \\right)\\left( {x - 2} \\right)}}\\)</p>\r\n<p>\\( = \\frac{{4x - 8 - 3x - 6 + 12}}{{\\left( {x + 2} \\right)\\left( {x - 2} \\right)}} = \\frac{{x - 2}}{{\\left( {x + 2} \\right)\\left( {x - 2} \\right)}} = \\frac{1}{{x + 2}}\\)</p>\r\n<p>d) \\(\\frac{{x + y}}{{{x^2} - xy}} - \\frac{{4x}}{{{x^2} - {y^2}}} - \\frac{{x - y}}{{{x^2} + xy}} = \\frac{{{{\\left( {x + y} \\right)}^2}}}{{x\\left( {x + y} \\right)\\left( {x - y} \\right)}} - \\frac{{4{x^2}}}{{x\\left( {x + y} \\right)\\left( {x - y} \\right)}} - \\frac{{{{\\left( {x - y} \\right)}^2}}}{{x\\left( {x + y} \\right)\\left( {x - y} \\right)}}\\)</p>\r\n<p>\\( = \\frac{{{x^2} + 2xy + {y^2} - 4{x^2} - {x^2} + 2xy - {y^2}}}{{x\\left( {x + y} \\right)\\left( {x - y} \\right)}} = \\frac{{4xy - 4{x^2}}}{{x\\left( {x + y} \\right)\\left( {x - y} \\right)}} = \\frac{{ - 4x\\left( {x - y} \\right)}}{{x\\left( {x + y} \\right)\\left( {x - y} \\right)}} = \\frac{{ - 4}}{{x + y}}\\)</p>","common_article":"","display_type":1,"vungoi_exam_id":"","article_type":1,"cmt_count":0,"zip_status":1,"last_modified_time":1693296961,"last_zip_time":1693296961,"zip_link":"https://offline.loigiaihay.com/articles/1541/148148/148148_1693296961.zip","picture":"https://img.loigiaihay.com/picture/article/2023/0829/1-0_51.png","youtube_id":"","video_start_time":"0","quizlet_id":"0","ref_article_id":0,"readmore_display_type":0,"wiki":0,"comment_url":"https://loigiaihay.com/comment/giai-bai-5-trang-22-sach-bai-tap-toan-8-chan-troi-sang-tao-c1541a148148.html","origin_url":"https://loigiaihay.com/giai-bai-5-trang-22-sach-bai-tap-toan-8-chan-troi-sang-tao-c1541a148148.html","relate_link":[],"exam_file":"","solution_file":""},"callouts":[],"relate_articles":[],"others_in_cat":[{"article_id":148150,"cat_id":1541,"publish_time":1693296960,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2023/0829/resize_1-0_52.png","title":"Giải bài 6 trang 22 sách bài tập toán 8 - Chân trời sáng tạo","alias":"giai-bai-6-trang-22-sach-bai-tap-toan-8-chan-troi-sang-tao","introtext":"Tính:\r\na) \\(\\frac{1}{{ab}} + \\frac{1}{{ac}} + \\frac{1}{{bc}}\\);\r\n","display_type":1,"article_type":1},{"article_id":148152,"cat_id":1541,"publish_time":1693297020,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2023/0829/resize_1-0_54.png","title":"Giải bài 7 trang 23 sách bài tập toán 8 - Chân trời sáng tạo","alias":"giai-bai-7-trang-23-sach-bai-tap-toan-8-chan-troi-sang-tao","introtext":"Tính giá trị của biểu thức:\r\na) \\(P = \\frac{5}{{a + b}} + \\frac{6}{{a - b}} - \\frac{{12b}}{{{a^2} - {b^2}}}\\) tại \\(a = 0,12\\) và \\(b =  - 0,11\\);\r\n","display_type":1,"article_type":1},{"article_id":148154,"cat_id":1541,"publish_time":1693297080,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2023/0829/resize_1-0_55.png","title":"Giải bài 8 trang 23 sách bài tập toán 8 - Chân trời sáng tạo","alias":"giai-bai-8-trang-23-sach-bai-tap-toan-8-chan-troi-sang-tao","introtext":"Cô Xuân đi bộ quãng đường dài 3km với tốc độ trung bình x (km/h). Sau đó, cô đi tiếp quãng đường dài 2km với tốc độ trung bình ","display_type":1,"article_type":1},{"article_id":148156,"cat_id":1541,"publish_time":1693297200,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2023/0829/resize_1-0_56.png","title":"Giải bài 9 trang 23 sách bài tập toán 8 - Chân trời sáng tạo","alias":"giai-bai-9-trang-23-sach-bai-tap-toan-8-chan-troi-sang-tao","introtext":"Một đội công nhân cần sửa x (m) đường. Dự kiến đội sửa được trung bình y (m) đường mỗi ngày. ","display_type":1,"article_type":1},{"article_id":148146,"cat_id":1541,"publish_time":1693296780,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2023/0829/resize_1-0_50.png","title":"Giải bài 4 trang 22 sách bài tập toán 8 - Chân trời sáng tạo","alias":"giai-bai-4-trang-22-sach-bai-tap-toan-8-chan-troi-sang-tao","introtext":"Thực hiện các phép cộng, trừ phân thức sau:\r\na) \\(\\frac{b}{{a - b}} + \\frac{{{a^2} - 3ab}}{{{a^2} - {b^2}}}\\);\r\n","display_type":1,"article_type":1},{"article_id":148143,"cat_id":1541,"publish_time":1693296720,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2023/0829/resize_1-0_49.png","title":"Giải bài 3 trang 22 sách bài tập toán 8 - Chân trời sáng tạo","alias":"giai-bai-3-trang-22-sach-bai-tap-toan-8-chan-troi-sang-tao","introtext":"ài 3 trang 22 sách bài tập toán 8 - Chân trời sáng tạo","display_type":1,"article_type":1},{"article_id":148141,"cat_id":1541,"publish_time":1693296660,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2023/0829/resize_1-0_48.png","title":"Giải bài 2 trang 22 sách bài tập toán 8 - Chân trời sáng tạo","alias":"giai-bai-2-trang-22-sach-bai-tap-toan-8-chan-troi-sang-tao","introtext":"Quy đồng mẫu thức của các phân thức sau:\r\na) \\(\\frac{{3x}}{{2x - 1}}\\) và \\(\\frac{3}{{2x + 1}}\\);\r\n","display_type":1,"article_type":1},{"article_id":148139,"cat_id":1541,"publish_time":1693296300,"is_link":0,"thumbnail":"https://img.loigiaihay.com/picture/article/2023/0829/resize_1-0_47.png","title":"Giải bài 1 trang 22 sách bài tập toán 8 - Chân trời sáng tạo","alias":"giai-bai-1-trang-22-sach-bai-tap-toan-8-chan-troi-sang-tao","introtext":"Thực hiện các phép cộng, trừ phân thức sau:\r\na) (frac{{a - 3b}}{{a + b}} - frac{{5a + b}}{{a + b}});\t\r\n","display_type":1,"article_type":1}],"event_info":{"title":"Bài 6. 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