How do you find the center and radius for #(x + 14)^2 + (y - 6)^2 = 9#?centre = (-14 ,6), radius = 3The standard equation of a circle is. where (a ,b) are the coordinates of the centre and r, the radius. The equation here is in this form and by comparison.#a=-14,b=6" and " r^2=9rArrr=3##rArr" centre " =(-14,6)" and " r=3#