75.25999999999999), ('Chile', 46.62)]    Thought: I now know the final answer    Final Answer: The customers from the USA spent the most, with a total of $523.06.        > Finished chain.    'The customers from the USA spent the most, with a total of $523.06.'agent_executor.run(    "Show the total number of tracks in each playlist. The Playlist name should be included in the result.")            > Entering new AgentExecutor chain...    Action: list_tables_sql_db    Action Input: ""    Observation: Invoice, MediaType, Artist, InvoiceLine, Genre, Playlist, Employee, Album, PlaylistTrack, Track, Customer    Thought: I should look at the schema of the Playlist and PlaylistTrack tables to see what columns I can use.    Action: schema_sql_db    Action Input: "Playlist, PlaylistTrack"    Observation:     CREATE TABLE "Playlist" (        "PlaylistId" INTEGER NOT NULL,         "Name" NVARCHAR(120),         PRIMARY KEY ("PlaylistId")    )        SELECT * FROM 'Playlist' LIMIT 3;    PlaylistId Name    1 Music    2 Movies    3 TV Shows            CREATE TABLE "PlaylistTrack" (        "PlaylistId" INTEGER NOT NULL,         "TrackId" INTEGER NOT NULL,         PRIMARY KEY ("PlaylistId", "TrackId"),         FOREIGN KEY("TrackId") REFERENCES "Track" ("TrackId"),         FOREIGN KEY("PlaylistId") REFERENCES "Playlist" ("PlaylistId")    )        SELECT * FROM 'PlaylistTrack' LIMIT 3;    PlaylistId TrackId    1 3402    1 3389    1 3390    Thought: I can use a SELECT statement to get the total number of tracks in each playlist.    Action: query_checker_sql_db    Action Input: SELECT Playlist.Name, COUNT(PlaylistTrack.TrackId) AS TotalTracks FROM Playlist INNER JOIN PlaylistTrack ON Playlist.PlaylistId = PlaylistTrack.PlaylistId GROUP BY Playlist.Name    Observation:         SELECT Playlist.Name, COUNT(PlaylistTrack.TrackId) AS TotalTracks FROM Playlist INNER JOIN PlaylistTrack ON Playlist.PlaylistId = PlaylistTrack.PlaylistId GROUP BY Playlist.Name    Thought: The query looks correct,
This notebook showcases an agent designed to interact with a SQL databases.
This notebook showcases an agent designed to interact with a SQL databases. ->: 75.25999999999999), ('Chile', 46.62)]    Thought: I now know the final answer    Final Answer: The customers from the USA spent the most, with a total of $523.06.        > Finished chain.    'The customers from the USA spent the most, with a total of $523.06.'agent_executor.run(    "Show the total number of tracks in each playlist. The Playlist name should be included in the result.")            > Entering new AgentExecutor chain...    Action: list_tables_sql_db    Action Input: ""    Observation: Invoice, MediaType, Artist, InvoiceLine, Genre, Playlist, Employee, Album, PlaylistTrack, Track, Customer    Thought: I should look at the schema of the Playlist and PlaylistTrack tables to see what columns I can use.    Action: schema_sql_db    Action Input: "Playlist, PlaylistTrack"    Observation:     CREATE TABLE "Playlist" (        "PlaylistId" INTEGER NOT NULL,         "Name" NVARCHAR(120),         PRIMARY KEY ("PlaylistId")    )        SELECT * FROM 'Playlist' LIMIT 3;    PlaylistId Name    1 Music    2 Movies    3 TV Shows            CREATE TABLE "PlaylistTrack" (        "PlaylistId" INTEGER NOT NULL,         "TrackId" INTEGER NOT NULL,         PRIMARY KEY ("PlaylistId", "TrackId"),         FOREIGN KEY("TrackId") REFERENCES "Track" ("TrackId"),         FOREIGN KEY("PlaylistId") REFERENCES "Playlist" ("PlaylistId")    )        SELECT * FROM 'PlaylistTrack' LIMIT 3;    PlaylistId TrackId    1 3402    1 3389    1 3390    Thought: I can use a SELECT statement to get the total number of tracks in each playlist.    Action: query_checker_sql_db    Action Input: SELECT Playlist.Name, COUNT(PlaylistTrack.TrackId) AS TotalTracks FROM Playlist INNER JOIN PlaylistTrack ON Playlist.PlaylistId = PlaylistTrack.PlaylistId GROUP BY Playlist.Name    Observation:         SELECT Playlist.Name, COUNT(PlaylistTrack.TrackId) AS TotalTracks FROM Playlist INNER JOIN PlaylistTrack ON Playlist.PlaylistId = PlaylistTrack.PlaylistId GROUP BY Playlist.Name    Thought: The query looks correct,