CC1CCOC(=O)/C=C/C=C\C(=O)OC2CC3OC4C5OC5(C)C(O)CC4(COC(=O)C1O)C2(C)C31CO1
For non-ionizable compounds Log P = Log D throughout pH range, whereas for ionizable compounds Log D takes into account the partition of both ionized and non-ionized forms. What is the negative log D of this molecule?