C#C[C@]1(O)CC[C@H]2[C@@H]3CCC4=C/C(=N/OC(=O)c5cccc6c(=O)c7ccccc7[nH]c56)CCC4[C@H]3CC[C@@]21CC
For non-ionizable compounds Log P = Log D throughout pH range, whereas for ionizable compounds Log D takes into account the partition of both ionized and non-ionized forms.  What is log D of this molecule?