CC(C)(C)OC(=O)C[C@@H]1C/C=C\C[C@H](CC(=O)NCCO)C(=O)NC[C@@H](c2ccccc2)OC1=O
For non-ionizable compounds Log P = Log D throughout pH range, whereas for ionizable compounds Log D takes into account the partition of both ionized and non-ionized forms. What is the negative log D of this molecule?