CCC(=O)O[C@H]1CC[C@H]2[C@@H]3CCC4=C/C(=N/OC(=O)c5cccc6cc7ccccc7nc56)CC[C@]4(C)[C@H]3CC[C@]12C
For non-ionizable compounds Log P = Log D throughout pH range, whereas for ionizable compounds Log D takes into account the partition of both ionized and non-ionized forms.  What is log D of this molecule?