ergo ADVPOS quoniam CONJ i PRON41NOMSN non ADV explic V11PRESPASSIVEIND3S numer N21DATSM in PREPABL e V11PRESACTIVEIND1S quadr V11FUTACTIVEIMP2S long ADJ11DATSMPOS et CONJ lat VPAR32DATSMPERFPASSIVEPPL pedes N31NOMSM x NUM20XXXCARD qu PRON10NOMSN fu V51PERFACTIVESUB3S line N11NOMSF ab PREPABL angul N21DATSM ad ADVPOS angul N21ACCSM diagoni ADJ26NOMSCPOS perduc V31PRESPASSIVESUB3S ut V31PRESINF0X divid V31PRESPASSIVESUB3P du NUM12NOMPMCARD trigon N22NOMPN aequ N22NOMPN magnitudi OTHER n V21PRESACTIVEIMP2S singul ADJ11NOMSFPOS are N11GENSF ped N22NOMSN quinquagen NUM20GENPCDIST ad ADVPOS e PRON41GENSX que CONJ line N11GENSF diagonal ADJ32NOMSCPOS longitudin N31ACCSF loc N21NOMSM quadrat VPAR11NOMSMPERFPASSIVEPPL par N31LOCPC later N31LOCPM describ V31PRESPASSIVESUB3S
Since arithmetic does not furnish a solution, let a diagonal line be drawn from angle to angle in the square which was 10 feet long and wide, so that two triangles of equal magnitude, each of the area of 50 feet, are described. On the length of the diagonal let a square be described with equal sides.
final_alignments\Vitruvius_Architecture_Book_9.json