Ergo quoniam id non explicatur numero, in eo quadrato, longo et lato pedes x quod fuerit, linea ab angulo ad angulum diagonios perducatur, uti dividantur duo trigona aequa magnitudine, singula areae pedum quinquagenm, ad eiusque lineae diagonalis longitudinem locus quadratus paribus lateribus describatur.
Since arithmetic does not furnish a solution, let a diagonal line be drawn from angle to angle in the square which was 10 feet long and wide, so that two triangles of equal magnitude, each of the area of 50 feet, are described. On the length of the diagonal let a square be described with equal sides.
final_alignments\Vitruvius_Architecture_Book_9.json