# questions

title: which-substance-has-a-dipole-moment
slug: which-substance-has-a-dipole-moment-89894
question: <div class="question">Which substance has a dipole moment?</div>
tags: ['Chemistry', 'Chemical Bonding and Molecular Structure', 'BITSAT', 'BITSAT 2018']
source_db: MarksBatch2_P4.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>CCl</mi><mn>4</mn></msub></math></span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>CH</mi><mn>2</mn></msub><msub><mi>Cl</mi><mn>2</mn></msub></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi mathvariant="normal">C</mi><mn>2</mn></msub><msub><mi>Cl</mi><mn>2</mn></msub></math></span> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi mathvariant="normal">C</mi><mn>2</mn></msub><msub><mi>Cl</mi><mn>4</mn></msub></math></span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>CH</mi><mn>2</mn></msub><msub><mi>Cl</mi><mn>2</mn></msub></math></span> </div>

answer:
<div class="solution"><p><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>CH</mi><mn>2</mn></msub><msub><mi>Cl</mi><mn>2</mn></msub></math> is similar to <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>CH</mi><mn>4</mn></msub></math> (tetrahedral) but it has three different bond angles.<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>HCH</mi><mo>,</mo><mi>HCCl</mi><mo>,</mo><mi>ClCCl</mi><mo>,</mo></math> which are close to but not equal to <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>109</mn><mo>.</mo><mn>5</mn><mo>°</mo><mo>.</mo></math> Since, electronegativity of <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>Cl</mi><mo>&gt;</mo><mi mathvariant="normal">C</mi><mo>&gt;</mo><mi mathvariant="normal">H</mi></math> the bond dipole moments do not cancel and the molecule has a dipole moment.</p><p><img src="https://cdn-question-pool.getmarks.app/pyq/bitsat/d9d2342b-0c1a-46bf-a87b-1fbff1c0ca92-image.png" style="width: 199px; height: 209px;"/></p></div>


tags: ['Chemistry', 'General Organic Chemistry', 'BITSAT', 'BITSAT 2018']
source_db: MarksBatch2_P4.db
title:
which-test-among-the-following-is-not-used-for-the-distinction-among-1-0-2-0-and-3-0-aliphatic-amine

slug:
which-test-among-the-following-is-not-used-for-the-distinction-among-1-0-2-0-and-3-0-aliphatic-amine-31294

question:
<div class="question">Which test among the following is not used for the distinction among <math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mn>1</mn><mn>0</mn></msup><mo>,</mo><mo> </mo><msup><mn>2</mn><mn>0</mn></msup></math> and <math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mn>3</mn><mn>0</mn></msup></math> aliphatic amine.</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Hinsberg's reagent test</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Carbylamine reaction</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">Azo dye test</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Action with nitrous acid</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Azo dye test</span> </div>

answer:
<div class="solution"><p>Hinsberg test for the detection and distinction of primary, secondary, and tertiary amines in a given sample.</p><p>Carbylamine reaction is the reaction of a primary amine, chloroform and a base to synthesize isocyanides.</p><p>Azo dye test is not used for the detection of primary, secondary and tertiary aliphatic amines.</p><p>The Reaction of Amines with Nitrous Acid, primary and secondary amines react with nitrous acid forming arene diazonium salts and N-nitrosoamine respectively.</p></div>


title: which-will-not-result-in-the-formation-of-anisole
slug: which-will-not-result-in-the-formation-of-anisole-24234
question: <div class="question">Which will not result in the formation of anisole?</div>
tags: ['Chemistry', 'Alcohols Phenols and Ethers', 'BITSAT', 'BITSAT 2023 (Memory Based Paper 2)']
source_db: MarksBatch2_P4.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\mathrm{PhOH}+\mathrm{CH}_3 \mathrm{Cl} \stackrel{\mathrm{OH}^{-}}{\longrightarrow}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\mathrm{Ph}-\mathrm{Cl}+\mathrm{CH}_3 \mathrm{ONa} \frac{623 \mathrm{~K}}{300 \mathrm{~atm}}$</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data"><br/><img src="https://cdn-question-pool.getmarks.app/pyq/bitsat/y-jyFVBV_1rofVOlbFMtU1rzYbtbhxMTIsJ44LMYkLg.original.fullsize.png"/><br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><br/><img src="https://cdn-question-pool.getmarks.app/pyq/bitsat/sZPaGtV-7mn-gpRkaoXsg1Yt4bkjNNwsjcbIsg6GQ8s.original.fullsize.png"/><br/></span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><br/><img src="https://cdn-question-pool.getmarks.app/pyq/bitsat/y-jyFVBV_1rofVOlbFMtU1rzYbtbhxMTIsJ44LMYkLg.original.fullsize.png"/><br/></span> </div>

answer:
<div class="solution">$\left[\mathrm{PtCl}_2\left(\mathrm{NH}_3\right)_4\right] \mathrm{Br}_2$ and $\left[\mathrm{PtBr}_2\left(\mathrm{NH}_3\right)_4\right] \mathrm{Cl}_2$ are ionisation isomers.</div>


tags: ['Mathematics', 'Binomial Theorem', 'BITSAT', 'BITSAT 2010']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">5780</span> </div>
source_db: MarksBatch2_P4.db
title:
with-17-consonants-and-5-vowels-the-number-of-words-of-four-letters-that-can-be-formed-having-two-different-vowels-in-the-middle-and-one-consonant-rep

slug:
with-17-consonants-and-5-vowels-the-number-of-words-of-four-letters-that-can-be-formed-having-two-different-vowels-in-the-middle-and-one-consonant-rep-55984

question:
<div class="question">With 17 consonants and 5 vowels the number of words of four letters that can be formed having two different vowels in the middle and one consonant, repeated or different at each end is</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">5780</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">2890</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">5440</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">2720</span> </li> </ul>

answer:
<div class="solution">The two letters, the first and the last of the four lettered word can be chosen in \((17)^2\) ways, as repetition is allowed for consonants. The two vowels in the middle are distinct so that the number of ways of filling up the two places is \({ }^5 \mathrm{P}_2=20\).<br/>The no. of different words \(=(17)^2 \cdot 20=5780\).</div>


tags: ['Mathematics', 'Vector Algebra', 'BITSAT', 'BITSAT 2010']
source_db: MarksBatch2_P4.db
title:
with-respect-to-a-rectangular-cartesian-coordinate-system-three-vectors-are-expressed-as-veca4-hatihatj-vecb3-hati2-hatj-and-vecchatk-quad-where-hatma

slug:
with-respect-to-a-rectangular-cartesian-coordinate-system-three-vectors-are-expressed-as-veca4-hatihatj-vecb3-hati2-hatj-and-vecchatk-quad-where-hatma-27649

question:
<div class="question">With respect to a rectangular cartesian coordinate system, three vectors are expressed as :<br/>\(\vec{a}=4 \hat{i}-\hat{j}, \vec{b}=-3 \hat{i}+2 \hat{j}\) and \(\vec{c}=-\hat{k} \quad\) where \(\hat{\mathrm{i}}, \hat{\mathrm{j}}, \hat{\mathrm{k}}\) are unit vectors, along the \(X\), \(Y\) and \(Z\)-axis respectively. The unit vector \(\hat{r}\) along the direction of sum of these vector is -</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">\(\hat{\mathrm{r}}=\frac{1}{\sqrt{3}}(\hat{\mathrm{i}}+\hat{\mathrm{j}}-\hat{\mathrm{k}})\)</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">\(\hat{\mathrm{r}}=\frac{1}{\sqrt{2}}(\hat{\mathrm{i}}+\hat{\mathrm{j}}-\hat{\mathrm{k}})\)</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">\(\hat{\mathrm{i}}=\frac{1}{3}(\hat{\mathrm{i}}-\hat{\mathrm{j}}+\hat{\mathrm{k}})\)</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">\(\hat{\mathrm{r}}=\frac{1}{\sqrt{2}}(\hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}})\)</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">\(\hat{\mathrm{r}}=\frac{1}{\sqrt{3}}(\hat{\mathrm{i}}+\hat{\mathrm{j}}-\hat{\mathrm{k}})\)</span> </div>

answer:
<div class="solution">\(\begin{aligned}<br/>&amp; \overrightarrow{\mathrm{r}}=\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}+\overrightarrow{\mathrm{c}}=4 \hat{\mathrm{i}}-\hat{\mathrm{j}}-3 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}-\hat{\mathrm{k}}=\hat{\mathrm{i}}+\hat{\mathrm{j}}-\hat{\mathrm{k}} \\<br/>&amp; \hat{\mathrm{r}}=\frac{\overrightarrow{\mathrm{r}}}{|\mathrm{r}|}=\frac{\hat{\mathrm{i}}+\hat{\mathrm{j}}-\hat{\mathrm{k}}}{\sqrt{1^2+1^2+(-1)^2}}=\frac{\hat{\mathrm{i}}+\hat{\mathrm{j}}-\hat{\mathrm{k}}}{\sqrt{3}}<br/>\end{aligned}\)</div>


tags: ['Physics', 'Mechanical Properties of Fluids', 'BITSAT', 'BITSAT 2017']
source_db: MarksBatch2_P4.db
title:
work-done-in-increasing-the-size-of-a-soap-bubble-from-radius-of-3-to-5-cm-is-nearly-surface-tension-of-soap-solution-0-03-nm-1

slug:
work-done-in-increasing-the-size-of-a-soap-bubble-from-radius-of-3-to-5-cm-is-nearly-surface-tension-of-soap-solution-0-03-nm-1-26146

question:
<div class="question">Work done in increasing the size of a soap bubble from radius of (<math xmlns="http://www.w3.org/1998/Math/MathML"><mn>3</mn></math> to <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>5</mn></math>) <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>cm</mi></math> is nearly (surface tension of soap solution <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mn>0</mn><mo>.</mo><mn>03</mn><mo> </mo><msup><mi>Nm</mi><mrow><mo>-</mo><mn>1</mn></mrow></msup></math>)</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.</mo><mn>2</mn><mi mathvariant="normal">π</mi><mo> </mo><mi>mJ</mi></math></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>2</mn><mi mathvariant="normal">π</mi><mo> </mo><mi>mJ</mi></math></span> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.</mo><mn>4</mn><mi mathvariant="normal">π</mi><mo> </mo><mi>mJ</mi></math></span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>4</mn><mi mathvariant="normal">π</mi><mo> </mo><mi>mJ</mi></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>4</mn><mi mathvariant="normal">π</mi><mo> </mo><mi>mJ</mi></math></span> </div>

answer:
<div class="solution"><p>Work done <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo></math> Change in surface energy</p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>r</mi><mn>2</mn></msub><mo>=</mo><mn>5</mn><mo> </mo><mi>cm</mi></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>r</mi><mn>1</mn></msub><mo>=</mo><mn>3</mn><mo> </mo><mi>cm</mi></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>⇒</mo><mo> </mo><mi>W</mi><mo>=</mo><mn>2</mn><mi>T</mi><mo>×</mo><mn>4</mn><mi>π</mi><mfenced><mrow><msubsup><mi>r</mi><mn>2</mn><mn>2</mn></msubsup><mo>-</mo><msubsup><mi>r</mi><mn>1</mn><mn>2</mn></msubsup></mrow></mfenced></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mn>2</mn><mo>×</mo><mn>0</mn><mo>.</mo><mn>03</mn><mo>×</mo><mn>4</mn><mi>π</mi><mfenced close="]" open="["><mrow><msup><mfenced><mn>5</mn></mfenced><mn>2</mn></msup><mo>-</mo><msup><mfenced><mn>3</mn></mfenced><mn>2</mn></msup></mrow></mfenced><mo>×</mo><msup><mn>10</mn><mrow><mo>-</mo><mn>4</mn></mrow></msup></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mn>0</mn><mo>.</mo><mn>4</mn><mi>π</mi><mo> </mo><mi>mJ</mi></math></p></div>


tags: ['Chemistry', 'Thermodynamics (C)', 'BITSAT', 'BITSAT 2021']
source_db: MarksBatch2_P4.db
title:
work-out-the-heat-change-cal-when-40-g-of-he-gas-at-2-7-c-undergoes-isothermal-and-reversible-compression-from-initial-pressure-of-1-atm-to-10-atm-r-2

slug:
work-out-the-heat-change-cal-when-40-g-of-he-gas-at-2-7-c-undergoes-isothermal-and-reversible-compression-from-initial-pressure-of-1-atm-to-10-atm-r-2-10060

question:
<div class="question">Work out the heat change (cal) when $40 \mathrm{~g}$ of He gas at $27^{\circ} \mathrm{C}$ undergoes isothermal and reversible compression from initial pressure of $1 \mathrm{~atm}$ to $10 \mathrm{~atm}\left(\mathrm{R}=2 \mathrm{cal} \mathrm{K}^{-1} \mathrm{~mol}^{-1}\right)$.</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$13.818 \mathrm{kcal}$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$-13.818 \mathrm{kcal}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$55.272 \mathrm{kcal}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$-55.272 \mathrm{k} \mathrm{cal}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$-13.818 \mathrm{kcal}$</span> </div>

answer:
<div class="solution">$\begin{aligned} \mathrm{q} &amp;=-\mathrm{w}_{\mathrm{rev}}=-\left(-2.303 \mathrm{nRT} \log \frac{\mathrm{P}_{1}}{\mathrm{P}_{2}}\right) \\ &amp;=2.303 \times \frac{40}{4} \times 2 \times 300 \log \frac{1}{10}=-13.82 \mathrm{kcal} \end{aligned}$</div>


