# questions

title: in-a-triangle-abc-a-2-b-c-0-the-value-of-cot-2-a-cot-2-c-is
slug: in-a-triangle-abc-a-2-b-c-0-the-value-of-cot-2-a-cot-2-c-is-90026
tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2017 (Phase 2)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">3</span> </div>
source_db: MarksBatch2_P1.db
question:
<div class="question">In a triangle $\mathrm{ABC}, \mathrm{a}-2 \mathrm{~b}+\mathrm{c}=0 .$ The value of $\cot \left(\frac{\mathrm{A}}{2}\right) \cot \left(\frac{\mathrm{C}}{2}\right)$ is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{9}{2}$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">3</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\frac{3}{2}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">1</span> </li> </ul>

answer:
<div class="solution">Given, $\mathrm{a}-2 \mathrm{~b}+\mathrm{c}=0 \Rightarrow \mathrm{a}+\mathrm{c}=2 \mathrm{~b} \cot \left(\frac{\mathrm{A}}{2}\right) \cot \left(\frac{\mathrm{C}}{2}\right)$<br/>$=\sqrt{\frac{\mathrm{s}(\mathrm{s}-\mathrm{a})}{(\mathrm{s}-\mathrm{b})(\mathrm{s}-\mathrm{c})} \times \frac{\mathrm{s}(\mathrm{s}-\mathrm{c})}{(\mathrm{s}-\mathrm{a})(\mathrm{s}-\mathrm{b})}}=\sqrt{\frac{\mathrm{s}^{2}}{(\mathrm{~s}-\mathrm{b})^{2}}}=\frac{\mathrm{s}}{\mathrm{s}-\mathrm{b}}$<br/>$=\frac{2 \mathrm{~s}}{2 \mathrm{~s}-2 \mathrm{~b}}=\frac{\mathrm{a}+\mathrm{b}+\mathrm{c}}{\mathrm{a}+\mathrm{b}+\mathrm{c}-2 \mathrm{~b}}=\frac{2 \mathrm{~b}+\mathrm{b}}{2 \mathrm{~b}-\mathrm{b}}=\frac{3 \mathrm{~b}}{\mathrm{~b}}=3$</div>


title: in-a-triangle-abc-a-8-b-10-and-c-12-what-is-the-angle-c-equal-to
slug: in-a-triangle-abc-a-8-b-10-and-c-12-what-is-the-angle-c-equal-to-43955
tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2011 (Phase 2)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In a triangle $\mathrm{ABC}, a=8, b=10$ and $c=12$. What is the angle C equal to?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$A / 2$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$2 \mathrm{~A}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$3 \mathrm{~A}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$3 \mathrm{~A} / 2$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$2 \mathrm{~A}$</span> </div>

answer:
<div class="solution"><img src="https://cdn-question-pool.getmarks.app/pyq/nda/jdnQbU3EwBQQ-EDwSPMunLUhvUOb80brTK2Jh6s_BVU.original.fullsize.png"/><br/><br/>$\cos C=\frac{a^{2}+b^{2}-c^{2}}{2 a b}=\frac{164-144}{2(8)(10)}=\frac{1}{8}$<br/>$\cos A=\frac{b^{2}+c^{2}-a^{2}}{2 b c}=\frac{3}{4}$<br/>$\operatorname{Sin} C=\frac{3 \sqrt{7}}{8}$ and $\operatorname{Sin} A=\frac{\sqrt{7}}{4}$<br/>$\frac{\cos C}{\cos A}=\frac{1}{6} &lt; 1 \Rightarrow \cos C &lt; \cos A \Rightarrow \mathrm{C}&gt;\mathbf{A}$<br/>$\cos (C-A)=\cos C \cos A+\sin C \sin A$<br/>$=\frac{1}{8} \times \frac{3}{4}+\frac{3 \sqrt{7}}{8} \times \frac{\sqrt{7}}{4}=\frac{3}{4}=\cos A$<br/>$\Rightarrow \mathrm{C}-\mathrm{A}=\mathrm{A} \Rightarrow \mathrm{C}=2 A$</div>


title: in-a-triangle-abc-b-3-cm-c-1-cm-a-3-0-what-is-the-value-of-a
slug: in-a-triangle-abc-b-3-cm-c-1-cm-a-3-0-what-is-the-value-of-a-41403
tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2008 (Phase 1)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In a triangle $\mathrm{ABC}, \mathrm{b}=\sqrt{3} \mathrm{~cm}, \mathrm{c}=1 \mathrm{~cm}, \angle \mathrm{A}=30^{\circ}$, what is<br/>the value of a?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\sqrt{2} \mathrm{~cm}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$2 \mathrm{~cm}$</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">$1 \mathrm{~cm}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$\frac{1}{2} \mathrm{~cm}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$1 \mathrm{~cm}$</span> </div>

answer:
<div class="solution">As given: In a triangle $\mathrm{ABC}, \mathrm{AC}=\mathrm{b}=\sqrt{3} \mathrm{~cm}, \mathrm{AB}$<br/>$=\mathrm{c}=1 \mathrm{~m}$ and $\angle \mathrm{A}=30^{\circ}$<br/>From cosine formulae<br/>$\cos A=\frac{b^{2}+c^{2}-a^{2}}{2 b c}=\frac{(\sqrt{3})^{2}+1^{2}-a^{2}}{2 \sqrt{3} \cdot 1}$<br/>$\Rightarrow \frac{\sqrt{3}}{2}=\frac{3+1-a^{2}}{2 \sqrt{3}} \Rightarrow 3=4-a^{2}$<br/>$\Rightarrow \mathrm{a}^{2}=4-3=1 \Rightarrow \mathrm{a}=1 \mathrm{~cm}$</div>


title: in-a-triangle-abc-c-2-a-4-5-a-2-2-than-what-is-c-equal-to
slug: in-a-triangle-abc-c-2-a-4-5-a-2-2-than-what-is-c-equal-to-15862
tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2014 (Phase 2)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In a triangle $\mathrm{ABC}, \mathrm{c}=2, \mathrm{~A}=45^{\circ}, \mathrm{a}=2 \sqrt{2}$, than what is $\mathrm{C}$<br/>equal to ?</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">$30^{\circ}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$15^{\circ}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$45^{\circ}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">None of these</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$30^{\circ}$</span> </div>

answer:
<div class="solution">According to sine rule,<br/>$\frac{\mathrm{a}}{\sin \mathrm{A}}=\frac{\mathrm{b}}{\sin \mathrm{B}}=\frac{\mathrm{c}}{\sin \mathrm{C}}$<br/>$\therefore \frac{\mathrm{a}}{\sin \mathrm{A}}=\frac{\mathrm{c}}{\sin \mathrm{C}}$<br/>$\Rightarrow \sin C=\frac{\mathrm{c} \cdot \sin \mathrm{A}}{\mathrm{a}}=\frac{2 \cdot \sin 45^{\circ}}{2 \sqrt{2}}$<br/>$=\frac{1}{\sqrt{2}} \cdot \frac{1}{\sqrt{2}}=\frac{1}{2}=\sin 30^{\circ}$<br/>$\mathrm{C}=30^{\circ}$</div>


title: in-a-triangle-abc-if-a-2-b-3-and-sin-a-3-2-then-what-is-angle-b-equal-to
slug: in-a-triangle-abc-if-a-2-b-3-and-sin-a-3-2-then-what-is-angle-b-equal-to-10703
tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2018 (Phase 1)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In a triangle $\mathrm{ABC}$ if $\mathrm{a}=2, \mathrm{~b}=3$ and $\sin \mathrm{A}=\frac{2}{3}$, then what is angle B equal to?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{\pi}{4}$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$\frac{\pi}{2}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\frac{\pi}{3}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$\frac{\pi}{6}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\frac{\pi}{2}$</span> </div>

answer:
<div class="solution">In $\Delta \mathrm{ABC}, \mathrm{a}=2, \mathrm{~b}=3$ and $\sin \mathrm{A}=\frac{2}{3}$<br/>We know, $\frac{\sin A}{a}=\frac{\sin B}{b}$<br/>$\Rightarrow \frac{\frac{2}{3}}{2}=\frac{\sin B}{3}$<br/>$\Rightarrow \frac{2}{6}=\frac{\sin B}{3} \Rightarrow \sin B=\frac{6}{6}=1$<br/>$\Rightarrow B=\sin ^{-1}(1)$ ...(1)<br/>$=\frac{\pi}{2}$.</div>


title: in-a-triangle-abc-if-a-2-b-and-a-3-b-then-which-one-of-the-following-is-correct
slug: in-a-triangle-abc-if-a-2-b-and-a-3-b-then-which-one-of-the-following-is-correct-83295
tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2007 (Phase 1)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In a triangle $\mathrm{ABC}$, if $\mathrm{a}=2 \mathrm{~b}$ and $\mathrm{A}=3 \mathrm{~B}$ then which one of the following is correct?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">The triangle is obtuse-angled</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">The triangle is acute-angled but not right-angled</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">The triangle is right-angled</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">The triangle is isosceles but not obtuse-angled</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">The triangle is right-angled</span> </div>

answer:
<div class="solution">We know from the Sine law that<br/>$\frac{\mathrm{a}}{\sin \mathrm{A}}=\frac{\mathrm{b}}{\sin \mathrm{B}}$<br/>$\Rightarrow \frac{2 b}{\sin 3 B}=\frac{b}{\sin B}$<br/>$\Rightarrow 2 \sin B=\sin 3 B$<br/>$\Rightarrow 2 \sin B=3 \sin B-4 \sin ^{3} B$<br/>$\Rightarrow \sin B-4 \sin ^{3} B=0$<br/>$\Rightarrow \sin B\left(1-4 \sin ^{2} B\right)=0$<br/>$\Rightarrow \sin B=0$ or $1-4 \sin ^{2} B=0 \Rightarrow B=0$ or $B=30^{\circ}$<br/>$\Rightarrow \mathrm{B}=30^{\circ}$ and $\mathrm{A}=3 \times 30^{\circ}=90^{\circ}$<br/>$\Rightarrow \mathrm{B}=0$ is not possible so, $\mathrm{B}=30^{\circ}$ and $\mathrm{A}=3 \times 30^{\circ}=90^{\circ}$<br/>$\Rightarrow$ The triangle is right angled triangle.</div>


title: in-a-triangle-abc-if-cos-a-cos-b-cos-c-what-is-the-value-of-tan-a-tan-b-tan-c
slug: in-a-triangle-abc-if-cos-a-cos-b-cos-c-what-is-the-value-of-tan-a-tan-b-tan-c-81163
tags: ['Mathematics', 'Trigonometric Ratios & Identities', 'NDA', 'NDA 2006 (Phase 1)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">0</span> </div>
source_db: MarksBatch2_P1.db
question:
<div class="question">In a triangle $\mathrm{ABC}$, $\mathrm{if} \cos \mathrm{A}=\cos \mathrm{B} \cos \mathrm{C}$, what is the value of<br/>$\tan A-\tan B-\tan C$ ?</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">0</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$-1$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$1+\tan A \tan B \tan C$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$\tan \mathrm{A} \tan \mathrm{B} \tan \mathrm{C}-1$</span> </li> </ul>

answer:
<div class="solution">As given, $\cos \mathrm{A}=\cos \mathrm{B} \cos \mathrm{C}$<br/>$\tan A-\tan B-\tan C$<br/>$=\frac{\sin A}{\cos A}-\frac{\sin B}{\cos B}-\frac{\sin C}{\cos C}$<br/>$=\frac{\sin A}{\cos A}-\frac{(\sin B \cos C+\cos B \sin C)}{\cos B \cos C}$<br/>$=\frac{\sin \mathrm{A}-\sin (\mathrm{B}+\mathrm{C})}{\cos \mathrm{A}} \quad \ldots[\mathrm{using}(1)]$<br/>$\begin{array}{rr}=\frac{\sin A-\sin (\pi-A)}{\cos A} &amp; {[\text { Since, } A+B+C=\pi} \\ &amp; \text { So, } B+C=\pi-A]\end{array}$<br/>$=\frac{\sin A-\sin A}{\cos A}=0$</div>


tags: ['Mathematics', 'Vector Algebra', 'NDA', 'NDA 2018 (Phase 2)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">One</span> </div>
source_db: MarksBatch2_P1.db
title:
in-a-triangle-abc-if-taken-in-order-consider-the-following-statements-1-ab-bc-ca-0-2-ab-bc-ca-0-3-ab-bc-ca-0-4-ba-bc-ca-0-how-many-of-the-above-statem

slug:
in-a-triangle-abc-if-taken-in-order-consider-the-following-statements-1-ab-bc-ca-0-2-ab-bc-ca-0-3-ab-bc-ca-0-4-ba-bc-ca-0-how-many-of-the-above-statem-59968

question:
<div class="question">In a triangle $\mathrm{ABC}$, if taken in order, consider the following statements:<br/>$1.$ $\overrightarrow{\mathrm{AB}}+\overrightarrow{\mathrm{BC}}+\overrightarrow{\mathrm{CA}}=\overrightarrow{0}$<br/>$2.$ $\overrightarrow{\mathrm{AB}}+\overrightarrow{\mathrm{BC}}-\overrightarrow{\mathrm{CA}}=\overrightarrow{0}$<br/>$3.$ $\overrightarrow{\mathrm{AB}}-\overrightarrow{\mathrm{BC}}+\overrightarrow{\mathrm{CA}}=\overrightarrow{0}$<br/>$4.$ $\overrightarrow{\mathrm{BA}}-\overrightarrow{\mathrm{BC}}+\overrightarrow{\mathrm{CA}}=\overrightarrow{0}$<br/>How many of the above statements are correct?</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">One</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Two</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Three</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Four</span> </li> </ul>

answer:
<div class="solution">From triangle law of vector addition<br/>$\overrightarrow{\mathrm{AB}}+\overrightarrow{\mathrm{BC}}+\overrightarrow{\mathrm{CA}}=0$<br/>Only statement $(1)$ is correct.</div>


title: in-a-triangle-abc-if-the-angles-a-b-c-are-in-ap-then-which-one-of-the-following-is-correct
slug: in-a-triangle-abc-if-the-angles-a-b-c-are-in-ap-then-which-one-of-the-following-is-correct-24851
tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2012 (Phase 1)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In a triangle $\mathrm{ABC}$ if the angles $\mathrm{A}, \mathrm{B}, \mathrm{C}$ are in $\mathrm{AP}$, then which one of the following is correct?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\quad \mathrm{c}=\mathrm{a}+\mathrm{b}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$c^{2}=a^{2}+b^{2}-a b$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$a^{2}=b^{2}+c^{2}-b c$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$\quad b^{2}=a^{2}+c^{2}-a c$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\quad b^{2}=a^{2}+c^{2}-a c$</span> </div>

answer:
<div class="solution">Since $\mathrm{A}, \mathrm{B}, \mathrm{C}$ are in A.P. $\therefore 2 \mathrm{~B}=\mathrm{A}+\mathrm{C}$<br/>Also, $\mathrm{A}+\mathrm{B}+\mathrm{C}=180^{\circ} \Rightarrow 2 \mathrm{~B}+\mathrm{B}=180^{\circ}$<br/>$\Rightarrow 3 \mathrm{~B}=180^{\circ} \Rightarrow \mathrm{B}=60^{\circ}$<br/>Now, we know<br/>$\cos B=\frac{a^{2}+c^{2}-b^{2}}{2 a c}$<br/>$\Rightarrow \cos 60^{\circ}=\frac{\mathrm{a}^{2}+\mathrm{c}^{2}-\mathrm{b}^{2}}{2 \mathrm{ac}}$<br/>$\Rightarrow \frac{1}{2}=\frac{\mathrm{a}^{2}+\mathrm{c}^{2}-\mathrm{b}^{2}}{2 \mathrm{ac}} \Rightarrow \mathrm{ac}=\mathrm{a}^{2}+\mathrm{c}^{2}-\mathrm{b}^{2}$<br/>$\Rightarrow b^{2}=a^{2}+c^{2}-a c$</div>


title: in-a-triangle-abc-sin-a-cos-b-cos-c-then-what-is-b-equal-to
slug: in-a-triangle-abc-sin-a-cos-b-cos-c-then-what-is-b-equal-to-91050
tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2014 (Phase 2)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In a triangle $\mathrm{ABC}, \sin \mathrm{A}-\cos \mathrm{B}=\cos \mathrm{C}$, then what is $\mathrm{B}$ equal<br/>to ?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\pi$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\pi / 3$</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">$\pi / 2$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$\pi / 4$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\pi / 2$</span> </div>

answer:
<div class="solution">In a $\triangle \mathrm{ABC}$, we have $\sin A-\cos B=\cos C \Rightarrow \sin A=\cos B+\cos C$<br/>$\Rightarrow 2 \sin \frac{A}{2} \cdot \cos \frac{A}{2}=2 \cos \left(\frac{B+C}{2}\right) \cdot \cos \left(\frac{B-C}{2}\right)$<br/>$[\because \sin 2 \mathrm{~A}=2 \sin \mathrm{A} \cdot \cos \mathrm{A}]$<br/>and $\cos B+\cos C=2 \cos \left(\frac{B+C}{2}\right) \cdot \cos \left(\frac{B-C}{2}\right)$<br/>$\Rightarrow 2 \sin \frac{\mathrm{A}}{2} \cdot \cos \frac{\mathrm{A}}{2}=2 \cos \left(90^{\circ}-\frac{\mathrm{A}}{2}\right) \cdot \cos \left(\frac{\mathrm{B}-\mathrm{C}}{2}\right)$<br/>$\left[\because \mathrm{A}+\mathrm{B}+\mathrm{C}=180^{\circ} \Rightarrow\left(\frac{\mathrm{B}+\mathrm{C}}{2}\right)=90^{\circ}-\frac{\mathrm{A}}{2}\right]$<br/>$\Rightarrow 2 \sin \frac{\mathrm{A}}{2} \cdot \cos \frac{\mathrm{A}}{2}=2 \sin \frac{\mathrm{A}}{2} \cdot \cos \left(\frac{\mathrm{B}-\mathrm{C}}{2}\right)$<br/>$\left[\because \cos \left(90^{\circ}-\theta\right)=\sin \theta\right]$<br/>$\Rightarrow \quad \cos \frac{\mathrm{A}}{2}=\cos \left(\frac{\mathrm{B}-\mathrm{C}}{2}\right)$<br/>$\Rightarrow \frac{A}{2}=\frac{B-C}{2}$<br/>$\Rightarrow \quad \mathrm{A}+\mathrm{C}=\mathrm{B}$ ....(i)<br/>Also, $A+C=180^{\circ}-B$ ....(ii)<br/>So, $180^{\circ}-\mathrm{B}=\mathrm{B}$<br/>$\Rightarrow \quad 2 \mathrm{~B}=180^{\circ}$<br/>$\therefore \quad \mathrm{B}=90^{\circ}$</div>


title: in-a-woody-dicotyledonous-tree-which-of-the-following-parts-will-mainly-consist-of-primary-tissues
tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET', 'NEET 2005']
source_db: MarksBatch2_P1.db
slug:
in-a-woody-dicotyledonous-tree-which-of-the-following-parts-will-mainly-consist-of-primary-tissues-91082

question:
<div class="question">In a woody dicotyledonous tree, which of the following parts will mainly consist of primary tissues?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">all parts</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">stem and root</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">flowers, fruits and leaves</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">shoot tips and root tips.</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">flowers, fruits and leaves</span> </div>

answer:
<div class="solution">The tissues which develop from apical meristem and procambium are known as primary tissues and these constitute the primary structures of the plant body. The development of the primary tissues causes the stem to grow in length and to some extent in thickness. Stem and root in dicotyledons show secondary growth as they have development of secondary vascular tissues (i.e., secondary xylem and secondary phloem) in them. Flowers, fruits and leaves are primary tissues.</div>


title: in-abc-if-a-b-c-1-2-3-then-what-is-bc-ca-ab
slug: in-abc-if-a-b-c-1-2-3-then-what-is-bc-ca-ab-44944
tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2006 (Phase 2)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In $\Delta \mathrm{ABC}$, if $\angle \mathrm{A}: \angle \mathrm{B}: \angle \mathrm{C}=1: 2: 3$, then what is $\mathrm{BC}: \mathrm{CA}$ :<br/>$\mathrm{AB}$ ?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$1: 2: 3$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$1: \sqrt{3}: 2$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$2: \sqrt{3}: 1$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$\sqrt{3}: 1: 2$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$1: \sqrt{3}: 2$</span> </div>

answer:
<div class="solution">Ratio of angles is given by $\angle \mathrm{A}: \angle \mathrm{B}: \angle \mathrm{C}=1: 2: 3$<br/>Let $\angle \mathrm{A}=\mathrm{x}, \angle \mathrm{B}=2 \mathrm{x}$ and $\angle \mathrm{C}=3 \mathrm{x}$<br/><img src="https://cdn-question-pool.getmarks.app/pyq/nda/Za7cnT6aL2vnPCgDdh0NTYTDX5RId-Ix9hh-2hD1Yg4.original.fullsize.png"/><br/><br/>We know that in a triangle $\angle \mathrm{A}+\angle \mathrm{B}+\angle \mathrm{C}=180^{\circ}$<br/>$\Rightarrow \mathrm{x}+2 \mathrm{x}+3 \mathrm{x}=180^{\circ}$<br/>$\Rightarrow \quad x=\frac{180^{\circ}}{6}=30^{\circ}$<br/>So, $\angle \mathrm{A}=30^{\circ}, \angle \mathrm{B}=60^{\circ}$ and $\angle \mathrm{C}=90^{\circ}$<br/>From sin law<br/>$\frac{\mathrm{BC}}{\sin \mathrm{A}}=\frac{\mathrm{CA}}{\sin \mathrm{B}}=\frac{\mathrm{AB}}{\sin \mathrm{C}}=\mathrm{K}$<br/>$\frac{\mathrm{BC}}{\sin 30^{\circ}}=\frac{\mathrm{CA}}{\sin 60^{\circ}}=\frac{\mathrm{AB}}{\sin 90^{\circ}}=\mathrm{K}$<br/>$\mathrm{BC}=\mathrm{K} \sin 30^{\circ}$<br/>$\mathrm{CA}=\mathrm{K} \sin 60^{\circ}$<br/>$\mathrm{AB}=\mathrm{K} \sin 90^{\circ}$<br/>$\mathrm{BC}: \mathrm{CA}: \mathrm{AB}$<br/>$=\sin 30^{\circ}: \sin 60^{\circ}: \sin 90^{\circ}=\frac{1}{2}: \frac{\sqrt{3}}{2}: 1=1: \sqrt{3}: 2$</div>


tags: ['Physics', 'Alternating Current', 'JEE Main']
source_db: MarksBatch2_P1.db
title:
in-an-ac-circuit-an-alternating-voltage-e200-sqrt2-sin-100-t-volts-is-connected-to-a-capacitor-of-capacity-1-mu-mathrmf-the-rms-value-of-the-current-i

slug:
in-an-ac-circuit-an-alternating-voltage-e200-sqrt2-sin-100-t-volts-is-connected-to-a-capacitor-of-capacity-1-mu-mathrmf-the-rms-value-of-the-current-i-64200

question:
<div class="question">In an ac circuit, an alternating voltage \( e=200 \sqrt{2} \sin 100 t \) volts is connected to a capacitor of capacity \( 1 \mu \mathrm{F} \). The rms value of the current in the circuit is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">\( 10 \mathrm{~mA} \)</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">\( 100 \mathrm{~mA} \)</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">\( 200 \mathrm{~mA} \)</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">\( 20 \mathrm{~mA} \)</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">\( 20 \mathrm{~mA} \)</span> </div>

answer:
<div class="solution"><blockquote><p>The given equation of alternating voltage is,<br/>       <math xmlns="http://www.w3.org/1998/Math/MathML"><mtext mathvariant="italic">e</mtext><mo>=</mo><mn>2</mn><mn>0</mn><mn>0</mn><msqrt><mn>2</mn></msqrt><mtext> sin </mtext><mn>1</mn><mn>0</mn><mn>0</mn><mi>t</mi><mo> </mo><mo> </mo><mo>.</mo><mo>.</mo><mo>.</mo><mo>(</mo><mi mathvariant="normal">i</mi><mo>)</mo></math><br/>The standard equation of alternating voltage is,<br/>      <math xmlns="http://www.w3.org/1998/Math/MathML"><mtext mathvariant="italic">e</mtext><mo>=</mo><msub><mtext mathvariant="italic">e</mtext><mn>0</mn></msub><mtext>sin</mtext><mi>ω</mi><mi>t</mi><mo> </mo><mo> </mo><mo>.</mo><mo>.</mo><mo>.</mo><mo>(</mo><mi>ii</mi><mo>)</mo></math><br/>Comparing equations <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>(</mo><mi mathvariant="normal">i</mi><mo>)</mo></math> and <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>(</mo><mi>ii</mi><mo>)</mo></math>, we get,<br/>    <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mtext mathvariant="italic">e</mtext><mn>0</mn></msub><mo>=</mo><mn>2</mn><mn>0</mn><mn>0</mn><msqrt><mn>2</mn></msqrt><mtext> V</mtext><mtext>, </mtext><mi>ω</mi><mo>=</mo><mn>1</mn><mn>0</mn><mn>0</mn><mtext> rad</mtext><msup><mtext> s</mtext><mrow><mo>-</mo><mn>1</mn></mrow></msup></math><br/>The capacitive reactance is,<br/>    <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mtext mathvariant="italic">X</mtext><mtext mathvariant="italic">C</mtext></msub><mo>=</mo><mfrac><mn>1</mn><mrow><mi>ω</mi><mtext mathvariant="italic">C</mtext></mrow></mfrac><mo>=</mo><mfrac><mn>1</mn><mrow><mn>1</mn><mn>0</mn><mn>0</mn><mo>×</mo><mn>1</mn><mo>×</mo><mn>1</mn><msup><mn>0</mn><mrow><mo>-</mo><mn>6</mn></mrow></msup></mrow></mfrac><mo> </mo><mi mathvariant="normal">Ω</mi></math><br/>The rms value of current in the circuit is,<br/>    <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>i</mi><mrow><mi>r</mi><mi>m</mi><mi>s</mi></mrow></msub><mo>=</mo><mfrac><msub><mi>v</mi><mtext>rms</mtext></msub><msub><mtext mathvariant="italic">X</mtext><mtext mathvariant="italic">C</mtext></msub></mfrac><mo>=</mo><mfrac><mrow><msub><mtext mathvariant="italic">e</mtext><mn>0</mn></msub><mo>/</mo><msqrt><mn>2</mn></msqrt></mrow><mrow><mn>1</mn><mo>/</mo><mi>ω</mi><mtext mathvariant="italic">C</mtext></mrow></mfrac><mo>=</mo><mfrac><mfenced><mrow><mn>2</mn><mn>0</mn><mn>0</mn><msqrt><mn>2</mn></msqrt><mo>/</mo><msqrt><mn>2</mn></msqrt></mrow></mfenced><mrow><mn>1</mn><mo>/</mo><mn>1</mn><mn>0</mn><mn>0</mn><mo>×</mo><mn>1</mn><msup><mn>0</mn><mrow><mo>-</mo><mn>6</mn></mrow></msup></mrow></mfrac></math><br/>             <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mn>2</mn><mn>0</mn><mn>0</mn><mo>×</mo><mn>1</mn><mn>0</mn><mn>0</mn><mo>×</mo><mn>1</mn><msup><mn>0</mn><mrow><mo>-</mo><mn>6</mn></mrow></msup><mo> </mo><mtext>A</mtext><mo>=</mo><mn>2</mn><mo>×</mo><mn>1</mn><msup><mn>0</mn><mrow><mo>-</mo><mn>2</mn></mrow></msup><mo> </mo><mtext>A</mtext><mo>=</mo><mn>2</mn><mn>0</mn><mtext> mA</mtext></math></p></blockquote></div>


tags: ['Physics', 'Alternating Current', 'JEE Main', 'JEE Main 2024 (29 Jan Shift 2)']
source_db: MarksBatch2_P1.db
title:
in-an-ac-circuit-voltage-and-current-are-given-by-v-100-sin-100-t-v-and-i-100-sin-100-t-3-ma-respectively-the-average-power-dissipated-in-one-cycle-is

slug:
in-an-ac-circuit-voltage-and-current-are-given-by-v-100-sin-100-t-v-and-i-100-sin-100-t-3-ma-respectively-the-average-power-dissipated-in-one-cycle-is-84420

question:
<div class="question">In an a.c. circuit, voltage and current are given by:Â <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>V</mi><mo>=</mo><mn>100</mn><mi>sin</mi><mo>(</mo><mn>100</mn><mi>t</mi><mo>)</mo><mo>Â </mo><mi mathvariant="normal">V</mi></math> and <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>I</mi><mo>=</mo><mn>100</mn><mi>sin</mi><mfenced><mrow><mn>100</mn><mi>t</mi><mo>+</mo><mfrac><mi>Ï</mi><mn>3</mn></mfrac></mrow></mfenced><mo>Â </mo><mi>mA</mi></math> respectively. The average power dissipated in one cycle is :</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>5</mn><mo>Â </mo><mi mathvariant="normal">W</mi></math></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>10</mn><mo>Â </mo><mi mathvariant="normal">W</mi></math></span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>2</mn><mo>.</mo><mn>5</mn><mo>Â </mo><mi mathvariant="normal">W</mi></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>25</mn><mo>Â </mo><mi mathvariant="normal">W</mi></math></span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>2</mn><mo>.</mo><mn>5</mn><mo>Â </mo><mi mathvariant="normal">W</mi></math></span> </div>

answer:
<div class="solution"><p>Standard expression of voltage is given by,Â <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>V</mi><mo>=</mo><msub><mi>V</mi><mn>0</mn></msub><mi>sin</mi><mfenced><mrow><mi>Ï</mi><mi>t</mi></mrow></mfenced></math>Â and for current is given by,Â <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>I</mi><mo>=</mo><msub><mi>I</mi><mn>0</mn></msub><mi>sin</mi><mfenced><mrow><mi>Ï</mi><mi>t</mi><mo>+</mo><mi>Ï</mi></mrow></mfenced></math>. Clearly,Â <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>Ï</mi></math>Â is the phase difference here. From the given expression,Â <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>Ï</mi><mo>=</mo><mfrac><mi>Ï</mi><mn>3</mn></mfrac></math>.</p><p>Average power dissipated in one cycle is given by,</p><p>Â <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>P</mi><mrow><mi>a</mi><mi>v</mi><mi>g</mi></mrow></msub><mo>=</mo><msub><mi>V</mi><mrow><mi>r</mi><mi>m</mi><mi>s</mi></mrow></msub><msub><mi>I</mi><mrow><mi>r</mi><mi>m</mi><mi>s</mi></mrow></msub><mi>cos</mi><mo>(</mo><mi>Ï</mi><mo>)</mo></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mfrac><mn>100</mn><msqrt><mn>2</mn></msqrt></mfrac><mo>Ã</mo><mfrac><mrow><mn>100</mn><mo>Ã</mo><msup><mn>10</mn><mrow><mo>-</mo><mn>3</mn></mrow></msup></mrow><msqrt><mn>2</mn></msqrt></mfrac><mo>Ã</mo><mi>cos</mi><mfenced><mfrac><mi>Ï</mi><mn>3</mn></mfrac></mfenced></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mfrac><msup><mn>10</mn><mn>4</mn></msup><mn>2</mn></mfrac><mo>Ã</mo><msup><mn>10</mn><mrow><mo>-</mo><mn>3</mn></mrow></msup><mo>Ã</mo><mfrac><mn>1</mn><mn>2</mn></mfrac></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mfrac><mn>10</mn><mn>4</mn></mfrac><mo>=</mo><mn>2</mn><mo>.</mo><mn>5</mn><mo>Â </mo><mi mathvariant="normal">W</mi></math></p></div>


title: in-an-annual-ring-the-light-coloured-part-is-known-as
slug: in-an-annual-ring-the-light-coloured-part-is-known-as-11486
question: <div class="question">In an annual ring, the light coloured part is known as:</div>
tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">Early wood</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Late wood</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Heartwood</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Sapwood</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Early wood</span> </div>

answer:
<div class="solution">Annual ring consists of two concentric light and dark colour ring, which are formed due unequal activity of cambium in different season. In spring season the cambium is more active producing more amount of secondary xylem with wider lumen which is light in colour, in autumn season cambium is less active and produces less amount of xylem with narrow lumen and which is dark in colour.</div>


title: in-an-ap-the-m-th-term-1-n-and-n-th-term-is-1-m-what-is-its-mn-th-term
slug: in-an-ap-the-m-th-term-1-n-and-n-th-term-is-1-m-what-is-its-mn-th-term-83421
tags: ['Mathematics', 'Sequences and Series', 'NDA', 'NDA 2009 (Phase 2)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">1</span> </div>
source_db: MarksBatch2_P1.db
question:
<div class="question">In an AP, the $m^{\text {th }}$ term $1 / n$ and $n^{\text {th }}$ term is $1 / m$. What is its $(m n)^{\text {th }}$ term?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$1 /(\mathrm{mn})$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\mathrm{m} / \mathrm{n}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$n / m$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">1</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

answer:
<div class="solution">Let 'a' be the first term and 'd' be the common difference of an A.P<br/>Now, Given $\mathrm{m}^{\text {th }}$ term $=\frac{1}{n}$<br/>and $\mathrm{n}^{\text {th }}$ term $=\frac{1}{m}$<br/>$\Rightarrow \mathrm{a}+(\mathrm{m}-1) \mathrm{d}=\frac{1}{n}$ and<br/>$a+(n-1) d=\frac{1}{m}$<br/>By subtracting the above two eqns, we get<br/>$(\mathrm{m}-1-\mathrm{n}+1) \mathrm{d}=\frac{1}{n}-\frac{1}{m}$<br/>$\Rightarrow(\mathrm{m}-\mathrm{n}) \mathrm{d}=\frac{m-n}{m n}$<br/>$\Rightarrow d=\frac{1}{m n}$<br/>Now, $(\mathrm{mn})^{\text {th }}$ term $=\mathrm{a}+(\mathrm{mn}-1) \mathrm{d}$<br/>$=a+(m n-1) \frac{1}{m n}=a+1-\frac{1}{m n}$<br/>Now, $a=\frac{1}{m}-(n-1) d$<br/>$=\frac{1}{m}-(n-1) \frac{1}{m n}=\frac{1}{m}-\frac{n}{m n}+\frac{1}{m n}=\frac{1}{m n}$<br/>$\therefore(\mathrm{mn})^{\text {th }}$ term $=\frac{1}{m n}+1-\frac{1}{m n}=1$</div>


title: in-an-ecosystem-the-rate-of-production-of-organic-matter-during-photosynthesis-is-termed-as-1
slug: in-an-ecosystem-the-rate-of-production-of-organic-matter-during-photosynthesis-is-termed-as-1-87566
tags: ['Biology', 'Ecosystem', 'NEET', 'NEET 2015 (Phase 1)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In an ecosystem the rate of production of organic matter during photosynthesis is termed as:</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Net primary productivity</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">Gross primary productivity</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Secondary productivity</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Net productivity</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Gross primary productivity</span> </div>

answer:
<div class="solution">Gross primary productivity is the amount of organic matter produced at given length of time during photosynthesis.</div>


tags: ['Chemistry', 'Electrochemistry', 'JEE Main', 'JEE Main 2023 (11 Apr Shift 1)']
options: None
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">2</span> </div>
source_db: MarksBatch2_P1.db
title:
in-an-electrochemical-reaction-of-lead-at-standard-temperature-if-e-pb-2-pb-o-m-volt-and-e-pb-4-pb-o-n-volt-then-the-value-of-e-pb-2-pb-4-is-given-by-

slug:
in-an-electrochemical-reaction-of-lead-at-standard-temperature-if-e-pb-2-pb-o-m-volt-and-e-pb-4-pb-o-n-volt-then-the-value-of-e-pb-2-pb-4-is-given-by-55483

question:
<div class="question"><p>In an electrochemical reaction of lead, at standard temperature, if  <math xmlns="http://www.w3.org/1998/Math/MathML"><msubsup><mi mathvariant="normal">E</mi><mfenced><mrow><msup><mi>Pb</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>/</mo><mi>Pb</mi></mrow></mfenced><mi mathvariant="normal">o</mi></msubsup><mo>=</mo><mi mathvariant="normal">m</mi><mtext> Volt  </mtext></math>and <math xmlns="http://www.w3.org/1998/Math/MathML"><mo> </mo><msubsup><mi mathvariant="normal">E</mi><mfenced><mrow><msup><mi>Pb</mi><mrow><mn>4</mn><mo>+</mo></mrow></msup><mo>/</mo><mi>Pb</mi></mrow></mfenced><mi mathvariant="normal">o</mi></msubsup><mo>=</mo><mi mathvariant="normal">n</mi><mo> </mo><mi>Volt</mi><mo>,</mo></math>then the value of  <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">E</mi><mo>°</mo><mfenced><mrow><msup><mi>Pb</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>/</mo><msup><mi>Pb</mi><mrow><mn>4</mn><mo>+</mo></mrow></msup></mrow></mfenced></math>  is given by <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">m</mi><mo> </mo><mo>–</mo><mo> </mo><mi>xn</mi></math>. The value of x is _______. (Nearest integer)</p><p> </p></div>

answer:
<div class="solution"><p>The relation between Gibbs Free energy and emf of the cell can be related as follows,</p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>∆</mo><mi mathvariant="normal">G</mi><mo>=</mo><mo>-</mo><msub><mi>nFE</mi><mi>cell</mi></msub></math></p><p>The electrode reactions can be written as follows,</p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mi>Pb</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>+</mo><mn>2</mn><msup><mi mathvariant="normal">e</mi><mo>-</mo></msup><mover><mo>→</mo><mrow></mrow></mover><mi>Pb</mi><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo>∆</mo><msub><mi mathvariant="normal">G</mi><mn>1</mn></msub><mo>=</mo><mo>-</mo><mn>2</mn><msubsup><mi>FE</mi><mrow><msup><mi>Pb</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>/</mo><mi>Pb</mi></mrow><mi mathvariant="normal">o</mi></msubsup></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mi>Pb</mi><mrow><mn>4</mn><mo>+</mo></mrow></msup><mo>+</mo><mn>4</mn><msup><mi mathvariant="normal">e</mi><mo>-</mo></msup><mover><mo>→</mo><mrow></mrow></mover><mi>Pb</mi><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo>∆</mo><msub><mi mathvariant="normal">G</mi><mn>2</mn></msub><mo>=</mo><mo>-</mo><mn>4</mn><msubsup><mi>FE</mi><mrow><msup><mi>Pb</mi><mrow><mn>4</mn><mo>+</mo></mrow></msup><mo>/</mo><mi>Pb</mi></mrow><mi mathvariant="normal">o</mi></msubsup></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mi>Pb</mi><mrow><mn>4</mn><mo>+</mo></mrow></msup><mo>+</mo><mn>2</mn><msup><mi mathvariant="normal">e</mi><mo>-</mo></msup><mover><mo>→</mo><mrow></mrow></mover><msup><mi>Pb</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo> </mo><mo>∆</mo><msub><mi mathvariant="normal">G</mi><mn>3</mn></msub><mo>=</mo><mo>-</mo><mn>2</mn><msubsup><mi>FE</mi><mrow><msup><mi>Pb</mi><mrow><mn>4</mn><mo>+</mo></mrow></msup><mo>/</mo><msup><mi>Pb</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup></mrow><mi mathvariant="normal">o</mi></msubsup></math></p><p>Now, <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>∆</mo><msub><mi mathvariant="normal">G</mi><mn>3</mn></msub><mo>=</mo><mo>∆</mo><msub><mi mathvariant="normal">G</mi><mn>2</mn></msub><mo>-</mo><mo>∆</mo><msub><mi mathvariant="normal">G</mi><mn>1</mn></msub></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>-</mo><mn>2</mn><msubsup><mi>FE</mi><mrow><msup><mi>Pb</mi><mrow><mn>4</mn><mo>+</mo></mrow></msup><mo>/</mo><msup><mi>Pb</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup></mrow><mi mathvariant="normal">o</mi></msubsup><mo>=</mo><mo>-</mo><mn>4</mn><msubsup><mi>FE</mi><mrow><msup><mi>Pb</mi><mrow><mn>4</mn><mo>+</mo></mrow></msup><mo>/</mo><mi>Pb</mi></mrow><mi mathvariant="normal">o</mi></msubsup><mo>+</mo><mn>2</mn><msubsup><mi>FE</mi><mrow><msup><mi>Pb</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>/</mo><mi>Pb</mi></mrow><mi mathvariant="normal">o</mi></msubsup></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>⇒</mo><mn>4</mn><msubsup><mi mathvariant="normal">E</mi><mrow><msup><mi>Pb</mi><mrow><mo>+</mo><mn>4</mn></mrow></msup><mo>/</mo><mi>Pb</mi></mrow><mi mathvariant="normal">o</mi></msubsup><mo>=</mo><mn>2</mn><msubsup><mi mathvariant="normal">E</mi><mrow><msup><mi>Pb</mi><mrow><mo>+</mo><mn>2</mn></mrow></msup><mo>/</mo><mi>Pb</mi></mrow><mi mathvariant="normal">o</mi></msubsup><mo>+</mo><mn>2</mn><msubsup><mi mathvariant="normal">E</mi><mrow><msup><mi>Pb</mi><mrow><mo>+</mo><mn>4</mn></mrow></msup><mo>/</mo><msup><mi>Pb</mi><mrow><mo>+</mo><mn>2</mn></mrow></msup></mrow><mi mathvariant="normal">o</mi></msubsup></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>⇒</mo><mn>4</mn><mi mathvariant="normal">n</mi><mo>=</mo><mn>2</mn><mi mathvariant="normal">m</mi><mo>+</mo><mn>2</mn><msubsup><mi mathvariant="normal">E</mi><mrow><msup><mi>Pb</mi><mrow><mo>+</mo><mn>4</mn></mrow></msup><mo>/</mo><msup><mi>Pb</mi><mrow><mo>+</mo><mn>2</mn></mrow></msup></mrow><mi mathvariant="normal">o</mi></msubsup><mspace linebreak="newline"></mspace><mo>⇒</mo><msubsup><mi mathvariant="normal">E</mi><mrow><msup><mi>Pb</mi><mrow><mo>+</mo><mn>4</mn></mrow></msup><mo>/</mo><msup><mi>Pb</mi><mrow><mo>+</mo><mn>2</mn></mrow></msup></mrow><mi mathvariant="normal">o</mi></msubsup><mo>=</mo><mn>2</mn><mi mathvariant="normal">n</mi><mo>-</mo><mi mathvariant="normal">m</mi><mspace linebreak="newline"></mspace><mo>⇒</mo><msubsup><mi mathvariant="normal">E</mi><mrow><msup><mi>Pb</mi><mrow><mo>+</mo><mn>2</mn></mrow></msup><mo>/</mo><msup><mi>Pb</mi><mrow><mo>+</mo><mn>4</mn></mrow></msup></mrow><mi mathvariant="normal">o</mi></msubsup><mo>=</mo><mi mathvariant="normal">m</mi><mo>-</mo><mn>2</mn><mi mathvariant="normal">n</mi></math></p><p>Hence, the value of <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">x</mi><mo>=</mo><mn>2</mn></math></p><p> </p></div>


title: in-an-ellipse-9-x-2-5-y-2-45-the-distance-between-the-foci-is
slug: in-an-ellipse-9-x-2-5-y-2-45-the-distance-between-the-foci-is-50785
question: <div class="question">In an ellipse $9 x^2+5 y^2=45$, the distance between the foci is</div>
tags: ['Mathematics', 'Ellipse', 'JEE Main']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">$4$</span> </div>
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$4 \sqrt{5}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$3 \sqrt{5}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$3$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$4$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

answer:
<div class="solution">Given equation may be written as $\frac{x^2}{5}+\frac{y^2}{9}=1$. Comparing the given equation with standard equation, we get $a^2=5$ and $b^2=9$. We also know that in an ellipse (where $\left.b^2 \gt a^2\right) a^2=b^2\left(1-e^2\right) \lambda$<br/>or $e^2=\frac{b^2-a^2}{b^2}=\frac{9-5}{9}=\frac{4}{9}$ or $e=\frac{2}{3}$.<br/>Therefore distance between foci $=2 b e=2 \times 3 \times \frac{2}{3}=4$.</div>


tags: ['Mathematics', 'Ellipse', 'AP EAMCET', 'AP EAMCET 2021 (19 Aug Shift 2)']
source_db: MarksBatch2_P1.db
title:
in-an-ellipse-if-the-distance-between-the-foci-is-6-units-and-the-length-of-its-minor-axis-is-8-units-then-its-eccentricity-is

slug:
in-an-ellipse-if-the-distance-between-the-foci-is-6-units-and-the-length-of-its-minor-axis-is-8-units-then-its-eccentricity-is-67097

question:
<div class="question">In an ellipse, if the distance between the foci is <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>6</mn></math> units and the length of its minor axis is <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>8</mn></math> units, then its eccentricity is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mn>2</mn></mfrac></math></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>7</mn><mn>5</mn></mfrac></math></span> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><msqrt><mn>5</mn></msqrt></mfrac></math></span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>3</mn><mn>5</mn></mfrac></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>3</mn><mn>5</mn></mfrac></math></span> </div>

answer:
<div class="solution"><p>Consider the standard equation of the ellipse </p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><msup><mi>x</mi><mn>2</mn></msup><msup><mi>a</mi><mn>2</mn></msup></mfrac><mo>+</mo><mfrac><msup><mi>y</mi><mn>2</mn></msup><msup><mi>b</mi><mn>2</mn></msup></mfrac><mo>=</mo><mn>1</mn></math>,</p><p>The distance between it's foci is <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>6</mn><mo> </mo></math>, so, <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>2</mn><mi>c</mi><mo>=</mo><mn>6</mn><mo> </mo><mo>⇒</mo><mi>c</mi><mo>=</mo><mn>3</mn></math></p><p>and given length of minor axis is <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>8</mn></math> units,</p><p>hence, <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>2</mn><mi>b</mi><mo>=</mo><mn>8</mn><mo> </mo><mo>⇒</mo><mo> </mo><mi>b</mi><mo>=</mo><mn>4</mn></math></p><p>So, the value of <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>a</mi><mo>=</mo><msqrt><msup><mi>b</mi><mn>2</mn></msup><mo>+</mo><msup><mi>c</mi><mn>2</mn></msup></msqrt><mo>=</mo><msqrt><msup><mn>4</mn><mn>2</mn></msup><mo>+</mo><msup><mn>3</mn><mn>2</mn></msup></msqrt><mo>=</mo><mn>5</mn></math></p><p>Hence, <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>e</mi><mo>=</mo><mfrac><mi>c</mi><mi>a</mi></mfrac><mo>=</mo><mfrac><mn>3</mn><mn>5</mn></mfrac></math></p></div>


tags: ['Mathematics', 'Statistics', 'NDA', 'NDA 2017 (Phase 1)']
source_db: MarksBatch2_P1.db
title:
in-an-examination-40-of-candidates-got-second-class-when-the-data-are-represented-by-a-pie-chart-what-is-the-angle-corresponding-to-second-class

slug:
in-an-examination-40-of-candidates-got-second-class-when-the-data-are-represented-by-a-pie-chart-what-is-the-angle-corresponding-to-second-class-11902

question:
<div class="question">In an examination, $40 \%$ of candidates got second class When the data are represented by a pie chart, what is the angle corresponding to second class'</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">4</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">90</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">$144^{5}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$320^{\circ}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$144^{5}$</span> </div>

answer:
<div class="solution">First, convert $40 \%$ into fraction<br/>$40 \%=\frac{40}{100}=\frac{2}{5}$<br/>Angle $=\frac{2}{5} \times 360=144^{\circ}$</div>


tags: ['Mathematics', 'Sets and Relations', 'NDA', 'NDA 2016 (Phase 2)']
source_db: MarksBatch2_P1.db
title:
in-an-examination-70-students-passed-in-physics-80-students-passed-in-chemistry-75-students-passed-in-mathematics-and-85-students-passed-in-biology-an

slug:
in-an-examination-70-students-passed-in-physics-80-students-passed-in-chemistry-75-students-passed-in-mathematics-and-85-students-passed-in-biology-an-18615

question:
<div class="question">In an examination, $70 \%$ students passed in Physics, $80 \%$ students passed in Chemistry, $75 \%$ students passed in Mathematics and $85 \%$ students passed in Biology, and $x \%$ students failed in all the four subjects. What is the minimum value of $\mathrm{x}$ ?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">10</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">12</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">15</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">None of the above</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

answer:
<div class="solution">Here, maximum number of students failed in all the four subjects $=15 \%$ But, minimum number of students failed in all the four subjects varies from 0 to $15 \%$. So, correctoption is (d).</div>


tags: ['Mathematics', 'Sets and Relations', 'NDA', 'NDA 2009 (Phase 1)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">45</span> </div>
source_db: MarksBatch2_P1.db
title:
in-an-examination-out-of-100-students-75-passed-in-english-60-passed-in-mathematics-and-45-passed-in-both-english-and-mathematics-what-is-the-number-o

slug:
in-an-examination-out-of-100-students-75-passed-in-english-60-passed-in-mathematics-and-45-passed-in-both-english-and-mathematics-what-is-the-number-o-79037

question:
<div class="question">In an examination out of 100 students, 75 passed in English<br/>60 passed in Mathematics and 45 passed in both English and Mathematics. What is the number of students passed in exactly one of the two subjects?</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">45</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">60</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">75</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">90</span> </li> </ul>

answer:
<div class="solution">Total no. of students $=100$ Let $E$ denote the students who have passed in English Let $M$ denote the students who have passed in Maths $n(E)=75, n(M)=60$ and $n(E \cap M)=45$<br/>we know $n(E \cup M)=n(E)+n(M)-n(E \cap M)$<br/>$=75+60-45=90$<br/>Required number of students $=90-45=4^{5}$</div>


tags: ['Mathematics', 'Probability', 'NDA', 'NDA 2015 (Phase 1)']
source_db: MarksBatch2_P1.db
title:
in-an-examination-the-probability-of-a-candidate-solving-a-question-is-2-1-out-of-given-5-questions-in-the-examination-what-is-the-probability-that-th

slug:
in-an-examination-the-probability-of-a-candidate-solving-a-question-is-2-1-out-of-given-5-questions-in-the-examination-what-is-the-probability-that-th-11099

question:
<div class="question">In an examination, the probability of a candidate solving a question is $\frac{1}{2}$. Out of given 5 questions in the examination, what is the probability that the candidate was able to solve at least 2 questions?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{1}{64}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\frac{3}{16}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\frac{1}{2}$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$\frac{13}{16}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\frac{13}{16}$</span> </div>

answer:
<div class="solution">$\begin{aligned} &amp; P={ }^{5} C_{2}\left(\frac{1}{2}\right)^{2}\left(\frac{1}{2}\right)^{3}+{ }^{5} C_{3}\left(\frac{1}{2}\right)^{3}\left(\frac{1}{2}\right)^{2} \\ &amp;+{ }^{5} C_{4}\left(\frac{1}{2}\right)^{4}\left(\frac{1}{2}\right)^{1}+{ }^{5} C_{5}\left(\frac{1}{2}\right)^{5}\left(\frac{1}{2}\right)^{0} \\ &amp;=\left(\frac{1}{2}\right)^{5}\left[{ }^{5} C_{2}+{ }^{5} C_{3}+{ }^{5} C_{4}+{ }^{5} C_{5}\right] \\ &amp;=\frac{1}{3^{2}}[10+10+5+1] \\ &amp;=\frac{1}{3^{2}} \times 26=\frac{13}{16} \end{aligned}$</div>


tags: ['Mathematics', 'Probability', 'NDA', 'NDA 2011 (Phase 1)']
source_db: MarksBatch2_P1.db
title:
in-an-examination-there-are-3-multiple-choice-questions-and-each-question-has-4-choices-if-a-student-randomly-selects-answer-for-all-the-3-questions-w

slug:
in-an-examination-there-are-3-multiple-choice-questions-and-each-question-has-4-choices-if-a-student-randomly-selects-answer-for-all-the-3-questions-w-22008

question:
<div class="question">In an examination, there are 3 multiple choice questions and each question has 4 choices. If a student randomly selects answer for all the 3 questions, what is the probability that the student will not answer all the 3 questions correctly?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$1 / 64$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$63 / 64$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$1 / 12$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$11 / 12$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$63 / 64$</span> </div>

answer:
<div class="solution">Since, probability of answering all the three questions correctly $=\frac{1}{4} \times \frac{1}{4} \times \frac{1}{4}=\frac{1}{64}$<br/>$\therefore$ Probability of not answering all the three questions correctly $=1-\frac{1}{64}=\frac{63}{64}$</div>


tags: ['Physics', 'Experimental Physics', 'JEE Main']
source_db: MarksBatch2_P1.db
title:
in-an-experiment-for-the-determination-of-the-speed-of-sound-in-air-using-the-resonance-method-the-length-of-the-air-column-that-resonates-in-the-fund

slug:
in-an-experiment-for-the-determination-of-the-speed-of-sound-in-air-using-the-resonance-method-the-length-of-the-air-column-that-resonates-in-the-fund-70304

question:
<div class="question">In an experiment for the determination of the speed of sound in air using the resonance method, the length of the air column that resonates in the fundamental mode with a tuning fork is <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.</mo><mn>1</mn><mo> </mo><mi mathvariant="normal">m</mi></math>. When this length is changed to <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.</mo><mn>35</mn><mo> </mo><mi mathvariant="normal">m</mi></math>, the same tuning fork resonates with the first overtone. The end correction is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.</mo><mn>012</mn><mo> </mo><mi mathvariant="normal">m</mi></math></span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.</mo><mn>025</mn><mo> </mo><mi mathvariant="normal">m</mi></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.</mo><mn>05</mn><mo> </mo><mi mathvariant="normal">m</mi></math></span> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.</mo><mn>024</mn><mo> </mo><mi mathvariant="normal">m</mi></math></span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.</mo><mn>025</mn><mo> </mo><mi mathvariant="normal">m</mi></math></span> </div>

answer:
<div class="solution"><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mi>Î»</mi><mn>4</mn></mfrac><mo>=</mo><mi>e</mi><mo>+</mo><msub><mi>l</mi><mn>1</mn></msub></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>3</mn><mi>Î»</mi></mrow><mn>4</mn></mfrac><mo>=</mo><mi>e</mi><mo>+</mo><msub><mi>l</mi><mn>2</mn></msub></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>e</mi><mo>+</mo><msub><mi>l</mi><mn>2</mn></msub><mo>=</mo><mn>3</mn><mi>e</mi><mo>+</mo><mn>3</mn><msub><mi>l</mi><mn>1</mn></msub></math></p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>e</mi><mo>â¡</mo><mo>=</mo><mfrac><mrow><mi>l</mi><msub><mo>â¡</mo><mn>2</mn></msub><mo>-</mo><mn>3</mn><mi>l</mi><msub><mo>â¡</mo><mn>1</mn></msub></mrow><mn>2</mn></mfrac><mo>=</mo><mfrac><mrow><mtext>0.35</mtext><mo>-</mo><mtext>0.3</mtext></mrow><mn>2</mn></mfrac><mo>=</mo><mfrac><mtext>0.05</mtext><mn>2</mn></mfrac><mo>=</mo><mtext>0.025 m</mtext></math></p></div>


tags: ['Physics', 'Alternating Current', 'TS EAMCET', 'TS EAMCET 2023 (12 May Shift 2)']
source_db: MarksBatch2_P1.db
title:
in-an-ideal-step-up-transformer-if-the-input-voltage-and-input-power-are-v-1-and-p-1-respectively-and-the-output-voltage-and-output-power-are-v-2-and-

slug:
in-an-ideal-step-up-transformer-if-the-input-voltage-and-input-power-are-v-1-and-p-1-respectively-and-the-output-voltage-and-output-power-are-v-2-and-64344

question:
<div class="question">In an ideal step up transformer, if the input voltage and input power are $\mathrm{V}_1$ and $\mathrm{P}_1$ respectively and the output voltage and output power are $\mathrm{V}_2$ and $\mathrm{P}_2$ respectively, then</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\mathrm{V}_1=\mathrm{V}_2 ; \mathrm{P}_1=\mathrm{P}_2$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\mathrm{V}_1&gt;\mathrm{V}_2 ; \mathrm{P}_1&gt;\mathrm{P}_2$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\mathrm{V}_1 &lt; \mathrm{V}_2 ; \mathrm{P}_1 &lt; \mathrm{P}_2$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$\mathrm{V}_1 &lt; \mathrm{V}_2 ; \mathrm{P}_1=\mathrm{P}_2$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\mathrm{V}_1 &lt; \mathrm{V}_2 ; \mathrm{P}_1=\mathrm{P}_2$</span> </div>

answer:
<div class="solution">In step up transformer the output voltage is greater than input voltage because the number of turns on the secondary is more than the number of turns in the primary. Therefore $\mathrm{V}_2&gt;\mathrm{V}_1$<br/><br/>Input power is equal to output power.<br/>$$<br/>\therefore \mathrm{P}_1=\mathrm{P}_2<br/>$$<br/><br/>Hence (4) is correct.</div>


tags: ['Physics', 'Alternating Current', 'MHT CET', 'MHT CET 2021 (20 Sep Shift 1)']
source_db: MarksBatch2_P1.db
title:
in-an-ideal-stepdown-transformer-out-of-the-following-quantities-which-quantity-increases-in-the-secondary-coil

slug:
in-an-ideal-stepdown-transformer-out-of-the-following-quantities-which-quantity-increases-in-the-secondary-coil-86614

question:
<div class="question">In an ideal step-down transformer, out of the following quantities, which quantity increases in the secondary coil?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Power</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Voltage</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">Current</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Frequency</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Current</span> </div>

answer:
<div class="solution">For an ideal transformer,<br/>$$<br/>\frac{\mathrm{V}_{\mathrm{s}}}{\mathrm{V}_{\mathrm{p}}}=\frac{\mathrm{I}_{\mathrm{p}}}{\mathrm{I}_{\mathrm{s}}}<br/>$$<br/>Hence, if $\mathrm{V}_{\mathrm{s}} &lt; \mathrm{V}_{\mathrm{p}}$ then $\mathrm{I}_{\mathrm{p}} &lt; \mathrm{I}_{\mathrm{s}}$</div>


title: in-an-old-tree-trunk-of-mango-which-tissue-will-be-present-in-the-maximum-amount
slug: in-an-old-tree-trunk-of-mango-which-tissue-will-be-present-in-the-maximum-amount-56101
tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
question:
<div class="question">In an old tree trunk of mango, which tissue will be present in the maximum amount?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Primary xylem</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Primary phloem</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">Secondary xylem</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Secondary cortex</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Secondary xylem</span> </div>

answer:
<div class="solution">In an old trunk, increase in thickness occurs due to secondary growth. The secondary growth in the stellar region occurs due to activity of vascular cambium, which forms more amount of secondary xylem and this forms the heart of the trunk.</div>


title: in-an-open-beaker-containing-reactants-what-is-considered-the-boundary-of-the-system
slug: in-an-open-beaker-containing-reactants-what-is-considered-the-boundary-of-the-system-28355
tags: ['Chemistry', 'Thermodynamics (C)', 'NEET']
source_db: MarksBatch2_P1.db
question:
<div class="question">In an open beaker containing reactants, what is considered the boundary of the system?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">The walls of the beaker</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">The reactants inside the beaker</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">An imaginary surface enclosing the beaker and reactants</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">The air surrounding the beaker</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">An imaginary surface enclosing the beaker and reactants</span> </div>

answer:
<div class="solution">In this context, the boundary is defined as an imaginary surface that encloses both the beaker and the reactants inside it.</div>


title: in-andalusian-fowls-the-mating-of-black-and-white-fowls-will-produce
slug: in-andalusian-fowls-the-mating-of-black-and-white-fowls-will-produce-90140
question: <div class="question">In Andalusian fowls, the mating of black and white fowls will produce</div>
tags: ['Biology', 'Principles of Inheritance and Variation', 'NEET']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Black fowls</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">White fowls</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">Blue fowls</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Grey fowls</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Blue fowls</span> </div>

answer:
<div class="solution">The colour of Andalusian fowl exhibits incomplete dominance. Black fowls are homozygous dominant with the genotype BB. White fowls are homozygous recessive with the genotype bb. When they mate, all fowls are heterozygous having the genotype Bb which is expressed as blue.</div>


title: in-angiosperms-microsporogenesis-and-megasporogenesis
slug: in-angiosperms-microsporogenesis-and-megasporogenesis-70082
question: <div class="question">In Angiosperms, microsporogenesis and megasporogenesis:</div>
tags: ['Biology', 'Sexual Reproduction in Flowering Plants', 'NEET', 'NEET 2015 (Phase 2)']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Form gametes without further divisions</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">Involve meiosis</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Occur in ovule</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Occur in anther</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Involve meiosis</span> </div>

answer:
<div class="solution"><p>The Angiosperms are heterosporous. The stamens of the flower are the male sexual parts and they are highly modified leaves called microsporophylls. The microsporophylls produce anthers or microsporangia.  Within the anther, there are special diploid cells called pollen mother cell or microspore mother cells. The microspore mother cells undergo meiosis to produce haploid microspores or pollen grains. The microspore produces a few celled male gametophytes, each male gametophyte has two cells tube cell and a generative cell. This process is called microsporogenesis.</p><p>Gynoecium or pistil is the female sexual parts. The gynoecium is made up of highly modified leaves called megasporophylls or carpels. The megasporophylls fused to form ovaries. The function of carpels is to produce ovules or megasporangia by a process called megasporogenesis. Within the ovules, there are specialized cells called the megaspore mother cells (2n). The megaspores mother cells are diploid (2n) which undergo meiosis or reduction division to form haploid megaspores (n). The megaspores produce a multicellular female gametophyte or embryo sac. The mature embryo sac has a group of three antipodal cells, two synergid cells, one female gamete or egg cell. There are two haploid polar nuclei which fuse together to produce a diploid secondary nucleus.</p></div>


tags: ['Mathematics', 'Statistics', 'NDA', 'NDA 2018 (Phase 2)']
source_db: MarksBatch2_P1.db
title:
in-any-discrete-series-when-all-values-are-not-same-if-x-represents-mean-deviation-about-mean-and-y-represents-standard-deviation-then-which-one-of-th

slug:
in-any-discrete-series-when-all-values-are-not-same-if-x-represents-mean-deviation-about-mean-and-y-represents-standard-deviation-then-which-one-of-th-97410

question:
<div class="question">In any discrete series (when all values are not same) if $x$ represents mean deviation about mean and $y$ represents standard deviation, then which one of the following is correct?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$y \geq x$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$y \leq x$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$x=y$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$x   &lt; y$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$x   &lt; y$</span> </div>

answer:
<div class="solution">$x=\mathrm{M}, \mathrm{D}_{-,}, y=\mathrm{S} . \mathrm{D}$.<br/>$$<br/>\mathrm{M}, \mathrm{D},=\frac{4}{5} \mathrm{S.D.} \Rightarrow x   &lt; y<br/>$$</div>


tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2011 (Phase 2)']
source_db: MarksBatch2_P1.db
title:
in-any-triangle-a-bc-the-sides-are-6-cm-10-cm-and-14-cm-then-the-triangle-is-obtuse-angled-with-the-obtuse-angle-equal-to

slug:
in-any-triangle-a-bc-the-sides-are-6-cm-10-cm-and-14-cm-then-the-triangle-is-obtuse-angled-with-the-obtuse-angle-equal-to-90042

question:
<div class="question">In any triangle $A B C$, the sides are $6 \mathrm{~cm}, 10 \mathrm{~cm}$ and $14 \mathrm{~cm}$. Then the triangle is obtuse angled with the obtuse angle equal to</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$150^{\circ}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$135^{\circ}$</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">$120^{\circ}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$105^{\circ}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$120^{\circ}$</span> </div>

answer:
<div class="solution"><img src="https://cdn-question-pool.getmarks.app/pyq/nda/7bQmOFkof7MQo1sf2Kp_Vt3SRytcT1dLqRh5hsD4IS0.original.fullsize.png"/><br/><br/>Since, $\mathrm{c}=14$ is the largest side $\therefore$ Angle $\mathrm{C}$ will be obtuse<br/>$\cos C=\frac{a^{2}+b^{2}-c^{2}}{2 a b}=\frac{(6)^{2}+(10)^{2}-(14)^{2}}{2(6)(10)}$<br/>$=\frac{36+100-196}{2 \times 6 \times 10}=\frac{-1}{2}$<br/>$\Rightarrow C=\cos ^{-1}\left(\frac{-1}{2}\right)=\pi-\frac{\pi}{3}=\frac{2 \pi}{3}=\frac{2 \times 180}{3}=120$</div>


title: in-any-triangle-abc-a-18-b-24-and-c-30-then-what-is-sin-c-equal-to
slug: in-any-triangle-abc-a-18-b-24-and-c-30-then-what-is-sin-c-equal-to-59230
tags: ['Mathematics', 'Properties of Triangles', 'NDA', 'NDA 2013 (Phase 1)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">1</span> </div>
source_db: MarksBatch2_P1.db
question:
<div class="question">In any triangle $\mathrm{ABC}, \mathrm{a}=18, \mathrm{~b}=24$ and $\mathrm{c}=30$. Then what is $\begin{array}{ll}\text { sin C equal to : } &amp; {}\end{array}$</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{1}{4}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\frac{1}{3}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\frac{1}{2}$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">1</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

answer:
<div class="solution">$\cos C=\frac{a^{2}+b^{2}-c^{2}}{2 a b}$<br/>$\Rightarrow \cos C=\frac{(18)^{2}+(24)^{2}-(30)^{2}}{2 \times 18 \times 24}=\frac{9+16-5^{2}}{2 \times 3 \times 4}=0$<br/>Now, $\sin C=\sqrt{1-\cos ^{2} C}=\sqrt{1-0}=1$<br/>Hence $\sin C=1$</div>


title: in-bacteria-plasmid-is
slug: in-bacteria-plasmid-is-42835
question: <div class="question">In bacteria, plasmid is:</div>
tags: ['Biology', 'Biological Classification', 'NEET', 'NEET 2002']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">extra chromosomal material</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">main DNA</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">non-functional DNA</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">repetitive gene</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">extra chromosomal material</span> </div>

answer:
<div class="solution">A plasmid is a small, often circular DNA molecule found in bacteria and other cells. Plasmids are separate from the bacterial chromosome and replicate independently of it.<br/>Related Theory<br/>Each bacterial cell typically produces many copies of a plasmid, in contrast to making only one copy of its own chromosome. The fact that plasmids are smaller and in greater number than the host chromosome make plasmids easier to isolate in pure form, which is why researchers commonly use them for studying DNA in the laboratory. Plasmids are thus a fundamental tool of recombinant DNA technology.</div>


title: in-basidiomycetes-meiosis-will-take-place-in
slug: in-basidiomycetes-meiosis-will-take-place-in-55613
question: <div class="question">In Basidiomycetes, meiosis will take place in</div>
tags: ['Biology', 'Biological Classification', 'NEET']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Primary mycelium</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Secondary mycelium</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Basidiocarp</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">Basidium</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Basidium</span> </div>

answer:
<div class="solution">Basidium is a club-shaped structure. Karyogamy and meiosis both will occur in basidium, and four basidiospores will form.</div>


title: in-binary-system-the-decimal-number-03-can-be-expressed-as
slug: in-binary-system-the-decimal-number-03-can-be-expressed-as-48219
question: <div class="question">In binary system the decimal number $0.3$ can be expressed as</div>
tags: ['Mathematics', 'Sets and Relations', 'NDA', 'NDA 2011 (Phase 2)']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">$(0.01001 \ldots \ldots)_{2}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$(0.10110 \ldots \ldots)_{2}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$(0.11001 \ldots \ldots)_{2}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$(0.10101 \ldots \ldots)$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$(0.01001 \ldots \ldots)_{2}$</span> </div>

answer:
<div class="solution">Consider $0.3 \times 2=0.6 \times 2=1.2 \times 2$<br/>Now, treated 1 as 0<br/>So, $0.2 \times 2=0.4 \times 2=0.8 \times 2=1.6 \times 2$<br/>Again, $1.6 \times 2=0.6 \times 2=1.2$<br/>Thus,<br/>$0.3 \times 2=0.6 \times 2=1.2 \times 2=0.4 \times 2$<br/>Hence, $0.3=(0.01001 \ldots-)_{2}$</div>


title: in-calotropis-the-leaves-show-x-phyllotaxy-while-the-petals-show-y-aestivation
slug: in-calotropis-the-leaves-show-x-phyllotaxy-while-the-petals-show-y-aestivation-56109
tags: ['Biology', 'Morphology of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
question:
<div class="question">In Calotropis, the leaves show (X) phyllotaxy while the petals show (Y) aestivation.</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><math><mo>(</mo><mi mathvariant="normal">X</mi><mo>)</mo><mo>:</mo></math>  opposite and  <math><mo>(</mo><mi mathvariant="normal">Y</mi><mo>)</mo><mo>:</mo></math>  valvate</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><math><mo>(</mo><mi mathvariant="normal">X</mi><mo>)</mo><mo>:</mo></math>  alternate and  <math><mo>(</mo><mi mathvariant="normal">Y</mi><mo>)</mo><mo>:</mo></math>  valvate</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><math><mo>(</mo><mi mathvariant="normal">X</mi><mo>)</mo><mo>:</mo></math>  opposite and  <math><mo>(</mo><mi mathvariant="normal">Y</mi><mo>)</mo><mo>:</mo></math>  twisted.</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><math><mo>(</mo><mi mathvariant="normal">X</mi><mo>)</mo><mo>:</mo></math>  alternate and  <math><mo>(</mo><mi mathvariant="normal">Y</mi><mo>)</mo><mo>:</mo></math>  twisted</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math><mo>(</mo><mi mathvariant="normal">X</mi><mo>)</mo><mo>:</mo></math>  opposite and  <math><mo>(</mo><mi mathvariant="normal">Y</mi><mo>)</mo><mo>:</mo></math>  valvate</span> </div>

answer:
<div class="solution">When sepals or petals in a whorl just touch one another at the margin, without overlapping, it is said to be valvate.<br/><br/>If one margin of the appendage overlaps that of the next one and so on, it is called twisted. Calotropis has valvate aestivation. In alternate type of phyllotaxy, a single leaf arises at each node in alternate manner. In opposite type, a pair of leaves arise at each node and lie opposite to each other as in Calotropis.</div>


tags: ['Physics', 'Motion In Two Dimensions', 'WBJEE', 'WBJEE 2021']
answer: <div class="solution">Horizontal component of velocity remains constant.</div>
source_db: MarksBatch2_P1.db
title:
in-case-of-projectile-motion-which-one-of-the-following-figures-represent-variation-of-horizontal-component-of-velocity-u-x-with-time-t-assume-that-ai

slug:
in-case-of-projectile-motion-which-one-of-the-following-figures-represent-variation-of-horizontal-component-of-velocity-u-x-with-time-t-assume-that-ai-25839

question:
<div class="question">In case of projectile motion, which one of the following figures represent variation of horizontal component of velocity $\left(\mathrm{u}_{\mathrm{x}}\right)$ with time $\mathrm{t} ?$ (assume that air resistance is negligible)</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><img src="https://cdn-question-pool.getmarks.app/pyq/wbjee/BLt8n-_o-x6HQjRUQ242japxyVX5KPjw_7rndaObE3Y.original.fullsize.png"/></span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data"><img src="https://cdn-question-pool.getmarks.app/pyq/wbjee/nVFSHZFHSuimxd_9QH8l9bACoXvJDwhC640QLuBJN3M.original.fullsize.png"/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><img src="https://cdn-question-pool.getmarks.app/pyq/wbjee/uRQt51lbc3qKtQ5wxEOIcRT8rwJ9vKwhgU_R2Hzb0ZM.original.fullsize.png"/></span> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><img src="https://cdn-question-pool.getmarks.app/pyq/wbjee/SxTnpvv0fWN-QluAWMaxWmq0MvOc2TxwL5XC3zeziMY.original.fullsize.png"/></span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><img src="https://cdn-question-pool.getmarks.app/pyq/wbjee/nVFSHZFHSuimxd_9QH8l9bACoXvJDwhC640QLuBJN3M.original.fullsize.png"/></span> </div>


tags: ['Physics', 'Units and Dimensions', 'AP EAMCET', 'AP EAMCET 2001']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">$3.6$</span> </div>
source_db: MarksBatch2_P1.db
title:
in-cgs-system-the-magnitude-of-the-force-is-100-dynes-in-another-system-where-the-fundamental-physical-quantities-are-kilogram-meter-and-minute-the-ma-1

slug:
in-cgs-system-the-magnitude-of-the-force-is-100-dynes-in-another-system-where-the-fundamental-physical-quantities-are-kilogram-meter-and-minute-the-ma-1-93694

question:
<div class="question">In CGS system the magnitude of the force is 100 dynes. In another system where the fundamental physical. quantities are kilogram, meter and minute, the magnitude of the force is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$0.036$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$0.36$</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">$3.6$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$36$</span> </li> </ul>

answer:
<div class="solution">$n_2=n_1\left[\left(\frac{m_1}{m_2}\right)^a\left(\frac{L_1}{L_2}\right)^b\left(\frac{T_1}{T_2}\right)^c\right]$<br/>Dimensions of force is [ $\mathrm{M} \mathrm{L} \mathrm{T}^{-2}$ ]<br/>$a=1, b=1, c=-2$<br/>$\begin{aligned} n_2 &amp; =100\left[\left(\frac{\mathrm{g}}{\mathrm{kg}}\right)^1\left(\frac{\mathrm{cm}}{\text { metre }}\right)^1\left(\frac{\mathrm{sec}}{\mathrm{min}}\right)^{-3}\right] \\ &amp; =100\left[\frac{\mathrm{g}}{100 \mathrm{~g}} \times \frac{\mathrm{cm}}{100 \mathrm{~cm}} \times\left(\frac{\mathrm{sec}}{60 \mathrm{sec}}\right)^{-2}\right] \\ &amp; =100\left[\frac{1}{1000} \times \frac{1}{100} \times(60)^2\right] \\ &amp; =100 \times \frac{1}{1000} \times \frac{1}{100} \times 3600=3.6\end{aligned}$</div>


tags: ['Physics', 'Units and Dimensions', 'JEE Main']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">$3.6$</span> </div>
source_db: MarksBatch2_P1.db
title:
in-cgs-system-the-magnitude-of-the-force-is-100-dynes-in-another-system-where-the-fundamental-physical-quantities-are-kilogram-meter-and-minute-the-ma-2

slug:
in-cgs-system-the-magnitude-of-the-force-is-100-dynes-in-another-system-where-the-fundamental-physical-quantities-are-kilogram-meter-and-minute-the-ma-2-60984

question:
<div class="question">In CGS system the magnitude of the force is 100 dynes. In another system where the fundamental physical. quantities are kilogram, meter and minute, the magnitude of the force is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$0.036$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$0.36$</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">$3.6$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$36$</span> </li> </ul>

answer:
<div class="solution">$n_2=n_1\left[\left(\frac{m_1}{m_2}\right)^a\left(\frac{L_1}{L_2}\right)^b\left(\frac{T_1}{T_2}\right)^c\right]$<br/>Dimensions of force is [ $\mathrm{M} \mathrm{L} \mathrm{T}^{-2}$ ]<br/>$a=1, b=1, c=-2$<br/>$\begin{aligned} n_2 &amp; =100\left[\left(\frac{\mathrm{g}}{\mathrm{kg}}\right)^1\left(\frac{\mathrm{cm}}{\text { metre }}\right)^1\left(\frac{\mathrm{sec}}{\mathrm{min}}\right)^{-3}\right] \\ &amp; =100\left[\frac{\mathrm{g}}{100 \mathrm{~g}} \times \frac{\mathrm{cm}}{100 \mathrm{~cm}} \times\left(\frac{\mathrm{sec}}{60 \mathrm{sec}}\right)^{-2}\right] \\ &amp; =100\left[\frac{1}{1000} \times \frac{1}{100} \times(60)^2\right] \\ &amp; =100 \times \frac{1}{1000} \times \frac{1}{100} \times 3600=3.6\end{aligned}$</div>


tags: ['Physics', 'Units and Dimensions', 'TS EAMCET', 'TS EAMCET 2001']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">$3.6$</span> </div>
source_db: MarksBatch2_P1.db
title:
in-cgs-system-the-magnitude-of-the-force-is-100-dynes-in-another-system-where-the-fundamental-physical-quantities-are-kilogram-meter-and-minute-the-ma

slug:
in-cgs-system-the-magnitude-of-the-force-is-100-dynes-in-another-system-where-the-fundamental-physical-quantities-are-kilogram-meter-and-minute-the-ma-34902

question:
<div class="question">In CGS system the magnitude of the force is 100 dynes. In another system where the fundamental physical. quantities are kilogram, meter and minute, the magnitude of the force is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$0.036$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$0.36$</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">$3.6$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$36$</span> </li> </ul>

answer:
<div class="solution">$n_2=n_1\left[\left(\frac{m_1}{m_2}\right)^a\left(\frac{L_1}{L_2}\right)^b\left(\frac{T_1}{T_2}\right)^c\right]$<br/>Dimensions of force is [ $\mathrm{M} \mathrm{L} \mathrm{T}^{-2}$ ]<br/>$a=1, b=1, c=-2$<br/>$\begin{aligned} n_2 &amp; =100\left[\left(\frac{\mathrm{g}}{\mathrm{kg}}\right)^1\left(\frac{\mathrm{cm}}{\text { metre }}\right)^1\left(\frac{\mathrm{sec}}{\mathrm{min}}\right)^{-3}\right] \\ &amp; =100\left[\frac{\mathrm{g}}{100 \mathrm{~g}} \times \frac{\mathrm{cm}}{100 \mathrm{~cm}} \times\left(\frac{\mathrm{sec}}{60 \mathrm{sec}}\right)^{-2}\right] \\ &amp; =100\left[\frac{1}{1000} \times \frac{1}{100} \times(60)^2\right] \\ &amp; =100 \times \frac{1}{1000} \times \frac{1}{100} \times 3600=3.6\end{aligned}$</div>


tags: ['Physics', 'Units and Dimensions', 'JEE Main']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">$3.6$</span> </div>
source_db: MarksBatch2_P1.db
title:
in-cgs-system-the-magnitutde-of-the-force-is-100-dynes-in-another-system-where-the-fundamental-physical-quantities-are-kilogram-metre-and-minute-the-m

slug:
in-cgs-system-the-magnitutde-of-the-force-is-100-dynes-in-another-system-where-the-fundamental-physical-quantities-are-kilogram-metre-and-minute-the-m-92978

question:
<div class="question">In C.G.S. system the magnitutde of the force is 100 dynes. In another system where the fundamental physical quantities are kilogram, metre and minute, the magnitude of the force is</div>

answer:
<div class="solution">$\begin{aligned} &amp; n_2=n_1\left(\frac{M_1}{M_2}\right)^1\left(\frac{L_1}{L_2}\right)^1\left(\frac{T}{T_2}\right)^{-2} \\ &amp; =100\left(\frac{g m}{k g}\right)^1\left(\frac{\mathrm{cm}}{\mathrm{m}}\right)^1\left(\frac{\mathrm{sec}}{\mathrm{min}}\right)^{-2} \\ &amp; =100\left(\frac{\mathrm{gm}}{10^3 \mathrm{gm}}\right)^1\left(\frac{\mathrm{cm}}{10^2 \mathrm{~cm}}\right)^1\left(\frac{\mathrm{sec}}{60 \mathrm{sec}}\right)^{-2} \\ &amp; n_2=\frac{3600}{10^3}=3.6\end{aligned}$</div>


title: in-china-rose-the-flowers-are-1
slug: in-china-rose-the-flowers-are-1-76985
question: <div class="question">In China rose the flowers are</div>
tags: ['Biology', 'Morphology of Flowering Plants', 'NEET', 'NEET 2013 (All India)']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">actinomorphic, hypogynous with twisted aestivation</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">actinomorphic, epigynous with valvate aestivation</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">zygomorphic, hypogynous with imbricate aestivation</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">zygomorphic, epigynous with twisted aestivation</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">actinomorphic, hypogynous with twisted aestivation</span> </div>

answer:
<div class="solution">Actinomorphic (star-shaped) can be divided into 3 or more identical sectors, which are related to each other by rotation about the centre of the flower, e.g., China rose. Zygomorphic flowers can be divided by only a single plane into two mirror image halves, e.g., orchids.<br/>Valvate aestivation The sepals or petals in a whorl just touch one another at the margin, e.g., Calotropis.<br/>Twisted aestivation One margin of the appendage overlaps that of the next one, e.g., China rose. Imbricate aestivation the margins of sepals or petals overlap but not necessarily in specific direction, e.g., Cassia. For further detail refer to ans. 97</div>


title: in-chloroethane-the-carbon-bearing-halogen-is-bonded-to-hydrogen-s-it-is-called-alkyl-halide-1
tags: ['Chemistry', 'Haloalkanes and Haloarenes', 'AP EAMCET', 'AP EAMCET 2002']
source_db: MarksBatch2_P1.db
slug:
in-chloroethane-the-carbon-bearing-halogen-is-bonded-to-hydrogen-s-it-is-called-alkyl-halide-1-89460

question:
<div class="question">In chloroethane, the carbon bearing halogen is bonded to ... hydrogen $(s)$. It is called ...... alkyl halide.</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">Two, primary</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Three, primary</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Two, secondary</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">One, tertiary</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Two, primary</span> </div>

answer:
<div class="solution"><img src="https://cdn-question-pool.getmarks.app/pyq/ap_eamcet/scBofkiPEhYmTeQD-sNTMYBCB7KKe8acMlK84iNqM28.original.fullsize.png"/><br/></div>


title: in-chloroethane-the-carbon-bearing-halogen-is-bonded-to-hydrogen-s-it-is-called-alkyl-halide
slug: in-chloroethane-the-carbon-bearing-halogen-is-bonded-to-hydrogen-s-it-is-called-alkyl-halide-96475
tags: ['Chemistry', 'Haloalkanes and Haloarenes', 'TS EAMCET', 'TS EAMCET 2002']
source_db: MarksBatch2_P1.db
question:
<div class="question">In chloroethane, the carbon bearing halogen is bonded to ... hydrogen $(s)$. It is called ...... alkyl halide.</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">Two, primary</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Three, primary</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Two, secondary</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">One, tertiary</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Two, primary</span> </div>

answer:
<div class="solution"><img src="https://cdn-question-pool.getmarks.app/pyq/ts_eamcet/scBofkiPEhYmTeQD-sNTMYBCB7KKe8acMlK84iNqM28.original.fullsize.png"/><br/></div>


tags: ['Mathematics', 'Statistics', 'NDA', 'NDA 2007 (Phase 2)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">Mode</span> </div>
answer: <div class="solution">Mode is the required measure.</div>
source_db: MarksBatch2_P1.db
title:
in-computing-a-measure-of-the-central-tendency-for-any-set-of-51-numbers-which-one-of-the-following-measures-is-welldefined-but-uses-only-very-few-of-

slug:
in-computing-a-measure-of-the-central-tendency-for-any-set-of-51-numbers-which-one-of-the-following-measures-is-welldefined-but-uses-only-very-few-of-60759

question:
<div class="question">In computing a measure of the central tendency for any set of 51 numbers, which one of the following measures is welldefined but uses only very few of the numbers of the set?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Arithmetic mean</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Geometric mean</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Median</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">Mode</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>


title: in-conifers-fibres-are-likely-to-be-absent-in
slug: in-conifers-fibres-are-likely-to-be-absent-in-82350
question: <div class="question">In conifers fibres are likely to be absent in</div>
tags: ['Biology', 'Anatomy of Flowering Plants']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>secondary phloem <br/></span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data"><br/>secondary xylem<br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><br/>primaryphloem <br/></span> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><br/>leaves</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>secondary xylem<br/></span> </div>

answer:
<div class="solution">Fibres occur in all those parts of plants where mechanical strength is required i.e., leaves, petioles, cortex, xylem, phloem, etc. In conifers, they are likely to be absent in secondary xylem.</div>


tags: ['Chemistry', 'Hydrocarbons', 'NEET']
source_db: MarksBatch2_P1.db
title:
in-dehydrohalogenation-the-rate-of-the-reaction-is-influenced-by-the-nature-of-the-alkyl-group-which-type-of-alkyl-group-exhibits-the-highest-rate-of-

slug:
in-dehydrohalogenation-the-rate-of-the-reaction-is-influenced-by-the-nature-of-the-alkyl-group-which-type-of-alkyl-group-exhibits-the-highest-rate-of-31593

question:
<div class="question">In dehydrohalogenation, the rate of the reaction is influenced by the nature of the alkyl group. Which type of alkyl group exhibits the highest rate of reaction?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Primary alkyl group</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Secondary alkyl group</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">Tertiary alkyl group</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Quaternary alkyl group</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Tertiary alkyl group</span> </div>

answer:
<div class="solution">Tertiary alkyl groups exhibit the highest rate of dehydrohalogenation reactions.</div>


title: in-dicot-root-the-vascular-cambium-is
slug: in-dicot-root-the-vascular-cambium-is-31412
question: <div class="question">In dicot root, the vascular cambium is</div>
tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Completely primary in origin</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Partly primary and partly secondary</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">Completely secondary in origin</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">None of these</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Completely secondary in origin</span> </div>

answer:
<div class="solution">In dicot roots cambium is absent, thus during secondary growth parenchyma cells of pericycle and parenchyma cells of conjuctive tissue lying inner to phloem becomes meristematic and forms wavy ring of vascular cambium which is completely secondary in origin.</div>


title: in-dicot-stem-the-xylem-is
slug: in-dicot-stem-the-xylem-is-58762
question: <div class="question">In dicot stem, the xylem is</div>
tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Exarch</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Mesarch</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Centarch</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">Endarch</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Endarch</span> </div>

answer:
<div class="solution">There are four types of primary xylem development: <strong>exarch, endarch, centrarch, and mesarch.</strong><br/>In <strong>endarch </strong>development, the protoxylem begins its development from the innermost procambial cells located adjacent to the pith and development progresses outward. Therefore, the protoxylem is found toward the inside and metaxylem toward the outside of the stem. Endarch development is considered the most highly advanced type of primary xylem development.</div>


title: in-dicot-stem-vascular-bundles-are
slug: in-dicot-stem-vascular-bundles-are-88324
question: <div class="question">In dicot stem, vascular bundles are:</div>
tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Numerous and scattered</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">Arranged in a ring</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Without cambium</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Surrounded by bundle sheath</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Arranged in a ring</span> </div>

answer:
<div class="solution">The characteristic features of vascular bundles of dicot stem are as follows:<br/>1. Vascular bundles are arranged in a ring.<br/>2. They are conjoint, i.e. xylem and phloem are present on the same radius.<br/>3. They are open, i.e. cambium layer is found between xylem and phloem.<br/>4. They are not surrounded by bundle sheath.<br/>5. The position of protoxylem is towards the centre, i.e.<em> </em>endarch.</div>


title: in-dicotyledonous-stems-what-is-present-between-phloem-and-xylem
slug: in-dicotyledonous-stems-what-is-present-between-phloem-and-xylem-21697
question: <div class="question">In dicotyledonous stems, what is present between phloem and xylem?</div>
tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
answer: <div class="solution">In dicotyledonous stems, cambium is present between phloem and xylem.</div>
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">Cambium</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Secondary xylem</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Secondary phloem</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Closed vascular bundles</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Cambium</span> </div>


tags: ['Mathematics', 'Probability', 'NDA', 'NDA 2019 (Phase 1)']
source_db: MarksBatch2_P1.db
title:
in-eight-throws-of-a-die-5-or-6-is-considered-a-success-the-mean-and-standard-deviation-of-total-number-of-successes-is-respectively-given-by

slug:
in-eight-throws-of-a-die-5-or-6-is-considered-a-success-the-mean-and-standard-deviation-of-total-number-of-successes-is-respectively-given-by-82364

question:
<div class="question">In eight throws of a die, 5 or 6 is considered a success. The mean and standard deviation of total number of successes<br/>is respectively given by</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{8}{3}, \frac{16}{9}$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$\frac{8}{3}, \frac{4}{3}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\frac{4}{3}, \frac{4}{3}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$\frac{4}{3}, \frac{16}{9}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\frac{8}{3}, \frac{4}{3}$</span> </div>

answer:
<div class="solution">5 or 6 is success<br/>$\therefore p=\frac{2}{6}=\frac{1}{3}$<br/>$\therefore q=1-\frac{1}{3}=\frac{2}{3}$<br/>$\mathrm{n}=8$<br/>$\therefore$ Mean $=\mathrm{n} \mathrm{p}=8\left(\frac{1}{3}\right)=\frac{8}{3}$<br/>Standard deviation $=\sqrt{n p q}=\sqrt{8\left(\frac{1}{3}\right)\left(\frac{2}{3}\right)}$<br/>$=\sqrt{\frac{16}{9}}=\frac{4}{3}$</div>


title: in-ellingham-diagram-the-plot-is-drawn-between
slug: in-ellingham-diagram-the-plot-is-drawn-between-77628
question: <div class="question">In Ellingham diagram, the plot is drawn between</div>
source_db: MarksBatch2_P1.db
tags:
['Chemistry', 'General Principles and Processes of Isolation of Metals', 'AP EAMCET', 'AP EAMCET 2018 (22 Apr Shift 1)']

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">temperature, $\Delta H^{\circ}$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">temperature, $\Delta G^{\circ}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">pressure, $\Delta S^{\circ}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">temperature, $\Delta E^{\circ}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">temperature, $\Delta G^{\circ}$</span> </div>

answer:
<div class="solution">Standard Gibbs free energy âGÂ° is plotted<br/>against temperature (T)<br/><img src="https://cdn-question-pool.getmarks.app/pyq/ap_eamcet/o79nYCvGxG7G-YugF_Jih2jm5kHjQGpZEqB672pTCyI.original.fullsize.png"/><br/></div>


title: in-endarch-condition-of-xylem-metaxylem-lies-of-protoxylem
slug: in-endarch-condition-of-xylem-metaxylem-lies-of-protoxylem-55654
question: <div class="question">In endarch condition of xylem, metaxylem lies _____ of protoxylem</div>
tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">on outer side</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">on inner side</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">both on inner and outer side</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">in centre</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">on outer side</span> </div>

answer:
<div class="solution">The endarch condition of xylem refers to the condition when the metaxylem lies towards the periphery and the protoxylem towards the pith while in exarch condition the metaxylem lies towards the centre and the protoxylem is situated towards the periphery. Endarch condition is seen in stem whereas exarch condition is found in roots of all vascular plants.</div>


tags: ['Biology', 'Sexual Reproduction in Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
title:
in-flowering-plants-arrange-the-following-steps-in-their-correct-sequence-a-formation-of-the-embryo-sac-b-megasporogenesis-c-formation-of-endosperm-d-

slug:
in-flowering-plants-arrange-the-following-steps-in-their-correct-sequence-a-formation-of-the-embryo-sac-b-megasporogenesis-c-formation-of-endosperm-d-60576

question:
<div class="question">In flowering plants, arrange the following steps in their correct sequence.<br/> <br/> <math><mfenced separators="|"><mrow><mi mathvariant="normal">a</mi></mrow></mfenced></math> Formation of the embryo sac<br/> <br/> <math><mfenced separators="|"><mrow><mi mathvariant="normal">b</mi></mrow></mfenced></math> Megasporogenesis<br/> <br/> <math><mfenced separators="|"><mrow><mi mathvariant="normal">c</mi></mrow></mfenced></math> Formation of endosperm<br/> <br/> <math><mfenced separators="|"><mrow><mi mathvariant="normal">d</mi></mrow></mfenced></math> Fertilization<br/> <br/> <math><mfenced separators="|"><mrow><mi mathvariant="normal">e</mi></mrow></mfenced></math> Development of embryo</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math><mi mathvariant="normal">b</mi><mo>â</mo><mi mathvariant="normal">Â </mi><mi mathvariant="normal">a</mi><mo>â</mo><mi mathvariant="normal">e</mi><mo>â</mo><mi mathvariant="normal">c</mi><mo>â</mo><mi mathvariant="normal">d</mi></math></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><math><mi mathvariant="normal">b</mi><mo>â</mo><mi mathvariant="normal">a</mi><mo>â</mo><mi mathvariant="normal">c</mi><mo>â</mo><mi mathvariant="normal">d</mi><mo>â</mo><mi mathvariant="normal">e</mi></math></span> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><math><mi mathvariant="normal">a</mi><mo>â</mo><mi mathvariant="normal">b</mi><mo>â</mo><mi mathvariant="normal">Â </mi><mi mathvariant="normal">c</mi><mo>â</mo><mi mathvariant="normal">d</mi><mi mathvariant="normal">Â </mi><mo>â</mo><mi mathvariant="normal">e</mi></math></span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data"><math><mi mathvariant="normal">b</mi><mo>â</mo><mi mathvariant="normal">a</mi><mo>â</mo><mi mathvariant="normal">d</mi><mo>â</mo><mi mathvariant="normal">c</mi><mo>â</mo><mi mathvariant="normal">e</mi><mi mathvariant="normal">Â </mi></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math><mi mathvariant="normal">b</mi><mo>â</mo><mi mathvariant="normal">a</mi><mo>â</mo><mi mathvariant="normal">d</mi><mo>â</mo><mi mathvariant="normal">c</mi><mo>â</mo><mi mathvariant="normal">e</mi><mi mathvariant="normal">Â </mi></math></span> </div>

answer:
<div class="solution">Formation of megaspore is called megasporogenesis and megaspore germinates to form female gametophyte i.e. embryo sac. Embryo sac has egg that participates in fertilization and secondary nucleus of embryo sac leads to formation of PEN after double fertilization. Thus endosperm formation is followed by embryo formation.</div>


tags: ['Biology', 'Sexual Reproduction in Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
title:
in-flowering-plants-what-is-the-correct-sequence-of-events-that-takes-place-in-the-integumented-ovule-a-embryo-sac-formation-b-megasporogenesis-c-endo

slug:
in-flowering-plants-what-is-the-correct-sequence-of-events-that-takes-place-in-the-integumented-ovule-a-embryo-sac-formation-b-megasporogenesis-c-endo-86146

question:
<div class="question">In flowering plants, what is the correct sequence of events that takes place in the integumented ovule?<br/> <br/>
a. Embryo sac formation<br/>
b. Megasporogenesis<br/>
c. Endosperm formation<br/>
d. Fertilization<br/>
e. Embryogenesis</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math><mi mathvariant="normal">a</mi><mo>â</mo><mi mathvariant="normal">b</mi><mo>â</mo><mi mathvariant="normal">c</mi><mo>â</mo><mi mathvariant="normal">d</mi><mo>â</mo><mi mathvariant="normal">e</mi></math></span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data"><math><mi mathvariant="normal">b</mi><mo>â</mo><mi mathvariant="normal">a</mi><mo>â</mo><mi mathvariant="normal">d</mi><mo>â</mo><mi mathvariant="normal">c</mi><mo>â</mo><mi mathvariant="normal">e</mi></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><math><mi mathvariant="normal">b</mi><mo>â</mo><mi mathvariant="normal">a</mi><mo>â</mo><mi mathvariant="normal">e</mi><mo>â</mo><mi mathvariant="normal">c</mi><mo>â</mo><mi mathvariant="normal">d</mi></math></span> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><math><mi>b</mi><mo>â</mo><mi mathvariant="normal">a</mi><mo>â</mo><mi mathvariant="normal">c</mi><mo>â</mo><mi mathvariant="normal">d</mi><mo>â</mo><mi mathvariant="normal">e</mi></math></span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math><mi mathvariant="normal">b</mi><mo>â</mo><mi mathvariant="normal">a</mi><mo>â</mo><mi mathvariant="normal">d</mi><mo>â</mo><mi mathvariant="normal">c</mi><mo>â</mo><mi mathvariant="normal">e</mi></math></span> </div>

answer:
<div class="solution">Formation of megaspore is called megasporogenesis, and megaspore germinates to form female gametophyte, i.e., embryosac. Embryosac has an egg that participates in fertilization, and secondary nucleus of embryo sac leads to the formation of PEN after double fertilization. Thus, endosperm formation is followed by embryo formation.</div>


title: in-friedelcrafts-alkylation-of-aniline-one-gets
slug: in-friedelcrafts-alkylation-of-aniline-one-gets-89796
question: <div class="question">In Friedel-Crafts alkylation of aniline, one gets:</div>
tags: ['Chemistry', 'Carboxylic Acid Derivatives', 'JEE Main', 'JEE Main 2022 (29 Jun Shift 2)']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">alkylated product with ortho and para substitution.</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">secondary amine after acidic treatment.</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">an amide product.</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">positively charged nitrogen at benzene ring.</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">positively charged nitrogen at benzene ring.</span> </div>

answer:
<div class="solution"><p>Aniline does not undergo Friedel-crafts reaction due to salt formation with aluminium chloride, the Lewis acid, which is used as a catalyst, whereas aniline is a strong base. So, an acid-base reaction will take place. Thus, aniline reacts with <math><mi mathvariant="normal">A</mi><mi mathvariant="normal">l</mi><mi mathvariant="normal">C</mi><msub><mrow><mi mathvariant="normal">l</mi></mrow><mrow><mn>3</mn></mrow></msub></math> to form a salt.<br/><img alt="" src="https://cdn-question-pool.getmarks.app/pyq/jee_main/75d7b7ac-4e45-493a-91c6-85fa0ddc3273-9711822.png" style="width: 270px; height: 157px;"/><br/>Due to the positive charge on the nitrogen atom (shows <math><mo>-</mo><mi mathvariant="normal">I</mi></math> effect and it is meta directing), electrophilic substitution in the benzene ring is deactivated. Hence, the Friedel-Crafts reaction will not take place in aniline.</p></div>


title: in-frog-chromosome-number-is-reduced-to-half
slug: in-frog-chromosome-number-is-reduced-to-half-22221
question: <div class="question">In frog chromosome number is reduced to half</div>
tags: ['Biology', 'Structural Organisation in Animals', 'JIPMER', 'JIPMER 2005']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">when 2nd polar body is separated</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">when 2nd polar body is divided</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">when 3rd polar body is separated</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">when 1st polar body is separated</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">when 1st polar body is separated</span> </div>

answer:
<div class="solution">Each primary oocyte undergo two maturation divisions, first meiotic and the second meiotic division. In the I-meiotic division, the primary oocyte divides into two unequal haploid daughter cells-a large secondary oocyte and very small first polar body. In II-maturation division, the first polar body may divide to form two second polar bodies. The secondary oocyte again divides into two unequal daughter cells, a large ootid and a very small second polar body. The ootid grows into a functional haploid ovum. The I meiotic division is reductional and II meiotic division is equational division.</div>


tags: ['Physics', 'Waves and Sound', 'MHT CET', 'MHT CET 2022 (08 Aug Shift 2)']
source_db: MarksBatch2_P1.db
title:
in-fundamental-mode-the-time-required-for-the-sound-wave-to-each-upto-the-closed-end-of-a-pipe-filled-with-air-is-t-second-the-frequency-of-vibration-

slug:
in-fundamental-mode-the-time-required-for-the-sound-wave-to-each-upto-the-closed-end-of-a-pipe-filled-with-air-is-t-second-the-frequency-of-vibration-88436

question:
<div class="question">In fundamental mode, the time required for the sound wave to each upto the closed end of a pipe filled with air is ' $t$ ' second. The frequency of vibration of air column is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{2}{t}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\frac{0.5}{t}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\frac{1}{t}$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$\frac{0.25}{t}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\frac{0.25}{t}$</span> </div>

answer:
<div class="solution"><img src="https://cdn-question-pool.getmarks.app/pyq/mht_cet/plpXCqwKgPCOKTOFZNWOrHlqeawJwxJIHmuyZJlAYfg.original.fullsize.png"/><br/><br/>$\begin{aligned}<br/>&amp; \Rightarrow V=\frac{L}{y}=(4 L) g \\<br/>&amp; \Rightarrow f=\frac{0.25}{t}<br/>\end{aligned}$<br/>Option (D) is correct</div>


tags: ['Physics', 'Waves and Sound', 'MHT CET', 'MHT CET 2019 (02 May Shift 1)']
source_db: MarksBatch2_P1.db
title:
in-fundamental-mode-the-time-required-for-the-sound-wave-to-reach-up-to-the-closed-end-of-a-pipe-lled-with-air-is-t-second-the-frequency-of-vibration-

slug:
in-fundamental-mode-the-time-required-for-the-sound-wave-to-reach-up-to-the-closed-end-of-a-pipe-lled-with-air-is-t-second-the-frequency-of-vibration-99338

question:
<div class="question">In fundamental mode, the time required for the sound wave to reach up to the closed end of a pipe ï¬lled with air is â <math><mi>t</mi></math> â second. The frequency of vibration of air column is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math><msup><mrow><mfenced separators="|"><mrow><mn>2</mn><mi>t</mi></mrow></mfenced></mrow><mrow><mo>-</mo><mn>1</mn></mrow></msup></math></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><math><mn>4</mn><msup><mrow><mfenced separators="|"><mrow><mi>t</mi></mrow></mfenced></mrow><mrow><mo>-</mo><mn>1</mn></mrow></msup></math></span> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><math><mn>2</mn><msup><mrow><mfenced separators="|"><mrow><mi>t</mi></mrow></mfenced></mrow><mrow><mo>-</mo><mn>1</mn></mrow></msup></math></span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data"><math><msup><mrow><mfenced separators="|"><mrow><mn>4</mn><mi>t</mi></mrow></mfenced></mrow><mrow><mo>-</mo><mn>1</mn></mrow></msup></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math><msup><mrow><mfenced separators="|"><mrow><mn>4</mn><mi>t</mi></mrow></mfenced></mrow><mrow><mo>-</mo><mn>1</mn></mrow></msup></math></span> </div>

answer:
<div class="solution"><math><mo>âµ</mo><mo>â</mo><msub><mrow><mi>f</mi></mrow><mrow><mn>0</mn></mrow></msub><mo>=</mo><mo>â</mo><mfrac><mrow><mi>v</mi></mrow><mrow><mn>4</mn><mi>l</mi></mrow></mfrac></math> <br/><math><mo>â</mo><mo>â</mo><mo>â</mo><msub><mrow><mi>f</mi></mrow><mrow><mn>0</mn></mrow></msub><mo>=</mo><mo>â</mo><mfrac><mrow><mn>1</mn></mrow><mrow><mn>4</mn><mi>l</mi></mrow></mfrac><mfenced separators="|"><mrow><mfrac><mrow><mi mathvariant="normal">D</mi><mi mathvariant="normal">i</mi><mi mathvariant="normal">s</mi><mi mathvariant="normal">t</mi><mi mathvariant="normal">a</mi><mi mathvariant="normal">n</mi><mi mathvariant="normal">c</mi><mi mathvariant="normal">e</mi></mrow><mrow><mi mathvariant="normal">t</mi><mi mathvariant="normal">i</mi><mi mathvariant="normal">m</mi><mi mathvariant="normal">e</mi></mrow></mfrac></mrow></mfenced></math> <br/><math><mo>â</mo><mo>â</mo><mo>â</mo><msub><mrow><mi>f</mi></mrow><mrow><mn>0</mn></mrow></msub><mo>=</mo><mfrac><mrow><mn>1</mn></mrow><mrow><mn>4</mn><mi>l</mi></mrow></mfrac><mfenced separators="|"><mrow><mfrac><mrow><mi>l</mi></mrow><mrow><mi>t</mi></mrow></mfrac></mrow></mfenced></math> <br/><math><mo>â</mo><mo>â</mo><mo>â</mo><msub><mrow><mi>f</mi></mrow><mrow><mn>0</mn></mrow></msub><mo>=</mo><mfrac><mrow><mn>1</mn></mrow><mrow><mn>4</mn><mi>t</mi></mrow></mfrac></math></div>


tags: ['Physics', 'Waves and Sound', 'MHT CET', 'MHT CET 2021 (21 Sep Shift 1)']
source_db: MarksBatch2_P1.db
title:
in-fundamental-mode-the-time-required-for-the-sound-wave-to-reach-up-to-the-closed-end-of-pipe-filled-with-air-is-t-second-the-frequency-of-vibration-

slug:
in-fundamental-mode-the-time-required-for-the-sound-wave-to-reach-up-to-the-closed-end-of-pipe-filled-with-air-is-t-second-the-frequency-of-vibration-75106

question:
<div class="question">In fundamental mode, the time required for the sound wave to reach up to the closed end of pipe filled with air is $t$ second. The frequency of vibration of air column is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{1}{\mathrm{t}}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\frac{2}{\mathrm{t}}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\frac{3}{\mathrm{t}}$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$\frac{0.25}{\mathrm{t}}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\frac{0.25}{\mathrm{t}}$</span> </div>

answer:
<div class="solution">In fundamental mode the length of the closed tube is $\frac{\lambda}{4}$<br/>Time required to travel a distance $\frac{\lambda}{4}$ is $\mathrm{t}$.<br/>Hence time required to travel a distance $\lambda$ will be $4 \mathrm{t}$.<br/>$\therefore$ Time period $\mathrm{T}=4 \mathrm{t}$<br/>Frequency, $\mathrm{n}=\frac{1}{\mathrm{~T}}=\frac{1}{4 \mathrm{t}}=\frac{0.25}{\mathrm{t}}$</div>


tags: ['Physics', 'Waves and Sound', 'MHT CET', 'MHT CET 2020 (14 Oct Shift 2)']
source_db: MarksBatch2_P1.db
title:
in-fundamental-mode-the-time-required-for-the-sound-wave-to-reach-upto-the-closed-end-of-a-pipe-filled-with-air-is-t-second-the-frequency-of-vibration

slug:
in-fundamental-mode-the-time-required-for-the-sound-wave-to-reach-upto-the-closed-end-of-a-pipe-filled-with-air-is-t-second-the-frequency-of-vibration-81004

question:
<div class="question">In fundamental mode, the time required for the sound wave to reach upto the closed end of a pipe filled with air is 't' second. The frequency of vibration of air column is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{1}{3 t}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\frac{1}{t}$</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">$\frac{1}{4 t}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$\frac{1}{2 t}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\frac{1}{4 t}$</span> </div>

answer:
<div class="solution">The distance between the open end and the closed end in the fundamental mode is $\frac{\lambda}{4}$. If the time required to cover the distance is $\mathrm{t}$, then the time required to travel distance equal to $\lambda$ will be $4 \mathrm{t}$. Therefore the period of the wave is $4 \mathrm{t}$. Hence the frequency is $\frac{1}{4 \mathrm{t}}$.</div>


tags: ['Biology', 'Ecosystem', 'NEET']
source_db: MarksBatch2_P1.db
title:
in-how-many-of-the-following-primary-succession-will-occur-abandoned-farmland-newly-created-pond-bare-rock-burnt-forest

slug:
in-how-many-of-the-following-primary-succession-will-occur-abandoned-farmland-newly-created-pond-bare-rock-burnt-forest-77034

question:
<div class="question">In how many of the following, primary succession will occur?<br/>
(Abandoned farmland, newly created pond, bare rock, burnt forest)</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Newly created ponds, bare rock, bandoned farmlands and burnt forests</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">Newly created ponds and bare rock </span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Abandoned farmlands, bare rocks and burnt forests </span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Bare rocks</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Newly created ponds and bare rock </span> </div>

answer:
<div class="solution">When succession occurs in an area where no living organism ever existed; it is called primary succession and when it takes place in areas that have lost all living organisms that had existed there; it is called secondary succession. Newly created ponds, bare rock are examples of primary succession. Abandoned farmlands and burnt forests are examples of secondary succession.</div>


title: in-how-many-points-do-the-ellipse-4-x-2-8-y-2-1-and-the-circle-x-2-y-2-9-intersect
slug: in-how-many-points-do-the-ellipse-4-x-2-8-y-2-1-and-the-circle-x-2-y-2-9-intersect-28264
tags: ['Mathematics', 'Ellipse', 'NDA', 'NDA 2007 (Phase 2)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In how many points do the ellipse $\frac{x^{2}}{4}+\frac{y^{2}}{8}=1$ and the circle $\mathrm{x}^{2}+\mathrm{y}^{2}=9$ intersect ?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">One</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Two</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Four</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">None of the above</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

answer:
<div class="solution">The given equation of circle is: $x^{2}+y^{2}=9$...(i)<br/>and ellipse is : $\frac{x^{2}}{4}+\frac{y^{2}}{8}=1$...(ii)<br/>From eqn. (1) and (2), we get<br/>$\frac{x^{2}}{4}+\frac{9-x^{2}}{8}=1$<br/>$\Rightarrow 2 x^{2}+9-x^{2}=8 \Rightarrow \quad x^{2}=-1$<br/>$x$ is not real Hence, circle and ellipse do not intersect.</div>


title: in-how-many-trophic-levels-can-humans-function-in-a-food-chain
slug: in-how-many-trophic-levels-can-humans-function-in-a-food-chain-96580
question: <div class="question">In how many trophic levels can humans function in a food chain?</div>
tags: ['Biology', 'Ecosystem', 'NEET']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">3</span> </div>
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">4</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">3</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">2</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">1</span> </li> </ul>

answer:
<div class="solution">Humans feed on vegetables and fruits. So they can be called primary consumers (Trophic level T2). Some humans also consume herbivores animals such as goat and lamb. So humans can be called secondary consumers (Trophic level T3). Humans also consume fishes such as salmon which are carnivorous animals. So humans can be tertiary consumers (Trophic level T4)</div>


title: in-how-many-ways-6-girls-can-be-seated-in-two-chairs
slug: in-how-many-ways-6-girls-can-be-seated-in-two-chairs-86190
question: <div class="question">In how many ways 6 girls can be seated in two chairs?</div>
tags: ['Mathematics', 'Permutation Combination', 'NDA', 'NDA 2011 (Phase 1)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">30</span> </div>
answer: <div class="solution">Required number of ways $=6 \times 5=30$</div>
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">10</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">15</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">24</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">30</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>


tags: ['Mathematics', 'Permutation Combination', 'NDA', 'NDA 2008 (Phase 2)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">576</span> </div>
source_db: MarksBatch2_P1.db
title:
in-how-many-ways-can-3-books-on-hindi-and-3-books-on-english-be-arranged-in-a-row-on-a-shelf-so-that-not-all-the-hindi-books-are-together

slug:
in-how-many-ways-can-3-books-on-hindi-and-3-books-on-english-be-arranged-in-a-row-on-a-shelf-so-that-not-all-the-hindi-books-are-together-25794

question:
<div class="question">In how many ways can 3 books on Hindi and 3 books on English be arranged in a row on a shelf, so that not all the Hindi books are together?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">144</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">360</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">576</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">720</span> </li> </ul>

answer:
<div class="solution">Total number of arrangement $=6 !=720$ Total number of arrangement while all the Hindi books are together $=4 ! \times 3 !=24 \times 6=144$ $\therefore$ The number of ways, in which books are arranged, while all the Hindi books are not together $=720-144=576$</div>


title: in-how-many-ways-can-7-persons-stand-in-the-form-of-a-ring
slug: in-how-many-ways-can-7-persons-stand-in-the-form-of-a-ring-99810
question: <div class="question">In how many ways can 7 persons stand in the form of a ring?</div>
tags: ['Mathematics', 'Permutation Combination', 'NDA', 'NDA 2006 (Phase 2)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">$6 !$</span> </div>
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\mathrm{P}(7,2)$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$7 !$</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">$6 !$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$\frac{7 !}{2}$</span> </li> </ul>

answer:
<div class="solution">Number of ways in which 7 persons can stand in the form of a ring $=(7-1) !=6 !$</div>


title: in-how-many-ways-can-a-committee-consisting-of-3-men-and-2-women-be-formed-from-7-men-and-5-women
tags: ['Mathematics', 'Permutation Combination', 'NDA', 'NDA 2010 (Phase 2)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">350</span> </div>
source_db: MarksBatch2_P1.db
slug:
in-how-many-ways-can-a-committee-consisting-of-3-men-and-2-women-be-formed-from-7-men-and-5-women-54828

question:
<div class="question">In how many ways can a committee consisting of 3 men and 2 women be formed from 7 men and 5 women?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">45</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">350</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">700</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">4200</span> </li> </ul>

answer:
<div class="solution">Total no. of Men $=7$ Total no. of women $=5$ Required number of ways $={ }^{7} \mathrm{C}_{3} \times{ }^{5} \mathrm{C}_{2}$<br/>$=\frac{7 !}{3 ! 4 !} \times \frac{5 !}{2 ! 3 !}=\frac{7 \times 6 \times 5}{3 \times 2} \times \frac{5 \times 4}{2}$<br/>$=7 \times 5 \times 10=35 \times 10=350$</div>


tags: ['Mathematics', 'Permutation Combination', 'NDA', 'NDA 2007 (Phase 1)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">36</span> </div>
source_db: MarksBatch2_P1.db
title:
in-how-many-ways-can-be-letters-of-the-word-cable-be-arranged-so-that-the-vowels-should-always-occupy-odd-positions

slug:
in-how-many-ways-can-be-letters-of-the-word-cable-be-arranged-so-that-the-vowels-should-always-occupy-odd-positions-36042

question:
<div class="question">In how many ways can be letters of the word 'CABLE' be arranged so that the vowels should always occupy odd positions?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">12</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">18</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">24</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">36</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

answer:
<div class="solution">There are two vowels A and E. There are total 5 places out of which two places are to be occupied by vowels. So, 3 places can be occupied by 2 vowels in ${ }^{3} \mathrm{P}_{2}$ ways and after two vowels occupy two places, 3 consonants will occupy 3 places in ${ }^{3} \mathrm{P}_{3}=3$ ! way, hence, Required number of ways $={ }^{3} \mathrm{P}_{2} \times 3 !=6 \times 6=36$</div>


tags: ['Mathematics', 'Permutation Combination', 'NDA', 'NDA 2006 (Phase 1)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">7200</span> </div>
source_db: MarksBatch2_P1.db
title:
in-how-many-ways-can-the-letters-of-the-word-corporation-be-arranged-so-that-vowels-always-occupy-even-places

slug:
in-how-many-ways-can-the-letters-of-the-word-corporation-be-arranged-so-that-vowels-always-occupy-even-places-14292

question:
<div class="question">In how many ways can the letters of the word CORPORATION be arranged so that vowels always occupy even places?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">120</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">2700</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">720</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">7200</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

answer:
<div class="solution">CORPORATION is 11 letter word. It has 5 vowels $(\mathrm{O}, \mathrm{O}, \mathrm{O}, \mathrm{A}, \mathrm{I})$ and 6 consonants $(\mathrm{C}, \mathrm{R}$<br/>$\mathrm{P}, \mathrm{R}, \mathrm{T}, \mathrm{N})$<br/>In 11 letters, there are 5 even places $\left(2^{\text {nd }}, 4^{\text {th }}, 6^{\text {th }}, 8^{\text {th }}\right.$ and $10^{\text {th }}$ positions)<br/>5 vowels can take 5 even places in $\frac{5 !}{3 !}$ ways<br/>$(\because$ Since $\mathrm{O}$ is repeated thrice)<br/>Similarly, 6 consonasts can take 6 odd places in $\frac{6 !}{2 !}$<br/>ways. $(\because \mathrm{R}$ is repeated twice)<br/>$\therefore \quad$ Total number of ways $=\frac{5 !}{3 !} \times \frac{6 !}{2 !}=20 \times 360=7200$</div>


tags: ['Mathematics', 'Permutation Combination', 'NDA', 'NDA 2013 (Phase 1)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">240</span> </div>
answer: <div class="solution">$\frac{6 !}{2 !}-5 !=240$</div>
source_db: MarksBatch2_P1.db
title:
in-how-many-ways-can-the-letters-of-the-word-gloomy-be-arranged-so-that-the-two-o-s-should-not-be-together

slug:
in-how-many-ways-can-the-letters-of-the-word-gloomy-be-arranged-so-that-the-two-o-s-should-not-be-together-68703

question:
<div class="question">In how many ways can the letters of the word 'GLOOMY' be arranged so that the two $\mathrm{O}$ 's should not be together?</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">240</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">480</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">600</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">720</span> </li> </ul>


title: in-human-female-second-polar-body-is-formed-in-the-ovum
slug: in-human-female-second-polar-body-is-formed-in-the-ovum-72389
question: <div class="question">In human female, second polar body is formed in the ovum</div>
tags: ['Biology', 'Human Reproduction', 'NEET']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">within ovary</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">within oviducts</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">within uterine cavity</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">within uterine endometrium</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">within oviducts</span> </div>

answer:
<div class="solution">During oogenesis, the primary oocyte undergoes meiosis I to form the secondary oocyte and the first polar body during the formation of the Graafian follicle. This occurs in the ovary. This secondary oocyte is released during ovulation and reaches the fallopian tubes (oviducts). Fertilization occurs here. When the sperm enters the ovum, the secondary oocyte undergoes the second meiotic division to release the second polar body. Also, the first polar body at the same time completes second meiotic division to form two secondary polar bodies.</div>


title: in-human-females-meiosisii-is-not-completed-until
slug: in-human-females-meiosisii-is-not-completed-until-18918
question: <div class="question">In human females, meiosis-II is not completed until?</div>
tags: ['Biology', 'Human Reproduction', 'NEET', 'NEET 2015 (Phase 2)']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">Fertilization</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Uterine implantation</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Birth</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Puberty</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Fertilization</span> </div>

answer:
<div class="solution">In human females, meiosis-II is completed after the entry of sperm into the cytoplasm of the secondary oocyte at the time of fertilization leading to the formation of ovum and secondary polar body.</div>


title: in-humans-at-the-end-of-first-meiotic-division-the-male-germ-cells-differentiate-into-the
slug: in-humans-at-the-end-of-first-meiotic-division-the-male-germ-cells-differentiate-into-the-83276
tags: ['Biology', 'Human Reproduction', 'AIIMS', 'AIIMS 2009']
source_db: MarksBatch2_P1.db
question:
<div class="question">In humans at the end of first meiotic division, the male germ cells differentiate into the</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">primary spermatocytes</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">secondary spermatocytes</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">spermatids</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">spermatogonia.</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">secondary spermatocytes</span> </div>

answer:
<div class="solution">At sexual maturity, the undifferentiated primordial germ cells divide several times by mitosis to produce a large number of spermatogonia. Each spermatogonium then actively grows to a larger primary spermatocyte. Each primary spermatocyte undergoes two successive divisions, called maturation divisions. The first maturation division is reductional or meiotic. Hence, the primary spermatocyte divides into the haploid daughter cells called secondary spermatocytes.</div>


title: in-humans-at-the-end-of-the-first-meiotic-division-the-male-germ-cells-differentiate-into-the-1
tags: ['Biology', 'Human Reproduction', 'NEET', 'NEET 2008 (Screening)']
source_db: MarksBatch2_P1.db
slug:
in-humans-at-the-end-of-the-first-meiotic-division-the-male-germ-cells-differentiate-into-the-1-56932

question:
<div class="question">In humans, at the end of the first meiotic division, the male germ cells differentiate into the</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">primary spermatocytes</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">secondary spermatocytes</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">spermatids</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">spermatogonia</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">secondary spermatocytes</span> </div>

answer:
<div class="solution">At sexual maturity the germ cells in human male divide several times by mitosis to produce a large number of spermatogonia. In growth phase each spermatogonium actively grows to a larger primary spermatocyte by obtaining a nourishment from the nurshing cells. In maturation phase each primary spermatocyte undergoes two successive divisions called maturation divisions. The primary spermatocyte undergoes first maturation division (meiotic) to producing two haploid daughter cells called secondary spermatocytes. Both secondary spermatocytes undergo second maturation division to form four haploid spermatids. The transformation of spermatids into spermatozoa is called spermiogenesis or spermateliosis.</div>


title: in-humans-at-the-end-of-the-first-meiotic-division-the-male-germ-cells-differentiate-into-the
slug: in-humans-at-the-end-of-the-first-meiotic-division-the-male-germ-cells-differentiate-into-the-55611
tags: ['Biology', 'Human Reproduction', 'NEET', 'NEET 2008 (Mains)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In humans, at the end of the first meiotic division, the male germ cells differentiate into the</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Spermatozonia</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Primary spermatocytes</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">Secondary spermatocytes</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Spermatids</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Secondary spermatocytes</span> </div>

answer:
<div class="solution">After the first meiotic division primary spermatocytes divide to form secondary spermatocytes. Whereas, after second meiotic division secondary spermatocytes will divide to form spermatids.</div>


title: in-humans-blood-passes-from-the-post-caval-to-the-diastolic-right-atrium-of-heart-due-to-1
slug: in-humans-blood-passes-from-the-post-caval-to-the-diastolic-right-atrium-of-heart-due-to-1-18791
tags: ['Biology', 'Body Fluids and Circulation', 'NEET', 'NEET 2008 (Screening)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In humans, blood passes from the post caval to the diastolic right atrium of heart due to</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">pushing open of the venous valves</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">suction pull</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">stimulation of the sino auricular node</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">pressure difference between the caval and atrium</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">pressure difference between the caval and atrium</span> </div>

answer:
<div class="solution">The action of heart includes contractions and relaxations of the atria and ventricles. Contraction of the heart is called systole and relaxation is called diastole. The dynamics of blood flow in blood vessels is no exception and blood flows through the blood vessels along a pressure gradient, always moving from higher to lower pressure areas. Fundamentaly, the pumping action of heart generates blood flow. The contraction of atria is initiated and activated by sinoatrial node (SA node-Pacemaker), which spreads waves of contraction across the wall of atria via muscle fibres at regular intervals.</div>


title: in-india-ecosan-toilets-are-found-in
slug: in-india-ecosan-toilets-are-found-in-22099
question: <div class="question">In India, 'ecosan' toilets are found in</div>
tags: ['Biology', 'Environmental Issues', 'NEET']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">Kerala</span> </div>
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">West Bengal</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Sikkim</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Andaman and Nicobar</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">Kerala</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

answer:
<div class="solution">Ecological sanitation, commonly abbreviated as ecosan, is an approach to sanitation provision which aims to safely reuse excreta in agriculture. It desires to 'close the loop' mainly for the nutrients and organic matter between sanitation and agriculture. It is a process where human excreta can be recycled into a resource as a natural fertilizer, which reduces the need of chemical fertilizers. In India, Kerala was the first state to use it on a large scale.</div>


tags: ['Chemistry', 'General Organic Chemistry', 'NEET']
source_db: MarksBatch2_P1.db
title:
in-kjeldahls-method-of-estimation-of-nitrogen-nitrogen-is-quantitatively-converted-to-ammonium-sulphate-it-is-then-treated-with-standard-solution-of-a

slug:
in-kjeldahls-method-of-estimation-of-nitrogen-nitrogen-is-quantitatively-converted-to-ammonium-sulphate-it-is-then-treated-with-standard-solution-of-a-49502

question:
<div class="question">In Kjeldahl's method of estimation of nitrogen, nitrogen is quantitatively converted to ammonium sulphate. It is then treated with standard solution of alkali. The nitrogen which is present is estimated as</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math><msub><mrow><mi mathvariant="normal">N</mi></mrow><mrow><mn>2</mn></mrow></msub></math></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><math><mi mathvariant="normal">N</mi><msub><mrow><mi mathvariant="normal">O</mi></mrow><mrow><mn>2</mn></mrow></msub></math></span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data"><math><mi mathvariant="normal">N</mi><msub><mrow><mi mathvariant="normal">H</mi></mrow><mrow><mn>3</mn></mrow></msub></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><math><mo>(</mo><mi mathvariant="normal">N</mi><msub><mrow><mi mathvariant="normal">H</mi></mrow><mrow><mn>4</mn></mrow></msub><msub><mrow><mo>)</mo></mrow><mrow><mn>2</mn></mrow></msub><mi mathvariant="normal">S</mi><msub><mrow><mi mathvariant="normal">O</mi></mrow><mrow><mn>4</mn></mrow></msub></math> ppt.</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math><mi mathvariant="normal">N</mi><msub><mrow><mi mathvariant="normal">H</mi></mrow><mrow><mn>3</mn></mrow></msub></math></span> </div>

answer:
<div class="solution">When treated with standard solution of alkali nitrogen is liberated as <math><mi mathvariant="normal">N</mi><msub><mrow><mi mathvariant="normal">H</mi></mrow><mrow><mn>3</mn></mrow></msub></math> which is absorbed in <math><msub><mrow><mi mathvariant="normal">H</mi></mrow><mrow><mn>2</mn></mrow></msub><mi mathvariant="normal">S</mi><msub><mrow><mi mathvariant="normal">O</mi></mrow><mrow><mn>4</mn></mrow></msub></math> to get percentage of nitrogen.</div>


tags: ['Biology', 'Human Health and Diseases']
source_db: MarksBatch2_P1.db
title:
in-malignant-tumours-the-cells-proliferate-grow-rapidly-and-move-to-other-parts-of-the-body-to-form-new-tumours-this-stage-of-disease-is-called

slug:
in-malignant-tumours-the-cells-proliferate-grow-rapidly-and-move-to-other-parts-of-the-body-to-form-new-tumours-this-stage-of-disease-is-called-93936

question:
<div class="question">In malignant tumours, the cells proliferate, grow rapidly and move to other parts of the body to form new tumours. This stage of disease is called</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>metagenesis<br/></span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data"><br/> metastasis<br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><br/>teratogenesis<br/></span> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><br/>mitosis</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><br/> metastasis<br/></span> </div>

answer:
<div class="solution">Cancer is defined as an uncontrolleddivision or proliferation of cells without any differentiation. Repeated division of cells form a large mass of tissue called tumours. These are of two types i.e., benign (non-cancerous) and malignant (cancerous).<br/>The invasion of malignant tumour from primary site of cancer to the other secondary growth is called metastasis, while metagenesis is the alteration of generation.<br/>Teratogenesis is a prenatal toxicity, that is characterised by structural, functional defects in the developing embryo or foetus. Mitosis is a type of cell division that results in two daughter cells.</div>


title: in-mammals-growing-oocytes-are-surrounded-by-special-nutritive-cells-called
slug: in-mammals-growing-oocytes-are-surrounded-by-special-nutritive-cells-called-43438
tags: ['Biology', 'Human Reproduction', 'NEET']
source_db: MarksBatch2_P1.db
question:
<div class="question">In mammals growing oocytes are surrounded by special nutritive cells called</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">Follicle cells</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Nurse cells</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Follicle cells and nurse cells </span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">None of the above</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Follicle cells</span> </div>

answer:
<div class="solution">Graffian follicle is about 2.5 cm in diameter and has a secondary oocyte surrounded by a few layers of follicular cells, those are nourishing cells formed from undifferentiated oogonia.</div>


title: in-meghalaya-sacred-groves-are-found-in
slug: in-meghalaya-sacred-groves-are-found-in-32539
question: <div class="question">In Meghalaya, sacred groves are found in</div>
tags: ['Biology', 'Biodiversity and its Conservation', 'NEET']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">Khasi and Jaintia Hills</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Aravalli Hills</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Western Ghat regions</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Sarguja, Chanda and Bastar areas</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Khasi and Jaintia Hills</span> </div>

answer:
<div class="solution">Sacred groves are forests which are generally worshipped by certain cultures. Such sacred groves are found in Khasi and Jaintia Hills in Meghalaya, Aravalli Hills of Rajasthan, Western Ghat regions of Karnataka and Maharashtra and the Sarguja, Chanda and Bastar areas of Madhya Pradesh.</div>


tags: ['Physics', 'Current Electricity', 'MHT CET', 'MHT CET 2022 (05 Aug Shift 1)']
source_db: MarksBatch2_P1.db
title:
in-metre-bridge-experiment-the-null-point-is-obtained-at-20-cm-from-left-end-of-the-wire-when-resistance-x-is-balanced-against-another-resistance-y-x-

slug:
in-metre-bridge-experiment-the-null-point-is-obtained-at-20-cm-from-left-end-of-the-wire-when-resistance-x-is-balanced-against-another-resistance-y-x-77170

question:
<div class="question">In metre bridge experiment, the null point is obtained at $20 \mathrm{~cm}$ from left end of the wire, when resistance $X$ is balanced against another resistance $Y(X<y a="" against="" balance="" be="" end="" from="" new="" null="" of="" point="" position="" resistance="" same="" the="" to="" will="" x=""> <div class="tags" data-pagefind-ignore=""> <span class="tag">Physics</span><span class="tag">Current Electricity</span><span class="tag">MHT CET</span><span class="tag">MHT CET 2022 (05 Aug Shift 1)</span> </div> <span class="label">Options:</span>
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$40 \mathrm{~cm}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$80 \mathrm{~cm}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$60 \mathrm{~cm}$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$50 \mathrm{~cm}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul> <!-- /Question --> <!-- Solution --> <section class="solution-container" id="accepted-answer"> <div class="solution-header"> <span class="label">Solution:</span> <div class="badges-container" data-pagefind-ignore=""> <span class="badge upvotes-count"> <svg fill="none" height="16" viewbox="0 0 16 16" width="16" xmlns="http://www.w3.org/2000/svg"> <path d="M14.625 5.0075C14.4842 4.84795 14.3111 4.72019 14.1171 4.63269C13.9231 4.54519 13.7128 4.49996 13.5 4.5H10V3.5C10 2.83696 9.73661 2.20107 9.26777 1.73223C8.79893 1.26339 8.16304 1 7.5 1C7.40711 0.999934 7.31604 1.02574 7.237 1.07454C7.15795 1.12333 7.09407 1.19318 7.0525 1.27625L4.69125 6H2C1.73478 6 1.48043 6.10536 1.29289 6.29289C1.10536 6.48043 1 6.73478 1 7V12.5C1 12.7652 1.10536 13.0196 1.29289 13.2071C1.48043 13.3946 1.73478 13.5 2 13.5H12.75C13.1154 13.5001 13.4684 13.3668 13.7425 13.1252C14.0166 12.8835 14.1931 12.5501 14.2388 12.1875L14.9888 6.1875C15.0153 5.97626 14.9966 5.76179 14.9339 5.55833C14.8712 5.35488 14.7659 5.16711 14.625 5.0075ZM2 7H4.5V12.5H2V7Z" fill="#014A82"></path> </svg> 2082 Upvotes
</span> <span class="badge expert-verification-badge" data-pagefind-ignore=""> <svg fill="none" height="16" viewbox="0 0 16 16" width="16" xmlns="http://www.w3.org/2000/svg"> <path d="M14.1163 6.42625C13.8806 6.18 13.6369 5.92625 13.545 5.70312C13.46 5.49875 13.455 5.16 13.45 4.83187C13.4406 4.22187 13.4306 3.53062 12.95 3.05C12.4694 2.56937 11.7781 2.55937 11.1681 2.55C10.84 2.545 10.5012 2.54 10.2969 2.455C10.0744 2.36312 9.82 2.11937 9.57375 1.88375C9.1425 1.46937 8.6525 1 8 1C7.3475 1 6.85812 1.46937 6.42625 1.88375C6.18 2.11937 5.92625 2.36312 5.70312 2.455C5.5 2.54 5.16 2.545 4.83187 2.55C4.22187 2.55937 3.53062 2.56937 3.05 3.05C2.56937 3.53062 2.5625 4.22187 2.55 4.83187C2.545 5.16 2.54 5.49875 2.455 5.70312C2.36312 5.92562 2.11937 6.18 1.88375 6.42625C1.46937 6.8575 1 7.3475 1 8C1 8.6525 1.46937 9.14187 1.88375 9.57375C2.11937 9.82 2.36312 10.0738 2.455 10.2969C2.54 10.5012 2.545 10.84 2.55 11.1681C2.55937 11.7781 2.56937 12.4694 3.05 12.95C3.53062 13.4306 4.22187 13.4406 4.83187 13.45C5.16 13.455 5.49875 13.46 5.70312 13.545C5.92562 13.6369 6.18 13.8806 6.42625 14.1163C6.8575 14.5306 7.3475 15 8 15C8.6525 15 9.14187 14.5306 9.57375 14.1163C9.82 13.8806 10.0738 13.6369 10.2969 13.545C10.5012 13.46 10.84 13.455 11.1681 13.45C11.7781 13.4406 12.4694 13.4306 12.95 12.95C13.4306 12.4694 13.4406 11.7781 13.45 11.1681C13.455 10.84 13.46 10.5012 13.545 10.2969C13.6369 10.0744 13.8806 9.82 14.1163 9.57375C14.5306 9.1425 15 8.6525 15 8C15 7.3475 14.5306 6.85812 14.1163 6.42625ZM10.8538 6.85375L7.35375 10.3538C7.30731 10.4002 7.25217 10.4371 7.19147 10.4623C7.13077 10.4874 7.06571 10.5004 7 10.5004C6.93429 10.5004 6.86923 10.4874 6.80853 10.4623C6.74783 10.4371 6.69269 10.4002 6.64625 10.3538L5.14625 8.85375C5.05243 8.75993 4.99972 8.63268 4.99972 8.5C4.99972 8.36732 5.05243 8.24007 5.14625 8.14625C5.24007 8.05243 5.36732 7.99972 5.5 7.99972C5.63268 7.99972 5.75993 8.05243 5.85375 8.14625L7 9.29313L10.1462 6.14625C10.1927 6.09979 10.2479 6.06294 10.3086 6.0378C10.3692 6.01266 10.4343 5.99972 10.5 5.99972C10.5657 5.99972 10.6308 6.01266 10.6914 6.0378C10.7521 6.06294 10.8073 6.09979 10.8538 6.14625C10.9002 6.1927 10.9371 6.24786 10.9622 6.30855C10.9873 6.36925 11.0003 6.4343 11.0003 6.5C11.0003 6.5657 10.9873 6.63075 10.9622 6.69145C10.9371 6.75214 10.9002 6.8073 10.8538 6.85375Z" fill="#00672E"></path> </svg>
Verified Answer
</span> </div> </div> <div class="correct-answer">
The correct answer is:
<span class="option-value">$50 \mathrm{~cm}$</span> </div> <div class="solution">The correct option is (D).<br/>Concept: Meter bridge experiment is based on two facts:<br/>(1) the resistance across a wire is directly proportional to its length<br/>(2) balanced Wheatstone bridge has null deflection when the ratio of resistances is equal, and no current flows through the circuit.<br/>The current through galvanometre is zero, when the ratio of resistances, i.e., $\frac{P}{Q}=\frac{R}{S}$.<br/><img src="https://cdn-question-pool.getmarks.app/pyq/mht_cet/_iSWhLl7GrDftuuFr-CdkojqqqEkIq3sHBjDSr0lAGg.original.fullsize.png"/><br/>As given in the problem, $P=X, Q=Y, R \propto 20 \mathrm{~cm}$ and $S \propto 80 \mathrm{~cm}$.<br/>Therefore,<br/>$\frac{X}{Y}=\frac{20}{80}=\frac{1}{4}$<br/>Similarly, to balance a resistance $P=4 X$ against $Q=Y$, let us assume a length $l$ is required. Then, $R=l$<br/>$\frac{4 X}{Y}=\frac{l}{100-l}$<br/>On solving, we get $l=50 \mathrm{~cm}$.</div> </section> <!-- /Solution --> <!-- Call to Action --> <section class="call-to-action" data-pagefind-ignore=""> <div class="call-to-action-header"> <svg fill="none" height="24" viewbox="0 0 25 24" width="25" xmlns="http://www.w3.org/2000/svg"> <path d="M19.9999 13.5C20.0018 13.8058 19.9089 14.1047 19.734 14.3555C19.559 14.6063 19.3107 14.7968 19.023 14.9006L14.1874 16.6875L12.4062 21.5269C12.3007 21.8134 12.1098 22.0608 11.8594 22.2355C11.6089 22.4101 11.3109 22.5038 11.0055 22.5038C10.7002 22.5038 10.4022 22.4101 10.1517 22.2355C9.90124 22.0608 9.71039 21.8134 9.60491 21.5269L7.8124 16.6875L2.97303 14.9062C2.68646 14.8008 2.43915 14.6099 2.26445 14.3595C2.08976 14.109 1.99609 13.811 1.99609 13.5056C1.99609 13.2003 2.08976 12.9022 2.26445 12.6518C2.43915 12.4013 2.68646 12.2105 2.97303 12.105L7.8124 10.3125L9.59366 5.47313C9.69914 5.18656 9.88998 4.93924 10.1404 4.76455C10.3909 4.58985 10.6889 4.49619 10.9943 4.49619C11.2996 4.49619 11.5977 4.58985 11.8481 4.76455C12.0986 4.93924 12.2894 5.18656 12.3949 5.47313L14.1874 10.3125L19.0268 12.0938C19.3146 12.1986 19.5628 12.3901 19.7371 12.642C19.9114 12.8939 20.0033 13.1937 19.9999 13.5ZM14.7499 4.5H16.2499V6C16.2499 6.19891 16.3289 6.38968 16.4696 6.53033C16.6102 6.67098 16.801 6.75 16.9999 6.75C17.1988 6.75 17.3896 6.67098 17.5302 6.53033C17.6709 6.38968 17.7499 6.19891 17.7499 6V4.5H19.2499C19.4488 4.5 19.6396 4.42098 19.7802 4.28033C19.9209 4.13968 19.9999 3.94891 19.9999 3.75C19.9999 3.55109 19.9209 3.36032 19.7802 3.21967C19.6396 3.07902 19.4488 3 19.2499 3H17.7499V1.5C17.7499 1.30109 17.6709 1.11032 17.5302 0.96967C17.3896 0.829018 17.1988 0.75 16.9999 0.75C16.801 0.75 16.6102 0.829018 16.4696 0.96967C16.3289 1.11032 16.2499 1.30109 16.2499 1.5V3H14.7499C14.551 3 14.3602 3.07902 14.2196 3.21967C14.0789 3.36032 13.9999 3.55109 13.9999 3.75C13.9999 3.94891 14.0789 4.13968 14.2196 4.28033C14.3602 4.42098 14.551 4.5 14.7499 4.5ZM22.9999 7.5H22.2499V6.75C22.2499 6.55109 22.1709 6.36032 22.0302 6.21967C21.8896 6.07902 21.6988 6 21.4999 6C21.301 6 21.1102 6.07902 20.9696 6.21967C20.8289 6.36032 20.7499 6.55109 20.7499 6.75V7.5H19.9999C19.801 7.5 19.6102 7.57902 19.4696 7.71967C19.3289 7.86032 19.2499 8.05109 19.2499 8.25C19.2499 8.44891 19.3289 8.63968 19.4696 8.78033C19.6102 8.92098 19.801 9 19.9999 9H20.7499V9.75C20.7499 9.94891 20.8289 10.1397 20.9696 10.2803C21.1102 10.421 21.301 10.5 21.4999 10.5C21.6988 10.5 21.8896 10.421 22.0302 10.2803C22.1709 10.1397 22.2499 9.94891 22.2499 9.75V9H22.9999C23.1988 9 23.3896 8.92098 23.5302 8.78033C23.6709 8.63968 23.7499 8.44891 23.7499 8.25C23.7499 8.05109 23.6709 7.86032 23.5302 7.71967C23.3896 7.57902 23.1988 7.5 22.9999 7.5Z" fill="#1589EE"></path> </svg> <h3>Looking for more such questions to practice?</h3> </div> <p>
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options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$40 \mathrm{~cm}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$80 \mathrm{~cm}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$60 \mathrm{~cm}$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$50 \mathrm{~cm}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$50 \mathrm{~cm}$</span> </div>

answer:
<div class="solution">The correct option is (D).<br/>Concept: Meter bridge experiment is based on two facts:<br/>(1) the resistance across a wire is directly proportional to its length<br/>(2) balanced Wheatstone bridge has null deflection when the ratio of resistances is equal, and no current flows through the circuit.<br/>The current through galvanometre is zero, when the ratio of resistances, i.e., $\frac{P}{Q}=\frac{R}{S}$.<br/><img src="https://cdn-question-pool.getmarks.app/pyq/mht_cet/_iSWhLl7GrDftuuFr-CdkojqqqEkIq3sHBjDSr0lAGg.original.fullsize.png"/><br/>As given in the problem, $P=X, Q=Y, R \propto 20 \mathrm{~cm}$ and $S \propto 80 \mathrm{~cm}$.<br/>Therefore,<br/>$\frac{X}{Y}=\frac{20}{80}=\frac{1}{4}$<br/>Similarly, to balance a resistance $P=4 X$ against $Q=Y$, let us assume a length $l$ is required. Then, $R=l$<br/>$\frac{4 X}{Y}=\frac{l}{100-l}$<br/>On solving, we get $l=50 \mathrm{~cm}$.</div>


tags: ['Physics', 'Ray Optics', 'KCET', 'KCET 2017']
source_db: MarksBatch2_P1.db
title:
in-metre-bridge-experiment-with-a-standard-resistance-in-the-right-gap-and-a-resistance-coil-dipped-in-water-in-a-beaker-in-the-left-gap-the-balancing

slug:
in-metre-bridge-experiment-with-a-standard-resistance-in-the-right-gap-and-a-resistance-coil-dipped-in-water-in-a-beaker-in-the-left-gap-the-balancing-68720

question:
<div class="question">In metre bridge experiment, with a standard resistance in the right gap and a resistance coil<br/>dipped in water (in a beaker) in the left gap, the balancing length obtained is '1'. If the<br/>temperature of water is increased, the new balancing length is</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">\(&gt;l \)</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">\( &lt; l \)</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">\( =l \)</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">\( =0 \)</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">\(&gt;l \)</span> </div>

answer:
<div class="solution">Given, balancing length of bridge with standard resistance in right gap and a resistance coil dipped in water in left gap is<br/>\( I=1 \). If temperature of water is increased the new balancing length is greater than \( 1 \).<br/>Unknown resistance is calculated as \( X=R \frac{l}{(1-l)} \)<br/>If temperature increases then resistance increases. Thus, option (1) is correct.</div>


title: in-monocot-roots-which-types-of-vascular-bundles-are-found
slug: in-monocot-roots-which-types-of-vascular-bundles-are-found-83792
question: <div class="question">In monocot roots which types of vascular bundles are found?</div>
tags: ['Biology', 'Anatomy of Flowering Plants', 'JIPMER', 'JIPMER 2005']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Collateral, conjoint and closed</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">Radial with exarch xylem</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Bicollateral, conjoint and closed</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Radial with endarch xylem</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Radial with exarch xylem</span> </div>

answer:
<div class="solution">When xylem and phloem groups are located on different radii, the bundles are said to be radial e.g. root. The protoxylem element lie at the periphery and metaxylem in the centre, this condition is called exarch e.g. root.</div>


title: in-old-trees-the-central-darkcoloured-nonconducting-part-of-secondary-xylem-is-referred-to
slug: in-old-trees-the-central-darkcoloured-nonconducting-part-of-secondary-xylem-is-referred-to-44915
tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
question:
<div class="question">In old trees, the central dark-coloured, non-conducting part of secondary xylem is referred to</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">heartwood</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">sapwood</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">softwood</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">hardwood</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">heartwood</span> </div>

answer:
<div class="solution">Over time the centre of the innermost layers of the stem gets deposited with organic compounds like tannins, raisins, oils, gums and other aromatic substances. This deposition gives the secondary xylem a dark brownish colour and makes it durable and resistant to the microorganisms and insects. This dead inner wood with highly lignified walls is known as the hardwood. They are not involved in the conduction and transport of water but gives mechanical support to the stem. The sapwood is the outermost portion of the secondary xylem lighter in colour and involved in the conduction of water and minerals.</div>


tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET', 'NEET 2022 (Phase 1)']
source_db: MarksBatch2_P1.db
title:
in-old-trees-the-greater-part-of-secondary-xylem-is-dark-brown-and-resistant-to-insect-attack-due-to-a-secretion-of-secondary-metabolites-and-their-de

slug:
in-old-trees-the-greater-part-of-secondary-xylem-is-dark-brown-and-resistant-to-insect-attack-due-to-a-secretion-of-secondary-metabolites-and-their-de-93310

question:
<div class="question">In old trees the greater part of secondary xylem is dark brown and resistant to insect attack due to:<br/>(a) secretion of secondary metabolites and their deposition in the lumen of vessels.<br/>(b) deposition of organic compounds like tannins and resins in the central layers of stem.<br/>(c) deposition of suberin and aromatic substances in the outer layer of stem.<br/>(d) deposition of tannins, gum, resin and aromatic substances in the peripheral layers of stem.<br/>(e) presence of parenchyma cells, functionally active xylem elements and essential oils.<br/>Choose the correct answer from the options given below:</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">(c) and (d) Only</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">(d) and (e) Only</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">(b) and (d) Only</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">(a) and (b) Only</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">(a) and (b) Only</span> </div>

answer:
<div class="solution">In old trees, the greater part of secondary xylem is dark brown due to deposition of organic compounds like tannins, resins, oils, gums, aromatic substances and essential oils in the central or innermost layers of the stem. These substances make it hard, durable and resistant to the attacks of microorganisms and insects. This region comprises dead elements with highly lignified walls and is called heartwood.</div>


title: in-oppenauers-oxidation
slug: in-oppenauers-oxidation-20626
question: <div class="question">In Oppenauer's oxidation,</div>
tags: ['Chemistry', 'Aldehydes and Ketones', 'AIIMS', 'AIIMS 2009']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">secondary alcohol is oxidised to carboxylic acid in acetone solvent using aluminium tertiary butoxide</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">secondary alcohol is oxidised to carboxylic acid without affecting the $\mathrm{C}=\mathrm{C}$ or $\mathrm{C} \equiv \mathrm{C}$ bond by aluminium tertiary butoxide in acetone solvent</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">secondary alcohol is oxidised to ketone without affecting $\mathrm{C}=\mathrm{C}$ or $\mathrm{C} \equiv \mathrm{C}$ bond by aluminium tertiary butoxide</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">secondary alcohol is oxidised to ketone by chromic acid - pyridine complex.</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">secondary alcohol is oxidised to ketone without affecting $\mathrm{C}=\mathrm{C}$ or $\mathrm{C} \equiv \mathrm{C}$ bond by aluminium tertiary butoxide</span> </div>

answer:
<div class="solution">In Oppenauer's oxidation, secondary alcohol is oxidised to corresponding ketone in the presence of aluminium tertiary butoxide. Other oxidisable groups are not affected.<br/><img src="https://cdn-question-pool.getmarks.app/pyq/aiims/h_wHESG4nWEz1LnI5DJkPHok-kra4fOkc-1k-dBV10Y.original.fullsize.png"/><br/></div>


tags: ['Physics', 'Waves and Sound', 'AP EAMCET', 'AP EAMCET 2001']
source_db: MarksBatch2_P1.db
title:
in-order-to-double-the-frequency-of-the-fundamental-note-emitted-by-a-stretched-string-the-length-is-reduced-to-4-3-th-of-the-original-length-and-the--1

slug:
in-order-to-double-the-frequency-of-the-fundamental-note-emitted-by-a-stretched-string-the-length-is-reduced-to-4-3-th-of-the-original-length-and-the-1-80620

question:
<div class="question">In order to double the frequency of the fundamental note emitted by a stretched string, the length is reduced to $\frac{3}{4}$ th of the original length and the tension is changed. The factor by which the tension is to be changed is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{3}{8}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\frac{2}{3}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\frac{8}{9}$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$\frac{9}{4}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\frac{9}{4}$</span> </div>

answer:
<div class="solution">Frequency of stretched string.<br/>$\mathrm{n}=\frac{1}{2 l} \frac{\sqrt{T}}{m}$<br/>$\begin{aligned} &amp; n \propto \frac{\sqrt{T}}{l} \\ &amp; \frac{n_1}{n_2}=\frac{l_2}{I_1} \sqrt{\frac{T_1}{T_2}} \Rightarrow \frac{n}{2 n}=\frac{\frac{3}{4}}{l} \sqrt{\frac{T_1}{T_2}} \\ &amp; \frac{1}{2}=\frac{3}{4} \sqrt{\frac{T_1}{T_2}} \Rightarrow \sqrt{\frac{T_1}{T_2}}=\frac{2}{3} \\ &amp; \frac{T_1}{T_2}=\frac{4}{9} \Rightarrow T_2=\frac{9}{4} T_1\end{aligned}$<br/>$\therefore$ Tension should be changed by the factor $\frac{9}{4}$.</div>


tags: ['Physics', 'Waves and Sound', 'JEE Main']
source_db: MarksBatch2_P1.db
title:
in-order-to-double-the-frequency-of-the-fundamental-note-emitted-by-a-stretched-string-the-length-is-reduced-to-4-3-th-of-the-original-length-and-the--2

slug:
in-order-to-double-the-frequency-of-the-fundamental-note-emitted-by-a-stretched-string-the-length-is-reduced-to-4-3-th-of-the-original-length-and-the-2-20730

question:
<div class="question">In order to double the frequency of the fundamental note emitted by a stretched string, the length is reduced to $\frac{3}{4}$ th of the original length and the tension is changed. The factor by which the tension is to be changed is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{3}{8}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\frac{2}{3}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\frac{8}{9}$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$\frac{9}{4}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\frac{9}{4}$</span> </div>

answer:
<div class="solution">Frequency of stretched string.<br/>$\mathrm{n}=\frac{1}{2 l} \frac{\sqrt{T}}{m}$<br/>$\begin{aligned} &amp; n \propto \frac{\sqrt{T}}{l} \\ &amp; \frac{n_1}{n_2}=\frac{l_2}{I_1} \sqrt{\frac{T_1}{T_2}} \Rightarrow \frac{n}{2 n}=\frac{\frac{3}{4}}{l} \sqrt{\frac{T_1}{T_2}} \\ &amp; \frac{1}{2}=\frac{3}{4} \sqrt{\frac{T_1}{T_2}} \Rightarrow \sqrt{\frac{T_1}{T_2}}=\frac{2}{3} \\ &amp; \frac{T_1}{T_2}=\frac{4}{9} \Rightarrow T_2=\frac{9}{4} T_1\end{aligned}$<br/>$\therefore$ Tension should be changed by the factor $\frac{9}{4}$.</div>


tags: ['Physics', 'Waves and Sound', 'TS EAMCET', 'TS EAMCET 2001']
source_db: MarksBatch2_P1.db
title:
in-order-to-double-the-frequency-of-the-fundamental-note-emitted-by-a-stretched-string-the-length-is-reduced-to-4-3-th-of-the-original-length-and-the-

slug:
in-order-to-double-the-frequency-of-the-fundamental-note-emitted-by-a-stretched-string-the-length-is-reduced-to-4-3-th-of-the-original-length-and-the-85426

question:
<div class="question">In order to double the frequency of the fundamental note emitted by a stretched string, the length is reduced to $\frac{3}{4}$ th of the original length and the tension is changed. The factor by which the tension is to be changed is</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\frac{3}{8}$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\frac{2}{3}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$\frac{8}{9}$</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">$\frac{9}{4}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\frac{9}{4}$</span> </div>

answer:
<div class="solution">Frequency of stretched string.<br/>$\mathrm{n}=\frac{1}{2 l} \frac{\sqrt{T}}{m}$<br/>$\begin{aligned} &amp; n \propto \frac{\sqrt{T}}{l} \\ &amp; \frac{n_1}{n_2}=\frac{l_2}{I_1} \sqrt{\frac{T_1}{T_2}} \Rightarrow \frac{n}{2 n}=\frac{\frac{3}{4}}{l} \sqrt{\frac{T_1}{T_2}} \\ &amp; \frac{1}{2}=\frac{3}{4} \sqrt{\frac{T_1}{T_2}} \Rightarrow \sqrt{\frac{T_1}{T_2}}=\frac{2}{3} \\ &amp; \frac{T_1}{T_2}=\frac{4}{9} \Rightarrow T_2=\frac{9}{4} T_1\end{aligned}$<br/>$\therefore$ Tension should be changed by the factor $\frac{9}{4}$.</div>


tags: ['Biology', 'Microbes in Human Welfare', 'NEET']
source_db: MarksBatch2_P1.db
title:
in-oxidation-pond-once-bod-from-the-sewage-is-reduced-significantly-the-flocs-are-allowed-to-sediment-and-it-is-known-as

slug:
in-oxidation-pond-once-bod-from-the-sewage-is-reduced-significantly-the-flocs-are-allowed-to-sediment-and-it-is-known-as-14209

question:
<div class="question">In oxidation pond, once BOD from the sewage is reduced significantly, the 'flocs' are allowed to sediment and it is known as:</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">Activated sludge</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Inactivated sludge</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Primary sludge</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Secondary sludge</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Activated sludge</span> </div>

answer:
<div class="solution">Once BOD of sewage water is reduced significantly, the effluent is the passed into the setteling tank where the bacterial ' flocs' are allowed to sediment. This sediment is called as activated sludge.</div>


title: in-photosystemi-the-first-electron-acceptor-is
slug: in-photosystemi-the-first-electron-acceptor-is-97641
question: <div class="question">In photosystem-I, the first electron acceptor is:</div>
tags: ['Biology', 'Photosynthesis in Higher Plants', 'NEET', 'NEET 2006']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">an iron-sulphur protein</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">ferredoxin</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">cytochrome</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">plastocyanin</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">an iron-sulphur protein</span> </div>

answer:
<div class="solution">In photosystem I, the primary electron acceptor is probably a Fe-S protein. The reduced primary acceptor transfers the electrons to the secondary electron acceptor $\mathrm{P}_{430}$. The reduced $\mathrm{P}_{430}$ passes its electrons to ferredoxin $(\mathrm{Fd})$ present at the outer surface of the thylakoid membrane.<br/>Related Theory<br/>In light reaction of photosynthesis two types of photosystems are involved. PS-I consists of plenty of chlorophyll- $a$ and very less quantity of chlorophyll-b. These pigments absorb light energy and transfer it to the reaction centre - $P_{700}$ After absorbing adequate amount of light energy electron gets excited from $P_{700}$ molecule and moves to iron-sulphur protein complex, designated as $A$ (Fe-S). It gets reduced after accepting electrons. It later gives this electron to ferredoxin and gets oxidized again.<br/><img src="https://cdn-question-pool.getmarks.app/pyq/neet/ANK1dt8OPQTtllT3bbNMVj9lOa-6chPwE-LSA0XWXks.original.fullsize.png"/><br/></div>


tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
title:
in-plants-towards-the-centre-of-the-root-next-to-endodermis-lies-a-few-layers-of-thickwalled-parenchymatous-cells-referred-to-as

slug:
in-plants-towards-the-centre-of-the-root-next-to-endodermis-lies-a-few-layers-of-thickwalled-parenchymatous-cells-referred-to-as-29711

question:
<div class="question">In plants towards the centre of the root, next to endodermis lies a few layers of thick-walled parenchymatous cells referred to as</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">pith.</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">epidermis.</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">phloem.</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">pericycle.</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">pericycle.</span> </div>

answer:
<div class="solution">In the root of angiospermic plant, the tissue group adjacent to endodermis and towards the central part is called as pericycle. Pericycle generally is composed of parenchymatous cell and in the centre of it lies the pith which is mostly inconspicuous. Formation of lateral root and vascular cambium during the secondary growth occurs at this section.<br/><br/>Epidermis forms the outermost layer of the root having cells giving out root hair in some cells. Phloem is a type of complex vascular tissue which helps in transportation of food throughout the plant.</div>


tags: ['Mathematics', 'Quadratic Equation', 'NDA', 'NDA 2017 (Phase 2)']
source_db: MarksBatch2_P1.db
title:
in-pqr-r-2-if-than-2-1-and-2-q-are-the-roots-of-the-equation-a-x-2-b-x-c-0-then-which-one-of-the-following-is-correct

slug:
in-pqr-r-2-if-than-2-1-and-2-q-are-the-roots-of-the-equation-a-x-2-b-x-c-0-then-which-one-of-the-following-is-correct-44104

question:
<div class="question">In $\Delta \mathrm{PQR}, \angle \mathrm{R}=\frac{\pi}{2}$. If than $\left(\frac{1}{2}\right)$ and<br/>$\left(\frac{Q}{2}\right)$ are the roots of the equation $a x^{2}+b x+c=0$, then which one of the following is correct?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$a=b+c$</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$\mathrm{b}=\mathrm{c}+\mathrm{a}$</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">$\mathrm{c}=\mathrm{a}+\mathrm{b}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$\mathrm{b}=\mathrm{c}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$\mathrm{c}=\mathrm{a}+\mathrm{b}$</span> </div>

answer:
<div class="solution">$\angle \mathrm{R}=\frac{\pi}{2}$<br/><img src="https://cdn-question-pool.getmarks.app/pyq/nda/KoPzS0TYxJgZsyjjOaiXHJ5TNB7daOIFGZ9Bq8D2PPQ.original.fullsize.png"/><br/><br/>$\therefore \angle \mathrm{P}+\angle \mathrm{Q}=\frac{\pi}{2}$<br/>$\Rightarrow \frac{\angle \mathrm{P}+\angle \mathrm{Q}}{2}=\frac{\pi}{4}$...(1)<br/>$\tan \left(\frac{P}{2}+\frac{Q}{2}\right)=\frac{\tan \frac{P}{2}+\tan \frac{Q}{2}}{1-\tan \frac{P}{2} \tan \frac{Q}{2}}$...(2)<br/>Given, $\tan \frac{P}{2}$ and $\tan \frac{Q}{2}$ are roots of $a x^{2}+b x+c=0$. $\tan \frac{P}{2}+\tan \frac{Q}{2}=\frac{-b}{a} ; \tan \frac{P}{2} \cdot \tan \frac{Q}{2}=\frac{c}{a}$<br/>$(2) \Rightarrow \tan \left(\frac{\mathrm{P}}{2}+\frac{\mathrm{Q}}{2}\right)=\frac{\frac{-\mathrm{b}}{\mathrm{a}}}{1-\frac{\mathrm{c}}{\mathrm{a}}}$<br/>$\Rightarrow \tan \frac{\pi}{4}=\frac{\frac{-b}{a}}{1-\frac{c}{a}} \quad($ from $(1))$<br/>$\Rightarrow 1=\frac{-b}{a-c} \Rightarrow-b=a-c \Rightarrow a+b=c$<br/>$11-x+z^{2}=5$</div>


tags: ['Physics', 'Waves and Sound', 'MHT CET', 'MHT CET 2020 (20 Oct Shift 1)']
source_db: MarksBatch2_P1.db
title:
in-resonance-tube-of-length-08-m-air-column-vibrates-with-a-source-of-frequency-375-hz-for-a-certain-height-of-water-from-bottom-of-the-tube-water-lev

slug:
in-resonance-tube-of-length-08-m-air-column-vibrates-with-a-source-of-frequency-375-hz-for-a-certain-height-of-water-from-bottom-of-the-tube-water-lev-98411

question:
<div class="question">In resonance tube of length $0.8 \mathrm{~m}$, air column vibrates with a source of frequency<br/>$375 \mathrm{~Hz}$ for a certain height of water from bottom of the tube. Water level corresponding to fundamental frequency is (Neglect end correction, speed of sound in air = $330 \mathrm{~m} / \mathrm{s}$ )</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$0.45 \mathrm{~m}$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$0.58 \mathrm{~m}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$0.8 \mathrm{~m}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$0.65 \mathrm{~m}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$0.58 \mathrm{~m}$</span> </div>

answer:
<div class="solution">$\ell=0.8 \mathrm{~m} \quad \mathrm{f}=375 \mathrm{~Hz} \quad \mathrm{v}=330 \mathrm{~m}$<br/>$\mathrm{n}_{0}=\frac{\mathrm{v}}{4 \ell}=375$<br/>$\therefore \ell=\frac{330}{4 \times 375}=0.22 \mathrm{~m}$<br/>$\therefore \mathrm{L}-\ell=0.8-0.22 \mathrm{~m}=0.58 \mathrm{~m}$</div>


tags: ['Mathematics', 'Determinants', 'NDA', 'NDA 2006 (Phase 2)']
source_db: MarksBatch2_P1.db
title:
in-respect-of-the-equation-2-4-3-6-x-y-5-c-5-correctly-match-list-i-with-list-ii-and-select-the-correct-answer-using-the-code-given-below-the-lists

slug:
in-respect-of-the-equation-2-4-3-6-x-y-5-c-5-correctly-match-list-i-with-list-ii-and-select-the-correct-answer-using-the-code-given-below-the-lists-43886

question:
<div class="question">In respect of the equation<br/>$\left[\begin{array}{ll}<br/>2 &amp; 3 \\<br/>4 &amp; 6<br/>\end{array}\right]\left[\begin{array}{l}<br/>\mathrm{x} \\<br/>\mathrm{y}<br/>\end{array}\right]=\left[\begin{array}{c}<br/>5 \\<br/>\mathrm{c}-5<br/>\end{array}\right]$<br/>correctly match List I with List II and select the correct answer using the code given below the lists:<br/><img src="https://cdn-question-pool.getmarks.app/pyq/nda/fcnp2NHCmqgrav4jqTHfI9pVJhkn6FGRtwbdeQMkOGo.original.fullsize.png"/></div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$A-4 \quad B-2 \quad C-3$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$A-1 \quad B-1 \quad C-3$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$A-2 \quad B-2 \quad C-4$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$A-4 \quad B-1 \quad C-3$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$A-1 \quad B-1 \quad C-3$</span> </div>

answer:
<div class="solution">$\left[\begin{array}{ll}2 &amp; 3 \\ 4 &amp; 6\end{array}\right]\left[\begin{array}{l}x \\ y\end{array}\right]=\left[\begin{array}{l}5 \\ c-5\end{array}\right] \Rightarrow\left[\begin{array}{l}2 x+3 y \\ 4 x+6 y\end{array}\right]=\left[\begin{array}{l}5 \\ c-5\end{array}\right]$<br/>$\Rightarrow 2 x+3 y=5$ ...(1)<br/>and $4 x+6 y=c-5$ ...(2)<br/>$\Rightarrow$ Solving equation (1) and (2) $\mathrm{c}=15$ Now, if $\mathrm{c}=15$, equations 1 and 2 becomes $\Rightarrow 2 x+3 y=5$ and $4 x+6 y=10$<br/>This shows that the equation has an infinite set of solutions. For other values of $\mathrm{c}$, equation has no solution.</div>


title: in-secondary-proteins-hbonding-occurs-between
slug: in-secondary-proteins-hbonding-occurs-between-97865
tags: ['Chemistry', 'Biomolecules', 'NEET']
answer: <div class="solution">Correct Option is : 3 <br/> CO and NH</div>
source_db: MarksBatch2_P1.db
question:
<div class="question"><img src="https://cdn-question-pool.getmarks.app/modules/dbq/cheas77dtry/lw0IbX23DhjcnhFFSe8Q4WbPyJ9DNH4fob5qG3hkoHIQy2rm7l.png"/><br/><img src="https://cdn-question-pool.getmarks.app/modules/dbq/cheas77dtry/9LaHJUFBZpn5d4ABtlpZoroi4Tkg6Rqt0T3of9FTEsvxWWO2aC.png"/>In secondary proteins H-bonding occurs between :</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">CO and CO</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">NH and NH</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">CO and NH</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">None of these</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">CO and NH</span> </div>


title: in-situ-conservation-refers-to
slug: in-situ-conservation-refers-to-11062
question: <div class="question"><em>In situ</em> conservation refers to:</div>
tags: ['Biology', 'Biodiversity and its Conservation', 'NEET', 'NEET 2022 (Phase 1)']
source_db: MarksBatch2_P1.db
options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Conserve only high risk species</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Conserve only endangered species</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Conserve only extinct species</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">Protect and conserve the whole ecosystem</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Protect and conserve the whole ecosystem</span> </div>

answer:
<div class="solution"><p style="text-align: justify;">In the <em>in</em><em> situ</em> conservation, the protection of an organism will automatically take place, since the natural habitat of the organisms is protected in this sort of conservation. For example, announcing Kanha forest as a tiger reserve. It is nothing but conservation ‘at home’. This helps in conserving biodiversity hotspots. India has three of the world’s biodiversity hotspots, Western ghats, Indo Burma and Eastern-Himalayas.</p></div>


tags: ['Mathematics', 'Quadratic Equation', 'NDA', 'NDA 2015 (Phase 1)']
source_db: MarksBatch2_P1.db
title:
in-solving-a-problem-that-reduces-to-a-quadratic-equation-one-student-makes-a-mistake-in-the-constant-term-and-obtains-8-and-2-for-roots-another-stude

slug:
in-solving-a-problem-that-reduces-to-a-quadratic-equation-one-student-makes-a-mistake-in-the-constant-term-and-obtains-8-and-2-for-roots-another-stude-35696

question:
<div class="question">In solving a problem that reduces to a quadratic equation, one student makes a mistake in the constant term and obtains 8 and 2 for roots. Another student makes a mistake only in the coefficient of first-degree term and finds $-9$ and $-1$ for roots. The correct equation is</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">$x^{2}-10 x+9=0$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$x^{2}-10 x+9=0$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$x^{2}-10 x+16=0$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$x^{2}-8 x-9=0$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$x^{2}-10 x+9=0$</span> </div>

answer:
<div class="solution">Letcorrect equation is $a x^{2}+b x+c=0$ According to first student, equation is $a x^{2}+b x+c_{1}=0$ and roots are 8 and<br/>$8+2=\frac{-b}{a} \Rightarrow \frac{b}{a}=-10$<br/>Quadratic equation according to second student $a x^{2}+b_{1} x+c=0$ and roots are $-9$ and $-1$<br/>$(-9) \times(-1)=\frac{\mathrm{c}}{\mathrm{a}} \Rightarrow \frac{\mathrm{c}}{\mathrm{a}}=9$<br/>Putting value in original equation<br/>$x^{2}+\frac{b}{a} x+\frac{c}{a}=0$<br/>$x^{2}-10 x+9=0$</div>


title: in-spermatogenesis-reduction-division-of-chromosome-occurs-during-the-conversion-of
slug: in-spermatogenesis-reduction-division-of-chromosome-occurs-during-the-conversion-of-24091
tags: ['Biology', 'Human Reproduction', 'NEET']
source_db: MarksBatch2_P1.db
question:
<div class="question">In spermatogenesis reduction division of chromosome occurs during the conversion of</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">primary spermatocytes to secondary spermatocytes</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">spermatogonia to primary spermatocytes</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">spermatids to sperms</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">secondary spermatocytes to spermatids</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">primary spermatocytes to secondary spermatocytes</span> </div>

answer:
<div class="solution">The germ cells in the seminiferous tubules giving rise to the haploid spermatozoa are known as spermatogenesis. The three stages involved in this process are mitosis, meiosis, and spermiogenesis. The first step begins when the stem cells start multiplying and produce duplicate cells(spermatogonia). When these cells mature they are known as primary spermatocytes which undergo meiotic-I cell division to form secondary spermatocytes. </div>


tags: ['Physics', 'Wave Optics', 'JEE Main']
source_db: MarksBatch2_P1.db
title:
in-standard-youngs-doubleslit-experiment-visible-light-350-nm-750-nm-is-used-in-both-the-slits-distance-between-the-slits-is-2-mm-and-the-distance-of-

slug:
in-standard-youngs-doubleslit-experiment-visible-light-350-nm-750-nm-is-used-in-both-the-slits-distance-between-the-slits-is-2-mm-and-the-distance-of-30065

question:
<div class="question"><p>In standard Young's double-slit experiment, visible light <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">λ</mi><mo>∈</mo><mfenced><mrow><mn>350</mn><mo>nm</mo><mtext>, </mtext><mn>750</mn><mo>nm</mo></mrow></mfenced></math> is used in both the slits. Distance between the slits is <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>2</mn><mo> </mo><mi>mm</mi></math>, and the distance of the screen from the slits is <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>1</mn><mo> </mo><mi mathvariant="normal">m</mi></math>. A thin glass slab <math><mrow><mfenced close=")" open="(" separators=","><mrow><mi>μ</mi> <mo>=</mo> <mtext>1.5</mtext> </mrow> </mfenced> </mrow> </math> of thickness <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>6</mn><mo> </mo><mi mathvariant="normal">μ</mi><mtext>m</mtext></math> is placed in front of slit <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi mathvariant="normal">S</mi><mn>2</mn></msub></math>. Which among the following wavelengths is missing at point <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">P,</mi></math> which is directly in front of slit <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi mathvariant="normal">S</mi><mn>2</mn></msub></math>?(Neglect dispersion of light)<br/> <br/> <br/>
            <img alt="" src="https://cdn-question-pool.getmarks.app/nta_abhyas/jee_main/images/EM0068292.png" style="width: 230px; height: 145px;"/></p> </div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>400</mn><mo> </mo><mi>nm</mi></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>500</mn><mo> </mo><mi>nm</mi></math></span> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>600</mn><mo> </mo><mi>nm</mi></math></span> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>700</mn><mo> </mo><mi>nm</mi></math></span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>400</mn><mo> </mo><mi>nm</mi></math></span> </div>

answer:
<div class="solution">Net path difference <math><mrow><mo>=</mo> <mfenced close=")" open="(" separators=","> <mrow> <mi>Î¼</mi> <mo>-</mo> <mn>1</mn> </mrow> </mfenced> <mtext>t</mtext> <mo>-</mo> <mfrac> <mrow> <mtext>yd</mtext> </mrow> <mrow> <mtext>D</mtext> </mrow> </mfrac> </mrow> </math><br/><br/><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mfenced><mrow><mfrac><mn>3</mn><mn>2</mn></mfrac><mo>-</mo><mn>1</mn></mrow></mfenced><mn>6</mn><mo> </mo><mi mathvariant="normal">Î¼</mi><mtext>m</mtext><mo>-</mo><mfrac><mrow><mfenced><mrow><mtext>d</mtext><mo>/</mo><mn>2</mn></mrow></mfenced><mtext>d</mtext></mrow><mtext>D</mtext></mfrac><mo>=</mo><mn>1</mn><mo> </mo><mi mathvariant="normal">Î¼</mi><mtext>m</mtext></math><br/><br/>For Destructive interference<br/><br/><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>Î</mo><mtext>x</mtext><mo>=</mo><mn>1</mn><mo> </mo><mi mathvariant="normal">Î¼</mi><mtext>m</mtext><mo>=</mo><mfenced><mrow><mn>2</mn><mtext>n</mtext><mo>+</mo><mn>1</mn></mrow></mfenced><mfrac><mi mathvariant="normal">Î»</mi><mn>2</mn></mfrac><mo>â</mo><mi mathvariant="normal">Î»</mi><mo>=</mo><mfrac><mn>2</mn><mfenced><mrow><mn>2</mn><mtext>n</mtext><mo>+</mo><mn>1</mn></mrow></mfenced></mfrac><mo> </mo><mi mathvariant="normal">Î¼</mi><mtext>m</mtext></math><br/><br/><math> <mrow> <mi>Î»</mi> <mo>=</mo> <mfrac> <mrow> <mtext>2000 nm</mtext> </mrow> <mrow> <mfenced close=")" open="(" separators=","> <mrow> <mn>2</mn> <mo>+</mo> <mn>1</mn> </mrow> </mfenced> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mtext>2000</mtext> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> </mrow> </math>           <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>(</mo><mo> </mo><mi mathvariant="normal">n</mi><mo>=</mo><mn>1</mn><mo> </mo><mo>)</mo></math><br/><br/><math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">Î»</mi><mo>=</mo><mfrac><mtext>2000 nm</mtext><mfenced><mrow><mn>4</mn><mo>+</mo><mn>1</mn></mrow></mfenced></mfrac><mo>=</mo><mfrac><mtext>2000</mtext><mn>5</mn></mfrac><mtext>nm</mtext><mo>=</mo><mtext>400 nm</mtext></math>      <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>(</mo><mo> </mo><mi mathvariant="normal">n</mi><mo>=</mo><mn>2</mn><mo> </mo><mo>)</mo></math></div>


tags: ['Physics', 'Alternating Current', 'COMEDK', 'COMEDK 2020']
source_db: MarksBatch2_P1.db
title:
in-stcpup-transformer-relation-between-number-of-turns-in-primary-n-p-and-number-of-turns-in-secondary-n-s-coils-is

slug:
in-stcpup-transformer-relation-between-number-of-turns-in-primary-n-p-and-number-of-turns-in-secondary-n-s-coils-is-20949

question:
<div class="question">In stcp-up transformer, relation between number of turns in primary $\left(N_{P}\right)$ and number of turns in secondary $\left(N_{S}\right)$ coils is</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">$N_{S}$ is greater than $N_{P}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$N_{P}$ is greater than $N_{S}$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$N_{S}$ is equal to $N_{P}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$N_{P}=2 N_{S}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$N_{S}$ is greater than $N_{P}$</span> </div>

answer:
<div class="solution">In step-up transformer, number of turns in secondary coil is greater than the number of turns in the jxrimary coil.<br/>1.e. $\quad N_{g}&gt;N_{\mathrm{P}}$</div>


tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
title:
in-stems-the-protoxylem-lies-towards-the-center-pith-and-the-metaxylem-lies-towards-the-periphery-of-the-organ-this-type-of-primary-xylem-is-called

slug:
in-stems-the-protoxylem-lies-towards-the-center-pith-and-the-metaxylem-lies-towards-the-periphery-of-the-organ-this-type-of-primary-xylem-is-called-34475

question:
<div class="question">In stems, the protoxylem lies towards the center (pith) and the metaxylem lies towards the periphery of the organ. This type of primary xylem is called</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Exarch</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">Endarch</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Both (A) and (B)</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">None of these</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Endarch</span> </div>

answer:
<div class="solution">In stems, the protoxylem lies towards the centre (pith) and the metaxylem lies towards the periphery of the organ. This type of primary xylem is called endarch. In roots, the protoxylem lies towards periphery and metaxylem lies towards the centre. Such an arrangement of primary xylem is called exarch.</div>


tags: ['Biology', 'Anatomy of Flowering Plants', 'NEET']
source_db: MarksBatch2_P1.db
title:
in-temperate-regions-cambium-is-less-active-during-the-winter-season-and-forms-fewer-xylary-elements-that-have-narrow-vessels-this-wood-is-called

slug:
in-temperate-regions-cambium-is-less-active-during-the-winter-season-and-forms-fewer-xylary-elements-that-have-narrow-vessels-this-wood-is-called-69136

question:
<div class="question">In temperate regions, cambium is less active during the winter season and forms fewer xylary elements that have narrow vessels, this wood is called ____________.</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">early wood</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">late wood</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">heart wood</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">sapwood</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">late wood</span> </div>

answer:
<div class="solution">In the spring season, cambium is very active and produces a large number of xylary elements having vessels with wider cavities. The wood formed during this season is called spring wood or early wood. In winter, the cambium is less active and forms fewer xylary elements that have narrow vessels, and this wood is called autumn wood or late wood.<br/><br/>In old trees, the greater part of secondary xylem is dark brown due to deposition of organic compounds like tannins, resins, oils, gums, aromatic substances and essential oils in the central or innermost layers of the stem. These substances make it hard, durable and resistant to the attacks of microorganisms and insects. This region comprises dead elements with highly lignified walls and is called heartwood. The peripheral region of the secondary xylem, is lighter in colour and is known as the sapwood.</div>


tags: ['Mathematics', 'Sets and Relations', 'NDA', 'NDA 2017 (Phase 1)']
source_db: MarksBatch2_P1.db
title:
in-the-binary-equation-1-pl-01-2-10-ql-2-100-r-00-2-where-p-q-and-r-are-binary-digits-what-are-the-possible-values-of-p-q-and-r-respectively

slug:
in-the-binary-equation-1-pl-01-2-10-ql-2-100-r-00-2-where-p-q-and-r-are-binary-digits-what-are-the-possible-values-of-p-q-and-r-respectively-37670

question:
<div class="question">In the binary equation $(1 \mathrm{pl} 01)_{2}+(10 \mathrm{ql})_{2}=(100 \mathrm{r} 00)_{2}$<br/>where $\mathrm{p}, \mathrm{q}$ and $\mathrm{r}$ are binary digits, what are the possible values of $\mathrm{p}, \mathrm{q}$ and $\mathrm{r}$ respectively?</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">$0,1,0$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">$1,1,0$</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">0,0,1</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$1,0,1$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$0,1,0$</span> </div>

answer:
<div class="solution">$\quad(1 \mathrm{p} 101)_{2}+(10 \mathrm{q} 1)_{2}=(100 \mathrm{r} 00)_{2}$<br/>$\Rightarrow\left(1 \times 2^{4}+\mathrm{p} \times 2^{3}+1 \times 2^{2}+0 \times 2^{1}+1 \times 2^{0}\right)$<br/>$+\left(1 \times 2^{3}+0 \times 2^{2}+q \times 2^{1}+1 \times 2^{0}\right)$<br/>$=1 \times 2^{5}+0+0+\mathrm{r} \times 2^{2}+0+0$<br/>$\Rightarrow 16+8 \mathrm{p}+4+1+8+2 \mathrm{q}+1=32+4 \mathrm{r}$<br/>$\Rightarrow 30+8 p+2 q=32+4 r$<br/>$\Rightarrow 8 \mathrm{p}+2 \mathrm{q}=2+4 \mathrm{r}$<br/>from options, substitute $\mathrm{p}=0, \mathrm{q}=1, \mathrm{r}=0$ we get<br/>$0+2(1)=2+0 \Rightarrow 2=2$.</div>


tags: ['Biology', 'Microbes in Human Welfare', 'NEET']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">Flocs</span> </div>
source_db: MarksBatch2_P1.db
title:
in-the-biological-treatment-for-sewage-microbes-are-used-for-the-reduction-of-the-organic-matter-in-the-sewage-water-which-are-held-together-by-fungal

slug:
in-the-biological-treatment-for-sewage-microbes-are-used-for-the-reduction-of-the-organic-matter-in-the-sewage-water-which-are-held-together-by-fungal-21225

question:
<div class="question">In the biological treatment for sewage, microbes are used for the reduction of the organic matter in the sewage water which are held together by fungal filament to form mesh like structures. These are called as:</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Activated sludge</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Aerobic process</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">Flocs</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Anaerobic sludge</span> </li> </ul>

answer:
<div class="solution">In the wastewater treatment process, the primary effluent is passed into aeration tanks for the secondary treatment. This is also called as biological treatment. The aeration tanks are constantly agitated and the air is pumped; this allows for vigorous growth of aerobic microbes which help in the treatment. Such microbial growth is called flocs which form a mesh due to the association of fungal filaments with bacteria.</div>


tags: ['Chemistry', 'Amines', 'NEET']
source_db: MarksBatch2_P1.db
title:
in-the-carbylamine-test-why-do-foulsmelling-compounds-result-from-the-reaction-of-primary-amines-with-chloroform-and-ethanolic-potassium-hydroxide

slug:
in-the-carbylamine-test-why-do-foulsmelling-compounds-result-from-the-reaction-of-primary-amines-with-chloroform-and-ethanolic-potassium-hydroxide-18066

question:
<div class="question">In the carbylamine test, why do foul-smelling compounds result from the reaction of primary amines with chloroform and ethanolic potassium hydroxide?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Chloroform emits a foul odour when heated.</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">Potassium hydroxide produces a strong odour.</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">The isocyanide or carbylamine products are foul-smelling.</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Secondary amines produce foul-smelling compounds.</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">The isocyanide or carbylamine products are foul-smelling.</span> </div>

answer:
<div class="solution">The foul odour in the carbylamine test is due to the formation of isocyanides or carbylamines, which are inherently foul-smelling compounds.</div>


tags: ['Chemistry', 'Electrochemistry', 'JEE Main', 'JEE Main 2019 (10 Jan Shift 2)']
source_db: MarksBatch2_P1.db
title:
in-the-cell-pt-s-h-2-g-1-bar-hcl-aq-agcl-s-ag-s-pt-s-the-cell-potential-is-0-92-v-when-a-10-6-molar-hcl-solution-is-used-the-standard-electrode-potent

slug:
in-the-cell-pt-s-h-2-g-1-bar-hcl-aq-agcl-s-ag-s-pt-s-the-cell-potential-is-0-92-v-when-a-10-6-molar-hcl-solution-is-used-the-standard-electrode-potent-71828

question:
<div class="question">In the cell, <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>Pt</mi><mfenced separators="|"><mi mathvariant="normal">s</mi></mfenced><mfenced close="|" open="|" separators="|"><mrow><msub><mi mathvariant="normal">H</mi><mn>2</mn></msub><mfenced separators="|"><mrow><mi mathvariant="normal">g</mi><mo>,</mo><mi mathvariant="normal"> </mi><mn>1</mn><mi>bar</mi></mrow></mfenced></mrow></mfenced><mi mathvariant="normal"> </mi><mi>HCl</mi><mi mathvariant="normal"> </mi><mfenced separators="|"><mi>aq</mi></mfenced><mfenced close="|" open="|" separators="|"><mrow><mi>AgCl</mi><mfenced separators="|"><mi mathvariant="normal">s</mi></mfenced></mrow></mfenced><mi>Ag</mi><mfenced separators="|"><mi mathvariant="normal">s</mi></mfenced><mfenced close="" open="|" separators="|"><mrow><mi>Pt</mi><mfenced separators="|"><mi mathvariant="normal">s</mi></mfenced><mo>,</mo></mrow></mfenced></math>the cell potential is <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.92</mo><mi mathvariant="normal"> </mi><mi mathvariant="normal">V</mi></math> when a <math><msup><mrow><mn>10</mn></mrow><mrow><mo>-</mo><mn>6</mn></mrow></msup></math> molar <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>HCl</mi></math> solution is used. The standard electrode potential of <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>Ag</mi><mo>|</mo><mi>AgCl</mi><mo>|</mo><msup><mi>Cl</mi><mo>-</mo></msup></math> electrode is:<br/><br/>(Given, <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>2</mn><mo>.303</mo><mi>RT</mi></mrow><mi mathvariant="normal">F</mi></mfrac><mo>=</mo><mn>0</mn><mo>.06</mo><mi mathvariant="normal"> </mi><mi mathvariant="normal">V</mi></math> at <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>298</mn><mi mathvariant="normal"> </mi><mi mathvariant="normal">K</mi></math>)</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.76</mo><mi mathvariant="normal"> </mi><mi mathvariant="normal">V</mi></math></span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.20</mo><mi mathvariant="normal"> </mi><mi mathvariant="normal">V</mi></math></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.40</mo><mi mathvariant="normal"> </mi><mi mathvariant="normal">V</mi></math></span> </li><li class=""> <span class="option-label">D</span> <span class="option-data"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.94</mo><mi mathvariant="normal"> </mi><mi mathvariant="normal">V</mi></math></span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value"><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.20</mo><mi mathvariant="normal"> </mi><mi mathvariant="normal">V</mi></math></span> </div>

answer:
<div class="solution"><blockquote><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">A</mi><mo>:</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><msub><mi mathvariant="normal">H</mi><mn>2</mn></msub><mfenced separators="|"><mi mathvariant="normal">g</mi></mfenced><mo>→</mo><msup><mi mathvariant="normal">H</mi><mo>+</mo></msup><mi mathvariant="normal"> </mi><mfenced separators="|"><mrow><mi>aq</mi><mo>.</mo></mrow></mfenced><mo>+</mo><msup><mi mathvariant="normal">e</mi><mo>-</mo></msup><mo>;</mo><mo> </mo><msup><mi mathvariant="normal">E</mi><mi mathvariant="normal">o</mi></msup><mo>=</mo><mn>0</mn><mo>.0</mo><mi mathvariant="normal"> </mi><mi mathvariant="normal">V</mi></math><br/><math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">C</mi><mi mathvariant="normal"> </mi><mo>:</mo><mi>AgCl</mi><mi mathvariant="normal"> </mi><mfenced separators="|"><mi mathvariant="normal">s</mi></mfenced><mo>+</mo><msup><mi mathvariant="normal">e</mi><mo>-</mo></msup><mo>→</mo><mi>Ag</mi><mi mathvariant="normal"> </mi><mfenced separators="|"><mi mathvariant="normal">s</mi></mfenced><mo>+</mo><msup><mi>Cl</mi><mo>-</mo></msup><mo>;</mo><mo> </mo><msup><mi mathvariant="normal">E</mi><mi mathvariant="normal">o</mi></msup><mo>=</mo><mi>xV</mi></math><br/><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi mathvariant="normal">E</mi><mi>cell</mi></msub><mo>=</mo><msubsup><mi mathvariant="normal">E</mi><mi>cell</mi><mi mathvariant="normal">o</mi></msubsup><mo>-</mo><mfrac><mrow><mn>0</mn><mo>.06</mo></mrow><mn>1</mn></mfrac><mi>log</mi><mo>⁡</mo><mfenced close="}" open="{" separators="|"><mrow><mfenced close="]" open="[" separators="|"><msup><mi mathvariant="normal">H</mi><mo>+</mo></msup></mfenced><mfenced close="]" open="[" separators="|"><msup><mi>Cl</mi><mo>-</mo></msup></mfenced></mrow></mfenced></math><br/><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.92</mo><mo>=</mo><mi mathvariant="normal">x</mi><mo>-</mo><mfrac><mrow><mn>0</mn><mo>.</mo><mn>06</mn></mrow><mn>1</mn></mfrac><mi>log</mi><mo>⁡</mo><mfenced separators="|"><msup><mn>10</mn><mrow><mo>-</mo><mn>12</mn></mrow></msup></mfenced></math><br/><math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn><mo>.92</mo><mo>=</mo><mi mathvariant="normal">x</mi><mo>+</mo><mn>0</mn><mo>.</mo><mn>72</mn></math><br/><math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">x</mi><mo>=</mo><mn>0</mn><mo>.92</mo><mo>-</mo><mn>0</mn><mo>.72</mo></math><br/><math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mn>0</mn><mo>.</mo><mn>2</mn><mi mathvariant="normal">V</mi></math></p></blockquote></div>


title: in-the-coaxial-system-of-circle-x-2-y-2-2-gx-c-0-where-g-is-a-parameter-if-c-0-then-the-circles-are
tags: ['Mathematics', 'Circle', 'JEE Main']
source_db: MarksBatch2_P1.db
slug:
in-the-coaxial-system-of-circle-x-2-y-2-2-gx-c-0-where-g-is-a-parameter-if-c-0-then-the-circles-are-92605

question:
<div class="question">In the co-axial system of circle $x^2+y^2+2 g x+c=0$, where $g$ is a parameter, if $c\gt0$ then the circles are</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">Orthogonal</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">Touching type</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">Intersecting type</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">Non-intersecting type</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">Touching type</span> </div>

answer:
<div class="solution">Given, equation of the circle $x^2+y^2+2 g x+c=0$, where $c$ is constant and $g$ represents the parameter of a coaxial system and $c\gt0$. We know that the standard equation of a circle is $x^2+y^2+2 g x+2 f y+c=0$. Comparing the given equation with the standard equation, we get centre $\equiv(-g, 0)$ and radius $\sqrt{g^2-c}$. Therefore radius becomes zero, when $g^2-c=0$ or $g= \pm \sqrt{c}$. Therefore $(\sqrt{c}, 0)$ and $(-\sqrt{c}, 0)$ are the limiting points of the coaxial system of circles. Since $c\gt0$, therefore $\sqrt{c}$ is real and limiting points are real and distinct. Thus the co-axial system is said to be touching type.</div>


tags: ['Chemistry', 'Coordination Compounds', 'NEET']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">5, 6</span> </div>
source_db: MarksBatch2_P1.db
title:
in-the-complex-potassium-pentacyanonitrosylvandate-0-the-number-of-potassium-atoms-per-molecule-and-the-coordination-number-of-central-metal-ion-are-r

slug:
in-the-complex-potassium-pentacyanonitrosylvandate-0-the-number-of-potassium-atoms-per-molecule-and-the-coordination-number-of-central-metal-ion-are-r-34814

question:
<div class="question">In the complex, potassium pentacyanonitrosylvandate (0), the number of potassium atoms per molecule and the coordination number of central metal ion are respectively</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">5, 5</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">4, 6</span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data">5, 6</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">D</span> <span class="option-data">4, 4</span> </li> </ul>

answer:
<div class="solution">Here in the complex, potassium pentacyanonitrosylvandate (0), the number of potassium atoms per molecule and the coordination number of central metal ion are 5, 6 respectively as oxidation number of V in this complex is '0' thus the charge on pentacyanonitrosylvandate is -5. Thus formula of the complex is <math><msub><mrow><mi mathvariant="normal">K</mi></mrow><mrow><mn>5</mn></mrow></msub><mo>[</mo><mi mathvariant="normal">V</mi><mo>(</mo><mi mathvariant="normal">C</mi><mi mathvariant="normal">N</mi><msub><mrow><mo>)</mo></mrow><mrow><mn>5</mn></mrow></msub><mi mathvariant="normal">N</mi><mi mathvariant="normal">O</mi><mo>]</mo></math> .<br/> </div>


title: in-the-context-of-a-chemical-reaction-in-a-beaker-what-is-considered-the-system
slug: in-the-context-of-a-chemical-reaction-in-a-beaker-what-is-considered-the-system-11361
tags: ['Chemistry', 'Thermodynamics (C)', 'NEET']
source_db: MarksBatch2_P1.db
question:
<div class="question">In the context of a chemical reaction in a beaker, what is considered the "system"?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">The room where the beaker is kept</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">The reaction mixture inside the beaker</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">The boundary that separates the beaker from the surroundings</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">The beaker itself</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">The reaction mixture inside the beaker</span> </div>

answer:
<div class="solution">In this scenario, the system is defined as the beaker containing the reaction mixture.</div>


tags: ['Chemistry', 'p Block Elements (Group 13 & 14)', 'KCET', 'KCET 2017']
source_db: MarksBatch2_P1.db
title:
in-the-electrolysis-of-aqueous-sodium-chloride-solution-which-of-the-half-cell-reaction-will-occur-at-anode

slug:
in-the-electrolysis-of-aqueous-sodium-chloride-solution-which-of-the-half-cell-reaction-will-occur-at-anode-82215

question:
<div class="question">In the electrolysis of aqueous sodium chloride solution, which of the half cell reaction will occur<br/>at anode?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">\( N a^{+}(a q)+e^{-} \rightarrow N a(s) ; E_{\text {cell }}^{\circ}=-2.71 \) volts</span> </li><li class=""> <span class="option-label">B</span> <span class="option-data">\( 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{O}_{2}+4 \mathrm{H}^{+}+4 e^{-} ; \mathrm{E}_{\text {cell }}^{\circ}=1.23 \) \$volts</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">\( H^{+}(a q)+e^{-} \rightarrow \frac{1}{2} H_{2} ; E_{\text {cell }}^{\circ}=0.00 \) volts</span> </li><li class="correct"> <span class="option-label">D</span> <span class="option-data">\( \mathrm{Cl}^{-}(a q) \rightarrow \frac{1}{2} \mathrm{Cl}_{2}+e^{-} ; E_{\text {cell }}^{\circ}=1.36 \) volts</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">\( \mathrm{Cl}^{-}(a q) \rightarrow \frac{1}{2} \mathrm{Cl}_{2}+e^{-} ; E_{\text {cell }}^{\circ}=1.36 \) volts</span> </div>

answer:
<div class="solution">In water sodium chloride ionizes as<br/>\( N a C l(a q) \rightleftharpoons N a^{+}(a q)+C l^{-}(a q) \)<br/>water also dissociates into ions, though to very slight degree as,<br/>\( \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{OH}^{-}(a q) \)<br/>Thus, the aqueous solution of sodium chloride contains \( \mathrm{N} a^{+}, \mathrm{H}^{+}, \mathrm{OH}^{-} \)and \( \mathrm{Cl}^{-} \)ions. When electric current is passed<br/>through the solution, \( \mathrm{Cl}_{2} \) gas evolved at anode and hydrogen is evolved at the cathode. The resulting solution contains<br/>\( \mathrm{Na}^{+} \)and \( \mathrm{OH}^{-} \)ions. Oxidation of \( \mathrm{Cl}^{-} \)ions and \( \mathrm{H}_{2} \mathrm{O} \) is possible at anode but, standard electrode potential of \( \mathrm{Cl}^{-} \)is<br/>more, therefore, \( \mathrm{Cl}^{-} \)will oxidized at anode.</div>


tags: ['Mathematics', 'Binomial Theorem', 'NDA', 'NDA 2019 (Phase 1)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">9</span> </div>
source_db: MarksBatch2_P1.db
title:
in-the-expansion-of-1-a-x-n-the-urst-three-terms-are-respectively-1-12-x-and-64-x-2-what-is-n-equal-to

slug:
in-the-expansion-of-1-a-x-n-the-urst-three-terms-are-respectively-1-12-x-and-64-x-2-what-is-n-equal-to-21878

question:
<div class="question">In the expansion of $(1+a x)^{n}$, the urst three terms are respectively 1, $12 \mathrm{x}$ and $64 \mathrm{x}^{2}$. What is n equal to?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">6</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">9</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">10</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">12</span> </li> </ul>

answer:
<div class="solution">The first three terms in expansion of $(1+\mathrm{ax})^{\mathrm{n}}$ are ${ }^{\mathrm{n}} \mathrm{C}_{0},{ }^{\mathrm{n}} \mathrm{C}_{1} \mathrm{ax},{ }^{\mathrm{n}} \mathrm{C}_{2} \mathrm{a}^{2} \mathrm{x}^{2}$<br/>Given, ${ }^{1} \mathrm{C}_{0}=1 ;{ }^{\mathrm{n}} \mathrm{C}_{1} \mathrm{ax}=12 \mathrm{x} ;{ }^{\mathrm{n}} \mathrm{C}_{2} \mathrm{a}^{2} \mathrm{x}^{2}=64 \mathrm{x}^{2}$<br/>$\Rightarrow \operatorname{nax}=12 \mathrm{x} ; \frac{n(n-1)}{2} a^{2}=64$<br/>$\Rightarrow \mathrm{na}=12 \Rightarrow a=\frac{12}{n}$<br/>$\therefore \frac{n(n-1)}{2} a^{2}=64 \Rightarrow \frac{n(n-1)}{2} \times \frac{144}{n^{2}}=64$<br/>$\Rightarrow \frac{n-1}{n}=\frac{64 \times 2}{144}=\frac{8}{9}$<br/>$\therefore \mathrm{n}=9$</div>


tags: ['Mathematics', 'Binomial Theorem', 'NDA', 'NDA 2018 (Phase 1)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">14</span> </div>
source_db: MarksBatch2_P1.db
title:
in-the-expansion-of-1-x-43-if-the-coefficients-of-2-r-1-th-and-r-2-th-terms-are-equal-then-what-is-the-value-of-r-r-1

slug:
in-the-expansion-of-1-x-43-if-the-coefficients-of-2-r-1-th-and-r-2-th-terms-are-equal-then-what-is-the-value-of-r-r-1-78560

question:
<div class="question">In the expansion of $(1+\mathrm{x})^{43}$, if the coefficients of $(2 \mathrm{r}+1)^{\text {th }}$ and $(\mathrm{r}+2)^{\text {th }}$ terms are equal, then what is the value of $\mathrm{r}(\mathrm{r} \neq 1)$ ?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">5</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">14</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">21</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">22</span> </li> </ul>

answer:
<div class="solution">Given, in the expansion $\mathrm{g}(1+\mathrm{x})^{43}$, coefficients of $(2 \mathrm{r}+1)^{\text {th }}$ term and $(\mathrm{r}+2)^{\mathrm{th}}$ term are equal.<br/>Coefficient of $(2 \mathrm{r}+1)^{\text {th }}$ term $=\mathrm{n}_{\mathrm{C}_{2 \mathrm{r}}}$<br/>Coefficient of $(\mathrm{r}+2)^{\text {th }}$ term $=\mathrm{n}_{\mathrm{C}_{\mathrm{r}+1}}$<br/>$\mathrm{n}_{\mathrm{C}_{2 \mathrm{r}}}=\mathrm{n}_{\mathrm{C}_{\mathrm{r}+1}}$<br/>$\Rightarrow 43_{\mathrm{C}_{2 \mathrm{r}}}=43_{\mathrm{C}_{\mathrm{r}+1}}$<br/>$(\because \mathrm{n}=43)$<br/>$\Rightarrow 2 \mathrm{r}+\mathrm{r}+1=43$<br/>$\Rightarrow 3 r+1=43$<br/>$\Rightarrow 3 \mathrm{r}+42 \Rightarrow \mathrm{r}=14$</div>


title: in-the-expansion-of-1-x-50-the-sum-of-the-coefficients-of-odd-powers-of-x-is
slug: in-the-expansion-of-1-x-50-the-sum-of-the-coefficients-of-odd-powers-of-x-is-36887
tags: ['Mathematics', 'Binomial Theorem', 'NDA', 'NDA 2017 (Phase 2)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In the expansion of $(1+x)^{50}$, the sum of the coefficients of $\begin{array}{ll}\text { odd powers of } \mathrm{x} \text { is } &amp; \end{array}$</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$2^{26}$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$2^{49}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$2^{50}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">$2^{51}$</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$2^{49}$</span> </div>

answer:
<div class="solution">Sum of odd terms of expansion $(\mathrm{a}+\mathrm{b})^{\mathrm{n}}$ is $\frac{1}{2} \cdot 2^{\mathrm{n}}$.<br/>$\therefore$ Sum of odd terms of expansion $(1+\mathrm{x})^{50}$ is $\frac{1}{2} \cdot 2^{50}$<br/>$=2^{-1} .2^{50}=2^{49}$</div>


title: in-the-expansion-of-1-x-n-what-is-the-sum-of-even-binomial-coefficients
slug: in-the-expansion-of-1-x-n-what-is-the-sum-of-even-binomial-coefficients-40694
tags: ['Mathematics', 'Binomial Theorem', 'NDA', 'NDA 2012 (Phase 1)']
source_db: MarksBatch2_P1.db
question:
<div class="question">In the expansion of $[1+\mathrm{x}]^{\mathrm{n}}$, what is the sum of even binomial coefficients?</div>

options:
<ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$2^{\mathrm{n}}$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$2^{n-1}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">C</span> <span class="option-data">$2^{n+1}$</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">None of the above</span> </li> </ul>

correct_option:
<div class="correct-answer">
The correct answer is:
<span class="option-value">$2^{n-1}$</span> </div>

answer:
<div class="solution">Sum of all binomial coefficients $=(1+1)^{\mathrm{n}}=2^{\mathrm{n}}$<br/>$\therefore$ Sum of even binomial coefficient $=\frac{2^{\mathrm{n}}}{2}=2^{\mathrm{n}-1}$</div>


title: in-the-expansion-of-x-3-x-2-1-10-the-value-of-constant-term-independent-of-x-is-2015-ii
slug: in-the-expansion-of-x-3-x-2-1-10-the-value-of-constant-term-independent-of-x-is-2015-ii-11322
tags: ['Mathematics', 'Binomial Theorem', 'NDA', 'NDA 2015 (Phase 2)']
correct_option: <div class="correct-answer"> The correct answer is: <span class="option-value">5</span> </div>
source_db: MarksBatch2_P1.db
question:
<div class="question">In the expansion of $\left(\sqrt{\mathrm{x}}+\frac{1}{3 \mathrm{x}^{2}}\right)^{10}$ the value of constant term (independent of $\mathrm{x}$ ) is $[2015-I I]$</div>

options:
<ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">5</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6.48726 2.99218 8.26884C2.25422 10.0504 2.06114 12.0108 2.43735 13.9021C2.81355 15.7934 3.74215 17.5307 5.10571 18.8943C6.46928 20.2579 8.20656 21.1865 10.0979 21.5627C11.9892 21.9389 13.9496 21.7458 15.7312 21.0078C17.5127 20.2699 19.0355 19.0202 20.1068 17.4168C21.1782 15.8134 21.75 13.9284 21.75 12C21.7473 9.41498 20.7192 6.93661 18.8913 5.10872C17.0634 3.28084 14.585 2.25273 12 2.25ZM16.2806 10.2806L11.0306 15.5306C10.961 15.6004 10.8783 15.6557 10.7872 15.6934C10.6962 15.7312 10.5986 15.7506 10.5 15.7506C10.4014 15.7506 10.3038 15.7312 10.2128 15.6934C10.1218 15.6557 10.039 15.6004 9.96938 15.5306L7.71938 13.2806C7.57865 13.1399 7.49959 12.949 7.49959 12.75C7.49959 12.551 7.57865 12.3601 7.71938 12.2194C7.86011 12.0786 8.05098 11.9996 8.25 11.9996C8.44903 11.9996 8.6399 12.0786 8.78063 12.2194L10.5 13.9397L15.2194 9.21937C15.2891 9.14969 15.3718 9.09442 15.4628 9.0567C15.5539 9.01899 15.6515 8.99958 15.75 8.99958C15.8486 8.99958 15.9461 9.01899 16.0372 9.0567C16.1282 9.09442 16.2109 9.14969 16.2806 9.21937C16.3503 9.28906 16.4056 9.37178 16.4433 9.46283C16.481 9.55387 16.5004 9.65145 16.5004 9.75C16.5004 9.84855 16.481 9.94613 16.4433 10.0372C16.4056 10.1282 16.3503 10.2109 16.2806 10.2806Z" fill="#24A865"></path> </svg> </li><li class=""> <span class="option-label">B</span> <span class="option-data">8</span> </li><li class=""> <span class="option-label">C</span> <span class="option-data">45</span> </li><li class=""> <span class="option-label">D</span> <span class="option-data">90</span> </li> </ul>

answer:
<div class="solution">Let $\mathrm{r}^{\text {th }}$ term is independent of $\mathrm{x}$. $\mathrm{T}_{\mathrm{r}}={ }^{\mathrm{n}} \mathrm{C}_{\mathrm{r}} \mathrm{x}^{\mathrm{r}} \mathrm{y}^{\mathrm{n}-\mathrm{r}}$<br/>$={ }^{10} \mathrm{C}_{\mathrm{r}}(\sqrt{\mathrm{x}})^{\mathrm{r}}\left(\frac{1}{3 \mathrm{x}^{2}}\right)^{10-\mathrm{r}}$<br/>$={ }^{10} \mathrm{C}_{\mathrm{r}}\left(\frac{1}{3}\right)^{10-\mathrm{r}} \cdot(\sqrt{\mathrm{x}})^{\mathrm{r}}\left(\frac{1}{\mathrm{x}^{2}}\right)^{10-\mathrm{r}}$<br/>Equating the coefficient of $\mathrm{x}$ to zero. $\Rightarrow \mathrm{x}^{\mathrm{r} / 2} \cdot \mathrm{x}^{-2(10-\mathrm{r})}=\mathrm{x}^{0}$<br/>$\Rightarrow \quad \frac{\mathrm{r}}{2}-20+2 \mathrm{r}=0$<br/>$\Rightarrow \quad \frac{5}{2} r=20 \Rightarrow r=8$<br/>Coefficient $={ }^{10} C_{r}\left(\frac{1}{3}\right)^{10-r}$<br/>$={ }^{10} \mathrm{C}_{8}\left(\frac{1}{3}\right)^{10-8}=\frac{10 \times 9}{2} \times \frac{1}{9}=5$</div>


