What is Bismuth(V) fluoride?
'''Bismuth(V) fluoride''', also known as '''bismuth pentafluoride''', is a [[chemical compound]]. Its [[chemical formula]] is BiF<sub>5</sub>. It has five [[bismuth]]-[[fluorine]] [[chemical bond|bond]]s in it. The bismuth is in its +5 [[oxidation state]]. ==Properties== Bismuth(V) fluoride is a white [[crystalline]] [[solid]]. It is an extremely strong [[oxidizing agent]] and fluorinating agent, something that adds fluoride ions to other chemicals. It reacts with water to make [[ozone]] and [[oxygen difluoride]]. It also reacts with [[iodine]] and [[sulfur]] at [[room temperature]]. Above 50°C, it reacts with [[hydrocarbon]]s like [[paraffin]] to make fluorocarbons. At 180°C, it reacts with chlorine to make [[chlorine monofluoride]] and with bromine to make [[bromine trifluoride]]. ==Preparation== It is made by reacting [[bismuth(III) fluoride]] with [[fluorine]] at a high temperature. It is also made by reacting bismuth(III) fluoride with [[chlorine trifluoride]]. ==Uses== It is used as a fluorinating agent. ==Related pages== *[[Bismuth(V) oxide]] *[[Bismuth(III) chloride]] *[[Bismuth(III) oxide]] [[Category:Bismuth compounds]] [[Category:Fluorine compounds]] {{Fluorine compounds}}