text: Question
  Sat March 17, 2012 By:
  
  # Divide 243 into 3 parts such that half of the first part,one-third of the second part and one-fourth of the third part are all equal.
  
  Sat March 17, 2012
  let the numbers be x, y , z
  So 1/2 x = 1/3 y = 1/4 z = k
  
  x = 2k , y = 3k , z = 4k
  Also,
  x+y+z = 243
  2k+3k+4k = 243
  9k = 243
  k = 27
  So numbers are x = 54 , y = 81 , z = 108
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