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  # XXXVII, CXXXIX, XXIX, XXVI, LXXX, XL, XI Roman Numerals In Numbers
  
  I will be solving some Roman Numerals examples in this article. Roman numerals are the numbers that were used in ancient Rome, which are in base ten and comprise of Latin alphabet (I, V, X, L, C, D and M)
  
  ## Basic Roman Numerals Rule
  
  • If a bigger letter precedes or comes before a smaller letter, the letters are added. For example: VI = 5 +1 = 6, X1 = 10 + 1= 11, LX = 50 + 10 = 60
  • If a smaller letter precedes a bigger letter, the letters are subtracted. For example IV = 5 -1 = 4, IX = 10 – 1= 9, XL = 50- 10 = 40
  • If a letter is repeated 2 or 3 times, they are added. For example: CCC = C + C + C = 100 + 100 + 100 = 300
  • The same letter cannot be used more than three times in succession.
  
  ## XXXVII, CXXXIX, XXIX, XXVI, LXXX, XL, XI Roman Numerals
  
  ### XXXVII Roman Numeral in Number
  
  XXXVII = X + X + X + VII (note X is 10 and VII is 7)
  
  XXXVII = 10 + 10 + 10 + 7 = 37
  
  ### CXXXIX Roman Numeral in Number
  
  CXXXIX = C + X + X + X + IX (note C is 100 and IX is 9)
  
  The reason why I put IX together is because a smaller number comes before a bigger number
  
  And IX = 10 – 1 = 9
  
  CXXXIX = 100 + 10 + 10 + 10 + 9 = 139
  
  ### XXIX Roman Numeral in Number
  
  XXIX = X + X + IX = 10 + 10 + 9 = 29
  
  ### XXVI Roman Numeral in Number
  
  XXVI = X + X + V + I (X is 10, V is 5, and I is 1)
  
  XXVI = 10 + 10 + 5 + 1 = 26
  
  ### LXXX Roman Numeral in Number
  
  LXXX = L + X + X + X (note L is 50)
  
  LXXX = 50 + 10 + 10 + 10 = 80
  
  ### XL Roman Numeral in Number
  
  In this case, a smaller number comes before a bigger number. This implies that we are going to subtract the smaller number from the bigger number.
  
  XL = 50 – 10 = 40
  
  ### XI Roman Numeral in Number
  
  XI = X + I = 10 + 1 = 11
  
  Conclusively, I will make a table to represent the values of all the roman numerals I have discussed.
  
  If you have any questions that you will like me to solve on the above topic, kindly drop a comment in the box below.
  
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