text: Anonymous
  Anonymous asked in Computers & InternetProgramming & Design · 8 months ago
  
  # math problem?
  
  Relevance
  • 8 months ago
  
  First step is to find S6.
  
  We do that by computing S1 through S5.
  
  We have S1 = S0. So S1 = {0}
  
  Then S2 = S1 U S2 = {0} U {0} = {0}
  
  Knowing S1 and S2 it is analogous that any Sn = {0}
  
  Therefore S6 = {0}
  
  Now what is a power set?
  
  The power set is the set of all subsets of S, including the empty set and S itself.
  
  Let's take an example.
  
  For S = {1, 2}
  
  The power set of S is P(S) = { {}, {1}, {2}, {1, 2} }
  
  So, in layman's terms, it's all the different combinations you can create with the elements of S.
  
  Knowing this, the power set of S6 is:
  
  P(S6) = { {}, {0} }
  
  So, depending if you want to count the set of outer brackets, the number of opening braces is either 2 or 3