text: ## Name WORKSHEET 4 Class6 Sec-c 3. Playing with Numbers 1. Find the greatest number that will divide 328, 4
  
  Question
  
  Name
  WORKSHEET 4
  Class6
  Sec-c
  3. Playing with Numbers
  1.
  Find the greatest number that will divide
  328, 436 and 544 leaving remainder 7, 8 and
  9 respectively,
  Solution:
  
  in progress 0
  1 month 2021-08-19T09:00:27+00:00 2 Answers 0 views 0
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107__________________________
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107__________________________107 is the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively