text: • # question_answer In the figure emf of the cell is 2 V and internal resistance is negligible. The resistance of the voltmeter is 80 ohm. The reading of voltmeter will be A)  2.00 volt                     B)  1.33 voltC)  1.60 volt                     D)  0.80
  
  The voltmeter is in parallel with $80\,\Omega$ resistance. Let equivalent resistance be $R'$Here $R'=40\Omega .$Now $20\,\Omega$ resistance is in series with $R'=$So, the equivalent resistance of the circuit$=20+40+60\Omega$ Current in the circuit = (2/60) amp. Current across $80\Omega$ resistance $=\frac{1}{2}\left[ \frac{2}{60} \right]=\frac{1}{60}\,amp.$ $\therefore$Reading of voltmeter $=80\times (1/60)=1.33\,V$ Hence, the correction option is [b].