text: # Find the distance of the point (3,4,5) from the plane x+y+z=2 measured parallel to the line 2x=y=z.
  
  Yash Jain
  55 Points
  9 years ago
  The answer is 6 units. I’ll give you hints.
  Dr’s of the line is ] = 6units2+(5-1)2+(4-0)2Therefore, PN = sqrt[(3-1)
  So N = (1,0,1)
  Satisfying this point on the plane gives u=-4
  General point on this line is..(u/2 +3, u+4, u+5) say N
  Eq. of the line passing through given point P(3,4,5) with these Dr’s (x-3)/1/2 = (y-4)/1 = (z-5)/1
  
  Yash Jain
  55 Points
  9 years ago
  The answer is 6 units. I’ll give you hints.
  Dr’s of the line is Therefore, PN = sqrt[(3-1)
  So N = (1,0,1)
  Satisfying this point on the plane gives u=-4
  General point on this line is..(u/2 +3, u+4, u+5) say N
  Eq. of the line passing through given point P(3,4,5) with these Dr’s (x-3)/1/2=(y-4)/1=(z-5)/1
  2+(5-1)2+(4-0)2] = 6units