text: +0
  
  # help
  
  0
  108
  1
  
  Let $$S$$ be the set of points with polar coordinates $$(r,\theta)$$ such that $$2 \le r \le 6$$and $$\frac{\pi}{3} \le \theta \le \frac{5 \pi}{6}$$. Find the area of $$S$$.
  
  Nov 15, 2019
  
  #1
  +109563
  +1
  
  pi/3 =  60°
  
  5pi/6 =  150°
  
  150 - 60   =  90°
  
  So....this  is  just  the area  between a quarter-circle with a radius of 6 and a quarter-circle with a radius of 2
  
  So  S  =
  
  (pi/4)   [ 6^2 - 2^2 ] =
  
  (pi /4 ) [ 32]  =
  
  8 pi units^2
  
  Nov 15, 2019