text: # How much kerosene was burned if 688 MJ was released?
  
  1) Let’s calculate the mass of the burnt kerosene.
  
  Q = q * m, where Q is the energy released during the combustion of kerosene (Q = 688 MJ = 688 * 10 ^ 6 J), q is the specific heat of combustion (for kerosene we take q = 4.6 * 10 ^ 7 J / kg) , m is the mass of burnt kerosene.
  
  m = Q / q = 688 * 10 ^ 6 / 4.6 * 10 ^ 7 = 14.96 kg.
  
  2) Calculate the volume of kerosene burned:
  
  V = m / ρ, where ρ is the density (for kerosene ρ = 810 kg / m3).
  
  V = m / ρ = 14.96 / 810 = 0.018 m3.
  
  Answer: 0.018 m3 of kerosene was burned.
  
  One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.