text: Question
  
  # In the following reaction, how many grams of hydrogen, H2, will be produced from 53.5 g...
  
  In the following reaction, how many grams of hydrogen, H2, will be produced from 53.5 g of aluminum, Al? 2Al + 3H2SO4 -> 3H2 + Al2(SO4)3
  
  In the following reaction, how many grams of hydrogen, H2, will be produced from 53.5 g of aluminum, Al?
  
  2Al + 3H2SO4 -> 3H2 + Al2(SO4)3
  
  From equation, from 2moles of Al we will get 3moles of H2.
  
  First convert 53.5 g of Al into moles.
  
  Al M.Wt = 27
  
  Al moles = Wt/M.Wt = 53.5/27 = 1.98 moles
  
  So, If 2 moles of Al generates 3 mloles of H2
  
  Then, from 1.98 moles of Al how H2 will produce
  
  =(1.98*3)/2 = 2.972 moles of H2 will produce
  
  Convert 2.972 moles into grams
  
  Moles = wt/m.wt
  
  H2 m.wt = 2
  
  Wt of H2 = 2.972*2 = 5.944 grams of H2 will generate