text: # NCERT Class 9 Solutions: Surface Areas and Volumes (Chapter 13) Exercise 13.6 – Part 2 (For CBSE, ICSE, IAS, NET, NRA 2023)
  
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  Q-3 A soft drink is available in two packs
  
  1. A tin can with a rectangular base of length and width , having a height of and
  2. A plastic cylinder with circular base of diameter and height
  
  Which container has greater capacity and by how much?
  
  Solution (i)
  
  Capacity of tin can
  
  Capacity
  
  Solution (ii)
  
  Capacity or volume of plastic cylinder is given as
  
  Diameter , therefore radius (r)
  
  Height (h)
  
  Therefore, capacity
  
  Clearly the second container, the plastic cylinder has greater capacity than the first container, a tin can. The cylinder has more volume.
  
  Q-4 If the lateral surface of a cylinder is and its height is , and then find
  
  1. Radius of its base
  2. Its volume . ()
  
  Solution:
  
  1. Consider the radius of the cylinder be
  
  Height
  
  • Later surface area
  
  So, the radius of the base is
  
  1. Now, volume of cylinder
  
  Q-5 It costs to paint the inner curved surface of a cylindrical vessel deep. If the cost of painting is at the rate of find
  
  1. Inner curved surface area of the vessel
  2. Radius of the base
  3. Capacity of the vessel
  
  Solution:
  
  1. Inner curved surface area of the vessel
  2. Radius of the base
  3. Consider the radius of the base
  4. The height of the cylindrical vessel
  
  We know that inner curved surface area
  
  • Therefore,
  
  So, the radius of the base is
  
  1. Capacity of the vessel