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  # IGCSE maths paper4 question help watch
  
  1. Hi guys, I think I'm probably just not approaching this correctly and the mark scheme is useless so here is the question:
  
  The information: Polygons, their number of sides and their total number of diagonals:
  ----------------------------------------------
  Number of sides 3,4,5,6, 7 , 8
  Total number of diagonals: 0,2,5,9,14,20
  ----------------------------------------------
  The questions:
  (a) A polygon with n sides has a total of 1/pn(n - q) diagonals, where p and q are integers.
  (i) Find the values of p and q.
  (ii) Find the total number of diagonals in a polygon with 100 sides.
  (iii) Find the number of sides of a polygon with has a total of 170 diagonals.
  
  (b) A polygon with (n + 1) sides has 30 more diagonals than a polygon with n sides.Find n.
  
  ----------------------------------------------
  How would you approach this? I'm clueless apart from the fact you start (a)(i) by inserting 2 values from the table but I couldn't get further to find p and q. Could someone explain?
  
  a)(i) p = 2 , q = 3
  (a)(ii) 4850
  (a)(iii) 20
  (b) 31
  2. Can you tell me which paper is this exactly?
  You can look it up on igcseworld.com, pastpapers.net, etc.. .
  Tell me the year, variant and question number and I will solve it in video for you
  3. It's:
  
  Question 10
  
  Paper 4 (Extended) 0580/42
  May/June 2010
  
  Some numbers in the bottom left:
  IB10 06_0580_42/2RP
  Cambridge IGCSE
  
  That's what it says on the front - thanks
  Josh
  
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