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  Is xy < 0?
  
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  Math Expert
  Joined: 02 Sep 2009
  Posts: 58312
  Is xy < 0?  [#permalink]
  
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  14 Jan 2017, 09:00
  3
  2
  00:00
  
  Difficulty:
  
  45% (medium)
  
  Question Stats:
  
  51% (00:51) correct 49% (00:48) wrong based on 120 sessions
  
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  Is xy < 0?
  
  (1) xy is not a positive integer.
  (2) xy is not a negative integer.
  
  _________________
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  Joined: 02 Aug 2009
  Posts: 7952
  Re: Is xy < 0?  [#permalink]
  
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  14 Jan 2017, 10:03
  Bunuel wrote:
  Is xy < 0?
  
  (1) xy is not a positive integer.
  (2) xy is not a negative integer.
  
  Hi..
  Few points to remember while dealing with numbers and variable..
  1) a variable can be any of the three - positive, negative and ZERO..
  2) a variable can be integer or non integer unless specified
  
  Now let's see the statements..
  
  (1) xy is not a positive integer.
  xy can be positive non integer OR negative number OR 0..
  So answer can be YES if negative number otherwise NO..
  Insufficient
  
  (2) xy is not a negative integer
  xy can be negative non integer OR positive number OR 0..
  So answer can be YES if negative non integer otherwise NO..
  Insufficient
  
  Combined..
  It can be positive noninteger or negative noninteger or 0..
  Insufficient
  
  E
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  Re: Is xy < 0?  [#permalink]
  
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  14 Jan 2017, 11:01
  E
  
  1.) XY is not positive integer.
  Possible values are -ve integer, 0 , +ve/-ve decimal .
  Insufficient
  
  2.) XY is not negative integer.
  Possible values are +ve integer, 0 , +ve/-ve decimal .
  Insufficient
  
  Comsidering both 1+2
  Possible values are 0 , +ve/-ve decimal .
  Insufficient
  
  Hence E
  
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  Re: Is xy < 0?  [#permalink]
  
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  14 Jan 2017, 23:23
  stmt-1 : xy can be either -ve Number or +ve fraction or zero. insuff.
  
  stmt-2 : xy can be either +ve Number or -ve fraction or zero. insuff.
  
  If we combine the two - xy can be either zero or +ve/-ve fraction. hence xy cab be <0 or >0 or =0. Insuff.
  
  Answer should be E.
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  Re: Is xy < 0?  [#permalink]
  
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  02 Mar 2018, 01:18
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  Re: Is xy < 0?   [#permalink] 02 Mar 2018, 01:18
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