text: ## Precalculus (6th Edition) Blitzer
  
  See figure; solution: $(0,5)$ and $(0,-5)$
  Step 1. Graph the given equations $\begin{cases} x^2+y^2=25 \\ 25x^2+y^2=25 \end{cases}$ as shown in the figure. Step 2. We can identify the intersect points as $(0,5)$ and $(0,-5)$ Step 3. Checking the solutions with the first equation, we have $(0)^2+(5)^2=25$ and $(0)^2+(-5)^2=25$ Step 4. Checking the solutions with the second equation, we have $25 (0)^2+(5)^2=25$ and $25 (0)^2+(-5)^2=25$