text: Question 47
  
  # A bag contains 2 red, 3 green and 2 blue balls. 2 balls are to be drawn randomly. Whatis the probability that the balls drawn contain no blue ball?
  
  Solution
  
  There areÂ 2 red, 3 green and 2 blue balls
  
  Probability of drawing blue balls = $$\frac{2}{7}$$
  
  => ProbabilityÂ that the balls drawn contain no blue ball = $$1-\frac{2}{7}$$
  
  = $$\frac{5}{7}$$
  
  => Ans - (A)