text: ## Giải nhanh hộ mk ạ, chi tiết nha
  
  Question
  
  Giải nhanh hộ mk ạ, chi tiết nha
  
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  4 years 2020-11-03T22:11:02+00:00 1 Answers 81 views 0
  
  $\begin{array}{l} {3^{2020}} + {3^{2019}} – {3^{2018}}\\ = {3^{2018 + 2}} + {3^{2018 + 1}} – {3^{2018}}\\ = {3^{2018}}{.3^2} + {3^{2018}}.3 – {3^{2018}}\\ = {3^{2018}}\left( {{3^2} + 3 – 1} \right)\\ = {3^{2018}}.11 \vdots 11\\ Vay\,\left( {{3^{2020}} + {3^{2019}} – {3^{2018}}} \right) \vdots 11 \end{array}$