text: # How do you find the vertex of y= -x^2+ 4x + 2?
  
  ##### 1 Answer
  Dec 27, 2017
  
  $- {\left(x - 2\right)}^{2} + 6$
  
  #### Explanation:
  
  −x^2+4x+2
  
  $\implies - 1 \cdot \left[{x}^{2} - 4 x - 2\right]$
  
  $\implies - 1 \cdot \left[\left({x}^{2} - 2 \cdot 2 x + {2}^{2}\right) - {2}^{2} - 2\right]$
  
  $\implies - 1 \cdot \left[{\left(x - 2\right)}^{2} - 4 - 2\right]$
  
  $\implies - 1 \cdot \left[{\left(x - 2\right)}^{2} - 6\right]$
  
  (-(x-2)^2+6)/