text: # How to solve ; ax + 2bx + 3cx – 3a – 6b – 9c ?
  
  Welcome to my article How to solve ; ax + 2bx + 3cx – 3a – 6b – 9c ?. This question is taken from the simplification lesson.
  The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.
  For complete information on how to solve this question How to solve ; ax + 2bx + 3cx – 3a – 6b – 9c ?, read and understand it carefully till the end.
  
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  First write the question on the page of the notebook.
  
  ## How to solve ; ax + 2bx + 3cx – 3a – 6b – 9c ?
  
  On writing this query like this,
  
  \displaystyle \mathbf{a}\times \mathbf{x}\text{ }+\text{ }\mathbf{2}\times \mathbf{b}\times \mathbf{x}\text{ }+\text{ }\mathbf{3}\times \mathbf{c}\times \mathbf{x}\text{ }-\text{ }\mathbf{3}\times \mathbf{a}\text{ }-\text{ }\mathbf{6}\times \mathbf{b}\text{ }-\text{ }\mathbf{9}\times \mathbf{c}
  
  \displaystyle x\times a\text{ }+\text{ }x\times \mathbf{2}\times \mathbf{b}\times \text{ }+x\times \mathbf{3}\times \mathbf{c}\text{ }-\text{ }\mathbf{3}\times \mathbf{a}\text{ }-\text{ 2}\times \text{3}\times \mathbf{b}\text{ }-\text{ 3}\times \text{3}\times \mathbf{c}
  
  \displaystyle x\times a\text{ }+\text{ }x\times \mathbf{2}\times \mathbf{b}\times \text{ }+x\times \mathbf{3}\times \mathbf{c}\text{ }-\text{ }\mathbf{3}\times \mathbf{a}\text{ }-\text{ 3}\times 2\times \mathbf{b}\text{ }-\text{ 3}\times \text{3}\times \mathbf{c}
  
  \displaystyle x\times a\text{ }+\text{ }x\times \mathbf{2b}+x\times \mathbf{3c}\text{ }-\text{ }\mathbf{3}\times \mathbf{a}\text{ }-\text{ 3}\times 2\mathbf{b}\text{ }-\text{ 3}\times \text{3}\mathbf{c}
  
  \displaystyle x(a+\mathbf{2b}+\mathbf{3c}\text{ )}-\text{ }\mathbf{3}(\mathbf{a}\text{+}2\mathbf{b}\text{+3}\mathbf{c})