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  # Algebra 2
  
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  Use the graphs of f(x) = 2/x  and g(x) = 1/-3-x to determine the solutions to f(x) = g(x).
  
  A)(-2, -1)
  
  B)(-2, 1)
  
  C)(2, 1)
  
  D)(2, -1)
  
  Simplify the expression.
  
  x^2 + x - 6/x^2 - 4 * x^2 - 9/x^2 + 6x + 9
  
  A)
  
  x - 3/x + 2
  
  B)
  
  x + 3/x - 2
  
  C)
  
  x - 2/x + 3
  
  D)
  
  x + 2/x - 3
  
  Aug 16, 2017
  
  #1
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  +1
  
  It looks as though f(x) = g (x ) at  (-2, -1)
  
  [x^2 + x - 6] / [x^2 - 4] *  [x^2 - 9] / [x^2 + 6x + 9]     factor numerators and denominators
  
  [ (x + 3) (x - 2)] / [ (x + 2) ( x - 2) ]  *  [ ( x + 3) ( x - 3) ] / [ (x + 3) ( x + 3) ]
  
  Simplifies to
  
  [ ( x + 3) ] / [ ( x + 2) ]  *  [ ( x - 3) ] / [ ( x + 3) ]    =
  
  [ ( x + 3) ] / [ ( x + 3) ] * [ x - 3) ] /  [ ( x + 2) ]  =
  
  [ ( x - 3) ] / [ ( x + 2) ]
  
  Aug 16, 2017