text: Question
  
  # Solve the following pair of equations. 5xâˆ’1+1yâˆ’2=2 6xâˆ’1âˆ’3yâˆ’2=1 Here, x â‰  1 and y â‰  2
  
  A
  
  x = 4, y = 5
  
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  B
  
  x = 5, y = 3
  
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  C
  
  x=13, y=13
  
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  D
  
  x = 7, y = 11
  
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  Solution
  
  ## The correct option is A x = 4, y = 5 If we substitute 1x−1 as p and 1y−2 as q in the given equations, we get the equations as 5p+q=2 .......(1) 6q−3q=1 .......(2) Now, we can solve the pair of equations by method of elimination. On multiplying the first equation by 3 and then adding it to (2), we get 15p+3q=6 6p−3q=1 _____________ p=13 Now by substituting the value of p in equation (2) we get q=13 Now, p=1x−1 ⇒1x−1=13 ⇒x=4 Similarly we assumed q=1y−2 ⇒1y−2=13 ⇒y−2=3 ⇒y=5 ∴x=4 and y=5
  
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