text: Friday
  May 6, 2016
  
  # Homework Help: math
  
  Posted by sonya on Thursday, January 24, 2008 at 6:32pm.
  
  x^3-4x-2 [2,3]
  
  we have to use the intermediate value thereom. not sure how to do this.
  • math - Damon, Thursday, January 24, 2008 at 7:30pm
  
  x^3-4x-2 [2,3]
  the function is continuous between 2 and 3
  at 2 f(2) = -2
  at 3 f(3) = +13
  
  The theorem states that for every number N between -2 and +13, there is some x between 2 and 3 such that f(x) = N
  
  Now they did not give you an N so I will say 5 for example is between -2 and +13
  
  The theorem says that some x between 2 and 3 will come out with f(x)= 5
  
  I would have to solve it by trial and error but I know to start between 2 and 5
  x f(x)
  2 -2
  
  try 2.5 --> 3.63 too small
  try 2.7 --> 6.88 too big
  try 2.6 --> 5.18 closer, a bit big
  try 2.58 -> 4.85 a little small
  try 2.585-> 4.93 well you get the idea
  
  3 13
  
  The theorem says that