text: ## PAP Unit 1 Test Review Solutions September 19, 2013
  
  Posted by Ms. Miller in Geometry.
  
  Note: These are the answers to the PAP Test Review.
  
  Proof #1:
  
   1. Given equation 2. Dist. prop. 3. $3x-13=3$ 3. Subtr. prop. = 4. $3x=16$ 4. Add. prop. = 5. $x=\frac{16}{3}$ 5. Div. prop. =
  Proof #2:
  
   1. $7x+11=3x-5$ 1. Given equation 2. $4x+11=-5$ 2. Subtr. prop. = 3. $4x=-16$ 3. Add. prop. = 4. $x=-4$ 4. Div. prop. =
  1. C 2. $m=\frac{-6}{4}=\frac{-3}{2}$
  3. $m=\frac{0-b}{3b-0}=\frac{-b}{3b}=-\frac{1}{3}$ 4. $\frac{a-17}{2-4}=6$
  $a-17=-12$
  $a=5$
  5. $-4y=-5x+10$
  $y=\frac{-5}{-4}x+\frac{10}{-4}$
  $m=\frac{5}{4}$
  6. $y+3=-2(x-7)$
  7. $y-0=3(x+2)$
  $y=3x+6$
  8. $y-1=\frac{2}{3}(x-3)$
  9. perpendicular slope: $m=\frac{1}{3}$,
  therefore C
  10.
  11. $\overrightarrow{}TW$ 12. collinear; coplanar
  13. $2\frac{1}{4}"$; $6.1 \mathrm{cm}$ 14. $6$
  15. omit 16. omit
  17. $15\sqrt{2}$ 18. $5\sqrt{3}=\sqrt{(5)(5)(3)}=\sqrt{75}$
  19. $c^2=8^2+14^2$
  $c^2=260$
  $c=\sqrt{260}=2\sqrt{65}$
  20. $a^2+5^2=18^2$
  $a^2=299$
  $a=\sqrt{299}$
  21. $7$ (Pythagorean triple) 22. $LS^2+5^2=10^2$
  $LS^2=75$
  $LS=\sqrt{75}=5\sqrt{3}$
  23. $(\frac{-1+3}{2},\frac{7-4}{2})=(1,\frac{3}{2})$ 24. $\frac{2+y}{2}=0$
  $y=-2$
  25. $(\frac{a+a-6}{2},\frac{b+3b}{2})=(\frac{2a-6}{2},\frac{4b}{2})$
  $=(a-3,2b)$
  26. $(7,11)$
  27. $d=\sqrt{(7-3)^2+(1+1)^2}=\sqrt{20}=2\sqrt{5}$
  28. $d=\sqrt{(2-1)^2+(-7-7)^2}=\sqrt{197}$
  29. $C(-3,4)$ 30. $d=\sqrt{(-3-4)^2+(9-0)^2}$
  $\sqrt{130}\approx 11.4$
  31. $d=\sqrt{(2a-3a)^2+(3b-4b)^2}=\sqrt{(-a)^2+(-b)^2}$
  $=\sqrt{a^2+b^2}$