text: equation: x^2-6x+1=5
  
  Complete the square
  
  x^2-6x=4
  then i took have of 6 which is 3 and squared it to come up with 9
  
  this is what I have now:
  
  x^2-6x+9=4+9
  
  $a(x-\frac{b}{2a})^{2}+\underbrace{c-\frac{b^{2}}{4a}}_{\text{constant}}$