text: # SOLUTION: Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
  
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   Click here to see ALL problems on Geometry Word Problems Question 118284: Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?Answer by stanbon(57962)   (Show Source): You can put this solution on YOUR website!Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? ------------------- Martina DATA: Rate = 24 mph ; Time = x hrs ; distance = rt = 24x miles ---------------------------- John DATA: Rate = 48 mph ; Time = x-2 ; distance = rt = 48(x-2) miles ------------------------------ EQUATION: Martina distance = John distance 24x = 48(x-2) 24x = 48x-96 24x = 96 x = 4 hrs -------------- John will catch Martina at 9:00 AM = 4 hrs = 1:00 PM ============== Cheers, Stan H.