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  # acid mixture
  
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  Pure acid is to be added to a 10% acid solution to obtain 90L of 58% solution. What amounts of each should be used? How many of 100% pure acid should be used to make the solution?
  
  Feb 10, 2021
  
  #1
  +120129
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  Pure  acid   =100%  acid  =  1
  
  So...let  x  be the amout of pure acid to  be added and we  have that
  
  1x +.10 *( 90 - x)  =  ( .58)(90)
  
  x  + 9  - .10x  =  52.2
  
  .90x  =  52.2  - 9
  
  .90x  =  43.2      divide both sides by  .90
  
  x  = 43.2  / .90  =  48   L
  
  Feb 10, 2021