text: ## Elementary Linear Algebra 7th Edition
  
  Published by Cengage Learning
  
  # Chapter 1 - Systems of Linear Equations - 1.1 Introduction to Systems of Linear Equations - 1.1 Exercises - Page 10: 41
  
  #### Answer
  
  Ans: $x=-\frac{1}{3}, y=-\frac{2}{3}$
  
  #### Work Step by Step
  
  Step 1: Simplify second equation $\frac{1}{5}x+\frac{2}{5}y=-\frac{1}{3}$ $3x+6y=-5$ $6y=-5-3x$ Step 2: Put $6y$ to one side on first equation $3y=9x+1$ $6y=18x+2$ Step 3: The other side of $6y$ are equal, so make an equation and solve $x$ $18x+2=-5-3x$ $21x=-7$ $x=-\frac{1}{3}$ Step 4: Substitute $x$ to one of the equations $9\times(-\frac{1}{3})-3y=-1$ $-3y=2$ $y=-\frac{2}{3}$
  
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