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  Question
  
  # Following are forecasts of worldwide annual cell phone handset sales:$\begin{matrix} \text{Year x} & \text{3} & \text{5} & \text{7}\\ \text{Sales y (millions)} & \text{500} & \text{600} & \text{800}\\ \end{matrix}$(x=3 represents 2003). Complete the following table and obtain the associated regression line. (Round coefficients to 2 decimal places.)$\begin{matrix} & \text{} & \text{x} & \text{y} & \text{xy} & \text{}{x^{2}}\\ & \text{} & \text{3} & \text{500} & \text{} & \text{}\\ & \text{} & \text{5} & \text{600} & \text{} & \text{}\\ & \text{} & \text{7} & \text{800} & \text{} & \text{}\\ \text{Totals} & \text{} & \text{} & \text{} & \text{}\\ \end{matrix}$Use your regression equation to project the 2008 sales.
  
  Solution
  
  Verified
  Step 1
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  Given the set of points
  
  $(\mathrm{x}_{1},y_{1}), (x_{2},y_{2}), \ldots, (x_{n},y_{n})$
  
  The regression line (least squares line, best-fit line):
  
  $y=mx+b,$
  
  where $m$ and $b$ are computed as follows.
  
  $m=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^{2})-(\sum x)^{2}}\qquad b=\frac{\sum y-m(\sum x)}{n}$
  
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