text: # Math
  
  posted by Dylan
  
  Help please on how to solve the following problem: If E,N,O,T, and W each represent a different integer, can you find more than one solution to this problem?
  
  1. Dylan
  
  I don't know if this is imperative but at the top of the problem it says one + one = two .... not sure if that is a hint or just a title so to speak for the problem...
  
  2. bobpursley
  
  This is a cryptrythm. Each letter in the one is a numberal, as in 123.
  
  ONE
  ONE
  ____
  TWO
  
  Well, O+O is nine or less, when means O is four or less. If O is four, E is 2. O cant be three, because two E's add to it. IF O is 2, E is one.
  
  Lets try both
  4N2
  4N2
  TW4
  Now W has to be even, and it cant be 2 or 4, they are used. If W is six, N is three, and T is eight.
  W cannot be4 or 2 as they are used. This is solution one.
  
  Solution two. E=1
  2N1
  2N1
  TW2 Again, W has to be even, it cannot be 4 (why?). Try w=six, then n is three, and T is four. Try w=8, N=4, which cannot be, as T will be 4. Try W=(1)0, or N=5. That makes T=5 also.
  
  We have two solutions.
  
  3. bobpursley
  
  Now here is another for you to work:
  
  SEND
  +MORE
  -----
  Money
  
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