text: ## 65 Reputation
  
  1 years, 184 days
  
  ## Thanks...
  
  @Kitonum bundle of thanks sir by the way why we take eval(rhs(%), x = 1);? rhs stand for right-hand side or is there any other meaning and % meaning?
  
  ## lambda...
  
  @Kitonum sir i am looking for how to find the value of lambda?
  
  ## error...
  
  @Kitonum why it gives error
  
  restart;
  h := k - (k - 1)*x;
  DE := diff(p(x), x) = 6/h^2 - 12*lambda/h^3;
  d                6              12 lambda
  DE := --- p(x) = ---------------- - ----------------
  dx                       2                  3
  (k - (k - 1) x)    (k - (k - 1) x)
  BC := p(0) = 0, p(1) = 0;
  BC := p(0) = 0, p(1) = 0
  simplify(dsolve({BC, DE}, p(x)));
  Error, invalid input: simplify uses a 1st argument, s, which is missing
  
  ## thanks...
  
  @Kitonum thanks sir, it is working well, i have confusion in the last step can you please explain how and why you did this
  
  ```p:=unapply(eval(p(x),%), x);
  h:='h':
  eval(p(x),x=solve(h=k-(k-1)*x,x));
  simplify(%);```
  
  and how to fine the value of lambda=k/1+k after integration
  
  ## Thanks...
  
  @Kitonum Thanks sir for your effort but i am looking for the solution which shows in the attached picture. first, need to put the value of h in the given first order ode and then solve obtained expression by using BCS that you b the same as p in the picture and neet to put the expression p=0 solve for lambda. but I do not obtained the exact value of p that is given papers
  
  ## problem...
  
  @Mariusz Iwaniuk pls have a look and required results
  
  ## Thanks...
  
  @Mariusz Iwaniuk that better idea can you please update the sheet that how could I generate the different graph in the same picture for different value of M=0.1----0.9 and for fix k=2 etc
  
  ## Thanks for help...
  
  @Mariusz Iwaniuk can you please give a little explanation that you did in the sheet and why you take rhs(sol)?
  
  ## thanks...
  
  @Carl Love I have already solved this by using dsolve command now I am looking for the algorithm of FDM
  
  ## Thanks...
  
  @acer Thanks sir, it is working and your way of helping is always helpful for me. But i don't understand why you convert into EXP?
  
  ## wrong value...
  
  @vv sorry sir in the first file there was a mistake in expression. Still, at my pc, it is not giving result and not integrating, I do not know why?
  
  Help.mw
  
  ## not working...
  
  @vv it is not working, can you please have a look on my try, pls have attached work
  
  Help.mw
  
  ## checked...
  
  @Kitonum sir i already checked this link but could not succeed in my problem. i am sure that me doing in wrong way that is way i posted here for help.
  
  ## other questions...
  
  @Kitonum thanks it is ok but can you please help me about the remaining questions pf my worksheet. There is other questions 2 and 3, pls help me to solve them
  
  ## Thanks...
  
  @Carl Love  i wrote thanks alot
  
   1 2 3 4 5 6 7 Page 2 of 8
  ﻿