text: Thursday
  May 5, 2016
  
  # Homework Help: ALGEBRA 1
  
  Posted by DANIELLE on Monday, April 16, 2007 at 2:35pm.
  
  CAN SOMEONE PLEASE CHECK TO SEE IF I HAVE DONE THESE CORRECTLY. Thanks for your help.
  
  Solve by completing the square
  1. X^2-6x=16
  X^2-6x + (-6/2) ^2=16+ (-6/2) ^2
  X^2-6x+36/4= 16+36/4
  (X-6/2)=100/4
  X-6/2= +or - 10/2
  X=6 + or - 10/2
  X=-4, X=8
  
  2. 2x^2-3x+1
  2x^2-3x=-1
  X^2-3/2x=-1/2
  X^2-3/2x +(-3/2)^2 =-1/2+(-3/2)^2
  X^2-3/2+9/4 =-1/2+9/4
  X+3/2=7/4
  X+3/2=+ or - sqrt7/4
  X=-3 + or – sqrt 7/2
  X= -3+sqrt7/2 , x=-3-sqrt7/2
  
  Put the values in the letters and see if you get the right answer
  
  For example
  
  -4 squared - 6(8) = 16
  
  See if it works in this way
  
  No1 in line 4
  why don't your reduce 6/2 to 3
  line 4 would read (x-3)^2 = 25
  then x-3 = +/- √25
  x-3 = +/- 5
  then x=8 or x = -2
  
  no 2 you have to take 1/2 of 3/2 which would be 3/4.
  then 3/4 squared is 9/16
  
  x^2 - (3/2)x + 9/16 = -1/2 + 9/16
  .
  .
  .
  (x-3/4)^2 = 1/16
  ..
  
  x=1 or x=1/2