text: # algebra 11
  
  posted by .
  
  (K+1)x+2y=6; M=k-2
  
  • algebra 11 -
  
  Apparently you mean that M is the slope. Most folks use lower-case letters.
  
  In any case, we have
  
  2y = -(k+1)x + 6
  y = -(k+1)/2 x + 3
  The slope is -(k+1)/2
  
  -(k+1)/2 = k-2
  -(k+1) = 2k - 2
  -k-1 = 2k-2
  3k = 1
  k = 1/3
  
  • algebra 11 -
  
  oops
  -(k+1) = 2k - 4
  -k-1 = 2k-4
  3k=3
  k=1
  
  • algebra 11 -
  
  Steve, You made another mistake in that second edit.
  
  Once you reach -k-1=2k-4.
  
  You need to subtract 2k from the right side.
  That gets you -3k-1=-4.
  
  You add 1 to get rid of that negative one which gets -3k=-3. Solve for k=1
  
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