text: # PHYSICS
  
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  a 0.1 kg mass is suspended at rest from a spring near the Earth's surface, the distance that the spring is stretched is measured to be 1.0 cm. What is the spring constant of the spring (remember the MKS units)?
  
  A mass of 2 kg is attached to a spring with constant 18 N/m. How far is the spring stretched?
  
  A spring with a spring constant of 28.9 N/m is attached to different masses, and is stretched 5cm. What is the force exerted on the spring?
  
  • PHYSICS -
  
  Part 1: A M=0.1 kg mass weighs F = Mg = 0.98 Newtons. The spring constant is
  k = F/X . If you put X in meters (0.01 m), do the computation and you will get k in MKS units of N/m
  
  Part 2:
  Use the same Hooke's law formula,
  k = F/X
  Rearrange it to get X= F/k
  The do the calculation. They told you what k is. You will have to convert the 2 kh mass to weight force.
  
  Part 3: F = k X
  In this case they tell you that X = 0.05 m
  
  Do the numbers.
  
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