text: ##### (c) Find its maximum or minimum value. f(x) =
  
  label Algebra
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  f(x) = 8x2 − 16x + 1
  (a) Express the quadratic function in standard form.
   f(x) =
  
  (c) Find its maximum or minimum value.
  
  f(x) =
  
  Jul 6th, 2015
  
  The given equation is 8 x^2-16x+1
  
  Here a= 8, b= -16 and c= 1
  
  Using the formula
  
  x= -{b+-(b^2-4ac)}/2a Put the values of a,b and c.
  
  We get x1= 1+1/4 sqrt 14
  
  x2= 1-1/4 sqrt 14
  
  To find the maximum and minimum value, we will use Perfect square method.
  
  Make the coefficient of  positive by multiplying it by  in case.
  Maxima / Minima is decided from the sign of 'a'.
  If 'a' is positive then we have Minima and for 'a'negative we have Maxima.
  
  Step two:
  Now make the perfect square with the same  and  coefficient.
  
  Maxima / Minima lies at the point where this squared term is equal to zero.
  
  Hence,
  =>
  
  This point is a minima if value of coefficient of x2 is positive and vice versa. For our function the point x=1 is a .
  
  Jul 6th, 2015
  
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  Jul 6th, 2015
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  Jul 6th, 2015
  Oct 18th, 2017
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