text: # How do you convert the Cartesian coordinates (1 , sqrt(3)) to polar coordinates?
  
  $r = 2$ and $\theta = \frac{\pi}{3}$ OR simply
  $\left(2 , \frac{\pi}{3}\right)$
  
  #### Explanation:
  
  give $x = 1$ and $y = \sqrt{3}$
  
  $r = \sqrt{{x}^{2} + {y}^{2}} = \sqrt{{1}^{2} + {\sqrt{3}}^{2}} = \sqrt{4} = 2$
  
  $\theta = {\tan}^{-} 1 \left(\frac{y}{x}\right) = {\tan}^{-} 1 \left(\frac{\sqrt{3}}{1}\right) = \frac{\pi}{3}$
  
  God bless America !!!