text: ## . An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it go
  
  Question
  
  . An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station is 210 m long. (a) How long is the nose of the train in the station
  
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  8 hours 2021-07-22T04:26:50+00:00 1 Answers 0 views 0
  
  Explanation:
  
  Give it that,
  
  Initial velocity
  
  u = 22m/s
  
  Deceleration a = – 0.15m/s2
  
  Time taken to travel a station long of 210m
  
  Using equation of motion
  
  Let know the final velocity, when it leaves the station
  
  v² = u²+2as
  
  v² = 22²+2×(-0.15)×210
  
  v² = 484—63
  
  v² = 421
  
  v =√421
  
  v = 20.52m/s
  
  Then,
  
  Using equation of motion to find time taken
  
  v = u + at
  
  20.52 = 22 +(-0.15)t
  
  20.52-22 = -0.15t
  
  -0.15t = -1.48
  
  t = -1.48/-0.15
  
  t = 9.88 sec