text: # How do you find the derivative of 2x^2+x-1?
  
  Apr 13, 2017
  
  $\frac{\mathrm{dy}}{\mathrm{dx}} \left(2 {x}^{2} + x - 1\right) = 4 x + 1$
  
  #### Explanation:
  
  Use the power rule $r {\left(a\right)}^{r - 1}$ and recall that the derivative of a constant is $0$
  
  Therefore the derivative is,
  
  $\frac{\mathrm{dy}}{\mathrm{dx}} = 2 \cdot 2 {x}^{2 - 1} + 1 {x}^{1 - 0} - 0$
  
  $\frac{\mathrm{dy}}{\mathrm{dx}} = 4 x + 1$