text: # Q.9.     In how many ways can a student choose a programme of 5 courses if 9 courses are available and 2 specific courses are compulsory for every student?
  
  9 courses are available and 2 specific courses are compulsory for every student.
  
  Therefore, every student has to select 3 courses out of the remaining 7 courses.
  
  This can be selected in $^7C_3$ ways.
  
  Thus, using multiplication priciple, number of ways of selecting courses  $=^7C_3$
  
  $=\frac{7!}{3!4!}$
  
  $= \frac{7\times 6\times 5}{ 3\times 2}$
  
  $=35$
  
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