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  If 6.9^a = 4.7^b, then b/a = ?
  
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  If 6.9^a = 4.7^b, then b/a = ? Round the answer to two decimal places.
  
  a*log(6.9) = b*log(4.7)
  
  log(4.7)/log(6.9) = 0.80
  
  Did I do this wrong? This dosn't seem to be the correct answer.
  
  Jan 30, 2018
  
  #1
  +2338
  +1
  
  You are so incredibly close to the right answer. Let me see if I can steer you in the right direction, if I can.
  
  $$6.9^a=4.7^b\\ \log\left(6.9^a\right)=\log\left(4.7^b\right)\\ a\log 6.9=b\log4.7\\ \frac{a}{b}=\frac{\log 4.7}{\log 6.9}\approx0.80$$
  
  Your answer is wrong because you solved for something other than what the question asked for. The above is the work that you provided. In the above, you solved for $$\frac{a}{b}$$, but what is the question asking you to solve for? Adjust your solving so that you are solving for the correct expression.
  
  Jan 30, 2018
  
  #1
  +2338
  +1
  
  You are so incredibly close to the right answer. Let me see if I can steer you in the right direction, if I can.
  
  $$6.9^a=4.7^b\\ \log\left(6.9^a\right)=\log\left(4.7^b\right)\\ a\log 6.9=b\log4.7\\ \frac{a}{b}=\frac{\log 4.7}{\log 6.9}\approx0.80$$
  
  Your answer is wrong because you solved for something other than what the question asked for. The above is the work that you provided. In the above, you solved for $$\frac{a}{b}$$, but what is the question asking you to solve for? Adjust your solving so that you are solving for the correct expression.
  
  TheXSquaredFactor Jan 30, 2018