text: ## Minimum value
  
  For discussing Olympiad Level Algebra (and Inequality) problems
  lizzythebest
  Posts: 3
  Joined: Mon Jul 03, 2017 4:05 pm
  
  ### Minimum value
  
  Determine the minimum value of
  $\frac{4x^3}{y}+\frac{y+1}{x}$
  
  with $x>0$ and $y>0$ real numbers.
  
  Ragib Farhat Hasan
  Posts: 62
  Joined: Sun Mar 30, 2014 10:40 pm
  
  ### Re: Minimum value
  
  Apparently, the denominators should be 1. So the minimum value will be 6.
  
  NABILA
  Posts: 35
  Joined: Sat Dec 15, 2018 5:19 pm
  Location: Munshigonj, Dhaka
  
  ### Re: Minimum value
  
  No.
  If, X>0, y>0
  Then, it could be x=y=0.1 or 0.01 or 0.000001
  Because, x and y are real number.
  
  NABILA
  Posts: 35
  Joined: Sat Dec 15, 2018 5:19 pm
  Location: Munshigonj, Dhaka
  
  ### Re: Minimum value
  
  Ragib Farhat Hasan wrote:
  Thu Sep 27, 2018 7:31 pm
  Apparently, the denominators should be 1. So the minimum value will be 6.
  I don't think so. Bcoz, x>0 and y>0 are real numbers not natural.
  
  Ragib Farhat Hasan
  Posts: 62
  Joined: Sun Mar 30, 2014 10:40 pm
  
  ### Re: Minimum value
  
  NABILA wrote:
  Mon Dec 17, 2018 6:11 pm
  Ragib Farhat Hasan wrote:
  Thu Sep 27, 2018 7:31 pm
  Apparently, the denominators should be 1. So the minimum value will be 6.
  I don't think so. Bcoz, x>0 and y>0 are real numbers not natural.
  I know the difference.
  
  What I meant was: in the solution to the problem, both $x$ and $y$ should be 1.
  
  BTW, this is just an observation since I didn't go through with the solution; it is an "apparent result".