text: # Homogenous Differential (Theoritical) - Wrosnkian Determinant Question
  
  I found myself hard to understand how to proceed in an exercise given.
  
  Suppose that $y_1 , y_2$ hold a fundamental set of solutions of : $y'' + p(t)y' + q(t)y = 0$ and also $y_3 = a_1y_1 + a_2y_2$ , $y_4 = b_1y_1 + b_2y_2$, where $a_1,a_2,b_1,b_2 \in \mathbb R$.
  
  Show that : $W(y_3,y_4) = (a_1b_2 - a_2b_1)W(y_1,y_2)$
  
  Do the solutions $y_3,y_4$ hold a fundamental set of solutions too ? Yes or not and why ?
  
  Attempt/Think :
  
  First of all I combined as $y = y_3 + y_4 = (a_1 + b_1)y_1 + (a_2 + b_2)y_2$ and said that it should be :
  
  $(a_1 + b_1)y_1(t_0) + (a_2 + b_2)y_2(t_0) = y_0$ and $(a_1 + b_1)y_1'(t_0) + (a_2 + b_2)y_2'(t_0) = y_0'$
  
  But after that, I got the same Wronski as always, since it's a combination of $y_1,y_2$, so I couldn't show the first part of the exercise.
  
  As for the second, we know that a fundamental set of solutions is held if $W(y_3,y_4) \neq 0$. Now we know that $W(y_1,y_2) \neq 0$ but if $(a_1b_2 - a_2b_1) = 0$ then a fundamental set of solutions isn't held, so that's answered.
  
  I would really appreciate any help in the first part of the exercise, because probably my mind has stuck in something simple. Thanks in advance !