text: # If 8 L of a gas at room temperature exerts a pressure of 32 kPa on its container, what pressure will the gas exert if the container's volume changes to 5 L?
  
  Dec 24, 2016
  
  The pressure is $= 51.2 k P a$
  
  #### Explanation:
  
  We apply Boyle's Law
  
  ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$
  
  ${P}_{1} = 32 k P a$
  
  ${V}_{1} = 8 L$
  
  ${V}_{2} = 5 L$
  
  ${P}_{2} = \frac{{P}_{1} {V}_{1}}{V} _ 2 = \frac{32 \cdot 8}{5} = 51.2 k P a$