text: Intermediate Algebra (12th Edition)
  
  $(x+8)^2+(y+5)^2=5$
  $\bf{\text{Solution Outline:}}$ Use the Center-Radius Form of the equation of circles to get the equation with the given center, $C( -8,-5 ),$ and the given radius, $r= \sqrt{5} .$ $\bf{\text{Solution Details:}}$ With the given center, then $h= -8$ and $k= -5 .$ Using the Center-Radius Form of the equation of circles which is given by $(x-h)^2+(y-k)^2=r^2,$ the equation of the circle is \begin{array}{l}\require{cancel} (x-(-8))^2+(y-(-5))^2=(\sqrt{5})^2 \\\\ (x+8)^2+(y+5)^2=5 .\end{array}