text: 1. ## Antiderivative of Log
  
  Find f given that f''= $\frac{-3}{x^2}$, f'(3) =5, and f(1) =3.
  
  I got this far:
  
  f'= $\frac{3}{x} + 4$
  
  f=3log(x)+ 4x + C = 3
  
  so log((1)^3) + 4(1) + C =3
  
  Am I on the right track? If so I don't quite know what to do next
  
  2. Yes, looks good. Remember that log(1) = 0. Evaluate C.
  
  3. Right! why do I keep forgetting these simple things
  
  3logx + 4x -1 Thanks!