text: ## Algebra 1
  
  Solution:($\frac{7}{10}$,$\frac{-4}{5}$)
  Given: 4x+y=2 and 3y+2x=-1 3(4x+y=2)=12x+3y=6 (12x+3y)-(3y+2x)=6-(-1) (Subtract two equations) 12x+3y-3y-2x=7 (Simplify) 12x-2x=7 (Simplify) 10x=7 x=$\frac{7}{10}$ (Divide both sides by 10) Plug in value of x: 4($\frac{7}{10}$)+y=2 =>$\frac{14}{5}$+y=2 => y=2-$\frac{14}{5}$=>y=$\frac{-4}{5}$ Solution ($\frac{7}{10}$,$\frac{-4}{5}$)