text: ## College Algebra (11th Edition)
  
  $\sum_{i=1}^9(\frac{1}{3i})$ or $\frac{1}{3}\sum_{i=1}^{9}(\frac{1}{i})$
  We can see that the number in the denominator, in brackets is changing from 1 to 9, with steps of 1. Therefore this will be our variable, and the $\frac{1}{3}$ is constant in all the fractions in the series. We can write that the sum is: $\sum_{i=1}^9(\frac{1}{3i})=\frac{1}{3}\sum_{i=1}^{9}\frac{1}{i}$
explanation: The text extract is from a college algebra textbook and provides an explanation of a summation expression. It shows how the expression $\sum_{i=1}^9(\frac{1}{3i})$ can be rewritten as $\frac{1}{3}\sum_{i=1}^{9}(\frac{1}{i})$. The extract does not contain a question or an answer to a question.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: ## College Algebra (11th Edition)
  
  $\sum_{i=1}^9(\frac{1}{3i})$ or $\frac{1}{3}\sum_{i=1}^{9}(\frac{1}{i})$
  We can see that the number in the denominator, in brackets is changing from 1 to 9, with steps of 1. Therefore this will be our variable, and the $\frac{1}{3}$ is constant in all the fractions in the series. We can write that the sum is: $\sum_{i=1}^9(\frac{1}{3i})=\frac{1}{3}\sum_{i=1}^{9}\frac{1}{i}$
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The text extract is from a college algebra textbook and provides an explanation of a summation expression. It shows how the expression $\sum_{i=1}^9(\frac{1}{3i})$ can be rewritten as $\frac{1}{3}\sum_{i=1}^{9}(\frac{1}{i})$. The extract does not contain a question or an answer to a question.
  
  Label: no-question