text: Ex 9.5
  
  Chapter 9 Class 8 Algebraic Expressions and Identities
  Serial order wise
  
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  ### Transcript
  
  Ex 9.5, 3 Find the following squares by using the identities. (vi) (2π₯π¦+5π¦)^2 (2π₯π¦+5π¦)^2 (π+π)^2=π^2+π^2+2ππ Putting π = 2π₯π¦ & π = 5π¦ = (2π₯π¦)^2+(5π¦)^2+2(2π₯π¦)(5π¦) = (2^2Γπ₯^2Γπ¦^2 )+(5^2Γπ¦^2 )+(2Γ2Γ5)Γπ₯Γ(π¦Γπ¦) = ππ^π π^π+πππ^π+ππππ^π
explanation: The document is a transcript from a math lesson or exercise, specifically from Chapter 9, Class 8, on Algebraic Expressions and Identities. It contains a question and its solution, where the task is to find the square of the expression \((2xy + 5y)^2\) using algebraic identities.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: Ex 9.5
  
  Chapter 9 Class 8 Algebraic Expressions and Identities
  Serial order wise
  
  This video is only available for Teachoo black users
  
  Get live Maths 1-on-1 Classs - Class 6 to 12
  
  ### Transcript
  
  Ex 9.5, 3 Find the following squares by using the identities. (vi) (2π₯π¦+5π¦)^2 (2π₯π¦+5π¦)^2 (π+π)^2=π^2+π^2+2ππ Putting π = 2π₯π¦ & π = 5π¦ = (2π₯π¦)^2+(5π¦)^2+2(2π₯π¦)(5π¦) = (2^2Γπ₯^2Γπ¦^2 )+(5^2Γπ¦^2 )+(2Γ2Γ5)Γπ₯Γ(π¦Γπ¦) = ππ^π π^π+πππ^π+ππππ^π
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document is a transcript from a math lesson or exercise, specifically from Chapter 9, Class 8, on Algebraic Expressions and Identities. It contains a question and its solution, where the task is to find the square of the expression \((2xy + 5y)^2\) using algebraic identities.
  
  Label: question-and-answer