text: ## Help me with Pre-Calc.
  
  Post any maths and/or physics related questions here.
  
  Moderators: Darobat, RecursiveS, Dante Shamest, Bugdude, Wizard
  
  go home wrote:That is obviously Dave Sinkula so go back to http://cboard.cprogramming.com/index.php? and stay there.
  Last edited by Guest on Thu Jan 06, 2005 12:21 am, edited 1 time in total.
  Guest
  
  Thanks for the link. The first persons post in the left link is pretty much what I am trying to ask. Il use this when I study tonight. My test is tomorro. So wish me luck after I study.
  
  I think through after school lessons, this forum , the internet lessons, and my text book; I can safely say that I might be able to learn how to do this.
  
  ~Thanks everyone~
  Sin
  
  Posts: 1570
  Joined: Tue Oct 07, 2003 10:16 am
  
  Simply put: The domain of x is all reals unless there is a value(s) that make x undefined, or where there are no x values.
  
  Take this set:
  
  f(x)={ 2x, x<4}
  { 3x, x>4}
  
  Notice that there is no value at x=4!! So the domain of x is:
  {x|x R, x!=4} or all reals except at x=4.
  
  Range works the same way: If there are undefined values, then the range is affected. Otherwise, it is all real numbers as well.
  "Given enough time, man can do anything with a bit of string and some Tinker toys." Bruce Bolden, Senior Instructor at the University of Idaho.
  
  leas5040
  
  Posts: 1214
  Joined: Mon Apr 12, 2004 9:51 pm
  Location: Moscow, ID
  
  leas5040 wrote:Range works the same way: If there are undefined values, then the range is affected. Otherwise, it is all real numbers as well.
  
  Hummm... nope! Range is more complicated. The range of f(x)=x^2 is not all reals.
  
  Alvaro
  Moderator
  
  Posts: 5185
  Joined: Mon Sep 22, 2003 4:57 pm
  Location: NY, USA
  
  ### Well........
  
  Alvaro wrote:
  leas5040 wrote:Range works the same way: If there are undefined values, then the range is affected. Otherwise, it is all real numbers as well.
  
  Hummm... nope! Range is more complicated. The range of f(x)=x^2 is not all reals.
  
  The range is easily found with the caculator for x^2.
  
  Oh and by the way I was able to study enough to understand how to find the domain and range.
  
  for this:
  f(x)= {2x, X < 2}
  {3x, X >= 2}
  
  The domain would be all reals.
  Its almost like common sense when finding the domain for that one. The calculator can also aid to find the domain.
  
  f(x)= 1/(X+2)(X-1)
  the domain would be every real number but not equal to -2 and 1.
  Easy.
  
  and for F(x)= 1/Square root of (x+1)
  The domain would be X >= -1.
  Thanks everyone for the help........
  Sin
  
  Posts: 1570
  Joined: Tue Oct 07, 2003 10:16 am
  
  ### Re: Well........
  
  Christopher wrote:The range is easily found with the caculator for x^2.
  
  How would you do that with a calculator?
  
  f(x)= 1/(X+2)(X-1)
  the domain would be every real number but not equal to -2 and 1.
  Easy.
  
  Yes, except you are missing some parenthesis in that expression. It should be 1/((X+2)(X-1)).
  
  and for F(x)= 1/Square root of (x+1)
  The domain would be X >= -1.
  
  Here you got the `X' and `x' mixed up (Math, like C++, is usually case-sensitive), and x=-1 is not in the domain.
  
  Alvaro
  Moderator
  
  Posts: 5185
  Joined: Mon Sep 22, 2003 4:57 pm
  Location: NY, USA
  
  Hummm... nope! Range is more complicated. The range of f(x)=x^2 is not all reals.
  
  Sure, because y<0 is undefined or isn't on the interval. So the range is [0, infinity) or non-negative numbers.
  "Given enough time, man can do anything with a bit of string and some Tinker toys." Bruce Bolden, Senior Instructor at the University of Idaho.
  
  leas5040
  
  Posts: 1214
  Joined: Mon Apr 12, 2004 9:51 pm
  Location: Moscow, ID
  
  ### Re: Well........
  
  Here you got the `X' and `x' mixed up (Math, like C++, is usually case-sensitive), and x=-1 is not in the domain.
  
  x >= -1 is not in the domain?
  Sin
  
  Posts: 1570
  Joined: Tue Oct 07, 2003 10:16 am
  
  It should be all reals except x=-1, because that makes the denominator sqrt(0), which is anti-good.
  "Given enough time, man can do anything with a bit of string and some Tinker toys." Bruce Bolden, Senior Instructor at the University of Idaho.
  
  leas5040
  
  Posts: 1214
  Joined: Mon Apr 12, 2004 9:51 pm
  Location: Moscow, ID
  
  ### Re: Well........
  
  Christopher wrote:
  Here you got the `X' and `x' mixed up (Math, like C++, is usually case-sensitive), and x=-1 is not in the domain.
  
  x >= -1 is not in the domain?
  
  That's not what I said. I said that x=1 is not in the domain. The domain is {x>1}.
  
  Alvaro
  Moderator
  
  Posts: 5185
  Joined: Mon Sep 22, 2003 4:57 pm
  Location: NY, USA
  
  Previous
explanation: The document is a series of posts from a forum where users are discussing math concepts, specifically the domain and range of functions. The posts include a user asking for help with pre-calculus and another user providing explanations and examples. There are also some corrections and clarifications from other users. The document contains multiple questions and answers related to math concepts.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: ## Help me with Pre-Calc.
  
  Post any maths and/or physics related questions here.
  
  Moderators: Darobat, RecursiveS, Dante Shamest, Bugdude, Wizard
  
  go home wrote:That is obviously Dave Sinkula so go back to http://cboard.cprogramming.com/index.php? and stay there.
  Last edited by Guest on Thu Jan 06, 2005 12:21 am, edited 1 time in total.
  Guest
  
  Thanks for the link. The first persons post in the left link is pretty much what I am trying to ask. Il use this when I study tonight. My test is tomorro. So wish me luck after I study.
  
  I think through after school lessons, this forum , the internet lessons, and my text book; I can safely say that I might be able to learn how to do this.
  
  ~Thanks everyone~
  Sin
  
  Posts: 1570
  Joined: Tue Oct 07, 2003 10:16 am
  
  Simply put: The domain of x is all reals unless there is a value(s) that make x undefined, or where there are no x values.
  
  Take this set:
  
  f(x)={ 2x, x<4}
  { 3x, x>4}
  
  Notice that there is no value at x=4!! So the domain of x is:
  {x|x R, x!=4} or all reals except at x=4.
  
  Range works the same way: If there are undefined values, then the range is affected. Otherwise, it is all real numbers as well.
  "Given enough time, man can do anything with a bit of string and some Tinker toys." Bruce Bolden, Senior Instructor at the University of Idaho.
  
  leas5040
  
  Posts: 1214
  Joined: Mon Apr 12, 2004 9:51 pm
  Location: Moscow, ID
  
  leas5040 wrote:Range works the same way: If there are undefined values, then the range is affected. Otherwise, it is all real numbers as well.
  
  Hummm... nope! Range is more complicated. The range of f(x)=x^2 is not all reals.
  
  Alvaro
  Moderator
  
  Posts: 5185
  Joined: Mon Sep 22, 2003 4:57 pm
  Location: NY, USA
  
  ### Well........
  
  Alvaro wrote:
  leas5040 wrote:Range works the same way: If there are undefined values, then the range is affected. Otherwise, it is all real numbers as well.
  
  Hummm... nope! Range is more complicated. The range of f(x)=x^2 is not all reals.
  
  The range is easily found with the caculator for x^2.
  
  Oh and by the way I was able to study enough to understand how to find the domain and range.
  
  for this:
  f(x)= {2x, X < 2}
  {3x, X >= 2}
  
  The domain would be all reals.
  Its almost like common sense when finding the domain for that one. The calculator can also aid to find the domain.
  
  f(x)= 1/(X+2)(X-1)
  the domain would be every real number but not equal to -2 and 1.
  Easy.
  
  and for F(x)= 1/Square root of (x+1)
  The domain would be X >= -1.
  Thanks everyone for the help........
  Sin
  
  Posts: 1570
  Joined: Tue Oct 07, 2003 10:16 am
  
  ### Re: Well........
  
  Christopher wrote:The range is easily found with the caculator for x^2.
  
  How would you do that with a calculator?
  
  f(x)= 1/(X+2)(X-1)
  the domain would be every real number but not equal to -2 and 1.
  Easy.
  
  Yes, except you are missing some parenthesis in that expression. It should be 1/((X+2)(X-1)).
  
  and for F(x)= 1/Square root of (x+1)
  The domain would be X >= -1.
  
  Here you got the `X' and `x' mixed up (Math, like C++, is usually case-sensitive), and x=-1 is not in the domain.
  
  Alvaro
  Moderator
  
  Posts: 5185
  Joined: Mon Sep 22, 2003 4:57 pm
  Location: NY, USA
  
  Hummm... nope! Range is more complicated. The range of f(x)=x^2 is not all reals.
  
  Sure, because y<0 is undefined or isn't on the interval. So the range is [0, infinity) or non-negative numbers.
  "Given enough time, man can do anything with a bit of string and some Tinker toys." Bruce Bolden, Senior Instructor at the University of Idaho.
  
  leas5040
  
  Posts: 1214
  Joined: Mon Apr 12, 2004 9:51 pm
  Location: Moscow, ID
  
  ### Re: Well........
  
  Here you got the `X' and `x' mixed up (Math, like C++, is usually case-sensitive), and x=-1 is not in the domain.
  
  x >= -1 is not in the domain?
  Sin
  
  Posts: 1570
  Joined: Tue Oct 07, 2003 10:16 am
  
  It should be all reals except x=-1, because that makes the denominator sqrt(0), which is anti-good.
  "Given enough time, man can do anything with a bit of string and some Tinker toys." Bruce Bolden, Senior Instructor at the University of Idaho.
  
  leas5040
  
  Posts: 1214
  Joined: Mon Apr 12, 2004 9:51 pm
  Location: Moscow, ID
  
  ### Re: Well........
  
  Christopher wrote:
  Here you got the `X' and `x' mixed up (Math, like C++, is usually case-sensitive), and x=-1 is not in the domain.
  
  x >= -1 is not in the domain?
  
  That's not what I said. I said that x=1 is not in the domain. The domain is {x>1}.
  
  Alvaro
  Moderator
  
  Posts: 5185
  Joined: Mon Sep 22, 2003 4:57 pm
  Location: NY, USA
  
  Previous
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document is a series of posts from a forum where users are discussing math concepts, specifically the domain and range of functions. The posts include a user asking for help with pre-calculus and another user providing explanations and examples. There are also some corrections and clarifications from other users. The document contains multiple questions and answers related to math concepts.
  
  Label: multiple-question-and-answer