text: ## Name WORKSHEET 4 Class6 Sec-c 3. Playing with Numbers 1. Find the greatest number that will divide 328, 4
  
  Question
  
  Name
  WORKSHEET 4
  Class6
  Sec-c
  3. Playing with Numbers
  1.
  Find the greatest number that will divide
  328, 436 and 544 leaving remainder 7, 8 and
  9 respectively,
  Solution:
  
  in progress 0
  1 month 2021-08-19T09:00:27+00:00 2 Answers 0 views 0
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107__________________________
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107__________________________107 is the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively
explanation: The document is a worksheet for Class 6, Section C, and it includes a math problem under the topic "Playing with Numbers." The problem asks to find the greatest number that will divide 328, 436, and 544, leaving remainders of 7, 8, and 9, respectively. The document does not provide a solution or answer to the question.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: ## Name WORKSHEET 4 Class6 Sec-c 3. Playing with Numbers 1. Find the greatest number that will divide 328, 4
  
  Question
  
  Name
  WORKSHEET 4
  Class6
  Sec-c
  3. Playing with Numbers
  1.
  Find the greatest number that will divide
  328, 436 and 544 leaving remainder 7, 8 and
  9 respectively,
  Solution:
  
  in progress 0
  1 month 2021-08-19T09:00:27+00:00 2 Answers 0 views 0
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107__________________________
  
  • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107__________________________107 is the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document is a worksheet for Class 6, Section C, and it includes a math problem under the topic "Playing with Numbers." The problem asks to find the greatest number that will divide 328, 436, and 544, leaving remainders of 7, 8, and 9, respectively. The document does not provide a solution or answer to the question.
  
  Label: question