text: # Find the largest number which divides 615 and 963 leaving remainder 6 in each case.
  
  Question:
  
  Find the largest number which divides 615 and 963 leaving remainder 6 in each case.
  
  Solution:
  
  We need to find the largest number which divides 615 and 963 leaving remainder 6 in each case.
  
  The required number when divides 615 and 963 , leaves remainder 6 , this means $615-6=609$ and $963-6=957$ are completely divisible by the number.
  
  Therefore,
  
  The required number = H.C.F. of 609 and 957.
  
  By applying Euclid’s division lemma
  
  $957=609 \times 1+348$
  
  $609=348 \times 1+261$
  
  $348=216 \times 1+87$
  
  $261=87 \times 3+0$
  
  Therefore, H.C.F. = 87.
  
  Hence, the required number is 87 .
explanation: The document contains a math question and a detailed solution to the problem. The question asks for the largest number that divides 615 and 963, leaving a remainder of 6 in each case. The solution uses the concept of the highest common factor (H.C.F.) and Euclid's division lemma to find the answer, which is 87.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # Find the largest number which divides 615 and 963 leaving remainder 6 in each case.
  
  Question:
  
  Find the largest number which divides 615 and 963 leaving remainder 6 in each case.
  
  Solution:
  
  We need to find the largest number which divides 615 and 963 leaving remainder 6 in each case.
  
  The required number when divides 615 and 963 , leaves remainder 6 , this means $615-6=609$ and $963-6=957$ are completely divisible by the number.
  
  Therefore,
  
  The required number = H.C.F. of 609 and 957.
  
  By applying Euclid’s division lemma
  
  $957=609 \times 1+348$
  
  $609=348 \times 1+261$
  
  $348=216 \times 1+87$
  
  $261=87 \times 3+0$
  
  Therefore, H.C.F. = 87.
  
  Hence, the required number is 87 .
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math question and a detailed solution to the problem. The question asks for the largest number that divides 615 and 963, leaving a remainder of 6 in each case. The solution uses the concept of the highest common factor (H.C.F.) and Euclid's division lemma to find the answer, which is 87.
  
  Label: question-and-answer