text: # Coin on Turntable
  
  1. Feb 27, 2009
  
  ### julz3216
  
  1. The problem statement, all variables and given/known data
  A coin is placed on a turntable that is rotating at 45.0 rpm. If the coefficient of static friction between the coin and the turntable is 0.186, how far from the center of the turntable can the coin be placed without having it slip off?
  
  2. Relevant equations
  
  mv^2/r <= usmg
  us= coefficient of static friction
  
  3. The attempt at a solution
  I tried using the equation and I converted 45 rpms to rad/sec and I got r=12.17 but this is wrong so I don't know what to do. Maybe im using the wrong equation?
  
  2. Feb 27, 2009
  
  ### hage567
  
  3. Feb 27, 2009
  
  ### julz3216
  
  mv^2/r =usmg
  v^2/r = usg
  (4.71^2)/r <= .186g
  22.184 = 1.8228r
  r= 12.17
  
  This seems logical to me but it says it is wrong.
  
  4. Feb 27, 2009
  
  ### hage567
  
  Note: the 4.71 rad/s, is angular velocity. You need to convert that to m/s, which is linear velocity. Do you know the relationship between these two? It should be in your textbook.
  
  5. Feb 27, 2009
  
  ### julz3216
  
  I think v = omega*r
  
  Where v is the velocity, omega is angular speed (rad/s), and r is the radius.
  so v= 4.71r
  then (4.71r)^2/r= 22.18r = 1.8228
  so r= .082
  
  which is right! thank you!!
  
  6. Feb 27, 2009
  
  ### hage567
  
  You're welcome.
explanation: The document is a discussion thread from a physics forum where a user named julz3216 posts a question about a physics problem involving a coin on a rotating turntable. The user provides the problem statement, relevant equations, and their attempt at a solution. Another user, hage567, provides guidance, and julz3216 eventually arrives at the correct answer.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
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distilabel_metadata.role: system
distilabel_metadata.content: # Coin on Turntable
  
  1. Feb 27, 2009
  
  ### julz3216
  
  1. The problem statement, all variables and given/known data
  A coin is placed on a turntable that is rotating at 45.0 rpm. If the coefficient of static friction between the coin and the turntable is 0.186, how far from the center of the turntable can the coin be placed without having it slip off?
  
  2. Relevant equations
  
  mv^2/r <= usmg
  us= coefficient of static friction
  
  3. The attempt at a solution
  I tried using the equation and I converted 45 rpms to rad/sec and I got r=12.17 but this is wrong so I don't know what to do. Maybe im using the wrong equation?
  
  2. Feb 27, 2009
  
  ### hage567
  
  3. Feb 27, 2009
  
  ### julz3216
  
  mv^2/r =usmg
  v^2/r = usg
  (4.71^2)/r <= .186g
  22.184 = 1.8228r
  r= 12.17
  
  This seems logical to me but it says it is wrong.
  
  4. Feb 27, 2009
  
  ### hage567
  
  Note: the 4.71 rad/s, is angular velocity. You need to convert that to m/s, which is linear velocity. Do you know the relationship between these two? It should be in your textbook.
  
  5. Feb 27, 2009
  
  ### julz3216
  
  I think v = omega*r
  
  Where v is the velocity, omega is angular speed (rad/s), and r is the radius.
  so v= 4.71r
  then (4.71r)^2/r= 22.18r = 1.8228
  so r= .082
  
  which is right! thank you!!
  
  6. Feb 27, 2009
  
  ### hage567
  
  You're welcome.
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document is a discussion thread from a physics forum where a user named julz3216 posts a question about a physics problem involving a coin on a rotating turntable. The user provides the problem statement, relevant equations, and their attempt at a solution. Another user, hage567, provides guidance, and julz3216 eventually arrives at the correct answer.
  
  Label: question-and-answer