text: # How do you convert the Cartesian coordinates (1 , sqrt(3)) to polar coordinates?
  
  $r = 2$ and $\theta = \frac{\pi}{3}$ OR simply
  $\left(2 , \frac{\pi}{3}\right)$
  
  #### Explanation:
  
  give $x = 1$ and $y = \sqrt{3}$
  
  $r = \sqrt{{x}^{2} + {y}^{2}} = \sqrt{{1}^{2} + {\sqrt{3}}^{2}} = \sqrt{4} = 2$
  
  $\theta = {\tan}^{-} 1 \left(\frac{y}{x}\right) = {\tan}^{-} 1 \left(\frac{\sqrt{3}}{1}\right) = \frac{\pi}{3}$
  
  God bless America !!!
explanation: The document contains a math question about converting Cartesian coordinates to polar coordinates, along with a detailed answer and explanation.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # How do you convert the Cartesian coordinates (1 , sqrt(3)) to polar coordinates?
  
  $r = 2$ and $\theta = \frac{\pi}{3}$ OR simply
  $\left(2 , \frac{\pi}{3}\right)$
  
  #### Explanation:
  
  give $x = 1$ and $y = \sqrt{3}$
  
  $r = \sqrt{{x}^{2} + {y}^{2}} = \sqrt{{1}^{2} + {\sqrt{3}}^{2}} = \sqrt{4} = 2$
  
  $\theta = {\tan}^{-} 1 \left(\frac{y}{x}\right) = {\tan}^{-} 1 \left(\frac{\sqrt{3}}{1}\right) = \frac{\pi}{3}$
  
  God bless America !!!
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math question about converting Cartesian coordinates to polar coordinates, along with a detailed answer and explanation.
  
  Label: question-and-answer