text: # An alloy contains the copper and aluminum in the ratio of 7 : 4
  
  ## d) 14.4 kg
  
  Solution -
  
  Copper and Aluminum in the ratio = 7 : 4
  
  Let,
  
  Copper and Aluminum be 7x and 4x respectively in the weapons.
  
  Aluminum in the weapon = 12 kg (given)
  
  4x = 12
  
  x = 3
  
  Therefore,
  
  Copper in the Weapon = 7x
  
  Copper in the weapon = 7*3
  
  Copper in the weapon = 21 kg
  
  Total Alloy in the weapon = 12 + 21
  
  Total Alloy in the weapon = 33 kg
  
  12% of the alloy got destroyed.
  
  Now,
  
  Total alloy in the weapon = (100% - 12%)
  
  Total alloy in the weapon = 88%
  
  But,
  
  Total alloy in the weapon = 33kg
  
  88%  = 33kg
  
  1% = (33/88)
  
  1% = (3/8)
  
  100% = [(3/8)*100]
  
  100% = 300/8
  
  100% = 37.5
  
  Therefore,
  
  Weight of the alloy required is 37.5
  
  Hence,
  
  The correct option is (c) 37.5
  
  Thank You
explanation: The document describes a math problem involving the calculation of the weight of an alloy based on the given ratio of copper to aluminum and the weight of aluminum. The document also provides a detailed solution to the problem, leading to the final answer of 37.5 kg. The correct option is identified as (c) 37.5.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # An alloy contains the copper and aluminum in the ratio of 7 : 4
  
  ## d) 14.4 kg
  
  Solution -
  
  Copper and Aluminum in the ratio = 7 : 4
  
  Let,
  
  Copper and Aluminum be 7x and 4x respectively in the weapons.
  
  Aluminum in the weapon = 12 kg (given)
  
  4x = 12
  
  x = 3
  
  Therefore,
  
  Copper in the Weapon = 7x
  
  Copper in the weapon = 7*3
  
  Copper in the weapon = 21 kg
  
  Total Alloy in the weapon = 12 + 21
  
  Total Alloy in the weapon = 33 kg
  
  12% of the alloy got destroyed.
  
  Now,
  
  Total alloy in the weapon = (100% - 12%)
  
  Total alloy in the weapon = 88%
  
  But,
  
  Total alloy in the weapon = 33kg
  
  88%  = 33kg
  
  1% = (33/88)
  
  1% = (3/8)
  
  100% = [(3/8)*100]
  
  100% = 300/8
  
  100% = 37.5
  
  Therefore,
  
  Weight of the alloy required is 37.5
  
  Hence,
  
  The correct option is (c) 37.5
  
  Thank You
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document describes a math problem involving the calculation of the weight of an alloy based on the given ratio of copper to aluminum and the weight of aluminum. The document also provides a detailed solution to the problem, leading to the final answer of 37.5 kg. The correct option is identified as (c) 37.5.
  
  Label: question-and-answer