text: ## Elementary Technical Mathematics
  
  $$-\frac{3}{8}rs^2+2rst.$$
  By multiplying each term of the polynomial by the factor $-\frac{1}{8}rs$, and then adding the products, we have $$-\frac{1}{8}rs(3s-16t)=-\frac{1}{8}rs(3s)-\frac{1}{8}rs(-16t)\\ =-\frac{3}{8}rs^2+2rst.$$
explanation: The text extract is from a mathematics textbook, specifically dealing with elementary technical mathematics. It demonstrates the process of multiplying each term of a polynomial by a factor and then simplifying the expression. The extract does not contain a question but rather provides a step-by-step explanation of a mathematical operation.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: ## Elementary Technical Mathematics
  
  $$-\frac{3}{8}rs^2+2rst.$$
  By multiplying each term of the polynomial by the factor $-\frac{1}{8}rs$, and then adding the products, we have $$-\frac{1}{8}rs(3s-16t)=-\frac{1}{8}rs(3s)-\frac{1}{8}rs(-16t)\\ =-\frac{3}{8}rs^2+2rst.$$
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The text extract is from a mathematics textbook, specifically dealing with elementary technical mathematics. It demonstrates the process of multiplying each term of a polynomial by a factor and then simplifying the expression. The extract does not contain a question but rather provides a step-by-step explanation of a mathematical operation.
  
  Label: no-question