text: # What is the moment of inertia of a pendulum with a mass of 4 kg that is 6 m from the pivot?
  
  Sep 21, 2017
  
  =144$k g \cdot {m}^{2}$
  
  #### Explanation:
  
  For this question we will assume that the pendelum has no friction and is only being acted upon by gravity. In conditions like this, the moment of inertia for the pendulum is equal to
  $I = m {r}^{2}$, where $I$ is the moment of inertia in kilograms times metres squared, $m$ is the mass of the pendulum in kilograms, and $r$ is the length of the pendulum from its pivot, in metres.
  
  We know that $m = 4$, and $r = 6$. Plug these into the formula to get
  $I = 4 \cdot {6}^{2}$
  $I = 4 \cdot 36$
  $I = 144 k g \cdot {m}^{2}$, the moment of inertia.
  
  https://en.wikipedia.org/wiki/Moment_of_inertia
  
  I hope that helped!
explanation: The document contains a math question and its corresponding answer. The question asks for the moment of inertia of a pendulum with specific parameters, and the answer provides a step-by-step calculation to arrive at the result.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # What is the moment of inertia of a pendulum with a mass of 4 kg that is 6 m from the pivot?
  
  Sep 21, 2017
  
  =144$k g \cdot {m}^{2}$
  
  #### Explanation:
  
  For this question we will assume that the pendelum has no friction and is only being acted upon by gravity. In conditions like this, the moment of inertia for the pendulum is equal to
  $I = m {r}^{2}$, where $I$ is the moment of inertia in kilograms times metres squared, $m$ is the mass of the pendulum in kilograms, and $r$ is the length of the pendulum from its pivot, in metres.
  
  We know that $m = 4$, and $r = 6$. Plug these into the formula to get
  $I = 4 \cdot {6}^{2}$
  $I = 4 \cdot 36$
  $I = 144 k g \cdot {m}^{2}$, the moment of inertia.
  
  https://en.wikipedia.org/wiki/Moment_of_inertia
  
  I hope that helped!
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math question and its corresponding answer. The question asks for the moment of inertia of a pendulum with specific parameters, and the answer provides a step-by-step calculation to arrive at the result.
  
  Label: question-and-answer