text: # Maximum number of squares that can fit in a right angle isosceles triangle in C++
  
  Given the task is to find the maximum number of squares having side ‘a’ that can fit inside a give right angle isosceles triangle with base of ‘s’(An isosceles triangle has at least 2 equal sides).
  
  Let’s now understand what we have to do using an example:
  
  ## Input
  
  s=5, a=1
  
  ## Output
  
  10
  
  Explanation − The number of squares in the base can be calculated by dividing s by a and subtracting 1. So the number of squares in base = 5/1 – 1 = 4.
  
  Similarly when the bottom 4 squares are placed then we get a new isosceles triangle with base (s-a) and then we repeat the same procedure and get 3 squares and so on until a single square is placed at the top.
  
  ## Input
  
  s=7, a=2
  
  ## Output
  
  3
  
  ## Approach used in the below program as follows
  
  • To find the maximum number of squares we will have to start from the base of the triangle and find out the number of squares.
  
  • To find the number of squares we will divide the base s by the side of the square a and subtract 1 from it = s/a – 1.
  
  • Then it will leave us another isosceles triangle with base (s - a) which will accommodate one less square than the previous row below it which we can calculate in the following way −
  
  Squares in next row = (s - a)/a – 1 = (s/a – a/a) – 1= s/a - 1 - 1 = s/a – 2 = one square less than the previous row.
  
  • The number of squares keep decreasing until it reaches 1, therefore we have to only find the number of squares in the base row and use the formula of adding natural numbers to find the final sum which is −
  
  (n) * (n + 1) / 2
  
  In this case the formula becomes − ((s / a) – 1) * (s / a) / 2
  
  ## Example
  
  Live Demo
  
  #include<bits/stdc++.h>
  using namespace std;
  int Max(int s, int a){
  //formula for calculating maximum squares
  return ((s / a) - 1) * (s / a) / 2;
  }
  //Main function
  int main(){
  int s = 5, a = 1;
  cout <<"Maximum squares possible are: "<<Max(s,a);
  return 0;
  }
  
  ## Output
  
  10
  
  Advertisements
explanation: The document describes a problem related to finding the maximum number of squares that can fit inside a right-angled isosceles triangle. It includes an explanation of the problem, examples with inputs and outputs, and a detailed approach to solving the problem. The document also provides a C++ code snippet that implements the solution.
  
  The document contains multiple questions and answers, as it presents different input scenarios and their corresponding outputs.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # Maximum number of squares that can fit in a right angle isosceles triangle in C++
  
  Given the task is to find the maximum number of squares having side ‘a’ that can fit inside a give right angle isosceles triangle with base of ‘s’(An isosceles triangle has at least 2 equal sides).
  
  Let’s now understand what we have to do using an example:
  
  ## Input
  
  s=5, a=1
  
  ## Output
  
  10
  
  Explanation − The number of squares in the base can be calculated by dividing s by a and subtracting 1. So the number of squares in base = 5/1 – 1 = 4.
  
  Similarly when the bottom 4 squares are placed then we get a new isosceles triangle with base (s-a) and then we repeat the same procedure and get 3 squares and so on until a single square is placed at the top.
  
  ## Input
  
  s=7, a=2
  
  ## Output
  
  3
  
  ## Approach used in the below program as follows
  
  • To find the maximum number of squares we will have to start from the base of the triangle and find out the number of squares.
  
  • To find the number of squares we will divide the base s by the side of the square a and subtract 1 from it = s/a – 1.
  
  • Then it will leave us another isosceles triangle with base (s - a) which will accommodate one less square than the previous row below it which we can calculate in the following way −
  
  Squares in next row = (s - a)/a – 1 = (s/a – a/a) – 1= s/a - 1 - 1 = s/a – 2 = one square less than the previous row.
  
  • The number of squares keep decreasing until it reaches 1, therefore we have to only find the number of squares in the base row and use the formula of adding natural numbers to find the final sum which is −
  
  (n) * (n + 1) / 2
  
  In this case the formula becomes − ((s / a) – 1) * (s / a) / 2
  
  ## Example
  
  Live Demo
  
  #include<bits/stdc++.h>
  using namespace std;
  int Max(int s, int a){
  //formula for calculating maximum squares
  return ((s / a) - 1) * (s / a) / 2;
  }
  //Main function
  int main(){
  int s = 5, a = 1;
  cout <<"Maximum squares possible are: "<<Max(s,a);
  return 0;
  }
  
  ## Output
  
  10
  
  Advertisements
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document describes a problem related to finding the maximum number of squares that can fit inside a right-angled isosceles triangle. It includes an explanation of the problem, examples with inputs and outputs, and a detailed approach to solving the problem. The document also provides a C++ code snippet that implements the solution.
  
  The document contains multiple questions and answers, as it presents different input scenarios and their corresponding outputs.
  
  Label: multiple-question-and-answer