text: • # question_answer In the figure emf of the cell is 2 V and internal resistance is negligible. The resistance of the voltmeter is 80 ohm. The reading of voltmeter will be A)  2.00 volt                     B)  1.33 voltC)  1.60 volt                     D)  0.80
  
  The voltmeter is in parallel with $80\,\Omega$ resistance. Let equivalent resistance be $R'$Here $R'=40\Omega .$Now $20\,\Omega$ resistance is in series with $R'=$So, the equivalent resistance of the circuit$=20+40+60\Omega$ Current in the circuit = (2/60) amp. Current across $80\Omega$ resistance $=\frac{1}{2}\left[ \frac{2}{60} \right]=\frac{1}{60}\,amp.$ $\therefore$Reading of voltmeter $=80\times (1/60)=1.33\,V$ Hence, the correction option is [b].
explanation: The document contains a math question related to electrical circuits, specifically about calculating the reading of a voltmeter given the resistance values and the emf of the cell. The document also provides a detailed solution and the correct answer.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: • # question_answer In the figure emf of the cell is 2 V and internal resistance is negligible. The resistance of the voltmeter is 80 ohm. The reading of voltmeter will be A)  2.00 volt                     B)  1.33 voltC)  1.60 volt                     D)  0.80
  
  The voltmeter is in parallel with $80\,\Omega$ resistance. Let equivalent resistance be $R'$Here $R'=40\Omega .$Now $20\,\Omega$ resistance is in series with $R'=$So, the equivalent resistance of the circuit$=20+40+60\Omega$ Current in the circuit = (2/60) amp. Current across $80\Omega$ resistance $=\frac{1}{2}\left[ \frac{2}{60} \right]=\frac{1}{60}\,amp.$ $\therefore$Reading of voltmeter $=80\times (1/60)=1.33\,V$ Hence, the correction option is [b].
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math question related to electrical circuits, specifically about calculating the reading of a voltmeter given the resistance values and the emf of the cell. The document also provides a detailed solution and the correct answer.
  
  Label: question-and-answer