text: # When divided by 30, 36, & 80 gives a remainder 11 in each case is :
  
  A number between 1000 and 2000 which when divided by 30, 36, & 80 gives a remainder 11 in each case is
  
  1. 1641
  2. 1712
  3. 1523
  4. 1451
  Anurag Mishra Professor Asked on 29th December 2015 in
  
  Explanation:-
  The factors of 30 = 2 x 3 x 5
  The factors of 36 = 2 x 2 x 3 x 3
  The factors of 80 = 2 x 2 x 2 x 2 x 5
  
  Then, the L C M of 30, 36, 80 = 2 x 2 x 2 x 2 x 3 x 3 x 5
  = 720
  
  The second multiple of 720 = 720 x 2 = 1440 which is between 1, 000 and 2, 000.
  Gives remainder = 11
  Then, the number = 1440 + 11
  = 1451
  
  Then, a number between 1, 000  and 2, 000 which when divided by 30, 36  & 80 gives a remainder 11 in each case is 1451.
  
  Hence, the correct answer is option (4) 1451.
  
  Monis Rasool Professor Answered on 29th December 2015.
explanation: The document contains a math question and its corresponding answer. The question asks for a number between 1000 and 2000 that, when divided by 30, 36, and 80, gives a remainder of 11 in each case. The answer provided is 1451, and the explanation includes the calculation of the least common multiple (LCM) of 30, 36, and 80, and the subsequent steps to find the correct number.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # When divided by 30, 36, & 80 gives a remainder 11 in each case is :
  
  A number between 1000 and 2000 which when divided by 30, 36, & 80 gives a remainder 11 in each case is
  
  1. 1641
  2. 1712
  3. 1523
  4. 1451
  Anurag Mishra Professor Asked on 29th December 2015 in
  
  Explanation:-
  The factors of 30 = 2 x 3 x 5
  The factors of 36 = 2 x 2 x 3 x 3
  The factors of 80 = 2 x 2 x 2 x 2 x 5
  
  Then, the L C M of 30, 36, 80 = 2 x 2 x 2 x 2 x 3 x 3 x 5
  = 720
  
  The second multiple of 720 = 720 x 2 = 1440 which is between 1, 000 and 2, 000.
  Gives remainder = 11
  Then, the number = 1440 + 11
  = 1451
  
  Then, a number between 1, 000  and 2, 000 which when divided by 30, 36  & 80 gives a remainder 11 in each case is 1451.
  
  Hence, the correct answer is option (4) 1451.
  
  Monis Rasool Professor Answered on 29th December 2015.
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math question and its corresponding answer. The question asks for a number between 1000 and 2000 that, when divided by 30, 36, and 80, gives a remainder of 11 in each case. The answer provided is 1451, and the explanation includes the calculation of the least common multiple (LCM) of 30, 36, and 80, and the subsequent steps to find the correct number.
  
  Label: question-and-answer