text: # physics!
  
  posted by .
  
  while running a marathon, alex is producing about 900 calories per hour. 1 calorie is 4184 j. if the specific heat of the human body is 3500 j/kg x c, how many degrees celsius would alexs temperature increase if he did not sweat and ran the marathon in 3 h and 10 min? he has a mass of 75 kg.
  
  thank god for sweat. if alex wants to release all of the caloric energy he produced so he doesnt heat up, how many litres of sweat would he need to produce and evaporate? the heat of vaporization for the water in sweat is 2.26 x 10^6 j/kg. the density of water is 1 g/ml
  
  • physics! -
  
  You are talking about kilocalories, not calories. (It is written as capitalized Calories when talking about nutrition and metabolic rates)
  
  In a 3.17 hour race, the body heat generated will be
  Q = 3.17h*900Cal/h*4184J/Cal = 1.19*10^7 Joules
  Temperature would increase by
  delta T = Q/M*C = 45.5 C
  
  For the second question, divide Q by the heat of vaporization in J/kg. Then convert that mass to volume in liters, using the density.
  
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  During a dry day, a 70.0 kg athlete runs a marathon while the outside temperature is T2 = 33.2 ¢XC. The thermal power produced by the athlete's body is P = 1.05 ¡Ñ 103 W and the skin temperature is T3 = 35.5 ¢XC so that the themal …
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explanation: The text extract contains a physics problem related to heat and energy transfer in the human body during a marathon. It includes two questions:
  
  1. **Temperature Increase Calculation**: The first question asks how many degrees Celsius Alex's temperature would increase if he did not sweat and ran the marathon in 3 hours and 10 minutes, given his mass and the specific heat of the human body.
  
  2. **Sweat Evaporation Calculation**: The second question asks how many liters of sweat Alex would need to produce and evaporate to release all the caloric energy he produced during the marathon, given the heat of vaporization for water and the density of water.
  
  The text also provides a solution for the first question and a method for solving the second question.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # physics!
  
  posted by .
  
  while running a marathon, alex is producing about 900 calories per hour. 1 calorie is 4184 j. if the specific heat of the human body is 3500 j/kg x c, how many degrees celsius would alexs temperature increase if he did not sweat and ran the marathon in 3 h and 10 min? he has a mass of 75 kg.
  
  thank god for sweat. if alex wants to release all of the caloric energy he produced so he doesnt heat up, how many litres of sweat would he need to produce and evaporate? the heat of vaporization for the water in sweat is 2.26 x 10^6 j/kg. the density of water is 1 g/ml
  
  • physics! -
  
  You are talking about kilocalories, not calories. (It is written as capitalized Calories when talking about nutrition and metabolic rates)
  
  In a 3.17 hour race, the body heat generated will be
  Q = 3.17h*900Cal/h*4184J/Cal = 1.19*10^7 Joules
  Temperature would increase by
  delta T = Q/M*C = 45.5 C
  
  For the second question, divide Q by the heat of vaporization in J/kg. Then convert that mass to volume in liters, using the density.
  
  ## Similar Questions
  
  1. ### science
  
  why is a burn from steam potentially more serios than a burn from very hot water?
  2. ### Physics Problem
  
  While running, a 70.0 kg student generates thermal energy at a rate of 1200 W. To maintain a constant body temperature of 37.0 C, this energy must be removed by perspiration or other mechanisms. If these mechanisms failed and the heat …
  3. ### Physics
  
  If the air temperature is the same as the temperature of your skin (about 30 degrees Celcius), your body cannot get rid of heat by transferring it to the air. In that case, it gets rid of the heat by evaporating water (sweat). During …
  4. ### Astronomy/Physics
  
  I'd love thorough solutions to these problems, but simply providing the specific formulas that I should solve each part of the problem with would be really good too. :-) Thanks! Human energetics You are sitting down to study in the …
  5. ### physics
  
  The basal metabolic rate is the rate at which energy is produced in the body when a person is at rest. A 70.0 kg person of height 1.79 m would have a body surface area of approximately 1.90 m^2. What is the net amount of heat this …
  6. ### physic problem-thermoregulation
  
  During a dry day, a 70.0 kg athlete runs a marathon while the outside temperature is T2 = 33.2 ¢XC. The thermal power produced by the athlete's body is P = 1.05 ¡Ñ 103 W and the skin temperature is T3 = 35.5 ¢XC so that the themal …
  7. ### Chemistry
  
  How many joules (J) are needed to increase the temperature of15.0g of lead from 20 degrees celsius to 40 degrees celsius?
  8. ### physics
  
  water has a specific heat of 4184 j(kg K). How much energy is needed to increase the temperature of a kilogram of water 5 degrees celcius?
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The text extract contains a physics problem related to heat and energy transfer in the human body during a marathon. It includes two questions:
  
  1. **Temperature Increase Calculation**: The first question asks how many degrees Celsius Alex's temperature would increase if he did not sweat and ran the marathon in 3 hours and 10 minutes, given his mass and the specific heat of the human body.
  
  2. **Sweat Evaporation Calculation**: The second question asks how many liters of sweat Alex would need to produce and evaporate to release all the caloric energy he produced during the marathon, given the heat of vaporization for water and the density of water.
  
  The text also provides a solution for the first question and a method for solving the second question.
  
  Label: multiple-question-and-answer