text: How do you solve the following linear system 3x-7y=1, x+3y=1? ?
  
  Jun 23, 2018
  
  Multiply the second equation by $3$ (everything) and then subtract the second equation from the first
  
  Explanation:
  
  So if you multiply the 2nd equation by $3$, you have
  
  $3 x + 9 y = 3$
  
  The first one is
  
  $3 x - 7 y = 1$
  
  Now, after subtracting them. we have:
  
  $16 y = 2$
  
  so
  
  $y = \frac{1}{8}$
  
  Now simply put it into any equation from the initial part (let's say the second). We have
  
  $x + 3 \cdot \frac{1}{8} = 1$
  
  So
  
  $x = \frac{5}{8}$
  
  $y = \frac{1}{8}$
  
  is the only solution.
explanation: The document contains a math question and a detailed answer explaining how to solve a system of linear equations.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: How do you solve the following linear system 3x-7y=1, x+3y=1? ?
  
  Jun 23, 2018
  
  Multiply the second equation by $3$ (everything) and then subtract the second equation from the first
  
  Explanation:
  
  So if you multiply the 2nd equation by $3$, you have
  
  $3 x + 9 y = 3$
  
  The first one is
  
  $3 x - 7 y = 1$
  
  Now, after subtracting them. we have:
  
  $16 y = 2$
  
  so
  
  $y = \frac{1}{8}$
  
  Now simply put it into any equation from the initial part (let's say the second). We have
  
  $x + 3 \cdot \frac{1}{8} = 1$
  
  So
  
  $x = \frac{5}{8}$
  
  $y = \frac{1}{8}$
  
  is the only solution.
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math question and a detailed answer explaining how to solve a system of linear equations. 
  
  Label: question-and-answer