text: # Textile Calculation
  
  ## Mathematical Problems of Jute Spreader Machine
  
  Mathematical Problems of Jute Spreader Machine
  Engr Avijit Dey
  Production Officer
  Fabian Group, Chittagong
  Mobile: 01836124490
  E-mail: avijitdey43@yahoo.com
  
  Jute spreader machine is used to comb and open the pieced out of long reeds of jute. It is done combing action on the jute. To convert them into an even and continuous sliver which receives an even application of batching emulsion. To prepare ribbon like sliver jute spreader machine is used.
  
  Problem-1
  A jute spreader machine is running with following data:
  
  • Dollop wt =1000 lbs,
  • Clock gearing const =10,
  • Clock charge pinion = 20T.
  • Draft const = 350,
  • Emulsification applied =25%,
  • Feed wt in lbs/1000yds?
  Delivery wt/100yds?
  
  Solution:
  
  Clock length = Clock gearing const × clock change pinion
  =10×20=200Yds.
  
  Feed mt count/wt of feed jute in lbs/100Yds = 1000÷200×100
  =500 lbs/100Yds.
  
  Draft const       350
  Draft = ………………. = ……. =10
  DCP             35
  
  Emulsion applied = (25÷100)×500 = 125 lbs/100yds.
  
  After application of emulsion wt of total feed material = (500+125)
  = 625 lbs/100yds
  
  Feed material wt       625
  Delivered sliver weight = ………………..…. = ………..
  Draft                 100
  
  = 6.25lb/1000 Yds.(ANS)
  
  Problem -2:
  Find the production in lbs/hr of S. M/C from the following data:
  
  • Delivered speed = 60yds/min.
  • Draft =12,
  • Efficiency = 80%,
  • Emulsion applied = 20%,
  • Wt of feed material = 6lb/yds.
  Solution:
  
  Production in lbs/hour = (6÷12) × 60 × 60 × (100+20) ÷ 100 × 0.8
  
  = 1728 (ANS).
  
  Problem-3:
  Find out the production of spreader M/C from the following data:
  
  • Dollop wt = 36lbs,
  • Clock length = 6yds,
  • Delivery speed = 60yds/min,.
  • M/C draft = 12 ,
  • Emulsion applied =12%
  Solution:
  
  Delivery speed × dollop wt
  Production of spreader machine in lbs/hour = ………………………………
  Draft × clock length
  
  = 60 × 60 × 36 ÷ (12×6) × (100+12) ÷ 100
  
  = 2016Yds/hr. (ANS).
explanation: The document contains multiple mathematical problems related to the operation of a jute spreader machine. Each problem is followed by a detailed solution. The problems involve calculations for feed weight, delivered sliver weight, production in pounds per hour, and other relevant metrics.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # Textile Calculation
  
  ## Mathematical Problems of Jute Spreader Machine
  
  Mathematical Problems of Jute Spreader Machine
  Engr Avijit Dey
  Production Officer
  Fabian Group, Chittagong
  Mobile: 01836124490
  E-mail: avijitdey43@yahoo.com
  
  Jute spreader machine is used to comb and open the pieced out of long reeds of jute. It is done combing action on the jute. To convert them into an even and continuous sliver which receives an even application of batching emulsion. To prepare ribbon like sliver jute spreader machine is used.
  
  Problem-1
  A jute spreader machine is running with following data:
  
  • Dollop wt =1000 lbs,
  • Clock gearing const =10,
  • Clock charge pinion = 20T.
  • Draft const = 350,
  • Emulsification applied =25%,
  • Feed wt in lbs/1000yds?
  Delivery wt/100yds?
  
  Solution:
  
  Clock length = Clock gearing const × clock change pinion
  =10×20=200Yds.
  
  Feed mt count/wt of feed jute in lbs/100Yds = 1000÷200×100
  =500 lbs/100Yds.
  
  Draft const       350
  Draft = ………………. = ……. =10
  DCP             35
  
  Emulsion applied = (25÷100)×500 = 125 lbs/100yds.
  
  After application of emulsion wt of total feed material = (500+125)
  = 625 lbs/100yds
  
  Feed material wt       625
  Delivered sliver weight = ………………..…. = ………..
  Draft                 100
  
  = 6.25lb/1000 Yds.(ANS)
  
  Problem -2:
  Find the production in lbs/hr of S. M/C from the following data:
  
  • Delivered speed = 60yds/min.
  • Draft =12,
  • Efficiency = 80%,
  • Emulsion applied = 20%,
  • Wt of feed material = 6lb/yds.
  Solution:
  
  Production in lbs/hour = (6÷12) × 60 × 60 × (100+20) ÷ 100 × 0.8
  
  = 1728 (ANS).
  
  Problem-3:
  Find out the production of spreader M/C from the following data:
  
  • Dollop wt = 36lbs,
  • Clock length = 6yds,
  • Delivery speed = 60yds/min,.
  • M/C draft = 12 ,
  • Emulsion applied =12%
  Solution:
  
  Delivery speed × dollop wt
  Production of spreader machine in lbs/hour = ………………………………
  Draft × clock length
  
  = 60 × 60 × 36 ÷ (12×6) × (100+12) ÷ 100
  
  = 2016Yds/hr. (ANS).
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains multiple mathematical problems related to the operation of a jute spreader machine. Each problem is followed by a detailed solution. The problems involve calculations for feed weight, delivered sliver weight, production in pounds per hour, and other relevant metrics.
  
  Label: multiple-question-and-answer