text: # ML Aggarwal Solutions Class 8 Mathematics Solutions for Simple and Compound Interest Exercise 8.2 in Chapter 8 - Simple and Compound Interest
  
  Question 4 Simple and Compound Interest Exercise 8.2
  
  a man invests Rs 46875 at 4% per annum compound interest for 3 years.
  
  Calculate:
  
  (i) the interest for the first year
  
  (ii) the amount standing to his credit at the end of the second year
  
  (iii) the interest for the third year
  
  (i) Principal for the first year = Rs 46875
  
  Rate of interest = 4% per annum
  
  Therefore,
  
  Interest for the first year = Rs (46875 × 4 × 1) / 100
  
  We get,
  
  = Rs 46875 / 25
  
  = Rs 1875
  
  Hence, interest for the first year is Rs 1875
  
  (ii) Amount at the end of first year
  
  = Rs 46875 + Rs 1875
  
  We get,
  
  = Rs 48750
  
  Principal for the second year = Rs 48750
  
  Interest for the second year = Rs (48750 × 4 × 1) / 100
  
  = Rs 48750 / 25
  
  We get,
  
  = Rs 1950
  
  Amount at the end of second year = Rs 48750 + Rs 1950
  
  We get,
  
  = Rs 50700
  
  Hence, the amount at the end of second year is Rs 50700
  
  (iii) Principal for the third year = Rs 50700
  
  Interest for the third year = Rs (50700 × 4 × 1) / 100
  
  We get,
  
  = Rs 507 × 4
  
  = Rs 2028
  
  Hence, the interest in the third year is Rs 2028
  
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explanation: The document is a solution to a math problem from a textbook, specifically from the chapter on Simple and Compound Interest. It provides a detailed solution to a question about calculating compound interest over three years, including the interest for each year and the amount at the end of the second year. The document also mentions related questions but does not provide them.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
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distilabel_metadata.role: system
distilabel_metadata.content: # ML Aggarwal Solutions Class 8 Mathematics Solutions for Simple and Compound Interest Exercise 8.2 in Chapter 8 - Simple and Compound Interest
  
  Question 4 Simple and Compound Interest Exercise 8.2
  
  a man invests Rs 46875 at 4% per annum compound interest for 3 years.
  
  Calculate:
  
  (i) the interest for the first year
  
  (ii) the amount standing to his credit at the end of the second year
  
  (iii) the interest for the third year
  
  (i) Principal for the first year = Rs 46875
  
  Rate of interest = 4% per annum
  
  Therefore,
  
  Interest for the first year = Rs (46875 × 4 × 1) / 100
  
  We get,
  
  = Rs 46875 / 25
  
  = Rs 1875
  
  Hence, interest for the first year is Rs 1875
  
  (ii) Amount at the end of first year
  
  = Rs 46875 + Rs 1875
  
  We get,
  
  = Rs 48750
  
  Principal for the second year = Rs 48750
  
  Interest for the second year = Rs (48750 × 4 × 1) / 100
  
  = Rs 48750 / 25
  
  We get,
  
  = Rs 1950
  
  Amount at the end of second year = Rs 48750 + Rs 1950
  
  We get,
  
  = Rs 50700
  
  Hence, the amount at the end of second year is Rs 50700
  
  (iii) Principal for the third year = Rs 50700
  
  Interest for the third year = Rs (50700 × 4 × 1) / 100
  
  We get,
  
  = Rs 507 × 4
  
  = Rs 2028
  
  Hence, the interest in the third year is Rs 2028
  
  Related Questions
  
  Lido
  
  Courses
  
  Teachers
  
  Book a Demo with us
  
  Syllabus
  
  Maths
  CBSE
  Maths
  ICSE
  Science
  CBSE
  
  Science
  ICSE
  English
  CBSE
  English
  ICSE
  Coding
  
  Terms & Policies
  
  Selina Question Bank
  
  Maths
  Physics
  Biology
  
  Allied Question Bank
  
  Chemistry
  Connect with us on social media!
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document is a solution to a math problem from a textbook, specifically from the chapter on Simple and Compound Interest. It provides a detailed solution to a question about calculating compound interest over three years, including the interest for each year and the amount at the end of the second year. The document also mentions related questions but does not provide them.
  
  Label: question-and-answer