text: # A metal oxide has the formula Z2O3. It can be reduced by hydrogen to give free metal and water…
  
  Q: A metal oxide has the formula Z2O3. It can be reduced by hydrogen to give free metal and water. 0.1596g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is
  
  (A) 27.9
  
  (B) 159.6
  
  (C) 79.8
  
  (D) 55.8
  
  Solution: Valency of metal in Z2O3 = 3
  
  Z2O3 + 3H2 → 2Z + 3H2O
  
  0.1596g of Z2O3 reacts with 6 mg of H2
  
  1g H2 will react with g of Z2O3
  
  equivalent weight of Z2O3 = 0.1596/0.006 = 26.6g
  
  equivalent weight of Z2O3 = 26.6
  
  = eq.wt. of Z + eq. wt. of = E + 8
  
  E + 8 = 26.6
  
  E = 18.6
  
  Atomic weight of Z = 18.6 × 3 = 55.8
explanation: The document contains a chemistry problem that involves stoichiometry and the calculation of the atomic weight of a metal. It includes a question and a detailed solution leading to the answer.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # A metal oxide has the formula Z2O3. It can be reduced by hydrogen to give free metal and water…
  
  Q: A metal oxide has the formula Z2O3. It can be reduced by hydrogen to give free metal and water. 0.1596g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is
  
  (A) 27.9
  
  (B) 159.6
  
  (C) 79.8
  
  (D) 55.8
  
  Solution: Valency of metal in Z2O3 = 3
  
  Z2O3 + 3H2 → 2Z + 3H2O
  
  0.1596g of Z2O3 reacts with 6 mg of H2
  
  1g H2 will react with g of Z2O3
  
  equivalent weight of Z2O3 = 0.1596/0.006 = 26.6g
  
  equivalent weight of Z2O3 = 26.6
  
  = eq.wt. of Z + eq. wt. of = E + 8
  
  E + 8 = 26.6
  
  E = 18.6
  
  Atomic weight of Z = 18.6 × 3 = 55.8
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a chemistry problem that involves stoichiometry and the calculation of the atomic weight of a metal. It includes a question and a detailed solution leading to the answer.
  
  Label: question-and-answer