text: # Find the least number which when divided by 35, 56 and 91 leaves the same remainder
  
  Question:
  
  Find the least number which when divided by 35, 56 and 91 leaves the same remainder 7 in each case.
  
  Solution:
  
  Least number which can be divided by 35, 56 and 91 is LCM of 35, 56 and 91.
  
  Prime factorization of 35, 56 and 91 is:
  
  35 = 5 × 7
  
  $56=2^{3} \times 7$
  
  91 = 7 × 13
  
  LCM = product of greatest power of each prime factor involved in the numbers $=2^{3} \times 5 \times 7 \times 13=3640$
  
  Least number which can be divided by 35, 56 and 91 is 3640.
  
  Least number which when divided by 35, 56 and 91 leaves the same remainder 7 is 3640 + 7 = 3647.
  
  Thus, the required number is 3647.
explanation: The document contains a math question and a detailed solution to the problem. The question asks for the least number that, when divided by 35, 56, and 91, leaves the same remainder of 7 in each case. The solution involves finding the least common multiple (LCM) of 35, 56, and 91 and then adding the remainder to the LCM to get the final answer.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # Find the least number which when divided by 35, 56 and 91 leaves the same remainder
  
  Question:
  
  Find the least number which when divided by 35, 56 and 91 leaves the same remainder 7 in each case.
  
  Solution:
  
  Least number which can be divided by 35, 56 and 91 is LCM of 35, 56 and 91.
  
  Prime factorization of 35, 56 and 91 is:
  
  35 = 5 × 7
  
  $56=2^{3} \times 7$
  
  91 = 7 × 13
  
  LCM = product of greatest power of each prime factor involved in the numbers $=2^{3} \times 5 \times 7 \times 13=3640$
  
  Least number which can be divided by 35, 56 and 91 is 3640.
  
  Least number which when divided by 35, 56 and 91 leaves the same remainder 7 is 3640 + 7 = 3647.
  
  Thus, the required number is 3647.
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math question and a detailed solution to the problem. The question asks for the least number that, when divided by 35, 56, and 91, leaves the same remainder of 7 in each case. The solution involves finding the least common multiple (LCM) of 35, 56, and 91 and then adding the remainder to the LCM to get the final answer.
  
  Label: question-and-answer