text: # How much kerosene was burned if 688 MJ was released?
  
  1) Let’s calculate the mass of the burnt kerosene.
  
  Q = q * m, where Q is the energy released during the combustion of kerosene (Q = 688 MJ = 688 * 10 ^ 6 J), q is the specific heat of combustion (for kerosene we take q = 4.6 * 10 ^ 7 J / kg) , m is the mass of burnt kerosene.
  
  m = Q / q = 688 * 10 ^ 6 / 4.6 * 10 ^ 7 = 14.96 kg.
  
  2) Calculate the volume of kerosene burned:
  
  V = m / ρ, where ρ is the density (for kerosene ρ = 810 kg / m3).
  
  V = m / ρ = 14.96 / 810 = 0.018 m3.
  
  Answer: 0.018 m3 of kerosene was burned.
  
  One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
explanation: The document contains a math question and a detailed step-by-step solution to the problem. The question is about calculating the amount of kerosene burned given the energy released. The solution involves calculating the mass of the burnt kerosene and then the volume of kerosene burned. The answer is provided as 0.018 m³ of kerosene.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # How much kerosene was burned if 688 MJ was released?
  
  1) Let’s calculate the mass of the burnt kerosene.
  
  Q = q * m, where Q is the energy released during the combustion of kerosene (Q = 688 MJ = 688 * 10 ^ 6 J), q is the specific heat of combustion (for kerosene we take q = 4.6 * 10 ^ 7 J / kg) , m is the mass of burnt kerosene.
  
  m = Q / q = 688 * 10 ^ 6 / 4.6 * 10 ^ 7 = 14.96 kg.
  
  2) Calculate the volume of kerosene burned:
  
  V = m / ρ, where ρ is the density (for kerosene ρ = 810 kg / m3).
  
  V = m / ρ = 14.96 / 810 = 0.018 m3.
  
  Answer: 0.018 m3 of kerosene was burned.
  
  One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math question and a detailed step-by-step solution to the problem. The question is about calculating the amount of kerosene burned given the energy released. The solution involves calculating the mass of the burnt kerosene and then the volume of kerosene burned. The answer is provided as 0.018 m³ of kerosene.
  
  Label: question-and-answer