text: ## Algebra 1
  
  Solution:($\frac{7}{10}$,$\frac{-4}{5}$)
  Given: 4x+y=2 and 3y+2x=-1 3(4x+y=2)=12x+3y=6 (12x+3y)-(3y+2x)=6-(-1) (Subtract two equations) 12x+3y-3y-2x=7 (Simplify) 12x-2x=7 (Simplify) 10x=7 x=$\frac{7}{10}$ (Divide both sides by 10) Plug in value of x: 4($\frac{7}{10}$)+y=2 =>$\frac{14}{5}$+y=2 => y=2-$\frac{14}{5}$=>y=$\frac{-4}{5}$ Solution ($\frac{7}{10}$,$\frac{-4}{5}$)
explanation: The document contains a detailed solution to a system of linear equations. It shows the steps to solve for the variables \( x \) and \( y \) given the equations \( 4x + y = 2 \) and \( 3y + 2x = -1 \). The solution is provided as \( \left( \frac{7}{10}, \frac{-4}{5} \right) \).
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: ## Algebra 1
  
  Solution:($\frac{7}{10}$,$\frac{-4}{5}$)
  Given: 4x+y=2 and 3y+2x=-1 3(4x+y=2)=12x+3y=6 (12x+3y)-(3y+2x)=6-(-1) (Subtract two equations) 12x+3y-3y-2x=7 (Simplify) 12x-2x=7 (Simplify) 10x=7 x=$\frac{7}{10}$ (Divide both sides by 10) Plug in value of x: 4($\frac{7}{10}$)+y=2 =>$\frac{14}{5}$+y=2 => y=2-$\frac{14}{5}$=>y=$\frac{-4}{5}$ Solution ($\frac{7}{10}$,$\frac{-4}{5}$)
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a detailed solution to a system of linear equations. It shows the steps to solve for the variables \( x \) and \( y \) given the equations \( 4x + y = 2 \) and \( 3y + 2x = -1 \). The solution is provided as \( \left( \frac{7}{10}, \frac{-4}{5} \right) \).
  
  Label: question-and-answer