text: # How do you find the derivative of 2x^2+x-1?
  
  Apr 13, 2017
  
  $\frac{\mathrm{dy}}{\mathrm{dx}} \left(2 {x}^{2} + x - 1\right) = 4 x + 1$
  
  #### Explanation:
  
  Use the power rule $r {\left(a\right)}^{r - 1}$ and recall that the derivative of a constant is $0$
  
  Therefore the derivative is,
  
  $\frac{\mathrm{dy}}{\mathrm{dx}} = 2 \cdot 2 {x}^{2 - 1} + 1 {x}^{1 - 0} - 0$
  
  $\frac{\mathrm{dy}}{\mathrm{dx}} = 4 x + 1$
explanation: The document contains a math question asking how to find the derivative of the function \(2x^2 + x - 1\), and it also provides the answer along with an explanation of the steps involved in finding the derivative.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # How do you find the derivative of 2x^2+x-1?
  
  Apr 13, 2017
  
  $\frac{\mathrm{dy}}{\mathrm{dx}} \left(2 {x}^{2} + x - 1\right) = 4 x + 1$
  
  #### Explanation:
  
  Use the power rule $r {\left(a\right)}^{r - 1}$ and recall that the derivative of a constant is $0$
  
  Therefore the derivative is,
  
  $\frac{\mathrm{dy}}{\mathrm{dx}} = 2 \cdot 2 {x}^{2 - 1} + 1 {x}^{1 - 0} - 0$
  
  $\frac{\mathrm{dy}}{\mathrm{dx}} = 4 x + 1$
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math question asking how to find the derivative of the function \(2x^2 + x - 1\), and it also provides the answer along with an explanation of the steps involved in finding the derivative.
  
  Label: question-and-answer