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  ## Algebra (all content)
  
  ### Unit 10: Lesson 29
  
  Polynomial identities with complex numbers
  
  # Complex numbers & sum of squares factorization
  
  Learn how expressions of the form x^2+y^2 can be factored into linear factors. This would not be possible without the aid of complex numbers! Created by Sal Khan.
  
  ## Video transcript
  
  Voiceover:Long ago in algebra class, we learned to factor things like X squared minus Y squared. We saw that this was a difference of squares that you could factor this as X plus Y, times X minus Y. This is a little bit of a refresher, you can multiply these two together to verify you get X squared minus Y squared. In fact, let's just do that for fun. X times X is X squared, X times negative Y is negative XY, Y times X is positive XY, and then Y times negative Y is minus Y squared. These two middle terms cancel out and your left with X squared minus Y squared. What I want to tackle in this video is something that we didn't know how to factor before and that's the sum of the squares. So if we were to factor X, let me use a brighter color, if we want to try to factor X squared plus Y squared, before we knew about imaginary numbers, complex numbers, we didn't know how to factor this. But now that we do, what I want to try to do and I encourage you actually to pause the video and try to do it before me, is to try to express this as a difference of squares, using the imaginary unit I. So let's try to do this. So the first we want to write as a difference of squares, so X square we'll just keep as X squared, but now I want to write this part, I want to write the second part, right over here, as subtracting a squares. I want to subtract a square. So we could write this part as subtracting negative Y squared, obviously you subtract a negative that's the same thing as adding. Now how does this help us? Well this is the same thing as subtracting negative one times Y squared. If we wanted to write this whole thing as a square, how would we do it? Well we have Y squared and what's negative one the square of? Well we know by definition, negative one is equal to I squared or that I squared is equal to negative one. Let's rewrite it that way, so this is going to be equal to X squared minus, instead of negative one, I'll write that as I squared, minus I squared Y squared. All I did was replace this negative one with an I squared. And now this is interesting. I think you see where this is going, but I'll just make it very explicit. This is now X squared minus IY squared. And just like that, using I, I've been able to write this sum of squares as a difference of squares. And now we can factor just the exact same way we factored this original expression. This thing is going to be equal to X plus IY times X minus IY. And we can verify that if you multiply these two expressions together, you're going to get X squared plus Y squared. Let's do that, X times X is X squared. X times negative IY is negative IXY, and then IY times X is positive IXY, and then finally let me do this in a color I'm not using yet, finally, IY times negative IY is equal to negative I squared Y squared. Now these middle two terms cancel out, I squared is negative one, and so we have X squared minus negative one Y squared, so this is subtracting a negative, the same thing as adding a positive, and so this simplifies to X squared plus Y squared. So hopefully this now gives you an appreciation of using the complex imaginary unit I, how you can actually factor this expression into essentially the product of two complex numbers.
explanation: The document is a transcript from a video lesson on algebra, specifically focusing on polynomial identities with complex numbers. The lesson explains how to factor the sum of squares using the imaginary unit \( i \). The text includes a detailed step-by-step explanation of how to rewrite \( x^2 + y^2 \) as a difference of squares and then factor it into \( (x + iy)(x - iy) \).
  
  The document contains a question and an answer, as it explains the process of factoring the sum of squares and verifies the result.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: If you're seeing this message, it means we're having trouble loading external resources on our website.
  
  If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked.
  
  ## Algebra (all content)
  
  ### Unit 10: Lesson 29
  
  Polynomial identities with complex numbers
  
  # Complex numbers & sum of squares factorization
  
  Learn how expressions of the form x^2+y^2 can be factored into linear factors. This would not be possible without the aid of complex numbers! Created by Sal Khan.
  
  ## Video transcript
  
  Voiceover:Long ago in algebra class, we learned to factor things like X squared minus Y squared. We saw that this was a difference of squares that you could factor this as X plus Y, times X minus Y. This is a little bit of a refresher, you can multiply these two together to verify you get X squared minus Y squared. In fact, let's just do that for fun. X times X is X squared, X times negative Y is negative XY, Y times X is positive XY, and then Y times negative Y is minus Y squared. These two middle terms cancel out and your left with X squared minus Y squared. What I want to tackle in this video is something that we didn't know how to factor before and that's the sum of the squares. So if we were to factor X, let me use a brighter color, if we want to try to factor X squared plus Y squared, before we knew about imaginary numbers, complex numbers, we didn't know how to factor this. But now that we do, what I want to try to do and I encourage you actually to pause the video and try to do it before me, is to try to express this as a difference of squares, using the imaginary unit I. So let's try to do this. So the first we want to write as a difference of squares, so X square we'll just keep as X squared, but now I want to write this part, I want to write the second part, right over here, as subtracting a squares. I want to subtract a square. So we could write this part as subtracting negative Y squared, obviously you subtract a negative that's the same thing as adding. Now how does this help us? Well this is the same thing as subtracting negative one times Y squared. If we wanted to write this whole thing as a square, how would we do it? Well we have Y squared and what's negative one the square of? Well we know by definition, negative one is equal to I squared or that I squared is equal to negative one. Let's rewrite it that way, so this is going to be equal to X squared minus, instead of negative one, I'll write that as I squared, minus I squared Y squared. All I did was replace this negative one with an I squared. And now this is interesting. I think you see where this is going, but I'll just make it very explicit. This is now X squared minus IY squared. And just like that, using I, I've been able to write this sum of squares as a difference of squares. And now we can factor just the exact same way we factored this original expression. This thing is going to be equal to X plus IY times X minus IY. And we can verify that if you multiply these two expressions together, you're going to get X squared plus Y squared. Let's do that, X times X is X squared. X times negative IY is negative IXY, and then IY times X is positive IXY, and then finally let me do this in a color I'm not using yet, finally, IY times negative IY is equal to negative I squared Y squared. Now these middle two terms cancel out, I squared is negative one, and so we have X squared minus negative one Y squared, so this is subtracting a negative, the same thing as adding a positive, and so this simplifies to X squared plus Y squared. So hopefully this now gives you an appreciation of using the complex imaginary unit I, how you can actually factor this expression into essentially the product of two complex numbers.
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document is a transcript from a video lesson on algebra, specifically focusing on polynomial identities with complex numbers. The lesson explains how to factor the sum of squares using the imaginary unit \( i \). The text includes a detailed step-by-step explanation of how to rewrite \( x^2 + y^2 \) as a difference of squares and then factor it into \( (x + iy)(x - iy) \).
  
  The document contains a question and an answer, as it explains the process of factoring the sum of squares and verifies the result.
  
  Label: question-and-answer