text: # The car starts off with an acceleration of 0.2 ms2 and reaches a speed of 18 km / h.
  
  The car starts off with an acceleration of 0.2 ms2 and reaches a speed of 18 km / h. Determine the work done by the car in this area, if the traction force is 3 kN
  
  a = 0.2 m / s2.
  
  V0 = 0 m / s.
  
  V = 18 km / h = 5 m / s.
  
  Ft = 3 kN = 3000 N.
  
  At -?
  
  We express the work of the traction force of the car Am by the formula: At = Ft * S * cosα. Since the direction of the traction force Ft of the car coincides with the direction of its movement, then ∠α = 0 °.
  
  We express the movement of the car S by the formula: S = (V ^ 2 – V0 ^ 2) / 2 * a.
  
  Since the car starts to move V0 = 0 m / s, the formula will take the form: S = V ^ 2/2 * a.
  
  Am = Ft * V ^ 2/2 * a.
  
  Am = 3000 N * (5 m / s) ^ 2/2 * 0.2 m / s2 = 187500 J.
  
  Answer: on the site, the car does work Am = 187500 J.
  
  One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
explanation: The document contains a math problem and its solution. The problem involves calculating the work done by a car's traction force given its acceleration, initial and final velocities, and the traction force. The solution is provided, and the answer is 187,500 J. The document also includes a brief statement about the importance of education, which is not related to the math problem.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # The car starts off with an acceleration of 0.2 ms2 and reaches a speed of 18 km / h.
  
  The car starts off with an acceleration of 0.2 ms2 and reaches a speed of 18 km / h. Determine the work done by the car in this area, if the traction force is 3 kN
  
  a = 0.2 m / s2.
  
  V0 = 0 m / s.
  
  V = 18 km / h = 5 m / s.
  
  Ft = 3 kN = 3000 N.
  
  At -?
  
  We express the work of the traction force of the car Am by the formula: At = Ft * S * cosα. Since the direction of the traction force Ft of the car coincides with the direction of its movement, then ∠α = 0 °.
  
  We express the movement of the car S by the formula: S = (V ^ 2 – V0 ^ 2) / 2 * a.
  
  Since the car starts to move V0 = 0 m / s, the formula will take the form: S = V ^ 2/2 * a.
  
  Am = Ft * V ^ 2/2 * a.
  
  Am = 3000 N * (5 m / s) ^ 2/2 * 0.2 m / s2 = 187500 J.
  
  Answer: on the site, the car does work Am = 187500 J.
  
  One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math problem and its solution. The problem involves calculating the work done by a car's traction force given its acceleration, initial and final velocities, and the traction force. The solution is provided, and the answer is 187,500 J. The document also includes a brief statement about the importance of education, which is not related to the math problem.
  
  Label: question-and-answer