text: # 4x+2=16
  
  jess1999 | Student
  
  4x + 2 = 16
  
  First we have to get " x " alone, so subtract 2 on both sides
  
  By subtracting, you should get
  
  4x = 14 now divide both sides by 4
  
  By dividing, you should get
  
  X = 14/4 simplify
  
  atyourservice | Student
  
  4x+2=16 First combine like terms
  
  -2   -2
  
  4x=14
  
  `(4x)/4 = 14/4`
  
  `x=3.5`
  
  llltkl | Student
  
  To solve for x:
  
  `4x+2=16`
  
  `rArr 4x=16-2`
  
  `rArr 4x=14`
  
  `rArr x=14/4=7/2`
  
  Therefore the value of x is `7/2` or `3 1/2` .
explanation: The document contains a math problem, specifically a linear equation, and multiple answers provided by different students. Each student has solved the equation step-by-step, leading to the same solution.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # 4x+2=16
  
  jess1999 | Student
  
  4x + 2 = 16
  
  First we have to get " x " alone, so subtract 2 on both sides
  
  By subtracting, you should get
  
  4x = 14 now divide both sides by 4
  
  By dividing, you should get
  
  X = 14/4 simplify
  
  atyourservice | Student
  
  4x+2=16 First combine like terms
  
  -2   -2
  
  4x=14
  
  `(4x)/4 = 14/4`
  
  `x=3.5`
  
  llltkl | Student
  
  To solve for x:
  
  `4x+2=16`
  
  `rArr 4x=16-2`
  
  `rArr 4x=14`
  
  `rArr x=14/4=7/2`
  
  Therefore the value of x is `7/2` or `3 1/2` .
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math problem, specifically a linear equation, and multiple answers provided by different students. Each student has solved the equation step-by-step, leading to the same solution.
  
  Label: question-and-answer