text: Precalculus: Mathematics for Calculus, 7th Edition
  
  $\frac{2}{3}y+\frac{1}{2}(y-3)=\frac{y+1}{4}$ Solution:$y=\frac{21}{11}$
  1. $\frac{2}{3}y+\frac{1}{2}(y-3)=\frac{y+1}{4}$ 2. Distribute $\frac{1}{2}$ to simply the equation to:$\frac{2}{3}y+\frac{1}{2}y-\frac{3}{2}=\frac{y+1}{4}$ 3. Multiply both sides by 4: $4\frac{2}{3}y-6=y+1$ 4. Subtract y from both sides:$3\frac{2}{3}y-6=1$ 5. Add 6 to both sides: $3\frac{2}{3}y=7$ 6. Change $3\frac{2}{3}$ to an improper fraction: $\frac{11}{3}y = 7$ 7. Divide both sides by $\frac{11}{3}$ (equivalent to multiplying both sides by $\frac{3}{11}$) :$y=\frac{7}{\frac{11}{3}} = \frac{21}{11}$
explanation: The document contains a precalculus problem and its solution. The problem is a linear equation in one variable, and the solution is provided step-by-step, leading to the final answer \( y = \frac{21}{11} \).
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: Precalculus: Mathematics for Calculus, 7th Edition
  
  $\frac{2}{3}y+\frac{1}{2}(y-3)=\frac{y+1}{4}$ Solution:$y=\frac{21}{11}$
  1. $\frac{2}{3}y+\frac{1}{2}(y-3)=\frac{y+1}{4}$ 2. Distribute $\frac{1}{2}$ to simply the equation to:$\frac{2}{3}y+\frac{1}{2}y-\frac{3}{2}=\frac{y+1}{4}$ 3. Multiply both sides by 4: $4\frac{2}{3}y-6=y+1$ 4. Subtract y from both sides:$3\frac{2}{3}y-6=1$ 5. Add 6 to both sides: $3\frac{2}{3}y=7$ 6. Change $3\frac{2}{3}$ to an improper fraction: $\frac{11}{3}y = 7$ 7. Divide both sides by $\frac{11}{3}$ (equivalent to multiplying both sides by $\frac{3}{11}$) :$y=\frac{7}{\frac{11}{3}} = \frac{21}{11}$
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a precalculus problem and its solution. The problem is a linear equation in one variable, and the solution is provided step-by-step, leading to the final answer \( y = \frac{21}{11} \).
  
  Label: question-and-answer