text: ## Geometry: Common Core (15th Edition)
  
  $m = -1$
  We are given the two points X $(0, a)$ and Y $(-a, 2a)$. Let's use the formula to find the slope $m$ given two points: $m = \frac{y_2 - y_1}{x_2 - x_1}$, where $(x_1, y_1)$ and $(x_2, y_2)$ are points on the line. Let's plug in the values into this formula: $m = \frac{2a - a}{-a - 0}$ Simplify the numerator and denominator: $m = \frac{a}{-a}$ Divide both the numerator and denominator by their greatest common factor, $a$: $m = -1$
explanation: The document contains a math problem and its solution. It provides the coordinates of two points and uses the slope formula to determine the slope of the line passing through these points. The final answer is given as \( m = -1 \).
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: ## Geometry: Common Core (15th Edition)
  
  $m = -1$
  We are given the two points X $(0, a)$ and Y $(-a, 2a)$. Let's use the formula to find the slope $m$ given two points: $m = \frac{y_2 - y_1}{x_2 - x_1}$, where $(x_1, y_1)$ and $(x_2, y_2)$ are points on the line. Let's plug in the values into this formula: $m = \frac{2a - a}{-a - 0}$ Simplify the numerator and denominator: $m = \frac{a}{-a}$ Divide both the numerator and denominator by their greatest common factor, $a$: $m = -1$
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math problem and its solution. It provides the coordinates of two points and uses the slope formula to determine the slope of the line passing through these points. The final answer is given as \( m = -1 \).
  
  Label: question-and-answer