text: # Physics
  
  posted by on .
  
  I have been given this question and with very little knowledge of physics and a book and flex studies that I am not finding very explanitory. I am not sure I am on the correct path as the vlaues I have seem very large. I would appreciate any help/assistance anyone could give.
  Question
  You measure the blood pressure at the bicep and find that it is 140 mmHg systolic and 80mmHg diastolic. What would you expect the blood pressure to be at the top of the head given that this point is 45cm above the measurement point? Remember thisis a gauge pressure and give your answers in both mmHg and kPa. (The density of blood is about 1060 kgm^-3)
  
  This is what I have done but I am so unsure on what I am doing.
  
  1. Converted the systolic and diastolic blood pressure into Pa.
  Systolic Blood pressure= 140mmHg x 133.322Pa/1mmHg= 18665 Pa
  Diastolic Blood pressure= 80mmHg x 133.322Pa/1mmHg= 10665.76Pa
  
  2. Due to being gauge pressure I then converted to actual pressure. (this is something I am very unsure if it is needed)
  P1 actual systolic pressure= 18665Pa + 101325Pa = 119990Pa
  P1 actual diastolic pressure= 10665.76Pa + 101325Pa = 111990.76Pa
  
  3. Due to the change in hieght I named the top of the head P2.
  P2 - P1=pg h2-h1
  P2=P1+pgh
  P2 systolic = 119990Pa + (1060kgm^-3 x 9.81 m s^-2 x 45m) = 587927Pa
  P2 diastolic = 111990.76 + ( 1060kgm^-3 x 9.81 m s^-2 x 45m) = 579928Pa
  
  4. I then converted the P2 into kPa.
  P2 systolic kPa = 587927Pa x .1kPa/100Pa = 587.9kPa
  P2 diastolic KPa = 579928Pa x .1kPa/100Pa = 579.9kPa
  
  5. I then converted the P2 into mmHg. (this seems very large)
  P2 systolic mmHg = 587927Pa x 1mmHg/133.322Pa = 4410mmHg
  P2 diastolic mmHg = 579928Pa x 1mmHg/133.322Pa=4350mmHg
  
  I have spent a lot of time trying to work this out. If you can please assist me I would be very greatful
  
  • Physics - ,
  
  Both pressures will be higher by pressure = (rho)*g*H when measured at elevation H higher than the arm. rho is the density of blood. Assume it is the same as water
  
  Your numbers are much too high.
  
  Atmospheric pressure is 760 mm Hg
  
  450 mm higher elevation is equivalent to 45/13.6 = 33 mm Hg higher pressure, measured in mm Hg. The 13.6 factor id the ratio of the densities of mercury and water.
  
  • Physics (correction) - ,
  
  Pressures in the head will be lower, not higher, because of the higher elevation than the measurement point.
  
  The number is also wrong:
  
  It should be 45 mmHg/13.6 = 3.3 mmHg lower
  
  I just wasn't thinking and apologize for the errors.
  
  • Physics - ,
  
  Thank you for your help. I am still unsure on the formulas I am meant to be using and when I am meant to be converting from mmHg to Pa.
explanation: The document is a physics problem related to blood pressure and its variation with height. It includes a detailed attempt by the user to solve the problem, followed by a response from an instructor or another user providing corrections and clarifications. The document contains both a question and an answer.
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distilabel_metadata.content: # Physics
  
  posted by on .
  
  I have been given this question and with very little knowledge of physics and a book and flex studies that I am not finding very explanitory. I am not sure I am on the correct path as the vlaues I have seem very large. I would appreciate any help/assistance anyone could give.
  Question
  You measure the blood pressure at the bicep and find that it is 140 mmHg systolic and 80mmHg diastolic. What would you expect the blood pressure to be at the top of the head given that this point is 45cm above the measurement point? Remember thisis a gauge pressure and give your answers in both mmHg and kPa. (The density of blood is about 1060 kgm^-3)
  
  This is what I have done but I am so unsure on what I am doing.
  
  1. Converted the systolic and diastolic blood pressure into Pa.
  Systolic Blood pressure= 140mmHg x 133.322Pa/1mmHg= 18665 Pa
  Diastolic Blood pressure= 80mmHg x 133.322Pa/1mmHg= 10665.76Pa
  
  2. Due to being gauge pressure I then converted to actual pressure. (this is something I am very unsure if it is needed)
  P1 actual systolic pressure= 18665Pa + 101325Pa = 119990Pa
  P1 actual diastolic pressure= 10665.76Pa + 101325Pa = 111990.76Pa
  
  3. Due to the change in hieght I named the top of the head P2.
  P2 - P1=pg h2-h1
  P2=P1+pgh
  P2 systolic = 119990Pa + (1060kgm^-3 x 9.81 m s^-2 x 45m) = 587927Pa
  P2 diastolic = 111990.76 + ( 1060kgm^-3 x 9.81 m s^-2 x 45m) = 579928Pa
  
  4. I then converted the P2 into kPa.
  P2 systolic kPa = 587927Pa x .1kPa/100Pa = 587.9kPa
  P2 diastolic KPa = 579928Pa x .1kPa/100Pa = 579.9kPa
  
  5. I then converted the P2 into mmHg. (this seems very large)
  P2 systolic mmHg = 587927Pa x 1mmHg/133.322Pa = 4410mmHg
  P2 diastolic mmHg = 579928Pa x 1mmHg/133.322Pa=4350mmHg
  
  I have spent a lot of time trying to work this out. If you can please assist me I would be very greatful
  
  • Physics - ,
  
  Both pressures will be higher by pressure = (rho)*g*H when measured at elevation H higher than the arm. rho is the density of blood. Assume it is the same as water
  
  Your numbers are much too high.
  
  Atmospheric pressure is 760 mm Hg
  
  450 mm higher elevation is equivalent to 45/13.6 = 33 mm Hg higher pressure, measured in mm Hg. The 13.6 factor id the ratio of the densities of mercury and water.
  
  • Physics (correction) - ,
  
  Pressures in the head will be lower, not higher, because of the higher elevation than the measurement point.
  
  The number is also wrong:
  
  It should be 45 mmHg/13.6 = 3.3 mmHg lower
  
  I just wasn't thinking and apologize for the errors.
  
  • Physics - ,
  
  Thank you for your help. I am still unsure on the formulas I am meant to be using and when I am meant to be converting from mmHg to Pa.
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document is a physics problem related to blood pressure and its variation with height. It includes a detailed attempt by the user to solve the problem, followed by a response from an instructor or another user providing corrections and clarifications. The document contains both a question and an answer.
  
  Label: question-and-answer