text: # Question ffe51
  
  Sep 10, 2017
  
  $\text{0.24 moles}$
  
  #### Explanation:
  
  For starters, you know that $1$ mole of sodium chloride contains $1$ mole of sodium cations, ${\text{Na}}^{+}$, and $1$ mole of chloride anions, ${\text{Cl}}^{-}$.
  
  This is equivalent to saying that in order to have $1$ mole of sodium chloride, you need to combine $1$ mole of sodium atoms and $1$ mole of chlorine atoms.
  
  In order to find the number of moles of sodium chloride present in your sample, you can use the molar mass of this compound, i.e. the mass of exactly $1$ mole of sodium chloride.
  
  You will have
  
  14 color(red)(cancel(color(black)("g"))) * overbrace("1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))))^(color(blue)("the molar mass of NaCl")) = "0.2396 moles NaCl"#
  
  This means that your sample will contain
  
  $0.2396 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{moles NaCl"))) * "1 mole Cl"/(1color(red)(cancel(color(black)("mole NaCl")))) = color(darkgreen)(ul(color(black)("0.24 moles Cl}}}}$
  
  The answer is rounded to two sig figs, the number of sig figs you have for the mass of sodium chloride.
  
  So, you can say that $\text{14 g}$ of sodium chloride will contain $0.24$ moles of chloride anions, ${\text{Cl}}^{-}$, i.e. $0.24$ moles of chlorine atoms, $\text{Cl}$, reacted to make this sample.
explanation: The document is a detailed explanation of a chemistry problem that involves calculating the number of moles of chloride anions in a given mass of sodium chloride. It includes the question, the step-by-step solution, and the final answer.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # Question ffe51
  
  Sep 10, 2017
  
  $\text{0.24 moles}$
  
  #### Explanation:
  
  For starters, you know that $1$ mole of sodium chloride contains $1$ mole of sodium cations, ${\text{Na}}^{+}$, and $1$ mole of chloride anions, ${\text{Cl}}^{-}$.
  
  This is equivalent to saying that in order to have $1$ mole of sodium chloride, you need to combine $1$ mole of sodium atoms and $1$ mole of chlorine atoms.
  
  In order to find the number of moles of sodium chloride present in your sample, you can use the molar mass of this compound, i.e. the mass of exactly $1$ mole of sodium chloride.
  
  You will have
  
  14 color(red)(cancel(color(black)("g"))) * overbrace("1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))))^(color(blue)("the molar mass of NaCl")) = "0.2396 moles NaCl"#
  
  This means that your sample will contain
  
  $0.2396 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{moles NaCl"))) * "1 mole Cl"/(1color(red)(cancel(color(black)("mole NaCl")))) = color(darkgreen)(ul(color(black)("0.24 moles Cl}}}}$
  
  The answer is rounded to two sig figs, the number of sig figs you have for the mass of sodium chloride.
  
  So, you can say that $\text{14 g}$ of sodium chloride will contain $0.24$ moles of chloride anions, ${\text{Cl}}^{-}$, i.e. $0.24$ moles of chlorine atoms, $\text{Cl}$, reacted to make this sample.
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document is a detailed explanation of a chemistry problem that involves calculating the number of moles of chloride anions in a given mass of sodium chloride. It includes the question, the step-by-step solution, and the final answer.
  
  Label: question-and-answer