text: ## Essential University Physics: Volume 1 (3rd Edition)
  
  We know that $t=\sqrt{\frac{2h}{g}}$ We plug in the known values to obtain: $t=\sqrt{\frac{(2)(1.9)}{9.8}}=0.623s$ Now we can find the horizontal speed as $v=\frac{x}{t}$ We plug in the known values to obtain: $v=\frac{4.5}{0.623}=7.2\frac{m}{s}$
explanation: The text extract is from a physics textbook and contains a series of calculations to determine the time of fall and the horizontal speed of an object. It includes the steps and formulas used to solve the problem, but it does not present a question; instead, it provides a solution to a problem.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: ## Essential University Physics: Volume 1 (3rd Edition)
  
  We know that $t=\sqrt{\frac{2h}{g}}$ We plug in the known values to obtain: $t=\sqrt{\frac{(2)(1.9)}{9.8}}=0.623s$ Now we can find the horizontal speed as $v=\frac{x}{t}$ We plug in the known values to obtain: $v=\frac{4.5}{0.623}=7.2\frac{m}{s}$
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The text extract is from a physics textbook and contains a series of calculations to determine the time of fall and the horizontal speed of an object. It includes the steps and formulas used to solve the problem, but it does not present a question; instead, it provides a solution to a problem.
  
  Label: no-question