text: # Q.A parachutist bails out from an aero plane and after dropping through a distance of 40m, he opens his parachute and decelerates at 2m/s. If he reaches the ground with a speed of 2m/s, how long is in air? At what height did he bail out of the plane?
  
  Initial velocity u = 0
  Travels 40 m in time t with acceleration g.​
  
  • 8
  
  u = 0, g = 9.8 ms-2, s= 40m , t=?, v=?
  
  s= ut + 1/2 gt2
  
  40= 0 + 1/2 * 9.8* t2
  
  t= root 80/9.8 = 20/7s = 2.86s
  
  v = u+gt = 0+9.8*20/7 = 28ms-1
  
  when the parachutist decdelarates uniformly
  
  u= 28 m/s , a= -2 ms-2 ,v= 2 m/s
  
  t= v-u/t = 2-28/-2 = 13s
  
  s= ut+1/2at2 =28*13- 1/2*2*132
  
  = 364-169 = 195 m
  
  total time in air = 2.86+13 = 15.86 s
  
  height at which parachutist bails out = 40+195 = 235m
  
  • 21
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explanation: The document contains a detailed math problem involving the motion of a parachutist, including the initial conditions, the equations used, and the step-by-step solution to find the total time in the air and the height at which the parachutist bailed out. The document also includes the final answers to the questions posed.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # Q.A parachutist bails out from an aero plane and after dropping through a distance of 40m, he opens his parachute and decelerates at 2m/s. If he reaches the ground with a speed of 2m/s, how long is in air? At what height did he bail out of the plane?
  
  Initial velocity u = 0
  Travels 40 m in time t with acceleration g.​
  
  • 8
  
  u = 0, g = 9.8 ms-2, s= 40m , t=?, v=?
  
  s= ut + 1/2 gt2
  
  40= 0 + 1/2 * 9.8* t2
  
  t= root 80/9.8 = 20/7s = 2.86s
  
  v = u+gt = 0+9.8*20/7 = 28ms-1
  
  when the parachutist decdelarates uniformly
  
  u= 28 m/s , a= -2 ms-2 ,v= 2 m/s
  
  t= v-u/t = 2-28/-2 = 13s
  
  s= ut+1/2at2 =28*13- 1/2*2*132
  
  = 364-169 = 195 m
  
  total time in air = 2.86+13 = 15.86 s
  
  height at which parachutist bails out = 40+195 = 235m
  
  • 21
  What are you looking for?
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a detailed math problem involving the motion of a parachutist, including the initial conditions, the equations used, and the step-by-step solution to find the total time in the air and the height at which the parachutist bailed out. The document also includes the final answers to the questions posed.
  
  Label: question-and-answer