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  # Is x > y? 1) (a^n)*x > (a^n)*y 2) 3n + 1 is odd open
  
  Author Message
  Manager
  Joined: 28 Feb 2003
  Posts: 100
  Is x > y? 1) (a^n)*x > (a^n)*y 2) 3n + 1 is odd open [#permalink]
  
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  29 May 2003, 05:52
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  Is x > y?
  
  1) (a^n)*x > (a^n)*y
  2) 3n + 1 is odd
  
  open to debate......i hope i don't screw up on this one like the last one
  Manager
  Joined: 25 May 2003
  Posts: 54
  
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  29 May 2003, 13:22
  am i missing something here?? seems suspiciously easy...A?
  Manager
  Joined: 12 Mar 2003
  Posts: 59
  
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  29 May 2003, 19:44
  Ans : C
  
  1) Insuff, since a and n can be -ve or +ve
  
  2) Insuff, n is even - nothing about x and y
  
  Combined : n is even, and if a is -ve or +ve a^n can be divided out.
  => x>y
  Suff
  Intern
  Joined: 25 May 2003
  Posts: 17
  Location: Thailand
  
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  29 May 2003, 21:40
  In my view, I vote for C
  supposed that X and Y are positive 5 and 2 repectively.
  
  Clearly, the statement (I) doesn't tell the values of a^n. If a^n is negative value, X may be less than Y. On the contrary, if a^n is positive, X will be more than Y. Thus, Insufficient.
  
  The statment II only show the value of n which can be negative or positve,the value of a and the value of x and y. Therefore. Insufficient
  
  Combined them together, Thus, the answer is C because a^n always be positive and therefore, X always be more than Y
  Manager
  Joined: 28 Feb 2003
  Posts: 100
  
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  30 May 2003, 02:41
  I also had C in mind
  
  to prove that x > y, you have to prove that the common number that is multiplied on both sides is POSITIVE.
  
  From 1, a^n can be negative if n is odd and "a" is negative..
  
  however if n is even than a^n will AlWAYS be positive....
  
  therefore both together are sufficient
  Manager
  Joined: 08 Apr 2003
  Posts: 150
  
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  30 May 2003, 02:50
  Hi bhavesh,
  I went on the same lines of reasoning as you gave. I put in C. But, another thing crossed my mind.
  
  The question is x > y ?? So it can be YES or NO, correct
  
  So, even if you say if a is negative and n is odd, you are multiplying the same number on both sides. So they get cancelled anyhow and even if the greater than sign reverses to say x < y , you still have an answer.
  
  Am i right???
  Manager
  Joined: 28 Feb 2003
  Posts: 100
  
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  30 May 2003, 02:54
  if "a" is positive, than x>y...the answer is YES
  
  however if "a" is negative and "n" is odd, than a^n will be negative and in this case x<y.......answer is NO
  
  therefore you cannot say for sure YES or NO.....
  
  depends on sign of "a" and value of "n"
  Founder
  Joined: 04 Dec 2002
  Posts: 15153
  Location: United States (WA)
  GMAT 1: 750 Q49 V42
  
  ### Show Tags
  
  06 Jun 2003, 20:25
  neema wrote:
  Is it C?
  
  you are still a student and you are getting into MBA?
  
  you feel like you are ready?
  
  or you are a different kind of student ?
  Senior Manager
  Joined: 11 Nov 2003
  Posts: 356
  Location: Illinois
  
  ### Show Tags
  
  11 Feb 2004, 11:58
  This one is a very old one.
  
  Quote:
  Is x > y?
  
  1) (a^n)*x > (a^n)*y
  2) 3n + 1 is odd
  
  open to debate......i hope i don't screw up on this one like the last one
  
  The agreed upon answer for this question by all the members who responded to this question in the past is C.
  
  I have following questios.
  
  (1) Should the second statement be given as 3n + 1 is positive odd integer ?
  
  If the word positive is not included then we can take
  
  3n + 1 = -1 => n -2/3 = 0.66666..... (Is this odd or even? )
  
  If the word integer is not included,
  
  Can we consider 3n + 1 = 5.5 ? (This is odd number, correct?)
  => n= 4.5/3 => 1.5 (This should be odd)
  
  I think if these conditions are not included, then the answer should be E.
  
  Finally, please let me know (-1)^1.2 = ?
  
  I thought that 1.2 is considered even number so answer should be 1. But the calculator says invalid input function.
  
  (1.2 here is decimal number = 12/10)[/b]
  Senior Manager
  Joined: 11 Nov 2003
  Posts: 356
  Location: Illinois
  
  ### Show Tags
  
  11 Feb 2004, 12:05
  Quote:
  Finally, please let me know (-1)^1.2 = ?
  
  I thought that 1.2 is considered even number so answer should be 1. But the calculator says invalid input function.
  
  (1.2 here is decimal number = 12/10)
  
  But my other questions remain.
  11 Feb 2004, 12:05
  Display posts from previous: Sort by
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: It is currently 28 Jun 2017, 14:42
  
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  # Events & Promotions
  
  ###### Events & Promotions in June
  Open Detailed Calendar
  
  # Is x > y? 1) (a^n)*x > (a^n)*y 2) 3n + 1 is odd open
  
  Author Message
  Manager
  Joined: 28 Feb 2003
  Posts: 100
  Is x > y? 1) (a^n)*x > (a^n)*y 2) 3n + 1 is odd open [#permalink]
  
  ### Show Tags
  
  29 May 2003, 05:52
  00:00
  
  Difficulty:
  
  (N/A)
  
  Question Stats:
  
  0% (00:00) correct 0% (00:00) wrong based on 0 sessions
  
  ### HideShow timer Statistics
  
  This topic is locked. If you want to discuss this question please re-post it in the respective forum.
  
  Is x > y?
  
  1) (a^n)*x > (a^n)*y
  2) 3n + 1 is odd
  
  open to debate......i hope i don't screw up on this one like the last one
  Manager
  Joined: 25 May 2003
  Posts: 54
  
  ### Show Tags
  
  29 May 2003, 13:22
  am i missing something here?? seems suspiciously easy...A?
  Manager
  Joined: 12 Mar 2003
  Posts: 59
  
  ### Show Tags
  
  29 May 2003, 19:44
  Ans : C
  
  1) Insuff, since a and n can be -ve or +ve
  
  2) Insuff, n is even - nothing about x and y
  
  Combined : n is even, and if a is -ve or +ve a^n can be divided out.
  => x>y
  Suff
  Intern
  Joined: 25 May 2003
  Posts: 17
  Location: Thailand
  
  ### Show Tags
  
  29 May 2003, 21:40
  In my view, I vote for C
  supposed that X and Y are positive 5 and 2 repectively.
  
  Clearly, the statement (I) doesn't tell the values of a^n. If a^n is negative value, X may be less than Y. On the contrary, if a^n is positive, X will be more than Y. Thus, Insufficient.
  
  The statment II only show the value of n which can be negative or positve,the value of a and the value of x and y. Therefore. Insufficient
  
  Combined them together, Thus, the answer is C because a^n always be positive and therefore, X always be more than Y
  Manager
  Joined: 28 Feb 2003
  Posts: 100
  
  ### Show Tags
  
  30 May 2003, 02:41
  I also had C in mind
  
  to prove that x > y, you have to prove that the common number that is multiplied on both sides is POSITIVE.
  
  From 1, a^n can be negative if n is odd and "a" is negative..
  
  however if n is even than a^n will AlWAYS be positive....
  
  therefore both together are sufficient
  Manager
  Joined: 08 Apr 2003
  Posts: 150
  
  ### Show Tags
  
  30 May 2003, 02:50
  Hi bhavesh,
  I went on the same lines of reasoning as you gave. I put in C. But, another thing crossed my mind.
  
  The question is x > y ?? So it can be YES or NO, correct
  
  So, even if you say if a is negative and n is odd, you are multiplying the same number on both sides. So they get cancelled anyhow and even if the greater than sign reverses to say x < y , you still have an answer.
  
  Am i right???
  Manager
  Joined: 28 Feb 2003
  Posts: 100
  
  ### Show Tags
  
  30 May 2003, 02:54
  if "a" is positive, than x>y...the answer is YES
  
  however if "a" is negative and "n" is odd, than a^n will be negative and in this case x<y.......answer is NO
  
  therefore you cannot say for sure YES or NO.....
  
  depends on sign of "a" and value of "n"
  Founder
  Joined: 04 Dec 2002
  Posts: 15153
  Location: United States (WA)
  GMAT 1: 750 Q49 V42
  
  ### Show Tags
  
  06 Jun 2003, 20:25
  neema wrote:
  Is it C?
  
  you are still a student and you are getting into MBA?
  
  you feel like you are ready?
  
  or you are a different kind of student ?
  Senior Manager
  Joined: 11 Nov 2003
  Posts: 356
  Location: Illinois
  
  ### Show Tags
  
  11 Feb 2004, 11:58
  This one is a very old one.
  
  Quote:
  Is x > y?
  
  1) (a^n)*x > (a^n)*y
  2) 3n + 1 is odd
  
  open to debate......i hope i don't screw up on this one like the last one
  
  The agreed upon answer for this question by all the members who responded to this question in the past is C.
  
  I have following questios.
  
  (1) Should the second statement be given as 3n + 1 is positive odd integer ?
  
  If the word positive is not included then we can take
  
  3n + 1 = -1 => n -2/3 = 0.66666..... (Is this odd or even? )
  
  If the word integer is not included,
  
  Can we consider 3n + 1 = 5.5 ? (This is odd number, correct?)
  => n= 4.5/3 => 1.5 (This should be odd)
  
  I think if these conditions are not included, then the answer should be E.
  
  Finally, please let me know (-1)^1.2 = ?
  
  I thought that 1.2 is considered even number so answer should be 1. But the calculator says invalid input function.
  
  (1.2 here is decimal number = 12/10)[/b]
  Senior Manager
  Joined: 11 Nov 2003
  Posts: 356
  Location: Illinois
  
  ### Show Tags
  
  11 Feb 2004, 12:05
  Quote:
  Finally, please let me know (-1)^1.2 = ?
  
  I thought that 1.2 is considered even number so answer should be 1. But the calculator says invalid input function.
  
  (1.2 here is decimal number = 12/10)
  
  But my other questions remain.
  11 Feb 2004, 12:05
  Display posts from previous: Sort by
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The provided text is a GMAT question from a GMAT prep forum. The question is:
  
  **Is x > y?**
  
  1) \((a^n) \cdot x > (a^n) \cdot y\)
  2) \(3n + 1\) is odd
  
  ### Analysis:
  - **Question Type:** This is a Data Sufficiency (DS) question.
  - **Context:** The question asks whether \(x\) is greater than \(y\).
  - **Statements:**
    - **Statement 1:** \((a^n) \cdot x > (a^n) \cdot y\)
      - This statement alone is not sufficient because the sign of \(a^n\) is unknown. If \(a^n\) is positive, then \(x > y\). If \(a^n\) is negative, then \(x < y\).
    - **Statement 2:** \(3n + 1\) is odd
      - This statement alone is not sufficient because it only tells us that \(n\) is even, but it does not provide any information about \(x\) and \(y\).
  
  - **Combined Analysis:**
    - From Statement 2, we know that \(n\) is even.
    - If \(n\) is