text: ## Algebra and Trigonometry 10th Edition
  
  $\lt \dfrac {18}{\sqrt {29}}, \dfrac{ 45}{\sqrt {29}} \gt$
  Since $v$ has the same direction as $u$ and since it is a multiple of a unit vector $n$, we can write it as: $\overrightarrow{v} = < 2 n, 5n>$ To find the unit vector, we must first find the magnitude: $\sqrt {((2n)^{2} + (5n)^{2}} = 3$ or, $144 \ n^2+25 \ n^2 =9$ This implies that $n^2=\dfrac{ 81}{29} \implies n=\dfrac{9}{\sqrt {29}}$ Now, $\overrightarrow{v} = < 2 (\dfrac{9}{\sqrt {29}}), 5 (\dfrac{9}{\sqrt {29}})> = \lt \dfrac {18}{\sqrt {29}}, \dfrac{ 45}{\sqrt {29}} \gt$
explanation: The text extract is from a mathematics textbook, specifically dealing with vector algebra. It provides a detailed solution to a problem involving the calculation of a vector in the same direction as another vector, given the magnitude of the vector. The extract does not contain a question but rather a step-by-step solution to a problem.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: ## Algebra and Trigonometry 10th Edition
  
  $\lt \dfrac {18}{\sqrt {29}}, \dfrac{ 45}{\sqrt {29}} \gt$
  Since $v$ has the same direction as $u$ and since it is a multiple of a unit vector $n$, we can write it as: $\overrightarrow{v} = < 2 n, 5n>$ To find the unit vector, we must first find the magnitude: $\sqrt {((2n)^{2} + (5n)^{2}} = 3$ or, $144 \ n^2+25 \ n^2 =9$ This implies that $n^2=\dfrac{ 81}{29} \implies n=\dfrac{9}{\sqrt {29}}$ Now, $\overrightarrow{v} = < 2 (\dfrac{9}{\sqrt {29}}), 5 (\dfrac{9}{\sqrt {29}})> = \lt \dfrac {18}{\sqrt {29}}, \dfrac{ 45}{\sqrt {29}} \gt$
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The text extract is from a mathematics textbook, specifically dealing with vector algebra. It provides a detailed solution to a problem involving the calculation of a vector in the same direction as another vector, given the magnitude of the vector. The extract does not contain a question but rather a step-by-step solution to a problem.
  
  Label: no-question