text: ## Intermediate Algebra (6th Edition)
  
  $x=7$
  If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x$ and every real number $y$. Therefore, $log_{x}49=2$ is equivalent to $x^{2}=49$. We can now solve for x. Take the square root of both sides. $(x^{2})^{\frac{1}{2}}=(49)^{\frac{1}{2}}$ $x=7$
explanation: The document contains a math problem and its solution. It explains the equivalence between logarithmic and exponential forms and solves the equation \( \log_{x}49 = 2 \) to find \( x = 7 \).
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: ## Intermediate Algebra (6th Edition)
  
  $x=7$
  If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x$ and every real number $y$. Therefore, $log_{x}49=2$ is equivalent to $x^{2}=49$. We can now solve for x. Take the square root of both sides. $(x^{2})^{\frac{1}{2}}=(49)^{\frac{1}{2}}$ $x=7$
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document contains a math problem and its solution. It explains the equivalence between logarithmic and exponential forms and solves the equation \( \log_{x}49 = 2 \) to find \( x = 7 \).
  
  Label: question-and-answer