text: # Perpendicular equation help
  
  • Aug 18th 2012, 09:39 AM
  snickerdoodle27
  Perpendicular equation help
  Find p such that the lines whose equations are 3px + 8y = 5 and 6y - 4px = -1 are perpendicular.
  
  The answer should be p = 2, -2
  
  But I don't understand how to obtain that.
  • Aug 18th 2012, 10:35 AM
  Right the equations in y=mx+b form. In the first equation you'll have the slope $m_1=\frac{-3p}{8}$ and in the second $m_2=\frac{4p}{6}=\frac{2p}{3}$. Use what you know about the relationship between the slopes of perpendicular lines to solve for p.
  Right the equations in y=mx+b form. In the first equation you'll have the slope $m_1=\frac{-3p}{8}$ and in the second $m_2=\frac{4p}{6}=\frac{2p}{3}$. Use what you know about the relationship between the slopes of perpendicular lines to solve for p.
explanation: The document is a forum post and response about a math problem. It contains a question asking how to find the value of \( p \) such that two given lines are perpendicular, and it also includes the correct answer \( p = 2, -2 \). The response provides a method to solve the problem by rewriting the equations in slope-intercept form and using the relationship between the slopes of perpendicular lines.
distilabel_metadata.content: Evaluate the user given text extract and determine if it contains a math question and optionally and answer to this question.
  
  Output rules:
  
  1. Briefly describe the document and mention if it contains a question or a question and answer.
  2. Finalize the output with: Label: no-question,question,question-and-answer,multiple-question,multiple-question-and-answer
distilabel_metadata.role: system
distilabel_metadata.content: # Perpendicular equation help
  
  • Aug 18th 2012, 09:39 AM
  snickerdoodle27
  Perpendicular equation help
  Find p such that the lines whose equations are 3px + 8y = 5 and 6y - 4px = -1 are perpendicular.
  
  The answer should be p = 2, -2
  
  But I don't understand how to obtain that.
  • Aug 18th 2012, 10:35 AM
  Right the equations in y=mx+b form. In the first equation you'll have the slope $m_1=\frac{-3p}{8}$ and in the second $m_2=\frac{4p}{6}=\frac{2p}{3}$. Use what you know about the relationship between the slopes of perpendicular lines to solve for p.
  Right the equations in y=mx+b form. In the first equation you'll have the slope $m_1=\frac{-3p}{8}$ and in the second $m_2=\frac{4p}{6}=\frac{2p}{3}$. Use what you know about the relationship between the slopes of perpendicular lines to solve for p.
distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The document is a forum post and response about a math problem. It contains a question asking how to find the value of \( p \) such that two given lines are perpendicular, and it also includes the correct answer \( p = 2, -2 \). The response provides a method to solve the problem by rewriting the equations in slope-intercept form and using the relationship between the slopes of perpendicular lines.
  
  Label: question-and-answer