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  # Calc03_7 - 3.7 Implicit Differentiation Niagara Falls NY...
  
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  3.7 Implicit Differentiation Niagara Falls, NY & Canada Greg Kelly, Hanford High School, Richland, Washington Photo by Vickie Kelly, 2003
  
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  Before we start, we are going to load the Calculus Tools flash application software to your calculator. 1. Connect the sending and receiving calculators together. 2. On the sending unit, press , and then . 2nd VAR-LINK 2nd F7 Press to select . F4 Calculus Tools 3. On the receiving unit, press . 2nd VAR-LINK 4. On both units, press (Link). F3 4. On the receiving unit, select (Receive). 2 5. On the sending unit, select (Send). 1
  2 2 1 x y + = This is not a function, but it would still be nice to be able to find the slope. 2 2 1 d d d x y dx dx dx + = Do the same thing to both sides. 2 2 0 dy x y dx + = Note use of chain rule. 2 2 dy y x dx = - 2 2 dy x dx y - = dy x dx y = -
  
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  2 2 sin y x y = + 2 2 sin d d d y x y dx dx dx = + This can’t be solved for y . 2 2 cos dy dy x y dx dx = + 2 cos 2 dy dy y x dx dx - = ( 29 2 2 cos dy x y dx = - 2 2 cos dy x dx y = - This technique is called implicit differentiation.
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explanation: The provided text is a transcript or a set of slides from a lesson on implicit differentiation in calculus. It includes an introduction to the topic, an example of how to perform implicit differentiation, and a step-by-step explanation of the process. The text does not contain a specific question or a question-and-answer pair.
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  # Calc03_7 - 3.7 Implicit Differentiation Niagara Falls NY...
  
  This preview shows pages 1–5. Sign up to view the full content.
  
  3.7 Implicit Differentiation Niagara Falls, NY & Canada Greg Kelly, Hanford High School, Richland, Washington Photo by Vickie Kelly, 2003
  
  This preview has intentionally blurred sections. Sign up to view the full version.
  
  View Full Document
  Before we start, we are going to load the Calculus Tools flash application software to your calculator. 1. Connect the sending and receiving calculators together. 2. On the sending unit, press , and then . 2nd VAR-LINK 2nd F7 Press to select . F4 Calculus Tools 3. On the receiving unit, press . 2nd VAR-LINK 4. On both units, press (Link). F3 4. On the receiving unit, select (Receive). 2 5. On the sending unit, select (Send). 1
  2 2 1 x y + = This is not a function, but it would still be nice to be able to find the slope. 2 2 1 d d d x y dx dx dx + = Do the same thing to both sides. 2 2 0 dy x y dx + = Note use of chain rule. 2 2 dy y x dx = - 2 2 dy x dx y - = dy x dx y = -
  
  This preview has intentionally blurred sections. Sign up to view the full version.
  
  View Full Document
  2 2 sin y x y = + 2 2 sin d d d y x y dx dx dx = + This can’t be solved for y . 2 2 cos dy dy x y dx dx = + 2 cos 2 dy dy y x dx dx - = ( 29 2 2 cos dy x y dx = - 2 2 cos dy x dx y = - This technique is called implicit differentiation.
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distilabel_metadata.role: user
distilabel_metadata.raw_output_q_a_detector_0: The provided text is a transcript or a set of slides from a lesson on implicit differentiation in calculus. It includes an introduction to the topic, an example of how to perform implicit differentiation, and a step-by-step explanation of the process. The text does not contain a specific question or a question-and-answer pair.
  
  Label: no-question