text: Pre-Calculus Homework Solutions 123
  
  Pre-Calculus Homework Solutions 123 - CEB 6. SAS 7. A w E w...
  
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  125 Chapter 5 29. m 5 } ( ( y x 2 2 2 2 y x 1 1 ) ) } 5 } 7 0 2 2 3 3 } or 2 } 4 3 } 30. No, R w X w is not an altitude of n RST .The slope of S w T w is 1. The product of the slopes of S w T w and R w X w is 2 } 4 3 } , not 2 1. Thus, the segments are not perpendicular. 31. Given: C w A w > C w B w , A w D w > B w D w Prove: C and D are on the perpendicular bisector of A w B w . Proof: 32. Given: / BAC , P is in the interior of / BAC , PD 5 PE Prove: AP #\$ is the angle bisector of / BAC Proof: A B D P E C C D E B A y x ( 2 1, 6) (3, 3) R S (1, 8) T y x ( 2 1, 6) (3, 3) R S (1, 8) T Statements Reasons 1. / BAC , P is in the interior of / BAC , PD 5 PE 1. Given 2. P w D w > P w E w 2. Def. of > 3. P w D w ' A w B w , P w E w ' A w C w 3. Distance from a point to a line is measured along ' segment from the point to the line. 4. / ADP and / AEP are rt. ? 4. Def. of ' 5. n ADP and n AEP are rt. n s 5. Def. of rt. n 6. A w P w > A w P w 6. Reflexive Property 7. n ADP > n AEP 7. HL 8. / DAP > / EAP 8. CPCTC 9. AP #\$ is the angle bisector of / BAC 9. Def. of / bisector Statements Reasons 1. C w A w > C w B w , A w D w > B w D w 1. Given 2. C w D w > C w D w 2. Reflexive Property 3. n ACD > n BCD 3. SSS 4. / ACD > / BCD 4. CPCTC 5. C w E w > C w E w 5. Reflexive Property 6. n CEA > n
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  Unformatted text preview: CEB 6. SAS 7. A w E w > B w E w 7. CPCTC 8. E is the midpoint of A w B w . 8. Def. of midpoint 9. / CEA > / CEB 9. CPCTC 10. / CEA and / CEB form a linear pair. 10. Def. of linear pair 11. / CEA and / CEB are supplementary. 11. Supplement Theorem 12. m / CEA 1 m / CEB 5 180 12. Def. of suppl. ? 13. m / CEA 1 m / CEA 5 180 13. Substitution 14. 2( m / CEA ) 5 180 14. Substitution 15. m / CEA 5 90 15. Division Property 16. / CEA and / CEB are rt. ? . 16. Def. of rt. / 17. C w D w ' A w B w 17. Def. of ' 18. C w D w is the perpendicular bisector of A w B w . 18. Def. of ' bisector 19. C and D are on the perpendicular bisector of A w B w . 19. Def. of points on a line...
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  This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.
  
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  Pre-Calculus Homework Solutions 123 - CEB 6. SAS 7. A w E w...
  
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  125 Chapter 5 29. m 5 } ( ( y x 2 2 2 2 y x 1 1 ) ) } 5 } 7 0 2 2 3 3 } or 2 } 4 3 } 30. No, R w X w is not an altitude of n RST .The slope of S w T w is 1. The product of the slopes of S w T w and R w X w is 2 } 4 3 } , not 2 1. Thus, the segments are not perpendicular. 31. Given: C w A w > C w B w , A w D w > B w D w Prove: C and D are on the perpendicular bisector of A w B w . Proof: 32. Given: / BAC , P is in the interior of / BAC , PD 5 PE Prove: AP #\$ is the angle bisector of / BAC Proof: A B D P E C C D E B A y x ( 2 1, 6) (3, 3) R S (1, 8) T y x ( 2 1, 6) (3, 3) R S (1, 8) T Statements Reasons 1. / BAC , P is in the interior of / BAC , PD 5 PE 1. Given 2. P w D w > P w E w 2. Def. of > 3. P w D w ' A w B w , P w E w ' A w C w 3. Distance from a point to a line is measured along ' segment from the point to the line. 4. / ADP and / AEP are rt. ? 4. Def. of ' 5. n ADP and n AEP are rt. n s 5. Def. of rt. n 6. A w P w > A w P w 6. Reflexive Property 7. n ADP > n AEP 7. HL 8. / DAP > / EAP 8. CPCTC 9. AP #\$ is the angle bisector of / BAC 9. Def. of / bisector Statements Reasons 1. C w A w > C w B w , A w D w > B w D w 1. Given 2. C w D w > C w D w 2. Reflexive Property 3. n ACD > n BCD 3. SSS 4. / ACD > / BCD 4. CPCTC 5. C w E w > C w E w 5. Reflexive Property 6. n CEA > n
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  Unformatted text preview: CEB 6. SAS 7. A w E w > B w E w 7. CPCTC 8. E is the midpoint of A w B w . 8. Def. of midpoint 9. / CEA > / CEB 9. CPCTC 10. / CEA and / CEB form a linear pair. 10. Def. of linear pair 11. / CEA and / CEB are supplementary. 11. Supplement Theorem 12. m / CEA 1 m / CEB 5 180 12. Def. of suppl. ? 13. m / CEA 1 m / CEA 5 180 13. Substitution 14. 2( m / CEA ) 5 180 14. Substitution 15. m / CEA 5 90 15. Division Property 16. / CEA and / CEB are rt. ? . 16. Def. of rt. / 17. C w D w ' A w B w 17. Def. of ' 18. C w D w is the perpendicular bisector of A w B w . 18. Def. of ' bisector 19. C and D are on the perpendicular bisector of A w B w . 19. Def. of points on a line...
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  This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.
  
  Ask a homework question - tutors are online
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