bash variable with spaces why cd "$myvar" results in one parameter, but myvar='"some stuff"' in two? I'm struggling to understand why following does not work as expected in bash:

$ myvar='"some stuff"'
$ echo $myvar
"some stuff"
$ cd $myvar
bash: cd: "some: No such file or directory


I know the canonical way is to (How to use cd with shell variable containing spaces):

$ myvar="some stuff"
$ echo $myvar
some stuff
$ cd "$myvar"


But e.g. here https://stackoverflow.com/a/12258418/881191 answer by Alex for macOS advices to escape quotations, which I also tried and it's the same as putting double quotations inside single ones in my case. Why in one case cd gets two parameters and in other two from as I see it same "some stuff"?
Typically, quotes are strip in a parameter/variable assignment, unless the quotes them self are quoted and they then become part of the string. As in your example "some stuff" is the string attached to $myvar. When you issue the command-

cd $myvar


the command is broken up into tokens- words and operators. The shell parses them into a command and arguments, then parameter/variable expansion takes place on $myvar. Since $myvar isn't quoted the contents are split into two words (known as field or word splitting) -

"some and stuff"


Thus, the error message- bash: cd: "some: No such file or directory. Since cd only accepts one argument stuff" is disregarded.
Even when you quote the variable $myvar it still produces an error message because the directory name is some stuff not "some stuff"- 

cd "$myvar" 
bash: cd: "some stuff": No such file or directory