Using Javascript | Applescript to click button in Safari I realize there are several threads about this and they are all very specific to certain website . My background is in Python, not Javascript or Applescript, and I'm confused on exactly how to achieve this action .

I've seen several scripts doing this action, namely:

tell application "Safari"

activate

do JavaScript "document.forms['search']['order_list_search_batch'].click()"

end tell


What is the best method to act this out ?

i'm confused on what goes in between "document.forms[WHATGOESHERE?].click()"

I'm trying to click the Proceed button on http://rna.tbi.univie.ac.at/cgi-bin/RNAfold.cgi.

I went to "Inspect Element" on the Proceed button and got this code:

&lt;input style="cursor: pointer;" value="" name="proceed" class="proceed" onmouseover="this.style.cursor=&amp;quot;pointer&amp;quot;" type="submit"&gt;


How do I know what to put in script to click this button based off of the Inspect Element results ? I want to understand so I can use this method in more than one case. There's not a href link that it goes to.



Current code is not working

tell application "Safari" to activate
open location "http://rna.tbi.univie.ac.at/cgi-bin/RNAfold.cgi"
delay 3
tell application "Safari" to do JavaScript "document.forms[0].elements[document.forms[0].elements.length-1].click()"
For a minute there I thought you were asking the same question again as last time.

But  realise now you want to know how to use Inspect Element to construct your own code.

In the example you give: document.forms[WHATGOESHERE?].click()

The WHATGOESHERE would be the form name.

i.e document.forms['theFormName'].click()

Your website in their wisdom has named the form 'form'

&lt;form method="post" action="/cgi-bin/RNAfold.cgi" enctype="multipart/form-data" name="form"&gt;
 &lt;input type="hidden" name="PAGE" value="2"&gt;

i.e document.forms['form'].click()

But this would not click the input button

You can use the submit() function dot syntax'd on the end :

document.forms['form'].submit()

Safari Applescript : do JavaScript "document.forms['form'].submit()" 



Also

In the code I provided you in your last question. I used:

tell document 1

        do JavaScript "document.getElementsByClassName('proceed')[0].click()"

    end tell


This uses the class Name proceed of the forms input element seen here: class="proceed"

&lt;input value="" name="proceed" type="submit" class="proceed" onmouseover="this.style.cursor=&amp;quot;pointer&amp;quot;" style="cursor: pointer;"&gt;

The  getElementsByClassName('proceed')[0] does exactly what it says.

It gets the Elements By ClassName  'proceed'.

The [0]  means it will give you the first element in it's results from the Array that would be returned. The array is counted from 0-9. So the first item would be item 0.



A good place to get working examples and information about Javascript is at www.w3schools.com On the front page the have links to their HTML and Javascript examples and Tutorials. The elements of the HTML Dom and Javascript functions are listed for easy access.