Can't run one particular program from Terminal without using its full path I want to run a program ds9 from the Terminal. The program is clearly in the PATH, which I determined by running:

which ds9
/Users/evgenii/miniconda3/envs/iraf/bin/ds9


But when I run the command by typingds9, it shows me the following error:

-bash: /Applications/ds9.app/Contents/MacOS/ds9: No such file or directory


I can still execute it fine if I use the full path as follows:

/Users/evgenii/miniconda3/envs/iraf/bin/ds9


What's going on? Why is it trying to run /Applications/ds9.app?

Permissions are as follows:

-rwxrwxr-x@ 1 evgenii  staff  18613852  9 Nov 20:13 /Users/evgenii/miniconda3/envs/iraf/bin/ds9


Update:

Here is the output of running type -a ds9 command:

type -a ds9
ds9 is aliased to `/Applications/ds9.app/Contents/MacOS/ds9 -xpa no'
ds9 is /Users/evgenii/miniconda3/envs/iraf/bin/ds9
The command is apparently aliased to a broken alias. First, check for all the matches for ds9 in PATH environment variable, by executing the following command:

type -a ds9

As per your updated question, it's apparent from the output of type -a ds9 command, that an alias is shadowing the actual command.

To execute the actual command by ignoring the alias, and without specifying the full path, prepend a \ (backslash) character before the command. This ignores any bash defined alias.

If you do not wish to prepend the backslash before the command every time, figure out where the alias is being created, and either remove it, or override the alias with the actual command.