Open application from terminal and remain linked to the process (like Linux) so when CTRL+C is sent to terminal the application closes too I have an application (closed-source tool not developed by me) which requires another process to exist before executing properly.  When I quit this application, I also want that custom process to be killed.  My solution is to have a shell script "launcher".  I can handle creating shell script menus, the on-close event, and opening/killing the processes.  The problem is that I can't seem to figure out how to open an application from Terminal but keep Terminal locked on that application so that when I close the Terminal window or send CTRL+C the application closes.  If you're familiar with Linux, a simple example of my desired behavior is just "gedit file.txt".  The text-editor would open but it only lives as long as the terminal window does.

On OSX with the "open" command, I can start applications but they aren't linked to the Terminal window.  Is there an alternative command I should be using to achieve this behavior?

Here is my script so far:

#!/bin/bash
set -e
function cleanup {
    osascript -e 'tell application "APP1" to quit'
    osascript -e 'tell application "APP2" to quit'
}
trap cleanup EXIT

clear

PS3='Please select an option: '
options=("Start Apps" "Stop Apps")
select opt in "${options[@]}"
do
    case $opt in
        "Start Apps")
            open -a "APP1"
            open -a "APP2"
            ;;
        "Stop Apps")
            cleanup 
            ;;
        *) echo invalid option;;
    esac
done
Rather than use the Unix command open.

You can execute the executable file of the applications directly.

For example for TextEdit.app

Running the command in Terminal.app

/Applications/TextEdit.app/Contents/MacOS/TextEdit

This will open TextEdit using a process from Terminal.app

When you close the terminal window or use Ctrl  + C

TextEdit will quit.