Reaction of alcohols with bromine In a reaction between $\ce{R-OH}$ and $\ce{Br2}$, what will the product be?
Initially I thought it would be $\ce{R-Br}$, but that doesn't seem right.

I'm oscillating between the product being either $\ce{R-OBr}$ or no reaction occurring at all. I've searched a bit on the web too, but couldn't get an answer.

What is the product?
No reaction occurs with the reagents you have stated at room temperature. Maybe with different conditions (eg. basic conditions) the haloform reaction that Ivan commented would occur.