Redox reactions of halides in hexane When we have two test tubes and we add:


In the first test tube: hexane, aqueous solution of $\ce{NaCl}$ and aqueous solution of $\ce{I2}$ 
In the second test tube: hexane, aqueous solution of $\ce{NaI}$ and aqueous solution of $\ce{Cl2}$


We are asked to write the reactions that take place in these experiments. Do we write only this:  

$$\ce{NaCl + I2 → no reaction}$$

$$\ce{2NaI + Cl2 → 2NaCl + I2 (displacement)}$$

Or should hexane appear in the reactions too?
Hexane is the solvent for the two halogens. It does not react with either so leave it out of your answer.