How to choose the correct name for calcium sulfate based on a calculations of the crystallisation water included? I have a test review question which i really need help on. It states : 


  A student heated a sample of the hydrate $\ce{CaSO4 * xH2O}$ in an evaporating dish over a bunsen burner to remove all the water and recorded the following data:  
  
  Mass of empty evaporating dish: $\pu{19.73g}$
  Mass of evaporating dish + hydrate: $\pu{21.50g}$
  Mass of evaporating dish + anhydrous $\ce{CaSO4}$: $\pu{20.80g}$  
  
  Determine A) the value of $x$ and B) the most likely name/formula of the hydrate.


I already figured out $x$ by getting the mass of water then simplifying the ratio of anhydrous to water.
But the second question which asks to name the formula of the hydrate really confused me. I would appreciate if anyone can guide me how to solve B.
From my calculations

\begin{align}
x &amp;= \frac{M(\ce{CaSO4}) \times \left[m(\ce{CaSO4 * xH2O}) - m(\ce{CaSO4})\right]}{M(\ce{H2O}) \times m(\ce{CaSO4})} =\\ 
&amp;= \frac{\pu{136.14 g mol-1} \times (\pu{1.77 g} - \pu{1.07 g})}{\pu{18.02 g mol-1} \times \pu{1.07 g}} =\\
&amp;= 4.94,
\end{align}

which gives $\ce{CaSO4* 5 H2O}$, calcium(II) sulfate pentahydrate.