Deprotection of carboxybenzyl (Cbz) in the presence of Methyl ester? Deprotection of carboxybenzyl and methyl ester can easily be achieved by using ammonium formate followed by addition of 10% Pd/C and LiOH/MeOH respectively. 

But how we can achieve deprotection of carboxybenzyl group in the presence of methyl ester?
Just leave out the last step, i.e., LiOH/MeOH and you should be just fine, the Cbz group gets removed under reductive conditions which leave the methyl ester unaffected. If you lose the methyl ester, you could just add it again afterwards.