Fluorination with xenon difluoride Is this an error? Why is the nitro group reduced as the benzene ring is oxidized? I don't see any possible reducing agents here.. 

Also, what is the mechanism of aromatic fluorination by xenon difluoride? This appears analogous to electrophilic aromatic substitution in which benzene acts as a nucleophile and attacks an electrophile because of the expected meta-substitution pattern given the presence of the nitro group. 

Is fluorine really electrophilic here? How so?
The reaction as pictured above is incorrect, the nitro group is not reduced.  As you suggest this is (predominantly) an electrophilic aromatic substitution reaction.  

Usually $\ce{HF}$ is used as a catalyst in these reactions and the following equilibrium is established.

$$\ce{XeF2 + HF &lt;=&gt; XeF+ + HF2^-}$$

The electrophilic $\ce{XeF^+}$ is the reactive species forming a complex with the aromatic ring.  Xenon is expelled from the complex and the reaction proceeds to yield the meta-fluoro isomer as expected for an electrophilic aromatic substitution.  Some other products, such as substituted biphenyls, are usually formed in small amounts suggesting that some minor pathway (radical-cation?) is also in play.