Does ethanol react with potassium to form potassium ethanolate and hydrogen gas? I'm finding information in Google with the keyword (C2H5OH + K) to find the reaction between $\ce{C2H5OH}$ and $\ce{K}$ and found very little information about it. Just 2-3 related results with contradictory pieces of information.

The first one gave

$$
\ce{K + C2H5OH -&gt; KOH + C2H5},
$$

the second one gave

$$
\ce{2C2H5OH + 2K -&gt; 2C2H5OK + H2},
$$

and the third one gave

$$
\ce{C2H5OH + KOH -&gt; C2H5OK + H2O}
$$

There are no trusted public sources so I'm very baffled. I think that $\ce{C2H5OH}$ will react with $\ce{K}$ to form $\ce{C2H5OK}$ because it looks like the reaction with $\ce{Na}$. But I'm not sure and just want to find a trusted source. Can anyone confirm the true result for this reaction?
You can view water as the simplest alcohol, and indeed, water reacts with all of the Group 1 metals to form hydrogen gas and the corresponding metal hydroxide according to the following equation

$\ce{2M + 2HOH -&gt; 2MOH + H2}$

where $\ce{M}$ is the metal.  

The same reaction occurs with simple alcohols to produce the corresponding metal alkoxide and hydrogen gas

$\ce{2M + 2ROH -&gt; 2MOR + H2}$

As you increase the hydrocarbon portion of the alcohol, or reduce accessibility to the $\ce{OH}$ portion of the alcohol (e.g. make the alcohol less like water), you slow down the rate of the reaction.  

Here is a nice link that compares and discusses the relative reactivities of the Group 1 metals with water.