Mechanism for acid-catalyzed dehydration of 2,3-dimethylcyclopentanol How do you get from 2,3-dimethylcyclopentanol to 1,2-dimethylcyclopent-1-ene? 

I know the -OH group leaves as water (being protonated by acid) forming a carbocation. Then the weak nucleophile (water) attacks the beta-hydrogen to form what I think is 2,3-dimethylcyclopent-1-ene. But why is it 1,2-dimethylcyclopent-1-ene? 

I know Zaitsev's rule wants the more substituted alkene, but forming the 1,2-dimethylcyclopent-1-ene would leave the carbocation hanging there, wouldn't it (the carbocation would still be unsatisfied)? 

  

Update:
See this:


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