Half-Reactions of Hydroxide The following is the equation I have:

$$\ce{Ca(s) + 2H2O(l) -&gt; Ca(OH)2 v  + H2 ^}$$

I am tasked to write the half-reaction equations for both the oxidation and/or reduction process. So, currently I have:
$$\ce{ Ca(s) -&gt; Ca^{2+}(aq) + 2e-}\quad\text{(oxidation)}$$

but I'm not sure how do you write the reduction equation for the water and hydroxide.

Any help is appreciated :)

P.S.: I have no idea how to superscript or subscript in the forum.
Alright, so I've worked out my answer (thanks to @user55119). The Reduction step was:


  $$\ce{ 2H2O_{(l)} + 2e^- -&gt; 2OH^-_{(aq)} + H_2_{(g)}}\quad\text{(Reduction)}$$