Heating of Ethers with HI and Cleavage of Ethers Question:

Give the major product formed by the heating of the following ether with HI.
        CH3
        |
CH3-CH2-CH-CH2-O-CH2-CH3


My Attempt:
According to me, the product should be this due to delocalization of positive charge among the neighboring carbon atoms.

        CH3
        |    
CH3-CH2-CH-CH2-I + CH3-CH2-OH


Answer:
I checked the answer in my book and it is completely different:

        CH3
        |
CH3-CH2-CH-CH2-OH + CH3-CH2-I


Now, I think they may have considered steric hindrance to be the deciding factor of site of attack of OH but will not delocalization be dominant over steric effect?
Also, what will be the effect of hyperconjugation on the reaction?
Your ether has $\ce{CH2}$ groups at both sides of the oxygen atom. 

I would exclude a $S_N1$ reaction here! Instead, cleavage of the ether proceeds via $S_N2$. The oxonium ion resulting from addition of a proton is attacked by iodide at the least hindered carbon atom. Iodide is quite big ;-)