Finding major product when bromonium compound is acted upon by a nucleophile The original question is:-


  The major product obtained in the following conversion is:-
  


(Note that Me here means methyl group)

The initial step would be the formation of a bromonium intermediate. Which would then be attacked by a nucleophile $\ce{CH_3OH}$ as it is present in excess in solvent. 

What I think is, $\ce{CH_3OH}$ would attack the carbon atom close to ketone, because that’s the carbon best able to stabilize positive charge due to resonance with keto group. This is what I think will happen 




But the proposed answer was



Can anyone explain me why how and why this compound is formed?
I'd like to point out that the ketone would actually disfavor an attack at its alpha position:



Placing two positive charges on adjacent carbon atoms is much less favorable than not, especially when there is an oxygen perfectly poised to help stabilize this positive charge, as user55119 pointed out.