Hydrogen atom transfer between enantiomers of rac-1-phenylethanol (Taken from Dalton Trans., 2012, 41, 13423–13428. DOI:10.1039/c2dt31781h)

I have difficulties understanding the hydrogen transfer in the image above. I always thought that hydrogen transfers followed the following formula:

$$\ce{X^. + H-Y -&gt; X-H + Y^.}$$

I can't really see the connection between the picture and the formula. Is it the whole ethanol group that is transferred?
Did you continue reading the paper? :) The source is important and is what was needed to answer the question!

I'm just going to quote from it.


  In DKR [dynamic kinetic resolution] a chemical catalyst is added in order to racemize the enantiomers, ensuring that all the substrate can be utilized. [...] Highly successful catalysts are often Ru(II) complexes [...] The metal complex catalyses racemization by a hydrogen transfer mechanism (Scheme 2).




So, the supposed hydrogen transfer occurs via coordination to a metal, followed by β-hydride elimination. Readdition of the metal hydride across the opposite face of the resultant ketone (acetophenone in this case) produces the other enantiomer.