How to identify an unknown compound with spectroscopic data? I need some help identifying the following unknown compound. Any suggestions or hints regarding the possible compound would be highly appreciated.

So far I am thinking the broad peak on the IR is an alcohol that somehow mixed with possible $\ce{sp^3-CH}$ bonds. And the peak around $\pu{1600 cm-1}$ is I think a $\ce{sp-C-C}$ bond. The compound should have four distinct groups of protons. Beyond this basic analysis, I couldn't really come up with a compound. 



I have updated (07/09/14) the question with a newer NMR (below) and an IR. 





Some other additional info I worked out in the lab:


look: white powder like solid.
melting point: $\pu{116.3-119.0 ^\circ C}$
Solubility:


Water - insoluble
NaOH - insoluble
Sulfuric Acid - soluble

Classification Tests:


Water insoluble phenol test - positive; a dark red precipitate formed. 
Chromic acid test - positive; green precipitate formed. 
Bromine test for unsaturation - positive; bromine discoloration happened until about $\pu{2 ml}$ of bromine was added. White precipitate formed. 



This is my first time doing these tests so please don't consider their results too strictly. My Instructor said the IR is a much safer way to determine functional groups.
Have a look at typical IR bands (other source) and identify them.


   - 3424 phenolic $\ce{OH}$ stretch
 - 1640 aromatic $\ce{C=C}$ bending or $\ce{C=C}$ alkenyl stretch
 - 1264 aromatic $\ce{C-O}$ stretch
 -  747 aromatic $\ce{C-H}$ bending


Have a look at you spectrum, identify your residual solvent signal.


    7.15 is chloroform $\ce{CDCl3}$


Have a look at the typical $\ce{{}^{1}H-NMR}$ shifts table and identify the protons.


   These are aromatic protons


What is the summary of your first conclusions?


   It's an aromatic compound with an hydroxyl group.


How many protons?


   multiple of 5


Calculate the coupling constants via $$J=\Delta\delta_{\mathrm{ppm}}\cdot\nu_0$$ and identify the splitting pattern. (I can only assume it is a 500MHz spectrometer, hence $\nu_0=500~\mathrm{MHz}$.)
Example: Doublet at 7.55 ppm:
$$J=(7.5615-7.5461)\cdot500~\mathrm{MHz}=7.7~\mathrm{Hz}$$
Solutions:  


   7.55 doublet, $2\ce{H}$, $J=7.7~\mathrm{Hz}$
 7.40 doublet of doublet (fake triplet), $2\ce{H}$, $J=7.6~\mathrm{Hz}$, $J=7.5~\mathrm{Hz}$
 The last one is tricky because there is one peak not picked
 It should be at 7.30 a doublet of doublet, $1\ce{H}$,  ${}^3J=7.7~\mathrm{Hz}$, $J=7.6~\mathrm{Hz}$  


Disclaimer:
Please read long's answer and follow his thoughts. They make a lot of sense and hint that the compound we are looking at is not the one I am proposing. But due to my lack of current knowledge, I cannot make another suggestion.

Combine all you see and you will get a clue which substance it is.


   7.55 ortho
 7.40 meta
 7.30 para
 Phenol.