Quaternary Ammonium salts and peroxy acid I came across this question in my test:


  This compound
  
  
  
  is treated with $\ce{CH_3CH_2I}$ and then with $\ce{H_2SO_5}$ and heated.
  The product is:
  A)
  
  
  
  B)
  $\ce{CH_2CH_2}$
  and two other impossible options.


I first don't understand the role of $\ce{H_2SO_5}$ in this. I know about Hoffmann elimination of quaternary ammonium hydroxides but in that we use silver oxide to form the hydroxide from the iodide. And then heating is done for elimination.    

Secondly the answer given is option B but I am not able to understand why is that. The second example in this page says otherwise Quaternary ammonium salts
Does this have anything to do with the $\ce{H_2SO_5}$?  

My third doubt is a general one. What happens in general when different alkyl groups are attached to the the nitrogen in a quaternary ammonium hydroxide. Which one undergoes elimination first? Are there any rules to determine that?
I believe this is an example of a Cope elimination mechanism here

The EtI is making the tertiary amine. The persulfate is taking the tertiary amine to the N-oxide. Heating this produces ethene and hydroxylamine of the starting amine. 

This is consistent with the Cope as "The sterically demanding amine oxide function reacts preferentially with the more easily accessible hydrogens"