Reaction between n-butylithium and either an aromatic bromide or an alkylbromide What exactly happens? Does the butylithium chain add to the carbon where the bromine is attached? or do the 2 undergo halogen metal exchange?
It's quite a long time that I did myself, but I used BuLi to transmetalate. I.e. $\ce{MesBr + BuLi -&gt; MesLi + BuBr}$