Out of the given reagents, find the ones to be used to convert benzene to p-aminophenol $\ce{Br2/FeBr3}$
$\ce{CH3Cl/AlCl3}$
$\ce{KMnO4}$
$\ce{HNO3/H2SO4}$
$\ce{NBS}$/hv
$\ce{NaOH}$
$\ce{Sn/HCl}$
$\ce{NH4SH}$
$\ce{NaBH4}$


I'm able to get the amino group onto the ring by using 4 and 7.
But I have no idea how to get $\ce{-OH}$ in para position (also specify the order).
Steps:


Use $\ce{Br2/FeBr3}$ to make bromobenzene.
Nitrate with $\ce{HNO3/H2SO4}$ to make 4-bromo-nitrobenzene.
Treat with $\ce{NaOH}$ to displace the $\ce{Br}$ making 4-nitrophenol.
Reduce with $\ce{Sn/HCl}$ to make the required p-aminophenol.