Lewis Structure on (CH3)2NO? I've been taking an chemistry class online (for fun only) and one of the questions in the homework threw me a bit. Here's the wording:

"Draw the Lewis structure for a nitrogen atom attached to. two methyl groups ($\ce{CH3}$) and one oxygen atom."

OK, so I know that $\ce{NO}$ is a free radical due to the odd combined valence, i.e., the octet rule isn't satisfied. Will that carry over when the $\ce{NO}$ bonds with the two methyl groups?

Here's the sketch of what I did:



Lastly, what's the name of this compound? This is not part of the HW question; I'm just curious.
Name of the compund: Dimethyl nitroxide
Lewis structure:





The properly way to determine the Lewis structure, based on this example, is:


Total valence electrons: $4\cdot2 + 5 + 6 + 1\cdot6 = 25$
Total electrons needed for octets/doublets: $8\cdot4+2\cdot6 = 44$
Total shared/bonding electrons: $44 - 25 = 19$ (In other words, there is only nine single bonds and one electron left.)
Total electrons in lone pairs: $\text{Step 1} - \text{Step 3} = 25 - 19 = 6$ (In other words, the are only 3 pairs of lone electrons.)

Furhter information on how to draw Lewis structures, please follow the link
Further information of related Lewis structures and how this knowledge is applied on real top science, I recommend seeing this reference: Moreira, G.; Charles, L.; Major, M.; Vacandio, F.; Guillaneuf, Y.; Lefay, C. and Gigmes, D. Beilstein J. Org. Chem., 2013, 9, 1589 - 1600.