Enol form of acetone is treated with D2O Could find the mechanism in brief online. Still have few queries. What makes the D2O not attack the the central carbon (to which OH is attached) and choose other the carbon instead (both have a double bond). Again, in the 'repeat' part of mechanism, there's only one carbon with double-bond (carbonyl group). Why does D2O attack the second carbon again and not the carbonyl group one? I'm really confused.
The oxygen of the water will attack the carbon of the C=O forming the hydrate, but this is in equilibrium and completely reversible and a dead end so of no consequence when considering the enol reaction.