How does the cyclisation of the 3,6-dimethylocta-2,6-dien-4-yne occur? The given molecule is treated with $\ce{H+}$ and an acid, that is all. I know that the alkene part reacts with the $\ce{H+}$ first, but have no idea on how to proceed further. I don't see how a cyclisation takes place as the final answer given is 3,4,5,6-tetramethyl-3-cyclohexen-1-one. Any help on how this happens?
First add water to the triple bond a ketone would be formed as the molecule is symmetrical hydroxy group can be attached yo any of the two carbons after that it would undergo tautomerism to form a ketone. Now the second step cyclisation occurs as follows: