Chair conformations of cyclohexane with two substituents I have been studying the chair conformations of cyclohexane but I get confused when it comes to two substituents.

I came across an example, in which the one substituent is the ethyl group (Et) and the other one is methyl (Me).  The ethyl is drawn like a solid wedge, whereas the methyl is drawn like a dashed wedge. As far as I  know, I have to draw the chair and then the equatorial positions and the axial ones. I thought that since the bigger substituent is the ethyl group, that it would be better in a equatorial position and the methyl would be better in a axial position. But the example, draws the ethyl group in an axial position and the methyl in an equatorial position

Why is that?I really don't understand.

Thank you.
Here are some structures to help you. You noted that one group was a solid wedge and the other a dashed wedge without mentioning the substitution pattern. I presume that this was a flat, 2-D structure. You also note that in the chair structure, one group is axial, the other equatorial. Only the 1,3-isomer 2 fits these conditions. The conformation 2a is more stable than 2b.
ADDENDUM: The 1,1-disubstituted isomer would also fit the conditions of the question. The questioner did not designate the structure.