Mechanisms involved in iodination of salicylamide protocol In the laboratory, I performed an eletrophilic aromatic subsitution by reacting $\ce{I+}$ with salicylamide. The mechanism for this reaction is pretty straightforward, but it's the mechanisms for the supplementary reactions used in this lab that I can't seem work out.


In order to prepare the electrophile  $\ce{I+}$, sodium iodide was reacted with sodium hypochlorite:

$$\ce{ ClO- (aq) + I- (aq) + 2H3O+(aq) -&gt; I+ (s) + Cl- (aq) + 3H2O (l)}$$

The equation (I think) is right, but can anyone provide some mechanistic insight or literature on how the hypochlorite manages to oxidize the Iodide?

Does it first have to go into an iodine ($\ce{I2}$) form? The reason I propose this is because as the hypochlorite was added to the salicylamide/sodium iodide absolute ethanol solution, color change was observed from dark red-brown to increasingly lighter shades of yellow.

It seems a similar question was asked about a year ago, but I was hoping to take it a step further.
Once the reaction had finished, a 10% (w/v) sodium thiosulfate solution was added. I assume this was because thiosulfate is a well known bleach (hypochlorite) neutralization agent: $$\ce{HOCl + 2 S2O3^2- -&gt; Cl- + S4O6^2- + OH-}$$

Assuming the above equation is correct, how exactly (mechanistically) does thiosulfate neutralize hypochlorite/hypochlorous acid? The $\ce{S-S}$ bond of the tetrathionate is whats tripping me up.
The order of events is probably:


  Protonation of the hypochlorite ion


$$\ce{ClO- + H3O+ &lt;=&gt; ClOH + H2O}$$


  Nucleophilic displacement of chloride by iodide


$$\ce{I- + ClOH \phantom{0}&lt;=&gt; Cl- + IOH}$$


  Protonation of hypoiodous acid


$$\phantom{000}\ce{IOH + H3O+ &lt;=&gt; IOH2+ + H2O}$$


  Fragmentation of the $\ce{IOH2+}$ cation


$$\phantom{00000}\ce{IOH2+ &lt;=&gt; I+ + H2O}$$

Alternatively, the second step could have been protonation of hyochlorous acid, followed by displacement of water by iodide, and then fragmentation of iodine monochloride:

$$
\begin{align}
\ce{ClOH + H3O+ &amp;&lt;=&gt; ClOH2+ + H2O}\\
\ce{I- + ClOH2+ &amp;&lt;=&gt; ICl + H2O}\\
\ce{ICl &amp;&lt;=&gt; I+ + Cl-}
\end{align}$$