Alkylation of benzene I was solving a question where I had to determine a way to convert benzene into n-propyl benzene.
I figured out a way by first performing Friedel-Craft acylation with propanoyl chloride and then performing Clemmensen reduction to form the desired compound.
On checking the solution,  there were 2 alternative ways portrayed:
One was the same method I had used.
The other involved reaction of benzene with n-chloropropane in the presence of $\ce{FeBr3}$.
However wouldn't there be carbocationic rearrangements taking place that convert the carbocation to isopropyl carbocation?
Please tell me what prevents the rearrangements from happening in the second case.
Initially one would assume that cumene (isopropyl benzene) would be the major product. However, kinetic control does have a say in this reaction, according to Gilman and Means.1

At - 2°, n-propyl bromide with benzene and aluminum chloride gave n-propylbenzene, identified as its sulfonamide. Genvresse (6) obtained both n-propylbenzene and isopropylbenzene by conducting the reaction at reflux temperature. Konowalow (7) found that below $0^\circ$, n-propyl chloride gave n-propylbenzene, while from $0^\circ$ to reflux temperature it gave mixtures of n-propylbenzene and isopropylbenzene. More recently it has been shown that at $-6^\circ$, 60% of the monopropylbenzene was n-propylbenzene, and 40% was isopropylbenzene. At $35^\circ$, this ratio was reversed.

a low temperature would facilitate the production of larger amounts of n-propylbenzene due to kinetic control. However, this is still not a very efficient method of preparing n-propylbenzene, and acylation followed by Clemmensen/Wolff-Kishner reduction would be more suitable here.
References:

Gilman, Henry, R. N. Meals, “Rearrangements in the Friedel-Crafts Alkylation of Benzene” Journal of Organic Chemistry 1943, 08(2), 126–146. doi:10.1021/jo01190a003.