What is the product of the reaction of 2-methyl-5-phenyl-2-pentene with sulfuric acid? The reaction is 2-methyl-5-phenyl-2-pentene with $\ce{H2SO4 }$ 



I have tried multiple attempts at this question but am still getting it wrong. I have no idea why any of these answers are wrong.

I know that the chain off the aromatic ring is weak aromatic activator and an ortho-para director. I figured para would be better than ortho because of the size of the chain but obviously both answers were incorrect. I then figured that $\ce{H2SO4}$ is just a strong acid so its basically $\ce{H3O+}$ but adding $\ce{H}$ and $\ce{OH}$ across the double bond in the chain did not work either.
With the help of user SendersReagent in comments, the answer to the question was a simple intramolecular Friedel–Crafts reaction: