Which process would separate the mixture of toluene, cyclohexane and water? toluene: $\ce{C6H5-CH3}$
cyclohexane: $\ce{C6H12}$

I think that answer would be:

Toluene and cyclohexane do not dissolve in water (since they are nonpolar), so I would first separate the water from the mixture with a separator funnel.

A mixture of cyclohexane and toluene would be separated by fractional distillation. Cyclohexane, which has a lower boiling point than toluene, would be eliminated from the mixture.


Is there anything wrong in my answer? Would there also be anything to add?
Distillation
The most effective and easiest way to separate the mixture of toluene and cyclohexane is simple distillation. Cyclohexane has boiling point is about 81°C, and toluene’s boiling point is 111°C.
References:

http://origin-www.thermoscientific.jp/content/dam/tfs/ATG/CAD/CAD%20Documents/Product%20Support%20Bulletins/NMR%20Support%20Documents/pS45-pS80-Simple-Distillation-of-Cyclohexane-and-Toluene.pdf
https://www.sas.upenn.edu/~dbalmer/chem502/Labs/lab2_distillations/balmerexp2.pdf