What is the final temperature of each substance upon absorbing 2.25 kJ of heat? Suppose that $\pu{28 g}$ of silver is initially at $\pu{29.0^\circ C}$. What is its temperature upon absorbing $\pu{2.25 kJ}$ of heat?


My work: $2250 = 0.240 \times 28 \times t - 29$

Solve for $t$ and I get $\pu{340 ^\circ C}$. But the correct answer is $\pu{370 ^\circ C}$ and I have no clue how to get there.
You are almost correct, however, to calculate these values you need to put a bracket around he $t-29$ term (which is the $\Delta T$ term from $Q = mc \Delta T$). Hence, from your working out step:

$$2250 = 0.240 \times 28 \times (t - 29)$$

You'll need to expand the brackets.