Will water allow salts to be dissolved in methanol (that are otherwise poorly soluble)? If we make a mixture of water, methanol and a salt like $\ce{FeCl2}$, $\ce{NaCl}$ etc, will the ability of water and methanol to mix allow $\ce{FeCl2}$ and $\ce{NaCl}$ to be a part of this mixture and form a solution as opposed to when $\ce{NaCl}$ and $\ce{FeCl2}$ are just added to methanol in which they are poorly soluble? 

Or will we see layers forming (which I don't see happening because of the strong tendency for water and methanol to mix)? Or will we just see a methanol-water layer with some salt dissolved in it and some salt left at the bottom (even though they are soluble in water)?
Thanks in advance
This is a highly complicated question, and the answer can't be derived by logic alone.

Maybe the liquid phase will remain mixed, and just dissolve some salt (more than would dissolve in methanol, but less than would in pure water). Or maybe it will separate into water-rich and alcohol-rich layers, with nearly all dissolved salt staying in the former. This may be considered an extreme case of salting out.

I know for sure that separation does occur in water/ethanol/$\ce{CaCl2}$ system, even though ethanol by itself is miscible with water in any ratio, as is methanol. Then again, $\ce{CaCl2}$ is much better soluble in water than $\ce{NaCl}$, so the latter might not be strong enough to produce the same effect.

The bottom line is that you can't tell for sure until you try it. Chemistry is an experimental science, after all.