Can antimony pentafluoride be made by adding hydrogen fluoride to antimony trifluoride? I was looking at how the strongest acid was made and I found something I did not understand. On the Wikipedia page for antimony trifluoride it shows the production of $\ce{SbF3}$ using $\ce{HF}$:
$$\ce{Sb2O3 + 6 HF -&gt; 2 SbF3 + 3 H2O}$$
The page also shows production of $\ce{SbF5}$ using $\ce{F2}$:
$$\ce{SbF3 + F2 -&gt; SbF5}$$
However on the page for fluoroantimonic acid it shows production of:

$$\ce{SbF5 + 2 HF -&gt; SbF6- + H2F+}$$

So my question is why the production of $\ce{SbF5}$ seems to require fluorine insted of hydrogen fluoride? And is it possible to use hydrogen fluoride to make $\ce{SbF5}$?
It can be prepared using hydrogen fluoride, in a double displacement reaction:


  $\ce{SbCl5 + 5 HF -&gt; SbF5 + 5 HCl}$


However, hydrogen holds onto fluorine more tightly than does antimony in $\ce{SbF5}$. 

Consider the reverse of your proposed reaction, which is preferred energetically:


  $\ce{SbF5 + H2 -&gt; SbF3 + 2HF}$