What is the effect of thrust vectoring effect on the rate of turn? I just got a question after reading my old Principles of Flight book. The equation for the rate of turn is $\textrm{ROT} = 1,091 \cdot \frac{\tan(\phi)}{V}$,
with $\phi$ denoting bank angle and $V$ denoting airspeed
How would that change when the airplane is equipped with thrust vectoring like the F22 or SU35? Is there an equation for that?
The standard equation applies to any coordinated level turn (so that the G felt is &quot;straight down&quot; to an occupant of the aircraft, in an aircraft frame of reference). Matters not how it's all achieved - flaps, high-lift devices, helo rotor, thrust vectoring, whatever... a coordinated level turn at &quot;this&quot; bank will take &quot;this&quot; much radius. And it will have a calculable G load.
Actually achieving (and sustaining) that G load may take all sorts of interesting effects, such as thrust vectoring. But once you're there, the standard equations apply.
And, if you choose to fly an un-coordinated turn, with some amount of side-loaded G force (example, a car turning at high speed... no appreciable &quot;bank angle&quot; so the G force pushes you toward the outside of the turn), then all the standard assumptions are out the window. At that point, your radius would be a function of G &amp; not bank... and it'd get uncomfortable really fast!