Can we borrow Formula One's ground effect for airplanes? (Source)

Inspired by the now banned late 70's F1 ground effect, I wondered if it can be adopted by airplanes. So, I came up with this:



(Own work)

The system

A belly door that opens at slow speeds and leads to a narrowing cavity—inverted diffuser.

In essence, the same as the F1 image above, but enclosed since there's no ground. And inverted since we need lift, not downforce. An F1 car's ground effect is the opposite of a plane's ground effect. The door is to stop its operation at high speed.

Theory of operation

The narrowing cavity will speed up the air, the air in the cavity thus will lose pressure (potential energy tuned into kinetic), the air outside the plane and underneath the cavity will be higher pressure, forcing the plane up.



There's no mission, just an experimental racing Howard Hughes kind of thing.

The engineering why is higher top speed, and low angle of attack slow flight.


The way I see it at slow speed the center of lift will shift aft, thus lowering the required angle of attack, I'm not sure about the longitudinal control authority and stability though.
Also, there'll be no need for high-lift devices and their associated systems, and possibly shorter wings, thus shedding weight and increasing top speed.


Can it fly? Are the assumptions above correct?

Engine location, nose gear location, etc., are not part of the question, just a pure aerodynamics question if we can make a cavity produce lift.
The reduced pressure on the car not only exerts a downward force on the car, but an equal upward force on the ground. Mythbusters did an episode where they drove an Indy car over a manhole to show that it does lift the manhole cover slightly.

The force on the ground is irrelevant because it doesn't move and is not attached to the car. But in your drawing the same thing is happening. The reduced pressure exerts an upward force on the bottom of the channel and an equal downward force on thing top of it. They cancel each other.